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Measures of
Central Tendency
K.THIYAGU, Assistant Professor DoE, Central University of Kerala, Kasaragod
1
@ThiyaguSuriya
Measures of Central Tendency
The central tendency is stated as the statistical measure
that represents the single value of the entire
distribution or a dataset.
A measure of central tendency is a single value that
attempts to describe a data set by identifying the
central position within that set of data.
2
@ThiyaguSuriya
Characteristics
Measures of central
tendency are sometimes
called measures of
central location.
A single number that
represents the entire set
of data (average)
3
@ThiyaguSuriya
Central Tendency
Mean
Average Value
Median
Middle Value
Mode
Most Common Value
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@ThiyaguSuriya
5
@ThiyaguSuriya
6
@ThiyaguSuriya
Requisites of Measures of Central Tendency
3. Least affected by
Fluctuations of Sampling
There should be
sampling stability in an
average.
2. Easy to Understand
and Calculate
The value of an average
should be computed using
a method that is simple
1. Rigidly Defined
An average should be
rigid and clear.
4. Not Affected much
by Extreme Values
The value of an average should
not be affected by just one or two
very large or very small items,
5. Based on all the
Observations
An average should be
based on all the
observations,
6. Capable of further
Algebraic Treatment
A good average should have the
capability of further statistical
and mathematical calculations
7
@ThiyaguSuriya
Mean
8
@ThiyaguSuriya
Mean
The mean represents the average
value of the dataset.
It can be calculated as the
sum of all the values in the dataset
divided by the number of values.
9
@ThiyaguSuriya
Mean Symbol (X Bar)
Mean is the average of the given numbers and is calculated by
dividing the sum of given numbers by the total number of
numbers.
Mean = ( Sum of all the observations / Total number of observations )
X = (Sum of values ÷ Number of values)
X= (x1 + x2 + x3 +….+xn)/n
10
@ThiyaguSuriya
Example
What is the mean of 2, 4, 6, 8 and 10?
Solution:
First, add all the numbers.
2 + 4 + 6 + 8 + 10 = 30
Now divide by 5 (total number of observations).
Mean = 30/5 = 6
11
@ThiyaguSuriya
Example - Mean
X: 8, 6, 7, 11, 3
Sum = 35
N = 5
M = 35/5 = 7
12
@ThiyaguSuriya
Example - Mean
X
X
n n
X X X Xn
= =
+ + + +
=
+ + + + +
=
=
å 1 2 3
57 86 42 38 90 66
6
379
6
63 167
...
.
13
@ThiyaguSuriya
Let's find Ahalya’s
MEAN science test score.
97
84
73
88
100
63
97
95
86
+
783
783 ÷ 9
The mean is 87
Mean =
( Sum of all the observations /
Total number of observations )
14
@ThiyaguSuriya
Median
15
@ThiyaguSuriya
Median
The median is the middle value of the
dataset in which the dataset is arranged in
ascending order or in descending order.
The median is the middle score for a data set
arranged in order of magnitude.
16
@ThiyaguSuriya
Finding the Median
1. Arrange the scores in ascending or
descending numerical order
2. Calculate the value of [(N+1)/2]
3. round the {(N+1)/2]th item
17
@ThiyaguSuriya
18
@ThiyaguSuriya
Odd number of Observations Even number of Observations
19
@ThiyaguSuriya
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@ThiyaguSuriya
Example - Median
X: 6, 6, 7, 8, 9, 10, 11
Median = 8
Y: 1, 3, 5, 6, 8, 12
Median = 5.5
21
@ThiyaguSuriya
97
84
73 88 100
63 97
95
86
The median is 88.
Half the numbers are
less than the median.
Half the numbers are
greater than the median. 22
@ThiyaguSuriya
Mode
23
@ThiyaguSuriya
Mode
The mode represents the
frequently occurring value
in the dataset.
Sometimes the dataset may
contain multiple modes &
in some cases, it does not
contain any mode at all.
The mode is the
most frequent score
in our data set.
24
@ThiyaguSuriya
25
@ThiyaguSuriya
Mode
Score or qualitative category that occurs with the greatest frequency
Always used with nominal data, we find the most frequently occurring category
Bimodal -- Data sets that have two modes
Multimodal -- Data sets that contain more than two modes
26
@ThiyaguSuriya
Example - Mode
X: 8, 6, 7, 9, 10, 6
Mode = 6
Y: 1, 8, 12, 3, 8, 5, 6
Mode = 8
Can have more than one mode
Z: 1, 2, 2, 8, 10, 5, 5, 6
Mode = 2 and 5
27
@ThiyaguSuriya
97
84
73 88 100
63 97
95
86
The value 97 appears twice.
All other numbers appear just once.
97 is the MODE 28
@ThiyaguSuriya
A Hint for remembering the MODE…
The first two letters give you a hint…
MOde
Most Often
29
@ThiyaguSuriya
Which set of data has ONE MODE?
9, 11, 16, 8, 16
9, 11, 16, 6, 7, 17, 18
18, 7, 10, 7, 18
A
C
B
30
@ThiyaguSuriya
Which set of data has NO MODE?
13, 12, 12, 11, 12
9, 11, 16, 6, 7, 17, 18
18, 7, 10, 7, 18
A
C
B
31
@ThiyaguSuriya
Which set of data has MORE THAN ONE MODE?
9, 11, 16, 8, 16
9, 11, 16, 6, 7, 17, 18
18, 7, 10, 7, 18
A
C
B
32
@ThiyaguSuriya
GROUPED
DATA
33
@ThiyaguSuriya
x = f1x1 + f2x2 + …. + fnxn/f1 + f2+… + fn
Mean = ∑(fi.xi)/∑fi
Mean = ∑(f.x)/∑N
Mean
34
@ThiyaguSuriya
Mean
Midpoint (X) CI f f X
95.5 91-100 5 477.5
85.5 81-90 10 855
75.5 71-80 15 1132.5
65.5 61-70 10 655
55.5 51-60 6 333
45.5 41-50 3 136.5
35.5 31-40 1 35.5
N = 50 fX =3625
S
N
fX
Mean
S
=
M = 3625/50 = 72.5
35
@ThiyaguSuriya
Direct Method for Calculating Mean
Step 1: For each class, find the Midpoint / class mark xi, as
x=1/2(lower limit + upper limit)
Step 2: Calculate fi.xi for each i.
Step 3: Use the formula Mean = ∑(fi.xi)/∑fi.
Class Interval 0-10 10-20 20-30 30-40 40-50
Frequency 12 16 6 7 9
Example: Find the mean of the following data
36
@ThiyaguSuriya
Class
Interval
Frequency
fi
Class
Mark xi
( fi.xi )
0-10 12 5 60
10-20 16 15 240
20-30 6 25 150
30-40 7 35 245
40-50 9 45 405
∑fi=50 ∑fi.xi=1100
Mean
N
fX
Mean
S
=
Mean = ∑(fi.xi)/∑fi = 1100/50 = 22
37
@ThiyaguSuriya
38
@ThiyaguSuriya
Merits of Arithmetic Mean
Simple to understand
Easy to compute,
Capable of further mathematical treatment,
Calculated based on all the items of the series,
It gives the value which balances the either side,
It can be calculated even if some values of the series are missing.
It is least affected by fluctuations in sampling.
39
@ThiyaguSuriya
Demerits of Arithmetic Mean
Extreme Items Have
Disproportionate Effect.
When Data is Vast, The
Calculations Become
Tedious.
In the case of Open-
ended Classes, the
mean can only be
calculated by making
some assumptions.
IT Is Not Representative
If Series Is
Asymmetrical.
40
@ThiyaguSuriya
Median
41
@ThiyaguSuriya
Median
CCI / ECI CI f CF
90.5 - 100.5 91-100 5 50
80.5 – 90.5 81-90 10 45
70.5 – 80.5 71-80 15 35
60.5 – 70.5 61-70 10 20
50.5 – 60.5 51-60 6 10
40.5 – 50.5 41-50 3 4
30.5 – 40.5 31-40 1 1
N = 50
Locate the Median Class = N / 2 = 50 / 2 = 25
42
@ThiyaguSuriya
MEDIAN
ECI/ CCI CI f cf
55.5-60.5 56-60 6 60
50.5-55.5 51-55 9 54
45.5-50.5 46-50 15 45
40.5 (L)-45.5 41-45 13 (f) 30
35.5-40.5 36-40 10 17 (M)
30.5-35.5 31-35 7 7
N = 60
30
2
60
=
=
5
13
)
17
2
60
(
5
.
40 ´
-
+
=
c
f
m
N
L ´
-
+
)
2
(
LOCATION OF THE
MEDIAN CLASS
MEDIAN=
43
@ThiyaguSuriya
Merits of Median
Easy to calculate,
Can be calculated even if the data is incomplete,
It is unaffected in case of asymmetrical series,
Useful in case the series of qualitative characteristics is given for example beauty, intelligence etc.
Median is a reliable measure of central tendency if in a series, frequencies do not tend to be evenly
distributed.
Median can be expressed graphically.
44
@ThiyaguSuriya
Mode
Mo = xk + h{(fk – fk-1)/(2fk – fk-1 – fk+1)}
Where,
• xk = lower limit of the modal class interval.
• fk = frequency of the modal class.
• fk-1= frequency of the class preceding the modal class.
• fk+1 = frequency of the class succeeding the modal
class.
• h = width of the class interval.
45
@ThiyaguSuriya
Example : Calculate the mode for the following frequency distribution.
Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80
Frequency 5 8 7 12 28 20 10 10
Class 40-50 has the maximum frequency, which is called the modal class.
xk = 40, h = 10, fk = 28, fk-1 = 12, fk+1 = 20
Mode, Mo= xk + h{(fk – fk-1)/(2fk – fk-1 – fk+1)}
= 40 + 10{(28 – 12)/(2 × 28 – 12 – 20)}
= 46.67
Hence, mode = 46.67
46
@ThiyaguSuriya
Relationship
among mean,
median and mode,
Mode = 3(Median) – 2(Mean)
47
@ThiyaguSuriya
Type of Variable Best measure of central tendency
Nominal Mode
Ordinal Median
Interval/Ratio (not skewed) Mean
Interval/Ratio (skewed) Median
48
@ThiyaguSuriya
Thank You
49
@ThiyaguSuriya

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Measures of Central Tendency: Mean, Median and Mode

  • 1. Measures of Central Tendency K.THIYAGU, Assistant Professor DoE, Central University of Kerala, Kasaragod 1 @ThiyaguSuriya
  • 2. Measures of Central Tendency The central tendency is stated as the statistical measure that represents the single value of the entire distribution or a dataset. A measure of central tendency is a single value that attempts to describe a data set by identifying the central position within that set of data. 2 @ThiyaguSuriya
  • 3. Characteristics Measures of central tendency are sometimes called measures of central location. A single number that represents the entire set of data (average) 3 @ThiyaguSuriya
  • 4. Central Tendency Mean Average Value Median Middle Value Mode Most Common Value 4 @ThiyaguSuriya
  • 7. Requisites of Measures of Central Tendency 3. Least affected by Fluctuations of Sampling There should be sampling stability in an average. 2. Easy to Understand and Calculate The value of an average should be computed using a method that is simple 1. Rigidly Defined An average should be rigid and clear. 4. Not Affected much by Extreme Values The value of an average should not be affected by just one or two very large or very small items, 5. Based on all the Observations An average should be based on all the observations, 6. Capable of further Algebraic Treatment A good average should have the capability of further statistical and mathematical calculations 7 @ThiyaguSuriya
  • 9. Mean The mean represents the average value of the dataset. It can be calculated as the sum of all the values in the dataset divided by the number of values. 9 @ThiyaguSuriya
  • 10. Mean Symbol (X Bar) Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers. Mean = ( Sum of all the observations / Total number of observations ) X = (Sum of values ÷ Number of values) X= (x1 + x2 + x3 +….+xn)/n 10 @ThiyaguSuriya
  • 11. Example What is the mean of 2, 4, 6, 8 and 10? Solution: First, add all the numbers. 2 + 4 + 6 + 8 + 10 = 30 Now divide by 5 (total number of observations). Mean = 30/5 = 6 11 @ThiyaguSuriya
  • 12. Example - Mean X: 8, 6, 7, 11, 3 Sum = 35 N = 5 M = 35/5 = 7 12 @ThiyaguSuriya
  • 13. Example - Mean X X n n X X X Xn = = + + + + = + + + + + = = å 1 2 3 57 86 42 38 90 66 6 379 6 63 167 ... . 13 @ThiyaguSuriya
  • 14. Let's find Ahalya’s MEAN science test score. 97 84 73 88 100 63 97 95 86 + 783 783 ÷ 9 The mean is 87 Mean = ( Sum of all the observations / Total number of observations ) 14 @ThiyaguSuriya
  • 16. Median The median is the middle value of the dataset in which the dataset is arranged in ascending order or in descending order. The median is the middle score for a data set arranged in order of magnitude. 16 @ThiyaguSuriya
  • 17. Finding the Median 1. Arrange the scores in ascending or descending numerical order 2. Calculate the value of [(N+1)/2] 3. round the {(N+1)/2]th item 17 @ThiyaguSuriya
  • 19. Odd number of Observations Even number of Observations 19 @ThiyaguSuriya
  • 21. Example - Median X: 6, 6, 7, 8, 9, 10, 11 Median = 8 Y: 1, 3, 5, 6, 8, 12 Median = 5.5 21 @ThiyaguSuriya
  • 22. 97 84 73 88 100 63 97 95 86 The median is 88. Half the numbers are less than the median. Half the numbers are greater than the median. 22 @ThiyaguSuriya
  • 24. Mode The mode represents the frequently occurring value in the dataset. Sometimes the dataset may contain multiple modes & in some cases, it does not contain any mode at all. The mode is the most frequent score in our data set. 24 @ThiyaguSuriya
  • 26. Mode Score or qualitative category that occurs with the greatest frequency Always used with nominal data, we find the most frequently occurring category Bimodal -- Data sets that have two modes Multimodal -- Data sets that contain more than two modes 26 @ThiyaguSuriya
  • 27. Example - Mode X: 8, 6, 7, 9, 10, 6 Mode = 6 Y: 1, 8, 12, 3, 8, 5, 6 Mode = 8 Can have more than one mode Z: 1, 2, 2, 8, 10, 5, 5, 6 Mode = 2 and 5 27 @ThiyaguSuriya
  • 28. 97 84 73 88 100 63 97 95 86 The value 97 appears twice. All other numbers appear just once. 97 is the MODE 28 @ThiyaguSuriya
  • 29. A Hint for remembering the MODE… The first two letters give you a hint… MOde Most Often 29 @ThiyaguSuriya
  • 30. Which set of data has ONE MODE? 9, 11, 16, 8, 16 9, 11, 16, 6, 7, 17, 18 18, 7, 10, 7, 18 A C B 30 @ThiyaguSuriya
  • 31. Which set of data has NO MODE? 13, 12, 12, 11, 12 9, 11, 16, 6, 7, 17, 18 18, 7, 10, 7, 18 A C B 31 @ThiyaguSuriya
  • 32. Which set of data has MORE THAN ONE MODE? 9, 11, 16, 8, 16 9, 11, 16, 6, 7, 17, 18 18, 7, 10, 7, 18 A C B 32 @ThiyaguSuriya
  • 34. x = f1x1 + f2x2 + …. + fnxn/f1 + f2+… + fn Mean = ∑(fi.xi)/∑fi Mean = ∑(f.x)/∑N Mean 34 @ThiyaguSuriya
  • 35. Mean Midpoint (X) CI f f X 95.5 91-100 5 477.5 85.5 81-90 10 855 75.5 71-80 15 1132.5 65.5 61-70 10 655 55.5 51-60 6 333 45.5 41-50 3 136.5 35.5 31-40 1 35.5 N = 50 fX =3625 S N fX Mean S = M = 3625/50 = 72.5 35 @ThiyaguSuriya
  • 36. Direct Method for Calculating Mean Step 1: For each class, find the Midpoint / class mark xi, as x=1/2(lower limit + upper limit) Step 2: Calculate fi.xi for each i. Step 3: Use the formula Mean = ∑(fi.xi)/∑fi. Class Interval 0-10 10-20 20-30 30-40 40-50 Frequency 12 16 6 7 9 Example: Find the mean of the following data 36 @ThiyaguSuriya
  • 37. Class Interval Frequency fi Class Mark xi ( fi.xi ) 0-10 12 5 60 10-20 16 15 240 20-30 6 25 150 30-40 7 35 245 40-50 9 45 405 ∑fi=50 ∑fi.xi=1100 Mean N fX Mean S = Mean = ∑(fi.xi)/∑fi = 1100/50 = 22 37 @ThiyaguSuriya
  • 39. Merits of Arithmetic Mean Simple to understand Easy to compute, Capable of further mathematical treatment, Calculated based on all the items of the series, It gives the value which balances the either side, It can be calculated even if some values of the series are missing. It is least affected by fluctuations in sampling. 39 @ThiyaguSuriya
  • 40. Demerits of Arithmetic Mean Extreme Items Have Disproportionate Effect. When Data is Vast, The Calculations Become Tedious. In the case of Open- ended Classes, the mean can only be calculated by making some assumptions. IT Is Not Representative If Series Is Asymmetrical. 40 @ThiyaguSuriya
  • 42. Median CCI / ECI CI f CF 90.5 - 100.5 91-100 5 50 80.5 – 90.5 81-90 10 45 70.5 – 80.5 71-80 15 35 60.5 – 70.5 61-70 10 20 50.5 – 60.5 51-60 6 10 40.5 – 50.5 41-50 3 4 30.5 – 40.5 31-40 1 1 N = 50 Locate the Median Class = N / 2 = 50 / 2 = 25 42 @ThiyaguSuriya
  • 43. MEDIAN ECI/ CCI CI f cf 55.5-60.5 56-60 6 60 50.5-55.5 51-55 9 54 45.5-50.5 46-50 15 45 40.5 (L)-45.5 41-45 13 (f) 30 35.5-40.5 36-40 10 17 (M) 30.5-35.5 31-35 7 7 N = 60 30 2 60 = = 5 13 ) 17 2 60 ( 5 . 40 ´ - + = c f m N L ´ - + ) 2 ( LOCATION OF THE MEDIAN CLASS MEDIAN= 43 @ThiyaguSuriya
  • 44. Merits of Median Easy to calculate, Can be calculated even if the data is incomplete, It is unaffected in case of asymmetrical series, Useful in case the series of qualitative characteristics is given for example beauty, intelligence etc. Median is a reliable measure of central tendency if in a series, frequencies do not tend to be evenly distributed. Median can be expressed graphically. 44 @ThiyaguSuriya
  • 45. Mode Mo = xk + h{(fk – fk-1)/(2fk – fk-1 – fk+1)} Where, • xk = lower limit of the modal class interval. • fk = frequency of the modal class. • fk-1= frequency of the class preceding the modal class. • fk+1 = frequency of the class succeeding the modal class. • h = width of the class interval. 45 @ThiyaguSuriya
  • 46. Example : Calculate the mode for the following frequency distribution. Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 Frequency 5 8 7 12 28 20 10 10 Class 40-50 has the maximum frequency, which is called the modal class. xk = 40, h = 10, fk = 28, fk-1 = 12, fk+1 = 20 Mode, Mo= xk + h{(fk – fk-1)/(2fk – fk-1 – fk+1)} = 40 + 10{(28 – 12)/(2 × 28 – 12 – 20)} = 46.67 Hence, mode = 46.67 46 @ThiyaguSuriya
  • 47. Relationship among mean, median and mode, Mode = 3(Median) – 2(Mean) 47 @ThiyaguSuriya
  • 48. Type of Variable Best measure of central tendency Nominal Mode Ordinal Median Interval/Ratio (not skewed) Mean Interval/Ratio (skewed) Median 48 @ThiyaguSuriya