2. • In a solution to a PDE, if the number of
arbitrary constants and the number of
independent variables are equal, then the
solution is called complete solution or
complete integral.
3. :
• In a Complete Integral (Complete Solution) , if a
particular values found for the arbitrary constants ,
then it is called particular Solution or Particular
Integral.
• (i.e) A solution obtained by giving particular values to
the arbitrary constants in a complete integral is called
particular Integral or Particular Solution.
4. • A solution which contains no arbitrary terms
is called Singular Solution (or) Singular
Integral.
5. • A solution which contains only arbitrary
function but no arbitrary constants is called
General Solution or General Integral.
• (i.e) the solution contains maximum possible
number of arbitrary functions
6.
7.
8.
9.
10.
11. Take 𝑧 = 𝑓 𝑢 , where 𝑢 = 𝑥 + 𝑎𝑦 -------- (1)
Differentiate (1) partially with respect to x & y , we will get
𝛿𝑢
𝛿𝑥
= 1 &
𝛿𝑢
𝛿𝑦
= 𝑎
But W.K.T
𝛿𝑧
𝛿𝑥
= 𝑝 &
𝛿𝑧
𝛿𝑦
= 𝑞
Also W.K.T, 𝑝 =
𝜕𝑧
𝜕𝑥
=
𝑑𝑧
𝑑𝑢
𝜕u
𝜕x
=
dz
du
and 𝑞 =
𝜕𝑧
𝜕𝑦
=
𝑑𝑧
𝑑𝑢
𝜕u
𝜕y
= a
dz
du
(∵
𝛿𝑢
𝛿𝑥
= 1 &
𝛿𝑢
𝛿𝑦
= 𝑎)
Substitute 𝑝 =
dz
du
& q = a
dz
du
in the given pde, we will get 𝑓 𝑧,
𝑑𝑧
𝑑𝑢
= 0 , which is
a ODE of first order.
Solving the ODE by using variable separable method, we will get C.I of the given
pde
12. In this type, there is no Singular Solution like
TYPE I
13. Put 𝑐 = ∅(𝑎) in C.I and proceed same like
previous Type
14. The pde is in the form f(p, q, x) = 0
(PDE contains p, q & x)
15. Take 𝑞 = 𝑎,
Substitute 𝑞 = 𝑎 in the given equation f(p,q,x) = 0
Then find p
W.K.T dz = p dx +q dy & substitute the values of p & q
in this equation and integrate, we will get C.I
16.
17. Procedure to find General Integral
(General Solution):
Put 𝑐 = ∅(𝑎) in C.I and proceed same like
previous Type
18. Type IV
The pde is in the form f(p, q, y) = 0
(PDE contains p, q & y)
19. Procedure to find Singular Integral
(Singular Solution) S.I:
• In this type, there is no Singular Solution like
TYPE I
20. Procedure to find General Integral
(General Solution):
Put 𝑐 = ∅(𝑎) in C.I and proceed same like
previous Type
25. The pde is in the form 𝒇 𝟏 𝒙, 𝒑 =
𝒇 𝟐 𝒚, 𝒒 𝒐𝒓 𝒇 𝒙, 𝒚, 𝒑, 𝒒 = 𝟎
(The pde contains only x, y, p & q and does
not contain z)
26. Procedure to find Complete Integral
(Complete Solution) C.I:
If the given function is in the form 𝑓 𝑥, 𝑦, 𝑝, 𝑞 = 0,
then separate this into 𝑓1 𝑥, 𝑝 = 𝑓2(𝑦, 𝑞)
Take 𝑓1 𝑥, 𝑝 = 𝑓2 𝑦, 𝑞 = 𝑎
From 𝑓1 𝑥, 𝑝 = 𝑎 , find p and from 𝑓2 𝑦, 𝑞 = 𝑎,
find q W.K.T dz = p dx +q dy
Substitute the values of p & q in the above and
integrate both sides , we will get C.I
28. Procedure to find General Integral
(General Solution):
Put 𝑐 = ∅(𝑎) in C.I and proceed same like
previous Type
29. Type VII - Equation reducible to
standard form
The pde is in the form 𝒇 𝒙 𝒎
𝒑 , 𝒚 𝒏
𝒒 = 𝟎 and
𝒇 𝒛, 𝒙 𝒎
𝒑, 𝒚 𝒏
𝒒 = 𝟎
30. Procedure to find Complete Integral
(Complete Solution) C.I:
Case (i) If 𝒎 ≠ 𝟏 and 𝒏 ≠ 𝟏
Put 𝑋 = 𝑥1−𝑚
& 𝑌 = 𝑦1−𝑛
Substitute 𝑥 𝑚
𝑝 = 𝑃 1 − 𝑚 & 𝑦 𝑛
𝑞 = 𝑄(1 − 𝑛) in the given equation ,
where P =
𝜕𝑧
𝜕𝑋
, 𝑄 =
𝜕𝑧
𝜕𝑌
After substitution, the given equation reduced to the equation of the form
𝑓 𝑃, 𝑄 = 0 𝑜𝑟 𝑓 𝑧, 𝑃, 𝑄 = 0, as per the previous procedure find the C.I
Case(ii) If 𝒎 = 𝟏 𝒂𝒏𝒅 𝒏 = 𝟏
Put 𝑋 = log 𝑥 & 𝑌 = log 𝑦
Substitute 𝑥𝑝 = 𝑃 & 𝑦𝑞 = 𝑄 in the given equation where P =
𝜕𝑧
𝜕𝑋
, 𝑄 =
𝜕𝑧
𝜕𝑌
After substitution, the given equation reduced to the equation of the form
𝑓 𝑃, 𝑄 = 0 𝑜𝑟 𝑓 𝑧, 𝑃, 𝑄 = 0, as per the previous procedure find the C.I
32. Procedure to find General
Integral (General Solution):
Put 𝑐 = ∅(𝑎) in C.I and proceed same like
previous Type
33. Type VIII - Equation reducible to
standard form
The pde is in the form 𝒇 𝒛 𝒎 𝒑 , 𝒛 𝒎 𝒒 = 𝟎 and 𝒇 𝒙, 𝒛 𝒎 𝒑, 𝒛 𝒎 𝒒 = 𝟎
34. Procedure to find Complete Integral
(Complete Solution) C.I
Case (i) If 𝒎 ≠ −𝟏
Put 𝑍 = 𝑧 𝑚+1 ,
𝑃
𝑚+1
= 𝑧 𝑚 𝑝 &
𝑄
𝑚+1
= 𝑧 𝑚 𝑞 Where 𝑃 =
𝜕𝑍
𝜕𝑥
& 𝑄 =
𝜕𝑍
𝜕𝑦
Substitute in given equation,
After substitution, the given equation reduced to the equation of the form
𝑓 𝑃, 𝑄 = 0 𝑜𝑟 𝑓1 𝑥, 𝑃 = 𝑓2 𝑦, 𝑄 , as per the previous procedure find the C.I
Case(ii) If 𝒎 = −𝟏
Put 𝑍 = 𝑙𝑜𝑔𝑧
Substitute 𝑧𝑃 = 𝑝 & 𝑧𝑄 = 𝑞 in the given equation , where 𝑃 =
𝜕𝑍
𝜕𝑥
& 𝑄 =
𝜕𝑍
𝜕𝑦
After substitution, the given equation reduced to the equation of the form
𝑓 𝑃, 𝑄 = 0 𝑜𝑟 𝑓1 𝑥, 𝑃 = 𝑓2 𝑦, 𝑄 , as per the previous procedure find the C.I
35. Procedure to find Singular
Integral (Singular Solution) S.I
• There is no Singular Solution
36. Procedure to find General Integral (General
Solution):
Put c = ∅(a) in C.I and proceed same like
previous Type