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Derivatives of Trigonometric Functions
Derivatives of Trigonometric Functions
In part 1, we showed that:
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Let’s now find the derivative of f (x) = cos x.
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Let’s now find the derivative of f (x) = cos x.
There are two ways to proceed:
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Let’s now find the derivative of f (x) = cos x.
There are two ways to proceed:
1. Apply the definition of the derivative.
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Let’s now find the derivative of f (x) = cos x.
There are two ways to proceed:
1. Apply the definition of the derivative.
2. Apply the chain rule.
Derivatives of Trigonometric Functions
In part 1, we showed that:
d
dx
(sin x) = cos x
Let’s now find the derivative of f (x) = cos x.
There are two ways to proceed:
1. Apply the definition of the derivative.
2. Apply the chain rule.
Derivatives of Trigonometric Functions
So, let’s consider the identity:
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
.
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) .
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
2 sin x cos x
2 1 − sin2
x
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
¡2 sin x cos x
¡2 1 − sin2
x
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
¡2 sin x cos x
¡2$$$$$$$Xcos x
1 − sin2
x
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
¡2 sin x cos x
¡2$$$$$$$Xcos x
1 − sin2
x
= −
sin x cos x
cos x
=
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
¡2 sin x cos x
¡2$$$$$$$Xcos x
1 − sin2
x
= −
sin x$$$cos x
$$$cos x
=
Derivatives of Trigonometric Functions
So, let’s consider the identity:
f (x) = cos x = 1 − sin2
x
We can apply the chain rule directly:
f (x) =
1
2
.
1
1 − sin2
x
. (−2 sin x) . cos x
= −
¡2 sin x cos x
¡2$$$$$$$Xcos x
1 − sin2
x
= −
sin x$$$cos x
$$$cos x
= − sin x
= −
sin x$$$cos x
$$$cos x
= − sin x
Derivatives of Trigonometric Functions
So, we have that:
Derivatives of Trigonometric Functions
So, we have that:
d
dx
(cos x) = − sin x
Derivatives of Trigonometric Functions
So, we have that:
d
dx
(cos x) = − sin x
Derivatives of Trigonometric Functions
So, we have that:
d
dx
(cos x) = − sin x
We can now solve some problems.
Example 1
Let’s find the derivative of the function:
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
We’ve already found this derivative when we calculated the
derivative of cos x.
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
We’ve already found this derivative when we calculated the
derivative of cos x.
We apply the chain rule:
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
We’ve already found this derivative when we calculated the
derivative of cos x.
We apply the chain rule:
f (x) = 2 sin x
d
dx
(sin x)
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
We’ve already found this derivative when we calculated the
derivative of cos x.
We apply the chain rule:
f (x) = 2 sin x
d
dx
(sin x) = 2 sin x cos x
Example 1
Let’s find the derivative of the function:
f (x) = sin2
x
We’ve already found this derivative when we calculated the
derivative of cos x.
We apply the chain rule:
f (x) = 2 sin x
d
dx
(sin x) = 2 sin x cos x
Example 2
Example 2
f (x) = tan x
Example 2
f (x) = tan x
Here we can use the product rule:
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) =
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x.
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
d
dx
(cos x) +
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
d
dx
(cos x) + cos x. (cos x)−1
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨
¨¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨¨
¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
=
sin2
x.
cos2 x
+
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨¨
¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
=
sin2
x.
cos2 x
+
cos x
cos x
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨¨
¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
=
sin2
x.
cos2 x
+
&
&
&b
1
cos x
cos x
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨¨
¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
=
sin2
x.
cos2 x
+
&
&
&b
1
cos x
cos x
= tan2
x + 1
Example 2
f (x) = tan x
Here we can use the product rule:
f (x) =
sin x
cos x
=
f (x) =
sin x
cos x
= sin x. (cos x)−1
f (x) = sin x. (cos x)−1
+
d
dx
(sin x) . (cos x)−1
= sin x.(−1). (cos x)−2
.
¨¨¨
¨¨¨B− sin x
d
dx
(cos x) + cos x. (cos x)−1
=
sin2
x.
cos2 x
+
&
&
&b
1
cos x
cos x
= tan2
x + 1
Derivatives of Trigonometric Functions, Part 2

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Derivatives of Trigonometric Functions, Part 2

  • 1.
  • 2.
  • 4. Derivatives of Trigonometric Functions In part 1, we showed that:
  • 5. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x
  • 6. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x Let’s now find the derivative of f (x) = cos x.
  • 7. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x Let’s now find the derivative of f (x) = cos x. There are two ways to proceed:
  • 8. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x Let’s now find the derivative of f (x) = cos x. There are two ways to proceed: 1. Apply the definition of the derivative.
  • 9. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x Let’s now find the derivative of f (x) = cos x. There are two ways to proceed: 1. Apply the definition of the derivative. 2. Apply the chain rule.
  • 10. Derivatives of Trigonometric Functions In part 1, we showed that: d dx (sin x) = cos x Let’s now find the derivative of f (x) = cos x. There are two ways to proceed: 1. Apply the definition of the derivative. 2. Apply the chain rule.
  • 11. Derivatives of Trigonometric Functions So, let’s consider the identity:
  • 12. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x
  • 13. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly:
  • 14. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 .
  • 15. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x .
  • 16. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) .
  • 17. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x
  • 18. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − 2 sin x cos x 2 1 − sin2 x
  • 19. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − ¡2 sin x cos x ¡2 1 − sin2 x
  • 20. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − ¡2 sin x cos x ¡2$$$$$$$Xcos x 1 − sin2 x
  • 21. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − ¡2 sin x cos x ¡2$$$$$$$Xcos x 1 − sin2 x = − sin x cos x cos x =
  • 22. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − ¡2 sin x cos x ¡2$$$$$$$Xcos x 1 − sin2 x = − sin x$$$cos x $$$cos x =
  • 23. Derivatives of Trigonometric Functions So, let’s consider the identity: f (x) = cos x = 1 − sin2 x We can apply the chain rule directly: f (x) = 1 2 . 1 1 − sin2 x . (−2 sin x) . cos x = − ¡2 sin x cos x ¡2$$$$$$$Xcos x 1 − sin2 x = − sin x$$$cos x $$$cos x = − sin x = − sin x$$$cos x $$$cos x = − sin x
  • 24. Derivatives of Trigonometric Functions So, we have that:
  • 25. Derivatives of Trigonometric Functions So, we have that: d dx (cos x) = − sin x
  • 26. Derivatives of Trigonometric Functions So, we have that: d dx (cos x) = − sin x
  • 27. Derivatives of Trigonometric Functions So, we have that: d dx (cos x) = − sin x We can now solve some problems.
  • 28. Example 1 Let’s find the derivative of the function:
  • 29. Example 1 Let’s find the derivative of the function: f (x) = sin2 x
  • 30. Example 1 Let’s find the derivative of the function: f (x) = sin2 x We’ve already found this derivative when we calculated the derivative of cos x.
  • 31. Example 1 Let’s find the derivative of the function: f (x) = sin2 x We’ve already found this derivative when we calculated the derivative of cos x. We apply the chain rule:
  • 32. Example 1 Let’s find the derivative of the function: f (x) = sin2 x We’ve already found this derivative when we calculated the derivative of cos x. We apply the chain rule: f (x) = 2 sin x d dx (sin x)
  • 33. Example 1 Let’s find the derivative of the function: f (x) = sin2 x We’ve already found this derivative when we calculated the derivative of cos x. We apply the chain rule: f (x) = 2 sin x d dx (sin x) = 2 sin x cos x
  • 34. Example 1 Let’s find the derivative of the function: f (x) = sin2 x We’ve already found this derivative when we calculated the derivative of cos x. We apply the chain rule: f (x) = 2 sin x d dx (sin x) = 2 sin x cos x
  • 36. Example 2 f (x) = tan x
  • 37. Example 2 f (x) = tan x Here we can use the product rule:
  • 38. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x =
  • 39. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1
  • 40. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) =
  • 41. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x.
  • 42. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 +
  • 43. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1
  • 44. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.
  • 45. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . d dx (cos x) +
  • 46. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . d dx (cos x) + cos x. (cos x)−1
  • 47. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨ ¨¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1
  • 48. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨¨ ¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1 = sin2 x. cos2 x +
  • 49. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨¨ ¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1 = sin2 x. cos2 x + cos x cos x
  • 50. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨¨ ¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1 = sin2 x. cos2 x + & & &b 1 cos x cos x
  • 51. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨¨ ¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1 = sin2 x. cos2 x + & & &b 1 cos x cos x = tan2 x + 1
  • 52. Example 2 f (x) = tan x Here we can use the product rule: f (x) = sin x cos x = f (x) = sin x cos x = sin x. (cos x)−1 f (x) = sin x. (cos x)−1 + d dx (sin x) . (cos x)−1 = sin x.(−1). (cos x)−2 . ¨¨¨ ¨¨¨B− sin x d dx (cos x) + cos x. (cos x)−1 = sin2 x. cos2 x + & & &b 1 cos x cos x = tan2 x + 1