Why The Moon Apogee Circumference =2.55 mkm?

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Why The Moon Apogee Circumference =2.55 mkm?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –9th
March 2021
Abstract
- The moon moves daily a displacement =88000 km and during 29.53 solar days the
total displacements be = 2598693 km
- This distance should be the moon orbital circumference, based on that this distance
2598693 km = 2π x 413600 km
- The moon apogee radius = 406000 km
- Where the moon apogee point is the most far point the moon reach from Earth, that
creates a question how the apogee radius be =406000 km instead be =413600 km?
- The difference =2%
- This question is solved by explain the moon Pythagorean triangle technique.
- In this technique the moon creates an angle (θ) between its displacement motion
direction and its orbit horizontal level and by that the real displacement (L) will be
shorter than 88000 km where (L = 88000 cos (θ)).
- As a result the total (real) displacements will be shorter than 2598693 km and be
limited to 2550973 km where the apogee radius be 406000 km NOT 413600 km.
- This intelligent technique solved this question clearly BUT
- A difference 1% is still found! For example:
- The moon orbital circumference = 2550973 km (100%)
- Earth moves per solar day a distance = 2573482 km (101%)
- The moon displacements total during 29.53 days = 2598693 km (102%)

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- Pluto motion distance during (153.3 h) = 2593836 km (102%)
(153.3 h = Pluto Day Period)
- The intelligent Pythagorean technique solved the moon motion dilemma but can't
solve the other planets motions questions!
- Why these 3 planets move equal distances during different periods of time?
- Pythagorean technique answers just a part of the question, because different
planets move equal distances in different periods of time – and by these motions
these planets create the difference 1% between their motions distances!
- We don't know why these planets move equal distances during different periods of
time? And based on that, we don't know also why they create this difference 1%
between their motions distances
- Shortly For What Geometrical Necessity This 1% Is Created?
- Let's use the moon orbit as example
- The Pythagorean technique explains how the moon can decrease its apogee orbital
circumference than its displacements total during its day period (29.53 days),
- BUT Why is this difference 1% required geometrically?
- Why the moon couldn't decrease its orbital circumference by a rate 4% instead of
2%? Why there's a difference 1% in order between 3 planets motions during their
days periods (the Earth, its moon and Pluto)?
- What's the useful result if Pluto moves during its day period a distance = Earth
motion distance during its day period with a difference 1%? Why these 2 distances
are equal and why they have a difference 1%?
- I want to say that - there's a geometrical mechanism is created by these distances
equality and their difference 1%, but we don't see this geometrical mechanism at
all because we don't understand why these planets move equal distances during
different periods of time?
- In this paper we try to follow this difference 1% to know its origin and for what
geometrical reason this difference 1% is created?

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Contents
Subject Page No.
Abstract 1
Contents 3
1- The Moon Apogee Circumference Analysis 4
2- Uranus Cycle 9
3- Metonic Cycle Analysis 19
4- The Difference 1% Origin 26
References 37

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1- The Moon Apogee Circumference Analysis
1-1 Earth and its moon motion harmony
1-2 Uranus Orbital Circumference Analysis
1-3 Uranus motion effect on the Earth moon motion (hypothesis)
1-1 Earth and its moon motion harmony
I - Data
- The moon orbital circumference = 2550973 km (100%)
- Earth moves per solar day a distance = 2573482 km (101%)
- The moon displacements total during 29.53 days = 2598693 km (102%)
- Pluto motion distance during (153.3 h) = 2593836 km (102%)
(153.3 h = Pluto Day Period)
- Uranus (63.8 km/s) moves (during 378675 sec) = 2574990 km (101%)
- Saturn (9.7 km/s) moves during 6.8 x (10.7 hours) = 2540779 km
(Uranus motion distance – Saturn motion distance = π x 10921 km)
II – Discussion
- This data we have seen before, let's explain what we try to do here in following:
o Although Pythagorean triangle technique solves the moon motion question
but the difference 1% in the moon data is inherited from a general using –
that means- even after the moon solves its dilemma –the difference 1% -
still effects on many other planets – as the data shows that clearly –
o We need to know:
o (1) from where this difference 1% is originated?
o (2) for what geometrical result this difference 1% is found?
o For that, we added the data together, to see the distance (2573843 km =
Earth motion during a solar day) is a required distance to be passed by other
different planets! whose move it in different periods of time and with
difference 1%.

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Notice
- The planets move the required distance in different periods of time,
- But
- These periods of time are defined as cycles periods for these planets
- For example
o Pluto moves during its day period a distance = (101%) of Earth motion
distance during its day period – so equal distances are passed by different
planets but during their periods of cycles. (we should ask Why?)
o Uranus depends on the period (378675 sec) where (Saturn Circumference
=378675 km) – this data is complex to be explained – because many planets
use other planets circumferences as periods of time – for example – Jupiter
(13.1 km/sec) moves during (10921 seconds) a distance = 142984 km =
Jupiter diameter – but 10921 km = the Earth moon circumference
o This is a common using in the solar system which we can't solve till now –
more examples – Uranus (6.8 km/sec) moves during 7510 seconds a
distance =51118 km =Uranus diameter (but 7510 km= Pluto circumference).
o Just we understand that, specific relationship is found between Jupiter and
the moon, also found between Uranus and Pluto and then must be found
between Uranus and Saturn – for that reason – Saturn uses the rate 6.8 of its
days period (Uranus velocity =6.8 km/sec) to pass this required distance.

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1-2 Uranus Orbital Circumference Analysis
I-Data
(1)
Earth moves during (6939.75 solar days) a distance = 17859 mkm (-1%)
(2)
Pluto moves during (6939.75) x (153.3 hours) a distance = 18000.57 mkm
(3)
The moon displacements total during (6939.75) x (29.53 days) = 18034.278 mkm
(4)
Uranus Orbital Circumference = 18048.449 mkm
(5)
Mercury moves during (4405.6 days) a distance = 18040 mkm
(6)
Mars moves during (2x 4331 days) a distance = 18036.3 mkm
(7)
Venus moves during (5906 days) a distance = 17860 mkm (-1%)
II-Discussion
Notice (1)
- 4405.6 days = 25.04 Mercury days period But (25.04 = π x 8) and we know that,
Mercury has a cycle during 8 Mercury days. (I try to show that, the planets move
during cycles periods and NOT during any random period. By that, the equal
distances are mentioned and not created by any random process).
- 5906 mkm = Pluto orbital distance, But Venus (frequently) uses the distance
values as periods of time, this using is still puzzled till now!
Notice (2)
- The difference 1% is found with Earth motion.
- means, the difference 1% is found between Earth and Uranus motions, and if
Uranus effects on the Earth moon motion that may create the difference 1%
between the Earth and its moon motions.

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1-3 Uranus motion effect on the Earth moon motion (hypothesis)
- This idea we have discussed before, let's summarize it in following
o Uranus orbital circumference =19 Earth orbital circumferences, means,
during Uranus revolution around the sun, Earth revolve s19 times around the
sun, this explanation depends on the distances and not on the periods!
o So, if Uranus motion effect on the Earth and its moon motions, the number
19 should be seen in their motions data
o Metonic Cycle, is a cycle of the moon motion continues 19 years (6939.75
days), during this cycle period the moon doesn't pass through any point 2
times.
o Because Metonic Cycle is 19 years, the hypothesis is suggested that, Uranus
motion effect on the moon motion…
o And we know that (Earth moves during Metonic Cycle 19 years a distance
=99% of Uranus orbital Circumference)
o If the hypothesis is proved, so the difference 1% is found in Earth motion
relative to Uranus orbital circumference, this difference is transported to the
moon motion relative to Earth motion… means, there's some geometrical
mechanism by which this difference 1% is transported from Uranus to the
moon motion! and how to discover this geometrical mechanism?
Notice
- In some explanation, I have suggested that, the difference 1% is found between the
moon displacements total and its orbital circumference as a result of creation the
moon orbital inclination 5.1 degrees – and this idea told us that- because the moon
orbital inclination =5.1 degrees, that causes the moon orbital circumference to be
less than its displacements total with 1%, I still support this idea because it
depends on some planets data and geometrical interactions, BUT

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- What about the other planets? Where all planets have orbital inclinations, So, can
all planets orbital circumferences be decreased as a result of their orbital
inclinations creation? Another question, does this rate 1% depend on the
inclination degrees or it's a standard? Means, the moon orbital inclination =5.1
degrees and because of that its orbital circumference is decreased with 1% (as the
explanation told us), Now suppose the moon orbital inclination =17.2 degrees (as
Pluto orbital inclination), how much reduction will be found for the moon orbital
circumference?!
- I want to say
- This explanation isn't mistake but it's insufficient to solve the question. Basically
because the rate 1% is inherited from many different planets motions and we have
to know its origin and for what geometrical effect this rate is used?

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2- Uranus Cycle
2-1 Jupiter 8 days Cycle
2-2 Uranus Cycle (depends on 8 of Pluto days)
2-1 Jupiter 8 days Cycle
o Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = Jupiter
circumference (449197 km) + 17695 km
o During 8 of Jupiter days periods (9.9 x 8 =79.2 h), Jupiter moves a distance
= 8 Jupiter circumferences + Jupiter diameter (error 1%)
o Because of Jupiter diameter I concluded that, Jupiter has a cycle in 8 days
Then
o Jupiter motion distance during 8 of its days (79.2 h) which = 3735072 km,
this same distance = Saturn motion distance during 10 of Saturn days period
o Means, Saturn moves during 10 of its days a distance = 3735072 km,
o I have concluded that, Jupiter motion energy is transported to Saturn motion
energy by the rate 80% Because of that I expected that, Saturn should
transport its motion energy to Uranus by the same 80% (but it's incorrect!)
o Saturn transported the motion energy with this rate 80% to Neptune and that
means the distance Saturn passes during 8 of Saturn days period, Neptune
passes during 10 of Neptune days period (error 5%)
The question is why Saturn doesn't transport the motion energy to Uranus?!
- A surprise was in our waiting…
- Uranus (6.8 km/sec) moves during Pluto day period (153.3 h) a distance = Jupiter
motion distance during 8 of its days period (79.2 h) + 17695 km
- means, during 8 Pluto days period (153.3 h x 8) Uranus moves a distance = Jupiter
motion distance during 64 Jupiter days (9.9 h x 64) +Jupiter diameter (1%)
- Uranus Cycle behavior is very similar to Jupiter (8 days) cycle behavior.

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- Why These Distances Are Equal?
- What's The Result Effect Of These Cycles?
- Because Jupiter motion energy is transported to Saturn and from Saturn to Neptune
the distances of these planets should be equal (even approximately) – by that – a
chance is available to compare between these distances - let's do in following

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2-2 Uranus Cycle (depends on 8 of Pluto days)
I- Data
1. Uranus (6.8 km/s) moves during 8 days of Pluto days period (1226.4 hours) a
distance = (4415040 seconds x 6.8 km/s) = 30.022272 million km
2. Jupiter (13.1 km/s) moves during 64 days of Jupiter days period (64 x9.9 h =
633.6 hours) a distance = (2280960 seconds x 13.1 km/s) = 29.880576 million km
3. Saturn (9.7 km/s) moves during 80 days of Saturn days period (80 x10.7 h = 856
hours) a distance = (3081600 seconds x 9.7 km/s) = 29.891520 million km
4. Neptune (5.4 km/s) moves during 100 days of Neptune days period (100 x16.1 h =
1610 hours) a distance = (5796000 seconds x 5.4 km/s) = 31.298400 million km
5. Jupiter Circumference (449197 km) x 64 = 28.748639 million km
6. Saturn Circumference (378675 km) x 80 = 30.294001 million km
7. Neptune Circumference x 2 (311193.6 km) x 100 = 31.119360 million km
Notice (1)
- The equal distances are approximately passed by
o (1) Uranus during 8 Pluto days (2) Jupiter during 64 of its days
o (3) Saturn during 80 of its days (4) Neptune during 100 of its days
Notice (2)
- The data shows, Jupiter and Uranus are independent planets but Saturn and
Neptune depends on Jupiter motion–means- Uranus may have an interaction with
Jupiter but the other 2 planets are effected by this interaction through Jupiter.

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II-Discussion
(1st
Point)
- Uranus motion distance during 8 of Pluto days period (30.022272 mkm) – Jupiter
motion distance during 64 of Jupiter days period (29.880576 mkm) = 142984 km
(= Jupiter diameter) (error 1%)
- Because of Jupiter diameter value, I have concluded that, Uranus & Jupiter Creates
a cycle by their motions interaction.. Where Uranus uses 8 of Pluto days periods
and Jupiter uses 64 of its days period.
(2nd
Point)
- Jupiter motion distance during 64 of its days period (29.880576 mkm) – the total
of 64 Jupiter Circumferences (28.748639 mkm) = 1.1318 m km
- Jupiter moves per a solar day a distance = 1.1318 m km
- That means, these 2 values express 2 motions interacted together to produce this
value (1.1318 m km) which is considered as a value defined based on cycle
period (a solar day).
(3rd
Point)
- Saturn motion distance during 80 of its days (=29.891520 mkm) – Jupiter motion
distance during 64 of its days period (= 29.880576 mkm) = 10921 km
o 10921 km = The Earth Moon Circumference
o The 2 values are considered to be equal, and its almost correct because the
difference between both = 0.036%
o But this very small error = the moon circumference
o Please Note 29891520 km = 10921 x 2737
o But 29880576 km = 10921 x 2736
o Please remember the cycle 2737 years

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(4th
Point)
- Neptune motion distance during 100 of Neptune days periods (=31298400 km) –
Saturn motion distance during 80 of Saturn days periods (=29891520 km) =
1406880 km ………. But
o 1406880 km = The Sun Diameter 139200 km (Error 1%)
o The Sun Diameter 139200 km = 49528 km Neptune diameter x 28.1
o Neptune Axial Tilt =28.3 degrees
(5th
Point)
- Neptune motion distance during 100 of Neptune days periods (=31.298400 mkm)
– Uranus motion distance during 8 of Pluto days periods (=30.022272 mkm) =
1.276128 mkm = π x 406000 km
- Earth Moon Distance at apogee radius = 406000 km, where this is the most far
point the moon can reach from Earth.

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Uranus 144 days Cycle
- 144 days of Uranus days periods = 144 x 17.2 hours = 2476.8 hours
- 16 days of Pluto days period = 16 x 153.3 hours = 2452.8 hours
- The Difference = 24 hours = 1 Solar Day
- The data shows these are 3 values (144 Uranus days, 16 Pluto days and the solar
day) they are 3 cycles
Notice
Pluto moves during 16 Pluto days a distance =41.5 mkm = Venus Earth Distance

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Discussion
- We have one question to answer
- Are These Cycles Different Cycles Or One Cycle?
- In more clear words
- Jupiter has a cycle of 8 days, and Uranus has a cycle of 8 Pluto days, are these
2 different cycles are one cycle only?
- Let's answer in following
- First, we know that, Saturn and Neptune depends on Jupiter for that we will use
Jupiter as their head, so the question tells about 2 cycles which are Jupiter 8 days
cycle and Uranus cycle of 8 Pluto days…. The question again
- Are These 2 Cycles Different Cycles Or One Cycle Only?
- Let's move step by step in following:
o Uranus (6.8 km/sec) during Pluto day (153.3 hours) moves a distance =
3752784 km
o Uranus (6.8 km/sec) during 8 Pluto days (8 x 153.3 = 1226.4 hours) moves a
distance = 30022272 km (No.1)
o Jupiter (13.1 km/sec) during 64 Jupiter days period (=633.6 hours), moves a
distance = 29880576 km (No.2)
o No. (1) – No. (2) = 141515 km = Jupiter diameter (error 1%)
BUT
o 30022272 km= 64 Jupiter Circumferences+ 9 Jupiter diameters (1%)
o Why?
o During 8 Jupiter days, Jupiter moves a distance = 8 (Jupiter circumferences
449197 km ) + (1 Jupiter diameter 141515 km "error 1%")

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o During 64 Jupiter days, Jupiter moves a distance = 64 (Jupiter
circumferences 449197 km ) + (8 Jupiter diameter 141515 km "error 1%")
o But
o Uranus during 8 Pluto days moves a distance = Jupiter motion distance
during 64 Jupiter days + 1 Jupiter diameter 141515 km "error 1%")
o i.e.
o Uranus during 8 Pluto days moves a distance = 64 (Jupiter circumferences
449197 km ) + (8 Jupiter diameter 141515 km "error 1%") + (1 Jupiter
diameter 141515 km "error 1%")
o i.e.
o Uranus during 8 Pluto days moves a distance = 64 (Jupiter circumferences
449197 km ) + (9 Jupiter diameter 141515 km "error 1%")
o The error is 1%
o 9 Jupiter diameter = 1286856 km but the error 1% causes this total to be
1273987 km
o The difference = 1286856 km – 1273633 km= 12756 km (Earth Diameter)
Notice (1)
o The value is (13223 km) and it's different with Earth diameter with around
500 km (by error 3.5%) but this error is not true error – because this value is
a result of collection 9 Jupiter diameters and if Jupiter diameter has a very
small error this great error can be produced in Earth diameter – by that the
difference (500 km) should be attributed to the value (1273633 km) where
the error is only 0.04%)
A Conclusion
o Earth Diameter Proves That, These Cycles Are Only One Cycle
Let's explain why in following…

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- The cycle produces a rest distance = Jupiter diameter with an error 1%
- i.e. the produced distance = 141515 km where Jupiter diameter =142984 km
- The difference = 1470 km
- 9 pieces of this distance produces 9 x 1470 km = 13221 km
- Where Earth diameter =12756 km (The difference 465 km, can't be attributed for
Earth diameter but attributed for the 9 Jupiter diameters and will be considered a
very small error)
- Now
- These 9 Jupiter diameters are found as the following
o 8 Jupiter diameters found by Jupiter motion during 8 cycles each cycle is
consisted of 8 Jupiter days
o 1 Jupiter diameter is produced by Uranus Cycle (8 Pluto days)
o But
o Earth diameter needs the 9 pieces found in 9 Jupiter diameters
o That tells these all motions should be considered as one motion
o It's a cycle is created by these planets motions harmony, means, they move
mentioned motions to create this specific cycle (one cycle) by which the
Earth diameter is defined.
o Of course it's just a distance = Earth diameter, but this distance tells that, the
geometrical design mentioned to create this cycle using different planets in
one cycle to create defined motions and distances….
o It means, there's a geometrical mechanism found behind this cycle where the
cycle itself is a massive cycle because it's done by different planets which is
not usual using.
Notice
- The previous explanation helps greatly my suggested description about the solar
system motion – let's remember it here

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- We should consider the solar system as puppets theater, where one thread connect
all puppets together and causes their motions.
- Or the solar system is similar to a machine of gears each planet causes the other
planets motions by its motion.
- For that, this one cycle (8 Pluto days) is a motion done by different planets to
create mentioned distances in defined periods because these distances and periods
are required for the solar system motion geometry
- Because of that reason, although Uranus moves this cycle (8 Pluto days) the cycle
is defined by Jupiter diameter and not by Uranus diameter – that because – this
cycle is done by different planets motions as we have seen
- That forces us to abandon the solar system classical vision as rigid bodies revolve
around the sun, because
- The solar system is one trajectory of energy and each planet is a point on this same
trajectory and because of that the planets data is created complementary to each
other through the general geometrical design.

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3- Metonic Cycle Analysis
3-1 Uranus Cycle Effect On The Earth & Its Moon Motions
3-2 Uranus Cycle effect on Mercury motion
3-3 Uranus Cycle effect on Pluto motion
3-1 Uranus Cycle Effect On The Earth & Its Moon Motions
I- Data
(1)
Uranus during (1440 of its days) moves a distance = 606.32064 mkm
(2)
The moon displacements total during Metonic (6939.75 days) = 610.698 mkm
(3)
18034.2 mkm = 29.5306 x 610.698 mkm = 29.74 x 606.3206 mkm
II- Discussion
Data no. (1)
Uranus during (1440 of its days) moves a distance = 606.32064 mkm
- (Uranus day =17.2 hours)
- Uranus (6.8 km/s) x 1440 x 17.2 h x 3600 s = 606.3204 mkm
- Notice (as we have discussed before)
- 1440 Uranus days = 16 Pluto days + 10 Solar days
Data no. (2)
The moon displacements total during Metonic (6939.75 days x 88000 km) = 610.698
mkm

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Data no. (3)
(a)
18034.2 mkm (Uranus orbital circumference) = 29.5306 x 610.698 mkm
- 29.53 solar days = the moon day period
- 610.698 mkm = the moon displacements total during Metonic Cycle
- How to understand this data?
- The moon day period is created as a rate between Uranus orbital circumference
and the moon displacements total during Metonic Cycle.
- The question is
- Why?
(b)
18034.2 mkm (Uranus orbital circumference) = 29.74 x 606.3206 mkm
- 606.3206 mkm = The Distance Uranus Passed During Its 1440 Days
- What's this rate 29.74?
- Let's try to explain the complexity behind in following….
o I suppose that, the moon velocity is 29.53 km/sec and this velocity is less
than Earth velocity with 1%, where Earth velocity =29.8 km
o I suppose, the solar system compensates the difference in velocity between
the Earth and its moon by some geometrical mechanism, in this mechanism
the moon day period became (29.53 solar days) which hides the moon
velocity (29.53 km/sec).
o The value 606.3206 mkm = Uranus motion distance during 1440 of its days
and 610.698 mkm = the moon displacements total during 6939.75 days. The
difference between these 2 values very near to (1%), means (29.8/29.53) =
(610.698/606.3206)

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o So, if 29.53 expresses the moon day period (29.53 solar days) which hides
the moon velocity (29.53 km/sec) that means …
o 29.8 must be = 29.8 km/sec = Earth velocity
In this data we have 2 basic question
o (1) Why the result is Uranus orbital circumference?
o (2) Why the rate (610.698/ 606.32) = the rate (29.8/29.53)?
o Both data (a & b) tells that, both distances (606.32 mkm and 610.698 mkm)
are created in proportionality with Uranus orbital circumference!
o Why?
o And they are rated by the rate (29.8/29.53)
o Why?

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3-2 Uranus Cycle effect on Mercury motion
I- Data
(a)
- Mercury moves during 1440 Uranus days a distance = 4224 mkm but Jupiter
Uranus distance 2094 mkm and 2094 mkm x 2 = 4188 mkm (error 1%)
(b)
- 720.7 mkm = Uranus motion distance during 1440 of its days + 2 x 57.9 mkm
(error 1.3%)
(c)
- Mercury moves during 25.15 of its days (= 8π) a distance = Uranus orbital
circumference
(d)
- Mercury moves during Metonic a distance = 28243.5 mkm +177.4 mkm
(e)
- Mercury moves during (62 Pluto days) a distance = 1622 mkm.
II- Discussion
- Data no. (a) tells that
- Mercury moves during 1440 Uranus days a distance = 4224 mkm
- Jupiter Uranus distance 2094 mkm and its diameter = 2094 x 2 = 4188 mkm
- The difference between 4224 mkm and 4188 mkm = (1%)
- That means
- Mercury (47.4 km/s) moves during 1440 Uranus days a distance = Jupiter Uranus
Distance x 2 WHY?
- The difference 1% is found here again between Mercury motion and the required
distance (Jupiter Uranus Distance), tells, some geometrical reason must be found.
- But let's analyze this number 4224 mkm as possible in following…

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The Distance 4224 mkm
- The following discussion is an old one – let’s summarize it:
o We have supposed that, a light velocity 1.16 mkm/sec is found, so we will
use this velocity as a real one because we have discussed its proves before.
o Also
o We know that, light motion can use the distance values as a periods of time
that because (x = ct and if c=1 so x=t)
o Based on that,
o The distance 4224 mkm will be used as a period of time (4224 seconds)
o Light with supposed velocity (1.16 mkm/sec) travels during 4224 seconds a
distance =4900 mkm = (Jupiter Orbital Circumference) (Result 1)
o Mercury day period =4222.6 hours which is very near to this value 4224
seconds and So, we suppose Mercury day period is created based on this
same value (4224 seconds), supposing that, light motion of a second causes
Mercury to move for an hour. (Result 2)
o Mercury moves during its day period (4222.6 hours) a distance = 720.7
mkm = Mercury Jupiter Distance. (Data No. 3)
o The previous explanation tries to prove that, the light beam (1.16 mkm) is
sent from Jupiter to Mercury and this light beam created Jupiter orbital
circumference and causes to make Mercury day period =4222.6 hours
Now
o Mercury moves during 1440 Uranus days a distance = (2 x Jupiter Uranus
distance), that shows Mercury as a point on which both 2 planets motions
effect greatly. Means, 2 strong forces (Jupiter and Uranus) connected each
other on Mercury (as if Mercury the land the 2 planets stand on it).

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The Value 4224 (More Discussion)
- The value 4224 shows Jupiter effect not only on Mercury but on all inner planets
- Let's see that in following
(1)
o 4224 mkm = 2π x 670.4 mkm (670.4 mkm = Jupiter Venus Distance)
(2)
o (5040 s/ 4224 s) = (928 mkm/778.6 mkm)
o Where
o 778.6 mkm = Jupiter orbital distance
o 928 mkm = Jupiter Earth distance = 778.6 mkm +149.6 mkm
o But
o Mercury day needs 5040 seconds to be 176 solar days
o And
o 4224 seconds which is equivalent to 4224 mkm
(3)
o (4222.6 hours /24.7 hours) =170
o Where
o 4222.6 hours = Mercury Day Period
o 24.7 hours = Mars Day Period
o 170 mkm = the distance between Mercury and Mars
- I try to prove, the number 4224 is inherited in all inner planets motions data
- Let's see more data to prove this same claim in following

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Jupiter orbital Circumference
(I)
- Mercury moves during its day period a distance = Mercury Jupiter Distance
(No error)
- Venus moves during its orbital period a distance = Venus Jupiter Distance
(1.3%)
- Earth moves during its orbital period a distance = Earth Jupiter Distance
(778.6 mkm +149.6 mkm = 928 mkm has an error 1.2% with 940 mkm)
(II)
- Mercury orbital circumference =360 mkm
- Venus orbital circumference =680 mkm
- Earth orbital circumference =940 mkm
- Mars orbital circumference =1433.5 mkm
- The 4 planets orbital circumferences total = 3413.5 mkm
BUT
- Jupiter orbital circumference =4900 mkm …..And
- 3413.5 mkm + 1433.5 mkm = 4900 mkm ……Means
- Jupiter orbital circumference = the inner planets orbital circumferences total
+ Mars orbital circumference
- Means, Mars orbital circumference is used 2 times with the other 3 inner planets
circumferences to create Jupiter orbital circumference
- I try to show, the inner planets motions data is created as a function in Jupiter
motion data. Means, Jupiter is almost the inner planets parent, and by the energy
(4224) which is sent from Jupiter to Mercury the inner planets formed their orbital
motions and circumferences to be rated with Jupiter motion and orbital
circumference.
(Notice Mars orbital circumference = Saturn orbital distance)

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4- The Difference 1% Origin
4-1 Preface
4-2 Jupiter Uranus Distance Analysis
4-1 Preface
- Let's review what we know about this difference 1% in following
o There's a difference 1% between Earth, its moon and Pluto motion distances
o There's a difference 1% between Earth motion during 19 years and Uranus
Orbital Circumference
o The moon total displacements during Metonic Cycle (6939.75 days) =610.7
mkm but Uranus motion distance during 1440 Uranus days = 606. 3mkm the
difference is 0.7% (very near to 1%)
o Mercury moves during 1440 Uranus days a distance increased 1% than
(Jupiter Uranus Distance 2094 mkm x 2)
o The moon moves during 1440 Uranus days a distance = 90.8 mkm but
Jupiter Uranus distance 2094 mkm =90.8 mkm x 23.1 (Earth axial tilt 23.4
degrees error 1.4%)
o Uranus & Jupiter Cycle produces Jupiter diameter with an error 1%
Also
o 17.4 degrees (the inner planets orbital inclination total) x 0.99 = 17.2 deg
(Pluto Orbital Inclination)
o 23.6 degrees (the outer planets orbital inclination total) x 0.99 = 23.4 deg
(Earth Axial Tilt)
The conclusion
o The difference 1% is related to (Jupiter Uranus Distance) and also to
(Metonic Cycle Period).

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4-2 Jupiter Uranus Distance Analysis
I- Data
Group No. (1)
(1)
Light known velocity (0.3mkm/sec) x 6939.75 seconds =2082 mkm
(but (0.3mkm/sec) x 2094 seconds = 628 mkm)
(2)
Light supposed velocity (1.16 mkm/sec) x 3600 seconds =2088 mkm x 2
(3)
Light supposed velocity (1.16 mkm/sec) x 2088 seconds = π x 778.6 mkm (1%)
Group No. (2)
(4)
Uranus moves during 3600 solar days a distance = 2115 mkm (1%)
But
4495.1 x (9.9 h) x (13.1 km/sec) = 2099 mkm
(5)
610.7 mkm x 3.4 = 2076 km
606.32 mkm x 3600 = 2061.5 km
(6)
(5906/149.6) =(6939.75/175.94)
Group No. (3)
(7)
- Uranus moves during 6939.75 solar days a distance = 4077.3 mkm
- Uranus moves during 6939.75 x (153.3 h) a distance = 26044 mkm
- Uranus moves during 6939.75 x (29.53 days) a distance = 120404 mkm
- Pluto moves during (778.6 x 2) (153.3 h) a distance = 4040 mkm
- But (1.16 mkm/sec x 6939.75 = 2 x 4025 mkm)

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II- Discussion
Group No. (1)
Equation No. (1)
Light known velocity (0.3mkm/sec) x 6939.75 seconds =2082 mkm
(but (0.3mkm/sec) x 2094 seconds = 628 mkm)
- Jupiter Uranus Distance 2094 mkm, I claim, is the source of the difference 1%
- How?
- Many planets pass a distance = Jupiter Uranus Distance in different cycles periods
an by that this same distance (2094 mkm) is seen in different planets motions
- But
- Not every motion pass this distance (2094 mkm) accurately but some motions
create a difference 1% with the original distance value – and even there are more
motions create a difference 1% with the previous one creating 2% with the original
distance –showing some geometrical classification is found behind.
- Let's move step by step to see what happens here
(1)
o Light velocity (0.3mkm/sec) travels 2082 mkm during 6939.75 seconds but
Metonic Cycle =6939.75 solar days and if we consider 1 day of planet
motion can be caused by light motion for 1 second – so the value 6939.75
days will be 6939.75 seconds.
o The distance 2082 is very near to Jupiter Uranus distance (2094 mkm) (the
difference is 0.6% BUT Not 1%)
o We should consider that, Metonic Cycle (6939.75 seconds or days) must be
created by light motion effect, because the previous data uses both values
(Jupiter Uranus distance and Metonic Cycle period) where the error is less
than 1% that tells this data is correct and real, by that, these 2 values must be
created depending one another – means – Metonic Cycle and Jupiter Uranus
distance must be created depending on one another

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(2)
o Light velocity (0.3mkm/sec) travels during 2094 seconds a distance = 628
mkm (Earth Jupiter Distance)
o Let's consider this data ….
o The period 6939.75 second is used by light motion to pass 2082 mkm
(which is very near to 2094 mkm = Jupiter Uranus distance)
o The distance 2094 mkm is used (as a period of time 2094 seconds) by light
motion to pass a distance 628 mkm (Earth Jupiter Distance)
o That tells, the light travels between Earth and Uranus, where this light beam
passes Jupiter in its journey from Earth to Uranus (or vice versa)
o Light uses 2094 mkm as a period of time 2094 seconds, it's one feature of
light motion
o What conclusion we have?
o A light beam travels between Earth and Uranus, this light beam passes
Jupiter in its journey.
(3)
o Because this light beam connects Earth and Uranus, Metonic Cycle is
created as a motion done by the Earth moon motion – that – explains how
Uranus effect on the moon motion – although this is a light motion – but
Uranus is still the connection point and by that Uranus effects on the moon
motion can causes to create Metonic Cycle – But Metonic Cycle is a cycle
effects on different other planets because it's created by the light motion.
- Nothing can be added here, let's discuss the data Group no. (2) in following..

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Discussion
Group No. (2)
Equation No. (5)
610.7 mkm x 3.4 = 2076 km
606.32 mkm x 3.4 = 2061.5 km
- 610.7 mkm = the moon displacements total during Metonic Cycle (6939.75 days)
- 606.32 mkm = Uranus Motion Distance during 1440 Uranus Days Cycle
- 3.4 deg = Venus orbital inclination
- The produced distances are 2076 mkm but (2094 mkm x 0.99 =2073 mkm) and
that tells this value is almost 99% of Jupiter Uranus Distance, showing that, the
moon displacements total is decreased with 1% than the required distance
- Also, 2061.5 mkm = 2082 mkm x 0.99, where the distance 2082 mkm is the light
motion distance during 6939.75 seconds. That shows some interaction between
Uranus motion and light motion…
- (Notice 6939.75 = 71 x 97.8 but Uranus axial tilt =97.8 degrees)
Equation No. (4)
Uranus moves during 3600 solar days a distance = 2115 mkm (1%)
- The distance 2115 mkm is different from Jupiter Uranus distance (=2094 mkm)
with 1%, Uranus passes this distance in 3600 solar days
- But
- 1.16 mkm/sec x 3600 seconds = 2 x 2088 mkm
- Light supposed velocity (1.16 mkm/sec) passes during 3600 seconds a distance = 2
x 2088 mkm (Jupiter Uranus Distance 2094 mkm)
- The period 1 day in Uranus motion be used as 1 second in light motion – but it's
similar to Metonic Cycle (6939.75 days) which is used by light as (6939.75 sec)

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Notice
4495.1 x (9.9 h) x (13.1 km/sec) = 2099 mkm
- Jupiter (13.1 km/sec) moves during (4495.1 Jupiter days) a distance =2099 mkm
(= Jupiter Uranus Distance)
- But
- 4495.1 mkm = Neptune Orbital Distance
- Jupiter doesn't use this value as 4495.1 solar days but as 4495.1 Jupiter days
- We can't discuss the interaction between Jupiter and Neptune here because it's
discussed frequently before in Jupiter energy discussion
- This equation tells that, Neptune orbital distance is defined by Jupiter effect in its
interaction concerning the distance 2094 mkm (Jupiter Uranus distance)
Equation No. (6)
(5906/149.6) =(6939.75/175.94)
- 5906 mkm = Pluto Orbital Distance
- 149.6 mkm = Earth Orbital Distance
- 6939.75 days = Metonic Cycle Period
- 175.94 days = Mercury Day Period.
- Equation no. (6) shows that, there's a relationship between Mercury and Pluto
which contains Earth also in addition to Metonic Cycle.

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What Are The Useful Results We Have Get From This Discussion?
(1)
The difference 1% is found in Jupiter Uranus Distance by light motion (which creates
Metonic Cycle)
(2)
The difference 1% is transported to the moon motion through Metonic Cycle which is
created based on Jupiter Uranus Distance
Why these results are useful?
- The paper provides a suggested vision for the solar system different from the
classical one- the solar planets are not rigid bodies revolve around the sun by the
gravity forces – instead – it's a mechanical clock – each planet works as a gear
causes the other planets motions – or it's a puppets theater – all planets are
connected with the same thread and moves by one force in harmony with each
other – the planets data also is created complementary with each other (as the
electron and positron are created complementary one another by Gamma rays in
the double production experiment)
- By this vision, the solar planets will be as one garment, it's created based on
calculations taken into consideration the general harmony of motions as a basic
goal behind the data creation…
- This is the idea
- And the difference 1% is repeated in different planets because it’s the thread by
which this garment is sewn with its parts – without this thread the garment will be
disassembled from its parts –
- I want to say
- The solar system is created by one geometrical structure, and this geometrical
structure creates this difference 1% for geometrical necessity – this is the key –
by which we can discover the solar system geometrical structure details.

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- Light motion is a real player in the solar system geometry and because of that the
data can't avoid it even if I have tried to do.
- But
- The difference 1% is the geometrical structure secret which is transported from
point to another point – showing by that – the planets are not independent-
- I wish to explain my idea as possible, let's try to do that in more clear words
o The solar system is one machine – we accept that – this machine transports
(Data or energy) from planet to another – this transportation process is done
based on geometrical rules
o And
o These geometrical rules need to create this difference 1% in different places
to be able to transport this (data or energy)
o Means
o This difference 1% has the solar system geometrical structure secret.
o If we can understand why this difference (1%) is found in the data, that will
gives us the chance to discover the (one) geometrical structure based on
which the solar group is created
o Why??
o Because this difference (1%) is found for geometrical necessity – the
machine can transport this (data or energy) just by using this 1% difference
o And by that, we define the solar system (navel) point.
- Why is this difficult to explain this difference 1% using and mechanism?
- Because light motion is a player in the solar system motion – and we can't define
the category of this motion effect – we see light motion features in the planets
motions but we can't understand from which point these features are created – we
deal with planets motions (low velocity) but light motions features still observed.

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Light Motion Features Examples
Example no. (1)
Light supposed velocity (1.16 mkm/sec) x 2088 seconds = π x 778.6 mkm (1%)
- 778.6 mkm = Jupiter Orbital Distance
- We remember that, Uranus moves during 3600 solar days a distance (2115 mkm)
which is different with Jupiter Uranus distance (=2094 mkm) with (1%)
- Where
- Light supposed velocity (1.16 mkm/sec) uses this period as (3600 seconds) and
pass a distance = 2 x 2088 mkm (Jupiter Uranus distance =2094 mkm)
- After that
- Light supposed velocity (1.16 mkm/sec) uses this distance 2088 mkm as a period
of time (2088 seconds) to pass a distance = 778.6 mkm= Jupiter orbital distance,
creating (again) the difference 1%
- We may remember that
- This supposed light beam used (4224 seconds) to pass 4900 mkm = (Jupiter
orbital circumference)
- The situation is more complex because
(1)
o 778.6 mkm = 1.16 mkm/sec (light supposed velocity) x 670 seconds
o Where 670 mkm = Venus Jupiter distance
(2)
o 720.7 mkm = Mercury Jupiter distance = 1.16 mkm/sec x 622 seconds
o But 629 mkm = Earth Jupiter distance (error 1.2%)

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Also
o (778.6 /720.7) = (720.7/670.4) = (670.4/629) = 1.0725
o Where
o 778.6 mkm = Jupiter Orbital Distance
o 720.7 mkm = Mercury Jupiter Distance
o 670.4 mkm = Venus Jupiter Distance
o 629 mkm = Earth Jupiter Distance
o I try to show that, the 3 inner planets and Jupiter data show clearly light
motion features in their data because of the energy which is sent in form of
the value (4224) we have discussed before
o But
o No light beam we can catch
o Just light motion features are found, and by effect of these light motion
features the difference 1% is transported from point to another through the
solar system but we can't catch the light beam and can't understand the
geometrical necessity of this difference 1%

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To whom may concern
- I have tried to show that, the difference 1% is not created by any random process
- For that reason I have provided different source of data
- Also
- I have tried to arrange the data to be in logical form as possible –
- But still I can't catch why this difference 1% is found or for what geometrical
reason…
- In Fizu experiment, the result tells that, light velocity be decreased with 1%
through liquids than vacuum, I have used this data, and claimed that, this
difference 1% is found as a feature of light motion found accompanying the
planets motions
- But
- That's not useful
- Because
- The difference 1% is found for a geometrical necessity and it has the secret of the
solar system general geometrical structure, means, when we discover the
geometrical job of this difference 1% we will discover the solar system general
geometrical structure – but light motion features which are widespread through the
solar system prevented me to catch the treasure
- For that reason, I have written this paper to be a source of data to whom may
concern to find out an answer for this hard question
- What's the geometrical rule done by this difference 1%?

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References
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-trajectory-analysis-ii
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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