Paper hypothesis
- Uranus orbital inclination 0.8 degrees is created by an effect of the Earth moon orbital motion.
o Jupiter diameter 142984 km = 13.1 x 10921 km (the moon circumference)
o But
o Jupiter velocity =13.1 km/sec
o And
o Jupiter orbital circumference= Jupiter circumference x the moon circumference
o The data tells interesting ideas!
o Jupiter has to move during 10921 seconds to pass a distance = its diameter, now the moon circumference (10921 km) is used as time period! With some analysis we have found this behavior is followed by many other planets!
o The Earth moon also has to rotate around its axis 13.1 time to move a distance = 142984 km = Jupiter diameter – where the moon rotation period is 27.3 days, the 13.1 time consumes around one year – so it's interesting to rotate for a defined period of time!
o The value (13.1) has still has many interesting forms, for example 13.18 degrees = the moon motion degrees per solar day! Also
o 13.18 degrees = the moon motion degrees per solar day/ 0.526 degrees (Mars motion degrees per solar day) =25.2 (where Mars axial tilt =25.2 deg)
Gerges Francis Tawdrous +201022532292
Artificial Intelligence In Microbiology by Dr. Prince C P
Uranus Is Perpendicular On Earth Moon Orbit (III)
1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Uranus Is Perpendicular On Earth Moon Orbit (III)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 16th
November 2020
Abstract
Paper hypothesis
- Uranus orbital inclination 0.8 degrees is created by an effect of the Earth
moon orbital motion.
o Jupiter diameter 142984 km = 13.1 x 10921 km (the moon circumference)
o But
o Jupiter velocity =13.1 km/sec
o And
o Jupiter orbital circumference= Jupiter circumference x the moon circumference
o The data tells interesting ideas!
o Jupiter has to move during 10921 seconds to pass a distance = its diameter,
now the moon circumference (10921 km) is used as time period! With some
analysis we have found this behavior is followed by many other planets!
o The Earth moon also has to rotate around its axis 13.1 time to move a
distance = 142984 km = Jupiter diameter – where the moon rotation period
is 27.3 days, the 13.1 time consumes around one year – so it's interesting to
rotate for a defined period of time!
o The value (13.1) has still has many interesting forms, for example 13.18
degrees = the moon motion degrees per solar day! Also
o 13.18 degrees = the moon motion degrees per solar day/ 0.526 degrees
(Mars motion degrees per solar day) =25.2 (where Mars axial tilt =25.2 deg)
o ALSO
o 1.16 million km = 13.18 x 88000 km (the moon daily displacement = 88000
km) and light supposed velocity =1.16 mkm/sec
o There's surely a geometrical reason behind this data!
- So I have discovered this value 130 km (Jupiter motion per 10 seconds), it's
incredible value as a key for any door- by analyze this value using the paper
hypothesis can be proves – the paper tries to do that
2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Uranus & Jupiter Motions Interaction
1-1Their Motions Interaction In The Earth Moon Orbit
Let's review The Earth Moon Orbital Triangle
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees
3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
Let's review and correct the moon orbital triangle data
(1st
Point)
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and the
outer circle is apogee orbit – and we have calculated the tangent
AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435 degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =47513.7 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg) (ACD
= 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees
4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
1-2 Uranus Orbital inclination 0.8 degrees
In Uranus Orbital inclination discussion we will use the value 131 km
Jupiter moves during 10 seconds 131 km and we try to show Uranus & Jupiter
interaction by examine the using of this value 131 km in the solar system
Geometry
I- Data Analysis
Equation No. 1
0.08 second x 13.1 km/sec = 0.8 degrees x 1.3 degrees
- Equation No. (1) tells that, during 0.08s, Jupiter moves a distance = 1.3 x 0.8 km,
where Uranus orbital inclination =0.8 degrees and Jupiter orbital inclination =1.3
degrees – that tells us both orbital inclinations are created based on each other by
Jupiter motion during this period 0.08 seconds –
- to support this meaning ….
- (Uranus axial tilt / Jupiter axial tilt) = π3
(approximately), that tells there's some
interaction found between both planets different data…
- But
- What's this 0.08 seconds?
- In the moon triangle, we have found that the distance (AB = 181843 km) is a basic
distance in the moon orbital triangle –
- The moon orbital circumference at perigee radius =2.28 mkm but
- 181843 km /2.28 mkm = 0.08
(Remember, 2872.5 mkm Uranus orbital distance = 2.28 mkm x 1260)
- Please Note
- The previous equation is so complex, but we need it here because the paper is
written for it and this is the proof for the paper hypothesis – the next equations can
show the meaning clearly
Equation No. 2
49197 km (Jupiter circumference) = 131 x 3475 km (The Earth moon diameter)
Equation No. 3
3475 km (the moon diameter) = 131 x 26.7 (Saturn axial tilt =26.7 degrees)
- The value 131 km is Jupiter motion distance during 10 seconds
- Equations No. (2) and (3) tells that the moon diameter is created as a function
Jupiter motion during 10 seconds (131 km). Clearly the moon diameter is created
based on this motion and based on the moon diameter with this motion Jupiter
circumference is created. that tells us why (Jupiter orbital circumference 4900
mkm= Jupiter circumference x The Earth moon circumference. (i.e. The Moon Is
Created Based On Jupiter Motion)
- Saturn axial tilt 26.7 degrees is a common value because, as we know 26.7+90
=116.7 degrees = 116.75 days (Venus day period) and we know that the Earth
moon distance at apogee 406000 km = 3475 (the moon diameter) x 116.7
5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
Equation No. 4
3 million km = 131 km x (655.7 seconds x 35 km/sec)
- 35 km/sec = Venus Velocity
- 655.7 hours = the earth moon rotation period
- 131 km = Jupiter motion distance during 10 seconds
- Equation No. (4) is the main motor in our discussion, and the most important one,
- It tells that clearly, Jupiter moves as a light beam
- i.e.
- when light known velocity travels for (10 seconds) and moves 3 mkm, during this
same period, Jupiter and Venus motions get interaction based on the moon rotation
period and cause to pass a distance = 3 million km
- means,
- Jupiter and Venus interaction causes Jupiter motion distance during 10 seconds be
considered as light motion during 10 seconds –
- The interaction between 3 planets perform a light motion result
Please Note
- The value 130 km is a common value in the solar system motion – because of that
Equation No. (5)
A-
130 km = 5.4 x 24.1
- Where
- 5.4 km/sec = Neptune velocity, and 24.1 km/sec = Mars velocity,
- In this equation, when Neptune uses its velocity Mars provides the period of time
and vice versa, both motions save the same result 130 km
B-
130 km = 4.7 km/sec x 27.3
- 4.7 km/sec = Pluto velocity, and 27.3 days = the Earth moon orbital period which
is used here as 27.3 seconds
C-
130 km = 9.7 km/sec x 13.4
- 9.7 km/sec = Saturn velocity
- 13.4 = (13.18 degrees /0.985 degrees) where 13.18 deg = the Earth moon motion
degrees per solar day, 0.985 degrees= Earth motion degrees per solar day
6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
D-
130 km = 6.8 km/sec x 19 seconds
- 6.8 km = Uranus velocity
- 19 = Uranus Axial Tilt / The Moon Orbital Inclination
E-
130 km = 112 km/sec x 1.16
- 112 km/sec (total velocity of Mercury + Venus + Earth)
- 1.16 mkm/sec (light supposed velocity)
- The result should be 130 million km …. But
- The moon orbital diameter =1 million km – because of that- the result is 130 km
F-
232.7 degrees = 130 km x 1.8
- 232.7 degrees = The Inner Planets Axial Tilts Total
- 1.8 degrees = Neptune Axial Tilt
G-
130 degrees = π x 41.4 degrees
- 41 degrees = The Solar Planets Orbital Inclinations Total
- 232.7 degrees = The Inner Planets Axial Tilts Total
- 1.8 degrees = Neptune Axial Tilt
- 112 km/sec (total velocity of Mercury + Venus + Earth)
- 1.16 mkm/sec (light supposed velocity)
- The result should be 130 million km …. But
- The moon orbital diameter =1 million km – because of that- the result is 130 km
Please remember -
(a)
177.4 deg (Venus axial tilt) + 3.4 deg (Venus orbital inclination) = 180.8 degrees
(90 deg +90 deg+0.8 degree Uranus orbital inclination)
(b)
97.8 degrees (Uranus axial tilt) = 90 deg +7 degrees (Mercury orbital inclination)
+ 0.8 degrees (Uranus orbital inclination)
7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
II- Discussion
The paper claims that
- Uranus orbital inclination (0.8 degrees) is created based on the Earth moon orbital
motion – Perfectly as tries Equation No. (1) to tell us
- Let's remember why this hypothesis is suggested…
o Jupiter diameter 142984 km = 13.1 x 10921 km (the moon circumference)
o But
o Jupiter velocity =13.1 km/sec
o And
o Jupiter orbital circumference= Jupiter circumference x the moon circumference
o The data tells interesting ideas!
o Jupiter has to move during 10921 seconds to pass a distance = its diameter,
now the moon circumference (10921 km) is used as time period! With some
analysis we have found this behavior is followed by many other planets!
o The Earth moon also has to rotate around its axis 13.1 time to move a
distance = 142984 km = Jupiter diameter – where the moon rotation period
is 27.3 days, the 13.1 time consumes around one year – so it's interesting to
rotate for a defined period of time!
o The value (13.1) has still has many interesting forms, for example 13.18
degrees = the moon motion degrees per solar day! Also
o 13.18 degrees = the moon motion degrees per solar day/ 0.526 degrees
(Mars motion degrees per solar day) =25.2 (where Mars axial tilt =25.2 deg)
o ALSO
o 1.16 million km = 13.18 x 88000 km (the moon daily displacement = 88000
km) and light supposed velocity =1.16 mkm/sec
o There's surely a geometrical reason behind this data!
o So I have discovered this value 130 km (Jupiter motion per 10 seconds),
it's incredible value as a key for any door, simply tenths of the solar system
basic values are created based on it – as we have seen
o So how to understand all this data – let's return to our discussion
- I understand the situation as following
- Mars ancient orbital distance was 84 mkm and Pluto was the mercury moon, also
Mercury axial tilt was 1 degree, and Mars orbital inclination was 1.8 degrees…
then both planets had migrated Mars and Pluto…
- Mars during its journey had collided with Venus at first and then with Earth and
from these collisions debris the earth created its moon – Mars reach to its new
orbital distance (227.9 mkm) and from the debris created its 2 moons
8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
- The last debris are attracted by Jupiter gravity and created the asteroid belt
- Pluto had migrated and collided with Neptune whose ancient orbital distance was
5906 mkm and Pluto extort Neptune orbital distance (point), Neptune had to be
more near to the sun and created for itself a new orbit, from the collision debris
Pluto moon were created.
- The main problem was Mercury
- Because it's axial tilt was 1 degree and became almost (0.01 degree)
- The changes in the solar system could destroy it but
- Uranus and Jupiter unified their forces to save the solar system
- The problem was 1 degree of Mercury and 0.1 degree of Mars (because mars
orbital inclination became 1.9 deg and was 1.8 deg)
- Uranus created the Earth moon orbit to be the cornerstone of the solar system new
configuration!! Why?
- Because the moon orbital triangle is declined on the horizontal level with 1.1
degrees, this value Uranus is created to compensate the value of Mercury and Mars
missing degrees (1 +0.1 = 1.1 degrees),
- So Uranus is perpendicular on the moon orbit but Uranus axial tilt has an angle
91.1 degrees with the moon axial tilt (1.1 degrees is consumed in the triangle
decline on the horizontal level).
- Because this is the main repair in the solar system, and it's done in the moon orbit,
the rest planets data has to be in configuration with the moon orbit data
- That explains Equation No. 1 (0.08 second x 13.1 km/sec = 0.8 deg x 1.3 deg)
- Which tells us, based on the moon orbit data, Uranus orbital inclination is created
in interaction with Jupiter orbital inclination)- because the interaction between
both planets is done in the moon orbit, and by this interaction both planets get their
orbital inclination – the moon here is a follower for the repair made by Uranus, and
because this repair is the safe method for the solar system geometry, all solar
planets have to support it, because of that Uranus and Jupiter does so
Please Note
- As a result of Uranus perpendicularity on the moon orbit, the moon orbit
regresses 19 degrees per year
- This regression suggests that some motion must be done by Earth to save its
distances with the moon in the same equal values
- And because of this perpendicularity and the moon orbit regression, the
Metonic Cycle is created for the moon motion
9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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