1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf

•

0 likes•3 views

1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary storage for IO devices which is used to store sufficient amount of data before it is transferred to CPU. In a system, CPU communicates with the IO devices and vice versa and in order for a system to operate properly the devices must be in synchronization with the CPU. IO devices are usually slower than CPU e:g printer is slower than CPU and when CPU sends some data to be printed this data is stored in the buffer and then transferred to the printer with a speed suitable for printer. Similarly a buffer is used to temporarily store data being entered from a n input device like keyboard, which allows a large block of data to be keyed. held, and then transferred all at once to the CPU and in during the typing period CPU performs some other tasks. Benefits of IO Device Control Unit Buffer are Flow Control. (Modules canbuffer data until the adjacent module is ready to receive it), Better CPU utiization, BetterThroughput etc Solution 1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary .

Education

redeable and vice versa) .
3. IO Device Control Unit Buffer is a special kind of temporary storage for IO devices which is
used to store sufficient amount of data before it is transferred to CPU. In a system, CPU
communicates with the IO devices and vice versa and in order for a system to operate properly
the devices must be in synchronization with the CPU. IO devices are usually slower than CPU
e:g printer is slower than CPU and when CPU sends some data to be printed this data is stored in
the buffer and then transferred to the printer with a speed suitable for printer. Similarly a buffer
is used to temporarily store data being entered from a n input device like keyboard, which allows
a large block of data to be keyed. held, and then transferred all at once to the CPU and in during
the typing period CPU performs some other tasks. Benefits of IO Device Control Unit Buffer are
Flow Control. (Modules canbuffer data until the adjacent module is ready to receive it), Better
CPU utiization, BetterThroughput etc

Similar to 1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf

Operating System Case Study and I/O System

prakash ganesan

Computer architecture input output organization

Mazin Alwaaly

Computer Architecture Design (CAD)

Saira Kanwal

UNIT 5- UNDERSTANDING THE SYSTEM DESIGN PROCESS.pptx

LeahRachael

Chapter 1 CSC118

Luqman al-Hakim

INTERFACE UNIT IV.pptx

NidaKhan232565

Input output

jyoti_lakhani

Input - Output Organization and I/O Interface

kasthurimukila

Csc118 chapter1

Mazlan Salleh

Computer architecture presentation

Muhammad Hamza

Chapter 4

Er. Nawaraj Bhandari

COMPUTER BASIC AND FUNDAMENTAL AND ITS ORGANISATION.pptx

PannaBushratul

Unit 5 I/O organization

chidabdu

co1_aiml_new.pptx

KUNTALADAS5

Comp App Lect 2 System Unit.pptx

FUNCTIONAL UNIT

Control unit

I/O Management

Data transferschemes

Fp203 chp1.1

Similar to 1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf (20)

Operating System Case Study and I/O System

Computer architecture input output organization

Computer Architecture Design (CAD)

UNIT 5- UNDERSTANDING THE SYSTEM DESIGN PROCESS.pptx

Chapter 1 CSC118

INTERFACE UNIT IV.pptx

Input output

Input - Output Organization and I/O Interface

Csc118 chapter1

Computer architecture presentation

Chapter 4

COMPUTER BASIC AND FUNDAMENTAL AND ITS ORGANISATION.pptx

Unit 5 I/O organization

co1_aiml_new.pptx

Comp App Lect 2 System Unit.pptx

FUNCTIONAL UNIT

Control unit

I/O Management

Data transferschemes

Fp203 chp1.1

More from arakalamkah11

Particulars $Amount Direct materials 64452 Direct Labour (1332 * 14) 18648 Manufacturing Overheads (1490 * 15) 22350 Total cost 105450 Number of units produced 3700 Unit product cost = Total cost / Number of units produced 28.5 Solution Particulars $Amount Direct materials 64452 Direct Labour (1332 * 14) 18648 Manufacturing Overheads (1490 * 15) 22350 Total cost 105450 Number of units produced 3700 Unit product cost = Total cost / Number of units produced 28.5.

Particulars $Amount Direct materials 64452 Direct Labour (1332.pdf

arakalamkah11

Decrease in inventory Source of cash $ 440 Decrease in accounts payable Use of cash $ (170) Increase in notes payable Source of cash $ 155 Increase in accounys receivables Use of cash $ (185) Cash increased by $ $ 240 Solution Decrease in inventory Source of cash $ 440 Decrease in accounts payable Use of cash $ (170) Increase in notes payable Source of cash $ 155 Increase in accounys receivables Use of cash $ (185) Cash increased by $ $ 240.

Decrease in inventory Source of cash $ 440 Decrease in account.pdf

arakalamkah11

Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up. Solution Diamond is sp3 covalent. It makes for bonds to neighboring carbons. forming an endless network of tetrahedrons Graphite is a delocalized sp2 hybridized carbon system. the entire sheet is flat because all carbons are trigonal planar and sp2 hybridized. Fullerenes have sp2 carbons in a ball shape. It is a mixture of hexagons and pentagons. Nanotubes it is one layer of graphite, aka graphene rolled up..

Diamond is sp3 covalent. It makes for bonds to ne.pdf

arakalamkah11

Too low. If you do not dry the sodium thiosulfate the extra water molecules will increase volume while decreasing your actual number of moles of the salt and therefore produce a lower molar concentration. Solution Too low. If you do not dry the sodium thiosulfate the extra water molecules will increase volume while decreasing your actual number of moles of the salt and therefore produce a lower molar concentration..

Too low. If you do not dry the sodium thiosulfate.pdf

arakalamkah11

1. E) The vapor pressure of a liquid. Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly to each other. Thus it is more difficult for the molecules to escape into the gas phase and the vapor pressure decreases. All the other properties listed should increase in value. 2. A) Ba(OH)2 The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+ and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water and insoluble BaSO4: Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l) The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows and the bulb dims. 3. D) hydration Hydration is the process whereby water molecules form dipole-dipole interactions with the solute ions, releasing energy and causing the salt to fall apart. 4. E)All of these are correct. All the statements about light, matter and energy are true. 5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your question but I have put the correct values here for you) Silicon has electronic configuration 1s2 2s2p6 3s2p2 The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing) ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to the nucleus, so the ionization energy shows a large increase. Solution 1. E) The vapor pressure of a liquid. Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly to each other. Thus it is more difficult for the molecules to escape into the gas phase and the vapor pressure decreases. All the other properties listed should increase in value. 2. A) Ba(OH)2 The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+ and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water and insoluble BaSO4: Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l) The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows and the bulb dims. 3. D) hydration Hydration is the process whereby water molecules form dipole-dipole interactions with the solute ions, releasing energy and causing the salt to fall apart. 4. E)All of these are correct. All the statements about light, matter and energy are true. 5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your question but I have put the correct values here for you) Silicon has electronic configuration 1s2 2s2p6 3s2p2 The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing) ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to the nucleus, so the ionization energy shows a large increase..

1. E) The vapor pressure of a liquid.Increasing attractive intermo.pdf

arakalamkah11

Light is a form of energy that can be released by an atom. It is made up of many small particle-like packets that have energy and momentum but no mass. These particles, called light photons, are the most basic units of light. Atoms release light photons when their electrons become excited. When an atom gains or loses energy, the change is expressed by the movement of electrons. When something passes energy on to an atom, an electron may be temporarily boosted to a higher orbital (farther away from the nucleus). The electron only holds this position for a tiny fraction of a second; almost immediately, it is drawn back toward the nucleus, to its original orbital. As it returns to its original orbital, the electron releases the extra energy in the form of a photon, in some cases a light photon. Solution Light is a form of energy that can be released by an atom. It is made up of many small particle-like packets that have energy and momentum but no mass. These particles, called light photons, are the most basic units of light. Atoms release light photons when their electrons become excited. When an atom gains or loses energy, the change is expressed by the movement of electrons. When something passes energy on to an atom, an electron may be temporarily boosted to a higher orbital (farther away from the nucleus). The electron only holds this position for a tiny fraction of a second; almost immediately, it is drawn back toward the nucleus, to its original orbital. As it returns to its original orbital, the electron releases the extra energy in the form of a photon, in some cases a light photon..

Light is a form of energy that can be released by.pdf

arakalamkah11

1) Presence of jaws with paired fins in fish helps to feed them. Fins helps them with increased stability and maneuverability and jaws helps to capture the prey and seize it. 2) Fish with jaws need to regulate their body temperature so they need to feed themselves often. It capture the prey and send it to stomach for digestion and for temporary storage. Jawless fish donot regulate their own body temperature so they don\'t need temporary storage like stomach and also they have sucking mouth and sharp teeth which helps in digestion without the need for pre digestion with gastric juice. So the fish which needs more food has jaw (Capture large prey) with stomach (Temporary storage and pre digestion). The fish which needs less food has no jaw and no stomach but with sucking mouth and also they have no fins. Jawless fish examples : Lampreys and hagfish. Majority of the fishes are with jaws. 3) Two chambered heart have one atrium and one ventricle and three chambered heart have two atrium and one ventricle. There are two types of circulatory system that is single circulation system (fish) and double circulation system (reptiles, mammals) In single circulation system, blood from the parts of the body enters heart through atrium and then ventricle pumps the blood to gills where re-oxygenation takes place. From the gills, blood is sent back to body parts. Blood enters the heart only once that is only deoxygenated blood enters. In double circulation system, blood enters the heart twice that is from parts of the body to heart then from heart to pulmonary circulation (Lungs) and from lungs to heart then heart to parts of the body. Both deoxygenated and oxygenated blood enters the heart. Solution 1) Presence of jaws with paired fins in fish helps to feed them. Fins helps them with increased stability and maneuverability and jaws helps to capture the prey and seize it. 2) Fish with jaws need to regulate their body temperature so they need to feed themselves often. It capture the prey and send it to stomach for digestion and for temporary storage. Jawless fish donot regulate their own body temperature so they don\'t need temporary storage like stomach and also they have sucking mouth and sharp teeth which helps in digestion without the need for pre digestion with gastric juice. So the fish which needs more food has jaw (Capture large prey) with stomach (Temporary storage and pre digestion). The fish which needs less food has no jaw and no stomach but with sucking mouth and also they have no fins. Jawless fish examples : Lampreys and hagfish. Majority of the fishes are with jaws. 3) Two chambered heart have one atrium and one ventricle and three chambered heart have two atrium and one ventricle. There are two types of circulatory system that is single circulation system (fish) and double circulation system (reptiles, mammals) In single circulation system, blood from the parts of the body enters heart through atrium and then ventricle pumps the blood to gills .

1) Presence of jaws with paired fins in fish helps to feed them. Fin.pdf

arakalamkah11

You\'re looking for Ka, the dissociation constant, so you measure this by adding the substance to water. 1. Write the balanced equation HBrO + H2O = BrO- + H30+ 2. the pH is 4.95, so you know its acidic and there has to have hydronium as a product. if the pH was >7.0, there would be OH- instead. the pH is a measure of H ions, and to get the concentration, you simply do 10^(-pH). 10^(-4.95) = 1.12E-5 3. The equation for Ka is concentration of products/concentration of reactants. always look at the coefficients infront of the molecules in the reaction. in this case, it is [BrO-)][H3O+]/[HBrO] *liquids and solids are never included in this, only aqueous solutions and gases are* 4. Your concentration of H3O was found to be 1.12E-5, and because the H30 and BrO are in a 1:1 ration in the equation, the concentration for BrO is also 1.12E-5. The concentration for HBrO as a reactant is given, but the final concentration is 0.063-concentration of hydronium...but since the concentration of the hydronium is so small, it doesnt at all affect the final answer. 5. your equation for Ka=((1.12E- 5)(1.12E-5))/(0.063-1.12E-5). The final answer for your Ka is 2.0E-9 Hope this helps, please rate. Solution You\'re looking for Ka, the dissociation constant, so you measure this by adding the substance to water. 1. Write the balanced equation HBrO + H2O = BrO- + H30+ 2. the pH is 4.95, so you know its acidic and there has to have hydronium as a product. if the pH was >7.0, there would be OH- instead. the pH is a measure of H ions, and to get the concentration, you simply do 10^(-pH). 10^(-4.95) = 1.12E-5 3. The equation for Ka is concentration of products/concentration of reactants. always look at the coefficients infront of the molecules in the reaction. in this case, it is [BrO-)][H3O+]/[HBrO] *liquids and solids are never included in this, only aqueous solutions and gases are* 4. Your concentration of H3O was found to be 1.12E-5, and because the H30 and BrO are in a 1:1 ration in the equation, the concentration for BrO is also 1.12E-5. The concentration for HBrO as a reactant is given, but the final concentration is 0.063-concentration of hydronium...but since the concentration of the hydronium is so small, it doesnt at all affect the final answer. 5. your equation for Ka=((1.12E- 5)(1.12E-5))/(0.063-1.12E-5). The final answer for your Ka is 2.0E-9 Hope this helps, please rate..

Youre looking for Ka, the dissociation constant.pdf

arakalamkah11

Okay so dipole-dipole interactions would occur between polar molecules such as water. The H has a + charge while O has a - charge. Dipole- induced dipole(or dispersion forces) would be like a molecule that has a polar part to it such as a -COOH group and then a nonpolar part such as a long hydrocarbon chain. The nonpolar part has no charge except the transient charge among the different atoms. I hope that helps Solution Okay so dipole-dipole interactions would occur between polar molecules such as water. The H has a + charge while O has a - charge. Dipole- induced dipole(or dispersion forces) would be like a molecule that has a polar part to it such as a -COOH group and then a nonpolar part such as a long hydrocarbon chain. The nonpolar part has no charge except the transient charge among the different atoms. I hope that helps.

Okay so dipole-dipole interactions would occur be.pdf

arakalamkah11

remote operating system installation Remote Installation Services (RIS) ships as a part of the Windows® 2000 Server software system. This document outlines the steps necessary to put in, configure, and use RIS. RIS was designed to cut back the prices incurred by pre-installing or physically visiting every consumer pc to put in the software system (OS). By combining RIS with alternative Windows 2000 IntelliMirror™ management technologies features—User knowledge Management, software package Installation and Maintenance, and User Settings Management—companies get pleasure from higher disaster recovery with easier OS and application management. Prerequisites See Appendix A below to confirm that each your server and consumer hardware meet the remote installation hardware necessities. The drive on the server wherever you decide on to put in RIS should be formatted with the NTFS filing system. RIS needs a big quantity of space and can\'t be put in on constant drive or partition on that Windows 2000 Server is put in. make sure that the chosen drive contains enough free space for a minimum of one full Windows 2000 skilled compact disc—a minimum of roughly 800 megabytes (MB)–1 GB (GB). RIS needs many alternative services that conjointly ship as a part of Windows 2000 Server. These services will be put in on individual servers, or all on one server, counting on your network design: Domain Name Service (DNS) Server. Remote installation depends on DNS for locating the directory service and consumer machine accounts. you\'ll use any Windows 2000 Active DirectoryTM service-compliant DNS server, otherwise you will use the DNS server given Windows 2000 Server. Dynamic Host Configuration Protocol (DHCP) Server. RIS needs a DHCP server to be gift and active on the network. The remote boot-enabled consumer computers receive AN information processing address from the DHCP server before contacting RIS. Active Directory. RIS depends on Windows 2000 Active Directory for locating existing consumer machines further as existing RIS servers. RIS should be put in on a Windows 2000- based server that has access to Active Directory. this will be a site controller or a server that\'s a member of a site with access to the Active Directory. To ensure a in installation, you want to install and tack together the extra services delineate higher than so as for RIS to perform. additionally, certify that you just have each the Windows 2000 Server and skilled CDs on the market. Before starting this gradual guide, you wish to create the common infrastructure, that specifies a specific hardware and software package configuration. The common infrastructure is roofed within the Common Infrastructure gradual guide, \"Part 1: putting in a Windows 2000 Server as a site Controller\" http://www.microsoft.com/windows2000/techinfo/planning/server/serversteps.asp. If you\'re not victimization the common infrastructure, you wish to create the suitable changes to the current instruction set. Alth.

remote operating system installationRemote Installation Services (.pdf

arakalamkah11

Title of this process is \"The Project Life Cycle (Phases)\" The project manager and project team have one shared goal: to carry out the work of the project for the purpose of meeting the project’s objectives. Every project has a beginning, a middle period during which activities move the project toward completion, and an ending. A standard project typically has the following four major phases: initiation, planning, implementation, and closure. Taken together, these phases represent the path a project takes from the beginning to its end and are generally referred to as the project “life cycle.” Initiation Phase During the first phases, the initiation phase, the project objective is identified; this can be a business problem or opportunity. An appropriate response to the objective of the project is documented with recommended solution options. A feasibility study is conducted to investigate whether each option addresses the project objective and a final recommended solution is determined. Issues of feasibility (“can we do the project?”) and justification (“should we do the project?”) are addressed. Once the recommended solution is approved, a project is initiated to deliver the approved solution and a project manager is appointed. Approval is then sought by the project manager to move onto the detailed planning phase. Planning Phase The planning phase, is where the project solution is further developed in as much detail as possible and the steps necessary to meet the project’s objective are planned. In this step, the team identifies all of the work to be done. The project’s tasks and resource requirements are identified, along with the strategy for producing them. A project plan is created outlining the activities, tasks, dependencies, and timeframes. The project manager coordinates the preparation of a project budget by providing cost estimates for the labor, equipment, and materials costs. The budget is used to monitor and control cost expenditures during project implementation. Implementation (Execution) Phase During the third phase, the implementation phase, the project plan is put into motion and the work of the project is performed. It is important to maintain control and communicate as needed during implementation. Progress is continuously monitored and appropriate adjustments are made and recorded as variances from the original plan. Throughout this step, project sponsors and other key stakeholders should be kept informed of the project’s status according to the agreed-on frequency and format of communication. The plan should be updated and published on a regular basis. Status reports should always emphasize the anticipated end point in terms of cost, schedule, and quality of deliverables. Each project deliverable produced should be reviewed for quality and measured against the acceptance criteria. Once all of the deliverables have been produced and the customer has accepted the final solution, the project is ready for closure. Closing.

Title of this process is The Project Life Cycle (Phases)The pr.pdf

arakalamkah11

The answer is A) Pol II, with twelve subunits on its own, is capable of initiating transcription. because it is composed with 12 subunits and due to incapable of specific promoter recognition it can\'t initiate transcription. Solution The answer is A) Pol II, with twelve subunits on its own, is capable of initiating transcription. because it is composed with 12 subunits and due to incapable of specific promoter recognition it can\'t initiate transcription..

The answer is A) Pol II, with twelve subunits on its own, is capable.pdf

arakalamkah11

solution: A= 1 1 0 4 3 1 2 0 5 Finding the determinant of the matrix ? det A = -3 The determinant of A is non-zero, hence the inverse matrix A-1 exists. To find the inverse matrix was calculated the minors and cofactors of the matrix ? M1,1 = 3 1 0 5 = 15 C1,1 = (-1)1+1M1,1 = 15 M1,2 = 4 1 2 5 = 18 C1,2 = (-1)1+2M1,2 = -18 M1,3 = 4 3 2 0 = -6 C1,3 = (-1)1+3M1,3 = -6 M2,1 = 1 0 0 5 = 5 C2,1 = (-1)2+1M2,1 = -5 M2,2 = 1 0 2 5 = 5 C2,2 = (-1)2+2M2,2 = 5 M2,3 = 1 1 2 0 = -2 C2,3 = (-1)2+3M2,3 = 2 M3,1 = 1 0 3 1 = 1 C3,1 = (-1)3+1M3,1 = 1 M3,2 = 1 0 4 1 = 1 C3,2 = (-1)3+2M3,2 = -1 M3,3 = 1 1 4 3 = -1 C3,3 = (-1)3+3M3,3 = -1 Matrix of cofactors: C = 15 -18 -6 -5 5 2 1 -1 -1 Transpose of cofactor matrix: CT = 15 -5 1 -18 5 -1 -6 2 -1 Finding the inverse matrix. A-1 = CT = det A -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 B) First, let\'s add the Identity Matrix to the right of our matrix 1 1 0 1 0 0 4 3 1 0 1 0 2 0 5 0 0 1 Now, let\'s do Gauss-Jordan Elimination on our new matrix... Add (-4 * row1) to row2 1 1 0 1 0 0 0 -1 1 -4 1 0 2 0 5 0 0 1 Add (-2 * row1) to row3 1 1 0 1 0 0 0 -1 1 -4 1 0 0 -2 5 -2 0 1 Divide row2 by -1 1 1 0 1 0 0 0 1 -1 4 -1 0 0 -2 5 -2 0 1 Add (2 * row2) to row3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 3 6 -2 1 Divide row3 by 3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 1 2 -2/3 1/3 Add (1 * row3) to row2 1 1 0 1 0 0 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 Add (-1 * row2) to row1 1 0 0 -5 5/3 -1/3 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 The inverse matrix can now be found in the right 3 columns of our reduced row echelon matrix Here is the inverse matrix: -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 A= 1 1 0 4 3 1 2 0 5 Solution solution: A= 1 1 0 4 3 1 2 0 5 Finding the determinant of the matrix ? det A = -3 The determinant of A is non-zero, hence the inverse matrix A-1 exists. To find the inverse matrix was calculated the minors and cofactors of the matrix ? M1,1 = 3 1 0 5 = 15 C1,1 = (-1)1+1M1,1 = 15 M1,2 = 4 1 2 5 = 18 C1,2 = (-1)1+2M1,2 = -18 M1,3 = 4 3 2 0 = -6 C1,3 = (-1)1+3M1,3 = -6 M2,1 = 1 0 0 5 = 5 C2,1 = (-1)2+1M2,1 = -5 M2,2 = 1 0 2 5 = 5 C2,2 = (-1)2+2M2,2 = 5 M2,3 = 1 1 2 0 = -2 C2,3 = (-1)2+3M2,3 = 2 M3,1 = 1 0 3 1 = 1 C3,1 = (-1)3+1M3,1 = 1 M3,2 = 1 0 4 1 = 1 C3,2 = (-1)3+2M3,2 = -1 M3,3 = 1 1 4 3 = -1 C3,3 = (-1)3+3M3,3 = -1 Matrix of cofactors: C = 15 -18 -6 -5 5 2 1 -1 -1 Transpose of cofactor matrix: CT = 15 -5 1 -18 5 -1 -6 2 -1 Finding the inverse matrix. A-1 = CT = det A -5 5/3 -1/3 6 -5/3 1/3 2 -2/3 1/3 B) First, let\'s add the Identity Matrix to the right of our matrix 1 1 0 1 0 0 4 3 1 0 1 0 2 0 5 0 0 1 Now, let\'s do Gauss-Jordan Elimination on our new matrix... Add (-4 * row1) to row2 1 1 0 1 0 0 0 -1 1 -4 1 0 2 0 5 0 0 1 Add (-2 * row1) to row3 1 1 0 1 0 0 0 -1 1 -4 1 0 0 -2 5 -2 0 1 Divide row2 by -1 1 1 0 1 0 0 0 1 -1 4 -1 0 0 -2 5 -2 0 1 Add (2 * row2) to row3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 3 6 -2 1 Divide row3 by 3 1 1 0 1 0 0 0 1 -1 4 -1 0 0 0 1 2 -2/3 1/3 Add (1 * row3) to row2 1 1 0 1 0 0 0 1 0 6 -5/3 1/3 0 0 1 2 -2/3 1/3 Add (-1 * row2) to row1 1.

solutionA= 1 1 0 4 3 1 2 0 .pdf

arakalamkah11

Q1). Gene therapy is an experimental approach to treat the disease by inserting therapeutic genes or changing gene expression levels in the patient’s cells. Genes are nucleic acid polymers; these therapeutic genes used in gene therapy generally encode a functional gene that replaces mutated gene. Potential treatment for single gene genetic disorders such as haemophilia, muscular dystrophy, cystic fibrosis, etc. was demonstrated. Treatment of cancer, AIDS (acquired immune deficiency syndrome), Alzheimer’s disease and rheumatoid arthritis are also under active investigation. All the diseases cannot be cured by gene therapy. Some of hte good targets of the gene therapy include, 1). Diseases with known genetic defects or mutations 2). Diseases with point mutations on one or more genes 3). The possibility of delivering genes to the affected tissues 4). If the substitution of defective gene correct the disease status Solution Q1). Gene therapy is an experimental approach to treat the disease by inserting therapeutic genes or changing gene expression levels in the patient’s cells. Genes are nucleic acid polymers; these therapeutic genes used in gene therapy generally encode a functional gene that replaces mutated gene. Potential treatment for single gene genetic disorders such as haemophilia, muscular dystrophy, cystic fibrosis, etc. was demonstrated. Treatment of cancer, AIDS (acquired immune deficiency syndrome), Alzheimer’s disease and rheumatoid arthritis are also under active investigation. All the diseases cannot be cured by gene therapy. Some of hte good targets of the gene therapy include, 1). Diseases with known genetic defects or mutations 2). Diseases with point mutations on one or more genes 3). The possibility of delivering genes to the affected tissues 4). If the substitution of defective gene correct the disease status.

Q1). Gene therapy is an experimental approach to treat the disease b.pdf

arakalamkah11

Solution : Three modes of DNA replication 1) Semi conservative: => Each daughter strand is composed of one old DNA strand and one new DNA strand. 2) Conservative: => The original double helix remains as complete unit. => The new DNA double helix is produced as a single unit. => The old DNA is completly conserved. 3) Dispersive mode: =>Separation of the individual covalent phosphodiester bonds is required for this mode of replication..

Solution Three modes of DNA replication 1) Semi conservative.pdf

arakalamkah11

package s3; // Copy paste this Java Template and save it as \"EmergencyRoom.java\" import java.util.*; import java.io.*; // write your matric number here: // write your name here: // write list of collaborators here: // year 2016 hash code: XAbyuzR78fXeaMHBdLan (do NOT delete this line) class patientlist { private String PatientName; private int emergencyLvl; public patientlist(String PatientName, int emergencyLvl) { this.PatientName = PatientName; this.emergencyLvl = emergencyLvl; } public String getPatientName() { return PatientName; } public void setPatientName(String PatientName) { this.PatientName = PatientName; } public int getEmergencyLvl() { return emergencyLvl; } public void setEmergencyLvl(int emergencyLvl) { this.emergencyLvl = emergencyLvl; } } class EmergencyRoom { // if needed, declare a private data structure here that // is accessible to all methods in this class private List patientlist; public EmergencyRoom() { // Write necessary code during construction patientlist = new ArrayList(); } void ArriveAtHospital(String patientName, int emergencyLvl) { // You have to insert the information (patientName, emergencyLvl) // into your chosen data structure if (patientName.length() > 15 || patientName.length() < 1) { System.out.println(\"patient name is either too long or too short.\ Please enter a name between 1 to 15 characters.\"); } else if (emergencyLvl > 100 || emergencyLvl < 30) { System.out.println(\"Emergency level is either too high or too low.\ Please enter a valid level between 30 to 100.\"); } else { int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { System.out.println(\"Patient already admitted\"); break; } } if (i == patientlist.size()) { patientlist p = new patientlist(patientName.toUpperCase(), emergencyLvl); patientlist.add(p); } } } void UpdateEmergencyLvl(String patientName, int incEmergencyLvl) { // You have to update the emergencyLvl of patientName to // emergencyLvl += incEmergencyLvl // and modify your chosen data structure (if needed) int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { //System.out.println(\"Patient already admitted\"); //break; if (incEmergencyLvl > 70 || incEmergencyLvl < 0) { System.out.println(\"Emergency level is either too high or too low.\ Please enter a valid increment between 0 to 70.\"); break; } else { patientlist.get(i).setEmergencyLvl(patientlist.get(i).getEmergencyLvl() + incEmergencyLvl); } } } } void Treat(String patientName) { // This patientName is treated by the doctor // remove him/her from your chosen data structure int i; for (i = 0; i < patientlist.size(); i++) { if (patientlist.get(i).getPatientName().compareToIgnoreCase(patientName) == 0) { patientlist.remove(i); } } } String Query() { String ans = \"The emergency room is empty\"; int i; if(patientlist.isEmpty()) return ans; else{ int max=patientlist.get(0).getEme.

package s3; Copy paste this Java Template and save it as Emer.pdf

arakalamkah11

Our body is having two line defence system against pathogens.Pathogens are micro-organisms such like virus,bactria,parasite,fungi. First line of defence system:- It is a outside defence system which protect body from the outside ,it includes skin ,tear,mucus,cilia,stomach acid,urine flow. Skin acts as a barrier between pathogens and your body. it stops all microarganisms to enter in to your body unless your skin get brokken.The pathogens can get enter through your nose ,eye,mouth, but through that if pathogen passes .Nose ,eye,mouth contains mucus,tear .they stop pathogen and break down their cell wall because they contain enzyme.those that are not killed immediately are trapped in mucus swallowed. cilia is present in our windpipe.it helps to move mucus and traped pathogens from lungs.Urine flow help to flush out pathogens from the bladder.stomach acid is present in stomach and helps to kill pathogens.this is the fine defence. Second line of defence system :- once pathogen cross your first line of defence second line of defence active for example ,through the cut pathogen enter into body and develope infection then second line defence active .Through a sequence of steps called immune response ,the immune system attacks these pathogens. In the second line of deffence system is a group of cells ,tissues,organs work together to protect the body .This is called immune system. The cells involved in the immune system called white blood cells is helps to destoys the desease causing organisms.there are different types of white blood cells but function is same that protect you from the organisms. They are neutrophiles,T-helper cells,Cytotoxic cells,marcophases,B-cells. These cells work together and kill the micro organism. Tissues and Organs :- This are involved in the immune system are the lymphatic system ,lymph nodes and lymp fluid.This are having specific function. Lymphatic system is a system of thin tube present through out the body .These tubes are called lymph vessels.they contain lymph. Lymph is a fluid that contains white blood cells. lymph helps to protect body form micro organisms. This is a second line of defence system. Solution Our body is having two line defence system against pathogens.Pathogens are micro-organisms such like virus,bactria,parasite,fungi. First line of defence system:- It is a outside defence system which protect body from the outside ,it includes skin ,tear,mucus,cilia,stomach acid,urine flow. Skin acts as a barrier between pathogens and your body. it stops all microarganisms to enter in to your body unless your skin get brokken.The pathogens can get enter through your nose ,eye,mouth, but through that if pathogen passes .Nose ,eye,mouth contains mucus,tear .they stop pathogen and break down their cell wall because they contain enzyme.those that are not killed immediately are trapped in mucus swallowed. cilia is present in our windpipe.it helps to move mucus and traped pathogens from lungs.Urine flow help to flush out.

Our body is having two line defence system against pathogens.Pathoge.pdf

arakalamkah11

Once neurons are produced, they migrate and modify to form six layered structure of cortex. The earliest formed neurons form the preplate which is then split into marginal plate and subplate by invading newly formed neurons. The neurons can have two origin: cortical ventricular zone and ganglionic eminences. The corticular neurons exhibit radial migration and form projection neurons while the ganglionic neurons exhibit tangantial migration and form interneurons. Both types arrange in inside out sequence and the early neurons form the deep layers while the late born neuron form the outer layers of cortex. Solution Once neurons are produced, they migrate and modify to form six layered structure of cortex. The earliest formed neurons form the preplate which is then split into marginal plate and subplate by invading newly formed neurons. The neurons can have two origin: cortical ventricular zone and ganglionic eminences. The corticular neurons exhibit radial migration and form projection neurons while the ganglionic neurons exhibit tangantial migration and form interneurons. Both types arrange in inside out sequence and the early neurons form the deep layers while the late born neuron form the outer layers of cortex..

Once neurons are produced, they migrate and modify to form six layer.pdf

arakalamkah11

PDU is called Protocol Data Unit.It consists of user data and protoc.pdf

arakalamkah11

1.A hole is the absence of an electron in a particular place in an atom.Electrons and holes do not move as rapidly through the solid materials as electrons do in a vaccum.The holes move more slowly than the electrons.The holes and electrons move in opposite direction. 2.Here if the electric current moving from left to right ,than the holes will be moving in opposite direction that is from right to left. Regardless of the semiconductor type ,with the potencial applied there will be net effect.Both electrons and holes contribute to total current flow,altough they are moving in opposite directions,they are of opposite charge. Solution 1.A hole is the absence of an electron in a particular place in an atom.Electrons and holes do not move as rapidly through the solid materials as electrons do in a vaccum.The holes move more slowly than the electrons.The holes and electrons move in opposite direction. 2.Here if the electric current moving from left to right ,than the holes will be moving in opposite direction that is from right to left. Regardless of the semiconductor type ,with the potencial applied there will be net effect.Both electrons and holes contribute to total current flow,altough they are moving in opposite directions,they are of opposite charge..

1.A hole is the absence of an electron in a particular place in an a.pdf

arakalamkah11

More from arakalamkah11 (20)

Particulars $Amount Direct materials 64452 Direct Labour (1332.pdf

Decrease in inventory Source of cash $ 440 Decrease in account.pdf

Diamond is sp3 covalent. It makes for bonds to ne.pdf

Too low. If you do not dry the sodium thiosulfate.pdf

1. E) The vapor pressure of a liquid.Increasing attractive intermo.pdf

Light is a form of energy that can be released by.pdf

1) Presence of jaws with paired fins in fish helps to feed them. Fin.pdf

Youre looking for Ka, the dissociation constant.pdf

Okay so dipole-dipole interactions would occur be.pdf

remote operating system installationRemote Installation Services (.pdf

Title of this process is The Project Life Cycle (Phases)The pr.pdf

The answer is A) Pol II, with twelve subunits on its own, is capable.pdf

solutionA= 1 1 0 4 3 1 2 0 .pdf

Q1). Gene therapy is an experimental approach to treat the disease b.pdf

Solution Three modes of DNA replication 1) Semi conservative.pdf

package s3; Copy paste this Java Template and save it as Emer.pdf

Our body is having two line defence system against pathogens.Pathoge.pdf

Once neurons are produced, they migrate and modify to form six layer.pdf

PDU is called Protocol Data Unit.It consists of user data and protoc.pdf

1.A hole is the absence of an electron in a particular place in an a.pdf

Recently uploaded

OS-operating systems- ch05 (CPU Scheduling) ...

Dr. Mazin Mohamed alkathiri

Andreas Schleicher presents at the launch of What does child empowerment mean...

EduSkills OECD

Trauma-Informed Leadership - Five Practical Principles

Pooky Knightsmith

會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文

中央社

會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽

中央社

PSYPACT- Practicing Over State Lines May 2024.pptx

Marlene Maheu

Spellings Wk 4 and Wk 5 for Grade 4 at CAPS

AnaAcapella

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

Pondicherry University

Mattingly "AI & Prompt Design: Named Entity Recognition"

National Information Standards Organization (NISO)

Observing-Correct-Grammar-in-Making-Definitions.pptx

AdelaideRefugio

Major project report on Tata Motors and its marketing strategies

AmanpreetKaur157993

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

Nguyen Thanh Tu Collection

How to Manage Website in Odoo 17 Studio App.pptx

Celine George

The Department of Emergency Medicine at Carolinas Medical Center is passionate about education! Dr. Michael Gibbs is a world-renowned clinician and educator and has helped guide numerous young clinicians on the long path of Mastery of Emergency Medical Care. With his oversight, the EMGuideWire team aim to help augment our understanding of emergent imaging. You can follow along with the EMGuideWire.com team as they post these educational, self-guided radiology slides or you can also use this section to learn more in-depth about specific conditions and diseases. This Radiology Reading Room pertains to Sternal Fractures and Dislocations and is brought to you by Carrie Bissell, MD, Aaron Fox, MD, Kendrick Lim, MD, Stephanie Jensen, MD, and Olivia Rice, MD. It is has special guest editor: Sean Dieffenbaugher, MD and Laurence Kempton, MD

Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room

Sean M. Fox

VAMOS CUIDAR DO NOSSO PLANETA! .

Colégio Santa Teresinha

An overview of the various scriptures in Hinduism

Dabee Kamal

ESSENTIAL of (CS/IT/IS) class 07 (Networks)

Dr. Mazin Mohamed alkathiri

Improved Approval Flow in Odoo 17 Studio App

Celine George

How to Send Pro Forma Invoice to Your Customers in Odoo 17

Celine George

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Limon Prince

Recently uploaded (20)

OS-operating systems- ch05 (CPU Scheduling) ...

Andreas Schleicher presents at the launch of What does child empowerment mean...

Trauma-Informed Leadership - Five Practical Principles

會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文會考英文

會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽

PSYPACT- Practicing Over State Lines May 2024.pptx

Spellings Wk 4 and Wk 5 for Grade 4 at CAPS

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

Mattingly "AI & Prompt Design: Named Entity Recognition"

Observing-Correct-Grammar-in-Making-Definitions.pptx

Major project report on Tata Motors and its marketing strategies

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

How to Manage Website in Odoo 17 Studio App.pptx

Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room

VAMOS CUIDAR DO NOSSO PLANETA! .

An overview of the various scriptures in Hinduism

ESSENTIAL of (CS/IT/IS) class 07 (Networks)

Improved Approval Flow in Odoo 17 Studio App

How to Send Pro Forma Invoice to Your Customers in Odoo 17

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf

1. 1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary storage for IO devices which is used to store sufficient amount of data before it is transferred to CPU. In a system, CPU communicates with the IO devices and vice versa and in order for a system to operate properly the devices must be in synchronization with the CPU. IO devices are usually slower than CPU e:g printer is slower than CPU and when CPU sends some data to be printed this data is stored in the buffer and then transferred to the printer with a speed suitable for printer. Similarly a buffer is used to temporarily store data being entered from a n input device like keyboard, which allows a large block of data to be keyed. held, and then transferred all at once to the CPU and in during the typing period CPU performs some other tasks. Benefits of IO Device Control Unit Buffer are Flow Control. (Modules canbuffer data until the adjacent module is ready to receive it), Better CPU utiization, BetterThroughput etc Solution 1. A bus is a bunch of wires used to connect multiple subsystems. Bus is a shared communication link for different devices. It allows easy addition of new devices and components in a system. Bus lines are divided into two types a) Control lines and b) Data lines. Control lines are used to control the information flow in the datalines between source and destination. 2. IO device Control unit is a unit responsible for handling the working of IO devices in a system. IO Device Control Unit receives the input and output requests from the central processor and send device-specific control signals to the device they control. The unit actually control the IO devices and thus relieves the cpu from the burden of controlling each IO device. Another key function of IO Device Control Unit is to convert the data which is read from input device or which is to be transferred to output device in appropriate form (human readeable to machine

2. redeable and vice versa) . 3. IO Device Control Unit Buffer is a special kind of temporary storage for IO devices which is used to store sufficient amount of data before it is transferred to CPU. In a system, CPU communicates with the IO devices and vice versa and in order for a system to operate properly the devices must be in synchronization with the CPU. IO devices are usually slower than CPU e:g printer is slower than CPU and when CPU sends some data to be printed this data is stored in the buffer and then transferred to the printer with a speed suitable for printer. Similarly a buffer is used to temporarily store data being entered from a n input device like keyboard, which allows a large block of data to be keyed. held, and then transferred all at once to the CPU and in during the typing period CPU performs some other tasks. Benefits of IO Device Control Unit Buffer are Flow Control. (Modules canbuffer data until the adjacent module is ready to receive it), Better CPU utiization, BetterThroughput etc

1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf

Recommended

Recommended

More Related Content

Similar to 1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf

Similar to 1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf (20)

More from arakalamkah11

More from arakalamkah11 (20)

Recently uploaded

Recently uploaded (20)

1. A bus is a bunch of wires used to connect multiple subsystems. Bu.pdf