RANDOMIZED COMPLETE BLOCK DESIGN (RCBD) 
BY: 
SITI AISYAH NAWAWI
Description of the Design 
• RCBD is an experimental design for 
comparing a treatment in b blocks. 
• The blocks consist of a homogeneous 
experimental unit. 
• Treatments are randomly assigned to 
experimental units within a block, with 
each treatment appearing exactly once 
in every block.
Cont.. 
• So, complete mean that each block 
contain the all the treatments. 
• Completely randomize block design 
mean that each block have all 
treatment and the treatments are 
randomize with the all block.
When is the design useful? 
• The experimental unit is not homogeneous 
but can sort experimental unit into 
homogeneous group that we call block. 
• An extraneous source of validity (nuisance 
factor) is present. 
• The treatments are assigning at random 
the experimental unit within each block. 
• Nuisance factor is a design factor that 
probably has an effect on the response, 
but we are not interested in that effect.
Cont.. 
• When the nuisance factor is known 
and controllable, blocking can be 
used to systematically eliminate its 
effect on the statistical comparisons 
among treatments.
Advantage and disadvantage 
Advantages 
• Generally more precise than the 
CRD. 
• No restriction on the number of 
treatments or replicates. 
• Some treatments may be replicated 
more times than others. 
• Missing plots are easily estimated.
Cont.. 
Disadvantages 
• Error df is smaller than that for the CRD 
(problem with a small number of 
treatments). 
• If there is a large variation between 
experimental units within a block, a large 
error term may result (this may be due to 
too many treatments). 
• If there are missing data, a RCBD 
experiment may be less efficient than a CRD
Designing a simple RCBD 
experiment 
For example, an agricultural scientists wants to study the effect of 4 different 
fertilizers (A,B,C,D) on corn productivity. He has three fields (1,2,3) ranging in 
size from 4-6 ha. Since this is a large experiment, 1 ha is devoted to each 
fertilizer type in each field. But, the fields have different crop histories, 
herbicide use, etc. Field identity is an extraneous variable (block) 
! 
➢ Treatment : Types of fertilizer (A,B,C,D) 
➢ Block : Fields (1,2,3) 
➢ Experimental unit : Corn 
➢ Dependent variable : Production of corn
• Randomization for block 1 
First, find 4 three digit random 
number from random number table. 
Rank the random number from 
smallest to largest. 
Random Number Ranking 
(experimental 
Treatment 
625 2 A 
939 4 B 
493 1 C 
713 3 D
• Randomization for block 2 
Find the next 4 three digit random 
number from random number table. 
Rank the random number from smallest 
to largest. 
Random Number Ranking 
(experimental 
Treatment 
496 2 A 
906 4 B 
440 1 C 
690 3 D
• Randomization for block 3 
Find the next 4 three digit random 
number from random number table. 
Rank the random number from smallest 
to largest. 
Random Number Ranking 
(experimental 
Treatment 
253 2 A 
081 1 B 
901 4 C 
521 3 D
• The following table shows the plan of 
experiment with the treatments have been 
allocated to experimental units according 
to RCBD 
! 
! 
! 
Treatment 
experimental 
unit number 
! 
Block (Field) 
1 2 3 
A 2 1 2 
B 4 4 1 
C 1 2 4 
D 3 3 3
Linear Model and the ANOVA
ANOVA table 
! 
! 
! 
! 
! 
*a= number of treatment * b= number of block
Hypothesis testing 
• Testing the equality of treatment mean 
H0 : μ1= μ2=…= μa 
H0 : At least one μi≠μj 
! 
Îą = 0.05 
Test Statistics : F0 (F calculated) 
Critical value : FÎą,(a-1),(a-1)(b-1) 
Decision : Reject H0 if F calculated > F table 
Conclusion :
Multiple comparison
Multiple comparison: Least Significant 
Difference(LSD) test 
LSD compares treatment means to see whether 
the difference of the observed means of 
treatment pairs exceeds the LSD numerically. 
LSD is calculated by 
! 
t 2 
MSE ! 
α / 2,( a −1)( b 
−1) 
b 
! 
where t is the value of Student’s t (2-tail)with 
error df Îą / at 2 100 Îą 
% level of significance, n is the 
no. of replication of the treatment. For unequal 
replications, n1 and n2 LSD= 
( 1 1 ) 
t / 2,( 1)( 1) MSE b b a b × + α − − 
1 2
Multiple comparison: Tukey’s test 
Compares treatment means to see whether 
the difference of the observed means of 
treatment pairs exceeds the Tukey’s 
numerically. Tukey’s q is calculated MSE 
by 
T Îą = 
(a, f ) ! 
Îą 
b 
Where f is df error .
Example 
An agricultural scientists wants to study 
the effect of 4 different fertilizers 
(A,B,C,D) on corn productivity. He has six 
fields (1,2,3,4,5,6) ranging in size from 
4-6 ha. Since this is a large experiment, 
1 ha is devoted to each fertilizer type in 
each field. But, the fields have different 
crop histories, herbicide use, etc. Field 
identity is an extraneous variable (block)
Cont.. 
1) State treatment, block and 
experimental unit. 
Treatment : Types of fertilizer (A,B,C,D) 
Block : Fields (1,2,3,4,5,6) 
Experimental unit : Corn 
Dependent variable : Production of corn(KG)
Cont.. 
Types of 
fertilizer 
Batch of Resin (Block) Treatment 
Total 
Average 
1 2 3 4 5 6 
A 90.3 89.2 98.2 93.9 87.4 97.9 556.9 92.82 
B 92.5 89.5 90.6 94.7 87.0 95.8 550.1 91.68 
C 85.5 90.8 89.6 86.2 88.0 93.4 533.5 88.92 
D 82.5 89.5 85.6 87.4 78.9 90.7 514.6 85.77 
B l o c k 
Totals 
350.8 359.0 364.0 362.2 341.3 377.8 2155.1
Cont.. 
2)Write down the linear statistical 
model for this experiment and explain 
the model terms?
Cont.. 
2)Calculate the analysis of variance 
manually and construct the table?
Source of 
variation 
Sum of 
Squares 
Degrees of 
Freedom 
Mean 
Square 
F 
Fertilizer 178.17 3 59.39 8.11 
Block 192.25 5 38.45 
Error 109.89 15 7.33 
Total 480.31 23
3)Test the hypothesis 
H0: All fertilizers give the same mean corn production (types of fertilizer do not 
affects the mean corn production) 
H1: At least two fertilizers give different mean corn production (fertilizer affects 
the mean corn production) 
! 
Îą = 0.05 
! 
Test Statistics : 8.11 
Critical value : F0.05,3,15 =3.29 
Decision : Reject H0 if F calculated > F table 
! 
Conclusion: There is significant difference among the fertilizer on mean yield 
!
Model comparison 
• Model comparison

Randomized complete block_design_rcbd_

  • 1.
    RANDOMIZED COMPLETE BLOCKDESIGN (RCBD) BY: SITI AISYAH NAWAWI
  • 2.
    Description of theDesign • RCBD is an experimental design for comparing a treatment in b blocks. • The blocks consist of a homogeneous experimental unit. • Treatments are randomly assigned to experimental units within a block, with each treatment appearing exactly once in every block.
  • 3.
    Cont.. • So,complete mean that each block contain the all the treatments. • Completely randomize block design mean that each block have all treatment and the treatments are randomize with the all block.
  • 4.
    When is thedesign useful? • The experimental unit is not homogeneous but can sort experimental unit into homogeneous group that we call block. • An extraneous source of validity (nuisance factor) is present. • The treatments are assigning at random the experimental unit within each block. • Nuisance factor is a design factor that probably has an effect on the response, but we are not interested in that effect.
  • 5.
    Cont.. • Whenthe nuisance factor is known and controllable, blocking can be used to systematically eliminate its effect on the statistical comparisons among treatments.
  • 6.
    Advantage and disadvantage Advantages • Generally more precise than the CRD. • No restriction on the number of treatments or replicates. • Some treatments may be replicated more times than others. • Missing plots are easily estimated.
  • 7.
    Cont.. Disadvantages •Error df is smaller than that for the CRD (problem with a small number of treatments). • If there is a large variation between experimental units within a block, a large error term may result (this may be due to too many treatments). • If there are missing data, a RCBD experiment may be less efficient than a CRD
  • 8.
    Designing a simpleRCBD experiment For example, an agricultural scientists wants to study the effect of 4 different fertilizers (A,B,C,D) on corn productivity. He has three fields (1,2,3) ranging in size from 4-6 ha. Since this is a large experiment, 1 ha is devoted to each fertilizer type in each field. But, the fields have different crop histories, herbicide use, etc. Field identity is an extraneous variable (block) ! ➢ Treatment : Types of fertilizer (A,B,C,D) ➢ Block : Fields (1,2,3) ➢ Experimental unit : Corn ➢ Dependent variable : Production of corn
  • 9.
    • Randomization forblock 1 First, find 4 three digit random number from random number table. Rank the random number from smallest to largest. Random Number Ranking (experimental Treatment 625 2 A 939 4 B 493 1 C 713 3 D
  • 10.
    • Randomization forblock 2 Find the next 4 three digit random number from random number table. Rank the random number from smallest to largest. Random Number Ranking (experimental Treatment 496 2 A 906 4 B 440 1 C 690 3 D
  • 11.
    • Randomization forblock 3 Find the next 4 three digit random number from random number table. Rank the random number from smallest to largest. Random Number Ranking (experimental Treatment 253 2 A 081 1 B 901 4 C 521 3 D
  • 12.
    • The followingtable shows the plan of experiment with the treatments have been allocated to experimental units according to RCBD ! ! ! Treatment experimental unit number ! Block (Field) 1 2 3 A 2 1 2 B 4 4 1 C 1 2 4 D 3 3 3
  • 13.
  • 14.
    ANOVA table ! ! ! ! ! *a= number of treatment * b= number of block
  • 15.
    Hypothesis testing •Testing the equality of treatment mean H0 : μ1= μ2=…= μa H0 : At least one μi≠μj ! α = 0.05 Test Statistics : F0 (F calculated) Critical value : Fα,(a-1),(a-1)(b-1) Decision : Reject H0 if F calculated > F table Conclusion :
  • 16.
  • 17.
    Multiple comparison: LeastSignificant Difference(LSD) test LSD compares treatment means to see whether the difference of the observed means of treatment pairs exceeds the LSD numerically. LSD is calculated by ! t 2 MSE ! α / 2,( a −1)( b −1) b ! where t is the value of Student’s t (2-tail)with error df α / at 2 100 α % level of significance, n is the no. of replication of the treatment. For unequal replications, n1 and n2 LSD= ( 1 1 ) t / 2,( 1)( 1) MSE b b a b × + α − − 1 2
  • 19.
    Multiple comparison: Tukey’stest Compares treatment means to see whether the difference of the observed means of treatment pairs exceeds the Tukey’s numerically. Tukey’s q is calculated MSE by T α = (a, f ) ! α b Where f is df error .
  • 21.
    Example An agriculturalscientists wants to study the effect of 4 different fertilizers (A,B,C,D) on corn productivity. He has six fields (1,2,3,4,5,6) ranging in size from 4-6 ha. Since this is a large experiment, 1 ha is devoted to each fertilizer type in each field. But, the fields have different crop histories, herbicide use, etc. Field identity is an extraneous variable (block)
  • 22.
    Cont.. 1) Statetreatment, block and experimental unit. Treatment : Types of fertilizer (A,B,C,D) Block : Fields (1,2,3,4,5,6) Experimental unit : Corn Dependent variable : Production of corn(KG)
  • 23.
    Cont.. Types of fertilizer Batch of Resin (Block) Treatment Total Average 1 2 3 4 5 6 A 90.3 89.2 98.2 93.9 87.4 97.9 556.9 92.82 B 92.5 89.5 90.6 94.7 87.0 95.8 550.1 91.68 C 85.5 90.8 89.6 86.2 88.0 93.4 533.5 88.92 D 82.5 89.5 85.6 87.4 78.9 90.7 514.6 85.77 B l o c k Totals 350.8 359.0 364.0 362.2 341.3 377.8 2155.1
  • 24.
    Cont.. 2)Write downthe linear statistical model for this experiment and explain the model terms?
  • 25.
    Cont.. 2)Calculate theanalysis of variance manually and construct the table?
  • 26.
    Source of variation Sum of Squares Degrees of Freedom Mean Square F Fertilizer 178.17 3 59.39 8.11 Block 192.25 5 38.45 Error 109.89 15 7.33 Total 480.31 23
  • 27.
    3)Test the hypothesis H0: All fertilizers give the same mean corn production (types of fertilizer do not affects the mean corn production) H1: At least two fertilizers give different mean corn production (fertilizer affects the mean corn production) ! Îą = 0.05 ! Test Statistics : 8.11 Critical value : F0.05,3,15 =3.29 Decision : Reject H0 if F calculated > F table ! Conclusion: There is significant difference among the fertilizer on mean yield !
  • 28.
    Model comparison •Model comparison