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IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar Eclipse (Questions And Answers)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –16th
July 2022
Abstract
Paper objective
The paper answers the following questions
1. Can each planet orbital distance depend on its neighbor planet orbital distance? In
this case how the distance between the sun and Pluto be created? (Can One Map
Be Drawn For All Planets Orbital Distances?)
2. Is There a necessity to create a proportionality between planet diameter and orbital
distance?
3. Can Planet rotation period be defined based on its velocity?
4. Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its
Orbital Distance And By That This Planet Will Not Be Broken Through Its
Motion?)
5. Why Does Venus Have The Longest Rotation Period In The Solar System?
6. Can Planet orbital Distance be Defined before this planet creation? where planet
orbital distance be defined based on its neighbor orbital distance?
7. Why Doesn't The Planet Break After Its Creation?
8. Planet data be (Mass – Diameter- Orbital Distance- Period –Inclination….etc)
what data be created at first and what be created later?
9. Explain The Relationship Between Planet Diameter And Orbital Distance?
10. Why does the moon orbital period = the moon rotation period (No For Tidal
Locking – this idea is wrong)?
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
11.Can The Planets Velocities Total Be Defined At First And Each Planet Velocity
Be A Function In This Total?
12- Can Solar System Depend On One Geometrical Design?
13- Why Does The Moon Orbital Apogee Radius = 406000 km?
14- Can Mars Orbital Distance Be Changed From 84 million km to 228 million km?
15- Did Newton realize The Solar system Motion Logic?
16- How Be The Sun Disc Created?
Paper reference
The Solar Eclipse Phenomenon Analysis (Revised)
https://www.academia.edu/83032629/The_Solar_Eclipse_Phenomenon_Analysis_Revised_
or
https://app.box.com/s/i9a544tf79wzo7ly1id22dd8jtjc5w9c
Please enjoy the reading - kind regards (Please scan the figure (ORCID)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com, mrwaheid1@yahoo.com
gergesgerges@yandex.ru
ORCID https://orcid.org/0000-0002-1041-7147
Facebook https://www.facebook.com/gergis.tawadrous
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PUBLICATIONS
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Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous
Slideshare https://www.slideshare.net/Gergesfrancis
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
The Answers
Answer No.(1)
Can each planet orbital distance depend on its neighbor planet orbital distance? In this
case how the distance between the sun and Pluto be created? (Can One Map Be
Drawn For All Planets Orbital Distances?)
- The distance from the sun to Pluto has 3 features
- (1st
Feature)
- Each planet orbital distance depends on its neighbor planet orbital distance – my
first equation proves that - my first equation tells
- d2
= 4d0 (d-d0)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
- Example No. (1) (Venus)
- (108.2)2
= 4 x 57.9 x (50.3)
- d= 108.2 million km = Venus Orbital Distance
- d0= 57.9 million km = Mercury Orbital Distance
- 50.3 million km = The Distance Between Venus And Mercury
- Venus Depends On Mercury
- By that,
- My first equation proves planet orbital distance depends on its neighbor,
- My first equation is tested on my page https://www.facebook.com/gergestawdrous2022
- (please review it)
- Notice
- My first equation provides a clear concept states (Each planet orbital distance
depends on its neighbor planet orbital distance), by that the planet be forced for its
orbital distance because it's defined by its neighbor and not by any planet data.
- (2nd
Feature)
- The distance from the sun to Pluto depends on 2 columns (Jupiter and Pluto),
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
- Means
- Each planet orbital distance depends on its neighbor orbital distance
- But, the whole distance from the sun to Pluto be designed based on one Map
depends on the 2 columns (Jupiter and Pluto) – The data proves this fact.
Data
(1)
37100 million km – 4900 million km = 32200 million km
32200 million km x π = 100733 million km
Where
100733 million km = The planets orbital circumferences total
37100 million km = Pluto Orbital Circumference
4900 million km = Jupiter Orbital Circumference
(2)
Jupiter Orbital Circumference = 4900 million km
Uranus needs 4900 days to pass a distance = Uranus Orbital Distance
(3)
Light (300000 km/s) travels during 16330 sec a distance = 4900 million km
Light (1160000 km/s) travels during 4222.6 sec a distance = 4900 million km
16330 hours = Mars orbital period and 4222.6 hours = Mercury Day period
Discussion
- The data no. (1) proves the idea - because
- The 3 values (4900 , 37100 and 100733) depend on one another, any 2 values
enable us to conclude the third one theoretically
- Means, If we know Jupiter orbital circumference =4900 million km and The
planets orbital circumferences total = 100733 million km, We can conclude
theoretically Pluto orbital circumference =37100 million km – We do that by using
the data no. (1)
- The distances map is a simple idea and be clear from data
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
- The basic point is the distance 4900 million km (Jupiter orbital circumference),
because it has a wide range of effect on all planets motions – that because – Jupiter
is the base in both maps (distance and velocity maps)
- Let's review the using of the distance 4900 million km
- (1)
- The inner planets orbital circumferences total be (Mercury 360 mkm + Venus 680
mkm + Earth 940 mkm + Mars 1433 mkm + 1433 mkm) = 4900 million km (1%)
- The total = 4900 million km but the distance (1433 mkm) be used 2 times!
- (2)
- Jupiter Orbital Circumference (4900 million km)
- (3)
- Uranus needs 4900 days to pass a distance = Uranus Orbital Distance
- Neptune needs 2 x 4900 days to pass a distance = Neptune Orbital Distance (2%)
- Pluto needs 3 x 4900 days to pass a distance = Pluto Orbital Distance (1%)
- (4)
- (10747 /9800) = (9800 /9007)
- 10747 days = Saturn Orbital Period
- 9007 million km = Saturn Orbital Circumference
- 9800 = 2 x 4900
- The data tells that, the value 4900 be used by all planets (in different units)
- The distance for Jupiter (and the inner planets) be used as a period of time for
Uranus, Neptune and Pluto–and Saturn uses this value as a distance and as a period
- We can conclude
- The distance 4900 million km is the central one in the solar system design for that
reason Jupiter be a column in both maps (distance and velocity)
- The data proves the idea clearly – that
- One map of distance be used the solar planets distances distribution and in this
map Jupiter and Pluto be used as the 2 basic points (or columns)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
- Mercury point discussion will extend this vision and cause it to be so rich – we
discuss it in the proof no. (3) ((3) Mercury is the origin point (of the distance)
- Notice
- 100733 million km = 928 million km x 108.2
- Where
- 100733 million km = The planets orbital circumferences total
- 928 million km = Jupiter Earth Distance when be on 2 different sides
(928 mkm = 149.6 mkm + 778.6 mkm)
- 108.2 million km = Venus orbital distance
- This data shows Venus and the Earth distances be effective in definition of the
solar planets orbital circumferences total (100733million km) but no one of them
be used in the Map of distances because Jupiter and Pluto data shows clearly that
they are the columns – but still Venus and Earth have effective role we need to
discover later -
- (3rd
Feature)
- Mercury be used as an origin point for the 2 planets (Jupiter and Pluto), the data
proves that
(1)
4222.6 seconds x 1.16 million km /sec = 4900 million km
(2)
5040 seconds x 1.16 million km /sec = 5848 million km
Discussion
- Data no. (1) tells that, light supposed velocity (1160000 km/s) travels during
4222.6 seconds a distance = 4900 million km (Jupiter orbital circumference)
- Mercury day period =4222.6 hours
- The light uses each one hour as one second
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
- This data tells, Jupiter orbital circumference be defined based on Mercury Motion
data (Mercury day period) and that tells Mercury be used as a reference to define
Jupiter orbital distance.
- Data no. (2) tells that, light supposed velocity (1160000 km/s) travels during 5040
seconds a distance = 5848 million km (Mercury Pluto Distance)
- Pluto position also be defined by light motion based on Mercury data
- because
- Mercury day period needs 5040 seconds to be =4224 hours
- The type of motion is unknown and for that the importance of the period 5040 s is
undefined but both periods are related to Mercury motion –
- Means
- Mercury is the point of origin to define the 2 positions (Jupiter and Pluto) but the
using methods and types of motions are unknown
- The data proves the idea
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
Answer No.(2)
Is There a necessity to create a proportionality between planet diameter and orbital
distance?
- Yes,
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's explain that in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion –
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
- My fourth equation proves that,
- Planet diameter be a function in its rotation period and the rotation period be a
function in its velocity and the velocity be a function in its orbital distance (kepler
law)
- My fourth equation be tested here https://www.facebook.com/gergestawdrous2022
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
Answer No.(3)
Can Planet rotation period be defined based on its velocity?
- My fourth equation proves this fact
- Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination ( a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- Notice / (The Equation Works From The Earth To Pluto Only)
- Let's use one example
Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter
9.7 km/s = Saturn velocity
5.4 km/s = Neptune velocity
59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
- By this equation Planet diameter be created as a function in its rotation period and
the rotation be a function in its velocity
- The example explains the idea clearly –
- The equation still needs explanation – because the strange planet its velocity (v1)
can't be defined by any rule we search for the minimum error – for that- Saturn
velocity be used for Neptune Equation –let's provide the equation list:
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Pluto Equation uses the Earth moon velocity (As Jupiter)
- My fourth equation be tested on https://www.facebook.com/gergestawdrous2022
- A Question
- Why Does The Equation Work From The Earth To Pluto Only?
- Let's answer in following…
- The moon rotation period = its orbital period =27.3 days
- By that for the moon (s) = 1
- So the equation depends on the moon cycles equality
- And
- The equation ends with Pluto – where Pluto also provide 2 equal values which are
- s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h)
- and
- Pluto needs 14547 solar days to move a distance = Pluto orbital distance
- the numbers (14178 and 14547) are equal approximately (error 2.5%) and this
equality of Pluto cycles be in comparison with the moon cycles equality
- Here the moon and Pluto work as 2 terminals of the equation – both provide 2
equal values– these 2 equal values be found to enable the equation to create a
function between the planets diameters and their rotation periods and also between
these planets rotation periods and their velocities
- Now
- The moon orbital period = the moon rotation period NOT because of the tidal
locking – the idea is wrong – they are equal because of my fourth equation –
- The equality of the cycles is necessary to enable the equation to create the required
functions between planet diameter and rotation period and between planet rotation
period and velocity.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
12
- I want to say
- My fourth equation refers to a geometrical effect be found between the moon and
Pluto motions passing through all planets data – where this effect enables the
equation to create the required functions (diameter with rotation period) and
(rotation period with velocity), this geometrical effect guarantees the equation
works for all planets to create all diameters under the one equation by that all
diameters be in harmony with their planets orbital distances by indirect
relationship which saves the planets in their motions and also in their migrations in
case of any planet migration from its original orbital distance.
- Notice
- (29.53/27.3) = (243/224.7)= 1.0725
- Where
- 29.53 days = The Moon Day Period
- 27.3 days = The Moon Orbital Period
- 243 days = Venus Rotation Period
- 224.7 days = Venus Orbital Period
- This data tells, there's a consistency between the moon and Venus cycles periods,
this consistency is required because the equality between the moon orbital period
and rotation period forms the base on which my fourth Equation depends – means
– the system by which the planets diameters be defined as function in their
rotations and then velocities and then orbital distances – this system depends on
the equality of the moon 2 cycles periods – and this equality be supported by
Venus Cycles in addition to the moon cycles – that means- the system depends on
the moon motion but the moon motion be supported strongly by Venus motion, for
that the cycles equality be strong value because it be consisted of 2 planets cycles
integration – and by that the moon and Venus consist together a strong base on
which the system depends
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
13
Answer No.(4)
- Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its
Orbital Distance And By That This Planet Will Not Be Broken Through Its
Motion?)
- NOT A DIRECT ONE
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's deepen our discussion in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion –
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
14
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
- My fourth equation proves planet diameter be created a function in its rotation
period and the rotation be created a function in its velocity
- Notice
- My first equation proves each planet orbital distance depends on its neighbor
planet orbital distance.
- My first equation (d2
= 4d0 (d-d0))
- d = A Planet Orbital Distance d0= Its Previous Neighbor Orbital Distance
- My equations be tested on https://www.facebook.com/gergestawdrous2022
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
15
Answer No.(5)
- Why Does Venus Have The Longest Rotation Period In The Solar System?
- For answer we have to review my fourth equation here – let's do it
- My theory tells based on one geometrical design the solar system be created – it
deals with the solar planets as members in one creature body – they are created
complementary with one another and in proportionality with one another.
- Here we deal with the solar system starts from the sun to Pluto as one piece of
distance and as one unified motion – and we don't deal with any individual point or
planet instead we deal with the whole system as One Machine
- The solar system design (the machine design) uses 2 maps one for distance and
one for velocity – Let's explain that in following..
- (POINT NO. 1) THE MAP OF DISTANCES
- The distance from the sun to Pluto be distributed based on one rule by my first
equations (d2
= 4d0 (d-d0) where (d= planet orbital distance) and (d0 it neighbor)
- The equation tells, each planet orbital distance be defined based on its neighbor
orbital distance – by that no any other data be used to define the distance –
- shortly
- Planet orbital distance be defined based on its neighbor planet orbital distance, as a
result the distances be defined based on one another and no other data be required
- Briefly
- If (Mercury Orbital Distance =57.9 million km), by using my first equation and
this one data we can conclude by mathematical calculations only all planets orbital
distances – no any other data be required neither mass nor diameter – the distances
be defined based on one another
- That tells the designer deals with the distance from the sun to Pluto as one piece of
distance which be distributed geometrically based on one rule or one design.
- That tells also –
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
16
- The distances be somehow forced values for the planets – because they be
distributed geometrically by that the planets be forced to be in their positions.
- The distances map uses 2 columns which are (Jupiter and Pluto)
- The data proves this fact we should discuss in the proof discussion
- Briefly
- There are 2 features of the distances map which are
- (1st
Feature)
- Planets orbital distances be distributed geometrically based on one another by
using my first equation (d2
= 4d0 (d-d0) and regardless any planet data.
- (2nd
Feature)
- The distances map uses 2 columns which are (Jupiter and Pluto)
- Means,
- If we know Jupiter and Pluto orbital distances we can conclude all planets orbital
circumferences total without any equation – the data proves that-
- Simply,
- The solar planets orbital circumferences total depends on Jupiter and Pluto orbital
distances – that means – these 3 players consist the whole system – any 2 values
are available enable to conclude the third value theoretically and simply
- Means
- The distances distribution be done by one geometrical design based on my first
equation – but – mentioned to define the 2 columns (Jupiter and Pluto) as the basic
2 points of the whole distance creation.
- The data proves this fact
- Notice
- Mercury is the origin point based on which the 2 columns depend- means
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
17
- The solar system map of distances depends on Jupiter and Pluto orbital distances
as 2 basic columns of the map and these 2 columns depend on Mercury position as
the origin point for them. (the data will prove that)
- (POINT NO. 2) THE MAP OF VELOCITY
- The design deals with the solar planets motions as one unified motion – that be
similar to a machine of gears – where many gears move and one motion only be
produced – similar to that - the solar planets move but one unified motion only be
produced.
- The Map of velocity depends on 2 columns (Jupiter And Uranus)
- The data proves– The solar planets motions depend on the velocities of Jupiter and
Uranus.
- We have a very good reason and a group of data forces for this conclusion we will
discuss in the proof discussion.
- By that
- There's a phase between the distance and the velocity Maps because
- The map of distances depends on (Jupiter and Pluto) – but
- The map of velocities depends on (Jupiter and Uranus) –
- For the 2 maps the base is the same (Jupiter) but the distances reaches to Pluto
where the velocities be limited to Uranus – based on that -
- We have to ask
- Why does the designer need 2 maps for the distance and velocity?
- Let's answer in following…
- (A Question)
- Why does the designer need 2 maps for the distance and velocity?
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's explain that in following…
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
18
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion – The idea is clear
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
19
- Shortly
- The phase be created between Pluto (distance map) and Uranus (velocity map) be
found because of the solar planets diameters total (406000 km)
- The velocity map doesn't use Pluto as end point (as the distance map does) instead
it uses Uranus as end point – because – the 2 maps work to define the planets
diameters as indirect functions in their orbital distances and for that the planets
diameters total 406000 km be the most important distance for (Uranus, Jupiter and
Pluto) motions – we discuss that in details later.
- Now
- Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet
orbital distance and its velocity is the most basic relationship we do need in our
explanation – because – planet diameter be a function in its rotation period and the
rotation period be function in its velocity – just because – the velocity is a function
in the orbital distance – an indirect proportionality between planet orbital distance
and its diameter be created and that's the required proportionality to save the planet
in its motion.
- But,
- How do we know that planet diameter is a function in its rotation period and the
rotation period be a function in its velocity?!
- This relationship be proved by my fourth equation – here we can understand how
these relationships be created and why-
- We have to analyze the distance 406000 km and discuss my fourth equation to
explain how this machine works
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
20
- (POINT NO. 3) My Fourth Equation
- Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination ( a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- Notice / (The Equation Works From The Earth To Pluto Only)
- Let's use one example
Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter
9.7 km/s = Saturn velocity
5.4 km/s = Neptune velocity
59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
- By this equation Planet diameter be created as a function in its rotation period and
the rotation be a function in its velocity
- The example explains the idea clearly –
- The equation still needs explanation – because the strange planet its velocity (v1)
can't be defined by any rule we search for the minimum error – for that- Saturn
velocity be used for Neptune Equation –let's provide the equation list:
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Pluto Equation uses the Earth moon velocity (As Jupiter)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
21
- Notice
- Jupiter and Pluto (The Distances Map Columns) use the Earth moon velocity
- And
- Uranus and Earth (the 2 players in the velocity Map) use Neptune velocity
- A Question
- Why Does The Equation Work From The Earth To Pluto Only?
- Let's answer in following…
- The moon rotation period = its orbital period =27.3 days
- By that for the moon (s) = 1
- So the equation depends on the moon cycles equality
- And
- The equation ends with Pluto – where Pluto also provide 2 equal values which are
- s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h)
- and
- Pluto needs 14547 solar days to move a distance = Pluto orbital distance
- the numbers (14178 and 14547) are equal approximately (error 2.5%) and this
equality of Pluto cycles be in comparison with the moon cycles equality
- Here the moon and Pluto work as 2 terminals of the equation – both provide 2
equal values– these 2 equal values be found to enable the equation to create a
function between the planets diameters and their rotation periods and also between
these planets rotation periods and their velocities
- Now
- The moon orbital period = the moon rotation period NOT because of the tidal
locking – the idea is wrong – they are equal because of my fourth equation –
- The equality of the cycles is necessary to enable the equation to create the required
functions between planet diameter and rotation period and between planet rotation
period and velocity.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
22
- I want to say
- My fourth equation refers to a geometrical effect be found between the moon and
Pluto motions passing through all planets data – where this effect enables the
equation to create the required functions (diameter with rotation period) and
(rotation period with velocity), this geometrical effect guarantees the equation
works for all planets to create all diameters under the one equation by that all
diameters be in harmony with their planets orbital distances by indirect
relationship which saves the planets in their motions and also in their migrations in
case of any planet migration from its original orbital distance.
- Notice
- (29.53/27.3) = (243/224.7)= 1.0725
- Where
- 29.53 days = The Moon Day Period
- 27.3 days = The Moon Orbital Period
- 243 days = Venus Rotation Period
- 224.7 days = Venus Orbital Period
- This data tells, there's a consistency between the moon and Venus cycles periods,
this consistency is required because the equality between the moon orbital period
and rotation period forms the base on which my fourth Equation depends – means
– the system by which the planets diameters be defined as function in their
rotations and then velocities and then orbital distances – this system depends on
the equality of the moon 2 cycles periods – and this equality be supported by
Venus Cycles in addition to the moon cycles – that means- the system depends on
the moon motion but the moon motion be supported strongly by Venus motion, for
that the cycles equality be strong value because it be consisted of 2 planets cycles
integration – and by that the moon and Venus consist together a strong base on
which the system depends
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
23
- Here we can answer the question
- Venus cycles creates an equality to support the moon cycles equality –
- But the moon orbit the Earth where Venus orbit the sun by that the rotation period
of Venus has to be equal its orbital period
- By that Venus created its cycles to support the moon motion cycles to perform the
base of the equation
- Notice
- The rate 1.0725 we have discussed frequently before and it be found for a
geometrical necessity.
- Please review the paper Reference
- (The Solar Eclipse Phenomenon Analysis (Revised))
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
24
- Answer No.(6)
- Can Planet orbital Distance be Defined before this planet creation? where planet
orbital distance be defined based on its neighbor orbital distance?
- In this question we need to prove only the fact tells
- (Planet orbital distance depends on its neighbor planet orbital distance)
- Because,
- If planet orbital distance depends on its neighbor, that tells this distance can be
defined before creation – it's a simple idea –
- Imagine we are in some crowded bus – the other people pushes you and forces you
to stand in some place – you can't change your place because they force you, by
that this place was defined before you come into the bus – it was the most crowded
place and every one left it for you!
- My first equation proves that ,planet orbital distance depends on its neighbor
planet orbital distance – let's remember it here – it tells
- d2
= 4d0 (d-d0)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
- Example No. (1) (Venus)
- (108.2)2
= 4 x 57.9 x (50.3)
- d= 108.2 million km = Venus Orbital Distance
- d0= 57.9 million km = Mercury Orbital Distance
- 50.3 million km = The Distance Between Venus And Mercury
- Venus Depends On Mercury
- By that,
- My first equation proves planet orbital distance depends on its neighbor,
- My first equation is tested on my page https://www.facebook.com/gergestawdrous2022
- (please review it)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
25
- Answer No.(7)
- Why Doesn't The Planet Break After Its Creation?
- Because
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's explain that in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion –
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
26
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
- My fourth equation proves that,
- Planet diameter be a function in its rotation period and the rotation period be a
function in its velocity and the velocity be a function in its orbital distance (kepler
law)
- My fourth equation be tested on my page https://www.facebook.com/gergestawdrous2022
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
27
- Answer No.(8)
- Planet data be (Mass – Diameter - Orbital Distance- Period –Inclination….etc)
what data be created at first and what be created later?
- The planet orbital distance is created first before any other data – because – any
planet orbital distance depends on its neighbor planet orbital distance-
- My first equation proves this fact –
- By that the planet orbital distance be defined before its creation because this
distance doesn't depend on any data of the planet – but depends on its previous
neighbor orbital distance- and by that the distance be defined before the creation
and we can consider the planet orbital distance be defined firstly before any other
planet data be created – let's review my first equation in following – it tells
- d2
= 4d0 (d-d0)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
- Example No. (1) (Venus)
- (108.2)2
= 4 x 57.9 x (50.3)
- d= 108.2 million km = Venus Orbital Distance
- d0= 57.9 million km = Mercury Orbital Distance
- 50.3 million km = The Distance Between Venus And Mercury
- Venus Depends On Mercury
- By that,
- My first equation proves planet orbital distance depends on its neighbor,
- My first equation is tested on my page https://www.facebook.com/gergestawdrous2022
- (please review it)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
28
- Answer No.(9)
- Explain The Relationship Between Planet Diameter And Orbital Distance?
- There's a necessity to create a proportionality between planet diameter and orbital
distance – because
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's explain that in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion –
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
29
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
- My fourth equation proves that,
- Planet diameter be a function in its rotation period and the rotation period be a
function in its velocity and the velocity be a function in its orbital distance (kepler
law)
- My fourth equation be tested on my page https://www.facebook.com/gergestawdrous2022
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
30
Answer No.(10)
- Why does the moon orbital period = the moon rotation period (No For Tidal
Locking – this idea is wrong)?
- To answer this question we need to review my fourth equation, let's do that…
- My theory tells based on one geometrical design the solar system be created – it
deals with the solar planets as members in one creature body – they are created
complementary with one another and in proportionality with one another.
- Here we deal with the solar system starts from the sun to Pluto as one piece of
distance and as one unified motion – and we don't deal with any individual point or
planet instead we deal with the whole system as One Machine
- The solar system design (the machine design) uses 2 maps one for distance and
one for velocity – Let's explain that in following..
- (POINT NO. 1) THE MAP OF DISTANCES
- The distance from the sun to Pluto be distributed based on one rule by my first
equations (d2
= 4d0 (d-d0) where (d= planet orbital distance) and (d0 it neighbor)
- The equation tells, each planet orbital distance be defined based on its neighbor
orbital distance – by that no any other data be used to define the distance –
- shortly
- Planet orbital distance be defined based on its neighbor planet orbital distance, as a
result the distances be defined based on one another and no other data be required
- Briefly
- If (Mercury Orbital Distance =57.9 million km), by using my first equation and
this one data we can conclude by mathematical calculations only all planets orbital
distances – no any other data be required neither mass nor diameter – the distances
be defined based on one another
- That tells the designer deals with the distance from the sun to Pluto as one piece of
distance which be distributed geometrically based on one rule or one design.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
31
- That tells also –
- The distances be somehow forced values for the planets – because they be
distributed geometrically by that the planets be forced to be in their positions.
- The distances map uses 2 columns which are (Jupiter and Pluto)
- The data proves this fact we should discuss in the proof discussion
- Briefly
- There are 2 features of the distances map which are
- (1st
Feature)
- Planets orbital distances be distributed geometrically based on one another by
using my first equation (d2
= 4d0 (d-d0) and regardless any planet data.
- (2nd
Feature)
- The distances map uses 2 columns which are (Jupiter and Pluto)
- Means,
- If we know Jupiter and Pluto orbital distances we can conclude all planets orbital
circumferences total without any equation – the data proves that-
- Simply,
- The solar planets orbital circumferences total depends on Jupiter and Pluto orbital
distances – that means – these 3 players consist the whole system – any 2 values
are available enable to conclude the third value theoretically and simply
- Means
- The distances distribution be done by one geometrical design based on my first
equation – but – mentioned to define the 2 columns (Jupiter and Pluto) as the basic
2 points of the whole distance creation.
- The data proves this fact
- Notice
- Mercury is the origin point based on which the 2 columns depend- means
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
32
- The solar system map of distances depends on Jupiter and Pluto orbital distances
as 2 basic columns of the map and these 2 columns depend on Mercury position as
the origin point for them. (the data will prove that)
- (POINT NO. 2) THE MAP OF VELOCITY
- The design deals with the solar planets motions as one unified motion – that be
similar to a machine of gears – where many gears move and one motion only be
produced – similar to that - the solar planets move but one unified motion only be
produced.
- The Map of velocity depends on 2 columns (Jupiter And Uranus)
- The data proves– The solar planets motions depend on the velocities of Jupiter and
Uranus.
- We have a very good reason and a group of data forces for this conclusion we will
discuss in the proof discussion.
- By that
- There's a phase between the distance and the velocity Maps because
- The map of distances depends on (Jupiter and Pluto) – but
- The map of velocities depends on (Jupiter and Uranus) –
- For the 2 maps the base is the same (Jupiter) but the distances reaches to Pluto
where the velocities be limited to Uranus – based on that -
- We have to ask
- Why does the designer need 2 maps for the distance and velocity?
- Let's answer in following…
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
33
- (A Question)
- Why does the designer need 2 maps for the distance and velocity?
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely –
let's explain that in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will
be broken through its motion – The idea is clear
- We have a distance be defined by force - for that – we have to create the diameter
as a function in this distance to support the planet safe motion otherwise this planet
will be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and
its diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet
diameter will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its
orbital distance but has to create it as indirect proportionality to save the planet
- For that reason
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but
this proportionality contains also the planet rotation period and velocity – why?
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
34
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on
velocity (change in velocity value) and then effect on the diameter (change in the
diameter) by small value and doesn't cause to break the planet – the effect causes
planet suffering but not death.
- Shortly
- The phase be created between Pluto (distance map) and Uranus (velocity map) be
found because of the solar planets diameters total (406000 km)
- The velocity map doesn't use Pluto as end point (as the distance map does) instead
it uses Uranus as end point – because – the 2 maps work to define the planets
diameters as indirect functions in their orbital distances and for that the planets
diameters total 406000 km be the most important distance for (Uranus, Jupiter and
Pluto) motions – we discuss that in details later.
- Now
- Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet
orbital distance and its velocity is the most basic relationship we do need in our
explanation – because – planet diameter be a function in its rotation period and the
rotation period be function in its velocity – just because – the velocity is a function
in the orbital distance – an indirect proportionality between planet orbital distance
and its diameter be created and that's the required proportionality to save the planet
in its motion.
- But,
- How do we know that planet diameter is a function in its rotation period and the
rotation period be a function in its velocity?!
- This relationship be proved by my fourth equation – here we can understand how
these relationships be created and why-
- We have to analyze the distance 406000 km and discuss my fourth equation to
explain how this machine works
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
35
(Point No.3) My Fourth Equation
- Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination ( a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- Notice / (The Equation Works From The Earth To Pluto Only)
- Let's use one example
Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter
9.7 km/s = Saturn velocity
5.4 km/s = Neptune velocity
59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
- By this equation Planet diameter be created as a function in its rotation period and
the rotation be a function in its velocity
- The example explains the idea clearly –
- The equation still needs explanation – because the strange planet its velocity (v1)
can't be defined by any rule we search for the minimum error – for that- Saturn
velocity be used for Neptune Equation –let's provide the equation list:
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Pluto Equation uses the Earth moon velocity (As Jupiter)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
36
- Notice
- Jupiter and Pluto (The Distances Map Columns) use the Earth moon velocity
- And
- Uranus and Earth (the 2 players in the velocity Map) use Neptune velocity
- A Question
- Why Does The Equation Work From The Earth To Pluto Only?
- Let's answer in following…
- The moon rotation period = its orbital period =27.3 days
- By that for the moon (s) = 1
- So the equation depends on the moon cycles equality
- And
- The equation ends with Pluto – where Pluto also provide 2 equal values which are
- s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h)
- and
- Pluto needs 14547 solar days to move a distance = Pluto orbital distance
- the numbers (14178 and 14547) are equal approximately (error 2.5%) and this
equality of Pluto cycles be in comparison with the moon cycles equality
- Here the moon and Pluto work as 2 terminals of the equation – both provide 2
equal values– these 2 equal values be found to enable the equation to create a
function between the planets diameters and their rotation periods and also between
these planets rotation periods and their velocities
- Now
- The moon orbital period = the moon rotation period NOT because of the tidal
locking – the idea is wrong – they are equal because of my fourth equation –
- The equality of the cycles is necessary to enable the equation to create the required
functions between planet diameter and rotation period and between planet rotation
period and velocity.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
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- I want to say
- My fourth equation refers to a geometrical effect be found between the moon and
Pluto motions passing through all planets data – where this effect enables the
equation to create the required functions (diameter with rotation period) and
(rotation period with velocity), this geometrical effect guarantees the equation
works for all planets to create all diameters under the one equation by that all
diameters be in harmony with their planets orbital distances by indirect
relationship which saves the planets in their motions and also in their migrations in
case of any planet migration from its original orbital distance.
- Notice
- (29.53/27.3) = (243/224.7)= 1.0725
- Where
- 29.53 days = The Moon Day Period
- 27.3 days = The Moon Orbital Period
- 243 days = Venus Rotation Period
- 224.7 days = Venus Orbital Period
- This data tells, there's a consistency between the moon and Venus cycles periods,
this consistency is required because the equality between the moon orbital period
and rotation period forms the base on which my fourth Equation depends – means
– the system by which the planets diameters be defined as function in their
rotations and then velocities and then orbital distances – this system depends on
the equality of the moon 2 cycles periods – and this equality be supported by
Venus Cycles in addition to the moon cycles – that means- the system depends on
the moon motion but the moon motion be supported strongly by Venus motion, for
that the cycles equality be strong value because it be consisted of 2 planets cycles
integration – and by that the moon and Venus consist together a strong base on
which the system depends
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Gerges Francis Tawdrous/
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Answer No.(11)
Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A
Function In This Total?
The Question Explanation
My theory tells (One Geometrical Design Be Found Behind The Solar System) –
means- the planets motions be integrated and produce One Unified Motion – As A
Machine Of Gears Produces One Motion-
Based on this theory
Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A
Function In This Total?
Or
Can The Solar System Design Use One Map To Distribute The Planets Velocities?
YES
The design deals with the solar planets motions as one unified motion – that be
similar to a machine of gears – where many gears move and one motion only be
produced – similar to that - the solar planets move but one unified motion only be
produced.
The Map of velocity depends on 2 columns (Jupiter And Uranus)
The data proves– The solar planets motions depend on the velocities of Jupiter and
Uranus.
We have a very good reason and a group of data forces for this conclusion we will
discuss in the proof discussion.
Let's provide them in following…
THE PROVES
Data
(A)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
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Where
100733 million km = The Planets Orbital Circumferences Total
197393 days = The Planets Orbital Periods Total
1.16 million km/s = Light Supposed Velocity
0.6 million km/s = 2 x 0.3 million km/s (Light Velocity)
1.1318 million km/day = Jupiter Velocity Per A Solar Day
0.5875 million km/day = Uranus Velocity Per A Solar Day
(B)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
1.16 million km/s = Light Supposed Velocity
0.6 million km/s = 2 x 0.3 million km/s (Light Supposed Velocity)
47.4 km/s = Mercury Velocity 24.1 km/s = Mars Velocity
35 km/s = Venus Velocity 17.9 km/s = Ceres Velocity
13.1 km/s = Jupiter Velocity
6.8 km/s = Uranus Velocity
Discussion
Data No. (A) shows the planets orbital circumferences and periods total depend on the
2 planets (Jupiter and Uranus) velocities in comparison with the 2 velocities of light
(the known velocity 300000 km/s and the supposed velocity 1160000 km/s)
Data No. (B) shows that, the rate of velocities between (Jupiter and Uranus) be used
also by (Mars and Mercury) and by (Venus and Ceres) –
But
No any couple can be replaced in place of (Jupiter and Uranus) in Data no. (A) – that
shows, the planets orbital circumferences and periods be related to (Jupiter and
Uranus) velocities and not to any other couple of planets – they are the 2 basic players
in the design structure -
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The data proves the idea tells
One Map of velocity be used for all planets velocities and in this map Jupiter and
Uranus are the 2 basic points (or 2 columns)
ANOTHER QUESTION
The solar system map of distances depends on (Jupiter and Pluto)
But
The solar system map of velocities depends on (Jupiter and Uranus)
Why does the designer need 2 maps for the distance and velocity? Why Not One Map
for both?
- The designer has to create a proportionality between each planet diameter and its
orbital distance – because – by this proportionality the planet can move safely – let's
explain that in following…
- Planet orbital distance be a forced value for it, because each planet orbital distance
depends on its neighbor orbital distance, by that the planet isn't free to choose its
orbital distance and planet data isn't a player to define its orbital distance – instead
planet orbital distance be a forced value for it defined by its neighbor position.
- If this planet diameter be not in harmony with its orbital distance this planet will be
broken through its motion – The idea is clear
- We have a distance be defined by force - for that – we have to create the diameter as
a function in this distance to support the planet safe motion otherwise this planet will
be broken.
- Here we find one job for the designer
- The designer has to find a proportionality between the planet orbital distance and its
diameter - But
- If the planet diameter be a direct function in its orbital distance, this planet diameter
will be broken if this planet migrate from its orbital distance
- The situation be as that
- The designer has to create the proportionality between planet diameter and its orbital
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distance but has to create it as indirect proportionality to save the planet
- For that reason
- The designer created the planet diameter a function in its rotation period, and the
rotation period be a function in its velocity and its velocity a function in its orbital
distance –
- Here we have a proportionality between planet orbital distance and diameter, but this
proportionality contains also the planet rotation period and velocity – why?
- Because - If the planet migrates and changes its orbital distance, the shock of this
migration will effect on the rotation (change in rotation period) and effect on velocity
(change in velocity value) and then effect on the diameter (change in the diameter) by
small value and doesn't cause to break the planet – the effect causes planet suffering
but not death.
- Shortly
- The phase be created between Pluto (distance map) and Uranus (velocity map) be
found because of the solar planets diameters total (406000 km)
- The velocity map doesn't use Pluto as end point (as the distance map does) instead it
uses Uranus as end point – because – the 2 maps work to define the planets diameters
as indirect functions in their orbital distances and for that the planets diameters total
406000 km be the most important distance for (Uranus, Jupiter and Pluto) motions –
we discuss that in details later.
- Now
- Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet
orbital distance and its velocity is the most basic relationship we do need in our
explanation – because – planet diameter be a function in its rotation period and the
rotation period be function in its velocity – just because – the velocity is a function in
the orbital distance – an indirect proportionality between planet orbital distance and
its diameter be created and that's the required proportionality to save the planet in its
motion.
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- But,
- How do we know that planet diameter is a function in its rotation period and the
rotation period be a function in its velocity?!
- This relationship be proved by my fourth equation – here we can understand how
these relationships be created and why-
We have to analyze the distance 406000 km and discuss my fourth equation to explain
how this machine works
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Answer No. (12)
Can Solar System Depend On One Geometrical Design?
What does mean (One Geometrical Design)?
The solar planets move a s pieces of the chess game – each planet motion depends on
mathematical calculations and geometrical rules in comparison to the other planets –
and as in the chess game –the players are teams and enemies but all of them are
members in the same battle and they consist its structure- no one moves individually
or independently
It's the general idea – let's try to examine and test if it can be a fact
(1)
We accepted that (Newton Theory Of The Sun Gravity Is Wrong In Logic) basically
because – The planet should be created and moving by the same one force – means-
the force which created the planet it causes its motion – otherwise this planet will be
broken because 2 forces effect on it-
That tells, no planet moves by the sun gravity, because no planet be created by the sun
gravity effect.
But why the sun be found in the solar system if it doesn't cause any planet motion?
And
How Does The Planet Move If The Sun Doesn't Cause That?
Shortly
The planet creation and motion depends on one force only and for that this planet
creation and motion data be in harmony one another-
But - There are no 9 forces to cause the 9 planets creations and motions - instead –
it's just one force causes all planets creation and motion – this vision tells that – this
one force uses a geometrical design to cause the planets creation and motion.
Briefly
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One force causes all planets creation and motion by using One Geometrical Design
to do these 2 jobs (the creation and motion)
(2)
What's This One Geometrical Design? Can We Discover It?
Let's see this idea
The solar planets and their distances be created from one energy – this one energy
was in one geometrical design by that the planets be created by this One Geometrical
Design. And this geometrical design controls the planets creation and motion data for
that the planets data be created based on exact equations – we have discovered that
and proves it before – because I have 5 equations based on which the planets data be
created where we have explained before that the planet creation and motion data be
similar to any plane or rocket creation data depends on exact equations to enable its
motion to be done without negative effects.
By that – My 5 Equations Prove That The Planets Creation And Motion Depends On
One Geometrical Design.
Notice (My 5 Equations Be Tested And Proved In Point No. 2)
Shortly,
My 5 equations prove one geometrical design be found behind the solar system
(3)
Now do we realize this meaning (One Geometrical Design)?
The idea tells (from one energy the planets and their distances be created), can we
have any particles be created from the same energy? from gamma ray electron and
positron be created, also the male and female creatures refer to similar system of
creation –
How do the 2 particles (or 2 creatures) behave after creation? They have attraction for
one another – What Does Mean Attraction?
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The electron and position attraction will cause the annihilation and produce Gamma
ray – but the (male and female) creatures give more wide of the attractions (forms)
Some one carries flowers for his wife – and so – why these flowers effect on their
attraction?
From one energy the 2 particles are created and they have to produce this one energy
one more time to save the cycle and give chance for more particles to be created – if
the 2 particles be in fighting their energies will be consumed in vain losing their
chance of existence and the other (potential) particles chance
Shortly
They have to be under attraction to cause a safety for themselves and for the potential
particles – I hope I can explain the idea
The planets motions agreement and integration is the necessary requirement for their
existence and for (potential) lives existence – they are in full agreement –
And what,
A man and his wife live in happiness – what should they do to explain that?!
The dancing planets do different forms show the agreement and integration of their
motions – they show their integration because their integration is the only hope to
produce the original energy from which they are created and give safety for the cycle.
We are very near now
The planets motions forms be seen in phenomena – as eclipses – planets alignments-
planets perpendicularity ….etc
These phenomena shows form of the integration of the planets motions which enable
to produce the original energy one more time
Let's use the solar eclipse as example to explain the idea
Eclipse Phenomenon
The sun, Earth and the moon create the conspiracy of the eclipse phenomena, they
agreed together to be on one straight line (180 degrees)
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Now (the designer) supports their conspiracy, and create the sun and moon diameters
rate to be equal their distances rate to the Earth and by that we can see the sun disc =
the moon disc and the eclipse can be occurred
The motion be done by 3 players in comparison one another – that explains the
meaning of "One Geometrical Design"
The planets creation data – for some unknown wonder – support the phenomenon by
data proportionality
The total solar eclipse be occurred and the beautiful sun be absent and return
An intelligent student asked me (What's The Result Of This Eclipse?)
I couldn't answer – The Sun Be Absent And Return – that's all
Why the 3 players interested so much to do this action? and why the designer changed
the creation data to be in proportionality to enable the eclipse to be done? What a big
deal behind?
A group of dancers do some beautiful piece of theater on stage, the people applaud
strongly – The dancers did some motions only!!
Can This Dancing Depend On Geometrical Rule?
Can the eclipse be done based on Geometrical Rule?
Let’s examine to answer
(a)
(The sun diameter/ moon diameter) =(Earth orbital distance / Earth moon distance)
And
Jupiter orbital distance = Earth orbital distance x 5.2
(5.1 degrees = The Moon Orbital Inclination)
(b)
2 x Jupiter orbital distance = Jupiter diameter x 10921 km (the moon circumference)
And
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Jupiter (13.1km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter
(c)
The sun diameter x the moon diameter = 4900 million km = Jupiter orbital
circumference = Jupiter circumference x 10921 km
We see the moon circumference (10921 km) be used as a period of time (10921 s) for
Jupiter motion – it's hard to explain how!
But
This data tells 2 information
First (the eclipse be done based on geometrical rules and calculations) second (the
used geometrical rules are unknown)
Shortly
About what does this writing argue?
The Argument
The planets and their distances be created of one energy and based on one geometrical
design which causes their creations and motions –
The planets motion have to be in harmony to integrate their energies to produce the
original energy from which they were created to save the cycle
By that, the planets move together in full agreement and harmony –
In their motions they create phenomenon caused by the one geometrical design they
depend on and these phenomenon cause more geometrical effects for the solar system
By that,
The planet be similar to a tube through which a water moves – but – the water here is
similar to geometrical effects – because by these geometrical effects the planets do the
phenomena and the phenomena itself cause more geometrical effects
The whole proves is required to show the continuous harmony and agreement without
which the original energy will never be found and the cycle will be destroyed.
Again
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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Shortly about what does this writing argue?
About the book of geometry
Because, the eclipse be created based on geometrical rule and the eclipse process
causes more geometrical effects to be created on the solar system
the book of geometry be written in the dancing planets phenomenon (eclipses,
alignments, perpendicularity…etc)
the rules are unknown, for that we need to examine in details to discover them.
The physicist have seen nothing of the party – he simply supposed – all eclipses,
alignments, perpendicularity.. etc be created by pure coincidences –
he wasn't invited to the party and the missed the whole dance.
We try to examine the planet motion as possible to know the fact.
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2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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(Answer No. 13)
Why Does The Moon Orbital Apogee Radius = 406000 km?
- First (we search for interesting data)
- The moon daily displacement =88000 km and during 29.53 solar days the
displacements total be = 2.598 million km = 2π x 413600 km
- This data is interesting – why - Because
- The data tells the moon orbital apogee radius should be 413600 km
- But, the moon orbital apogee radius in fact be =406000 km!
- And, The data tells also,
- The moon daily displacement (88000 km) be so long, because of that, the moon
should be prisoner in the orbit with radius (=413600 km) and the moon can't
revolve around the Earth through any more near orbit!
- Not fact – the moon revolves around the Earth through more near orbits and can
reach to perigee radius (363000 km)
- How to explain this interesting data?? What hypothesis can we create?
- The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level by that the real displacement (L) through the orbit be less than
(88000 km) because it be (L = 88000 km cos θ) by that the real displacement be
shorter than (88000 km) and the total displacement be less than (2.598 million km)
and that makes the moon orbital apogee radius to be decreased from 413600 km to
406000 km.
- We should pay attention to the angle (θ), because this angle controls the moon
motion features – where- with the angle (θ) increasing the real displacement (L) be
shorter and the moon can revolve around the Earth through more near orbits – but
–with the angle (θ) deceasing the real displacement (L) be longer and that pushes
the moon far from the Earth to more far orbits.
- I have an equation for the moon orbital motion depends on this angle (θ)
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- In fact, the idea of the angle (θ) solves many basic problems in the moon orbital
motion explanation – we can reach to this idea only by using the planets data
analysis method–
- For example –
- The Moon Orbital Perigee Radius = 363000 km
- The Total Solar Eclipse Radius = 373000 km
- The Moon Orbital Distance = 384000 km
- The Moon Orbital Apogee Radius = 363000 km
- But
- (363000 km)2
+ (86000 km)2
= (373000 km)2
- (373000 km)2
+ (86000 km)2
= (384000 km)2
- (384000 km)2
+ (86000 km)2
= (393500 km)2
- (393500 km)2
+ (86000 km)2
= (406000 km)2
(error 1%)
- The data simply tells that, the moon 4 basic orbital radiuses be created depending
on one another by Pythagorean rule because of the moon using of the angle (θ) in
its motion. this data should be considered one more proof for the hypothesis.
- In fact - this data provides some discovery in the moon orbital motion explanation
– and almost no one knew before that the moon orbital apogee radius should be
=413600 km and be decreased by some intelligent technique to be 406000 km –
- This whole point of discussion in the moon orbital motion was absent and
unknown because no one used the planet data analysis method in astrophysics
research.
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2nd
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(Answer No. 14)
Can Mars Orbital Distance Be Changed From 84 million km to 228 million km?
- The 3 planets (Mercury – Venus – Earth) give the interesting data! why?
- Because, the 3 planets be in order for their diameters, masses and orbital distances.
Can this order be found based on a geometrical rule? let's try to discover
- But
- Mars causes a question, because Mars causes to break this order!
- What hypothesis we need to explain this interesting data?
- The hypothesis tells (Mars Original Position Was Between Mercury And Venus)
- If this is the original position of Mars the planets order will be
- (Mercury – Mars – Venus – Earth)
- The 4 planets be in order for their diameters, masses and orbital distances
- Can we prove this hypothesis? Yes
- Mars had migrated from its original orbital distance to its current one – and Mars
in its migration motion had collided with Venus and then with Earth and Mars
itself caused to create the Earth Moon!
- Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the
Earth and caused the moon creation.
- Can Mars Itself do that? the theory tells No Hope
- But, Planets data analysis suggested that Mars had migrated from its original
orbital distance to its current one –
- Let's move with this hypothesis for a while
- Suppose Mars was the second planet after Mercury and had migrated to its current
point (227.9 million km) and Mars had collided with Venus and then with Earth –
can this idea help Giant-impact hypothesis? for example can this idea answers
(Why Does Venus Have No Moon?)
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- (a)
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushing by force
and had collided with Venus and pushed all debris with it in its motion direction
- Venus had found no debris around – for that Venus couldn't create its own moon-
- (b)
- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the
collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
- Earth gravity is greater than Venus' and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- This analysis proves that My Mars Migration theory is a correct one (point no.10)
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(Answer No. 15)
Did Newton realize The Solar system Motion Logic?
Preface
The idea tells– The Solar System Is Consisted Of One Light Beam –
The planets matters and distances be created from one light beam energy and the
planets move by this light beam motion- it's the idea shortly but I need to define 3
basic concepts before discussion
(1st
Concept) Planet Data Unification And Harmony
This is a simple idea – it tells planet data be created in harmony with one another and
be unified by this planet motion – means – all planets data support this planet motion
Why do I write this concept? – because – in one astronomy book the author told that
(Earth axial tilt cycle motion is independent from Earth own motion!)
This category of ideas is wrong – the planet does one motion and all its data do this
one motion and all planet motions be unified into one general motion – by that – Earth
rotation around its axis daily and Earth revolution around the sun with the Earth axial
tilt cycle motion – all these motions be unified in One Motion – because the planet is
one planet.
(2nd
Concept) Planet Motion Logic
I have 2 examples to explain this idea
Example No. (1)
Newton Theory Of The Sun Gravity Is Wrong And No One Planet Moves By The
Sun Gravity – Newton Theory Is Wrong In Logic
By One Force The Planet Should Be Created And Moving – why?
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Because if the sun forces a planet to revolve around it by its gravity – this planet will
move against its internal structure – and this planet will be broken –
Shortly
The force which created the planet is its reason of motion – we need one force to do
the 2 jobs (Planet Creation And Motion) - It's A Wrong In Logic
This vision produces many useful results – because –
We have no 9 forces in the solar system – each planet creation and motion be done by
one force – instead – we have one force which created all planets and cause their
motions – here – we catch a new meaning in the solar system motion – because – this
one force can cause 9 planets to move only if it uses one geometrical design – means
– the 9 planets creation and motions depend on one geometrical design.
Example No. (2)
The Big Bang Theory Is A Wrong One Also Because Of A Wrong In Logic
The big bang told us – the first energy be created by the first explosion- as a result the
first energy be in a chaos form –
The creation random process is the main concept be taught by the big bang theory
Here we catch the fatal error of this theory because
How the solar system which depend on geometrical rules and physical laws can be
created from energy be found in (a chaos form)
Wrong in Logic
The physicists tried to find a solution for this wrong in logic by creating thousands of
(pure coincidences ideas) to enable them to create a geometrical design from chaos
and they never succeeded to do
The mistake is clear – the first energy wasn't in a chaos form – also no natural energy
be found in a chaos form – the chaos and random idea is a pure imaginary one –
What's the fact?
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The solar planets matters and their distances be created of one energy and this energy
was in a geometrical design and controlled by geometrical rules – by that – the solar
system be created based on geometrical rules and physical laws
Notice
I have tried to prove - The theories neglected the correct logic – and because of that -
these theories can be refuted since long period– Why they were persistent till now?
Because the logic isn't defined correctly
No measurement can be used to test the theory- means- the theory is wrong but no
weapon to kill it!
(3rd
Concept) The Solar System Motion Rules Definition
The solar system motion be studied to discover this motion rules
The rules are the basic aim behind
How can we discover the solar system motion rules?
I use planets data analysis method to discover the rules –
Planets data analysis put the planets data in comparison with the theories to test if the
theories be sufficient –
My method of planet data analysis needs 3 steps which are
We need interesting data – then – a hypothesis explains this data – then more data
prove the hypothesis – Let's use 2 examples to explain how this method works
Example No. (3) (Mars Migration Theory)
- The 3 planets (Mercury – Venus – Earth) give the interesting data! why?
- Because
- The 3 planets be in order for their diameters, masses and orbital distances. Can this
order be found based on a geometrical rule? let's try to discover
- But
- Mars causes a question, because Mars causes to break this order!
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
56
- What hypothesis we need to explain this interesting data?
- The hypothesis tells (Mars Original Position Was Between Mercury And Venus)
- If this is the original position of Mars the planets order will be
- (Mercury – Mars – Venus – Earth)
- The 4 planets be in order for their diameters, masses and orbital distances
- Can we prove this hypothesis? Yes
- Mars had migrated from its original orbital distance to its current one – and Mars
in its migration motion had collided with Venus and then with Earth and Mars
itself caused to create the Earth Moon!
- Giant-Impact hypothesis tells, a planet in Mars Size had collided with the Earth
and caused the moon creation.
- Can Mars Itself do that? Giant-impact hypothesis tells No
- But,
- Planets data analysis suggested that Mars had migrated from its original orbital
distance to its current one –
- Let's move with this hypothesis for a while
- (a)
- (Why Does Venus Have No Moon?)
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushing by force
and had collided with Venus and pushed all debris with it in its motion direction
-Venus had found no debris around – for that Venus couldn't create its own moon-
- By that our theory answers a question of Giant-impact hypothesis –
- (b)
- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the
collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
57
- Earth gravity is greater than Venus' and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- This analysis proves that My Mars Migration theory is a correct one.
Example No. (4) (The Moon Motion Equation)
- Why Does The Moon Orbital Apogee Radius = 406000 km?
- First (we search for interesting data)
- The moon daily displacement =88000 km and during the moon day period (29.53
solar days) the displacements total be = 2.598 million km = 2π x 413600 km
- This data is interesting – Because
- The data tells the moon orbital apogee radius should be 413600 km
- Also it tells
- The moon daily displacement (88000 km) is so long, because of that, the moon
should be prisoner in the apogee orbit its radius (=413600 km) and the moon can't
revolve around the Earth through any more near orbit!
- Not A Fact
- The moon orbital apogee radius in fact be =406000 km!
- And
- The moon revolves around the Earth through more near orbits and can reach to
perigee radius (363000 km)
- How to explain this interesting data?? What hypothesis can we create?
- The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level by that the real displacement (L) through the orbit be less than
(88000 km) because it be (L = 88000 km cos θ) and the total displacement be less
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
58
than (2.598 million km) and that makes the moon orbital apogee radius to be
decreased from 413600 km to 406000 km.
- We should pay attention to the angle (θ), because this angle controls the moon
motion features – where- with the angle (θ) increasing the real displacement (L) be
shorter and the moon can revolve around the Earth through more near orbits – but
–with the angle (θ) deceasing the real displacement (L) be longer and that pushes
the moon far from the Earth to more far orbits.
- I have an equation for the moon orbital motion depends on this angle (θ)
- It tells (θ1 = θ0 +1.7 degrees) where (θ1= today angle and θ0= yesterday angle)
- In fact, the idea of the angle (θ) solves many basic problems in the moon orbital
motion explanation – we can reach to this idea only by using the planets data
analysis method–
- Notice
- The Moon Orbital Perigee Radius = 363000 km
- The Total Solar Eclipse Radius = 373000 km
- The Moon Orbital Distance = 384000 km
- The Moon Orbital Apogee Radius = 363000 km
- But
- (363000 km)2
+ (86000 km)2
= (373000 km)2
- (373000 km)2
+ (86000 km)2
= (384000 km)2
- (384000 km)2
+ (86000 km)2
= (393500 km)2
- (393500 km)2
+ (86000 km)2
= (406000 km)2
(error 1%)
- The data simply tells, the moon 4 basic orbital radiuses be created depending on
one another by Pythagorean rule because of the moon using of the angle (θ) in its
motion. this data should be considered one more proof for the hypothesis.
Notice
The 2 examples (no.3 and 4) provide new discoveries in the planets motions – I use
them to explain my research method (Planet Data Analysis Method)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
59
But
We should distinguish between the basic and the additional
I refer to a river and tell that I get water from this river by my bottle – you can use a
barrel, a trunk, or a cup – up to you –
It's my method to analyze PLANETS DATA and it's good for me – you can use it
also or you can create another method (to use PLANETS DATA)
But
PLANETS DATA Should Be The Basic Reference For Any Theory
Means
You should accept any theory because this theory explains how planet data be created
– and no contradiction be found between this theory and the planets data
it's very important moment now
because we create a law by which we can test the theory – after we will know if the
theory is wrong and the imaginary ideas will not deceive us for years again
the next question should be (how planet data be created?)
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The Solar Eclipse (Questions And Answers).pdf

  • 1. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 1 The Solar Eclipse (Questions And Answers) The Author Authorized To Be Used By Mr. Gerges Francis Tawdrous A Student–Physics Department- Physics & Mathematics Faculty – Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Dr. Budochkina, Svetlana Aleksandrovna Associate Professor (Mathematical Analysis and Theory of Functions Department) Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Phone +201022532292 E-Mail: mrwaheid@gmail.com Curriculum Vitae http://vixra.org/abs/1902.0044 Phone +7 (495) 952-35-83 E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru Website http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024 The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –16th July 2022 Abstract Paper objective The paper answers the following questions 1. Can each planet orbital distance depend on its neighbor planet orbital distance? In this case how the distance between the sun and Pluto be created? (Can One Map Be Drawn For All Planets Orbital Distances?) 2. Is There a necessity to create a proportionality between planet diameter and orbital distance? 3. Can Planet rotation period be defined based on its velocity? 4. Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its Orbital Distance And By That This Planet Will Not Be Broken Through Its Motion?) 5. Why Does Venus Have The Longest Rotation Period In The Solar System? 6. Can Planet orbital Distance be Defined before this planet creation? where planet orbital distance be defined based on its neighbor orbital distance? 7. Why Doesn't The Planet Break After Its Creation? 8. Planet data be (Mass – Diameter- Orbital Distance- Period –Inclination….etc) what data be created at first and what be created later? 9. Explain The Relationship Between Planet Diameter And Orbital Distance? 10. Why does the moon orbital period = the moon rotation period (No For Tidal Locking – this idea is wrong)?
  • 2. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 2 11.Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total? 12- Can Solar System Depend On One Geometrical Design? 13- Why Does The Moon Orbital Apogee Radius = 406000 km? 14- Can Mars Orbital Distance Be Changed From 84 million km to 228 million km? 15- Did Newton realize The Solar system Motion Logic? 16- How Be The Sun Disc Created? Paper reference The Solar Eclipse Phenomenon Analysis (Revised) https://www.academia.edu/83032629/The_Solar_Eclipse_Phenomenon_Analysis_Revised_ or https://app.box.com/s/i9a544tf79wzo7ly1id22dd8jtjc5w9c Please enjoy the reading - kind regards (Please scan the figure (ORCID) Gerges Francis Tawdrous +201022532292 Physics Department- Physics & Mathematics Faculty Peoples' Friendship university of Russia – Moscow (2010-2013) Curriculum Vitae http://vixra.org/abs/1902.0044 E-mail mrwaheid@gmail.com, mrwaheid1@yahoo.com gergesgerges@yandex.ru ORCID https://orcid.org/0000-0002-1041-7147 Facebook https://www.facebook.com/gergis.tawadrous VK https://vk.com/id696655587 Tumblr https://www.tumblr.com/blog/itsgerges Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/ Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en Livejournal https://gerges2022.livejournal.com/profile Pocket https://getpocket.com/@646g8dZ0p3aX5Ad1bsTr4d9THjA5p6a5b2fX99zd54g221E4bs76eBdtf6aJw5d0?src=navbar PUBLICATIONS box https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv Academia https://rudn.academia.edu/GergesTawadrous List of publications http://vixra.org/author/gerges_francis_tawdrous Slideshare https://www.slideshare.net/Gergesfrancis
  • 3. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 3 The Answers Answer No.(1) Can each planet orbital distance depend on its neighbor planet orbital distance? In this case how the distance between the sun and Pluto be created? (Can One Map Be Drawn For All Planets Orbital Distances?) - The distance from the sun to Pluto has 3 features - (1st Feature) - Each planet orbital distance depends on its neighbor planet orbital distance – my first equation proves that - my first equation tells - d2 = 4d0 (d-d0) - d = A Planet Orbital Distance - d0= Its Direct Previous Neighbor Planet Orbital Distance - Example No. (1) (Venus) - (108.2)2 = 4 x 57.9 x (50.3) - d= 108.2 million km = Venus Orbital Distance - d0= 57.9 million km = Mercury Orbital Distance - 50.3 million km = The Distance Between Venus And Mercury - Venus Depends On Mercury - By that, - My first equation proves planet orbital distance depends on its neighbor, - My first equation is tested on my page https://www.facebook.com/gergestawdrous2022 - (please review it) - Notice - My first equation provides a clear concept states (Each planet orbital distance depends on its neighbor planet orbital distance), by that the planet be forced for its orbital distance because it's defined by its neighbor and not by any planet data. - (2nd Feature) - The distance from the sun to Pluto depends on 2 columns (Jupiter and Pluto),
  • 4. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 4 - Means - Each planet orbital distance depends on its neighbor orbital distance - But, the whole distance from the sun to Pluto be designed based on one Map depends on the 2 columns (Jupiter and Pluto) – The data proves this fact. Data (1) 37100 million km – 4900 million km = 32200 million km 32200 million km x π = 100733 million km Where 100733 million km = The planets orbital circumferences total 37100 million km = Pluto Orbital Circumference 4900 million km = Jupiter Orbital Circumference (2) Jupiter Orbital Circumference = 4900 million km Uranus needs 4900 days to pass a distance = Uranus Orbital Distance (3) Light (300000 km/s) travels during 16330 sec a distance = 4900 million km Light (1160000 km/s) travels during 4222.6 sec a distance = 4900 million km 16330 hours = Mars orbital period and 4222.6 hours = Mercury Day period Discussion - The data no. (1) proves the idea - because - The 3 values (4900 , 37100 and 100733) depend on one another, any 2 values enable us to conclude the third one theoretically - Means, If we know Jupiter orbital circumference =4900 million km and The planets orbital circumferences total = 100733 million km, We can conclude theoretically Pluto orbital circumference =37100 million km – We do that by using the data no. (1) - The distances map is a simple idea and be clear from data
  • 5. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 5 - The basic point is the distance 4900 million km (Jupiter orbital circumference), because it has a wide range of effect on all planets motions – that because – Jupiter is the base in both maps (distance and velocity maps) - Let's review the using of the distance 4900 million km - (1) - The inner planets orbital circumferences total be (Mercury 360 mkm + Venus 680 mkm + Earth 940 mkm + Mars 1433 mkm + 1433 mkm) = 4900 million km (1%) - The total = 4900 million km but the distance (1433 mkm) be used 2 times! - (2) - Jupiter Orbital Circumference (4900 million km) - (3) - Uranus needs 4900 days to pass a distance = Uranus Orbital Distance - Neptune needs 2 x 4900 days to pass a distance = Neptune Orbital Distance (2%) - Pluto needs 3 x 4900 days to pass a distance = Pluto Orbital Distance (1%) - (4) - (10747 /9800) = (9800 /9007) - 10747 days = Saturn Orbital Period - 9007 million km = Saturn Orbital Circumference - 9800 = 2 x 4900 - The data tells that, the value 4900 be used by all planets (in different units) - The distance for Jupiter (and the inner planets) be used as a period of time for Uranus, Neptune and Pluto–and Saturn uses this value as a distance and as a period - We can conclude - The distance 4900 million km is the central one in the solar system design for that reason Jupiter be a column in both maps (distance and velocity) - The data proves the idea clearly – that - One map of distance be used the solar planets distances distribution and in this map Jupiter and Pluto be used as the 2 basic points (or columns)
  • 6. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 6 - Mercury point discussion will extend this vision and cause it to be so rich – we discuss it in the proof no. (3) ((3) Mercury is the origin point (of the distance) - Notice - 100733 million km = 928 million km x 108.2 - Where - 100733 million km = The planets orbital circumferences total - 928 million km = Jupiter Earth Distance when be on 2 different sides (928 mkm = 149.6 mkm + 778.6 mkm) - 108.2 million km = Venus orbital distance - This data shows Venus and the Earth distances be effective in definition of the solar planets orbital circumferences total (100733million km) but no one of them be used in the Map of distances because Jupiter and Pluto data shows clearly that they are the columns – but still Venus and Earth have effective role we need to discover later - - (3rd Feature) - Mercury be used as an origin point for the 2 planets (Jupiter and Pluto), the data proves that (1) 4222.6 seconds x 1.16 million km /sec = 4900 million km (2) 5040 seconds x 1.16 million km /sec = 5848 million km Discussion - Data no. (1) tells that, light supposed velocity (1160000 km/s) travels during 4222.6 seconds a distance = 4900 million km (Jupiter orbital circumference) - Mercury day period =4222.6 hours - The light uses each one hour as one second
  • 7. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 7 - This data tells, Jupiter orbital circumference be defined based on Mercury Motion data (Mercury day period) and that tells Mercury be used as a reference to define Jupiter orbital distance. - Data no. (2) tells that, light supposed velocity (1160000 km/s) travels during 5040 seconds a distance = 5848 million km (Mercury Pluto Distance) - Pluto position also be defined by light motion based on Mercury data - because - Mercury day period needs 5040 seconds to be =4224 hours - The type of motion is unknown and for that the importance of the period 5040 s is undefined but both periods are related to Mercury motion – - Means - Mercury is the point of origin to define the 2 positions (Jupiter and Pluto) but the using methods and types of motions are unknown - The data proves the idea
  • 8. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 8 Answer No.(2) Is There a necessity to create a proportionality between planet diameter and orbital distance? - Yes, - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason
  • 9. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 9 - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - My fourth equation proves that, - Planet diameter be a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance (kepler law) - My fourth equation be tested here https://www.facebook.com/gergestawdrous2022
  • 10. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 10 Answer No.(3) Can Planet rotation period be defined based on its velocity? - My fourth equation proves this fact - Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I - v = Planet Velocity - r= Planet Diameter - s= Planet Rotation Periods Number In Its Orbital Period - I= Planet Orbital Inclination ( a rate to inclination unit) - v2, s, r and I be belonged to one planet and v1 be belonged to another planet - Notice / (The Equation Works From The Earth To Pluto Only) - Let's use one example Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8 89143 = Neptune rotation periods number in Neptune orbital period 49528 km = Neptune diameter 9.7 km/s = Saturn velocity 5.4 km/s = Neptune velocity 59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours) 1.8 degrees = Neptune Orbital Inclination - By this equation Planet diameter be created as a function in its rotation period and the rotation be a function in its velocity - The example explains the idea clearly – - The equation still needs explanation – because the strange planet its velocity (v1) can't be defined by any rule we search for the minimum error – for that- Saturn velocity be used for Neptune Equation –let's provide the equation list: - Earth Equation uses Neptune velocity - Mars Equation uses Pluto velocity - Jupiter Equation uses the Earth moon velocity
  • 11. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 11 - Saturn Equation uses Mars velocity - Uranus Equation uses Neptune velocity (As Earth) - Pluto Equation uses the Earth moon velocity (As Jupiter) - My fourth equation be tested on https://www.facebook.com/gergestawdrous2022 - A Question - Why Does The Equation Work From The Earth To Pluto Only? - Let's answer in following… - The moon rotation period = its orbital period =27.3 days - By that for the moon (s) = 1 - So the equation depends on the moon cycles equality - And - The equation ends with Pluto – where Pluto also provide 2 equal values which are - s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h) - and - Pluto needs 14547 solar days to move a distance = Pluto orbital distance - the numbers (14178 and 14547) are equal approximately (error 2.5%) and this equality of Pluto cycles be in comparison with the moon cycles equality - Here the moon and Pluto work as 2 terminals of the equation – both provide 2 equal values– these 2 equal values be found to enable the equation to create a function between the planets diameters and their rotation periods and also between these planets rotation periods and their velocities - Now - The moon orbital period = the moon rotation period NOT because of the tidal locking – the idea is wrong – they are equal because of my fourth equation – - The equality of the cycles is necessary to enable the equation to create the required functions between planet diameter and rotation period and between planet rotation period and velocity.
  • 12. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 12 - I want to say - My fourth equation refers to a geometrical effect be found between the moon and Pluto motions passing through all planets data – where this effect enables the equation to create the required functions (diameter with rotation period) and (rotation period with velocity), this geometrical effect guarantees the equation works for all planets to create all diameters under the one equation by that all diameters be in harmony with their planets orbital distances by indirect relationship which saves the planets in their motions and also in their migrations in case of any planet migration from its original orbital distance. - Notice - (29.53/27.3) = (243/224.7)= 1.0725 - Where - 29.53 days = The Moon Day Period - 27.3 days = The Moon Orbital Period - 243 days = Venus Rotation Period - 224.7 days = Venus Orbital Period - This data tells, there's a consistency between the moon and Venus cycles periods, this consistency is required because the equality between the moon orbital period and rotation period forms the base on which my fourth Equation depends – means – the system by which the planets diameters be defined as function in their rotations and then velocities and then orbital distances – this system depends on the equality of the moon 2 cycles periods – and this equality be supported by Venus Cycles in addition to the moon cycles – that means- the system depends on the moon motion but the moon motion be supported strongly by Venus motion, for that the cycles equality be strong value because it be consisted of 2 planets cycles integration – and by that the moon and Venus consist together a strong base on which the system depends
  • 13. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 13 Answer No.(4) - Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its Orbital Distance And By That This Planet Will Not Be Broken Through Its Motion?) - NOT A DIRECT ONE - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's deepen our discussion in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason
  • 14. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 14 - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - My fourth equation proves planet diameter be created a function in its rotation period and the rotation be created a function in its velocity - Notice - My first equation proves each planet orbital distance depends on its neighbor planet orbital distance. - My first equation (d2 = 4d0 (d-d0)) - d = A Planet Orbital Distance d0= Its Previous Neighbor Orbital Distance - My equations be tested on https://www.facebook.com/gergestawdrous2022
  • 15. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 15 Answer No.(5) - Why Does Venus Have The Longest Rotation Period In The Solar System? - For answer we have to review my fourth equation here – let's do it - My theory tells based on one geometrical design the solar system be created – it deals with the solar planets as members in one creature body – they are created complementary with one another and in proportionality with one another. - Here we deal with the solar system starts from the sun to Pluto as one piece of distance and as one unified motion – and we don't deal with any individual point or planet instead we deal with the whole system as One Machine - The solar system design (the machine design) uses 2 maps one for distance and one for velocity – Let's explain that in following.. - (POINT NO. 1) THE MAP OF DISTANCES - The distance from the sun to Pluto be distributed based on one rule by my first equations (d2 = 4d0 (d-d0) where (d= planet orbital distance) and (d0 it neighbor) - The equation tells, each planet orbital distance be defined based on its neighbor orbital distance – by that no any other data be used to define the distance – - shortly - Planet orbital distance be defined based on its neighbor planet orbital distance, as a result the distances be defined based on one another and no other data be required - Briefly - If (Mercury Orbital Distance =57.9 million km), by using my first equation and this one data we can conclude by mathematical calculations only all planets orbital distances – no any other data be required neither mass nor diameter – the distances be defined based on one another - That tells the designer deals with the distance from the sun to Pluto as one piece of distance which be distributed geometrically based on one rule or one design. - That tells also –
  • 16. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 16 - The distances be somehow forced values for the planets – because they be distributed geometrically by that the planets be forced to be in their positions. - The distances map uses 2 columns which are (Jupiter and Pluto) - The data proves this fact we should discuss in the proof discussion - Briefly - There are 2 features of the distances map which are - (1st Feature) - Planets orbital distances be distributed geometrically based on one another by using my first equation (d2 = 4d0 (d-d0) and regardless any planet data. - (2nd Feature) - The distances map uses 2 columns which are (Jupiter and Pluto) - Means, - If we know Jupiter and Pluto orbital distances we can conclude all planets orbital circumferences total without any equation – the data proves that- - Simply, - The solar planets orbital circumferences total depends on Jupiter and Pluto orbital distances – that means – these 3 players consist the whole system – any 2 values are available enable to conclude the third value theoretically and simply - Means - The distances distribution be done by one geometrical design based on my first equation – but – mentioned to define the 2 columns (Jupiter and Pluto) as the basic 2 points of the whole distance creation. - The data proves this fact - Notice - Mercury is the origin point based on which the 2 columns depend- means
  • 17. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 17 - The solar system map of distances depends on Jupiter and Pluto orbital distances as 2 basic columns of the map and these 2 columns depend on Mercury position as the origin point for them. (the data will prove that) - (POINT NO. 2) THE MAP OF VELOCITY - The design deals with the solar planets motions as one unified motion – that be similar to a machine of gears – where many gears move and one motion only be produced – similar to that - the solar planets move but one unified motion only be produced. - The Map of velocity depends on 2 columns (Jupiter And Uranus) - The data proves– The solar planets motions depend on the velocities of Jupiter and Uranus. - We have a very good reason and a group of data forces for this conclusion we will discuss in the proof discussion. - By that - There's a phase between the distance and the velocity Maps because - The map of distances depends on (Jupiter and Pluto) – but - The map of velocities depends on (Jupiter and Uranus) – - For the 2 maps the base is the same (Jupiter) but the distances reaches to Pluto where the velocities be limited to Uranus – based on that - - We have to ask - Why does the designer need 2 maps for the distance and velocity? - Let's answer in following… - (A Question) - Why does the designer need 2 maps for the distance and velocity? - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following…
  • 18. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 18 - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – The idea is clear - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death.
  • 19. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 19 - Shortly - The phase be created between Pluto (distance map) and Uranus (velocity map) be found because of the solar planets diameters total (406000 km) - The velocity map doesn't use Pluto as end point (as the distance map does) instead it uses Uranus as end point – because – the 2 maps work to define the planets diameters as indirect functions in their orbital distances and for that the planets diameters total 406000 km be the most important distance for (Uranus, Jupiter and Pluto) motions – we discuss that in details later. - Now - Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet orbital distance and its velocity is the most basic relationship we do need in our explanation – because – planet diameter be a function in its rotation period and the rotation period be function in its velocity – just because – the velocity is a function in the orbital distance – an indirect proportionality between planet orbital distance and its diameter be created and that's the required proportionality to save the planet in its motion. - But, - How do we know that planet diameter is a function in its rotation period and the rotation period be a function in its velocity?! - This relationship be proved by my fourth equation – here we can understand how these relationships be created and why- - We have to analyze the distance 406000 km and discuss my fourth equation to explain how this machine works
  • 20. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 20 - (POINT NO. 3) My Fourth Equation - Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I - v = Planet Velocity - r= Planet Diameter - s= Planet Rotation Periods Number In Its Orbital Period - I= Planet Orbital Inclination ( a rate to inclination unit) - v2, s, r and I be belonged to one planet and v1 be belonged to another planet - Notice / (The Equation Works From The Earth To Pluto Only) - Let's use one example Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8 89143 = Neptune rotation periods number in Neptune orbital period 49528 km = Neptune diameter 9.7 km/s = Saturn velocity 5.4 km/s = Neptune velocity 59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours) 1.8 degrees = Neptune Orbital Inclination - By this equation Planet diameter be created as a function in its rotation period and the rotation be a function in its velocity - The example explains the idea clearly – - The equation still needs explanation – because the strange planet its velocity (v1) can't be defined by any rule we search for the minimum error – for that- Saturn velocity be used for Neptune Equation –let's provide the equation list: - Earth Equation uses Neptune velocity - Mars Equation uses Pluto velocity - Jupiter Equation uses the Earth moon velocity - Saturn Equation uses Mars velocity - Uranus Equation uses Neptune velocity (As Earth) - Pluto Equation uses the Earth moon velocity (As Jupiter)
  • 21. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 21 - Notice - Jupiter and Pluto (The Distances Map Columns) use the Earth moon velocity - And - Uranus and Earth (the 2 players in the velocity Map) use Neptune velocity - A Question - Why Does The Equation Work From The Earth To Pluto Only? - Let's answer in following… - The moon rotation period = its orbital period =27.3 days - By that for the moon (s) = 1 - So the equation depends on the moon cycles equality - And - The equation ends with Pluto – where Pluto also provide 2 equal values which are - s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h) - and - Pluto needs 14547 solar days to move a distance = Pluto orbital distance - the numbers (14178 and 14547) are equal approximately (error 2.5%) and this equality of Pluto cycles be in comparison with the moon cycles equality - Here the moon and Pluto work as 2 terminals of the equation – both provide 2 equal values– these 2 equal values be found to enable the equation to create a function between the planets diameters and their rotation periods and also between these planets rotation periods and their velocities - Now - The moon orbital period = the moon rotation period NOT because of the tidal locking – the idea is wrong – they are equal because of my fourth equation – - The equality of the cycles is necessary to enable the equation to create the required functions between planet diameter and rotation period and between planet rotation period and velocity.
  • 22. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 22 - I want to say - My fourth equation refers to a geometrical effect be found between the moon and Pluto motions passing through all planets data – where this effect enables the equation to create the required functions (diameter with rotation period) and (rotation period with velocity), this geometrical effect guarantees the equation works for all planets to create all diameters under the one equation by that all diameters be in harmony with their planets orbital distances by indirect relationship which saves the planets in their motions and also in their migrations in case of any planet migration from its original orbital distance. - Notice - (29.53/27.3) = (243/224.7)= 1.0725 - Where - 29.53 days = The Moon Day Period - 27.3 days = The Moon Orbital Period - 243 days = Venus Rotation Period - 224.7 days = Venus Orbital Period - This data tells, there's a consistency between the moon and Venus cycles periods, this consistency is required because the equality between the moon orbital period and rotation period forms the base on which my fourth Equation depends – means – the system by which the planets diameters be defined as function in their rotations and then velocities and then orbital distances – this system depends on the equality of the moon 2 cycles periods – and this equality be supported by Venus Cycles in addition to the moon cycles – that means- the system depends on the moon motion but the moon motion be supported strongly by Venus motion, for that the cycles equality be strong value because it be consisted of 2 planets cycles integration – and by that the moon and Venus consist together a strong base on which the system depends
  • 23. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 23 - Here we can answer the question - Venus cycles creates an equality to support the moon cycles equality – - But the moon orbit the Earth where Venus orbit the sun by that the rotation period of Venus has to be equal its orbital period - By that Venus created its cycles to support the moon motion cycles to perform the base of the equation - Notice - The rate 1.0725 we have discussed frequently before and it be found for a geometrical necessity. - Please review the paper Reference - (The Solar Eclipse Phenomenon Analysis (Revised))
  • 24. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 24 - Answer No.(6) - Can Planet orbital Distance be Defined before this planet creation? where planet orbital distance be defined based on its neighbor orbital distance? - In this question we need to prove only the fact tells - (Planet orbital distance depends on its neighbor planet orbital distance) - Because, - If planet orbital distance depends on its neighbor, that tells this distance can be defined before creation – it's a simple idea – - Imagine we are in some crowded bus – the other people pushes you and forces you to stand in some place – you can't change your place because they force you, by that this place was defined before you come into the bus – it was the most crowded place and every one left it for you! - My first equation proves that ,planet orbital distance depends on its neighbor planet orbital distance – let's remember it here – it tells - d2 = 4d0 (d-d0) - d = A Planet Orbital Distance - d0= Its Direct Previous Neighbor Planet Orbital Distance - Example No. (1) (Venus) - (108.2)2 = 4 x 57.9 x (50.3) - d= 108.2 million km = Venus Orbital Distance - d0= 57.9 million km = Mercury Orbital Distance - 50.3 million km = The Distance Between Venus And Mercury - Venus Depends On Mercury - By that, - My first equation proves planet orbital distance depends on its neighbor, - My first equation is tested on my page https://www.facebook.com/gergestawdrous2022 - (please review it)
  • 25. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 25 - Answer No.(7) - Why Doesn't The Planet Break After Its Creation? - Because - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance –
  • 26. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 26 - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - My fourth equation proves that, - Planet diameter be a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance (kepler law) - My fourth equation be tested on my page https://www.facebook.com/gergestawdrous2022
  • 27. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 27 - Answer No.(8) - Planet data be (Mass – Diameter - Orbital Distance- Period –Inclination….etc) what data be created at first and what be created later? - The planet orbital distance is created first before any other data – because – any planet orbital distance depends on its neighbor planet orbital distance- - My first equation proves this fact – - By that the planet orbital distance be defined before its creation because this distance doesn't depend on any data of the planet – but depends on its previous neighbor orbital distance- and by that the distance be defined before the creation and we can consider the planet orbital distance be defined firstly before any other planet data be created – let's review my first equation in following – it tells - d2 = 4d0 (d-d0) - d = A Planet Orbital Distance - d0= Its Direct Previous Neighbor Planet Orbital Distance - Example No. (1) (Venus) - (108.2)2 = 4 x 57.9 x (50.3) - d= 108.2 million km = Venus Orbital Distance - d0= 57.9 million km = Mercury Orbital Distance - 50.3 million km = The Distance Between Venus And Mercury - Venus Depends On Mercury - By that, - My first equation proves planet orbital distance depends on its neighbor, - My first equation is tested on my page https://www.facebook.com/gergestawdrous2022 - (please review it)
  • 28. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 28 - Answer No.(9) - Explain The Relationship Between Planet Diameter And Orbital Distance? - There's a necessity to create a proportionality between planet diameter and orbital distance – because - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason
  • 29. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 29 - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - My fourth equation proves that, - Planet diameter be a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance (kepler law) - My fourth equation be tested on my page https://www.facebook.com/gergestawdrous2022
  • 30. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 30 Answer No.(10) - Why does the moon orbital period = the moon rotation period (No For Tidal Locking – this idea is wrong)? - To answer this question we need to review my fourth equation, let's do that… - My theory tells based on one geometrical design the solar system be created – it deals with the solar planets as members in one creature body – they are created complementary with one another and in proportionality with one another. - Here we deal with the solar system starts from the sun to Pluto as one piece of distance and as one unified motion – and we don't deal with any individual point or planet instead we deal with the whole system as One Machine - The solar system design (the machine design) uses 2 maps one for distance and one for velocity – Let's explain that in following.. - (POINT NO. 1) THE MAP OF DISTANCES - The distance from the sun to Pluto be distributed based on one rule by my first equations (d2 = 4d0 (d-d0) where (d= planet orbital distance) and (d0 it neighbor) - The equation tells, each planet orbital distance be defined based on its neighbor orbital distance – by that no any other data be used to define the distance – - shortly - Planet orbital distance be defined based on its neighbor planet orbital distance, as a result the distances be defined based on one another and no other data be required - Briefly - If (Mercury Orbital Distance =57.9 million km), by using my first equation and this one data we can conclude by mathematical calculations only all planets orbital distances – no any other data be required neither mass nor diameter – the distances be defined based on one another - That tells the designer deals with the distance from the sun to Pluto as one piece of distance which be distributed geometrically based on one rule or one design.
  • 31. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 31 - That tells also – - The distances be somehow forced values for the planets – because they be distributed geometrically by that the planets be forced to be in their positions. - The distances map uses 2 columns which are (Jupiter and Pluto) - The data proves this fact we should discuss in the proof discussion - Briefly - There are 2 features of the distances map which are - (1st Feature) - Planets orbital distances be distributed geometrically based on one another by using my first equation (d2 = 4d0 (d-d0) and regardless any planet data. - (2nd Feature) - The distances map uses 2 columns which are (Jupiter and Pluto) - Means, - If we know Jupiter and Pluto orbital distances we can conclude all planets orbital circumferences total without any equation – the data proves that- - Simply, - The solar planets orbital circumferences total depends on Jupiter and Pluto orbital distances – that means – these 3 players consist the whole system – any 2 values are available enable to conclude the third value theoretically and simply - Means - The distances distribution be done by one geometrical design based on my first equation – but – mentioned to define the 2 columns (Jupiter and Pluto) as the basic 2 points of the whole distance creation. - The data proves this fact - Notice - Mercury is the origin point based on which the 2 columns depend- means
  • 32. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 32 - The solar system map of distances depends on Jupiter and Pluto orbital distances as 2 basic columns of the map and these 2 columns depend on Mercury position as the origin point for them. (the data will prove that) - (POINT NO. 2) THE MAP OF VELOCITY - The design deals with the solar planets motions as one unified motion – that be similar to a machine of gears – where many gears move and one motion only be produced – similar to that - the solar planets move but one unified motion only be produced. - The Map of velocity depends on 2 columns (Jupiter And Uranus) - The data proves– The solar planets motions depend on the velocities of Jupiter and Uranus. - We have a very good reason and a group of data forces for this conclusion we will discuss in the proof discussion. - By that - There's a phase between the distance and the velocity Maps because - The map of distances depends on (Jupiter and Pluto) – but - The map of velocities depends on (Jupiter and Uranus) – - For the 2 maps the base is the same (Jupiter) but the distances reaches to Pluto where the velocities be limited to Uranus – based on that - - We have to ask - Why does the designer need 2 maps for the distance and velocity? - Let's answer in following…
  • 33. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 33 - (A Question) - Why does the designer need 2 maps for the distance and velocity? - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – The idea is clear - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital distance but has to create it as indirect proportionality to save the planet - For that reason - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why?
  • 34. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 34 - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - Shortly - The phase be created between Pluto (distance map) and Uranus (velocity map) be found because of the solar planets diameters total (406000 km) - The velocity map doesn't use Pluto as end point (as the distance map does) instead it uses Uranus as end point – because – the 2 maps work to define the planets diameters as indirect functions in their orbital distances and for that the planets diameters total 406000 km be the most important distance for (Uranus, Jupiter and Pluto) motions – we discuss that in details later. - Now - Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet orbital distance and its velocity is the most basic relationship we do need in our explanation – because – planet diameter be a function in its rotation period and the rotation period be function in its velocity – just because – the velocity is a function in the orbital distance – an indirect proportionality between planet orbital distance and its diameter be created and that's the required proportionality to save the planet in its motion. - But, - How do we know that planet diameter is a function in its rotation period and the rotation period be a function in its velocity?! - This relationship be proved by my fourth equation – here we can understand how these relationships be created and why- - We have to analyze the distance 406000 km and discuss my fourth equation to explain how this machine works
  • 35. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 35 (Point No.3) My Fourth Equation - Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I - v = Planet Velocity - r= Planet Diameter - s= Planet Rotation Periods Number In Its Orbital Period - I= Planet Orbital Inclination ( a rate to inclination unit) - v2, s, r and I be belonged to one planet and v1 be belonged to another planet - Notice / (The Equation Works From The Earth To Pluto Only) - Let's use one example Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8 89143 = Neptune rotation periods number in Neptune orbital period 49528 km = Neptune diameter 9.7 km/s = Saturn velocity 5.4 km/s = Neptune velocity 59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours) 1.8 degrees = Neptune Orbital Inclination - By this equation Planet diameter be created as a function in its rotation period and the rotation be a function in its velocity - The example explains the idea clearly – - The equation still needs explanation – because the strange planet its velocity (v1) can't be defined by any rule we search for the minimum error – for that- Saturn velocity be used for Neptune Equation –let's provide the equation list: - Earth Equation uses Neptune velocity - Mars Equation uses Pluto velocity - Jupiter Equation uses the Earth moon velocity - Saturn Equation uses Mars velocity - Uranus Equation uses Neptune velocity (As Earth) - Pluto Equation uses the Earth moon velocity (As Jupiter)
  • 36. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 36 - Notice - Jupiter and Pluto (The Distances Map Columns) use the Earth moon velocity - And - Uranus and Earth (the 2 players in the velocity Map) use Neptune velocity - A Question - Why Does The Equation Work From The Earth To Pluto Only? - Let's answer in following… - The moon rotation period = its orbital period =27.3 days - By that for the moon (s) = 1 - So the equation depends on the moon cycles equality - And - The equation ends with Pluto – where Pluto also provide 2 equal values which are - s= 14178 (Pluto orbital period 90560 days has 14178 Pluto rotations 153.3 h) - and - Pluto needs 14547 solar days to move a distance = Pluto orbital distance - the numbers (14178 and 14547) are equal approximately (error 2.5%) and this equality of Pluto cycles be in comparison with the moon cycles equality - Here the moon and Pluto work as 2 terminals of the equation – both provide 2 equal values– these 2 equal values be found to enable the equation to create a function between the planets diameters and their rotation periods and also between these planets rotation periods and their velocities - Now - The moon orbital period = the moon rotation period NOT because of the tidal locking – the idea is wrong – they are equal because of my fourth equation – - The equality of the cycles is necessary to enable the equation to create the required functions between planet diameter and rotation period and between planet rotation period and velocity.
  • 37. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 37 - I want to say - My fourth equation refers to a geometrical effect be found between the moon and Pluto motions passing through all planets data – where this effect enables the equation to create the required functions (diameter with rotation period) and (rotation period with velocity), this geometrical effect guarantees the equation works for all planets to create all diameters under the one equation by that all diameters be in harmony with their planets orbital distances by indirect relationship which saves the planets in their motions and also in their migrations in case of any planet migration from its original orbital distance. - Notice - (29.53/27.3) = (243/224.7)= 1.0725 - Where - 29.53 days = The Moon Day Period - 27.3 days = The Moon Orbital Period - 243 days = Venus Rotation Period - 224.7 days = Venus Orbital Period - This data tells, there's a consistency between the moon and Venus cycles periods, this consistency is required because the equality between the moon orbital period and rotation period forms the base on which my fourth Equation depends – means – the system by which the planets diameters be defined as function in their rotations and then velocities and then orbital distances – this system depends on the equality of the moon 2 cycles periods – and this equality be supported by Venus Cycles in addition to the moon cycles – that means- the system depends on the moon motion but the moon motion be supported strongly by Venus motion, for that the cycles equality be strong value because it be consisted of 2 planets cycles integration – and by that the moon and Venus consist together a strong base on which the system depends
  • 38. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 38 Answer No.(11) Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total? The Question Explanation My theory tells (One Geometrical Design Be Found Behind The Solar System) – means- the planets motions be integrated and produce One Unified Motion – As A Machine Of Gears Produces One Motion- Based on this theory Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total? Or Can The Solar System Design Use One Map To Distribute The Planets Velocities? YES The design deals with the solar planets motions as one unified motion – that be similar to a machine of gears – where many gears move and one motion only be produced – similar to that - the solar planets move but one unified motion only be produced. The Map of velocity depends on 2 columns (Jupiter And Uranus) The data proves– The solar planets motions depend on the velocities of Jupiter and Uranus. We have a very good reason and a group of data forces for this conclusion we will discuss in the proof discussion. Let's provide them in following… THE PROVES Data (A) (2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
  • 39. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 39 Where 100733 million km = The Planets Orbital Circumferences Total 197393 days = The Planets Orbital Periods Total 1.16 million km/s = Light Supposed Velocity 0.6 million km/s = 2 x 0.3 million km/s (Light Velocity) 1.1318 million km/day = Jupiter Velocity Per A Solar Day 0.5875 million km/day = Uranus Velocity Per A Solar Day (B) (1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where 1.16 million km/s = Light Supposed Velocity 0.6 million km/s = 2 x 0.3 million km/s (Light Supposed Velocity) 47.4 km/s = Mercury Velocity 24.1 km/s = Mars Velocity 35 km/s = Venus Velocity 17.9 km/s = Ceres Velocity 13.1 km/s = Jupiter Velocity 6.8 km/s = Uranus Velocity Discussion Data No. (A) shows the planets orbital circumferences and periods total depend on the 2 planets (Jupiter and Uranus) velocities in comparison with the 2 velocities of light (the known velocity 300000 km/s and the supposed velocity 1160000 km/s) Data No. (B) shows that, the rate of velocities between (Jupiter and Uranus) be used also by (Mars and Mercury) and by (Venus and Ceres) – But No any couple can be replaced in place of (Jupiter and Uranus) in Data no. (A) – that shows, the planets orbital circumferences and periods be related to (Jupiter and Uranus) velocities and not to any other couple of planets – they are the 2 basic players in the design structure -
  • 40. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 40 The data proves the idea tells One Map of velocity be used for all planets velocities and in this map Jupiter and Uranus are the 2 basic points (or 2 columns) ANOTHER QUESTION The solar system map of distances depends on (Jupiter and Pluto) But The solar system map of velocities depends on (Jupiter and Uranus) Why does the designer need 2 maps for the distance and velocity? Why Not One Map for both? - The designer has to create a proportionality between each planet diameter and its orbital distance – because – by this proportionality the planet can move safely – let's explain that in following… - Planet orbital distance be a forced value for it, because each planet orbital distance depends on its neighbor orbital distance, by that the planet isn't free to choose its orbital distance and planet data isn't a player to define its orbital distance – instead planet orbital distance be a forced value for it defined by its neighbor position. - If this planet diameter be not in harmony with its orbital distance this planet will be broken through its motion – The idea is clear - We have a distance be defined by force - for that – we have to create the diameter as a function in this distance to support the planet safe motion otherwise this planet will be broken. - Here we find one job for the designer - The designer has to find a proportionality between the planet orbital distance and its diameter - But - If the planet diameter be a direct function in its orbital distance, this planet diameter will be broken if this planet migrate from its orbital distance - The situation be as that - The designer has to create the proportionality between planet diameter and its orbital
  • 41. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 41 distance but has to create it as indirect proportionality to save the planet - For that reason - The designer created the planet diameter a function in its rotation period, and the rotation period be a function in its velocity and its velocity a function in its orbital distance – - Here we have a proportionality between planet orbital distance and diameter, but this proportionality contains also the planet rotation period and velocity – why? - Because - If the planet migrates and changes its orbital distance, the shock of this migration will effect on the rotation (change in rotation period) and effect on velocity (change in velocity value) and then effect on the diameter (change in the diameter) by small value and doesn't cause to break the planet – the effect causes planet suffering but not death. - Shortly - The phase be created between Pluto (distance map) and Uranus (velocity map) be found because of the solar planets diameters total (406000 km) - The velocity map doesn't use Pluto as end point (as the distance map does) instead it uses Uranus as end point – because – the 2 maps work to define the planets diameters as indirect functions in their orbital distances and for that the planets diameters total 406000 km be the most important distance for (Uranus, Jupiter and Pluto) motions – we discuss that in details later. - Now - Kepler stated (Planet Orbit Defines Its Velocity)- This relationship between planet orbital distance and its velocity is the most basic relationship we do need in our explanation – because – planet diameter be a function in its rotation period and the rotation period be function in its velocity – just because – the velocity is a function in the orbital distance – an indirect proportionality between planet orbital distance and its diameter be created and that's the required proportionality to save the planet in its motion.
  • 42. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 42 - But, - How do we know that planet diameter is a function in its rotation period and the rotation period be a function in its velocity?! - This relationship be proved by my fourth equation – here we can understand how these relationships be created and why- We have to analyze the distance 406000 km and discuss my fourth equation to explain how this machine works
  • 43. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 43 Answer No. (12) Can Solar System Depend On One Geometrical Design? What does mean (One Geometrical Design)? The solar planets move a s pieces of the chess game – each planet motion depends on mathematical calculations and geometrical rules in comparison to the other planets – and as in the chess game –the players are teams and enemies but all of them are members in the same battle and they consist its structure- no one moves individually or independently It's the general idea – let's try to examine and test if it can be a fact (1) We accepted that (Newton Theory Of The Sun Gravity Is Wrong In Logic) basically because – The planet should be created and moving by the same one force – means- the force which created the planet it causes its motion – otherwise this planet will be broken because 2 forces effect on it- That tells, no planet moves by the sun gravity, because no planet be created by the sun gravity effect. But why the sun be found in the solar system if it doesn't cause any planet motion? And How Does The Planet Move If The Sun Doesn't Cause That? Shortly The planet creation and motion depends on one force only and for that this planet creation and motion data be in harmony one another- But - There are no 9 forces to cause the 9 planets creations and motions - instead – it's just one force causes all planets creation and motion – this vision tells that – this one force uses a geometrical design to cause the planets creation and motion. Briefly
  • 44. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 44 One force causes all planets creation and motion by using One Geometrical Design to do these 2 jobs (the creation and motion) (2) What's This One Geometrical Design? Can We Discover It? Let's see this idea The solar planets and their distances be created from one energy – this one energy was in one geometrical design by that the planets be created by this One Geometrical Design. And this geometrical design controls the planets creation and motion data for that the planets data be created based on exact equations – we have discovered that and proves it before – because I have 5 equations based on which the planets data be created where we have explained before that the planet creation and motion data be similar to any plane or rocket creation data depends on exact equations to enable its motion to be done without negative effects. By that – My 5 Equations Prove That The Planets Creation And Motion Depends On One Geometrical Design. Notice (My 5 Equations Be Tested And Proved In Point No. 2) Shortly, My 5 equations prove one geometrical design be found behind the solar system (3) Now do we realize this meaning (One Geometrical Design)? The idea tells (from one energy the planets and their distances be created), can we have any particles be created from the same energy? from gamma ray electron and positron be created, also the male and female creatures refer to similar system of creation – How do the 2 particles (or 2 creatures) behave after creation? They have attraction for one another – What Does Mean Attraction?
  • 45. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 45 The electron and position attraction will cause the annihilation and produce Gamma ray – but the (male and female) creatures give more wide of the attractions (forms) Some one carries flowers for his wife – and so – why these flowers effect on their attraction? From one energy the 2 particles are created and they have to produce this one energy one more time to save the cycle and give chance for more particles to be created – if the 2 particles be in fighting their energies will be consumed in vain losing their chance of existence and the other (potential) particles chance Shortly They have to be under attraction to cause a safety for themselves and for the potential particles – I hope I can explain the idea The planets motions agreement and integration is the necessary requirement for their existence and for (potential) lives existence – they are in full agreement – And what, A man and his wife live in happiness – what should they do to explain that?! The dancing planets do different forms show the agreement and integration of their motions – they show their integration because their integration is the only hope to produce the original energy from which they are created and give safety for the cycle. We are very near now The planets motions forms be seen in phenomena – as eclipses – planets alignments- planets perpendicularity ….etc These phenomena shows form of the integration of the planets motions which enable to produce the original energy one more time Let's use the solar eclipse as example to explain the idea Eclipse Phenomenon The sun, Earth and the moon create the conspiracy of the eclipse phenomena, they agreed together to be on one straight line (180 degrees)
  • 46. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 46 Now (the designer) supports their conspiracy, and create the sun and moon diameters rate to be equal their distances rate to the Earth and by that we can see the sun disc = the moon disc and the eclipse can be occurred The motion be done by 3 players in comparison one another – that explains the meaning of "One Geometrical Design" The planets creation data – for some unknown wonder – support the phenomenon by data proportionality The total solar eclipse be occurred and the beautiful sun be absent and return An intelligent student asked me (What's The Result Of This Eclipse?) I couldn't answer – The Sun Be Absent And Return – that's all Why the 3 players interested so much to do this action? and why the designer changed the creation data to be in proportionality to enable the eclipse to be done? What a big deal behind? A group of dancers do some beautiful piece of theater on stage, the people applaud strongly – The dancers did some motions only!! Can This Dancing Depend On Geometrical Rule? Can the eclipse be done based on Geometrical Rule? Let’s examine to answer (a) (The sun diameter/ moon diameter) =(Earth orbital distance / Earth moon distance) And Jupiter orbital distance = Earth orbital distance x 5.2 (5.1 degrees = The Moon Orbital Inclination) (b) 2 x Jupiter orbital distance = Jupiter diameter x 10921 km (the moon circumference) And
  • 47. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 47 Jupiter (13.1km/s) moves during 10921 seconds a distance = 142984 km = Jupiter diameter (c) The sun diameter x the moon diameter = 4900 million km = Jupiter orbital circumference = Jupiter circumference x 10921 km We see the moon circumference (10921 km) be used as a period of time (10921 s) for Jupiter motion – it's hard to explain how! But This data tells 2 information First (the eclipse be done based on geometrical rules and calculations) second (the used geometrical rules are unknown) Shortly About what does this writing argue? The Argument The planets and their distances be created of one energy and based on one geometrical design which causes their creations and motions – The planets motion have to be in harmony to integrate their energies to produce the original energy from which they were created to save the cycle By that, the planets move together in full agreement and harmony – In their motions they create phenomenon caused by the one geometrical design they depend on and these phenomenon cause more geometrical effects for the solar system By that, The planet be similar to a tube through which a water moves – but – the water here is similar to geometrical effects – because by these geometrical effects the planets do the phenomena and the phenomena itself cause more geometrical effects The whole proves is required to show the continuous harmony and agreement without which the original energy will never be found and the cycle will be destroyed. Again
  • 48. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 48 Shortly about what does this writing argue? About the book of geometry Because, the eclipse be created based on geometrical rule and the eclipse process causes more geometrical effects to be created on the solar system the book of geometry be written in the dancing planets phenomenon (eclipses, alignments, perpendicularity…etc) the rules are unknown, for that we need to examine in details to discover them. The physicist have seen nothing of the party – he simply supposed – all eclipses, alignments, perpendicularity.. etc be created by pure coincidences – he wasn't invited to the party and the missed the whole dance. We try to examine the planet motion as possible to know the fact.
  • 49. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 49 (Answer No. 13) Why Does The Moon Orbital Apogee Radius = 406000 km? - First (we search for interesting data) - The moon daily displacement =88000 km and during 29.53 solar days the displacements total be = 2.598 million km = 2π x 413600 km - This data is interesting – why - Because - The data tells the moon orbital apogee radius should be 413600 km - But, the moon orbital apogee radius in fact be =406000 km! - And, The data tells also, - The moon daily displacement (88000 km) be so long, because of that, the moon should be prisoner in the orbit with radius (=413600 km) and the moon can't revolve around the Earth through any more near orbit! - Not fact – the moon revolves around the Earth through more near orbits and can reach to perigee radius (363000 km) - How to explain this interesting data?? What hypothesis can we create? - The intelligent moon creates an angle (θ) between its motion direction and its orbit horizontal level by that the real displacement (L) through the orbit be less than (88000 km) because it be (L = 88000 km cos θ) by that the real displacement be shorter than (88000 km) and the total displacement be less than (2.598 million km) and that makes the moon orbital apogee radius to be decreased from 413600 km to 406000 km. - We should pay attention to the angle (θ), because this angle controls the moon motion features – where- with the angle (θ) increasing the real displacement (L) be shorter and the moon can revolve around the Earth through more near orbits – but –with the angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far from the Earth to more far orbits. - I have an equation for the moon orbital motion depends on this angle (θ)
  • 50. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 50 - In fact, the idea of the angle (θ) solves many basic problems in the moon orbital motion explanation – we can reach to this idea only by using the planets data analysis method– - For example – - The Moon Orbital Perigee Radius = 363000 km - The Total Solar Eclipse Radius = 373000 km - The Moon Orbital Distance = 384000 km - The Moon Orbital Apogee Radius = 363000 km - But - (363000 km)2 + (86000 km)2 = (373000 km)2 - (373000 km)2 + (86000 km)2 = (384000 km)2 - (384000 km)2 + (86000 km)2 = (393500 km)2 - (393500 km)2 + (86000 km)2 = (406000 km)2 (error 1%) - The data simply tells that, the moon 4 basic orbital radiuses be created depending on one another by Pythagorean rule because of the moon using of the angle (θ) in its motion. this data should be considered one more proof for the hypothesis. - In fact - this data provides some discovery in the moon orbital motion explanation – and almost no one knew before that the moon orbital apogee radius should be =413600 km and be decreased by some intelligent technique to be 406000 km – - This whole point of discussion in the moon orbital motion was absent and unknown because no one used the planet data analysis method in astrophysics research.
  • 51. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 51 (Answer No. 14) Can Mars Orbital Distance Be Changed From 84 million km to 228 million km? - The 3 planets (Mercury – Venus – Earth) give the interesting data! why? - Because, the 3 planets be in order for their diameters, masses and orbital distances. Can this order be found based on a geometrical rule? let's try to discover - But - Mars causes a question, because Mars causes to break this order! - What hypothesis we need to explain this interesting data? - The hypothesis tells (Mars Original Position Was Between Mercury And Venus) - If this is the original position of Mars the planets order will be - (Mercury – Mars – Venus – Earth) - The 4 planets be in order for their diameters, masses and orbital distances - Can we prove this hypothesis? Yes - Mars had migrated from its original orbital distance to its current one – and Mars in its migration motion had collided with Venus and then with Earth and Mars itself caused to create the Earth Moon! - Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the Earth and caused the moon creation. - Can Mars Itself do that? the theory tells No Hope - But, Planets data analysis suggested that Mars had migrated from its original orbital distance to its current one – - Let's move with this hypothesis for a while - Suppose Mars was the second planet after Mercury and had migrated to its current point (227.9 million km) and Mars had collided with Venus and then with Earth – can this idea help Giant-impact hypothesis? for example can this idea answers (Why Does Venus Have No Moon?)
  • 52. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 52 - (a) - Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to its current position (227.9 mkm), in its displacement, Mars was pushing by force and had collided with Venus and pushed all debris with it in its motion direction - Venus had found no debris around – for that Venus couldn't create its own moon- - (b) - Another question asks about (the origin of the lunar magma ocean!) Venus, The Lunar Magma Ocean is came from Venus, it's a part of Venus found by the collision between Mars and Venus but Mars had pushed all debris with it in its motion direction and left Venus without debris - Earth gravity is greater than Venus' and the debris lost some of their momentum and by that the Earth could create its own moon where the moon rocks are consisted of Venus, Earth and Mars debris - The fact Mars has 2 moons is one more proof for this idea, because Mars with small mass could attract 2 moons and Venus couldn't. - The rest debris be attracted by Jupiter and consisted the asteroid belt - This analysis proves that My Mars Migration theory is a correct one (point no.10)
  • 53. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 53 (Answer No. 15) Did Newton realize The Solar system Motion Logic? Preface The idea tells– The Solar System Is Consisted Of One Light Beam – The planets matters and distances be created from one light beam energy and the planets move by this light beam motion- it's the idea shortly but I need to define 3 basic concepts before discussion (1st Concept) Planet Data Unification And Harmony This is a simple idea – it tells planet data be created in harmony with one another and be unified by this planet motion – means – all planets data support this planet motion Why do I write this concept? – because – in one astronomy book the author told that (Earth axial tilt cycle motion is independent from Earth own motion!) This category of ideas is wrong – the planet does one motion and all its data do this one motion and all planet motions be unified into one general motion – by that – Earth rotation around its axis daily and Earth revolution around the sun with the Earth axial tilt cycle motion – all these motions be unified in One Motion – because the planet is one planet. (2nd Concept) Planet Motion Logic I have 2 examples to explain this idea Example No. (1) Newton Theory Of The Sun Gravity Is Wrong And No One Planet Moves By The Sun Gravity – Newton Theory Is Wrong In Logic By One Force The Planet Should Be Created And Moving – why?
  • 54. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 54 Because if the sun forces a planet to revolve around it by its gravity – this planet will move against its internal structure – and this planet will be broken – Shortly The force which created the planet is its reason of motion – we need one force to do the 2 jobs (Planet Creation And Motion) - It's A Wrong In Logic This vision produces many useful results – because – We have no 9 forces in the solar system – each planet creation and motion be done by one force – instead – we have one force which created all planets and cause their motions – here – we catch a new meaning in the solar system motion – because – this one force can cause 9 planets to move only if it uses one geometrical design – means – the 9 planets creation and motions depend on one geometrical design. Example No. (2) The Big Bang Theory Is A Wrong One Also Because Of A Wrong In Logic The big bang told us – the first energy be created by the first explosion- as a result the first energy be in a chaos form – The creation random process is the main concept be taught by the big bang theory Here we catch the fatal error of this theory because How the solar system which depend on geometrical rules and physical laws can be created from energy be found in (a chaos form) Wrong in Logic The physicists tried to find a solution for this wrong in logic by creating thousands of (pure coincidences ideas) to enable them to create a geometrical design from chaos and they never succeeded to do The mistake is clear – the first energy wasn't in a chaos form – also no natural energy be found in a chaos form – the chaos and random idea is a pure imaginary one – What's the fact?
  • 55. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 55 The solar planets matters and their distances be created of one energy and this energy was in a geometrical design and controlled by geometrical rules – by that – the solar system be created based on geometrical rules and physical laws Notice I have tried to prove - The theories neglected the correct logic – and because of that - these theories can be refuted since long period– Why they were persistent till now? Because the logic isn't defined correctly No measurement can be used to test the theory- means- the theory is wrong but no weapon to kill it! (3rd Concept) The Solar System Motion Rules Definition The solar system motion be studied to discover this motion rules The rules are the basic aim behind How can we discover the solar system motion rules? I use planets data analysis method to discover the rules – Planets data analysis put the planets data in comparison with the theories to test if the theories be sufficient – My method of planet data analysis needs 3 steps which are We need interesting data – then – a hypothesis explains this data – then more data prove the hypothesis – Let's use 2 examples to explain how this method works Example No. (3) (Mars Migration Theory) - The 3 planets (Mercury – Venus – Earth) give the interesting data! why? - Because - The 3 planets be in order for their diameters, masses and orbital distances. Can this order be found based on a geometrical rule? let's try to discover - But - Mars causes a question, because Mars causes to break this order!
  • 56. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 56 - What hypothesis we need to explain this interesting data? - The hypothesis tells (Mars Original Position Was Between Mercury And Venus) - If this is the original position of Mars the planets order will be - (Mercury – Mars – Venus – Earth) - The 4 planets be in order for their diameters, masses and orbital distances - Can we prove this hypothesis? Yes - Mars had migrated from its original orbital distance to its current one – and Mars in its migration motion had collided with Venus and then with Earth and Mars itself caused to create the Earth Moon! - Giant-Impact hypothesis tells, a planet in Mars Size had collided with the Earth and caused the moon creation. - Can Mars Itself do that? Giant-impact hypothesis tells No - But, - Planets data analysis suggested that Mars had migrated from its original orbital distance to its current one – - Let's move with this hypothesis for a while - (a) - (Why Does Venus Have No Moon?) - Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to its current position (227.9 mkm), in its displacement, Mars was pushing by force and had collided with Venus and pushed all debris with it in its motion direction -Venus had found no debris around – for that Venus couldn't create its own moon- - By that our theory answers a question of Giant-impact hypothesis – - (b) - Another question asks about (the origin of the lunar magma ocean!) Venus, The Lunar Magma Ocean is came from Venus, it's a part of Venus found by the collision between Mars and Venus but Mars had pushed all debris with it in its motion direction and left Venus without debris
  • 57. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 57 - Earth gravity is greater than Venus' and the debris lost some of their momentum and by that the Earth could create its own moon where the moon rocks are consisted of Venus, Earth and Mars debris - The fact Mars has 2 moons is one more proof for this idea, because Mars with small mass could attract 2 moons and Venus couldn't. - The rest debris be attracted by Jupiter and consisted the asteroid belt - This analysis proves that My Mars Migration theory is a correct one. Example No. (4) (The Moon Motion Equation) - Why Does The Moon Orbital Apogee Radius = 406000 km? - First (we search for interesting data) - The moon daily displacement =88000 km and during the moon day period (29.53 solar days) the displacements total be = 2.598 million km = 2π x 413600 km - This data is interesting – Because - The data tells the moon orbital apogee radius should be 413600 km - Also it tells - The moon daily displacement (88000 km) is so long, because of that, the moon should be prisoner in the apogee orbit its radius (=413600 km) and the moon can't revolve around the Earth through any more near orbit! - Not A Fact - The moon orbital apogee radius in fact be =406000 km! - And - The moon revolves around the Earth through more near orbits and can reach to perigee radius (363000 km) - How to explain this interesting data?? What hypothesis can we create? - The intelligent moon creates an angle (θ) between its motion direction and its orbit horizontal level by that the real displacement (L) through the orbit be less than (88000 km) because it be (L = 88000 km cos θ) and the total displacement be less
  • 58. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 58 than (2.598 million km) and that makes the moon orbital apogee radius to be decreased from 413600 km to 406000 km. - We should pay attention to the angle (θ), because this angle controls the moon motion features – where- with the angle (θ) increasing the real displacement (L) be shorter and the moon can revolve around the Earth through more near orbits – but –with the angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far from the Earth to more far orbits. - I have an equation for the moon orbital motion depends on this angle (θ) - It tells (θ1 = θ0 +1.7 degrees) where (θ1= today angle and θ0= yesterday angle) - In fact, the idea of the angle (θ) solves many basic problems in the moon orbital motion explanation – we can reach to this idea only by using the planets data analysis method– - Notice - The Moon Orbital Perigee Radius = 363000 km - The Total Solar Eclipse Radius = 373000 km - The Moon Orbital Distance = 384000 km - The Moon Orbital Apogee Radius = 363000 km - But - (363000 km)2 + (86000 km)2 = (373000 km)2 - (373000 km)2 + (86000 km)2 = (384000 km)2 - (384000 km)2 + (86000 km)2 = (393500 km)2 - (393500 km)2 + (86000 km)2 = (406000 km)2 (error 1%) - The data simply tells, the moon 4 basic orbital radiuses be created depending on one another by Pythagorean rule because of the moon using of the angle (θ) in its motion. this data should be considered one more proof for the hypothesis. Notice The 2 examples (no.3 and 4) provide new discoveries in the planets motions – I use them to explain my research method (Planet Data Analysis Method)
  • 59. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawdrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 59 But We should distinguish between the basic and the additional I refer to a river and tell that I get water from this river by my bottle – you can use a barrel, a trunk, or a cup – up to you – It's my method to analyze PLANETS DATA and it's good for me – you can use it also or you can create another method (to use PLANETS DATA) But PLANETS DATA Should Be The Basic Reference For Any Theory Means You should accept any theory because this theory explains how planet data be created – and no contradiction be found between this theory and the planets data it's very important moment now because we create a law by which we can test the theory – after we will know if the theory is wrong and the imaginary ideas will not deceive us for years again the next question should be (how planet data be created?)