Venus Day Period Analysis

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Venus Day Period Analysis
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –3rd
May 2021
1- Abstract
Paper question
- Can The Motion Be Transported From A Solar Planet To Another?
The Question Explanation
- The planets use (8 days and 6 days) cycles and these cycles refers to a form of the
transportation of motion among the solar planets
- The motion transportation is done based on different rates of time found among the
planets
- Based on that
- 1 hour of Mercury motion be equivalent to 24 hours of Uranus motion
- And because
- (Venus velocity / Mercury velocity) = 0.738
- 1 hour of Venus motion be equivalent to 17.7 hours of Uranus motion
- This claim should be the paper hypothesis, where the paper tries to prove this fact
- By proving the different rates of time (specifically 1 hour of Venus Motion = 17.7
hours of Uranus Motion), that gives a reference of mutual effect of planets motion
on one another which gives support for the motion transposition claim.
- Shortly
- The paper tells that, the motion is transported among the planets by some
geometrical rule unknown for us.

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Contents
Subject Page no.
1- Abstract 1
Contents 2
2- The Solar Group is a Clock (A General Description) 3
3- Venus Rotation Period Analysis 9
4- Venus And Uranus Motions Interactions 35
5- (1 hour of Venus Motion = 17.7 hours of Uranus Motion)
(More Proves)
54
References 58

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2- The Solar Group is a Clock (A General Description)
2-1 The main Idea
2-2 The difficulties to accept the description
2-3 The proving method
2-1 The Main Idea
- The solar group works as a machine of gears each planet transports the motion to
another planet
- The motion transportation among the Planets create different rates of time for the
planets motions
- Because of that, the second period of time be different from a planet to another (for
example 1 second of Mercury motion = 24 seconds of Uranus motion)
- The solar planets works as one team and use a motion of 1 second period of time
to cause another motion of (86400 seconds).
- i.e.
- The machine input is a motion done in 1 second and its output is a motion done in
a solar day.
- By that, the solar group works as A Mechanical Clock
- The planets different rates of time depend on their velocities and that means, where
Venus velocity =35 km/s and Mercury velocity =47.4 km/s, because of that, 1 hour
of Mercury motion will be equivalent to 1.354 hours of Venus Motion – that tells –
based on the planets velocities their rates of time is created.
- But
- This rule has an exception, because, the greatest velocity (Mercury) =47.4 km/s
and the smallest velocity (Pluto) = 4.7 km/s and the rate between them = 10.08 and
based on the rule, each 1 hour of Mercury motion be equivalent to 10.08 hours of
Pluto motion, where this rate (10.08) is the max rate can be available based on the
planets velocities

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- Where this very limited rate (10.08) and the solar group uses a motion of 1 second
to cause a motion of 1 solar day, So, this task can't be limited to the planets
velocities…!
- The dilemma is solved by unification between several planets motions, for
example, the total velocities of (Mercury + Venus + Earth) = 112.2 km/s where
Pluto velocity =4.7 km/s, so the rate between both values (122.2/4.7) = 24 and that
means each 1 hour of the 3 planets velocities total be equivalent to 24 hours of
Pluto motion and by that the rate 1: 24 be created.
- This paper discusses the rate (1: 24) to define how this rate be used in the solar
system motion
- The rate 1 hour be equivalent to 24 hours is used between 3 planets groups which
are:
o 1 Hour Of Mercury Motion = 24 Hours Of Uranus Motion
o 1 Hour Of Mars Motion = 24 Hours Of The Earth Moon Motion
o 1 Hour Of the 3 planets velocities total = 24 Hours Of Pluto Motion
- The previous description provides a new idea about the solar system motion, and
many difficulties are found to accept this description, we need to define these
difficulties and prove that the idea can be fact and proved by the planets motions
data…
- Let's discuss the idea difficulties in the next point…

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2-2 The Difficulties To Accept The Description
- The motion transportation concept is a new idea and shows great difficulties
because the planets are not gears
- How the motion is transported from a planet to another?
- Let's try to answer in following
o I have discovered planets motion cycle depend on 8 planets days
o And
o I have discovered planets motion cycle depend on 6 planets days
o Of course the planets aren't gears, but the cycles of (8 and 6 days) show that
equal distances are passed by the planets in defined periods of time, for
example the distance Jupiter passes during 8 Jupiter days = The distance
Saturn passes during 10 Saturn days = The distance Neptune passes during
12 Neptune days (this cycles are explained in full details in this paper)
o Because the distances equality is used frequently in the solar planets
motions we have to consider that some transportation of motion is done
among the planets, even if we can't catch the geometrical mechanism by
which this transportation of motion is done but the process is still fact
because of the distances equality using
o If we refuse the motion transportation hypothesis we should answer the
question why these distances are equal
o I want to say that, the distances equality is a proof for the motion
transportation based on some geometrical rule which we don't know yet but
when this rule be discovered the distances equality will be the prove for the
motion transposition process.
o The cycles are explained in point no. (3) of this paper in details, I tried to
summarize the whole idea before the cycle details discussion to explain for
what reason we analyze the cycles

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2-3 The Proving Method
- If 1 hour of Mercury Motion be equivalent to 24 hours of Uranus Motion, how can
we prove that?
- Let's summarize the proving method in following
o I suggest a hypothesis that (1 hour of Mercury motion =24 hours of Uranus
Motion) (This rate doesn't depend on the direct velocities rate between
Mercury and Uranus, where Mercury velocity = 7 Uranus Velocity)
o The Planet rate of time is created usually based on the planets velocities
o By that 1 hour of Mercury Motion = 1.354 hours of Venus Motion
o But
o 1 hour of Mercury motion =24 hours of Uranus Motion
o Based on that
o 1 hour of Venus motion must be = 17.7 hours of Uranus Motion
o How to prove these rates?
o In Uranus motion data, Uranus Mercury data should show the rate 24 but
Uranus Venus Data should show the rate 17.7
o Shortly
o If we find the rate 24 in Mercury Uranus Motions data and the rate 17.7 in
Venus Uranus Motions data, that provides a proof for the paper hypothesis.
o Let's use one example
o Mercury Uranus Distance = 2815 mkm
o Suppose each 1 mkm = 1 hour
o So, the value 2815 mkm will be = 2815 hours
o But
o Mercury rotation period =1407.6 hours
o means, the period 2815 hours = 1407.6 hours x 2
o but

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o Mercury moves during its rotation period (1407.6 hours) a distance = 243
mkm (error 1%)
o Venus rotation period =243 solar days
o Means, the distance 243 mkm be used as 1 mkm for 1 solar day
o By that, Mercury rotation period defines 2 different periods for the same
distance (1mkm) which creates the rate 1 hour be equivalent to 24 hours
o This example shows the proving method and test its credibility.
Notice
- Because we don't know the geometrical rule based on which the motion is
transported and don't know how the different rates of time is created by this motion
transportation process, we have to depend on the planets data analysis
- The planets data analysis isn't a weak method of proof, the following example can
support this meaning
o The value 12430 km is the middle rate between Venus diameter 12104 km
and Earth diameter 12756 km
o There's no planet its diameter =12430 km, this value is defined as the middle
rate between the 2 planets diameters but
o Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km
o Saturn (9.7 km/s) moves during 12430 seconds a distance = 120536 km
o Where
o 300000 km = light motion distance for 1 second
o 120536 km = Saturn diameter
o The data shows the value (12430 km) behaves as any planet, for example
o (Jupiter moves during 10921 seconds a distance = Jupiter diameter where
10921 km = the moon circumference) and
o (Uranus moves during 7510 seconds a distance = Uranus diameter where
7510 km = Pluto Circumference).

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The Solar Planets Data Creation
- The solar planets is similar to a puppets theater, or
- The solar group is similar to one building and each planet is a part of this same
building
- Because of that the planets are parts in the same building or members in the same
creature body
- Also because of that, the planets move together one unified motion as train
carriages.
- Based on that
- The solar planets data are created complementary to each other and because of
that we can conclude the absent data based on the found data analysis…
- The best example to explain (the complementary data meaning) is the double
production experiment, in which from a gamma ray electron and positron are
created, each particle charge is created depending on the other particle change
because of the charge reservation law
- Similar to that, each planet data is created complementarily with the other planets
data, to save the motions general harmony
- This description can help greatly our hypothesis that, the solar group is similar to a
great clock.
- Although this description is so interesting and useful but many difficulties are still
face us because the motion transportation proves is complex to be defined
- One more difficulty we have to face is that, the planet diameter definition, because
the planet diameter is used as a period of time in its motion and we can't catch how
the planet diameter be defined as a function in its motion and velocity (that means
Venus diameter =12104 km because Venus velocity =35 km/s) (This point we
discuss in Venus & Uranus motions interaction).

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3- Venus Rotation Period Analysis
3-1 Planets Motions (8 days Cycle)
3-2 Earth Velocity Per A Solar Day
3-3 Venus Rotation Period Origin
3-5 Saturn orbital Distance 1433.5 mkm
3-6 The Distance 243 mkm
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km passed also by Saturn and Neptune with a rate 80%
depends on one another as following
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %)

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(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km = (Jupiter diameter error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance passed by Uranus during 8 Pluto days equal the distance
passed by Jupiter during 64 Jupiter days and equal the distance passed by Saturn
during 80 Saturn days and equal the distance passed by Neptune during 100
Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider that they
are equal distances
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference

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The Discussion:
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance passed by Jupiter in 8 Jupiter days will be equal the distance passed
by Saturn in 10 Saturn days and be equal the distance passed by Neptune during 12
Neptune Days
- The motion depends on the cycle (8 days) because Jupiter is the master motion in
this team and the 2 other planets follow its motion (according to the provided data
analysis)
- Why these 3 planets move equal distances? We still search for an answer … but
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- Why the difference = the moon circumference? We still search for answer, but, the
moon circumference itself tells that it's a cycle because if it's not a cycle we would
find a part of the moon circumference
- (as in Earth motion… earth orbital period 365.25 days, but we don't consider this
0.25 day because it has no definition, each 4 years, we consider it as (1 day) and by
that we know Earth has a cycle of 4 years because this (1 day) is defined but the
(0.25 day) isn't defined)
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km

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- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km = Jupiter Diameter 1%)
- Based on that
- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- The cycle depends on (8 days) and connect between Jupiter and Uranus motions as
the 2 heads of the 2 teams and by that the 5 planets motions be in harmony
- Why this cycle (8 days) is required?
- We need to analyze the produced distances to answer this question – so this
process will be done with the next point (3-3 Venus Rotation Period Origin)
- What we know now is that, the planets move equal distances in defined periods of
time following a cycle depends on 8 days (between Jupiter and Uranus) then this
cycle be seen in Saturn as (10 days) and in Neptune as (12 days), it's the same
cycle but it be modified to be suitable for the planet motion and velocity
- The point is that, the planets move based on a geometrical design, and not by a
direct effect of force – that means- the planets move as trains on railways and not
move as cars by their own engine – the planets move on designed geometrical
map.

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3-2 Earth Velocity Per A Solar Day
I- Data
Group No. (I)
(a)
Earth moves per a solar day (24 h) a distance = 2574720 km
(b)
Pluto moves during its day period (153.3 h) a distance = 2593836 km
(c)
The moon displacements total during its day period (29.53 days) = 2598693 km
(d)
Uranus moves during 378675 seconds a distance = 2574990 km
Group No. (II)
(e)
Jupiter moves during its day period (9.9 h) = 466884 km
(f)
Neptune moves during the solar day = 466560 km
II- Discussion
- Group no. (I) shows that,
- Earth, Pluto and the Earth moon motion distances during their days periods are
equal (where the difference between them isn't greater than 1%)
- Still the (small) differences have geometrical meaning
- For example
- The moon displacements total (2598693 km) – Pluto distance (2593836 km) =
4857 km (where Mercury Diameter = 4879 km error 0.4%)
- It's almost a general feature that, 2 planets move 2 equal distances in 2 defined
periods of time where these 2 equal distances have (a small) difference which be
another planet diameter or circumference …why?

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- Earth motion distance per a solar day discussion is found here to create an
extension for our discussion that because the (8 days) cycle provides us some new
behavior of data and I try to show that this behavior is used usually in the solar
system motion
- It's noticeable that, Pluto day period is so long day period in comparison with the
outer planets, and Pluto moves during its day period a distance = Earth motion
distance during its day period – is there any relationship between these 2 facts?
Means, is there any geometrical necessity for which Pluto day period should be so
long to enable Pluto to move a distance = Earth motion distance during its day
period? Why does Pluto need to do that? what's the geometrical benefits behind?
Notice (1)
- (b) (Pluto motion) - (a) (Earth motion) = 19116 km
- Where 19116 km x 2 = 38232 km (= Venus Circumference 38025 km error 0.5%)
- This same difference be between Uranus and Pluto motions,
- That means, Venus diameter is a value mentioned by the 3 planets motions (Earth,
Uranus and Pluto).
Notice (2)
- (c) (the moon displacements) - (a) (Earth motion) = 23973 km
- Where
- The moon displacements total = 2598693 km
- The moon orbital apogee circumference = 2550973 km
- The difference = 47720 km
- But
- 23973 km x 2 = 47946 km
- Data Group no. (II) tells a similar message,
- Some deep relationship is found between Neptune and Jupiter motions,
- the question is that, why Jupiter moves during its day period a distance = Neptune
motion distance during the solar day?!

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2-3 Venus Rotation Period Origin
I- Data
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Data Analysis
(2) - (1) = 10921 km = The Earth Moon Circumference
(4) – (1) = 141516 km = Jupiter Diameter (error 1%)
(3) – (4) = 1276128 km = π x 406204 km
(4) – (3) = 130752 km = notice (406000 km = π x 129234 km)
(3) – (1) = 1417644 km
(3) – (2) = 1406880 km
- The difference between 130752 km and 129234 km =1518 km
- During (8 cycles) this value (1518 km) will be = (12104 km Venus diameter)
- In the next data (after discussion) we will use the (8 cycles) to see how to create
the difference 12104 km
- Let's start our discussion

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II- Discussion
- The rule became clear, that, different planets move equal distances during defined
periods of time
- Although the distances are equal because the difference between them is less than
1% but the (small) differences between them show geometrical effects
- Usually these small differences be = planets diameters or circumferences and
sometimes equal planets motions distances during the solar day or during these
planet days periods
- Why? is the question which we search to answer
- In the previous data
o The difference between Uranus motion (no 4) and Jupiter motion (no.1) =
141516 km = Jupiter diameter (1%)
o Because of this value (141516 km) we conclude a cycle of (8 days) is found
here because during 8 days this distance (141516 km) is accumulated (8 x
17690 km) and be completed after 8 days cycle and by that we concluded
the (8 days cycle)
o The difference between Saturn (29891520 km) and Jupiter (29880756 km) =
10921 km = The Earth Moon Circumference
Notice
- Pluto moves during its day period a distance = 2593836 km
- But
- Uranus moves during Pluto day period a distance = 3752784 km
- The difference = 1.16 mkm (the distance passed by Jupiter during Mars rotation
period).

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In following we use (8 days Cycle)
I- Data
(5)
Jupiter moves during (512 Jupiter days = 64 d x 8) a distance = 239.0446 mkm
(6)
Saturn moves during (640 Saturn days = 80 d x 8) a distance = 239.13216 mkm
(7)
Neptune moves during (800 Neptune d= 100 x 8) a distance = 250.3872 mkm
(8)
Uranus moves during (64 Pluto days = 8 d x 8 ) a distance =240.17818 mkm
(9)
Mercury (47.4 km/s) moves during (1407.6 h) a distance =240.192 mkm
(10)
Mars (24.1 km/s) moves during (2802 h) a distance =243.10152 mkm
(11)
Neptune (5.4km/s) moves during (12430 hours) a distance = 241.6392 mkm
Data Analysis
(6) (Saturn motion) – (5) (Jupiter Motion) = 87550 km
(The moon daily displacement =88000 km)
(8) (Uranus Motion) - (5) (Jupiter Motion) = 1.133566 mkm
(Jupiter motion distance per solar day = 1131840 km )
(8) (Uranus motion) – (6) (Saturn Motion) = 1.04602 mkm
Where
((8 x 406000 km) /π) = 1033870 km
And 1046020 – 1033870 km = 12150 km (Venus diameter = 12104 km)
406000 km = the moon apogee radius = Pluto motion distance during a solar day

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(9) (Mercury Motion) – (5) (Jupiter Motion) = 1148252 km = π x 365500 km
(The outer planets diameters total = 366556 km)
(9) (Mercury Motion)– (6) (Saturn Motion) = 1060700 km
(where 1067148 km x 2 = 2134256 km Mars motion distance during Mars rotation
period)
(10) (Mars Motion) – (5) (Jupiter Motion) = 4.056912 km
(= 4.095 mkm = Mercury velocity per solar day error 1%)
(10) (Mars Motion) - (11) (Neptune Motion) = 1.46232 mkm = π x 466556 km
(Neptune Velocity Per Solar Day =466556 km)
(11) (Neptune Motion)– (5) (Jupiter Motion) =2.594592 mkm
(Pluto motion distance during its day period = 2.593836 mkm)

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II- Discussion
- We used the (8 days Cycle) for the distances we have discussed because the
difference 1518 km will be = 12104 km (Venus Diameter) during (8 days Cycle)
- By performance this objective we have found that,
- The planets move a distance = 243 mkm (Approximately) (error in range 1%)
- And we know that,
- Mercury moves during its rotation period (1407.6 h) a distance = 240.2 mkm
- And
- Mars moves during Venus day period (2802 h) a distance = 243.1 mkm
- For that reason I have added them to our data to see what message is told by this
data…
- What does message the data tell us?
- Notice No. 1
- The distance passed by Saturn during (80 Saturn days) = 29891520 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880756 km
- The difference = 10921 km = the Earth moon circumference
But
- The distance passed by Saturn during (80 Saturn d x 8) = 239132160 km
- The distance passed by Jupiter during (64 Jupiter d x 8) = 239044608 km
- Where
- The moon displacement per a solar day = 88000 km
- Simply 88000 = 10921 km x 8
- But
- We should ask, does this cycle different distances mentioned the moon
circumference and motion per a solar day or the values be created by chance?

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- Notice No. 2
- The distance passed by Uranus during (8 Pluto days) = 30022272 km
- The distance passed by Jupiter during (64 Jupiter days) = 29880576 km
- The difference =141696 km (= Jupiter diameter error 1%)
But
- The distance passed by Uranus during (8 Pluto days x 8) = 240178176 km
- The distance passed by Jupiter during (64 Jupiter days x 8) = 239044608 km
- Where
- Jupiter motion distance per a solar day =1131800 km
- Simply 1131800 = 141696 km x 8
- The data tells, the planets diameters and their motions distances per solar day are
defined based on geometrical rules
Notice (3)
- Mercury moves during its rotation period (1407.6hours) a distance = 240.192 mkm
- Mercury Jupiter Distance =720.7 mkm
- But
- 720.7 mkm = 3 x 240.192 mkm
- i.e.
- 2 x 720.7 mkm = 6 x 240.192 mkm
- But Mercury Jupiter distance (720.7 mkm) must be used in double value (2 x 720.7
mkm) because it creates 180 degrees through the sun (for a complete revolution)
- That means, the distances (2 x 720.7 mkm and 240. 19 mkm) are defined relative
to each other based on the rate (6) which shows the Cycle (6 periods) (this cycle
will be discussed in this current paper).

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- Notice No. 4
- The distance passed by Uranus during (64 Pluto days) = 240178176 km
- The distance passed by Mercury during (1407.6 hours) = 240192864km
- Where
- 88000 km (the moon daily displacement) = 6 x 14688 km
- That tells, a cycle of (6 days Period) is used to create the distance (88000 km)
depends on this difference (14688 km)
- Based on that we have to review Then (6 days Cycle) and show if it can help to
perform this process.

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Preface
- Uranus (6.8 km/s) moves during its day period (17.2 h) a distance = 421056 km
- Venus (35 km/s) moves during 12104 seconds a distance = 423640 km
- Pluto (4.7 km/s) moves during 90560 seconds a distance = 425632 km
- Where
- 12104 km = Venus Diameter
- 90560 days = Pluto orbital Period
- The previous data gives the base on which the (6 time units Cycle) is created – and
based on that, the provided data uses (6 Uranus days 10.3h) and (6 x 12104 s) and
(6 x 90560 s) to pass the mentioned distances and creates the defined differences
- Based on that,
(1)
Venus (35 km/s) moves during 12104 seconds (x 6) a distance = 2541840 km
Uranus moves during 6 Uranus days period (103.2 h) a distance = 2526336 km
2541840 km – 2526336 km = 15504 km (Mercury Circumference error 1%)
(2)
Pluto (4.7 km/s) moves during 90560 s x 6 a distance = 2553792 km
Venus (35 km/s) moves during 12104 seconds (x 6) a distance = 2541840 km
2553792 km – 2541840 km = 11952 km (Venus Diameter 12104 km error 1.2%)
(3)
Pluto (4.7 km/s) moves during 90560 s x 6 a distance = 2553792 km
Uranus moves during 6 Uranus days period (103.2 h) a distance = 2526336 km
And
2553792 km – 2526336 km = 27456 km (= 86400 km /π)
(4)
Jupiter (13.1 km/s) moves during (6) of Jupiter days (59.4 h) a distance = 2.8 mkm =
2π2
x 142984 km (Jupiter Diameter)

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(5)
Neptune (5.4 km/s) moves during (6) of Neptune days (96.6 h) a distance = 1.87 mkm
= Jupiter (13.1 km/s) motion distance during 142984 seconds.
Basic Questions
- The cycle of (6 units) doesn’t depend on planet day period Why?
- Because
o The planet diameter is used as a period of time, and also planet orbital
period is a period of time
o These all data consist together the planet motion required periods of time
but in categories- as we have seen in Saturn analysis – let's remember it
o Saturn day period =10.7 hours but Saturn diameter =120536 km and can be
used as 120536 seconds where 10.7 h x 3600 s x π = 120536 s
o That means, Saturn diameter in fact = Saturn day period but be seen in
another form – Saturn orbital period should be a third form for the same
period of time
o But we have no equation can express these 3 values in each planet..! that's
the difficulty because we don't know the geometrical rule based on which
the planet diameter is created (again we need to ask, how the matter is
created?)
Notice
- Pluto moves during (6 x 90560 s) a distance = 2553792 km
- Pluto moves during its day period (153.3 h) a distance =2593836 km
- The difference = 40080 km = Earth Circumference
- Please remember 40080 km = the 5 inner planets diameters total

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The Cycle Discussion
I-Data
(A)
Venus motion distance during its day period = 352.6 mkm
But
2115 mkm = 6 x 352.6 mkm (2136 mkm =680 mkm x π)
(B)
1458 days = 6 x 243 days (Venus Rotation Period)
(C)
18048 mkm (Uranus orbital Circumference) = 6 x 3030 mkm (error 1%)
(D)
30589 days x 6 = 366556 days
And 742 days x 6 = 4452 days
(E)
175.94 days = 6 x 29.32 days
II-Discussion
- Let's analyze the data as possible in following…
o Pluto motion during (6 x 90560 s) pass a distance = 2553792 km
o Pluto moves during its day period (153.3h) a distance = 2593836 km
o Uranus moves during (153.3 h) a distance = 3752784 km
But
o 2593836 km – 2553792 km = 40044 km (Earth Circumference)
o Venus moves during (6 x 12104 s) a distance = 2541840 km
Where
o 2541840 km – 2553792 = 12104 km (Venus Diameter) (error 1.2%)
o That makes Pluto in specific position, so let's analyze it in following:

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Pluto Positions In 3 Different Cycles
(1st
Cycle)
- Pluto (4.7 km/s) moves during its day period (153.3 h) a distance =2593836 km
(2nd
Cycle)
- Pluto (4.7 km/s) moves during (6 x 90560 seconds) a distance =2553792 km
(3rd
Cycle)
- Uranus (6.8 km/s) moves during (153.3 h) a distance = 3752784 km
- Let's write a word to remember each cycle in following
o (1st
Cycle) Pluto moves the distance 2593836 km which is equal earth
motion distance during its day period = the moon displacements total
during 29.53 days = Uranus motion distance during (378675 seconds)
o (2nd
Cycle) Pluto moves the distance 2553792 km during the cycle of (6
units) in which Uranus, Venus and Pluto moves equal distances, where
Uranus uses (6 of its days) and Venus uses (6 x 12104 seconds) and Pluto
uses (6 x 90560 seconds)
o (3rd
Cycle) Uranus motion during Pluto day period a distance = Jupiter
motion distance during (8 Jupiter days) = Saturn motion distance during (10
Saturn days) = Neptune motion distance during (12 Neptune days) – by this
cycle Uranus causes Pluto day to be =153.3 hours.
- In this analysis we interest for the following
o 2593836 km – 2553792 km = 40080 km = Earth Circumference
o This is very important because the 2 distances are passed by Pluto motion
during 2 different cycles periods – that makes the 2 cycles as 2 walls to
define the distance 40080 km clearly
o Also, The Earth Circumference = Mercury diameter+ Venus diameter +
Earth diameter + the moon diameter + Mars diameter

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A Question
Why does Pluto 2 motion distances difference = Earth Circumference?
- 2593836 km – 2553792 km = 40080 km = Earth Circumference
- In what period of time this difference is found?
- (153.3 hours) – (6 x 90560 seconds) = 8520 seconds
- Pluto (4.7 km/s) moves during 8520 s a distance =40044 km= Earth Circumference
- Is this period 8520 seconds so specific?
Saturn Day Period =10.7 hours
- 10.7 hours x 3600 = 38520 seconds
- That means
- 38520 seconds – 8520 seconds = 30000 seconds ( Zero Error)
- Can we use 10 Saturn days? Yes, Why?
- Because
- Uranus motion distance during (Pluto day period 153.3 h) = Jupiter motion
distance during (8 Jupiter days) = Saturn motion distance during (10 Saturn days)
= Neptune motion distance during (12 Neptune days)
- So during 10 Saturn days
- 10 x (10.7 hours) x 3600 = 10 x (38520 seconds - 8520 seconds) = 300000 s
- Why we need this value 300000 seconds? Because
Mercury Day Period =176 solar days – 5040 seconds
- 5040 minutes x 0.99 = 4990 minutes
- 4990 minutes x 60 s = 299400 seconds (approximately = 300000 seconds)
- Why do we need that?
- Because Mercury Day Period is less than 176 solar days by 5040 seconds because
of Saturn motion. (Specifically, because Saturn motion distance during its day
period less with 5040 km than its Circumference).

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Notice (1)
- Pluto moves during 8520 seconds a distance = Earth Circumference
- But
- Mercury (47.4 km/s) moves during 8520 seconds a distance = 404000 km = Earth
Moon distance at apogee radius (r =406000 km error = 0.5%)
- Please remember that
o The moon displacements total during 29.53 days = 2598693 km
o This distance should be the moon orbital circumference and where
o 2598693 km = 2π x 413600 km
o That means, the moon apogee radius have to be = 413600 km but
o The moon uses Pythagorean rule and by that could decrease this distance
413600 km to be only 406000 km
o The previous data tells us this decreasing is done depends on the period
8520 seconds by Mercury Motion.
But why Mercury motion is used here?
- Because
- Mercury (47.4 km/s) moves during 366556 seconds distance = 17.37 mkm
- And
- (366556 km /Pluto diameter 2390 km) =153.3 (where Pluto Day Period =153.3h)
- (366556 km /The moon diameter 3475 km) =105.5 And (105.5 x 2π =663 km)
- Where the Moon Rotation Period =655.7 hours. (error 1%)
- (366556 km = the outer planets diameters total)
Where
- The moon orbit inclination (5.1 deg) is created depends on (17.2 deg), and as a
result of the moon orbital inclination creation, the moon orbit radius is decreased
from 413600 km to 406000 km – this process is done by Mercury motion during
366556 seconds –
Also 366556 days = 6 x 30589 days (Uranus Orbital Period)

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Notice (2)
- Pluto moves during 8520 seconds a distance = Earth Circumference
- Pluto moves during 8520 Minutes a distance = 2.4 mkm = the moon motion
distance during a solar day
- Pluto moves during 8520 hours a distance =144 mkm = Mars displacement from
its original orbital distance (84 mkm) to its current orbital distance (227.9 mkm)
- Pluto moves during 8520 days a distance =3475 mkm = the moon diameter 3475
km x 1 mkm.
Notice (3)
- Light known velocity (0.3 mkm/s) moves during (2 x 8520 seconds) a distance =
5127 mkm (Jupiter Pluto Distance)
- This data is important because it tells there's some reason to use (2) values of this
value (8520 seconds)
- The value (8520 seconds) is the difference (Pluto day period 153.3 hours) and (a
period = 6 x 90560 seconds where 90560 days Pluto orbital period)
- The data tells there's some reason to use the double value (2 Pluto days – 12 x
90560 seconds), let's see why it should be
o During (2 Pluto days 153.3 h x 2) Pluto moves a distance = 5.187672 mkm
o During (12 x 90560 seconds) Pluto moves a distance =5.107584 mkm
o 2 Pluto days 153.3 h x 2) Pluto moves = 5.187672 mkm
o The difference = 80088 km = 4 Earth Circumferences
o Why the period (2 Pluto days) or (12 x 90560 s) is required?
o Because the moon orbital inclination =5.1 deg =5.1 mkm
o That means
o The moon orbital inclination creation needs double value of the distance by
which the moon orbital circumference is created…
Notice (4)
- 12 x 90560 seconds = 224.7 sec x 4846 = 243 sec x 4472

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Notice (5)
- Venus moves during (12104 s x 12) a distance = 5083680 km
- But
- 47720 km = 2 x 23860 km
- (47720 km is the difference between the moon displacement total and the moon
orbital circumference)
- That tells we need a double value?!!
- So
- Venus moves during (12104 s x 24) a distance = 10167360 km
- The difference = 47808 km (equal approximately the distance 47720 km)
Notice (6)
- Uranus moves during its day period a distance =421056 km
- Saturn moves during its day period a distance = 373644 km
- That tells
- This value 47720 km is created as a difference between Uranus and Saturn motion
during their days periods – but this is done as a general concept – the direct effect
is done by the difference of motion between Venus and Pluto motions.
- That means, there's one geometrical context by which this process is done…
Notice (7)
- Uranus moves during (24 of its days periods) (= 412.8 h) a distance = 10.105 mkm
- Pluto moves during (24 x 90560 seconds) a distance = 10.215168 mkm
- The difference = 1% (accurately) = (109824 km) = (6.8 x51118)/π (0.7%)

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Let's complete our data discussion in following…
Equation (A)
Venus motion distance during its day period = 352.6 mkm
But 2115 mkm = 6 x 352.6 mkm (2136 mkm =680 mkm x π) (1%)
- 2094 mkm = Jupiter Uranus Distance
- The Equation shows that, the (6) cycles effects on Venus distances
Equation (B)
1458 days = 6 x 243 days (Venus Rotation Period)
- Where
- 1461 days = earth cycle
- There's 3 days different and this value needs more analysis to know why this
difference is found.
Equation (C)
18048 mkm (Uranus orbital Circumference) = 6 x 3030 mkm (error 1%)
- 3030 mkm = Uranus Pluto Distance
- Equation no. (6) tells that Uranus orbital circumference depends on the distance
between Pluto and Uranus based on the Cycle (of 6 units)
Equation (D)
30589 days x 6 = 366556 days And 742 days x 6 = 4452 days
- Where
- 30589 days = Uranus Orbital Period
- 366556 km = the outer planets diameters total
- 742 seconds = (Uranus day period 17.2 h) – (2 x 30589 sec).
- 4495.1 mkm = Neptune Orbital Distance

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Equation (4)
Jupiter (13.1 km/s) moves during (6) of Jupiter days (59.4 h) a distance = 2.8 mkm =
2π2
x 142984 km (Jupiter Diameter)
Equation no (8) shows the cycle (6 units) effect on Jupiter motion
Equation (5)
Neptune (5.4 km/s) moves during (6) of Neptune days (96.6 h) a distance = 1.87 mkm
= Jupiter (13.1 km/s) motion distance during 142984 seconds.
Equation no. (9) shows that, Neptune uses the cycle as (6Neptune days) but the
distance depends on Jupiter and not on Uranus - some interaction must be found
behind this data – and the interaction between Uranus and Jupiter (through Pluto day
period) is very useful to understand this relationship.
Equation (E)
175.94 days = 6 x 29.32 days
- Where
- 175.94 days = Mercury day period
- The moon day period =29.53 days and the value 29.32 days is different by around
0.7%).
- (142984 km Jupiter diameter/4879 km Mercury diameter) = 29.32
Notice
- Jupiter moves during 2 Saturn days a distance = 1 mkm (error 1%)
- The moon moves during 2 Saturn days a distance = Mars motion distance during
Mars day period
- Mercury moves during 2 Saturn days a distance =3.65 mkm

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The two Cycles Motions Interaction
I- Data
Equation No. (1)
2 x 6 x 243 days = ( 2 x 1461 days) – 6 days
Equation No. (2)
2.908660 mkm x 2π = 18.275 mkm = 3.02 mkm x 6
- Where
- 1461 days = Earth Cycle (365 +365 +365 +366 )
- 2.908660 mkm = Mars motion during (116.7 days) – Mercury motion during
(58.66 days)
II- Discussion
- The 2 cycles discussion follow Venus rotation period as a basic value (243 days
which is equivalent to 243 mkm)
- The previous 2 equations show that, Venus connects between the 2 cycles (8 days
cycle) and (6 days cycle)
- This connection is done for Venus rotation period as a targeted value
Equation No. (1)
2 x 6 x 243 days = ( 2 x 1461 days) – 6 days
- Earth Cycle for (8 years = 2 x 1461 days) depends on Venus rotation period (6
values)
- But the difference between both = 6 solar days
- Venus (35 km/s) moves during 6 solar days (6 x 86400 s) a distance = 18.2 mkm
- This value is defined as the difference between 2 motions which are
o Mars motion distance during Venus day period (116.75 days) =243.1 mkm
o And
o Mercury motion distance during its rotation period (58.66 days) =240 mkm
- The geometrical mechanism behind still need more analysis – but the data shows
that- the two cycles are connected together through Venus rotation period.

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3-5 Saturn orbital Distance 1433.5 mkm
Periods Cycle
In the previous motions done by planets to pass distances = 243 mkm approximately
We need to use a cycle of (6 periods) as in following
I- Data
(A)
Jupiter moves during (512 Jupiter days x 6) a distance =1434.267648 mkm
(B)
Saturn moves during (640 Saturn days x 6) a distance = 1434.79296 mkm
(C)
Neptune moves during (12430 hours x 6) a distance = 1449.8352 mkm
(D)
Uranus moves during (64 Pluto days x 6) a distance =1441.069056 mkm
(E)
Mercury moves during (1407.6 h x 6) a distance = 1441.157184 mkm
(F)
Mars moves during (2802 h x 6) a distance = 1458.60912 mkm
(G)
Neptune moves during (778.6 x 16.1 h x 6) a distance = 1462.136055 mkm
II- Data Analysis
(E) – (D) = 88100 km
(F) – (E) = 17.4519 mkm

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A Comment
- We should remember that,
- Mercury moves during its rotation period a distance = 243 mkm (error 1%)
- But
- Mercury moves during its day period a distance = 720.7 mkm
- The distance 720.7 mkm between Mercury and Jupiter is the orbital radius and the
diameter needs 2 x 720.7 mkm which need 2 x 4222.6 hours (= 6 x 1407.6 hours
Mercury rotation period)
- And during (6 Mercury rotation periods) Mercury movies a distance = 1433 mkm
- That creates a connection between (243 mkm) and (1433 mkm) that tells both
distances are created depending on each other by the (6 periods) Cycle.

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4- Venus And Uranus Motions Interactions
4-1 Preface
4-2 Venus and Uranus Velocities Proportionality
4-3 1 hour of Venus motion = 17.7 hours of Uranus Motion
4-4 Uranus Day Period Analysis
4-5 Pluto Day Period
4-6 Venus and Uranus Motions Interaction
4-1 Preface
- We have supposed, 1 hour of Mercury motion = 24 hours of Uranus Motion
- This hypothesis doesn’t depend on Planet velocity, because Mercury Velocity = 7
x Uranus velocity
- This hypothesis depends on the distance between Mercury and Uranus which
=2815 mkm and if we use each 1 mkm = 1 hour this distance 2815 mkm will be =
2815 hours = 2 x Mercury Rotation Periods (1407.6 hours)
- We use this hypothesis as a fact for now to see what results can be built on it
- Mercury velocity 47.4 km/s = Venus Velocity 35 km/s x 1.354
- Then
- If 1 hour of Mercury Motion = 24 hours of Uranus Motion
- And
- 1 hour of Mercury Motion = 1.354 hours of Venus Motion
- So
- 1 hour of Venus Motion = 17.7 hours of Uranus Motion
- This is an interesting result, because, the number 17.2 connects strongly between
Venus and Uranus Motions Data
- Where 17.2 hours = Uranus Day Period
- Let's discover how this data works

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4-2 Venus and Uranus Velocities Proportionality
I- Data
(1)
(35 km/s) (Venus Velocity) / (6.8 km /s) (Uranus Velocity) = 5.1
(2)
(17.2 h x 3600 s) / (12104 s) = 5.1
(3)
17.4 hours = 5.1 x 3.4 hours
(4)
(35 km/s) x 12104s = 423640 km
(BUT, Uranus motion distance during its day period 17.2 h be = 421056 km)
(5)
(5832.5 h /17.2 h) = (17.3 mkm/51118 km)
(6)
17.32 mkm = 12104 km x 1430
(7)
17.2 h x 680 = 2 x 5832.5 hours
(8)
(1461/1433.5) = (1433.5/1407.6)
(9)
(1440/1433.5) = (2815/2802)

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II- Discussion
- We analyze the data to prove that, 1 hour of Venus motion is equivalent to 17.2
hours of Uranus Motion
- The discussion isn't a simple one because of Venus Diameter.
- Shortly (How the matter is created?) or (Why Venus Diameter = 12104 km?)
- Can the planet diameter be created as a function in this planet motion velocity?
Means, because Venus velocity =35 km/s, so Venus diameter =12104 km? can that
be possible….
- The data provides us great puzzles and we need to discuss it as deep as possible to
catch the geometrical idea behind…
Equation no. (1)
(35 km/s) (Venus Velocity) / (6.8 km /s) (Uranus Velocity) = 5.1
- Venus velocity = 5.1 Uranus Velocity
- The puzzle data is found with the rate (5.1) because this same rate controls Venus
diameter, that tells, Venus diameter is created as (12104 km) because Venus
velocity =35 km/s
- The next question helps greatly this discussion
Equation no. (2)
(17.2 h x 3600 s) / (12104 s) = 5.1
- Where
- 17.2 hours = Uranus Day Period = 61920 seconds
- Venus diameter = 12104 km
- If each 1 km = 1 second
- So
- 61920 seconds / 12104 seconds = 5.1
- And
- Venus (35 km/s) motion during 12104 seconds a distance = 423640 km

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- But
- Uranus (6.8 km/s) moves during its day period (17.2 h) a distance = 421056 km
- The difference between both values = 0.6% = 2584 km
- The equations use Venus diameter as a period of time where 1 km = 1 second (this
using is found widely in the solar plants motions) by that Venus diameter (12104
km) will be = (12104 seconds) where Uranus day period (17.2 h = 61920 s) and
these 2 values have a rate 5.1 between them
- Where Venus velocity =5.1 x Uranus velocity
- Also the period 12104 seconds = 3.4 hours and Venus orbital inclination =3.4 deg
- The data is puzzled but provide a strong approach to define how the matter is
created or how the matter dimensions are defined, (again why Venus diameter
=12104 km)
- The classical description provides no solution for our hard discussion and can't
help us because this description imagine that the planets diameters (and data) is
created by some random process by effect of thousands unknown effects through
the solar group creation history but no idea that the planet diameter and data is
created as a function in its motion (or its velocity). By that no one imagine if
Venus velocity be changed (from 35 km/s to 30 km /s for example) that will
change Venus diameter from 12104 km into 11000 km (for example).
- But the discussion doesn't tell by what effect Venus diameter is created as 12104
km, does it by Uranus motion effect?
- We should keep our eyes on this discussion basic question, if 1hour of Venus
motion = 17.2 hours of Uranus motion, this question is important because it shows
a part of the solar system (as a great clock) and also it shows a transportation of
motion this complex process which we need to define as clear as possible because
the planets are not gears but the motion is transported from a planet to another as
among gears – we still need to see as deep as possible
- To save our discussion objective we need to keep our eyes on the value 17.2

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Notice (1)
- The rate 5.1 between Venus & Uranus velocities is a rate used between other 4
planets
- Mars velocity 24.1 km/s = 5.14 x Pluto velocity 4.7 km/s
- The Moon velocity 27.78 km/s = 5.14 x Neptune velocity 5.4 km/s
- Where
- The moon velocity 27.78 km/s = Earth velocity 29.8 / 1.0725
Notice (2)
- 17.2 degrees = Pluto Orbital Inclination
- 17.4 degrees = the inner planets orbital inclinations total
- 23.6 degrees = the outer planets orbital inclinations total
- 23.4 degrees = Earth Axial Tilt
- But
- (23.6 /23.4) = (17.4/17.2)
- Where
- 23.6 degrees +17.2 degrees = 40.8 degrees = 23.4 degrees + 17.4 degrees
Notice (3)
- 30589 days = Uranus orbital period
- But
- 30589 days x 2 = 12104 days x 5.05
- But our rate is (5.1)
- The difference between (5.05 and 5.1) = 1%
- That shows a proportionality between Venus diameter with Uranus orbital period
in addition to Uranus day period! (Why?)
- Because Uranus day period 61920 seconds = 2 x 30589 seconds (error 1.2%)
- Accurately 61920 seconds = 2 x 30589 seconds + 742 seconds

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Equation no. (3)
17.4 hours = 5.1 x 3.4 hours
- We know that 17.2 hours = Uranus day Period, And
- We will consider that this value (17.4 hours) express Uranus day period for now…
- Venus diameter =12104 km
- (if we consider each 1 km = 1 second) So,
- 12104 seconds = 3600 s x 3.4 hours
- Where
- 3.4 degrees = Venus orbital inclination
- Equation no. (3) tells that, Uranus Day period is rated with Venus diameter with
the rate 5.1, and this proportionality is mentioned geometrically because of Venus
orbital inclination = 3.4 degrees
- The data causes more puzzles, the basic difficulty is found in our minds, because
we consider the planet diameter is created before and independent from this planet
motion velocity, and based on that, the previous data has no meaning!
- The point is that, the matter dimensions are created based on this matter motion
features and because of that the matter dimensions are created in proportionality
with this matter motion features…
- What we can conclude till now is that, Some strong interaction must be found
between Uranus and Venus Motions
- The next equation may help our discussion
Equation no. (5)
(5832.5 h /17.2 h) = (17.3 mkm/51118 km)
- Where
- 5832.5 hours = Venus Rotation Period
- 17.2 hours = Uranus Day Period = (Uranus Rotation Period)
- 51118 km = Uranus Diameter

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- Equation no. (5) tells that, Venus and Uranus (rotation periods) are rated with
Uranus diameter and the value 17.3 mkm
- If the value 17.3 mkm expresses Venus diameter, So, the 2 planets rotation periods
are rated with their diameters
- Equation no (6) shows that the distance 17.3 mkm = 12104 km x 1430 where
12104 km = Venus Diameter,
- But the distance 1430 we don't know and need to wait to the next points to
discover this value (1430)
- So, we consider now that, the 2 planets rotation periods (motions) are in
proportionality with their diameters.
- We can't discuss the rest equations because we need to discover the distance 17.3
mkm which has a great effect on the 2 planets motions interaction.
Equation no. (6)
17.32 mkm = 12104 km x 1430
- Where
- 12104 km = Venus Diameter
- 1430 = this value we need to discuss later
Equation no. (7)
17.2 h x 680 = 2 x 5832.5 hours
- Where
- 17.2 hours = Uranus Day Period
- 5832.5 hours = Venus rotation period
- 680 mkm = Venus Orbital Circumference
Equation no. (8)
(1461/1433.5) = (1433.5/1407.6)
Equation no. (9)
(1440/1433.5) = (2815/2802)

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4-3 One hour of Venus motion = 17.7 hours of Uranus Motion
I- Data
(10)
4222.6 hours = 243 x 17.37 hours
(11)
329.8 x 17.4 hours = 2 x 2872.5 hours
(12)
346.6 days x 24 hours = 2 x 241.8 x 17.2
II- Discussion
Notice
- There are 3 values (17.2, 17.4 and 17.7), the rate between Venus and Uranus is 1
hour of Venus motion = 17.7 hours of Uranus Motion
- But the other rates still work because of the geometrical necessities, for that we
need to take care of the difference between them
Equation no. (10)
4222.6 hours = 243 x 17.37 hours
- Where
- 4222.6 hours = Mercury Day Period
- 243 solar days = 5832.5 hours = Venus Rotation Period
- Equation no. (10) tells that, if each day of (243 days) has 17.4 hours, in this case
Venus rotation period will be = Mercury Day Period
- By that, Mercury day period (175.95 solar days =4222.6 hours) will be = Venus
rotation period (243 days each day has 17.4 hours and by that the value 243 days
will have 4222.6 hours)
- But
- Venus rotation period has 5832.5 hours

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- That means, each hour of this value (5832.5 hours) should be = 0.72 hours of the
period (243 days x 27.4 hours)
Equation no. (11)
329.8 x 17.4 hours = 2 x 2872.5 hours
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 329.8 = lunar sidereal year (327.6 solar days)
- Notice
- 329.8 days = a lunar sidereal year (327.6 solar days) but it doesn't finish with
the moon sidereal month (27.3 days), instead, it finishes with a synodic month
(29.53 days)
- If 1 mkm = 1 hour
- So, 2872.5 mkm will be = 2872.5 hours
- Equation no. (11) tells that, if each day of (329.8 days) = 17.4 hours, so this
sidereal year (329.8 days) will be equal Uranus orbital diameter after using 1 mkm
for each 1 hour
- This equation also tells about the value 17.4 hours is used geometrically in the
planets motion data
Equation no. (12)
346.6 days x 24 hours = 2 x 241.8 x 17.2
- Where
- 346.6 solar days = the nodal year
- 243 solar days = Venus rotation period (241.8 is very near to 243)
- Equation no. (3) tells that, if each day ( in the nodal year) has only 17.2 hours, in
this case the nodal year will be equal = 2 Venus Rotation period.
- The data supports this meaning (1 hour of Venus Motion = 17.14 hours of Uranus
Motion Distance).

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4-4 Uranus Day Period Analysis
I- Data
(13)
4222.6 h x 2 = 17.2 hours x 491
(14)
0.5875 mkm x 29.53 days = 17.4 mkm
(15)
0.5875 mkm x 4879 days = 2 x 1433.5 mkm
(16)
(47.4 km/s) x 366556 s = 17.37 mkm
(17)
2.8 mkm = 160000 km x 17.5 (notice 17.5 x 2 = 35)
II- Discussion
Equation no. (13)
4222.6 h x 2 = 17.2 hours x 491
- Where
- 4222.6 hours = Mercury Day Period
- The rate 491 shows that, a mentioned proportionality is found between Mercury
day period and Uranus day period, because this rate (491) is an integer and
specific number, the geometrical design mentioned this value (491) to be a rate
between the 2 planets days periods – but why?
- But
- 491 = 28.64 x 17.14
- Where 28.64 degrees = (180 degrees /2π) and Neptune axial tilt =28.3 deg (1.2%)
(the equation tells that, Neptune motion must have an effect on the interaction of
Mercury and Uranus motions!)

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- Notice
- Our discussion interests to discover the value (17.2) effect on Uranus and Venus
Motions. Many data shows this value effect but we still follow the geometrical
mechanism by which this value creates such great effect on both planets motions
Equation no. (14)
0.5875 mkm x 29.53 days = 17.4 mkm
- The 2 planets interaction depends on the distance 17.4 mkm (or 17.2 mkm), but we
need to know what planet pass this distance (17.4 mkm). Let's try to discover that
in following
o Uranus motion during 29.53 solar days ( the moon day period) a = 17.4
mkm
o Mercury moves during 366557 seconds a distance = 17.4 mkm
o Venus moves during 138 hours a distance = 17.38 mkm
o Pluto moves during 6.7 Pluto days (6.7 x 153.3 h = 1027 h) a distance =
17.37 mkm
Equation no. (15)
0.5875 mkm x 4879 days = 2 x 1433.5 mkm
- Equation no. (15) tells that, Uranus during 4879 days move a distance = 2 x 1433.5
mkm (Saturn Orbital Distance)
- Where
- 4879 km = Mercury diameter
- Equation no. (15) shows an interaction between Mercury and Uranus Motions
depending on Mercury Diameter using as a period of time.

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Equation no. (16)
(47.4 km/s) x 366556 s = 17.37 mkm
- Where
- 366556 km = the outer planets diameters total
- 47.4 km/s = Mercury velocity
- Equation no. (16) tells that, mercury moves during 366556 seconds a distance =
17.37 mkm
- Notice
- 366556 km (the outer planets diameters total) /2390 km (Pluto diameter) =153.3
- Where
- 153.3 hours = Pluto day period.
Equation no. (17)
2.8 mkm = 160000 km x 17.5 (notice 17.5 x 2 = 35)
- Where
- 2.8 mkm is the distance passed by Jupiter during 6 Jupiter days (13.1 km/s x 6 x
9.9 hours x 3600 = 2.8 mkm).
- 160000 km = Uranus Circumference.

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4-5 Pluto Day Period
I- Data
(18)
4 x 655.7 hours = 153.3 hours x 17.1
(19)
4 x 748 mkm = 2992 mkm (Uranus Pluto Distance 3030 mkm error 1.2%)
Equation no. (18)
4 x 655.7 hours = 153.3 hours x 17.2
- 655.7 hours = The Moon Rotation Period
- 153.3 hours = Pluto Day period
- Equation no. (18) tells that, Pluto day period be so long (153.3 h) because of
Uranus motion effect on Pluto motion, where this effect from Uranus on Pluto
motion is done through the moon rotation period (655.7 hours)
- Notice, Uranus diameter 51118 km = 4 x 12756 km Earth diameter

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4-6 Venus and Uranus Motions Interaction
I- Data
(20)
2 x 30589 days = 17.7 x 3475 days
(21)
5832.5 hours = 17.7 hours x 329.8
(22)
3475 mkm = 5.1 x 680 mkm (Venus Orbital Circumference)
(23)
(3475/180.8) = (2872.5 /149.6)
II- Discussion
- Let's remember the hypothesis of this point…. It tells that,
- 1 hour of Venus Motion =17.7 hours of Uranus motion,
- If this hypothesis is a fact, can this proportionality be found between Venus and
Uranus Motions Data? Let's discuss the equations in following
Equation no. (20)
2 x 30589 days = 17.7 x 3475 days
- Where
- 30589 solar days = Uranus Orbital Period
- 3475 km = The Earth Moon Diameter (here is used as a period of time)
- 17.7 = The rate between Venus and Uranus hours
- Equation no (20) should be used as a proof for the hypothesis that (1 hour of
Venus Motion be equivalent to 17.7 hours of Uranus motion)
- Why this equation can be used as a proof?
- We remember that
- 2 x 30589 seconds = 12104 seconds x 5.05 (error 1% with the rate 5.1)
- Also

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- Uranus day period (17.2 hours = 61920 seconds) = 2 x 30589 s + 742 s
- Equation no. (20) shows that the rate (1 : 17.7) is found between Venus and
Uranus through the moon diameter (3475 km)
- That means, Uranus motion effect on Venus motion through the moon diameter (or
the moon motion) and that may tell an answer for the question why does the moon
orbit regress? Where Uranus axial tilt regresses and Venus axial tilt regresses and
if Venus motion be effected by Uranus motion through the moon motion, that tells
this effect of Uranus motion on Venus motion through the moon motion causes the
moon orbit regression (19 degrees per year).
- Equation no. (20) shows that, if each day of the days (3475) has 17.7 hours, so the
hours number of this period (3475 days) will be = 2 x 30589 hours
- So the moon diameter (3475 km) will be used as a period of time (days) where
each day be = 17.7 hours.
Equation no. (21)
5832.5 hours = 17.7 hours x 329.8 days
- Where
- 5832.5 hours = Venus rotation period
- 329.8 days = a lunar sidereal year (327.6 solar days) but it doesn't finish with
the moon sidereal month (27.3 days), instead, it finishes with a synodic month
(29.53 days)
- Equation (21) shows that, if each day of the year (329.8 days) has 17.7 hours, so
this period of time (329.8 days) will have a number of hours = Venus rotation
period.
- Why this data can be a proof for the hypothesis?
- Because different cycles and periods are defined in proportionality with the rate
17.7 hours, where this rate is different from Uranus day period (17.2 hours), that
means, the geometrical design aims to create these data in proportionality with the
rate 17.7 which we have concluded based on the hypothesis.

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- I want to say that, the geometrical design define the data taken into consideration
the rate 17.7, and we have no other reason for this rate except the proportionality
between Uranus and Venus motions (1 hour of Venus motion = 17.7 hours of
Uranus Motion)
- The data shows that clearly
Equation no. (22)
3475 mkm = 5.1 x 680 mkm (Venus Orbital Circumference)
- Where
- 3475 km = The Moon Diameter
- 3475 mkm = 3475 km x 1 mkm
- 5.1 = The rate between Venus & Uranus velocities
- Also 5.1 deg = The Moon Orbital Inclination
- Equation no. (22) shows that, the proportionality between the moon diameter and
Venus motion data is so wide and this equation is one more form of this
proportionality
- The geometrical mechanism still needs more analysis but the data shows that the
interaction between the moon data (specially the moon diameter) with Venus
Motion data is so strong interaction
Equation no. (23)
(3475/180.8) = (2872.5 /149.6)
- Where
- 3475 km = The Moon Diameter
- 180.8 degrees = 177.4 degrees +3.4 degrees
- 2872.5 mkm = Uranus Orbital Distance
- 149.6 mkm = Earth Orbital Distance
- Equation no. (23) tries to show Uranus motion effect on Venus motion data, where
the value 180.8 degrees shows Uranus Motion data effect.

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- 180.8 deg = 177.4 deg (Venus Axial Tilt) + 3.4 deg (Venus orbital; inclination)
- But
- 180.8 degrees = 180 degrees +0.8 deg (Uranus Orbital Inclination)
- That shows Uranus motion effect on Venus Motion Data.
- Equation no. (23) shows that Uranus motion effect on Venus Motion data is done
through the moon diameter and this effect is seen through the rate between Uranus
and Earth orbital distances.

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4-7 The General Conclusions
- The paper hypothesis tells that, 1 hour of Venus Motion b equivalent to 17.7 hours
of Uranus Motion
- This rate of time isn't defined based on Planets velocities Rate, because Mercury
velocity = 7 Uranus velocity but 1 hour or Mercury motion should be = 24 hours
of Uranus Motion
- This rate of time is defined based on the distance between Mercury and Uranus,
where Mercury Uranus distance = 2815 mkm and if we use 1mkm = 1 hour that
will make the distance 2815 mkm be equivalent to 2815 hours = 2 x Mercury
rotation period (1407.6 hours).
- Also
- Mercury moves during its rotation period (1407.6 hours) a distance =243 mkm
(error 1%)
- If we use 1 mkm = 1 solar day, so this distance 243 mkm will be = 243 solar days
(= Venus rotation period)
- We have 2 rates of time (one uses 1mkm = 1 hour and the other uses 1 mkm = 1
solar day), based on this data I have supposed that 1 hour of Mercury motion be
equivalent to 24 hours of Uranus motion
- But
- Mercury velocity (47.4 km/s) = Venus velocity (35 km/s) x 1.354
- 1 hour of Mercury motion = 24 hours of Uranus motion
- And
- 1 hour of Mercury motion = 1.354 hours of Venus motion
- So,
- 1 hour of Venus motion = 17.7 hours of Uranus motion
- This is our conclusion based on which the hypothesis is discussed, and then we
have found that many of Uranus and Venus motions data be created in
proportionality with the rate 17.7

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- Venus & Uranus motions data almost depend on the rate (17.7 or 17.2) and by that
the hypothesis may be supported.
- The geometrical mechanism by which this data is created depended on the
hypothesis that (1 hour of Venus motion = 17.7 hours of Uranus motion).

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5- (1 hour of Venus Motion = 17.7 hours of Uranus Motion) (More Proves)
5-1 Jupiter effect on Venus Uranus Motions interaction
5-2 Conclusions
5-1 Jupiter effect on Venus Uranus Motions interaction
I- Data
(1)
30589 x 2π x (17.7/24) = 142984 (1%)
(2)
30589 x 2π = 17.7 x 10921
(3)
4900 mkm = 6.6 x 742.5 mkm
(4)
2π x 742 mkm = 6 x 778.6 mkm
(5)
4331 days = 17.7 x 243 days
But
4331 = 6 x 720.7
(6)
449197 km = 12756 x 35 =12104 x (116.7/π)

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II- Discussion
Equation no. (1)
30589 x 2π x (17.7/24) = 142984 (error 1%)
- Where
- 30589 days = Uranus Orbital Period
- 142984 km = Jupiter diameter
- Equation no. (1) tells that, Jupiter diameter is created in proportionality with
Uranus orbital period based on the rate (17.7/24) because 1 hour of Mercury
motion =24 hours of Uranus motion and 1 hour of Venus Motion = 17.7 hours of
Uranus motion
- The rate (17.7/24) proves clearly the paper hypothesis
- We should note that, Jupiter diameter is the basic value used in the (8 days cycle)
by that, Jupiter (8 days cycle) is defined because of Jupiter diameter creation as a
different distance between Jupiter motion distance during 8 Jupiter days and 8
Jupiter circumferences.
- Also Jupiter diameter is the difference between Uranus motion distance during 8
Pluto days and Jupiter motion distance during 64 Jupiter days
- That tells Jupiter diameter is a value has geometrical effect on the planets motions
- And
- We have seen that, Uranus orbital period (30589 days) is effective value on Uranus
day period (17.2 h) which we have discussed deeply before, that tells equation no.
(1) shows a part of the geometrical mechanism by which the motion is transported
between Venus and Uranus creating the rate of time (1 hour =17.7 hours).
- But
- Mercury velocity (47.4 km/s) = Venus velocity (35 km/s) x 1.354
- 1 hour of Mercury motion = 24 hours of Uranus motion
- And
- 1 hour of Mercury motion = 1.354 hours of Venus motion

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Equation no. (2)
30589 x 2π = 17.7 x 10921
- Where
- 10921 km = The Earth Moon Circumference
- The moon circumference is defined by (almost) the same equation by which
Jupiter diameter is defined
- We know that,
- Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter where 10921 km = the moon circumference
- Not only but
- Jupiter circumference (449197 km) x the moon circumference (10921 km) = 4900
mkm = Jupiter orbital circumference
- Equation no. (2) tells that, the rate of time (1 hour = 17.7 hours) is the reason based
on which the moon and Jupiter diameters be created to be in so harmony for their
motions, because both are created based on the same geometrical necessity.
Equation no. (3)
4900 mkm = 6.6 x 742 mkm
- Where
- 4900 mkm = Jupiter orbital circumference
- 742 mkm = the distance passed by Uranus during 30589 hours
- Please remember
- This distance 742 mkm is so important distance because the moon displacements
total be equal it during (8445 solar days) where this value 8445 hours = 2 Mercury
Day period – based on this discussion we have discovered that 1 hour of Mercury
motion =48 hours of the moon motion.
- What's the rate 6.6?

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- Jupiter velocity = 0.374 of Venus Velocity but 1 hour of Venus motion = 17.7
hours of Uranus motion, based on that 1 hour of Jupiter motion = 6.6 hours of
Uranus motion.
- The data provides more proves for the paper hypothesis…
Equation no. (4)
2π x 742 mkm = 6 x 778.6 mkm
- Where
- 778.6 mkm = Jupiter Orbital Distance
- Equation no. (4) tells that, the connection between Jupiter motion and the distance
742 mkm (which is passed by Uranus during 30589 hours) depends on the (6
periods cycle)
Equation no. (5)
4331 days = 17.7 x 243 days
But
4331 = 6 x 720.7
- Where
- 4331 solar days = Jupiter orbital period
- 243 solar days = Venus Rotation Period
- Equation no. (5) tells that, Jupiter orbital period will be = Venus rotation period if
the rate ( 1 hour =17.7 hours) is used
- The period 4331days depends on the distance 720.7 mkm (Mercury Jupiter
distance) by the (6 periods) Cycle.
Equation no. (6)
449197 km (Jupiter circumference) = 12756 x 35 =12104 x (116.7/π)
- 12756 km = Earth diameter
- 12104 km = Venus diameter
- 35 km/s = Venus velocity
- 116.75 solar days = Venus Day Period

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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