Interpretation of statistical values
                &
  fundamentals of epidemiology
                      Dr.Asma Rahim
                    Dr.Bindhu vasudevan


                Dept. of Community Medicine
What you are expected to Know?
•   Mean
•   What is SD ?
•   What is SE?
•   What is Confidence limits as noted
    in many journals?
• What is P value ?How to interpret it?

• Which are the different statistical tests to be
  applied on different situations?

• Study designs in Medical research.

• Measurements of risk in clinical research

• What is sensitivity ,Specificity, Predictive
  value of a test?
Dilemma of a PG Student!!!
•DNB exams more stress on Original work.

•Methodology of your work is important.

•Look ahead for statistical queries.

•Examiners familiar with research designs

•OSCE stations have questions on
Statistics.
Types of variables
• Qualitative
  – Dichotomous
  – Nominal
  – Ordinal
• Quantitative
  – Discrete
  – Continuous
1. Which is a qualitative variable
•   a) BMI
•   b) S. bilirubin
•   c) Name of residing place
•   d) Blood urea
2. Which is a quantitative variable

•   Causes of deaths
•   Religious distribution
•   Age group distribution
•   Age distribution
4. Which is an ordinal variable

•   A)Blood pressure
•   B)Name of residing place
•   C)Grading of carcinoma
•   D) temperature
5. Which is not a nominal scale
               variable
•   A)Causes of death
•   B) religion
•   C)diagnosis
•   D)visual analogue scale
Quantitative data   Qualitative data

Hb in gm%           Anemic/non anemic

Height in cm        Tall/short

B.P in mm of Hg     Hypo/normo/
                    hypertensives
In a group of 100 under five children
attending IMCH O.P the mean weight is
   15kg. The standard deviation is 2.

1.In what range 95% of children’s weight
          will lie in the sample?

 2. In what range the mean weight of all
  children who are attending IMCH OP
                will lie?
Range in which 95% children’s weight in the
 sample will lie:
  95% reference range =
    mean +/- 2SD = 13-17Kg

Range in which 95% children’s weight
 attending IMCH O.P will lie:
  95% Confidence interval =
  mean +/- 2SE( Standard error)-
Standard Error



           17
     19

                           16



          17kg
                            18

15
Central limit Theorem
• Central limit theorem states that
• The random sampling distribution of
  sample means will be normal distribution
• Means of random sample means will be
  equal to population mean
• The standard deviation of sample means
  from population mean is the standard error
• The PEFR of 100, 11 year old girls follow a
  normal distribution with a mean of 300 1/min,
  standard deviation 20 l/min and standrd error of
  2 l/min

• What will be the range in which 95% of the girl’s
  PEFR will lie in the sample?


• What will be the range in which mean of the
  population will lie from which the sample was
  taken?
Range in which 95% of girls PEFR in the
 sample will lie:
  mean +/- 2SD = 260 - 340

Range in which mean PEFR Value will lie:
 mean +/- 2SE( Standard error)- 95%
 Confidence interval = 298-304
Normal distribution curve
•
Sample size
• Calculate the sample size to find out the
  prevalence of a disease after implementing
  a control programme with 10% allowable
  error. Prevalence of the disease before
  implementing the programme was 80 %
Sample size
• Qualitative data N = 4pq/L2
• P = positive factor /prevalence/proportion
     • Q = 100 – p
     • L = allowable error or precision or
       variability
• Quantitative data N = 4SD2/L2
• N= 4 x 80 x 20/8 x 8 = 100
• Determine the sample size to find out the Vitamin A
  requirement in the under five children of Calicut
  district . From the existing literature the mean daily
  requirement of the same was documented as 930 I.U
  with a SD of 90 I.U. Consider the precision as 9.
• N = 4SD2/L2

• 4 x 90 x 90 /9 x9 = 400
• Determine the sample size to prove that
  drug A is better than drug B in reducing the
  S.Cholesterol. The findings from a previous
  study is given
      Drug        Mean        SD


      A           215         20


      B           240         30
• Quantitative data N =
     (Zα + Zβ )2 x S2 x 2 /d2
Zα = Z value for α level = 1.96 at α 0.05
Zβ = Z value for β level =1.28 for β at 10%
S = average SD
d = difference between the two means
• Qualitative data N =
      (Zα + Zβ )2 p x q /d2
Zα = Z value for α level = 1.96 at α 0.5
Zβ = Z value for β level =1.28 for β at 10%
P = average prevalence
d = difference between the prevalence
Reject           Accept
                Null hypothesis Null hypothesis

Null hypothesis Type 1 error    Correct
true            (alpha error)   decision

Null hypothesis Correct         Type 2 error
false           decision        (Beta error)
•   Alpha = 1.96.
•   Beta = 0.1 to 0.2 or 10 to 20%.
•   Power of the study = 1- beta error
•   Strength at which we conclude there is no
    difference between the two groups.
Statistical test chosen depends on----

• Whether comparison is between
  independent or related groups.

• Whether proportions or means are being
  compared.

• Whether more than 2 groups are compared.
Deciding statistical tests?
• In a clinical trial of a micronutrient on
  growth, the weight was measured before
  and after giving the micronutrient.. Which
  test will you use for comparison?
• paired t test
• F test
• T test
• Chi square test
Parametric and Nonparametric tests

Parametric: When the data is normally
  distributed.

Nonparametric : When data is not normally
 distributed,usually with small sample size.
Common statistical tests
Design            Nature of variable          Statistical test   Statistic derived

Two independent    Qualitative (nominal)        Chi square       Chi square

Groups             Quantitative (continous)     Student t test   t


Two related
groups            Qualitative (nominal)         Chi square       Chi square

                  Quantitative (continous)      Paired t test    t




More than 2       Qualitative (nominal          Chi square       Chi square


Independent       Quantitative (continous)       Anova           F
groups
Difference in proportion    Chi-square test, Z test,




Difference in mean(Before   Paired t test
and after comparison-same
group)
Difference in mean (two     Unpaired t test, If sample
independent groups)         > 30-Z test
More than 2 means(> 2       Anova
groups)
Association                 Spearman correlation
Prediction                  regression
Non parametric tests
Chi-square test
Fishers test,
Mc Nemar test
Wilcoxon Signed rank test Paired t test
Wilcoxon test , Mann-     independent t test
Whitney U , Kolmogrov

Kruskal-wallis test       Anova
The most appropriate test for
 comparing Hb values in the adult
women in two different population of
       size 150 and 200 is
 •   A) t test
 •   B) Anova
 •   C) Z test
 •   D) Chi square test
Answer

• C
  –   Two groups
  –   >30
  –   Continuous variable
  –   Comparing mean
The most appropriate test to
         compare birth weight in 3
            different regions is
•   A) t test
•   B) Anova
•   C) Z test
•   D) Chi square test
Answer

• B
  – Continuous variable
  – Compare means
  – > 2 groups
The most appropriate test to
      compare BMI in two different
      adult population of size 24 and
                   30 is
•   A) Two sampled t test
•   B) Paired t test
•   C) Z test
•   D) Chi square test
Answer

• A
  – Two different groups
  – Continuous variable
  – Size <30
The association between smoking
       status and MI is tested by
•   A) t test
•   B) Anova
•   C) F test
•   D) Chi square test
Standard drug used 40% of patients responded
  and a new drug when used 60% of patients
  responded. Which of the following tests of
 parametric significance is most useful in this
                    study?
• A) Fishers t Test
• B) Independent sample t test
• C) Paired t test
• D) Chi square test.
• A consumer group would like to evaluate
  the success of three different commercial
  weight loss programmes. Subjects are
  assigned to one of three programmes
  (Group A , Group B ,GROUP C) . Each
  group follows different diet regimen. At
  first time and at the end of 6 weeks subjects
  are weighed an their BP measurements
  recorded.
Test to detect mean difference in
body weight between Group A &
            Group B

• T-TEST

• Difference between means of two samples
Is there a significant difference in body
 weight in Group A at Time 1 and Time
                     2?
• Paired T Test

• Same people sampled on two Occasions.
Is the difference in body weight of subjects in
  Group A,GROUP b ,group C significantly
               different at Time 2
• Analysis of variance
Is there any relation between blood pressure
      and body weight of these subjects?

• Correlation
Correlation coefficient
• Shows the relation between two quantitative
  variable
• Shows the rate of change of one variable as
  the other variable change
• The value lies between –1 to + 1
• Correlation coefficient of zero means that
  there is no relationship
No.of deaths in 8 villages due to
 water borne diseases before &
after installation of water supply
               system
• Villages: 1 2 3 4     5 6 7 8
• Before :13 6 12 13    4 13 9 10
• After    :15 4 10 9   1 11 8 13
Did the Installation of water
     supply system significantly
            reduce deaths

•   Small sample size
•   Distribution is not normal
•   Non parametric test
•   Wilcoxon signed rank test
For treatment of Hepatitis A 7
     patients treated with herbal
 medicines& 7 patients treated with
Allopathic symptomatic management.
S.Br values after 10 days of treatment
            is given below
• Herbal   :9    6   10   3   6   3   2

• Allopathy: 6   3   5    6   2   4   8
Is herbal treatment is better than
          allopathic treatment?
•   Small sample size
•   Distribution is not normal
•   Non parametric test
•   Mann- Whitney test
After applying a statistical test an
    investigator get the p value as
          0.01. It means that
• A)The probability of finding a significant
  difference is 1%
• B) The probability of finding a significant
  difference when there is no difference is 1%
• C) The difference is not significant 1%
  times and significant 99% times
• D) The power of the test used is 99%
Answer
• B
• Null hypothesis states there is no difference,If
  there is any difference it is due to chance
• P value = If the null hypothesis is true the
  probability of the sample variation to occur by
  chance
• P value 0.05= probability of the sample variation
  by chance is only 5% if null hypothesis was true
• 95% the sample variation is not due to chance,&
  there is a difference. So we will reject NH
• P = 0.01 - probability of the sample
  variation by chance is only 1% if null
  hypothesis was true
• 99 % the sample variation is not due to
  chance,& there is a difference. So we will
  reject NH
• As p value decreases the difference become
  more significant
• For practical purpose p value < 0.05 ; the
  difference is significant
In assessing the association between
    maternal nutritional status and Birth
weight of the newborns two investigators
   A and B studied separately and found
  significant results with p values 0.02 &
0.04 respectively. From this what can you
 infer about the magnitude of association
                found by the
              two investigators
Type of study                         Alternative      Unit of study
                                      name
Descriptive        Case series        Prevalence
                   Cross sectional    study           Individual
                   Longitudinal       Incidence study

                                      Correlational
Analytical         Ecological         Case reference   Populations
studies            Case control       Follow up        Individuals
(observational     Cohort                              Individuals

Analytical studies Randomised         Clinical trial   Patients
(interventional)   controlled trial   Community        Healthy people
                   Field trial        intervention
                   Community          Community        Healthy people
                   trials
Study questions and appropriate designs

Type of question      Appropriate study design
Burden of illness     Cross sectional survey
                      Longitudinal survey
Causation, risk and   Case control study, Cohort study
prognosis
Occupational risk,    Ecological studies
environmental risk
Treatment efficacy    RCT
Diagnostic test       Paired comparative study
evaluation
Cost effectiveness    RCT
Odd’s ratio
• In a study conducted by Gireesh G N etal
  about the ‘Prevalence of Worm infestation
  in children”,50 children in anganwadi were
   examined. Out of this 5 had worm
  infestation. 2 out of this 5 have a history of
  pet animals at home while 21 out of the 45
  non infested has a history of pet animals at
  home. Is there any association between pet
  animals and worm infestations?
Study design –Case control
• Measure of risk –Odd’s ratio
• Set up a 2x2 table       Worm infestation
                           +           -

                                   a        b
                       +   2           21
         Pet animals

                       -           c          d
                               3       24
• Odd’s ratio = ad /bc

• 2 x 24 = 0.76
  21 x3
Interpretation
• OR =1,RISK FACTOR NOT RELATED
  TO DISEASE

• OR <1 ,RISK FACTOR PROTECTIVE

• OR >1 RISK FACTOR POSITIVELY
  ASSOCIATED WITH DISEASE
Relative risk
• In a study to find the effect of Birth weight
  on subsequent growth of children , 300
  children with birth weight 2kg to 2.5 kg
  were followed till age 1 . A similar number
  of children with birth weight greater 2.5 kg
  were followed up too. Anthropometric
  measurements done in both groups. Results
  are shown below
Low birth weight Normal



No.children studied        300          300



No.malnourished
At age one                 102          51
Study design –Cohort study
• Measure of risk –Relative risk ,Attributable
  risk.
• Relative risk –Incidence among exposed
                 Incidence among nonexposed
                 = 102/300 = 0.34 = 2
                    51/ 300   0.17
           Inference ?
• An out break of Pediculosis capitis being
  investigated in a girls school with 291
  pupils.Of 130 Children who live in a nearby
  housing estate 18 were infested and of 161
  who live elsewhere 37 were infested. The
  Chi square value was found to be 3.93 .
• P value = 0.04
• Is there a significant difference in the
  infestation rates between the two groups?
Results of a screening test
                          Disease
                   Positive      Negative
        Positive   TP(a)         FP(b)

Test

       Negative    FN©           TN(d)
Features of a screening test
          Sensitivity = a/ a+c

          Specificity = d/b+d

     Positive predictive value = a/a+b
     Negative predictive value = d/c+d
     False positive rate = bb+d
     False negative rate = c/a+c
In a group of patients presenting to a hospital emergency
   with abdominal pain, 30% of patients have acute
   appendicitis, 70% of patients with appendicitis have a
   temperature greater than 37.50c and 40% of patients
   without appendictis have a temperature greater than
   37.50c. Considering these findings which of the
   following statement is correct ?
   a) Sensitivity of temperature greater than 37.50c as a
   marker for appendicitis is 21/49
   b) Specificity of temperature grater than 37.50c as a
   marker for appendicitis is 42/70
   c) The positive predictive value of temperature greater
   than 37.50c as marker for appendicitis is 21/30
   d) Specificity of the test will depend upon the
   prevalence of appendicitis in the population to which it
   is applied.
Sensitivity and Specificity
                              +
                   Appendicitis           -
                            21a     28b
Fever > 37.50c +
              -              9c           42d



                            30a+c    70b+d
• Sensitivity = a/a+c - 21/30=70%
• Specificity = d/b+d = 42/70=60%
• Positive predictive value = a/a+b =
                                 21/49=43%
• Negative predictive value = d/c+d = 42/51
Exercise 11
Disease prevalence in a population of
 10,000 was 5%. A urine sugar test with
 sensitivity of 70% and specificity of 80%
 was done on the population. The positive
 predictive value will be :
 a)15.55% b) 70.08% c) 84.4%
 d)98.06%
•   Total population = 10,000
•   Disease prevalence       = 5%
•   No diseased         = 500
•   Applying this to a 2x2 table :
2x2 table
          +           -


+ TEST   350 a     1900 b   2250


  -      150c       7600d   7750
         500        9500    10000
All the Best!!1

Statistics

  • 1.
    Interpretation of statisticalvalues & fundamentals of epidemiology Dr.Asma Rahim Dr.Bindhu vasudevan Dept. of Community Medicine
  • 2.
    What you areexpected to Know? • Mean • What is SD ? • What is SE? • What is Confidence limits as noted in many journals?
  • 3.
    • What isP value ?How to interpret it? • Which are the different statistical tests to be applied on different situations? • Study designs in Medical research. • Measurements of risk in clinical research • What is sensitivity ,Specificity, Predictive value of a test?
  • 4.
    Dilemma of aPG Student!!! •DNB exams more stress on Original work. •Methodology of your work is important. •Look ahead for statistical queries. •Examiners familiar with research designs •OSCE stations have questions on Statistics.
  • 5.
    Types of variables •Qualitative – Dichotomous – Nominal – Ordinal • Quantitative – Discrete – Continuous
  • 6.
    1. Which isa qualitative variable • a) BMI • b) S. bilirubin • c) Name of residing place • d) Blood urea
  • 7.
    2. Which isa quantitative variable • Causes of deaths • Religious distribution • Age group distribution • Age distribution
  • 8.
    4. Which isan ordinal variable • A)Blood pressure • B)Name of residing place • C)Grading of carcinoma • D) temperature
  • 9.
    5. Which isnot a nominal scale variable • A)Causes of death • B) religion • C)diagnosis • D)visual analogue scale
  • 10.
    Quantitative data Qualitative data Hb in gm% Anemic/non anemic Height in cm Tall/short B.P in mm of Hg Hypo/normo/ hypertensives
  • 11.
    In a groupof 100 under five children attending IMCH O.P the mean weight is 15kg. The standard deviation is 2. 1.In what range 95% of children’s weight will lie in the sample? 2. In what range the mean weight of all children who are attending IMCH OP will lie?
  • 12.
    Range in which95% children’s weight in the sample will lie: 95% reference range = mean +/- 2SD = 13-17Kg Range in which 95% children’s weight attending IMCH O.P will lie: 95% Confidence interval = mean +/- 2SE( Standard error)-
  • 13.
    Standard Error 17 19 16 17kg 18 15
  • 14.
    Central limit Theorem •Central limit theorem states that • The random sampling distribution of sample means will be normal distribution • Means of random sample means will be equal to population mean • The standard deviation of sample means from population mean is the standard error
  • 15.
    • The PEFRof 100, 11 year old girls follow a normal distribution with a mean of 300 1/min, standard deviation 20 l/min and standrd error of 2 l/min • What will be the range in which 95% of the girl’s PEFR will lie in the sample? • What will be the range in which mean of the population will lie from which the sample was taken?
  • 16.
    Range in which95% of girls PEFR in the sample will lie: mean +/- 2SD = 260 - 340 Range in which mean PEFR Value will lie: mean +/- 2SE( Standard error)- 95% Confidence interval = 298-304
  • 17.
  • 18.
    Sample size • Calculatethe sample size to find out the prevalence of a disease after implementing a control programme with 10% allowable error. Prevalence of the disease before implementing the programme was 80 %
  • 19.
    Sample size • Qualitativedata N = 4pq/L2 • P = positive factor /prevalence/proportion • Q = 100 – p • L = allowable error or precision or variability • Quantitative data N = 4SD2/L2
  • 20.
    • N= 4x 80 x 20/8 x 8 = 100
  • 21.
    • Determine thesample size to find out the Vitamin A requirement in the under five children of Calicut district . From the existing literature the mean daily requirement of the same was documented as 930 I.U with a SD of 90 I.U. Consider the precision as 9.
  • 22.
    • N =4SD2/L2 • 4 x 90 x 90 /9 x9 = 400
  • 23.
    • Determine thesample size to prove that drug A is better than drug B in reducing the S.Cholesterol. The findings from a previous study is given Drug Mean SD A 215 20 B 240 30
  • 24.
    • Quantitative dataN = (Zα + Zβ )2 x S2 x 2 /d2 Zα = Z value for α level = 1.96 at α 0.05 Zβ = Z value for β level =1.28 for β at 10% S = average SD d = difference between the two means
  • 25.
    • Qualitative dataN = (Zα + Zβ )2 p x q /d2 Zα = Z value for α level = 1.96 at α 0.5 Zβ = Z value for β level =1.28 for β at 10% P = average prevalence d = difference between the prevalence
  • 26.
    Reject Accept Null hypothesis Null hypothesis Null hypothesis Type 1 error Correct true (alpha error) decision Null hypothesis Correct Type 2 error false decision (Beta error)
  • 27.
    Alpha = 1.96. • Beta = 0.1 to 0.2 or 10 to 20%. • Power of the study = 1- beta error • Strength at which we conclude there is no difference between the two groups.
  • 28.
    Statistical test chosendepends on---- • Whether comparison is between independent or related groups. • Whether proportions or means are being compared. • Whether more than 2 groups are compared.
  • 29.
    Deciding statistical tests? •In a clinical trial of a micronutrient on growth, the weight was measured before and after giving the micronutrient.. Which test will you use for comparison? • paired t test • F test • T test • Chi square test
  • 30.
    Parametric and Nonparametrictests Parametric: When the data is normally distributed. Nonparametric : When data is not normally distributed,usually with small sample size.
  • 31.
    Common statistical tests Design Nature of variable Statistical test Statistic derived Two independent Qualitative (nominal) Chi square Chi square Groups Quantitative (continous) Student t test t Two related groups Qualitative (nominal) Chi square Chi square Quantitative (continous) Paired t test t More than 2 Qualitative (nominal Chi square Chi square Independent Quantitative (continous) Anova F groups
  • 32.
    Difference in proportion Chi-square test, Z test, Difference in mean(Before Paired t test and after comparison-same group) Difference in mean (two Unpaired t test, If sample independent groups) > 30-Z test More than 2 means(> 2 Anova groups) Association Spearman correlation Prediction regression
  • 33.
    Non parametric tests Chi-squaretest Fishers test, Mc Nemar test Wilcoxon Signed rank test Paired t test Wilcoxon test , Mann- independent t test Whitney U , Kolmogrov Kruskal-wallis test Anova
  • 34.
    The most appropriatetest for comparing Hb values in the adult women in two different population of size 150 and 200 is • A) t test • B) Anova • C) Z test • D) Chi square test
  • 35.
    Answer • C – Two groups – >30 – Continuous variable – Comparing mean
  • 36.
    The most appropriatetest to compare birth weight in 3 different regions is • A) t test • B) Anova • C) Z test • D) Chi square test
  • 37.
    Answer • B – Continuous variable – Compare means – > 2 groups
  • 38.
    The most appropriatetest to compare BMI in two different adult population of size 24 and 30 is • A) Two sampled t test • B) Paired t test • C) Z test • D) Chi square test
  • 39.
    Answer • A – Two different groups – Continuous variable – Size <30
  • 40.
    The association betweensmoking status and MI is tested by • A) t test • B) Anova • C) F test • D) Chi square test
  • 41.
    Standard drug used40% of patients responded and a new drug when used 60% of patients responded. Which of the following tests of parametric significance is most useful in this study? • A) Fishers t Test • B) Independent sample t test • C) Paired t test • D) Chi square test.
  • 42.
    • A consumergroup would like to evaluate the success of three different commercial weight loss programmes. Subjects are assigned to one of three programmes (Group A , Group B ,GROUP C) . Each group follows different diet regimen. At first time and at the end of 6 weeks subjects are weighed an their BP measurements recorded.
  • 43.
    Test to detectmean difference in body weight between Group A & Group B • T-TEST • Difference between means of two samples
  • 44.
    Is there asignificant difference in body weight in Group A at Time 1 and Time 2? • Paired T Test • Same people sampled on two Occasions.
  • 45.
    Is the differencein body weight of subjects in Group A,GROUP b ,group C significantly different at Time 2 • Analysis of variance
  • 46.
    Is there anyrelation between blood pressure and body weight of these subjects? • Correlation
  • 47.
    Correlation coefficient • Showsthe relation between two quantitative variable • Shows the rate of change of one variable as the other variable change • The value lies between –1 to + 1 • Correlation coefficient of zero means that there is no relationship
  • 49.
    No.of deaths in8 villages due to water borne diseases before & after installation of water supply system • Villages: 1 2 3 4 5 6 7 8 • Before :13 6 12 13 4 13 9 10 • After :15 4 10 9 1 11 8 13
  • 50.
    Did the Installationof water supply system significantly reduce deaths • Small sample size • Distribution is not normal • Non parametric test • Wilcoxon signed rank test
  • 51.
    For treatment ofHepatitis A 7 patients treated with herbal medicines& 7 patients treated with Allopathic symptomatic management. S.Br values after 10 days of treatment is given below • Herbal :9 6 10 3 6 3 2 • Allopathy: 6 3 5 6 2 4 8
  • 52.
    Is herbal treatmentis better than allopathic treatment? • Small sample size • Distribution is not normal • Non parametric test • Mann- Whitney test
  • 53.
    After applying astatistical test an investigator get the p value as 0.01. It means that • A)The probability of finding a significant difference is 1% • B) The probability of finding a significant difference when there is no difference is 1% • C) The difference is not significant 1% times and significant 99% times • D) The power of the test used is 99%
  • 54.
    Answer • B • Nullhypothesis states there is no difference,If there is any difference it is due to chance • P value = If the null hypothesis is true the probability of the sample variation to occur by chance • P value 0.05= probability of the sample variation by chance is only 5% if null hypothesis was true • 95% the sample variation is not due to chance,& there is a difference. So we will reject NH
  • 55.
    • P =0.01 - probability of the sample variation by chance is only 1% if null hypothesis was true • 99 % the sample variation is not due to chance,& there is a difference. So we will reject NH • As p value decreases the difference become more significant • For practical purpose p value < 0.05 ; the difference is significant
  • 56.
    In assessing theassociation between maternal nutritional status and Birth weight of the newborns two investigators A and B studied separately and found significant results with p values 0.02 & 0.04 respectively. From this what can you infer about the magnitude of association found by the two investigators
  • 57.
    Type of study Alternative Unit of study name Descriptive Case series Prevalence Cross sectional study Individual Longitudinal Incidence study Correlational Analytical Ecological Case reference Populations studies Case control Follow up Individuals (observational Cohort Individuals Analytical studies Randomised Clinical trial Patients (interventional) controlled trial Community Healthy people Field trial intervention Community Community Healthy people trials
  • 58.
    Study questions andappropriate designs Type of question Appropriate study design Burden of illness Cross sectional survey Longitudinal survey Causation, risk and Case control study, Cohort study prognosis Occupational risk, Ecological studies environmental risk Treatment efficacy RCT Diagnostic test Paired comparative study evaluation Cost effectiveness RCT
  • 59.
    Odd’s ratio • Ina study conducted by Gireesh G N etal about the ‘Prevalence of Worm infestation in children”,50 children in anganwadi were examined. Out of this 5 had worm infestation. 2 out of this 5 have a history of pet animals at home while 21 out of the 45 non infested has a history of pet animals at home. Is there any association between pet animals and worm infestations?
  • 60.
    Study design –Casecontrol • Measure of risk –Odd’s ratio
  • 61.
    • Set upa 2x2 table Worm infestation + - a b + 2 21 Pet animals - c d 3 24
  • 62.
    • Odd’s ratio= ad /bc • 2 x 24 = 0.76 21 x3
  • 63.
    Interpretation • OR =1,RISKFACTOR NOT RELATED TO DISEASE • OR <1 ,RISK FACTOR PROTECTIVE • OR >1 RISK FACTOR POSITIVELY ASSOCIATED WITH DISEASE
  • 64.
    Relative risk • Ina study to find the effect of Birth weight on subsequent growth of children , 300 children with birth weight 2kg to 2.5 kg were followed till age 1 . A similar number of children with birth weight greater 2.5 kg were followed up too. Anthropometric measurements done in both groups. Results are shown below
  • 65.
    Low birth weightNormal No.children studied 300 300 No.malnourished At age one 102 51
  • 66.
    Study design –Cohortstudy • Measure of risk –Relative risk ,Attributable risk. • Relative risk –Incidence among exposed Incidence among nonexposed = 102/300 = 0.34 = 2 51/ 300 0.17 Inference ?
  • 67.
    • An outbreak of Pediculosis capitis being investigated in a girls school with 291 pupils.Of 130 Children who live in a nearby housing estate 18 were infested and of 161 who live elsewhere 37 were infested. The Chi square value was found to be 3.93 . • P value = 0.04 • Is there a significant difference in the infestation rates between the two groups?
  • 68.
    Results of ascreening test Disease Positive Negative Positive TP(a) FP(b) Test Negative FN© TN(d)
  • 69.
    Features of ascreening test Sensitivity = a/ a+c Specificity = d/b+d Positive predictive value = a/a+b Negative predictive value = d/c+d False positive rate = bb+d False negative rate = c/a+c
  • 70.
    In a groupof patients presenting to a hospital emergency with abdominal pain, 30% of patients have acute appendicitis, 70% of patients with appendicitis have a temperature greater than 37.50c and 40% of patients without appendictis have a temperature greater than 37.50c. Considering these findings which of the following statement is correct ? a) Sensitivity of temperature greater than 37.50c as a marker for appendicitis is 21/49 b) Specificity of temperature grater than 37.50c as a marker for appendicitis is 42/70 c) The positive predictive value of temperature greater than 37.50c as marker for appendicitis is 21/30 d) Specificity of the test will depend upon the prevalence of appendicitis in the population to which it is applied.
  • 71.
    Sensitivity and Specificity + Appendicitis - 21a 28b Fever > 37.50c + - 9c 42d 30a+c 70b+d
  • 72.
    • Sensitivity =a/a+c - 21/30=70% • Specificity = d/b+d = 42/70=60% • Positive predictive value = a/a+b = 21/49=43% • Negative predictive value = d/c+d = 42/51
  • 73.
    Exercise 11 Disease prevalencein a population of 10,000 was 5%. A urine sugar test with sensitivity of 70% and specificity of 80% was done on the population. The positive predictive value will be : a)15.55% b) 70.08% c) 84.4% d)98.06%
  • 74.
    Total population = 10,000 • Disease prevalence = 5% • No diseased = 500 • Applying this to a 2x2 table :
  • 75.
    2x2 table + - + TEST 350 a 1900 b 2250 - 150c 7600d 7750 500 9500 10000
  • 77.