ANALYSIS OF ARCH STRUCTURE
SEQUENCEAssumptions Pertaining Geometry of StructureAssumptions Pertaining Material PropertiesSalient of Finite Element ModelAnalysis for Factor of Safety for Self WeightAnalysis for Factor of Safety for DisplacementConclusion
Assumptions Pertaining Geometry of Structure5’8’1.5’2’ Thick10’2’8’3’ Thick1’73.5’15’1.5’10’1.5’10’4’ Thick
Assumptions Pertaining material properties(stone)E					=	30,000 N/mm2Density				=	2500 kg / m3Poisson’s Ratio			=	0.2Compressive Strength		=	30 N / mm2Tensile Strength			=	2 N / mm2
Salient of finite element modelElement Type		-	Shell (Thick)Element Size		-	6 inchesMaterial			-	Stone
Salient of finite element model
Salient of finite element model
Analysis for safety factor for self weight
PROCEDUREStart from self weight multiplier zeroIncrease the multiplier step by step and by iterative approach find the factor of safety required for collapseSince self weight acts downward causing compression in the structure so it will fail in compression
Distribution of stress sigma zz(Self weight multiplier = 0)
Distribution of stress sigma zz(Self weight multiplier = 1)
Distribution of stress sigma zz(Self weight multiplier = 5)
Distribution of stress sigma zz(Self weight multiplier = 10)
Distribution of stress sigma zz(Self weight multiplier = 15)
Distribution of stress sigma zz(Self weight multiplier = 19)
Distribution of stress sigma zz(Self weight multiplier = 20)
Distribution of stress sigma zz(Self weight multiplier = 19.1)
Distribution of stress sigma zz(Self weight multiplier = 19.072)Max Compressive Force Develops Here
Analysis for fos for self weight1319.072
Analysis for safety factor for displacement
PROCEDUREImpose boundary condition on central pier i.e allow downward movement so as to cause differential settlement in the structureStart from self weight multiplier zeroIncrease the multiplier step by step and by iterative approach find the factor of safety required for collapseSince differential settlement will cause tension in central pier so it will fail in tension
Distribution of stress sigma zz(Self weight multiplier = 0)
Distribution of stress sigma zz(Self weight multiplier = 1)
Distribution of stress sigma zz(Self weight multiplier = 2)
Distribution of stress sigma zz(Self weight multiplier = 3)
Distribution of stress sigma zz(Self weight multiplier = 3.5)
Distribution of stress sigma zz(Self weight multiplier = 3.59)
Distribution of stress sigma zz(Self weight multiplier = 3.565)Max Tensile Force Develops Here
Analysis for fos for DISPLACEMENT212.53.565
CONCLUSION
CONCLUSIONSELF WEIGHT				-	19.072DISPLACEMENTSTART OF MECHANISM	-	3.565FAILURE				-	12.5

Analysis of Arch Structure By Qazi Jvaid