The document explains Pascal's Law, attributed to Blaise Pascal, which states that pressure applied to an enclosed fluid is transmitted undiminished to all parts of the fluid and its container. It discusses the principle's applications in hydraulic systems, including a series of calculations and problems related to force and area in these systems. Various example problems illustrate the practical use of Pascal's principle in determining input and output forces in hydraulic lifts and other applications.

1. 1
Pascal’s Law
Ang Sovann

2. 2
Pascal law
 Why ???

3. 3
Blaise Pascal
 French mathematician, physicist,
inventor, writer.
 Born in 1623 and died in 1662,
France

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Pressure
 “Pressure applied to any part of an
enclosed fluid is transmitted undimished
to every point of the fluid and to the walls
of the container”

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Transmitting Pressure
 French Scientist
Blaise Pascal
studied fluid pressure
in 1600.
 What happens when
you press on a closed
bottle?

6. 6
Transmitting Pressure
 When a force is
applied to a confined
liquid, the change in
pressure transmitted
equally to all parts of
the fluid

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Pascal’s principle
 Pascal stated that “pressure applied to an enclosed fluid
is transmitted undiminished to every portion of the fluid
and the walls of the containing vessel”.

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Pascal’s principle

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Pascal’s principle

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Pascal’s principle

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Hydraulic system
 Pascal’s s is very applicable in hydraulic system.

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Hydraulic system

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Hydraulic system

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Problem 1
 The area of A1 = 10 cm2
 The area of A2 = 100 cm2
 Force 2 (F2) = 100 Newton
 Calculate F1.

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Problem 2
 If the area of A1 = 0.001 m2 and the area of A2 = 0.1 m2 ,
external input force F1 = 100 N, then the external output
force F2 ?

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Problem 3
 Car’s weight = 16,000 N. What is the external input force
F?

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Problem 4
 Area of A is 60 cm2 and
area of B is 4,200 cm2,
determine the external input
force of F.

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Problem 5
 The hydraulic lift has a large cross section and a small
cross section. Large cross-sectional area is 20 times the
small cross-sectional area. If on the small cross section is
given an input force of 25 N, then determine the output
force.

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Problem 6
 Calculate F2

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Problem 7
 The large piston in a hydraulic lift has a radius of 250 cm2
What force must be applied to the small piston with a
radius of 25 cm2 in order to raise a car of mass 1500 kg?

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Problem 8
 A trash compactor pushes down with a force of 500 N on
a 3 cm2 input piston, causing a force of 30,000 N to
crush the trash. What is the area of the output piston that
crushes the trash?

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Problem 9
 When the button of a is pushed, a force of 350 N pushes
down on a 1.3 cm2 trash compactor input piston,
creating a force of 22,076 N to crush the trash. What is
the area of the piston that crushes the trash?

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Problem 10
 Johnny the auto mechanic is raising a 1200 kg car on her
hydraulic lift so that she can work underneath. If the area
of the input piston is 12 cm2 while the output piston has
an area of 700 cm2
 what force must be exerted on the input piston to lift the
car?

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Problem 12
 Mr. Sharlow is raising a 2000kg car on his hydraulic lift. If
the area of the input piston is 9cm2 , while the area of the
output piston is 630 cm2
 what force must be exerted on the input piston to lift the
car?