SlideShare a Scribd company logo
Simultaneous Equations
Simultaneous Equations
 1) Eliminate a variable
Simultaneous Equations
 1) Eliminate a variable
 2) Solve for the other variable
Simultaneous Equations
 1) Eliminate a variable
 2) Solve for the other variable

 3) Substitute to find the eliminated variable
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
        5 x  2 y  3  (2)
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
        4 x  6 y  42
       15 x  6 y  9
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
        4 x  6 y  42
       15 x  6 y  9
       11x       =  33
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
        4 x  6 y  42
       15 x  6 y  9
       11x       =  33
         x       = 3
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
        4 x  6 y  42
       15 x  6 y  9
       11x       =  33              2  3  3 y  21
         x       = 3                           3 y  27
                                                y9
Simultaneous Equations
  1) Eliminate a variable
  2) Solve for the other variable

  3) Substitute to find the eliminated variable
e.g. (i ) 2 x  3 y  21 (1)
       5 x  2 y  3  (2)
 Multiply (1) by 2 and (2) by 3
        4 x  6 y  42
       15 x  6 y  9
       11x       =  33                 2  3  3 y  21
         x       = 3                              3 y  27
                                                   y9
                      x  3, y  9
(ii ) 2 x  y  14 (1)
   x 2  y 2  9  (2)
(ii ) 2 x  y  14 (1)
   x 2  y 2  9  (2)
Make y the subject in (1)
  y  14  2 x
(ii ) 2 x  y  14 (1)
   x 2  y 2  9  (2)
Make y the subject in (1)
  y  14  2 x
Substitute into (2)
  x 2  14  2 x   9
                  2
(ii ) 2 x  y  14 (1)
       x 2  y 2  9  (2)
   Make y the subject in (1)
     y  14  2 x
   Substitute into (2)
       x 2  14  2 x   9
                      2


x 2  196  56 x  4 x 2  9
     3 x 2  56 x  205  0
(ii ) 2 x  y  14 (1)
       x 2  y 2  9  (2)
   Make y the subject in (1)
     y  14  2 x
   Substitute into (2)
       x 2  14  2 x   9
                      2


x 2  196  56 x  4 x 2  9
     3 x 2  56 x  205  0
      3x  41 x  5   0
                         41
        x  5 or x 
                          3
(ii ) 2 x  y  14 (1)
        x 2  y 2  9  (2)
    Make y the subject in (1)
      y  14  2 x
    Substitute into (2)
        x 2  14  2 x   9
                       2


 x 2  196  56 x  4 x 2  9
        3 x 2  56 x  205  0
         3x  41 x  5   0
                            41
           x  5 or x 
                             3
                           41    14
2  5   y  14 or 2   y
                          3
                               40
           y  4 or y  
                                3
(ii ) 2 x  y  14 (1)
        x 2  y 2  9  (2)
    Make y the subject in (1)
      y  14  2 x
    Substitute into (2)
        x 2  14  2 x   9
                       2


 x 2  196  56 x  4 x 2  9
        3 x 2  56 x  205  0
         3x  41 x  5   0
                            41
           x  5 or x 
                             3
                           41    14
2  5   y  14 or 2   y
                          3
                                                             41       40
                               40        x  5, y  4 or x  , y  
           y  4 or y                                      3        3
                                3
(iii )      x  2 y  z  5  (1)
         2 x  3 y  4 z  28  (2)   any time you have the same number of
                                        pronumerals as equations it should
         4 x  5 y  3 z  10 (3)       be possible to find their values
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2
           2 x  4 y  2 z  10
           2 x  3 y  4 z  28
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2
           2 x  4 y  2 z  10
           2 x  3 y  4 z  28
                7 y  6 z  38
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2              Multiply (1) by 4
           2 x  4 y  2 z  10          4 x  8 y  4 z  20
           2 x  3 y  4 z  28           4 x  5 y  3 z  10
                7 y  6 z  38
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2              Multiply (1) by 4
           2 x  4 y  2 z  10          4 x  8 y  4 z  20
           2 x  3 y  4 z  28           4 x  5 y  3 z  10
                7 y  6 z  38                   3 y  z  10
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2                      Multiply (1) by 4
           2 x  4 y  2 z  10                  4 x  8 y  4 z  20
           2 x  3 y  4 z  28                   4 x  5 y  3 z  10
                7 y  6 z  38                           3 y  z  10
                      Solve these new equations simultaneously
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2                         Multiply (1) by 4
           2 x  4 y  2 z  10                    4 x  8 y  4 z  20
           2 x  3 y  4 z  28                   4 x  5 y  3 z  10
                7 y  6 z  38                           3 y  z  10
                      Solve these new equations simultaneously
                                       7 y  6 z  38
                                      18 y  6 z  60
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2                         Multiply (1) by 4
           2 x  4 y  2 z  10                    4 x  8 y  4 z  20
           2 x  3 y  4 z  28                   4 x  5 y  3 z  10
                7 y  6 z  38                           3 y  z  10
                      Solve these new equations simultaneously
                                       7 y  6 z  38
                                      18 y  6 z  60
(iii )      x  2 y  z  5  (1)
                                 any time you have the same number of
         2 x  3 y  4 z  28  (2)
                                   pronumerals as equations it should
         4 x  5 y  3 z  10 (3)  be possible to find their values
  Create two pairs of two equations and
  eliminate the same variable from both
           Multiply (1) by 2                          Multiply (1) by 4
           2 x  4 y  2 z  10                      4 x  8 y  4 z  20
           2 x  3 y  4 z  28                   4 x  5 y  3 z  10
                7 y  6 z  38                           3 y  z  10
                      Solve these new equations simultaneously
                                       7 y  6 z  38
                                      18 y  6 z  60
                                      11 y        22
                                         y      2
 3  2   z  10
           z  4
            z4
 3  2   z  10    x  2  2   4  5
           z  4                      x3
            z4
 3  2   z  10                      x  2  2   4  5
           z  4                                        x3
            z4

                        x  3, y  2, z  4
 3  2   z  10                      x  2  2   4  5
           z  4                                        x3
            z4

                        x  3, y  2, z  4




             Exercise 1H; 1bg, 2cfil, 3aceg, 4aegh, 5a,
                       6ace, 7ad, 8*b, 9***

More Related Content

What's hot

Succesive differntiation
Succesive differntiationSuccesive differntiation
Succesive differntiation
JaydevVadachhak
 
Understanding the remainder theorem
Understanding  the remainder theoremUnderstanding  the remainder theorem
Understanding the remainder theorem
MartinGeraldine
 
College algebra p4
College algebra p4College algebra p4
College algebra p4
Jeneva Clark
 
7.1 7.3 review (11-12)
7.1 7.3 review (11-12)7.1 7.3 review (11-12)
7.1 7.3 review (11-12)
MsKendall
 
Multiple Choice Questions_Successive Differentiation (CALCULUS)
Multiple Choice Questions_Successive Differentiation (CALCULUS)Multiple Choice Questions_Successive Differentiation (CALCULUS)
Multiple Choice Questions_Successive Differentiation (CALCULUS)
sanjay gupta
 
7.3
7.37.3
7.3
7.37.3
11X1 T05 06 line through point of intersection (2010)
11X1 T05 06 line through point of intersection (2010)11X1 T05 06 line through point of intersection (2010)
11X1 T05 06 line through point of intersection (2010)
Nigel Simmons
 
1. functions
1. functions1. functions
1. functions
Amirudin Mustapha
 
Int Math 2 Section 2-5 1011
Int Math 2 Section 2-5 1011Int Math 2 Section 2-5 1011
Int Math 2 Section 2-5 1011
Jimbo Lamb
 
Ecuaciones
EcuacionesEcuaciones
Ecuaciones
aranbilbao
 
7.4
7.47.4
7.4
kulpat
 
Module 2 linear functions
Module 2   linear functionsModule 2   linear functions
Module 2 linear functions
dionesioable
 
Chapter 01
Chapter 01Chapter 01
Chapter 01
ramiz100111
 
Lesson 11: Implicit Differentiation
Lesson 11: Implicit DifferentiationLesson 11: Implicit Differentiation
Lesson 11: Implicit Differentiation
Matthew Leingang
 
Unit 7 Review A
Unit 7 Review AUnit 7 Review A
Unit 7 Review A
Sedona Red Rock HS
 

What's hot (16)

Succesive differntiation
Succesive differntiationSuccesive differntiation
Succesive differntiation
 
Understanding the remainder theorem
Understanding  the remainder theoremUnderstanding  the remainder theorem
Understanding the remainder theorem
 
College algebra p4
College algebra p4College algebra p4
College algebra p4
 
7.1 7.3 review (11-12)
7.1 7.3 review (11-12)7.1 7.3 review (11-12)
7.1 7.3 review (11-12)
 
Multiple Choice Questions_Successive Differentiation (CALCULUS)
Multiple Choice Questions_Successive Differentiation (CALCULUS)Multiple Choice Questions_Successive Differentiation (CALCULUS)
Multiple Choice Questions_Successive Differentiation (CALCULUS)
 
7.3
7.37.3
7.3
 
7.3
7.37.3
7.3
 
11X1 T05 06 line through point of intersection (2010)
11X1 T05 06 line through point of intersection (2010)11X1 T05 06 line through point of intersection (2010)
11X1 T05 06 line through point of intersection (2010)
 
1. functions
1. functions1. functions
1. functions
 
Int Math 2 Section 2-5 1011
Int Math 2 Section 2-5 1011Int Math 2 Section 2-5 1011
Int Math 2 Section 2-5 1011
 
Ecuaciones
EcuacionesEcuaciones
Ecuaciones
 
7.4
7.47.4
7.4
 
Module 2 linear functions
Module 2   linear functionsModule 2   linear functions
Module 2 linear functions
 
Chapter 01
Chapter 01Chapter 01
Chapter 01
 
Lesson 11: Implicit Differentiation
Lesson 11: Implicit DifferentiationLesson 11: Implicit Differentiation
Lesson 11: Implicit Differentiation
 
Unit 7 Review A
Unit 7 Review AUnit 7 Review A
Unit 7 Review A
 

Viewers also liked

11 x1 t08 05 t results (2012)
11 x1 t08 05 t results (2012)11 x1 t08 05 t results (2012)
11 x1 t08 05 t results (2012)Nigel Simmons
 
11 x1 t04 07 3d trigonometry (2013)
11 x1 t04 07 3d trigonometry (2013)11 x1 t04 07 3d trigonometry (2013)
11 x1 t04 07 3d trigonometry (2013)
Nigel Simmons
 
12X1 T03 01 arcs & sectors
12X1 T03 01 arcs & sectors12X1 T03 01 arcs & sectors
12X1 T03 01 arcs & sectors
Nigel Simmons
 
11 x1 t02 06 relations & functions (2012)
11 x1 t02 06 relations & functions (2012)11 x1 t02 06 relations & functions (2012)
11 x1 t02 06 relations & functions (2012)
Nigel Simmons
 
11 X1 T03 04 absolute value (2010)
11 X1 T03 04 absolute value (2010)11 X1 T03 04 absolute value (2010)
11 X1 T03 04 absolute value (2010)
Nigel Simmons
 
12 x1 t03 01 arcs & sectors (2012)
12 x1 t03 01 arcs & sectors (2012)12 x1 t03 01 arcs & sectors (2012)
12 x1 t03 01 arcs & sectors (2012)
Nigel Simmons
 
11 X1 T05 01 Division Of An Interval
11 X1 T05 01 Division Of An Interval11 X1 T05 01 Division Of An Interval
11 X1 T05 01 Division Of An Interval
Nigel Simmons
 
11 x1 t01 10 matrices (2012)
11 x1 t01 10 matrices (2012)11 x1 t01 10 matrices (2012)
11 x1 t01 10 matrices (2012)Nigel Simmons
 
11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)
Nigel Simmons
 
11 ext1 t4 4 trig equations (2013)
11 ext1 t4 4 trig equations (2013)11 ext1 t4 4 trig equations (2013)
11 ext1 t4 4 trig equations (2013)Nigel Simmons
 
12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)Nigel Simmons
 
12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)Nigel Simmons
 
Goodbye slideshare UPDATE
Goodbye slideshare UPDATEGoodbye slideshare UPDATE
Goodbye slideshare UPDATE
Nigel Simmons
 

Viewers also liked (13)

11 x1 t08 05 t results (2012)
11 x1 t08 05 t results (2012)11 x1 t08 05 t results (2012)
11 x1 t08 05 t results (2012)
 
11 x1 t04 07 3d trigonometry (2013)
11 x1 t04 07 3d trigonometry (2013)11 x1 t04 07 3d trigonometry (2013)
11 x1 t04 07 3d trigonometry (2013)
 
12X1 T03 01 arcs & sectors
12X1 T03 01 arcs & sectors12X1 T03 01 arcs & sectors
12X1 T03 01 arcs & sectors
 
11 x1 t02 06 relations & functions (2012)
11 x1 t02 06 relations & functions (2012)11 x1 t02 06 relations & functions (2012)
11 x1 t02 06 relations & functions (2012)
 
11 X1 T03 04 absolute value (2010)
11 X1 T03 04 absolute value (2010)11 X1 T03 04 absolute value (2010)
11 X1 T03 04 absolute value (2010)
 
12 x1 t03 01 arcs & sectors (2012)
12 x1 t03 01 arcs & sectors (2012)12 x1 t03 01 arcs & sectors (2012)
12 x1 t03 01 arcs & sectors (2012)
 
11 X1 T05 01 Division Of An Interval
11 X1 T05 01 Division Of An Interval11 X1 T05 01 Division Of An Interval
11 X1 T05 01 Division Of An Interval
 
11 x1 t01 10 matrices (2012)
11 x1 t01 10 matrices (2012)11 x1 t01 10 matrices (2012)
11 x1 t01 10 matrices (2012)
 
11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)11 x1 t08 01 radian measure (13)
11 x1 t08 01 radian measure (13)
 
11 ext1 t4 4 trig equations (2013)
11 ext1 t4 4 trig equations (2013)11 ext1 t4 4 trig equations (2013)
11 ext1 t4 4 trig equations (2013)
 
12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)12 x1 t02 01 differentiating exponentials (2014)
12 x1 t02 01 differentiating exponentials (2014)
 
12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)12 x1 t02 02 integrating exponentials (2014)
12 x1 t02 02 integrating exponentials (2014)
 
Goodbye slideshare UPDATE
Goodbye slideshare UPDATEGoodbye slideshare UPDATE
Goodbye slideshare UPDATE
 

Similar to 11 x1 t01 09 simultaneous equations (2012)

11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)
Nigel Simmons
 
0307 ch 3 day 7
0307 ch 3 day 70307 ch 3 day 7
0307 ch 3 day 7
festivalelmo
 
A2 ch6sg
A2 ch6sgA2 ch6sg
A2 ch6sg
vhiggins1
 
A2 Chapter 6 Study Guide
A2 Chapter 6 Study GuideA2 Chapter 6 Study Guide
A2 Chapter 6 Study Guide
vhiggins1
 
Lecture 03 special products and factoring
Lecture 03 special products and factoringLecture 03 special products and factoring
Lecture 03 special products and factoring
Hazel Joy Chong
 
2010 mathematics hsc solutions
2010 mathematics hsc solutions2010 mathematics hsc solutions
2010 mathematics hsc solutions
jharnwell
 
Algebra 2 benchmark 3 review
Algebra 2 benchmark 3 reviewAlgebra 2 benchmark 3 review
Algebra 2 benchmark 3 review
jackieeee
 
4.2 derivatives of logarithmic functions
4.2 derivatives of logarithmic functions4.2 derivatives of logarithmic functions
4.2 derivatives of logarithmic functions
dicosmo178
 
Pc12 sol c03_3-5
Pc12 sol c03_3-5Pc12 sol c03_3-5
Pc12 sol c03_3-5
Garden City
 
ฟังก์ชัน(function)
ฟังก์ชัน(function)ฟังก์ชัน(function)
ฟังก์ชัน(function)
Yodhathai Reesrikom
 
Integrating factors found by inspection
Integrating factors found by inspectionIntegrating factors found by inspection
Integrating factors found by inspection
Shin Kaname
 
Chapter 1 (maths 3)
Chapter 1 (maths 3)Chapter 1 (maths 3)
Chapter 1 (maths 3)
Prathab Harinathan
 
Sau quantitative methods problem set 3
Sau   quantitative methods problem set  3Sau   quantitative methods problem set  3
Sau quantitative methods problem set 3
Naresh Sehdev
 
Limit of algebraic functions
Limit of algebraic functionsLimit of algebraic functions
Limit of algebraic functions
Dewi Setiyani Putri
 
Feb 22. Factoring Difference Of Squares
Feb 22. Factoring Difference Of SquaresFeb 22. Factoring Difference Of Squares
Feb 22. Factoring Difference Of Squares
ste ve
 
STUDY MATERIAL FOR IIT-JEE on Complex number
STUDY MATERIAL FOR IIT-JEE on Complex numberSTUDY MATERIAL FOR IIT-JEE on Complex number
STUDY MATERIAL FOR IIT-JEE on Complex number
APEX INSTITUTE
 
Special Products and Factors.pptx
Special Products and Factors.pptxSpecial Products and Factors.pptx
Special Products and Factors.pptx
JanineCaleon
 
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptxG8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
CatherineGanLabaro
 
1-1 Algebra Review HW
1-1 Algebra Review HW1-1 Algebra Review HW
1-1 Algebra Review HW
nechamkin
 
Calculus :Tutorial 2
Calculus :Tutorial 2Calculus :Tutorial 2
Calculus :Tutorial 2
Nuril Ekma
 

Similar to 11 x1 t01 09 simultaneous equations (2012) (20)

11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)11 x1 t01 03 factorising (2014)
11 x1 t01 03 factorising (2014)
 
0307 ch 3 day 7
0307 ch 3 day 70307 ch 3 day 7
0307 ch 3 day 7
 
A2 ch6sg
A2 ch6sgA2 ch6sg
A2 ch6sg
 
A2 Chapter 6 Study Guide
A2 Chapter 6 Study GuideA2 Chapter 6 Study Guide
A2 Chapter 6 Study Guide
 
Lecture 03 special products and factoring
Lecture 03 special products and factoringLecture 03 special products and factoring
Lecture 03 special products and factoring
 
2010 mathematics hsc solutions
2010 mathematics hsc solutions2010 mathematics hsc solutions
2010 mathematics hsc solutions
 
Algebra 2 benchmark 3 review
Algebra 2 benchmark 3 reviewAlgebra 2 benchmark 3 review
Algebra 2 benchmark 3 review
 
4.2 derivatives of logarithmic functions
4.2 derivatives of logarithmic functions4.2 derivatives of logarithmic functions
4.2 derivatives of logarithmic functions
 
Pc12 sol c03_3-5
Pc12 sol c03_3-5Pc12 sol c03_3-5
Pc12 sol c03_3-5
 
ฟังก์ชัน(function)
ฟังก์ชัน(function)ฟังก์ชัน(function)
ฟังก์ชัน(function)
 
Integrating factors found by inspection
Integrating factors found by inspectionIntegrating factors found by inspection
Integrating factors found by inspection
 
Chapter 1 (maths 3)
Chapter 1 (maths 3)Chapter 1 (maths 3)
Chapter 1 (maths 3)
 
Sau quantitative methods problem set 3
Sau   quantitative methods problem set  3Sau   quantitative methods problem set  3
Sau quantitative methods problem set 3
 
Limit of algebraic functions
Limit of algebraic functionsLimit of algebraic functions
Limit of algebraic functions
 
Feb 22. Factoring Difference Of Squares
Feb 22. Factoring Difference Of SquaresFeb 22. Factoring Difference Of Squares
Feb 22. Factoring Difference Of Squares
 
STUDY MATERIAL FOR IIT-JEE on Complex number
STUDY MATERIAL FOR IIT-JEE on Complex numberSTUDY MATERIAL FOR IIT-JEE on Complex number
STUDY MATERIAL FOR IIT-JEE on Complex number
 
Special Products and Factors.pptx
Special Products and Factors.pptxSpecial Products and Factors.pptx
Special Products and Factors.pptx
 
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptxG8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
 
1-1 Algebra Review HW
1-1 Algebra Review HW1-1 Algebra Review HW
1-1 Algebra Review HW
 
Calculus :Tutorial 2
Calculus :Tutorial 2Calculus :Tutorial 2
Calculus :Tutorial 2
 

More from Nigel Simmons

Goodbye slideshare
Goodbye slideshareGoodbye slideshare
Goodbye slideshare
Nigel Simmons
 
11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)Nigel Simmons
 
11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)
Nigel Simmons
 
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)
Nigel Simmons
 
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)Nigel Simmons
 
12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)
Nigel Simmons
 
X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)Nigel Simmons
 
X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)
Nigel Simmons
 
X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)
Nigel Simmons
 
X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)
Nigel Simmons
 
11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)
Nigel Simmons
 
11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)Nigel Simmons
 
11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)
Nigel Simmons
 
11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)
Nigel Simmons
 
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)Nigel Simmons
 
11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)
Nigel Simmons
 
11 x1 t16 01 area under curve (2013)
11 x1 t16 01 area under curve (2013)11 x1 t16 01 area under curve (2013)
11 x1 t16 01 area under curve (2013)
Nigel Simmons
 
X2 t01 11 nth roots of unity (2012)
X2 t01 11 nth roots of unity (2012)X2 t01 11 nth roots of unity (2012)
X2 t01 11 nth roots of unity (2012)
Nigel Simmons
 
X2 t01 10 complex & trig (2013)
X2 t01 10 complex & trig (2013)X2 t01 10 complex & trig (2013)
X2 t01 10 complex & trig (2013)Nigel Simmons
 
X2 t01 09 de moivres theorem
X2 t01 09 de moivres theoremX2 t01 09 de moivres theorem
X2 t01 09 de moivres theoremNigel Simmons
 

More from Nigel Simmons (20)

Goodbye slideshare
Goodbye slideshareGoodbye slideshare
Goodbye slideshare
 
11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)11 x1 t01 02 binomial products (2014)
11 x1 t01 02 binomial products (2014)
 
11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)
 
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)
 
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)
 
12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)
 
X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)
 
X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)
 
X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)
 
X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)
 
11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)
 
11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)
 
11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)
 
11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)
 
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)
 
11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)
 
11 x1 t16 01 area under curve (2013)
11 x1 t16 01 area under curve (2013)11 x1 t16 01 area under curve (2013)
11 x1 t16 01 area under curve (2013)
 
X2 t01 11 nth roots of unity (2012)
X2 t01 11 nth roots of unity (2012)X2 t01 11 nth roots of unity (2012)
X2 t01 11 nth roots of unity (2012)
 
X2 t01 10 complex & trig (2013)
X2 t01 10 complex & trig (2013)X2 t01 10 complex & trig (2013)
X2 t01 10 complex & trig (2013)
 
X2 t01 09 de moivres theorem
X2 t01 09 de moivres theoremX2 t01 09 de moivres theorem
X2 t01 09 de moivres theorem
 

Recently uploaded

Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxChapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Mohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
 
writing about opinions about Australia the movie
writing about opinions about Australia the moviewriting about opinions about Australia the movie
writing about opinions about Australia the movie
Nicholas Montgomery
 
Wound healing PPT
Wound healing PPTWound healing PPT
Wound healing PPT
Jyoti Chand
 
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
imrankhan141184
 
Film vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movieFilm vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movie
Nicholas Montgomery
 
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
Nguyen Thanh Tu Collection
 
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptxC1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
mulvey2
 
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Diana Rendina
 
UGC NET Exam Paper 1- Unit 1:Teaching Aptitude
UGC NET Exam Paper 1- Unit 1:Teaching AptitudeUGC NET Exam Paper 1- Unit 1:Teaching Aptitude
UGC NET Exam Paper 1- Unit 1:Teaching Aptitude
S. Raj Kumar
 
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
Nguyen Thanh Tu Collection
 
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdfANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
Priyankaranawat4
 
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
GeorgeMilliken2
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
Priyankaranawat4
 
Liberal Approach to the Study of Indian Politics.pdf
Liberal Approach to the Study of Indian Politics.pdfLiberal Approach to the Study of Indian Politics.pdf
Liberal Approach to the Study of Indian Politics.pdf
WaniBasim
 
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptxPengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Fajar Baskoro
 
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
Nguyen Thanh Tu Collection
 
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
PECB
 
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem studentsRHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
Himanshu Rai
 
A Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdfA Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdf
Jean Carlos Nunes Paixão
 
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPLAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
RAHUL
 

Recently uploaded (20)

Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxChapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
 
writing about opinions about Australia the movie
writing about opinions about Australia the moviewriting about opinions about Australia the movie
writing about opinions about Australia the movie
 
Wound healing PPT
Wound healing PPTWound healing PPT
Wound healing PPT
 
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
Traditional Musical Instruments of Arunachal Pradesh and Uttar Pradesh - RAYH...
 
Film vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movieFilm vocab for eal 3 students: Australia the movie
Film vocab for eal 3 students: Australia the movie
 
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
BÀI TẬP BỔ TRỢ TIẾNG ANH LỚP 9 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2024-2025 - ...
 
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptxC1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
C1 Rubenstein AP HuG xxxxxxxxxxxxxx.pptx
 
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
Reimagining Your Library Space: How to Increase the Vibes in Your Library No ...
 
UGC NET Exam Paper 1- Unit 1:Teaching Aptitude
UGC NET Exam Paper 1- Unit 1:Teaching AptitudeUGC NET Exam Paper 1- Unit 1:Teaching Aptitude
UGC NET Exam Paper 1- Unit 1:Teaching Aptitude
 
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
BÀI TẬP DẠY THÊM TIẾNG ANH LỚP 7 CẢ NĂM FRIENDS PLUS SÁCH CHÂN TRỜI SÁNG TẠO ...
 
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdfANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
 
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
 
clinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdfclinical examination of hip joint (1).pdf
clinical examination of hip joint (1).pdf
 
Liberal Approach to the Study of Indian Politics.pdf
Liberal Approach to the Study of Indian Politics.pdfLiberal Approach to the Study of Indian Politics.pdf
Liberal Approach to the Study of Indian Politics.pdf
 
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptxPengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
 
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
BÀI TẬP BỔ TRỢ TIẾNG ANH 8 CẢ NĂM - GLOBAL SUCCESS - NĂM HỌC 2023-2024 (CÓ FI...
 
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
 
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem studentsRHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
RHEOLOGY Physical pharmaceutics-II notes for B.pharm 4th sem students
 
A Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdfA Independência da América Espanhola LAPBOOK.pdf
A Independência da América Espanhola LAPBOOK.pdf
 
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UPLAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
LAND USE LAND COVER AND NDVI OF MIRZAPUR DISTRICT, UP
 

11 x1 t01 09 simultaneous equations (2012)

  • 2. Simultaneous Equations 1) Eliminate a variable
  • 3. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable
  • 4. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable
  • 5. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2)
  • 6. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3
  • 7. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3 4 x  6 y  42 15 x  6 y  9
  • 8. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3 4 x  6 y  42 15 x  6 y  9 11x =  33
  • 9. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3 4 x  6 y  42 15 x  6 y  9 11x =  33 x = 3
  • 10. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3 4 x  6 y  42 15 x  6 y  9 11x =  33  2  3  3 y  21 x = 3 3 y  27 y9
  • 11. Simultaneous Equations 1) Eliminate a variable 2) Solve for the other variable 3) Substitute to find the eliminated variable e.g. (i ) 2 x  3 y  21 (1) 5 x  2 y  3  (2) Multiply (1) by 2 and (2) by 3 4 x  6 y  42 15 x  6 y  9 11x =  33  2  3  3 y  21 x = 3 3 y  27 y9  x  3, y  9
  • 12. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2)
  • 13. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x
  • 14. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x Substitute into (2) x 2  14  2 x   9 2
  • 15. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x Substitute into (2) x 2  14  2 x   9 2 x 2  196  56 x  4 x 2  9 3 x 2  56 x  205  0
  • 16. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x Substitute into (2) x 2  14  2 x   9 2 x 2  196  56 x  4 x 2  9 3 x 2  56 x  205  0  3x  41 x  5   0 41 x  5 or x  3
  • 17. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x Substitute into (2) x 2  14  2 x   9 2 x 2  196  56 x  4 x 2  9 3 x 2  56 x  205  0  3x  41 x  5   0 41 x  5 or x  3  41    14 2  5   y  14 or 2   y 3 40 y  4 or y   3
  • 18. (ii ) 2 x  y  14 (1) x 2  y 2  9  (2) Make y the subject in (1) y  14  2 x Substitute into (2) x 2  14  2 x   9 2 x 2  196  56 x  4 x 2  9 3 x 2  56 x  205  0  3x  41 x  5   0 41 x  5 or x  3  41    14 2  5   y  14 or 2   y 3 41 40 40  x  5, y  4 or x  , y   y  4 or y   3 3 3
  • 19. (iii ) x  2 y  z  5  (1) 2 x  3 y  4 z  28  (2) any time you have the same number of pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values
  • 20. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both
  • 21. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 2 x  4 y  2 z  10 2 x  3 y  4 z  28
  • 22. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 2 x  4 y  2 z  10 2 x  3 y  4 z  28 7 y  6 z  38
  • 23. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38
  • 24. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38 3 y  z  10
  • 25. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38 3 y  z  10 Solve these new equations simultaneously
  • 26. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38 3 y  z  10 Solve these new equations simultaneously 7 y  6 z  38 18 y  6 z  60
  • 27. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38 3 y  z  10 Solve these new equations simultaneously 7 y  6 z  38 18 y  6 z  60
  • 28. (iii ) x  2 y  z  5  (1) any time you have the same number of 2 x  3 y  4 z  28  (2) pronumerals as equations it should 4 x  5 y  3 z  10 (3) be possible to find their values Create two pairs of two equations and eliminate the same variable from both Multiply (1) by 2 Multiply (1) by 4 2 x  4 y  2 z  10 4 x  8 y  4 z  20 2 x  3 y  4 z  28 4 x  5 y  3 z  10 7 y  6 z  38 3 y  z  10 Solve these new equations simultaneously 7 y  6 z  38 18 y  6 z  60 11 y  22 y  2
  • 29.  3  2   z  10  z  4 z4
  • 30.  3  2   z  10  x  2  2   4  5  z  4 x3 z4
  • 31.  3  2   z  10  x  2  2   4  5  z  4 x3 z4  x  3, y  2, z  4
  • 32.  3  2   z  10  x  2  2   4  5  z  4 x3 z4  x  3, y  2, z  4 Exercise 1H; 1bg, 2cfil, 3aceg, 4aegh, 5a, 6ace, 7ad, 8*b, 9***