Abstract Paper hypothesis There's a light beam its velocity =1.16 million km per second. The hypothesis explanation - The Solar Planets Data Analysis proves that a light beam with velocity 1.16 mkm/sec must be found in the universe. - Shortly, the solar planets data is created depends on a light beam its velocity 1.16 mkm/sec. And if this light beam isn't found the solar planets data can't be created. Paper objective - The paper provides and discuss the planets data which proves the hypothesis. Mr. Gerges Francis Tawdrous +201022532292 Physics Department- Physics & Mathematics Faculty

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
(Preprint No. 4) (There's A light Beam Velocity = 1.16 mkm per second)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
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The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –28th
May 2021
Abstract
Paper hypothesis
There's a light beam its velocity =1.16 million km per second.
The hypothesis explanation
- The Solar Planets Data Analysis proves that a light beam with velocity 1.16
mkm/sec must be found in the universe.
- Shortly, the solar planets data is created depends on a light beam its velocity 1.16
mkm/sec. And if this light beam isn't found the solar planets data can't be created.
Paper objective
- The paper provides and discusses the planets data which proves the hypothesis.
Please scan the figure
(ORCID)

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Methodology
- I use The planets data analysis to discover the solar system origin and motion.
- The planets data analysis is a method search behind the planets data, for example,
it asks (why Earth axial tilt =23.4 degrees?).
- The planets data proves that they are created depending on light beam its velocity
= 1.16 mkm/s.
- Let's use one example to explain how the Planets data analysis method works?
Example No. (1)
- Let's suppose there's a planet its diameter = 12430 km
- In fact no planet in the solar system has this diameter, it's just a hypothesis.
- But
o 12430 km is the only middle rate between Venus diameter (12104 km) and
Earth diameter (12756 km).
o (Earth diameter 12756 km/ the moon diameter 3475 km) = (Jupiter diameter
142984 km/ 39050 km) (where 39050 km = 12430 km x π)
o Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km=
light motion distance during 1 second.
o Saturn (9.7 km/s) moves during 12430 seconds a distance = 120536 km=
Saturn diameter.
- There's no logic to suppose this data is found by any pure coincidences because the
previous behavior is similar to any (real) planet behavior…
- That tells us, (1st
) the solar system is created based on a geometrical design, (2nd
)
the (real) planets data is defined depend on this geometrical design. Because of
that the supposed data defined (geometrically) be in harmony with the real data.
- Shortly, the example tries to prove that, the solar system is created based on a
geometrical design, and because of that, we can conclude The Absent Data
- The Solar Planets Data proves that, it's created depend on a light beam its velocity
1.16 mkm/s

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
2- Light Velocity 1.16 mkm (The Proves Discussion)
2-1 Preface
2-2 Jupiter Motion Distance during 24.6 hours.
2-3 The Period 4222.6 seconds.
2-4 The Period 5040 seconds
2-5 The Distance 201467 mkm
2-1- Preface
- How to prove that, A light beam with velocity 1.16 million km per second is
found in the solar system?
- Let's summarize what we do in following:
o Jupiter Different Distances show the light velocity 1.16 mkm/s, for that, we
should put Jupiter data together, then
o Then we should ask
o How this data is created?
o Can this data be created from (the same) one origin?
o Can a geometrical rule found behind this data
o Why Jupiter Distances shows this feature (specifically).
o Also
o We should refer to more geometrical features of Jupiter data and try to know
if these features are produced by this (supposed) velocity 1.16 mkm/s.
Shortly
o We put the data of (1.16 mkm/s) together and try to find a geometrical
connection between them.

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
2-2 Jupiter Motion Distance during 24.6 hours.
- Jupiter (13.1 km/s) moves during (24.6 hours) a distance = 1160000 km
- It's the first time we see the distance 1.16 mkm.
- Why does Jupiter use 24.6 h (Mars rotation period) to move 1.16 mkm/s?
- Let's try to answer
o 4331 days (Jupiter orbital period) = 4222.6 x 24.6 h (Mars rotation period)
o But
o 4331 days (Jupiter orbital period) = 2π x 687 days (Mars Orbital Period).
- Some proportionality is found between Jupiter motion (periods) and mars motion
(periods). Does that refer to some geometrical mechanism behind this data? Let's
deepen the data analysis in following.

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
2-3 The Period 4222.6 seconds.
- Light supposed velocity (1.16 mkm/s) travels during 4222.6 seconds a distance =
4900 mkm = Jupiter Orbital Circumference.
- 4222.6 hours = Mercury Day Period - Where
- (Mercury rotation period 1407.6 h / Mars rotation period 24.6 h) = (180/π)
- Some geometrical mechanism is found between Mercury, Mars and Jupiter.
Notice
- The rate (4222.6) controls the inner planets data but using in different forms.
- 4222.6 mkm = 2π x 671 mkm (Venus Jupiter Distance)
- 4222.6 hours = Mercury Day Period
- 4222.6s / 5040s) = (928 mkm/778.6 mkm) – Let's add more data in following
More Data
- 4900 mkm = 360 mkm + 680 mkm + 940 mkm + 1433.5 mkm +1433.5 mkm
- Where
- 4900 mkm = Jupiter Orbital Circumference.
- 360 mkm = Mercury Orbital Circumference.
- 680 mkm = Venus Orbital Circumference.
- 980 mkm = Earth Orbital Circumference.
- 1433.5 mkm = Mars Orbital Circumference. Also
- Mercury moves during its day period a distance = Mercury Jupiter distance
- Venus orbital circumference = Venus Jupiter distance (error 1.3%)
- Earth orbital circumference = Earth Jupiter distance (error 1.2 %) (Notice, Earth
and Jupiter should be on 2 different sides from the sun to create this distance 928
mkm which = 98.8% of Earth orbital circumference 940 mkm).
- The data shows some geometrical mechanism behind…
- Notice
- 778.6 mkm = 1.16 mkm/s x 671 seconds (778.6 mkm = Jupiter orbital distance)
- 720.7 mkm =1.16 mkm/s x 629 seconds (720.7 mkm = Mercury Jupiter distance)
- 671 mkm =1.16 mkm/s x 580 seconds (671 mkm = Venus Jupiter distance)
- 580 mkm =1.16 mkm/s x 500 seconds

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
2-4 The Period 5040 seconds
- Mercury day period =4222.6 hours
- i.e.
- It needs 5040 seconds to be 176 solar days.
- But
- Light supposed velocity (1.16 mkm/s) travels during 5040 seconds a distance =
5848 mkm = Mercury Pluto Distance.
Notice (1)
- 5848 mkm /57.9 mkm (Mercury orbital distance) = 101
- 153.3 hours (Pluto day period) = 101 hours x 1.5 and
- (Mercury orbital period 2112 h/ Mercury rotation period 1407.6 h) = 1.5
Notice (2)
- Mercury (47.4 km/s) moves during its day period (4222.6 h) a distance = 720.7
mkm= Mercury Jupiter distance
- Jupiter (13.1 km/s) moves during the period (4222.6 h) a distance = 629 mkm=
Earth Jupiter Distance.
But
- (778.6 mkm/720.7 mkm) = (720.7 mkm/ 671 mkm) = (671 mkm/629 mkm) = (629
mkm/580 mkm) =1.0725
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 720.7 mkm = Mercury Jupiter Distance
- 671 mkm = Venus Jupiter Distance
- 629 mkm = Earth Jupiter Distance
- 580 mkm = the distance passed by light supposed velocity (1.16) in 500 s

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
2-5 The Distance 201467 mkm
Equation no. (1)
201467 mkm = 2 x The Planets Orbital Circumferences Total 100733.5 mkm
Equation no. (2)
201467 mkm = 2 x 86400 seconds x 1.16 mkm/sec
Equation no. (3)
201467 mkm = (Pluto Orbital Circumference – Jupiter orbital circumference) x 2π
Equation no. (4)
201467 mkm = 28255 mkm + 2 x 86400 mkm
Equation no. (5)
201467 mkm = (Jupiter Circumference 449378.3 km)2
The Discussion
Equation no. (3)
201467 mkm =(Pluto Orbital Circumference –Jupiter orbital circumference) x2π
- Equation no. (3) summarizes the whole data meaning.
- The distance 201467 mkm can be passed in a period = 2 solar days (= 2 x 86400 s)
if the light velocity be (1.16 million per second).
- The distance 201467 mkm is the main data behind the paper hypothesis (a light
beam with velocity 1.16 mkm per second is found).
- The distance 201467 mkm is defined between Jupiter and Pluto orbits based on
Equation no. (3).
- Why can this distance prove the light supposed velocity (1.16 mkm/s) existence?
- Because,
- (1) Light needs 2 complete solar days to pass this distance, and the period 2 solar
days (2 x 86400 seconds) is a unit period and not part of any period, that tells some
cycle is found behind this period using.
- (2) The distance 201467 mkm = 2 x the solar planets orbital circumferences total
- That tells, the light supposed velocity (1.16 mkm/s) moves during 1 day a distance
= the solar planets orbital circumferences total, and this data shows a consistency.
- But Jupiter data shows using of 2 folds of these values, and that tells Jupiter
motion geometrical mechanism for geometrical necessities use the double value.

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
Equation no. (4)
201467 mkm = 28255 mkm + 2 x 86400 mkm
86400 mkm=(Neptune Orbital Circumference –Venus orbital circumference) x π
- Equation no. (4) shows that, the distance 201467 km is used to built the distances
between Neptune and Venus (1st
Trajectory) and between Neptune and Earth (2nd
Trajectory). i.e.
- 201467 mkm is decreased by 28255 mkm (Neptune orbital circumference) and the
rest value is divided into 2 equal trajectories from Neptune to Venus and to Earth
(notice, Earth Equation be similar to Venus equation because the error is less 1%)
- I want to say that,
- The distance 201467 mkm, isn't defined only by Jupiter and Pluto data, but this
same distance (value) controls the distances between the outer and inner planets.
We deal here with a light beam which can be reflected from point to another
creating the same effect.
Notice
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4
- Where
- 57.9 mkm = Mercury Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
- The data shows that, the inner planets distances depend on (4495.1 mkm) because
of the data tells by Equation no. (4).
- The distance 201467 mkm is defined between Jupiter and Pluto, but used by
Neptune toward the inner planets according to equation no. (4), because of that the
inner planets distances depend on Neptune orbital distance.

9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
References
Did Lorentz Ask (How The matter is Created)?
https://www.academia.edu/48987206/Did_Lorentz_Ask_How_The_matter_is_Created_
Can Saturn Motion effect on Venus Motion?
https://www.academia.edu/49005865/Can_Saturn_Motion_effect_on_Venus_Motion
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
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Physics Department- Physics & Mathematics Faculty
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