Quadratic Equations (Quadratic Formula) by Rich Rollo
The Equation 5y 2  –8y  + 3 = 0
The Quadratic Formula x = -b  + b 2  –4ac 2a
Identify the Parts ay 2  + by + c = 0 5y 2  –8y + 3 = 0 Therefore in this case, a = 5, b = -8, and c = 3.
Step One Plug in the values of a, b, and c into the quadratic formula. x = -(-8)  + (-8) 2  –4(5)(3) 2(5)
Step Two Simplify all terms found within the radicand. x = -(-8)  + 64 –60 2(5) x = -(-8)  + 4 2(5)
Step 3 Simplify the remaining terms in the formula. x = -(-8)  + 4 2(5) x = 8  + 2 10
Step 4 Isolate the variable to find the solution set. x = 8  + 2 10 X = 8 + 2 X = 8 –2  10 10 = = 1 .6 &
Solution Set 1 and .6
Check the 1 st  Solution Check ………………………………………… 1 5y 2  –8y + 3 = 0 5(1) 2  –8(1) + 3 = 0 5 –8 + 3 = 0 True
Check the 2 nd  Solution Check ………………………………six-tenths. (.6) 5y 2  –8y + 3 = 0 5(.6) 2  –8(.6) + 3 = 0 1.8 –4.8 + 3 = 0 True
Therefore 1 and .6 is the solution set for 5y 2  –8y  + 3 = 0

Quadratic Equations (Quadratic Formula) Using PowerPoint

  • 1.
    Quadratic Equations (QuadraticFormula) by Rich Rollo
  • 2.
    The Equation 5y2 –8y + 3 = 0
  • 3.
    The Quadratic Formulax = -b + b 2 –4ac 2a
  • 4.
    Identify the Partsay 2 + by + c = 0 5y 2 –8y + 3 = 0 Therefore in this case, a = 5, b = -8, and c = 3.
  • 5.
    Step One Plugin the values of a, b, and c into the quadratic formula. x = -(-8) + (-8) 2 –4(5)(3) 2(5)
  • 6.
    Step Two Simplifyall terms found within the radicand. x = -(-8) + 64 –60 2(5) x = -(-8) + 4 2(5)
  • 7.
    Step 3 Simplifythe remaining terms in the formula. x = -(-8) + 4 2(5) x = 8 + 2 10
  • 8.
    Step 4 Isolatethe variable to find the solution set. x = 8 + 2 10 X = 8 + 2 X = 8 –2 10 10 = = 1 .6 &
  • 9.
  • 10.
    Check the 1st Solution Check ………………………………………… 1 5y 2 –8y + 3 = 0 5(1) 2 –8(1) + 3 = 0 5 –8 + 3 = 0 True
  • 11.
    Check the 2nd Solution Check ………………………………six-tenths. (.6) 5y 2 –8y + 3 = 0 5(.6) 2 –8(.6) + 3 = 0 1.8 –4.8 + 3 = 0 True
  • 12.
    Therefore 1 and.6 is the solution set for 5y 2 –8y + 3 = 0