The Moon Motion Trajectory Analysis (II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Motion Trajectory Analysis (II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt –25th
October 2020
Abstract
Paper Objective
The Moon Motion Trajectory Rules Definition
- There 3 basic rules are known in the moon motion trajectory, which can help us in
our investigation to discover the moon motion trajectory…
- The 1st
rule
o "There Is Another Force Equal Earth Gravity Force Effect On The Moon
Motion Trajectory, This force Is expressed By point (A) in The moon orbital
triangle, This Point (A) is found beyond apogee point with 43000 km, i.e.
The distance between the Earth and this point (A) = 449000 km"
- The 2nd
rule
o The moon orbital triangle shows that, the moon motion 4 basic radius
(which are Perigee, Apogee, total solar eclipse, and the orbital distance),
these 4 points are defined based on each other by using Pythagoras rule (the
Pythagoras equation should use the term 86000 km as a right triangle
dimension and the other dimension should be any radius of the 4 radiuses
and the result will be another radius of them) – so is this the way by which
the moon move? i.e. does the moon move through its motion trajectory
based on Pythagoras rule?)
- The 3r rule
o The Cycle 1290 days of the moon motion, this cycle gives us a clear light
about how the moon moves through its orbital motion trajectory
- Because we know the rules No 1 and 3, the paper will discuss only the rule no. 3
and review both old rules.

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1- There moon orbital motion trajectory 3 rules
1-1 The Cycle 1290 Days
1-2 Pythagoras rule using
1-3 another force effect on the moon motion trajectory
1-1 The Cycle 1290 Days
- The moon daily displacement =88000 km, but the distance from perigee to apogee
= 43000 km
- Imagine the moon moves from perigee to apogee and return back in a vertical
motion without a displacement on horizontal line, so the moon in this motion will
move a distance = 43000 km x 2 = 86000 km, But the moon in this case still in its
original point on the horizontal line, i.e. the moon did no any displacement in the
moon orbital motion around Earth, instead, the moon uses the distance 86000 km
in a vertical motion from perigee to apogee and return back to its original point on
the moon orbital circumference – as seen in the figure
- The figure explains the idea
- There's no displacement in this motion, but only vertical motion from perigee to
apogee and return back to perigee – in this motion – the moon uses 86000 km of
its daily motion which =88000 km – means – the moon still has only 2 km
- Imagine that the moon will make a displacement by this 2 km on the horizontal
line as the figure shows
- Means, from each 88000 km of the moon motion, the moon moves a displacement
= 2 km at the horizontal line, i.e. the moon daily move 2 km as displacement on
the horizontal line…
- The moon orbital circumference at apogee point = 2.58 mkm
- That means, the moon needs 1290 days to revolve the moon orbital circumference
if this motion is used by the moon…
- How can we know that, if this motion is used by the moon or not? if the value
1290 days is one cycle of the moon cycles periods, that means, the moon uses this
method in its motion….

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I-Data
(1)
(6939.75 days /27.3 days) = (1290 degrees /5.1 degrees)
(2)
1290 days = 354.39 days x 3.66
(3)
1290 days = 27.3 days x 2 x 23.6
More Data
(4)
1461 mkm = 1290 days x 1.1318 mkm /daily
(5)
(6)
II-Discussion
Equation No. (1)
(6939.75 days /27.3 days) = (1290 degrees /5.1 degrees)
- Metonic Cycle 6939.75 days = 27.3 days (the moon orbital period) x 254, But
1290 degrees = 254 x 5.1 degrees (the moon orbital inclination)
- Equation No. (1) tells that, because Metonic Cycle and the moon sidereal month
are 2 known cycles periods of the moon motion, that means, the value 1290
degrees must be a cycle of the moon motion…
- Equation No. (1) connects the value 1290 strongly by the moon basic cycles and
because of that, we may conclude that, the value 1290 days (or degrees) expresses
a basic cycle in the moon motion …
- Please Note, 1 degree = 1 day why? because the moon orbit regresses 19 degrees
per year and causes to change the eclipse calendar by 19 days, means, 1 degree of
the moon orbit = 1 day. And Equation No.(1) shows the value 1290 relative to the
moon orbital inclination.. means 1290 days is equivalent to 1290 degrees
Equation No. (2)
1290 days = 354.39 days (the moon synodic year) x 3.66
We know a similar equation let's remember it … 365.25 days =27.3 days x (3.66)2
,
The previous equation tells that, Earth orbital period depends on the moon orbital
period by the rate 3.66 (= Earth diameter / the moon diameter)
- Equation No. 2 tells this same meaning, the period 1290 days depends on the moon
synodic year (354.39 days) by the same rate 3.66 –
- Equation No. (2) tells clearly that, the value 1290 days is an essential cycle for the
moon motion as much as earth orbital period…
- i.e. the period 1290 days is an essential cycle in moon motion.

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Equation No. (3)
1290 days = 27.3 days x 2 x 23.6
23.45 degrees (Earth Axial Tilt) = 23.6 degrees x 0.99
27.3 days = The Moon Sidereal Month
- Equation No. 3 shows that, the value 1290 days depends on the moon sidereal
month clearly with the Earth axial tilt as a rate
- But why uses the rate 2? Why (2 x 27.3 days)?!! We know that, 2 days expresses
the general values in the solar system, for example, Jupiter energy is sent in light
beam motion during 2 solar days, also Uranus orbital distance = 2 days of the solar
system motion (as we have proved before)
- I want to say that, the value 2 days expresses the general values in the solar system
i.e.
- Equation No. (3) tells that, 1290 days is a cycle equivalent to 27.3 cycles but
expresses the total energy…
- The conclusion we need is (the period 1290 days expresses a real cycle in the
moon motion)
- The rest data shows this value effect on the solar system geometry
Equation No. (4)
- Jupiter during 1290 days moves a distance = 1461 mkm which we see as 1461
days (365 +365+ 365+ 366)
Equation No. (5)
- Neptune during 1290 days moves a distance = the moon displacements total during
Metonic Cycle
Equation No. (6)
- Mars during 1290 days moves a distance = the distance between Mars and Uranus,
A Conclusion
- The period 1290 days is a real cycle of the moon motion
Based on that
- The moon uses the method of motion, I explained in the page no. 2 of this paper.
- Where the moon moves in vertical motion from perigee to apogee and return to use
86000 km of its total motion and the rest 2 km the moon uses for a horizontal
displacement – this method of motion is one of the moon essential methods.

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1-2 Pythagoras Rule Using
EB =363000 km = Perigee radius (The nearest point of the moon to the Earth)
EC= 378000 km = The Total Solar Eclipse Radius
EG= 384000 km = The Moon Orbital Distance
ED= 406000 km = Apogee radius (The most far point of the moon to the Earth)
(Note Please AB= BC= 86000 km….. and BR=CR also AD=BD=43000km)
I-Data
(EB)2
+ (86000 km)2
= (EC)2
(error 1%)
(EC)2
+ (86000 km)2
= (EG)2
(error 0.5%)
(EG)2
+ (86000 km)2
= (S)2
(where S= 394000 km- unknown point)
(S)2
+ (86000 km)2
= (ED)2
(error 0.7%)
II-Discussion
The points are created based on each other by Pythagoras rule, so let's ask
Is this way by which the moon moves?
i.e.
does the moon depend on Pythagoras rule to define each next point the moon will
move to? Still we don't know by which angle? We know the distance only!!
Means, if the moon in perigee point (363000 km) and the moon uses Pythagoras to
define its next point in motion, so the moon will move to the total solar eclipse radius
(378000 km), based on that, the moon will start from perigee (363000 km) to total
solar eclipse (378000 km) but by what angle? Because we don't know in what
direction the moon will move…
From this triangle, we have learnt one basic information which is, the moon orbital
motions through its basic 4 points depends on Pythagoras rule and which this rule is
used by the moon with more extension in its motion trajectory…
Data Interesting Data
AC = 120536 km = Saturn Diameter (Error 1%)
EC = 378000 km = Saturn Circumference (Error 1%)
AE= 449378.3 km = Jupiter Circumference

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Triangle Angles
E Angle = 13.33 degrees C= 121.7 degrees A Angle =45 degrees
(ABC is an Equilateral triangle)
ECB Angle = 76.66 degrees BCA Angle = 45 degrees
BDC Angle =63.4 degrees ADC = 116.6 degrees
DCB Angle = 26.6 degrees GCB = 13.7 degrees

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1-3 Another Force Effect On The Moon Motion Trajectory
- In The Figure
- The blue ball is the moon, and we see the Earth on one side, and on the other side
we see the Effect point of The Second Force,
- This second force must be = Earth Gravity Force, so Earth force causes the moon
to move 88000 km and the second force causes the moon to move also 88000 km
- The Effect Point is found on a distance = 43000 km from apogee radius (r=0.406
mkm) and that means, this Effect Point at a distance 449197 km from The Earth
- The effect point I have discovered in the moon orbital triangle because this point
was an essential point to create this triangle, i.e. there's a geometrical necessity in
the moon orbital triangle to use this point, based on which the triangle is built
- As we see in the triangle, Point (A) is found based on a geometrical necessity and
based on this triangle (AEC) the moon motion 4 points (perigee- apogee – total
solar eclipse – orbital distance), these distances are defined based on each other by
using Pythagoras rule, tells that (Point A) which is (The Effect Point), is a force
effect point, while it's so far from apogee point (43000 km) proving that some
other force must effect on this Point (A)

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The Moon Motion Trajectory
Let's remember the moon motion trajectory in following…..
- Earth moves daily a distance =2.58 mkm with 0.985 degrees on the horizontal line,
revolving around the sun…. the moon has to move by this same motion manner to
save its accompanying with Earth motion, i.e. the moon moves 2.58 mkm daily
- If there's no contraction effect on the moon motion distance, the moon motion
trajectory would be seen as a parallel line to Earth motion trajectory …. But
- A contraction with rate (1.0725) effected on the moon motion distance and
decreased it to be (2.41 mkm), which necessitates the moon to move an additional
distance =0.17 mkm to cover the difference causes by the contraction effect.
- The moon moves under Earth gravity force a distance =88000 km and still needs
to move an additional distance (88000 km) (2.41 mkm +88000 km +88000 km
=2.58 mkm)
- Point (A), in the moon orbital triangle shows an effect of force our of the moon
orbit, means, this effect must be done by another force and not by Earth force
- Because the 4 inner planets masses = Earth mass (error1%), I suppose that, these 4
inner planets masses total practices a force on the moon motion trajectory = Earth
gravity force and because of that, this another force causes the moon to move this
additional distance (88000 km)
- Because the 3 inner planets (Mercury, Venus and Mars) are so far from the moon
motion, the masses gravity force can't help to perform this task, so I concluded
that, there's an electric field consisted by the 5 inner planets where Earth alone is
one pole and the four inner planets together consisted the other pole of this field,
because of that, the 4 inner planets became able to practices a force on the moon
motion trajectory equal Earth mass gravity
- So there are 2 motions found for the moon in addition to its basic motion which
supposed to be a similar to Earth motion, these 2 motions are the moon motion
under Earth gravity and the moon motion under the other force… how to define
the directions?! The moon motion under Earth gravity force causes the moon to
be closer to Earth but the moon motion under the other force push the moon to
complete it's original motion trajectory… as shown in the figure
- As in the figure, the moon contracted distance reached only to the Point C, so on
this point 2 forces effect on the moon motion, one force is Earth gravity attracts the

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moon to it (the black arrow) and the other force pushes the moon on its original
trajectory (the blue dotted arrow)
- Because the moon motion contracted distance (2.41 mkm) is a displacement on
the Earth orbital circumference (as Earth motion), so this motion is not seen by us
because it's a displacement on the Earth Orbital Circumference, and because the
other force pushes the moon to move along its motion original trajectory with an
additional distance (88000 km) so this distance also isn't seen by us, where we see
only the moon displacement (88000 km) which is done by Earth gravity force.
- The previous explanation is almost a trustee one, because the contraction effect is
proved strongly by different distances in the solar system… the basic weaken point
is the distances… because the 3 planets are so far from the moon and spite the
masses are equal the effect can't be equal because of the high distances… this is
the weaken point for which I have to suggest that the inner planets motions has an
electric field based on their charges to enable the 3 planets to practice a force on
the moon motion (equal to Earth Gravity Force)
- Because I don't want to build a hypothesis on another hypothesis… I want in this
paper to prove that, there's another force effect on the moon motion trajectory…
this force must be equal to Earth gravity force…and the explanation how this force
is created by the 4 inner planets masses we will left to another paper
- So, what we need here, is to prove that, the other force is a fact and effect on the
moon motion trajectory on Point (A)as defined in the moon orbital triangle and to
discover this force different properties…
- The previous explanation gives us 2 proves for this force which are
o The Additional Distance (88000 km) which is required if the contraction
claim is correct. (the contraction claim I have proved by very strong proves
in my previous paper)
o Point (A) in the moon orbital triangle where the moon orbital triangle is
analyzed deeply and I have proved that, this triangle is the method based on
which the moon defines its basic motion points (i.e. the moon motion
triangle has a geometrical necessity to be built as a part of the moon motion
analysis).
But
- The hypothesis tells that, the moon moves a similar motion to Earth's one before
the contraction…! Is there any proof for this point?
i.e.
- Can the moon motion be proved as a similar to Earth motion? because for example
Earth moves per day 0.985 degrees but the moon moves 13.18 degrees, where is
this similarity in motion? and how to prove it..

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Earth and Moon Motions Similarity
I-Data
(1)
360 degrees = 29.53 days x 12.196 degrees (12.19 =13.18 deg - 0.985deg)
(2)
During 29.53 days Earth moves =29.2 degrees
Moon motion = 29.2 degrees +360 degrees
(3)
12.195 degrees = 2 x 6.1 degrees
II-Discussion
Equation No. (1)
- Equation No. (1) proves that, the moon and Earth motions are in perfect harmony
- Equation No. (1) supposes that, the moon moves a very similar motion to Earth
motion, because of that the moon moves 2.58 mkm daily with an angle 0.985 deg.
on the horizontal line (as earth does perfectly), but
- The moon daily motion =13.18 degrees, so Equation no. (1) supposes that, this
value is a total of 0.985 degrees and 12.19 degrees (which is done as a result to
Earth attraction for the moon to move 88000km) –
- i.e. 0.985 degrees is the original angle but 12.19 degrees is found by Earth gravity,
- Equation No (1) tells that, the moon during 29.53 days revolve around Earth a
complete revolution (360 degrees), that means, this value 13.18 was really a total
of 0.985 deg +12.19 deg which proves that the value 0.985 degrees is an essential
angle in the moon motion trajectory
- The angle (0.985 degrees) is the moon motion angle and the equation proves
Equation No. (2)
During 29.53 days Earth moves =29.2 degrees
Moon motion = 29.2 degrees +360 degrees
- Now the moon angle (0.985 degrees) is changed by Earth Attraction for the moon
and the total new angle is (13.18 degrees)…
- But when the moon angle was 0.985 degrees, there was a complete harmony
between the moon and Earth, and what will happen now? One degree of Earth
motion is almost equivalent to one degree of the moon motion (during its synodic
month 29.53 days)…
- i.e. This harmony can be seen only in (29.53 days) because it's the moon motion
unit (As we have discussed before the different rates of time between the Earth and
moon)

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- Equation No (2) shows the Earth and Moon Motions harmony after the contraction
and Earth gravity effect on the moon motion…
Equation No. (3)
12.195 degrees = 2 x 6.1 degrees (6.1 degrees = 5.1 degrees +1)
- We still analyze the value 12.195 degrees (= 13.18 - 0.985)
- Equation no. (3) tells that, this value 12.195 degrees is produced by effect of 2
forces and not 1 force because it = 2 x 6.1 degrees
- 6.1 degrees = 5.1 degrees (the moon orbital inclination) + 1 degree
- What's this 1 degree?
- Mercury ancient axial tilt was 1 degrees (before Mars Migration) and this axial tilt
is changed to be 0.01 degrees after Mars Migration, but this value still effect on the
solar system geometry even after its change
- For example, the moon orbital diameter = 1 million km, and
- We know that 1 mkm =1 degree, because Mercury orbital circumference =360
mkm =360 degrees…
- Also Jupiter diameter is created based on this 1 deg. where Jupiter diameter =
142984 km = (1000000 km/7), (Mercury orbital inclination =7 degrees)
- And Jupiter orbital circumference = Mercury diameter x 1 mkm (=1 degree)
- Equation No (3) tells that, 2 equal forces effect on the moon motion trajectory to
produce this 13.18 degrees daily (13.18 = 0.985 deg+ 2 x 6.1deg) and this explains
the moon motion trajectory history, and prove the description I explain it..
- Let's discuss more proves in the next point……
-

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The Other Force Effect Proves
I-Data
(a)
3.02 mkm = 88000 km x 2 x 17.2
(b)
2.082 mkm = 88000 km x 23.45
(c)
0.59 mkm = 88000 km x 6.7
(d)
(88000 km / 3475 km) = (13.18 deg/0.526 deg) =25.2
(e)
13.4 (13.18/0.985)
Equation (a)
3.02 mkm = 88000 km x 2 x 17.2
- 3.02 mkm = Venus motion distance daily, 88000 km = the moon motion daily
- 17.2 deg = Pluto orbital inclination = 0.99 x 17.4 degrees (17.4 deg = the inner
planets orbital inclinations total)
- Equation No. (a) shows both distances 88000 mkm x 2 which the moon has to
move to cover the difference (0.17mkm) found by the contraction
- Why 17.2 deg is used here? the equation uses basically 17.4 degrees because the
moon motion (88000 km) is done by the 3inner planets and the other (88000km) is
done by Earth gravity force … means both distance (88000 km x 2) is a motion
done by all inner planets and their orbital inclination total is found here to prove
this fact…why the equation uses (17.4 x 0.99)? it's hard question because always
we have found 2 rates (1 or 0.99) for each different values, and for geometrical
necessities planets use any of both (1 or 0.99)…
- Equation No. (a) tells that, the moon motion (88000 km x 2) is a motion done by a
general cooperation between the 5 inner planets
Equation (b)
2.082 mkm (Mars velocity daily) = 88000 km (moon motion daily) x 23.45
- This equation we have seen before
- Equation no. (b) shows the 3 inner planets effect on the moon motion pushing it to
move the additional distance (88000 km)
- Mars is the representative of the 3 planets, and this idea we have seen before
because (mars mass/ the moon mass) = 8.8 = (88000 km /10000), but we know that
(light velocity /earth velocity)= 10000 = 365.25 x 27.3

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Equation (c)
0.59 mkm = 88000 km x 6.7
- 0.59 mkm = Uranus velocity daily but 6.7 degrees = The Moon Axial Tilt
- Equation no. (c) tells that, the moon additional motion (88000 km) is defined by
Uranus motion relative to the moon axial tilt…
- But why based on 6.7 degrees? Because
- Uranus axial tilt is perpendicular on the moon axial tilt (97.8 deg -6.7 deg) = 91.1
deg, and because of that, Uranus axial tilt effect on the moon axial tilt and its
motion deeply…
- Note please, Uranus doesn't cause the moon additional motion (88000 km), the
moon is pushed by the 3 inner planets through Mars as representative, But Uranus
defines the tasks and directions…
- i.e. Uranus defines the moon axial tilt to be =6.7 degrees
(Note please "Uranus diameter = 6.7 x the moon diameter")
Equation (d)
(88000 km / 3475 km) = (13.18 deg/0.526 deg) =25.2
3475 km = the moon diameter,
13.18 degrees = the moon motion degrees daily
0.526 degrees = Mars motion degrees daily
25.2 degrees = Mars Axial Tilt
- Equation no (d) shows the deep interaction between Mars and the moon motions
which extends into the moon diameter definition, where (Mars Mass/ Mercury
Mass) = (Mars diameter / the moon diameter)
Equation (e) 13.4 (13.18/0.985)
13.4 = (365.25 days /27.3 days) (Earth diameter/ the moon diameter)2
- Equation No. (e) tells that, the rate between the moon new motion daily degrees
(13.18 deg) and the moon old motion daily degrees (0.985 deg) causes to define
the Earth and moon diameters, and also , most important, their orbital periods
relative to each other, why??
- To create a new harmony in their motions depends on the old harmony in their
motions, and by that, the contraction effect can't cause any negative effect on the
moon and Earth motions harmony… i.e. the cases before is equivalent to the case
after and by that the motions stability can be guaranteed.

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References
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
session
https://www.academia.edu/s/69edd1d0ea
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Matter Origin and Creation
https://www.academia.edu/43214351/Matter_Origin_and_Creation
Is Saturn The Last Planet Created In The Solar System? (II)
https://www.academia.edu/43197587/Is_Saturn_The_Last_Planet_Created_In_The_Solar_System_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Moon Motion Trajectory Analysis (II)

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