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Coordinate Geometry
Concept Session
The Cartesian plane
2
Distance between 2 Points P(x1, y1) and Q(x2,
y2)
Distance PQ :
𝑥2 − 𝑥1
2 + 𝑦2 − 𝑦1
2
Distance from origin of point P :
𝑥1
2 + 𝑦1
2
3
Distance between 2 Points - Problems
Let the vertices of a triangle ABC be
(−8, 8), (2, −8) and (−2, 2) then the triangle is
A. Right angled
B. Equilateral
C. Isosceles
D. Scalene
E. Cannot be determined
4
The midpoint of an interval
The midpoint of an interval with endpoints
𝑃(𝑥1, 𝑦1) and 𝑄(𝑥2, 𝑦2) is
𝑥1 + 𝑥2
2
,
𝑦1 + 𝑦2
2
5
The midpoint of an interval - Problem
If C(3, 5) is the midpoint of line interval AB
and A has coordinates (–2, 1), find the
coordinates of B.
6
Answer : (8, 9)
Section formula – Internal
division
Given two end points of line segment A(x1, y1) and B
(x2, y2) you can determine the coordinates of the point
P(x, y) that divides the given line segment in the ratio
m : n internally using Section Formula
𝑥 =
𝑚𝑥2+𝑛𝑥1
𝑚+𝑛
𝑦 =
𝑚𝑦2+𝑛𝑦1
𝑚+𝑛
7
Section formula – External
division
Given two end points of line segment A(x1, y1) and B
(x2, y2) you can determine the coordinates of the point
P(x, y) that divides the given line segment in the ratio
m : n externally using Section Formula given by
𝑥 =
𝑚𝑥2−𝑛𝑥1
𝑚−𝑛
𝑦 =
𝑚𝑦2−𝑛𝑦1
𝑚−𝑛
8
Area of a Triangle
The area of a triangle ABC whose vertices are
A(x1, y1), B (x2, y2) and C(x3, y3) is denoted by
1
2
| 𝑥1 𝑦2 − 𝑥2 𝑦1 + 𝑥2 𝑦3 − 𝑥3 𝑦2
+ 𝑥3 𝑦1 − 𝑥1 𝑦3 |
9
Centroid of a triangle
Centroid – meeting point of the three medians.
The centroid(G) of a triangle ABC whose vertices are
A(𝑥1, 𝑦1), B(𝑥2, 𝑦2) and C(𝑥3, 𝑦3) is denoted by
𝐺 =
𝑥1 + 𝑥2 + 𝑥3
3
,
𝑦1 + 𝑦2 + 𝑦3
3
10
Straight Line
▪Slope of a Line
▪Equations of a straight line
–General form of Equation
–Slope-intercept form
–Point slope form
–Two point form
–Intercept form
11
Slope of a line ( Gradient)
The slope, represented by the letter m, measures
the inclination or steepness of the line.
The slope is always measured anti-clock wise
𝑆𝑙𝑜𝑝𝑒 =
𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑦 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒
𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑥 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒
=
𝑅𝑖𝑠𝑒
𝑅𝑢𝑛
𝑆𝑙𝑜𝑝𝑒 =
∆𝑦
∆𝑥
=
𝑦2 − 𝑦1
𝑥2 − 𝑥1
12
Slope of a line ( Gradient) - values
Positive Slope – On moving from
left to right, the line rises
Negative Slope - On moving from left
to right, the line dips
13
Slope of a line ( Gradient) - values
Zero Slope – Parallel to x axis and
hence “No rise”
Undefined Slope – Parallel to y axis
and hence “ infinite rise”
14
Slope of a special line
Parallel Lines  equal slope
𝑚1 = 𝑚2
Perpendicular lines  negative
inverses
𝑚1 ∗ 𝑚2 = −1
15
Problems
16
Quantity A Quantity B
Sole of a line
perpendicular to
Line 1
Slope of a line
perpendicular to
Line 2
Equation of a straight line – General Form
𝑎𝑥 + 𝑏𝑦 + 𝑐 = 0
Slope of the line =
−𝑎
𝑏
Y intercept =
𝑐
𝑏
17
Equation of a straight line – Slope intercept Form
Equation of a straight line whose slope
is 𝑚 and which cuts of a y-intercept of 𝐶
units is given by
𝑦 = 𝑚𝑥 + 𝐶
18
Equation of a straight line – Problems
Find the equation of a line that
intersects the Y axis at the point
(0,3) and has a slope of
5
3
Answer : 3𝑦 − 5𝑥 = 9
19
Equation of a straight line – Point-slope Form
Equation of a straight line passing
through a point (𝑥1, 𝑦1) and having a
slope m is given by
𝑦 − 𝑦1 = 𝑚 ∗ (𝑥 − 𝑥1)
20
Equation of a straight line – Problems
Find an equation of the line that passes through
(4, 6) and is parallel to the line whose equation is
𝑦 =
2
3
𝑥 + 5.
a) 2𝑦 = 3𝑥 + 10
b) 3𝑦 = 3𝑥 + 10
c) 3𝑦 = 2𝑥 + 10
d) 4𝑦 = 3𝑥 + 15
e) 𝑛𝑜𝑛𝑒 𝑜𝑓 𝑡ℎ𝑒𝑠𝑒
Answer: Option
3
21
Equation of a straight line – Problems
Find an equation of the line that passes through
(4, 6) and is perpendicular to the line whose
equation is 𝑦 =
2
3
𝑥 + 5.
1. 2𝑦 = −3𝑥 + 10
2. 3𝑦 = −3𝑥 + 24
3. 3𝑦 = 2𝑥 + 10
4. 4𝑦 = 3𝑥 + 13
5. 𝑛𝑜𝑛𝑒 𝑜𝑓 𝑡ℎ𝑒𝑠𝑒
Answer: 2𝑦 = −3𝑥 + 24
22
Equation of a straight line – Two-point Form
Equation of a straight line passing
through two points (𝑥1, 𝑦1) and (𝑥2, 𝑦2)
is given by
𝑦 − 𝑦1 =
(𝑦2−𝑦1)
(𝑥2−𝑥1)
∗ (𝑥 − 𝑥1)
23
Equation of a straight line – Intercept Form
Equation of a straight
line which cuts off x-
intercept (a) and y-
intercept (b) is
𝑥
𝑎
+
𝑦
𝑏
= 1
24
Transformations – Vertical and Horizontal Shifts
25
Vertical Shift
To Graph Shift the Graph of ƒ(x)
ƒ(𝑥) + 𝑐 c units upward
ƒ 𝑥 − 𝑐 c units upward
Horizontal Shift
To Graph Shift the Graph of ƒ(x)
ƒ(𝑥 + 𝑐) c units to the left
ƒ 𝑥 − 𝑐 c units to the right
Transformations – Reflections
26
Reflection along coordinate axis
To Graph Shift the Graph of ƒ(x)
−ƒ(𝑥) Reflect along x axis
ƒ −𝑥 Reflect along y axis
Problems
27
Which of the following
could be the equation of
the figure given ?
A. 𝑦 = 𝑥2
B. 𝑦 = 𝑥2
+ 9
C. 𝑦 = 10𝑥 + 6
D. 𝑦 = 𝑥2
− 4
E. 𝑦 = 𝑥3
+ 4
Problems
28
Which of the following
could be the equation of
the figure given ?
A. 𝑦 = 𝑥2
B. 𝑦 = −𝑥2
+ 9
C. 𝑦 = −𝑥 + 6
D. 𝑦 = −(𝑥 + 2)2
− 4
E. 𝑦 = − 𝑥 + 2 2
+ 2
Sin, cos and tan values
𝟎° 𝟑𝟎° 𝟒𝟓° 𝟔𝟎° 𝟗𝟎°
Sin 0
1
2
1
2
3
2
1
Cos
1 3
2
1
2
1
2
0
Tan
0 1
3
1
3 𝑢𝑛𝑑𝑒𝑓𝑖𝑛𝑒𝑑
29
Conditions of Collinearity of three Points
1. Area of triangle ABC is zero.
2. Slope of AB = Slope of BC = Slope of AC
3. Distance between A and B + Distance between
B and C = Distance between A and C
30
Practice Problems
If 𝐴(1,2), 𝐵(4,3), 𝐶(6,6) and 𝐷(𝑥, 𝑦) are the
four vertices of a parallelogram taken in an
order, then the value of 𝑥 + 𝑦 is
A. 5
B. 7
C. 8
D. 10
E. None of these
Answer : option 3
31

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GRE - Coordinate Geometry

  • 3. Distance between 2 Points P(x1, y1) and Q(x2, y2) Distance PQ : 𝑥2 − 𝑥1 2 + 𝑦2 − 𝑦1 2 Distance from origin of point P : 𝑥1 2 + 𝑦1 2 3
  • 4. Distance between 2 Points - Problems Let the vertices of a triangle ABC be (−8, 8), (2, −8) and (−2, 2) then the triangle is A. Right angled B. Equilateral C. Isosceles D. Scalene E. Cannot be determined 4
  • 5. The midpoint of an interval The midpoint of an interval with endpoints 𝑃(𝑥1, 𝑦1) and 𝑄(𝑥2, 𝑦2) is 𝑥1 + 𝑥2 2 , 𝑦1 + 𝑦2 2 5
  • 6. The midpoint of an interval - Problem If C(3, 5) is the midpoint of line interval AB and A has coordinates (–2, 1), find the coordinates of B. 6 Answer : (8, 9)
  • 7. Section formula – Internal division Given two end points of line segment A(x1, y1) and B (x2, y2) you can determine the coordinates of the point P(x, y) that divides the given line segment in the ratio m : n internally using Section Formula 𝑥 = 𝑚𝑥2+𝑛𝑥1 𝑚+𝑛 𝑦 = 𝑚𝑦2+𝑛𝑦1 𝑚+𝑛 7
  • 8. Section formula – External division Given two end points of line segment A(x1, y1) and B (x2, y2) you can determine the coordinates of the point P(x, y) that divides the given line segment in the ratio m : n externally using Section Formula given by 𝑥 = 𝑚𝑥2−𝑛𝑥1 𝑚−𝑛 𝑦 = 𝑚𝑦2−𝑛𝑦1 𝑚−𝑛 8
  • 9. Area of a Triangle The area of a triangle ABC whose vertices are A(x1, y1), B (x2, y2) and C(x3, y3) is denoted by 1 2 | 𝑥1 𝑦2 − 𝑥2 𝑦1 + 𝑥2 𝑦3 − 𝑥3 𝑦2 + 𝑥3 𝑦1 − 𝑥1 𝑦3 | 9
  • 10. Centroid of a triangle Centroid – meeting point of the three medians. The centroid(G) of a triangle ABC whose vertices are A(𝑥1, 𝑦1), B(𝑥2, 𝑦2) and C(𝑥3, 𝑦3) is denoted by 𝐺 = 𝑥1 + 𝑥2 + 𝑥3 3 , 𝑦1 + 𝑦2 + 𝑦3 3 10
  • 11. Straight Line ▪Slope of a Line ▪Equations of a straight line –General form of Equation –Slope-intercept form –Point slope form –Two point form –Intercept form 11
  • 12. Slope of a line ( Gradient) The slope, represented by the letter m, measures the inclination or steepness of the line. The slope is always measured anti-clock wise 𝑆𝑙𝑜𝑝𝑒 = 𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑦 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑥 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 = 𝑅𝑖𝑠𝑒 𝑅𝑢𝑛 𝑆𝑙𝑜𝑝𝑒 = ∆𝑦 ∆𝑥 = 𝑦2 − 𝑦1 𝑥2 − 𝑥1 12
  • 13. Slope of a line ( Gradient) - values Positive Slope – On moving from left to right, the line rises Negative Slope - On moving from left to right, the line dips 13
  • 14. Slope of a line ( Gradient) - values Zero Slope – Parallel to x axis and hence “No rise” Undefined Slope – Parallel to y axis and hence “ infinite rise” 14
  • 15. Slope of a special line Parallel Lines  equal slope 𝑚1 = 𝑚2 Perpendicular lines  negative inverses 𝑚1 ∗ 𝑚2 = −1 15
  • 16. Problems 16 Quantity A Quantity B Sole of a line perpendicular to Line 1 Slope of a line perpendicular to Line 2
  • 17. Equation of a straight line – General Form 𝑎𝑥 + 𝑏𝑦 + 𝑐 = 0 Slope of the line = −𝑎 𝑏 Y intercept = 𝑐 𝑏 17
  • 18. Equation of a straight line – Slope intercept Form Equation of a straight line whose slope is 𝑚 and which cuts of a y-intercept of 𝐶 units is given by 𝑦 = 𝑚𝑥 + 𝐶 18
  • 19. Equation of a straight line – Problems Find the equation of a line that intersects the Y axis at the point (0,3) and has a slope of 5 3 Answer : 3𝑦 − 5𝑥 = 9 19
  • 20. Equation of a straight line – Point-slope Form Equation of a straight line passing through a point (𝑥1, 𝑦1) and having a slope m is given by 𝑦 − 𝑦1 = 𝑚 ∗ (𝑥 − 𝑥1) 20
  • 21. Equation of a straight line – Problems Find an equation of the line that passes through (4, 6) and is parallel to the line whose equation is 𝑦 = 2 3 𝑥 + 5. a) 2𝑦 = 3𝑥 + 10 b) 3𝑦 = 3𝑥 + 10 c) 3𝑦 = 2𝑥 + 10 d) 4𝑦 = 3𝑥 + 15 e) 𝑛𝑜𝑛𝑒 𝑜𝑓 𝑡ℎ𝑒𝑠𝑒 Answer: Option 3 21
  • 22. Equation of a straight line – Problems Find an equation of the line that passes through (4, 6) and is perpendicular to the line whose equation is 𝑦 = 2 3 𝑥 + 5. 1. 2𝑦 = −3𝑥 + 10 2. 3𝑦 = −3𝑥 + 24 3. 3𝑦 = 2𝑥 + 10 4. 4𝑦 = 3𝑥 + 13 5. 𝑛𝑜𝑛𝑒 𝑜𝑓 𝑡ℎ𝑒𝑠𝑒 Answer: 2𝑦 = −3𝑥 + 24 22
  • 23. Equation of a straight line – Two-point Form Equation of a straight line passing through two points (𝑥1, 𝑦1) and (𝑥2, 𝑦2) is given by 𝑦 − 𝑦1 = (𝑦2−𝑦1) (𝑥2−𝑥1) ∗ (𝑥 − 𝑥1) 23
  • 24. Equation of a straight line – Intercept Form Equation of a straight line which cuts off x- intercept (a) and y- intercept (b) is 𝑥 𝑎 + 𝑦 𝑏 = 1 24
  • 25. Transformations – Vertical and Horizontal Shifts 25 Vertical Shift To Graph Shift the Graph of ƒ(x) ƒ(𝑥) + 𝑐 c units upward ƒ 𝑥 − 𝑐 c units upward Horizontal Shift To Graph Shift the Graph of ƒ(x) ƒ(𝑥 + 𝑐) c units to the left ƒ 𝑥 − 𝑐 c units to the right
  • 26. Transformations – Reflections 26 Reflection along coordinate axis To Graph Shift the Graph of ƒ(x) −ƒ(𝑥) Reflect along x axis ƒ −𝑥 Reflect along y axis
  • 27. Problems 27 Which of the following could be the equation of the figure given ? A. 𝑦 = 𝑥2 B. 𝑦 = 𝑥2 + 9 C. 𝑦 = 10𝑥 + 6 D. 𝑦 = 𝑥2 − 4 E. 𝑦 = 𝑥3 + 4
  • 28. Problems 28 Which of the following could be the equation of the figure given ? A. 𝑦 = 𝑥2 B. 𝑦 = −𝑥2 + 9 C. 𝑦 = −𝑥 + 6 D. 𝑦 = −(𝑥 + 2)2 − 4 E. 𝑦 = − 𝑥 + 2 2 + 2
  • 29. Sin, cos and tan values 𝟎° 𝟑𝟎° 𝟒𝟓° 𝟔𝟎° 𝟗𝟎° Sin 0 1 2 1 2 3 2 1 Cos 1 3 2 1 2 1 2 0 Tan 0 1 3 1 3 𝑢𝑛𝑑𝑒𝑓𝑖𝑛𝑒𝑑 29
  • 30. Conditions of Collinearity of three Points 1. Area of triangle ABC is zero. 2. Slope of AB = Slope of BC = Slope of AC 3. Distance between A and B + Distance between B and C = Distance between A and C 30
  • 31. Practice Problems If 𝐴(1,2), 𝐵(4,3), 𝐶(6,6) and 𝐷(𝑥, 𝑦) are the four vertices of a parallelogram taken in an order, then the value of 𝑥 + 𝑦 is A. 5 B. 7 C. 8 D. 10 E. None of these Answer : option 3 31

Editor's Notes

  1. Answer : (4, 9)
  2. Answer: Externally in the ratio 2 : -7
  3. Answer: Externally in the ratio 2 : -7
  4. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  5. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  6. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  7. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  8. Answer: Quantity A S1>S2 ( Both are negative but L1 is less steep so lesser magnitude) (1/S1) <(1/S2) -(1/S1)>1(1/S2)
  9. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  10. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  11. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  12. Answer: Option 3
  13. Answer: Option 4
  14. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  15. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  16. Answer: Option D  x^2 -4
  17. Answer : Otion E  -(x + 2)² + 2
  18. Answer: 3rd coordinate = (-7, 8) and area = 18 units.
  19. Answer: 45 degrees
  20. Reference : http://www.learnnext.com/nganswers/ask-question/answer/To-find-4th-vertex-of-a-parallelogram-/Coordinate-Geometry/4645.htm