SlideShare a Scribd company logo
Point Slope Formula
Point Slope Formula
      y  y1  m  x  x1 
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
              46
         m
             3  2
             10
           
             5
            2
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
              46
         m                             y  4  2  x  3
             3  2
             10
           
             5
            2
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
              46
         m                             y  4  2  x  3
             3  2
                                        y  4  2 x  6
             10
                                 2x  y  2  0
             5
            2
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
              46
         m                             y  4  2  x  3
             3  2
                                        y  4  2 x  6
             10
                                 2x  y  2  0
             5
            2
(ii) Find the equation of the line passing through (2,–3) and is parallel to
     3x + 4y – 5 =0
Point Slope Formula
                            y  y1  m  x  x1 

e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
               46
         m                             y  4  2  x  3
              3  2
                                        y  4  2 x  6
              10
                                 2x  y  2  0
              5
             2
(ii) Find the equation of the line passing through (2,–3) and is parallel to
     3x + 4y – 5 =0
          3     5
    y  x
          4     4
Point Slope Formula
                             y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                             y  4  2  x  3
               3  2
                                         y  4  2 x  6
               10
                                  2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0
           3     5
     y  x
           4     4
                  3
required m  
                  4
Point Slope Formula
                             y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                             y  4  2  x  3
               3  2
                                         y  4  2 x  6
               10
                                  2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3
                          y  3    x  2
           3     5                 4
     y  x
           4     4
                  3
required m  
                  4
Point Slope Formula
                             y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3
                          y  3    x  2
           3     5                 4
     y  x           4 y  12  3 x  6
           4     4
                  3     3x  4 y  6  0
required m  
                  4
Point Slope Formula
                             y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3             OR
                          y  3    x  2
           3     5                 4
     y  x           4 y  12  3 x  6
           4     4
                  3     3x  4 y  6  0
required m  
                  4
Point Slope Formula
                             y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3             OR         3x  4 y  k  0
                          y  3    x  2
           3     5                 4
     y  x           4 y  12  3 x  6
           4     4
                  3     3x  4 y  6  0
required m  
                  4
Point Slope Formula
                                 y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3             OR           3x  4 y  k  0
                          y  3    x  2
           3
     y  x
                 5                 4               2, 3 : 3  2   4  3  k  0
           4     4     4 y  12  3 x  6
                  3     3x  4 y  6  0
required m  
                  4
Point Slope Formula
                                 y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3             OR           3x  4 y  k  0
                          y  3    x  2
           3
     y  x
                 5                 4               2, 3 : 3  2   4  3  k  0
                       4 y  12  3 x  6
           4     4                                                   6  k  0
                        3x  4 y  6  0
required m  
                  3                                                         k 6
                  4
Point Slope Formula
                                 y  y1  m  x  x1 

 e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
                46
          m                              y  4  2  x  3
               3  2
                                          y  4  2 x  6
               10
                                   2x  y  2  0
               5
              2
 (ii) Find the equation of the line passing through (2,–3) and is parallel to
      3x + 4y – 5 =0               3             OR           3x  4 y  k  0
                          y  3    x  2
           3
     y  x
                 5                 4               2, 3 : 3  2   4  3  k  0
                       4 y  12  3 x  6
           4     4                                                   6  k  0
                        3x  4 y  6  0
required m  
                  3                                                         k 6
                  4                                        3x  4 y  6  0
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0

      9   6
   y  x
      4   4
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0

      9   6
   y  x
      4   4
               4
required m  
               9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                 4
      9   6             y  4    x  6
   y  x                        9
      4   4
               4
required m  
               9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                  4
      9   6             y  4    x  6
   y  x                         9
      4   4         9 y  36  4 x  24
               4
required m         4 x  9 y  60  0
               9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR
                                    4
         9    6          y  4    x  6
     y  x                         9
         4    4      9 y  36  4 x  24
                4
required m           4 x  9 y  60  0
                9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR       4x  9 y  k  0
                                    4
         9    6          y  4    x  6
     y  x                         9
         4    4      9 y  36  4 x  24
                4
required m           4 x  9 y  60  0
                9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24
                4
required m           4 x  9 y  60  0
                9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0

     To prove three lines (l, m, n) are concurrent;
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0

     To prove three lines (l, m, n) are concurrent;
         (i ) solve l and m simultaneously
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0

     To prove three lines (l, m, n) are concurrent;
         (i ) solve l and m simultaneously
         (ii ) substitute point of intersection into n
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0

     To prove three lines (l, m, n) are concurrent;
         (i ) solve l and m simultaneously
         (ii ) substitute point of intersection into n
        (iii ) if it satisfies the equation, then the lines are concurrent
(ii) Find the equation of the line passing through (6,4) and is
     perpendicular to 9x – 4y + 6 =0
                                              OR            4x  9 y  k  0
                                    4
         9
     y  x
              6          y  4    x  6      6, 4  : 4  6   9  4   k  0
                                    9
         4    4      9 y  36  4 x  24                        60  k  0
                4                                                       k  60
required m           4 x  9 y  60  0
                9                                       4 x  9 y  60  0

     To prove three lines (l, m, n) are concurrent;
         (i ) solve l and m simultaneously
         (ii ) substitute point of intersection into n
        (iii ) if it satisfies the equation, then the lines are concurrent

       Exercise 5D; 1e, 2c, 4abc (i), 5b, 7d, 9, 11, 13, 15, 17ab (i),
                       18ab (ii), 19, 22, 23c, 26*

More Related Content

What's hot

9-7 Graphing Points in Coordinate Plane
9-7 Graphing Points in Coordinate Plane9-7 Graphing Points in Coordinate Plane
9-7 Graphing Points in Coordinate Plane
Rudy Alfonso
 
Chapter 1 functions
Chapter 1  functionsChapter 1  functions
Chapter 1 functions
Umair Pearl
 
Yr.12 Transition Workshop 2012-2013
Yr.12 Transition Workshop 2012-2013Yr.12 Transition Workshop 2012-2013
Yr.12 Transition Workshop 2012-2013
rdk.rdk
 
9-10 Writing Equations
9-10 Writing Equations9-10 Writing Equations
9-10 Writing Equations
Rudy Alfonso
 
Maieee04
Maieee04Maieee04
Maieee04
Ashish Yadav
 
Polynomial function
Polynomial functionPolynomial function
Polynomial function
maricel mas
 
1538 graphs & linear equations
1538 graphs & linear equations1538 graphs & linear equations
1538 graphs & linear equations
Dr Fereidoun Dejahang
 
Tricky log graphs
Tricky log graphsTricky log graphs
Tricky log graphs
Shaun Wilson
 
Q uiz sequence n series...stpm
Q uiz sequence n series...stpmQ uiz sequence n series...stpm
Q uiz sequence n series...stpm
miearjuana
 
Engg. math 1 question bank by mohammad imran
Engg. math  1 question bank by mohammad imran Engg. math  1 question bank by mohammad imran
Engg. math 1 question bank by mohammad imran
Mohammad Imran
 
11 X1 T01 08 Simultaneous Equations (2010)
11 X1 T01 08 Simultaneous Equations (2010)11 X1 T01 08 Simultaneous Equations (2010)
11 X1 T01 08 Simultaneous Equations (2010)
Nigel Simmons
 
1050 text-bop
1050 text-bop1050 text-bop
1050 text-bop
Ainemukama Moses
 
Module 4 quadratic functions
Module 4 quadratic functionsModule 4 quadratic functions
Module 4 quadratic functions
dionesioable
 
Power point chapter 8 test preparation
Power point chapter 8 test preparationPower point chapter 8 test preparation
Power point chapter 8 test preparation
rmackenzie2012
 
Core 2 revision notes
Core 2 revision notesCore 2 revision notes
Core 2 revision notes
claire meadows-smith
 
Module 1 polynomial functions
Module 1   polynomial functionsModule 1   polynomial functions
Module 1 polynomial functions
dionesioable
 
Completing the square
Completing the squareCompleting the square
Completing the square
Shaun Wilson
 

What's hot (17)

9-7 Graphing Points in Coordinate Plane
9-7 Graphing Points in Coordinate Plane9-7 Graphing Points in Coordinate Plane
9-7 Graphing Points in Coordinate Plane
 
Chapter 1 functions
Chapter 1  functionsChapter 1  functions
Chapter 1 functions
 
Yr.12 Transition Workshop 2012-2013
Yr.12 Transition Workshop 2012-2013Yr.12 Transition Workshop 2012-2013
Yr.12 Transition Workshop 2012-2013
 
9-10 Writing Equations
9-10 Writing Equations9-10 Writing Equations
9-10 Writing Equations
 
Maieee04
Maieee04Maieee04
Maieee04
 
Polynomial function
Polynomial functionPolynomial function
Polynomial function
 
1538 graphs & linear equations
1538 graphs & linear equations1538 graphs & linear equations
1538 graphs & linear equations
 
Tricky log graphs
Tricky log graphsTricky log graphs
Tricky log graphs
 
Q uiz sequence n series...stpm
Q uiz sequence n series...stpmQ uiz sequence n series...stpm
Q uiz sequence n series...stpm
 
Engg. math 1 question bank by mohammad imran
Engg. math  1 question bank by mohammad imran Engg. math  1 question bank by mohammad imran
Engg. math 1 question bank by mohammad imran
 
11 X1 T01 08 Simultaneous Equations (2010)
11 X1 T01 08 Simultaneous Equations (2010)11 X1 T01 08 Simultaneous Equations (2010)
11 X1 T01 08 Simultaneous Equations (2010)
 
1050 text-bop
1050 text-bop1050 text-bop
1050 text-bop
 
Module 4 quadratic functions
Module 4 quadratic functionsModule 4 quadratic functions
Module 4 quadratic functions
 
Power point chapter 8 test preparation
Power point chapter 8 test preparationPower point chapter 8 test preparation
Power point chapter 8 test preparation
 
Core 2 revision notes
Core 2 revision notesCore 2 revision notes
Core 2 revision notes
 
Module 1 polynomial functions
Module 1   polynomial functionsModule 1   polynomial functions
Module 1 polynomial functions
 
Completing the square
Completing the squareCompleting the square
Completing the square
 

Viewers also liked

11 x1 t09 02 first principles (2013)
11 x1 t09 02 first principles (2013)11 x1 t09 02 first principles (2013)
11 x1 t09 02 first principles (2013)
Nigel Simmons
 
X2 t04 03 t results (2013)
X2 t04 03 t results (2013)X2 t04 03 t results (2013)
X2 t04 03 t results (2013)Nigel Simmons
 
11 x1 t10 03 equations reducible to quadratics (2013)
11 x1 t10 03 equations reducible to quadratics (2013)11 x1 t10 03 equations reducible to quadratics (2013)
11 x1 t10 03 equations reducible to quadratics (2013)Nigel Simmons
 
11 Ext1 t02 07 sketching graphs (13)
11 Ext1 t02 07 sketching graphs (13)11 Ext1 t02 07 sketching graphs (13)
11 Ext1 t02 07 sketching graphs (13)
Nigel Simmons
 
11 x1 t09 04 chain rule (13)
11 x1 t09 04 chain rule (13)11 x1 t09 04 chain rule (13)
11 x1 t09 04 chain rule (13)Nigel Simmons
 
11 x1 t03 01 inequations & inequalities (2013)
11 x1 t03 01 inequations & inequalities (2013)11 x1 t03 01 inequations & inequalities (2013)
11 x1 t03 01 inequations & inequalities (2013)
Nigel Simmons
 
12 x1 t07 03 simple harmonic motion (2013)
12 x1 t07 03 simple harmonic motion (2013)12 x1 t07 03 simple harmonic motion (2013)
12 x1 t07 03 simple harmonic motion (2013)
Nigel Simmons
 
X2 t07 03 addition, subtraction, multiplication & division (2013)
X2 t07 03 addition, subtraction,  multiplication & division (2013)X2 t07 03 addition, subtraction,  multiplication & division (2013)
X2 t07 03 addition, subtraction, multiplication & division (2013)
Nigel Simmons
 
11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)
Nigel Simmons
 
X2 t03 02 hyperbola (2013)
X2 t03 02 hyperbola (2013)X2 t03 02 hyperbola (2013)
X2 t03 02 hyperbola (2013)
Nigel Simmons
 
11 x1 t04 03 pythagorean trig identities (2013)
11 x1 t04 03 pythagorean trig identities (2013)11 x1 t04 03 pythagorean trig identities (2013)
11 x1 t04 03 pythagorean trig identities (2013)Nigel Simmons
 
11 x1 t05 01 permutations i (2013)
11 x1 t05 01 permutations i (2013)11 x1 t05 01 permutations i (2013)
11 x1 t05 01 permutations i (2013)
Nigel Simmons
 
X2 t03 04 parameters, hyperbola (2013)
X2 t03 04 parameters, hyperbola (2013)X2 t03 04 parameters, hyperbola (2013)
X2 t03 04 parameters, hyperbola (2013)Nigel Simmons
 
12 x1 t05 03 graphing inverse trig (2013)
12 x1 t05 03 graphing inverse trig (2013)12 x1 t05 03 graphing inverse trig (2013)
12 x1 t05 03 graphing inverse trig (2013)Nigel Simmons
 
11 x1 t05 05 perpendicular distance (2013)
11 x1 t05 05 perpendicular distance (2013)11 x1 t05 05 perpendicular distance (2013)
11 x1 t05 05 perpendicular distance (2013)
Nigel Simmons
 
11 x1 t04 02 angles of any magnitude (2013)
11 x1 t04 02 angles of any magnitude (2013)11 x1 t04 02 angles of any magnitude (2013)
11 x1 t04 02 angles of any magnitude (2013)Nigel Simmons
 
11 x1 t09 06 quotient & reciprocal rules (2013)
11 x1 t09 06 quotient & reciprocal rules (2013)11 x1 t09 06 quotient & reciprocal rules (2013)
11 x1 t09 06 quotient & reciprocal rules (2013)
Nigel Simmons
 
11 x1 t03 06 asymptotes (2013)
11 x1 t03 06 asymptotes (2013)11 x1 t03 06 asymptotes (2013)
11 x1 t03 06 asymptotes (2013)Nigel Simmons
 
11X1 T14 09 mathematical induction 2 (2011)
11X1 T14 09 mathematical induction 2 (2011)11X1 T14 09 mathematical induction 2 (2011)
11X1 T14 09 mathematical induction 2 (2011)
Nigel Simmons
 
X2 T04 04 reduction formula (2011)
X2 T04 04 reduction formula (2011)X2 T04 04 reduction formula (2011)
X2 T04 04 reduction formula (2011)
Nigel Simmons
 

Viewers also liked (20)

11 x1 t09 02 first principles (2013)
11 x1 t09 02 first principles (2013)11 x1 t09 02 first principles (2013)
11 x1 t09 02 first principles (2013)
 
X2 t04 03 t results (2013)
X2 t04 03 t results (2013)X2 t04 03 t results (2013)
X2 t04 03 t results (2013)
 
11 x1 t10 03 equations reducible to quadratics (2013)
11 x1 t10 03 equations reducible to quadratics (2013)11 x1 t10 03 equations reducible to quadratics (2013)
11 x1 t10 03 equations reducible to quadratics (2013)
 
11 Ext1 t02 07 sketching graphs (13)
11 Ext1 t02 07 sketching graphs (13)11 Ext1 t02 07 sketching graphs (13)
11 Ext1 t02 07 sketching graphs (13)
 
11 x1 t09 04 chain rule (13)
11 x1 t09 04 chain rule (13)11 x1 t09 04 chain rule (13)
11 x1 t09 04 chain rule (13)
 
11 x1 t03 01 inequations & inequalities (2013)
11 x1 t03 01 inequations & inequalities (2013)11 x1 t03 01 inequations & inequalities (2013)
11 x1 t03 01 inequations & inequalities (2013)
 
12 x1 t07 03 simple harmonic motion (2013)
12 x1 t07 03 simple harmonic motion (2013)12 x1 t07 03 simple harmonic motion (2013)
12 x1 t07 03 simple harmonic motion (2013)
 
X2 t07 03 addition, subtraction, multiplication & division (2013)
X2 t07 03 addition, subtraction,  multiplication & division (2013)X2 t07 03 addition, subtraction,  multiplication & division (2013)
X2 t07 03 addition, subtraction, multiplication & division (2013)
 
11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)
 
X2 t03 02 hyperbola (2013)
X2 t03 02 hyperbola (2013)X2 t03 02 hyperbola (2013)
X2 t03 02 hyperbola (2013)
 
11 x1 t04 03 pythagorean trig identities (2013)
11 x1 t04 03 pythagorean trig identities (2013)11 x1 t04 03 pythagorean trig identities (2013)
11 x1 t04 03 pythagorean trig identities (2013)
 
11 x1 t05 01 permutations i (2013)
11 x1 t05 01 permutations i (2013)11 x1 t05 01 permutations i (2013)
11 x1 t05 01 permutations i (2013)
 
X2 t03 04 parameters, hyperbola (2013)
X2 t03 04 parameters, hyperbola (2013)X2 t03 04 parameters, hyperbola (2013)
X2 t03 04 parameters, hyperbola (2013)
 
12 x1 t05 03 graphing inverse trig (2013)
12 x1 t05 03 graphing inverse trig (2013)12 x1 t05 03 graphing inverse trig (2013)
12 x1 t05 03 graphing inverse trig (2013)
 
11 x1 t05 05 perpendicular distance (2013)
11 x1 t05 05 perpendicular distance (2013)11 x1 t05 05 perpendicular distance (2013)
11 x1 t05 05 perpendicular distance (2013)
 
11 x1 t04 02 angles of any magnitude (2013)
11 x1 t04 02 angles of any magnitude (2013)11 x1 t04 02 angles of any magnitude (2013)
11 x1 t04 02 angles of any magnitude (2013)
 
11 x1 t09 06 quotient & reciprocal rules (2013)
11 x1 t09 06 quotient & reciprocal rules (2013)11 x1 t09 06 quotient & reciprocal rules (2013)
11 x1 t09 06 quotient & reciprocal rules (2013)
 
11 x1 t03 06 asymptotes (2013)
11 x1 t03 06 asymptotes (2013)11 x1 t03 06 asymptotes (2013)
11 x1 t03 06 asymptotes (2013)
 
11X1 T14 09 mathematical induction 2 (2011)
11X1 T14 09 mathematical induction 2 (2011)11X1 T14 09 mathematical induction 2 (2011)
11X1 T14 09 mathematical induction 2 (2011)
 
X2 T04 04 reduction formula (2011)
X2 T04 04 reduction formula (2011)X2 T04 04 reduction formula (2011)
X2 T04 04 reduction formula (2011)
 

Similar to 11X1 T06 04 point slope formula (2011)

Lesson slope power point
Lesson slope power pointLesson slope power point
Lesson slope power point
breesed
 
11 X1 T05 04 Point Slope Formula
11 X1 T05 04 Point Slope Formula11 X1 T05 04 Point Slope Formula
11 X1 T05 04 Point Slope Formula
Nigel Simmons
 
Form 4 Add Maths Note
Form 4 Add Maths NoteForm 4 Add Maths Note
Form 4 Add Maths Note
Chek Wei Tan
 
Form 4-add-maths-note
Form 4-add-maths-noteForm 4-add-maths-note
Form 4-add-maths-note
jacey tan
 
Cs 60
Cs 60Cs 60
Dec 14
Dec 14Dec 14
Dec 14
khyps13
 
Algebra i ccp quarter 3 benchmark review 2013 (2)
Algebra i ccp quarter 3 benchmark review 2013 (2)Algebra i ccp quarter 3 benchmark review 2013 (2)
Algebra i ccp quarter 3 benchmark review 2013 (2)
MsKendall
 
The angle between two lines
 The angle between two lines  The angle between two lines
The angle between two lines
Janak Singh saud
 
Form 4 add maths note
Form 4 add maths noteForm 4 add maths note
Form 4 add maths note
Sazlin A Ghani
 
11 x1 t01 09 simultaneous equations (2012)
11 x1 t01 09 simultaneous equations (2012)11 x1 t01 09 simultaneous equations (2012)
11 x1 t01 09 simultaneous equations (2012)
Nigel Simmons
 
11 x1 t01 09 simultaneous equations (2013)
11 x1 t01 09 simultaneous equations (2013)11 x1 t01 09 simultaneous equations (2013)
11 x1 t01 09 simultaneous equations (2013)
Nigel Simmons
 
11X1 T01 08 simultaneous equations (2011)
11X1 T01 08 simultaneous equations (2011)11X1 T01 08 simultaneous equations (2011)
11X1 T01 08 simultaneous equations (2011)
Nigel Simmons
 
Equation of straight line
Equation of straight lineEquation of straight line
Equation of straight line
Nadeem Uddin
 
Finding The Slope And Y Intercept
Finding The Slope And Y InterceptFinding The Slope And Y Intercept
Finding The Slope And Y Intercept
Thief River Falls
 
Int Math 2 Section 8-1 1011
Int Math 2 Section 8-1 1011Int Math 2 Section 8-1 1011
Int Math 2 Section 8-1 1011
Jimbo Lamb
 
Integrated Math 2 Section 8-1
Integrated Math 2 Section 8-1Integrated Math 2 Section 8-1
Integrated Math 2 Section 8-1
Jimbo Lamb
 
Lesson 3 (write the equation of a line)
Lesson 3 (write the equation of a line)Lesson 3 (write the equation of a line)
Lesson 3 (write the equation of a line)
nathanprescott
 
Soalan kuiz matematik tambahan ting empat 2006
Soalan kuiz matematik tambahan ting empat 2006Soalan kuiz matematik tambahan ting empat 2006
Soalan kuiz matematik tambahan ting empat 2006
zabidah awang
 
Derivadas
DerivadasDerivadas
Derivadas
Educación
 
Gradient of a curve and equation of a
Gradient of a curve and equation of aGradient of a curve and equation of a
Gradient of a curve and equation of a
Chadwick International School
 

Similar to 11X1 T06 04 point slope formula (2011) (20)

Lesson slope power point
Lesson slope power pointLesson slope power point
Lesson slope power point
 
11 X1 T05 04 Point Slope Formula
11 X1 T05 04 Point Slope Formula11 X1 T05 04 Point Slope Formula
11 X1 T05 04 Point Slope Formula
 
Form 4 Add Maths Note
Form 4 Add Maths NoteForm 4 Add Maths Note
Form 4 Add Maths Note
 
Form 4-add-maths-note
Form 4-add-maths-noteForm 4-add-maths-note
Form 4-add-maths-note
 
Cs 60
Cs 60Cs 60
Cs 60
 
Dec 14
Dec 14Dec 14
Dec 14
 
Algebra i ccp quarter 3 benchmark review 2013 (2)
Algebra i ccp quarter 3 benchmark review 2013 (2)Algebra i ccp quarter 3 benchmark review 2013 (2)
Algebra i ccp quarter 3 benchmark review 2013 (2)
 
The angle between two lines
 The angle between two lines  The angle between two lines
The angle between two lines
 
Form 4 add maths note
Form 4 add maths noteForm 4 add maths note
Form 4 add maths note
 
11 x1 t01 09 simultaneous equations (2012)
11 x1 t01 09 simultaneous equations (2012)11 x1 t01 09 simultaneous equations (2012)
11 x1 t01 09 simultaneous equations (2012)
 
11 x1 t01 09 simultaneous equations (2013)
11 x1 t01 09 simultaneous equations (2013)11 x1 t01 09 simultaneous equations (2013)
11 x1 t01 09 simultaneous equations (2013)
 
11X1 T01 08 simultaneous equations (2011)
11X1 T01 08 simultaneous equations (2011)11X1 T01 08 simultaneous equations (2011)
11X1 T01 08 simultaneous equations (2011)
 
Equation of straight line
Equation of straight lineEquation of straight line
Equation of straight line
 
Finding The Slope And Y Intercept
Finding The Slope And Y InterceptFinding The Slope And Y Intercept
Finding The Slope And Y Intercept
 
Int Math 2 Section 8-1 1011
Int Math 2 Section 8-1 1011Int Math 2 Section 8-1 1011
Int Math 2 Section 8-1 1011
 
Integrated Math 2 Section 8-1
Integrated Math 2 Section 8-1Integrated Math 2 Section 8-1
Integrated Math 2 Section 8-1
 
Lesson 3 (write the equation of a line)
Lesson 3 (write the equation of a line)Lesson 3 (write the equation of a line)
Lesson 3 (write the equation of a line)
 
Soalan kuiz matematik tambahan ting empat 2006
Soalan kuiz matematik tambahan ting empat 2006Soalan kuiz matematik tambahan ting empat 2006
Soalan kuiz matematik tambahan ting empat 2006
 
Derivadas
DerivadasDerivadas
Derivadas
 
Gradient of a curve and equation of a
Gradient of a curve and equation of aGradient of a curve and equation of a
Gradient of a curve and equation of a
 

More from Nigel Simmons

Goodbye slideshare UPDATE
Goodbye slideshare UPDATEGoodbye slideshare UPDATE
Goodbye slideshare UPDATE
Nigel Simmons
 
Goodbye slideshare
Goodbye slideshareGoodbye slideshare
Goodbye slideshare
Nigel Simmons
 
12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)Nigel Simmons
 
11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)
Nigel Simmons
 
11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)Nigel Simmons
 
12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)Nigel Simmons
 
11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)
Nigel Simmons
 
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)
Nigel Simmons
 
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)Nigel Simmons
 
12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)
Nigel Simmons
 
X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)Nigel Simmons
 
X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)
Nigel Simmons
 
X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)
Nigel Simmons
 
X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)
Nigel Simmons
 
11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)
Nigel Simmons
 
11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)Nigel Simmons
 
11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)
Nigel Simmons
 
11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)
Nigel Simmons
 
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)Nigel Simmons
 
11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)
Nigel Simmons
 

More from Nigel Simmons (20)

Goodbye slideshare UPDATE
Goodbye slideshare UPDATEGoodbye slideshare UPDATE
Goodbye slideshare UPDATE
 
Goodbye slideshare
Goodbye slideshareGoodbye slideshare
Goodbye slideshare
 
12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)
 
11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)
 
11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)
 
12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)
 
11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)
 
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)
 
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)
 
12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)
 
X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)
 
X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)
 
X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)
 
X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)
 
11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)
 
11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)
 
11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)
 
11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)
 
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)
 
11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)
 

Recently uploaded

Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
Executive Directors Chat  Leveraging AI for Diversity, Equity, and InclusionExecutive Directors Chat  Leveraging AI for Diversity, Equity, and Inclusion
Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
TechSoup
 
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
GeorgeMilliken2
 
Film vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movieFilm vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movie
Nicholas Montgomery
 
Main Java[All of the Base Concepts}.docx
Main Java[All of the Base Concepts}.docxMain Java[All of the Base Concepts}.docx
Main Java[All of the Base Concepts}.docx
adhitya5119
 
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityNatural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Akanksha trivedi rama nursing college kanpur.
 
How to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP ModuleHow to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP Module
Celine George
 
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
IreneSebastianRueco1
 
The History of Stoke Newington Street Names
The History of Stoke Newington Street NamesThe History of Stoke Newington Street Names
The History of Stoke Newington Street Names
History of Stoke Newington
 
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective UpskillingYour Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Excellence Foundation for South Sudan
 
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPLAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
RAHUL
 
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHatAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
Scholarhat
 
A Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdfA Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdf
Jean Carlos Nunes Paixão
 
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptxPengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Fajar Baskoro
 
How to Make a Field Mandatory in Odoo 17
How to Make a Field Mandatory in Odoo 17How to Make a Field Mandatory in Odoo 17
How to Make a Field Mandatory in Odoo 17
Celine George
 
How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17
Celine George
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
Priyankaranawat4
 
DRUGS AND ITS classification slide share
DRUGS AND ITS classification slide shareDRUGS AND ITS classification slide share
DRUGS AND ITS classification slide share
taiba qazi
 
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
RitikBhardwaj56
 
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
National Information Standards Organization (NISO)
 
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRMHow to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
Celine George
 

Recently uploaded (20)

Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
Executive Directors Chat  Leveraging AI for Diversity, Equity, and InclusionExecutive Directors Chat  Leveraging AI for Diversity, Equity, and Inclusion
Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
 
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
 
Film vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movieFilm vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movie
 
Main Java[All of the Base Concepts}.docx
Main Java[All of the Base Concepts}.docxMain Java[All of the Base Concepts}.docx
Main Java[All of the Base Concepts}.docx
 
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama UniversityNatural birth techniques - Mrs.Akanksha Trivedi Rama University
Natural birth techniques - Mrs.Akanksha Trivedi Rama University
 
How to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP ModuleHow to Add Chatter in the odoo 17 ERP Module
How to Add Chatter in the odoo 17 ERP Module
 
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
 
The History of Stoke Newington Street Names
The History of Stoke Newington Street NamesThe History of Stoke Newington Street Names
The History of Stoke Newington Street Names
 
Your Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective UpskillingYour Skill Boost Masterclass: Strategies for Effective Upskilling
Your Skill Boost Masterclass: Strategies for Effective Upskilling
 
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPLAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
 
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHatAzure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
 
A Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdfA Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdf
 
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptxPengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
 
How to Make a Field Mandatory in Odoo 17
How to Make a Field Mandatory in Odoo 17How to Make a Field Mandatory in Odoo 17
How to Make a Field Mandatory in Odoo 17
 
How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17How to Fix the Import Error in the Odoo 17
How to Fix the Import Error in the Odoo 17
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
 
DRUGS AND ITS classification slide share
DRUGS AND ITS classification slide shareDRUGS AND ITS classification slide share
DRUGS AND ITS classification slide share
 
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...The simplified electron and muon model, Oscillating Spacetime: The Foundation...
The simplified electron and muon model, Oscillating Spacetime: The Foundation...
 
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
 
How to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRMHow to Manage Your Lost Opportunities in Odoo 17 CRM
How to Manage Your Lost Opportunities in Odoo 17 CRM
 

11X1 T06 04 point slope formula (2011)

  • 2. Point Slope Formula y  y1  m  x  x1 
  • 3. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6)
  • 4. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m 3  2 10  5  2
  • 5. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 10  5  2
  • 6. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2
  • 7. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0
  • 8. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 5 y  x 4 4
  • 9. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 5 y  x 4 4 3 required m   4
  • 10. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 y  3    x  2 3 5 4 y  x 4 4 3 required m   4
  • 11. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 y  3    x  2 3 5 4 y  x 4 y  12  3 x  6 4 4 3 3x  4 y  6  0 required m   4
  • 12. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 OR y  3    x  2 3 5 4 y  x 4 y  12  3 x  6 4 4 3 3x  4 y  6  0 required m   4
  • 13. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 OR 3x  4 y  k  0 y  3    x  2 3 5 4 y  x 4 y  12  3 x  6 4 4 3 3x  4 y  6  0 required m   4
  • 14. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 OR 3x  4 y  k  0 y  3    x  2 3 y  x 5 4  2, 3 : 3  2   4  3  k  0 4 4 4 y  12  3 x  6 3 3x  4 y  6  0 required m   4
  • 15. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 OR 3x  4 y  k  0 y  3    x  2 3 y  x 5 4  2, 3 : 3  2   4  3  k  0 4 y  12  3 x  6 4 4 6  k  0 3x  4 y  6  0 required m   3 k 6 4
  • 16. Point Slope Formula y  y1  m  x  x1  e.g. (i) Find the equation of the line passing through (–3,4) and (2,–6) 46 m y  4  2  x  3 3  2 y  4  2 x  6 10  2x  y  2  0 5  2 (ii) Find the equation of the line passing through (2,–3) and is parallel to 3x + 4y – 5 =0 3 OR 3x  4 y  k  0 y  3    x  2 3 y  x 5 4  2, 3 : 3  2   4  3  k  0 4 y  12  3 x  6 4 4 6  k  0 3x  4 y  6  0 required m   3 k 6 4  3x  4 y  6  0
  • 17. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0
  • 18. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 9 6 y  x 4 4
  • 19. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 9 6 y  x 4 4 4 required m   9
  • 20. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 4 9 6 y  4    x  6 y  x 9 4 4 4 required m   9
  • 21. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 4 9 6 y  4    x  6 y  x 9 4 4 9 y  36  4 x  24 4 required m   4 x  9 y  60  0 9
  • 22. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4 9 6 y  4    x  6 y  x 9 4 4 9 y  36  4 x  24 4 required m   4 x  9 y  60  0 9
  • 23. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 6 y  4    x  6 y  x 9 4 4 9 y  36  4 x  24 4 required m   4 x  9 y  60  0 9
  • 24. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 4 required m   4 x  9 y  60  0 9
  • 25. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9
  • 26. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0
  • 27. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0 To prove three lines (l, m, n) are concurrent;
  • 28. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0 To prove three lines (l, m, n) are concurrent; (i ) solve l and m simultaneously
  • 29. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0 To prove three lines (l, m, n) are concurrent; (i ) solve l and m simultaneously (ii ) substitute point of intersection into n
  • 30. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0 To prove three lines (l, m, n) are concurrent; (i ) solve l and m simultaneously (ii ) substitute point of intersection into n (iii ) if it satisfies the equation, then the lines are concurrent
  • 31. (ii) Find the equation of the line passing through (6,4) and is perpendicular to 9x – 4y + 6 =0 OR 4x  9 y  k  0 4 9 y  x 6 y  4    x  6  6, 4  : 4  6   9  4   k  0 9 4 4 9 y  36  4 x  24 60  k  0 4 k  60 required m   4 x  9 y  60  0 9  4 x  9 y  60  0 To prove three lines (l, m, n) are concurrent; (i ) solve l and m simultaneously (ii ) substitute point of intersection into n (iii ) if it satisfies the equation, then the lines are concurrent Exercise 5D; 1e, 2c, 4abc (i), 5b, 7d, 9, 11, 13, 15, 17ab (i), 18ab (ii), 19, 22, 23c, 26*