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Internal Combustion 
Engine and 
Turbomachinery 
MCHE 562 
Dr. Gongtao Wang
Policy and Outline 
 Class policy 
 Mandatory attendance unless specially approved 
 No late homework 
 No makeup test/exams 
 Test schedule 
 Floating within 2 weeks
Lecture Outline 
1. Introduction to Internal Combustion Engine 
2. Introduction to Gas Turbine Engine 
• Definition and Applications 
• Thermal Cycles 
• Applications 
• Illustrations 
1. Introduction to Turbomachinery Terms 
• Definition and classifications 
• Coordination systems and velocity diagrams 
• Variables and geometry
Lecture Outline 
4. Review of Aerodynamics and Fluidics 
• Conservation: Mass, energy and Momentum 
• Gas Dynamics: Compressible flow 
4. Dimensionless Analysis 
• Off Design Performance and specific speed 
• Buckingham P-Theorem 
• Application in Turbomachinery
Lecture Outline 
6. Energy transfer between fluid and a rotor 
• Euler’s Equation 
• Energy Transfer and velocity diagram 
• Reaction – Definition 
• Definition of total relative properties 
6. Radial Equilibrium Theory 
• Derivation of Radial Equilibrium Equation 
• Free vertex 
• Problem
Lecture Outline 
8. Axial flow turbine 
• Preliminary design of axial flow turbines 
• Detailed design 
• Final project 
8. Axial flow compressor 
9. Polytropic (small stage) efficiency
Introduction to Internal 
Combustion Engine 
 Classification 
 Otto Cycle – Four stroke 
 Clark Cycle – Two Stroke 
 Diesel Cycle – Compression Ignition 
 Wankel cycle – Rotary Engine
Latest 2-Stroke Engine
Wankel Engine
Clerk/Otto/Diesel Cycle 
 Mechanism 
 Thermal Cycle 
 Design Issues
Reciprocating Mechanism
Piston Dynamics 
 Exact piston acceleration
Piston Dynamics 
 Approximate piston acceleration
Gas Force and Torque 
 Gas force 
 Gas torque
Inertia and Shaking force 
 Shaking = - inertia forces
Inertia and Shaking
Inertia and Shaking
Inertia and Shaking
Inertia and Shaking
Otto Cylce
Otto Cycle P-V & T-s Diagrams
Otto Cycle Derivation 
 Thermal Efficiency: 
= 1 - Q 
Q 
= Q - Q 
H L 
Q 
L 
H 
H 
th h 
 Air standard assumption (constant v + q) 
Qin = m Cv T D 
 Cold-air standard assumption (constant c) 
ö çè 
T T 
4 
- 1 
T 
ö çè 
÷ø 
æ 
÷ø 
æ 
T T 
3 
-1 
T 
= 1- 
= 1 - m C v (T 4 - T 1 
) 
m C (T - T ) 
2 
2 
1 
1 
v 3 2 
th h 
Q = m Cv DT Rej
Otto Cycle Derivation 
 For an isentropic compression (and expansion) 
process: 
æ g æ 
g 
= V 
= V 
T 
ö 
2 ÷ ÷ø 
1 
 where: γ = Cp/Cv 
 Then, by transposing, 
= T 
T 
V 
V 
T 
3 
4 
4 
3 
-1 
2 
-1 
1 
ö 
ç çè 
÷÷ø 
ççè 
= T 
T 
T 
T 
4 
1 
3 
2 
= 1- T 
T 
1 
2 
th Leading to h
Otto Cycle Derivation 
The compression ratio (rv) is a volume ratio and is 
equal to the expansion ratio in an otto cycle 
engine. 
 Compression Ratio 
= V 
V 
V 
r = V 
4 
3 
1 
2 
v 
r = v 
s 
+ 1 
v 
= v + v 
s cc 
v 
= Total volume r 
Clearance volume 
cc 
v 
cc 
v 
where Compression ratio is defined as
Otto Cycle Derivation 
 Then by substitution, 
g 
- 
1 
æ g 
- 
÷÷øö 
1 1 
= ( r ) 
= V 
T 
V 
T 
v 
2 
1 
2 
ççè 
The air standard thermal efficiency of the Otto cycle 
then becomes: 
) = 1 - 1 = 1 - ( r -1 
( r v 
) 
1- 
h g 
th v g
 Summarizing 
= 1 - Q 
th h Q = m Cv DT 
Q 
= Q - Q 
H L 
Q 
L 
H 
H 
ö çè 
T T 
4 
- 1 
T 
ö çè 
÷ø 
æ 
÷ø 
æ 
T T 
3 
-1 
T 
= 1- 
2 
2 
1 
1 
th h 
ö 
æ 
T 
3 
= T 
T 
2 
T 1- 
1 g 
= ( r ) 
= V 
T 
V 
v 
2 
1 
1- 
2 
g 
÷÷ø 
ççè 
T 
4 
1 
T th h = - 
1 1 
T 
) = 1 - 1 = 1 - ( r -1 
( r v 
) 
1- 
h g 
th v g 
2 
where 
and then 
Isentropic 
behavior 
Otto Cycle Derivation
Otto Cycle P & T Prediction 
 Determine the temperatures and pressures at each point in 
the Otto cycle. k=1.4 
Compression ratio = 9:1 
T1 temperature = 25oc = 298ok 
Qin heat add in = 850 kj/kg 
P1 pressure = 101 kPa 
T2 = 717 p2 = 2189kpa 
T3 = 1690k p3 = 5160kpa cv=1.205 
T4 = 701k p4 =238kpa
Diesel Cycle P-V & T-s Diagrams
Diesel Cycle Derivation 
 Thermal Efficiency (Diesel): 
= 1 - Q 
Q 
= Q - Q 
H L 
Q 
L 
H 
H 
th h 
For a constant pressure heat 
addition process; 
Q = m Cp DT 
For a constant volume heat 
rejection process; 
Q = m Cv DT 
Assuming constant specific heat: 
ö çè 
T T 
4 
- 1 
T 
h where: γ = Cp/Cv 
ö çè 
÷ø 
æ 
÷ø 
æ 
T T 
3 
-1 
T 
= 1 - 
= 1 - m C v (T 4 - T 1 
) 
m C (T - T ) 
2 
2 
1 
1 
p 3 2 
th 
g
Diesel Cycle Derivation 
 For an isentropic compression (and expansion) process: 
æ g g 
= V 
T 
ö 
æ 
ö 
2 ÷ ÷ø 
V 
T 
1 
ççè 
 However, in a Diesel 
= T 
T 
V 
V 
3 
4 
4 
3 
-1 
1 
2 
-1 
ç çè 
÷÷ø 
V 
V 
V = V V 
1 4 ¹ 
V 
4 
3 
1 
2 
 The compression ratio (rv) is a volume ratio and, in a diesel, is 
equal to the product of the constant pressure expansion and 
the expansion from cut-off.
 Compression Ratio 
V 
V 
r = V 
vc ¹ 
V 
4 
3 
1 
2 
 Then by substitution, 
V 
v 
r = r r = V 
vc cp e · · 
V 
3 
4 
2 
3 
ö 
æ 
T 1- 
1 g 
= ( r ) 
( ) 
ù 
ú úû 
é 
( r -1) 
ê êë 
r - 1 
= V 
T 
2 
= 1 - 1 
th g 
( r ) 
cp 
cp 
-1 
v 
h 
g 
g 
V 
v 
1 
1- 
2 
g 
÷÷ø 
ççè 
Diesel Cycle Derivation
Diesel Cycle P & T Prediction 
 Determine the temperatures and pressures 
at each point in the Diesel Cycle 
Compression Ratio = 20:1 
Cut off ratio = 2:1 
T1 temperature = 25oC = 298oK 
Qin Heat added = 1300 kJ/kg 
P1 pressure = 100 kPa
Otto-Diesel Cycle Comparison
Dual Cycle P-V Diagrams:
Dual Cycle Efficiency 
 Dual Cycle Thermal Efficiency 
Qin = m Cv (T 2.5 - T 2 ) + m Cp (T3 - T 2.5 ) 
g g 
h a b 
V 
3 
V 
2.5 
= 1 - 1 
ö çè 
= P 
é 
a 3 b = 
P 
2 
ù 
úû 
êë 
÷ø 
æ 
- 1 
( -1) + ( -1) 
CR 
( -1) 
a ga b 
where: γ = Cp/Cv 
( ) Rej 4 1 Q = m Cv T -T
Diesel Cycle Derivation 
 Critical Relationships in the process include 
ö 
æ 
T 1- 
1 g 
= ( r ) 
= V 
T 
V 
v 
2 
1 
1- 
2 
g 
÷÷ø 
ççè 
F = m 
Q 
A 
Q 
cycle 
æ 
= V 
P 
ö 
2 g 
a fuel 
= (r ) 
V 
P 
v 
1 
2 
1 
g 
÷÷ø 
ççè 
Q = m Cp DT Q = m Cv DT 
( ) 
ù 
ú úû 
é 
( r -1) 
ê êë 
r - 1 
= 1 - 1 
th g 
( r ) 
cp 
cp 
-1 
v 
h 
g 
g
Design Issue 
 Improve efficiency 
 Higher compression ratio 
 Combustion control 
 Ignition timing 
 Exhaust recuperate 
 Minimize shaking force/torque 
 Lubrication 
 Pollution control 
 Cost deduction – short stroke engine
MCHE 569 Project 1 
Given a single cylinder internal combustion engine, 
 r=2.6”, l=10.4”, m2=0.060 blob, 
 rG2=0.4r, m3=0.12, rG3=0.36l, 
 m4=0.16blob. Piston dia. is 5.18”. 
 The crank rotates at 1850 rpm. 
 Compression ratio is 8:1. 
 Thermal condition: 
 T1 = 20 deg. C, P1 = 101kpa, Qin = 810 kJ/kg 
 Calculate in Excel: 
 Thermal condition of all 4 stroke 
 Thermal efficiency 
 Gas force 
 Gas torque 
 When theta = 0, 90, 180, 270, …720 calculate shaking force and torque 
 Gas-fuel mixture mass flow rate 
 If mass ratio of the mixture is 4 part air vs. 1 part fuel, calculate fuel consumption rate, and volumetric air 
flow rate.
Gas Turbines - Definition 
 Definitions 
 Thermal energy conversion device 
 Fuel -> mechanical/electrical power 
 Fuel -> Propulsion 
 Difference from ICE 
 Absence of Reciprocating and Rubbing 
Members 
 Power/Weight ration
Gas Turbine – Components 
 Frame 
 Casing 
 Front / main 
 Gas generator 
 Compressor – rotor/stator 
 Combustor 
 Power conversion 
 Turbine – rotor /stator/ exhaust
Gas Turbine / ICE 
 Higher Efficiency, 
 High power/weight 
 Robust Combustion/Insensitive to fuel 
condition 
 Minimum Power output 
 Complexity/Maintenance 
 Higher Cost
Application of Turbine 
 Power Generation 
 Lycoming TF-35 
 Garrett’s GTCP660 Auxiliary Power Unit 
 Propulsion 
 Turbojet: GE J85-21 (F-5E/F) ; CJ610 
 Turbofan: Garatte F-109 (T-46 Twin-Shaft) 
 Turboprop Garret’s TPE331-14
Turbine Configuration 
 Shaft arrangement 
 Single: Fix speed and load 
 Twin/Triple shafting 
 HPT drives compressor and LPT not need for gear 
reducer 
 High efficiency at variable speed 
 High reliability at variable power 
 Multiple coaxial shaftes 
 Complex control, high efficiency with more flexibility
Ch 2. Terminology of Turbomachinery 
 Critical, challenging and special design 
problem for turbomachinery is with blades. 
 Definition of turbomachines 
 Energy conversion device 
 Continues flow 
 Dynamics acting 
 Rotating blade rows
Classification of Turbomachine 
 By function 
 Work absorber - Compressors, fans and pumps 
 Worker - Turbines 
 By fluid 
 Compressible 
 Incompressible 
 By meridional flow path 
 Axial 
 Radial
Stage 
 Definition -- Stator and rotor pair 
 Stator 
 Convert fluid thermal to fluid kinetic energy 
 No energy transfer to or from blade 
 Rotor 
 Energy transfer from or to the fluid -- fluid total 
energy change
Coordinate System and Velocity Diagram 
 Coordination system 
 Polar cylindrical system 
 Radial – r, tangential θ, axial – z 
 Velocity diagram 
 Total (absolute) velocity -- V 
 Relative (fluid flow vs. blade) -- W 
 Blade velocity due to rotation – U 
 1 – inlet, 2 -- exit 
 V=W+U
Blade VD 
 Stator 
 U = 0 
 V = W 
 Rotor 
 V=W+U 
 Impeller 
 Compressor and turbine VD are reversed 
 Subscription convention Vr1 , …
Axial Flow Turbine 
 Sign convention 
 Positive if along the rotation 
 How to determine fluid acting surface 
 Turbine – Fluid acting on the convex side of 
blade airfoil 
 Compressor – Concave side
Comparison Between Axial and Radial 
Flow Turbine 
 Signal stage efficiency 
 Radial is higher 
 Loss between stages 
 Radial is higher 
 Way to improve efficiency 
 Radial – make the diameter of the rotor larger 
 Axial – add stages
Compressor Stall, Surge 
 Stall 
 In axial compressors, gas density/pressure, sometime even 
temperature, may change sharply in certain stage 
 Low-speed, low-flow, high stagger, stall is imperceptible, 
and recoverable 
 Surge 
 Domino stalls occur from last stage in high speed 
compressor 
 Non-recoverable, cause temperature rise, significantly 
reduce the performance of the compressor, and often end 
up with blade damage
Turbine Choke / Blade Cooling 
 Choke / shock 
 Relative velocity become supersonic 
 Blade 
 High temperature alloy 
 Intensive cooling 
 Current technology – turbine temperature can be 
25% high than the melting point of the blade
Variable Geometry in Compressor 
and Turbine 
 Power = pressure * volume flow rate 
 Recover from surge in compressor 
 Startup – ignition – surge 
 Squeeze stall out 
 Different turbine work at different design point 
 Keep pressure the same, reduce flow channel cross-section 
area  reduces volume flow rate  reduce power 
and mass flow rate  to maintain the pressure and less 
mass flow  burn less fuel
Ch3. Aerodynamics of Flow Processes 
 General flow governing equation 
 Total properties 
 Ideal gas isentropic properties 
 Sonic speed and mach numbers 
 Mach number expressed relations 
 Isentropic relation in term of local mach 
 Critical velocity and critical properties 
 Isentropic relation in term of critical mach
Continue 
 Compressible flow in isentropic nozzle 
 Varying-area equation 
 DeLaval nozzle - CD nozzle 
 Unfavorable back pressure gradient 
 Other important relations for nozzle 
 Choking flow 
 Shock equations
Continue Outline 
 Definition of turbomachinery isentropic 
efficiency 
 Total-total efficiency 
 Compressor 
 Turbine 
 Total-static efficiency 
 Total condition of an incompressible flow 
 Limitation of Bernoulli's equation
General Flow Governing Equation 
 Continuity equation 
m = ×V A = ×V A = const 1 1 1 2 2 2  r r 
 Linear momentum equation 
 Energy equation 
q w h h V V g Z Z 
+ = - + - + - 
   
( ) 1 
( ) ( ) 
shaft 
+ = - + - + - 
[( ) ( ) ( )] 
2 1 
2 
1 
2 
1 
2 2 
2 1 
2 1 
2 
1 
2 
2 2 
2 1 
Q W m h h V V g Z Z 
Shaft 
( ) ( ) x 2x 1x y 2 y 1y F = m × V - V F = m × V - V
Total Properties 
 Isentropically convert all energy into enthalpy 
 Total/Stagnational, local/static 
= + 2 + 
h ( h ) 1 
V gZ 
t 
2 
= = 
h c T h c T 
t p t p 
P P 
r rt 
t
Ideal gas isentropic relations 
 State 
equation and 
Constants 
 Entropy 
change of a 
process 
 Isentropic 
process 
p = RT R = 
J 
kg K 
for compressor 
for turbine 
1.4 
1.33 
287 
g 
= 
g 
= 
r  
g 
c = × R c = × R 
g - g - 
D = × - 
P 
P v 
s c T 
R 
ln( 2 
) ln( 2 
) 1 
1 
1 
1 
1 
P 
T 
P 
g g 
1 
T 
2 
1 
r 
2 
1 
P 
2 
1 
- 
ö 
÷ ÷ø 
æ 
= ÷ ÷ø 
ç çè 
ö 
æ 
= 
ç çè 
g 
r 
T 
P
Ideal Gas Adiabatic Relations 
 Adiabatic means Tt = const. 
s R P 
T 
g 
/ ln 
ö 
æ 
ö 
2 
æ 
ö 
æ 
ö 
æ 
P 
2 
æ D - 
T 
2 
P 
s 
t 
q e P 
2 
2 
2 
t 
g 
 Adiabatic process is a better assumption for all 
stationary turbo components 
÷ ÷ø 
ç çè 
÷ ÷ø 
ç çè 
= = 
÷ ÷ø 
ç çè 
- = D ÷ ÷ø 
ç çè 
= 
- 
÷ ÷ø ö 
ç çè 
- 
1 
1 
1 
1 
1 
1 
1 
1 
/ 
T 
P 
P 
T 
P 
P 
cP 
t 
t 
g 
g
Sonic Speed and Mach Number 
 Sonic speed 
a dp g 
 Mach Number 
RT 
= = 
d 
r 
M = V 
a
Isentropic Relations in Term of Mach 
 Total to local 
g 
çè 
2 
ö g 
g 
- 
ö çè 
2 1 
1 
1 
M 
çè 
2 
ö 1 1 
2 
1 1 
2 
1 1 
2 
- 
÷ø 
T 
P 
t 
r 
=æ + - 
÷ø 
=æ + - 
÷ø 
=æ + - 
g 
g 
r 
g 
M 
P 
M 
T 
t 
t
Critical Property 
 The local condition at 
unity mach 
ö 
æ 
+ 
cr t cr cr t T T V a R ×T 
 Critical mach 
g 
+ 
= = × ÷ ÷ø 
ç çè 
= 
1 
2 
1 
2 
g 
g 
) 
M V 
cr g 
× + - 
2 M 2 
(1 1 
1 
2 
2 
1 
M 
R T 
t 
+ 
= 
× 
+ 
= 
g 
g g
Isentropic Flow in Critical Mach 
2 
g 
g 
- 
ö 
ö 
2 1 
1 
1 
2 
æ 
= - g 
- 
1 1 
T T M 
t cr 
1 
æ 
g 
= - g 
- 
1 1 
P P M 
t cr 
1 
æ 
g 
r r g 
= - - 
1 1 
t cr 
1 
- 
ö 
÷ ÷ø 
ç çè 
+ 
÷ ÷ø 
ç çè 
+ 
÷ ÷ø 
ç çè 
+ 
g 
g 
M
Isentropic Flow in Varying Nozzle 
 To increase the speed of fluid 
 Converging the subsonic flow 
 Diverging the supersonic flow 
g 
+ 
1 
2( 1) 
g M 
1` 
- 
2 
2 
2 
1 
A 
* 
ö 
æ + = 
1 1 - 
+ 
÷ ÷ø 
ç çè 
g 
g 
A M
Nozzles in turbomachinery 
 The most important feature 
 Diffuser must be carefully designed so that 
the flow remains attached to the wall 
 Unfavorable pressure gradient makes the 
design curve of diffuser
Other Important Features 
 Choking flow
Normal Shocks-1 
 Control Volume
Normal Shocks-2 
 Basic Equations for a Normal Shock
Normal Shocks-3 
 Intersection of Fanno & Rayleigh Lines
Normal Shocks-4 
 Normal Shock Relations
Normal Shocks-5 
 Normal Shock Relations (Continued)
Supersonic Channel Flow 
with Shocks 
 Flow in a Converging-Diverging Nozzle
Isentropic Flow of an Ideal Gas 
– Area Variation 
 Isentropic flow in a 
converging-diverging nozzle
Example 3-1
Example 3-2
Example 3-3
Definition of Turbomachinery Efficiency 
 Total-to-total 
efficiency 
 Compressor 
 Turbine 
1 
1 
= D 
h 
( ) 
t ideal 
( ) 
1 
2 
1 
1 
2 
g 
- ÷ø ö 
çè æ 
- ÷ø ö 
çè æ 
= 
D 
- 
- 
t 
t 
t 
t 
t actual 
t t 
T 
T 
P 
P 
h 
g 
h 
1 
1 
h 
= ( D ) 
- - 
h 
t actual 
g ( ) 
1 
1 
2 
1 
2 
- ÷ø ö 
çè æ 
- ÷ø ö 
çè æ 
= 
D 
g 
t 
t 
t 
t 
t ideal 
t t 
P 
P 
T 
T 
h
Turbine Efficiency 
 Total-to-static 
Efficiency – 
use in 
applications 
where exhaust 
is counted as 
waste, such as 
power plant 
h 
= D 
- - 
ù 
g 
( g 
- 
1 
2 ) 1 
1 2 
( ) 
é 
2 2 
P P 
1 
2 
2 2 
2 
1 
1 
2 
1 
, 
1 
(1 ) 
1 
1 
g 
- 
+ 
- 
= - 
+ 
= 
ú ú 
û 
ê ê 
ë 
÷ø ö 
çè æ 
- 
- 
g 
g 
g 
g 
g 
g 
h 
t cr 
t 
t 
P t 
t actual 
t s turbine 
P M 
M 
P 
c T P
Compressibility and Bernoulli 
Equation 
 Error of Bernoulli when used in compressible flow 
é 
g 
- = æ + - - 
1 1 1 
ö çè 
 M<= 0.3 incompressible 
... 
2 1 
M 
4 40 1600 
1 
ù 
1 
2 
2 4 6 
2 
2 
2 
= + + + + 
ú ú 
û 
ê ê 
ë 
- ÷ø 
M M M 
M 
P P 
t 
V 
g 
r 
g 
g
Chapter 4 
 Dimensional analysis 
 Buckingham Π-Theorem 
 Off-design performance of gas turbine 
 Dimensional analysis in turbomachinery 
 Specific speed
Dimensional Analysis 
 Buckingham π-theorem 
 Select all related as a set of n variables 
 Determine k (either MLT 3, or MLTt 4) 
 Select k most important variables as the central 
group 
 Multiply each of the rest n-k variables to solve for 
n-k πs 
 Set up the system of equation 
 Arbitrarily set one variable’s exponential as unity 
 Solve the rest exponentials
Application to Turbomachinery 
 Geometric similarity 
 Dimensional proportional 
 Dynamical similarity 
 Geometrical similar machines with each velocity 
vector parallel 
 Similarity principle 
 Geometrically similar 
 Non-dimensional term/number identical
Performance Characteristic 
 Head coefficient 
 Head efficiency 
f Q 
gH 
y r 
, 
f Q 
gH 
h r 
 Power coefficient 
ö 
ö 
÷ ÷ø 
æ 
æ 
, 
f Q 
act 
P P 
h r 
ç çè 
æ 
= = = 
÷ ÷ø 
ç çè 
= = 
ö 
÷ ÷ø 
ç çè 
= = 
m 
m 
m 
2 
3 
2 
3 
2 
2 3 
ˆ , 
ND 
ND 
o 
P 
ND 
ND 
gH 
ND 
ND 
U 
i 
P 
ideal 
H
Compressible-flow Turbomachine 
æ 
m RT 
f 
t in 
ND 
Pr, , t 
, ,Re, 
Pr : Total - to -Total Pressure ratio 
: Total - to total efficiency 
ö 
: Total temperature change vs. inlet total temperature 
h 
t t 
t 
R : Gas constant 
: ratio of specific heat of the gas mixture 
g 
Compressor 1.4 
Turbine 1.33 
, 
, , 
2 
, 
, 
= 
= 
D 
÷ ÷ 
ø 
ç ç 
è 
D = 
- 
- 
g 
g 
h g 
t in 
t in t in 
t in 
t t 
T 
T 
RT 
D P 
T 
T 
Another Function and More Terms 
æ 
m T 
f 
t , 
in 
h 
Pr, , , 
N 
, , 
, 
P 
t 
T 
t 
t 
ö 
: Standard atmosphere temperature, i.e. 298K 
: Standard atmosphere pressure, 101 kPa 
T 
STP 
STP 
STP 
STP 
t in t in 
t in 
t t 
P 
P 
T 
T 
P 
T 
T 
= = 
÷ ÷ 
ø 
ç ç 
è 
D = 
- 
q d 

Map and Characteristics 
 Turbine or compressor map – the plot 
 Characteristic – the curves in the plot 
 Design point of compressor is close to surge 
 Design point for turbine is close to choke
Specific Speed – Incompressible 
N Q 
4 
(gH)3 
Ns = 
 It was experimentally verified that certain 
type of turbomachinery (axial, radial, 
mixture) gives highest possible performance 
(efficiency) over certain range of specific 
speed value
Specific Speed - Compressible 
N Q 
ex 
 Qex is the volumetric flow rate at stage exit, which is 
not the same as that at the inlet due compressible 
flow 
 is the idea specific work extracted from or to 
the turbomachine 
4 
( h 
)3 t ,ideal 
Ns 
D 
= 
t ideal h , D
Ch5. Euler’s Equation 
 Energy transfer between fluid and rotors 
 Force/torque generated through momentum 
change 
 Energy transfer happens while these force/torque 
do works
Momentum Change at All Directions 
 Axial velocity change 
 Axial load on to the shaft – no works 
 Radial velocity change 
 Radial load bending moment  vibration 
 Destructive works 
 Both of above should be minimized 
 Tangential direction – effective works
Euler’s Equation 
 Torque 
 Power 
 Specific work 
m r V rV 
= - 
( ) 
q q 
2 2 1 1 
 
P = = m U V - 
U V 
( ) 
q q 
2 2 1 1 
 
q q 
tw 
2 2 1 1 
t 
p = U V - 
U V
Component of Energy Transfer 
 Typical velocity 
diagram 
 Vz1 = Vz2 = const 
V Vz z 
W - ( U - V ) 
= V - 
V 
q q 
W - ( V - U ) 
= V - 
V 
q q 
W - ( U + V - 2 U V ) 
= V - 
V 
q q q 
U V = V + U - 
W 
( ) ( ) ( ) 
2 
2 
2 
1 
2 
2 
2 
2 
2 
1 
2 
2 
2 
1 
q 
1 1 2 2 
2 
2 
2 
2 
2 
2 
2 2 
2 
2 
2 
2 2 2 
2 
2 
2 
2 
2 
2 
2 
1 
2 
1 
2 
1 1 
2 
1 
2 
2 
2 
2 
2 
2 2 
2 
2 
2 
2 
2 
1 
U V - U V = V - V + U - U + W - 
W 
= 
q q
Heads 
 Dynamic Head (Absolute V) 
 Total kinetic energy lost/gain in fluid flow 
 Effective shaft works 
 Convective Head (U) 
 Annual expansion/shrinkage 
 Small 
 Static Head (relative W) 
 Action of fluid flow to stages
Enthalpy Across A Stage 
 Absolute 
 Relative 
 Rothalpy 
g 
- 
T T M M 
= + = 
(1 ) 
g 
- 
T T M M 
= + = 
(1 ) 
Ts Local Static temperature 
h = c T - 
absolute total 
t p t 
h = c T - 
relative total 
t r p t r 
I h UV Rothalpy 
t 
a W 
t r s r 
V 
a 
t s 
r 
= - - 
q 
, , 
2 
2 
1 
, 
2 
2 
1 
: ( )
Reaction 
 Definition 
2 
1 
2 
2 
2 
2 
2 
1 
R = U - U + W - 
W 
( ) ( ) 
2 
1 
2 
2 
2 
2 
2 
1 
2 
2 
2 
1 
V - V + U - U + W - 
W 
( ) ( ) ( ) 
2 
2 
2 
1 
2 
1 
2 
2 
Turbine 
R = U - U + W - 
W 
( ) ( ) 
2 
2 
2 
1 
2 
1 
2 
2 
2 
1 
2 
2 
V V U U W W 
( ) ( ) ( ) 
Compressor 
- + - + -
Stage Blade Design vs. Reaction 
 Inlet and exit angles for stator 
 α0, α1 
 Inlet and exit angles for rotor 
 β0, β1 
 Deviation angle 
 difference of flow and metal 
 Swirl angle 
 local absolute angles
Axial Turbomachine 
 Zero-reaction stage – Impulse stage 
 W1=W2, β1= -β2 
 50% reaction (symmetric) turbine stage 
 V1=W2, V2=W1 
 α1= -β2, α2 = - β1 
 50% reaction (symmetric) compressor stage 
 V1=W2, V2=W1 
 α1= -β2, α2 = - β1
Incidence and Deviation Angles 
 Incidence angle 
 Flow angle to leading edge metal angle 
 Always exists like attacking angle 
 Positive or negative 
 Deviation angle 
 Insufficient flow momentum change 
 A very important controlled feature in compressor 
 A measure to adverse/unfavorable pressure gradient
Real-life Flow path in Axial Turbo 
 Explain with isentropic and γ / (γ-1)>>1 
 Total pressure drop much faster than temperature 
 Total density decrease across rotor 
 If Mach change over rotor is neglected, 
 Static density decreases across the rotor 
 To keep Vz constant, the annular cross area 
 Decreasing for compressor 
 Increasing for turbine 
 Flow passage over stator, due to significant M increase 
 Converging for compressor 
 Diverging for Turbine
Definition of Total Relative Properties in 
the Rotor Sub-domain 
 Relative properties can be modeled as flow through nozzle 
at speed W across 
T const across rotor 
1 
T T W 
M 
c 
W 
RT 
W 
W 
cr tr 
T T M T M 
g 
- 
g 
- 
= + = 
= = 
g 
g 
= - = - 
tr t 
g 
g 
r cr 
P = P - M = P - 
M 
g 
g 
- - 
1 
2 
2 1 
- 
1 
(1 ) (1 ) 
2 1 
- 
1 
(1 ) (1 ) 
g 
- 
tr r cr 
t 
2 1 
1 
1 
, 
g 
1 1 
, 
, 
1 
2 
2 
g 
- 
1 
(1 ) (1 ) 
1 
1 
2 
1 
1 
2 
1 
1 
, 
, 
2 
- - 
+ 
+ 
+ 
+ 
+ 
+ 
+ 
= - = - 
g g 
g 
g 
g 
g 
g 
g 
g 
r r M r M 
tr t 
r cr 
t r 
p 
tr s 
r cr
Continue 
 General term 
 Isentropic – Total 
relative pressure is 
constant across rotor 
 Other process total 
relative pressure 
decrease 
2 
T = 
T 
tr tr 
1 2 
P 
t 
( 2 
) 1 
1 
1 
2 
1 
g 
- 
= 
g 
T 
t 
t 
t 
T 
P 
P 
tr 
P 
tr
Graphic Shown 
 For Turbine 
 P2 < Pt2 <P1< Ptr2 <=Ptr1<Pt1<=Pt0 
 For Compressor 
 Po<P1<Pto <= Pt1 < P2<Ptr1<=Ptr2<Pt2
Ch6 Radial Equilibrium Theory 
 Background 
 Study for thermal properties as traverses a stage 
 Pitch line analysis 
 How properties (except U) vary at a given axial location 
 Assumption – axi-symmetric flow 
 Note – Wake at gap is negligible 
 The Problem 
 Find the relationship among fluid properties, annual 
geometry, and velocity
Derivation 
 Pressure force, and 
mass of the differential 
control elements 
F p dp r dr d 
top 
= - + + 
( )( ) 
F prd 
dp dr d 
under 
= 
F p r 
side 
= + + 
2( )( )sin( ) 
2 2 2 
F = F + F + F = r × dp × 
d 
p top under side 
[ ] r q 
r p p q 
p 
q 
q 
q 
q 
m = r + dr - r d = 
rdrd 
2 
( ) 
2 2
Acceleration 
 Centrifigal 
a V 
Centrifigal 
 Meridional curvature 
a V 
m 
 Convective sin( ) 
cos( ) 
2 
2 
convective m m 
m 
m 
meridional centrifigal 
a V 
r 
r 
a 
a 
q 
=  
= 
= 
-
Radial Equilibrium Theory 
 F=ma 
a a a 
= + + - 
Centrifigal meridional centrifigal convective 
× × = - - 
cos( ) sin( ) 
2 2 
V 
2 2 
V 
q 
V 
F 
dm 
r dp d 
dp 
V 
m 
1 = q 
- m 
cos( ) - 
sin( ) ( ) 
2 2 
V 
V 
dp 
 
1 m 
cos( ) V sin( ) ( Converging 
) 
r 
r 
dr 
V diverging 
r 
r 
dr 
V 
r 
r 
rdrd 
m m m 
m 
m m m 
m 
m m m 
m 
a a 
r 
a a 
r 
a a 
r q 
q 
q 
 
 
= + +
Simplified cases 
 Vm = const 
Vr=0 
 Invoke 
total 
enthalpy 
1 dp V 
2 q 
r 
r 
dr 
= 
2 2 1 
h h c T V V V V 
= + = + + = + + 
( ) ( ) 
1 
+ 
meridional centrifigal convective 
dV 
dV 
V V 
= + + - 
t z 
( ) 
q 
g 
- 
p dp 
= Û - = Û = 
g g 
g 
= + + - 
V 
r 
dV 
q 
dV 
dr 
const 
dV 
V V 
t z 
dV 
dr 
dh 
dh 
dh 
dr z 
p d 
r r r 
dp 
p 
dr 
2 
0 
p 
dp 
d 
dp 
dr 
dr 
dr 
dr z 
dp 
dr 
d 
dr p 
dr 
dr 
dr 
dr 
dr 
dr 
dr z 
p 
p z z 
V 
t 
V V 
a 
t z 
2 
2 
2 
r 
( 1 
) 
1 
1 
1 
1 
g 
1 
2 2 
2 
2 
2 
q q 
q 
g 
g r r 
q 
g 
r r 
r 
g r r 
q 
g r 
q q 
= + + 
- 
- 
-
Continue Simplification 
 dVz / dr = 0 dht / dr = 0  
 Free Vertex 
0 = 0 
+ + 
2 V 
dV 
dV 
 Nature fluid flow 
 Flow vorticity – flow particles spinning around 
its own axis 
 Least vorticity in free vortex flow 
 Free vortex blade design is most desired in 
aerodynamics, but unrealistic 
 Disadvantage in structural design and 
manufacturing 
 Boundary layer and tip leakage cancel the idea 
effect of free-vortex 
V 
rV const 
V 
r 
dr 
r 
dr 
= - Û = 
q 
q 
q q 
q q
Chapter 7 Axial Flow Turbine 
 Steam Turbine 
 Superheated Region 
 Wet Mixture Region 
 Gas Turbine 
 Similar to superheat steam turbine 
 High temperature alloy 
 Basic gas turbine design process
Stage Definition 
 Stator followed by rotor 
 Stator airfoil cascades – vanes 
 Rotor airfoil cascades – blades 
 Design process 
 Preliminary phases 
 Compressor/combustor exit, inlet path/nozzle, 
 Stage 1,2,3,4, Casing, pitch line, interstage axial gap 
 Detailed phases 
 Blade geometry design 
 Real flow effects 
 Empirical equation 
 Stacking vanes and blade sections 
 CAD Approach to axial turbine
Preliminary Design of Axial-Flow Turbines 
 Given conditions 
 Turbine inlet conditions (p, t,α,β) 
 Rotary speed 
 min. tip clearance, 
 max tip Mach 
 Envelope radial constrains (casing), max axial 
length, max diverging angle 
 Interstage Tt, max exit flow rate (A*N^2), Mach 
 Other, (such as overall efficiency, etc.)
Preliminary Design -- Find 
 Meridional flow path 
 Flow condition along pitch line 
 Hub and tip velocity diagram (assuming free-vortex 
stages)
Design Processes 
 Step 1 -- Justify axial turbine type 
 Ns = N*Q^0.5/(Δht)^0.75 > = 0.775 
 Δht is enthalpy change over a single stage, you change the number of stages 
to make the Ns to be optimum (usually “1”) 
 Step 2 –Split work across turbine individual stages (Δht1, Δht2…), 
according to experience 
 Efficiency 
 Off-design, and operation conditions usually 60:40, 55:45,50:50 
 Step 3 According to the experienced work split, and efficiency, determine 
interstage total condition 
 Too small axial gap triggers strong and dangerous flow interaction 
 Too large axial gap increases end-wall friction loss 
 Stator/rotor gap is more critical that interstage because large swirl velocity
Formulating an Simplified Approach 
 Calculate specific speed 
 Find optimum number of stage 
 Estimate turbine efficiency 
 Define a stage work coefficient 
c T 
= = D = - = - = - 
W W 
V V 
U V V 
( ) 1 2 1 2 ) 
W 
y s p t 
q 1 q 2 
q q q q 
2 2 
2 
y = V 
b - 
b 
(tan tan ) 1 2 
U 
 Define Flow coefficient 
U 
U 
U 
U 
U 
z 
Vz 
f 
= U 
= - 
(tan tan ) 1 2 y f b b
Coefficient Design-1 
V - V = W - W = 
U 
q q q q 
W - W = W + W - W - W = W - 
W 
Z Z 
q q q q 
2 
1 
1 2 1 2 
2 
1 
W W 
= + 
q q 
W W 
= - 
q q 
- 
R W W 
- 
 = - 
2 ( ) 2 ( ) 2 
q q 
(tan tan ) 
2 
q q 
W q = W q 
= W = 
V 
b b 
tan tan 
2 
2 
(tan tan ) 
R V 
2 
1 2 1 2 
1 
1 
1 2 
1 2 
2 
2 
1 2 
2 
2 
2 
1 
2 
2 
2 2 
1 
2 2 
2 
2 
1 
2 
2 
b b f b b 
= + = + 
U 
U 
U W W 
U V V 
z 
z z 

Coefficient Design-2 
f b b 
= + 
(tan tan ) 
2 
1 2 
tan = tan + 
1 
f 
2 2 
a b 
f 
a b 
tan 1 
= - 
R 
( 2 ) 
2 
tan 1 
y 
f 
b 
y 
f 
b 
y f b b 
tan tan 1 
( 2 ) 
2 
(tan tan ) 
1 1 
2 
1 
1 2 
= + 
ì 
ï ïî 
ï ïí 
= - + 
Û 
ïî 
ïí ì 
= - 
R 
R
Example 7-1 
Flow inlet angle 0 
Mass flow rate m 20kg/s 
³ 
Stage efficiency 90% 
Inlet total temperature 1100 K 
Inlet total pressure 4 bars 
Total Pressure ration 1.873 
Rotational speed 15000 rpm 
£ 
= 
= 
Mean blade speed 340 / 
Stage work coefficient ( h 
t 
= = - 
Assume 1.333, R 287 / 
Find one stage turbine 
m s 
kJ kg K 
- 
D £ 
: 
) 1.5 
U 
Given : 
gas 
2 
0 
g 
a 
 

Solution 
 Calculate specific speed 
 As a rule of thumb, you may assume the density 
of the fluid is 1kg/m^3 
 It may invoke too much error if calculate 
isentropic process, why? -- rotor 
 This is just an initial calculation, so it is not wise 
to spend too much time and effort to make your 
result very accurate
Step 1. 
 From density; mass flow rate  volumetric flow rate 
 From inlet total temperature; inlet/exit total pressure 
ratio  outlet temperature assuming isentropic 
process 
 Inlet/exit temperature and Cp  total enthalpy 
change over the turbine stages 
 Calculate Ns using N*Qex^1/2 / (Δht)^0.75 
 Increase number of stages to make Ns per each stage 
to be > 0.775
Design the stages 
 ψ 
Cp T 
=D = ´D 
t t 
2 2 
D = - = - = - 
P 
T 
U 
h 
U 
t 
t 
ö 
æ 
g 
ö 
æ 
,2 
,2 
U use the given m s 
T 
t 
,2 
One stage may be fine 
¬ 
g 
Cp R 
P 
T 
T 
T T T T T T 
t 
tt 
t 
t 
t t t t t t 
- 
= 
1 
= ---- 
÷ ÷ ÷ 
ø 
ç ç ç 
è 
÷ ÷ø 
ç çè 
- = - 
- 
1.427 
340 / 
1 1 
(1 ) 
1 
1 , 
1 , 
1 , 
,0 ,2 ,1 ,2 ,1 
y 
g 
h 
y 
g
Φ 
 Use Φ and α2 to set R close to 0.5 
ì 
tan 1 
= - 
R 
1 y 
f 
b 
( 2 ) 
2 
 Try α2 = 0 R=? 
 and α2 =-15 R=? 
ì 
ï ïî 
ï ïí 
tan 1 
= - + 
y 
f 
( 2 ) 
2 
= + 
ï ïî 
ï ïí 
= + 
f 
b 
2 
a b 
f 
a b 
tan tan 1 
tan tan 1 
2 2 
1 1 
or 
R
Other parameters 
 U=340 m/s and N – 1500rpm 
  rm = 0.216m 
 α1= atan (tanβ1+1/Φ)=? 
 Sketch the velocity diagram 
 Calculate V1, W1, V2, W2 
 Check Mcr 
 None of the Mach can be greater than 1
Blade Design at 0,1,2 
 Density 
 From mass flow rate 
m 
r r m 
  
hub m 
æ 
æ 
+ 
m r VA r r 1 g 
1 
V 
1 
r r r 
 
Þ = = ´ ´ - 
2 ( ) 
m 
A m 
p 
r r m 
tip m 
cr 
m tip hub 
t 
V r 
V r 
V 
V 
´ ´ 
= - 
´ ´ 
= + 
ö 
÷ ÷ 
ø 
ç ç 
è 
ö 
÷ ÷ø 
ç çè 
= Þ = - - 
1 
- 
1 
2 
r p r p 
r 
g 
g 
2 2 2 2 

Stage Configuration 
 Symmetric design (Config 1.) 
 Simplest for design calculation 
 Rotor rubbing 
 Descendent (Configuration 2) 
 No rotor and simple enough 
 Hub weakening 
 Optimized (Config. 3) 
 Theoretically optimum
Design for blade shape 
 Aspect ratio 
 Chord (the axial projective length of blade) 
Cz_vane, Cz_blade 
 Gap between rotor and stator 
 Gap = 0.25*(Cz_vane+Cz_blade)/2 
 1/8 of the stage solidity length
Detail turbine airfoil cascades 
 Select an airfoil 
 Camber the center line to achieve the inlet 
and exit flow 
 Consider other factors that affects the 
efficiency of the flow 
 The detailed design procedure
Detail Design Procedure 
 With the velocity diagram 
 Design for the efficiency of flow deflection 
 Blade geometry parameters 
 Iterative process 
 Given inlet/exit condition 
 Find the most efficient shape of blade 
 Real flow considerations 
 Some CAD packages
Blade Geometry 
 Geometry to be determined -- page 120 
 Suction side (SS) and pressure side (PS) 
 Design Principle 
 Higher loaded – larger P/V difference between SS 
and PS 
 Real fluid consideration
Typical Blade Load 
100 
90 
80 
70 
60 
50 
40 
30 
20 
10 
0 
0 1 2 3 4 5
Force Applied To The Blade 
 Cascade x-y coordination  r- θ - z 
 X  Z (axial direction) 
 Y  θ direction 
 S - pitch of blades 
 Circulation around each blade 
S V V 
S 2 
r 
= G = - 
F P P S F V 
= - = G 
( ) 
x in exit y z 
F Rp P S Rp P 
exit 
in 
x in 
P 
no blades 
= - = 
(1 ) 
( ) 
._ 
2 1 
r 
p 
q q
Real Fluid Effects 
 Pitch/axial chord ratio s/c 
 Aspect ratio h/c 
 Incidence 
 Tip clearance 
 Viscosity and friction
Pitch/axial chord ratio s/c 
 Definition of s and c 
 s: circular pitch of at given radius, usually the 
meridional 
 c: tip to trail linear distance, not counting the 
curvature of the blade 
 Figure 7.14 on Page 124 
 Conclusion: larger deflection  smaller s/c
Aspect Ratio h/c 
 Definition 
 h: tip-hub distance (delta-R) 
 c: tip to hub distance of blade 
 Design perference - smaller the better 
 <<1.0  boundary layer affects performance 
 >6.0  vibration and bending stress 
 Old optimum value is 3.0 ~~ 4.0 
 Modern design is around 1.0
Incidence 
 Gas (attacking) angle and metal angle 
 Profile (pressure) loss coefficient Yp 
 Yp = ( Total pressure loss ) 
(exit total to local pressure Difference) 
 Reaction blade (momentum absorber – both 
velocity magnitude and direction change counts) 
has lower Yp than Impulse blade (direction only) 
 Lead edge thickness reduces sensitivity of 
incidence effect on Yp
Tip Clearance 
 Tip leakage 
 Direct leakage  axial leakage 
 Indirect leakage  tangential from pressure side 
to suction side 
 Leakage prevention 
 Direct leakage prevention  slot in casing 
 Indirect leakage prevention  Full or partial 
shroud
Reynolds Number - Viscosity 
 Similar to a plate 
 Re > 10^5 Ypconstant 
 Re > 10^5 Yp change rapidly
Guideline For Blade Design 
 Criterion for Acceptable Diffusion 
 Downstream turning angle of cambered airfoil 
 Location of front stagnation point 
 Trailing edge thickness 
 Effect of Endwall contouring
Criterion for Acceptable Diffusion 
 Diffusion – expansion or de-compression 
 Velocity decline Diffusion  aversive pressure 
(with large deflection) boundary layer separation 
 large loss 
 Diffusion factor 
0.25 
ö 
P 
P 
t exit t V 
1 
max ( ) 
ö 
P 
t V 
max ( ) 
£ 
ö 
÷ ÷ø 
- 
÷ ÷ø 
- ÷ ÷ø 
= 
Vcr 
Vcr 
P 
P 
P 
l
Downstream Turning Angle 
 Definition: 
 A build-in camber angle of airfoil centerline – design for 
camber curve of airfoil 
 Reasoning: straight portion of latter half camber line in 
airfoil 
 The purpose is to control diffusion 
 With the angle δ build into blades squeeze the 
subsonic flow path  increase flow momentum  
decrease diffusion 
 However, if too much  Mach ~~ 1.0  supersonic 
pocket  shock  abrupt total pressure drop 
 With M~~0.8, δ = [8.0, 12] deg
Location of Front Stagnation Point 
 Front Stagnation Point  the point where 
flow hit metal surface at 90deg 
 Actual stagnation point s can be far from the 
theoretically point a 
 With high flow velocity  separation 
 Correction 
 Negative incidence angle 
 leading edge radius, arc length …
Trailing Edge Thickness 
 Trailing edge of airfoil 
 Flow from different blades mixed after 
trailing edge  sudden expansion duct flow 
 Thinner the better, but 
 Strength consideration 
 Coolant pass
Endwall Contouring 
 Contour of surface of either casing or hub 
 Purpose of the contouring -- to improve blade 
aerodynamic loading 
 Form a nozzle to change the flow property 
 Accelerate the flow at rear portion of suction side 
 Force the boundary layer thinner 
 Gather/collect the scatter fluid
Useful Equations 
 Choice of stagger angle 
 Stagger angle between the connecting line airfoil front 
tip to trailing edge and the axial direction 
é 
ö çèb = - æ b - b 
0.95 tan 1 tan 1 tan 1 + úû 
 Note: 
 Stator design use α instead of β 
 One of the two angle is negative 
5 
2 
ù 
êë 
÷ø
Optimum Spacing and Chord Ratio 
 Definition of Zweifel’s loading coefficient 
 Zweifel’s law 
 Optimum Zweifel’s coefficient is 0.8 
ö 
- ÷ ÷ø 
æ 
= 
ç çè 
s 
y b b b 
2 cos (tan tan ) 
c 
z 
Solidity Ratio : 
s 
= 
c 
z 
s 
0.8 2cos (tan tan ) 
2 1 2 
2 
2 1 2 
2 
s = b b - 
b 
T
Staking of 2D Sections 
 Blade design is first done by design sections at each 
radius 
 Staking these 2d Sections to form a 3D blade 
 Experiment and and reworking 
 Problems: secondary flow – flow crossed original design 
path into other plane 
 Method of staking 
 Fix a staking axis 
 Rotate each design 2d airfoil to optimize
Chapter 8 Axial Flow Compressors 
 Introduction 
 Centrifugal compressor is first used 
 Axial flow compressor is much more efficnet 
 Axial turbine can be used as a compressor if 
reversed, at price of significant efficiency loss
Axial compressor vs turbine 
 Turbine 
 Fluid flow from high pressure to low pressure 
naturally 
 Accelerating though passage 
 Compressor 
 Fluid flow from low pressure to high pressure 
 Convert kinetic energy to pressure potential 
 Compression must be a slow decelerating flow
Multi-stage Compressors and Stage 
Definition 
 Multi-staging is necessary 
 Pressure ratio vs performance 
 Compressor stages 
 Inlet Guide vane – nozzle  axial flow to 
tangential flow 
 Rotor-stator for each stage 
 Subscription 1 rotor inlet; 2 rotor 
outlet/stator inlet; 3vane outlet 
 V3=V1; α3=α1
Compressor Blade 
 Simpler than turbine blade 
 Selected from standard 
 British C4 – design from pressure distribution but 
no definite form 
 Base profile and camber line 
 Standard parameter – t/c 10% above appr. 40%
US NACA Series 
 Classified according to CL 
 The amount of cambers 
 4, 5, 6, 7 series 
 Most commonly used is 65xxx 
 Deflection angle ε 
 Solidity c/s
Real Flow Effect 
 Incident and deviation 
 Total pressure loss coefficient (PLC) ΔPt/ 
(ρV^2/2) 
 Deflection angle 
 Stalling 
 PLC is twice as minimum 
 Nominal e* is 0.8 of stalling es 
 Positive incident angle cause high loss
Reynolds Number 
 Lower than 2x10^5 leads to high profile loss 
 Higher than 3x10^5  does not change much 
 Critical Re is 3x10^5 
 This effect is partially affected by the 
turbulence.
Effect of Mach
Principle of turbomachinery
Principle of turbomachinery
Principle of turbomachinery
Principle of turbomachinery
Principle of turbomachinery

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Principle of turbomachinery

  • 1. Internal Combustion Engine and Turbomachinery MCHE 562 Dr. Gongtao Wang
  • 2. Policy and Outline  Class policy  Mandatory attendance unless specially approved  No late homework  No makeup test/exams  Test schedule  Floating within 2 weeks
  • 3. Lecture Outline 1. Introduction to Internal Combustion Engine 2. Introduction to Gas Turbine Engine • Definition and Applications • Thermal Cycles • Applications • Illustrations 1. Introduction to Turbomachinery Terms • Definition and classifications • Coordination systems and velocity diagrams • Variables and geometry
  • 4. Lecture Outline 4. Review of Aerodynamics and Fluidics • Conservation: Mass, energy and Momentum • Gas Dynamics: Compressible flow 4. Dimensionless Analysis • Off Design Performance and specific speed • Buckingham P-Theorem • Application in Turbomachinery
  • 5. Lecture Outline 6. Energy transfer between fluid and a rotor • Euler’s Equation • Energy Transfer and velocity diagram • Reaction – Definition • Definition of total relative properties 6. Radial Equilibrium Theory • Derivation of Radial Equilibrium Equation • Free vertex • Problem
  • 6. Lecture Outline 8. Axial flow turbine • Preliminary design of axial flow turbines • Detailed design • Final project 8. Axial flow compressor 9. Polytropic (small stage) efficiency
  • 7. Introduction to Internal Combustion Engine  Classification  Otto Cycle – Four stroke  Clark Cycle – Two Stroke  Diesel Cycle – Compression Ignition  Wankel cycle – Rotary Engine
  • 10. Clerk/Otto/Diesel Cycle  Mechanism  Thermal Cycle  Design Issues
  • 12. Piston Dynamics  Exact piston acceleration
  • 13. Piston Dynamics  Approximate piston acceleration
  • 14. Gas Force and Torque  Gas force  Gas torque
  • 15. Inertia and Shaking force  Shaking = - inertia forces
  • 21. Otto Cycle P-V & T-s Diagrams
  • 22. Otto Cycle Derivation  Thermal Efficiency: = 1 - Q Q = Q - Q H L Q L H H th h  Air standard assumption (constant v + q) Qin = m Cv T D  Cold-air standard assumption (constant c) ö çè T T 4 - 1 T ö çè ÷ø æ ÷ø æ T T 3 -1 T = 1- = 1 - m C v (T 4 - T 1 ) m C (T - T ) 2 2 1 1 v 3 2 th h Q = m Cv DT Rej
  • 23. Otto Cycle Derivation  For an isentropic compression (and expansion) process: æ g æ g = V = V T ö 2 ÷ ÷ø 1  where: γ = Cp/Cv  Then, by transposing, = T T V V T 3 4 4 3 -1 2 -1 1 ö ç çè ÷÷ø ççè = T T T T 4 1 3 2 = 1- T T 1 2 th Leading to h
  • 24. Otto Cycle Derivation The compression ratio (rv) is a volume ratio and is equal to the expansion ratio in an otto cycle engine.  Compression Ratio = V V V r = V 4 3 1 2 v r = v s + 1 v = v + v s cc v = Total volume r Clearance volume cc v cc v where Compression ratio is defined as
  • 25. Otto Cycle Derivation  Then by substitution, g - 1 æ g - ÷÷øö 1 1 = ( r ) = V T V T v 2 1 2 ççè The air standard thermal efficiency of the Otto cycle then becomes: ) = 1 - 1 = 1 - ( r -1 ( r v ) 1- h g th v g
  • 26.  Summarizing = 1 - Q th h Q = m Cv DT Q = Q - Q H L Q L H H ö çè T T 4 - 1 T ö çè ÷ø æ ÷ø æ T T 3 -1 T = 1- 2 2 1 1 th h ö æ T 3 = T T 2 T 1- 1 g = ( r ) = V T V v 2 1 1- 2 g ÷÷ø ççè T 4 1 T th h = - 1 1 T ) = 1 - 1 = 1 - ( r -1 ( r v ) 1- h g th v g 2 where and then Isentropic behavior Otto Cycle Derivation
  • 27. Otto Cycle P & T Prediction  Determine the temperatures and pressures at each point in the Otto cycle. k=1.4 Compression ratio = 9:1 T1 temperature = 25oc = 298ok Qin heat add in = 850 kj/kg P1 pressure = 101 kPa T2 = 717 p2 = 2189kpa T3 = 1690k p3 = 5160kpa cv=1.205 T4 = 701k p4 =238kpa
  • 28. Diesel Cycle P-V & T-s Diagrams
  • 29. Diesel Cycle Derivation  Thermal Efficiency (Diesel): = 1 - Q Q = Q - Q H L Q L H H th h For a constant pressure heat addition process; Q = m Cp DT For a constant volume heat rejection process; Q = m Cv DT Assuming constant specific heat: ö çè T T 4 - 1 T h where: γ = Cp/Cv ö çè ÷ø æ ÷ø æ T T 3 -1 T = 1 - = 1 - m C v (T 4 - T 1 ) m C (T - T ) 2 2 1 1 p 3 2 th g
  • 30. Diesel Cycle Derivation  For an isentropic compression (and expansion) process: æ g g = V T ö æ ö 2 ÷ ÷ø V T 1 ççè  However, in a Diesel = T T V V 3 4 4 3 -1 1 2 -1 ç çè ÷÷ø V V V = V V 1 4 ¹ V 4 3 1 2  The compression ratio (rv) is a volume ratio and, in a diesel, is equal to the product of the constant pressure expansion and the expansion from cut-off.
  • 31.  Compression Ratio V V r = V vc ¹ V 4 3 1 2  Then by substitution, V v r = r r = V vc cp e · · V 3 4 2 3 ö æ T 1- 1 g = ( r ) ( ) ù ú úû é ( r -1) ê êë r - 1 = V T 2 = 1 - 1 th g ( r ) cp cp -1 v h g g V v 1 1- 2 g ÷÷ø ççè Diesel Cycle Derivation
  • 32. Diesel Cycle P & T Prediction  Determine the temperatures and pressures at each point in the Diesel Cycle Compression Ratio = 20:1 Cut off ratio = 2:1 T1 temperature = 25oC = 298oK Qin Heat added = 1300 kJ/kg P1 pressure = 100 kPa
  • 34. Dual Cycle P-V Diagrams:
  • 35. Dual Cycle Efficiency  Dual Cycle Thermal Efficiency Qin = m Cv (T 2.5 - T 2 ) + m Cp (T3 - T 2.5 ) g g h a b V 3 V 2.5 = 1 - 1 ö çè = P é a 3 b = P 2 ù úû êë ÷ø æ - 1 ( -1) + ( -1) CR ( -1) a ga b where: γ = Cp/Cv ( ) Rej 4 1 Q = m Cv T -T
  • 36. Diesel Cycle Derivation  Critical Relationships in the process include ö æ T 1- 1 g = ( r ) = V T V v 2 1 1- 2 g ÷÷ø ççè F = m Q A Q cycle æ = V P ö 2 g a fuel = (r ) V P v 1 2 1 g ÷÷ø ççè Q = m Cp DT Q = m Cv DT ( ) ù ú úû é ( r -1) ê êë r - 1 = 1 - 1 th g ( r ) cp cp -1 v h g g
  • 37. Design Issue  Improve efficiency  Higher compression ratio  Combustion control  Ignition timing  Exhaust recuperate  Minimize shaking force/torque  Lubrication  Pollution control  Cost deduction – short stroke engine
  • 38. MCHE 569 Project 1 Given a single cylinder internal combustion engine,  r=2.6”, l=10.4”, m2=0.060 blob,  rG2=0.4r, m3=0.12, rG3=0.36l,  m4=0.16blob. Piston dia. is 5.18”.  The crank rotates at 1850 rpm.  Compression ratio is 8:1.  Thermal condition:  T1 = 20 deg. C, P1 = 101kpa, Qin = 810 kJ/kg  Calculate in Excel:  Thermal condition of all 4 stroke  Thermal efficiency  Gas force  Gas torque  When theta = 0, 90, 180, 270, …720 calculate shaking force and torque  Gas-fuel mixture mass flow rate  If mass ratio of the mixture is 4 part air vs. 1 part fuel, calculate fuel consumption rate, and volumetric air flow rate.
  • 39. Gas Turbines - Definition  Definitions  Thermal energy conversion device  Fuel -> mechanical/electrical power  Fuel -> Propulsion  Difference from ICE  Absence of Reciprocating and Rubbing Members  Power/Weight ration
  • 40. Gas Turbine – Components  Frame  Casing  Front / main  Gas generator  Compressor – rotor/stator  Combustor  Power conversion  Turbine – rotor /stator/ exhaust
  • 41. Gas Turbine / ICE  Higher Efficiency,  High power/weight  Robust Combustion/Insensitive to fuel condition  Minimum Power output  Complexity/Maintenance  Higher Cost
  • 42. Application of Turbine  Power Generation  Lycoming TF-35  Garrett’s GTCP660 Auxiliary Power Unit  Propulsion  Turbojet: GE J85-21 (F-5E/F) ; CJ610  Turbofan: Garatte F-109 (T-46 Twin-Shaft)  Turboprop Garret’s TPE331-14
  • 43. Turbine Configuration  Shaft arrangement  Single: Fix speed and load  Twin/Triple shafting  HPT drives compressor and LPT not need for gear reducer  High efficiency at variable speed  High reliability at variable power  Multiple coaxial shaftes  Complex control, high efficiency with more flexibility
  • 44. Ch 2. Terminology of Turbomachinery  Critical, challenging and special design problem for turbomachinery is with blades.  Definition of turbomachines  Energy conversion device  Continues flow  Dynamics acting  Rotating blade rows
  • 45. Classification of Turbomachine  By function  Work absorber - Compressors, fans and pumps  Worker - Turbines  By fluid  Compressible  Incompressible  By meridional flow path  Axial  Radial
  • 46. Stage  Definition -- Stator and rotor pair  Stator  Convert fluid thermal to fluid kinetic energy  No energy transfer to or from blade  Rotor  Energy transfer from or to the fluid -- fluid total energy change
  • 47. Coordinate System and Velocity Diagram  Coordination system  Polar cylindrical system  Radial – r, tangential θ, axial – z  Velocity diagram  Total (absolute) velocity -- V  Relative (fluid flow vs. blade) -- W  Blade velocity due to rotation – U  1 – inlet, 2 -- exit  V=W+U
  • 48. Blade VD  Stator  U = 0  V = W  Rotor  V=W+U  Impeller  Compressor and turbine VD are reversed  Subscription convention Vr1 , …
  • 49. Axial Flow Turbine  Sign convention  Positive if along the rotation  How to determine fluid acting surface  Turbine – Fluid acting on the convex side of blade airfoil  Compressor – Concave side
  • 50. Comparison Between Axial and Radial Flow Turbine  Signal stage efficiency  Radial is higher  Loss between stages  Radial is higher  Way to improve efficiency  Radial – make the diameter of the rotor larger  Axial – add stages
  • 51. Compressor Stall, Surge  Stall  In axial compressors, gas density/pressure, sometime even temperature, may change sharply in certain stage  Low-speed, low-flow, high stagger, stall is imperceptible, and recoverable  Surge  Domino stalls occur from last stage in high speed compressor  Non-recoverable, cause temperature rise, significantly reduce the performance of the compressor, and often end up with blade damage
  • 52. Turbine Choke / Blade Cooling  Choke / shock  Relative velocity become supersonic  Blade  High temperature alloy  Intensive cooling  Current technology – turbine temperature can be 25% high than the melting point of the blade
  • 53. Variable Geometry in Compressor and Turbine  Power = pressure * volume flow rate  Recover from surge in compressor  Startup – ignition – surge  Squeeze stall out  Different turbine work at different design point  Keep pressure the same, reduce flow channel cross-section area  reduces volume flow rate  reduce power and mass flow rate  to maintain the pressure and less mass flow  burn less fuel
  • 54. Ch3. Aerodynamics of Flow Processes  General flow governing equation  Total properties  Ideal gas isentropic properties  Sonic speed and mach numbers  Mach number expressed relations  Isentropic relation in term of local mach  Critical velocity and critical properties  Isentropic relation in term of critical mach
  • 55. Continue  Compressible flow in isentropic nozzle  Varying-area equation  DeLaval nozzle - CD nozzle  Unfavorable back pressure gradient  Other important relations for nozzle  Choking flow  Shock equations
  • 56. Continue Outline  Definition of turbomachinery isentropic efficiency  Total-total efficiency  Compressor  Turbine  Total-static efficiency  Total condition of an incompressible flow  Limitation of Bernoulli's equation
  • 57. General Flow Governing Equation  Continuity equation m = ×V A = ×V A = const 1 1 1 2 2 2  r r  Linear momentum equation  Energy equation q w h h V V g Z Z + = - + - + -    ( ) 1 ( ) ( ) shaft + = - + - + - [( ) ( ) ( )] 2 1 2 1 2 1 2 2 2 1 2 1 2 1 2 2 2 2 1 Q W m h h V V g Z Z Shaft ( ) ( ) x 2x 1x y 2 y 1y F = m × V - V F = m × V - V
  • 58. Total Properties  Isentropically convert all energy into enthalpy  Total/Stagnational, local/static = + 2 + h ( h ) 1 V gZ t 2 = = h c T h c T t p t p P P r rt t
  • 59. Ideal gas isentropic relations  State equation and Constants  Entropy change of a process  Isentropic process p = RT R = J kg K for compressor for turbine 1.4 1.33 287 g = g = r  g c = × R c = × R g - g - D = × - P P v s c T R ln( 2 ) ln( 2 ) 1 1 1 1 1 P T P g g 1 T 2 1 r 2 1 P 2 1 - ö ÷ ÷ø æ = ÷ ÷ø ç çè ö æ = ç çè g r T P
  • 60. Ideal Gas Adiabatic Relations  Adiabatic means Tt = const. s R P T g / ln ö æ ö 2 æ ö æ ö æ P 2 æ D - T 2 P s t q e P 2 2 2 t g  Adiabatic process is a better assumption for all stationary turbo components ÷ ÷ø ç çè ÷ ÷ø ç çè = = ÷ ÷ø ç çè - = D ÷ ÷ø ç çè = - ÷ ÷ø ö ç çè - 1 1 1 1 1 1 1 1 / T P P T P P cP t t g g
  • 61. Sonic Speed and Mach Number  Sonic speed a dp g  Mach Number RT = = d r M = V a
  • 62. Isentropic Relations in Term of Mach  Total to local g çè 2 ö g g - ö çè 2 1 1 1 M çè 2 ö 1 1 2 1 1 2 1 1 2 - ÷ø T P t r =æ + - ÷ø =æ + - ÷ø =æ + - g g r g M P M T t t
  • 63. Critical Property  The local condition at unity mach ö æ + cr t cr cr t T T V a R ×T  Critical mach g + = = × ÷ ÷ø ç çè = 1 2 1 2 g g ) M V cr g × + - 2 M 2 (1 1 1 2 2 1 M R T t + = × + = g g g
  • 64. Isentropic Flow in Critical Mach 2 g g - ö ö 2 1 1 1 2 æ = - g - 1 1 T T M t cr 1 æ g = - g - 1 1 P P M t cr 1 æ g r r g = - - 1 1 t cr 1 - ö ÷ ÷ø ç çè + ÷ ÷ø ç çè + ÷ ÷ø ç çè + g g M
  • 65. Isentropic Flow in Varying Nozzle  To increase the speed of fluid  Converging the subsonic flow  Diverging the supersonic flow g + 1 2( 1) g M 1` - 2 2 2 1 A * ö æ + = 1 1 - + ÷ ÷ø ç çè g g A M
  • 66. Nozzles in turbomachinery  The most important feature  Diffuser must be carefully designed so that the flow remains attached to the wall  Unfavorable pressure gradient makes the design curve of diffuser
  • 67. Other Important Features  Choking flow
  • 68. Normal Shocks-1  Control Volume
  • 69. Normal Shocks-2  Basic Equations for a Normal Shock
  • 70. Normal Shocks-3  Intersection of Fanno & Rayleigh Lines
  • 71. Normal Shocks-4  Normal Shock Relations
  • 72. Normal Shocks-5  Normal Shock Relations (Continued)
  • 73. Supersonic Channel Flow with Shocks  Flow in a Converging-Diverging Nozzle
  • 74. Isentropic Flow of an Ideal Gas – Area Variation  Isentropic flow in a converging-diverging nozzle
  • 78. Definition of Turbomachinery Efficiency  Total-to-total efficiency  Compressor  Turbine 1 1 = D h ( ) t ideal ( ) 1 2 1 1 2 g - ÷ø ö çè æ - ÷ø ö çè æ = D - - t t t t t actual t t T T P P h g h 1 1 h = ( D ) - - h t actual g ( ) 1 1 2 1 2 - ÷ø ö çè æ - ÷ø ö çè æ = D g t t t t t ideal t t P P T T h
  • 79. Turbine Efficiency  Total-to-static Efficiency – use in applications where exhaust is counted as waste, such as power plant h = D - - ù g ( g - 1 2 ) 1 1 2 ( ) é 2 2 P P 1 2 2 2 2 1 1 2 1 , 1 (1 ) 1 1 g - + - = - + = ú ú û ê ê ë ÷ø ö çè æ - - g g g g g g h t cr t t P t t actual t s turbine P M M P c T P
  • 80. Compressibility and Bernoulli Equation  Error of Bernoulli when used in compressible flow é g - = æ + - - 1 1 1 ö çè  M<= 0.3 incompressible ... 2 1 M 4 40 1600 1 ù 1 2 2 4 6 2 2 2 = + + + + ú ú û ê ê ë - ÷ø M M M M P P t V g r g g
  • 81. Chapter 4  Dimensional analysis  Buckingham Π-Theorem  Off-design performance of gas turbine  Dimensional analysis in turbomachinery  Specific speed
  • 82. Dimensional Analysis  Buckingham π-theorem  Select all related as a set of n variables  Determine k (either MLT 3, or MLTt 4)  Select k most important variables as the central group  Multiply each of the rest n-k variables to solve for n-k πs  Set up the system of equation  Arbitrarily set one variable’s exponential as unity  Solve the rest exponentials
  • 83. Application to Turbomachinery  Geometric similarity  Dimensional proportional  Dynamical similarity  Geometrical similar machines with each velocity vector parallel  Similarity principle  Geometrically similar  Non-dimensional term/number identical
  • 84. Performance Characteristic  Head coefficient  Head efficiency f Q gH y r , f Q gH h r  Power coefficient ö ö ÷ ÷ø æ æ , f Q act P P h r ç çè æ = = = ÷ ÷ø ç çè = = ö ÷ ÷ø ç çè = = m m m 2 3 2 3 2 2 3 ˆ , ND ND o P ND ND gH ND ND U i P ideal H
  • 85. Compressible-flow Turbomachine æ m RT f t in ND Pr, , t , ,Re, Pr : Total - to -Total Pressure ratio : Total - to total efficiency ö : Total temperature change vs. inlet total temperature h t t t R : Gas constant : ratio of specific heat of the gas mixture g Compressor 1.4 Turbine 1.33 , , , 2 , , = = D ÷ ÷ ø ç ç è D = - - g g h g t in t in t in t in t t T T RT D P T T 
  • 86. Another Function and More Terms æ m T f t , in h Pr, , , N , , , P t T t t ö : Standard atmosphere temperature, i.e. 298K : Standard atmosphere pressure, 101 kPa T STP STP STP STP t in t in t in t t P P T T P T T = = ÷ ÷ ø ç ç è D = - q d 
  • 87. Map and Characteristics  Turbine or compressor map – the plot  Characteristic – the curves in the plot  Design point of compressor is close to surge  Design point for turbine is close to choke
  • 88. Specific Speed – Incompressible N Q 4 (gH)3 Ns =  It was experimentally verified that certain type of turbomachinery (axial, radial, mixture) gives highest possible performance (efficiency) over certain range of specific speed value
  • 89. Specific Speed - Compressible N Q ex  Qex is the volumetric flow rate at stage exit, which is not the same as that at the inlet due compressible flow  is the idea specific work extracted from or to the turbomachine 4 ( h )3 t ,ideal Ns D = t ideal h , D
  • 90. Ch5. Euler’s Equation  Energy transfer between fluid and rotors  Force/torque generated through momentum change  Energy transfer happens while these force/torque do works
  • 91. Momentum Change at All Directions  Axial velocity change  Axial load on to the shaft – no works  Radial velocity change  Radial load bending moment  vibration  Destructive works  Both of above should be minimized  Tangential direction – effective works
  • 92. Euler’s Equation  Torque  Power  Specific work m r V rV = - ( ) q q 2 2 1 1  P = = m U V - U V ( ) q q 2 2 1 1  q q tw 2 2 1 1 t p = U V - U V
  • 93. Component of Energy Transfer  Typical velocity diagram  Vz1 = Vz2 = const V Vz z W - ( U - V ) = V - V q q W - ( V - U ) = V - V q q W - ( U + V - 2 U V ) = V - V q q q U V = V + U - W ( ) ( ) ( ) 2 2 2 1 2 2 2 2 2 1 2 2 2 1 q 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 2 1 2 1 1 2 1 2 2 2 2 2 2 2 2 2 2 2 2 1 U V - U V = V - V + U - U + W - W = q q
  • 94. Heads  Dynamic Head (Absolute V)  Total kinetic energy lost/gain in fluid flow  Effective shaft works  Convective Head (U)  Annual expansion/shrinkage  Small  Static Head (relative W)  Action of fluid flow to stages
  • 95. Enthalpy Across A Stage  Absolute  Relative  Rothalpy g - T T M M = + = (1 ) g - T T M M = + = (1 ) Ts Local Static temperature h = c T - absolute total t p t h = c T - relative total t r p t r I h UV Rothalpy t a W t r s r V a t s r = - - q , , 2 2 1 , 2 2 1 : ( )
  • 96. Reaction  Definition 2 1 2 2 2 2 2 1 R = U - U + W - W ( ) ( ) 2 1 2 2 2 2 2 1 2 2 2 1 V - V + U - U + W - W ( ) ( ) ( ) 2 2 2 1 2 1 2 2 Turbine R = U - U + W - W ( ) ( ) 2 2 2 1 2 1 2 2 2 1 2 2 V V U U W W ( ) ( ) ( ) Compressor - + - + -
  • 97. Stage Blade Design vs. Reaction  Inlet and exit angles for stator  α0, α1  Inlet and exit angles for rotor  β0, β1  Deviation angle  difference of flow and metal  Swirl angle  local absolute angles
  • 98. Axial Turbomachine  Zero-reaction stage – Impulse stage  W1=W2, β1= -β2  50% reaction (symmetric) turbine stage  V1=W2, V2=W1  α1= -β2, α2 = - β1  50% reaction (symmetric) compressor stage  V1=W2, V2=W1  α1= -β2, α2 = - β1
  • 99. Incidence and Deviation Angles  Incidence angle  Flow angle to leading edge metal angle  Always exists like attacking angle  Positive or negative  Deviation angle  Insufficient flow momentum change  A very important controlled feature in compressor  A measure to adverse/unfavorable pressure gradient
  • 100. Real-life Flow path in Axial Turbo  Explain with isentropic and γ / (γ-1)>>1  Total pressure drop much faster than temperature  Total density decrease across rotor  If Mach change over rotor is neglected,  Static density decreases across the rotor  To keep Vz constant, the annular cross area  Decreasing for compressor  Increasing for turbine  Flow passage over stator, due to significant M increase  Converging for compressor  Diverging for Turbine
  • 101. Definition of Total Relative Properties in the Rotor Sub-domain  Relative properties can be modeled as flow through nozzle at speed W across T const across rotor 1 T T W M c W RT W W cr tr T T M T M g - g - = + = = = g g = - = - tr t g g r cr P = P - M = P - M g g - - 1 2 2 1 - 1 (1 ) (1 ) 2 1 - 1 (1 ) (1 ) g - tr r cr t 2 1 1 1 , g 1 1 , , 1 2 2 g - 1 (1 ) (1 ) 1 1 2 1 1 2 1 1 , , 2 - - + + + + + + + = - = - g g g g g g g g g r r M r M tr t r cr t r p tr s r cr
  • 102. Continue  General term  Isentropic – Total relative pressure is constant across rotor  Other process total relative pressure decrease 2 T = T tr tr 1 2 P t ( 2 ) 1 1 1 2 1 g - = g T t t t T P P tr P tr
  • 103. Graphic Shown  For Turbine  P2 < Pt2 <P1< Ptr2 <=Ptr1<Pt1<=Pt0  For Compressor  Po<P1<Pto <= Pt1 < P2<Ptr1<=Ptr2<Pt2
  • 104. Ch6 Radial Equilibrium Theory  Background  Study for thermal properties as traverses a stage  Pitch line analysis  How properties (except U) vary at a given axial location  Assumption – axi-symmetric flow  Note – Wake at gap is negligible  The Problem  Find the relationship among fluid properties, annual geometry, and velocity
  • 105. Derivation  Pressure force, and mass of the differential control elements F p dp r dr d top = - + + ( )( ) F prd dp dr d under = F p r side = + + 2( )( )sin( ) 2 2 2 F = F + F + F = r × dp × d p top under side [ ] r q r p p q p q q q q m = r + dr - r d = rdrd 2 ( ) 2 2
  • 106. Acceleration  Centrifigal a V Centrifigal  Meridional curvature a V m  Convective sin( ) cos( ) 2 2 convective m m m m meridional centrifigal a V r r a a q =  = = -
  • 107. Radial Equilibrium Theory  F=ma a a a = + + - Centrifigal meridional centrifigal convective × × = - - cos( ) sin( ) 2 2 V 2 2 V q V F dm r dp d dp V m 1 = q - m cos( ) - sin( ) ( ) 2 2 V V dp  1 m cos( ) V sin( ) ( Converging ) r r dr V diverging r r dr V r r rdrd m m m m m m m m m m m m a a r a a r a a r q q q   = + +
  • 108. Simplified cases  Vm = const Vr=0  Invoke total enthalpy 1 dp V 2 q r r dr = 2 2 1 h h c T V V V V = + = + + = + + ( ) ( ) 1 + meridional centrifigal convective dV dV V V = + + - t z ( ) q g - p dp = Û - = Û = g g g = + + - V r dV q dV dr const dV V V t z dV dr dh dh dh dr z p d r r r dp p dr 2 0 p dp d dp dr dr dr dr z dp dr d dr p dr dr dr dr dr dr dr z p p z z V t V V a t z 2 2 2 r ( 1 ) 1 1 1 1 g 1 2 2 2 2 2 q q q g g r r q g r r r g r r q g r q q = + + - - -
  • 109. Continue Simplification  dVz / dr = 0 dht / dr = 0   Free Vertex 0 = 0 + + 2 V dV dV  Nature fluid flow  Flow vorticity – flow particles spinning around its own axis  Least vorticity in free vortex flow  Free vortex blade design is most desired in aerodynamics, but unrealistic  Disadvantage in structural design and manufacturing  Boundary layer and tip leakage cancel the idea effect of free-vortex V rV const V r dr r dr = - Û = q q q q q q
  • 110. Chapter 7 Axial Flow Turbine  Steam Turbine  Superheated Region  Wet Mixture Region  Gas Turbine  Similar to superheat steam turbine  High temperature alloy  Basic gas turbine design process
  • 111. Stage Definition  Stator followed by rotor  Stator airfoil cascades – vanes  Rotor airfoil cascades – blades  Design process  Preliminary phases  Compressor/combustor exit, inlet path/nozzle,  Stage 1,2,3,4, Casing, pitch line, interstage axial gap  Detailed phases  Blade geometry design  Real flow effects  Empirical equation  Stacking vanes and blade sections  CAD Approach to axial turbine
  • 112. Preliminary Design of Axial-Flow Turbines  Given conditions  Turbine inlet conditions (p, t,α,β)  Rotary speed  min. tip clearance,  max tip Mach  Envelope radial constrains (casing), max axial length, max diverging angle  Interstage Tt, max exit flow rate (A*N^2), Mach  Other, (such as overall efficiency, etc.)
  • 113. Preliminary Design -- Find  Meridional flow path  Flow condition along pitch line  Hub and tip velocity diagram (assuming free-vortex stages)
  • 114. Design Processes  Step 1 -- Justify axial turbine type  Ns = N*Q^0.5/(Δht)^0.75 > = 0.775  Δht is enthalpy change over a single stage, you change the number of stages to make the Ns to be optimum (usually “1”)  Step 2 –Split work across turbine individual stages (Δht1, Δht2…), according to experience  Efficiency  Off-design, and operation conditions usually 60:40, 55:45,50:50  Step 3 According to the experienced work split, and efficiency, determine interstage total condition  Too small axial gap triggers strong and dangerous flow interaction  Too large axial gap increases end-wall friction loss  Stator/rotor gap is more critical that interstage because large swirl velocity
  • 115. Formulating an Simplified Approach  Calculate specific speed  Find optimum number of stage  Estimate turbine efficiency  Define a stage work coefficient c T = = D = - = - = - W W V V U V V ( ) 1 2 1 2 ) W y s p t q 1 q 2 q q q q 2 2 2 y = V b - b (tan tan ) 1 2 U  Define Flow coefficient U U U U U z Vz f = U = - (tan tan ) 1 2 y f b b
  • 116. Coefficient Design-1 V - V = W - W = U q q q q W - W = W + W - W - W = W - W Z Z q q q q 2 1 1 2 1 2 2 1 W W = + q q W W = - q q - R W W - = - 2 ( ) 2 ( ) 2 q q (tan tan ) 2 q q W q = W q = W = V b b tan tan 2 2 (tan tan ) R V 2 1 2 1 2 1 1 1 2 1 2 2 2 1 2 2 2 2 1 2 2 2 2 1 2 2 2 2 1 2 2 b b f b b = + = + U U U W W U V V z z z 
  • 117. Coefficient Design-2 f b b = + (tan tan ) 2 1 2 tan = tan + 1 f 2 2 a b f a b tan 1 = - R ( 2 ) 2 tan 1 y f b y f b y f b b tan tan 1 ( 2 ) 2 (tan tan ) 1 1 2 1 1 2 = + ì ï ïî ï ïí = - + Û ïî ïí ì = - R R
  • 118. Example 7-1 Flow inlet angle 0 Mass flow rate m 20kg/s ³ Stage efficiency 90% Inlet total temperature 1100 K Inlet total pressure 4 bars Total Pressure ration 1.873 Rotational speed 15000 rpm £ = = Mean blade speed 340 / Stage work coefficient ( h t = = - Assume 1.333, R 287 / Find one stage turbine m s kJ kg K - D £ : ) 1.5 U Given : gas 2 0 g a  
  • 119. Solution  Calculate specific speed  As a rule of thumb, you may assume the density of the fluid is 1kg/m^3  It may invoke too much error if calculate isentropic process, why? -- rotor  This is just an initial calculation, so it is not wise to spend too much time and effort to make your result very accurate
  • 120. Step 1.  From density; mass flow rate  volumetric flow rate  From inlet total temperature; inlet/exit total pressure ratio  outlet temperature assuming isentropic process  Inlet/exit temperature and Cp  total enthalpy change over the turbine stages  Calculate Ns using N*Qex^1/2 / (Δht)^0.75  Increase number of stages to make Ns per each stage to be > 0.775
  • 121. Design the stages  ψ Cp T =D = ´D t t 2 2 D = - = - = - P T U h U t t ö æ g ö æ ,2 ,2 U use the given m s T t ,2 One stage may be fine ¬ g Cp R P T T T T T T T T t tt t t t t t t t t - = 1 = ---- ÷ ÷ ÷ ø ç ç ç è ÷ ÷ø ç çè - = - - 1.427 340 / 1 1 (1 ) 1 1 , 1 , 1 , ,0 ,2 ,1 ,2 ,1 y g h y g
  • 122. Φ  Use Φ and α2 to set R close to 0.5 ì tan 1 = - R 1 y f b ( 2 ) 2  Try α2 = 0 R=?  and α2 =-15 R=? ì ï ïî ï ïí tan 1 = - + y f ( 2 ) 2 = + ï ïî ï ïí = + f b 2 a b f a b tan tan 1 tan tan 1 2 2 1 1 or R
  • 123. Other parameters  U=340 m/s and N – 1500rpm   rm = 0.216m  α1= atan (tanβ1+1/Φ)=?  Sketch the velocity diagram  Calculate V1, W1, V2, W2  Check Mcr  None of the Mach can be greater than 1
  • 124. Blade Design at 0,1,2  Density  From mass flow rate m r r m   hub m æ æ + m r VA r r 1 g 1 V 1 r r r  Þ = = ´ ´ - 2 ( ) m A m p r r m tip m cr m tip hub t V r V r V V ´ ´ = - ´ ´ = + ö ÷ ÷ ø ç ç è ö ÷ ÷ø ç çè = Þ = - - 1 - 1 2 r p r p r g g 2 2 2 2 
  • 125. Stage Configuration  Symmetric design (Config 1.)  Simplest for design calculation  Rotor rubbing  Descendent (Configuration 2)  No rotor and simple enough  Hub weakening  Optimized (Config. 3)  Theoretically optimum
  • 126. Design for blade shape  Aspect ratio  Chord (the axial projective length of blade) Cz_vane, Cz_blade  Gap between rotor and stator  Gap = 0.25*(Cz_vane+Cz_blade)/2  1/8 of the stage solidity length
  • 127. Detail turbine airfoil cascades  Select an airfoil  Camber the center line to achieve the inlet and exit flow  Consider other factors that affects the efficiency of the flow  The detailed design procedure
  • 128. Detail Design Procedure  With the velocity diagram  Design for the efficiency of flow deflection  Blade geometry parameters  Iterative process  Given inlet/exit condition  Find the most efficient shape of blade  Real flow considerations  Some CAD packages
  • 129. Blade Geometry  Geometry to be determined -- page 120  Suction side (SS) and pressure side (PS)  Design Principle  Higher loaded – larger P/V difference between SS and PS  Real fluid consideration
  • 130. Typical Blade Load 100 90 80 70 60 50 40 30 20 10 0 0 1 2 3 4 5
  • 131. Force Applied To The Blade  Cascade x-y coordination  r- θ - z  X  Z (axial direction)  Y  θ direction  S - pitch of blades  Circulation around each blade S V V S 2 r = G = - F P P S F V = - = G ( ) x in exit y z F Rp P S Rp P exit in x in P no blades = - = (1 ) ( ) ._ 2 1 r p q q
  • 132. Real Fluid Effects  Pitch/axial chord ratio s/c  Aspect ratio h/c  Incidence  Tip clearance  Viscosity and friction
  • 133. Pitch/axial chord ratio s/c  Definition of s and c  s: circular pitch of at given radius, usually the meridional  c: tip to trail linear distance, not counting the curvature of the blade  Figure 7.14 on Page 124  Conclusion: larger deflection  smaller s/c
  • 134. Aspect Ratio h/c  Definition  h: tip-hub distance (delta-R)  c: tip to hub distance of blade  Design perference - smaller the better  <<1.0  boundary layer affects performance  >6.0  vibration and bending stress  Old optimum value is 3.0 ~~ 4.0  Modern design is around 1.0
  • 135. Incidence  Gas (attacking) angle and metal angle  Profile (pressure) loss coefficient Yp  Yp = ( Total pressure loss ) (exit total to local pressure Difference)  Reaction blade (momentum absorber – both velocity magnitude and direction change counts) has lower Yp than Impulse blade (direction only)  Lead edge thickness reduces sensitivity of incidence effect on Yp
  • 136. Tip Clearance  Tip leakage  Direct leakage  axial leakage  Indirect leakage  tangential from pressure side to suction side  Leakage prevention  Direct leakage prevention  slot in casing  Indirect leakage prevention  Full or partial shroud
  • 137. Reynolds Number - Viscosity  Similar to a plate  Re > 10^5 Ypconstant  Re > 10^5 Yp change rapidly
  • 138. Guideline For Blade Design  Criterion for Acceptable Diffusion  Downstream turning angle of cambered airfoil  Location of front stagnation point  Trailing edge thickness  Effect of Endwall contouring
  • 139. Criterion for Acceptable Diffusion  Diffusion – expansion or de-compression  Velocity decline Diffusion  aversive pressure (with large deflection) boundary layer separation  large loss  Diffusion factor 0.25 ö P P t exit t V 1 max ( ) ö P t V max ( ) £ ö ÷ ÷ø - ÷ ÷ø - ÷ ÷ø = Vcr Vcr P P P l
  • 140. Downstream Turning Angle  Definition:  A build-in camber angle of airfoil centerline – design for camber curve of airfoil  Reasoning: straight portion of latter half camber line in airfoil  The purpose is to control diffusion  With the angle δ build into blades squeeze the subsonic flow path  increase flow momentum  decrease diffusion  However, if too much  Mach ~~ 1.0  supersonic pocket  shock  abrupt total pressure drop  With M~~0.8, δ = [8.0, 12] deg
  • 141. Location of Front Stagnation Point  Front Stagnation Point  the point where flow hit metal surface at 90deg  Actual stagnation point s can be far from the theoretically point a  With high flow velocity  separation  Correction  Negative incidence angle  leading edge radius, arc length …
  • 142. Trailing Edge Thickness  Trailing edge of airfoil  Flow from different blades mixed after trailing edge  sudden expansion duct flow  Thinner the better, but  Strength consideration  Coolant pass
  • 143. Endwall Contouring  Contour of surface of either casing or hub  Purpose of the contouring -- to improve blade aerodynamic loading  Form a nozzle to change the flow property  Accelerate the flow at rear portion of suction side  Force the boundary layer thinner  Gather/collect the scatter fluid
  • 144. Useful Equations  Choice of stagger angle  Stagger angle between the connecting line airfoil front tip to trailing edge and the axial direction é ö çèb = - æ b - b 0.95 tan 1 tan 1 tan 1 + úû  Note:  Stator design use α instead of β  One of the two angle is negative 5 2 ù êë ÷ø
  • 145. Optimum Spacing and Chord Ratio  Definition of Zweifel’s loading coefficient  Zweifel’s law  Optimum Zweifel’s coefficient is 0.8 ö - ÷ ÷ø æ = ç çè s y b b b 2 cos (tan tan ) c z Solidity Ratio : s = c z s 0.8 2cos (tan tan ) 2 1 2 2 2 1 2 2 s = b b - b T
  • 146. Staking of 2D Sections  Blade design is first done by design sections at each radius  Staking these 2d Sections to form a 3D blade  Experiment and and reworking  Problems: secondary flow – flow crossed original design path into other plane  Method of staking  Fix a staking axis  Rotate each design 2d airfoil to optimize
  • 147. Chapter 8 Axial Flow Compressors  Introduction  Centrifugal compressor is first used  Axial flow compressor is much more efficnet  Axial turbine can be used as a compressor if reversed, at price of significant efficiency loss
  • 148. Axial compressor vs turbine  Turbine  Fluid flow from high pressure to low pressure naturally  Accelerating though passage  Compressor  Fluid flow from low pressure to high pressure  Convert kinetic energy to pressure potential  Compression must be a slow decelerating flow
  • 149. Multi-stage Compressors and Stage Definition  Multi-staging is necessary  Pressure ratio vs performance  Compressor stages  Inlet Guide vane – nozzle  axial flow to tangential flow  Rotor-stator for each stage  Subscription 1 rotor inlet; 2 rotor outlet/stator inlet; 3vane outlet  V3=V1; α3=α1
  • 150. Compressor Blade  Simpler than turbine blade  Selected from standard  British C4 – design from pressure distribution but no definite form  Base profile and camber line  Standard parameter – t/c 10% above appr. 40%
  • 151. US NACA Series  Classified according to CL  The amount of cambers  4, 5, 6, 7 series  Most commonly used is 65xxx  Deflection angle ε  Solidity c/s
  • 152. Real Flow Effect  Incident and deviation  Total pressure loss coefficient (PLC) ΔPt/ (ρV^2/2)  Deflection angle  Stalling  PLC is twice as minimum  Nominal e* is 0.8 of stalling es  Positive incident angle cause high loss
  • 153. Reynolds Number  Lower than 2x10^5 leads to high profile loss  Higher than 3x10^5  does not change much  Critical Re is 3x10^5  This effect is partially affected by the turbulence.