Earth Velocity Daily Analysis (Revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Earth Velocity Daily Analysis (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –23rd
May 2021
Abstract
Paper hypothesis
- The Motion Is Transported Among The Solar Planets.
The hypothesis explanation
- The Earth moon displacements total during 29.53 days = 2598693 km
- Pluto (4.7 km/s) moves during (153.3 h) a distance = 2593836 km
- Why These Distances Are Equal?
- How the motion at distance be done? or by what geometrical mechanism the
masses gravity causes a motion at distance? These questions still need answers
- The motion transportation among the planets can be answer for these questions.
- What does mean "A motion Transportation"?
- It means, a planet motion causes another planet to move, and this motion depends
on the planet motion and not on its masses gravity only. That tells, the motion
transportation process must be done based on new geometrical rules.
- If the paper hypothesis is true and the motion is transported among the solar
planets, that will answer why these 2 distances are equal? Because the motion is
transported from one planet to another and by that the 2 planets move equal
distances in defined periods of time.

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Paper objective
- The paper tries to prove that, the motion is transported from a planet to another
planet through the solar system and this motion transportation caused Pluto motion
distance during its day period to be = the moon displacements total
Paper conclusion
- The paper concludes that, the solar system is one building and each planet is a part
of this same building and
- This building has one geometrical design
- And this geometrical design necessitates to make Pluto motion distance during its
day period = the moon displacements total during its day period for geometrical
necessities.
Please scan the figure
(ORCID)

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1- Introduction
- Earth (29.8 km/s) moves during (24 hours) a distance = 2574720 km
- The Earth moon displacements total during 29.53 days = 2598693 km
- Pluto (4.7 km/s) moves during (153.3 h) a distance = 2593836 km
- Uranus (6.8 km/s) moves during 378675 seconds a distance = 2574990 km
- Mars (24.1km/s) moves during 29.53 hours a distance = 2562023 km
- Why These Distances Are Equal Approximately? (The difference 1%)
- Saturn (9.7 km/s) moves during its day period a distance = 373644 km= 98.76 %
of Saturn Circumference (378675 km) (the difference =5031 km)
- If Saturn moves during its day period a distance = Its circumference, that would
make (Saturn orbital circumference (9010 mkm) / Saturn Circumference) = (Saturn
orbital period / Saturn day period)
- Because Saturn moves less than its circumference with 1.3% this proportionality
isn't produced perfectly.
- Why Saturn doesn't move in its day period a distance = it circumference?
- Can this 5 planets motions distances equality be the reason?
- What does this paper try to do?
- If the motion be transported from a planet to another and this motion transportation
cause Pluto to move during its day period a distance = the moon displacements
total during the moon day period… that necessitates the transporting motion to
effect on different planets through its trajectory. The paper claims that, the
transporting motion cause Saturn motion distance during its day period to be less
than its circumference with 1.3% as a geometrical mechanism for the motion
transportation process.
- The paper task can be summarized in 2 points, (1st
) to prove that the 5 planets
motions distances are one motion transported from one planet to another (2nd
) to
prove that the transporting motion caused Saturn to move during its day period a
distance less than its circumference with 1.3%

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2- Saturn Motion Distance During Its Day Period
2-1 Preface
2-2 The Distance 23700 Km
2-3 The Period 518 seconds
2-4 Venus Data Effect on Saturn motion
2-1 Preface
- How to make Saturn (9.7 km/s) to move in its day period (10.7 h) a distance = its
circumference (378675 km)?
- Saturn needs 518 seconds to be added to its day period, and by that, Saturn day
period no longer be 38520 seconds but be 39038 seconds
- But
- Saturn Orbital Circumference (9007 mkm) = 378675 km x 23785 km
- Means, Saturn motion has 2 basic values are (23785 km and 518 seconds)
- The paper hypothesis tells that, because the 5 planets motions distances are equal,
Saturn day period which should be (39038 seconds) be (38520 seconds) only and
because of that Saturn moves during its day period a distance = 373644 km which
is less than Saturn circumference (378675 km) with 1.3%
- We follow the paper hypothesis and search if these 2 values have any relationship
with the 5 planets motions distances, and if this relationship is found we hope to
discover the geometrical reason which causes this relationship
- That's why we analyze the values (23700 km and 518 seconds) in this point of
discussion
- Let's start immediately

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2-2 The Distance 23700 Km
I- Data
Group No. (A)
Saturn Orbital Circumference (9007 mkm) = 378675 km x 23785
Group No. (B)
1. Earth (29.8 km/s) moves during (24 hours) a distance = 2574720 km
2. The Earth moon displacements total during 29.53 days = 2598693 km
3. Pluto (4.7 km/s) moves during (153.3 h) a distance = 2593836 km
4. Uranus (6.8 km/s) moves during 378675 seconds a distance = 2574990 km
5. Mars (24.1km/s) moves during 29.53 hours a distance = 2562023 km
Group No. (C)
(6)
The difference between the moon motion (2) – Uranus motion (4) = 23703 km
(7)
2598693 km -2550973 km =47720 km = 2 x 23860
(8)
Uranus (6.8 km/s) moves during 3475 seconds a distance = 23630 km
(9)
47720 km = 7510 km x 6.3875 (error 0.5%)
(10)
Pluto (4.7 km/s) moves during 5040 seconds a distance = 23688 km
(11)
Saturn (9.7 km/s) moves during 4879 seconds a distance = 23663 km x2
(12)
Mercury (47.4 km/s) moves during 500 seconds a distance = 23700 km

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II- Discussion
- Data Group No. (A) tells
Saturn Orbital Circumference (9007 mkm) = 378675 km x 23785
- The value 23785 is the rate between Saturn orbital circumference and Saturn
Circumference.
- If Saturn moves during its day period a distance = its circumference, in this case
this value (23785) will be the rate between Saturn orbital period (10747 days =
257928 hours) and Saturn day period(10.7 hours).
- But because Saturn (9.7 km/s) moves during its day period (10.7 h) a distance
=373644 km = 98.67% of Saturn Circumference the real rate is increased 1.3%
than this value (23785) and be (24105 = 2 x12053)
- Venus diameter =12104 km and different 12053 km with (0.4%) (we should Venus
data effect on Saturn motion in point no. 2-5)
- What we need here is to notice the value 23785 and keep our eyes on it because it
will answer the question (why doesn't Saturn during its day period a distance = its
Circumference)?
Group No. (C)
The data tells that, the value 23785 km is a value defined by other planets motions,
let's discuss that in following….
- The moon displacements total during 29.53 days (its day period) = 2598693 km,
this distance should be the moon apogee orbital circumference, in this case the
moon apogee radius should be = 413600 km
- But
- The moon real apogee radius =406000 km, so its circumference = 2550973 km
- The difference between 2598693 km and 2550973 km= 47720 km = 2 x 23860 km
- That shows, the value (23860 km) is belonged to the moon motion (as shown in
equation no. 7)
- But

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- The moon displacements total (2598693 km) is increased than the distance passed
by Uranus (2574990km) with the value 23703 km
- That means, the difference between the moon displacements and Uranus motion
distance = 50% of the different distance between the moon displacements total and
the moon apogee orbital circumference
- Why?
- Can this data provide any reference that Uranus motion effect on the moon motion
and caused the moon apogee orbital circumference to be decreased from 2598693
km to 2550973 km?
- We can't answer now, more analysis may help us
Equation no. (8)
Uranus (6.8 km/s) moves during 3475 seconds a distance = 23630 km
- Where
- 3475 km = The Moon Diameter
- This equation tells that, some geometrical mechanism is found behind this data, the
distance passed by Uranus is decreased than the moon displacements total with
23703 km – and equal distance Uranus passes during (3475 sec) where (the moon
diameter =3475 km) when the moon apogee orbital circumference is less than the
moon displacements total with 2 x 23703
- We deal with a geometrical system creates the data geometrically….
- What geometrical mechanism is behind this data? How they are created? we can
conclude only that, this geometrical mechanism caused the moon apogee orbital
circumference to be less than the moon displacements with the value 47720 km,
this process must be effected greatly by Uranus Motion

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Equation no. (9)
47720 km = 7510 km x 6.3875 (error 0.5%)
- Where
- 7510 km = Pluto Circumference
- 47720 km = 2598693 km – 2550973 km
- But
- What's the rate 6.3875?
- Earth velocity 29.8 km /s = Pluto Velocity 4.7 km/s x 6.3875
- Pluto Day Period 153.3 hours = Earth Day Period 24 hours x 6.3875
- Frequently we have asked why (Earth velocity/ Pluto velocity) = (Pluto day period/
earth day period)? What geometrical reason was found behind this proportionality?
And Equation no. (9) tells us some answer,
- The geometrical process by which the moon orbital circumference is crated shorter
than the moon displacements total during its day period was the process in which
this proportionality is done –we can say that – it's a complex process –where in it
many planets (players) effect on one another to perform the required result.
- How can we understand this data? Let's summarize the idea in following
- Uranus motion effected on Pluto motion, by this effect Uranus motion caused
Pluto day period to be 153.3 hours which is very long day period in comparison
with the outer planets (Jup. 9.9 h, Satu 10.7 h, Ura 17.2 h and Neptune 16.1 h).
- Uranus caused Pluto day period to be so long (153.3 hours) by Uranus motion
effect on Pluto motion. we know that Uranus did this effect because Uranus day
period =17.2 hours and Pluto orbital inclination =17.2 degrees, by this data we
conclude that, the (period of time) is transported to Pluto in (degrees form) and by
this transportation Uranus effects on Pluto motion to extend Pluto day period (let's
use this idea as a hypothesis for now).
- Uranus extends Pluto day period by using the earth moon motion

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- That means, this process is done inside the moon orbit
- So, the moon orbit has some (so) complex process, where Pluto day period is
extending and that effect on the moon orbital circumference to be shorter than the
moon displacements total this process also effects on Saturn motion and caused
Saturn to move during its day period a distance less than its circumference with
(5031 km), this is not the last effect of this process but, before all, this process
caused mercury day period to be less than 176 solar days with 5040 seconds.
- So we need to see how these effects are created by this one process- and these
effects should be considered as proves for the motion transportation among the
solar planets because the same (one ) process effects on different planets and
caused (modifications) for this data which be in harmony with the process caused
them.
- Also
- We have to keep our eyes on the question, because we don’t need to miss the paper
objective through the discussion…. We need to know what geometrical result or
effect be found by the 5 planets motions distances equality – simply – what result
we get if these 5 planets move equal distances?
Equation no. (10)
Pluto (4.7 km/s) moves during 5040 seconds a distance = 23688 km
- Where
- Mercury day period =176 solar days minus 5040 seconds
- Pluto (4.7 km/s) moves during (5040 sec) a distance = 23688 km, that means,
Pluto moves during 2 x 5040 seconds a distance = 2 x 23688 km = 47720 km (1%)
- Equation no. (10) tells that Pluto motion is related (surely) to the different distance
between the moon displacements total and its apogee orbital circumference. Pluto
is a direct player in this effect…
- The paper hypothesis tells, the moon displacements total is transported to Pluto
and be Pluto motion distance during its day period. It may be a fact!

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- Also
- The value (5040 seconds x 2 = 10080 seconds) is so important value because it's
the rate between light velocity and earth velocity
- We may remember that, the best harmony of 2 planets data is found in Earth and
Pluto data. Their data depends on one another almost in all motions data, that
shows the value (10080) has a deep geometrical effect.
Notice
- The value 5040 seconds is a basic geometrical value in the solar system motion.
we need to pay attention to it each time we see it for its massive geometrical effect
- Also
- Saturn motion distance during its day period is less than Saturn circumference with
5031 km and if 1 km = 1 second, that make this value =5031 seconds
- That may tell some reason may be found an connect Saturn and Mercury motions
- Specially because
o Mercury moves during 5040 seconds a distance = 2 x 119448 km = 2 Saturn
diameters (error - 1%) and
o Mars moves during 5040 seconds a distance = 121646 km = Saturn
diameters (error + 1%).

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Equation no. (11)
Saturn (9.7 km/s) moves during 4879 seconds a distance = 23663 km x 2
- Where
- 4879 km = Mercury Diameter
- Equation no. (11) tells, Saturn moves during (4879 seconds) a distance = 2 x
23663 km (we still deal the same distance 23703 km)
- Simply the value (2 x 23663 km= 47720 km = the difference between the moon
displacements total and the moon apogee orbital circumference)
- Why does Saturn use Mercury Diameter?!
Old Equation no. (A)
Uranus (0.5875 mkm / day) moves during 4879 days = 2872.5 mkm
- Where
- 2872.5 mkm= Uranus Orbital Distance
- 0.5875 mkm= Uranus velocity per a solar day
- Simply we can remove the value (4879) in 2 equations and make them as one
equation, and by that we will conclude that, the distance (23663 km) in Saturn
motion is defined by Uranus motion effect.
- What does that mean?
- Uranus motion effected on Saturn motion and caused to create the distance 23703
km between Saturn motion distance during its day period and Saturn
circumference, that tells us why Uranus uses Saturn circumference (378675 km) as
a period of ti9me (378675 seconds) to pass during it the distance 2574990 km.
(where this distance is one of the 5 planets motions equal distances).
- Shortly
- Uranus motion distance caused to create the distance 23703 km and its effect on
the moon orbital circumference and on Saturn motion during its day period.
- Uranus depends on (Venus, Earth and Pluto) to perform this process.

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Equation no. (12)
Mercury (47.4 km/s) moves during 500 seconds a distance = 23700 km
- Equation no. (12) tells that, Mercury moves during 500 seconds a distance =
23700 km, which is the distance we analyze in this point of discussion
- We know that, the distance (23700 km) is found by Uranus motion effect on the
moon and Saturn motions, and Uranus depends on (Venus, the Earth and Pluto) in
this process
- But
- Equation no. (12) tells that, Mercury moves during 500 seconds a distance =23700
km why?
- This equation is interesting not only because of the distance 23700 km but also
because of the period 500 seconds where light needs 500 second to reach from the
sun to Earth….
- Is there any geometrical puzzle behind this data? What's happening here?
- Let's analyze this value 500 seconds in following….
o Saturn (9.7 km/s) moves during 500s a distance = 4879 km= Mercury
Diameter
o Mars (24.1 km/s) moves during 500s a distance = 12050 km
o Neptune (5.4 km/s) moves during 4 x 500s a distance = 10800 km
o It's interesting that, Mercury moves during 5040s a distance = 2 Saturn
diameters and Saturn moves during 500 seconds a distance = Mercury
diameter
o Also, interesting that, Mars moves during 500 s a distance =12050 km
where this value (12053 km) is used in Saturn orbital period and distance
frequently and based on geometrical reason. So very great geometrical
mechanism must be found under this data
o We should complete this discussion with the analysis of the period 518 s in
following…

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2-3 The Period 518 seconds
I – Data
- Mercury (47.4 km/s) moves during 518 s a distance = 24553 km= Neptune radius
(0.8%)
- Venus (35 km/s) moves during 518 s a distance = 18130 km (But 18130 seconds =
5.04 hours)
- Earth (29.8 km/s) moves during 518 s a distance = 15436 km (Mercury
circumference) (error 0.7%)
- Mars (24.1 km/s) moves during 518 s a distance = 12484 km
- Jupiter (13.1 km/s) moves during 518 s a distance = 6786 km = Mars diameter
- Saturn (9.7 km/s) moves during 518 s a distance = 5031 km
- Uranus (6.8 km/s) moves during 518 s a distance = 3522.4 km = (Mars
Circumference /6) (error 1%)
- Neptune (5.4 km/s) moves during 518 s a distance = 2798 km= 4.7 x 595s
- Pluto (4.7 km/s) moves during 518 s a distance = 2435 km =Mercury Radius
II – Discussion
- Why we need to analyze the period 518 seconds?
- Because
- Saturn (9.7 km/s) moves during its day period (10.7 h) a distance = 98.67% of
Saturn Circumference
- We ask how Saturn moves during its day period a distance = its circumference? If
Saturn day period be extending with 518 seconds it will do…. Means
- Saturn day period =38520 seconds and need to be 39039 seconds to do the task
- For that we analyze the period 518 seconds – as shown in the previous data-
- From the different planets motions we choose Mars Motion
- Why? because
- Mars moves during 518 seconds a distance = 12484 km
- Where 39039 km = π x 12430 km (different from 12484 km with 0.4%)

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- Means, Mars moves the distance (value) which we need to use it (as a period of
time) to make Saturn moves during its day period a distance = its circumference.
- The value 12430 km is so interesting number generally…. Why?
A- The diameter 12430 km is the only middle rate between Venus diameter
(12104 km) and earth diameter (12756 km)
B- Saturn (9.7 km/s) moves during 12430 seconds a distance = 120536 km =
Saturn diameter.
C- Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km =
light motion distance during 1 second of time
D- (Earth Diameter / its moon diameter) = (Jupiter diameter /39039 km)
- The data tells clearly that, we deal with a geometrical system and the data is
created bas on geometrical rules depends on each other.
- That tells, there's some geometrical reason behind Mars motion during 518 s
- But what does this geometrical reason?
- We remember our distance 23700 km
- 12430 km = 1.9 x 23700 km But (1.9 degrees = Mars orbital inclination)
- Can we conclude any geometrical mechanism behind this data? Let's try to see
o 1.9 hours = 6840 seconds (Mars diameter =6792 km the error 0.7%)
o Based on that, we try the following
o 47720 km = 6792 km (Mars Diameter) x 7
o (where 7 degrees = Mercury Orbital Inclination) But
- Mars moves during (29.53 hours) a distance = 2562075 km
- 2562075 km = 7 x 366556 km (the outer planets diameters total)
- Why we need this value? Because
- Mercury moves during 366556 seconds a distance =17.4 mkm
- What I try to do is to prove that, some geometrical system is found under this data
creation, nothing here is created neither independent nor by chance. The data
clearly is created based on each other by geometrical rules.

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Means,
- Some geometrical mechanism uses Mars motion distance to define the value
(12430) geometrically based on the period (518 seconds)
- That tells, the difference in periods from (39039 seconds) to (38520 seconds) is
found for geometrical necessity.
Notice (1)
- Uranus motion (2574990km) – Mars motion (2562075 km) =12915 km
- But
- Earth motion ( 2574720 km) – Mars motion (2562075 km) =12645 km
- (the value 12645 km is more near to Earth diameter 12756 km than 12915 km, the
errors are 0.8% and 1.2% respectively, means we should depend on Earth motion
and not Uranus motion, but because Uranus uses Saturn circumference for that we
use it for Saturn data – that means – some geometrical interaction is still need to be
discovered to know how Earth motion is interacted with Uranus motion)
Notice (2)
- 7 hours x 2 = 50400 seconds
- The moon displacements total during 50400 solar days = 4437 mkm = Mercury
Notice (3)
- 7 hours x 2 = 50400 seconds
- The moon displacements total during 50400 solar days = 4437 mkm = Mercury
Neptune Distance.
- Where
- 4437 mkm =23700 km x 187215 And
- Pluto (4.7km/s) moves during 39833 seconds a distance =187215 km
- (Earth Circumference =40080km error 0.6%)
Notice (4)
- Mercury moves during 511 seconds a distance = 2 x 12104 km

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2-4 Venus Data Effect on Saturn motion
(I) Venus Motion
- Venus (35km/s) moves during 73571 seconds a distance = 2574990 km = Uranus
motion distance during (378675 seconds).
- By this data, Venus motion be included among the 5 planets motions equal
distances, and by that Venus should be (the 6th
planet) among the group
- But
- What's this period 73751 seconds?
- 73751 km = π x 23476 km
- The distance 23476 km is very near to our distance 23700 km (error 1%)
- That tells Venus is a partner in the same interaction from which the moon apogee
orbital circumference be shorter than displacements total with the distance 47720
km
- Notice
- 12104 km (Venus diameter) x 6 =72624 km (very near to 73751 km error 1.3%)

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(II) Venus Diameter
Data
(A)
- 10747 days = 257928 hours (Saturn orbital period) = 10.7 h x 2 x 12053
- 1433.5 mkm = Saturn orbital distance = (12053 km x π)2
- 12050 km = Mars motion distance during 500 seconds
(B)
- Uranus day period 17.2 h = 61920 s = 12104 s x 5.1
- Where
- Venus velocity 35/ Uranus velocity 6.8 = 5.1
- Also
- 30589 days (Uranus orbital period) x 2 = 12104 x 5.05
(C)
- 6.7 hours = 2 x 12060 seconds
Discussion
- The data tells if there's some motion transportation is occurred based on the 6
planets motions distances equality, so, Venus diameter should be a basic method to
perform this motion transportation.
- The data we have discussed before in details
- The concluded meaning almost is a correct one because the data is created based
on geometrical design, means, the data is mentioned geometrically.
- Notice
- 12430 km = Venus motion distance during 355.2 seconds where (355.2/360)=
(373644 km/378675km).

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3- Earth Velocity Daily Analysis
3-1 The Moon And Pluto Data Analysis
3-2 Uranus Effect on Pluto Motion
3-3 Uranus Effect on The Moon Motion
3-4 Saturn Motion Effect
3-1 The Moon And Pluto Data Analysis
I-Data
(1)
The Moon Mass (0.073 x 1024
kg) = 5 x Pluto Mass (0.0146 x 1024
kg)
(2)
17.4 degrees = 5.1 deg (the moon orbital inclination) x 3.4 deg
(3)
Saturn Mass (568 x 1024
kg) = 39050 x Pluto Mass (0.0146 x 1024
kg)
II-Discussion
- The data shows that the rate (5) is found between the moon and Pluto masses
where we remember that the rate (5.05) controls the data of Venus, Saturn and
Uranus motions (between 5 and 5.05 the error 1% and with 5.1 the error 2%)
- Equation no. (2) we know, 17.4 deg = the inner planets orbital inclinations total,
but 17.2 deg = Pluto orbital inclination (=0.99 x 17.4 deg)
- 3.4 dg = Venus orbital inclination
- Equation (1) and (2) tell that, the rate (5 or 5.1) is created by the moon and Pluto
data proportionality and it controls the motions data of 3 great planets (at least) ,
Why?
- Equation no. (3) shows the rate of masses between Saturn and Pluto producing the
rate 39050 (= π x 12430), and we know this number (12430) which is very specific
number for Saturn motion – we should review it later
- Saturn mass = 116.75 x Venus mass but 116.75 solar days = Venus day period, I
try to tell that, the planets masses a rate be used geometrically in their motions.

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3-2 Uranus Effect on Pluto Motion
- Why are the 6 planets motions distances equal? Let's summarize the idea:
o Uranus motion effects on Pluto motion to extend Pluto day period
o Because of that, Pluto day period be =153.3 hours which is the longest day
period among the outer planets. This result is done by Uranus motion effect
on Pluto motion
o Pluto orbital inclination =17.2 degrees where Uranus day period =17.2 hours
and I claim that, this data can be used as a proof that Uranus caused Pluto
day period to be extending and be =153.3hours.
o Venus diameter =12104 km but it's used as a period of time (12104 seconds)
where 12104 seconds =3.4 hours and Venus orbital inclination =3.4 degrees,
I try to show that the data which we accept as defined data clearly in fact can
be used in another form completely. And by that Planet orbital inclination
can be used as a period of time.
o Why did Uranus that?
o Uranus wanted to enable Pluto to move during its day period a distance =
earth motion distance during its day period (error 1%) or in more accurate
words equal the Earth moon displacements total during its day period.
o Shortly,
o Pluto motion distance during its day period should be = the moon
displacements total during its day period (29.53 solar days) for that Pluto
Day Period be = 153.3 hours.
o We have 2 questions, Why? and How?
o The question (Why) is the paper objective we should answer with the
general conclusions
o The question (How), Uranus did that depends on Saturn motion data.
o Now let's discuss the data of Uranus effect on Pluto motion in following..

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I-Data
(4)
12104 km /2390 km = 5.05
(5)
122.5 hours = 5.1 days (where 122.5 degrees = Pluto Axial Tilt)
(6)
3033.5 mkm = 5.1 x 595 mkm (where 742 mkm x 0.8 =595 mkm)
(7)
(30589 days/ 27.3 days) = (5757 mkm/149.6 mkm)
II-Discussion
- This discussion completes the previous 2 papers discussion, so we have to review
them
- (1st
paper, (Did Lorentz ask (How The matter is Created)?
- (2nd
paper, (,Can Saturn Motion effect on Venus Motion)?
- Please review the references
- We need these 2 papers because, the data is one continuum and the data part is
inserted in these 2 papers so huge to be added here but we need it.
- Shortly
- Uranus, Venus and Saturn Motions depend on 2 Basic data which are (12104
seconds and 5.1) where (12104 km = Venus diameter and 5.1 deg = the moon
orbital inclination).
- So, this paper data supports the same direction and uses the same rates (12104 and
5.1), showing that the data is created by a geometrical system and because of that
this geometrical system forces to use the same data frequently – let's refer to each
equation contents in following

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Equation No. (4)
12104 km /2390 km = 5.05
- Where
- 12104 km = Venus Diameter
- 2390 km = Pluto Diameter
- (Notice 12430 km/2390 km = 5.2)
Equation No. (5)
122.5 hours = 5.1 days (where 122.5 degrees = Pluto Axial Tilt)
- Equation no. (5) uses Pluto axial tilt as a period of time (122.5 hours) which is a
general using we have practiced frequently in the solar system motion data.
Equation No. (6)
3033.5 mkm = 5.1 x 595 mkm (where 742 mkm x 0.8 =595 mkm)
- Where
- 3033 mkm = Uranus Pluto Distance
- 595 mkm = is a distance be found based on Venus rotation period (243 days).
Equation No. (7)
(30589 days/ 27.3 days) = (5757 mkm/149.6 mkm)
- Where
- 30589 days = Uranus Orbital Period
- 27.3 days = The Moon Orbital Period
- 5757 mkm = Earth Pluto Distance
- 149.6 mkm = Earth Orbital Distance
Notice
- Because Uranus uses Pluto day period in (Planet 8 Days Cycle) that causes Uranus
motion to be interested with Pluto motion (continuously). Means, the cycle
provides a proof that Uranus motion effects on Pluto motion.

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3-3 Uranus Effect on The Moon Motion
I- Data
(8)
3475 seconds x 6.8 km /s = 23630 km
(9)
9007 mkm = 378675 km (Saturn Circumference) x 23705 km (0.3%)
(10)
378675 seconds =4.38 solar days (where (29.53 days /4.38 days) = 6.737
(But 6.7 deg = the moon axial tilt error 0.6%)
(11)
6.7 hours x 3600 s = 2 x 12060 seconds
(12)
2598693km = 6.8 km/s x 382000 seconds
(13)
2.76 mkm = 6.8 km/s x 406000 seconds
But
27.6 mkm = 1.0725 x 2.574 mkm (Earth motion distance during its day period).
II- Discussion
Equation No. (8)
3475 seconds x 6.8 km /s = 23630 km
- Where
- 3475 km = The Moon Diameter
- 6.8 km/s = Uranus velocity
Equation No. (9)
9007 mkm = 378675 km (Saturn Circumference) x 23705 km (0.3%)
- Where
- 9007 mkm = Saturn Orbital Circumference
- 378675 km = Saturn Circumference

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Equation No. (10)
378675 seconds =4.38 solar days (where (29.53 days /4.38 days) = 6.737
(But 6.7 deg = the moon axial tilt error 0.6%)
- equation no. (10) gives us a new extension, it tells the moon axial tilt 6.7 degrees is
defined based on the interaction of Saturn and the moon motions data
- the simple idea is that, because Saturn circumference 378675 km is used as a
period of time (378675 seconds) as done by Uranus motion, so this period be =
4.38 solar days
- The rate between 29.53 days and 4.38 days = 6.7 (The Moon Axial Tilt)
Equation No. (11)
6.7 hours x 3600 s = 2 x 12060 seconds
- Equation no. (11) tells that, the moon axial tilt (6.7 deg) can be used as 6.7 hours
(as many other planets data do) in this case the period 6.7 hours be equal = 2x
12060 seconds
- Where 12104 km = Venus diameter
- We should remember Saturn data where (10747 days Saturn orbital period =
257928 hours = 10.7 hours (Saturn day period) x 2 x 12053
- Simply the rate (12104) is used in the most planets motions data. It's a value found
frequently and continuously…. Why?
- It's one unified motion done by these 5 planets and because of that this (one)
motion data is found in all planets

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3-4 Saturn Motion Effect
Equation no. (14)
0.3 mkm/s (light velocity) x 120536 seconds = 36161 mkm = 2π x 5757 mkm
- Where
- 5757 mkm = Earth Pluto Distance
- 120536 km = Saturn Diameter
- Equation no. (14) tells the orbital circumference between Earth and Pluto depends
on Saturn diameter.
- It tells light travels during 120536 seconds a distance = the orbital circumference
between earth and Pluto,
- Geometrically, we can't now depend on light motion to explain how the data is
created, because there's a geometrical mechanism depends on the rigid bodies
motions perform this same task but the data still needs more analysis to discover
this geometrical mechanism, so, light motion gives the required reference directly.
- This equation we need because the 5 planets motions equal distances depend on
Earth motion distance during its day period, and based on that the 5 planets move
equal distances for that reason equation no. (14) uses the distance between earth
and Pluto
- Also
- Uranus depends on uses circumference (378675 km) as a period of time
(378675seconds) because of that the light uses the period 120536 seconds to pass
the required distance
- The geometrical design behind must be so complex but equation no. (14) tells
directly, Saturn is the pillar on which the 5 planets motions distances be equal.
Means, without Saturn these 5 distances can't be equal.
Notice
2π x 5756.5 mkm = 2.593836 mkm x 4437.2 days
4437.2 mkm = Mercury Neptune Distance

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References
Can Saturn Motion effect on Venus Motion?
https://www.academia.edu/49005865/Can_Saturn_Motion_effect_on_Venus_Motion
Did Lorentz Ask (How The matter is Created)?
https://www.academia.edu/48987206/Did_Lorentz_Ask_How_The_matter_is_Created_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
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http://orcid.org/0000-0003-3447-0425
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Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
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Earth Velocity Daily Analysis (Revised)

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