Why is Saturn Velocity 9.7 km Per Second (II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Why is Saturn Velocity 9.7 km Per Second? (II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 12th
November 2020
Abstract
Paper hypothesis
The Planet Day Period Definition
- The planet day period is the period during which the planet moves a distance = its
circumference.
- Saturn follows this definition and moves during its day period 10.7 hours a
distance = Saturn Circumference (error 1.3)
But
- Neptune moves during its day period (16.1 hours) a distance = 2 Neptune
Circumferences
- Why not all planets follow this same definition? How the planet day period is
defined?
- The paper discusses these questions

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1- Planet Day Period Definition
1-1 The 4 outer Planets Days Periods Features
(1st
Point)
The 4 outer planets (Jupiter – Saturn – Uranus and Neptune) – their days periods are
arranged according to their masses
- Jupiter its day period 9.9 hours
- Saturn its day period 10.7 hours
- Neptune its day period 16.1 hours
- Uranus its day period 17.2 hours
The arrangement is done by masses, greater mass required shorter day period
(2nd
Point)
The 4 outer planets days periods are rated to each other
(9.9 hours/10.7 hours) = (16.1 hours /17.2 hours) (error 1%)
(3rd
Point)
The distance passed by the planet during its day period (for the 4 outer planets)
(466884 km – Jupiter motion during its day period) / (391086.7 km) =
(373644 km – Saturn motion / 312984 km –Neptune motion during its day period)
421056 km (Uranus motion during its day period) = 1.0725 x 391086.7 km
i.e.
(Jupiter motion / Uranus motion) = (Saturn motion / Neptune motion)
(During Their Days Periods)
- Saturn moves during its day period a distance = its circumference (error 1.3%)
but
- Jupiter moves during its day period a distance = its circumference (error 4%)
- Neptune moves during its day period a distance = 2 circumferences
- Uranus moves during its day period a distance = 2.62 circumferences (because
Uranus distance is seen relative under the contraction rate 1.0725)…
- Not very clear?! Uranus moves an additional distance with 1.0725?! the
contraction discounts the distance and not increased it! how that happened?
- The answer is that,
- The 3 Planets motions are measured under contraction (1.0725) but nothing is
observed because all distances are shorted by the same rate…

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1-2 The solar Planets Days Periods Features
- The solar plants days periods can be classified into 3 categories
- 1st
category contains 3 planets which are
o Mercury its day period =4222.6 hours = 175.94 solar days
o Venus its day period = 2802 hours = 116.75 solar days
o The Earth moon day period = 708.7 hours = 29.53 solar days
o Pluto day period = 153.3 hours = 6.387 solar days
- 2nd
category contains 2 planets which are
o Earth its day period =24 hours = 1 solar days
o Mars its day period = 24.7 hours = 1.029 solar days
- 3rd
category contains 4 outer planets which are
o Jupiter
o Saturn
o Uranus
o Neptune
- We have analyzed the 4 outer planets motions during their days periods – so
let's study the 1st
category
- Mercury moves during its day period 720 mkm = Mercury Jupiter distance
- Venus moves during its day period 351.88 mkm
- The moon moves during its day period (29.53 days) a distance = 71 mkm
- Earth moves during 27.3 days a distance = 71 mkm
The 2nd
category
- Earth moves during its day (24 hours) a distance = 2.58 mkm
- Mars moves during its day (24.7 hours) a distance = 2.2.12 mkm (error 1%)
- (The difference between Earth and mars motions distances during their days
periods = Jupiter circumference = 449197 km)
Note please
- Earth moves during its day (24 hours) a distance = 2.58 mkm
- Pluto moves during its day (153.3 hours) a distance = 2.58 mkm
- The moon rotation distances during its day period (29.53 days) = 2.58 mkm

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1-3 Can planet circumference be used as a period of time?
- This feature we have discovered by Jupiter motion analysis let's review it
- Jupiter velocity =13.1 km per second, Jupiter needs 10921 seconds to pass a
period = 142984 km = Jupiter diameter –
- But
- We know that, 10921 km = The Earth Moon Circumference
- We will not go deeper in this discussion – we will try to know only if it's a real
future that, the planet circumference can be used as a period of time
- Theoretically it's possible … why
- Because the planet rotates around its axis and by that, the planet moves a
distance = its circumference, Now the matter dimension becomes a distance
and we know that the light motion can use the distance value as a period of
time (x =ct and if c =1 so x=t)
- It's the theoretical argument – but how can we use this for better understanding
for the solar system motion? First let's see if it’s a real feature
- To use the planer circumference as a period of time that needs a light motion so
let's test if the light can use the planets circumferences values as useful periods
for motion – in following
o Mercury circumference = 15334 km, equivalent to 15334 seconds!
o Venus circumference = 38041 km, equivalent to 38041 seconds, the light
known velocity (0.3mkm/sec) travels during 38041 seconds a distance =
= 5687.1 mkm (Mars Pluto Distance)
o The Earth moon circumference = 10921 km, equivalent to
10921seconds, the light known velocity (0.3mkm/sec) travels during
10921 seconds a distance = 1622.7 mkm (Uranus Neptune Distance)
o Earth circumference = 40080 km, equivalent to 40080 seconds, the light
known velocity (0.3mkm/sec) travels during 40080 seconds a distance =
120536 mkm (Saturn diameter 120536 km x the moon orbital diameter
1mkm)
o Mars circumference = 21346.6km, equivalent to 21346.6 seconds, the
light known velocity (0.3mkm/sec) travels during 21346.6 seconds a
distance = π x 2040 mkm (Jupiter Uranus Distance) (error 2.5%)
The outer planets diameters are used
o Jupiter diameter 142984 km, equivalent to 142984 s, the light known
velocity (0.3mkm/sec) travels during it a distance = 2π x 3413 mkm
o But

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o (360 mkm +680 mkm +940 mkm +1443 mkm) = 3413 mkm (the 4 inner
planets orbital circumferences total)
o And we know that 4900 = 3413 mkm+ Mars orbital circumference where
4900 mkm = Jupiter Orbital Circumference
o Saturn diameter 120536 km, equivalent to 120536 s, the light known
velocity (0.3mkm/sec) travels during it a distance = 2π x 5756 mkm
(Earth Pluto Distance)
o Uranus diameter 51118 km, equivalent to 51118 s, the light known
velocity (0.3mkm/sec) travels during it a distance = π x 4900 mkm
(Jupiter orbital circumference)
o Neptune diameter 49528 km, equivalent to 49528 s, the light known
velocity (0.3mkm/sec) travels during it a distance = 14858 mkm = (0.5
Neptune orbital circumference 28255 mkm (error 5%)
Why Mercury Circumference is not used here?
Because Mercury uses the supposed light velocity 1.16 mkm/sec
o Mercury circumference = 15334 km, equivalent to 15334 seconds! Light
supposed velocity (1.16 mkm/sec) travels during 15334 seconds a
distance = 2π x 2814.6 mkm (Mercury Uranus Distance)
Discussion
- The previous analysis is not a proof for the claim that, the light uses the planet
circumference and diameter as a period of time
But
- We have discovered that in the relationship between Jupiter and the Earth moon
Let's review this discussion in following

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1-4 Jupiter and the Earth moon motions interaction
I-Data
- Jupiter velocity =13.1 km/sec
- But …
- Jupiter diameter = 13.1 x the Earth moon circumference
- And
- The Earth moon moves per a solar day 13.18 degrees
- Many numbers are similar and we need to be sure that, these number aren't
created for geometrical necessities… let's try to discover it…
II-Discussion
- We have 2 players (Jupiter and the Earth moon) let's see each one side
individually – first we use Jupiter side
- (1st
) Jupiter Motion
o Jupiter needs 10921 seconds to move a distance = its diameter = 142984
km, but
o Jupiter orbital circumference = Jupiter circumference x the moon
circumference
o If Jupiter moves during its day period a distance = Jupiter circumference,
that will cause the moon circumference 10921 km to be considered equal
to (10921 x Jupiter day period) because Jupiter during 1 day period
moves a distance = (1/10921) of its orbital circumference –
o Simply the moon circumference is used here as a measurement for the
period of time required for Jupiter motion distance to revolve its
circumference around the sun
o This same job we have discovered for this moon in its relationship with
Earth let's remember this equation
o 10921 km (the moon circumference) x 86400 seconds = 940 mkm, the
equation tells that, if Earth revolves around the sun one complete
revolution (940 mkm) during 1 solar day only (86400 seconds), the moon
circumference will be equal a distance of Earth motion during 1 second
of time
o In Jupiter case the situation is similar, if Jupiter moves a distance equal
its circumference during its day period, the moon circumference will be
considered as (10921 x Jupiter days period 9.9 hours) – a very similar
situation – without any change
o That supports the claim, that Jupiter creates one more force to effect on
the Earth moon motion in opposite to Earth gravity effect – the analysis
tells us that the moon behaves as similar with Earth as with Jupiter

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- (2nd
) The Earth Moon Motion
o 142984 km = 13.1 x 10921 km
o This equation tells that, Jupiter diameter =13.1 times the moon diameter
o But,
o The moon moves 10921 km in its rotation around its axis, and the moon
rotates around its axis one time each 27.3 days
o i.e. the moon moves 10921 km each 27.3 days
o And
o To move a distance =142984 km = Jupiter diameter distance, the moon
has to rotate around its axis 13.1 time and this motion needs a period of
time = 27.3 days x 13.1 which is equal one year approximately
o i.e.
o the moon rotation during one year cause the moon to move a distance =
142984 km and that means, Jupiter diameter is the moon targeted motion
during a complete year
o why this is useful?
o because
o in the moon orbital triangle we have found that, the distance between
Earth and The Point (A) = 449197 km = Jupiter Circumference – why?
o The only answer is that, because
o 1st
hypothesis (Planet Motion Depends On Light Motion) and
o 2nd
hypothesis (light motion for 1 second cause planet motion for 1 day)
o And
o The motion basic rule tells that
o (light moves through the circle circumference but its follower planet
moves along this same circle radius)
o Now, the moon moves during a year a targeted distance = 142984 km =
Jupiter circumference and
o The moon orbital triangle longest dimension which connects between
Earth and the point (A) = 449197 km = Jupiter Circumference!
o What conclusion can we reach based on that?
o We have 2 motions, a light motion and plant motion
o The planet we know it’s the Earth moon and its targeted motion per year
= 142984 km = Jupiter diameter

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o And where's the light motion?
o We have this dimension (EA)= 449197 km = Jupiter Circumference, so
o We just need one more a distance = 449197 km = Jupiter Circumference
and by that the total will be 2 x 449197 km = 2π x 142984
o The moon motion is142984 mkm and
o The light motion is 2π x 142984 and that means
o There's one more orbit for the moon motion, because we need the second
distance which = 449197 km = Jupiter Circumference to create the light
motion 2π x 142984
Conclusions
o Jupiter and the Earth moon motions are interacted with each other
o There's one more orbit for the moon motion
o Jupiter deals with the Earth moon based on the same rule the Earth deals
with its moon which supports that
o Jupiter mass gravity effects on the moon motion and create the point (A)
on the moon orbit as an effect point for a second force effective on the
Earth moon motion
o Light motion uses the planet circumference and diameter as periods of
time to build the solar system geometry.

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The moon orbital triangle revision
Let's insert the moon orbital triangle and its data to be our discussion reference
z
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees

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Let's Review The Moon Orbital Triangle Data
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = = 18586 km
- BF = = 21000 km
- BD = DA = 43000 km
- BY = =47513.7 km
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF = 88526.8 km
- CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
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Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
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List of publications http://vixra.org/author/gerges_francis_tawdrous

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