Is There another Orbit For The Moon Motion?

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Is There another Orbit For The Moon Motion?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 11th
November 2020
Abstract
Paper Hypothesis No. (1)
- Another Orbit must be found for the moon motion.
Paper Hypothesis No. (2)
- An interaction is found between Jupiter and the Earth moon motions, this
interaction shows that another orbit must be found for the moon motion –
Paper Objective
- The paper tries to prove that, there's an interaction between Jupiter and the moon
motion.
- And
- Based on this interaction, Jupiter effect on the moon motion suggests that another
orbit is required necessary for the moon orbital motion.
Paper Contents
1- Can another orbit be found for the moon motion?
2- Jupiter And The Moon Motions Interaction

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1- Can another orbit be found for the moon motion?
1-1 Preface
1-2 Another orbit is found for the moon motion?
1-1 Preface
- In the previous paper (The Moon Orbital Triangle Analysis (VII)) we have
discussed this question trying to know if another orbit can be found for the moon
motion – that means – We have one moon but 2 different orbits because we have 2
different motions –
- From where this idea is suggested?
- The perimeter of the moon orbital triangle (ACE) = 943817 km but the moon orbit
data depends on the value (2 x 943817 km= 1.88 mkm), this value (1.88 mkm) is
used almost as the min pillar in the moon orbital triangle – the question was why
the moon orbital geometrical structure depends heavily on this value (1.88mkm)?
- The answer, "There Must Be One More Orbit For The Moon Orbital Motion".
- But,
- Why there's one more orbit for the moon motion? what's geometrical necessary
for it, if it's really found?!
- There was one more proof for this hypothesis, that, the moon motion distance from
perigee to apogee (43000 km) contains an area = 50% of Jupiter total energy
(error 3.5%) (Space =Energy), So if Jupiter energy is transported to the moon orbit
where's the other 50%?!
- These questions provide more puzzles than answers! Why? because I have started
from the data, for example I ask why Jupiter diameter =142984 km or why Jupiter
diameter =13.1 x the moon circumference (10921 km)? the theoretical explanation
approach can provide more clear picture for our discussions…..
- I hope to provide some theoretical explanation approach in this paper trying to
make the picture as clear as possible
- The questions are confused with each other, (1st
question) can be another orbit
found for the moon motion and (2nd
question) can Jupiter motion perform an
interaction or effect on the Earth moon motion?
- The answer is one for both questions …. And simply
- Because Jupiter motion effects and interacts with the moon motion, the moon has 2
orbits of motion – let's start our discussion immediately…

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1-2 Another orbit is found for the moon motion?
Let's insert the moon orbital triangle and its data to be our discussion reference
z
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees

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Let's Review The Moon Orbital Triangle Data
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = = 18586 km
- BF = = 21000 km
- BD = DA = 43000 km
- BY = =47513.7 km
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF = 88526.8 km
- CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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The Discussion
Equation No. 1
449197 km x 2 = (2π) x 142984 km
- 449197 km = The Distance (AE) In The Moon Orbital Triangle
- 449197 km = Jupiter Circumference
- 142984 km = Jupiter Diameter
- Let's remember the motion hypotheses and rules
- 1st
hypotheses (Planet Motion depends On Light Motion)
- 2nd
hypotheses (Light motion for 1second causes planet motion for 1 solar day)
- The Motion Rule (Light moves at a circle circumference and its follower planet
moves along this same circle radius)
- The equation secret always is (2π) this rate tells that, we deal with 2 different
motions
o A Planet motion along a circle radius (142984 km= Jupiter diameter)
o A Light motion along a circle circumference (=(2π) x 142984 km)
- In the moon orbital triangle the value 449197 km is the distance (AE) which is the
longest distance in the triangle, and the moon orbital triangle is built based on this
distance (AE)
- So the value (2 x 449197 km) tells that there are 2 orbits for the moon motion,
- The value (2 x 449197 km) should be found necessarily if we have 2 motions ( a
planet and light motion), means, if it's possible to prove that there are 2 motions
one of them uses this distance (2 x 449197 km) and the other uses (142984 km =
Jupiter diameter) that tells us both distances are real and the moon must have
another orbit for its motion
- Shortly, In this case
o Jupiter will play as a light beam moves along the distance (2 x 449197 km)
and creates the 2 orbits of the moon motion –
o On the other side, the moon will move along the distance 142984 km =
Jupiter diameter) because the moon is the follower planet to the light beam,
and so the light beams moves (R2π) and the planet move (R) in this case…
Shortly
- We need to prove that, the moon moves along the distance 142984 km = Jupiter
diameter) to prove that the value (2 x 449197 km) is a real one
- To prove this fact we need to prove firstly the interaction between Jupiter and the
moon motions ….

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2- Jupiter And The Moon Motions Interaction
1-1 The Interaction Of The 2 Planets Motions
Data No. 1
A. Jupiter Velocity = 13.1 km per second
B. Jupiter Diameter (142984 km) = 13.1 x 10921 km (The Moon Circumference)
- Equation No. (B) tells that,
- When the moon rotates around its axis, it moves a distance =10921 km… So if the
moon rotates around its axis (13.1 times), the moon would move a distance =
142984 km = Jupiter diameter
- But …The moon rotates around its axis on time each 27.3 days,
- To move a distance =142984 km the moon needs to rotates (13.1 times) means
13.1 x 27.32 days = 358 days (almost needs a year to do that)
- So during a year (approximately) the moon rotations around its axis causes the
moon to move a distance =142984 km (=Jupiter diameter)
- i.e. Jupiter diameter is the moon (rotation) distance targeted per a year.
- Why Jupiter velocity =13.1 km per second??
- Jupiter creates an mirror for the moon motion to its motion, means, Jupiter moves
according to the moon motion but with Jupiter capacity of motion, because Jupiter
here (is a light beam)
- One year of the moon motion is equivalent to One second of Jupiter motion!
- The moon circumference (10921 km) for the moon motion is equivalent to 1 km
for Jupiter motion
- That means both motions are produced depending on each other … BUT
- How to believe this strange claim?! -
- If the moon circumference (10921 km) for the moon motion is equivalent to 1 km
for Jupiter motion! (we may accept that!) Because ….
- In moon orbital triangle we have found that, the triangle ABC, its perimeter =
292056 km (error 0.5%) and this value = 43 x 6792 km (Mars diameter) and we
have concluded that, each 1000 km of the moon orbital distance between perigee
and apogee (43000km) is equivalent to Mars diameter (6792 km) and by that the
moon orbital radiuses are created to be in harmony with the moon motion and
Mars data –
- But how 1 year of the moon motion can be equivalent to 1 second of any planet or
light motion?! how to understand that?

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Data No. 2
C. 86400 seconds x 365.25 degrees = (31.5) (2737 years x 365.25 days)
- 2737 years = the cycle we have discussed before, here we use its days value
- What does Equation no. (c ) tell us??
- 1 second should be equal 1 year (365.25 days)! How?
- 31.5 = Uranus Axial Tilt (97.8) / Jupiter Axial Tilt (3.1), this interaction is
clearly understood because the 2 planets are the major players in the moon orbit
and so the interaction between their axial tilts almost naturally be occurred
- 2737 years, is the cycle we have discussed frequently before, it's first using of it
here, we use its day period (999689.25 days)
- What does that mean?
- We need to make 1 second is equivalent to 1 year, to create this equality we need
the cycle 2737 years….
-
- We have faced a similar situation before let's remember it for easier explanation,
o The moon moves during 29.53 days a distance = 2.58 mkm and
o Earth moves during 1 solar day equal distance =2.58 mkm
o Because of that…
o I claimed that, 1 day on Earth = 29.53 days on the moon
o But
o 1 day on the sun = 365.25 days on Earth ….
o So
o 1 day on the sun = 29.53 x 365.25 = 10747 days on the moon
o And we have found that
o 10747 days = Saturn Orbital Period
o i.e.
o A planet cycle is created to create some rate of time–how can we know that?
because the cycle is consisted of 2 other cycles
o That's what happened here, the cycle 2737 is created for 2 other cycles
(86400 seconds and 365.25 days)
o That tells the cycle 2737 is a real one and its role is to create the rate of time
(1 second " Light motion" is equivalent to 1 sidereal year " Planet motion")
o This new rate of time is created based on the cycle 2737 years
Let's ask
- Has the cycle 2737 any relationship with Jupiter data ?
- let's answer in following

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The Cycle 2737 years
D. 2737 mkm = 2105 mkm x 1.3
E. 2737 mkm = 627 mkm x 4.4
F. (0.0831) degrees x 2737 mkm = 227.9 mkm
Equation No. (D)
2737 mkm = 2105 mkm x 1.3
- 2105 mkm = Jupiter Uranus Distance (error 0.6%)
- 1.3 degree = Jupiter orbital inclination
- 2737 mkm is the distance between Uranus & the point (135.5 mkm) from the sun,
- Equation no. (D) shows 2 distances, Uranus is the common point in both, so it's a
connection between Jupiter and the point (135.5 mkm) through Uranus and
because Uranus and Jupiter are the 2 major players in the moon orbit – that tells
this equation shows the connection point by which Uranus and Jupiter unifies to
effect on the inner planets and specifically on the moon orbit…
- Note Please 2105 mkm = π x 670 mkm (Venus Jupiter distance), Jupiter
position here works as a connection point to connect Uranus (2105 mkm) with
Venus (670 mkm)… through this same point (2105mkm) which is defined based
on the distance 2737 mkm - the equation shows The Interaction Clearly
Equation No. (E)
2737 mkm = 627 mkm x 4.4
- 627 mkm = Jupiter Earth Distance (error 0.8%)
- 4.4 degrees = 1.3 degrees (Jupiter orbital inclination) + 3.1 deg. ( Jupiter axial tilt)
- Equation no. (E) tells that, Jupiter Earth distance is defined as a function of the
distance between Uranus and the point (135.5 mkm), based on Jupiter degrees (3.1
+1.3) =4.4
- Shortly, Jupiter has to create an interaction with Uranus (whose effect extends to
the point 135.5 mkm from the sun) to enable Jupiter to effect on the inner planets
and specifically on the moon orbit…
Equation No. (F)
(0.0831) degrees x 2737 mkm = 227.9 mkm
- 0.0831 degrees = Jupiter motion degrees per a solar day
- Mars orbital distance (227.9 mkm) is defined based on the distance 2737 mkm by
this same rate (0.0831) which shows that Mars orbital distance is created based on
these 2 factors.

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Can the moon motion create an interaction with Jupiter motion?
G. 13.1 x 1.1 degree = 14.4 degrees
H. 13.1 x 1.8 degrees = 23.6 degrees
Equation No. (G)
13.1 x 1.1 degrees = 14.4 degrees
- 14.4 degrees =The total angle at Earth, as we see in the triangle, E angle=13.3 deg,
and under E there's an angle (=1.1 degrees) which is created by Uranus
perpendicularity on the moon orbit, Uranus axial tilt angle (91.1 degrees) with the
moon axial tilt – so the total =14.4 degrees
- 13.1 = Jupiter diameter 142984 km/ the moon circumference 10921 km
- Equation no. (G) tells that, the total angle (14.4 degrees) is defined theoretically by
the rate between Jupiter diameter and the moon circumference multiplies with the
angle (1.1 degrees) created by Uranus effect
- i.e.
- the moon circumference is created based on this angle (1.1 degree), means, Uranus
effect on the moon orbit defines the moon diameter as a function of this angle…
-
- The main point here is the angle 14.4 degrees, which with some interaction will be
equal 1.44 degrees (the moon orbit regression degrees monthly)
Equation No. (H)
13.1 x 1.8 degrees = 23.6 degrees
- 1.8 degrees = Neptune Orbital Inclination
- 23.6 degrees = the outer planets orbital inclinations total
- Note
- 23.6 degrees x 0.99 = 23.45 degrees (Earth Axial Tilt)
- Equation no. (H) tells that, the rate 13.1 is a player in earth axial tilt creation
Let's ask again

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Can the moon motion create an interaction with Jupiter motion?
- Let's summarize the idea in following…
- We have 2 values only, 13.1 = (Jupiter diameter / the moon circumference) and
13.1 km per second = Jupiter velocity….
- I suppose this data is created as a result of some interaction between Jupiter motion
and the moon motion, let's try to see this interaction if following
o The moon rotates around its axis and by this rotation it moves a distance
=10921 km in 27.3 days (or 27.5 days)…
o Now the distance 10921 km became a motion
o That makes the distance 142984 km also a motion passed by the moon
through its rotations during (13.1 x 27.3 or 27.5, approx. = A year)
o The distance (142984 km became a targeted motion by the moon rotation
during complete year (approximately)
o Jupiter velocity tells that, these (13.1 x 10921km) will be used as13.1 x 1km
o 1 km is used in place of 10921 km … Why?
o It's (1st
step)
o And then
o 1 year (365.25 days) will be equivalent to 1 second (2nd
step)
o And
o Based on that,
o Jupiter velocity 13.1 km /sec will be created based on the moon rotation
motion during 1 year…!
o WHY?
o For 2 reasons
o (1st
reason) because Jupiter is NOT a planet, It's A Light Beam, and this
proof is just an additional for tenth proves we have found frequently in
Jupiter data analysis….
o (2nd
reason) it's The Basic Creation Of Matter
o The old question, how the matter is created? the complex machine tells
us that, the matter is created here by this complex interaction…how can I
reach to this conclusion? Because the rate 13.1 is between 2 matters
dimensions (Jupiter diameter and the moon circumference),
o It's a complex process to produce the matter BUT the matter is created as
a function of its motion
o the analysis tells us that (the Earth diameter =12756 km because Earth
velocity =29.8 km per second)! how? The complex machine tells us there's a
method to know

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Why The Moon Motion Has 2 Orbits?
Because
Equation No. 1 (revision)
449197 km x 2 = (2π) x 142984 km
- 449197 km = The Distance (AE) In The Moon Orbital Triangle
- 449197 km = Jupiter Circumference
- 142984 km = Jupiter Diameter
- It's a light motion which we deal with here
- Jupiter moves as a light beam, and the moon follows this light beam, for that
- The light (Jupiter) moves along the distance 449197 km x 2 = 2π x142984 km
- But the moon follows the light beam along the radius (142984km)
- The distance 142984 km = Jupiter diameter because
- The matter is created based on light motion, the motion is found before any matter
creation and this motion is the light motion and by this motion is matter is created
and because of that the matter dimension are created as a function of the motion …
i.e.
- Jupiter motion effect tells us that, there's another orbit for the moon motion,
Shortly
- The Earth moon moves through 2 different orbit of motions around Earth
both are connected geometrically and because of that one orbit only can't
explain the moon orbital motion trajectory
- We need to add the second orbit to the first one to see the moon motion as clear as
possible

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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