Linear Equations
in Two Variables
Objectives:
illustrate linear equations in two
variables;
determine if an ordered pair is a
solution of the given linear
equation;
graph linear equations in two
variables.
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
5x + 3y = 6 Yes
Already in
standard form
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
x = 7y + 3
x – 7y = 7y – 7y + 3
x – 7y = 3
Yes
Standard form
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
3x2 – y = 9 No
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
3
𝑥
+ 𝑦 = 20
No
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
xy = -5 No
Determine whether or not each equation is a linear
equation in two variables. If yes, write it in
standard form.
𝑥
3
+
𝑦
6
= 1 Yes
Solutions of a Linear Equations in
Two Variables
These are ordered pairs (x, y) that
make the equation true.
Determine whether (3, -2) is a solution of
the equation 5y = -2x – 4.
5y = -2x – 4
5(-2) = -2(3) – 4
-10 = -6 – 4
-10 = -10 YES
Determine whether (-1, 4) is a solution of
the equation 6x + 2y = 3
6x + 2y = 3
6(-1) + 2(4) = 3
-6 + 8 = 3
2 ≠ 3 NO
Answer Skill Builder on page 76.
Skill Builder on p. 76
-y = 4x + 7; (-1, -3)
-(-3) = 4(-1) + 7
3 = -4 + 7
3 = 3
YES
Skill Builder on p. 76
-y = 4x + 7; (2, 15)
-(15) = 4(2) + 7
-15 = 8 + 7
-15 ≠ 15
NO
Skill Builder on p. 76
-y = 4x + 7; (0, 7)
-(7) = 4(0) + 7
-7 = 0 + 7
-7 ≠ 7
NO
In reality, why do you think checking
whether a solution to a problem is
correct is essential? Expound.
Graphing Linear Equations in Two
Variables
Three Ways:
1. Table of Values
2. x – and y – intercepts
3. Slope and one point
Graph y = 4x – 2 using table of values.
x y = 4x – 2 y (x, y)
-1
0
1
y = 4(-1) – 2 -6 (-1, -6)
- 2
y = 4(0) – 2 (0, -2)
(1, 2)
y = 4(1) – 2 2
(-1, -
Graph
y = 4x – 2
(-1, -6)
(0, -2)
(1, 2) (0, -
2)
(1,
2)
y = 4x – 2
Graph x – y = 3 using table of values.
x x – y = 3 y (x, y)
-2
1
3
-2 – y = 3 -5 (-2, -5)
- 2
1 – y = 3 (1, -2)
(3, 0)
3 – y = 3 0
(-2, -
5)
Graph
x – y = 3
(3,
0)
(1, -
2)
x – y = 3
(-2, -5)
(1, -2)
(3, 0)
Graphing Linear Equations in Two
Variables in Two Variables using x – and
y - intercepts
x – intercept is the point where a line
crosses the x - axis
To solve for the x – intercept, let y = 0 and solve
for x.
Example: Find the x – intercept of x - 2y = 4
y = 0
x – 2(0) = 4
x = 4
The graph of x – 2y = 4 will cross the x – axis at
y – intercept is the point where a line
crosses the y - axis
To solve for the y – intercept, let x = 0 and solve
for y.
Example: Find the y – intercept of x - 2y = 4
x = 0
0 – 2𝑦 = 4
−2𝑦
−2
=
4
−2
y = - 2
Graph
x – 2y = 4
(4,
0)
(0, -
2)
x – 2y = 4
(4, 0)
(0, -2)
Graph x – y = 3 using x – and y -
intercept.
x x – y = 3 y (x, y)
0
3
0 – y = 3 -3 (0, -3)
0
x – 0 = 3 (3, 0)
Graph
x – y = 3
(3,
0)
(0, -
3)
x – y = 3
(0, -3)
(3, 0)
Answer Skill Builder on page 81.
Graph the two equations on one
Cartesian plane. You may use any
methods on graphing.
Content, images, text, etc. used belong to the rightful owner. No copyright
infringement intended.

G8-Math-Q1-Week-5-Linear-Equations.pptx

  • 1.
  • 2.
    Objectives: illustrate linear equationsin two variables; determine if an ordered pair is a solution of the given linear equation; graph linear equations in two variables.
  • 3.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. 5x + 3y = 6 Yes Already in standard form
  • 4.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. x = 7y + 3 x – 7y = 7y – 7y + 3 x – 7y = 3 Yes Standard form
  • 5.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. 3x2 – y = 9 No
  • 6.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. 3 𝑥 + 𝑦 = 20 No
  • 7.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. xy = -5 No
  • 8.
    Determine whether ornot each equation is a linear equation in two variables. If yes, write it in standard form. 𝑥 3 + 𝑦 6 = 1 Yes
  • 9.
    Solutions of aLinear Equations in Two Variables These are ordered pairs (x, y) that make the equation true.
  • 10.
    Determine whether (3,-2) is a solution of the equation 5y = -2x – 4. 5y = -2x – 4 5(-2) = -2(3) – 4 -10 = -6 – 4 -10 = -10 YES
  • 11.
    Determine whether (-1,4) is a solution of the equation 6x + 2y = 3 6x + 2y = 3 6(-1) + 2(4) = 3 -6 + 8 = 3 2 ≠ 3 NO
  • 12.
  • 13.
    Skill Builder onp. 76 -y = 4x + 7; (-1, -3) -(-3) = 4(-1) + 7 3 = -4 + 7 3 = 3 YES
  • 14.
    Skill Builder onp. 76 -y = 4x + 7; (2, 15) -(15) = 4(2) + 7 -15 = 8 + 7 -15 ≠ 15 NO
  • 15.
    Skill Builder onp. 76 -y = 4x + 7; (0, 7) -(7) = 4(0) + 7 -7 = 0 + 7 -7 ≠ 7 NO
  • 16.
    In reality, whydo you think checking whether a solution to a problem is correct is essential? Expound.
  • 17.
    Graphing Linear Equationsin Two Variables Three Ways: 1. Table of Values 2. x – and y – intercepts 3. Slope and one point
  • 18.
    Graph y =4x – 2 using table of values. x y = 4x – 2 y (x, y) -1 0 1 y = 4(-1) – 2 -6 (-1, -6) - 2 y = 4(0) – 2 (0, -2) (1, 2) y = 4(1) – 2 2
  • 19.
    (-1, - Graph y =4x – 2 (-1, -6) (0, -2) (1, 2) (0, - 2) (1, 2) y = 4x – 2
  • 20.
    Graph x –y = 3 using table of values. x x – y = 3 y (x, y) -2 1 3 -2 – y = 3 -5 (-2, -5) - 2 1 – y = 3 (1, -2) (3, 0) 3 – y = 3 0
  • 21.
    (-2, - 5) Graph x –y = 3 (3, 0) (1, - 2) x – y = 3 (-2, -5) (1, -2) (3, 0)
  • 22.
    Graphing Linear Equationsin Two Variables in Two Variables using x – and y - intercepts
  • 23.
    x – interceptis the point where a line crosses the x - axis To solve for the x – intercept, let y = 0 and solve for x. Example: Find the x – intercept of x - 2y = 4 y = 0 x – 2(0) = 4 x = 4 The graph of x – 2y = 4 will cross the x – axis at
  • 24.
    y – interceptis the point where a line crosses the y - axis To solve for the y – intercept, let x = 0 and solve for y. Example: Find the y – intercept of x - 2y = 4 x = 0 0 – 2𝑦 = 4 −2𝑦 −2 = 4 −2 y = - 2
  • 25.
    Graph x – 2y= 4 (4, 0) (0, - 2) x – 2y = 4 (4, 0) (0, -2)
  • 26.
    Graph x –y = 3 using x – and y - intercept. x x – y = 3 y (x, y) 0 3 0 – y = 3 -3 (0, -3) 0 x – 0 = 3 (3, 0)
  • 27.
    Graph x – y= 3 (3, 0) (0, - 3) x – y = 3 (0, -3) (3, 0)
  • 28.
    Answer Skill Builderon page 81. Graph the two equations on one Cartesian plane. You may use any methods on graphing.
  • 29.
    Content, images, text,etc. used belong to the rightful owner. No copyright infringement intended.