Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
This presentation covers scalar quantity, vector quantity, addition of vectors & multiplication of vector. I hope this PPT will be helpful for Instructors as well as students.
In engineering, deflection is the degree to which a structural element is displaced under a load. It may refer to an angle or a distance.
The deflection distance of a member under a load is directly related to the slope of the deflected shape of the member under that load, and can be calculated by integrating the function that mathematically describes the slope of the member under that load. Deflection can be calculated by standard formula (will only give the deflection of common beam configurations and load cases at discrete locations), or by methods such as virtual work, direct integration, Castigliano's method, Macaulay's method or the direct stiffness method, amongst others. The deflection of beam elements is usually calculated on the basis of the Euler–Bernoulli beam equation while that of a plate or shell element is calculated using plate or shell theory.
This presentation covers scalar quantity, vector quantity, addition of vectors & multiplication of vector. I hope this PPT will be helpful for Instructors as well as students.
In engineering, deflection is the degree to which a structural element is displaced under a load. It may refer to an angle or a distance.
The deflection distance of a member under a load is directly related to the slope of the deflected shape of the member under that load, and can be calculated by integrating the function that mathematically describes the slope of the member under that load. Deflection can be calculated by standard formula (will only give the deflection of common beam configurations and load cases at discrete locations), or by methods such as virtual work, direct integration, Castigliano's method, Macaulay's method or the direct stiffness method, amongst others. The deflection of beam elements is usually calculated on the basis of the Euler–Bernoulli beam equation while that of a plate or shell element is calculated using plate or shell theory.
Rotational motion. The motion of a rigid body which takes place in such a way that all of its particles move in circles about an axis with a common angular velocity; also, the rotation of a particle about a fixed point in space.
Brief review of velocity and acceleration along with mathematically explained feature . speed of lava bomb is also explained in these slides and the example of cap is qouted
Hierarchical Digital Twin of a Naval Power SystemKerry Sado
A hierarchical digital twin of a Naval DC power system has been developed and experimentally verified. Similar to other state-of-the-art digital twins, this technology creates a digital replica of the physical system executed in real-time or faster, which can modify hardware controls. However, its advantage stems from distributing computational efforts by utilizing a hierarchical structure composed of lower-level digital twin blocks and a higher-level system digital twin. Each digital twin block is associated with a physical subsystem of the hardware and communicates with a singular system digital twin, which creates a system-level response. By extracting information from each level of the hierarchy, power system controls of the hardware were reconfigured autonomously. This hierarchical digital twin development offers several advantages over other digital twins, particularly in the field of naval power systems. The hierarchical structure allows for greater computational efficiency and scalability while the ability to autonomously reconfigure hardware controls offers increased flexibility and responsiveness. The hierarchical decomposition and models utilized were well aligned with the physical twin, as indicated by the maximum deviations between the developed digital twin hierarchy and the hardware.
About
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
Technical Specifications
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
Key Features
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface
• Compatible with MAFI CCR system
• Copatiable with IDM8000 CCR
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
Application
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
Student information management system project report ii.pdfKamal Acharya
Our project explains about the student management. This project mainly explains the various actions related to student details. This project shows some ease in adding, editing and deleting the student details. It also provides a less time consuming process for viewing, adding, editing and deleting the marks of the students.
Final project report on grocery store management system..pdfKamal Acharya
In today’s fast-changing business environment, it’s extremely important to be able to respond to client needs in the most effective and timely manner. If your customers wish to see your business online and have instant access to your products or services.
Online Grocery Store is an e-commerce website, which retails various grocery products. This project allows viewing various products available enables registered users to purchase desired products instantly using Paytm, UPI payment processor (Instant Pay) and also can place order by using Cash on Delivery (Pay Later) option. This project provides an easy access to Administrators and Managers to view orders placed using Pay Later and Instant Pay options.
In order to develop an e-commerce website, a number of Technologies must be studied and understood. These include multi-tiered architecture, server and client-side scripting techniques, implementation technologies, programming language (such as PHP, HTML, CSS, JavaScript) and MySQL relational databases. This is a project with the objective to develop a basic website where a consumer is provided with a shopping cart website and also to know about the technologies used to develop such a website.
This document will discuss each of the underlying technologies to create and implement an e- commerce website.
Cosmetic shop management system project report.pdfKamal Acharya
Buying new cosmetic products is difficult. It can even be scary for those who have sensitive skin and are prone to skin trouble. The information needed to alleviate this problem is on the back of each product, but it's thought to interpret those ingredient lists unless you have a background in chemistry.
Instead of buying and hoping for the best, we can use data science to help us predict which products may be good fits for us. It includes various function programs to do the above mentioned tasks.
Data file handling has been effectively used in the program.
The automated cosmetic shop management system should deal with the automation of general workflow and administration process of the shop. The main processes of the system focus on customer's request where the system is able to search the most appropriate products and deliver it to the customers. It should help the employees to quickly identify the list of cosmetic product that have reached the minimum quantity and also keep a track of expired date for each cosmetic product. It should help the employees to find the rack number in which the product is placed.It is also Faster and more efficient way.
Sachpazis:Terzaghi Bearing Capacity Estimation in simple terms with Calculati...Dr.Costas Sachpazis
Terzaghi's soil bearing capacity theory, developed by Karl Terzaghi, is a fundamental principle in geotechnical engineering used to determine the bearing capacity of shallow foundations. This theory provides a method to calculate the ultimate bearing capacity of soil, which is the maximum load per unit area that the soil can support without undergoing shear failure. The Calculation HTML Code included.
Gen AI Study Jams _ For the GDSC Leads in India.pdf
Unit 5 rigid body dynamics
1. ENGINEERING MECHANICS
Unit – V
Rigid Body Dynamics
by
S.Thanga Kasi Rajan
Assistant Professor
Department of Mechanical Engineering
Kamaraj College of Engineering & Technology,
Virudhunagar – 626001.
Tamil Nadu, India
Email : stkrajan@gmail.com
2. Kinematics of Rigid Bodies
A rigid body has size that is not negligible and does not deform
(distance between two points on body is constant). (Idealisation)
Rigid body motion involves translation and/or rotation
Types of Rigid Body Plane Motion
Translation: - No rotation of any line in the body
- All points in body have same velocity and acceleration
- No relative motion between any two particles
Rectilinear translation
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3. Translation
Every line segment on the body remains parallel to its original direction
during the motion
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4. Fixed-axis rotation:
- All points move in circular paths about axis of rotation
Curvilinear translation
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5. Rotation about fixed axis
All particles of the body move along circular paths
except those which lie on the axis of rotation
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7. General plane motion
- Both translation and rotation occur
- Distances between particles are fixed
Note: We will consider plane motion only.
- Relative motion of one particle to another will
always be a circular motion
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8. General Plane Motion is the summation of a Translation and a Rotation
Consider the motion of the rigid bar AB:
General Motion
B1
B2
A1 A2
Rotation about A
A2
B’1
B2
We could break this motion down another way:
General Motion
B1
B2
A1 A2
Translation with B
B1
B2
A1
A’1
Rotation about B
A’1
A2
B2
A1 A2
B1 B’1
Translation with A
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9. Rigid Bodies:
Why are Rigid Bodies so different from Particles?
- Size negligible compared to motion
Particles:
mg
N
F
- All forces act through center of gravity
- Neglect rotation about center of gravity
R2R1
F
mg
- Points of application, and lines of
action of forces are important
- Rotation and Moments about center of
gravity are important
Rigid Bodies Vs Particles
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10. Types of rigid body planar motion
Translation – only linear direction
Rotational about fixed axis – rotational motion
General plane motion – consists of both linear and rotational motion
Rigid-Body Motion
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13. Summary
• Time dependent acceleration
dt
ds
v
)(ts
2
2
dt
sd
dt
dv
a
dvvdsa
• Constant acceleration
tavv c 0
2
00
2
1
tatvss c
)(2 0
2
0
2
ssavv c
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14. Rotation About a Fixed axis
Angular Position ( q )
Defined by the angle q measured between a fixed
reference line and r
Measured in rad
Angular Displacement
Measured as dq
Vector quantity
Measured in radians or revolutions
1 rev = 2 p rad
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15. q
q
dt
d
Angular velocity ( )
“the time rate of change in the angular position”
q
dt
d
Angular acceleration
“the time rate of change of the angular velocity”
q
q
2
2
dt
d
= f(q)
q dd
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18. Motion of Point P
Prxv
Position :
qrs The arc-length is
Is defined by the position vector r
tv
dt
ds
( )qr
dt
d
r
dt
dq
r
Velocity
“tangent to the path”
14/12/2014S. ThangaKasiRajan, stkrajan@gmail.com18
19. Acceleration
ta
dt
d
( )r
dt
d
dt
d
r
r
r
an
2
r
r 2
)(
r2
Direction of an is always toward O
“rate of change in the velocity’s magnitude”
“rate of change in the velocity’s direction”
a 22
rt aa ( ) ( )222
rr 42
r
Motion of Point P
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21. Rest
at = 4t m/s2
=?
q=?
ra tP )(
2
/20
)2.0()4(
sradt
t
t
dt
d
20
sradt
dttd
t
/10
20
2
0 0
2
10 t
dt
d
q
radt
dttd
t
3
0 0
2
33.3
10
q
q
q
Problem 1
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22. Problem 2
Cable C has a constant acceleration of
225 mm/s2 and an initial velocity of 300
mm/s, both directed to the right.
Determine (a) the number of revolutions
of the pulley in 2 s, (b) the velocity and
change in position of the load B after 2 s,
and (c) the acceleration of the point D on
the rim of the inner pulley at t = 0.
SOLUTION:
• Due to the action of the cable, the
tangential velocity and acceleration of
D are equal to the velocity and
acceleration of C. Calculate the initial
angular velocity and acceleration.
• Apply the relations for uniformly
accelerated rotation to determine the
velocity and angular position of the
pulley after 2 s.
• Evaluate the initial tangential and
normal acceleration components of D.
14/12/2014 S. ThangaKasiRajan, stkrajan@gmail.com
23. Problem 2
SOLUTION:
• The tangential velocity and acceleration of D are equal to the
velocity and acceleration of C.
( ) ( )
( )
( )
srad4
75
300
smm300
0
0
00
00
r
v
rv
vv
D
D
CD
( )
( )
( ) 2
srad3
3
225
2/225
r
a
ra
smmaa
tD
tD
CtD
• Apply the relations for uniformly accelerated rotation to
determine velocity and angular position of pulley after 2 s.
( )( ) srad10s2srad3srad4 2
0 t
( )( ) ( )( )
rad14
s2srad3s2srad4 22
2
12
2
1
0
tt q
( ) revsofnumber
rad2
rev1
rad14
p
N rev23.2N
( )( )
( )( )rad14mm125
srad10mm125
q
ry
rv
B
B
m75.1
sm25.1
B
B
y
v
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24. Problem 2
• Evaluate the initial tangential and normal acceleration
components of D.
( )
2
smm225CtD aa
( ) ( )( ) 222
0 smm1200srad4mm57 DnD ra
( ) ( ) 22
smm1200smm225 nDtD aa
Magnitude and direction of the total acceleration,
( ) ( )
22
22
1200225
nDtDD aaa
2
smm1220Da
( )
( )
225
1200
tan
tD
nD
a
a
4.79
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25. Problem 3
The double gear rolls on the
stationary lower rack: the velocity of
its center is 1.2 m/s.
Determine (a) the angular velocity of
the gear, and (b) the velocities of the
upper rack R and point D of the gear.
SOLUTION:
• The displacement of the gear center in
one revolution is equal to the outer
circumference. Relate the translational
and angular displacements. Differentiate
to relate the translational and angular
velocities.
• The velocity for any point P on the gear
may be written as
Evaluate the velocities of points B and D.
APAAPAP rkvvvv
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26. Problem 3
SOLUTION:
• The displacement of the gear center in one revolution is
equal to the outer circumference.
For xA > 0 (moves to right), < 0 (rotates clockwise).
q
p
q
p 1
22
rx
r
x
A
A
Differentiate to relate the translational and angular
velocities.
m0.150
sm2.1
1
1
r
v
rv
A
A
( )kk
srad8
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27. Problem 3
• For any point P on the gear, APAAPAP rkvvvv
Velocity of the upper rack is equal to
velocity of point B:
( ) ( ) ( )
( ) ( )ii
jki
rkvvv ABABR
sm8.0sm2.1
m10.0srad8sm2.1
( )ivR
sm2
Velocity of the point D:
( ) ( ) ( )iki
rkvv ADAD
m150.0srad8sm2.1
( ) ( )
sm697.1
sm2.1sm2.1
D
D
v
jiv
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28. Slider Crank Mechanism
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Slider Crank Mechanism consists of
1. Crank shaft – Pure Rotation
2. Connecting rod – Both Translation and
Rotation
3. Piston – Pure Rotation
The motion of Connecting rod depends on
motion of crank shaft
Similarly the motion of piston depends on
motion of connecting rod.
Slider Crank MechanismSlider Crank Mechanism
29. 14/12/2014 S. ThangaKasiRajan, stkrajan@gmail.com 29
Slider Crank Mechanism
Motion of Crank AB
VB = VA + VB/A
here VA = 0 because A is fixed
therefore
VB = VB/A
= rAB . ωAB
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Slider Crank Mechanism
Motion of Connecting Rod:
When crank rotates in clockwise direction, connecting rod rotates in anticlockwise direction.
Also VC/B is perpendicular to the axis of the connecting rod
Apply sine and
cosine rule to find
the magnitude
and direction the
velocity of each
component
31. Problem 4
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In the reciprocating engine shown in the figure, the crank AB has a constant angular
velocity of 2000 rpm. For the crank position indicated determine
i). Angular velocity of Crank AB
ii). Angular Velocity of the Connecting Rod BC
iii). Velocity of Piston
35. References
1. Ferdinand P Beer & E.Russell Johnston “VECTOR MECHANICS FOR
ENGINEERS STATICS & Dynamics”, (Ninth Edition) Tata McGraw Hill
Education Private Limited, New Delhi.
2. Engineering Mechanics – Statics & Dynamics by S.Nagan,
M.S.Palanichamy, Tata McGraw-Hill (2001).
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36. Thank you
Any Queries contact
S.Thanga Kasi Rajan
Assistant Professor
Department of Mechanical Engineering
Kamaraj College of Engineering & Technology,
Virudhunagar – 626001.
Tamil Nadu, India
Email : stkrajan@gmail.com
02/01/2017 S.ThangaKasiRajan, stkrajan@gmail.com 36