Paper Question - Why Jupiter velocity =13.1 km per second? - Jupiter needs by this velocity a period =10921 seconds to pass a distance = 142984 km = Jupiter diameter - But - 10921 km = The Earth moon circumference - How this value can be used as 10921 seconds? - The paper tries to discover some geometrical method to solve this question Gerges Francis Tawdrous +201022532292

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Why is Saturn Velocity 9.7 km Per Second?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 12th
November 2020
Abstract
Paper Question
- Why Jupiter velocity =13.1 km per second?
- Jupiter needs by this velocity a period =10921 seconds to pass a distance = 142984
km = Jupiter diameter
- But
- 10921 km = The Earth moon circumference
- How this value can be used as 10921 seconds?
- The paper tries to discover some geometrical method to solve this question

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Introduction
- Why is Saturn Velocity 9.7 km /s?
- The direct answer is puzzled and causes confusion! Let's see
o Saturn velocity =9.7 km /sec and Saturn Day Period =10.7 hours
o i.e. Saturn moves during its day period (10.7 h) a distance = 373644 km
o But .. Saturn Circumference = 378675 km (the difference =1.3%)!
o i.e. Saturn moves during its day period a distance = its circumference!
o Means, Each 1 km of the motion distance is equivalent to 1 km of Saturn
Circumference – Is there any geometrical reason behind?!
o Neptune tells some different rate, each 1 km of Neptune Circumference is
equivalent to 2 km of the distance passed by Neptune during its day period
where the distance =(312984 km) and Neptune circumference = 155596 km.
o (Note 2 Neptune Circumferences = diameters (Jupiter +Saturn+ Neptune)
o Is there any geometrical reason behind?! This Data is an introduction to
discuss Jupiter data – let's do it
- Jupiter velocity =13.1 km/s and Jupiter needs 10921 seconds to pass a distance
=142984 km = Jupiter diameter! but we know that (10921 km = the Earth moon
circumference) and How the km becomes 1second?!
- During Jupiter day period (9.9 hours) Jupiter moves a distance = 466884 km which
is different from Jupiter circumference (449197 km) with difference (4%)
- Means Jupiter moves a distance = 449197 km = Jupiter circumference in 9.524 h
- And
- (9.9 hours /9.524 hours) = (365.8/ 351.88) (365.8 is near to 365.25)
- Can this data shows an interaction in motion between Jupiter on one side and
Mercury with Earth on the other side?
- Let's ask, Can the Earth moon circumference 10921 km works as a time period?
o As we have seen in Saturn Data, It motion distance during its day period =
its circumference – So the circumference 378675 km will be a distance of
space (=378675km)
o In light motion, we know, the distance value can be used as time value,
based on this explanation the moon circumference 10921 km is used as
10921 seconds! But why this is necessary or possible?
o What's behind this strange configuration between Jupiter and the moon
diameters values? Let's discuss that in following…

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
2- Jupiter & The Earth Moon Motions Interaction
Equation No. 1
449197 km (Jupiter circumference) x 10921 km (the moon circumference) =4900 km
(Jupiter orbital circumference)
Equation No. 2
10921 mkm = 4222.6 days x 2.58 mkm (Earth motion distance per solar day)
Equation No. 3
4900 km (Jupiter orbital circumference) = 4222.6 seconds x 1.16 mkm/sec
Equation No. 4 (Please remember)
(9.9 hours /9.524 hours) = (365.8/ 351.88)
- We know almost all the previous equations, but we need to see the depth behind,
let's start our discussion ….
- Jupiter needs 10921 seconds to pass a distance =142984 km = Jupiter diameter!
Why this distance (142984 km) is significant? We still need to discover …
- Jupiter orbital circumference is created as a function in its circumference and the
Earth moon circumference, i.e. Jupiter diameter is a player in Jupiter orbital
distance definition, that tells, the motion by which Jupiter passes this distance
142984 km is an important motion in Jupiter general motion – that makes the
moon circumference (10921km) a significant value in Jupiter motion definition.
- So we need 10921 km
- But
- 10921 million km can be produced by Earth motion distance daily (2.58 mkm)
during 4224 days – and we know that the moon moves daily a distance equal
Earth motion (2.58 mkm) because they are not separated from each other – means
the moon itself moves this distance (2.58 mkm) during 4224 days to produce
10921 million km –
- Can 1 km be 1 second or 1 million km be 1 second?? both possible
- Because Jupiter energy which is sent to the inner planets is sent in 86400 mkm an
the solar day =86400 seconds, both rates are working
- Let's use the ready one (10921 million km) to produce 10921 seconds
- And during this 10921 seconds Jupiter moves 142984 km

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
- Light Velocity Effect On Planets Motions
- More analysis my help us …
- Light velocity = Earth velocity (29.8 km/sec) x 10067
- Means
- Earth during 10067 seconds passes a distance = light motion for 1s = 0.3 mkm
- Now
- We have 2 values 10921 seconds and 10067 seconds
- But we know that,
- 10921 = 10067 x 1.0725
- The rate 1.0725 we know perfectly, it's Lorentz length contraction rate, one
example for revision is …
o (778.6 mkm = Jupiter orbital distance = 1.0725 x 720 mkm) where
o 720 mkm =Mercury Jupiter Distance …. We have discussed that
o Where we accepted that both distances are equal each other, and both
distances are created as light beam, But the sorter distance (720 mkm) is a
light beam passes through another frame (We deal with high velocity
motion), because this light beam passes through another frame we see it
under the Lorentz Length Contraction Phenomenon, and because of that we
see it shorter than the other
o That's the same doing with Earth and Jupiter motions … let's return to it
- Earth motion depends on the period 10067 seconds to create its consistency with
light motion and Jupiter depends on the period 10921 seconds to create its
consistency with its orbital circumference and both values (10921 s &10067 s) are
created based on the moon motion – that means the moon is a common effective
player with Earth and Jupiter –
- Please Note, This supports the claim that, Jupiter gravity creates the Point (A) on
the moon orbital triangle which proves Jupiter gravity effect ion the moon motion
- Why this analysis is useful?? Because 2 planets uses the same circumference as 2
periods of time – that proves the geometrical necessity in this using which supports
the paper claim …
Old Equation (No. A)
- Light velocity = 27.3 days x 10921 km
- This equation tells, if the moon rotates around its axis one time per solar day (as
Earth does), the moon would move during its orbital period a distance = light
motion distance during 1 second.

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
Equation No. 3
4900 km (Jupiter orbital circumference) = 4222.6 seconds x 1.16 mkm/sec
- We know this equation perfectly,
- Equation no. (3) tells that, a light beam travels during 4222.6 seconds with
supposed velocity 1.16 mkm/sec, will pass a distance =4900 km = Jupiter orbital
circumference
- That means
- This distance is defined basically by a light motion
- That's why, We have so complex situation here ..Because the light defined the
distance and created the matter to move through this distance but we consider that
the matter defined its motion distance – simply – the light is found before and
created the matter and its motion distance….
- The value 4222.6 seconds is used by Mercury as 4222.6 hours and created
Mercury day period
- That explains the equation no. (4)
Equation No. 4
(9.9 hours /9.524 hours) = (365.8/ 351.88) (365.8 is near to 365.2)
9.9 h = Jupiter day period
9.52h = Jupiter motion period to pass a distance 449197 km = Jupiter circumference
351.88 days = 2 x Mercury day periods
- Equation No. 4 tells that, Jupiter defines its motion based on its circumference,
spite the error (4%), that means, Jupiter mentioned to create 4% difference
between the distance Jupiter moves during its day period and Jupiter
circumference..! why? because based on this difference (4%) earth orbital period
365.25 days will be created as a function of Mercury day period (2 x 175.94 days =
351.88 days) and by that the interaction between Mercury and Earth motions will
be seen in their cycles periods … but why Mercury day period and not Mercury
orbital period? Because
o Mercury moves during its day period a distance =720 mkm = Mercury
Jupiter distance
o And
o Mercury moves during its orbital period =940 mkm = Earth Jupiter distance,
note in this cases Earth and Jupiter should be at 2 different sides from the
sun (error 1.2%). (That shows Jupiter effect on both planets because Jupiter
connects the planets 2 cycles by their distances to Jupiter point).

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
More Data (1)
The moon orbital distance from perigee (0.363 mkm) to apogee (0.406 mkm)
- The area of this distance = 103944 mkm2
- Jupiter orbital period 4331 solar days has 103944 hours
- Note Please
- Light motion during 86400 seconds with supposed velocity 1.16 mkm/sec passes a
distance = 100224 mkm with an error (4%) with the area of the moon orbit
- Jupiter aimed to create an error or difference 4% between the data for geometrical
necessities….
- That tells us, the moon orbit area contains a distance passed by light supposed
velocity (1.16 mkm/sec) during a solar day, but Jupiter energy is consisted of this
same light motion during 2 solar days – means – the moon orbit contains 50% of
Jupiter energy – that supports the claim there's one more orbit for the moon motion
More Data (2)
(I)
351.88 mkm = 116.75 days (Venus Day period) x 3.02 mkm /day (Venus velocity)
(351.88 days = 2 x Mercury Day Period)
And
243 mkm=58.66 days (Mercury Rotation period) x 4.09 mkm /day (Mercury velocity)
(243 days = Venus rotation period)
(II)
(Venus Mass/ The Earth Moon Mass) = (the moon rotation period / Jupiter
rotation period)
- The previous data tells that, because Mercury motion has an interaction with the
moon & Jupiter motion, and Mercury motion has interaction with Venus motion,
because of that Venus motion got interaction with the moon motion to create its
rotation period as a function of Jupiter rotation period!
- Why?
- Because Jupiter rotation period equal Jupiter day period and that shows the
previous analysis of Jupiter motion during its day period is found based on
geometrical necessities

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
More Data (3)
(III)
Jupiter moves during 175.94 days (Mercury day period) a distance = 1.3 x 153
mkm
- This data shows Jupiter effect on the interaction of Mercury and Earth motions
- Also this data supports the claim that Earth original orbital distance was 153 mkm,
which supports the claim that Earth moved near to the sun 3 million km.
More Data (4)
Pluto moves during its day period 2.58 mkm = Pluto circumference x 346.6
Where
(346.6 days = The Nodal Year) (error 0.4%)

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
The moon orbital triangle revision
Let's insert the moon orbital triangle and its data to be our discussion reference
z
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees

9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
Let's Review The Moon Orbital Triangle Data
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = = 18586 km
- BF = = 21000 km
- BD = DA = 43000 km
- BY = =47513.7 km
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF = 88526.8 km
- CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

10. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
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Mr.Gerges Francis Tawdrous +201022532292
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Gerges Francis Tawdrous +201022532292
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