Planet Motion Logic Disproves Newton Theory Of The Sun Gravity.pdf

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –23rd
July 2022
Abstract
Paper Argument
- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
- (1)
- By one force planet be created and moving – means - the force which created the
Planet– it causes its motion – as a result
- (No Planet Moves By The Sun Gravity) because (The Sun Had Created No Planet)
- One more force caused the planets creation and their motions
- For that reason
- Planet creation and motion data be in harmony one another –
- For example (Mercury creation and motion data be in harmony one another) and
Mercury moves safely and isn't broken
- But -we don't have 9 forces in the solar system – One force for each planet –
instead – We have one force only caused All Planets Creation And Motion
- Now- let's ask
- How Can One Force Create 9 Planets And Causes Their Motions?
- This force needs to use One Geometrical Design to do this job – as 9 gears be
moving by one motor we need a machine to do this job
- Based on this analysis – No planet moves by the sun gravity – Newton is wrong

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- (2)
- The gravitation equation is wrong because no planet orbital distance be defined
based on it- and that explains the contradiction between the planets masses order
and their orbital distances
- This fact is a powerful against Newton – but the logic still more power
- Because
- The planet orbital distance be defined before this planet creation – because – the
distance be defined by other planets distances – means - the new planet orbital
distance be defined based on the balancing of the current planets motions
trajectories and by that the new planet will find itself in a position defined
obligatory by other planets –
- This fact be proved also by my first equation which proves that each planet orbital
distance depends on its neighbor planet orbital distance (Not On Its Mass)
- My First Equation tells (d2
= 4d0 (d-d0))
- d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
- (My 5 Equations Be Tested And Discussed In The Paper)
- I want to say
- The principle idea is wrong because the distance be defined obligatory by other
planets motions trajectories and planet mass can do nothing to change it
- (3)
- The logic still moves against Newton because
- The planet is found itself in an obligatory position and has to revolve around the
sun from this position – now what about this planet diameter – because
- If the planet diameter isn't in harmony with its orbital distance this planet will be
broken – here – Newton idea is wrong completely because he looked at the mass
but planet mass can decrease its velocity where the wrong diameter can cause the
planet to be broken – by that – the planet has to create a function between its

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orbital distance and its diameter to move safely otherwise it will be broken – the
point is Newton defined the mass as the basic player!
- In fact the question be related to the diameter because it creates the geometrical
effect of this planet through its motion- and the wrong diameter can cause this
planet to be broken.
- Now Kepler is the source based on which Newton created his theory
- Kepler stated (Planet orbit defines its velocity) – but why?
- Newton idea tells – Planet motion depends on its mass – and by that – the mass
defines the distance and velocity – the whole idea is wrong
- The fact is that
- The planet is found itself in an obligatory position and has to revolve around the
sun – by that –
- The designer had 2 jobs
- First job to create a relationship (a function) between planet diameter and its
orbital distance to save this planet in its motion –
- But this relationship (function) can't be a direct one or a function between planet
orbital distance and its diameter as 2 variables only – the designer needed to add
more variables to be used between planet diameter and its orbital distance – and by
that – if this planet orbital distance be changed many variables will be changed not
only the diameter and by that the diameter may change by small value and can
survive and be in safe after the orbital distance change.
- As a result
- The designer second job to find as many variables as possible to be used between
planet orbital distance and its diameter –
- For that reason – planet diameter be created as a function in its rotation period and
the rotation period be a function in its velocity but the velocity be a function in its
orbital distance by that – the function between planet diameter and orbital distance

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be created and by that the planet can move safely and if its orbital distance be
changed the planet can still survive - My fourth equation proves this fact
- Notice
- The argument proves,
- (1) Planet data be created based on exact equations - as a plane manufacture – the
maker needs exact equations to define its length, width….etc
- (2) The solar system creation and motion depends on one geometrical design as a
machine of gears – many moving gears but produce one unified motion.
- These ideas be discussed in details in the paper
- Best Regards
(Please scan the figure (ORCID)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com, mrwaheid1@yahoo.com
gergesgerges@yandex.ru
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Paper Contents
Subject Page No.
i-Introduction 9
ii- Methodology 13
1- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity 15
1-1- Preface 16
1-2 Planet Data Be Created Based On Exact Equations 17
1-3 Planet Orbital Distance Be Defined Before Its Creation 18
1-4 Planet Diameter Should Be A Function In Its Orbital Distance (And NOT The Mass) 20
1-5 Planet Diameter Can't Be A Direct Function In Its Orbital Distance 21
1-6 Planet Diameter Definition Equation 23
1-7 (Planet Orbit Defines Its Velocity) Kepler Law Analysis 24
1-8 The Solar System Creation And Motion Depends On One Geometrical Design 25
1-9 The Solar System Geometrical Design Details 27
1-10 The Definition Of The Planets Diameters Total 32
1-11 Why Does The Moon Orbital Apogee Radius = 406000 Km? 41
1-12 Planet Mass Effect On Its Motion 44
1-13 The Sun Creation Process Analysis 49
2- One Geometrical Design Be Found Behind The Solar System 67
2-1 Preface 68
2-2 The One Geometrical Design Proves 69
2-3 The One Geometrical Design Reason 86
2-4 The Planet Motion Trajectory Analysis 82
2-5 The One Geometrical Design Discussion 84
2-6 The One Geometrical Design Result 98
3- Planet Data Depends On 5 Equations 95
3-1 Planet Orbital Distance Equation (My 1st
Equation) 97
3-2 Planet Velocity Equation (My 2nd
Equation) 102
3-3 My 3rd
Equation (Depends on Kepler Law) 106
3-4 Planet Rotation Period Equation (My 4th
Equation) 108
3-5 Planet Velocity Is A Complementary One (My 5th
Equation) 126
3-6- Planet Velocity Analysis 130
3-7 Planets Masses Rates Definition 142
4- The Solar System Geometrical Design Analysis 148
4-1 Preface 150
4-2 Newton Theory Of The Sun Gravity Is Wrong 152
4-3 The Solar System Is Created Based On One Geometrical Design 154
4-4 The One Geometrical Design Depends On One Light Beam Energy 155
4-5 The Solar System Be Created Out Of One Light Beam Its Velocity 1.16 Million
Km Per Second.
157
4-6 The Solar System Motion Depends On One Geometrical Design 160
4-7 THE DATA PROVE THE THEORY 162
4-8 The Solar System Geometrical Description 207

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4-9 How The Matter Be Produced Periodically? 212
4-10 The Planets Unified General Motion (More Data) 214
4-11 Questions And Answers (Extending Discussion) 224
5- The Moon Orbital Apogee Radius Analysis 239
5-1 Preface 240
5-2 The Moon Orbital Motion Description (And Equation) 243
5-3 The Moon Orbital Apogee Radius Analysis 259
5-4 Can Uranus Motion Effect On The Moon Motion 265
5-5 The Moon Daily Displacement Analysis 269
5-6 The Moon And Mercury Motions Data Analysis 274
5-7 The Moon And Pluto Motions Data Consistency 277
5-8 Uranus Motion Effect On Pluto Motion 285
5-9 The Moon Orbital Apogee Radius Decreasing Details 288
5-10 The Moon Orbit Description
5-10-1 Preface
5-10-2 The Moon Orbital Triangle Description
5-10-3 The Moon Orbital Triangle Data Analysis
5-10-4 The Moon Orbital Triangle Major Points
292
293
294
304
305
6- Jupiter Motion Effect On Earth And Venus Motions 341
6-1 Preface 342
6-2 Jupiter Motion Effect On Earth And Venus Motions 347
6-3 Jupiter Orbital Circumference Analysis 354
6-4 The Sun Rays Creation 358
6-5 Saturn Velocity Analysis 364
6-6 The Solar System Creation and Motion Theory 384
7- The Solar Planets Motions Use Different Rates Of Time 391
7-1 Preface 392
7-2 The Planets Motions Rates Of Time 394
8- The Solar Planets Rates Of Time Analysis 398
8-1 Preface 399
8-2 Venus Motion Rate of time 400
8-3 Earth Motion Rate of time 402
8-4 Mars Motion Rate of time 404
8-5 Jupiter Motion Rate of time 406
8-6 Saturn Motion Rate of time 408
8-7 Uranus Motion Rate of time 410
8-8 Neptune Motion Rate of time 412
8-9 Pluto Motion Rate of time 414
8-10 The Planets Orbital Distances Test 416
8-11 One Law Controls The Planets Orbital Periods And Distances 421
8-12 The General Discussion 422
9- The Planets Motions Rates Of Time Effect Analysis 425
9-1 Preface 426

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9-2 Planets Motions Rates Of Time And Distances Data 427
9-3 The Data Equal Distances 431
9-4 The Data and the planets velocities. 439
9-5 The Data Distances And Rates Of Time Interaction 443
9-6 The Data General Discussion 453
9-7 Mars, Jupiter and Saturn Motions Analysis 455
9-8 Why Saturn And The Moon Use Equal Rates Of Time? 460
9-9 Why Mercury Use A Double Of Its Orbital Distance? 465
9-10 The Rate (4.61) be used between Pluto and the moon motion 466
10- Mars Migration Theory 470
10-1 Mars Migration Theory 471
10-2 Pluto Migration Theory 474
10-3 Planets Migration Theories Proves 476
10-4 Is There An Absent Planet In The Solar Group? 479
11-The Solar System Distances Be Created In A Network Form 482
11-1 Preface 483
11-2 The Continuum effect Through the Solar System Distances 485
11-3 The Solar System Distances Distribution 490
11-4 The Solar System Distances Dependency On One Another 494
12- The Continuum Effect Proof 496
12-1 The Continuum Effect Proof 497
12-2 Saturn Motion Analysis 503
12-3 Planet Diameter Analysis 529
12-4 Why do the planets revolve around the sun if there's no sun gravity? 531
13- Planet Mass Effect On its Motion 532
13-1 Preface 533
13-2 Planet Mass effect on its Motion 535
13-3 Saturn and Earth Motions Interaction 546
13-4 Planets Velocities Proportionality 555
14- Saturn Motion Analysis 563
14-1 Preface 564
14-2 Saturn Diameter Analysis 566
14-3 Neptune Circumference Analysis 576
14-4 Neptune Day Period Analysis 585
14-5 Mercury Motion effect on Jupiter and Neptune Motions 594
14-6 Earth Motion Distance Daily Analysis 601
14-7 Uranus Day Period Analysis 605
14-8 The Inner Planets Motions Analysis 611
15- The Sun Age Description 619
15-1 Preface 620
15-2 The Sun Circles The Earth 621
15-3The Rate (1.0725) 622

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15-4 The Sun Diameter Analysis 625
15-5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 628
15-6 The Sun Rays Creation 636
16- Mercury Jupiter Distance Analysis 642
16-1 Mercury Jupiter Distance Analysis (720.7 mkm) 643
16-2 (Jupiter And Mercury Motions Analysis) 656
16-3 Jupiter Distances Analysis 660
Appendix No.1 The Solar System Equal Distances List 661
References and Biography 663

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i- Introduction
- The paper argues – Many astrophysics theories shows illogical features and can be
refuted by logical analysis only
- Above all – the big bang theory which losses many logical basics and be refuted
for its principle concept – because
- The theory supposed the first energy was in a chaos form which is not logical
- Planet data should be created based on exact equations as any plane or rocket
manufacture – the maker needs exact equations to define this plane length, width,
weight …and all its specifications otherwise this plane can't fly
- The moving planet safely under physical laws control the universe, this planet data
has to be created based on exact equations otherwise this planet will be broken
- How the planet data which be created based on exact equations can be produced
from the chaos form of the first energy? illogical idea
- On the contrary – the first energy was in a geometrical form – explaining how
planets data be created based on exact equations
- Newton theory of the sun gravity should be the next theory refuted by logical
analysis – Newton idea is wrong in its principle –
- By one force the planet be created and moving – means- the force which created
the planet it causes its motion – otherwise this planet will be broken by effect of 2
forces on it.
- The sun didn't cause any planet creation and for that No planet moves by the sun
gravity –
- The argument shows clearly Newton is wrong logically
- The fact disproves Newton idea decisively because the sun be created after all
planets creation and motion.

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- The question should be – Why Do The Theories Lose The Logical Basics?
- Because - the basic vision is wrong
- The concept (Random Creation Process)
- This is the real enemy behind our fighting – while every piece in the universe be
found based on geometrical effects and by mathematical calculations – the wrong
concept of (Random Creation) gives wrong vision for the facts.
- Now the theories did mistake to believe in this wrong concept
- but why couldn't the theories correct themselves?
- Because the planets data isn't used in the theories explanation – no theory explains
any planet data and no question asks (how did planet create its data?) by that we
move in the wrong direction losing the logic and no light to correct our motion
- What's the fact
- (1) The Solar System Be Created Of One Energy
- This idea is acceptable simply, because the physics book accepts that matter and
space be created of energies – my idea adds only – (From The Same One Energy
The Solar Planets And Their Distances Be Created)
- The double production experiment tells how that be occurred – from gamma ray
one electron and one position be created, 2 particles be created from the same one
energy – now – the type of creation (male and female) gives reference for similar
creation and we can conclude that from one energy the solar system be created
- (2) The One Energy Was One Light Beam Energy
- This idea can cause the change in our vision – it's one energy but be provided by
one light beam – and that means- the matter and space be created out of the same
one light beam energy and here we catch a treasure!
- How matter and space can be created by one light beam energy?
- By Using Different Geometrical Rules For The Creation

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- As you see the oil and coal as 2 sources of energy – one liquid but one solid both
produce equal energies
- The difference in creation be found by the used geometrical rules for this creation
– and the treasure be seen now – because
- The designer deposited his book of geometry in the creation process showing
different types of geometrical rules in creation and by the change of rule the
designer change the produced creature – by that – we received the treasure in
diversity of creatures and diversity of rules where the book of geometry will be so
rich one.
- (3) The energy be provided by one light beam – and – this light beam travels with
1.16 million km per second –
- The velocity be registered in the planets data and their distances because from this
energy the solar system be created.
- The velocity 1.16 million km is the secret key of the universe creation puzzles
- Shortly
- It's a beautiful one light beam which the solar system be created – from this great
light beam all planets matters and their distances be created where the wonderful
diversity depends on the designer book of Geometry, providing it for you as a
present proving of the generosity and love
- Please enjoy the light beam source of energy, and enjoy the rich geometry book
and then please enjoy the reading
- Kind regards
- The paper contents
- POINT NO. (1) Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
- POINT NO. (2) One Geometrical Design Be Found Behind The Solar System
- This Point Proves One Geometrical Design Be Found Behind The Solar System

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- POINT NO. (3) Planet Data Depends On 5 Equations
- This point discuses and tests my 5 equations by which we conclude planet data
- POINT NO. (4) The Solar System Geometrical Design Analysis
- This point analyzes the one geometrical design be found behind the solar system
- The point proves that – the solar system be created by energy provided by one
light beam its velocity 1.16 million km per second
- POINT NO. (5) The Moon Orbital Apogee Radius Analysis
- This point discusses the moon orbital motion description and equation – and also
the moon orbit design discussion
- POINT NO. (6) Jupiter Motion Effect On Earth And Venus Motions
- This point proves that – the sun is created after all planets creation and motion and
the sun creation depends on the planets motions – by that – the planets defend the
sun position before its creation – that's why the total solar eclipse phenomenon be
occurred – because – the Earth defined the sun position in the sky by help of its
moon motion – the sun position is defined by the Earth with help of Venus, Jupiter
and Uranus.
- POINTS NO. (7, 8 and 9)
- These Points discusses an idea tells (Planets motions use different rates of time)
- POINT NO. (10) Mars Migration Theory
- This point proves that Mars orbital distance be changed from its original one.
- POINTS NO. (11 and 12)
- These points discuss ideas tell (the solar system distances be created in a network
form) and ( a continuum be found in the solar system)
- POINT NO. (13) – discusses planet mass effect on its motion
- POINT NO. (14) – Analyzes Saturn Motion
- POINT NO. (15) – Discusses The Sun Creation And Age

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ii- Methodology
- I use the planets data analysis to discover the solar system creation and motion
facts – The method is so useful.
- The method simply put the planets data in comparison with the theory and tries to
know if there's a consistency between both – let's use an example to explain how
this method works
- An Example
- The 3 planets (Mercury – Venus – Earth) give the interesting data! why?
- Because, the 3 planets be in order for their diameters, masses and orbital distances.
Can this order be found based on a geometrical rule? let's try to discover
- But
- Mars causes a question, because Mars causes to break this order!
- What hypothesis do we need to explain this interesting data?
- The hypothesis tells (Mars Original Position Was Between Mercury And Venus)
- If this is the original position of Mars the planets order will be
- (Mercury – Mars – Venus – Earth)
- The 4 planets be in order for their diameters, masses and orbital distances
- Can we prove this hypothesis? Yes
- Mars had migrated from its original orbital distance to its current one – and Mars
in its migration motion had collided with Venus and then with Earth and Mars
itself caused to create the Earth Moon!
- Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the
Earth and caused the moon creation.
- Can Mars Itself do that? the theory tells No Hope
- But, Planets data analysis suggested that Mars had migrated from its original
orbital distance to its current one –

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- Let's move with this hypothesis for a while
- Suppose Mars was the second planet after Mercury and had migrated to its current
point (227.9 million km) and Mars had collided with Venus and then with Earth –
can this idea help Giant-impact hypothesis? for example can this idea answers
(Why Does Venus Have No Moon?)
- (a)
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushing by force
and had collided with Venus and pushed all debris with it in its motion direction
- Venus had found no debris around – for that Venus couldn't create its own moon-
- (b)
- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the
collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
- Earth gravity is greater than Venus' and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- Shortly
- The planets data analysis puts planet data in comparison with the theory explains
its motion to test if the theory be sufficient and to discover the geometrical rules
based on which this data be created.
- Notice
- Mars Migration Theory be discussed and proved in Point no.(10) of this paper.

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1- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
The Logic Analysis Process Contains 13 Points Let's Refer To Them:
1-1 Preface
1-2 Planet Data Be Created Based On Exact Equations
1-3 Planet Orbital Distance Be Defined Before Its Creation
1-4 Planet Diameter Should Be A Function In Its Orbital Distance (And NOT The Mass)
1-5 Planet Diameter Can't Be A Direct Function In Its Orbital Distance
1-6 Planet Diameter Definition Equation
1-7 (Planet Orbit Defines Its Velocity) Kepler Law Analysis
1-8 The Solar System Creation And Motion Depends On One Geometrical Design
1-9 The Solar System Geometrical Design Details
1-10 The Definition Of The Planets Diameters Total
1-11 Why Does The Moon Orbital Apogee Radius = 406000 Km?
1-12 Planet Mass Effect On Its Motion
1-13 The Sun Creation Process Analysis
Let's consider each point in details in following…

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1-1 Preface
In the following 13 points we analyze planet motion logical features to prove that
many believed ideas in the current theories be built out of logical analysis
By that
We disprove logically, the big bang theory, and Newton theory of the sun gravity.
Also
The analysis disproves the illogical idea tells (planet data be created by random
process, initial conditions or historical unknown factors)

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1-2 Planet Data Be Created Based On Exact Equations
Planet diameter, mass, orbital distance, period, inclination, rotation period and axial
tilt – All planet data be created based on exact equations and geometrical rules - No
single data be created based on random process, initial condition nor unknown
historical factors.
As in a plane or a rocket manufacture, the maker needs exact equations to define this
plane length, width, weight and all its specifications and dimensions –
If this plane data be created by inaccurate dimensions, this plane can't fly
Similar to that
Planet moves through the space under physical laws and if its data be not created
based on exact equations this planet will be broken through its motion – because – the
safe motion necessitates a full harmony between planet data one another and with the
physical laws controls the motions through space
In this investigation we try to define how Planet creates its data – or in more accurate
words – By What Order Planet Data Be Created? what data be created at first and
what be later? – by that – we can discover the harmony original point.
I have discovered 5 equations by which we can conclude planet data theoretically
without observation that proves the idea decisively
My 5 equations be discussed and tested in section no. (3)

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1-3- Planet Orbital Distance Be Defined Before Its Creation
This simple fact be proved by 2 basic proves – "First Proof" The Logical Analysis
The current planets positions define the new planet position
The balancing effect of the planets motions forces the new planet to take the left place
for it – because the planets revolve around the sun in their trajectories of motions – for
that – the new planet has to find a place far from these trajectories.
Imagine you are in some crowded bus – the people pushed you to the last place in this
bus because it's the only free place there – you came later and this is the only
available place for you – by that – you are forced to accept this place
Planet orbital distance be defined before the planet creation – the logic proves this fact
clearly
"Second Proof"
My First Equation tells (d2
= 4d0 (d-d0))
d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
My equation tells– Planet Orbital Distance Depends On Its Neighbor Distance
It's a simple and a trustee equation – let's use Venus as example
(108.2 million km)2
= 4 (57.9 million km) (50.3 million km)
where
108.2 million km = Venus orbital distance and
57.9 million km = Mercury orbital distance and (50.3 = 108.2 -57.9)
(There are 3 exceptions – Earth depends on Mercury – Mars depends on Venus and
Pluto depends on Uranus – All other planets depends on their direct neighbors)
Another example – Saturn Orbital Distance
(1433 million km)2
= 4 (778.6 million km) (655 million km)
where
1433 million km = Saturn Jupiter orbital distance and
778.6 million km = Jupiter orbital distance

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By this analysis we have 2 proves for the idea (Planet Orbital Distance Be Defined
Before This Planet Creation) because
The distance definition depends on other planets orbital distances – by that – the new
planet found itself forced to its orbital distance – also planet orbital distance doesn't
depend on any of planet data – it's simply be defined by another planet – it's a value
be forced by another planet orbital distance effect on the new planet orbital distance
Also,
My first equation proves, the distance from the sun to Pluto is one piece of distance be
distributed geometrically into parts defined based on one another – means- if we
remove the planets from the solar group – the distances would be still defined as them
without change because they are defined based on one another –
Newton idea– Planet orbital distance depends on its mass is a wrong one – and for
that Planets masses order disproves the gravitation equation.

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1-4 Planet Diameter Should Be A Function In Its Orbital Distance (And NOT
The Mass)
Based on our analysis, Planet finds itself forced for a specific orbital distance, because
this orbital distance be defined by its neighbor planet orbital distance- and by that –
this planet has to revolve around the sun through this orbital distance
The next data should be Planet Diameter
Planet diameter should be a function in its orbital distance and (Not Its Mass)
This idea also is a simple one
Imagine you loaded a truck with woods – but the woods were so long and be out of
the truck walls – while you drive out of a narrow street the woods be broken
Instead – if you put iron in place of the wood but the iron wasn't long and be inside
the truck walls only – while you drive out of the narrow street no breaking will be
happened but my the truck velocity be decreased for the heavy weight.
Planet diameter is the only one data should be in a strong relationship with its orbital
distance – this relationship is the basic requirement to save the planet in its motion
otherwise this planet will be broken through its motion.
Planet mass can't cause to break this planet – it can decrease planet motion velocity
and can effect on planet orbital inclination – but – the geometrical requirement be
related to Planet diameter – because – the wrong diameter can cause the planet to be
broken through its motion.
This idea is a simple one but it arises a serious question – because – if planet diameter
depends on its orbital distance what would happen if this planet orbital distance
changes for any reason?

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1-5 Planet Diameter Can't Be A Direct Function In Its Orbital Distance
If planet orbital distance be a function in its diameter as one variable in this function –
that means- if this planet orbital distance changes for any reason this planet will be
broken –
Here the designer had 2 jobs
First job to create a relationship between planet diameter and its orbital distance but
this relationship (function) can't be a direct one or a function between planet orbital
distance and its diameter as 2 variables only – the designer needed to add more
variables to be used between planet diameter and its orbital distance –
As a result
The designer second job to find as many variables as possible to be used between
planet orbital distance and its diameter –
For that reason – planet diameter be created as a function in its rotation period and the
rotation period be a function in its velocity but the velocity be a function in its orbital
distance by that – the function between planet diameter and orbital distance be created
but by using also planet rotation period and its velocity
For more clear explanation
Planet diameter be a function in the rate (s) where this rate refers to planet rotation
periods number in its orbital period – for example – Jupiter orbital period =4331 solar
days but Jupiter rotation period be 9.9 hours as a result Jupiter has 10500 rotation
periods in its orbital period – based on that – Jupiter diameter be created as a function
in the number 10500 – and this number be created as a function in Jupiter velocity
This description can be explained simply by my fourth equation – we see it in the next
section no. (1-5)
The point we discuss here is planet data creation order –
Planet orbital distance be defined at first and then planet diameter should be defined
as a function in its orbital distance – but for the migration risk – the planet diameter

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be created as a function in its rotation period and the rotation be a function in its
velocity and the velocity be a function in its orbital distance – by this function- when
planet orbital distance be changed – planet rotation period will be changes – and then
planet orbital period will be changed and also planet velocity will be changed and at
end planet diameter will be changed by small value to protect the planet and prevent it
to be broken.
This description tells us – There's A Direction Of Planet Data Creation –
Because
We have one direction to define 5 data (Planet Orbital Distance – Planet Diameter –
Its Rotation Period – Its Orbital Period – It Velocity) – this is a direction of data
creation – and proves the concept (planet data be created based on exact equations)
Let's see planet diameter definition equation in following

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1-6 Planet Diameter Definition Equation
- Planet Diameter Definition Equation (My Fourth Equation) (v1/v2) = (s/r) = I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination ( a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- Notice / (The Equation Works From The Earth To Pluto Only)
Example Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter
9.7 km/s = Saturn velocity
5.4 km/s = Neptune velocity
59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
- By this equation Planet diameter be created as a function in the rate (s) or its
rotation period and the rotation be a function in its velocity
- The equation still needs explanation – because the strange planet its velocity (v1)
can't be defined by any rule we search for the minimum error –let's provide its list:
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Neptune Equation uses Saturn velocity
- Pluto Equation uses the Earth moon velocity (As Jupiter)
- Also we have to ask (Why Does This Equation Work From The Earth To Pluto?)
- We should answer this question and discuss this equation in section No. (1-10)

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1-7- (Planet Orbit Defines Its Velocity) Kepler law analysis
Our investigation can help us to understand the basics on which this relation be found
– also we clearly disprove Newton theory of the sun gravity
Because
The concept tells (Planet Motion Depends On Its Mass) is a wrong one has no proof –
where – Planet orbital distance be defined based on its neighbor orbital distance and
its mass isn't be taken into consideration in the distance definition – that explains the
contraction between the planets masses order and their orbital distances – proving the
gravitation equation is wrong.
Also Planet velocity depends on its orbital distance – by that – No data supports this
wrong concept (Planet Motion Depends On Its Mass)
The relationship between planet orbital distance and its velocity be found basically to
connect the chain of relations between planet orbital distance and its diameter –
Shortly
Planet diameter be created as a function in its rotation period and the rotation period
be a function in its velocity – just because –Planet velocity be a function in its orbital
distance the chain be connected and the function between planet diameter and its
orbital distance be created.

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1-8 The Solar System Creation And Motion Depends On A Geometrical Design
By one force planet be created and moving – means
The force by which a Planet be created – it causes its motion
Based on that
(No Planet Moves By The Sun Gravity) because (The Sun Had Created No Planet)
One more force caused the planets creation and their motions
For that reason
Planet creation and motion data be in harmony one another –
For example (Mercury creation and motion data be in harmony one another) for that
reason Mercury moves safely and isn't broken
But -
We don't have 9 forces in the solar system – one force for each planet creation and
motion – instead – We have one force only caused all planets creation and motion
Now- let's ask
How Can One Force Create 9 Planets And Causes Their Motions?
We need One Geometrical Design to do this job
Means - we need one law based on which all planets data be created – that explains
how planet data be created based on exact equations
This One Law Depends on One Geometrical Design
As in the rule (3 angles total=180 degrees "one law") but this law means we deal with
(a triangle = one geometrical design)
I want to say
My first equation (d2
= 4d0 (d-d0)) – tells each planet orbital distance depends on its
neighbor orbital distance – by that – by using Mercury orbital distance (57.9 million
km) with this equation we can conclude all planets orbital distances – here we have
one law behind
But

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Planet diameter, rotation period, orbital period and velocity be created as a function in
this planet orbital distance – by that this one law doesn't control only the distances but
controls almost all data – here we have one law behind the solar system – that tells us
how planet data be created based on exact equations
But the question – should be – why planet data be created based on exact equations?
Let's try to answer in following
From Gamma ray one electron and one positron be created – the particles data be
defined based on exact equation –
The type of creation (male and female) tells us that, some similar method be used to
create the universe –
As a result – the 2 particles data be controlled by exact equations –
Shortly
The one law behind the solar system tells that the planets be created complementary
one another and because of that their motions be complementary one another and the
result be one unified motion – as a machine of gears has many moving gears but the
machine produces one unified motion
Here we deal with the solar system as one design has many members and produce one
unified motion.
Briefly
One Map must be found refers to this one design and this Map should distinguish
between the distances and velocities because depend on this distinguish the planets
diameters be created – let's discover that in the next section no. (1-9)

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1-9 The Solar System Geometrical Design Details
(a)
We analyze here the solar system one geometrical design – the previous analysis lead
us to conclude that – the solar planets be similar to gears in one machine of gears – or
similar to members of one creature – they move different motions but these motions
be integrated into One Unified Motion.
This description deals with the solar system as One Geometrical Design -
Means, we deal with the solar system as one piece and not as separated planets – and
means also – we deal with one geometrical design – the planets do distinguish jobs in
this design which be complementary one another and integrated together into one
final machine and design.
Based on this vision
The solar system has 2 maps – one for distance and one for velocity
The map of distances depend on Jupiter and Pluto as its 2 basic points
And
The map of velocity depends on Jupiter and Uranus as its 2 basic points
Both maps depend on Jupiter but the distance map reaches to Pluto where the velocity
map limits to Uranus –
The phase between Pluto and Uranus be found to use in planets diameters total
creation definition.
Let's discuss these maps in details in following….
(b)
(The Map Of Distance)
The distances from the sun to Pluto has 2 features which are
(1st
Feature)
Each Planet Orbital Distance Depends On Its Neighbor Orbital Distance – this feature
depends on my first equation (d2
= 4d0 (d-d0)) we have discussed before
(d= Planet Orbital Distance and d0 = Its Neighbor Planet Orbital Distance)

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(My 5 equations be discussed and tested in section no. 3)
(2nd
Feature)
The distances map depends on Jupiter and Pluto as 2 basic points of this map
(Proof)
Data
37100 million km – 4900 million km = 32200 million km
32200 million km x π = 100733 million km
Where
100733 million km = The planets orbital circumferences total
37100 million km = Pluto Orbital Circumference
4900 million km = Jupiter Orbital Circumference
Discussion
The data proves the idea - because
The 3 values (4900 , 37100 and 100733) depend on one another, any 2 values enable
us to conclude the third one theoretically
Means,
If we know Jupiter orbital circumference =4900 million km and The planets orbital
circumferences total = 100733 million km, We can conclude theoretically Pluto
orbital circumference =37100 million km – We do that by using the data and even
without my first equation (d2
= 4d0 (d-d0))
The distances map tells that –the map depends on 2 basic points which are (Jupiter
and Pluto)
More analysis of Data can prove that Mercury point be used as an origin point for
these 2 planets (Jupiter and Pluto) –
Shortly
Mercury be the origin point based on which the 2 points (Jupiter and Pluto) be created
based on them the solar planets orbital circumferences total be created.

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Notice
For the distances Map we need to notice that – the distance 4900 million km (Jupiter
orbital circumference) is the central distance in the solar system because
(i)
The inner planets orbital circumferences total be (Mercury 360 mkm + Venus 680
mkm + Earth 940 mkm + Mars 1433 mkm + 1433 mkm) = 4900 million km (1%)
The total = 4900 million km but the distance (1433 mkm) be used 2 times!
(ii)
Jupiter Orbital Circumference (4900 million km)
(iii)
Uranus needs 4900 days to pass a distance = Uranus Orbital Distance
Neptune needs 2 x 4900 days to pass a distance = Neptune Orbital Distance (2%)
Pluto needs 3 x 4900 days to pass a distance = Pluto Orbital Distance (1%)
(iv)
(10747 /9800) = (9800 /9007)
10747 days = Saturn Orbital Period
9007 million km = Saturn Orbital Circumference
9800 = 2 x 4900
The data tells, the value 4900 be used by all planets (in different units)
The distance for Jupiter (and the inner planets) be used as a period of time for Uranus,
Neptune and Pluto–and Saturn uses this value as a distance and as a period of time
We can conclude
The distance 4900 million km is the central one in the solar system design for that
reason Jupiter be a column in both maps (distance and velocity)

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(c)
(The Map Of Velocity)
The data shows that one map be found for the planets velocities – this map depends
on Jupiter and Uranus velocities – let's prove that in following –
Proof
Data
(i)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
Where
100733 million km = The Planets Orbital Circumferences Total
197393 days = The Planets Orbital Periods Total
1.16 million km/s = Light Supposed Velocity
0.6 million km/s = 2 x 0.3 million km/s (Light Velocity)
1.1318 million km/day = Jupiter Velocity Per A Solar Day
0.5875 million km/day = Uranus Velocity Per A Solar Day
(ii)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
1.16 million km/s = Light Supposed Velocity
0.6 million km/s = 2 x 0.3 million km/s (Light Supposed Velocity)
47.4 km/s = Mercury Velocity 24.1 km/s = Mars Velocity
35 km/s = Venus Velocity 17.9 km/s = Ceres Velocity
13.1 km/s = Jupiter Velocity
6.8 km/s = Uranus Velocity
Discussion
the discussion supposes a light beam its velocity 1.16 million km per second be found
Data No. (i) shows the planets orbital circumferences and periods total depend on the
2 planets (Jupiter and Uranus) velocities in comparison with the 2 velocities of light
(the known velocity 300000 km/s and the supposed velocity 1160000 km/s)

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Data No. (ii) shows that, the rate of velocities between (Jupiter and Uranus) be used
also by (Mars and Mercury) and by (Venus and Ceres) – But
No any couple can be replaced in place of (Jupiter and Uranus) in Data no. (i) – that
shows, the planets orbital circumferences and periods be related to (Jupiter and
Uranus) velocities and not to any other couple of planets – they are the 2 basic players
in the design structure -
The data proves the idea tells
One Map of velocity be used for all planets velocities and in this map Jupiter and
Uranus are the 2 basic points (or 2 columns)
The Motion Origin Point
The Distance Origin Point Is Mercury
But
The Velocity Origin Point Is The Earth – we discuss the reason in point No.(1-13)
Notice
Light (300000 km/s) travels during 16330 sec a distance = 4900 million km
Light (1160000 km/s) travels during 4222.6 sec a distance = 4900 million km
Where
4900 million km = Jupiter Orbital Circumference (we have discussed before)
16330 hours = Mars Orbital Period
4222.6 hours = Mercury Day Period
Light motion uses 1 hour of planets cycles periods as one second of light motion
(d)
Why Did The Designer Use 2 Maps For The Distance And Velocity?
Because the designer uses the phase between the distance map and velocity map to
define the planets diameters total– both Maps depend on Jupiter but the distance map
reaches to Pluto where the velocity map limits to Uranus – the phase between Pluto
and Uranus is found to define the planets diameters total 406000 km
Let's discover how that be happened in the next section no. (1-10)

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1-10 The Definition Of The Planets Diameters Total
The point discusses in details my fourth equation
Planet Diameter Definition Equation (My Fourth Equation)
v = Planet Velocity
r= Planet Diameter
s= Planet Rotation Periods Number In Its Orbital Period
I= Planet Orbital Inclination (a rate to inclination unit)
v2, s, r and I be belonged to one planet and v1 be belonged to another planet
as we have discussed – the planet (v1) be defined by test the minimum error
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Neptune Equation uses Saturn velocity
- Pluto Equation uses the Earth moon velocity (As Jupiter)
Notice / (The Equation Works From The Earth To Pluto Only)
1- The Equation Test
Earth equation (366.7/12756) = 5.4/ (29.8 x 2π) = 0.029
366.7 = Earth rotation periods number in Earth orbital period
12756 km = Earth diameter
29.8 km/s = Earth velocity
365.25 days = Earth orbital period (and Earth rotation period =23.9 hours)
Mars equation (671/6792) = 4.7/ (24.1 x 2) =0.098 (error 1.2%)
671 = Mars rotation periods number in Mars orbital period
6792 km = Mars diameter
I
r
s
v
v
=
=
2
1

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24.1 km/s = Mars velocity
4.7 km/s = Pluto velocity
687 days = Mars orbital period (and Mars rotation period =24.6 hours)
Jupiter equation (10500/142984) = 13.1/(27.78 x 2π) = 0.0734 (error 2.2%)
10500 = Jupiter rotation periods number in Jupiter orbital period
142984 km = Jupiter diameter
13.1 km/s = Jupiter velocity
27.78 km/s = The Earth Moon velocity
4331 days = Jupiter orbital period (and Jupiter rotation period =9.9 hours)
Saturn equation (24106 x2) /(120536) = 9.7/ 24.1 =0.4
24106 = Saturn rotation periods number in Saturn orbital period
120536 km = Saturn diameter
24.1 km/s = Mars velocity
10747 days = Saturn orbital period (and Saturn rotation period =10.7 hours)
(1/0.4) = 2.5 where 2.5 degrees = Saturn Orbital Inclination
Uranus equation (42683 / 51118) = 5.4/6.8 =0.8 (error 5%)
42683 = Uranus rotation periods number in Uranus orbital period
51118 km = Uranus diameter
6.8 km/s = Uranus velocity
30589 days = Uranus orbital period (and Uranus rotation period =17.2 hours)
0.8 degrees = Uranus Orbital Inclination
Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter

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59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
Pluto equation (14178 /2390) = 27.78/ 4.7 =5.9
14178 = Pluto rotation periods number in Pluto orbital period
23908 km = Pluto diameter
27.78 km/s = The Moon velocity
4.7 km/s = Pluto velocity
90560 days = Pluto orbital period (and Pluto rotation period =153.3 hours)
2- The Equation Discussion
(a) The equation modifications
Many planets cause modifications for the equation – let's refer to them in following
(a)
Mars and Saturn use the number (2) which isn't found in the original equation
(b)
The Earth and Jupiter use the rate (2π) which isn't found in the original equation
(c)
Uranus equation causes a great error = 5%
All errors are less than (1%) except Jupiter (2.2%) and Mars (1.2%)
(d)
Pluto equation depends on the moon velocity – but – connected with Neptune
Because
(Pluto orbital period / Pluto rotation period) x 2π = (Neptune orbital period / Neptune
rotation period)
(e)
Jupiter and Saturn uses the rate (r/s) in place of the rate (s/r)
(f)

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The orbital inclination rate (I) be produced in complex form – just with Saturn,
Uranus and Neptune the produced values refer to the planet orbital inclination clearly,
but with the others the produced values be complex – let's use an example
Example –Mars equation produces the value 0.098 – but
(1/0.098) = 10.2 = 2 x 5.1 (where the moon orbital inclination = 5.1 degrees)
Even if we accept this value – this isn't Mars orbital inclination– why??
7 deg (Mercury orbital inclination) = 5.1 degrees + 1.9 deg (Mars orbital inclination)
(5.1 degrees = The Moon Orbital Inclination)
Means - the definition isn't direct but with some complexity – that may be as result of
the moon motion effect on Mars motion.
(b) The equation objective
The equation creates a function between planet diameter and (s) (its rotation periods
number in its orbital period) – then the rate (s) be a function in this planet velocity and
velocity be a function in planet orbital distance - this chain creates a function between
planet diameter and orbital distance.
The equation shows that – planet diameter be created in harmony with its motion – as
in some canal water creates a vortex and for some reason the water lost its minerals
and salts around this vortex – with time some rock be created by the minerals and
salts and the rock be in a tube form through which the water moves – here the tube
dimensions be in harmony with this water motion because it be created by this water
motion effect.
(c) How Does The Equation Work?
The equation uses the moon and Pluto as 2 terminals of it – because
The Moon Orbital Period = The Moon Rotation Period =27.3 days, by that for the
moon the rate (s) be = 1
And

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Pluto has 14177 rotation period in its orbital period and Pluto needs 14547 days to
pass a distance = 5906 million km = Pluto orbital distance.
By that the moon and Pluto each planet has 2 equal periods in its motion for that
reason the 2 planets be used as 2 terminals for the equation.
Notice
The moon orbital period = The moon rotation period =27.3 days not for any tidal
locking – the idea is wrong – the moon periods are equal because of my fourth
equation – where this equality of the 2 cycles be used as a base for the equation by
which the planets diameter be created as a function in its rotation period
By that –
The moon and Pluto equal periods be used as 2 terminals for the equation
(d) Planet Rotation Period Analysis
According to kepler law (planet orbit defines its velocity), planet velocity be defined
by its orbital distance – by that –Planet should use its orbital velocity to define its
rotation period – and the rotation period by that will be a function in this planet
circumference -In this case Earth (29.8 km/s) would rotate around its axis in 22.4 min
only and not in 23.9 h
This is not the fact – Earth rotates around its axis in 23.9 hours –
Then we have to ask
Why doesn't planet use its orbital velocity to define its rotation period? because of my
fourth equation – the equation creates a function between planet diameter and its
rotation period is the reason which prevents planet to use its orbital velocity to define
its rotation period –
Shortly
My fourth equation refers to a geometrical effect starts from the moon and reaches to
Pluto, it passes through all planets data and forces each planet to create its diameter as
a function in its rotation period – or in more accurate words in the rate (s)
By that planet rotation period be defined almost before the planet diameter be created!

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Can planet rotation period be defined before its diameter creation? Let's use the moon
as example -
The moon be created by collisions between planets – the collisions debris revolve
around the Earth and later these debris be collected together into the moon – we can
imagine that the rotation period can be defined before the diameter creation – because
the debris revolve around the Earth by some rotation period – and during the moon
diameter be growing some rotation period was used also.
(e) Saturn Rotation Period Analysis
Saturn (9.7 km/s) moves during its rotation period (10.7 h) a distance = 373644 km
This distance equals approximately Saturn circumference (378675 km) (error 1.3%)
By that Saturn is the only planet uses its orbital velocity to define its rotation period
Jupiter (13.1km/s) also moves during its rotation period (9.9 h) a distance increased
4% than its circumference
Uranus (6.8 km/s) moves in its rotation period (17.2 h) a distance =2.6 its
Circumference
Neptune (5.4 km/s) moves in its rotation period (16.1 h) a distance = 2 its
Circumference
We can see that these distances be found by geometrical design – that tells we have an
effect passes through the planets and causes these distances
Notice
Because Saturn is the only planet uses its orbital velocity to define its rotation period
– that may explain the identical data be used by the moon and Saturn motions
For example
Saturn orbital period =10747 days
And

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The moon displacements total during 10747 days = 940 million km = Earth orbital
circumference
Also
The moon orbital inclination =5.1 degrees = 2 x 2.6 degrees
Saturn orbital inclination = 2.5 degrees (different from 2.6 degrees with 4%)
Shortly
A geometrical effect starts from the moon reaching to Pluto by which each planet
defines its diameter as a function in its rotation period – that's the reason why planet
doesn't use its orbital velocity to define its rotation period-
But
Saturn be used as a central point for this geometrical effect (and for the equation) –
by that – Saturn moves in its rotation period a distance = its circumference (error
1.3%).
And as a result Saturn and the moon create identical data for their motions because of
their connection through the geometrical effect which be expressed and proves by my
fourth equation.
Notice : more identical data between the moon and Saturn be discussed in section no.
(1-13) (The Sun Creation)
(f) Venus And Mercury Support The Moon Motion
The moon cycles equality be used as a base for the equation – but a small planet as the
moon can't be used as a base for all planets
For that, Venus and Mercury support this same base. For that reason Venus cycles be
in consistency with the moon cycles as we see in following
(29.53/27.3) = (243/224.7) = 1.0725
Where
29.53 days = The Moon Day Period
27.3 days = The Moon Orbital Period
243 days = Venus Rotation Period

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224.7 days = Venus Orbital Period
This data tells, there's a consistency between the moon and Venus cycles periods, this
consistency is required because the equality between the moon orbital period and
rotation period forms the base on which my fourth Equation depends – means – the
system by which the planets diameters be defined as function in their rotations and
then velocities and then orbital distances – this system depends on the equality of the
moon 2 cycles periods – and this equality be supported by Venus Cycles in addition to
the moon cycles – that means- the system depends on the moon motion but the moon
motion be supported strongly by Venus and Mercury motions, for that the cycles
equality be strong value because it be consisted of 2 planets cycles integration – and
by that the moon and Venus consist together a strong base on which the system
depends
Notice
Mercury moves during its rotation period (58.65 days) a distance =243 million km
(error 1%)
In case 1 million km = 1 day (the period 243 days = Venus rotation period)
Also
Venus moves during (365.25 days) a distance = 2π x 175.94 million km
In case 1million km =1 days (the period 175.94 days = Mercury Day Period)
The data tries to refer to the deep interaction behind the moon motion support.
(f) The Equation Geometrical Effect
What's the real effect transported by my fourth equation?
What's this geometrical effect be transported from planet to another to cause their
diameters be function in rotation period and rotation be function in velocity..?
The rate (s/r) shows that some complex geometrical effect be transported, because we
can't define the units of this rate (s/r) where (s) units be in hours (= planet rotation
period in hours) and (r) be in km – how to solve that?

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Planet rotation period be considered = one second
For example
Jupiter rotation period 9.9 hours and the period 9.9 h be considered = 1 second
And
planet diameter value be used in second units
Example – Jupiter diameter be 142984 km be used as 142984 seconds
By this using the equation can work
How this data can be used by these units?
The answer can be more understandable with examine light motion effect on planet
motion – that can shows the data has more deep geometrical effect – we should
discuss that later in details.

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1- 11- Why Does The Moon Orbital Apogee Radius = 406000 Km?
(1)
We have 2 terminal planets (the moon and Pluto) for my fourth equation - where
The Planets Diameters Total = 406000 km
Pluto moves in a solar day a distance = 406000 km
The moon orbital apogee radius = 406000km
(2)
Earth moves during its day period (24 hours) a distance = 2.574 million km
Pluto moves during its day period (153.3 hours) a distance = 2.59 million km
The Earth moon displacements total during 29.53 days = 2.59 million km
The 3 distances are equal (error 1%)
Why the 3 planets move equal distances in their days periods?!
(3)
The Moon Orbital Motion
The moon daily displacement =88000 km and during 29.53 days the displacements
total be = 2.598 million km = 2π x 413600 km
The data tells the moon orbital apogee radius should be 413600 km and
The moon daily displacement (88000 km) is long, because of that, the moon should be
prisoner in the orbit with radius (= 413600 km) and the moon can't revolve around the
Earth through any more near orbit!
Not facts – The moon orbital apogee radius =406000 km and the moon revolves
around the Earth through near orbits and can reach to perigee radius (363000 km).
How Can The Moon Do That?
The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level by that the real displacement (L) through the orbit be less than (88000
km) because it be (L = 88000 km cos θ), as a result the total displacements be less
than (2.598 million km) and that makes the moon orbital apogee radius to be
decreased from 413600 km to 406000 km.

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We should pay attention to the angle (θ), because this angle controls the moon motion
features – where- with the angle (θ) increasing the real displacement (L) be shorter
and the moon can revolve around the Earth through more near orbits – but –with the
angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far
from the Earth to more far orbits.
The moon orbital motion depends on this angle (θ) it tells θ1 = θ0 +1.7
where (θ1) = today angle and (θ0) =yesterday angle
Now, one more question be raised, why the moon apogee radius be 406000 km? why
not shorter if the moon uses this technique which enable the moon to decrease its
orbital apogee radius as possible? Why specifically the radius 406000 km be chosen?
Because 406000 km = The Planets Diameters Total
We still be connected with my fourth equation – and the geometrical effect based on
which the planets diameters be created as functions in their rotation periods
Means, the orbital apogee radius 406000 km be defined by effect of this equation on
the moon motion
(4)
Metonic Cycle
Why does the rotate Metonic Cycle (19 years)?
Because of Uranus motion effect on the moon motion – we know that because
Uranus Orbital Distance =19.2 Earth Orbital Distance - means
If Uranus and Earth velocities be equal, while Uranus revolves around the sun one
revolution Earth would revolve 19 revolutions (19 years)
That's why I have suggested Uranus effect is the reason of the moon Metonic Cycle
In fact Uranus has 3 effects which are
(a)
Uranus motion effect on the Earth moon to rotate Metonic Cycle –and by this effect -
Uranus cause the moon orbital inclination to be 5.1 degrees and this inclination causes
to decrease the moon orbital apogee radius from 413600 km to 406000 km

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(b)
Uranus effects on Pluto motion and causes Pluto rotation period to be (153.3 h)
Also Uranus uses Pluto rotation period in (Planet 8 days cycle)
(c)
Uranus axial tilt effects on all planets axial tilts and prevent the overturning motion of
any planet around the sun.
This effect shows why Earth and Uranus use Neptune velocity in their Equations (in
my fourth Equation) – because Uranus guides all planets motions directions and
Uranus is one column of the velocity map 2 columns – where Earth is the central
point of the solar system motion - we discuss that with the sun creation
The details of Uranus discussions be provided in Point No. (5)
Notice
I wish the (new) type of motion which be done by Planets be seen by us – because
Uranus effect on Pluto motion to increase its rotation period (and day period) to be
(153.3 hours) but Pluto moves during this period (153.3 h) a distance = Earth motion
distance during its day period (24 h) = The moon displacements total during its day
period (29.53 days) – here Uranus causes Pluto rotation period (153.3 h) for a
geometrical reason by which the planets move equal distances – but we understand
nothing! Because we don't realize any produced effect by motions equal distances -
Because we don't know the produced geometrical effect we don't understand the
whole process.
It's a type of motion - the planet does- (which be unknown for us)
We see only planet revolution around the sun but planet does many different other
motions which we don't observe nor understand because their geometrical effects are
unknown for us –

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1-12 Planet Mass Effect On Its Motion
I –Data
(1) (0.642/0.33) = 1.94
(2) (0.073 /0.0146) = 5.1
(3) (4.87/5.97) = 0.81
(4) (4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9)
(5) (1898 / 568) = 3.34
(6) (568/4.87) = 116.6
(7) (0.33 /0.0131) = 49
(8) (568/102) = (0.073 /0.0131) = 5.56 = (29.8/5.4)
(9) (102 /5.97) = 17.1
(10) (1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
No. (11) (The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772
No. (12) (The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44
Where
- 0.33 x 1024
kg = Mercury Mass
- 4.87 x 1024
kg = Venus Mass
- 5.97 x 1024
kg = Earth Mass
- 0.0.73 x 1024
kg = The Earth Moon Mass
- 0.642 x 1024
kg = Mars Mass
- 1898 x 1024
kg = Jupiter Mass
- 568 x 1024
kg = Saturn Mass
- 86.8 x 1024
kg = Uranus Mass
- 102 x 1024
kg = Neptune Mass
- 0.0131 1024
kg = Pluto Mass
- 47.4 km/s = Mercury velocity
- 24.1 km/s = Mars velocity
- The rate between the masses be so near to (planet orbital inclination)

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II- Discussion
Data No.(1)
- (Mars Mass / Mercury Mass) = 1.94
- (Mercury velocity / Mars velocity) = 1.96
- Mars orbital inclination = 1.9 degrees
- 7 deg (Mercury orbital inclination) = 1.9 deg+ 5.1 deg (the moon orb. Inclination)
- The data tells the masses rates = the velocities rates = Planet orbit. inclination
- This meaning can be understood logically because planet mass can effect on its
orbital inclination and by that the rate (1.94) can produce Mars orbital inclination
1.9 degrees
- But
- The velocities rate – we have discussed in my fourth Equation let's remember it
- (v1/v2) = (s/r) =I
- Where the 2 planets velocities rate = I = planet orbital inclination – we have
discussed that deeply
- The masses effect enters the seen from the other side – here we realize that – the
velocities rate be used by the masses rate through Planet orbital inclinations –
- That explains why planet orbital inclination isn't used inside my fourth equation
but just be produced as its result only – that because – planet orbital inclination be
used as a rate between planets masses on one side and planets velocities on the
other side – 2 forces on both sides
- This situation causes planet orbital inclination to be a balancing point between
forces and by that we realize the fourth equation defines planet diameter through
balancing points between the masses rates and velocities rates
- In fact the machine shows serious complexity by this approach
- There's more complex features
- Because – the planet creates its orbital inclination for its motion by its mass effect
– as we supposed – but – what will happen if this planet changes its orbital

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distance? For example – Mars original orbital distance was 84 million km and
changed it into the current one 227.9 million km- what did happen for its orbital
inclination?
- Of course the new orbital distance will show the inclination of the planet because
of its mass effect – but – what will happen for the first orbital inclination?
- I want to say
- The inclination isn't an independent data related to a planet mass – it's a shared
data be found by balancing points with other planets – Mars orbital inclination was
1.9 degrees (supposed) when Mars orbital distance was 84 million km based on
that Mercury orbital inclination was 7 degrees – but Mars had migrated to the new
position (227.9 million km) what would happen for Mercury orbital inclination?
- The data
- 7 deg (Mercury orbital inclination) = 1.9 deg+ 5.1 deg (the moon orb. Inclination)
- (1.9 deg = Mars orbital inclination)
- This data shows interesting interaction – I can't say surely the moon orbital
inclination was a necessary for recovery but the data tells the geometrical
interactions aren't limited for any one planet – instead we deal with a machine and
this machine geometrical details can tell how any planet orbital inclination be
created – the only data we sure of be – (planet orbital inclination is a balancing
point between masses on one side and between velocities on the other side –
making the orbital inclination a very important value produced based on balancing
points)
- Notice
- 1.94 (1.9 degrees Mars Orbital Inclination)
- 5.1 (5.1 degrees The Moon Orbital Inclination)
- 0.81 (0.8 degrees Uranus Orbital Inclination)
- 3.34 (3.4 degrees Venus Orbital Inclination)
- 116.6 (116.6 degrees = 90 degrees + 26.6 where 26.7 deg = Saturn Axial Tilt)

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- 49 (7 degrees Mercury Orbital Inclination)
- 5.56 (5.1 + 0.5 where 5.1 degrees The Moon Orbital Inclination
(0.5 degrees = The Moon Diameter Angle)
- 17.1 (17.2 degrees = Pluto Orbital Inclination) also
- (17.4 degrees = the inner planets Orbital Inclinations Total)
- 2.44 (2.5 degrees = Saturn Orbital Inclination)
- Notice
- (102 /5.97) = 17.1
- We have seen that – the couple Earth and Neptune velocities be used with my
fourth and fifth equations - both equations use the same couple
- Now
- 102 x 1024
kg = Neptune Mass
- 5.97 x 1024
kg = Earth Mass
- 17.2 degrees = Pluto orbital inclination
- 17.4 degrees = The Inner Planets Orbital Inclinations Total
- 23.6 degrees = The outer Planets Orbital Inclinations Total
- 23.4 degrees = Earth axial tilt
- That tells we have a system (17.2 and 17.4 error 1%) and (23.6 and 23.4 error 1%)
- It's one system create a distribution for planets
- The value 17.2 depends on (Earth and Neptune masses) why??
- Earth Circumference = The 5 Inner Planets Diameters Total
- Earth Mass = The 4 Inner Planets Diameters Total
- But
- Neptune Circumference = The outer Planets Diameters Total (without Neptune)
- Again we deal with one system – the 2 points (Earth and Neptune) be the 2 basics
for this job.
- Please remember Earth uses Neptune velocity in my fourth Equation and in my
fifth equation.

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Notice
3.4 deg (Venus orb. Inc) + 7 deg (Mercury orb. Inc)= 2 x 5.1 deg (the moon orb. Inc)
(568/4.87) = 116.6
Saturn mass = 116.6 Venus Mass
We have seen this rate before and I have claimed that – Venus day period (116.75
days) be produced as a result for this rate
Also 26.6 deg = Saturn axial tilt but 26.6 deg + 90 deg = 116.6 degrees
(10) (1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
(Jupiter Mass / Neptune Mass) = (Earth Mass / Mercury Mass)
No. (11) (The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772
31 =π3
No. (12) (The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44
2.5 deg = Saturn Orbital Inclination

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1-13 -The Sun Creation Discussion
- The sun creation process is an interesting theory let's summarize it in following:
- The sun rays isn't created by any nuclear interaction inside the sun – but
- The fact is that, the planets motions energies be accumulated together and this total
be used as the source of the sun rays – the energy is insufficient and for that reason
the sun uses different rate of time (1 s of the sun = 1461 s of the Earth) by this rate,
the energy which be accumulated during 1461 days be used by the sun in one day
and from it the sun rays be created
- Also we can consider the planets velocities total be used as a source to produce
light beam – the planets velocities total be (176 km/s) and
- The Earth moon velocity be added also because it's a player with the other planets
– the moon velocity be (29.8 km/s) equal Earth velocity because they aren't
separated from one another in their motions around the sun – by that the velocities
total be (205.8 km/s)
- During 1461 seconds this velocity (205.8 km/s) moves 300000 km = light motion
distance in one second
- The basic requirement be (1 s of the sun motion = 1461 s of the Earth motion) by
this rate the energy be sufficient to produce the sun rays –
- And because this rate (1= 1461) be produced by the Earth and moon motions – that
causes the Earth moon velocity to be used with the 9 planets as a basic player.
- Based on this idea
- The cornerstone to prove that 1 second of the sun motion = 1461 second of the
Earth motion – if we prove this fact the sun rays creation idea will be proved.
- The proof discussion be in 8 points which are:
- (a) The Rate Of Time (1=1461) (b)The Planets Energies Accumulation
- (c) The Sun Position (d) The Total Solar Eclipse
- (e) The Creation of The Rate (1 = 1461) (f) The Distance 629 million km
- (g) The Sun Cycle (h) Uranus Effect Analysis
- (i) Saturn And The Moon Motions Consistency

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(a) The Rate Of Time (1=1461)
- Data
- (1)
- 10921 km x 86400 = 940 million km
- (2)
- 25920 million km = 17.75 million km x 1461 days =0.3 mkm/s x 86400
- Discussion
- These 2 data proves the rate of time (1 day on the sun = 1461 days on the Earth)
- Data No. (2) is the same data we have discussed – but the velocity (205.8 km/s) be
used in a solar day (17.75 million km/day)
- The planets during 1461 days move a total distance = 25920 million km = light
(300000 km/s) motion distance during one solar day.
- Data no. (1)
- 10921 km x 86400 = 940 million km
- 10921 km = The moon circumference
- 940 million km = Earth Orbital Circumference
- 86400 seconds = The Solar Day
- This data tells,
- If Earth revolves around the sun one complete revolution in one solar day only the
moon circumference will be equal a distance of Earth motion during 1 second
- This data tells the rate (1 second = 365.25 seconds) is a rate be used between the
Earth and the sun and for that the moon circumference be created based on this
rate –
- I want to say –
- These 2 data are different data but provides one idea only which is the rate (1
second of the sun =365.25 seconds of the Earth)

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- The Earth Cycle (365+365+365+366) be created as a result for this relationship
and by that the rate (1 = 1461) be supported and proved by different data
- Notice (1)
- The sun circles the Earth during 365.25 days and gives the same one face always-
that tells – the sun know the cycle 365.25 days and that may prove the sun be
created after the cycle 365.25 days was defined.
- that disproves Newton theory of the sun gravity decisively because the sun is
created after all planets creations and motions –
- that also answers the question (Why the sun be found in the solar system if no
planet moves by the sun gravity?)
- Notice (2)
- 10921 km x 27.3 days =300000 km
- The data tells if the moon rotates around its axis one rotation per a solar day as the
Earth does – the moon would pass 300000 km in its orbital period 27.3 days
- 43000 km x 27.3 days =1160000 km
- The data tells if the moon is a point travels from perigee to apogee in one day, the
moon would pass 1160000 km in its orbital period 27.3 days
- The data shows a consistency be found between the moon motion and light 2
velocities (300000 km and 1160000 km)
(b) The Planets Energies Accumulation
- Data
- (1)
- 25920 million km = 17.75 million km x 1461 days =0.3 mkm/s x 86400
- (2)
- 90000 million km = (6939.75 days /24) x (17.75)2
- (3)

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- 90000 million km = 2872.5 million km x 31.3
- Discussion
- Data no.(1) we have discussed – it's the basic data – because the idea tells
- The sun rays energy be produced by planets motions energies accumulation – by
that - the data no.(1) shows
- Light (300000 km/s) motion distance during a solar day (86400 s) = the planets
motions distances total during 1461 days =25920 million km – that's the rate be
used by the sun to create the sun rays from the planets motions energies total.
- We interest for the period (86400 seconds) because it's the central period for the
planets orbital circumferences total (= 100733 million km)
- Where
- Light supposed velocity (1160000 km/s) travels during (86400s) a distance =
100733 million km. (we discuss that with sun position definition)
- Data No. (2)
- 90000 million km = (6939.75 days /24) x (17.75)2
- 6939.75 days = Metonic Cycle Period
- 17.75 million km = The Planets Motions Distances Total In One Solar Day
- The data tells during Metonic Cycle the planets motions distances total be = 90000
million km x 24
- We interest for 90000 million km because this distance be produced from C2
- C2
for one second be = 90000 million km
- This is the energy be used to produce the sun rays
- That means, the sun creation be related to Metonic Cycle and in fact Metonic
Cycle shows the unified motion of all planets motions and by that this cycle
motion provides the energy be used for the sun rays creations
- It's the same concept which tells
- From the planets motions energies total the sun rays be created – but this creation
depends on Metonic Cycle – that also tells the sun existence depends on a cycle

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- Data no. (3)
- 90000 million km = 2872.5 million km x 31.3
- 2872.5 million km = Uranus orbital distance
- 31.3 = Uranus axial tilt (97.8 deg) / Jupiter axial tilt (3.1)
- This data shows Uranus effect on the sun creation and shows the deep interaction
between Uranus and Jupiter motions which be seen in the rate (31.3)
- (Notice 31.3 is different from π3
with error 1%)
- (c) The Sun Position
- Data
- (1)
- 25920 million km = 4.37 million km x 5906 million km
- And
- 100733 million km = 1.16 million km/s x 86400 seconds
- 25920 million km = 0.3 million km/s x 86400 seconds
- (2)
- 25920 million km = 629 million km x 41
- And
- 2 x 100733 million km = 4900 million km x 41
- Discussion
- Data No.(1)
- Data No. (1) shows that by using the solar day period (86400s) both light
velocities (1160000km/s and 300000 km/s) travels defined distances which are
- 100733 million km (= 1.16 million km/s) and (25920 million km) respectively.
- 100733 million km = The Solar Planets Orbital Circumferences Total
- 25920 million km = The distance be passed by all planets motions during 1461
days
- I try to show the 2 distances (100733 mkm and 25920 mkm) be created based on
the same period (86400 s) by 2 light velocities –

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- By that, the distance 25920 mkm be found based on geometrical necessity based
on the distance 100733 mkm –means- the distance (25920mkm) is a result from
the distance (100733 mkm).
- I try to show- We have a geometrical reason behind causes this data to be created
based on one another – means – because the distance 100733 mkm be found the
distance 25920 mkm be found as a result – we deal with a geometrical mechanism
- The data we interest for is the following …
- Where
- 4.37 million km = The Sun Circumference
- 5906 million km = Pluto Orbital Distance
- The data tells, The sun circumference be created by geometrical necessity, because
the distance 25920 mkm is defined by the solar planets orbital circumferences total
(100733 mkm) as we have discussed and Pluto orbital distance (5906 mkm) be the
most far point from the sun – by that the sun circumference can't be larger than
4.37 million km.
- This data tells the sun data be created based on the planets data and that supports
the idea tells the sun be created by The Planets Motion Energies Total.
- I wish the proof shows sufficiency - because – I arrange many data proves that the
sun be created by effect of the planet data – there's no other explanation can be
provided for this data consistency.
- Data No. (2)
- 25920 million km = 629 million km x 41
- 2 x 100733 million km = 4900 million km x 41
- Where
- 629 million km = Earth Jupiter Distance
- 4900 million km = Jupiter Orbital Circumference

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- 41 degrees = The Planets Orbital Inclinations Total
- We know 4900 mkm is the central distance in the soar system – that shows the
distance 629 million km (Earth Jupiter Distance) is so important in comparison
with 4900 mkm. Means the distance 629 mkm is so important for the sun creation
and definition of its position.
- We will analyze the distance 629 mkm in the next point to define the sun position
in the sky.
- (d) The Total Solar Eclipse
- Data
- (1)
- (The Sun Diameter / The Moon Diameter) = (Earth Orbital Distance / Earth Moon
Distance) =400
- (2)
- (Earth orbital distance / the sun diameter) = (the sun diameter/ Earth diameter) =
(Earth moon distance / the moon diameter) =109
- (3)
- (Earth diameter / the moon diameter) = (the sun diameter / Earth moon distance)
=3.66
- (4)
- The sun diameter x the moon diameter = the moon circumference x Jupiter
circumference = Jupiter orbital circumference = 4900 million km
(The sun diameter = Jupiter diameter x π2
(error 1.4%))
- (5)
- Jupiter orbital circumference = Earth diameter x the moon orbital distance = Venus
diameter x the moon orbital apogee radius = 2 x Mars diameter x the moon orbital
perigee radius
- (6)
- Jupiter orbital distance =5.2 x Earth orbital distance

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- (the moon orbital inclination = 5.1 degrees error 2%)
- (7)
- Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter (where 10921 km = The Moon Circumference)
- (8)
- Saturn Circumference =378675 km= Earth moon distance at total solar eclipse
- Discussion
- The data tries to prove the fact, the total solar eclipse be done as a planned
phenomenon geometrically - that means- the planets (Jupiter- Earth and the moon)
be in cooperation with the sun motion to create the total solar eclipse – no hope for
pure coincidence behind – instead – it's the geometrical machine which defined the
sun position in the sky -
- Why??
- I suggest that, when the sun be created, and the rate of time (1 =1461) be defined
by the Earth and moon motions – the planets by help of Jupiter, Venus and Uranus
tried to define the sun position in the sky –
- The moon is a very important player in this process because the Earth can't define
the sun position (accurately) at a distance (=149.6 million km) – for that reason –
the accurate position of the sun be defined by the moon help –
- The total solar eclipse defines an accurate position for the sun in the sky in
comparison with the Earth and moon positions.

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- (e) The Creation of The Rate (1 = 1461)
- Data
- (1)
- Velocity 0.9999c causes a rate (1 = 71)
- (2)
- 71 x 5.1 = 365.25
- One day = 0.196 degrees when 5.1 days = 1 degrees
- 0.196 x 278.4 deg = 2 x 27.3 deg
- (3)
- 7.1 x 0.196 = 1.392 million km (The Sun Diameter)
- Discussion
- The idea tells, a velocity = 0.9999 c be found (299970 km/s)
- This velocity causes Lorentz contraction effect by a rate = 71 and
- The distances be used as periods of time for that – the rate 71 be used between the
sun and a point of the ecliptic before the moon orbit
- Means
- 1 day on the sun = 71 days on this point which be before the moon orbit toward the
sun.
- The moon orbital inclination (5.1 degrees) uses 71 days and transports it to Earth
motion as 365.25 days (71 x 5.1 = 365.25)
- As a result 1 day of the sun = 365.25 days of the Earth
- And the Earth cycle (365+365+365+366 =1461 days) causes the period (1461
days) be produced by which the planets motions distances be = light motion
distance in one day.
- The point here is that
- 1 day of the moon orbit = 1 degree because
- (the moon orbit regresses 19 degrees per year and change the eclipse calendar by
19 days) by that 1 day = 1 degree

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- We need only to prove that 1day on Earth = 0.196 degrees
- The data shows some proves
- Data No.2
- 0.196 x 278.4 deg = 2 x 27.3 deg
- 278.4 degrees = the outer planets axial tilts total
- 27.3 days = the moon orbital period
- This data may refer that the rate (0.196) be used in the Earth motion data.
- Why??
- The Inner Planets Orbital Inclinations Total (= 17.4 degrees)
- The outer Planets Orbital Inclinations Total (= 23.4 degrees)
- (17.2 degrees = Pluto orbital inclination) (error 1%)
- (23.4 degrees = Earth Axial Tilt) (error 1%)
- The data tells, there's a reason to connect the Earth with the outer planets data.
- Data (3)
- 7.1 x 0.196 = 1.392 million km (The Sun Diameter)
- This data also refers to using the rate (0.196), where 7.1 is a very famous rate in
the solar system because it be used for the rate 1.0725 we have discussed
frequently.
- We remember
- (7.1/100) + 1 = 1.071
- That tells a geometrical mechanism be found behind based on this rate (0.196)
- I try to show that
- The moon orbital inclining causes to transport the period (71 days) to the Earth in
a form (365.25 days) the inclination did that by change in the degrees rate for the
days where 1 day of the moon orbit = 1 degree but 1 day of the Earth = 0.196
degrees.
- By this method the rate (1 = 365.25) be produced by Earth and the moon motions.

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(f) The Distance 629 million km
- Data
- (1)
- 6939.75 s x 0.3 million km/s = 2094 million km
- 2094 s x 0.3 million km/s = 629 million km
- (2)
- 629 million km = 4.095 million km / day x 153.3 days
- 5127 million km = 4.095 million km / day x 629 days x 2
- (3)
- 629 million km = 2.574 million km / day x 243 days
- (4)
- 629 million km = 3475 km x 181000 km
- 149.6 million km = 3475 km x 43000 km
- Discussion
- Data no. (1)
- 6939.75 s x 0.3 million km/s = 2094 million km
- 2094 s x 0.3 million km/s = 629 million km
- This data tells the light (300000 km/s) travels during 6939.75 seconds a distance =
2094 million km (Jupiter Uranus Distance), and the light uses the distance as a
period of time (2094 seconds) to pass the distance 629 million (Jupiter Earth
distance)
- This light beam tells a clear relationship be found between Earth, Jupiter and
Uranus positions (where Metonic Cycle = 6939.75 days)
- Data no. (2)
- 629 million km = 4.095 million km / day x 153.3 days
- 5127 million km = 4.095 million km / day x 629 days x 2
- This data tells

Planet Motion Logic Disproves Newton Theory Of The Sun Gravity.pdf

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