Angular Measurements
Angular Measurements 
There are two systems used to measure angles.
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o.
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o. 
Extend your arm fully and make a fist as though you 
are handing a torch over to some one else, the 
vertical visual angle of the fist is about 10o.
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o. 
Extend your arm fully and make a fist as though you 
are handing a torch over to some one else, the 
vertical visual angle of the fist is about 10o. 
Rotate your shoulder of the out stretched 
arm incrementally to the sky by stacking 
the fist on top of the previous one until the 
arm is pointing straight up. 
It take about nine fists stacked end to end 
to make the 90o rotation, so 1fist ≈ 10o. 
The clinched fist measured about five 
thumb–nail width. Hence 1o is 
approximately the visual angle of half of 
the thumb–nail width. 
Your eye 
10o 
Your extended fist
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o. 
Extend your arm fully and make a fist as though you 
are handing a torch over to some one else, the 
vertical visual angle of the fist is about 10o. 
One degree is divided into 60 minutes, each 
minute is denoted as 1'. One minute is divided into 
60 seconds, each second is denoted as 1".
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o. 
Extend your arm fully and make a fist as though you 
are handing a torch over to some one else, the 
vertical visual angle of the fist is about 10o. 
One degree is divided into 60 minutes, each 
minute is denoted as 1'. One minute is divided into 
60 seconds, each second is denoted as 1". 
The degree system is used mostly in science and 
engineering.
Angular Measurements 
There are two systems used to measure angles. 
I. The Degree System 
The degree system divides one circular angle into 
360 equal angles and each is set to be 1o. 
Extend your arm fully and make a fist as though you 
are handing a torch over to some one else, the 
vertical visual angle of the fist is about 10o. 
One degree is divided into 60 minutes, each 
minute is denoted as 1'. One minute is divided into 
60 seconds, each second is denoted as 1". 
The degree system is used mostly in science and 
engineering. In mathematics, the radian system is 
used because of it's relationship with the geometry 
of circles.
Radian Measurements 
II. The Radian System
Radian Measurements 
II. The Radian System 
dial–length 
= r = 1 
The unit circle is the circle 
centered at (0, 0) with radius 1.
Radian Measurements 
II. The Radian System 
dial–length 
= r = 1 
 
The unit circle is the circle 
centered at (0, 0) with radius 1. 
Angles are formed between a 
dial (r =1) and the positive 
x-axis as the dial spins.
Radian Measurements 
II. The Radian System 
dial–length 
= r = 1 
 is + 
The unit circle is the circle 
centered at (0, 0) with radius 1. 
Angles are formed between a 
dial (r =1) and the positive 
x-axis as the dial spins. If the 
angle is dialed counter clock– 
wisely, it's a positive angle,
Radian Measurements 
II. The Radian System 
dial–length 
= r = 1 
 is + 
The unit circle is the circle 
centered at (0, 0) with radius 1. 
Angles are formed between a 
dial (r =1) and the positive 
x-axis as the dial spins. If the 
angle is dialed counter clock– 
wisely, it's a positive angle, if it 
is formed clock–wisely, it's 
negative. 
 is –
Radian Measurements 
II. The Radian System 
Arc length as angle 
measurement for  
dial–length 
= r = 1 
 is + 
The unit circle is the circle 
centered at (0, 0) with radius 1. 
Angles are formed between a 
dial (r =1) and the positive 
x-axis as the dial spins. If the 
angle is dialed counter clock– 
wisely, it's a positive angle, if it 
is formed clock–wisely, it's 
negative. 
 is – 
The radian measurement of an angle  is the length 
of the arc that the angle cuts out on the unit circle.
Radian Measurements 
II. The Radian System 
Arc length as angle 
measurement for  
dial–length 
= r = 1 
 is + 
The unit circle is the circle 
centered at (0, 0) with radius 1. 
Angles are formed between a 
dial (r =1) and the positive 
x-axis as the dial spins. If the 
angle is dialed counter clock– 
wisely, it's a positive angle, if it 
is formed clock–wisely, it's 
negative. 
 is – 
The radian measurement of an angle  is the length 
of the arc that the angle cuts out on the unit circle. 
Following formulas convert the measurements 
between degree and radian systems 
180o = rad 1o = rad = 1 rad  57o 
π π 180o 180 
π
Radian Measurements 
Degree system does not work well in mathematics.
Radian Measurements 
Degree system does not work well in mathematics. 
Theorem 1. Given a circle of radius r and the angle  
in radian measurement as shown, 
r 

Radian Measurements 
Degree system does not work well in mathematics. 
Theorem 1. Given a circle of radius r and the angle  
in radian measurement as shown, then 
* (Circular Arc Length) the length of the arc cut out by 
the angle is r. 
length= r 
r 

Radian Measurements 
Degree system does not work well in mathematics. 
Theorem 1. Given a circle of radius r and the angle  
in radian measurement as shown, then 
* (Circular Arc Length) the length of the arc cut out by 
the angle is r. 
* (Circular Wedge Area) the area of the slice cut out 
by the angle is r2/2. 
length= r 
r 
 
area = r2/2 
r 

Radian Measurements 
Degree system does not work well in mathematics. 
Theorem 1. Given a circle of radius r and the angle  
in radian measurement as shown, then 
* (Circular Arc Length) the length of the arc cut out by 
the angle is r. 
* (Circular Wedge Area) the area of the slice cut out 
by the angle is r2/2. 
length= r 
r 
 
area = r2/2 
r 
 
All angular measurements in calculus, including 
variables, are assumed to be in radian.
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Note that if we apply the arc length 
formula using 55o directly we get a 
ridiculous answer of 660” or 55’ of crust!
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement.
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas.
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r 
11π 
36 
(12)
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r 
11π 
36 
(12) = 
11π 
3 
≈ 11.5 inch.
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r 
11π 
36 
(12) = 
11π 
3 
≈ 11.5 inch. 
The area of the slice is r2/2
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r 
11π 
36 
(12) = 
11π 
3 
The area of the slice is r2/2 
11π 
36 
(12)2 (1/2) 
≈ 11.5 inch.
Radian Measurements 
Example A. Find the crust–length and the area of a 
slice of pizza with 12” radius as shown. 
12 
55o 
Convert 55o into the radian 
measurement. 
55o = 55 π 
rad 
180 
= 11π 
36 
Use the above formulas. 
The crust length is r 
11π 
36 
(12) = 
11π 
3 
≈ 11.5 
The area of the slice is r2/2 
11π 
36 
(12)2 (1/2) 
inch. 
= 22π = 69.1 inch2.
Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 

Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 

Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 
 
For example, the angles π/3 and –5π/3 give the 
same dial–tip position ( ½, 3 /2).
Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 
( ½, 3 /2) 
π/3 
For example, the angles π/3 and –5π/3 give the 
same dial–tip position ( ½, 3 /2).
Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 
( ½, 3 /2) 
π/3 
–5π/3 
For example, the angles π/3 and –5π/3 give the 
same dial–tip position ( ½, 3 /2).
Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 
( ½, 3 /2) 
π/3 
–5π/3 
For example, the angles π/3 and –5π/3 give the 
same dial–tip position ( ½, 3 /2). 
Specifically, the coordinate (x, y) of the dial–tip on 
the unit circle is the same for all angles  ±2nπ 
where n = 0, 1, 2, ..
Definition of Trigonometric Functions 
Angles placed in the unit circle 
in the above manner are said 
to be in the standard position. 
There are infinitely many ’s 
that dial to the same position 
so the tip of the dial has the 
same coordinates. 
( ½, 3 /2) 
π/3 
–5π/3 
For example, the angles π/3 and –5π/3 give the 
same dial–tip position ( ½, 3 /2). 
Specifically, the coordinate (x, y) of the dial–tip on 
the unit circle is the same for all angles  ±2nπ 
where n = 0, 1, 2, .. Following are the definitions of 
the basic trig–functions and their geometric 
significances.
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
(x , y) 
let (x , y) be the 
coordinate of the tip 
(1,0) 
of the dial on the unit 
 (± 2nπ) 
circle.
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
 (± 2nπ) 
(x , y) 
x 
y 
(1,0)
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
(1,0) 
(x , y) 
 (± 2nπ) x=cos() 
x 
y
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
(1,0) 
(x , y) 
 (± 2nπ) x=cos() 
x 
y
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
(1,0) 
(x , y) 
 (± 2nπ) x=cos() 
* tan() is the slope of the dial. 
x 
y
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
tan() 
(1,0) 
(x , y) 
 (± 2nπ) x=cos() 
x 
y 
* tan() is the slope of the dial. It is called “tangent” 
because tan() is the “length” of the tangent line x = 1, 
from (1, 0) to the extended dial as shown.
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
tan() 
(1,0) 
cot() 
(x , y) 
 (± 2nπ) x=cos() 
x 
y 
* tan() is the slope of the dial. It is called “tangent” 
because tan() is the “length” of the tangent line x = 1, 
from (1, 0) to the extended dial as shown. Cot() is 
defined similarly using the horizontal tangent y = 1.
Definition of Trigonometric Functions 
Given an angle  in 
the standard position, 
let (x , y) be the 
coordinate of the tip 
of the dial on the unit 
circle. We define 
cos() = x sin() = y 
tan() = cot() = 
y 
x 
tan() 
(1,0) 
cot() 
(x , y) 
 (± 2nπ) x=cos() 
x 
y 
* tan() is the slope of the dial. It is called “tangent” 
because tan() is the “length” of the tangent line x = 1, 
from (1, 0) to the extended dial as shown. Cot() is 
defined similarly using the horizontal tangent y = 1. 
* sin(–) = –sin() cos(–) = cos()
Angular Measurements 
The important positions on this unit circle, the ones 
that we may extract with the 30–60 and 45–45 right 
triangle templates are shown below. 
1 
1/2 
√3/2 ≈ 0.85 
1 
√2/2 
√2/2 ≈ 0.70 
π /6 
π /3 
π /4 
π /4
Analytic Trigonometry 
Trig–values are extracted from the unit circle so they 
satisfy many algebraic relations inherited from the 
equation x2 + y2 = 1 of the unit circle.
Analytic Trigonometry 
Trig–values are extracted from the unit circle so they 
satisfy many algebraic relations inherited from the 
equation x2 + y2 = 1 of the unit circle. With a given 
angle , replace x = cos(), y = sin(), we have the 
trig–identity cos2() + sin2() = 1
Analytic Trigonometry 
Trig–values are extracted from the unit circle so they 
satisfy many algebraic relations inherited from the 
equation x2 + y2 = 1 of the unit circle. With a given 
angle , replace x = cos(), y = sin(), we have the 
trig–identity cos2() + sin2() = 1 
Just as the equation x2 + y2 = 1 
may be written in multiple forms such as 
1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2
Analytic Trigonometry 
Trig–values are extracted from the unit circle so they 
satisfy many algebraic relations inherited from the 
equation x2 + y2 = 1 of the unit circle. With a given 
angle , replace x = cos(), y = sin(), we have the 
trig–identity cos2() + sin2() = 1 
Just as the equation x2 + y2 = 1 
may be written in multiple forms such as 
1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2 
we have correspondingly three forms of square– 
sum–identities.
Analytic Trigonometry 
Trig–values are extracted from the unit circle so they 
satisfy many algebraic relations inherited from the 
equation x2 + y2 = 1 of the unit circle. With a given 
angle , replace x = cos(), y = sin(), we have the 
trig–identity cos2() + sin2() = 1 
Just as the equation x2 + y2 = 1 
may be written in multiple forms such as 
1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2 
we have correspondingly three forms of square– 
sum–identities. 
These square–sum formulas, the reciprocal and 
divisional relations, are summarized by the Trig– 
Wheel given below and these identities are called 
the basic–trig–identities.
Analytic Trigonometry 
The Trig-Wheel
Analytic Trigonometry 
The Trig-Wheel 
the regular-side the co-side
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel 
I 
II III
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel 
I 
II III 
Following are some important divisional relations. 
tan(A) = sin(A)/cos(A)
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel 
I 
II III 
Following are some important divisional relations. 
tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A)
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel 
I 
II III 
or go straight through the 
center then I = 1 / III, i.e. 
two formulas on opposite 
ends are reciprocals. 
Following are some important divisional relations. 
tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A)
Analytic Trigonometry 
The Division and 
Reciprocal Relations 
Start from any function, 
go around the rim, then 
I = II / III or I * III = II 
The Trig-Wheel 
I 
II III 
or go straight through the 
center then I = 1 / III, i.e. 
two formulas on opposite 
ends are reciprocals. 
Following are some important divisional relations. 
tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A) 
csc(A) = 1/sin(A) sec(A) = 1/cos(A) 
cot(A) = 1/tan(A)
Analytic Trigonometry 
The Trig-Wheel Square-Sum Relations 
For each of the three inverted 
triangles in the wheel, the 
sum of the squares of the top 
two functions is the square of 
the bottom function.
Analytic Trigonometry 
The Trig-Wheel Square-Sum Relations 
For each of the three inverted 
triangles in the wheel, the 
sum of the squares of the top 
two functions is the square of 
the bottom function. 
sin2(A) + cos2(A)=1 
tan2(A) + 1 = sec2(A) 
1 + cot2(A) = csc2(A)
Analytic Trigonometry 
The Trig-Wheel Square-Sum Relations 
For each of the three inverted 
triangles in the wheel, the 
sum of the squares of the top 
two functions is the square of 
the bottom function. 
sin2(A) + cos2(A)=1 
tan2(A) + 1 = sec2(A) 
1 + cot2(A) = csc2(A) 
Sum & Difference of Angle Formulas 
Let A and B be angles then 
C(A±B) = C(A)C(B) + – S(A)S(B) 
S(A±B) = S(A)C(B) ± S(B)C(A) 
where S(x) = sin(x) and C(x) = cos(x).
Analytic Trigonometry 
The following are consequences of the sum and 
difference formulas. 
Double-Angle Formulas 
S(2A) = 2S(A)C(A) 
C(2A) = C2(A) – S2(A) 
= 2C2(A) – 1 
= 1 – 2S2(A) 
Half-Angle Formulas 
1 + C(B) 
2 
B 
2 
C( ) = 
± 
1 – C(B) 
2 
B 
2 
S( ) = ± 
From the C(2A) formulas we have the following. 
S2(A) = 
1 – C(2A) 
2 
C2(A) = 1 + C(2A) 
2 
HW. Derive all the formulas on this page from the 
Sum and Difference Formula.

1.3 review on trig functions

  • 1.
  • 2.
    Angular Measurements Thereare two systems used to measure angles.
  • 3.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System
  • 4.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o.
  • 5.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o. Extend your arm fully and make a fist as though you are handing a torch over to some one else, the vertical visual angle of the fist is about 10o.
  • 6.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o. Extend your arm fully and make a fist as though you are handing a torch over to some one else, the vertical visual angle of the fist is about 10o. Rotate your shoulder of the out stretched arm incrementally to the sky by stacking the fist on top of the previous one until the arm is pointing straight up. It take about nine fists stacked end to end to make the 90o rotation, so 1fist ≈ 10o. The clinched fist measured about five thumb–nail width. Hence 1o is approximately the visual angle of half of the thumb–nail width. Your eye 10o Your extended fist
  • 7.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o. Extend your arm fully and make a fist as though you are handing a torch over to some one else, the vertical visual angle of the fist is about 10o. One degree is divided into 60 minutes, each minute is denoted as 1'. One minute is divided into 60 seconds, each second is denoted as 1".
  • 8.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o. Extend your arm fully and make a fist as though you are handing a torch over to some one else, the vertical visual angle of the fist is about 10o. One degree is divided into 60 minutes, each minute is denoted as 1'. One minute is divided into 60 seconds, each second is denoted as 1". The degree system is used mostly in science and engineering.
  • 9.
    Angular Measurements Thereare two systems used to measure angles. I. The Degree System The degree system divides one circular angle into 360 equal angles and each is set to be 1o. Extend your arm fully and make a fist as though you are handing a torch over to some one else, the vertical visual angle of the fist is about 10o. One degree is divided into 60 minutes, each minute is denoted as 1'. One minute is divided into 60 seconds, each second is denoted as 1". The degree system is used mostly in science and engineering. In mathematics, the radian system is used because of it's relationship with the geometry of circles.
  • 10.
    Radian Measurements II.The Radian System
  • 11.
    Radian Measurements II.The Radian System dial–length = r = 1 The unit circle is the circle centered at (0, 0) with radius 1.
  • 12.
    Radian Measurements II.The Radian System dial–length = r = 1  The unit circle is the circle centered at (0, 0) with radius 1. Angles are formed between a dial (r =1) and the positive x-axis as the dial spins.
  • 13.
    Radian Measurements II.The Radian System dial–length = r = 1  is + The unit circle is the circle centered at (0, 0) with radius 1. Angles are formed between a dial (r =1) and the positive x-axis as the dial spins. If the angle is dialed counter clock– wisely, it's a positive angle,
  • 14.
    Radian Measurements II.The Radian System dial–length = r = 1  is + The unit circle is the circle centered at (0, 0) with radius 1. Angles are formed between a dial (r =1) and the positive x-axis as the dial spins. If the angle is dialed counter clock– wisely, it's a positive angle, if it is formed clock–wisely, it's negative.  is –
  • 15.
    Radian Measurements II.The Radian System Arc length as angle measurement for  dial–length = r = 1  is + The unit circle is the circle centered at (0, 0) with radius 1. Angles are formed between a dial (r =1) and the positive x-axis as the dial spins. If the angle is dialed counter clock– wisely, it's a positive angle, if it is formed clock–wisely, it's negative.  is – The radian measurement of an angle  is the length of the arc that the angle cuts out on the unit circle.
  • 16.
    Radian Measurements II.The Radian System Arc length as angle measurement for  dial–length = r = 1  is + The unit circle is the circle centered at (0, 0) with radius 1. Angles are formed between a dial (r =1) and the positive x-axis as the dial spins. If the angle is dialed counter clock– wisely, it's a positive angle, if it is formed clock–wisely, it's negative.  is – The radian measurement of an angle  is the length of the arc that the angle cuts out on the unit circle. Following formulas convert the measurements between degree and radian systems 180o = rad 1o = rad = 1 rad  57o π π 180o 180 π
  • 17.
    Radian Measurements Degreesystem does not work well in mathematics.
  • 18.
    Radian Measurements Degreesystem does not work well in mathematics. Theorem 1. Given a circle of radius r and the angle  in radian measurement as shown, r 
  • 19.
    Radian Measurements Degreesystem does not work well in mathematics. Theorem 1. Given a circle of radius r and the angle  in radian measurement as shown, then * (Circular Arc Length) the length of the arc cut out by the angle is r. length= r r 
  • 20.
    Radian Measurements Degreesystem does not work well in mathematics. Theorem 1. Given a circle of radius r and the angle  in radian measurement as shown, then * (Circular Arc Length) the length of the arc cut out by the angle is r. * (Circular Wedge Area) the area of the slice cut out by the angle is r2/2. length= r r  area = r2/2 r 
  • 21.
    Radian Measurements Degreesystem does not work well in mathematics. Theorem 1. Given a circle of radius r and the angle  in radian measurement as shown, then * (Circular Arc Length) the length of the arc cut out by the angle is r. * (Circular Wedge Area) the area of the slice cut out by the angle is r2/2. length= r r  area = r2/2 r  All angular measurements in calculus, including variables, are assumed to be in radian.
  • 22.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o
  • 23.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Note that if we apply the arc length formula using 55o directly we get a ridiculous answer of 660” or 55’ of crust!
  • 24.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement.
  • 25.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36
  • 26.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas.
  • 27.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r
  • 28.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r 11π 36 (12)
  • 29.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r 11π 36 (12) = 11π 3 ≈ 11.5 inch.
  • 30.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r 11π 36 (12) = 11π 3 ≈ 11.5 inch. The area of the slice is r2/2
  • 31.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r 11π 36 (12) = 11π 3 The area of the slice is r2/2 11π 36 (12)2 (1/2) ≈ 11.5 inch.
  • 32.
    Radian Measurements ExampleA. Find the crust–length and the area of a slice of pizza with 12” radius as shown. 12 55o Convert 55o into the radian measurement. 55o = 55 π rad 180 = 11π 36 Use the above formulas. The crust length is r 11π 36 (12) = 11π 3 ≈ 11.5 The area of the slice is r2/2 11π 36 (12)2 (1/2) inch. = 22π = 69.1 inch2.
  • 33.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. 
  • 34.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates. 
  • 35.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates.  For example, the angles π/3 and –5π/3 give the same dial–tip position ( ½, 3 /2).
  • 36.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates. ( ½, 3 /2) π/3 For example, the angles π/3 and –5π/3 give the same dial–tip position ( ½, 3 /2).
  • 37.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates. ( ½, 3 /2) π/3 –5π/3 For example, the angles π/3 and –5π/3 give the same dial–tip position ( ½, 3 /2).
  • 38.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates. ( ½, 3 /2) π/3 –5π/3 For example, the angles π/3 and –5π/3 give the same dial–tip position ( ½, 3 /2). Specifically, the coordinate (x, y) of the dial–tip on the unit circle is the same for all angles  ±2nπ where n = 0, 1, 2, ..
  • 39.
    Definition of TrigonometricFunctions Angles placed in the unit circle in the above manner are said to be in the standard position. There are infinitely many ’s that dial to the same position so the tip of the dial has the same coordinates. ( ½, 3 /2) π/3 –5π/3 For example, the angles π/3 and –5π/3 give the same dial–tip position ( ½, 3 /2). Specifically, the coordinate (x, y) of the dial–tip on the unit circle is the same for all angles  ±2nπ where n = 0, 1, 2, .. Following are the definitions of the basic trig–functions and their geometric significances.
  • 40.
    Definition of TrigonometricFunctions Given an angle  in the standard position, (x , y) let (x , y) be the coordinate of the tip (1,0) of the dial on the unit  (± 2nπ) circle.
  • 41.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x  (± 2nπ) (x , y) x y (1,0)
  • 42.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x (1,0) (x , y)  (± 2nπ) x=cos() x y
  • 43.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x (1,0) (x , y)  (± 2nπ) x=cos() x y
  • 44.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x (1,0) (x , y)  (± 2nπ) x=cos() * tan() is the slope of the dial. x y
  • 45.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x tan() (1,0) (x , y)  (± 2nπ) x=cos() x y * tan() is the slope of the dial. It is called “tangent” because tan() is the “length” of the tangent line x = 1, from (1, 0) to the extended dial as shown.
  • 46.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x tan() (1,0) cot() (x , y)  (± 2nπ) x=cos() x y * tan() is the slope of the dial. It is called “tangent” because tan() is the “length” of the tangent line x = 1, from (1, 0) to the extended dial as shown. Cot() is defined similarly using the horizontal tangent y = 1.
  • 47.
    Definition of TrigonometricFunctions Given an angle  in the standard position, let (x , y) be the coordinate of the tip of the dial on the unit circle. We define cos() = x sin() = y tan() = cot() = y x tan() (1,0) cot() (x , y)  (± 2nπ) x=cos() x y * tan() is the slope of the dial. It is called “tangent” because tan() is the “length” of the tangent line x = 1, from (1, 0) to the extended dial as shown. Cot() is defined similarly using the horizontal tangent y = 1. * sin(–) = –sin() cos(–) = cos()
  • 48.
    Angular Measurements Theimportant positions on this unit circle, the ones that we may extract with the 30–60 and 45–45 right triangle templates are shown below. 1 1/2 √3/2 ≈ 0.85 1 √2/2 √2/2 ≈ 0.70 π /6 π /3 π /4 π /4
  • 49.
    Analytic Trigonometry Trig–valuesare extracted from the unit circle so they satisfy many algebraic relations inherited from the equation x2 + y2 = 1 of the unit circle.
  • 50.
    Analytic Trigonometry Trig–valuesare extracted from the unit circle so they satisfy many algebraic relations inherited from the equation x2 + y2 = 1 of the unit circle. With a given angle , replace x = cos(), y = sin(), we have the trig–identity cos2() + sin2() = 1
  • 51.
    Analytic Trigonometry Trig–valuesare extracted from the unit circle so they satisfy many algebraic relations inherited from the equation x2 + y2 = 1 of the unit circle. With a given angle , replace x = cos(), y = sin(), we have the trig–identity cos2() + sin2() = 1 Just as the equation x2 + y2 = 1 may be written in multiple forms such as 1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2
  • 52.
    Analytic Trigonometry Trig–valuesare extracted from the unit circle so they satisfy many algebraic relations inherited from the equation x2 + y2 = 1 of the unit circle. With a given angle , replace x = cos(), y = sin(), we have the trig–identity cos2() + sin2() = 1 Just as the equation x2 + y2 = 1 may be written in multiple forms such as 1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2 we have correspondingly three forms of square– sum–identities.
  • 53.
    Analytic Trigonometry Trig–valuesare extracted from the unit circle so they satisfy many algebraic relations inherited from the equation x2 + y2 = 1 of the unit circle. With a given angle , replace x = cos(), y = sin(), we have the trig–identity cos2() + sin2() = 1 Just as the equation x2 + y2 = 1 may be written in multiple forms such as 1 + y2/x2 = 1/x2 or x2/y2 + 1= 1/y2 we have correspondingly three forms of square– sum–identities. These square–sum formulas, the reciprocal and divisional relations, are summarized by the Trig– Wheel given below and these identities are called the basic–trig–identities.
  • 54.
  • 55.
    Analytic Trigonometry TheTrig-Wheel the regular-side the co-side
  • 56.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel
  • 57.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel I II III
  • 58.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel I II III Following are some important divisional relations. tan(A) = sin(A)/cos(A)
  • 59.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel I II III Following are some important divisional relations. tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A)
  • 60.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel I II III or go straight through the center then I = 1 / III, i.e. two formulas on opposite ends are reciprocals. Following are some important divisional relations. tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A)
  • 61.
    Analytic Trigonometry TheDivision and Reciprocal Relations Start from any function, go around the rim, then I = II / III or I * III = II The Trig-Wheel I II III or go straight through the center then I = 1 / III, i.e. two formulas on opposite ends are reciprocals. Following are some important divisional relations. tan(A) = sin(A)/cos(A) cot(A) = cos(A)/sin(A) csc(A) = 1/sin(A) sec(A) = 1/cos(A) cot(A) = 1/tan(A)
  • 62.
    Analytic Trigonometry TheTrig-Wheel Square-Sum Relations For each of the three inverted triangles in the wheel, the sum of the squares of the top two functions is the square of the bottom function.
  • 63.
    Analytic Trigonometry TheTrig-Wheel Square-Sum Relations For each of the three inverted triangles in the wheel, the sum of the squares of the top two functions is the square of the bottom function. sin2(A) + cos2(A)=1 tan2(A) + 1 = sec2(A) 1 + cot2(A) = csc2(A)
  • 64.
    Analytic Trigonometry TheTrig-Wheel Square-Sum Relations For each of the three inverted triangles in the wheel, the sum of the squares of the top two functions is the square of the bottom function. sin2(A) + cos2(A)=1 tan2(A) + 1 = sec2(A) 1 + cot2(A) = csc2(A) Sum & Difference of Angle Formulas Let A and B be angles then C(A±B) = C(A)C(B) + – S(A)S(B) S(A±B) = S(A)C(B) ± S(B)C(A) where S(x) = sin(x) and C(x) = cos(x).
  • 65.
    Analytic Trigonometry Thefollowing are consequences of the sum and difference formulas. Double-Angle Formulas S(2A) = 2S(A)C(A) C(2A) = C2(A) – S2(A) = 2C2(A) – 1 = 1 – 2S2(A) Half-Angle Formulas 1 + C(B) 2 B 2 C( ) = ± 1 – C(B) 2 B 2 S( ) = ± From the C(2A) formulas we have the following. S2(A) = 1 – C(2A) 2 C2(A) = 1 + C(2A) 2 HW. Derive all the formulas on this page from the Sum and Difference Formula.