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Limits I
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)).
(x, f(x))
x
y = x2–2x+2
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)).
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)).
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)). We obtained the
cord–slope–formula 2x – 2 + h.
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
slope = 2x–2+h
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)). We obtained the
cord–slope–formula 2x – 2 + h.
We reason that as the values of
h shrinks to 0,
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
slope = 2x–2+h
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)). We obtained the
cord–slope–formula 2x – 2 + h.
We reason that as the values of
h shrinks to 0, the cords slide
towards the tangent line
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
slope = 2x–2+h
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)). We obtained the
cord–slope–formula 2x – 2 + h.
We reason that as the values of
h shrinks to 0, the cords slide
towards the tangent line so the
slope at (x, f(x)) must be 2x – 2
because h “fades” to 0.
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
slope = 2x–2+h
Limits I
In the calculation of the
derivative of f(x) = x2 – 2x + 2,
we simplified the slope
(difference-quotient) formula of
the cords with one end fixed at
(x, f(x)) and the other end at
(x+h, f(x+h)). We obtained the
cord–slope–formula 2x – 2 + h.
We reason that as the values of
h shrinks to 0, the cords slide
towards the tangent line so the
slope at (x, f(x)) must be 2x – 2
because h “shrinks” to 0.
(x+h, f(x+h)
(x, f(x))
x x + h
f(x+h)–f(x)
h
y = x2–2x+2
slope = 2x–2+h
clarify this procedure of obtaining slopes .
We use the language of “limits” to
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
Limits I
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
Limits I
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
Limits I
0 x’s
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
Limits I
0 x’s
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
Limits I
0 x’s
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
Limits I
0 x’s
ϵ
for any ϵ > 0
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
Limits I
0 x’s
ϵ
only finitely x’s are outside
for any ϵ > 0
The point here is that no matter
how small the interval (0, ϵ) is,
most of the x’s are in (0, ϵ).
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
Limits I
0 x’s
ϵ
only finitely x’s are outside
for any ϵ > 0
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
We say “as x goes to 0+ we get that …” we mean that
for “every sequence {xi} where xi 0+ we would obtain
the result mentioned”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
0 x’s
ϵ
only finitely x’s are outside
for any ϵ > 0
Limits I
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the right” or “xi 0+” where i = 1, 2, 3…
Let’s clarify the notion of
“x approaches 0 from the + (right) side”.
We say “as x goes to 0+ we get that …” we mean that
for “every sequence {xi} where xi 0+ we would obtain
the result mentioned”. So “as x 0+, |x| / x 1”
means that for any sequence xi 0+ we get |x| / x 1.
We write this as lim |x| / x = 1 or lim |x| / x = 1.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (0, ϵ)”.
0+
0 x’s
ϵ
only finitely x’s are outside
for any ϵ > 0
Limits I
x 0+
Similarly we define
“x approaches 0 from the – (left) side”.
Limits I
Similarly we define
“x approaches 0 from the – (left) side”.
Limits I
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
Similarly we define
“x approaches 0 from the – (left) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ,0)”.
only finitely x’s are outside for any ϵ > 0
Limits I
0
x’s –ϵ
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
Similarly we define
“x approaches 0 from the – (left) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ,0)”.
only finitely x’s are outside for any ϵ > 0
Limits I
0
x’s –ϵ
We say “as x goes to 0– we get that …” we mean that
for “every sequence {xi} where xi 0– we would obtain
the result mentioned”.
We say the sequence {xi} = {x1, x2, x3, ..}
“goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
Similarly we define
“x approaches 0 from the – (left) side”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ,0)”.
only finitely x’s are outside for any ϵ > 0
Limits I
0
x’s –ϵ
We say “as x goes to 0– we get that …” we mean that
for “every sequence {xi} where xi 0– we would obtain
the result mentioned”. So “as x 0–, |x| / x –1”
means that for any sequence xi 0– we’ve |x| / x –1.
We write this as lim |x| / x = –1 or lim |x| / x = –1.
0–
x 0–
Finally we say that
“xi goes to 0” or “xi 0” where i = 1, 2, 3…
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ, ϵ)”.
Limits I
Finally we say that
“xi goes to 0” or “xi 0” where i = 1, 2, 3…
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ, ϵ)”.
0
x’s –ϵ
only finitely many x’s are outside
x’s
ϵ
Limits I
Finally we say that
“xi goes to 0” or “xi 0” where i = 1, 2, 3…
We say “as x goes to 0 we get that …” we mean that
for “every sequence {xi} where xi 0 we obtain the
result mentioned”.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ, ϵ)”.
0
x’s –ϵ
only finitely many x’s are outside
x’s
ϵ
Limits I
Finally we say that
“xi goes to 0” or “xi 0” where i = 1, 2, 3…
We say “as x goes to 0 we get that …” we mean that
for “every sequence {xi} where xi 0 we obtain the
result mentioned”.
Hence lim |x| / x is undefined because its signs
are erratic if the signs of the x’s are erratic.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ, ϵ)”.
0
x’s –ϵ
only finitely many x’s are outside
x’s
ϵ
0
Limits I
Finally we say that
“xi goes to 0” or “xi 0” where i = 1, 2, 3…
We say “as x goes to 0 we get that …” we mean that
for “every sequence {xi} where xi 0 we obtain the
result mentioned”.
Hence lim |x| / x is undefined because its signs
are erratic if the signs of the x’s are erratic.
The direction of the x’s approaching 0 is important.
“if for any number ϵ > 0 only finitely many of the x’s
are outside of the neighborhood (–ϵ, ϵ)”.
0
x’s –ϵ
only finitely many x’s are outside
x’s
ϵ
0
Limits I
Keep in mind the following examples:
x’s
Limits I
lim |x| / x = 1
0 x–> 0+
lim |x| / x = –1
x–> 0–
x’s
0
lim |x| / x = UDF
x–> 0+
0
x’s
x’s
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
Limits I
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
Limits I
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
Limits I
The notation “xi a–” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a )."
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
a
x’s a–ϵ
Limits I
The notation “xi a–” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a )."
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
a
x’s a–ϵ
Limits I
The notation “xi a–” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a )."
The notation “xi a” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a + ϵ ).”
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
a
x’s a–ϵ
Limits I
The notation “xi a–” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a )."
The notation “xi a” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a + ϵ ).”
a
x’s a–ϵ a+ϵ x’s
The notation “xi a+” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a, a + ϵ )."
a x’s
a+ϵ
a
x’s a–ϵ
Limits I
The notation “xi a–” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a )."
The notation “xi a” where {xi} is a sequence of
numbers means that “for every ϵ > 0, only finitely
many x’s are outside of the interval (a – ϵ, a + ϵ ).”
a
x’s a–ϵ a+ϵ x’s
We say lim f(x) = L if f(xi) L for every xi a (or a±).
a (or a±)
Limits I
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
The following limits are obvious.
Limits I
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
The following limits are obvious.
* lim c = c where c is any constant.
x→a
(e.g lim 5 = 5)
Limits I
x→ a
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
The following limits are obvious.
* lim c = c where c is any constant.
x→a
* lim x = a
(e.g lim 5 = 5)
(e.g. lim x = 5)
Limits I
x→ a
x→ a x→ 5
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
The following limits are obvious.
* lim c = c where c is any constant.
x→a
* lim x = a
* lim cx = ca where c is any number.
(e.g lim 5 = 5)
(e.g. lim x = 5)
(e.g. lim 3x = 15)
Limits I
x→ a
x→ a
x→ a
x→ 5
x→ 5
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
* lim (xp) = (lim x)p = ap provided ap is well defined.
The following limits are obvious.
* lim c = c where c is any constant.
x→a
* lim x = a
* lim cx = ca where c is any number.
(e.g lim 5 = 5)
(e.g. lim x = 5)
(e.g. lim x½ = 5)
(e.g. lim 3x = 15)
Limits I
x→ a
x→ a
x→ a
x→ a
x→ 5
x→ 5
x→ a
x→ 25
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
* lim (xp) = (lim x)p = ap provided ap is well defined.
The following limits are obvious.
* lim c = c where c is any constant.
x→a
* lim x = a
* lim cx = ca where c is any number.
(e.g lim 5 = 5)
(e.g. lim x = 5)
(e.g. lim x½ = 5)
(e.g. lim 3x = 15)
* The same statements hold true for x a±.
Limits I
x→ a
x→ a
x→ a
x→ a
x→ 5
x→ 5
x→ a
x→ 25
Rules on limits: Given that all the limits exist as x a,
a. lim f(x) ± g(x) = lim f(x) ± lim g(x)
b. lim f(x)*g(x) = lim f(x)*lim g(x)
c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
Let P(x) and Q(x) be polynomials.
Limits of Polynomial and Rational Formulas I
Limits I
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
Limits I
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0.
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x),
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x), then
lim f(x) = f(a) as x a or x a±,
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x), then
lim f(x) = f(a) as x a or x a±,
provided the selections of such x’s are possible.
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x), then
lim f(x) = f(a) as x a or x a±,
provided the selections of such x’s are possible.
For example, the domain of the function f(x) = √x is
0 < x.
–
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x), then
lim f(x) = f(a) as x a or x a±,
provided the selections of such x’s are possible.
For example, the domain of the function f(x) = √x is
0 < x. Hence lim√x = √a for 0 < a.
– a
Limits I
a
Let P(x) and Q(x) be polynomials.
1. lim P(x) = P(a)
a
Limits of Polynomial and Rational Formulas I
2. lim =
P(x)
Q(x)
P(a)
Q(a)
, Q(a) = 0. (e.g. lim x + 2
x – 3
1
= –3/2)
In fact, if f(x) is an elementary function and f(a) is
well defined, i.e. a is in the domain of f(x), then
lim f(x) = f(a) as x a or x a±,
provided the selections of such x’s are possible.
For example, the domain of the function f(x) = √x is
0 < x. Hence lim√x = √a for 0 < a.
– a
However at a = 0, we could only
have lim √x = 0 = f(0) as shown.
y = x1/2
0+
(but not 0)
Limits I
a
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”.
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”. The domain of
the 1/x is the set of all numbers x except x = 0.
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”. The domain of
the 1/x is the set of all numbers x except x = 0.
Although we can’t evaluate 1/x with x = 0, we still
know the behavior of f(x) as x takes on small values
that are close to 0 as demonstrated in the table
below.
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”. The domain of
the 1/x is the set of all numbers x except x = 0.
Although we can’t evaluate 1/x with x = 0, we still
know the behavior of f(x) as x takes on small values
that are close to 0 as demonstrated in the table
below.
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 ?
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”. The domain of
the 1/x is the set of all numbers x except x = 0.
Although we can’t evaluate 1/x with x = 0, we still
know the behavior of f(x) as x takes on small values
that are close to 0 as demonstrated in the table
below.
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 ?
From the table we see that the corresponding 1/x
expands unboundedly to ∞.
Approaching ∞
Limits I
Let’s use the function f(x) = 1/x as an example for
defining the phrase “approaching ∞”. The domain of
the 1/x is the set of all numbers x except x = 0.
Although we can’t evaluate 1/x with x = 0, we still
know the behavior of f(x) as x takes on small values
that are close to 0 as demonstrated in the table
below.
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 ?
From the table we see that the corresponding 1/x
expands unboundedly to ∞. Let’s make “expands
unboundedly to ∞” more precise.
Approaching ∞
Limits I
A set of infinitely many numbers S = {x’s} is said to be
bounded above if there is a number R such that x < R
for all the numbers x in the set S.
Limits I
A set of infinitely many numbers S = {x’s} is said to be
bounded above if there is a number R such that x < R
for all the numbers x in the set S. The “R” stands for
“to the right” as shown.
R
x’s
Limits I
A set of infinitely many numbers S = {x’s} is said to be
bounded above if there is a number R such that x < R
for all the numbers x in the set S. The “R” stands for
“to the right” as shown.
A set of numbers S = {x’s} is said to be
bounded below if there is a number L such that L < x
for all the x in the set.
R
x’s
Limits I
A set of infinitely many numbers S = {x’s} is said to be
bounded above if there is a number R such that x < R
for all the numbers x in the set S. The “R” stands for
“to the right” as shown.
A set of numbers S = {x’s} is said to be
bounded below if there is a number L such that L < x
for all the x in the set. The “L” stands for “to the left”
as shown.
R
x’s
L x’s
Limits I
A set of infinitely many numbers S = {x’s} is said to be
bounded above if there is a number R such that x < R
for all the numbers x in the set S. The “R” stands for
“to the right” as shown.
A set of numbers S = {x’s} is said to be
bounded below if there is a number L such that L < x
for all the x in the set. The “L” stands for “to the left”
as shown.
R
x’s
L x’s
A set of numbers S = {x’s} is bounded if it’s bounded
above and below.
R
x’s
L
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x.
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x. However the list is not
bounded above.
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x. However the list is not
bounded above.
This list has the following property.
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x. However the list is not
bounded above.
This list has the following property.
For any large number G we select, there are only
finitely many entries that are smaller than G.
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x. However the list is not
bounded above.
This list has the following property.
For any large number G we select, there are only
finitely many entries that are smaller than G.
For example, if G = 10100 then only entries to the left
of the 100th entry are less than G.
Limits I
x 0.1 0.01 0.001 0.0001 0+
f(x) = 1/x 10 100 1,000 10,000 …
The 1/x–values on the list is bounded below – a
lower bound L = 0 < 1/x. However the list is not
bounded above.
This list has the following property.
For any large number G we select, there are only
finitely many entries that are smaller than G.
For example, if G = 10100 then only entries to the left
of the 100th entry are less than G.
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
only these entries are < 10100
Limits I
In the language of limits, we say that
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
lim 1/x = ∞
0+
Limits I
In the language of limits, we say that
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
lim 1/x = ∞
and it is read as “the limit of 1/x, as x goes to 0+ is ∞”.
0+
Limits I
In the language of limits, we say that
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
lim 1/x = ∞
and it is read as “the limit of 1/x, as x goes to 0+ is ∞”.
In a similar fashion we have that
“the limit of 1/x, as x goes to 0– is –∞” as
lim 1/x = –∞
0–
0+
Limits I
In the language of limits, we say that
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
lim 1/x = ∞
and it is read as “the limit of 1/x, as x goes to 0+ is ∞”.
In a similar fashion we have that
“the limit of 1/x, as x goes to 0– is –∞” as
lim 1/x = –∞
0–
0+
However lim 1/x is undefined (UDF) because the
signs of 1/x is unknown so no general conclusion
may be made except that |1/x| ∞.
0
Limits I
In the language of limits, we say that
x 0.1 0.01 0.001 0.0001 … 100th entry …
f(x) = 1/x 10 100 1,000 10,000
… G = 10100
< all entries
lim 1/x = ∞
and it is read as “the limit of 1/x, as x goes to 0+ is ∞”.
In a similar fashion we have that
“the limit of 1/x, as x goes to 0– is –∞” as
lim 1/x = –∞
0–
0+
However lim 1/x is undefined (UDF) because the
signs of 1/x is unknown so no general conclusion
may be made except that |1/x| ∞. The behavior of
1/x may fluctuate wildly depending on the selections
of the x’s.
0
Limits I
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L,
Limits I
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
Limits I
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0.
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
“boundary behaviors” of 1/x.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
0+
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
Similarly we say that “as x ∞, f(x) L” if for every
sequence xi ∞ we have that f(xi) L, and we also
lim 1/x = lim 1/x = 0. Let’s summarize the
∞
Limits I
Hence
say that “as x –∞, f(x) L” if for every sequence
xi –∞ we have that f(xi) L.
–∞
As x 0–, lim 1/x = –∞
0+
0–
As x ∞, lim 1/x = 0+
∞
As x –∞, lim 1/x = 0–
–∞
As x 0+, lim 1/x = ∞
“boundary behaviors” of 1/x. The domain of 1/x is
x = 0 so its “boundary” consists of the following.
I. The vertical asymptote x = 0.
II. The two “ends” of the line. y = 1/x
x= 0: Vertical
Asymptote
y = 0: Horizontal
Asymptote
Arithmetic of ∞
Limits I
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers. Hence we say that
“the sequence 1, 2, 3, .. goes to ∞” or that “the
sequence –1, –2, –3, .. goes to –∞”.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers. Hence we say that
“the sequence 1, 2, 3, .. goes to ∞” or that “the
sequence –1, –2, –3, .. goes to –∞”.
If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,..
the resulting sequence still goes to ∞.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers. Hence we say that
“the sequence 1, 2, 3, .. goes to ∞” or that “the
sequence –1, –2, –3, .. goes to –∞”.
If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,..
the resulting sequence still goes to ∞.
In fact, given any sequence of xi such that xi ∞,
then cxi ∞ for any 0 < c.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers. Hence we say that
“the sequence 1, 2, 3, .. goes to ∞” or that “the
sequence –1, –2, –3, .. goes to –∞”.
If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,..
the resulting sequence still goes to ∞.
In fact, given any sequence of xi such that xi ∞,
then cxi ∞ for any 0 < c. In short, we say that
c* ∞ = ∞ for any constant c > 0.
Arithmetic of ∞
Limits I
The symbol “∞” is not a number because it does not
represent a numerical measurement. It represents the
behavior of a list of endless numbers, specifically
eventually “almost all” of the numbers are larger than
any imaginable numbers. Hence we say that
“the sequence 1, 2, 3, .. goes to ∞” or that “the
sequence –1, –2, –3, .. goes to –∞”.
If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,..
the resulting sequence still goes to ∞.
In fact, given any sequence of xi such that xi ∞,
then cxi ∞ for any 0 < c. In short, we say that
c* ∞ = ∞ for any constant c > 0.
We summarize these facts about ∞ below.
Arithmetic of ∞
Limits I
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞.
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
so lim (x * x2) = lim x * lim x2 = ∞.
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
so lim (x * x2) = lim x * lim x2 = ∞. (Not true for “/“.)
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
so lim (x * x2) = lim x * lim x2 = ∞.
As x goes to ∞, lim x = ∞, so lim 3x = ∞.
(Not true for “/“.)
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
so lim (x * x2) = lim x * lim x2 = ∞.
As x goes to ∞, lim x = ∞, so lim 3x = ∞.
As x goes to ∞, lim x = ∞, so lim 3/x = 0.
(Not true for “/“.)
Arithmetic of ∞
Limits I
1. ∞ + ∞ = ∞
As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence
lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.)
2. ∞ * ∞ = ∞
3. c * ∞ = ∞ for any constant c > 0.
5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1
4. c / ∞ = 0 for any constant c.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
so lim (x * x2) = lim x * lim x2 = ∞.
As x goes to ∞, lim x = ∞, so lim 3x = ∞.
As x goes to ∞, lim x = ∞, so lim 3/x = 0.
As x goes to ∞, lim 2x = ∞ and lim (½)x = 0.
(Not true for “/“.)
Limits I
The following situations of limits are inconclusive.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x / x2 = 0,
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x / x2 = 0, lim x/x = 1,
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
Again, all these questions are in the form ∞/∞
but have different behaviors as x ∞.
Limits I
1. ∞ – ∞ = ? (inconclusive form)
The following situations of limits are inconclusive.
2. ∞ / ∞ = ? (inconclusive form)
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞.
As x goes to ∞, lim x = ∞ and lim x2 = ∞,
but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
Both questions are in the form of ∞ – ∞ yet they
have drastically different behaviors as x ∞.
We have to find other ways to determine the
limiting behaviors when a problem is in the
inconclusive ∞ – ∞ and ∞ / ∞ form.
Again, all these questions are in the form ∞/∞
but have different behaviors as x ∞.
Limits I
For example the is of the ∞ / ∞ form
as x ∞, therefore we will have to transform the
formula to determine its behavior.
3x + 4
5x + 6
Limits I
For example the is of the ∞ / ∞ form
as x ∞, therefore we will have to transform the
formula to determine its behavior.
3x + 4
5x + 6
3x + 4
5x + 6
lim = 3/5.
∞
We will talk about various methods in the next
section in determining the limits of formulas with
inconclusive forms and see that
(Take out the calculator and try to find it.)

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x2.1Limits I.pptx

  • 2. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). (x, f(x)) x y = x2–2x+2
  • 3. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2
  • 4. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2
  • 5. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). We obtained the cord–slope–formula 2x – 2 + h. (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2 slope = 2x–2+h
  • 6. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). We obtained the cord–slope–formula 2x – 2 + h. We reason that as the values of h shrinks to 0, (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2 slope = 2x–2+h
  • 7. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). We obtained the cord–slope–formula 2x – 2 + h. We reason that as the values of h shrinks to 0, the cords slide towards the tangent line (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2 slope = 2x–2+h
  • 8. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). We obtained the cord–slope–formula 2x – 2 + h. We reason that as the values of h shrinks to 0, the cords slide towards the tangent line so the slope at (x, f(x)) must be 2x – 2 because h “fades” to 0. (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2 slope = 2x–2+h
  • 9. Limits I In the calculation of the derivative of f(x) = x2 – 2x + 2, we simplified the slope (difference-quotient) formula of the cords with one end fixed at (x, f(x)) and the other end at (x+h, f(x+h)). We obtained the cord–slope–formula 2x – 2 + h. We reason that as the values of h shrinks to 0, the cords slide towards the tangent line so the slope at (x, f(x)) must be 2x – 2 because h “shrinks” to 0. (x+h, f(x+h) (x, f(x)) x x + h f(x+h)–f(x) h y = x2–2x+2 slope = 2x–2+h clarify this procedure of obtaining slopes . We use the language of “limits” to
  • 10. Let’s clarify the notion of “x approaches 0 from the + (right) side”. Limits I
  • 11. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. Limits I
  • 12. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. Limits I 0 x’s
  • 13. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. Limits I 0 x’s
  • 14. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. Limits I 0 x’s
  • 15. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. Limits I 0 x’s ϵ for any ϵ > 0
  • 16. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. Limits I 0 x’s ϵ only finitely x’s are outside for any ϵ > 0
  • 17. The point here is that no matter how small the interval (0, ϵ) is, most of the x’s are in (0, ϵ). We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. Limits I 0 x’s ϵ only finitely x’s are outside for any ϵ > 0
  • 18. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. We say “as x goes to 0+ we get that …” we mean that for “every sequence {xi} where xi 0+ we would obtain the result mentioned”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. 0 x’s ϵ only finitely x’s are outside for any ϵ > 0 Limits I
  • 19. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the right” or “xi 0+” where i = 1, 2, 3… Let’s clarify the notion of “x approaches 0 from the + (right) side”. We say “as x goes to 0+ we get that …” we mean that for “every sequence {xi} where xi 0+ we would obtain the result mentioned”. So “as x 0+, |x| / x 1” means that for any sequence xi 0+ we get |x| / x 1. We write this as lim |x| / x = 1 or lim |x| / x = 1. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (0, ϵ)”. 0+ 0 x’s ϵ only finitely x’s are outside for any ϵ > 0 Limits I x 0+
  • 20. Similarly we define “x approaches 0 from the – (left) side”. Limits I
  • 21. Similarly we define “x approaches 0 from the – (left) side”. Limits I We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
  • 22. Similarly we define “x approaches 0 from the – (left) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ,0)”. only finitely x’s are outside for any ϵ > 0 Limits I 0 x’s –ϵ We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the left” or “xi 0–” where i = 1, 2, 3…
  • 23. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the left” or “xi 0–” where i = 1, 2, 3… Similarly we define “x approaches 0 from the – (left) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ,0)”. only finitely x’s are outside for any ϵ > 0 Limits I 0 x’s –ϵ We say “as x goes to 0– we get that …” we mean that for “every sequence {xi} where xi 0– we would obtain the result mentioned”.
  • 24. We say the sequence {xi} = {x1, x2, x3, ..} “goes to 0 from the left” or “xi 0–” where i = 1, 2, 3… Similarly we define “x approaches 0 from the – (left) side”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ,0)”. only finitely x’s are outside for any ϵ > 0 Limits I 0 x’s –ϵ We say “as x goes to 0– we get that …” we mean that for “every sequence {xi} where xi 0– we would obtain the result mentioned”. So “as x 0–, |x| / x –1” means that for any sequence xi 0– we’ve |x| / x –1. We write this as lim |x| / x = –1 or lim |x| / x = –1. 0– x 0–
  • 25. Finally we say that “xi goes to 0” or “xi 0” where i = 1, 2, 3… “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ, ϵ)”. Limits I
  • 26. Finally we say that “xi goes to 0” or “xi 0” where i = 1, 2, 3… “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ, ϵ)”. 0 x’s –ϵ only finitely many x’s are outside x’s ϵ Limits I
  • 27. Finally we say that “xi goes to 0” or “xi 0” where i = 1, 2, 3… We say “as x goes to 0 we get that …” we mean that for “every sequence {xi} where xi 0 we obtain the result mentioned”. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ, ϵ)”. 0 x’s –ϵ only finitely many x’s are outside x’s ϵ Limits I
  • 28. Finally we say that “xi goes to 0” or “xi 0” where i = 1, 2, 3… We say “as x goes to 0 we get that …” we mean that for “every sequence {xi} where xi 0 we obtain the result mentioned”. Hence lim |x| / x is undefined because its signs are erratic if the signs of the x’s are erratic. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ, ϵ)”. 0 x’s –ϵ only finitely many x’s are outside x’s ϵ 0 Limits I
  • 29. Finally we say that “xi goes to 0” or “xi 0” where i = 1, 2, 3… We say “as x goes to 0 we get that …” we mean that for “every sequence {xi} where xi 0 we obtain the result mentioned”. Hence lim |x| / x is undefined because its signs are erratic if the signs of the x’s are erratic. The direction of the x’s approaching 0 is important. “if for any number ϵ > 0 only finitely many of the x’s are outside of the neighborhood (–ϵ, ϵ)”. 0 x’s –ϵ only finitely many x’s are outside x’s ϵ 0 Limits I
  • 30. Keep in mind the following examples: x’s Limits I lim |x| / x = 1 0 x–> 0+ lim |x| / x = –1 x–> 0– x’s 0 lim |x| / x = UDF x–> 0+ 0 x’s x’s
  • 31. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." Limits I
  • 32. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ Limits I
  • 33. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ Limits I The notation “xi a–” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a )."
  • 34. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ a x’s a–ϵ Limits I The notation “xi a–” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a )."
  • 35. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ a x’s a–ϵ Limits I The notation “xi a–” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a )." The notation “xi a” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a + ϵ ).”
  • 36. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ a x’s a–ϵ Limits I The notation “xi a–” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a )." The notation “xi a” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a + ϵ ).” a x’s a–ϵ a+ϵ x’s
  • 37. The notation “xi a+” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a, a + ϵ )." a x’s a+ϵ a x’s a–ϵ Limits I The notation “xi a–” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a )." The notation “xi a” where {xi} is a sequence of numbers means that “for every ϵ > 0, only finitely many x’s are outside of the interval (a – ϵ, a + ϵ ).” a x’s a–ϵ a+ϵ x’s We say lim f(x) = L if f(xi) L for every xi a (or a±). a (or a±)
  • 38. Limits I Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 39. The following limits are obvious. Limits I Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 40. The following limits are obvious. * lim c = c where c is any constant. x→a (e.g lim 5 = 5) Limits I x→ a Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 41. The following limits are obvious. * lim c = c where c is any constant. x→a * lim x = a (e.g lim 5 = 5) (e.g. lim x = 5) Limits I x→ a x→ a x→ 5 Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 42. The following limits are obvious. * lim c = c where c is any constant. x→a * lim x = a * lim cx = ca where c is any number. (e.g lim 5 = 5) (e.g. lim x = 5) (e.g. lim 3x = 15) Limits I x→ a x→ a x→ a x→ 5 x→ 5 Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 43. * lim (xp) = (lim x)p = ap provided ap is well defined. The following limits are obvious. * lim c = c where c is any constant. x→a * lim x = a * lim cx = ca where c is any number. (e.g lim 5 = 5) (e.g. lim x = 5) (e.g. lim x½ = 5) (e.g. lim 3x = 15) Limits I x→ a x→ a x→ a x→ a x→ 5 x→ 5 x→ a x→ 25 Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 44. * lim (xp) = (lim x)p = ap provided ap is well defined. The following limits are obvious. * lim c = c where c is any constant. x→a * lim x = a * lim cx = ca where c is any number. (e.g lim 5 = 5) (e.g. lim x = 5) (e.g. lim x½ = 5) (e.g. lim 3x = 15) * The same statements hold true for x a±. Limits I x→ a x→ a x→ a x→ a x→ 5 x→ 5 x→ a x→ 25 Rules on limits: Given that all the limits exist as x a, a. lim f(x) ± g(x) = lim f(x) ± lim g(x) b. lim f(x)*g(x) = lim f(x)*lim g(x) c. lim f(x)/g(x) = lim f(x)/lim g(x) (lim g(x) ≠ 0)
  • 45. Let P(x) and Q(x) be polynomials. Limits of Polynomial and Rational Formulas I Limits I
  • 46. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I Limits I
  • 47. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. Limits I a
  • 48. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) Limits I a
  • 49. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), Limits I a
  • 50. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), then lim f(x) = f(a) as x a or x a±, Limits I a
  • 51. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), then lim f(x) = f(a) as x a or x a±, provided the selections of such x’s are possible. Limits I a
  • 52. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), then lim f(x) = f(a) as x a or x a±, provided the selections of such x’s are possible. For example, the domain of the function f(x) = √x is 0 < x. – Limits I a
  • 53. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), then lim f(x) = f(a) as x a or x a±, provided the selections of such x’s are possible. For example, the domain of the function f(x) = √x is 0 < x. Hence lim√x = √a for 0 < a. – a Limits I a
  • 54. Let P(x) and Q(x) be polynomials. 1. lim P(x) = P(a) a Limits of Polynomial and Rational Formulas I 2. lim = P(x) Q(x) P(a) Q(a) , Q(a) = 0. (e.g. lim x + 2 x – 3 1 = –3/2) In fact, if f(x) is an elementary function and f(a) is well defined, i.e. a is in the domain of f(x), then lim f(x) = f(a) as x a or x a±, provided the selections of such x’s are possible. For example, the domain of the function f(x) = √x is 0 < x. Hence lim√x = √a for 0 < a. – a However at a = 0, we could only have lim √x = 0 = f(0) as shown. y = x1/2 0+ (but not 0) Limits I a
  • 56. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. Approaching ∞ Limits I
  • 57. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. The domain of the 1/x is the set of all numbers x except x = 0. Approaching ∞ Limits I
  • 58. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. The domain of the 1/x is the set of all numbers x except x = 0. Although we can’t evaluate 1/x with x = 0, we still know the behavior of f(x) as x takes on small values that are close to 0 as demonstrated in the table below. Approaching ∞ Limits I
  • 59. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. The domain of the 1/x is the set of all numbers x except x = 0. Although we can’t evaluate 1/x with x = 0, we still know the behavior of f(x) as x takes on small values that are close to 0 as demonstrated in the table below. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 ? Approaching ∞ Limits I
  • 60. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. The domain of the 1/x is the set of all numbers x except x = 0. Although we can’t evaluate 1/x with x = 0, we still know the behavior of f(x) as x takes on small values that are close to 0 as demonstrated in the table below. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 ? From the table we see that the corresponding 1/x expands unboundedly to ∞. Approaching ∞ Limits I
  • 61. Let’s use the function f(x) = 1/x as an example for defining the phrase “approaching ∞”. The domain of the 1/x is the set of all numbers x except x = 0. Although we can’t evaluate 1/x with x = 0, we still know the behavior of f(x) as x takes on small values that are close to 0 as demonstrated in the table below. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 ? From the table we see that the corresponding 1/x expands unboundedly to ∞. Let’s make “expands unboundedly to ∞” more precise. Approaching ∞ Limits I
  • 62. A set of infinitely many numbers S = {x’s} is said to be bounded above if there is a number R such that x < R for all the numbers x in the set S. Limits I
  • 63. A set of infinitely many numbers S = {x’s} is said to be bounded above if there is a number R such that x < R for all the numbers x in the set S. The “R” stands for “to the right” as shown. R x’s Limits I
  • 64. A set of infinitely many numbers S = {x’s} is said to be bounded above if there is a number R such that x < R for all the numbers x in the set S. The “R” stands for “to the right” as shown. A set of numbers S = {x’s} is said to be bounded below if there is a number L such that L < x for all the x in the set. R x’s Limits I
  • 65. A set of infinitely many numbers S = {x’s} is said to be bounded above if there is a number R such that x < R for all the numbers x in the set S. The “R” stands for “to the right” as shown. A set of numbers S = {x’s} is said to be bounded below if there is a number L such that L < x for all the x in the set. The “L” stands for “to the left” as shown. R x’s L x’s Limits I
  • 66. A set of infinitely many numbers S = {x’s} is said to be bounded above if there is a number R such that x < R for all the numbers x in the set S. The “R” stands for “to the right” as shown. A set of numbers S = {x’s} is said to be bounded below if there is a number L such that L < x for all the x in the set. The “L” stands for “to the left” as shown. R x’s L x’s A set of numbers S = {x’s} is bounded if it’s bounded above and below. R x’s L Limits I
  • 67. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. Limits I
  • 68. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. However the list is not bounded above. Limits I
  • 69. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. However the list is not bounded above. This list has the following property. Limits I
  • 70. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. However the list is not bounded above. This list has the following property. For any large number G we select, there are only finitely many entries that are smaller than G. Limits I
  • 71. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. However the list is not bounded above. This list has the following property. For any large number G we select, there are only finitely many entries that are smaller than G. For example, if G = 10100 then only entries to the left of the 100th entry are less than G. Limits I
  • 72. x 0.1 0.01 0.001 0.0001 0+ f(x) = 1/x 10 100 1,000 10,000 … The 1/x–values on the list is bounded below – a lower bound L = 0 < 1/x. However the list is not bounded above. This list has the following property. For any large number G we select, there are only finitely many entries that are smaller than G. For example, if G = 10100 then only entries to the left of the 100th entry are less than G. x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries only these entries are < 10100 Limits I
  • 73. In the language of limits, we say that x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries lim 1/x = ∞ 0+ Limits I
  • 74. In the language of limits, we say that x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries lim 1/x = ∞ and it is read as “the limit of 1/x, as x goes to 0+ is ∞”. 0+ Limits I
  • 75. In the language of limits, we say that x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries lim 1/x = ∞ and it is read as “the limit of 1/x, as x goes to 0+ is ∞”. In a similar fashion we have that “the limit of 1/x, as x goes to 0– is –∞” as lim 1/x = –∞ 0– 0+ Limits I
  • 76. In the language of limits, we say that x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries lim 1/x = ∞ and it is read as “the limit of 1/x, as x goes to 0+ is ∞”. In a similar fashion we have that “the limit of 1/x, as x goes to 0– is –∞” as lim 1/x = –∞ 0– 0+ However lim 1/x is undefined (UDF) because the signs of 1/x is unknown so no general conclusion may be made except that |1/x| ∞. 0 Limits I
  • 77. In the language of limits, we say that x 0.1 0.01 0.001 0.0001 … 100th entry … f(x) = 1/x 10 100 1,000 10,000 … G = 10100 < all entries lim 1/x = ∞ and it is read as “the limit of 1/x, as x goes to 0+ is ∞”. In a similar fashion we have that “the limit of 1/x, as x goes to 0– is –∞” as lim 1/x = –∞ 0– 0+ However lim 1/x is undefined (UDF) because the signs of 1/x is unknown so no general conclusion may be made except that |1/x| ∞. The behavior of 1/x may fluctuate wildly depending on the selections of the x’s. 0 Limits I
  • 78. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, Limits I
  • 79. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also Limits I say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L.
  • 80. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞
  • 81. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ “boundary behaviors” of 1/x.
  • 82. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following.
  • 83. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0.
  • 84. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ 0+ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0.
  • 85. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0.
  • 86. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. y = 1/x x= 0: Vertical Asymptote
  • 87. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. y = 1/x x= 0: Vertical Asymptote
  • 88. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. y = 1/x x= 0: Vertical Asymptote
  • 89. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. y = 1/x x= 0: Vertical Asymptote
  • 90. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. y = 1/x x= 0: Vertical Asymptote
  • 91. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote
  • 92. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote
  • 93. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote
  • 94. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote
  • 95. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote
  • 96. Similarly we say that “as x ∞, f(x) L” if for every sequence xi ∞ we have that f(xi) L, and we also lim 1/x = lim 1/x = 0. Let’s summarize the ∞ Limits I Hence say that “as x –∞, f(x) L” if for every sequence xi –∞ we have that f(xi) L. –∞ As x 0–, lim 1/x = –∞ 0+ 0– As x ∞, lim 1/x = 0+ ∞ As x –∞, lim 1/x = 0– –∞ As x 0+, lim 1/x = ∞ “boundary behaviors” of 1/x. The domain of 1/x is x = 0 so its “boundary” consists of the following. I. The vertical asymptote x = 0. II. The two “ends” of the line. y = 1/x x= 0: Vertical Asymptote y = 0: Horizontal Asymptote
  • 98. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement.
  • 99. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers.
  • 100. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers. Hence we say that “the sequence 1, 2, 3, .. goes to ∞” or that “the sequence –1, –2, –3, .. goes to –∞”.
  • 101. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers. Hence we say that “the sequence 1, 2, 3, .. goes to ∞” or that “the sequence –1, –2, –3, .. goes to –∞”. If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,.. the resulting sequence still goes to ∞.
  • 102. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers. Hence we say that “the sequence 1, 2, 3, .. goes to ∞” or that “the sequence –1, –2, –3, .. goes to –∞”. If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,.. the resulting sequence still goes to ∞. In fact, given any sequence of xi such that xi ∞, then cxi ∞ for any 0 < c.
  • 103. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers. Hence we say that “the sequence 1, 2, 3, .. goes to ∞” or that “the sequence –1, –2, –3, .. goes to –∞”. If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,.. the resulting sequence still goes to ∞. In fact, given any sequence of xi such that xi ∞, then cxi ∞ for any 0 < c. In short, we say that c* ∞ = ∞ for any constant c > 0.
  • 104. Arithmetic of ∞ Limits I The symbol “∞” is not a number because it does not represent a numerical measurement. It represents the behavior of a list of endless numbers, specifically eventually “almost all” of the numbers are larger than any imaginable numbers. Hence we say that “the sequence 1, 2, 3, .. goes to ∞” or that “the sequence –1, –2, –3, .. goes to –∞”. If we multiple 1, 2, 3 … by 2 so it becomes 2, 4, 6,.. the resulting sequence still goes to ∞. In fact, given any sequence of xi such that xi ∞, then cxi ∞ for any 0 < c. In short, we say that c* ∞ = ∞ for any constant c > 0. We summarize these facts about ∞ below.
  • 106. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c.
  • 107. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c.
  • 108. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c.
  • 109. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c. As x goes to ∞, lim x = ∞ and lim x2 = ∞, so lim (x * x2) = lim x * lim x2 = ∞.
  • 110. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c. As x goes to ∞, lim x = ∞ and lim x2 = ∞, so lim (x * x2) = lim x * lim x2 = ∞. (Not true for “/“.)
  • 111. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c. As x goes to ∞, lim x = ∞ and lim x2 = ∞, so lim (x * x2) = lim x * lim x2 = ∞. As x goes to ∞, lim x = ∞, so lim 3x = ∞. (Not true for “/“.)
  • 112. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c. As x goes to ∞, lim x = ∞ and lim x2 = ∞, so lim (x * x2) = lim x * lim x2 = ∞. As x goes to ∞, lim x = ∞, so lim 3x = ∞. As x goes to ∞, lim x = ∞, so lim 3/x = 0. (Not true for “/“.)
  • 113. Arithmetic of ∞ Limits I 1. ∞ + ∞ = ∞ As x goes to ∞, lim x = ∞ and lim x2 = ∞, hence lim (x + x2) = lim x + lim x2 = ∞. (Not true for “–“.) 2. ∞ * ∞ = ∞ 3. c * ∞ = ∞ for any constant c > 0. 5. Given a fixed b, b∞ = ∞ if b > 1, b∞ = 0 if 0 < b < 1 4. c / ∞ = 0 for any constant c. As x goes to ∞, lim x = ∞ and lim x2 = ∞, so lim (x * x2) = lim x * lim x2 = ∞. As x goes to ∞, lim x = ∞, so lim 3x = ∞. As x goes to ∞, lim x = ∞, so lim 3/x = 0. As x goes to ∞, lim 2x = ∞ and lim (½)x = 0. (Not true for “/“.)
  • 114. Limits I The following situations of limits are inconclusive.
  • 115. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive.
  • 116. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. As x goes to ∞, lim x = ∞ and lim x2 = ∞,
  • 117. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞.
  • 118. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 119. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 120. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 121. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x / x2 = 0, As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 122. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x / x2 = 0, lim x/x = 1, As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 123. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞. As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞.
  • 124. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞. As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞. Again, all these questions are in the form ∞/∞ but have different behaviors as x ∞.
  • 125. Limits I 1. ∞ – ∞ = ? (inconclusive form) The following situations of limits are inconclusive. 2. ∞ / ∞ = ? (inconclusive form) As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x / x2 = 0, lim x/x = 1, and lim x2/x = ∞. As x goes to ∞, lim x = ∞ and lim x2 = ∞, but lim x – x = lim 0 = 0, and lim x2 – x = ∞. Both questions are in the form of ∞ – ∞ yet they have drastically different behaviors as x ∞. We have to find other ways to determine the limiting behaviors when a problem is in the inconclusive ∞ – ∞ and ∞ / ∞ form. Again, all these questions are in the form ∞/∞ but have different behaviors as x ∞.
  • 126. Limits I For example the is of the ∞ / ∞ form as x ∞, therefore we will have to transform the formula to determine its behavior. 3x + 4 5x + 6
  • 127. Limits I For example the is of the ∞ / ∞ form as x ∞, therefore we will have to transform the formula to determine its behavior. 3x + 4 5x + 6 3x + 4 5x + 6 lim = 3/5. ∞ We will talk about various methods in the next section in determining the limits of formulas with inconclusive forms and see that (Take out the calculator and try to find it.)