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The Primitive Function
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

             If f  x   x n , then the primitive function is;
                                      x n1
                              f x        c
                                      n 1
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

                 If f  x   x n , then the primitive function is;
                                          x n1
                                  f x        c
                                          n 1

 e.g. i  f  x   3x 4
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

                 If f  x   x n , then the primitive function is;
                                          x n1
                                  f x        c
                                          n 1

 e.g. i  f  x   3x 4
                    3x 5
            f x       c
                     5
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

                 If f  x   x n , then the primitive function is;
                                           x n1
                                   f x        c
                                           n 1

 e.g. i  f  x   3x 4
                    3x 5
            f x       c
                     5
      ii  f  x   6 x3  5x 2  x  2
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

                 If f  x   x n , then the primitive function is;
                                           x n1
                                   f x        c
                                           n 1

 e.g. i  f  x   3x 4
                    3x 5
            f x       c
                     5
      ii  f  x   6 x3  5x 2  x  2
                    6 x 4 5x3 x 2
            f x            2x  c
                     4     3  2
The Primitive Function
If we know the equation of the tangent, how do we find the original
curve?

                 If f  x   x n , then the primitive function is;
                                           x n1
                                   f x        c
                                           n 1

 e.g. i  f  x   3x 4
                    3x 5
            f x       c
                     5
      ii  f  x   6 x3  5x 2  x  2
                   6 x 4 5x3 x 2
           f x             2x  c
                     4     3  2
                   3 4 5 3 1 2
           f x  x  x  x  2x  c
                   2      3   2
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
      y  x 2  3x  c
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
      y  x 2  3x  c

      when x = 1, y = 1
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
      y  x 2  3x  c

      when x = 1, y = 1
          i.e. 1  12  3  c
              c  3
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
      y  x 2  3x  c

      when x = 1, y = 1
         i.e. 1  12  3  c
             c  3
      y  x 2  3x  3
(iii) Find the equation of the curve which passes through (1,1) and has
      a gradient function of 2x + 3

     dy
         2x  3
     dx
      y  x 2  3x  c

      when x = 1, y = 1
         i.e. 1  12  3  c
             c  3
      y  x 2  3x  3



        Exercise 10J; 1ace etc, 2bdf, 3aceg, 4bd, 5b, 7ac, 8bdf
                    9ace, 10b, 12bd, 14a, 15, 17a

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11 x1 t01 01 algebra & indices (2014)11 x1 t01 01 algebra & indices (2014)
11 x1 t01 01 algebra & indices (2014)
 
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 03 integrating derivative on function (2013)
 
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)12 x1 t01 02 differentiating logs (2013)
12 x1 t01 02 differentiating logs (2013)
 
12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)12 x1 t01 01 log laws (2013)
12 x1 t01 01 log laws (2013)
 
X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)X2 t02 04 forming polynomials (2013)
X2 t02 04 forming polynomials (2013)
 
X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)X2 t02 03 roots & coefficients (2013)
X2 t02 03 roots & coefficients (2013)
 
X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)X2 t02 02 multiple roots (2013)
X2 t02 02 multiple roots (2013)
 
X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)X2 t02 01 factorising complex expressions (2013)
X2 t02 01 factorising complex expressions (2013)
 
11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)11 x1 t16 07 approximations (2013)
11 x1 t16 07 approximations (2013)
 
11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)11 x1 t16 06 derivative times function (2013)
11 x1 t16 06 derivative times function (2013)
 
11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)11 x1 t16 05 volumes (2013)
11 x1 t16 05 volumes (2013)
 
11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)11 x1 t16 04 areas (2013)
11 x1 t16 04 areas (2013)
 
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)11 x1 t16 03 indefinite integral (2013)
11 x1 t16 03 indefinite integral (2013)
 
11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)11 x1 t16 02 definite integral (2013)
11 x1 t16 02 definite integral (2013)
 

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11 x1 t10 07 primitive function (2012)

  • 2. The Primitive Function If we know the equation of the tangent, how do we find the original curve?
  • 3. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1
  • 4. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1 e.g. i  f  x   3x 4
  • 5. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1 e.g. i  f  x   3x 4 3x 5 f x  c 5
  • 6. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1 e.g. i  f  x   3x 4 3x 5 f x  c 5 ii  f  x   6 x3  5x 2  x  2
  • 7. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1 e.g. i  f  x   3x 4 3x 5 f x  c 5 ii  f  x   6 x3  5x 2  x  2 6 x 4 5x3 x 2 f x     2x  c 4 3 2
  • 8. The Primitive Function If we know the equation of the tangent, how do we find the original curve? If f  x   x n , then the primitive function is; x n1 f x  c n 1 e.g. i  f  x   3x 4 3x 5 f x  c 5 ii  f  x   6 x3  5x 2  x  2 6 x 4 5x3 x 2 f x     2x  c 4 3 2 3 4 5 3 1 2 f x  x  x  x  2x  c 2 3 2
  • 9. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3
  • 10. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx
  • 11. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx y  x 2  3x  c
  • 12. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx y  x 2  3x  c when x = 1, y = 1
  • 13. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx y  x 2  3x  c when x = 1, y = 1 i.e. 1  12  3  c c  3
  • 14. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx y  x 2  3x  c when x = 1, y = 1 i.e. 1  12  3  c c  3  y  x 2  3x  3
  • 15. (iii) Find the equation of the curve which passes through (1,1) and has a gradient function of 2x + 3 dy  2x  3 dx y  x 2  3x  c when x = 1, y = 1 i.e. 1  12  3  c c  3  y  x 2  3x  3 Exercise 10J; 1ace etc, 2bdf, 3aceg, 4bd, 5b, 7ac, 8bdf 9ace, 10b, 12bd, 14a, 15, 17a