Algebra 2

Benchmark Review
   Ms. Cheung
Standard
                            1.0

1)




     The absolute value of any number will always
     be positive, thus the equation |5 – 6m| > - 7
     will always be true!!
Standard
                                       1.0

   2)




10 5x   7   62                     10 5x   55


                 10 5x         55           10 5x     55
                     5x       45                 5x  65
                 x        9                     x 13
Standard 2.0
3. Which order pair is the solution to the system of equations below?




  x 7 y 20 Solve for x                                x   7 y 20
 4 7 y 20 4 y   16 Substitute for x                   x   7(2) 20
   28 y 80 4 y  16 Distribute                         x 14 20
        32y 80  16 Combine Like Term                  x     6
             32y      64    Combine Like term
               y     2      Solve for y
Standard 2.0
4. Which order pair is the solution to the system of equations below?




     8 x 2 y 20                                         4x   y        2
   2 4 x y 2 Multiply 2 to equation 2                   4x 6          2
    8 x 2 y 20                                          4x        4
                Add the two equations
   8x 2 y 4                                             x     1
        4y    24         y   6
Standard 2.0
5) Ms. Cheung’s current phone plan is about to
  be expired. She has been offered two
  promotions from two different phone
  providers. AT&T provides a 500 minute plan at
  $30 with 40 cents per text message. T-Mobile
  provides a 500 minute plan at $40 with 30
  cents per text message. If x represents the
  number of text sent and y is the total amount
  charge for both plans, how do you write a
  system of equations that model this situation?
                                 y 30 0.4 x
                               y   40   0 .3 x
Standard 2.0
6) Gerardo wrote a matrix equation.
           4    3        x        20
           1    2        y         6
What is the solution to Gerardo’s equation?
     4     3    x        20        4x 3 y     20
     1    2     y            6         x 2y   6

      4x 3y         20
                             2,   4
         x 2y       6
Standard 2.0
7) Jackie wrote a matrix equation.
         2     1       x            3
         3     2       y        6
What is the solution to Gerardo’s equation?
     2   1     x            3       2x   y   3
     3    2    y           6        3x 2 y   6

      2x y         3
                           0,   3
      3x 2 y       6
Standard 3.0
8)




                5n 4 3n3 8n 2
                3n 4 2n3 7n 2
                2n 4   n3 15n 2
Standard 3.0




           6a 2   6a
                  14a   14

          6a 2    20a 14
Standard 3.0




           6k 2 12 k
                5k 10

          6k 2 17k 10
Standard 3.0

11)




 6x 4   8x 3       4 2x 4   4x 3   3


               4        3
        8x 12x 1
Standard 3.0
12)
Given a polynomial expression x 4 10x 3 35x 2 50x 24
such that it has two factors of ( x 1) and ( x 4).

A)   (x   1) and ( x   2).
                                       1 4   4
B)   (x   1) and ( x   3).
C)   (x   2) and ( x   3). 2   3   6   24    4   6
D)   (x   3) and ( x   4).
Standard 5.0
13) Which of the following represent the graph
  of 3 2i ?


                  A          C


                  B          D
Standard 5.0
14. Kevin knows that   1   i . What will he get if
  he simplifies 16 ?

A) 4 and 4
B)   4
C) 4i
D) 4i and 4i
Standard 5.0
15. Jocelyn knows that 1 i . What will he get
  if he simplifies 64 ?

A) 8 and 8
B)    8
C) 8i and 8i
D) 8i
Standard 6.0
16. Jocelyn knows that 1 i . What will she
  get if he simplifies 2 25 ?

A) 5i
B) 10i
C) 10i
D) 5i
Standard 6.0
17)


               (3 i )(3 i )
                 9 3i 3i i 2
                 9 ( 1)
                  10
Standard 6.0
18)



                 3 2i 5 i
                 2 3i
Standard 6.0
19)



              12 5i ( 3 4i)
                12 5i 3 4i
                     9 i
20)




    2
p       4        0                 a 1, b   0, c       4
            0     0 2 4 (1)( 4 )       16    4
    x               2 (1)             2     2      x   2 or x   2
21)




6x   2
         5x 25 0                      a      6, b     5, c          25
         5   52 4 ( 6 )( 25)    5   25 600     5     625          5 25
 x             2(6)                 12             12             12
         5 25                5 25
 x       12    or x          12               x       5
                                                      3    or x      3
                                                                      5
Standard 9.0
22. Given the graph f(x)=ax2+bx+c. If a is
  negative, what would my graph look like?
                              f(x)=ax2+bx+c is a Quadratic
                              Equation since it has a
A)   A linear graph going up  power of 2.
B)   A linear graph going up         Since a is
C)   A quadratic graph going up      negative, the graph
                                     will be going
D)   A quadratic graph going down    downward.
Standard 9.0
            23)
 Vertex
 (-3, -2)

Vertex                                        From (-3, -2) to (2, 2)
 (2, 2)                                       We get ( 2, 2)
                                                         ( 3, 2)
                                                        (2 3, 2 2)

                                                        (5, 4)
                        Positive 5, so it’s 5 unit to      Positive 4,
                        the right.                         4 units UP!!
Standard 9.0
                 24)
     Vertex
      (5, 1)
   Vertex
   (-5, 1)
                                                   Both functions are
                                                   positive, so their vertices
                                                   are minimums.

Both functions
have the same
coefficient: 3, both
have the same
shape.

                           Both functions are
                           positive, so both
                           vertices are minimum.
Standard 10.0
25) What is the minimum value of the function
  f(x)=x2 – 9?
               Minimum  The lowest Point!
A)   –9        Find the vertex!
B)   –3          X= - b/2a
                 X = 0/2 = 0
C)   0
                  y = 0 – 9= -9
D)   9

                          The lowest Point!
Standard 10.0
26)

          X= - b/2a
          X = -6/2 = - 3

          y=(-3)2+6(-3)+5
            = 9 – 18 + 5 = - 4


            Vertex: ( - 3, - 4)
Standard 24.0

27)
Standard 24.0
28)
Standard 24.0
29) Which of the following functions is the
  inverse of f(x) = 3x – 2?
     A)       1            3
          f       ( x)    x 2

     B)   f 1 ( x)         3
                          x 2
              1           x 2
     C)   f ( x)           3

     D) f 1 ( x)          x 2
                           3
Standard 7.0
30) Rewrite the following exponents to positive
  exponents.

                      x 2
        A)   f ( x)     3
                      y
                       2    5
                      x y
        B)   f ( x)    4    2
                      x y
Standard 7.0
31)
Standard 7.0
32)
Standard 7.0
33)
Standard 7.0
34)



                     -1
Standard 22.0
35)
                             Strategy: Convert to decimal


      =0.5 + 0.25+ 0.125 + 0.625 + …

      =0.5 + 0.25+ 0.125 + 0.0625 + …

      =0.9375
      Closest to 1
Standard 22.0
36)
                                                      Strategy:
              1st term 2nd term term 4th term5th term Substitute n=1, 2, 3, 4, 5
                              3rd
                                                      into the answer choice to
                 n=1 n=2 n=3 n=4 n=5                  see if the term generated is
                   = 4(1) = 4               (first term) same as the question
                                                      the

                      = 3+4(1) = 7           (first term)
                      = 2(1)+1 = 3           (first term)
                       = 2(2)+1 = 5           (second term)
      = 4(1)-1 = 3 (first term) = 4(2)-1 = 7 (second term)
      = 4(3)-1 = 11 (third term)       = 4(4)-1 = 15 (fourth term)
      = 4(5)-1 = 19 (fifth term)
Standard PS 1.0
                                  Strategy: Identify Keywords
37)


                       P(cm label & no labels)
         Multiply
       No. of rulers
                                             No. of rulers
      with cm labels
                                            without labels

                                            One less ruler
       Total No. of
         Rulers
Standard PS 1.0
38)
                                           Strategy:
                                           Identify Keywords


        Not raining in San Francisco
                                                Multiply
         and not raining in Sydney
      P(not raining in SF & not raining in Sydney)
Standard PS 1.0
                                                  Strategy:
39)                                               Identify Keywords




                        Green and green                     Multiply

                 P(green & green)
 No. of green
 marble in 1st                       No. of green marbles
     bag                                   in 2nd bag

                                       Total No. of
  Total No. of
                                      marbles in 2nd
  Marbles in
                                           bag
    1st bag
Standard PS 2.0
40)
41)   Standard PS 2.0

Algebra 2 benchmark 3 review

  • 1.
  • 2.
    Standard 1.0 1) The absolute value of any number will always be positive, thus the equation |5 – 6m| > - 7 will always be true!!
  • 3.
    Standard 1.0 2) 10 5x 7 62 10 5x 55 10 5x 55 10 5x 55 5x 45 5x 65 x 9 x 13
  • 4.
    Standard 2.0 3. Whichorder pair is the solution to the system of equations below? x 7 y 20 Solve for x x 7 y 20 4 7 y 20 4 y 16 Substitute for x x 7(2) 20 28 y 80 4 y 16 Distribute x 14 20 32y 80 16 Combine Like Term x 6 32y 64 Combine Like term y 2 Solve for y
  • 5.
    Standard 2.0 4. Whichorder pair is the solution to the system of equations below? 8 x 2 y 20 4x y 2 2 4 x y 2 Multiply 2 to equation 2 4x 6 2 8 x 2 y 20 4x 4 Add the two equations 8x 2 y 4 x 1 4y 24 y 6
  • 6.
    Standard 2.0 5) Ms.Cheung’s current phone plan is about to be expired. She has been offered two promotions from two different phone providers. AT&T provides a 500 minute plan at $30 with 40 cents per text message. T-Mobile provides a 500 minute plan at $40 with 30 cents per text message. If x represents the number of text sent and y is the total amount charge for both plans, how do you write a system of equations that model this situation? y 30 0.4 x y 40 0 .3 x
  • 7.
    Standard 2.0 6) Gerardowrote a matrix equation. 4 3 x 20 1 2 y 6 What is the solution to Gerardo’s equation? 4 3 x 20 4x 3 y 20 1 2 y 6 x 2y 6 4x 3y 20 2, 4 x 2y 6
  • 8.
    Standard 2.0 7) Jackiewrote a matrix equation. 2 1 x 3 3 2 y 6 What is the solution to Gerardo’s equation? 2 1 x 3 2x y 3 3 2 y 6 3x 2 y 6 2x y 3 0, 3 3x 2 y 6
  • 9.
    Standard 3.0 8) 5n 4 3n3 8n 2 3n 4 2n3 7n 2 2n 4 n3 15n 2
  • 10.
    Standard 3.0 6a 2 6a 14a 14 6a 2 20a 14
  • 11.
    Standard 3.0 6k 2 12 k 5k 10 6k 2 17k 10
  • 12.
    Standard 3.0 11) 6x4 8x 3 4 2x 4 4x 3 3 4 3 8x 12x 1
  • 13.
    Standard 3.0 12) Given apolynomial expression x 4 10x 3 35x 2 50x 24 such that it has two factors of ( x 1) and ( x 4). A) (x 1) and ( x 2). 1 4 4 B) (x 1) and ( x 3). C) (x 2) and ( x 3). 2 3 6 24 4 6 D) (x 3) and ( x 4).
  • 14.
    Standard 5.0 13) Whichof the following represent the graph of 3 2i ? A C B D
  • 15.
    Standard 5.0 14. Kevinknows that 1 i . What will he get if he simplifies 16 ? A) 4 and 4 B) 4 C) 4i D) 4i and 4i
  • 16.
    Standard 5.0 15. Jocelynknows that 1 i . What will he get if he simplifies 64 ? A) 8 and 8 B) 8 C) 8i and 8i D) 8i
  • 17.
    Standard 6.0 16. Jocelynknows that 1 i . What will she get if he simplifies 2 25 ? A) 5i B) 10i C) 10i D) 5i
  • 18.
    Standard 6.0 17) (3 i )(3 i ) 9 3i 3i i 2 9 ( 1) 10
  • 19.
    Standard 6.0 18) 3 2i 5 i 2 3i
  • 20.
    Standard 6.0 19) 12 5i ( 3 4i) 12 5i 3 4i 9 i
  • 21.
    20) 2 p 4 0 a 1, b 0, c 4 0 0 2 4 (1)( 4 ) 16 4 x 2 (1) 2 2 x 2 or x 2
  • 22.
    21) 6x 2 5x 25 0 a 6, b 5, c 25 5 52 4 ( 6 )( 25) 5 25 600 5 625 5 25 x 2(6) 12 12 12 5 25 5 25 x 12 or x 12 x 5 3 or x 3 5
  • 23.
    Standard 9.0 22. Giventhe graph f(x)=ax2+bx+c. If a is negative, what would my graph look like? f(x)=ax2+bx+c is a Quadratic Equation since it has a A) A linear graph going up power of 2. B) A linear graph going up Since a is C) A quadratic graph going up negative, the graph will be going D) A quadratic graph going down downward.
  • 24.
    Standard 9.0 23) Vertex (-3, -2) Vertex From (-3, -2) to (2, 2) (2, 2) We get ( 2, 2) ( 3, 2) (2 3, 2 2) (5, 4) Positive 5, so it’s 5 unit to Positive 4, the right. 4 units UP!!
  • 25.
    Standard 9.0 24) Vertex (5, 1) Vertex (-5, 1) Both functions are positive, so their vertices are minimums. Both functions have the same coefficient: 3, both have the same shape. Both functions are positive, so both vertices are minimum.
  • 26.
    Standard 10.0 25) Whatis the minimum value of the function f(x)=x2 – 9? Minimum  The lowest Point! A) –9 Find the vertex! B) –3 X= - b/2a X = 0/2 = 0 C) 0 y = 0 – 9= -9 D) 9 The lowest Point!
  • 27.
    Standard 10.0 26) X= - b/2a X = -6/2 = - 3 y=(-3)2+6(-3)+5 = 9 – 18 + 5 = - 4 Vertex: ( - 3, - 4)
  • 28.
  • 29.
  • 30.
    Standard 24.0 29) Whichof the following functions is the inverse of f(x) = 3x – 2? A) 1 3 f ( x) x 2 B) f 1 ( x) 3 x 2 1 x 2 C) f ( x) 3 D) f 1 ( x) x 2 3
  • 31.
    Standard 7.0 30) Rewritethe following exponents to positive exponents. x 2 A) f ( x) 3 y 2 5 x y B) f ( x) 4 2 x y
  • 32.
  • 33.
  • 34.
  • 35.
  • 36.
    Standard 22.0 35) Strategy: Convert to decimal =0.5 + 0.25+ 0.125 + 0.625 + … =0.5 + 0.25+ 0.125 + 0.0625 + … =0.9375 Closest to 1
  • 37.
    Standard 22.0 36) Strategy: 1st term 2nd term term 4th term5th term Substitute n=1, 2, 3, 4, 5 3rd into the answer choice to n=1 n=2 n=3 n=4 n=5 see if the term generated is = 4(1) = 4 (first term) same as the question the = 3+4(1) = 7 (first term) = 2(1)+1 = 3 (first term) = 2(2)+1 = 5 (second term) = 4(1)-1 = 3 (first term) = 4(2)-1 = 7 (second term) = 4(3)-1 = 11 (third term) = 4(4)-1 = 15 (fourth term) = 4(5)-1 = 19 (fifth term)
  • 38.
    Standard PS 1.0 Strategy: Identify Keywords 37) P(cm label & no labels) Multiply No. of rulers No. of rulers with cm labels without labels One less ruler Total No. of Rulers
  • 39.
    Standard PS 1.0 38) Strategy: Identify Keywords Not raining in San Francisco Multiply and not raining in Sydney P(not raining in SF & not raining in Sydney)
  • 40.
    Standard PS 1.0 Strategy: 39) Identify Keywords Green and green Multiply P(green & green) No. of green marble in 1st No. of green marbles bag in 2nd bag Total No. of Total No. of marbles in 2nd Marbles in bag 1st bag
  • 41.
  • 42.
    41) Standard PS 2.0