Does Planet Day Period Depend On Its Circumference (III)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Does Planet Day Period Depend On Its Circumference ? (III)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 14th
November 2020
Abstract
Paper hypothesis
The Planet Day Period Definition : The Period Through Which The Planet Moves A Distance = Its Circumference.
Paper Question No. (1)
Is There An Interaction Between The Earth Moon & Jupiter Motions?
- Because
- Jupiter Diameter 142984 = The Earth Moon Circumference 10921 km x 13.1
- Where
- 13.1 km /sec = Jupiter Velocity …………And
- 13.18 degrees = the Earth moon motion degrees per solar day
- Shortly
- Are these 2 values (13.1 and 13.18) created depending on each other
- Which proves an interaction between Jupiter & the Earth moon Velocities
Paper Question No. (2)
If This interaction is found, can it effect on both Planets Days Periods?
- The paper discusses these questions

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1- Jupiter and The Earth Moon Motions Interaction
1-1 Jupiter Diameter Analysis 1-2 Planets Velocities Discussion
1-1 Jupiter Diameter Analysis
Equation No. (1)
2.58 million km = 10921 km x 237
Where 2.58 mkm = the moon motion distance daily
237 = (5832.5 hours Venus R. period / 24.6 hours Mars R. Period)
- We know that the moon daily displacement = 88000 km per solar day, and the moon day period = 29.53 solar days and
that means, the moon moves during its day period a distance = 2.58 mkm
- The paper hypothesis tells that, the planet moves during its day period a distance = its circumference, so the moon
circumference = 10921 km but the Equation still has one more rate (237).
- Equation No. (1) may tells that, the moon during its day period (29.53 days) would move just 10921 km (= the moon
circumference) but the interaction between Venus and Mars prevented that and forced the moon to move 2.58 mkm!
Equation No. (2)
142984 km = 10921 km x 13.1
Where 142984 = Jupiter diameter and 13.1 km/sec = Jupiter velocity
- We keep this equation by heart…..
- Equation No. (2) tells us, when the moon rotates around its axis one time, it moves 10921 km… so the moon needs to
rotate around its axis 13.1 times to move distance =142984 km = Jupiter diameter …..BUT
- 13.1 km/sec as a velocity, makes this Equation No. (2) to tell that during 10921 seconds, Jupiter moves a distance =
142984 km = its diameter, and by that 10921 km (the moon circumference) will b used as 10921 seconds!
- The equation is difficult because both planets depends on almost the same (13.1 or 13.18) in their motions, the pure
coincidence claim is so weak and can't be considered as a logical conclusion any how…So we search for the geometrical
necessity behind this values (13.1 and 13.18) ….now we see that, Equation no. 2 can be used by Jupiter or the moon and
we know that the moon circumference is created as a function of light velocity (300000 km =10921 km x 27.3), that
causes its significance BUT why Jupiter diameter (142984 km) is important for the moon motion? for what using this
value controls its motion? let's try to answer in following…

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Equation No. (3)
149.6 million km = 1047 x 142984 km (Jupiter diameter)
Where 149.6 mkm = Earth orbital distance 1047 = (the sun mass /Jupiter mass)
- Equation No. (3) tells that, Earth orbital distance is created based on some balance between the sun mass and Jupiter
mass…. this equation has a massive significance because now we consider that Jupiter mass is a player in Earth orbital
distance definition, based on this conclusion, my claim that "Jupiter and The Sun Masses interaction creates some point
in the moon orbit (The point A), and this interaction effect by another gravity force on the point (A), and by that there
are 2 gravity forces effect on the Earth moon motion"- this claim doesn't depend on any imaginary idea but depend on
the concept by which the Earth orbital distance is defined… Because if Earth orbital distance is defined by the sun and
Jupiter masses interaction effect, so logically this interaction can create this effect point (A) to effect by 2nd
gravity force
on the moon orbit opposite to the Earth gravity….
- Let's ask Is just Earth orbital distance defined by effect of Jupiter diameter? No
Equation No. (4)
142984 km (Jupiter diameter) = 6792 km (Mars Diameter) x 21
And
227.9 mkm (Mars orbital distance) x 21= 4900 mkm (Jupiter Orbital Circumference) (error 2.3%)
- Equation No. (4) is incorrect because the error =2.3%! how to explain that?
- The concept is correct but not with 4900 mkm (Jupiter orbit circumference) but with 4775 mkm!! Why?
- Because Jupiter orbital distance 778.6 mkm is consisted of 2 Parts (760 mkm +17.6 mkm) why??
o 760 mkm is created to recover Mars Migration results and
o 17.6 mkm is created to recover Mars Migration results
o How can we prove that?
o We remember that, Jupiter energy is sent to Pluto and Pluto reflected it to Neptune and Neptune used 14% of this
energy and sent the rest of energy into 2 trajectories of energy each has 86400 mkm (Space = Energy), so
o The first trajectory reached to Mercury 86400 mkm = 5040 x 17.2 mkm
o The second trajectory reached to Earth 86400 mkm = 113.6 x 760 mkm

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o Where, 113.6 degrees = 90 deg +23.6 degrees (the outer planets orbital inclinations total and 23.6 x 0.99 = 23.4
earth axial tilt), and Mercury day needs 5040 seconds to be 176 solar days
o 17.6 mkm is near to 17.4 mkm = 17.4 degrees = the inner planets orbital inclinations total, and 17.4 x 0.99 = 17.2
degrees = Pluto orbital inclination
o Why this explanation is correct?
o Because
o 760 seconds x 0.3 mkm /sc (light known velocity) = 227.9 mkm (Mars orbital distance), that means Mars new
orbital distance is defined basically based on light motion during 760 seconds – and that makes this number very
specific for Mars orbital distance, because of that we meet this number frequently in the previous explanation
o Shortly
o Jupiter orbital distance is consisted of 2 parts (760 mkm+17.2 mkm), and these values are used as periods
for light motion as we know
o That tells Jupiter diameter effects to define Earth and Mars orbital distances… and
o Because Mars diameter is created as a function of Jupiter diameter by which Mars orbital distance is defined,
because of that (Mars Circumference 21.346.6 km)2
= 227.9 mkm Mars Orbital Distance
- Let's remember the question (why Jupiter diameter (142984 km) is important for the moon motion?) we have
proved that Jupiter diameter effect on 3 planets orbital distance (Earth- Mars and The Earth Moon), but the question still
have more deep vision….
o Planet motion is effected by planet diameter and circumference because, planet day period is created as a function
of the planet circumference, that makes definition for the motion period of time and by that the planet velocity
must be in consistency with this data otherwise the harmony of motion will be disappeared…
o What meaning this conclusion does tell us?!
o The planet diameter and circumference is created as a function of the planet motion velocity!
o If this consistency between planet diameter and circumference with planet velocity isn't found, that means, all
previous data was found by pure coincidences! So let's test this conclusion – if the planet diameter and
circumference really is created as a function of its velocity!

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1-2 Planets Velocities Discussion
Equation No. (5)
51118 km (Uranus diameter) = 6.8 km/sec (Uranus velocity) x (Pluto Circumference)
- Equation No. (5) is typically with Equation No. (2)
- Uranus uses Pluto circumference (7511.4 km) as a period of time (7511.4 seconds) perfectly as Jupiter uses the earth
moon circumference (10921 km) as a period of time (10921 seconds)
- The concept is just clear, the planet diameter and circumference is created to perform this task.. and so this matter
dimension (7511.4 km) will be used as time period… how? Because the planet rotates around its axis and by that the
planet moves a distance = its circumference, so the Earth moon can move 10921 km and Pluto can move 7511.4 km by
one rotation around their axis –then in light motion the distance can be used as period of time as we have seen frequently
in the solar system data.
Equation No. (6)
378675 km (Saturn Circumference) = 9.7 km/sec (Saturn velocity) x 38041 km (Venus Circumference) (error 2.6%)
- We know that, Saturn Diameter = Venus Circumference x π
- We can see now the source from which this relationship is originated
- Please Note The Sun Diameter = Jupiter Circumference x π (error 1.3%)
- This relationship in fact uses (9.7) between the sun diameter and Jupiter diameter and that's the error reason.
Equation No. (7)
120536 km (Saturn diameter) = 9.7 km/sec (Saturn velocity) x (0.25) (Neptune Diameter)
- Neptune Diameter = 49528 km, Saturn uses 12382 km as 12382 seconds by its velocity to pass a distance = its diameter,
this interaction between the planets can explain the relationship which we have discovered and couldn't find their
reasons till now, for example
o (Neptune orbital distance = Saturn orbital distance x π) why? also
o (Neptune axial tilt / Saturn axial tilt) = (Saturn axial tilt/Mars axial tilt) = (Mars axial tilt / Earth axial tilt)

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Equation No. (8)
49528 km (Neptune diameter) = 5.4 km/sec (Neptune velocity) x 9000 (error 1.8%)
- 9000 km is the lunar umbra breadth… this umbra dimensions are so important because its length = the sun diameter
Equation No. (9)
40080 km (Earth Circumference) = 29.8 km/sec (Earth velocity) x 1334 seconds
- The value (1334 seconds = Mars Circumference/16)
- The Equation explains why (Earth diameter / Mars diameter = 1.9- error1%-), where 1.9 degrees = Mars orbital
inclination.
- Please note (1.9) is used widely in the inner planets data, for example (78.3 mkm Earth Mars distance x 1.9 = 149.6
mkm Earth orbital distance, and 120 mkm Venus Mars distance x 1.9 = 227.9 mkm Mars orbital distance….etc)
Equation No. (10)
40080 km (Earth Circumference) = 29.8 km/sec (Earth velocity) x 1334 seconds
Note please
- The rest 4 inner planets diameters are so small and their velocities so high, because of that this rule doesn't work with
them, but it works with Earth Circumference 40080 km where
o Earth circumference 40080 km = the 5inner planet diameters total
o And based on that the inner planets diameter are defined in earth circumference definition…

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Equation No. (11)
9.52 hours x 16.1 hours = 153.3 hours (Pluto Day Period)
- 9.52 hours is the period Jupiter needs to move a distance = its circumference and this period is very near to Jupiter day
period (9.9 hours with error 4%)
- Equation No. (11) shows more interaction is done between Jupiter day period (approximately) with Neptune day period
(16.1 hours), where this interaction cause to create Pluto day period (153.3 hours)
- It's so important to see the different interaction forms, but this one has massive significance because Neptune energy is
found by Jupiter – simply Neptune had no orbit and used 14 % of Jupiter energy to built its orbit and by that all Neptune
energy is Jupiter energy, and because of that, Neptune data shows frequently Jupiter effect in its creation.
- In next pages, I provide tables for references and the moon orbital triangle revision to be used in our discussions.

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1st
Table (The Planet Circumference And Its Day Period) (An Old Table)
Planet and its day
period
Its Circumference Its Motion distance
during its day period
The rate
Mercury 175.94 days 15334 km 720.7 million km 47000
Venus 116.75 days 38041 km 352.4 million km 9280
Earth moon 29.53 days 10921 km 71.16 million km 6510
The Earth 24 hours 40080 km 2.58 million km 64.3
Mars 24.7 hours 21346.6 km 2.1467 million km 100.5
Jupiter 9.9 hours 449197.5 km 466884 km 4%
Saturn 10.7 hours 378675 km 373644 km 1.3%
Uranus 17.2 160656.5 km 421056 km 2.62
Neptune 16.1 155660 km 312984 km 2
Pluto 153.3 7511.4 km 2.59 million km 345.3
Total 1277423 km 1153.15 million km 902.7
- Please Note
- The Paper Discussion Will Be Started After The Tables Of Data (2 Tables Only)

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Table (Planet motion degrees relative to different periods of time)
- Planet motion distance degrees per a solar day period (P. M. S) Planet days periods during its orbital period (P.D.O)
- Planet rotation periods during its orbital period (P.R.O) Planet motion distance per its day period (P. M. Dist)
- Planet motion distance degrees per its day period (P. M. D) Planet motion distance per its rotation (P. M. R. Dist)
- Planet motion distance degrees per its rotation period (P. M. R)
Planet P. M.S. P.D.O P.R.O (P. M. Dist) P.M.D. P. M. R. Dist P.M.R.
Mercury 4.095 mkm = 4.09 deg 0.5 days 1.5 rotations 720.7 m km 720.7 deg 240 mkm 240 deg
Venus 3.02 mkm = 1.6 deg 1.929 days 0.924 rotations 352.4 mkm 186.56 deg 733.8 mk 388.5 deg
Moon 88000 km = 13.18 deg 13.2 days 0.924 rotations 71.16 mkm - 65.8 mkm -
Earth 2.58 mkm = 0.985deg 365.25 days 366.7 rotations 2.58 mkm 0.98562 d 2.56 mk 0.9817 deg
Mars 2.082 mkm = 0.524 deg 667.5 days 670.2 rotations 2.146 m km 0.539 deg 2.138 m 0.5371 deg
Jupiter 1.1318 mkm = 0.083 deg 10495 days 10495 rotations 466884 km 0.0343 d 466884 km 0.0343 d
Saturn 0.838 mkm = 0.03349 24113.8 days 24113.8 rotation 373644 km 0.014929d 373644 km 0.014929d
Uranus 0.587 mkm = 0.01176 42880.3 days 42880.3 rotation 421056 km 0.00839 421056 km 0.00839
Neptune 0.466 mkm = 0.00602 90276.2 days 90276.2 rotation 312984 km 0.0039877 312984 km 0.0039877
Pluto 0.406 mkm = 0.003972 14324.3 days 14324.3 rotation 2.59 m km 0.025132 2.59 mkm 0.025132
Total (7.20 +0.1382 =7.342 deg) 183138 days 183129.84 1153.15 m 907.2+1.6067 1048.5 628.5+1.605
(940 mkm /71.16 mkm)= 13.2 =27.3 degrees
The moon moves per solar day 3 distances (1st
) 2.58 mkm (2nd
) 2.41 mkm (3rd
) 88000 km
- During 27.3 days , the moon moves (1st
) 71 mkm (2nd
) 65.8 mkm (3rd
) 2.41
- During 29.53 days , the moon moves (1st
) 76.2 mkm (2nd
) 65.8 mkm (3rd
) 2.58 mkm
- The moon orbital circumferences are (940 mkm, 2.58 mkm, 2.41 mkm and 2.28 mkm).
- The degrees (940/2.58= 0.985 deg) (940/2.41= 0.9365 deg) (940/0.00088 =0.0337), (2.58/0.88 =12.286 deg) (2.28/0.88=13.9)

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More Analysis In The Moon Orbital Triangle
Basic Data Correction And Revision

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Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees
Let's review and correct the moon orbital triangle data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the outer circle is apogee orbit – and we have calculated the
tangent AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2 angles will correct many data in the
orbital triangle.

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(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT the moon position in T. solar eclipse,
because the distance BC= 86000 km but the distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =47513.7 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg) (ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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References
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis) https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of publications: http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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