The Moon Orbital Inclination (Part II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Orbital Inclination (Part II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –7th
April 2021
Abstract
Paper Question
- The moon displacements total during 29.53 days = 2.5986 mkm
- The moon apogee circumference =2.550973 mkm
- The difference 47720 km
- Because the apogee orbit (r= 406000 km) is the most far point the moon can reach
from Earth, the question is raised that (why the moon apogee orbital circumference
doesn't equal its displacements total during 29.53 days?)
- The provided answer told that, because of the moon orbital inclination effect, this
answer contains a reference that the moon orbital inclination 5.1 deg is created by
an effect of Pluto orbital inclination 17.2 deg…
- The Now data tells that
- Uranus motion distance during its day period (421056 km) – Saturn motion
distance during its day period (373644 km) = 47720 km
- Can These 2 Planets Effect On The Moon Orbit Structure?
- Uranus day period =17.2 hours but Pluto orbital inclination =17.2 degrees, can
these 2 values be created related to each other?
- The question be logical because Pluto day period (153.3 h) is so long in
comparison with the other 4 outer planets days periods and we need to know why?
- The paper analyzes the data concerning this subject.

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1- The Moon Orbital Circumference
1-1 Uranus Day Period
1-2 Uranus Motion Analysis
1-1 Uranus Day Period
I- Data
(1)
97.8 deg (Uranus axial tilt) – 0.5 deg = 97.3 deg
And
97.3 deg / 5.6 deg = 17.37 deg
But
17.37 deg x 0.99 =17.2 deg
(2)
10.7 hours (Saturn Day) = 6.7 x 1.597
But
27.46 days = 17.2 days x 1.597
II- Discussion
- We remember that
- Uranus motion distance during its day period (421056 km) – Saturn motion
distance during its day period (373644 km) = 47720 km
- The question is
- Can Uranus day period (17.2 h) be created depending on the moon orbital period
(27.3 days)?!
- The moon is created later and Uranus was found before the moon creation – but if
the solar group is one trajectory of energy – that necessitates each planet modifies
its data as a result to a new planet born – means – Uranus day period can be
created depend on the moon orbital period – because Uranus modified its data after
the moon creation –

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- The hard question is how Uranus day period 17.2 hours can effect to create Pluto
orbital inclination 17.2 degrees – we have to try to answer this question later – now
our question is – did really Uranus day period (17.2 h) be created depending on the
moon orbital period? Let's discuss the data in following …
Equation No. (1)
97.8 deg (Uranus axial tilt) – 0.5 deg = 97.3 deg
And
97.3 deg / 5.6 deg = 17.37 deg
But
17.37 deg x 0.99 =17.2 deg
- 5.6 deg = 5.1 deg (the moon orbital inclination) + 0.5 deg (the moon angular
diameter)
- This equation tells that, the moon orbital inclination when be measured above the
moon diameter will be 5.6 degrees
- The value 17.2 deg is created as a rate between the moon orbital inclination and
Uranus axial tilt (through simple calculations)
- That means, the moon orbit effect on Uranus axial tilt and create the value 17.2
degrees – means – the value 17.2 degrees is created for first time by the moon orbit
effect on Uranus axial tilt
- The values 17.2 and 17.3.7 are created based on this interaction
- 17.37 deg = the inner planets orbital inclinations total (7 deg + 3.4 deg + 5.1 deg
+1.9 deg)
- This data shows a deep effect of this interaction

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Equation No. (2)
10.7 hours (Saturn Day) = 6.7 x 1.597
But
27.46 days = 17.2 days x 1.597
- 6.7 degrees = The Moon Axial Tilt
- By that, the moon creates a connection between 2 planets, because the moon
orbital inclination is interacted with Uranus axial tilt but the moon axial tilt is
interacted with Saturn day period -
- And the 2 produced rates are (17.2 and 1.597) by these 2 rates the moon orbital
period is created (27.3)
- But
- The equation shows (27.46) and not (27.3 days) Why?
- The reason is a complex one we should consider it deeply in following
o 10921 km (the moon circumference) x 27.46 = 300000 km
o This equation tells, if the moon rotates around its axis one rotation per solar
day (as the Earth does), the moon would move during (27.46 days) a
distance = 300000 km = light motion distance for 1 second
o Why this is a useful data?!
o But the value (27.32 days) can't perform the result 300000 km, but the value
27.46 days can, and because the difference is (0.5%) it can't disprove the
idea.
o Light velocity is a partner in planet motion - but if effect geometrically still
needs more analysis.

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- Let's summarize the discussion idea in following:
o The difference 47720 km between the moon orbital apogee circumference
and its displacements total is found by an effect of motions interaction
between Uranus and Saturn – the previous data tries to prove this claim –
now let's provide one more proof in following
o 406000 km (Apogee Radius) =1.0725 x 378675 km
o Where
o 378675 km = Saturn Circumference
o And
o The rate 1.0725 is found between different distances (I attribute this rate
1.0725 to Lorentz length contraction effect – but even if this attribution is
incorrect – that changes nothing because the rate is used frequently between
different distances- which tells some geometrical reason must be found
behind this using) – examples of these distances are:
o 778.6 mkm (Jupiter orbital distance) = 1.0725 x 720 mkm (Mercury Jupiter
distance)
o 720 mkm (Mercury Jupiter distance) = 1.0725 x 671 mkm (Venus Jupiter
Distance)
o 671 mkm (Venus Jupiter Distance) = 1.0725 x 627 mkm (Earth Jupiter
distance)
o These are just examples of many similar data, So, the geometrical reason
which causes this using, causes also the using of (406000 km =1.0725 x
378675 km) and by that connects the moon apogee radius with Saturn
circumference (as Saturn data) supporting the claim that, Saturn & Uranus
motions interaction causes the moon apogee orbit radius.
Notice (1)
27.46 days = 17.2 days x 1.597
17.2 days is used as 17.2 hours by Uranus motion as (Uranus Day Period).

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Notice (2)
- Mercury Orbital Distance =57.9 mkm
- Let's use this value as 57.9 seconds
- Light known velocity (0.3 mkm/s) moves during 57.9 seconds a distance = 17.37
mkm but we know that 1 mkm = 1 deg, mean 17.37 mkm =17.37 degrees
- That tells the value (17.37 deg) effect on the inner planets data in different forms
based on different geometrical rules
Notice (3)
- The previous data tells, Uranus creates its day period to be =17.2 hours to create a
harmony between its motion data and the inner planets motions data
Notice (4)
- Saturn is related to the moon apogee radius (406000 km) where
- Saturn and Uranus motions interaction causes the difference 47720 km
- That means, Uranus causes the moon daily displacement to be =88000 km
- But
- Uranus orbital distance 2872.5 mkm = Earth orbital distance 149.6 mkm x 19.2
- So,
- 88000 km x 19.2 = 1689600 km = 10921 km (the moon circumference) x 154.7
- That shows how Pluto day period (153.3 hours) is created
Notice (5)
- 300000 km =10921 km x 27.46 days
- This equation tells the moon moves a distance (10921 km) during 1 solar day –
because the moon orbital period =27.3 days
- 88000 km x 19.2 = 10921 km x 154.7
- This equation tells the moon moves a distance (10921 km) during 1 hour, because
Pluto day period =153.3 hours ….
- The rate of time (1 solar day = 1 hour) is created here!

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Notice (6)
- 17.37 mkm = 47720 km x 364
- But
- 364 mkm = 2π x 57.9 mkm (Mercury Orbital Distance)
- But 17.37 mkm = (0.3 mkm/s) x 57.9 seconds
Notice (7)
- Does Uranus cause the moon daily displacement to be 88000 km? Yes
o The moon displacements total during Metonic Cycle (6939.75 days) = 610.7
mkm
o Uranus motion distance during 1440 of Uranus days = 606.3 mkm
o The difference =0.7%
o This data supports the claim that, Uranus motion effect on the moon daily
displacement and causes it to be 88000 km
- Let's suppose, Uranus moves during 1440 of its days a distance = the moon
displacements total during Metonic Cycle period (6939.75 days), what's the
useful result of that? why we should care?
o The difficulty is found in the distances equality explanation. Because
suppose a distance A = a distance B, What good news we receive of that?
why this is useful for us at all?
o Mars orbital circumference =1433 mkm = Saturn orbital distance
o It's a known fact, but what useful result we can get?
o Where we consider the planets as separated rigid bodies, each moves by its
own masses gravity and no planet motion depends on any other planets, by
this description – the distances equality –has no positive effect on our
understanding
But
o Let's imagine the solar planets as gears move depend on each other – the
equal distances will be useful here because it tells us which gear causes the

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motion of which other gear – So– We may catch the motion transportation
process.
o I want to say, we need to create some flexibility for the current description
to contain the planets data geometrical meanings – otherwise our theories
will contradict the planets motions data.
Notice (8)
- The value 17.2 is created in the moon orbit by effect of Uranus and Saturn motions
interaction – but
- How this value 17.2 reaches to Pluto to be 17.2 deg = Pluto orbital inclination?
- By Jupiter effect
o 17.37 deg = 5.6 deg x 3.1 deg (Jupiter Axial Tilt)
o 86400 mkm =5040 m x 17.2 mkm
o We know that, the value 86400 mkm is found by Jupiter energy which is
sent to Pluto & reflected to Neptune and from Neptune to the inner planets,
Jupiter sent (2 x 86400 s x 1.16 mkm/s) to Pluto and Pluto reflected them to
Neptune – Neptune used 14% of this energy (=28255 mkm = Neptune
orbital circumference) and the rest of energy is reflected from Neptune to
the inner planets into 2 equal trajectories of energy – each trajectory has an
energy =86400 mkm (because space = Energy)
o By that, Jupiter transports the data (17.2) from the moon orbit to Pluto
motion –
Notice (9)
- 47720 km = 5040 seconds x 2 x 4.7 km/s (Pluto velocity)
Notice (10)
- (0.3 mkm /s) light known velocity x 17.2 seconds = 5.16 mkm =5.16 deg (= the
moon orbital inclination)

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1-2 Uranus Motion Analysis
Data No. 1
- 18048 mkm (Uranus orbital circumference) = 0.421 mkm x 42865 days
- But
- Uranus (6.8 km/s) moves during 6378 seconds = 43371 km
- The difference between 42865 and 43371 is 1%
The Explanation of Data No. 1
- Uranus needs 42865 (Uranus days) to revolve around the sun a complete
revolution – the number 42865 is interesting one because the distance between
perigee and apogee =43000 km – that pushes us to suppose that 1 Uranus day be =
1 km which makes the value 42865 Uranus days be 42865 km = 43000 km the
distance between perigee and apogee
- But
- Uranus moves this distance (43000 km or 43371 km) is a period =6378 s where
6378 km = Earth Radius – that shows how the matter dimensions are created based
on the motions
- The previous data connects Earth diameter with Uranus motion and day period

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Data No. 2
- Uranus (6.8 km/s) moves during 51118 seconds a distance = 347602 km
- 51118 km = Uranus diameter
- But
- If 1000 km = 1 day , So
- 347602 km = 347.6 days
- And
- 30589 days (Uranus orbital period) = 347.6 x 88 days (Mercury orbital period)
The Explanation of Data No. 1
- Uranus orbital period 30589 days is created based on this equation without doubt –
because it's perfect accurate
- 30589 days =(88 x 346.6 days +88 days) = 347.6 days x 88 days
- So, the distance 347602 km must have effect on this period creation and Mercury
motion must be effected but it also
Notice (1)
- The rate 1000 km = 1 day is another rate we discover –
- Let's remember the 1st
rate which is (1 mkm =1 day) where
- Mercury moves during its rotation period (58.66 days) a distance = 243 mkm
- And
- Mars moves during Venus day period (116.75 days) a distance = 243 mkm
- But
- Venus Rotation Period =243 days

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Data No. 3
- Uranus (6.8 km/s) moves during 347602 seconds a distance = 2363694 km
- Where
(1)
- 2363694 km = 2π x 378675 km (Saturn Circumference) (error 0.6%)
(2)
- 2363694 seconds = 656.6 hours (where Jupiter Saturn distance =655 mkm)
Notice
- Pluto (4.7 km/s) moves during 10921 seconds a distance = 51118 km
- Pluto (4.7 km/s) moves during 51118 seconds a distance = 2 x 120536 km
- Where
- 10921 km = The Earth Moon Circumference
- 51118 km = Uranus Diameter
- 120536 km = Saturn diameter
- The previous data tells that, Pluto velocity is defined by Uranus motion effect on
Pluto – that because – Saturn Circumference which is defined by Uranus own
motion is defined again by Pluto velocity motion depends on Uranus data, and that
can't be done except by making Pluto velocity (4.7 km/s) is defined by Uranus own
data
- The direct geometrical effect of Uranus on Pluto motion needs more analysis – but
because Pluto moves distances = 2 Saturn diameters based on Uranus data (Uranus
diameter is used as a period of time 51118 s) that necessitates the conclusion –
Pluto velocity is defined by Uranus motion data.

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Notice
- Uranus (6.8 km/s) moves during its day period (17.2 h) x 5.4 a distance = 2π x
362000 km (perigee radius =363000 km)
- Where
- 5.4 km/s = Neptune velocity
Notice
- Venus (35 km/s) moves during 23594 seconds a distance = 2 x 413000 km
- Where
- 23594 km = Pluto circumference 7510 km x π
- 413600 km x 2π = the moon displacements total during 29.53 days
- 12104 km (Venus Diameter) = 5.1 x 2390 km (Pluto Diameter)
Notice
- Uranus (6.8 km/s) moves during 12756 seconds a distance = 86400 km (0.4%)
- Where
- 12756 km = Earth Diameter
Notice
- Jupiter (13.1 km/s) moves during 6585.36 seconds a distance = 86400 km
- Where
- 6585.36 days = Saros Cycle

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Moon Orbital Inclination (Part II)

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