DECODERS
PRESENTED BY
GHOLAMREZA KAKAMANSHADI
PANJAB UNIVERSITY, CHD, INDIA
JUL,2013
Definition:
• An important part of the system which selects
the cells to be read from and written into is the
decoder.
– Accepts a value and decodes it
• Output corresponds to value of n inputs
• It also is called many-to-one decoder, a
decoder matrix or simply a decoder.
A decoder consists of:
• Inputs (n)
• Outputs (2n , numbered from 0  2n - 1)
• Selectors / Enable (active high or active low)
• The decoder has the characteristic that for each
of the possible 2 𝑛
binary input numbers which
can be taken by the n input cells, the matrix
will have a unique one of its 2 𝑛
output lines
selected.
Input
n=2
Output
22=4
Input
n=3
Output
23
=8
n
Input
𝟐 𝒏
Out putDecoder
n is the number of input flip-flop
being decoded.
Number of AND gates is equal to
number of output lines
Q0 = S1 S0
Q1 = S1 S0
Q2 = S1 S0
Q3 = S1 S0
Input
n=2
Output
22
=4
What a decoder does
• A n-to-2
n
decoder takes an n-bit input and produces 2
n
outputs. The
n inputs represent a binary number that determines which of the 2
n
outputs is uniquely true.
• A 2-to-4 decoder operates according to the following truth table.
– The 2-bit input is called S1S0, and the four outputs are Q0-Q3.
– If the input is the binary number i, then output Qi is uniquely true.
• For example, if the input S1 S0 = 10, then output Q2 is true, and Q0,
Q1, Q3 are all false.
• This circuit “decodes” a binary number into a “one-of-four” code.
S1 S0 Q0 Q1 Q2 Q3
0 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
1 1 0 0 0 1
How can you build a 2-to-4 decoder?
• Follow the design procedures from last time! We have a truth
table, so we can write equations for each of the four outputs
(Q0-Q3), based on the two inputs (S0-S1).
• Here are the equations:
S1 S0 Q0 Q1 Q2 Q3
0 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
1 1 0 0 0 1
Q0 = S1 S0
Q1 = S1 S0
Q2 = S1 S0
Q3 = S1 S0
A picture of a 2-to-4 decoder
S1 S0 Q0 Q1 Q2 Q3
0 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
1 1 0 0 0 1
2-to-4 Decoder
Enable inputs
• Many devices have an additional enable input, which is used to
“activate” or “deactivate” the device.
• For a decoder,
– EN=1 activates the decoder, so it behaves as specified earlier. Exactly
one of the outputs will be 1.
– EN=0 “deactivates” the decoder. By convention, that means all of the
decoder’s outputs are 0.
• We can include this additional input in the decoder’s truth table:
EN S1 S0 Q0 Q1 Q2 Q3
0 0 0 0 0 0 0
0 0 1 0 0 0 0
0 1 0 0 0 0 0
0 1 1 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
• In this table, note that whenever
EN=0, the outputs are always 0,
regardless of inputs S1 and S0.
• We can abbreviate the table by
writing x’s in the input columns
for S1 and S0.
EN S1 S0 Q0 Q1 Q2 Q3
0 0 0 0 0 0 0
0 0 1 0 0 0 0
0 1 0 0 0 0 0
0 1 1 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
EN S1 S0 Q0 Q1 Q2 Q3
0 x x 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
A 3-to-8 decoder
• Larger decoders are similar. Here is a 3-to-8
decoder.
– The block symbol is on the right.
– A truth table (without EN) is below.
– Output equations are at the bottom right.
• Again, only one output is true for any input
combination.
S2 S1 S0 Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7
0 0 0 1 0 0 0 0 0 0 0
0 0 1 0 1 0 0 0 0 0 0
0 1 0 0 0 1 0 0 0 0 0
0 1 1 0 0 0 1 0 0 0 0
1 0 0 0 0 0 0 1 0 0 0
1 0 1 0 0 0 0 0 1 0 0
1 1 0 0 0 0 0 0 0 1 0
1 1 1 0 0 0 0 0 0 0 1
Q0 = S2’ S1’ S0’
Q1 = S2’ S1’ S0
Q2 = S2’ S1 S0’
Q3 = S2’ S1 S0
Q4 = S2 S1’ S0’
Q5 = S2 S1’ S0
Q6 = S2 S1 S0’
Q7 = S2 S1 S0
Design a 3-to-8 decoderAssignment
• The decoder is often constructed by using
diodes or transistors in the AND gates.
• The number of diodes used in each AND gate
is equal to the number of input to each and
gate. The number of AND gates is equal to
number of output (2 𝑛
).
So total number of diodes is: n* 2 𝑛
• Number of diodes required increases sharply
with number of inputs to the network.
Example: To decode an eight flip-flop register we would
require 8*28
= 2048 diodes if the decoder were constructed
in this manner.
• Several types of structures are often used in
building of decoder networks.
Example:
 Parallel decoder
 Balanced decoder
 Tree decoder
Parallel decoder
X2 X2 X3 X3
X1
X1
X1 X2 X3
X1 X2 X3
X1 X2 X3
0 0 0
0 0 1
1 1 1
23
*3=24 diodes would be require to build the parallel decoder
• In tree network decoders there is four flip-
flops and so has 24
=16 output lines.
An examination will show that 56 diodes are
required to build it. There is another type of
decoder which is called a balanced decoder
network. This network requires only 48 diodes.
And it shown that this type of decoder network
requires the minimum number of diodes.
Tree Decoder
Balanced decoder
• The difference in the number of diodes or
decoding elements to build a network such as
balance decoders compared with parallel or
tree decoders becomes more significant as the
number of flip-flops to decoded increases.
• Parallel decoder network has the advantage of
being fastest and most regular in construction
of the three types.
The End

Decoders

  • 1.
  • 2.
    Definition: • An importantpart of the system which selects the cells to be read from and written into is the decoder. – Accepts a value and decodes it • Output corresponds to value of n inputs • It also is called many-to-one decoder, a decoder matrix or simply a decoder.
  • 3.
    A decoder consistsof: • Inputs (n) • Outputs (2n , numbered from 0  2n - 1) • Selectors / Enable (active high or active low) • The decoder has the characteristic that for each of the possible 2 𝑛 binary input numbers which can be taken by the n input cells, the matrix will have a unique one of its 2 𝑛 output lines selected. Input n=2 Output 22=4 Input n=3 Output 23 =8
  • 4.
    n Input 𝟐 𝒏 Out putDecoder nis the number of input flip-flop being decoded. Number of AND gates is equal to number of output lines
  • 5.
    Q0 = S1S0 Q1 = S1 S0 Q2 = S1 S0 Q3 = S1 S0 Input n=2 Output 22 =4
  • 6.
    What a decoderdoes • A n-to-2 n decoder takes an n-bit input and produces 2 n outputs. The n inputs represent a binary number that determines which of the 2 n outputs is uniquely true. • A 2-to-4 decoder operates according to the following truth table. – The 2-bit input is called S1S0, and the four outputs are Q0-Q3. – If the input is the binary number i, then output Qi is uniquely true. • For example, if the input S1 S0 = 10, then output Q2 is true, and Q0, Q1, Q3 are all false. • This circuit “decodes” a binary number into a “one-of-four” code. S1 S0 Q0 Q1 Q2 Q3 0 0 1 0 0 0 0 1 0 1 0 0 1 0 0 0 1 0 1 1 0 0 0 1
  • 7.
    How can youbuild a 2-to-4 decoder? • Follow the design procedures from last time! We have a truth table, so we can write equations for each of the four outputs (Q0-Q3), based on the two inputs (S0-S1). • Here are the equations: S1 S0 Q0 Q1 Q2 Q3 0 0 1 0 0 0 0 1 0 1 0 0 1 0 0 0 1 0 1 1 0 0 0 1 Q0 = S1 S0 Q1 = S1 S0 Q2 = S1 S0 Q3 = S1 S0
  • 8.
    A picture ofa 2-to-4 decoder S1 S0 Q0 Q1 Q2 Q3 0 0 1 0 0 0 0 1 0 1 0 0 1 0 0 0 1 0 1 1 0 0 0 1
  • 9.
  • 10.
    Enable inputs • Manydevices have an additional enable input, which is used to “activate” or “deactivate” the device. • For a decoder, – EN=1 activates the decoder, so it behaves as specified earlier. Exactly one of the outputs will be 1. – EN=0 “deactivates” the decoder. By convention, that means all of the decoder’s outputs are 0. • We can include this additional input in the decoder’s truth table: EN S1 S0 Q0 Q1 Q2 Q3 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 0 0 1 0 1 1 1 0 0 0 1
  • 11.
    • In thistable, note that whenever EN=0, the outputs are always 0, regardless of inputs S1 and S0. • We can abbreviate the table by writing x’s in the input columns for S1 and S0. EN S1 S0 Q0 Q1 Q2 Q3 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 0 0 1 0 1 1 1 0 0 0 1 EN S1 S0 Q0 Q1 Q2 Q3 0 x x 0 0 0 0 1 0 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 0 0 1 0 1 1 1 0 0 0 1
  • 12.
    A 3-to-8 decoder •Larger decoders are similar. Here is a 3-to-8 decoder. – The block symbol is on the right. – A truth table (without EN) is below. – Output equations are at the bottom right. • Again, only one output is true for any input combination. S2 S1 S0 Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 1 0 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 0 1 0 1 1 1 0 0 0 0 0 0 0 1 Q0 = S2’ S1’ S0’ Q1 = S2’ S1’ S0 Q2 = S2’ S1 S0’ Q3 = S2’ S1 S0 Q4 = S2 S1’ S0’ Q5 = S2 S1’ S0 Q6 = S2 S1 S0’ Q7 = S2 S1 S0 Design a 3-to-8 decoderAssignment
  • 13.
    • The decoderis often constructed by using diodes or transistors in the AND gates. • The number of diodes used in each AND gate is equal to the number of input to each and gate. The number of AND gates is equal to number of output (2 𝑛 ). So total number of diodes is: n* 2 𝑛
  • 14.
    • Number ofdiodes required increases sharply with number of inputs to the network. Example: To decode an eight flip-flop register we would require 8*28 = 2048 diodes if the decoder were constructed in this manner.
  • 15.
    • Several typesof structures are often used in building of decoder networks. Example:  Parallel decoder  Balanced decoder  Tree decoder
  • 16.
    Parallel decoder X2 X2X3 X3 X1 X1 X1 X2 X3 X1 X2 X3 X1 X2 X3 0 0 0 0 0 1 1 1 1 23 *3=24 diodes would be require to build the parallel decoder
  • 17.
    • In treenetwork decoders there is four flip- flops and so has 24 =16 output lines. An examination will show that 56 diodes are required to build it. There is another type of decoder which is called a balanced decoder network. This network requires only 48 diodes. And it shown that this type of decoder network requires the minimum number of diodes.
  • 18.
  • 19.
  • 20.
    • The differencein the number of diodes or decoding elements to build a network such as balance decoders compared with parallel or tree decoders becomes more significant as the number of flip-flops to decoded increases. • Parallel decoder network has the advantage of being fastest and most regular in construction of the three types.
  • 21.