The document discusses calculus quotient and reciprocal rules. It provides the quotient rule formula and explains that to use it you should "square the bottom, write down the bottom and differentiate the top, minus write down the top and differentiate the bottom." Examples are provided to demonstrate applying the quotient rule. The reciprocal rule formula is also given, along with the explanation that you should "minus the derivative of the function squared." More examples demonstrate applying the reciprocal rule.
The document discusses the concept of the derivative and slope of a tangent line to a curve. It explains that the slope of a secant line PQ provides an estimate of the slope of the tangent line k at point P on the curve. As Q moves closer to P, the slope of PQ will better estimate the true slope of the tangent line. The limit of this expression as Q approaches P is defined as the derivative, which represents the instantaneous rate of change and slope of the tangent line. An example demonstrates calculating the derivative of a function by using the definition and limits.
The document discusses calculus quotient and reciprocal rules. It provides the quotient rule formula and explains that to use it you should "square the bottom, write down the bottom and differentiate the top, minus write down the top and differentiate the bottom." Examples are provided to demonstrate applying the quotient rule. The reciprocal rule formula is also given, along with the explanation that you should "minus the derivative of the function squared." More examples demonstrate applying the reciprocal rule.
The document discusses the concept of the derivative and slope of a tangent line to a curve. It explains that the slope of a secant line PQ provides an estimate of the slope of the tangent line k at point P on the curve. As Q moves closer to P, the slope of PQ will better estimate the true slope of the tangent line. The limit of this expression as Q approaches P is defined as the derivative, which represents the instantaneous rate of change and slope of the tangent line. An example demonstrates calculating the derivative of a function by using the definition and limits.
The document discusses limits and continuity. It defines a limit as describing the behavior of a function as the input value approaches a particular number. It provides examples of calculating limits using direct substitution, factorizing, and special limits involving infinity. The key points covered are:
- A limit describes what value a function approaches as its input gets closer to a number
- Methods for calculating limits include direct substitution, factorizing, and using special rules for infinity
- A function is continuous if the left-hand and right-hand limits are equal at a point
11 x1 t10 02 quadratics and other methods (2013)Nigel Simmons
This document discusses quadratics and completing the square. It provides an example of sketching the parabola given by the equation 8x^2 + 12x + y = 0. It shows completing the square to find the vertex and x-intercepts. It also gives an example of writing the quadratic equation with given roots of 2 and 8 and a vertex of (5,3). Finally, it introduces the discriminant and its use in determining the number and type of solutions for a quadratic equation.
The document discusses two problems about rates of change:
1) A block of ice is melting, decreasing 1 mm/s. The volume is decreasing at a rate of 7.5 cm3/s when the edge is 5 cm.
2) A vessel is an inverted cone filled with water. If water is added at 0.2 cm3/min, the depth increases at a rate of 0.04 cm/min when the depth is 4 cm.
A block of ice is melting, with its dimensions decreasing at a rate of 1 mm/s. The document calculates that when the edge is 5 cm long, the volume is decreasing at a rate of 7.5 cm3/s. It also considers a vessel in the form of an inverted cone, where the volume of water is derived as 1/3πx3. When water is poured into the vessel at 0.2 cm/min and the depth is 4 cm, the rate of increase of the depth is calculated to be 0.08 cm/min.
11 x1 t10 04 maximum & minimum problems (2012)Nigel Simmons
The document discusses solving maximum/minimum problems involving quadratics. It provides an example of finding the maximum value of y = -3x^2 + x - 5. Through completing the square, it is determined that the maximum value is -4/12. It then gives an example of finding the dimensions of a rectangle with a perimeter of 64 cm that yields the maximum area. By setting up the area formula and taking the derivative, it is determined that the optimal dimensions are 16 cm by 16 cm.
The document discusses the discriminant of a quadratic equation and what it reveals about the nature of the roots. It gives the following information:
- The discriminant (Δ) tells us whether the roots are real or imaginary.
- If Δ > 0, there are two different real roots. If Δ = 0, there is one repeated real root. If Δ < 0, there are no real roots.
- If Δ is a perfect square, the roots are rational numbers.
- Several examples of quadratic equations are worked through to demonstrate applying the discriminant.
- Conditions are identified for quadratic equations to have equal, unreal or real roots based on the value of Δ.
The document discusses limits and how they describe the behavior of functions as the input value approaches a certain number. It provides examples of calculating limits using direct substitution, factorizing and canceling, and special limits involving infinity. Key aspects covered include defining the limit notation, calculating one-sided limits, and conditions for continuity.
The document defines key concepts related to quadratic functions and graphs quadratic functions. It explains that a quadratic function is represented by the quadratic polynomial f(x)=ax^2+bx+c and its graph is a parabola. The document outlines how to graph a quadratic function by identifying the y-intercept, x-intercepts (roots), axis of symmetry, and vertex (maximum or minimum point). An example graphs the function y=x^2+8x+12 to demonstrate these features.
The document discusses the concept of the derivative and how it relates to finding the slope of the tangent line to a curve. It explains that the derivative of a function f(x) with respect to x, written as f'(x), is defined as the limit of the difference quotient as h approaches 0. This represents the instantaneous rate of change and can be interpreted as the slope of the tangent line. The document provides an example of using the definition directly to find the derivative of a simple function y=6x+1.
11 x1 t10 07 sum & product of roots (2013)Nigel Simmons
The document discusses properties of the sum and product of roots of quadratic equations. It shows that:
- The sum of the roots α and β is equal to -b/a
- The product of the roots is equal to c/a
- Examples are given of forming quadratic equations with given roots and calculating properties like the sum and product of roots for specific equations.
The document discusses differentiability and implicit differentiation. It defines differentiability as a function having a smooth, continuous curve at a point. It provides examples of determining if functions are differentiable at various points. It then introduces implicit differentiation and uses it to find the derivative of implicitly defined functions. It works through examples of using implicit differentiation to find derivatives and the equation of a tangent line to an implicitly defined curve at a given point.
The document discusses trigonometric functions and radian measure. It states that 360 degrees equals 2 pi radians. It then provides a table with common conversions between degrees and radians for angles from 30 to 360 degrees. Examples are also given of converting degrees to radians and radians to degrees.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document discusses limits and continuity. It defines a limit as describing the behavior of a function as the input value approaches a particular number. It provides examples of calculating limits using direct substitution, factorizing, and special limits involving infinity. The key points covered are:
- A limit describes what value a function approaches as its input gets closer to a number
- Methods for calculating limits include direct substitution, factorizing, and using special rules for infinity
- A function is continuous if the left-hand and right-hand limits are equal at a point
11 x1 t10 02 quadratics and other methods (2013)Nigel Simmons
This document discusses quadratics and completing the square. It provides an example of sketching the parabola given by the equation 8x^2 + 12x + y = 0. It shows completing the square to find the vertex and x-intercepts. It also gives an example of writing the quadratic equation with given roots of 2 and 8 and a vertex of (5,3). Finally, it introduces the discriminant and its use in determining the number and type of solutions for a quadratic equation.
The document discusses two problems about rates of change:
1) A block of ice is melting, decreasing 1 mm/s. The volume is decreasing at a rate of 7.5 cm3/s when the edge is 5 cm.
2) A vessel is an inverted cone filled with water. If water is added at 0.2 cm3/min, the depth increases at a rate of 0.04 cm/min when the depth is 4 cm.
A block of ice is melting, with its dimensions decreasing at a rate of 1 mm/s. The document calculates that when the edge is 5 cm long, the volume is decreasing at a rate of 7.5 cm3/s. It also considers a vessel in the form of an inverted cone, where the volume of water is derived as 1/3πx3. When water is poured into the vessel at 0.2 cm/min and the depth is 4 cm, the rate of increase of the depth is calculated to be 0.08 cm/min.
11 x1 t10 04 maximum & minimum problems (2012)Nigel Simmons
The document discusses solving maximum/minimum problems involving quadratics. It provides an example of finding the maximum value of y = -3x^2 + x - 5. Through completing the square, it is determined that the maximum value is -4/12. It then gives an example of finding the dimensions of a rectangle with a perimeter of 64 cm that yields the maximum area. By setting up the area formula and taking the derivative, it is determined that the optimal dimensions are 16 cm by 16 cm.
The document discusses the discriminant of a quadratic equation and what it reveals about the nature of the roots. It gives the following information:
- The discriminant (Δ) tells us whether the roots are real or imaginary.
- If Δ > 0, there are two different real roots. If Δ = 0, there is one repeated real root. If Δ < 0, there are no real roots.
- If Δ is a perfect square, the roots are rational numbers.
- Several examples of quadratic equations are worked through to demonstrate applying the discriminant.
- Conditions are identified for quadratic equations to have equal, unreal or real roots based on the value of Δ.
The document discusses limits and how they describe the behavior of functions as the input value approaches a certain number. It provides examples of calculating limits using direct substitution, factorizing and canceling, and special limits involving infinity. Key aspects covered include defining the limit notation, calculating one-sided limits, and conditions for continuity.
The document defines key concepts related to quadratic functions and graphs quadratic functions. It explains that a quadratic function is represented by the quadratic polynomial f(x)=ax^2+bx+c and its graph is a parabola. The document outlines how to graph a quadratic function by identifying the y-intercept, x-intercepts (roots), axis of symmetry, and vertex (maximum or minimum point). An example graphs the function y=x^2+8x+12 to demonstrate these features.
The document discusses the concept of the derivative and how it relates to finding the slope of the tangent line to a curve. It explains that the derivative of a function f(x) with respect to x, written as f'(x), is defined as the limit of the difference quotient as h approaches 0. This represents the instantaneous rate of change and can be interpreted as the slope of the tangent line. The document provides an example of using the definition directly to find the derivative of a simple function y=6x+1.
11 x1 t10 07 sum & product of roots (2013)Nigel Simmons
The document discusses properties of the sum and product of roots of quadratic equations. It shows that:
- The sum of the roots α and β is equal to -b/a
- The product of the roots is equal to c/a
- Examples are given of forming quadratic equations with given roots and calculating properties like the sum and product of roots for specific equations.
The document discusses differentiability and implicit differentiation. It defines differentiability as a function having a smooth, continuous curve at a point. It provides examples of determining if functions are differentiable at various points. It then introduces implicit differentiation and uses it to find the derivative of implicitly defined functions. It works through examples of using implicit differentiation to find derivatives and the equation of a tangent line to an implicitly defined curve at a given point.
The document discusses trigonometric functions and radian measure. It states that 360 degrees equals 2 pi radians. It then provides a table with common conversions between degrees and radians for angles from 30 to 360 degrees. Examples are also given of converting degrees to radians and radians to degrees.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
7. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
8. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
9. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
f x kx
10. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
f x kx
f x h k x h
kx kh
11. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
kx kh kx
f x kx f x lim
h0 h
f x h k x h
kx kh
12. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
kx kh kx
f x kx f x lim
h0 h
f x h k x h kh
lim
kx kh h0 h
13. Rules For Differentiation
(1) y c
cc
f x c f x lim
h0 h
f x h c 0
lim
h 0 h
lim 0
h0
0
(2) y kx
kx kh kx
f x kx f x lim
h0 h
f x h k x h kh
lim
kx kh h0 h
lim k
h0
k
16. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
17. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
18. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
19. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn
20. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn f x h x h
n
21. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn f x h x h
n
x h xn
n
f x lim
h0 h
22. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn f x h x h
n
x h xn
n
f x lim
h0 h
lim
x h x x h x h x x h x n2 x n1
n 1 n2
h0 h
23. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn f x h x h
n
x h xn
n
f x lim
h0 h
lim
x h x x h x h x x h x n2 x n1
n 1 n2
h0 h
lim
h x h x h x x h x n2 x n1
n 1 n2
h0 h
24. (3) y x n
a 2 b 2 a b a b
a 3 b3 a b a 2 ab b 2
a 4 b 4 a b a 3 a 2b ab 2 b3
a n b n a b a n1 a n2b a n3b 2 a 2b n3 ab n2 b n1
f x xn f x h x h
n
x h xn
n
f x lim
h0 h
lim
x h x x h x h x x h x n2 x n1
n 1 n2
h0 h
lim
h x h x h x x h x n2 x n1
n 1 n2
h0 h
lim x h x h x x h x n2 x n1
n 1 n2
h0
25. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
26. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
27. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
28. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x
29. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x
1
f x
x
30. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x
1
f x
x
1
f x h
xh
31. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1
f x f x lim x h x
x h0 h
1
f x h
xh
32. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1
f x f x lim x h x
x h0 h
1 xxh
f x h lim
xh h0 hx x h
33. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1
f x f x lim x h x
x h0 h
1 xxh
f x h lim
xh h0 hx x h
h
lim
h0 hx x h
34. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1
f x f x lim x h x
x h0 h
1 xxh
f x h lim
xh h0 hx x h
h
lim
h0 hx x h
1
lim
h0 x x h
35. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1
f x f x lim x h x
x h0 h
1 xxh
f x h lim
xh h0 hx x h
h
lim
h0 hx x h
1
lim
h0 x x h
1
2
x
36. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1 Note:
f x f x lim x h x
x h0 h
1 xxh
f x h lim
xh h0 hx x h
h
lim
h0 hx x h
1
lim
h0 x x h
1
2
x
37. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1 Note:
f x f x lim x h x
x h0 h f x x 1
1 xxh
f x h lim
xh h0 hx x h
h
lim
h0 hx x h
1
lim
h0 x x h
1
2
x
38. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1 Note:
f x f x lim x h x
x h0 h f x x 1
1 xxh
f x h lim
xh h0 hx x h f x x 2
h
lim
h0 hx x h
1
lim
h0 x x h
1
2
x
39. f x lim x h x h x x h x n2 x n1
n 1 n2
h0
x n1 x n1 x n1 x n1
nx n1
1
(4) y
x 1 1
1 Note:
f x f x lim x h x
x h0 h f x x 1
1 xxh
f x h lim
xh h0 hx x h f x x 2
h 1
lim 2
h0 hx x h x
1
lim
h0 x x h
1
2
x
43. (5) y x
f x x
xh x
f x h x h f x lim
h 0 h
44. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
45. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
46. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x
47. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x
1
lim
h0
xh x
48. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x
1
lim
h0
xh x
1
x x
49. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x
1
lim
h0
xh x
1
x x
1
2 x
50. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x Note:
1
lim
h0
xh x
1
x x
1
2 x
51. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x Note:
1
1 f x x 2
lim
h0
xh x
1
x x
1
2 x
52. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x Note:
1
1 f x x
2
lim
h0
xh x 1 1
f x x 2
1 2
x x
1
2 x
53. (5) y x
f x x
xh x xh x
f x h x h f x lim
h 0 h xh x
xhx
lim
h0
h xh x
h
lim
h0
h xh x Note:
1
1 f x x
2
lim
h0
xh x 1 1
f x x 2
1 2
1
x x
2 x
1
2 x
57. e.g. i y 7
dy
0
dx
ii y 37 x
dy
37
dx
58. e.g. i y 7
dy
0
dx
ii y 37 x
dy
37
dx
iii y x10
59. e.g. i y 7
dy
0
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
60. e.g. i y 7
dy
0
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
61. e.g. i y 7
dy
0
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
62. e.g. i y 7 v y 2 x 1
2
dy
0
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
63. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
64. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x
dy
37
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
65. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
66. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx 3 x x 2
iii y x10
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
67. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx 3 x x 2
dy
3 2 x 3
iii y x10 dx
dy
10 x 9
dx
iv y 3x 2 6 x 2
dy
6x 6
dx
68. e.g. i y 7 v y 2 x 1
2
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx 3 x x 2
dy
3 2 x 3
iii y x10 dx
dy 2
10 x 9 3 3
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
69. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
dx dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx 3 x x 2
dy
3 2 x 3
iii y x10 dx
dy 2
10 x 9 3 3
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
70. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4
dx
ii y 37 x 1
dy vi y 3x 2
37 x
dx 3 x x 2
dy
3 2 x 3
iii y x10 dx
dy 2
10 x 9 3 3
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
71. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2
37 x
dx 3 x x 2
dy
3 2 x 3
iii y x10 dx
dy 2
10 x 9 3 3
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
72. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx
dy 2
10 x 9 3 3
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
73. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx viii If f x x3 3,
dy
10 x 9 3 3
2 find f 2
dx x
iv y 3x 2 6 x 2
dy
6x 6
dx
74. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx viii If f x x3 3,
dy
10 x 9 3 3
2 find f 2
dx x
f x x3 3
iv y 3x 2 6 x 2
dy
6x 6
dx
75. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx viii If f x x3 3,
dy
10 x 9 3 3
2 find f 2
dx x
f x x3 3
iv y 3x 2 6 x 2 f x 3x 2
dy
6x 6
dx
76. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx viii If f x x3 3,
dy
10 x 9 3 3
2 find f 2
dx x
f x x3 3
iv y 3x 2 6 x 2 f x 3x 2
dy
6x 6
f 2 3 2
2
dx
77. e.g. i y 7 v y 2 x 1
2
vii y x 2 x
dy
0 4x2 4 x 1
5
dx x 2
dy
8x 4 dy 5 3
dx x2
ii y 37 x 1 dx 2
dy vi y 3x 2 5
37 x x x
dx 3 x x 2 2
dy
3 2 x 3
iii y x10 dx viii If f x x3 3,
dy
10 x 9 3 3
2 find f 2
dx x
f x x3 3
iv y 3x 2 6 x 2 f x 3x 2
dy
6x 6
f 2 3 2
2
dx
12
78. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
79. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2
80. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2
dy
15 x 2 12 x
dx
81. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2
dy
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2
dx
82. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2
dy
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2
dx
3
83. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2
dy
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2
dx
3
required slope 3
84. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2
dx
3
required slope 3
85. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2
dx
3
required slope 3
86. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
87. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal
88. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal
y x 3 12 x
89. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal
y x 3 12 x
dy
3 x 2 12
dx
90. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal dy
tangents are horizontal when 0
y x 3 12 x dx
dy
3 x 2 12
dx
91. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal dy
tangents are horizontal when 0
y x 3 12 x dx
i.e. 3 x 12 0
2
dy
3 x 2 12
dx
92. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal dy
tangents are horizontal when 0
y x 3 12 x dx
i.e. 3 x 12 0
2
dy
3 x 2 12 x2 4
dx
x 2
93. xix Find the equation of the tangent to the curve y 5 x3 6 x 2 2
at the point 1,1
y 5 x3 6 x 2 2 y 1 3 x 1
dy y 1 3x 3
15 x 2 12 x
dx
dy
when x 1, 15 1 12 1
2 3x y 2 0
dx
3
required slope 3
x Find the points on the curve y x3 12 x where the tangents
are horizontal dy
tangents are horizontal when 0
y x 3 12 x dx
i.e. 3 x 12 0
2
dy
3 x 2 12 x2 4
dx
x 2
tangents are horizontal at 2,16 and 2, 16
94. A normal is a line perpendicular to the tangent at the point of contact
95. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
96. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
tangent
97. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
98. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
99. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
y 4 x 2 3x 2
100. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
y 4 x 2 3x 2
dy
8x 3
dx
101. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
y 4 x 2 3x 2
dy
8x 3
dx
dy
when x 3, 8 3 3
dx
102. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
y 4 x 2 3x 2
dy
8x 3
dx
dy
when x 3, 8 3 3
dx
21
103. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
y 4 x 2 3x 2
dy
8x 3
dx
dy
when x 3, 8 3 3
dx
21
1
required slope
21
104. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
1
y 4 x 3x 2
2
y 29 x 3
dy 21
8x 3
dx
dy
when x 3, 8 3 3
dx
21
1
required slope
21
105. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
1
y 4 x 3x 2
2
y 29 x 3
dy 21
8x 3 21 y 609 x 3
dx
dy
when x 3, 8 3 3
dx
21
1
required slope
21
106. A normal is a line perpendicular to the tangent at the point of contact
y
y f x
x
normal tangent
xi Find the equation of the normal to the curve y 4 x 2 3 x 2 at
the point 3, 29
1
y 4 x 3x 2
2
y 29 x 3
dy 21
8x 3 21 y 609 x 3
dx
dy
when x 3, 8 3 3 x 21 y 612 0
dx
21
1
required slope
21