TRIGONOMETRY
# Phase I: Ratios & Identities
# Phase II: Trigonometric Equation
# Phase III: Properties of Triangle
Ratio & Identities
Problem: Show that:
1. =
2. = ±
Extended definition of Trigonometric Function [Circular Function]
In cycle of unity raids sine all
= x(-, +) P(x, y) (+, +)
= y r=1
=
(-, -) (+, -)
tangent cosine
Convention:
i) If θ is measured in anticlockwise then it is assume positive.
ii) If θ is measured in clockwise then it is assume negative.
Angle MeasurementsSystem
(i) British System (Degree)
Right angle = 90°
1° = 60 min
1min = 60sec
e.g.: 43°23’37”
(ii) French System (grades)
Right angle =
= 100 min
1min = 100sec
e.g.: 63’97”
(iii) Circular System
Right angle = radian
e.g.:
NOTE: - If nothing is mentioned, consider it to be in radians.
T-Ratios of Allied Angles: (90°±θ,180°±θ, 270°±θ etc.)
= p”xP(x,y)
Proof: 90°-θ
= x yy
In ΔOPP”;θ
= x P’
⇒ = x
⇒ =
Working Rule:
Step1: First of all decide sing of T-Ratio from which quadrant is sutatute.
e.g.:180°+θ is in third quadrant where θ∈R
Step2: #If n is even ⇒ NO CHANGE
#If n is odd then interchanges as follows
sin ⟷ cos
tan ⟷ cot
sec ⟷ cosec
Problem: Prove that:
i) = -1
ii) = 0
iii) = 0
iv) +

Trigonometry

  • 1.
    TRIGONOMETRY # Phase I:Ratios & Identities # Phase II: Trigonometric Equation # Phase III: Properties of Triangle Ratio & Identities Problem: Show that: 1. = 2. = ± Extended definition of Trigonometric Function [Circular Function] In cycle of unity raids sine all = x(-, +) P(x, y) (+, +) = y r=1 = (-, -) (+, -) tangent cosine Convention: i) If θ is measured in anticlockwise then it is assume positive. ii) If θ is measured in clockwise then it is assume negative.
  • 2.
    Angle MeasurementsSystem (i) BritishSystem (Degree) Right angle = 90° 1° = 60 min 1min = 60sec e.g.: 43°23’37” (ii) French System (grades) Right angle = = 100 min 1min = 100sec e.g.: 63’97” (iii) Circular System Right angle = radian e.g.: NOTE: - If nothing is mentioned, consider it to be in radians. T-Ratios of Allied Angles: (90°±θ,180°±θ, 270°±θ etc.) = p”xP(x,y) Proof: 90°-θ = x yy In ΔOPP”;θ = x P’ ⇒ = x ⇒ = Working Rule: Step1: First of all decide sing of T-Ratio from which quadrant is sutatute. e.g.:180°+θ is in third quadrant where θ∈R Step2: #If n is even ⇒ NO CHANGE #If n is odd then interchanges as follows sin ⟷ cos tan ⟷ cot sec ⟷ cosec Problem: Prove that: i) = -1 ii) = 0
  • 3.