Perpendicular Distance Formula
Perpendicular Distance Formula The shortest distance from a point to a line is the  perpendicular distance.
Perpendicular Distance Formula The shortest distance from a point to a line is the  perpendicular distance.
Perpendicular Distance Formula The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0
Perpendicular Distance Formula The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d
Perpendicular Distance Formula The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0 r
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0 r
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0 r
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0 r
Perpendicular Distance Formula e.g. Find the equation of the circle with tangent 3 x  – 4 y  – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the  perpendicular distance. Ax + By + C =  0 d 3 x  – 4 y –  12  =  0 r
If  has different signs for different points, they are on different sides of the line.
If  has different signs for different points, they are on different sides of the line. Ax + By + C =  0
If  has different signs for different points, they are on different sides of the line. Ax + By + C =  0 Ax + By + C >  0
If  has different signs for different points, they are on different sides of the line. Ax + By + C =  0 Ax + By + C >  0 Ax + By + C <  0
If  has different signs for different points, they are on different sides of the line. Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b,  9abc, 10, 13, 14, 18* Ax + By + C =  0 Ax + By + C >  0 Ax + By + C <  0

11 X1 T05 05 Perpendicular Distance

  • 1.
  • 2.
    Perpendicular Distance FormulaThe shortest distance from a point to a line is the perpendicular distance.
  • 3.
    Perpendicular Distance FormulaThe shortest distance from a point to a line is the perpendicular distance.
  • 4.
    Perpendicular Distance FormulaThe shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0
  • 5.
    Perpendicular Distance FormulaThe shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d
  • 6.
    Perpendicular Distance FormulaThe shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d
  • 7.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d
  • 8.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d
  • 9.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0
  • 10.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0 r
  • 11.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0 r
  • 12.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0 r
  • 13.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0 r
  • 14.
    Perpendicular Distance Formulae.g. Find the equation of the circle with tangent 3 x – 4 y – 12 = 0 and centre (1,4). The shortest distance from a point to a line is the perpendicular distance. Ax + By + C = 0 d 3 x – 4 y – 12 = 0 r
  • 15.
    If hasdifferent signs for different points, they are on different sides of the line.
  • 16.
    If hasdifferent signs for different points, they are on different sides of the line. Ax + By + C = 0
  • 17.
    If hasdifferent signs for different points, they are on different sides of the line. Ax + By + C = 0 Ax + By + C > 0
  • 18.
    If hasdifferent signs for different points, they are on different sides of the line. Ax + By + C = 0 Ax + By + C > 0 Ax + By + C < 0
  • 19.
    If hasdifferent signs for different points, they are on different sides of the line. Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b, 9abc, 10, 13, 14, 18* Ax + By + C = 0 Ax + By + C > 0 Ax + By + C < 0