The Moon Creation Effect On The Solar System Geometry (II)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Creation Effect On The Solar System Geometry (II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –31st
March 2021
Abstract
Paper hypothesis
There's an interaction between Earth and Jupiter Motions
The hypothesis Explanation
- What does mean "an interaction of motions"?
- I have searched for a suitable word to explain a dependency of motions data for
both planets on one another - and I have choose the word "Interaction"
- Earth and Jupiter motions data depend on Each other – that means- I can write
Jupiter motion detailed data by analysis Earth Motion Data –
- The paper will discuss that as deep as possible to prove this point of view
- But how does that happen?
- The "Interaction of Motions" disproves the description supposes that the solar
planets are separated rigid bodies revolve around the sun, each planet creation and
motion data is independent from the others. "This description is incorrect"
- The solar planets are created from one trajectory of energy (or from one light
beam) which had created the planet and its orbital distance to be complementary
with the other planets data to create the general harmony of motions – that means-
the solar group is one geometrical building and each planet is a part of it
- "The Motions Interaction" is a method to examine the planets creation and motion
data origin and to answer (how this data be created)?

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1- Introduction
- We complete our discussion started in (Part I) of this papers series
- In that part we have searched after the number 12430 to know what's this number
origin…
- Let's summarize the idea behind this search:
o Let's imagine that, the solar planets are created by one light beam, and this
light beam creates the planet matter and its orbital distance
o This light beam travels from one planet to another, and by that the planets
data be created complementary one another – as the electron and positron
charges be created complementary to each other from Gamma ray (double
production experiment)
o This description tells, if this light beam energy equal (A) when this light
beam started to build Mercury and its orbital distance, this energy (A) will
be changed when this light beam reaches to Pluto – that means- all planets
energy should be =this origin energy (A)
o This description creates a connection method between the planets creation
and motion data -And based on that- the description gives a chance for some
(Geometrical Rules) to control this data creation -
o Now, let's suppose this light beam energy =12430 (energy unit), the light
beam builds Mercury when the energy was (12430) and then this value will
be changed after Mercury creation – that means – we will find this number
12430 in Mercury data but will not find it in Venus…
o I want to say, If really the planets are created from one light beam (or one
Trajectory of Energy), the search after any working value will be so useful –
because the data will tell us where this number (of energy) is used and what
change is done for it after this using –
o This simple description aims only to create a frame for our experiment – we
choose a number (12430) and we search after it through the planets data to

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know if this value can be transported from one planet to another through the
solar group, and by what form this transportation is done
o The number (12430) doesn't use any Unit!
o Because the solar system geometry uses planet circumference and diameter
as a period of time – still we don't know by what mechanism that's done –
but no room for doubt around this using – almost all planets circumferences
are used as periods for time for other planets…
Shortly
o In this paper, we will compare Jupiter & Earth Motions Data in details, this
comparison is done by searching for the number (12430) in each planet data,
when we find this number, we will try to know its origin and its outlet, then
we will examine to know if this value is transported to other planets –
Let's summarize what we have found already about it
o (Earth diameter 12756 km/12430 km) = (12430 km / Venus diameter 12104
km)
o So, the number 12430 km is The One Rate between both Diameters
o Saturn (9.7 km/s) moves during 12430 seconds a distance = 120536 km
(Saturn diameter)
o Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km
(Light known velocity 0.3 mkm/s For 1 second).
o Light known velocity 0.3 mkm/s travels during (39050 s) a distance = 5848
mkm (where 39050 = π x 12430) and (5848 mkm = Mercury Pluto distance)
o Light supposed velocity 1.16 mkm/s travels during (5040 s) a distance =
5848 (where Mercury Day Period needs 5040 seconds to be 176 solar days).
- Although the number 12430 is so interesting one, but in fact, this number origin is
The Earth and Jupiter Motions Interaction Data – and all the previous data is result
and not origin – let's start our discussion, hoping to be a rich & sufficient.

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2- Earth and Jupiter Motions Interaction
I-Data
(1)
135 mkm =29.8 km/s x 1259.3 h x 3600 s
(2)
135 mkm =88000 km x 778.6 days x 2 (error 1%)
(3)
29.53 x 327.6 = 4π x 778.6 (error 1%)
(4)
327.6 days x 29.53 days x 88000 km = 9674 days x 88000 km = 851.3 mkm
(5)
329.8 days x 29.53 days = 9738 days
(6)
30589 days = π x 9738 days
(7)
(10747 days /9738 days) = 1.1 = (2802 h/ 1259.3 h)
(8)
135.7 mkm = 10921 km x 12430 km
But (4900 mkm =10921 km x 449197 km)
(9)
135 x 88 = 2 x 5906
135x 670.4 = 90560
(10)
(29.8 /13.1) =2.23
(11)
4900 mkm = π x 40080 km x 39050 km = 449197 km x 10921 km
(12)
4900 mkm = 2.573 km x 1461 days x 1.3

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(13)
13.1 km/s x 9.9 h x 3600 s x 8 = 8 x 1980 x 29.8 km/s
(14)
595 mkm =1980 s x 0.3 mkm/s = 2.573 mkm x 232 = 135 mkm x 4.4
(1461 days = 232 x 2π)
(15)
2.5986 mkm x 1433.5 days = 3727 mkm
2.5509 mkm x 1461 days = 3727 mkm
2.573 mkm x 1440 days = 3706 mkm
(3717 mkm/3706 mkm) = (361/360)
II-Discussion
Equation No. (1)
135 mkm =29.8 km/s x 1259.3 h x 3600 s
- Earth (29.8 km/s) moves during 1259.3 hours a distance = 135 mkm
o 135 mkm – a distance starts from the sun to a point in space between Venus
and Earth – specifically – after Venus with 26.8 mkm and before Earth with
14.6 mkm
o Let's call this point (A) and its orbital distance =135 mkm
o From the point (A) to Uranus the distance = 2737 mkm
o 177.4 deg (Venus Axial Tilt) + 2.5 deg (Saturn Orbital Inclination) =179.9
o 179.9 deg x 7 ( Mercury Orbital Inclination) =1259.3 degrees2
o This value 1259.3 degrees is used by Earth motion as 1259.3 hours
Equation No. (2)
135 mkm =88000 km x 778.6 days x 2 (error 1%)
- 778.6 mkm = Jupiter orbital distance, this value is used here as a period of time
(778.6 days)

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- Equation no. (2) tells that, the moon displacements total during (778.6 days x 2) =
135 mkm – we need to know – why Jupiter orbital distance 778.6 mkm is used as a
period of time in the moon motion?
- We need the next equation to answer this question…
Equation No. (3)
29.53 x 327.6 = 4π x 778.6 (error 1%)
- 327.6 days = The Lunar Sidereal Year (12 x 27.3 days)
- 29.53 days = The Moon Day Period
- 778.6 mkm = Jupiter Orbital Distance
- 2π x 778.6 = 4900 mkm = Jupiter Orbital Circumference
- Equation no. (3) is the equation we need, the data tells that, the numbers (327.6,
29.53 and 778.6) are created depending on one another because the rate between
both is (4π) which be in proportionality with the circle radius (i.e. in harmony with
Jupiter orbital distance 778.6 mkm)
- So, the value 778.6 mkm can be used as 778.6 days resulting from equation no. (3)
because if it's done we will claim that the value 778.6 days is a part of the values
(327.6 days x 29.53 days)
- But why (4π)? And not (2π)?
- The 5 inner planets orbital circumferences total (Mercury + Venus + Earth + Mars
+ The moon) = (360mkm + 680 mkm + 940 mkm +1433 mkm +1433 mkm) =
4846 mkm
- (This total uses Mars orbital circumference 1433mkm for the Earth moon)
- Jupiter orbital circumference = 4900 mkm (the difference =1%)
- The total of both = 4846 mkm +4900 mkm = 9738 mkm

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Equation No. (5)
329.8 days x 29.53 days = 9738 days
o 329.8 days = 327.6 days +2.23 days, means, the period 329.8 days is a lunar
sidereal year (327.6 days) but this year is not ended on sidereal month
(27.32 days) but ended with a synodic month (29.53 days) because of that
the year days be 329.8 days.
o The multiply with the 2 cycles periods (329.8 x 29.53) produced the period
9738 days –
o The idea will be clear with the next equation …
Equation No. (6)
30589 days = π x 9738 days
- 30589 days = Uranus orbital period
- 9738 days = (329.8 days x 29.53 days)
- Please remember
- 10747 days (Saturn Orbital Period) = 365.25 days x 29.53 days
- It's almost a general behavior in the periods cycles data creation – the planets
cycles periods be created based on smaller cycles periods of other planets, by that
Uranus orbital period (30589 days) be created based on the period 9738 days
(329.8 days x 29.53 days), there's some geometrical rule to create these periods –
but we still try to discover it
- Uranus Orbital Circumference 30589 days is used by other cycles for example
(30589 days =88 days x 347.6 days) where ( 88 days = Mercury day period and
346.6 days = the nodal year)
- There's a general harmony of this data, when the rule be discovered this data will
be simply explained…
- But

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- There's an important result we have here that,
- The value 9738 mkm is used as a period of time by the moon cycles periods and
Uranus orbital period –
- So, not only Jupiter orbital distance 778.6 mkm, but also the total 9738 mkm both
are used as a period of time
Notice
- (9738 days /4331 days) =2.23
- 4331 days = Jupiter orbital period
- Please remember
- (29.8 Earth velocity /13.1 Jupiter velocity) =2.23
- But 29.53 days = 27.32 days + 2.23
- The data shows that, a deep interaction is found behind,
- Nothing is clear for us, because no motion is clear yet – let's try to find some
motion behind for better understanding….
Equation No. (4)
327.6 days x 29.53 days x 88000 km = 9674 days x 88000 km = 851.3 mkm
- The moon displacements total during (9674 days) = 851.3 mkm = 2π x135 mkm
- So, the period 9674 days is used by the moon motion to pass a distance = the
orbital circumference for the orbital distance 135 mkm (we remember Earth
moves during 1259.3 hours a distance =135 mkm)
- But
- 851.3 mkm = 1.0725 x 778.6 mkm (Jupiter orbital distance) (error 1.5%)
- That means, the moon motion defines Jupiter orbital distance!
- Please remember, the rate 1.0725 is found between Jupiter distances to other
planets – regardless any explanation for this rate – it's used with all distances and
by that it creates a rule (even undefined) but still works forcedly – please
remember the following data

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o 778.6 mkm (Jupiter orbital distance) = 1.0725 x 720.7 mkm (Mercury
Jupiter Distance)
o 720.7 mkm (Mercury Jupiter Distance) = 1.0725 x 670.4 mkm (Venus
Jupiter Distance)
o 670.4 mkm (Venus Jupiter Distance) = 1.0725 x 629 mkm (Earth
Jupiter Distance)
o 629 mkm (Earth Jupiter Distance) = 1.0725 x 588 mkm
o 588 mkm = 1.0725 x 550.7 mkm (Mars Jupiter Distance)
o So, the moon moves (851 mkm) but it can be considered as (778.6 mkm x
1.0725) which shows the moon moves a distance = 778.6 mkm = Jupiter
orbital distance
Now
o Suppose the moon moves during the period (327.6 days x 29.53 days) a
distance = Jupiter orbital distance! Why Jupiter should interest at all?
Because Jupiter and the moon motions are interacted one another- they move together
by common data!!! The data proves that….
o 4900 mkm (Jupiter orbital circumference) = 10921 km (the moon
circumference) x 449197 km (Jupiter circumference)
o This data tells, Jupiter motion depends on Jupiter and the moon diameters
o The moon moves 851 mkm = 2π x135 mkm
o But
o 135 mkm = 10921 km x 12430 km
o The moon motion depends on its circumference and the number we search
for 12430 km –
o That means, Jupiter motion depends on (the moon circumference) and the
moon motion depends on its own (circumference) – please remember the
data part no. (I) because it's so useful here, where

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o Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km =
Jupiter diameter
o Uranus (6.8 km/s) moves during 7510 seconds a distance = 51118 km =
Uranus diameter
We can't review thus data here – we need to discuss the new one – let's do in
following
Equation No. (7)
(10747 days /9738 days) = 1.1 = (2802 h/ 1259.3 h)
- The rate 1.1 is important between, Uranus axial tilt = 97.8 degrees and the moon
axial tilt =6.7 degrees and on vertical axis will be 6.7 +90 =96.7 degrees
- The difference 97.8 deg – 96.7 deg =1.1 degrees
- We have seen how Uranus orbit period be in harmony with the moon cycles
periods, that tells, this interaction causes one general rule controls all planets data
and defines their periods of time based on the motion transported from planet to
another –
Equation No. (8)
135.7 mkm = 10921 km x 12430 km
But (4900 mkm =10921 km x 449197 km)
This equation we have discussed already

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Earth and Jupiter Motion Interaction
Equation No. (11)
4900 mkm = π x 40080 km x 39050 km = 449197 km x 10921 km
- 4900 mkm = Jupiter orbital circumference
- 40080 km = Earth circumference
- Equation no. (11) tells, Jupiter orbital circumference depends on Earth
circumference and the value 39050 mkm (π x 12430 km)
- That tells the interaction between Jupiter and the moon is found through an
interaction between Jupiter and the Earth motions
Equation No. (12)
4900 mkm = 2.573 km x 1461 days x 1.3
- 2.573 mkm = Earth motion distance per a solar day
- Equation no. (12) tells that, earth moves during 1461 days a distance proportional
with 4900 mkm = Jupiter orbital circumference by the rate 1.3 (Jupiter orbital
inclination =1.3 degrees) that tells, Jupiter orbital inclination is created based on
this interaction..
Equation No. (13)
13.1 km/s x 9.9 h x 3600 s x 8 = 8 x 1980 x 29.8 km/s
- This is the equation we need to discuss
- Jupiter has a cycle in 8 of its days – we have discussed this cycle before frequently
- Jupiter moved during its day a distance =466884 km
- During 8 days the distance be = 3735072 km = 8 Jupiter circumferences +1 Jupiter
diameter (1%)
- This same distance (3735072 km) Earth passes during (8 x 1980 sec), this shows a
cycle of (8 periods) as Jupiter cycle of its (8 days)
- But what's this period (1980 seconds)?
- The 3 planets (Mercury, Venus and Earth) orbital circumventers total = (360 mkm
+680 mkm + 940 mkm = 1980 mkm)

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- 1980 mkm is used by earth motion as 1980 seconds! Why?
- The next equation may help us
Equation No. (14)
595 mkm =1980 s x 0.3 mkm/s = 2.573 mkm x 232 = 135 mkm x 4.4
(1461 days = 232 x 2π)
- Light known velocity (0.3 mkm/s) travels during 1980 mkm a distance =595 mkm,
this same distance can be passed by Earth daily velocity (2.573 mkm) during 232
days (1461 days = Earth Cycle = 365 +365 +365 +366 days)
- This distance 595 mkm = 135 mkm x 4.4
- Where
- 4.4 degrees (1.3 deg Jupiter orbital inclination + 3.1 deg Jupiter Axial Tilt)
- What's the distance 595 mkm?
- The point 183 mkm from the sun has a distance = 595.6 mkm to Jupiter
- The point 304 mkm from the sun divides the distance as following
- 304 mkm x 0.8 = 243 mkm (0.8 deg = Uranus Orbital Inclination)
- The distance from 304 mkm to Mercury =246 mkm (error 1%)
- That tells the distance 304 mkm is divided into 2 parts by Uranus effect on the
planets positions…
- The required distance is (595 mkm) (we have discussed it before).

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Equation No. (15)
2.5986 mkm x 1433.5 days = 3727 mkm
2.5509 mkm x 1461 days = 3727 mkm
2.573 mkm x 1440 days = 3706 mkm
(3717 mkm/3706 mkm) = (361/360)
- 3717 mkm = Jupiter Neptune Distance
- 2.589 mkm = The Moon Displacements Total during 29.53 days
- 2.55 mkm = The Moon Apogee Orbital Circumference
- 2.573 mkm = Earth motion distance per a solar day
- 1461 days = Earth cycle (365+365+365+366 =1461 days)
- 1433.5 mkm = Saturn orbital distance and used as a period of time 1433.5 days
- Equation no. (15) tells that, Jupiter Neptune distance is defined by Earth and its
moon motions – which shows that- interactions are found between Jupiter motion
on one side and earth and its moon motion on the other side
-

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Moon Creation Effect On The Solar System Geometry (II)

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