The Moon Orbital Inclination

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Orbital Inclination
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –6th
April 2021
Abstract
Paper Question
- The moon orbital inclination is 5.1 degrees
- But the rate 5.1 is used frequently through the planets motions data, for example
- (Venus velocity) / (Uranus velocity) = 5.14
- (Mars velocity) / (Pluto velocity) = 5.14
- (the moon velocity) / (Neptune velocity) = 5.14
- The rate 5.1 is used among tenths of the planets motions data – the question simply
is Why?
- The paper provides this data and discuss why this huge number of data rated to one
another by this same rate (5.1)!

I do this research
2nd
2
1- The Moon Orbital Inclination Data
(I) Between distances
(1)
550.7 mkm = 5.1 x 108.2 mkm
(2)
778.6 mkm = 5.1 x 153 mkm
(3)
610.5 mkm = 5.1 x 119.7 mkm
(4)
5906 mkm = 5.1 x 1158 mkm
(5)
3413 mkm = 5.1 x 671 mkm
(6)
1557.2 mkm =5.1 x 305.3 mkm
(7)
135 mkm = 5.1 x 26.8 mkm
(8)
299.2 mkm = 5.1 x 58.66 mkm
(9)
3717 mkm =5.1 x 728 mkm
(10)
3034 mkm =5.1 x 595
(11)
37100 mkm = (5.1)2
x 1433.5 mkm
(12)
2814.6 mkm = 5.1 x 550.7 mkm
(13)
25920 mkm = 5.1 x 5083 mkm (1%)
(14)

I do this research
2nd
3
5906 mkm = 5.1 x 1158 mkm
(15)
1162.3 mkm =5.1 x 227.9 mkm
(16)
18360 mkm = 5.1 x 3600 mkm
(II) Between Degrees
(17)
17.4 degrees = 5.1 x 3.4 degrees
(18)
28.56 degrees = 5.1 x 5.6 degrees
(19)
10098 mkm =5.1 x 1980 mkm
(II) Between Diameters
(20)
12104 km = 5.1 x 2390 km
(21)
49528 km = 5.1x 2 x 4879 km
(22)
10921 km x π = 5.1x 6792 km (1%)
(23)
12430 km x2 = 5.1 x 4875km
(24)
120536 km = 5.1 x π x 7510 km
(25)
232000 x π = 5.1 x 142984 km
(III) Between Cycles
(26)
6939.75days = 5.1 x 1361 days

I do this research
2nd
4
(27)
88 days =5.1 x 17.25
(28)
90560 days = (5.1)2
x 3475
(29)
7510 days = 5.1 x 1461 days
(30)
16.1 hours = 5.1 x π
(31)
10747 x 2 = 5.1 x 4222.6
(32)
30589 x2 = 5.1 x 12104
(33)
122.5 = 5.1 x 24
(34)
1407.6 h = 5.1 x 276 h

I do this research
2nd
5
2- The Moon Orbital Inclination Effect
2-1 Venus, Uranus and Pluto Cycles
2-2 Venus Data Analysis
2-1 Venus, Uranus and Pluto Cycles
This point provides only Venus Data which is rated based on 5.1
I- Data
(a)
Venus Velocity (35 km/s) = 5.14 x Uranus Velocity (6.8 km/s)
(b)
Venus Diameter 12104 km =5.1 x Pluto Diameter 2390
(c)
Venus orb. Inclination 3.4 deg = 17.2 deg Pluto orb. Inclination / 5.1 (1%)
(d)
3413 mkm = 5.1 x 671 mkm (Venus Jupiter Distance)
(e)
550.7 mkm = 5.1 x 108.2 mkm (Venus Orbital Distance)
(f)
135 mkm = 5.1 x 26.8 mkm
(g)
595.5 days = 5.1 x 116.75 days (Venus Day Period)
(h)
30589 days x 2 = 5.1 x 12104 days (1%)
(i)
610 mkm = 5.1 x 119.7 mkm (Venus Mars Distance)
(j)
119.7 mkm =5.1 x 23.45 mkm

I do this research
2nd
6
II- Discussion
Equation No. (a)
Venus Velocity (35 km/s) = 5.14 x Uranus Velocity (6.8 km/s)
Equation No. (b)
Venus Diameter 12104 km =5.1 x Pluto Diameter 2390
- We need to see the interaction between Uranus and Venus motions on one side and
Uranus and Pluto motions on the other side – let's try to do that in following:
1st
Point
- Pluto (4.7 km/s) moves during 90560 seconds a distance = 425632 km (1)
- But
- Venus (35 km/s) during 12104 sec moves a distance = 423640 km (2)
- And
- Uranus (6.8 km/s) during its day (17.2 h) moves a distance = 421056 km (3)
- And
- (1) – (2) = 1992 km
- (1) – (3) = 4576 km
- (2) – (3) = 2584 km
- The distance 1992 km during 6 Cycles be = 12104 km = Venus diameter
(Error 1.2%)
- The distance 2584 km during 6 Cycles be = 15334 km = Mercury Circumference
(Error 1%)
- Where, 90560 days = Pluto Orbital Period
i.e.
1. Pluto (4.7 km/s) during 6 x 90560 seconds moves a distance = 2553792 km
2. Uranus (6.8 km/s) during (6 x 17.2 hours) moves a distance = 2526336 km
3. Venus (35 km/s) during (6 x 12104 seconds) moves a distance = 2541840 km
- (1) – (2) = 27456 km (= The solar day 86400 seconds /π)
- (1) – (3) = 11952 km (= 12104 km Venus diameter error 1.2%)
- (3) – (2) = 15504 km (= 15328 km Mercury Circumference error 1%)

I do this research
2nd
7
2nd
Point
- Why Mercury Circumference & Venus diameter are defined by these cycles?
- The planet definition as a rigid body will not help us. We need to accept that, the
matter dimensions are defined based on its motion features – So, the motion of
matter is defined before this matter creation- and because of that the matter
dimensions are defined in harmony with its (potential) motion – even space
dimensions also is defined in proportionality with the matter dimensions based on
this matter (potential) motion
Notice (1)
- Pluto uses the period 90560 seconds, where Pluto orbital period =90560 days, that
because, the solar planets data are defined based on these planets motions (similar
to Mercury circumference and Venus diameter which are defined by these cycles)
and because of that, the planets data are used in different forms – that means-
there's a period =90560 days, but also there's a period = 90560 seconds, and there's
another period =90560 minutes, and another =90560 hours….these periods are
used in different planets motions (specially Pluto motion) but we see only Pluto
motion during its orbital period (90560 days) and because of that we know this
period 90560 days but we don't know the others
Notice (2)
- We here discover the cycle of (6) used by Uranus days, Pluto period (90560 s) and
Venus diameter as a period (12104 s)
- But we have discovered before the cycle of (8) days which is used by (8 days
Jupiter for Jupiter motion) and (8 days Pluto for Uranus motion) – So we have 2
numbers which are (6 and 8) BUT
o Mercury Day Period 175.94 days = 2 x 88 days (Mercury orbital period)
o Mercury Day Period 175.94 days = 3 x 58.66 days (Mercury rotation period)
o That tells these cycles effect on the planets motions but we need to follow
these cycles to see how these (6 and 8) cycles produce the (2 and 3) periods.

I do this research
2nd
8
3rd
Point
Pluto (4.7 km/s) during 6 x 90560 seconds moves a distance = 2553792 km
- This data shows the moon orbit circumference origin – and supports again the
claim that – the moon apogee circumference is created by an effect of Pluto
- 2553792 km = 2π x 406450 km
- The moon apogee radius =406000 km
- That means, the moon apogee circumference = 2553792 km = Pluto motion
distance during (6 x 90560 seconds)
- Which shows interaction reason between the moon apogee orbital circumference
and Mercury circumference on one side and Venus diameter on the other side
- The data shows clearly the origin reason why Pluto and Venus data is in full
harmony with the moon apogee orbital circumference

I do this research
2nd
9
4th
Point (Uranus Orbital Distance)
Uranus (6.8 km/s) during 2 x (243 h)2
moves a distance = 2891 mkm
Where
- 243 solar days = Venus Rotation Period
- 2872.5 mkm = Uranus Orbital Distance
- Uranus depends on Venus rotation period (243 days) to move a distance = Uranus
Orbital Distance (error 0.6%)
- That shows, the interaction of motion which we have discussed in the previous
points extends its effect on different data
- Why the equation uses the number (2)?? It's some usual feature in Uranus Venus
Data to use the number (2), for sure there's a geometrical reason pushes the data to
use this number between both planets – we have to find this reason once.
- But how this data can be related to Uranus day period – let's try to see that in
following…
Uranus (6.8 km/s) during 2 x (243 h)2
moves a distance = 2891 mkm
But
Uranus (6.8 km/s) during 243 x 17.2 h (Uranus day) x 28.3 moves a distance =
2895 mkm (error 1%)
- 2 x 243 h = 17.2 h (Uranus day period) x 28.3 (Neptune Axial Tilt)
- That means
- Neptune effects on Uranus orbital distance definition but Venus can veils Neptune
effect by using 2 values of its rotation period and by that (the value 243 x 17.2 x
28.3) will be (2 x 243), So Neptune axial tilt & Uranus day period both be hidden
inside Venus rotation period.
- The next question is that,
- Can Venus be so strong to veil these great planets data effect? Let's see in
following

I do this research
2nd
10
5th
Point (Venus Axial Tilt)
I-Data
(A-1)
177.4 deg (Venus Axial Tilt) = 28.3 deg (Neptune Axial Tilt) x 2π
(A-2)
177.4 deg (Venus Axial Tilt) = 98.6 deg x 1.8 deg (Neptune orb. Inclination)
(A-3)
273 degrees = 177.4 degrees +95.1 degrees
(A-4)
273 mkm = 88 x 3.1 mkm
327.6 mkm = 273 x 1.2 mkm
273 mkm = 1.16 mkm/ s x 235.3 seconds (but 6939.75 =27.3 x 235)
273 mkm = 0.406 mkm x 672.4 days
(A-5)
2 x 273 mkm = 3.02 mkm (Venus velocity daily) x 180.8
(A-6)
180.8 deg – 95.1 deg = 85.7 deg = π x 27.27 deg
II-Discussion
Equation (A-1)
177.4 deg (Venus Axial Tilt) = 28.3 deg (Neptune Axial Tilt) x 2π
- Equation (A-1) tells that, Venus axial tilt contains Neptune Axial Tilt, and because
of that, Venus can hide Neptune axial tilt effect by its own data
Equation (A-2)
177.4 deg (Venus Axial Tilt) = 98.6 deg x 1.8 deg (Neptune orb. Inclination)
- This equation tells how Venus axial tilt is created, where Uranus uses its number
(98.6 deg) to create it….
- 98.6 deg = 97.8 deg (Uranus Axial Tilt) + 0.8 deg (Uranus orb. Inclination), that
means, Uranus uses its full power to create Venus Axial Tilt.

I do this research
2nd
11
- Neptune orbital inclination (1.8 deg) effect on this process also, but still Uranus
effect on Venus axial tilt is so strong one and Venus axial tilt express Uranus
motion features more than Neptune motion features …. Why?
o Uranus Axial Tilt (97.8 deg) = 122.5 deg x 0.8 deg,
o Where
o 122.5 deg = Pluto Axial Tilt
o 0.8 deg = Uranus Orbital Inclination
o
o This data tells, Uranus and Pluto axial tilts are interacted with each other,
that creates one general power by them, and this power causes the regression
in the solar system motion -
o Venus axial tilt regresses also by this power effect on Venus motion, and
also the moon orbit regresses as a result for this power effect
o That shows, the previous points discussion about the 3 planets motions
depend on more wide discussion because these motions are not just
individual cases of data but it's the 3 planets general stream of data – means
the interaction between these 3 planets motions (and also with earth motion)
that causes great effect on these planets motions
o Because of that, the moon apogee circumference is created by these motions
interaction where the moon apogee circumference is shorter than the moon
displacements total during 29.53 days with (1%) but this effect on the moon
motion is inherited by these 3 planets motions interaction.
Equation (A-3)
273 degrees = 177.4 degrees +95.1 degrees
- 95.1 degrees = 90 deg +5.1 deg (The Moon Orbital Inclination)
- The value 273 degrees is created as a summation of these 2 important values,
Venus axial tilt and the moon orbital inclination. but why it's important one?

I do this research
2nd
12
Equation (A-5)
2 x 273 mkm = 3.02 mkm (Venus velocity daily) x 180.8 days
- Where
- 180.8 deg = 177.4 deg (Venus Axial Tilt) + 3.4 deg (Venus orb. Inclination)
- And
- 0.8 deg = Uranus orbital inclination but 180 deg +0.8 deg =180.8 degrees
- 180.8 deg can be used as 180.8 mkm, but the data uses it here as 180.8 days
- Venus during 180.8 days moves a distance = 2 x 273 mkm…
- Because the value 180.8 degrees shows Uranus data effect on Venus motion – So,
the value 273 mkm expresses Uranus motion effect on Venus motion
- Again the data uses the number (2) as a usual feature for Uranus effect on Venus
motion.
- We remember that
- 273 deg =177.4 deg (V. axial tilt) +95.1 deg (the moon orb. Inclination vertically)
- But
- ((2765 mkm Venus Uranus Distance) /273 mkm) = (47.4/4.7)
- 47.4 km/s Mercury Velocity
- 4.7 km/s Pluto Velocity
- Because Mercury is the greatest velocity and Pluto is the smallest that shows this
equation shows the solar system motion range – and that shows the great effect of
the distance 273 mkm
Equation (A-6)
180.8 deg – 95.1 deg = 85.7 deg = π x 27.27 deg
- This equation produces 27.2 deg (or 27.2 days = the nodal month) depends on both
values 180.8 & 95.1 degrees – showing that 27.2 days is produced by Uranus
effect on the moon motion

I do this research
2nd
13
Equation (A-7)
1392000 = 27.2 x 51118
- Where
- 1392000 km = The Sun Diameter
- 51118 km = Uranus Diameter
- The nodal month (27.2 days) is a rate between the sun and Uranus diameter which
shows that this value (27.2 days = the nodal month) is created by Uranus effect on
the moon motion.
Notice
18040 mkm = 273 mkm x 66.1
30589 days = 273 days x 112.1

I do this research
2nd
14
2-2 Venus Data Analysis
Equation (c)
Venus orb. Inclination 3.4 deg = 17.2 deg Pluto orb. Inclination / 5.1 (1%)
- 5.1 deg = the moon orbital inclination
- 17.4 deg = The inner planets orbital inclinations total (7 +3.4 +5.1+1.9 =17.4)
- The question is if this value 17.4 degrees has a difference 1% with 17.2 deg (Pluto
o0brtila inclination), does that mean these 2 values are equal? Or can we consider
these 2 values as one value only?
- I can't answer…. For example
- Mars orbital circumference = 1433 mkm = Saturn orbital distance,
- Of course these are different distances but Why They Are Equal?
- In square, we see its 4 dimensions are equal, but because of geometrical necessity,
what geometrical necessity forces Pluto orbital inclination (17.2 deg) to be 99% of
the inner planets orbital inclinations total
- The same argument still shows itself frequently
o The separated rigid bodies description for the solar planets is incorrect
description and prevents any serious try to understand the solar system
creation and motion.
o Because
o The data is created in proportionality with one another – not only between
17.2 and 17.4 but in hundreds of data (is provided here), the dependency
between the data is a basic feature no one can escape from it
o By different ways we try to explain how these data is created, but when the
explanation be insufficient, we have no option to refuse the dependency
concept as total because it's simply a fact.
o The equation tells some relationship is found between Venus, Pluto and the
moon motions – which causes this data..

I do this research
2nd
15
Equation (d)
3413 mkm = 5.1 x 671 mkm (Venus Jupiter Distance)
- Where
- 3413 mkm (360 mkm + 680 mkm +940 mkm +1433 mkm)
o 360 mkm = Mercury Orbital Circumference
o 680 mkm = Venus Orbital Circumference
o 940 mkm = Earth Orbital Circumference
o 1433 mkm = Saturn Orbital Circumference
- But we know that
- 4900 mkm = (360 mkm + 680 mkm +940 mkm +1433 mkm + 1433 mkm)
- 4900 mkm = Jupiter Orbital Circumference
- 5.2 x 149.6 mkm (Earth orbital distance) = 778.6 mkm (Jupiter orbital distance)
But
- 5.1 x 153 mkm (Earth orbital distance) = 780 mkm (Jupiter orbital distance)
(Ancient Values)
- There's a geometrical mechanism between Jupiter orbital distance and the inner
planets orbital distance based on which the rate 5.1 is created between Jupiter and
Earth orbital distances (ancient values) and based on this rate the moon orbital
inclination be created by 5.1 degrees
- Means,
- The geometrical mechanism by which Earth orbital distance is defined, defines
also the moon orbital inclination to be 5.1 degrees because the rate between Jupiter
and Earth orbital distance =5.1
- The rate 5.1 is changed because Earth changed its orbital distance (153 mkm) to be
149.6 mkm and Jupiter changed its orbital distance from (780 mkm) to be 778.6
mkm and that changes the rate from 5.1 to 5.2

I do this research
2nd
16
Uranus Motion Effect
- This story provides no more difficulties here than one change for the rate from 5.1
into 5.2 ….
- The difficulties is found with Uranus as a result
- Because
- 97 deg = 97.8 deg (Uranus Axial Tilt) – 0.8 deg (Uranus orb, inclination)
- But
- 97 deg = 19 x 5.1 deg (the moon orbital inclination)
- When the moon orbital inclination be 5.2 degrees, because of the rate between
Jupiter orbital distance and Earth orbital distance – the result will be
- 98.8 deg = 19 x 5.2 deg (the moon orbital inclination)
- This number 98.8 deg is NOT found at all
- Uranus has no this number ….
- But Uranus has 98.6 degrees only where
- 98.6 degrees = 19 x 5.18 degrees (the possible moon orbital inclination)
- But Uranus must do the following
- 97 deg = 97.8 deg (Uranus Axial Tilt) + 0.8 deg (Uranus orb, inclination)
- That shows change in Uranus motion behavior as a result for the change of the rate
5.1 to be 5.18
- Still the rate 5.18 needs to be 5.2 where Uranus data has no this ability to create
the number 98.8
- That tells some behavior must be found as a result to stop this stress on Uranus –
- When the geometrical mechanism be discovered we should expect what behavior
Uranus will do to correct this situation and makes the rate 5.1 again and not 5.2

I do this research
2nd
17
Equation (e)
550.7 mkm = 5.1 x 108.2 mkm (Venus Orbital Distance)
- Where
- 550.7 mkm = Mars Jupiter Distance
Equation (f)
135 mkm = 5.1 x 26.8 mkm
- Where
- 135 mkm = a distance Earth moves during 1259.3 hours
- The distance 135 mkm starts from the sun to a point between Venus and Earth,
specifically it's found after Venus with 26.8 mkm and before Earth with 14.6 mkm
- The distances 26.8 mkm and 135 mkm are rated by 5.1
- Some geometrical mechanism causes this rate
- Please remember
- The distance from this point (135 mkm) to Uranus =2737 mkm
Equation (g)
595.5 days = 5.1 x 116.75 days (Venus Day Period)
- Because Venus uses distance values as periods of time and vice versa we need to
analyze the value 595.5 days as 595.5 mkm
- This distance 595.5 mkm is specific one in the solar system let's provide its data in
following
- Venus (35 km/s) moves during 6.7 x (29.53 days) a distance = 598.3 mkm
o 29.53 days = The Moon Day Period
o 6.7 degrees = The Moon Axial Tilt
- Uranus (6.8 km/s) moves during 17.2 h x 1407.6 a distance = 592.7 mkm
o 17.2 hours = Uranus Day Period
o 1407.6 hours = Mercury Rotation Period

I do this research
2nd
18
- Pluto (6.8 km/s) moves during 50 x (29.53 days) a distance = 599.6 mkm
o 29.53 days = The Moon Day Period
- Pluto & Venus motions are very near but there's an error 1% with Uranus
Motion Distance
- Please Remember, we have a similar situation before – which is
Data No. 1
a- The Moon Orbital Circumference at apogee radius = 2550973 km (100%)
b- Earth Daily Motion Distance = 2573483 km (101%)
c- Pluto moves during 153.3 hours =2593836 (102%)
d- The displacements 88000 km total during (29.53 days) = 2598693 km (102%)
e- Uranus (63.8 km/s) moves (during 378675 seconds) = 2574990 km (101%)
f- Saturn (9.7 km/s) moves during 6.8 x (10.7 hours) = 2540779 km
Data no. 2
(1)
Earth moves during (6939.75 solar days) a distance = 17859.325 mkm
(2)
Pluto moves during (6939.75) x (153.3 hours) a distance = 18000.57 mkm
(3)
The moon displacements total during (6939.75) x (29.53 days) = 18034.278 mkm
(4)
Uranus Orbital Circumference = 18048.449 mkm
(5)
Mercury moves during (4331 days) a distance = 17737 mkm
(6)
Mars moves during (2x 4331 days) a distance = 18036.3 mkm
(7)
Venus moves during (5906 days) a distance = 17860 mkm
(notice Venus distance = Earth distance accurately)
There's a geometrical mechanism behind this data

I do this research
2nd
19
Equation (h)
30589 days x 2 = 5.1 x 12104 days (1%)
- Please remember
o Venus (3.02 mkm/ daily) moves during 12104 days = 2 x 18040 mkm
(Error 1.2%)
o Uranus (0.587 mkm/ daily) moves during 2x 30589 days = 2 x 18040 mkm
o The rate between both =5.1
o Because Venus velocity / Uranus velocity =5.1
o This data is created by geometrical necessities and rules.
Equation (i)
610.7 mkm = 5.1 x 119.7 mkm (Venus Mars Distance)
- Where
- 610.7 mkm = the moon displacements total during Metonic Cycle (6939.75 days)
- A geometrical mechanism is found behind.
Equation (j)
119.7 mkm =5.1 x 23.45 mkm
- Where
- 23.45 mkm = 23.45 degrees = Earth Axial Tilt
- 119.7 mkm = Venus Mars Distance

I do this research
2nd
20
References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The Moon Orbital Inclination

Recommended

Recommended

More Related Content

What's hot

What's hot (20)

Similar to The Moon Orbital Inclination

Similar to The Moon Orbital Inclination (20)

More from Gerges francis

More from Gerges francis (20)

Recently uploaded

Recently uploaded (20)

The Moon Orbital Inclination