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Mathematical Problem (Weaving)
width.FabricX
PPIXEPI
countweftXcountwarp
Problem: Fabric specification: 06
5070
810
′′×
×
×
1. Calculate the fabric weight
of 1000m.
2. Calculate production per hour if
PPM=180
Solution:
Warp calculation
EPI = 70
Width of fabric = 60 inch
So, Total no. of warp = 70 X 60 = 4200
Now, Length of each warp = 1000m + 1000 X 3% [3% = crimp]
= 1030m.
Total length of the warps = 4200 X 1030
= 4326000m.
= (4326000 X 1.09) = 4715340 yards
Total weight of the warps =
10x840
4715340
pounds [warp count = 10]
= 561.35 pounds
Weft calculation
PPI = 50
Fabric length = 1000 meter = 1000 X 39.37 inch = 39370 inch
So, Total no. of wefts = 50 X 39370
Now, Length of each weft = 60 + 60 X 5% [crimp = 5%]
= 63 inch = 63/36= 1.75 yards
Total length of the wefts = 50 X 39.37 X 1000 X 1.75 yards
= 3444875 yards
Total weight of the wefts =
8x840
3444875
Pounds [Weft count = 8]
= 512.63 pounds
So total weight of fabric = 561.35+512.63 = 1073.98 pounds (Answer)
= 1073/2.2 = 487.72 kg (Answer)
Again, we know, loom production = PPM/PPI
= (180/50) inch/minute
= 3.6 inch/minute
= (3.6 X 60)/36
= 6 yards/hour (Answer)
= (6/1.09) = 5.50 meter/hour (Answer)
Alternate solution: Fabric specification: 06
5070
810
′′×
×
×
Warp calculation
Weight of warps in Kg = 2.2×(Ne)Countx840
1.09×1.03×(m)Length×(inch)Width×PIE
=
2.2×10x840
1.09×1.03×1000×60×07
= 255.16 kg
Weft calculation
Weight of wefts in Kg = 2.2×(Ne)Countx84036
39.371.05×(m)Length×(inch)Width×PI
×
×P
=
2.2×8x84036
39.371.05×1000×60×05
×
×
= 233.01 kg
So total weight of fabric = 255.16+233.01 = 488.17 kg (Answer)
Again, loom productions in meter/hour =
36×1.09
60×PM
×PPI
P
=
36×1.0950
60×801
×
= 5.50 meter/hour (Answer)
For Practice…………….
Problem 2: Find out Wt. of 5000 m fabric. Fabric specification is 65
5860
2202
′′×
×
×
Problem 3: Find out the wt. of required warp & weft to produce 5000m fabric
85
6266
1618
′′×
×
×
18 16
58
66 62
×
′′×
×
Problem 4: Calculate the yarn consumption of a loom per hour running at 180 PPM for
producing
40 60
56
72 48
×
′′×
×
fabric.

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Weaving calculation

  • 1. Mathematical Problem (Weaving) width.FabricX PPIXEPI countweftXcountwarp Problem: Fabric specification: 06 5070 810 ′′× × × 1. Calculate the fabric weight of 1000m. 2. Calculate production per hour if PPM=180 Solution: Warp calculation EPI = 70 Width of fabric = 60 inch So, Total no. of warp = 70 X 60 = 4200 Now, Length of each warp = 1000m + 1000 X 3% [3% = crimp] = 1030m. Total length of the warps = 4200 X 1030 = 4326000m. = (4326000 X 1.09) = 4715340 yards Total weight of the warps = 10x840 4715340 pounds [warp count = 10] = 561.35 pounds Weft calculation PPI = 50 Fabric length = 1000 meter = 1000 X 39.37 inch = 39370 inch So, Total no. of wefts = 50 X 39370 Now, Length of each weft = 60 + 60 X 5% [crimp = 5%] = 63 inch = 63/36= 1.75 yards Total length of the wefts = 50 X 39.37 X 1000 X 1.75 yards = 3444875 yards Total weight of the wefts = 8x840 3444875 Pounds [Weft count = 8] = 512.63 pounds So total weight of fabric = 561.35+512.63 = 1073.98 pounds (Answer)
  • 2. = 1073/2.2 = 487.72 kg (Answer) Again, we know, loom production = PPM/PPI = (180/50) inch/minute = 3.6 inch/minute = (3.6 X 60)/36 = 6 yards/hour (Answer) = (6/1.09) = 5.50 meter/hour (Answer) Alternate solution: Fabric specification: 06 5070 810 ′′× × × Warp calculation Weight of warps in Kg = 2.2×(Ne)Countx840 1.09×1.03×(m)Length×(inch)Width×PIE = 2.2×10x840 1.09×1.03×1000×60×07 = 255.16 kg Weft calculation Weight of wefts in Kg = 2.2×(Ne)Countx84036 39.371.05×(m)Length×(inch)Width×PI × ×P = 2.2×8x84036 39.371.05×1000×60×05 × × = 233.01 kg So total weight of fabric = 255.16+233.01 = 488.17 kg (Answer) Again, loom productions in meter/hour = 36×1.09 60×PM ×PPI P = 36×1.0950 60×801 × = 5.50 meter/hour (Answer)
  • 3. For Practice……………. Problem 2: Find out Wt. of 5000 m fabric. Fabric specification is 65 5860 2202 ′′× × × Problem 3: Find out the wt. of required warp & weft to produce 5000m fabric 85 6266 1618 ′′× × × 18 16 58 66 62 × ′′× × Problem 4: Calculate the yarn consumption of a loom per hour running at 180 PPM for producing 40 60 56 72 48 × ′′× × fabric.