Earth Motion (Part III)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Earth Motion (Part III)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 7th
December 2020
Abstract
Paper hypothesis
- Planet diameter (or circumference) is created as a function in another planet
diameter and velocity
The hypothesis explanation
- By this technique the produced planet diameter will be in harmony with the
parent one, and accordingly, will be in harmony with all other planets
diameters, circumferences and motions
- This harmony is a necessary to guarantee the planets motions general harmony..
- Planet diameter creation depending on another planet diameter and velocity, is
done by A Motion Transportation Process, and by that planet diameter is
created in harmony with its velocity and day period
Based on this concept we can explain the following data
- Jupiter moves during its day period a distance = its circumference (+4%)
- Saturn moves during its day period a distance = its circumference (-1.2%)
- Neptune moves during its day period a distance = its circumference x 2
- This specific data is produced as results for the motion transportation process
Paper Contents
1- Planet Motion Transportation Concept
2- Why do Planets Motions Harmony Depend On Planets Diameters?

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1- Planet Motion Transportation Concept
1-1 Preface
1-2 Jupiter Motion Transportation
1-3 Saturn Motion Transportation
1-4 Neptune Motion Transportation
1-5 Earth Motion Transportation
1-1 Preface
- "Planet Motion Transportation Concept"…. We have searched from long time
for the method by which the solar plants motions are created in so harmony with
each other…
- I have suggested frequently that, the solar system is almost similar to a machine of
gears, each planet must be a gear in it – and accordingly – the planets motions
must be transported from to another – but the planets are not gears! Mechanically
we have no method proves this fact – although Planets data shows it clearly….
- Planet Motion Transportation Concept explains the method by which the motion is
transported from planet to another and shows the general harmony of planets
motions as a result this motion transportation…
- We have only 4 examples to be used as application for the motion transportation
concept…
- One rule we need to know before to start our discussion, let's write it in following:
- Planet Motion Is Transported By A Percentage 80% From The Sender Planet
To The Receiver Planet
- Now let's start our examples discussion …

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1-2 Jupiter Motion Transportation
I-Data
(1)
13.1 km/s (Jupiter velocity) x 10921 seconds = 142984 km = Jupiter diameter
(2)
(8 x 13.1 km/s x 9.9 h x 3600) – (8 x 449197 km "Jupiter circumference") = 142984
km (Jupiter diameter)
(3)
9.9 h x 3600 x 8 x 0.3 mkm /sec = 86400 mkm
(4)
4.7 km/s (Pluto velocity) x 7511 = 35302 km but (9.9 hours x 3600 = 35302 sec)
(error 1%)
II-Discussion
- The motion transportation process is noticed basically because of Jupiter data and
behavior, for that reason we need to move with the previous data step by step to
see how Jupiter performs planet motion transportation process from Jupiter to
Saturn. Let's start our discussion
Equation No. (1)
13.1 km/s (Jupiter velocity) x 10921 seconds = 142984 km = Jupiter diameter
- Equation no. (1) tells that, Jupiter moves during a period 10921 seconds a
distance = 14294 km = Jupiter Diameter
- We know that, 10921 km = The Earth Moon Circumference
- Equation no. (1) tells that, Jupiter diameter (or a distance equal it) is defined by
Jupiter motion….

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Equation No. (2)
(8 x 13.1 km/s x 9.9 h x 3600) – (8 x 449197 km "Jupiter circumference") =
142984 km (Jupiter diameter)
- Equation no. (2) is the equation tells us about the Motion transportation concept,
let's study it as possible
- The left side (8 x 13.1 km/s x 9.9 h x 3600) shows Jupiter motion distance during
8 days of Jupiter days period,
- Equation no. (2), left side, tells us that, Jupiter during (8) of its days periods moves
a distance = 3735072 km
- The right side shows (8 Jupiter circumferences = 449197.4 km x 8= 3593580)
- The difference between both = 142984 km = Jupiter diameter (error 1%)
- What does that mean?
- Equation no. (2) tells us that, Jupiter moves during its day period a distance =
Jupiter circumference, but not accurately, instead there's an additional distance
with rate (4%) is found ….
i.e.
- Jupiter during its day period moves a distance = its circumference + 4%
- This (4%) during (8 days periods) will be = Jupiter diameter
So
- Equation no. (2) tells that, Jupiter moves during 8 days of its days periods a
distance = 8 Jupiter circumferences + Jupiter diameter
- Because of Jupiter diameter ( a defined value) in Equation no. (2), we could
conclude that (8 days of Jupiter motion create a cycle for it)
- So, Equation No. (2) tells us that, there's some a cycle for Jupiter motion relating
to Jupiter motion during (8 days of Jupiter day period), this cycle is found because
Jupiter motion is transported to Saturn based on this value (8 days), where Jupiter
moves during 8 days of (Jupiter day period) a distance = Saturn motion distance
during 10 days of Saturn day period.

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- So, this cycle (8 days) is created because Jupiter Motion is transported to Saturn
motion based on this period of time… in Saturn motion discussion we should
discuss this point with more details …
Equation No. (3)
9.9 h x 3600 x 8 x 0.3 mkm /sec = 86400 mkm
- Equation no. 3 tries to know why Jupiter motion has a cycle in this period (8 days
of Jupiter days periods!) let's discuss this equation in following….
- 9.9 hours = Jupiter day period
- During 8 days period = 9.9 x 3600 x 8 = 285120 seconds
- Light known velocity (0.3 mkm/sec) travels during 285120 seconds a distance =
86400 mkm
- We know that, Jupiter energy is sent to Pluto and Pluto reflected it to Neptune
without any consumption, then Neptune consume from it 14% and reflected the
rest of energy toward the inner planets in 2 trajectory of energy have equal energy
each trajectory has 86400 mkm
- That means, the value 86400 mkm is basically related to Jupiter energy and is
considered one of the basic 2 parts of energy both equal each other…
- Light motion during (8 days of Jupiter days periods) shows a real cycle, that
explains why Jupiter has a cycle for (8 days of its days periods) –
- Let's remember the motion transportation concept summary
o Light motion causes one planet to move (Jupiter)
o And this planet transports its motion to the other planets, because of that, we
have a point of source which is considered as a point of energy which will
be distributed
o Energy is distributed by planet motion transportation from this planet to the
others.

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Equation No. (4)
4.7 km/s (Pluto velocity) x 7511 = 35302 km but (9.9 hours x 3600 = 35302 sec)
(error 1%)
- Equation no. (4) tells that, Pluto moves during (7511 seconds) a distance = 35302
km, where we know that, Pluto circumference =7511 km
- Now
- The produced distance 35302 km is used as a period of time 35302 seconds it will
be = Jupiter day period
- Why?
- There's 2 basic points with Pluto which we should consider here
o (1st
) Jupiter total energy is sent to Pluto basically and that created a very
specific relationship between Pluto and Jupiter
o (2nd
) Pluto is a planet used for different jobs! Why? let's use the Earth moon
as an example in place of Pluto here – and Pluto discussion we will do in
point no. 2 of this paper
- 13.1 km/sec x 10921 seconds = 142984 km, during 10921 seconds Jupiter moves
a distance = 142984 km = Jupiter Diameter,
- how to understand this equation? Which is found before, Jupiter or the moon?!
Jupiter, So how the equation produces Jupiter diameter based on the moon – it's
not true …. The moon circumference (10921 km) is created as a function in
Jupiter diameter, this equation tells us, Jupiter creates the moon circumference,
but how?
- By Jupiter…
- Jupiter diameter (142984 km) is defined before and Jupiter now moves a distance
= its diameter to create the Earth moon circumference depending on its diameter,
Why? we should answer in point no. (2) (Why do Planets Motions harmony
depend on planets diameters and circumferences?)

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1-3 Saturn Motion Transportation
Please Note
"8 Days Of Jupiter Motion = 10 Days Of Saturn Motion"
I-Data
(A)
Saturn moves during its day period (10.7 h) a distance = its circumference (1.2%)
(B)
5031 km (the error 1.2% Value) x 10 = 51118 km (Uranus diameter)
(C)
9.9 h x 3600 seconds x 13.1 km/s (Jupiter velocity) x8 = 10.7 h x 3600 seconds x 9.7
km/s (Saturn velocity) x10
(D)
10921 seconds x 13.1 km /sec (Jupiter velocity) = 142984 km (Jupiter Diameter)
7511 seconds x 6.8 km /sec (Uranus velocity) = 51118 km (Uranus Diameter)
12104 sec x 29.8 km/s (Earth velocity) =3 Saturn diameters =9 Earth Circumferences
(Earth radius x 19 = Saturn diameter)
49528 seconds x 9.7 km/s (Saturn velocity) = 4 Saturn diameters
9000 seconds x 5.4 km/s (Neptune velocity) = Neptune Diameter
(E)
4.7 km /sec (Pluto Velocity) x 10921 seconds = 51118 km (Uranus Diameter)
4.7 km /sec (Pluto Velocity) x 51118 seconds = 2 x 120536 km (Saturn Diameter)
4.7 km /sec (Pluto Velocity) x (2 x 120536 km (Saturn Diameter)) = 1.1318 mkm
(Jupiter moves during a solar day period a distance = 1.1318 mkm).
(F)
10747 x 30589 = 86400 x 354.39 x 10.7
(G)
9.7 x 10.7 x 3600 = 6.8 x 153.3 x 354.39

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II-Discussion
- The previous data tries to prove the motion transportation process from Jupiter to
Saturn….
- The transportation process is done based on 8 days of Jupiter motion which are
equal 10 days of Saturn motion, the data is rich and helpful, so we need to consider
them as deep as possible – the (8 days) of Jupiter created a cycle in Jupiter data as
we have discussed – but here these 8 days are equal 10 days of Saturn motion- so
the cycle which was created based on (8 days of Jupiter motion) will be created
here based on (10 days of Saturn motion) – let's see in following…
- Saturn moves during its day period (10.7 hours) a distance = Saturn circumference
but not perfectly…! Saturn moves during its day period a distance = 373644 km
but Saturn Circumference = 378675 km the difference = 5031 km ….
Equation No. (B)
5031 km (the error 1.2% Value) x 10 = 51118 km (Uranus diameter)
- We may remember, Jupiter moves during its day period a distance = 466884 km,
but Jupiter circumference = 449197 km the difference = 17686 km
- During 8 days periods of Jupiter days, Jupiter moves a distance = 8 Jupiter
circumferences + 142984 km (=Jupiter diameter)
- Because of Jupiter diameter in the data, we realized that, the period (8 days)
creates a cycle for Jupiter as we have discussed …. But these 8 days (of Jupiter
motion) is transported to Saturn as (10 days of motion), and during 10 days of
Motion, Saturn moves a distance = 10 Saturn Circumferences – Uranus diameter
- Because of Uranus diameter value in the previous data we have realize that these
10 days creates a cycle for Saturn motion… Now this energy which = (8 days of
Jupiter motion) and = (10 days of Saturn motion) is transported from Jupiter to
Saturn to create cycles for both of them why?? because the transportation is done
based on a quantum value – It's a quantum of energy transported from planet to
another and based on this energy the planets create their cycles…

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- Notice no. (1)
- Saturn moves during its day period a distance = 373644 km, Saturn Circumference
= 378675 km …. The difference between both 5031 km
- When a planet rotates round its axis 360 degrees, this planet moves during this
rotation a distance = its circumference… in Saturn case the distance doesn't equal
its circumference but less with 1.2%, so that means, the rotation isn't 360 degrees
but 355.2 degrees
- So, the distance which Saturn moves during its day period equal 355.2 degrees of
Saturn full rotation around its axis …. Why we need this notice?!
- Because of the number 355.2 degrees…. We will need it in our discussion… also
Please remember that, Saturn during 10 days of its motion needs a distance =
Uranus Diameter to make its motion total distance = 10 Saturn Circumferences.
Notice no. (2)
- Please remember our question in mind! (What's the relationship between the
transported motion or energy between planets and the planet diameter or
circumference?) we need to keep this question by heart because it's a cornerstone
in the discussion while we move step by step….
Equation No. (C)
9.9 h x 3600 seconds x 13.1 km/s (Jupiter velocity) x8 = 10.7 h x 3600 seconds x
9.7 km/s (Saturn velocity) x10
- This equation tells the story which we try with clearly…. The motion (energy) is
transported from Jupiter to Saturn by rate 80% but based on (8 days of Jupiter
motion) because it's the energy quantum and this (8 days motion distance) will be
seen as 10 days of Saturn motion as we have discussed
- Our discussion causes many useful result, we know now that, the energy is
transported from Jupiter to Saturn and not vice versa, also we know that, the
motion (energy) transportation is done depends on planet day period.., that shows
more geometrical features were hidden before…

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Equation No. (D)
10921 seconds x 13.1 km /sec (Jupiter velocity) = 142984 km (Jupiter Diameter)
7511 seconds x 6.8 km /sec (Uranus velocity) = 51118 km (Uranus Diameter)
12104 sec x 29.8 km/s (Earth velocity) =3 Saturn diameters =9 Earth Circumferences
(Earth radius x 19 = Saturn diameter)
- The previous equations try to put the data together beside each other, to help our
discussion proving process, avoiding the claim that, the data is crated by pure
coincidences… because many data are created based on the same meaning that
tells us we deal with a geometrical rule and not any random process – that shows
our discussion is built on a rock
- The previous data is so important and interesting because it's data created by some
directed process…for example 10921 seconds x 13.1 km /sec (Jupiter velocity) =
142984 km (Jupiter Diameter) this equation tells us that, Jupiter during 10921
seconds moves a distance = its diameter…. this equation is specific because the
planet uses its own velocity (own motion) to move a distance = its own diameter..
(we know that 10921 km = the moon circumference)…
- Let's use one more example 12756 seconds x 35 km /s (Venus velocity) = 449197
km (Jupiter Circumference),.. This equation produces also Jupiter circumference
but this equation is different from the previous one because in this one Venus
moves during 12756 seconds a distance = Jupiter circumference, here this result is
done by interaction between planets motions…. The first one is done by the same
planet (Its Velocity &Diameter) and by it’s The Motion Energy Transportation
this motion transportation can't be discovered when different hands are seen in the
transportation process – and because of that – Venus Equation can't tell us about
the motion transportation because we don't know the source point in this equation
– that's why the data of (Equation No. D) is so specific data.

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Equation No. (E)
- This equation group is so useful data
- I try to show that, the transportation process is done by some continuous process,
let's consider this data as deep as possible
- Pluto moves during 10921 seconds a distance = 51118 km = Uranus Diameter, in
this data, Pluto uses the Earth moon circumference (10921 km) as a period of time
and moves a distance = (51118 km) = Uranus diameter …… then
- Pluto moves during 51118 sec. a distance = 2 x120536 km = 2 Saturn Diameters,
here, Pluto uses Uranus diameter (51118 km) as a period of time and moves during
this period a distance = 2 x 120536 km =2 Saturn Diameters, …… then
- Pluto moves during 2 x 120536 seconds a distance = 1.1318 mkm = Jupiter
motion during a solar day…
- There's a geometrical reason for this data, Pluto gives us a treasure by this
behavior, because we see clearly how planets data are created depending on each
other, the geometrical mechanism to do this process uses planet motion (velocity)
to perform it, that provides the motor for the required design, because we knew
from long time that, planets diameters are created rates to each other but how?
And why? Planet velocity (motion) is used in this process during The Motion
Transportation Process…. So there are 2 basic question here, (1st
Question) Is
Motion Transportation process between the planets a real phenomenon? And we
try to answer this question in this point and (2nd
Question) Why planet diameter or
circumference is an effective player in planet motion?! we need to discuss this
question later…

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Equation No. (F)
10747 days (Saturn Orbital Period) x 30589 ( Uranus Orbital Period)= 86400 x
354.39 x 10.7
Equation No. (G)
9.7 km /s (Saturn velocity) x 10.7 (Saturn day period =10.7 hours) x 3600 = 6.8
km /s ( Uranus velocity) x 153.3 Seconds x 354.39
- The equations (F and G) are so complex equations, from them I need to refer to 2
facts (1st
Fact) the value 354.39 which is used in both equation…!
- We remember that, Saturn moves during its day period a distance = 373644 km an
Saturn circumference = 378675 km and the difference is 5031 km, and we
consider that, Saturn during its full rotation 360 degrees moves 378675 km, but if
moves only 373644 km so it's = 355.2 degrees (=354.39 deg) approximately…
- So this value (354.39 degrees) is found in both equation because of Saturn motion
during its day period, this motion is defined clearly in Equation no. (G) left side
- (2nd
Fact) we remember that, the difference 5031 km during (10 days of Saturn
motion) produces a distance =50310 km (= Uranus Diameter, error 1.6%),
- In both equations, Saturn has an interaction with Uranus, that means, Uranus
diameter is not created by Saturn (10 days) which is a cycle for Saturn motion by
chance but by an interaction between Saturn and Uranus motions, that may
explain why Uranus orbital distance = 2 Saturn orbital distance, because there's a
deep interaction between Uranus and Saturn motions
- That also explains, Why Saturn doesn't transport its motion to Uranus but to
Neptune! Because the deep interaction between Uranus and Saturn hides the
transportation process of motion… the interaction between both is more strong
than the transportation process!
- (Please remember Mercury day period needs 5040 seconds to be 176 solar days,
where 5040 seconds are very near to 5031 km… and we know that, Mercury
moves during 5040 seconds a distance = 2 Saturn diameters "error 1%")

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1-4 Neptune Motion Transportation
Please Note
"8 Days Of Saturn Motion = 10 Days Of Neptune Motion"
I-Data
(a)
Neptune moves during its day period (16.1 h) a distance = its circumference x 2
(b)
9.7 km/s (Saturn Velocity) x 10.7 x 3600 x 8 = 5.4 km/s (Neptune Velocity) x 16.1 x
3600 x 10 (where 10.7 h = Saturn day period and 16.1 h = Neptune day period)
(error 4.5 %)
(c)
2 Jupiter Circumferences – 2 Saturn circumferences = 1 Jupiter diameter
(d)
Saturn diameter 120536 km – 71492 km (Jupiter Radius) = 49528 km (Neptune
diameter) (1%).
(e)
(Please remember)
(49528 km = Neptune Diameter)
12104s x 29.8 km/sec (Earth velocity) = 3 Saturn Diameters = 4 Earth Circumference
(f)
7511 seconds x 5.4 km/s (Neptune velocity) = 40080 km (Earth Circumference) (1%)
(g)
Uranus orbital distance = 2 Saturn orbital distance
Neptune orbital distance = π Saturn orbital distance

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II-Discussion
- We repeat what we did with Saturn, here once again with Neptune,
- The data shows that, there's a deep relationship between Saturn and Neptune
motions, this relationship is seen in the planets diameters and orbital distances as
well, proving that, There's a motion (energy) transportation process is done here
from Saturn to Neptune….
- The great error of equation (4.5%) needs more explanation, where we have found
4% error in Jupiter equation but it was not error but a different used for Jupiter
motion cycle… here also this difference (4.5%) we should discuss later
- Equations no. (c ) and (d) show that, Neptune diameter is created based on Saturn
diameter, which is very similar to Saturn diameter production from Jupiter
diameter, we deal here with almost a series of similar actions between 2 planets
behaviors…
Equation No. (e)
- We know the first one, it tells us, Saturn during (49528 seconds) moves a distance
= 4 Saturn diameters, where (49528 km = Neptune Diameter)
- By this same method, Neptune diameter is created in the second equation
- During (9000 seconds) Neptune moves a distance = its diameter (49528 km)
- But
- What's this (9000 seconds) or (9000 km)??
- The lunar umbra breadth =9000 km
- Why it's used here for Neptune diameter? because it's related to Earth Diameter
- That shows some interaction is found between earth diameter and Neptune
diameter, this interaction is found through Saturn diameter …. Let's remember the
following equation….

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12104s x 29.8 km/sec (Earth velocity) = 3 Saturn Diameters= 4 Earth Circumferences
- As we see in this equation (3 Saturn diameters = 4 Earth Circumferences) for
that reason Earth & Neptune diameters are related through Saturn Diameter.
Equation No. (f)
7511 seconds x 5.4 km/s (Neptune velocity) = 40080 km (Earth Circumference) (1%)
- Neptune moves during (7511 seconds) a distance = Earth Circumference where we
know 7511 km = Pluto Circumference… that shows clearly a deep interaction
between Earth and Neptune…

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1-5 Earth Motion Transportation
I-Data
12104 seconds x 29.8 km /sec (earth velocity) = 360700 km = (3 Saturn diameters) =
(4 Earth Circumferences)
Where
12104 km = Venus Diameter
363000 km = Earth Moon Distance at perigee radius (error 0.6%)
- The previous equation shows that, Earth during a period =12104 seconds moves a
distance = 360700 km = 3 Saturn diameters = 4 Earth Circumferences
- The equation doesn't shows a transportation of motion, but shows clearly how
Earth Circumference is created depends on earth velocity –
- Still we need to discuss the reason as deep as possible, why planet diameter or
circumference is created based on this same planet motion or velocity? Or in more
clear words
- Why planet diameter is a player in planet motion definition? This question
which we need to discuss as deep as possible in the following point…

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2- Why do Planets Motions harmony depend on planets diameters and
circumferences?
I-Data
(E) (Revision)
II-Discussion
- This data we have discussed with Saturn discussion in (Point 1-3)
- We use this data here as an example to explain the idea, let's summarize it as clear
as possible in following…
o Planet diameter (or circumference) is created as a function in another planet
diameter and velocity
o By this technique the produced planet diameter will be in harmony with the
parent one, and accordingly, will be in harmony with all other planets
diameters, circumferences and motions
o This harmony is a necessary to guarantee the planets motions general
harmony..
o Planet diameter creation depending on another planet diameter and velocity,
is done by A Motion Transportation Process, and by that planet
diameter is created in harmony with its velocity and day period
o Based on this concept we can explain the following data
o Jupiter moves during its day period a distance = its circumference (+4%)
o Saturn moves during its day period a distance = its circumference (-1.2%)
o Neptune moves during its day period a distance = its circumference x 2
- This specific data is produced as results for the motion transportation process
But

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- Why Planet Diameter (Or Circumference) Is A Player In Planets Motions
General Harmony?
- As we have discussed in different examples,
- Planets diameters and circumferences are used as periods of time for different
planets motions, because of that, planets diameters and circumferences are players
in the motions harmony…
- Let's try to explain this idea as clear as possible
o 13.1 km/sec x 10921 seconds =142984 km (Jupiter diameter)
o Jupiter moves during 10921 seconds a distance = Jupiter diameter, and we
know that, Jupiter diameter is found before the Earth moon circumference
(10921 km)
o Means, the values 142984 km and 13.1 km/sec, are input and 10921
seconds is output….
o Why?
o Because Jupiter wants to create a moon circumference (10921 km) be in
harmony with Jupiter motion – and – Jupiter motion is in harmony with
Saturn, Uranus, Neptune, Pluto, Earth…..etc
o What does that mean?
o One tree will produce some a fruit, this fruit will be suitable for the tree
trunk, branches and leaves….etc
o The produced planet is created to support the other planets motions harmony
and not to disturb this harmony…. The new planet will add to the group
some benefits and not causes motions disturbances…
o It's the system by which a new planet is born, otherwise the solar system
will be destroyed with each new planet came to cause disturbances for the
solar planets motions harmony
o The question was… what's the matter? The answer is a period of time used
for some motion … The harmony between these motions save this matter
existence…

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o So by this method the planet is created
o We may look now at Pluto data…. By this method the created planet which
is Pluto in this time (7511 km or 7511 seconds) became so useful for
different motion and because of this high flexibility Pluto could create
different motions harmony features and to perform some series of motions
as the data shows….
o Why this series is useful, because the produced data (which is real data) is
created in harmony with each other,
o Planet motion Transportation process produces one unified motion in full
harmony –
o Because of that, the solar system can b considered as one trajectory of
energy and each planet is a point on this same trajectory

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3- The Moon Orbital Triangle Data
3-1 Preface
The Moon Orbital Motion (Revision)
- Why does the moon use Pythagoras Rule in its motion? and why do we need the
moon orbital triangle?
o The moon daily displacement =88000 km but the moon doesn’t use it as its
real displacement but instead the moon uses Pythagoras triangle to define
another real displacement
o Based on that
o The moon uses the right triangle dimension (L= 88000 km Cos θ) where
this (L) is the moon real displacement through its orbit daily
o The angle (θ) is the smallest angle in the right triangle, and it effects on the
moon real displacement and its motion height above perigee radius (r=0.363
mkm)
Why?
o The daily displacement = 88000 km and during 29.53 days, the total
distance the moon passes = 2.59 mkm which can be done only through
apogee orbit whose radius (r=0.406 mkm) –
That means –
o If the moon uses only 88000 km as its real displacement daily, the moon
would move only through the apogee orbit (r= 0.406 mkm)
o Because the moon tries to move in more near orbits to the Earth, the moon
uses Pythagoras triangle technique to produce smaller displacements though
its orbit while the moon move this same distance (88000 km) as a real
motion -
o So, this real displacement technique (L= 88000 km Cos θ) gives the moon
the ability to move through lower orbits to the Earth, and the change of the
angle θ changes also its real displacement

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o The smaller real displacement can be used for more near orbits to Earth (as
perigee radius r=0.363mkm) but the longer real displacements need more
wide orbit to be passed through, which forces the moon to move in higher
orbits above perigee.
o That means, the angle θ changes the real displacements and the height of the
moon motion above perigee radius (r= 0.363 mkm).
o Then based on that I have suggested the moon motion equation which is
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
o θ is the smallest angle in Pythagoras triangle used for the moon real
displacement (L= 88000 km Cos θ),
o 0.985 degrees = Earth daily motion degrees.
o With more analysis, a 2nd
force effects on the moon orbital motion is
discovered, this 2nd
force effects on the point (A) in the moon orbital triangle
– where this point is an essential part of the triangle but it's far with 43000
km beyond apogee radius (r= 0.406 mkm).
o This 2nd
force effects on the moon orbital motion is produced by gravity
forces interaction between the sun and Jupiter on Earth and its moon – So
this 2nd
force pulls the moon to apogee radius but Earth gravity tries to keep
the moon at perigee radius. (This 2nd
force effects on the point (A) in the
moon orbital triangle)
Notice
o 149.6 mkm Earth orbital distance = 142984 km (Jupiter diameter) x 1047
(The sun mass/ Jupiter mass), because of this data, we conclude that, Earth
orbital distance is defined by gravity forces interaction between the sun and
Jupiter masses. Which supports the claim that 2nd
force can be produced by
the sun and Jupiter gravities interaction effect on the Earth moon.

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3-2 The Moon Orbital Triangle Details
Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and
the outer circle is apogee orbit – and we have calculated the
tangent DB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras
triangle (1, 2 and 51/2
)
- The triangle (ODB) angles are 26.564 deg. and 63.435 deg.

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(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373900 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- CX= =87521 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km CY= 97766 km
- BA = BC = 86000 km
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km
- BY = = 46475 km
- SZ = 7665 km ZF= 2414 km
- DY = 3475 km BX= 16203 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.3 deg)
- BCY = 28.39 degrees ECZ= 88.9 degrees
- XCE = 66 degrees
- CZS = 77.8 degrees
- CZF =102.195 degrees
- XCB = 10.67deg
- (Uranus Axial Tilt = 97.8 degrees = FSC 97.2 degrees + 0.6 degrees) (i.e. the
angle under FSC)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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3-3 The Moon Diameter Division
Figure No. 2 (my figure) (The Moon Diameter Division)
- Uranus Axial Tilt (97.8 degrees) has an angle (91.1 degrees) with The Moon Axial
Tilt (6.7 degrees), so The blue vertical line is Uranus axial tilt and the angle in the
circles center = 91.1 degrees
- This value 91.1 degrees is decreased by 0.5 degrees which is consumed by the
moon diameter (the circles express the moon diameter with some division), also
0.6 degrees is consumed by the green box (I suppose Saturn & Jupiter motions
interaction effect is done here to create this 0.6 degrees)
- So the angle between the blue vertical line and the horizontal red line 90 degrees
- The red horizontal line is the moon orbital triangle base (AE = 449197 km)
- The blue vertical line angle above the moon directly =90.6 degrees
- But
- In this figure I cut layers from the moon diameter to create smaller moon diameters
to consume smaller angles than (0.5 degrees), and based on that we measure the
angle of The blue vertical line, let's explain this moon diameter division:
- The Blue Circle its diameter R1= 1390 km and r1 =695 km
- The Red Circle its diameter R2= 2085 km and r2 =1042.5 km
- The Black Circle its diameter R3= 2185 km =π x 695 km and r3 =1092.5 km
- The Brown Circle its diameter R4= 3208 km and r4 =1604 km =5040/π

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- The Orange Circle is the moon itself its diameter R5= 3475 km = 5 x 695 km
- The moon consumes 0.5 degrees for its diameter (3475 km) …So
- R1 = 1390 km, the consumed angle will be 0.2 degrees i.e. the angle above The
Blue Circle = 90.9 degrees.
- R2= 2085 km (60% of the moon diameter) and because of that, the consumed angle
will be only 0.3 degrees, means, the angle above The Red Circle =90.8 degrees
- Note Please, 90.8 degrees = 90 degrees + 0.8 degrees (Uranus orbital inclination),
by that the rest degree of Uranus axial tilt = its orbital inclination vertically.
Notice No. 1
- Pluto Axial Tilt 122.5 degrees = 7.1 x 17.2 degrees (Pluto orbital inclination),
- 7.1 a rate created by Lorentz Length Contraction Phenomenon…
- That tells us, the values (122.5 deg and 17.2 deg) are equivalent values, how? It's a
contraction, the energy of (122.5 deg) in contracted by 7.1 and the rest 17.2 deg is
created from this same energy (122.5 deg). they are 2 equivalent values but one of
them passed through a different frame and faced a contraction phenomenon and
because of that its value (122.5 deg) became (17.2 deg)
- This notice is provided here to show that in the solar system there's some way to
create A Planet Axial Tilt = Its Orbital Inclination…. What's the important
result for this equality? We have seen this equality in Uranus & Pluto data, where
we know that (122.5 deg x 0.8 deg = 97.8 deg)– there's some geometrical machine
found behind this equality…

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Notice No. 2
- Are these divided diameters real diameters or invented numbers? Let's test them :
(1)
- 149.6 mkm (Earth Orbital Distance) = 3475 km (the moon diameter) x 43000 km
(the distance from perigee to apogee)
- 149.6 mkm (Earth Orbital Distance) = 2085 km (R2) x 71492 km (Jupiter Radius)
- 149.6 mkm (Earth Orbital Distance) = 1047 x 142984 km (Jupiter diameter) (1047
= The Sun Mass / Jupiter Mass)
(2)
- R4= 3208 km x 466884 km = 149.6 mkm x π2
- 466884 km = Jupiter motion distance during its day period.
(3)
- R3= 2185 km x π x 21346.6 km (Mars Circumference) = 149.6 mkm (2%)
(4)
- R2= 2085 km x 71492 km (Jupiter Radius) =149.6 mkm
(5)
- 4900 mkm = 4222.6 x 1.16 mkm = 10921 km x 449197 km
- 302 mkm = 4222.6 x 71492 km (Jupiter Radius)
- 305 mkm = 88000 km x 3475 km = 25.2 x (3475 km)2
- 177.4 degrees -90 degrees = 87.4 degrees (+0.6 degree = 88 degrees)
- 3475 s x 0.3 mkm/sec =1042.5 mkm but
- 2085 mkm = 3475s x 0.3 mkm/s x2
Discussion
- The points (1-4) show, Earth orbital distance 149.6 mkm, is defined as a function
in the moon diameter, This same feature is used for the smaller diameters, which
proves these diameters are real values
- Point (No.5) shows light motions behind Planet Data – Let's remember 1st
hypothesis (Planet Motion depends On Light Motion), the show some of these
light motions which caused to create the provided data.

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

Earth Motion (Part III)

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Earth Motion (Part III)