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𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 =
𝑟𝐴𝐵 − 𝑟𝐴𝐶 𝑟𝐵𝐶
1 − 𝑟𝐴𝐶
2
1 − 𝑟𝐵𝐶
2
𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918
𝑟 𝐵𝐶 = −0.245
𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 =
(−0.369) − (0.918)(−0.245)
1 − 0.9182
1 − −0.245 2
𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 =
−0.1441
0.499
𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 = −0.375
𝑟 𝐴𝐵. 𝐶
𝑯 𝟎 = 𝝆 𝑨𝑩. 𝑪
𝒂𝒈𝒂𝒊𝒏𝒔𝒕
𝑯 𝟏 ≠ 𝝆 𝑨𝑩. 𝑪
≤
>
𝒕 =
𝒓 𝒑 𝒏 − 𝒗
𝟏 − 𝒓 𝒑
𝟐
rp = partial correlation computed on sample, rAB.C
n = sample size,
v = total number of variables employed in the analysis
rp
df = n – v
𝒕 =
𝒓 𝒑 𝒏 − 𝒗
𝟏 − 𝒓 𝒑
𝟐
𝒕 =
−𝟎. 𝟑𝟕𝟓 𝟏𝟎 − 𝟑
𝟏 − −𝟎. 𝟑𝟕𝟓 𝟐
=
−𝟎. 𝟗𝟗𝟐
𝟎. 𝟗𝟐𝟕
= 𝟏. 𝟔𝟗
df/
α (2 tail)
0.1 0.05 0.02 0.01
1 6.3138 12.7065 31.8193 63.6551
2 2.9200 4.3026 6.9646 9.9247
3 2.3534 3.1824 4.5407 5.8408
4 2.1319 2.7764 3.7470 4.6041
5 2.0150 2.5706 3.3650 4.0322
6 1.9432 2.4469 3.1426 3.7074
7 1.8946 2.3646 2.9980 3.4995
8 1.8595 2.3060 2.8965 3.3554
9 1.8331 2.2621 2.8214 3.2498
10 1.8124 2.2282 2.7638 3.1693
≤
≤
𝑦 = 𝛽0 + 𝛽1 𝑥
𝒚 = 𝜷 𝟎 + 𝜷 𝟏 𝒙
𝒚𝒊 = 𝜷 𝟎 + 𝜷 𝟏 𝒙𝒊+∈𝒊
yi
𝒚𝒊 = 𝜷 𝟎 + 𝜷 𝟏 𝒙𝒊+∈𝒊
X
Y
xi
𝑆𝑙𝑜𝑝𝑒 = 𝛽1
𝐼𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡
= 𝛽0
𝑂𝑏𝑠𝑒𝑟𝑣𝑒𝑑 𝑉𝑎𝑙𝑢𝑒 𝑜𝑓
𝑌 𝑓𝑜𝑟 𝑋𝑖
𝑃𝑟𝑒𝑑𝑖𝑐𝑡𝑒𝑑 𝑉𝑎𝑙𝑢𝑒 𝑜𝑓
𝑌 𝑓𝑜𝑟 𝑋𝑖
∈𝑖
𝑅𝑎𝑛𝑑𝑜𝑚 𝐸𝑟𝑟𝑜𝑟
𝑓𝑜𝑟 𝑡ℎ𝑖𝑠 𝑋𝑖 𝑣𝑎𝑙𝑢𝑒
𝛽1 =
𝑥 − 𝑥 𝑦 − 𝑦
𝑥 − 𝑥 2 =
𝑥𝑦 − 𝑛 𝑥 𝑦
𝑥2 − 𝑛 𝑥2
=
𝑥𝑦 −
𝑥 𝑦
𝑛
𝑥2 −
𝑥 2
𝑛
𝛽1 =
𝑆𝑆 𝑥𝑦
𝑆𝑆 𝑥𝑥
𝛽0 = 𝑦 − 𝛽1 𝑥 =
𝑦
𝑛
− 𝛽1
𝑥
𝑛
x y x2 xy
1 4 1 4
3 2 9 6
4 1 16 4
5 0 25 0
8 0 64 0
21 7 115 14
𝛽1 =
𝑥𝑦 −
𝑥 𝑦
𝑛
𝑥2 −
𝑥 2
𝑛
=
14 −
21 ∗ 7
5
115 −
21 2
5
=
−15.4
26.8
= −0.575
𝛽0 =
𝑦
𝑛
− 𝛽1
𝑥
𝑛
=
7
5
− −0.575
21
7
= 3.81
𝒚 = 𝟑. 𝟖𝟏 − 𝟎. 𝟓𝟕𝟓𝒙
𝑨𝒄𝒂𝒅𝒆𝒎𝒊𝒄 𝑨𝒄𝒉𝒊𝒆𝒗𝒆𝒎𝒆𝒏𝒕 = 𝜷 𝟎 + 𝜷 𝟏 × 𝑰𝒏𝒕𝒆𝒍𝒍𝒊𝒈𝒆𝒏𝒄𝒆 + ∈ 𝟏
𝑨𝒏𝒙𝒊𝒆𝒕𝒚 = 𝜷 𝟎 + 𝜷 𝟏 × 𝑰𝒏𝒕𝒆𝒍𝒍𝒊𝒈𝒆𝒏𝒄𝒆 + ∈ 𝟐
∈ 𝟏 ∈ 𝟐
∈ 𝟏 ∈ 𝟐
𝑟 𝑝 = ∈ 𝟏 ∈ 𝟐
𝒂 + 𝒃 + 𝒄 + 𝒅 = 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆 𝒊𝒏 𝑫𝑽
𝒂 + 𝒃 + 𝒄 = 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆 𝒊𝒏 𝑫𝑽
𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅 𝒃𝒚 𝑰𝑽 𝟏 &𝑰𝑽 𝟐
𝒂 + 𝒄 = 𝒖𝒏𝒊𝒒𝒖𝒆𝒍𝒚 𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅
𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆
𝒃 = 𝒏𝒐𝒏 − 𝒖𝒏𝒊𝒒𝒖𝒆𝒍𝒚 𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅
𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆
𝑺𝒆𝒎𝒊𝒑𝒂𝒓𝒕𝒊𝒂𝒍 𝑪𝒐𝒓𝒓𝒆𝒍𝒂𝒕𝒊𝒐𝒏
𝑺𝒆𝒎𝒊𝒑𝒂𝒓𝒕𝒊𝒂𝒍 𝑪𝒐𝒓𝒓𝒆𝒍𝒂𝒕𝒊𝒐𝒏
𝒃𝒆𝒕𝒘𝒆𝒆𝒏 𝑰𝑽 𝟏 𝒂𝒏𝒅 𝑫𝑽
𝒂𝒇𝒕𝒆𝒓 𝒄𝒐𝒏𝒕𝒓𝒐𝒍𝒍𝒊𝒏𝒈 𝒇𝒐𝒓
𝒑𝒂𝒓𝒕𝒊𝒂𝒍𝒍𝒊𝒏𝒈 𝒐𝒖𝒕 𝒕𝒉𝒆
𝒊𝒏𝒇𝒍𝒖𝒆𝒏𝒄𝒆 𝒐𝒇 𝑰𝑽 𝟐
𝑺𝒆𝒎𝒊𝒑𝒂𝒓𝒕𝒊𝒂𝒍 𝑪𝒐𝒓𝒓𝒆𝒍𝒂𝒕𝒊𝒐𝒏
𝒃𝒆𝒕𝒘𝒆𝒆𝒏 𝑰𝑽 𝟐 𝒂𝒏𝒅 𝑫𝑽
𝒂𝒇𝒕𝒆𝒓 𝒄𝒐𝒏𝒕𝒓𝒐𝒍𝒍𝒊𝒏𝒈 𝒇𝒐𝒓
𝒑𝒂𝒓𝒕𝒊𝒂𝒍𝒍𝒊𝒏𝒈 𝒐𝒖𝒕 𝒕𝒉𝒆
𝒊𝒏𝒇𝒍𝒖𝒆𝒏𝒄𝒆 𝒐𝒇 𝑰𝑽 𝟏
𝑟 𝐵( 𝐴. 𝐶)
𝒓 𝑺𝑷 = 𝒓 𝑩 𝑨.𝑪 =
𝒓 𝑨𝑩 − 𝒓 𝑨𝑪 𝒓 𝑩𝑪
𝟏 − 𝒓 𝑨𝑪
𝟐
𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918
𝑟 𝐵𝐶 = −0.245
𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶)
=
(−0.369) − (0.918)(−0.245)
1 − 0.9182
𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶)
=
−0.1441
0.3966
𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶)
= −0.363
𝑯 𝟎: 𝝆 𝑺𝑷 = 𝟎
𝒂𝒈𝒂𝒊𝒏𝒔𝒕
𝑯 𝟏: 𝝆 𝑺𝑷 ≠ 𝟎
≤
>
𝒕 =
𝒓 𝒔𝒑 𝒏 − 𝒗
𝟏 − 𝒓 𝒔𝒑
𝟐
rp = semi-partial correlation computed on sample, rB(A.C)
n = sample size,
v = total number of variables employed in the analysis
rsp
df = n – v
𝒕 =
𝒓 𝒔𝒑 𝒏 − 𝒗
𝟏 − 𝒓 𝒔𝒑
𝟐
𝒕 =
−𝟎. 𝟑𝟔𝟑 𝟏𝟎 − 𝟑
𝟏 − −𝟎. 𝟑𝟔𝟑 𝟐
= −𝟏. 𝟎𝟑𝟐
df/
α (2 tail)
0.1 0.05 0.02 0.01
1 6.3138 12.7065 31.8193 63.6551
2 2.9200 4.3026 6.9646 9.9247
3 2.3534 3.1824 4.5407 5.8408
4 2.1319 2.7764 3.7470 4.6041
5 2.0150 2.5706 3.3650 4.0322
6 1.9432 2.4469 3.1426 3.7074
7 1.8946 2.3646 2.9980 3.4995
8 1.8595 2.3060 2.8965 3.3554
9 1.8331 2.2621 2.8214 3.2498
10 1.8124 2.2282 2.7638 3.1693
≤
≤
𝒚 = 𝜷 𝟎 + 𝜷 𝟏 𝒙+∈𝒊
∈𝒊
∈𝒊
∈𝒊
RA.BCD…k
k
𝑹 𝑨.𝑩𝑪 =
𝒓 𝑨𝑩
𝟐
+ 𝒓 𝑨𝑪
𝟐
− 𝟐𝒓 𝑨𝑩 𝒓 𝑨𝑪 𝒓 𝑩𝑪
𝟏 − 𝒓 𝑩𝑪
𝟐
R A . BC = is multiple correlation between A & linear combination of B and C
rAB = is correlation between A and B
rAC = is correlation between A and C
rBC = is correlation between B and C
𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918
𝑟 𝐵𝐶 = −0.245
𝑅 𝐴. 𝐵𝐶 =
−0.369 2 + 0.918 2 −2 −.369 .918 −.245
1 − −0.245 2
𝑅 𝐴. 𝐵𝐶 =
0.813
0.94
𝑅 𝐴. 𝐵𝐶 = 0.929
R = 0 R2 = 0
Variance = 0%
R = ±0.2 R2 = 0.04
Variance = 4%
R = ±0.4 R2 = 0.16
Variance = 16%
R = ±0.6 R2 = 0.36
Variance = 36%
R = ±0.8 R2 = 0.64
Variance = 64%
R = ±1 R2 = 1
Variance = 100%
𝑹 𝟐𝛒 𝟐
𝑹 𝟐 = 𝟏 −
𝟏 − 𝑹 𝟐
𝒏 − 𝟏
𝒏 − 𝒌 − 𝟏
𝑅2 = is adjusted value of R2
k = number of predicted variables
n = sample size
𝑹 𝟐 = 𝟏 −
𝟏 − 𝑹 𝟐
𝒏 − 𝟏
𝒏 − 𝒌 − 𝟏
= 𝟏 −
𝟏 − 𝟎. 𝟖𝟔𝟓 𝟏𝟎 − 𝟏
𝟏𝟎 − 𝟐 − 𝟏
= 𝟏 −
𝟏. 𝟐𝟏𝟕
𝟕
= 𝟎. 𝟖𝟐𝟔
𝑹 𝟐 𝑹 𝟐
𝑯 𝟎: 𝝆 𝟐 = 𝟎
𝒂𝒈𝒂𝒊𝒏𝒔𝒕
𝑯 𝟏: 𝝆 𝟐 ≠ 𝟎
≤
>
𝑭 =
𝒏 − 𝒌 − 𝟏 𝑹 𝟐
𝒌 𝟏 − 𝑹 𝟐
𝑅2
dfnumerator = k
dfdenominator = n-k-1
𝑭 =
𝟏𝟎 − 𝟐 − 𝟏 𝟎. 𝟖𝟐𝟔
𝟐(𝟏 − 𝟎. 𝟖𝟐𝟔)
𝑭 =
𝒏 − 𝒌 − 𝟏 𝑹 𝟐
𝒌 𝟏 − 𝑹 𝟐
𝑭 =
𝟓. 𝟕𝟖𝟑
𝟎. 𝟑𝟒𝟖
𝑭 = 𝟏𝟔. 𝟔𝟑𝟓
𝑑𝑓1 = 𝑘 = 2 𝑑𝑓2 = 10 − 2 − 1 = 7 𝛼 = 5%
𝐹2,7
𝐶𝑉
= 4.74
Mpc 006 - 02-03 partial and multiple correlation
Mpc 006 - 02-03 partial and multiple correlation

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Mpc 006 - 02-03 partial and multiple correlation

  • 1.
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8.
  • 9. 𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 = 𝑟𝐴𝐵 − 𝑟𝐴𝐶 𝑟𝐵𝐶 1 − 𝑟𝐴𝐶 2 1 − 𝑟𝐵𝐶 2
  • 10.
  • 11. 𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918 𝑟 𝐵𝐶 = −0.245
  • 12. 𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 = (−0.369) − (0.918)(−0.245) 1 − 0.9182 1 − −0.245 2 𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 = −0.1441 0.499 𝑟 𝑝 = 𝑟 𝐴𝐵. 𝐶 = −0.375
  • 13.
  • 14.
  • 16.
  • 17.
  • 18. 𝑯 𝟎 = 𝝆 𝑨𝑩. 𝑪 𝒂𝒈𝒂𝒊𝒏𝒔𝒕 𝑯 𝟏 ≠ 𝝆 𝑨𝑩. 𝑪
  • 19. ≤ >
  • 20. 𝒕 = 𝒓 𝒑 𝒏 − 𝒗 𝟏 − 𝒓 𝒑 𝟐 rp = partial correlation computed on sample, rAB.C n = sample size, v = total number of variables employed in the analysis
  • 21. rp df = n – v
  • 22. 𝒕 = 𝒓 𝒑 𝒏 − 𝒗 𝟏 − 𝒓 𝒑 𝟐 𝒕 = −𝟎. 𝟑𝟕𝟓 𝟏𝟎 − 𝟑 𝟏 − −𝟎. 𝟑𝟕𝟓 𝟐 = −𝟎. 𝟗𝟗𝟐 𝟎. 𝟗𝟐𝟕 = 𝟏. 𝟔𝟗
  • 23. df/ α (2 tail) 0.1 0.05 0.02 0.01 1 6.3138 12.7065 31.8193 63.6551 2 2.9200 4.3026 6.9646 9.9247 3 2.3534 3.1824 4.5407 5.8408 4 2.1319 2.7764 3.7470 4.6041 5 2.0150 2.5706 3.3650 4.0322 6 1.9432 2.4469 3.1426 3.7074 7 1.8946 2.3646 2.9980 3.4995 8 1.8595 2.3060 2.8965 3.3554 9 1.8331 2.2621 2.8214 3.2498 10 1.8124 2.2282 2.7638 3.1693
  • 25.
  • 26.
  • 27.
  • 28.
  • 29.
  • 30.
  • 31.
  • 32.
  • 33.
  • 34. 𝑦 = 𝛽0 + 𝛽1 𝑥
  • 35. 𝒚 = 𝜷 𝟎 + 𝜷 𝟏 𝒙
  • 36. 𝒚𝒊 = 𝜷 𝟎 + 𝜷 𝟏 𝒙𝒊+∈𝒊 yi
  • 37. 𝒚𝒊 = 𝜷 𝟎 + 𝜷 𝟏 𝒙𝒊+∈𝒊 X Y xi 𝑆𝑙𝑜𝑝𝑒 = 𝛽1 𝐼𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡 = 𝛽0 𝑂𝑏𝑠𝑒𝑟𝑣𝑒𝑑 𝑉𝑎𝑙𝑢𝑒 𝑜𝑓 𝑌 𝑓𝑜𝑟 𝑋𝑖 𝑃𝑟𝑒𝑑𝑖𝑐𝑡𝑒𝑑 𝑉𝑎𝑙𝑢𝑒 𝑜𝑓 𝑌 𝑓𝑜𝑟 𝑋𝑖 ∈𝑖 𝑅𝑎𝑛𝑑𝑜𝑚 𝐸𝑟𝑟𝑜𝑟 𝑓𝑜𝑟 𝑡ℎ𝑖𝑠 𝑋𝑖 𝑣𝑎𝑙𝑢𝑒
  • 38. 𝛽1 = 𝑥 − 𝑥 𝑦 − 𝑦 𝑥 − 𝑥 2 = 𝑥𝑦 − 𝑛 𝑥 𝑦 𝑥2 − 𝑛 𝑥2 = 𝑥𝑦 − 𝑥 𝑦 𝑛 𝑥2 − 𝑥 2 𝑛 𝛽1 = 𝑆𝑆 𝑥𝑦 𝑆𝑆 𝑥𝑥 𝛽0 = 𝑦 − 𝛽1 𝑥 = 𝑦 𝑛 − 𝛽1 𝑥 𝑛
  • 39. x y x2 xy 1 4 1 4 3 2 9 6 4 1 16 4 5 0 25 0 8 0 64 0 21 7 115 14
  • 40. 𝛽1 = 𝑥𝑦 − 𝑥 𝑦 𝑛 𝑥2 − 𝑥 2 𝑛 = 14 − 21 ∗ 7 5 115 − 21 2 5 = −15.4 26.8 = −0.575 𝛽0 = 𝑦 𝑛 − 𝛽1 𝑥 𝑛 = 7 5 − −0.575 21 7 = 3.81 𝒚 = 𝟑. 𝟖𝟏 − 𝟎. 𝟓𝟕𝟓𝒙
  • 41.
  • 42. 𝑨𝒄𝒂𝒅𝒆𝒎𝒊𝒄 𝑨𝒄𝒉𝒊𝒆𝒗𝒆𝒎𝒆𝒏𝒕 = 𝜷 𝟎 + 𝜷 𝟏 × 𝑰𝒏𝒕𝒆𝒍𝒍𝒊𝒈𝒆𝒏𝒄𝒆 + ∈ 𝟏 𝑨𝒏𝒙𝒊𝒆𝒕𝒚 = 𝜷 𝟎 + 𝜷 𝟏 × 𝑰𝒏𝒕𝒆𝒍𝒍𝒊𝒈𝒆𝒏𝒄𝒆 + ∈ 𝟐
  • 43. ∈ 𝟏 ∈ 𝟐
  • 44. ∈ 𝟏 ∈ 𝟐 𝑟 𝑝 = ∈ 𝟏 ∈ 𝟐
  • 45.
  • 46.
  • 47.
  • 48. 𝒂 + 𝒃 + 𝒄 + 𝒅 = 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆 𝒊𝒏 𝑫𝑽 𝒂 + 𝒃 + 𝒄 = 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆 𝒊𝒏 𝑫𝑽 𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅 𝒃𝒚 𝑰𝑽 𝟏 &𝑰𝑽 𝟐 𝒂 + 𝒄 = 𝒖𝒏𝒊𝒒𝒖𝒆𝒍𝒚 𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆 𝒃 = 𝒏𝒐𝒏 − 𝒖𝒏𝒊𝒒𝒖𝒆𝒍𝒚 𝒆𝒙𝒑𝒍𝒂𝒊𝒏𝒆𝒅 𝒗𝒂𝒓𝒊𝒂𝒏𝒄𝒆
  • 50. 𝑺𝒆𝒎𝒊𝒑𝒂𝒓𝒕𝒊𝒂𝒍 𝑪𝒐𝒓𝒓𝒆𝒍𝒂𝒕𝒊𝒐𝒏 𝒃𝒆𝒕𝒘𝒆𝒆𝒏 𝑰𝑽 𝟏 𝒂𝒏𝒅 𝑫𝑽 𝒂𝒇𝒕𝒆𝒓 𝒄𝒐𝒏𝒕𝒓𝒐𝒍𝒍𝒊𝒏𝒈 𝒇𝒐𝒓 𝒑𝒂𝒓𝒕𝒊𝒂𝒍𝒍𝒊𝒏𝒈 𝒐𝒖𝒕 𝒕𝒉𝒆 𝒊𝒏𝒇𝒍𝒖𝒆𝒏𝒄𝒆 𝒐𝒇 𝑰𝑽 𝟐
  • 51. 𝑺𝒆𝒎𝒊𝒑𝒂𝒓𝒕𝒊𝒂𝒍 𝑪𝒐𝒓𝒓𝒆𝒍𝒂𝒕𝒊𝒐𝒏 𝒃𝒆𝒕𝒘𝒆𝒆𝒏 𝑰𝑽 𝟐 𝒂𝒏𝒅 𝑫𝑽 𝒂𝒇𝒕𝒆𝒓 𝒄𝒐𝒏𝒕𝒓𝒐𝒍𝒍𝒊𝒏𝒈 𝒇𝒐𝒓 𝒑𝒂𝒓𝒕𝒊𝒂𝒍𝒍𝒊𝒏𝒈 𝒐𝒖𝒕 𝒕𝒉𝒆 𝒊𝒏𝒇𝒍𝒖𝒆𝒏𝒄𝒆 𝒐𝒇 𝑰𝑽 𝟏
  • 52.
  • 53.
  • 54.
  • 55.
  • 57. 𝒓 𝑺𝑷 = 𝒓 𝑩 𝑨.𝑪 = 𝒓 𝑨𝑩 − 𝒓 𝑨𝑪 𝒓 𝑩𝑪 𝟏 − 𝒓 𝑨𝑪 𝟐
  • 58.
  • 59. 𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918 𝑟 𝐵𝐶 = −0.245
  • 60. 𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶) = (−0.369) − (0.918)(−0.245) 1 − 0.9182 𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶) = −0.1441 0.3966 𝑟 𝑆𝑃 = 𝑟 𝐵( 𝐴. 𝐶) = −0.363
  • 61.
  • 62.
  • 63.
  • 64. 𝑯 𝟎: 𝝆 𝑺𝑷 = 𝟎 𝒂𝒈𝒂𝒊𝒏𝒔𝒕 𝑯 𝟏: 𝝆 𝑺𝑷 ≠ 𝟎
  • 65. ≤ >
  • 66. 𝒕 = 𝒓 𝒔𝒑 𝒏 − 𝒗 𝟏 − 𝒓 𝒔𝒑 𝟐 rp = semi-partial correlation computed on sample, rB(A.C) n = sample size, v = total number of variables employed in the analysis
  • 67. rsp df = n – v
  • 68. 𝒕 = 𝒓 𝒔𝒑 𝒏 − 𝒗 𝟏 − 𝒓 𝒔𝒑 𝟐 𝒕 = −𝟎. 𝟑𝟔𝟑 𝟏𝟎 − 𝟑 𝟏 − −𝟎. 𝟑𝟔𝟑 𝟐 = −𝟏. 𝟎𝟑𝟐
  • 69. df/ α (2 tail) 0.1 0.05 0.02 0.01 1 6.3138 12.7065 31.8193 63.6551 2 2.9200 4.3026 6.9646 9.9247 3 2.3534 3.1824 4.5407 5.8408 4 2.1319 2.7764 3.7470 4.6041 5 2.0150 2.5706 3.3650 4.0322 6 1.9432 2.4469 3.1426 3.7074 7 1.8946 2.3646 2.9980 3.4995 8 1.8595 2.3060 2.8965 3.3554 9 1.8331 2.2621 2.8214 3.2498 10 1.8124 2.2282 2.7638 3.1693
  • 71.
  • 72. 𝒚 = 𝜷 𝟎 + 𝜷 𝟏 𝒙+∈𝒊
  • 76.
  • 77.
  • 78.
  • 80. 𝑹 𝑨.𝑩𝑪 = 𝒓 𝑨𝑩 𝟐 + 𝒓 𝑨𝑪 𝟐 − 𝟐𝒓 𝑨𝑩 𝒓 𝑨𝑪 𝒓 𝑩𝑪 𝟏 − 𝒓 𝑩𝑪 𝟐 R A . BC = is multiple correlation between A & linear combination of B and C rAB = is correlation between A and B rAC = is correlation between A and C rBC = is correlation between B and C
  • 81.
  • 82. 𝑟 𝐴𝐵 = −0.369 𝑟 𝐴𝐶 = 0.918 𝑟 𝐵𝐶 = −0.245
  • 83. 𝑅 𝐴. 𝐵𝐶 = −0.369 2 + 0.918 2 −2 −.369 .918 −.245 1 − −0.245 2 𝑅 𝐴. 𝐵𝐶 = 0.813 0.94 𝑅 𝐴. 𝐵𝐶 = 0.929
  • 84.
  • 85.
  • 86.
  • 87. R = 0 R2 = 0 Variance = 0% R = ±0.2 R2 = 0.04 Variance = 4% R = ±0.4 R2 = 0.16 Variance = 16%
  • 88. R = ±0.6 R2 = 0.36 Variance = 36% R = ±0.8 R2 = 0.64 Variance = 64% R = ±1 R2 = 1 Variance = 100%
  • 90.
  • 91. 𝑹 𝟐 = 𝟏 − 𝟏 − 𝑹 𝟐 𝒏 − 𝟏 𝒏 − 𝒌 − 𝟏 𝑅2 = is adjusted value of R2 k = number of predicted variables n = sample size
  • 92. 𝑹 𝟐 = 𝟏 − 𝟏 − 𝑹 𝟐 𝒏 − 𝟏 𝒏 − 𝒌 − 𝟏 = 𝟏 − 𝟏 − 𝟎. 𝟖𝟔𝟓 𝟏𝟎 − 𝟏 𝟏𝟎 − 𝟐 − 𝟏 = 𝟏 − 𝟏. 𝟐𝟏𝟕 𝟕 = 𝟎. 𝟖𝟐𝟔
  • 94.
  • 95.
  • 96. 𝑯 𝟎: 𝝆 𝟐 = 𝟎 𝒂𝒈𝒂𝒊𝒏𝒔𝒕 𝑯 𝟏: 𝝆 𝟐 ≠ 𝟎
  • 97. ≤ >
  • 98. 𝑭 = 𝒏 − 𝒌 − 𝟏 𝑹 𝟐 𝒌 𝟏 − 𝑹 𝟐 𝑅2
  • 100. 𝑭 = 𝟏𝟎 − 𝟐 − 𝟏 𝟎. 𝟖𝟐𝟔 𝟐(𝟏 − 𝟎. 𝟖𝟐𝟔) 𝑭 = 𝒏 − 𝒌 − 𝟏 𝑹 𝟐 𝒌 𝟏 − 𝑹 𝟐 𝑭 = 𝟓. 𝟕𝟖𝟑 𝟎. 𝟑𝟒𝟖 𝑭 = 𝟏𝟔. 𝟔𝟑𝟓
  • 101. 𝑑𝑓1 = 𝑘 = 2 𝑑𝑓2 = 10 − 2 − 1 = 7 𝛼 = 5% 𝐹2,7 𝐶𝑉 = 4.74