The Moon Orbital Triangle (General discussion) (Revised) (II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Orbital Triangle (General discussion) (Revised) (II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –29th
November 2020
Abstract
Paper Argument
- The Moon motion has 2 Orbits – we see one of them only
- The moon second orbit is declined by 0.8 degrees on the first one.
- The 2 orbits are neighbors and define together the Lunar Eclipse Umbra Length
(1.392 mkm)
- The second orbit is found because the moon moves 2 daily displacements each =
(88000 km) but we see one of them only
- Venus Axial Tilt is changed from 1.774 to 177.4 degrees because of Uranus Axial
Tilt angle (91.1 degrees) with The Moon Axial Tilt (6.7 deg).
- Venus original axial tilt (1.774 deg) is created as a rate between its diameter and
Mars diameter – that shows Mars diameter rate effect on the planets motions
- Mars diameter effect explains the reason why Kepler equation (P2
/d3
= Constant)
uses (25) as a constant while (25.2 deg = Mars Axial Tilt)
- The moon uses Pythagoras rule in its motion to define its real displacement
through its orbit which can be less or equal the value 88000 km.
Paper Conclusion
- The solar system motion is one motion.
- Saturn is the planets motions connection Point
- The solar system is similar to a machine of gears all planets are gears transports
their motions from one to another and the system uses Saturn as its general
connection point for all planets motions
- The solar system general motion uses (1 day) of the (3) planets (Mercury, Venus
and the Earth moon) in consistency with (2 days) of the rest planets
- Saturn is created after the 2 planets migration (Mars and Pluto) to create a general
stability for the solar system geometry and prevent the geometrical decomposition.
- Metonic Cycle is The General Motion For All Planets

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Contents
Subject Page number
1- The Moon Orbital Triangle Data 3
1-1 Preface 3
1-2 The Moon Orbital Triangle Details 5
1-3 The Moon diameter division 7
2- Venus Effect On The Moon Orbital Triangle 10
2-1 Venus Axial Tilt Creation 10
2-2 The Triangle BCF Analysis 14
2-3 The Moon 2nd
Orbit of Motion 22
2-4 Uranus Effect On Venus Motion 27
3- Saturn Effect On The Solar System Geometry 29
3-1 The Moon Orbit Regression Monthly 29
3-2 The Triangle (CZN) Analysis 33
3-3 Saturn Diameter Analysis 37
3-4 Saturn Diameter Effect 42

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1- The Moon Orbital Triangle Data
1-1 Preface
The Moon Orbital Motion (Revision)
- Why does the moon use Pythagoras Rule in its motion? and why do we need the
moon orbital triangle?
o The moon daily displacement =88000 km but the moon doesn’t use it as its
real displacement but instead the moon uses Pythagoras triangle to define
another real displacement
o Based on that
o The moon uses the right triangle dimension (L= 88000 km Cos θ) where
this (L) is the moon real displacement through its orbit daily
o The angle (θ) is the smallest angle in the right triangle, and it effects on the
moon real displacement and its motion height above perigee radius (r=0.363
mkm)
Why?
o The daily displacement = 88000 km and during 29.53 days, the total
distance the moon passes = 2.59 mkm which can be done only through
apogee orbit whose radius (r=0.406 mkm) –
That means –
o If the moon uses only 88000 km as its real displacement daily, the moon
would move only through the apogee orbit (r= 0.406 mkm)
o Because the moon tries to move in more near orbits to the Earth, the moon
uses Pythagoras triangle technique to produce smaller displacements though
its orbit while the moon move this same distance (88000 km) as a real
motion -
o So, this real displacement technique (L= 88000 km Cos θ) gives the moon
the ability to move through lower orbits to the Earth, and the change of the
angle θ changes also its real displacement

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o The smaller real displacement can be used for more near orbits to Earth (as
perigee radius r=0.363mkm) but the longer real displacements need more
wide orbit to be passed through, which forces the moon to move in higher
orbits above perigee.
o That means, the angle θ changes the real displacements and the height of the
moon motion above perigee radius (r= 0.363 mkm).
o Then based on that I have suggested the moon motion equation which is
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
o θ is the smallest angle in Pythagoras triangle used for the moon real
displacement (L= 88000 km Cos θ),
o 0.985 degrees = Earth daily motion degrees.
o With more analysis, a 2nd
force effects on the moon orbital motion is
discovered, this 2nd
force effects on the point (A) in the moon orbital triangle
– where this point is an essential part of the triangle but it's far with 43000
km beyond apogee radius (r= 0.406 mkm).
o This 2nd
force effects on the moon orbital motion is produced by gravity
forces interaction between the sun and Jupiter on Earth and its moon – So
this 2nd
force pulls the moon to apogee radius but Earth gravity tries to keep
the moon at perigee radius. (This 2nd
force effects on the point (A) in the
moon orbital triangle)
Notice
o 149.6 mkm Earth orbital distance = 142984 km (Jupiter diameter) x 1047
(The sun mass/ Jupiter mass), because of this data, we conclude that, Earth
orbital distance is defined by gravity forces interaction between the sun and
Jupiter masses. Which supports the claim that 2nd
force can be produced by
the sun and Jupiter gravities interaction effect on the Earth moon.

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1-2 The Moon Orbital Triangle Details
Let's review The Earth Moon Orbital Triangle because we use it
Figure No. (1) (my figure)
Let's Review The Moon Orbital Triangle Data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and
the outer circle is apogee orbit – and we have calculated the
tangent DB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras
triangle (1, 2 and 51/2
)
- The triangle (ODB) angles are 26.564 deg. and 63.435 deg.

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(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373900 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- CX= =87521 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km CY= 97766 km
- BA = BC = 86000 km
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km
- BY = = 46475 km
- SZ = 7665 km ZF= 2414 km
- DY = 3475 km BX= 16203 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg)
(ACD = 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.3 deg)
- BCY = 28.39 degrees ECZ= 88.9 degrees
- XCE = 66 degrees
- CZS = 77.8 degrees
- CZF =102.195 degrees
- XCB = 10.67deg
- (Uranus Axial Tilt = 97.8 degrees = FSC 97.2 degrees + 0.6 degrees) (i.e. the
angle under FSC)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

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1-3 The Moon Diameter Division
Figure No. 2 (my figure) (The Moon Diameter Division)
- Uranus Axial Tilt (97.8 degrees) has an angle (91.1 degrees) with The Moon Axial
Tilt (6.7 degrees), so The blue vertical line is Uranus axial tilt and the angle in the
circles center = 91.1 degrees
- This value 91.1 degrees is decreased by 0.5 degrees which is consumed by the
moon diameter (the circles express the moon diameter with some division), also
0.6 degrees is consumed by the green box (I suppose Saturn & Jupiter motions
interaction effect is done here to create this 0.6 degrees)
- So the angle between the blue vertical line and the horizontal red line 90 degrees
- The red horizontal line is the moon orbital triangle base (AE = 449197 km)
- The blue vertical line angle above the moon directly =90.6 degrees
- But
- In this figure I cut layers from the moon diameter to create smaller moon diameters
to consume smaller angles than (0.5 degrees), and based on that we measure the
angle of The blue vertical line, let's explain this moon diameter division:
- The Blue Circle its diameter R1= 1390 km and r1 =695 km
- The Red Circle its diameter R2= 2085 km and r2 =1042.5 km
- The Black Circle its diameter R3= 2185 km =π x 695 km and r3 =1092.5 km
- The Brown Circle its diameter R4= 3208 km and r4 =1604 km =5040/π
- The Orange Circle is the moon itself its diameter R5= 3475 km = 5 x 695 km

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- The moon consumes 0.5 degrees for its diameter (3475 km) …So
- R1 = 1390 km, the consumed angle will be 0.2 degrees i.e. the angle above The
Blue Circle = 90.9 degrees.
- R2= 2085 km (60% of the moon diameter) and because of that, the consumed angle
will be only 0.3 degrees, means, the angle above The Red Circle =90.8 degrees
- Note Please, 90.8 degrees = 90 degrees + 0.8 degrees (Uranus orbital inclination),
by that the rest degree of Uranus axial tilt = its orbital inclination vertically.
Notice No. 1
- Pluto Axial Tilt 122.5 degrees = 7.1 x 17.2 degrees (Pluto orbital inclination),
- 7.1 a rate created by Lorentz Length Contraction Phenomenon…
- That tells us, the values (122.5 deg and 17.2 deg) are equivalent values, how? It's a
contraction, the energy of (122.5 deg) in contracted by 7.1 and the rest 17.2 deg is
created from this same energy (122.5 deg). they are 2 equivalent values but one of
them passed through a different frame and faced a contraction phenomenon and
because of that its value (122.5 deg) became (17.2 deg)
- This notice is provided here to show that in the solar system there's some way to
create A Planet Axial Tilt = Its Orbital Inclination…. What's the important
result for this equality? We have seen this equality in Uranus & Pluto data, where
we know that (122.5 deg x 0.8 deg = 97.8 deg)– there's some geometrical machine
found behind this equality…

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Notice No. 2
- Are these divided diameters real diameters or invented numbers? Let's test them :
(1)
- 149.6 mkm (Earth Orbital Distance) = 3475 km (the moon diameter) x 43000 km
(the distance from perigee to apogee)
- 149.6 mkm (Earth Orbital Distance) = 2085 km (R2) x 71492 km (Jupiter Radius)
- 149.6 mkm (Earth Orbital Distance) = 1047 x 142984 km (Jupiter diameter) (1047
= The Sun Mass / Jupiter Mass)
(2)
- R4= 3208 km x 466884 km = 149.6 mkm x π2
- 466884 km = Jupiter motion distance during its day period.
(3)
- R3= 2185 km x π x 21346.6 km (Mars Circumference) = 149.6 mkm (2%)
(4)
- R2= 2085 km x 71492 km (Jupiter Radius) =149.6 mkm
(5)
- 4900 mkm = 4222.6 x 1.16 mkm = 10921 km x 449197 km
- 302 mkm = 4222.6 x 71492 km (Jupiter Radius)
- 305 mkm = 88000 km x 3475 km = 25.2 x (3475 km)2
- 177.4 degrees -90 degrees = 87.4 degrees (+0.6 degree = 88 degrees)
- 3475 s x 0.3 mkm/sec =1042.5 mkm but
- 2085 mkm = 3475s x 0.3 mkm/s x2
Discussion
- The points (1-4) show, Earth orbital distance 149.6 mkm, is defined as a function
in the moon diameter, This same feature is used for the smaller diameters, which
proves these diameters are real values
- Point (No.5) shows light motions behind Planet Data – Let's remember 1st
hypothesis (Planet Motion depends On Light Motion), the show some of these
light motions which caused to create the provided data.

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2-Venus Effect On The Moon Orbital Triangle
2-1 Venus Axial Tilt Creation
Equation No. (1)
90.9 x 1.1 =100 = 177.4 /1.774 (Venus Axial Tilt 177.4 degrees)
Mars Diameter Rate Effect: (Mars diameter=6792 km)
o 6792 / 4879 =1.392 (Mercury Diameter)
o 12104 /6792 =1.774 (Venus Diameter)
o 12756 /6792 =1.878 (Earth Diameter)
o 6792 /3475 =1.95 (Moon Diameter)
o 142984 /21346.6 = 6.7 (Jupiter Diameter)
o 120536 /21346.6 =5.64 (Saturn Diameter)
o 51118 /7070 =7.23 (Uranus Diameter)
o 49528 /7070 =7 (Neptune Diameter)
o 7509 /6792 =1.1 (Pluto Diameter)
o 10921 /6792 =1.6 (Moon Circumference)
The rates result
1.774 = (Venus Diameter / Mars Diameter)
1.878 = Mars orbital inclination (1%)
1.95 = (Mars Mass / Mercury Mass)
6.7 deg = The Moon Axial Tilt
5.6 = 0.5 deg (the moon diameter) +5.1 deg (moon orbital inclination)
7.23 = The angle (BCS) in the moon orbital triangle
7 deg = Mercury Orbital Inclination.
1.1 deg = The Angle between the base AE (449197 km) and the horizontal level.
1.6 deg = 6.7 deg (the moon axial tilt) – 5.1 deg (the moon orbital inclination)
Notice No. (1)
7070 km = Mars diameter before Mars migration, how to know it?
84 mkm =1092
x 7070 km - Mars ancient orbital distance was 84 mkm

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Notice No. (2)
- When Mars diameter 7070 km, the rate (Earth diameter / Mars diameter) was = 1.8
- When Mars diameter 6792 km, the rate (Earth diameter / Mars diameter) was = 1.9
- That shows, Mars orbital inclination was 1.8 deg and the new is 1.9 deg
Let's return to equation no.(1)
Equation No. (1) (continued)
- Equation no. (1) tells us a clear meaning let's summarize it in following:
o Venus Axial Tilt was 1.744 degrees (Why?)
o Because Mars & Venus Diameters Rate =1.774 caused Venus axial tilt to be
(1.774 deg)! why? and why Mars specifically? Later we should answer…
let's suppose and continue …
o 100 is produced by the angles (90.9 and 1.1 degrees), so this 100 is
produced under the moon orbital triangle, almost in the moon diameter, and
specifically above the smallest diameter R1=1390 km (The Blue Circle in
figure no.2)
o That may explain many data for example:
o 38025 km (Venus Circumference) = 1390 km x 27.3, This equation tells
that, if the small moon (1390 km) rotates around its axis once per day, so
during its orbital period (27.3 d) will move a distance = 38025 km (Venus
Circumference) x π ( (Venus Circumference) x π) = Saturn diameter)
o 12104 km (Venus Diameter)=17.4 x 695 km, where 17.4 deg = the inner
planets orbital inclinations total, (17.4 deg =3.4 deg V. Orb. Incl. x 5.1 deg)
- Simply the equation tells us, some great change is occurred in the solar system
geometry based on the geometrical effect of the moon orbital motion…
- Still the idea is so puzzled … we will accept this conclusion… but … how to
explain the data… Because NOT all planets axial tilts are produced by the
diameters rate with Mars? Why only Venus axial tilt is produced? And why Mars

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diameter specifically? Still also Uranus and Neptune deal with the ancient Mars
diameter!! Let's move step by step
(1st
Question) Why Mars diameter specifically?
- Why Mars Axial Tilt is the constant in Kepler equation?
- Kepler told us, Planets (P2
/d3
)= constant …by actual data the constant =25
Table No.1
Planet P2
* 25 = d3
Error
Mercury (88)2
*25 (57.9)3
0.2%
Venus (224.7)2
*25 (108.2)3
0.3%
Earth (366)2
*25 (149.6)3
0
Mars (687)2
*25 (227.9)3
0.3%
Jupiter (4331)2
*25 (778.6)3
1.4%
Saturn (10474)2
*25 (1433.5)3
1%
Uranus (30589)2
*25 (2872.5)3
1.3%
Neptune (59800)2
*25 (4495.1)3
1.5%
Pluto (90588)2
*25 (5870)3
1.4%
25.2 degrees = Mars Axial Tilt (But the rate 25 = 25.2 degrees/1degrees)
- Why the constant =25? Because
- Planet matter is created as a function in its motion and because of that, Mars
diameter rate defines the planets axial tilts, orbital inclinations and other degrees,
and as a result the planets motions became in consistency with Mars Motion (Data)
and that caused to use Mars axial tilt as a constant
- (1 degree = 1.1 degrees -0.1 degree), Uranus created the decline under the triangle
to produce this angle 1.1 degrees and by that to repair the destruction occurred for
Mercury Axial Tilt (which was 1 degrees) and became (0.01 degree).
Notice No. (3)
- The concept "Planet Matter Is Created As A Function In Its Motion" is a basic
concept has an extending proves discussion with Saturn Diameter Analysis in this
current paper (Point No. 3).

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(2nd
Question)
Why Not All Planets Axial Tilts Are Produced As Rates with Mars Diameter?
- Because there's an interaction occurred between planet axial tilt and orbital
inclination – as we have seen in Pluto data where (122.5 deg Pluto axial tilt =7.1 x
17.2 deg Pluto orbital inclination) and 7.1 is the contraction rate. Also there's an
interaction between the planets motions data as (97.8 deg Uranus axial tilt = 122.5
deg Pluto Axial Tilt x 0.8 deg Uranus orbital inclination) also as we have seen (5.1
deg (the moon orbital inclination) x 3.4 deg (Venus orbital inclination) = 17.4 deg
(the inner planets orbital inclinations total but 17.4 deg x 0.99 =17.2 deg Pluto
orbital inclination)
- So let's conclude what Equation no. 1 tells us…
- When (Uranus Axial Tilt) The Blue Vertical Line Angle =90.9 degrees (directly
above the moon smallest diameter R1 =1390 km) – at this point – with effect of the
declination angle 1.1 degrees (90.9 x1.1) the rate 100 is produced and by this rate
Venus axial tilt 1.774 became 177.4 degrees…
- This interaction helped to produce the moon orbital inclination because (180 deg -
177.4 degrees =2.6 degrees), So through the whole circle (360 degrees) the
difference will be 5.2 degrees (5.1 deg (the moon orbital inclination +0.1 degree),
but
- The value 0.1 degree is used here (1.799 deg +0.1 deg =1.9 deg Mars Orbital
Inclination), where 1.8 deg = Neptune orbital inclination and the value 1.8 degrees
can be produced easily because it = (179.9 degrees /100).
(179.9 deg = 177.4 deg Venus Axial Tilt +2.5 deg Saturn Orbital Inclination)

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2-2 The Triangle BCF Analysis
- We analyze the triangle BCF
- BC =86000 km
- BF = 21000 km
- CF =88527 km
- BCF = 13.7 degrees
- BFC = 76.3 degrees
- The line CB is perpendicular on FB (90 degrees) but
- The line CB has an angle 91.1 degrees on the black line
base (under the blue circle "the moon")
Equation No. (2)
1259.3 degrees = 91.9 degrees x 13.7 degrees
- The angle 13.7 degrees (=BCF)
- We have no 91.9 degrees! We have only 91.1 degrees and that means there's
another angle is added here (0.8 degrees) what's this angle? It's our next question
- We have 2 points here to investigate… which are
- (1st
Point) To analyze the triangle BCF because of the angle 13.7 degrees
And
- (2nd
Point) To analyze the angle 1259.3 degrees other using…
(1st
Point) ….The Triangle BCF
- Its perimeter = 195527 km but (2x 195527 = 391054 km) …..And
- BF = 21000 km and EB = perigee radius = 363000 km means EF = 384000 km
- (384000 km)2
+ (86000 km)2
= 393512 km
- The difference between the 2 values = 0.6% or around 2500 km while the
distance from perigee to apogee =43000 km, means the rate around 5.7%.
- The calculation is clear and puzzled, because the double value of the triangle
perimeter can be produced by using Pythagoras rule for (The Triangle Base and
Perigee Radius)

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- What geometrical reason behind this calculation? because it tells us that, the
triangle perimeter (knows!!) the perigee radius r= 363000 km, which is not part of
this triangle at all! But…. Let's look at the 2 triangles… (BCF and ECB)
- The dimension (86000 km) is used in both triangles
- And 13.328 degrees = The angle (E) in the triangle EBC
- And 13.7 degrees = The angle (BCF) in the triangle BCF
- If these 2 angles have a relationship, there's some geometrical way to perform this
effect. Let's try to discover this relationship ….
Equation No. (3)
A - 12.195 deg +1.1 deg =13.29 (13. 328)
B- 12.195 deg +1.5 deg = 13.7
C- 2.5 deg x 0.6 deg =1.5 deg
- Equation No (3) tells us why the angles (13.7 and 13.3 degrees are related to each
other), because both are created from the same source (12.195 degrees), this is the
moon motion angle (13.18 deg – 0.98562 deg= 12.195 deg)
- Equation No. (A) added this angle (12.195) to 1.1 degree, which is the angle
between the moon orbital triangle base (EA =449197 km) and the horizontal level.
- Equation (A) produces the angle 13.3 degrees and Equation (B) added the angle
(1.5 degrees) to (12.195 deg) to produce the (13.7 deg), but what's the relationship
between 1.1 degrees and 1.5 degrees?
- 180 deg -177.4 deg (Venus Axial Tilt)= 2.6 degrees =1.1 deg + 1.5 deg means
The angle 2.6 deg is produced by Venus Axial Tilt and that makes one source for
both value (1.1 and 1.5)
- Equation no. (c) shows the interaction between 2.5 deg (Saturn orbital inclination)
and the value (0.6 degrees) produced by the green box (in the figures), where the
result is 1.5 degrees….what does that tell to us??
- 6.7deg-5.1 deg =1.6 deg=0.1 +1.5 deg i.e. the value 0.1 which is used 1.8+0.1=1.9
is found by interaction with Saturn orbital inclination, that causes Mars and Saturn
motions interaction.

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Equation No. (4)
I - (365.25 days /354.39 days) = 13.736 /13.328
II- (2.6 degrees /2.5 degrees) = 13.7 /13.18
- More equations about theses 2 angles
- Equation (2) (I), shows that, the required rate is used between the lunar synodic
year and the sidereal year
- Equation (2) (II), shows that, 2.5 degrees = Saturn Orbital Inclination) deals with
(2.6 degrees = 180 deg – 177.4 deg (Venus Axial Tilt). We know that, the moon
daily motion =13.18 degrees.
- What's the useful result from this equation no. (2)? Why we searched for it?
- Equation no (2) (I) tells that the value (13.7 deg) depends on the value (13.3)! if
365.25 days depends on 354.39 days or vice versa?
- We accept that the moon motion depends on earth motion and that may cause the
rate (365.25/354.39) is created by some dependency…
- That means, there's some hidden machine connects the angle 13.3 and 13.7 degrees
and that causes perigee radius to be included in the triangle BCF perimeter. this
geometrical machine my tell us why (2 x the triangle perimeter) can be produced
by Pythagoras rule using (perigee r=0.363 mkm and the dimension 86000 km)
Equation No. (5)
97.8 deg (Uranus Axial Tilt) = 1.1 deg x 88.9 deg
- Why do we need this equation? Because sin (97.8) = 0.99
- I suppose there's some geometrical machine by which Uranus axial tilt (sin) effect
on the planets data to produce this rate 0.99
o I wish it's not boring to search about this rate (0.99), because hundreds of
important data is created in 2 rates (%100 and 99%) for examples
o 17.4 (The inner planet orbital inclinations total) x 0.99 =17.2 deg (Pluto

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o 23.6 (The outer planet orbital inclinations total) x 0.99 =23.4 deg (Earth
Axial Tilt)
o (180deg/π)= 28.66 degrees x 0.99 = 28.3 degrees (Neptune Axial Tilt)
- Please remember the angle ECZ =88.9 degrees.
Equation No. (6)
346.6 = 12.195 x 28.4 (where 28.3 degrees = Neptune Axial Tilt) (346.6 days = the
nodal year)
- We still analyze the source (12.195 degrees) trying to see its depth…
- Also I can add the following data ….
o 12.195 deg x 1.9 deg (Mars orb. Inclination) =23.17 =23.4 x0.99
o 12.195 deg =7 (Mercury orb. Inclination) + 5.19
o 12.195 deg = 25.2 – 13 = 28.3- 16.1
o 17.2 - 12.195 = 5
o 17.4 - 12.195 = 5.2 (5.2+5)/2) =5.1
o 63.41 =12.195 deg x 5.2
o 1259.3 =12.195 deg x 103.263 (103.263 -103.177 =0.085)
o 0.085/0.1= 0.85 (= 0.8 deg x1.0725)
- We will use this data in the analyze of the angle 1259.3 degrees
(2nd
Point) (The Angle 1259.3 Degrees Analysis)
- 177.4 deg (Venus axial tilt) +2.5 deg (Saturn orbital inclination) = 179.9 degrees
- 179.9 degrees x 7 deg (Mercury orbital inclination) =1259.3 degrees2
- We know this value, let's remember it here
o Because of the planets (Mars And Pluto) migration, the solar system basic
geometrical structure has changed, and because of that, the value 180
degrees is destroyed in the solar system
o Venus and Saturn together unified their powers to create another (180 deg)
but

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o The available value was only 179.9 degrees, so the solar system has to use
this value 179.9 degrees in the geometrical process in place of 180 degrees
(Where 177.4 deg "Venus Axial Tilt" +2.5 deg "Saturn Orbital Inclination"
As a proof for that
o 180 degrees x 0.8 =225 but 179.9 degrees x 0.8 = 224.7 degrees (224.7 days
= Venus Orbital Period) (0.8 deg = Uranus orbital inclination)
i.e.
o The solar geometrical structure depends on 179.9 degrees in place of
180 degrees.
Equation No. (7)
2094 degrees x 0.6 degree = 1259.3 degrees2
- 0.6 degrees is the angle created by the green box in figures (no. 1 and 2), it's found
above the moon and under the moon orbital triangle base (AE) = 449197 km -
- 2094 mkm = Jupiter Uranus Distance
- We know that 1 mkm = 1 degree, where Mercury orbital circumference =360 mkm
= 360 degrees, and the solar system is one machine, so any planet use this rate.
- i.e. 2094 mkm = 2094 degrees ….But
- The distance 2094 mkm (Jupiter Uranus Distance) is so important in our
discussion about the moon orbital triangle, because the data tells that this distance
effects on the triangle data- but how – because it's just a distance?! Let's review its
data analysis as possible to see what effect this distance (2094 mkm) can practice
on the moon orbital motion…
o Light known velocity (0.3 mkm/sec) travels this distance in 6939.75 seconds
o The value 6939.75 seconds = 71 x 97.8 seconds
o We know that 71 is Lorentz Length Contraction Effect Rate
o 97.8 degrees = Uranus Axial Tilt, the blue line in figure no. 2, and we
know that, light motion can use the time periods as distances (because x =ct

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and if c=1 so x=t) (where 1 mkm=1 degree, so 97.8 s= 97.8 mkm =97.8 deg)
where (97.8 s x 0.3 mkm/s =29.33 mkm and 29.33 mkm x 97.8 = 2872.5
mkm = Uranus Orbital Distance – that means Uranus orbital distance also is
created based on (97.8s) and not only Uranus axial tilt.
Also
o 2094 seconds x 0.3 mkm /sec (light known velocity) =627 mkm = Earth
Jupiter distance – that means, by using this distance (2094 mkm) as a period
of time (2094 seconds) the light travels from Jupiter to Earth
Notice No. 1
o Based on that, the light almost travels from Earth to Jupiter and then to
Uranus, it's one light beam starts from Earth to Jupiter and then to Uranus,
how we know this is the motion direction and not the reversed one? because
1.2 mkm = 40080 seconds x 29.8 km/sec (Earth velocity), where Earth saves
a value 40080 and the rest (1.16 mkm/sec) Earth sent to Jupiter, this is
Jupiter light supposed velocity (1.16 mkm/sec), and also its Jupiter motion
distance per solar day (error 2.5%) , that means Earth motion is Jupiter
source of energy…

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Notice No. 2
o Please remember in the moon diameter division we have found (R2) =2085
km and we know that the moon orbital diameter =1 mkm because of that
this value 2085 km can be 2085 million km and be the distance which we
deal with here… Please remember, above this diameter (2085 km) (Uranus
axial tilt) The Blue Line has an angle =90.8 degrees accurately which =
Uranus orbital inclination vertically (0.8 deg + 90 deg) – can be there a
geometrical connection between these 2 values 2085 mkm and 2085 km?
Notice No. 3
o The distance (2094 mkm) is very puzzled one, because it has different
values as (2094 mkm –2088 mkm- 2082 mkm – 2107 mkm), the differences
are so small (less than 1%) but these are different values because they are
used by these values in very accurate equations….
o For example
o Light known velocity (0.3 mkm/sec) during 6939.75 s moves 2082 mkm
But
o Light supposed velocity (1.16 mkm/sec) during 3600 s moves 2088 mkm
o Because of light motion, I prefer to use the value 2082 or 2088 mkm.
But
Equation No. (8)
- 2073 degrees = 2073 mkm = 0.99 x 2094 mkm
o 2073 mkm = 1153 mkm (the planets motion distances total during their
days periods) x 1.8 deg (Neptune orbital inclination)
o 2073 mkm = 175.94 mkm x 11.8 deg (11.8 deg=6.7 deg the moon axial tilt
+ 5.1 deg = the moon orbital inclination) but (175.94 days = Mercury day
period, where Venus moves during 365.25 days a distance=2π x 175.94mkm
o 2073 degrees = 1440 x 1.44 deg (the moon orbit regression monthly)

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o 2073 degrees=12.195 degrees x 170 where (170 deg = 6.7 deg x 25.2 deg
Mars Axial Tilt = 11.8 deg (the moon axial tilt + orbital inclination) x 14.4
degrees (in the moon orbital triangle this angle = E angle (13.3 deg +1.1
deg) the angle under E
- Please remember, Uranus axial tilt (97.8 degrees) has an angle (91.1 degrees)
with the moon axial tilt (6.7 deg).. but Uranus is perpendicular on the moon orbital
triangle based (EA =449197 km), because Uranus creates an angle 1.1 degrees
between the triangle base and the horizontal level (where this horizontal level is
the moon axial tilt 6.7). and this angle (1.1 degrees) is found under (E) as shown in
the moon orbital triangle. So (E angle =13.3 degrees +1.1 = 14.4 degrees)
Equation No. (9)
2073 degrees/1259.3 degrees = 327.6 /540
- 327.6 days = the lunar sidereal year
- 540 seconds x 1.16 mkm/sec (light supposed velocity) = 627 mkm = Earth Jupiter
distance
- Equation no. (9) makes the days are equivalent to seconds, it's an application my
research hypotheses let's review them here…
o 1st
hypothesis (Planet motion depends on light motion)
o 2nd
hypothesis (Light Motion For 1 Second Cause Planet Motion For 1
Solar Day)
o The motion rule (Light Moves Along A Circle Circumference But Its
Follower Planet Moves Along Its Radius)
- I try to show that, it's a complex machine by which the planets move, i.e. planet
motion can't be considered as result of rigid body mechanics, because the light
motion is part can't be departed from planet motion and planet motion depends on
light motion…

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2-3 The Moon 2nd
Orbit of Motion
We still need more analysis for equation No. 2
- What's the key of this equation? It's the value 91.9 degrees
- We have no this value in the moon orbital triangle, Uranus Axial Tilt (97.8 deg)
creates and angle =91.1 degrees with the Moon Axial Tilt (6.7 deg) and this angle
91.1 deg is decreased by the moon diameter with 0.5 degree and by the green box
(in the figure) by 0.6 degrees and then the angle between the triangle base (EA)
and Uranus axial tilt will be 90 degrees
- So how to find this angle 91.9 degrees we need 0.8 deg +91.1 deg to produce this
angle 91.9 degrees? So from where we can find this angle (0.8 degree )
- From The 2nd
Orbit Of The Moon Motion
The 2nd
Orbit For The Moon Motion:
- The moon moves a typical motion to Earth motion, to avoid the separation from
Earth during their motions…So
- The moon moves per solar day a distance 2.58 mkm with an angle =0.985 degrees
on the horizontal level, along Earth orbital circumference revolving around the
Sun.
- If there's no Lorentz Length Contraction phenomenon in the solar system, the
moon motion would to be a parallel line to Earth motion trajectory
- But because of Lorentz Length Contraction phenomenon with rate (1.0725), the
moon motion distance (2.58 mkm) be contracted to be (2.41 mkm)
- The moon needs to cover the different distance (0.17 mkm), because of that, the
moon moves its daily displacement (88000 km) depending on Earth gravity force
but this displacement isn't enough to cover the different distance
- Because the four inner planets masses total = Earth mass, I supposed that, these 4
inner planets practice a gravity equal Earth Mass Gravity on the moon orbital

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motion – and because of the distances between these planets and the moon, the 4
inner planets do this effect through Jupiter gravity
- Jupiter effect on the moon motion is done by an interaction between Jupiter gravity
and the sun gravity effect on the moon – and by that- Jupiter creates a 2nd
force
effects on the moon orbital motion- this second force effects on The Point (A) in
the moon orbital triangle – by this 2nd
force Jupiter pulls the moon to apogee radius
(r= 0.406 mkm) while earth gravity tries to save the moon on the perigee point
(r=0.363 mkm).
- Jupiter effect on the Point (A) causes the moon to move another displacement
(88000km) which is required for the moon motion to recover the different distance
(0.17 mkm) – that means – the moon per solar day moves 2 displacements, one of
them (88000 km) is done through the moon orbit around Earth but the second
(88000km) isn't seen by us! why??
- The moon original motion (2.58 mkm) is done on the Earth orbital circumference
trajectory revolving around the sun, and we don't see this motion- but it's a real one
regardless our vision because if the moon doesn't move this distance daily it would
be separated from the Earth motion…
- The 2nd
displacement (88000km) the moon moves along this same trajectory of
Earth orbital circumference revolving around the sun – and because of that we
can't see this displacement also.
- Means, the moon moves 2 displacements (88000 km x 2) per a solar day, one
displacement (88000 km) the moon moves through its orbit around Earth and we
see it, but where the moon moves its 2nd
displacement (88000 km)??
- We have to conclude that, There's One More Orbit For The Moon Motion. but
where is this orbit and how can we discover its position? Because we don't see this
displacement motion! let's return to Equation no.2 may it help us to define this 2nd
orbit position in Space…

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Equation No. (2) (continued)….
We have 2 features to define this 2nd
orbit
(1st
Feature)
- The angle 91.9 degrees =91.1 degrees +0.8 degrees
- We have the angle 91.1 degrees and then will add also 0.8 degree and this will
be the moon orbit direction …
- Where is this 0.8 degrees? Let's remember figure No.2
o The angle above the diameter R2 =2085 km is equal 90.8 degrees (the
decline angle of Uranus Axial Tilt on the moon diameter)
o But
o The angle between The vertical blue line (Uranus Axial Tilt) and the red
horizontal line (the triangle base 449197 km) =90 degrees
o The difference =0.8 degrees
o So we have 2 moon orbital triangles – from the first one we use 91.1 degrees
– and from the second orbital triangle we use 0.8 degrees – means we stand
on the R2= 2085 km
o This cooperation will produce the angle 91.9 degrees ….means
- The 2nd
orbit of the moon motion declines with 0.8 degrees on the first one and by
that we define the 2nd
orbit direction…
(2nd
Feature)
- The 2nd
orbit should be a neighbor for the 1st
one – because the 2 moon motion
orbits together define the lunar eclipse umbra length (1.392 mkm)
- In the moon orbital triangle, after the point(A) in the opposite direction to of Earth,
the distance from this point (A) to the end of the lunar eclipse umbra length (1.392
mkm) defines the second orbit…

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- Shortly
- The distance from the point (A) to the End of the lunar eclipse umbra = 1.392
mkm – 449197 km = 942803 km
- And this value 942803 km = the moon orbital triangle (ABC) Perimeter,
- That means the point (A) separates between 2 orbits of the moon motion,
- That also explains why this triangle (ABC) perimeter x 2 =1.88 mkm which is
equivalent to 1.9 degrees (Mars orbital inclination).
Equation No. (10)
- 180.8 degrees – 91.9 degrees = 88.9 degrees
- 180.8 degrees = 177.4 deg (Venus axial tilt) + 3.4 deg (Venus orbital inclination)
- 91.9 degrees our angle (Equation no. 2)
- 88.9 degrees is the angle ECZ
- Why this angle 88.9 deg is distinguished? Because the hypotenuse CZ =88000 km
the moon daily displacement –
- That tells, Venus data (177.4+3.4) is created in this interaction under the moon
orbital triangle – basically Venus diameter =1.774 x Mars diameter and Venus
axial tilt be 1.774 x 100 = 177.4 deg because of the interaction occurred under the
moon orbital triangle and by that Venus Axial Tilt became 177.4 degrees and
because of the Green box in the figure (shows Jupiter and Saturn Interaction),
because of that, a deep interaction is happened between Saturn and Venus based on
it the value 179.9 deg is created (177.4 deg +2.5 deg) – and the moon orbital
inclination be created in consistency with this data 180-177.4 =2.6 x 2=5.2 (where
5.1 the moon orbital inclination + 0.1 degree is consumed for mars orbital
inclination which was 1.8 degrees and became 1.9 degrees)

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Equation No. (11)
- 95.6 degrees =90+5.6 degrees and 5.6 degrees = 0.5 degree +5.1 degrees (the
moon orbital inclination)
- 5.6 degrees, means, the moon orbital inclination is measured above the moon
diameter (where the moon angular diameter consumes 0.5 degrees)
- 13.18 degrees = The Moon Motion Daily
- Equation no. (11) tells that, the value 1259.3 degrees is defined based on the moon
motion data!
- But
- Vertically…. (90+5.6 =95.6)
- It's the basic feature of this angle (1259.3 degrees), we work here under the moon
orbital triangle, under the angle 90 degrees, and because that, the perpendicularity
is seen in every used data…
Conclusion
- The Moon Has 2 Orbits For Its Motion
- The second orbit is declined by 0.8 degrees on the 1st
orbit (the moon orbital
triangle)
- The 2 orbits are neighbors and define together the lunar eclipse umbra length
(1.392 mkm)
- Venus Axial Tilt is changed from 1.774 to 177.4 degrees because of Uranus axial
tilt angle (91.1 degrees) with The Moon Axial Tilt (6.7 deg) and because of Uranus
Axial Tilt Perpendicularity on the moon orbital triangle base.

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2-4 Uranus Effect on Venus motion
- The paper conclusion tells us that, Venus axial tilt was 1.774 deg and because
Uranus Axial Tilt effect on the moon axial tilt, Venus axial tilt became 177.4
degrees – so this point of discussion may help us to find some confidence in this
conclusion – because we try see what effect Uranus practices on Venus.
Equation No. (12)
35 km /s x 12104 seconds = 423640 km (421056 km) (0.6%)
- Venus moves during (12104 seconds) a distance = Uranus motion distance during
its day period
- We know that, 12104 km = Venus Diameter
- Equation no. (12) tells us that, there's some consistency between Uranus & Venus
motions – this feature is added to other features show a consistency in motions
between Uranus and Venus…
Equation No. (13)
35 km /s x 120536 seconds = 4218760 km (421056 km x 10)
- Venus moves during (120536 seconds) a distance = Uranus motion distance during
its day period x 10 days
- We know that, 120536 km = Saturn Diameter
- Equation no. (13) shows more consistency between Venus, Saturn and Uranus
motions – because of the deep connection between Saturn and Venus which will
be discussed later
Equation No. (14)
35 km /s x 12756 seconds = 446460 km (449197 km)
- Venus moves during (12756 seconds) a distance = Jupiter Circumference = the
moon orbital triangle base AE
- Equation no. (14) tells us that, there's some consistency between Jupiter & Venus
motions – also – there's a deep consistency between Venus and the moon orbital
triangle data

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Equation No. (15)
35 km /s x 51118 seconds = 1789130 km (=1.8 mkm) (0.6%)
- Venus moves during (51118 seconds) a distance = 1.8 mkm
- 51118 km = Uranus Diameter
- We know that 1 mkm =1 degree
- 1.8 degrees = Neptune Orbital Inclination
Equation No. (16)
35 km /s x 10921 seconds = 382235 km
- Venus moves during (10921 seconds) a distance = the moon orbital distance
- That shows more consistency between the moon and Venus motions –
Equation No. (17)
177.4 deg (Venus Axial Tilt) / (12.195 deg the moon motion angle) =14.54
We know this rate
Uranus Diameter 51118 km / The Moon Diameter 3475 km = 14.7
Uranus Axial Tilt 97.8 deg / The Moon Axial Tilt 6.7 deg = 14.7
Uranus Mass / Earth Mass = 14.7
Venus Mass /Mercury Mass =14.7
2 Saturn diameters / Uranus diameter =14.7
Jupiter Radius / Mercury diameter =14.7
- Between 14.54 and 14.7 (error 1%)
- Equation No. (17) shows the deep consistency between Venus & Uranus Motions.

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3- Saturn Effect On The Solar System Geometry
3-1 The Moon Orbit Regression Monthly
Equation No. (18)
1.8 deg. (Neptune orbital inclination)x 0.8 deg. (Uranus orbital inclination) =1.44 deg.
(The moon orbit regresses per month 1.44 degrees)
Equation No. (19)
(0.8 deg + 0.6 deg) + (0.8 deg + 0.6 deg) + (0.08 deg) = 2 x 1.44 deg.
Equation No. (20)
18 x (0.08 deg) = 1.44 deg.
Equation No. (21)
18 x 3.18 = (180 deg /π)
Equation No. (22)
1.8 deg x 318 = 572.4
Equation No. (23)
5.1 deg x 112.2 = 572.4
Discussion
- The equations from (19 to 22) tell us why the moon orbit regresses monthly = 1.44
degrees – let's discuss these equations one by one …
Equation No. (19)
(0.8 deg + 0.6 deg) + (0.8 deg + 0.6 deg) + (0.08 deg) = 2 x 1.44 deg.
- Equation No. (19) tells that, the value 1.44 degrees is produced by an addition for
0.8 deg (Uranus orbital inclination) +0.6 deg (The Green Box In The Figures)
- Very simple equation, why this is a distinguished one?
- (0.08 deg) this value distinguishes it, for 2 reason, (1st
) it produces (0.8/0.1) and
that needs to use the value 0.1 degree we have produced in the discussion
- (2nd
) reason and the most important, because, it's used one time with each 2 values
of the others! i.e. for one month (1.44 deg) needs (0.08/2)!
- How to find this value??

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Equation No. (20)
18 x (0.08 deg) = 1.44 deg.
- This equation is very similar to the first one – just in place of (1.8 x 0.8) I used ( 18
x 0.08) – it's the same …
- I do that to produce the value (0.08 deg) – and to do that – we have to use (18) in
place of (1.8).
- The difficulty is, 1.8 deg = Neptune orbital inclination, but what's this 18??
Equation No. (21)
18 x 3.18 = (180 deg /π) = 57.24 deg
- This equation tells us how to find the value 18! But why this value has any
relationship with our discussion! Because (346.6 days /12 =28.8 days) and the
value 57.24 is very near to 2 x 28.8 days, where we use only one (0.08 deg) for 2
months (2 x 28.8 days)
Equation No. (22)
1.8 deg x 318 = 572.4
- 318 = (Jupiter Mass / Earth Mass) we have to remember here that, Earth Mass =
the 4 inner planets masses total, means this rate can be used for them also….
- 1.8 (Neptune orbital inclination)
- Equation No. (22) tells us there's here Some Force, this force is produced by
Jupiter /Earth masses rate – and that means – this force is a gravity force – and
means that – Earth gravity is effected by Jupiter mass gravity …. To see better
picture let's remember on more old equation…..
- 149. mkm (Earth orbital distance) = 1047 x 142984 km (Jupiter diameter) the
value 1047 is the sun/ Jupiter masses rate - this equation tells us that – Earth
orbital distance is define by an interaction of Jupiter and the sun masses gravity on
Earth – shortly – if Jupiter isn't found – Earth orbital distance would be a different
one – i.e. to consider that Earth orbital distance is defined based on the sun and

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Earth masses only – this consideration is incorrect- the previous equation gives us
a proof for this claim… the data tell directly that Jupiter Mass is a player in Earth
orbital distance definition…
- If this is a correct conclusion… So … Jupiter /Earth Masses Rate expresses a
gravity force, now this force is showed based on Neptune orbital inclination, why?
Equation No. (23)
5.1 deg x 112.2 = 572.4
- 5.1 deg = the moon orbital inclination …
- 112.2 km /sec = total velocities of Mercury, Venus and Earth
- The idea is easy, the previous equation gives the force (318 x 1.8) and this one
gives the motion -
- Equations (22 and 26) tells us that, masses gravity force causes the motion of 3
planets (Mercury, Venus and Earth) and the 3 planets pulls the moon orbital
inclination….
- i.e. the three planets motions produce the moon orbital inclination by gravity force
found by Jupiter effect on the inner planets masses
- Please Note
- (112.2 /5.1) =22
- Jupiter Mass /Uranus Mass = 22 (error 0.6%)
- What can we conclude form all that? let's suggest one idea and try to prove it:
o The moon orbital inclination is created based on 2 rates each =318 because
Earth mass = the 4 inner planets masses total, so Jupiter uses both rates (2 of
318) in the equation (no.22), one rate only will produce 2.6 degrees but the 2
rates together produces 5.2 degrees (Jupiter orbital distance =5.2 x Earth
orbital distance)…. 5.2 degrees = 5.1 degrees +0.1 degrees is used for Mars
orbital inclination (1.8 deg became 1.9 deg).
o This idea we'll try to prove later … but let's now observe the following…

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- The equations group (19-23) aim to find how to create the value (0.08) to be used
one time in 2 months – as the equation (no.19) tells us… we move with the
equations one by one and we reach to the final equations (22 & 23), the value
(0.08) is disappeared and its place we have the value 57.24 which became 572.4
- i.e. if the equation connected logically, so the value (0.08) is hidden behind the
other values – that means – this geometrical machine which uses 0.08 deg for 2
months to produce (the moon regression 1.44 deg monthly) is a hidden machine
behind other data… any why we see it and we know how it be hidden
- now the next question is ……what's the importance of this value 572.4?
- 580 mkm = 1.16 mkm/sec (light supposed velocity) x 500 seconds
- 500 seconds is required by light known velocity (0.3mkm/sec) to pass Earth orbital
distance…
- 580 mkm – 572.4 mkm = 7.6 mkm
- Light known velocity (0.3 mkm/sec) travels 7.6 mkm in 25.33 seconds where (25.2
deg = Mars Axial Tilt)… that may be the cause behind … mean the value 580
mkm is decreased to be 572.4 mkm because Mars axial tilt consumed 7.6 mkm
- Please, I wish the reader isn't astonished to use 572.4 km as 572.4 mkm without
any explanation… we have many ways to perform that, for example 5.1 deg can be
used as 5.1 mkm, also the value 572.4 km can be multiplied with the moon orbital
diameter 1 mkm and became 572.4 mkm
- The point is that, I believe (Planet Motion Depends On Light Motion) because
of that I use light motion features simply to explain the planets data and don't be
very restricted with the units because light motion can redefine the units.

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3-2 The Triangle (CZN) Analysis.
- The Triangle CZN is apart of the moon orbital triangle – (Figure no. 1) – let's
explain how I created this triangle ….
- We know the triangle CZB where
o (BZ = 18586 km, CB =86000 km and CZ = 88000 km)
o Angle (ZCB) =12.195 degrees
o Angle (CZB) =77.805 degrees
- I have created the triangle CBN is a typical one to the triangle CBZ, but we know
o B is the perigee point where EB =363000 km
o That means, the triangle CBN is found before perigee point and the moon
doesn't move through the distance BN because the moon can't be more near
to Earth than the perigee point (r= 363000 km).
Now let's analyze this triangle CZN in following…
(1st
Point- The Triangle Data)
- CZ = CN = 88000 km (The Moon Daily Displacement)
- The angle ZCN = 2 x (12.195 deg) = 24.39 degrees
- ZN = (2 x ZB) = 37172 km
- Both angles (Z) and ( N) = 77.8 degrees
- The triangle perimeter = 213172 km
- The triangle area = 1598.4 million km2

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(2nd
Point- 0.9856262 degrees = 1000 km)
- This rate is used in the moon orbital triangle, let's try to discover that in following..
- The triangle CBZ has a base (BZ = 18586 km) and its angle (ZCB) = 12.195 deg
- let's make this angle (ZCB) = 13.177 degrees
- So the base ZB will be = 19604 km
- Based on that
o 13.177 degrees – 12.195 degrees = 0.98562 degrees
o 19604km - 18586 km = 1000 km ………..i.e.
o Each 1000 Km Be Equivalent To 0.98562 Degrees (We will keep this rate
to be used generally in the solar system geometry).
(3rd
Point- the triangle ZCN (Data) analysis)
A- (77.8 deg /12.195 deg) = (153.3 h /24 h)
o Notice (1)
o (153.3 h Pluto day / 24 h solar day) = (Earth velocity / Pluto Velocity)
B- The triangle (CZN) perimeter = 213172 km
o = 17.6 x 12104 km (Venus Diameter)
o = 5.6 x 38040 km (Venus Circumference)
o = 5 x 43000 km (the distance between perigee and apogee)
o Notice (2)
o 5.6 deg= 5.1 deg (the moon orbital inclination) + 0.5 deg (the moon angular)
C- The triangle (CZN) area = 1598.4 mkm but (Uranus Neptune Distance
=1622.7 mkm (error 1.5%)
o 1622.7 mkm x 0.363 mkm (Perigee Radius) = 590 mkm
o 1622.7 mkm x 0.384 mkm (the moon orbital distance) = 627 mkm
o 1622.7 mkm x 0.406 mkm (Apogee Radius) = 655 mkm
627 mkm = Jupiter Earth distance 655 mkm = Jupiter Saturn Distance

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(4th
Point- Uranus Axial Tilt Effect on the triangle)
I- Uranus Axial Tilt Effect On Earth Axial Tilt (23.45 degrees)
Equation no. (3-1)
51118 km = 4x 12756 km (Earth diameter)
97.8 degrees = 4 x (23.45 deg) + 4 degrees
Equation no. (3-2)
5.1 deg (The Moon Orbital Inclination) = 4 degrees +1.1 degrees
II- Uranus Axial Tilt Effect On the triangle CZN
Equation no. (3-3)
24.39 degrees x 4 = 97.56 degrees
Equation no. (3-4)
97.8 deg (Uranus Axial Tilt) – 97.56 degrees = 0.24 degrees …..But
Equation no. (3-5)
0.24 million km = 4.7 km/s x 51118 km = 47.4 km/s x 5040
Discussion
- Equations (3-1) and (3-2) tells that, Earth axial tilt is created from Uranus axial tilt
based on the same rate by which Earth diameter is created from Uranus diameter –
simply, Earth diameter = 0.25 Uranus diameter and by this same rate Earth axial
tilt =0.25 Uranus Axial Tilt - But –
- 4 degrees are rest, the moon orbital inclination needs these 4 degrees perfectly to
add to the moon orbital triangle base declination (1.1 deg) to produce the result 5.1
degrees (the moon orbital inclination)
- So the moon motion is considered as a part of Earth motion by Uranus effect and
because of that- Uranus gives Earth its 0.25(Uranus axial tilt) and gives the moon
4 degrees.
- This explanation is in consistency with our previous idea – that (Venus axial tilt) is
created as a rate of its diameter with Mars, but here Earth with Uranus….

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- Now we need to discuss the point no (II)….
- The Triangle Angle (ZCB) =24.39 degrees
- 97.8 deg - (24.39 degrees x 4) = 0.24 degrees
- I suggest this value (0.24 degrees) has specific task in the solar system geometry
- Let's study it with more details (the astonished idea is, Saturn Is Created Based
On The Moon Orbit Data)

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3-3 Saturn Diameter Analysis.
( 2 Saturn Diameters = 241072km) (Point No. A)
I-Data
(A)
97.8 deg - (24.39 degrees x 4) = 0.24 degrees
(Because 1 deg= 1mkm so 0.24 degrees = 0.24 mkm = 2 Saturn Diameters)
(B)
(177.4/12.195)= (97.8/6.7)= (51118 km /3475 km) = (0.24 mkm/ 51118 km)
(C)
(1) Mercury moves during 5040 seconds a distance = 2 Saturn Diameters
(2) Pluto moves during 51118 seconds a distance = 2 Saturn Diameters
(3) Mars moves during 5040 seconds a distance = Saturn Diameter
(4) Venus moves during 6792 s a distance = 2 Saturn Diameters(1.4%)
(5) Earth moves during 12104 s a distance = 3 Saturn Diameters
(6) Earth moves during 12756 s a distance = Saturn Circumference
(7) Pluto moves during 12756 s a distance = Saturn Radius
(8) Saturn moves during 49528 s a distance = 4 Saturn Diameters
(9) Mars moves during 49528 s a distance = Saturn Diameter x π2
(10) Mercury moves during 49528 s a distance =2 Saturn Diameters x π2
(11) Neptune moves during 142984 s a distance =2Saturn Circumference(2%)
(12) Uranus Moves during 120536 s a distance = 819645 km = 2 x 382118
(Saturn Circumference) x 1.0725 (1%)
(13) Earth moves during 7511 s a distance =2 Saturn Diameters x1.0725
(14) Jupiter moves during 142984 s a distance = Saturn Radius x π3
Is Saturn a point for motions connection??

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( 2 Saturn Diameters = 241072km) (Point No. B)
Equation no. (3-6)
19300 km x 120536 km (Saturn Diameter) =1163 million km
How to understand this equation? Let's remember one more table here
The Planet Circumference And Its Day Period
Planet and its day
period
Its Circumference Its Motion distance
during its day period
The rate
Mercury 175.94 days 15334 km 720.7 million km 47000
Venus 116.75 days 38041 km 352.4 million km 9280
Earth moon 29.53 days 10921 km 71.16 million km 6510
The Earth 24 hours 40080 km 2.58 million km 64.3
Mars 24.7 hours 21346.6 km 2.1467 million km 100.5
Jupiter 9.9 hours 449197.5 km 466884 km 4%
Saturn 10.7 hours 378675 km 373644 km 1.3%
Uranus 17.2 160656.5 km 421056 km 2.62
Neptune 16.1 155660 km 312984 km 2
Pluto 153.3 7511.4 km 2.59 million km 345.3
Total 1277423 km 1153.15 million km 902.7
The Planets motions distances total during they days periods = 1153.15 mkm
But
Mercury +Venus +the Moon motions distances total during they days = 1144.26 mkm
The Rest Planets distances total = 1153.15 mkm - 1144.26 mkm = 8.89 mkm
Equation no. (3-6) (continued)
What's this 1163 mkm? It's (1 day) of (the 3 planets) + (2 days) of (the rest planets)
(3 planets are Mercury, Venus and The Earth Moon).
1163 million km =1144.26 mkm + 8.89 mkm + 8.89 mkm
And

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What's this 19300 km? this value = (366556km /19) where 366556km = the outer
planets diameters total….( 19 years (Metonic Cycle).
Let's see some more puzzled data
More Puzzled Data concerns Equation no. (3-6) (continued)
- 1163 million km =1144.26 mkm + 8.89 mkm + 8.89 mkm
- 1163 mkm =0.08 x (120536 Saturn)2
- 1153 mkm = 1375 days x 86400 seconds x 9.7 km/sec (Saturn Velocity)
- 1375 mkm = Mercury Saturn Distance
o Why Saturn velocity (9.7 km/sec) uses the distance 1375 mkm as a period of
time (1375 days)?
o Why does Saturn motion uses this distance 1375 mkm as a period of time?
Why this distance is specific one?
o 455.8 mkm (Mars orbital diameter) x 3 = 1375 mkm
o And the rate 3 = (Mercury Day Period / Mercury Rotation Period)
o Logically Saturn dos this motion where (Saturn orbital distance 1433 mkm =
Mars Orbital Circumference)
o Additional Equation no (3-A)
o Where 9.7 km/sec (Saturn Velocity) doesn't equal (Light Velocity)?
o 0.3 mkm /sec (light known velocity) = 9.7 km/s x 30589 seconds (1%)
o Where Uranus orbital period 30589 days = (88 x 346.6) +88 (Mercury
Orbital Period) and (346.6 days = The Nodal Year).
o Equation (3-A) tells that, Saturn depends on Uranus orbital period to move
by a velocity = light known velocity (0.3 mkm/sec) but how??
o Let's add one more additional equation
o Additional Equation no (3-B)
o 30589 days (Uranus orbital period) x 10747 days (Saturn orbital period) =
328739983 days
o 328739983 days = 86400 x 10.7 x 354.39 days

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o Equation Ni (3-B) tells, If 1 sec of Saturn = 30589 seconds or Uranus, in
this case Uranus will see Saturn motion as a light beam motion (0.3
mkm/sec) but how to explain these results (86400 x 10.7 x 354.39)??
o Additional Equation no (3-C)
o 9.7 km /s x 10.7 hours (x 3600) = 354.39 x1042 (=354.39 x 6.8 km/s x
153.3 s) (error 1%)
o Equation (3-C) tells that, Saturn motion distance during its day = Uranus
motion distance during (354.39 days) each day = (153.3 seconds)
- We have 3 basic information in this point let's summarize them:
o 1153 mkm = 1375 days x 86400 seconds x 9.7 km/sec (Saturn Velocity),
this equation tells, During 1375 days Saturn moves a distance = the solar
planets motions distances total during their days periods, (1st
feature), also
Saturn moves during its day period a distance = its circumference (2nd
feature), Why do we need these 2 features? Because (almost) the perfect
motion definition was (planet moves during its day period a distance = its
circumference) which Saturn does, but no the other planets – for that –
Saturn moves during (1375 mkm) a distance equal the planets motions
distances total during their days to correct the geometrical structure – that
means- the solar system geometry needs Saturn to do this motion to be
repaired.
o Saturn moves In Place Of All Solar Planets Generally, because of that,
17.75 mkm (Planets motions distances total/ solar day) x 511.1= 9010 mkm,
Where, 511.1 degrees = The Planets Axial Tilts Total, Note please..
o 9010 mkm = 2π x 1433.5 mkm (Saturn orbital distance), we know that,
light moves 9010 mkm and its follower planet moves 1433.5 mkm, that tells
Saturn motion is representative in place of all planets motions.
o Saturn motion relative to Uranus motion, shows that, Saturn moves as a
light beam relative to Uranus motion…

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o That explains why Saturn is representative in place of all planets motions,
because Saturn is considered a light motion and that makes the upper
boundary for planets motions.
Equation no. (3-7)
4.7 km/sec x 41 seconds x 100 = 19270 km
149.6 mkm = 15327.8 x 19300 km (error 1%)
- Equation no. (3-7) tells that, Earth orbital distance definition is effected by this
value (19300 km) which is produced by Pluto motion during 41 seconds (where 41
degrees = the solar planets orbital inclinations total), multiply with (100) which is
produced under the moon orbital inclination as we have discussed (91.1 x 1.1)
- Earth orbital distance uses this value (19300 km) with Mercury Circumference
(15327 km) to define Earth orbital distance (149.6 mkm (with error 1%) – please
note this 1% isn't error because we know that it's used geometrically, so it may be
caused by Uranus axial tilt (sin (97.8 deg) = 0.99) effect on Earth orbital distance
Equation no. (3-6) (continued)
- Let's summarize it in following
I. Saturn is the motions connection Point
II. The solar system general motion used (1 day) of the (3) planets in
consistency with (2 days) of the rest planets
III. The solar system motion is one motion.
IV. The solar system is similar to a machine of gears all planets are gears
transports their motions from one to another and the system uses Saturn as
its general connection point for all planets motions
V. Saturn is created after the planets migration to create a general stability for
the solar system geometry
VI. Metonic Cycle is The General Motion For All Planets

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3-4 Saturn Diameter Effect
W need to take an eye on Saturn Data Table here again
I - Data
( 2 Saturn Diameters = 241072km)
1- Mercury moves during 5040 seconds a distance = 2 Saturn Diameters
2- Pluto moves during 51118 seconds a distance = 2 Saturn Diameters
3- Mars moves during 5040 seconds a distance = Saturn Diameter
4- Venus moves during 6792 s a distance = 2 Saturn Diameters(1.4%)
5- Earth moves during 12104 s a distance = 3 Saturn Diameters
6- Earth moves during 12756 s a distance = Saturn Circumference
7- Pluto moves during 12756 s a distance = Saturn Radius
8- Saturn moves during 49528 s a distance = 4 Saturn Diameters
9- Mars moves during 49528 s a distance = Saturn Diameter x π2
10- Mercury moves during 49528 s a distance =2 Saturn Diameters x π2
11-Neptune moves during 142984 s a distance =2Saturn Circumference(2%)
12-Uranus Moves during 120536 s a distance = 819645 km = 2 x 382118
(Saturn Circumference) x 1.0725 (1%)
13-Earth moves during 7511 s a distance =2 Saturn Diameters x1.0725
14-Jupiter moves during 142984 s a distance = Saturn Radius x π3
This data gives us a chance to conclude the following Equations

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II - More Data
Saturn diameter Data leads us to the following equations
(I)
08.10
seconds5040
DiameterUranuskm51118
km/sec4.7VelocityPluto
km/sec47.4VelocityMercury
== (error 0.5%)
(II)
347.1
seconds5040
DiameterMarskm6792
km/sec35VelocityVenus
== (error 0.5%)
(III)
6.1
1.5xseconds5040
DiameterVenuskm12104
km/sec29.8VelocityEarth
== (error 0.6%)
(IV)
682.1
DiameterMoonthekm3475
1.16x5040
km/sec27.78VelocityMoonEarth
== (error 1.4 %)
(V)
988.1
4x5040
nceCircumfereEarthkm40080
km/sec24.1VelocityMars
== (error 1 %)
(VI)
637.3
7.8xseconds5040
DiameterJupiterkm142984
km/sec13.1VelocityJupiter
== (error 0.5%)
(VII)
9134.4
2xseconds5040
DiameterNeptunekm49528
km/sec9.7VelocitySaturn
== (error 0.5%)
(VIII)
034.7
3.4xseconds5040
DiameterSaturnkm120536
km/sec6.8VelocityUranus
== (error 1 %)
(IX)
777.8
0.08)(seconds5040
km/sec5.4VelocityNeptune
=
+
=
π
(error 0.3 %)

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III –Discussion
There are many important features in the previous (9) equations … As
- Almost all equations produce (2 Saturn Diameters) or its folds, that means,
Saturn is a common gear in the machine of gears, it's the cornerstone on which the
machine stability depends – but what geometrical rule this value (2 Saturn
diameters) does in the solar system geometry? We still need to discover
- Planets velocities are defined as functions in 3 parameters which are:
o Mercury velocity (47.4 km/sec)
o A Planet Diameter or Circumference
o Mercury Period 5040 seconds (where Mercury day period needs 5040
seconds to be 176 solar days).
- Many questions are left, but before all Why planet velocity is a function in its
diameter rate?! We may remember
o Saturn moves during its day period a distance = its circumference
o Jupiter moves during its day period a distance = its circumference (+4%)
o Because of Jupiter error (4%), so we have to consider that, only Saturn does
this astonished task to move during its day period a distance = its
circumference, this data tells that the question gives us a correct reference
that planet velocity depends on its diameter rate, but why??
o Mercury period 5040 seconds is still one more puzzle before us, why this
period is so important as such?! It's just a period needed to make Mercury
day =176 solar days, why this information is so essential in the solar system
geometry?
o We need to look at these equations one by one – because – they have many
deep data… let's do it in following…

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The Equation Analysis
Equation No. (I)
08.10
seconds5040
DiameterUranuskm51118
km/sec4.7VelocityPluto
==
(Error 0.5%)
- Let's remember one more equation!
o 4.7 km/sec x 10921 seconds = 51118 km
o This equation told us that, Pluto moves during a period (10921 seconds), a
distance =51118 km = Uranus diameter, but we know that, 10921 km = the
Earth moon circumference…
o Equation no. (I) tells that, 4.7 km/sec x 51118 seconds = 240255 km
o Equation no (I) tells that, Pluto moves during 51118 seconds a distance = 2
Saturn Diameters. Now Pluto does this complex task in 2 steps, in (1st
)
Pluto uses the moon circumference (10921) to move a distance = 51118 km
= Uranus diameter and then Pluto uses this produced distance 51118 km to
move a distance = 2 Saturn Diameters….. WHY??
o (2 Saturn diameters) 240255 seconds x 4.7 km /sec= 1.12919 mkm
1.12919 mkm = 2.5 x Jupiter Circumference
1.12919 mkm = 28.3 x Earth Circumference
1.12919 mkm = 3.1 x 363000 km (Perigee Radius)
o Almost this is the way by which planets data are created, planet moves using
planets diameters, circumferences or distances as periods of time and by its
motion this planet produce more data be in consistency with the used data…
o i.e. it's NOT so astonished, that Pluto moves a distance = Uranus diameter
during a period = 10921 seconds (the moon circumference), it's the
geometrical system, the planet moves to do that, and to move (or produce)
other planets diameters, circumferences or defined distances by using other
planets diameters, circumferences or defined distances as periods of time!

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So someone looks at a cat and think (it's so astonished this cat can breathe!)
but it's Not astonished – Because all creatures do the same …!
o BUT
o we should not lose the treasure for astonishing data- the treasure – which we
waited for long time, the planet tells us how planets data are defined and
why this data is in so high consistency with each other –so we have hope to
explain many strange data… for example
3475 km (the moon diameter) x 3.4 = 12104 km (Venus Diameter)
3475 km (the moon diameter) x 1.9 = 6792 km (Mars Diameter)
12756 km (Earth diameter) =6792 km (Mars Diameter) x 1.9
where
(3.4 deg= Venus orbital inclination & 1.9 deg= Mars Orbital Inclination)
Shortly
o By Motion Of One Planet, Other Planets Data Are Defined
o Why, how and by what force?!
o We still try to discover…but we have here 2 conclusions ready to be written.
Conclusions
- 2 Saturn diameters is the distance used to be A common Gear in the machine
of gears, shortly, this distance is the planets motions aim.
- By Motion Of One Planet, Other Planets Data Are Defined

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Equation No. (II)
347.1
seconds5040
DiameterMarskm6792
km/sec35VelocityVenus
==
(Error 0.5%)
- Let's analyze this equation no. (II) in following
o 35 km/sec x 6792 seconds = 237720 km
o 2 Saturn Diameters = 241072 km – so the error should be = (1.4%) how it
can be = 0.5%?!
o 47.4 km/sec x 5040 seconds = 238896 km = 241072 km (with error 1%)
o What does that mean?
o Mercury and Venus motions aim toward (0.99 x 2 Saturn diameters),
o The previous 2 equations are so accurate equations and show this difference
(1%) clearly … because the values are just planets diameters and velocities
o Equation no. (VII) gives this same accuracy because just planets diameters
are used, and its error is just (0.5%)…
o We can conclude clearly that, Mercury and Venus move toward the rate
(0.99 x 2 Saturn Diameters), this conclusion depends on the period 5040
seconds which is so accurate period defined by Mercury day period.
o We know that, the rate (0.99) can be produced by Uranus Axial Tilt effect,
where sin (97.8 deg) = 0.99, and we have seen that (2 Saturn Diameters) are
defined by Uranus axial tilt in previous equation… let's remember it
97.8 deg(Uranus Axial Tilt) - (24.39 degrees x 4) = 0.24 degrees
- For that, Mercury and Venus are effected by Uranus Axial Tilt, and move toward
the value (0.99 x 2 Saturn diameters).

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Equation No. (III)
6.1
1.5xseconds5040
DiameterVenuskm12104
km/sec29.8VelocityEarth
==
(error 0.6%)
- Equation no. (III) tells us…
o 29.8 km/sec x 12104 seconds = 3 x120536 km …..But…
o 47.4 km/sec x 5040 seconds = 2 x120536 km (error 1%)
o That explains why we have (1.5) in the equation, because Mercury motion
passes a distance = 2 Saturn diameters but Earth motion passes a distance =
3 Saturn diameters
- Point (No. A)
o 3 x120536 km = 0.363 mkm = (Perigee Radius) (error 0.6%), also
o 3 x 40080 km (Earth Circumference) = 120536 km (Saturn Diameter)
o But
o (3475 km the Earth moon diameter)2
= 100 x 120536 km (Saturn Diameter)
(90.9 degrees x 1.1 degrees =100)
- Equation no. (III) tells that, Earth moves during (12104 seconds) a distance =
Perigee Radius, that tells us, the moon orbit is created by cooperation between
Earth and Venus data (12104 km = Venus Diameter)
- Where the perigee radius (363000 km) = 3 x Saturn diameters, this data, and the
moon diameter equation tells that, Saturn diameter is created based on the moon
orbit data.. (Also Saturn Venus relationship may be created depending on the
moon and Earth data)
- Point (No. B)
o Earth moves during (40080 seconds) a distance =1.2 mkm, but 40080 km =
o (12104/5040) = 2.4
o Is there any motions interactions here?

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o Earth moves during (40080 seconds) a distance =1.2 mkm, but 40080 km =
Earth Circumference….. So
o 2.4 mkm needs Earth to move during a period = 2 x 40080 seconds
o It's 2 periods
o But
o 5040 seconds is required for Mercury day period (4222.6 hours), if Mercury
day gets this period (5040 s) it will be =176 solar day =2 x 88 days
o Also (2 x 88 days ) has 2 periods ….
So
o What connection between 88 days and 1.2 mkm ?!
o (88 days/58.66 days) = (1.8 deg/1.2 deg) =1.5 (But 1.8=1.2+0.6)
o Where (58.66 days = Mercury rotation period), and 1.8 deg = Neptune
orbital inclination).
Please Note
The moon equation (IV) will be discussed in the end of the equations discussion..

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Equation No. (V)
988.1
4x5040
nceCircumfereEarthkm40080
km/sec24.1VelocityMars
==
(error 1 %)
- The error (1%) is found because Mercury motion during 5040 seconds passes q
distance = 2 Saturn diameters x 0.99 (Mars and Earth equation has no error)
- Mars moves during (40080 seconds) a distance = 8 Saturn diameters
- BUT Mercury moves during 5040 seconds a distance = 2 Saturn diameters
- That's Why the equation uses 4
- But we should notice that, the number (4) is a feature of Earth diameter! why?
because Earth diameter 12756 km x 4 = 51118 km (Uranus diameter)
- The directed data gives us no room for our explanation, Uranus tells us strongly
that, Earth is followed it, Earth diameter is created by a direct effect of Uranus as
we have discussed before.. that explains the number (4) using….
- Notice No. (1)
- 2 Saturn diameters x 0.98 = 943817 km (= the orbital triangle perimeter ACE)
Please review the moon orbital triangle (figure no. 1)
- That again tells us, Saturn diameter (and other data) is created based on the moon
orbital motion (also we remember that 10747 days Saturn Orbital Period = 365.25
days x 29.53 days the moon synodic month)
- Notice No. (2)
- Now we know that, Perigee radius (0.363 mkm), and the perimeter of triangle
(ACE) and the dimension AC in the moon orbital triangle (figure no. 1) all are
created based on Saturn diameter and Earth motion during (12014 s) and Mars
motion during (40080 s) which shows clearly the motions interactions

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Equation No. (VI)
637.3
7.8xseconds5040
km/sec13.1VelocityJupiter
==
(error 0.5%)
- Jupiter moves during (142984 seconds) a distance = 2 Saturn Diameters x7.8
- And, Mercury moves during (5040 seconds) a distance = 2 Saturn Diameters
- (142984 /5040) = 28.3 where (28.3 deg = Neptune Axial Tilt)
- Why 7.8? Because (Uranus axial tilt 97.8 deg = 90 + 7.8 deg) so 7.8 deg is the
result of Uranus axial tilt perpendicularity (on the moon orbital triangle base AE)
and the result effect on the inner planet motions… but we need to analyze this
value 7.8 Specifically! (7.8= 7 deg Mercury orbital inclination + 0.8 deg Uranus
- That shows why the value 7.8 is used here, in comparison between Jupiter and
Mercury motions.
- Please Remember
- 142984 km = 13.1km/sec x 10921 seconds, this old equation told us that, Jupiter
moves during (10921 s) a distance = 142984 km = its diameter and then Jupiter
uses its diameter as a period of time in our equation no (VI) to move a distance =
7.8 x 2 Saturn Diameters (Mercury motion).
- But What's the relationship between 7.8 and 5040?
- 655.7 h (The Moon Rotation Period) x 7.7 = 5040 h
- This idea we have discussed before, when we concluded that, Mercury day is
decreased with 5040 seconds because of the Earth moon motion – and the previous
equation supports that-but the difference (7.7-7.8 =0.1)! is it a puzzle?! No
- We know it, the triangle declination angle 1.1 deg – 1 degree = 0.1 deg

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Equation No. (VII)
9134.4
2xseconds5040
DiameterNeptunekm49528
km/sec9.7VelocitySaturn
==
(error 0.5%)
- Saturn moves during (49528 seconds) a distance = 4 Saturn Diameters
- The equation is clear and defines Neptune Diameter
- So Neptune diameter is defined based Saturn motion, that may explain why
o 2 Saturn diameters – Jupiter diameter = 2 Neptune diameters (1%)
Equation No. (VII)
034.7
3.4xseconds5040
DiameterSaturnkm120536
km/sec6.8VelocityUranus
==
(error 1 %)
- Uranus moves during (120536 seconds) a distance = 3.4 x (2 Saturn diameters)
- Why 3.4?
- 3.4 deg = Venus orbital inclination…. And we know
- 177.4 deg (Venus Axial Tilt) + 3.4 deg (Venus orbital inclination) = 180.8 deg
- Where 180.8 deg = 0.8 deg (Uranus orbital inclination) +90+90
i.e.
- 3.4 deg shows Uranus effect on Venus data, that's why it's used here

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Equation No. (IX)
777.8
0.08)(seconds5040
km/sec5.4VelocityNeptune
=
+
=
π
(error 0.3 %)
- Neptune moves during (142984 sec.) a distance =(π+0.08) x (2 Saturn diameters)
- What's 0.08?
- 0.8 Uranus orbital inclination x 0.1 deg = 0.08 deg
- Neptune motion uses Jupiter diameter as a period of time because Neptune orbital
distance is created by (14%) of Jupiter energy sent to Pluto and reflected from
Pluto to Neptune and from Neptune to the inner planets
- Simply Neptune depends on Jupiter energy to create its data and because of that
Jupiter diameter is used here…
- Uranus motion interaction with Neptune is one pillar of the moon orbit geometrical
creation we know that from different data for example
o 1622.7 mkm (Uranus Neptune distance) x 0.363 = 589 mkm
o Where 0.363mkm (perigee radius), 0.384 mkm (the moon orbital distance)
and 0.406 mkm (apogee radius) –and 627 mkm (Earth Jupiter distance), and
655 mkm (Jupiter Saturn distance)
o Also
o 1.8 deg (Neptune orbital inclination) x 0.8 deg (Uranus orbital inclination) = 1.44
o Where 1.44 deg the moon regresses monthly

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Equation No. (VI)
682.1
DiameterMoonthekm3475
1.16x5040
km/sec27.78VelocityMoonEarth
==
(error 1.4 %)
- This equation doesn't produce Saturn diameters, why?
- Because the moon motion is a direct function in light motion 1.16 mkm/sec
- Saturn diameter is created based on the moon motion data but the moon motion
data is created based on light motion – we know that
o 10921 km (the moon circumference) x 27.3 days = 0.3 mkm
o This old equation told us that, if the moon rotates around its axis one per
solar day as the Earth does, so the moon will move during its orbital period
(27.3 days) a distance = 0.3 mkm = light motion distance per a second (light
known velocity 0.3 mkm/sec)
o 10921 km (the moon circumference) x 86400 s = 940 mkm
o This old equation also told us, if Earth revolves around the sun a complete
revolution in 1 solar day only, so the moon circumference will = its motion
distance for 1 second.
o 43000 km (perigee apogee distance) x 27.3 x 0.99= 1.16 mkm
o This also told us, if the moon is a point only (without diameter) and moves
from perigee to apogee once per solar day, so it will pass during its orbital
period (27.3 days) a distance = 1.16 mkm = light motion per 1 second
(light6 supposed velocity 1.16 mkm/sec)
o That tells the moon diameter is created based on a direct function with light
motion and because of that its equation doesn't produce Saturn diameters,
because Saturn diameter is found in the moon notion different data basically

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References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Moon Orbital Triangle (General discussion) (Revised) (II)

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