Paper Question - Why Jupiter motion effects on the Earth moon as similar to Uranus motion effect on Pluto? Let's prove that in following For Jupiter - Jupiter Velocity =13.1 km/sec, that means, Jupiter has to move during a period 10921 seconds to pass a distance =142984 km = Jupiter diameter - where 10921 km = the Earth moon circumference For Uranus - Uranus Velocity =6.8 km/sec, that means, Uranus has to move during a period 7511 seconds to pass a distance =51118 km = Uranus diameter - where 7511 km = Pluto circumference - The previous interesting data is just a window to complex relationships on both sides we have to discuss in this paper – any way the question asks directly why both planets are dealt by the same manner? Because Paper Hypothesis - Jupiter Orbital Distance is created as 2 Parts (778.6 mkm = 760 mkm +17.8 mkm), each one of the previous 2 relationships caused to create one part of Jupiter orbital distance Gerges Francis Tawdrous +201022532292

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Does Planet Day Period Depend On Its Circumference? (V)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt – 15th
November 2020
Abstract
Paper Question
- Why Jupiter motion effects on the Earth moon as similar to Uranus
motion effect on Pluto? Let's prove that in following
For Jupiter
- Jupiter Velocity =13.1 km/sec, that means, Jupiter has to move during a period
10921 seconds to pass a distance =142984 km = Jupiter diameter
- where 10921 km = the Earth moon circumference
For Uranus
- Uranus Velocity =6.8 km/sec, that means, Uranus has to move during a period
7511 seconds to pass a distance =51118 km = Uranus diameter
- where 7511 km = Pluto circumference
- The previous interesting data is just a window to complex relationships on both
sides we have to discuss in this paper – any way the question asks directly why
both planets are dealt by the same manner? Because
Paper Hypothesis
- Jupiter Orbital Distance is created as 2 Parts (778.6 mkm = 760 mkm +17.8
mkm), each one of the previous 2 relationships caused to create one part of
Jupiter orbital distance
- If it's true …. Why Jupiter orbital distance is created as 2 parts of distances and
how these 2 parts can be used to create one distance supposed to be defined
based on the masses gravity forces?! Let's try to answer in following…

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- Jupiter and Uranus identical behaviors
1-1 For Jupiter
- Let's summarize the data in following:
o Jupiter Velocity =13.1 km/sec, i.e. Jupiter has to move during a period
10921 seconds to pass a distance =142984 km = Jupiter diameter
o Because the Earth moon circumference = 10921 km
o The moon has to rotate around its axis 13.1 times to pass a distance =
142984 km = Jupiter diameter! (13.1 rotation x 27.3 days =A Year)
o 1.16 mkm = 13.18 x 88000 km (the moon displacement per solar day)
o 13.18 degrees = the moon motion degrees per a solar day (=360/27.3)
o Jupiter moves per a solar day a distance = 1.1318 mkm (difference only
2.5% with the value 1.16 mkm)
o 1.16 mkm x1 mkm = 449197 days x 2.58 mkm (Earth velocity daily)
where 449197 km = Jupiter Circumference!
o Also
o 13.18 - 13.1 = 0.08 but 0.08 x 2.28 mkm =181843 km
o Where 2.28 mkm =the moon orbital circumference at perigee radius and
181843 km is the main distance defined in the moon orbital triangle
(Please review in the end of the paper)
NOW
o The moon defines the period of time (A Year=365.25 solar days) as a
result of the moon and Jupiter motions interaction
o Mars moves during A Year=365.25 solar days a distance =760 mkm
(Result No. 1)
1-2 For Uranus
- Uranus Velocity =6.8 km/sec, i.e., Uranus has to move during a period 7511
seconds to pass a distance =51118 km = Uranus diameter
- Because Pluto circumference = 7511 km
- Pluto has to rotate around its axis 6.8 times to pass a distance = 51118 km =
Uranus diameter! (6.8 rotation x 153.3 hours =1042.5 hours)
- 0.406 million km (Pluto velocity per solar day) = 6.8 km/sec x 59800 seconds
(but 59800 days = Neptune orbital period) – (Please note that- Neptune orbital
period 59800 solar days = 90560 Neptune days but 90560 solar days = Pluto
orbital period)
- Pluto moves during the period 1042.5 hours a distance = 17.6 million km
(Result No. 2)

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
1-3 Jupiter orbital distance 778.6 million km
778.6 mkm = 760 mkm (Mars Motion) +17.6 mkm (Pluto Motion)
- Let's remember our hypothesis
o (1st
) Planet motion depends on light motion
o (2nd
) light motion for 1 second causes planet motion for 1 day
o The Motion Rule ( Light moves by a circle circumference but its
follower planet moves along its radius)
i.e.
- Planets motions are found based on light motions, so I inserted in this paper in
No. 2 a part of light motion network found behind the planets motions
- Jupiter orbital distance is created as 2 parts (778.6 mkm = 760 mkm +17.8
mkm) why?
- Because Mars and Pluto were migrated from their original orbital distances and
Jupiter created its orbital distance to establish connection points with the 2
migrants planets to support the solar system geometry
- How to define these 2 parts?
o Part No. 1 (760 mkm), the Earth moon defines the period (1 year = solar
365.25 days) and Mars does the motion (2.082 mkm per solar day)
during this period, and by Mars Motion the distance 760 mkm is created
o Part No. 2 (17.6 mkm), Uranus defines the period (1042 hours = 43.14
solar days) and Pluto did the motion (0.406 mkm per solar day)
- The previous explanation shows a deep dependency between the planets
motions which can be understood through the light motions interactions which
are found behind the planets motions…
Note Please
- 17.2 degrees = Pluto orbital inclination = 0.99 x 17.4 degrees (the inner planets
orbital inclinations total)
- 0.18 = 2.58 mkm Earth motion velocity per solar day / 0.466884 mkm Jupiter
motion during its day
- 160591.9 km (Uranus circumference) = 13.18 x 12104 km (Venus diameter)
- 142984 km (Jupiter diameter) = 27.78 km/sec (the moon velocity) x 5127 s
- (5127 mkm = Jupiter Pluto Distance)

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
2- Light motions behind planets motions
I- Data
- Mercury is created by a period of time =50 seconds
- Light beam with velocity =1.16 mkm/sec travels for 50 seconds and perform a
distance =58 mkm = Mercury Orbital Distance
- Mercury orbital circumference (58 x 2π =360 mkm)
- 360 mkm because of high velocity motion – is used as 360 seconds
- Light beam with velocity (0.3 mkm/sec) during 360 seconds travels a distance =
=108 mkm = Venus Orbital Distance
- 216.4 mkm (Venus orbital diameter) is a distance passed by light beam its velocity
0.3mkm/sec during a period =720 seconds
- 720 seconds (because of high velocity motion) is used as a distance =720 mkm =
Mercury Jupiter distance –
- Mercury Jupiter diameter (720 mkm x 2) needs a period = 720 seconds x 2 which
needs a distance = 216.4 x 2 mkm
- (the distance 216.4 mkm x 2) will be used as a time period in the following
equation 216.4x 2 x 1.16 = 500 mkm
- 500 mkm is used as a time period = 500 seconds
- Light beam ( 0.3 mkm/sec) needs 500 seconds to pass Earth orbital distance (149.6
mkm)
- Still the distance 720 mkm is produced by a light beam (1.16 mkm/sec) during a
period = 627 seconds
- Light its velocity (0.3mkm/sec) needs 2090 seconds to pass 627 mkm where 2090
seconds is used as distance 2090 mkm = Jupiter Uranus Distance
- But 6939.75 seconds x 0.3mkm/sec = 2090 mkm – means light with c velocity
travels during (6939.75 seconds) a distance = Jupiter Uranus Distance (6939.75
days =Metonic Cycle).
- 108 mkm = Venus Orbital Distance – So Venus Orbital Circumference =680
mkm but Venus Jupiter distance = 670.4 mkm (Venus & Jupiter positions are
defined before by their distances to Mercury and Earth – that means – the distance
670.4 mkm we didn't bring it from the planets data sheet but we define it relative
to Earth & Mercury positions to Jupiter - i.e. 670.4 mkm is not a new data but a
concluded data)
- light beam with velocity 1.16 mkm passes during 670.4 seconds a distance =778.6
mkm (Jupiter orbital distance)
- Also 670.4 mkm x2π = 4222.6 mkm (high velocity motion uses this value as time)

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
- Light beam with velocity 1.16 mkm travels during 4222.6 seconds a distance
=4900 mkm = Jupiter orbital distance
- Note Please (Mercury Day =4222.6 hours approximately- means the light motion
period is transferred to Mercury motion but the rate of time is changed from 1
second to 1 hour- that's similar to Metonic Cycle 6939.75 days which we have
seen before where the 6939.75 seconds in transferred into the moon motion in
form 6939.75 days)
- Light beam with velocity 1.16 mkm travels during 4900 seconds a distance
=5678.1 mkm = Mars Pluto Distance (6585.39 mkm= 1.16x 5678.1mkm) (where
6585.39 days = Saros Cycle)
- 670.4 mkm (Venus Jupiter Distance) = 1.0725 x 627 mkm (Earth Jupiter distance)
- Earth orbital circumference =940 mkm – which is used as 940 seconds
- A Light beam (0.3mkm/sec) during 940 seconds passes a distance 282 mkm
- A light beam (1.16 mkm/sec) during 282 seconds passes 327.6 mkm (which we
see as lunar sidereal year 327.6 days)
- Light beam (0.3 mkm) during 327.6 seconds pass distance =98.7 mkm (Uranus
axial tilt =97.8 degrees)
- Light beam (1.16 mkm) during 97.8 seconds pass distance =113.45 mkm (where
1mkm=1deg means 113.45 mkm = 113.45 deg = 90 +23.45 deg. Earth axial tilt)
- 149.6 mkm x 2 (Earth orbital diameter) is used as time value – so light with
velocity (1.16 mkm/sec) during this period 149.6 sec x 2 a distance =346.6mkm
where 346.6 days – the nodal year.
- 3717 mkm (Jupiter Neptune Distance) us used as time so –light with velocity
0.3mkm/sec travels during 3717 seconds a distance = Jupiter Mars distance (1.2%)
- 5127 mkm (Pluto Jupiter distance) is used as 5127 seconds where a light with
velocity 1.16 mkm/sec travels during 5127 s a distance = Pluto orbital distance.
But why Mars is exceptional always?!
- 655 mkm (Jupiter Saturn distance) (655 mkm will be used as 655 sec) x 1.16
mkm/sec = 760 mkm (will be used as 760seconds)
- Light beam (0.3mkm/sec) travels during 760 seconds a distance = 227.9 mkm =
Mars orbital distance
Please review
A light beam with velocity (1.16 mkm per sec), creates the solar system
https://www.academia.edu/42069495/A_light_beam_with_velocity_1.16_mkm_per_sec_creates_the_solar_system
or
https://www.slideshare.net/Gergesfrancis/a-light-beam-with-velocity-116-mkm-per-sec-creates-the-solar-system

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
More Analysis In The Moon Orbital Triangle
Basic Data Correction And Revision
Figure No. (1) (my figure)
Please Note
(1) The blue dotted arrow creates a point (Z) between F & S
SZ = 7665 km ZF = 2414 km
CZS = 77.8 degrees CZF =102.195 degrees
(2) The Green arrow creates a point (Y) after the point D
DY = 2513.7 km DYA= 118.92 degrees
Let's review and correct the moon orbital triangle data
(1st
Point)

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
- The figure I brought from internet to use in the Explanation -
- We have supposed that the inner circle is Perigee orbit and
the outer circle is apogee orbit – and we have calculated the
tangent AB = 181843 km
- AB = 363686 km (= perigee radius approximately)
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, the triangle (ODB) is a specific Pythagoras
triangle (1, 2 and 51/2
)
- i.e. the triangle (ODB) angles are 26.564 degrees and 63.435
degrees
NOTE
- for these 2 angles (26.564 deg and 63.435 deg) we have searched, because these 2
angles will correct many data in the orbital triangle.
(2nd
Point) The Moon Orbital Triangle Data Correction
- EB = Perigee radius = 363000 km
- ED = Apogee radius = 406000 km
- EA= (Jupiter Circumference) =449197 km
- AC = (Saturn diameter) =121620 km (error 1%)
- ES = total solar eclipse radius = 373000 km (error 1%)
(EC = 373000 km = Earth moon distance at T. Solar eclipse, BUT point C is NOT
the moon position in T. solar eclipse, because the distance BC= 86000 km but the
distance between perigee point and total solar eclipse point = 11000 km)
- BS= (the moon Circumference) =10921 km
- BZ = 18586 km BF =21000 km
- BD = DA = 43000 km (BY =47513.7 km)
- BA = BC = 86000 km
- CS = = 86690 km
- CZ= (the moon daily displacement) =88000 km
- CF= 88526.8 km CD =96150.9 km
THE ANGLES
- The angle between the black and red lines (under E) = 1.1 degrees
- (E) = 13.33 degrees (C)= 121.67 degrees (A) = 45 degrees
- (ECB) = 76.67 degrees (BCA) = 45 degrees
- (BCS = 7.23 deg) (BCZ = 12.195 deg) (BCF = 13.72 deg) (BCD = 26.564 deg) (ACD
= 18.435 deg)
- (BSC = 82.7 deg) (BZC = 77.8 deg) (BFC = 76.82 deg) (BDC = 63.434 deg)
- (CSA =97.23 deg) (CZA =102.195 deg) (CFA= 103.7 deg) (CDA = 116.564 deg)
- (CYA = 118.92 deg) (BYC = 61.08 deg)
- (Uranus axial tilt = 97.8 degrees = FSC 0.6 degrees) and
- (CYA +0.6 deg = 119.5 deg where 119.5 x 0.99 = 118.3 deg (Neptune A. T)
- Angle under (E) = 13.33 degrees 1.1 degrees = 14.43 degrees

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
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Full list of
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Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
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