This document discusses the nomenclature and formation of inorganic compounds. It focuses on binary compounds such as oxides, hydrates, hydroxides, acids and salts formed from metals and nonmetals. Specifically, it describes the naming and formation of haloid salts through the reaction of metals with nonmetallic halogens such as fluorine, chlorine and bromine. Examples of naming haloid salts using IUPAC nomenclature rules and balancing chemical equations for their formation are provided.

1. Names, formulas and uses of
inorganic compunds
Nomenclature

2. IUPAC
• The international union of pure and applied
chemistry.

3. • Compounds
– Binary
• Oxides
• Anhydride
• Hydrates
• Hydroxide
• Acids
• Salts
– Ternary
• Oxiacids
• Oxisal

4. Binary
• Oxides = A metal + Oxygen
• Anhydride = Non metal + oxygen
• Hydrates = Metal + hydrogen
• Hydroxide = hydrogen + Non metal
• Salts = Metal and Non Metal

5. Haloid Salts Tutorial
, where:
The non metal work with negative valence and the metal,
with positive valences. Observing the table of valences,
specifically the nonmetals, you will find that single nine
elements work with negative valence and they are
distributed in the groupsVA (P y N; con -3), VIA (S, Se
and Te; -2) and VIIA (F, Cl, Br and I; -1).
All of them are combined with any metal of the table and
form the called binary salts or haloids.
Metal and No Metal
Haloid Salts are formed by:

6. Then, if we link a metal with each one of the previous
elements and using the same process to cross the valences,
we will obtain the chemical formulas of some haloid Salts:
Example:
Au+1
F-1
AuF
Au+1
S-2
Au2S
Au+1
P-3
Au3P
In the formula,:
Which is the similarity that has the haloid salts with oxides
and hydrures?
Perfect! It is indeed the metal presence and is this one,
the same similarity in nomenclature. In order to name them,
we will use the nomenclature:

7. * _________ure of _________ _________
Root of no metal Metal Name Metal Valence
in Roman number
(It remember that a single Roman number is placed if the metal has 2 valences).
If we retake the formula that already we elaborated in
the previous section and we applied the nomenclature rule, we
will obtain the name of the next three:
Au+1
with F-1
AuF Fluorure of Gold I
Au+1
with S-2
Au2S Sulfure of Gold I
Au+1
with P-3
Au3P Fosfure of Gold I
Now we will see the obtaining reaction of haloid Salts:

8. Metal + No metal haloid Salt
Example:
Sn+4
+ Cl2 SnCl4
Remember that applying the reaction to form the
compound, there are not taken into account diatomic
molecules. The nonmetals that we used to form haloid salts,
are diatomic: Nitrogen, Phosphorus, Fluor, Chlorine, Bromine
and Iodine.
This means that you will put two of them like single subscript
when placing them like reagents, as well as we did it in the
previous example.
Retaking the example, now we will have
in order to conclude the exercise:
balance
by trial

9. Sn+4
+ Cl2 SnCl4
Observe that to equal the amount of masses, you must add a
coefficient in chlorine:
Sn+4
+ 2Cl2 SnCl4
As you see, the rules of nomenclature for the different
functions are very similar to each other, overall when we hand
functions that contain metals, we always named them equal.
In order to consolidate the subject, now solve the next
exercises:

10. I. make the formula corresponding to each compound:
1)Bromide of Silver 2) chlorure of Bismuth V.
3) manganese of Teluro III. 4) Selenuro of calcium
5) Nitride of iron II
II. write down the name corresponding to each chemical
formula:
1) CoP 4) SrF2
2) ZnTe 5) Cr3N2
3) KI
III. complete and balance the following reactions:
1) Pb+4
+ Br2 3) Ba + P2
2) Hg+1
+ S