Paper Questions: - (1) Does the planet Day Period Depend On Its Circumference?! - (2) Why Jupiter Motion depends on the Earth moon circumference? i.e. o (1st Point) What's Jupiter effect on the Earth moon motion? o (2nd side) has the Earth moon similar effect on other planets? - Saturn moves during its day period a distance = its circumference, and Jupiter does this same job with error (4%) only… because of these 2 planets I have suggested the rule (Planet Day Period is defined by motion distance = Planet circumference) - No other planets follow the rule, so no credibility to be used as a general rule - But - Before to give up, we have to analyze the source point from which this rule is created, which was the Earth moon effect on Jupiter motion! - Where - The moon (10921km) needs to rotate around its axis 13.1 times to move a distance = 142984 km = Jupiter diameter – on the other side – Jupiter velocity =13.1 km/sec, by this velocity Jupiter itself needs to move 10921 seconds to pass a distance=its diameter Gerges Francis Tawdrous +201022532292

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Does Planet Day Period Depend On Its Circumference ? (IV)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 15th
November 2020
Abstract
Paper Questions:
- (1) Does the planet Day Period Depend On Its Circumference?!
- (2) Why Jupiter Motion depends on the Earth moon circumference? i.e.
o (1st
Point) What's Jupiter effect on the Earth moon motion?
o (2nd
side) has the Earth moon similar effect on other planets?
- Saturn moves during its day period a distance = its circumference, and Jupiter does
this same job with error (4%) only… because of these 2 planets I have suggested
the rule (Planet Day Period is defined by motion distance = Planet circumference)
- No other planets follow the rule, so no credibility to be used as a general rule
- But
- Before to give up, we have to analyze the source point from which this rule is
created, which was the Earth moon effect on Jupiter motion!
- Where
- The moon (10921km) needs to rotate around its axis 13.1 times to move a distance
= 142984 km = Jupiter diameter – on the other side – Jupiter velocity =13.1
km/sec, by this velocity Jupiter itself needs to move 10921 seconds to pass a
distance=its diameter
- Because the data is interesting.. we can't give us before to see why this data is so
interesting and also to ask if the moon can practice such effect on Jupiter!! We
may ask if it has similar effects on other planets
- By what force the moon can practice any effect? Where the moon mass is so small,
but the data can't be just thrown under pure coincidence claim – we have some
obligation to see if there's a geometrical necessity behind…

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Jupiter And The Earth Moon Deep Relationship
Equation No. 1
4900 mkm = 1.16 mkm per second x 4222.6 seconds
= moon circumference 10921 km x Jupiter circumference 449197km
- Jupiter orbital circumference 4900 mkm, is the distance passed by light supposed
velocity 1.16 mkm/sec during a period =4222.6 seconds (this period Mercury
uses as 4222.6 hours = Mercury day period)
- That tells us, Jupiter orbital circumference (4900mkm) is created basically depends
on a light motion –
- We also now (4900 mkm =360 +680+940+1433+1433) (Inner Planets)
- The question is Why??
4900 mkm = moon circumference 10921 km x Jupiter circumference 449197km
- If Jupiter orbital circumference is created based on light motion (1.16 mkm/sec)
during a period 4222.6 seconds and this period is related to Mercury, based on
base the moon circumference 10921 km is seen here?! because we have 2 factors
are (1.16 mkm per second x 4222.6 seconds) where's the moon in these 2 factors?
- In 1.16 mkm !!
Old Equation (No. A) - 1.16 million km = 43000 km x 27.3 days x 0.99
- 43000 km = the distance between perigee and apogee (the moon orbital points),
- Equation No (A) tells that, if the moon is just a point (without diameter) and
moves from perigee to apogee (43000km) once per solar day, the moon would in
this case move during its orbital period (27.3 solar days) a distance = 1.16 mkm, so
if 27.3 days of the moon motion = 1 second of light motion (different rate of time
is created because of the high velocity motions), by that, the moon motion would
be equivalent to light motion (supposed velocity 1.16 mkm/sec)
- The moon motion is found inside the light motion (suppose velocity 1.16 mkm/se)
- But where is the moon circumference (10921 km)
Old Equation (No. B) - 2x 43000 km = 3475 km x24.7
- 3475 km = the moon diameter AND 24.7 hours = Mars Day Period
- So, the moon orbital distance between perigee and apogee defines the moon
diameter, rated to Mars Day Period (Mars Motion Interaction) – but the value
43000 km is defined by light motion - because of that- the moon diameter is
defined also by a light motion
Old Equation (No. C) - 300000 km = 10921 km (the moon circumference) x 27.3
- Equation No. (C) tells that, if the moon rotates arou7nd its axis one time per solar
day (as Earth does), the moon would move a distance = light motion distance
during 1 second of time (light known velocity 0.3mkm/sec)

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
A Conclusion
The moon receives its ability to make its motion in harmony with light motion by
Mars Motion interaction & effect on the moon motion.
- i.e.
- The moon motion harmony with light motion depends on Mars motion interaction
because of that, the moon and mars motions interaction is so strong and proved
o 687 days (Mars orbital period) = 27.3 days (the moon orbital period) x 25.2
o 25.2 deg = 13.18 deg ( the moon motion degrees per solar day) x 1.9
o Where 25.2 deg = Mars axial tilt and 1.9 degrees = Mars orbital inclination
- Because of the moon motion harmony with light motion, the moon can practice
some effect on other planets motions and because of that the moon effect on jupiter
motion!!

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
Equation No. 2
760 km =27.3 seconds x 27.83 km /sec
- 27.3 days = the moon orbital period BUT 27.83 km/sec = the moon velocity
- We may remember that Jupiter orbital distance 778.6 mkm is consisted of 2 parts
which are 760 mkm +17.8 mkm - and that because – after the planets had
migrated, Jupiter connected with Mars with (760 mkm) and with Pluto with (17.8
mkm) and by that Jupiter connected the 2 migrants planets to save the solar system
general geometry (this process Jupiter did with Uranus Cooperation).
- Equation No. (2) tells that the moon during 27.3 seconds moves a distance =760
km – 27.3 days in planet motion be used as 27.3 seconds in light motion and 760
km is multiply with the moon orbital diameter (=1 mkm), so the result will be
760mkm, why this number is so important?! Because
- 760 seconds x 0.3 mkm/sec (light known velocity) =227.9 mkm (Mars orbital
distance)
- That means, Mars New orbital distance (227.9 mkm) is defined based on the value
760 seconds which we see as 760 mkm (distance values are used as periods of time
because of light motion)
- That tells us, the moon effects on Jupiter to define (Jupiter orbital distance)! How
that can be possible? Because the moon motion is in harmony with light motion
and by light motion Jupiter defines its orbital distance
- I want to say, the solar system which we see is created based on millions of inside
interactions between the light and matter motions – the simple vision gives us
nothing….
- PLEASE NOTE
- The value 760 is the required value to define Mars new orbital distance (227.9
mkm) after Migration, and this value we have met 3 times, in my previous papers
series (Jupiter effect on the inner planets) and also in the previous parts of this
series (Does Planet Day Period Depend On Its Circumference), this value 760 is
the responsible to create the distance 227.9 mkm for Mars after its Migration – and
this value is defined by the moon motion – that means –
- While Mars in its Migration had collided with Venus and Earth and from these
collisions debris the Earth moon is crated, Mars new orbital distance is defined
after the Earth moon creation and stats its motion – during this period Mars was
straying around its new orbital distance point…

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
2- The Earth Moon Effect On Other planets
Equation No. 3
10921 km (moon circumference) x 120536 km (Saturn diameter) =1316.3 mkm
- 1325.3 mkm = Venus Saturn Distance (error 0.7%)
- Venus Saturn Distance is defined based on the moon effect on Saturn!
- Please remember
- Saturn diameter = Venus circumference x π
- Saturn orbital distance = (Venus circumference)2
(error 1%)
- The moon effect on Saturn is very similar to its effect on Jupiter… the behind
power is the harmony between the moon motion and light motion, by that the
moon makes itself very useful planet…
Equation No. 4
42 km =3475 km (the moon diameter) x 12104 km (Venus diameter)
- 41.4 million km = the distance between Venus ands Earth
- It's almost a similar effect the moon does here also
Equation No. 5
167 mkm =10921 km (the moon circumference) x 4879 km (Mercury diameter)
- 170 mkm = the distance between Mercury and Mars (error 1.7%)
- It's almost a similar effect the moon does here also
Equation No. 6
437.7 million km =10921 km (the moon circumference) x 40080 km (Earth
circumference)
- Light known velocity travels during 1461 seconds a distance =437.7 mkm
- 1461 seconds is used by Earth as 1461 solar days (= 365+365+365+36 days)
Equation No. 7
558 mkm =10921 km (the moon circumference) x 51118 km (Uranus diameter)
- 558 mkm x 5.1 (the moon orbital inclination =5.1 degrees) =2872.5 mkm
- (2872.5 mkm = Uranus Orbital Distance)
- (But also 550.7 mkm = Jupiter Mars distance error 1.3%)
A Conclusion
The moon has similar effects on different planets as does on Jupiter- that tells –
again – the Earth moon is not a common moon similar to any other planet moon-
something very specific is related to this moon in creation and motion

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
More Analysis In The Moon Orbital Triangle
Basic Data Correction And Revision
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees
Let's review and correct the moon orbital triangle data

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
(1st
Point)
- The figure I brought from internet to use in the
Explanation -
- We have supposed that the inner circle is Perigee orbit
and the outer circle is apogee orbit – and we have
calculated the tangent AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific
Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =47513.7 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg) (ACD
= 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
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Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
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