Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
- The moon orbital triangle data analysis lead to the following hypothesis (A 2nd Force must effect on the Moon Orbital Motion in addition to Earth Gravity Force)
- Also the 2nd hypothesis is created based on this first one, (Uranus effects on the moon orbital motion, causing to create Metonic Cycle).
Gerges Francis Tawdrous +201022532292
Paper hypothesis
The Moon Orbit Is Created In A Triangle Form
The hypothesis explanation
- The moon uses Pythagorean triangle as one of its motion techniques because the moon daily displacement =88000 km, and during 29.5 days the total distance will =2.598 mkm, which should be = the moon orbital circumference…. But
- (2.598 mkm = 2π x 413000 km) (the moon apogee radius =0.406 mkm) (1%)
- Based on that, if the moon uses its displacement as a real displacement through its orbit, the moon would revolve around Earth through its apogee orbit only along month.
- The intelligent moon creates an angle (θ) between its displacement motion direction and its orbit horizontal level, by that, the real displacement through the orbit be (L =88000 km cos (θ)), and will be shorter than 88000 km enables the moon to revolve around Earth through more near orbits.
- The moon using of Pythagorean triangle technique creates the moon orbit in a triangle form. (The paper hypothesis)
- The using of Pythagorean triangle is a proved fact otherwise the moon apogee radius should be (r=0.413 mkm) in place of (r=0.406 mkm).
Gerges Francis Tawdrous +201022532292
Paper Question
Why the moon orbital circumference at apogee orbit = 2.55 mkm?
- The moon displacement daily = 88000 km, and during 29.5 days (The Moon Day Period), the total displacements will =2.598 mkm, which should be = the moon orbital circumference. But 2.598 mkm = 2π x 413000 km
- The apogee radius =406000 km, is the most far point the moon can reach from Earth, where the perigee radius =363000 km, which is its nearest one
- Why the moon orbital circumference at apogee doesn't = 2.598 mkm?!
- also, the moon daily displacement (88000 km) should force the moon to revolve around Earth through it apogee orbit only (r=406000 km) or even further than it (r=413000 km)!
Gerges Francis Tawdrous +201022532292
Paper Question
Why the moon orbital circumference at apogee orbit = 2.55 mkm?
- The moon displacement daily = 88000 km, and during 29.5 days (The Moon Day Period), the total displacements will =2.598 mkm, which should be = the moon orbital circumference. But 2.598 mkm = 2π x 413000 km
- The apogee radius =406000 km, is the most far point the moon can reach from Earth, where the perigee radius =363000 km, which is its nearest one
- Why the moon orbital circumference at apogee doesn't = 2.598 mkm?!
- also, the moon daily displacement (88000 km) should force the moon to revolve around Earth through it apogee orbit only (r=406000 km) or even further than it (r=413000 km)!
- To solve this dilemma, the moon uses Pythagorean triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level. So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit. And by that the total (real) displacements will be less than 2.598 mkm and the moon can revolve around Earth through more near orbits than apogee.
Gerges Francis Tawdrous +201022532292
The Solar System Motion Analysis
Abstract
Paper hypothesis
- The Motion Is Transported Among The Solar Planets.
The hypothesis Explanation
- The paper suggests that, the solar group is similar to one machine of gears and each planet is a gear in it. or it's similar to one building and each planet is a part of this building.
- The paper vision tells that, the solar planets are created based on One Geometrical Design and because of that the planets data is created complementary with each other.
- Based on this vision, The Motion Must Be Transported Among The Solar Planets.
- The motion transportation doesn't force us to attribute mechanical features for the space, because the motion transportation isn't done mechanically.
- As a result for the motion transportation through the solar system, the Planets motions use different rates of time.
- As example of the different rates of time
- 1 hour of Mercury Motion = 9.18 hours of Pluto Motion. But
- 1 hour of Earth Motion = 6.387 hours of Pluto Motion
- The solar planets motions different rates of time be unified and created one general rate of time.
Paper Objective
- The paper discusses and proves The Motion Transportation Concept among the solar planets
- And
- The paper discusses and proves the solar planets motions using of different rates of time.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Geometry (Revised) (3)Gerges francis
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Gerges Francis Tawdrous +201022532292
The moon uses pythagoras triangle technique in its orbital motion (part no.3)Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No. 3)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
- The moon orbital triangle data analysis lead to the following hypothesis (A 2nd Force must effect on the Moon Orbital Motion in addition to Earth Gravity Force)
- Also the 2nd hypothesis is created based on this first one, (Uranus effects on the moon orbital motion, causing to create Metonic Cycle).
Gerges Francis Tawdrous +201022532292
Paper hypothesis
The Moon Orbit Is Created In A Triangle Form
The hypothesis explanation
- The moon uses Pythagorean triangle as one of its motion techniques because the moon daily displacement =88000 km, and during 29.5 days the total distance will =2.598 mkm, which should be = the moon orbital circumference…. But
- (2.598 mkm = 2π x 413000 km) (the moon apogee radius =0.406 mkm) (1%)
- Based on that, if the moon uses its displacement as a real displacement through its orbit, the moon would revolve around Earth through its apogee orbit only along month.
- The intelligent moon creates an angle (θ) between its displacement motion direction and its orbit horizontal level, by that, the real displacement through the orbit be (L =88000 km cos (θ)), and will be shorter than 88000 km enables the moon to revolve around Earth through more near orbits.
- The moon using of Pythagorean triangle technique creates the moon orbit in a triangle form. (The paper hypothesis)
- The using of Pythagorean triangle is a proved fact otherwise the moon apogee radius should be (r=0.413 mkm) in place of (r=0.406 mkm).
Gerges Francis Tawdrous +201022532292
Paper Question
Why the moon orbital circumference at apogee orbit = 2.55 mkm?
- The moon displacement daily = 88000 km, and during 29.5 days (The Moon Day Period), the total displacements will =2.598 mkm, which should be = the moon orbital circumference. But 2.598 mkm = 2π x 413000 km
- The apogee radius =406000 km, is the most far point the moon can reach from Earth, where the perigee radius =363000 km, which is its nearest one
- Why the moon orbital circumference at apogee doesn't = 2.598 mkm?!
- also, the moon daily displacement (88000 km) should force the moon to revolve around Earth through it apogee orbit only (r=406000 km) or even further than it (r=413000 km)!
Gerges Francis Tawdrous +201022532292
Paper Question
Why the moon orbital circumference at apogee orbit = 2.55 mkm?
- The moon displacement daily = 88000 km, and during 29.5 days (The Moon Day Period), the total displacements will =2.598 mkm, which should be = the moon orbital circumference. But 2.598 mkm = 2π x 413000 km
- The apogee radius =406000 km, is the most far point the moon can reach from Earth, where the perigee radius =363000 km, which is its nearest one
- Why the moon orbital circumference at apogee doesn't = 2.598 mkm?!
- also, the moon daily displacement (88000 km) should force the moon to revolve around Earth through it apogee orbit only (r=406000 km) or even further than it (r=413000 km)!
- To solve this dilemma, the moon uses Pythagorean triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level. So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit. And by that the total (real) displacements will be less than 2.598 mkm and the moon can revolve around Earth through more near orbits than apogee.
Gerges Francis Tawdrous +201022532292
The Solar System Motion Analysis
Abstract
Paper hypothesis
- The Motion Is Transported Among The Solar Planets.
The hypothesis Explanation
- The paper suggests that, the solar group is similar to one machine of gears and each planet is a gear in it. or it's similar to one building and each planet is a part of this building.
- The paper vision tells that, the solar planets are created based on One Geometrical Design and because of that the planets data is created complementary with each other.
- Based on this vision, The Motion Must Be Transported Among The Solar Planets.
- The motion transportation doesn't force us to attribute mechanical features for the space, because the motion transportation isn't done mechanically.
- As a result for the motion transportation through the solar system, the Planets motions use different rates of time.
- As example of the different rates of time
- 1 hour of Mercury Motion = 9.18 hours of Pluto Motion. But
- 1 hour of Earth Motion = 6.387 hours of Pluto Motion
- The solar planets motions different rates of time be unified and created one general rate of time.
Paper Objective
- The paper discusses and proves The Motion Transportation Concept among the solar planets
- And
- The paper discusses and proves the solar planets motions using of different rates of time.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Geometry (Revised) (3)Gerges francis
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Gerges Francis Tawdrous +201022532292
The moon uses pythagoras triangle technique in its orbital motion (part no.3)Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No. 3)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
The Solar Planets Motions Use Different Rates Of Time (Revised)Gerges francis
The Solar Planets Motions Use Different Rates Of Time (Revised)
Abstract
Paper hypothesis
The Solar Planets Motions Use Different Rates Of Time
Paper Hypothesis Explanation
- The planets motions rates of time be defined by using ONE RULE
- Based on the planets motions rates of time, the planets orbital periods and distances be defined. means,
- Based on this One Rule, the solar planets orbital periods and distances be defined.
- If the solar planets motions be independent from one another, how their orbital periods and distances be defined based on one rule only?
- The paper provides a proof that, the planets motions use different rates of time which proves that, the solar planets move one unified general motion. means,
- The solar planets motions be integrated with one another and created one unified general motion, because of that, the planets motions need to use different rates of time to enable their motions to be integrated into one unified general motion.
- This fact changes the solar system description inherited from Newton theory of the sun mass gravity. The solar planets be similar to carriages in one train move together one unified motion. also the solar group can be similar to a mechanical clock, and the planets be similar to the gears of this clock. Each gear does one motion (and creates one rate of time) and these motions be integrated into one unified gnarl motion (and the rates of time be integrated into one unified general rate of time)
Paper objectives
- The paper provides the rule based on which all solar planets orbital periods and distances be defined, and test all planets motions data to prove that, no planet motion contradicts this rule.
- The paper tries to answer the question (why the solar planets use different rates of time) by providing The Solar System Creation And Motion Theory.
- The paper is divided into 2 parts.
- (1st Part) Provides the rule and its proves discussion
- (2nd Part) Provides The Solar System Creation And Motion Theory
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The moon orbital motion geometry (revised) (2)Gerges francis
The Moon Orbital Motion Geometry (Revised) (2)
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
Neptune Motion Analysis Disproves Newton Theory Gerges francis
Abstract
Paper hypothesis
The Decision of Nobel Prize for Physics 2021 Is Mistaken
Paper hypothesis explanation
- Uranus Orbital Distance = 19.2 Earth Orbital Distance
- This fact tells, if Uranus and Earth velocities be equal, while Uranus revolves around the sun one complete revolution Earth would revolve around the sun 19.2 complete revolutions (19.2 years) - But
- The Earth moon moves a cycle called Metonic Cycle extends for 19 years. this fact creates a puzzle because Earth Cycle is 4 years only (365+365+365+366 =1461 days) and by that the Earth itself doesn't know about Metonic Cycle –
- The question be (How does the moon move Metonic Cycle if Earth doesn't?)
- The answer is …
- Uranus motion effects on the moon motion and caused the moon to move Metonic Cycle (19 years) – Simply, Metonic Cycle is the result of Uranus Motion effect on the moon motion.
- Now, Why The Nobel Prize Decision For Physics 2021 Is Mistaken?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The moon uses pythagoras triangle technique in its orbital motion (part no.3)...Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No.3) (Revised)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation (theta= theta + 1.7 degrees) which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Geometry (Revised)Gerges francis
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
(Preprint No. 3) (Planet 8 Days Cycle)
Abstract
Paper hypothesis
The Planets Motions depend On 2 Basic Cycles which are:
(A Cycle Of 8 Days) and (A Cycle of 6 days)
The hypothesis explanation
- The paper hypothesis tells, the solar planet motion can't be considered as an independent motion, because the planets move together based on one general system. This system uses (8 days Cycle) of some planets and (6 days Cycle) of other planets to create a general unified motion.
- Based on that the solar planets motions should be considered as (A Train Carriages Motion). The Planets move together one unified motion in which the planets motions data be complementary with each other
- That proves the claim, the solar group is created based on one geometrical design and that necessitates the planets data to be complementary with one another. by that the solar group should be considered as one machine of Gears and each planet is a gear in it.
- The (8 days) and (6 days) cycles should be used as a proof for this fact.
Paper contents
- The paper explains and discusses the 2 basic Cycles.
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Paper question
-Earth (29.8 km/s) moves during (24 hours) a distance = 2574720 km
- The Earth moon displacements total during 29.53 days = 2598693 km
- Pluto (4.7 km/s) moves during (153.3 h) a distance = 2593836 km
- Uranus (6.8 km/s) moves during 378675 seconds a distance = 2574990 km
- Mars (24.1km/s) moves during 29.53 hours a distance = 2562023 km
- Why These Distances Are Equal Approximately? (The difference 1%)
Paper Claim
- The paper claims, these distances are equal to enable Pluto to move during its day period a distance = the moon displacements total during its day period, because the equality of these distances has a geometrical necessity for the solar system motion.
- The claim depends on a new description for the solar system which is:
o The solar group is one building and each planet is a part of it
o The solar planets move one unified motion as train carriages
o The solar group is one machine can be considered as (A Great Clock)
o The solar planets data is created depending on one another.
Gerges Francis Tawdrous +201022532292
Can Light Velocity Effect On The Moon Orbital Motion? (Revised)Gerges francis
Abstract
Paper Question
-Can Light Velocity Effect On a Planet Motion?
The Question Explanation
- We observed frequently that, a Planet motion shows light motion features
- Indeed We have observed features as (different rates of time – Lorentz length Contraction phenomenon – distance values are used as periods of time) which are light motion features
- But,
- We couldn't catch the light motion (or any high velocity motion) can cause these features.
- because of that, I have to provide the detailed data in best order and description to be a source of knowledge to whom may concern to help.
- This paper provides a sufficient proof for the claim (Light Motion Features Are Discovered In Planets Motions). Where the paper tries to provide all detailed data and all possible support to whom tries to answer the question (How Can These Features Be Belonged To A Planet Motion?)
Gerges Francis Tawdrous +201022532292
The Moon Orbit Analysis
Earth Moon motion has specific 4 points which are:
1. Perigee Point (R1) : Radius 363000 km from Earth (the nearest point)
2. Total Solar Eclipse (R2) : Radius 377000 km from Earth
3. Average Moon Orbit (R3) : Radius 384000 km (registered)
4. Apogee Point (R4) : Radius 406000 km from Earth (the most far point)
These 4 points are defined by 4 geometrical rules which are:
- (1st Rule) Pythagoras rule : R2n + (86000km)2= R2n+1
(why 86000 km? we'll discuss that in this paper)
- (2nd Rule) Moon Orbital Circumference at Rn= (1/Rn+1)
- (3rd Rule) (Moon Orbital Circumference at Rn+1/ Moon Orbital Circumference at Rn) =1.0725
- (4th Rule) The Rate 365.25
This paper tries to prove this fact, and discusses more deep question… why the moon orbital different radiuses are defined by these 4 geometrical rules?
Another Force Effect On The Earth Moon Motion Gerges francis
Paper Hypothesis
- There's another force effects on the Earth moon motion
The Hypothesis Explanation
- The moon data shows that, there's one more force effects on the moon motion, the hypothesis means that, the moon motion revolving around Earth is a result of effect of 2 different forces – these 2 forces are (1) Earth gravity force (2) 2nd force effect on the moon motion
- This 2nd force must be equal Earth gravity force, and it effects on the moon motion orbit from the other side, and can be proved in the moon motion trajectory
- This 2nd force has a great effect on the moon motion understanding, because without it the moon orbit can't be created, but this force origin is a puzzle!…….
- The Earth mass = 4 planets (Mercury + Venus + Mars + the moon) masses total, this data tells that, the 4 inner planets masses may produce a total gravity = Earth gravity – but this conclusion can easily be disproved because of the great distances between the 3 inner planets and the Earth moon
- The dilemma is that, the 2nd force is a real one and its effect can be seen in the moon motion, and the masses equality provided the required data to explain this real force, but the distances disproves simply this proof…. How to solve that?
Paper Objective
- This paper objective is limited to prove the 2nd force existence. The paper tries to show this force effect as clear as possible on the moon motion trajectory, in addition to refer to this 2nd force origin.
Gerges Francis Tawdrous +201022532292
Is There A Geometrical Shape For The SpaceGerges francis
Is There A Geometrical Shape For The Space?
Yes …
How to prove?
Let's see the moon orbit data in following:
1- Earth moon distance at perigee radius = the outer planets diameters total (1%)
2- Earth moon distance at apogee radius = the solar planets diameters total
3- The moon orbital distance between Perigee and apogee = Earth Circumference = the inner planets diameters total
4- Earth moon distance at total solar eclipse radius = Saturn Circumference
How to explain this data? Can we imagine that Saturn is created after the Earth Moon creation and Saturn used the moon Data
Imagine you have an area and you used partitions to create rooms and offices in this area – now – imagine that – these partitions are so transparent and can't be seen by any person – how to know if the partitions are found or not?
They prevent you to pass– when we don't see the partition it forces us to stop – the moon has to stop at defined points in its motion – the moon can't move beyond neither perigee nor apogee, where both points are defined by other calculations NOT related to the moon motion – even if we don't know yet by what geometrical mechanism the planets diameters total can restrict the moon motion! but because the same points are defined by other calculations that tell us – the restriction points were made by The Space Division and not by the moon motion – that's what I try to prove in this paper – and if I prove that the space is divided, that will prove my claim – "There's A Geometrical Shape For The Space"
Paper Contents
2- The Earth Moon Orbit Analysis
3- Jupiter Effect of the Earth Moon Creation and Motion
4- Mars Migration Theory Revision (The Earth Moon Creation)
Gerges Francis Tawdrous +201022532292
Abstract
- The solar group is a clock..
- The paper tries to develop our understanding for the solar system motion…
- The classical description which tells - The solar planets are rigid bodies separated from each other in their creation and motion, revolving around the sun by the masses gravity forces – this description fails frequently to explain Planets Motions Data …
- The paper vision tells – The solar planets are one trajectory of energy, or one thread (or one light beam) and each planet is a knot on this thread or a point on this trajectory of energy –
- The solar group – based on the new vision – is one geometrical building and each planet is a part of this same building – and Because of that – Each plant data must be complementary to other planets data –
- (A Complementary Data) is similar to an electron and a positron are produced by the double production experiment – where each particle charge is defined based on the other particle (because of charge reservation law) – similar to that – each planet creation and motion data must be complementary to the other planets to support the general motions harmony –
- That makes the solar group as a machine of gears, and because of the data dependency on one another, that refers to (A Motion Transportation) is found among the planets.
Gerges Francis Tawdrous +201022532292
Why The Earth Moon Distance = The Planets Diameters Total (III) Gerges francis
Paper Question
Why The Earth Moon Distance (At Apogee Radius) = The Planets Diameters Total?
Because
(1)
The Matter Is Created Based On Its Motion –
That means
The moon daily displacement =88000 km – is the reason based on which– the moon diameter is created to be = 3475 km –
This fact can be proved by analyze Saturn Creation and Motion Data
(Point No. 2 of this paper discusses this question)
(2)
We Still Analyze The Moon Orbit Geometrical Structure, Where the moon orbit shows that there's a geometrical design forces the moon to move specific motion and specific displacement daily
Gerges Francis Tawdrous +201022532292
The moon uses Pythagorean triangle as one of its motion techniques
-The moon displacement = 88000 km, and during 29.5 days the total displacements will =2.598 mkm, which should be = the moon orbital circumference.
- (2.598 mkm = 2π x 413000 km) (the moon apogee radius =0.406 mkm) (1%)
- According to this data, the moon would revolve around Earth through its apogee orbit only during a month.
- The moon solves this dilemma by creating an angle (θ) between its displacement motion direction and its orbit horizontal level, by that, the real displacement through the orbit be (L =88000 km cos (θ)), where (L) will be less than 88000 km and the moon can revolve around Earth through more orbits than its apogee orbit
- The moon using of Pythagorean triangle technique creates the moon orbit in a triangle form.
Gerges Francis Tawdrous +201022532292
The Moon Geometry
The Moon Data Analysis shows the following:
1- Earth-Moon is an unique planet in the solar group and not similar to any other moon in the group.
2- The Solar Planets are connected together geometrically
i.e.
3- The solar planets are created to be complementary to each other, all of them together consist one geometrical structure (as a triangle, square, or pyramid….)
That means
a. There was an original energy before any matter existence. And from this energy the planet matter is created (based on E=mc2) and the planet orbital distance is created (I suppose the space = Energy). This same energy also causes the planet motion as part of the general geometrical structure.
b. Each solar planet is a part of this same geometrical structure and has a specific job in it (that means no part is absent..! means the original energy created all required planets to form the required geometrical structure)
c. Each Planet Data is created to be suitable for the planet job in the general geometrical structure..
Previous Paper Conclusion
-Planets Cycles Periods are defined relative to each other.
Example
-Mercury & Venus Cycles Periods interacted with each other, creating an effect on Earth Moon Cycles and causing that, The Moon Orbital Period to be equal Its Rotation Period (27.3 days)
-This effect of Mercury and Venus, on Earth Moon Cycles Periods, is a general effect on the solar system, and be seen also on the outer planets cycles periods
-A result of that, The Outer Planets Days Periods Are = Their Rotations Periods – this is found Because Earth Moon Orbital Period = Its Rotation Period =27.3 days
A Proof
-The Outer Planets Rotation Periods Total =(Earth Moon Rotation Period /Π)
(Planets Cycles Periods, Means, Planet Orbital Period, Planet Rotation Period And Planet Day Period)
Paper Objective
-This paper provides more proves for the claim that "The Outer Planets Rotations Periods Are Found Depending On Earth Moon Rotation Period"
The Solar Group is A Clock (VII)
Abstract
Paper Question
- Can The 1 second period of time be different from a planet to another?
The question discussion
- Someone told that, the second period is a human made unit!, It's not true,
- Earth day period (24 hours) – Earth rotation period (23.9 hours) = 0.1 hour
- This fact forces us to divide the solar day into 24 hours and the 1 hour into 60 minutes – easily by using the same rate we define the second period. That means, the time units are defined based on planets motions and cycles
- The direct question is, why we suppose (Earth second period of time) = (Mercury Second period of time)? On what base this hypothesis is suggested?
- The idea is that, because the time unit is defined depends on planet motion features, and these features are changed from one planet to another, that causes the time unit (period) to be different from one planet to another…
Gerges Francis Tawdrous +201022532292
Abstract
Paper question
- Can The Motion Be Transported From A Solar Planet To Another?
The Question Explanation
- The planets use (8 days and 6 days) cycles and these cycles refers to a form of the transportation of motion among the solar planets
- The motion transportation is done based on different rates of time found among the planets
- Based on that
- 1 hour of Mercury motion be equivalent to 24 hours of Uranus motion
- And because
- (Venus velocity / Mercury velocity) = 0.738
- 1 hour of Venus motion be equivalent to 17.7 hours of Uranus motion
- This claim should be the paper hypothesis, where the paper tries to prove this fact
- By proving the different rates of time (specifically 1 hour of Venus Motion = 17.7 hours of Uranus Motion), that gives a reference of mutual effect of planets motion on one another which gives support for the motion transposition claim.
Gerges Francis Tawdrous +201022532292
Abstract
Paper Question
How to form the required hypothesis?
The Question Explanation
- The data analysis method 1st step is (The Directed Data Definition)
- The data analysis method 2nd step is (The hypothesis formation)
- The hypothesis is the task without which the data can't create any meaning.
- The hypothesis basically tries to answer (How the directed data is created?)
- Sometimes the data be so difficult to enable any hypothesis to be formed but the hypothesis is a basic step can't be canceled, in this case such data can not be used.
Gerges Francis Tawdrous +201022532292
Jupiter And Uranus Effect On The Solar System GeometryGerges francis
Paper Hypothesis
The Solar System Coordinates have 3 Axis –XY Plane Is Controlled By Jupiter Effect – And Z-Axis Is Defined By Uranus Effect
The Hypothesis Explanation:
Uranus Effect
- Uranus effects on the solar system vertically
- Uranus effects on the planets axial tilts by a vertical force –
- Uranus Effect on the planets aims to prevent any overturn motion can be done by any planet around the sun and by that Uranus forces the planets to revolve around the sun in the same direction – by this effect- Uranus unifies the planets to revolve around the sun in the same direction
- Uranus effect is seen on the solar system geometry coordinates on Z-axis
Jupiter Effect
- Jupiter effect horizontally on the solar System Geometry
- Jupiter effect on the planets motions aims to provide the consistency between the planets orbital inclinations to save the planets revolutions around the sun in the same direction
Means
- Because of Jupiter horizontal effect on the solar system geometry– the planets don't collide each other through their revolutions around the sun because Jupiter produce the orbital inclinations consistency between all planets Motions
- Jupiter effect is seen on the solar system geometry coordinates on XY-Plain
Gerges Francis Tawdrous +201022532292
The Moon Orbital Apogee Radius Analysis.pdfGerges francis
The Moon Orbital Apogee Radius Analysis
Abstract
Paper hypothesis no. (1)
- The Solar System Be Created Based On One Geometrical Design
Paper hypothesis no. (2)
- The Solar Planets And Their Distances Be Created Out Of One Light Beam
- This Light Beam Travels With A Velocity 1.16 Million Km Per Second
Paper hypothesis no. (3)
- The moon Metonic Cycle be created by an effect of Uranus motion on the moon motion which necessitates to decrease the moon orbital apogee radius from 413600 km to 406000 km.
Paper hypotheses Explanation
- The paper provides a new vision tells that (The Solar System Be Built Based On One Geometrical Design)
- The design can be in any form as a cube or triangle ……etc
- Means,
- The solar planets and their distances integrate their motions into one design.
- Let's ask
- What does prove this vision? (question no. 1)
- What's the result of this design? (question no. 2)
- How this one design be created? (question no. 3)
- (1st Question)
- The solar system one design be proved by my 3 equations which are
- (1st Equation)
- d2= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- this equation uses the planets order because each planet orbital distance depends directly on its previous neighbor
- The equation tells, the distance from the sun to Pluto be distributed geometrically in order regardless the planets data – neither their masses nor their diameters –
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The moon uses pythagoras triangle technique in its orbital motionGerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion
Abstract
Paper hypothesis:
- The moon uses Pythagoras triangle as one of the moon orbital motion techniques
The hypothesis Explanation:
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement through its orbit can be less than (88000 km) by using Pythagoras triangle technique.
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- That means, if the moon displacement (88000 km) can't be decreased and be its daily orbital displacement through its, the moon would revolve around Earth through only its orbit apogee (r=0.406 mkm) and can't revolve through any more near orbits.
- The moon using of Pythagoras triangle in its orbital motion, creates a great Pythagoras triangle controls the moon orbital motion and its orbit geometrical structure.
Paper objective:
- The paper proves this fact and discusses the geometrical basics based on which the moon orbital triangle is created.
Gerges Francis Tawdrous +201022532292
The Solar Planets Motions Use Different Rates Of Time (Revised)Gerges francis
The Solar Planets Motions Use Different Rates Of Time (Revised)
Abstract
Paper hypothesis
The Solar Planets Motions Use Different Rates Of Time
Paper Hypothesis Explanation
- The planets motions rates of time be defined by using ONE RULE
- Based on the planets motions rates of time, the planets orbital periods and distances be defined. means,
- Based on this One Rule, the solar planets orbital periods and distances be defined.
- If the solar planets motions be independent from one another, how their orbital periods and distances be defined based on one rule only?
- The paper provides a proof that, the planets motions use different rates of time which proves that, the solar planets move one unified general motion. means,
- The solar planets motions be integrated with one another and created one unified general motion, because of that, the planets motions need to use different rates of time to enable their motions to be integrated into one unified general motion.
- This fact changes the solar system description inherited from Newton theory of the sun mass gravity. The solar planets be similar to carriages in one train move together one unified motion. also the solar group can be similar to a mechanical clock, and the planets be similar to the gears of this clock. Each gear does one motion (and creates one rate of time) and these motions be integrated into one unified gnarl motion (and the rates of time be integrated into one unified general rate of time)
Paper objectives
- The paper provides the rule based on which all solar planets orbital periods and distances be defined, and test all planets motions data to prove that, no planet motion contradicts this rule.
- The paper tries to answer the question (why the solar planets use different rates of time) by providing The Solar System Creation And Motion Theory.
- The paper is divided into 2 parts.
- (1st Part) Provides the rule and its proves discussion
- (2nd Part) Provides The Solar System Creation And Motion Theory
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The moon orbital motion geometry (revised) (2)Gerges francis
The Moon Orbital Motion Geometry (Revised) (2)
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
Neptune Motion Analysis Disproves Newton Theory Gerges francis
Abstract
Paper hypothesis
The Decision of Nobel Prize for Physics 2021 Is Mistaken
Paper hypothesis explanation
- Uranus Orbital Distance = 19.2 Earth Orbital Distance
- This fact tells, if Uranus and Earth velocities be equal, while Uranus revolves around the sun one complete revolution Earth would revolve around the sun 19.2 complete revolutions (19.2 years) - But
- The Earth moon moves a cycle called Metonic Cycle extends for 19 years. this fact creates a puzzle because Earth Cycle is 4 years only (365+365+365+366 =1461 days) and by that the Earth itself doesn't know about Metonic Cycle –
- The question be (How does the moon move Metonic Cycle if Earth doesn't?)
- The answer is …
- Uranus motion effects on the moon motion and caused the moon to move Metonic Cycle (19 years) – Simply, Metonic Cycle is the result of Uranus Motion effect on the moon motion.
- Now, Why The Nobel Prize Decision For Physics 2021 Is Mistaken?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The moon uses pythagoras triangle technique in its orbital motion (part no.3)...Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No.3) (Revised)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation (theta= theta + 1.7 degrees) which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Geometry (Revised)Gerges francis
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
(Preprint No. 3) (Planet 8 Days Cycle)
Abstract
Paper hypothesis
The Planets Motions depend On 2 Basic Cycles which are:
(A Cycle Of 8 Days) and (A Cycle of 6 days)
The hypothesis explanation
- The paper hypothesis tells, the solar planet motion can't be considered as an independent motion, because the planets move together based on one general system. This system uses (8 days Cycle) of some planets and (6 days Cycle) of other planets to create a general unified motion.
- Based on that the solar planets motions should be considered as (A Train Carriages Motion). The Planets move together one unified motion in which the planets motions data be complementary with each other
- That proves the claim, the solar group is created based on one geometrical design and that necessitates the planets data to be complementary with one another. by that the solar group should be considered as one machine of Gears and each planet is a gear in it.
- The (8 days) and (6 days) cycles should be used as a proof for this fact.
Paper contents
- The paper explains and discusses the 2 basic Cycles.
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Paper question
-Earth (29.8 km/s) moves during (24 hours) a distance = 2574720 km
- The Earth moon displacements total during 29.53 days = 2598693 km
- Pluto (4.7 km/s) moves during (153.3 h) a distance = 2593836 km
- Uranus (6.8 km/s) moves during 378675 seconds a distance = 2574990 km
- Mars (24.1km/s) moves during 29.53 hours a distance = 2562023 km
- Why These Distances Are Equal Approximately? (The difference 1%)
Paper Claim
- The paper claims, these distances are equal to enable Pluto to move during its day period a distance = the moon displacements total during its day period, because the equality of these distances has a geometrical necessity for the solar system motion.
- The claim depends on a new description for the solar system which is:
o The solar group is one building and each planet is a part of it
o The solar planets move one unified motion as train carriages
o The solar group is one machine can be considered as (A Great Clock)
o The solar planets data is created depending on one another.
Gerges Francis Tawdrous +201022532292
Can Light Velocity Effect On The Moon Orbital Motion? (Revised)Gerges francis
Abstract
Paper Question
-Can Light Velocity Effect On a Planet Motion?
The Question Explanation
- We observed frequently that, a Planet motion shows light motion features
- Indeed We have observed features as (different rates of time – Lorentz length Contraction phenomenon – distance values are used as periods of time) which are light motion features
- But,
- We couldn't catch the light motion (or any high velocity motion) can cause these features.
- because of that, I have to provide the detailed data in best order and description to be a source of knowledge to whom may concern to help.
- This paper provides a sufficient proof for the claim (Light Motion Features Are Discovered In Planets Motions). Where the paper tries to provide all detailed data and all possible support to whom tries to answer the question (How Can These Features Be Belonged To A Planet Motion?)
Gerges Francis Tawdrous +201022532292
The Moon Orbit Analysis
Earth Moon motion has specific 4 points which are:
1. Perigee Point (R1) : Radius 363000 km from Earth (the nearest point)
2. Total Solar Eclipse (R2) : Radius 377000 km from Earth
3. Average Moon Orbit (R3) : Radius 384000 km (registered)
4. Apogee Point (R4) : Radius 406000 km from Earth (the most far point)
These 4 points are defined by 4 geometrical rules which are:
- (1st Rule) Pythagoras rule : R2n + (86000km)2= R2n+1
(why 86000 km? we'll discuss that in this paper)
- (2nd Rule) Moon Orbital Circumference at Rn= (1/Rn+1)
- (3rd Rule) (Moon Orbital Circumference at Rn+1/ Moon Orbital Circumference at Rn) =1.0725
- (4th Rule) The Rate 365.25
This paper tries to prove this fact, and discusses more deep question… why the moon orbital different radiuses are defined by these 4 geometrical rules?
Another Force Effect On The Earth Moon Motion Gerges francis
Paper Hypothesis
- There's another force effects on the Earth moon motion
The Hypothesis Explanation
- The moon data shows that, there's one more force effects on the moon motion, the hypothesis means that, the moon motion revolving around Earth is a result of effect of 2 different forces – these 2 forces are (1) Earth gravity force (2) 2nd force effect on the moon motion
- This 2nd force must be equal Earth gravity force, and it effects on the moon motion orbit from the other side, and can be proved in the moon motion trajectory
- This 2nd force has a great effect on the moon motion understanding, because without it the moon orbit can't be created, but this force origin is a puzzle!…….
- The Earth mass = 4 planets (Mercury + Venus + Mars + the moon) masses total, this data tells that, the 4 inner planets masses may produce a total gravity = Earth gravity – but this conclusion can easily be disproved because of the great distances between the 3 inner planets and the Earth moon
- The dilemma is that, the 2nd force is a real one and its effect can be seen in the moon motion, and the masses equality provided the required data to explain this real force, but the distances disproves simply this proof…. How to solve that?
Paper Objective
- This paper objective is limited to prove the 2nd force existence. The paper tries to show this force effect as clear as possible on the moon motion trajectory, in addition to refer to this 2nd force origin.
Gerges Francis Tawdrous +201022532292
Is There A Geometrical Shape For The SpaceGerges francis
Is There A Geometrical Shape For The Space?
Yes …
How to prove?
Let's see the moon orbit data in following:
1- Earth moon distance at perigee radius = the outer planets diameters total (1%)
2- Earth moon distance at apogee radius = the solar planets diameters total
3- The moon orbital distance between Perigee and apogee = Earth Circumference = the inner planets diameters total
4- Earth moon distance at total solar eclipse radius = Saturn Circumference
How to explain this data? Can we imagine that Saturn is created after the Earth Moon creation and Saturn used the moon Data
Imagine you have an area and you used partitions to create rooms and offices in this area – now – imagine that – these partitions are so transparent and can't be seen by any person – how to know if the partitions are found or not?
They prevent you to pass– when we don't see the partition it forces us to stop – the moon has to stop at defined points in its motion – the moon can't move beyond neither perigee nor apogee, where both points are defined by other calculations NOT related to the moon motion – even if we don't know yet by what geometrical mechanism the planets diameters total can restrict the moon motion! but because the same points are defined by other calculations that tell us – the restriction points were made by The Space Division and not by the moon motion – that's what I try to prove in this paper – and if I prove that the space is divided, that will prove my claim – "There's A Geometrical Shape For The Space"
Paper Contents
2- The Earth Moon Orbit Analysis
3- Jupiter Effect of the Earth Moon Creation and Motion
4- Mars Migration Theory Revision (The Earth Moon Creation)
Gerges Francis Tawdrous +201022532292
Abstract
- The solar group is a clock..
- The paper tries to develop our understanding for the solar system motion…
- The classical description which tells - The solar planets are rigid bodies separated from each other in their creation and motion, revolving around the sun by the masses gravity forces – this description fails frequently to explain Planets Motions Data …
- The paper vision tells – The solar planets are one trajectory of energy, or one thread (or one light beam) and each planet is a knot on this thread or a point on this trajectory of energy –
- The solar group – based on the new vision – is one geometrical building and each planet is a part of this same building – and Because of that – Each plant data must be complementary to other planets data –
- (A Complementary Data) is similar to an electron and a positron are produced by the double production experiment – where each particle charge is defined based on the other particle (because of charge reservation law) – similar to that – each planet creation and motion data must be complementary to the other planets to support the general motions harmony –
- That makes the solar group as a machine of gears, and because of the data dependency on one another, that refers to (A Motion Transportation) is found among the planets.
Gerges Francis Tawdrous +201022532292
Why The Earth Moon Distance = The Planets Diameters Total (III) Gerges francis
Paper Question
Why The Earth Moon Distance (At Apogee Radius) = The Planets Diameters Total?
Because
(1)
The Matter Is Created Based On Its Motion –
That means
The moon daily displacement =88000 km – is the reason based on which– the moon diameter is created to be = 3475 km –
This fact can be proved by analyze Saturn Creation and Motion Data
(Point No. 2 of this paper discusses this question)
(2)
We Still Analyze The Moon Orbit Geometrical Structure, Where the moon orbit shows that there's a geometrical design forces the moon to move specific motion and specific displacement daily
Gerges Francis Tawdrous +201022532292
The moon uses Pythagorean triangle as one of its motion techniques
-The moon displacement = 88000 km, and during 29.5 days the total displacements will =2.598 mkm, which should be = the moon orbital circumference.
- (2.598 mkm = 2π x 413000 km) (the moon apogee radius =0.406 mkm) (1%)
- According to this data, the moon would revolve around Earth through its apogee orbit only during a month.
- The moon solves this dilemma by creating an angle (θ) between its displacement motion direction and its orbit horizontal level, by that, the real displacement through the orbit be (L =88000 km cos (θ)), where (L) will be less than 88000 km and the moon can revolve around Earth through more orbits than its apogee orbit
- The moon using of Pythagorean triangle technique creates the moon orbit in a triangle form.
Gerges Francis Tawdrous +201022532292
The Moon Geometry
The Moon Data Analysis shows the following:
1- Earth-Moon is an unique planet in the solar group and not similar to any other moon in the group.
2- The Solar Planets are connected together geometrically
i.e.
3- The solar planets are created to be complementary to each other, all of them together consist one geometrical structure (as a triangle, square, or pyramid….)
That means
a. There was an original energy before any matter existence. And from this energy the planet matter is created (based on E=mc2) and the planet orbital distance is created (I suppose the space = Energy). This same energy also causes the planet motion as part of the general geometrical structure.
b. Each solar planet is a part of this same geometrical structure and has a specific job in it (that means no part is absent..! means the original energy created all required planets to form the required geometrical structure)
c. Each Planet Data is created to be suitable for the planet job in the general geometrical structure..
Previous Paper Conclusion
-Planets Cycles Periods are defined relative to each other.
Example
-Mercury & Venus Cycles Periods interacted with each other, creating an effect on Earth Moon Cycles and causing that, The Moon Orbital Period to be equal Its Rotation Period (27.3 days)
-This effect of Mercury and Venus, on Earth Moon Cycles Periods, is a general effect on the solar system, and be seen also on the outer planets cycles periods
-A result of that, The Outer Planets Days Periods Are = Their Rotations Periods – this is found Because Earth Moon Orbital Period = Its Rotation Period =27.3 days
A Proof
-The Outer Planets Rotation Periods Total =(Earth Moon Rotation Period /Π)
(Planets Cycles Periods, Means, Planet Orbital Period, Planet Rotation Period And Planet Day Period)
Paper Objective
-This paper provides more proves for the claim that "The Outer Planets Rotations Periods Are Found Depending On Earth Moon Rotation Period"
The Solar Group is A Clock (VII)
Abstract
Paper Question
- Can The 1 second period of time be different from a planet to another?
The question discussion
- Someone told that, the second period is a human made unit!, It's not true,
- Earth day period (24 hours) – Earth rotation period (23.9 hours) = 0.1 hour
- This fact forces us to divide the solar day into 24 hours and the 1 hour into 60 minutes – easily by using the same rate we define the second period. That means, the time units are defined based on planets motions and cycles
- The direct question is, why we suppose (Earth second period of time) = (Mercury Second period of time)? On what base this hypothesis is suggested?
- The idea is that, because the time unit is defined depends on planet motion features, and these features are changed from one planet to another, that causes the time unit (period) to be different from one planet to another…
Gerges Francis Tawdrous +201022532292
Abstract
Paper question
- Can The Motion Be Transported From A Solar Planet To Another?
The Question Explanation
- The planets use (8 days and 6 days) cycles and these cycles refers to a form of the transportation of motion among the solar planets
- The motion transportation is done based on different rates of time found among the planets
- Based on that
- 1 hour of Mercury motion be equivalent to 24 hours of Uranus motion
- And because
- (Venus velocity / Mercury velocity) = 0.738
- 1 hour of Venus motion be equivalent to 17.7 hours of Uranus motion
- This claim should be the paper hypothesis, where the paper tries to prove this fact
- By proving the different rates of time (specifically 1 hour of Venus Motion = 17.7 hours of Uranus Motion), that gives a reference of mutual effect of planets motion on one another which gives support for the motion transposition claim.
Gerges Francis Tawdrous +201022532292
Abstract
Paper Question
How to form the required hypothesis?
The Question Explanation
- The data analysis method 1st step is (The Directed Data Definition)
- The data analysis method 2nd step is (The hypothesis formation)
- The hypothesis is the task without which the data can't create any meaning.
- The hypothesis basically tries to answer (How the directed data is created?)
- Sometimes the data be so difficult to enable any hypothesis to be formed but the hypothesis is a basic step can't be canceled, in this case such data can not be used.
Gerges Francis Tawdrous +201022532292
Jupiter And Uranus Effect On The Solar System GeometryGerges francis
Paper Hypothesis
The Solar System Coordinates have 3 Axis –XY Plane Is Controlled By Jupiter Effect – And Z-Axis Is Defined By Uranus Effect
The Hypothesis Explanation:
Uranus Effect
- Uranus effects on the solar system vertically
- Uranus effects on the planets axial tilts by a vertical force –
- Uranus Effect on the planets aims to prevent any overturn motion can be done by any planet around the sun and by that Uranus forces the planets to revolve around the sun in the same direction – by this effect- Uranus unifies the planets to revolve around the sun in the same direction
- Uranus effect is seen on the solar system geometry coordinates on Z-axis
Jupiter Effect
- Jupiter effect horizontally on the solar System Geometry
- Jupiter effect on the planets motions aims to provide the consistency between the planets orbital inclinations to save the planets revolutions around the sun in the same direction
Means
- Because of Jupiter horizontal effect on the solar system geometry– the planets don't collide each other through their revolutions around the sun because Jupiter produce the orbital inclinations consistency between all planets Motions
- Jupiter effect is seen on the solar system geometry coordinates on XY-Plain
Gerges Francis Tawdrous +201022532292
The Moon Orbital Apogee Radius Analysis.pdfGerges francis
The Moon Orbital Apogee Radius Analysis
Abstract
Paper hypothesis no. (1)
- The Solar System Be Created Based On One Geometrical Design
Paper hypothesis no. (2)
- The Solar Planets And Their Distances Be Created Out Of One Light Beam
- This Light Beam Travels With A Velocity 1.16 Million Km Per Second
Paper hypothesis no. (3)
- The moon Metonic Cycle be created by an effect of Uranus motion on the moon motion which necessitates to decrease the moon orbital apogee radius from 413600 km to 406000 km.
Paper hypotheses Explanation
- The paper provides a new vision tells that (The Solar System Be Built Based On One Geometrical Design)
- The design can be in any form as a cube or triangle ……etc
- Means,
- The solar planets and their distances integrate their motions into one design.
- Let's ask
- What does prove this vision? (question no. 1)
- What's the result of this design? (question no. 2)
- How this one design be created? (question no. 3)
- (1st Question)
- The solar system one design be proved by my 3 equations which are
- (1st Equation)
- d2= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- this equation uses the planets order because each planet orbital distance depends directly on its previous neighbor
- The equation tells, the distance from the sun to Pluto be distributed geometrically in order regardless the planets data – neither their masses nor their diameters –
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The moon uses pythagoras triangle technique in its orbital motionGerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion
Abstract
Paper hypothesis:
- The moon uses Pythagoras triangle as one of the moon orbital motion techniques
The hypothesis Explanation:
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement through its orbit can be less than (88000 km) by using Pythagoras triangle technique.
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- That means, if the moon displacement (88000 km) can't be decreased and be its daily orbital displacement through its, the moon would revolve around Earth through only its orbit apogee (r=0.406 mkm) and can't revolve through any more near orbits.
- The moon using of Pythagoras triangle in its orbital motion, creates a great Pythagoras triangle controls the moon orbital motion and its orbit geometrical structure.
Paper objective:
- The paper proves this fact and discusses the geometrical basics based on which the moon orbital triangle is created.
Gerges Francis Tawdrous +201022532292
The Solar System Creation And Motion (Question And Answers) (Part 1).pdfGerges francis
The Solar System Creation And Motion (Question And Answers) (Part 1)
Abstract
A Question No. 1
Is There A Simple Proof For Light Motion Effect On Planet Motion?
A Question No. 2
Can The Planets Velocities Be Distributed Based On A Geometrical Design?
A Question No. 3
Is There A Simple Proof For The Solar System Distances Creation In A Network Form?
A Question No. 4
What Proves Are Available For The Existence of The Light Supposed Velocity (1.16mkm/sec)
A Question No. 5
How does Planet velocity be defined? Is There an Equation can be used for all planets velocities?
A Question No. 6
(Planets Velocities Are Created Complementary To One Another)
How to prove this statement?
A Question No. 7
Can Jupiter and Uranus Velocities Be Defined Based On One Another?
A Question No.8
What Basic Points Be Provided By The Solar System Creation And Motion Theory?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Revised)Gerges francis
Paper hypothesis:
-The moon uses Pythagoras triangle as one of the moon orbital motion techniques
The hypothesis Explanation:
-The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement through its orbit can be less than (88000 km) by using Pythagoras triangle technique.
-The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- That means, if the moon displacement (88000 km) can't be decreased and be its daily orbital displacement through its, the moon would revolve around Earth through only its orbit apogee (r=0.406 mkm) and can't revolve through any more near orbits.
- The moon using of Pythagoras triangle in its orbital motion, creates a great Pythagoras triangle controls the moon orbital motion and its orbit geometrical structure.
Paper objective:
- The paper proves this fact and discusses the geometrical basics based on which the moon orbital triangle is created.
Gerges Francis Tawdrous +201022532292
Paper Question
Why The Moon Orbital Circumference At Apogee Orbit = 2.55 Mkm?
The Question Explanation
- The moon displacement daily = 88000 km, and during 29.5 days (The Moon Day Period), the total displacements will =2.598 mkm, which should be = the moon orbital circumference. But 2.598 mkm = 2π x 413000 km
- The apogee radius =406000 km, is the most far point the moon can reach from Earth, where the perigee radius =363000 km, which is its nearest one
- Why the moon orbital circumference at apogee doesn't = 2.598 mkm?!
Paper answer
- The moon uses a geometrical interaction depends on the difference between these 2 distances (2.55 mkm &2.598 mkm) to create the moon orbital inclination5.1 deg.
Paper hypotheses
(1st) There's a 2nd force effects on the moon motion in addition to Earth gravity
(2nd) Uranus Motion effects on the moon orbital motion and cause Metonic Cycle
Gerges Francis Tawdrous +201022532292
The Solar System Motion Analysis (Revised And Modified).pdfGerges francis
The Solar System Motion Analysis (Revised And Modified)
Abstract
Paper hypothesis no. (1)
- The Solar System Be Created Based On One Geometrical Design
Paper hypothesis no. (2)
- The Solar Planets And Their Distances Be Created Out Of One Light Beam
Paper hypothesis no. (3)
- This Light Beam Travels With A Velocity 1.16 Million Km Per Second
Paper hypotheses Explanation
- Hypothesis no. (1)
- The hypothesis tells, the solar system be created based on one geometrical design, means, the planets dimensions and data be defined by one equation and can be concluded based on one another – this fact the paper proves clearly –
- The paper provides 4 equations which can be considered as a discovery, by them we can conclude the planets fact sheet theoretically without observation, let's prove that by introducing the first equation of them
- d2= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- The equation tells, the distance from the sun to Pluto be distributed geometrically in order regardless the planets data – neither their masses nor their diameters – simply the distance be distributed geometrically regardless planets data –
- (The paper tests and proves the equation) - let's provide the 2nd equation
- (d1/d2) = (v2/v1)2 where (d = planet orbital distance) and (v= planet velocity),
- The equation doesn't use the planets order as the first one –
- The 4 equations tells one clear information which is
- If we know (Mercury orbital distance =57.9 mkm), By use these 4 equations, we can conclude theoretically all planets orbital distances, periods, velocities, their diameters, rotation periods, masses, orbital inclinations and axial tilts. This data we conclude theoretically without observation by these 4 equations
- The next question should be Why? hypothesis no. (2) answers -Because,
- The Solar Planets And Their Distances Be Created Out Of One Light Beam.
- This is similar to Young Experiment (the double slits experiment), the sun rays produces bright fringes and dark fringes (One Design) (If we accept that, we have to suppose the bright fringes be seen by us as matters and the dark as space)
- The paper proves this fact also, by analysis of Lorentz length contraction effect and tries to answer the question (Why does Particle length be contracted by its high velocity motion?)
- But, the complexity isn't finished
- The light beam based on which the solar planets and their distances be created, this light beam travels with a velocity 1.16 million km per second!!
- And how to prove this fact? and from where we know this number 1.16 mkm/s?? (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Abstract
Why Jupiter diameter =142984 km?
We have asked this question before … so why we need a new paper concerning this same question?!
I would write some theory in consistency with the physics book, But I can't!
While the big bang theory tells that the solar planets are created based random actions and events, I provide data proving that, no planet data can be created by any random process, on the contrary, planet data is created depending on each other and complementary to one another.
While the solar system current description tells that, each planet is a separated planet found independent from the other planets data. I provide crucial proves that the solar system is one building and each planet is a part of this same building, and each planet data is created based on the other planets data – as in any creature body its leg data should be proportional to its hand data
While the current theory tells that, the sun is a star produces the sun rays based on nuclear interactions, I prove that, the sun is a mirror and the sun rays energy is produced by planets motion energies total. where Earth motion concentrates the planets motions energies total and produce the rays which is reflected to us as the sun rays…
While the current theory tells that, the matter data is created independently from any factors, I prove that, the matter dimensions are created in proportionality with space dimensions, both are created by light motion.
While the current theory tells us that, Jupiter is a common planet similar to many others, I prove that, Jupiter energy is the origin by which the solar planets are created
While the physics book tells that, the sun is created independently from the planets data, I prove that, The Sun Is Created Depending On Jupiter And Earth Specifically…
The question is, from where I brought these strange ideas?! From the planets data… i.e. I brought these ideas from the Truth.
Gerges Francis Tawdrous +201022532292
The Sun Is The Solar System Last Created Piece (Newton Was Wrong) (Revised)Gerges francis
Abstract
Paper hypothesis
- Newton Theory of The Sun Mass Gravity Be Refuted Decisively By 2 Facts Which Are:
- (1st Fact) The Sun Is Created After All Solar Planets Creation And Motion.
- (2nd Fact) The Solar Planets Move A Type Of Motion Different Completely From The Planet Motion Be Described By Newton Theory Of The Sun Mass Gravity.
Paper Proves
- The (2nd Fact) is proved by The Solar Planets Motions Analysis.
- While Newton had supposed that, Each planet moves independently from the other planets. The fact is that, the planets motions be integrated into one unified general motion. by that, The Planets Motions Be similar to The Train Carriages Motion. or similar to A Machine Of Gears Motion.
- The Planets Motions Data Analysis disproves the Motion Independency Concept, showing that, the planets motions be different completely from Newton Motion Description.
- The (1st Fact) which is (The Sun is Created after all Planets Creation and Motion). This Fact disproves Newton Theory decisively. This fact proves are discussed in this paper introduction.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Paper hypothesis
Venus motion effect on the moon motion and causes the moon orbital period to be = the moon rotation period =27.3 days
The hypothesis explanation..
- The hypothesis explanation can be summarized in 3 questions:
- (1) Can Planet Data Depend On Exaction Equations?
- (2) By What Equation Planet Diameter Can Be Defined?
- (3) How Can Planet Diameter Equation Change The Solar System Vision?
- Let's try to answer these questions in following…
(1st Question)
Can Planet Data Depend On Exaction Equations?
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane or rocket manufacture – the manufacturer needs exact equations to define this plane length, width, weight and all specifications, otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its diameter, mass, orbital distance, period, inclination, rotation period, axial tilt …and all data based on Exact Equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically without observation which prove this fact decisively.
- Then we have to ask (How Planet Data Be Created In Order?)
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves this fact – because – it proves each planet orbital distance depends on its neighbor planet orbital distance –
- d2=4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orbital distance
- Example (Venus orbital distance)2= 4 (Mercury orbital distance) x50.3 million km (Venus orbital distance=108.2 million km Mercury orbital distance =57.9 million km)
- This equation be tested and discussed in this paper – but its concept is a clear one – it tells the planets leave an empty space for the new planet – for that reason each planet orbital distance depends on its neighbor planet orbital distance.
- Logically the new planet can't disturb the current planets positions or motions trajectories – by that –the orbital distance be defined by the neighbors positions –
- (3)
- The new planet has to revolve around the sun based on its orbital distance which be defined obligatorily where no data of this planet be taken into consideration in its orbital distance definition –neither mass nor diameter – instead – the distance be defined based on the neighbor distance.
- But
- Planet diameter should be a function in its orbital distance – otherwise – this planet will be broken through its motion –
- The function between planet diameter and its orbital distance is the necessary requirement to cause the planet safe motion
Gerges Francis Tawdrous +201022532292
We Should Refuse Newton Theory Of The Sun Mass Gravity.pdfGerges francis
We Should Refuse Newton Theory Of The Sun Mass Gravity
Abstract
Paper Discovery
- Planets data be created based on exact equations and mathematical calculations and doesn't depend on any (historical unknown factors or initial conditions)
- As a result, Planets creation and motion data can be concluded theoretically without observation because it's created based on mathematical equations
- I provide 3 new equations and use one more equation based on Kepler law, by these 4 equations using we can conclude All planets orbital distances, periods, velocities, inclinations, rotation periods, diameters, masses and axial tilts…
- This Data Can Be Concluded Theoretically Without Observation.
- The paper tests these 4 equations and proves this discovery
Paper Theory
- The Solar system be created based on One Geometrical Design.
- Means, based on one design all planets creation and motion data be created and by that the planets be parts in one building (or members in one body)
- Can one law control all planets creation and motion data?
- Let's suppose, The Planets Move A Unified Motion (as a machine of gears). This unified motion will force each planet to move a complementary motion to others' to enable the unified motion to be created.
- Planet data should be in consistency with its motion – otherwise – this planet will be destroyed. Means, if planets motions be complementary one another that will cause these planets creation and motion data to be complementary one another, by this vision, One Law controls all planets creation and motion data
- The paper theory tells, the solar system be created based on one geometrical design and be controlled by one law, for that reason the planets data be created based on exact equations – let's refer to these 4 equations in following
- My (1st Equation) d2 = 4d0 ( d- d0)
- d = Planet Orbital Distance d0= Its Previous Planet Orbital Distance
- the equation tells each planet orbital distance depends on its neighbor
- (Kepler Law) Equation (v1/v2)2 = (d2/d1)
- v = Planet Velocity d= Planet Orbital Distance
- The equation tells planet orbit defines its velocity
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Solar planet motion trajectory is a square (proves)Gerges francis
Abstract
The Moon Orbit Uses Earth Circumference To Cover The Solar Planet Motion Real Trajectory (Which Is A Square) And To Show The Imaginary One (An Ellipse)
i.e.
The Solar Planet Real Trajectory Is A Square But The Moon Orbit Uses Earth Circumference To Cover This Real Trajectory And Shows The Imaginary One Which Is The An Ellipse…
The Solar System Be Created By A Light Beam Its Velocity 1.16 mkm.Sec (Revise...Gerges francis
The Solar System Be Created By A Light Beam Its Velocity 1.16 mkm/Sec (Revised)
Abstract
Paper Hypothesis
The Solar System is created out of One light beam its velocity 1.16 mkm/sec
Paper Hypothesis Explanation
- The matter is created out of light beam, and the produced matter moves with its parent light beam by using different rates of time.
- The Solar planets and their distances be created out of one light beam its velocity be 1.16 million per second.
- The light supposed velocity (1.16 mkm/s) is registered in the planets creation and motions data.
The Solar System Description
- Light supposed velocity (1.16 mkm/s) travels a distance = The Planet Orbital Circumference in a period (T seconds)
- Light known velocity (0.3 mkm/s) travels during this period (Ts) a distance = D
- The same planet moves a distance d in a period (=P hours) where
- D = 2π d (Proved by the planets motions data)
- P days = The Same Planet Orbital Period
- And
- The rate between the time (Ts) and this planet orbital period P (in seconds units) be used to define this same planet velocity-
- Where
- (P/ Ts) = (1.16 mkm /V)
- V = the Same Planet Velocity during a solar day
- Shortly
- The planet moves on a circle radius in a period (=P hours) while the light (0.3 mkm/s) travels a distance = This same circle circumference in (Ts).
- The rate between (P and T) periods be used to define this same planet velocity in a solar day, by that both motions be accompanying.
- Where
- The period (Ts) be defined by light supposed velocity (1.16 mkm/s) passing this same planet orbital circumference.
- As a result the planet motion depends on the 2 light beams motions and the planet motion data analysis proves both light velocities are facts
Paper objective
- The paper analyzes the solar planets motions data to prove that their motions depend on Light beam Motion and a light beam its velocity be 1.16 mkm/sec is found and effective on the solar system motion.
- Notice
- This revised version of the paper adds only 4 points of discussion which are (4-4, 4-5, 4-6, 4-7) (from Page No. 48 to Page No. 59) – nothing else is changed
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Moon Orbital Motion More Analysis (II) (Revised) Gerges francis
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
- The moon orbital triangle data analysis lead to the following hypothesis (A 2nd Force must effect on the Moon Orbital Motion in addition to Earth Gravity Force)
- Also the 2nd hypothesis is created based on this first one, (Uranus effects on the moon orbital motion, causing to create Metonic Cycle).
Gerges Francis Tawdrous +201022532292
The Solar System Doesn't Move By The Sun Mass Gravity Gerges francis
Paper hypothesis
- The solar system is created out of one light beam its velocity (1.16 mkm/sec), and moves depending on this light beam motion, And
- The light (1.16 mkm/sec) created the solar system distances in a network form.
The hypothesis explanation
- The existence proves of light supposed velocity (1.16 mkm/s) depend on the solar system distances network proves.
- Because
- The solar system distances be created depending on each other by using the light motion that caused the distances to be created in a network form, or based on one geometrical design.
- Where (Distance = Energy). The distances creation process needed energy which is provided by light motion. by that, light energy be registered in the created distances, and by analysis of the distances values we can conclude that these distances be created by energy provided by a light beam. And also we can discover this light beam velocity be (1.16 mkm/s) because this light beam energy and motion features are registered in the created distances.
Paper objective
- The paper proves the solar system distances network and based on this proof, the paper proves the light supposed velocity (1.16 mkm/s) existence.
Paper Conclusion
- Because the solar system be created out of light supposed velocity (=1.16mkm/s) and the sun light velocity (= 0.3 mkm/s)
- Means, the light (0.3mkm/)be created as a side product from the original one (1.16 mkm/s)
- That proves
- The Sun Is Created After All Solar Planets Creation And Motion Which Disproves Decisively Newton Theory Of The Sun Mass Gravity.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Jupiter Gravity Effects On The Earth Moon Motion Gerges francis
Paper Claim
- Jupiter Mass Gravity Effects On The Earth Moon Motion
- Jupiter Mass Gravity Force Effect On The Earth Moon = 42% Of The Sun Mass Gravity Force Effect On Pluto
- Because the sun gravity keeps Pluto in its orbit, that tells Jupiter force must have an effect on the Earth moon motion
- Based on that, Jupiter gravity is the second force effect on the Earth moon motion
- Such effect can't be performed, neither by Mars because of its very small mass nor by Saturn because of its far distance
- That tells Jupiter Mass Gravity must have a greater effect on Mars motion than its effect on the Earth moon motion, and That's True and because of that (Mars Eccentricity = 0.094) but (The Moon Eccentricity = 0.055), proving that Jupiter gravity effect on Mars so greater than its effect on the Earth moon motion.
Shortly,
Gerges Francis Tawdrous +201022532292
The Solar System Motion Depends On One Geometrical Design.pdfGerges francis
The Solar System Motion Depends On One Geometrical Design
Abstract
Paper Discovery
- The Solar System Motion Depends On One Geometrical Design
The Discovery Explanation
- As in any geometrical design, for example, A triangle – this triangle dimensions and angles be defined based on exact equations –
- If The Solar System Motion Depends On One Geometrical Design – The planets data should be defined by exact equations and can be concluded theoretically
- This is the paper discovery –
- The planets data can be concluded theoretically without observation – means-
- If we know (Mercury orbital distance = 57.9 mkm), by this data only we should be able to conclude All Planets Orbital Distances, Periods, Velocities, Diameters, Masses, Orbital Inclinations And Axial Tilts THEORETICALLY Without Observation.
- The paper tells a new vision that – the planets data aren't created by any random action or historical events instead the data be created based on one mathematical system and based on exact equations – if yes – Why?
- Because
- The Solar System Data Depends On One Geometrical Design
- My (4) equations prove the paper discovery – let's remember them:
- (1st Equation)
- d2= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- This equation uses the planets order because each planet orbital distance depends directly on its previous neighbor
- The equation tells, the distance from the Sun to Pluto be distributed geometrically in order regardless the planets data – this distance be distributed based on one geometrical design (as a chess board). (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Jupiter And Mercury Motions Analysis (Revised)Gerges francis
Abstract
Paper Argument
- Jupiter Motion analysis disproves Newton Theory of The Sun Mass Gravity and Planet Motion Independency Concept.
- Because
- Jupiter Motion depends on Mercury and Mars Cycles Periods
- This dependency proves that,
- The solar planets motions be integrated into One Unified Motion
- Means,
- The solar planets be similar to gears move in one machine they do their motions in comparison with each other, or
- The solar planets be similar to train carriages they move together One Unified General Motion
- The solar system distances be similar to railways be built by energy and the planets be similar to trains move on these railways
- Jupiter Motion analysis disproves Newton theory in 2 basic points which are
- (1) The Planet Motion Can't be Independent from the other planets motions
- (2) The Planet Motion Be done by the same force by which Planet Matter is created, Because the motion features be effective in Planet Matter Dimensions.
Paper Conclusion
- The Solar System Distances Be Created In A Network Form And Based On One Geometrical Design.
- Means
- The distances be distributed based on geometrical design in comparison with other distances and no a single distance be created independent from the other distances
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Can Jupiter motion effect on the Earth moon motion?
The answer usually is (NO) because of the great distance which weaken the gravity force of Jupiter to effect on the Earth moon motion
The question – in fact – tries to reach to the classical mechanics puzzle depth – where the mechanics theory provides us just the gravity force as a reason for particle motion where this gravity force depends on points of masses in the space – by this description – the mechanics provides one choice only depends on separated points in the space removing any feature of the Integrating Geometrical Cooperation
Based on that –
The solar system is consisted of separated planets found independently from each other and these planets revolve around the sun by the masses gravity forces
The solar system planets data provides another vision – where there's a clear dependency between the planets data – which supports the integrating geometrical cooperation and contradicting the mechanics theory –
The situation becomes more clear now – it's not related to some similar data between 2 planets or some pure coincidence of 2 planets motions – it deals with the concept behind – where 2 different visions fight each other fiercely – one vision tells that we deal with separated points in the space and the other tells that we deal with a geometrical building uses the planets matters and distances to create one geometrical building – because of that – the planets data are created depending on each other –
Now – we may ask again –
Why We See The Sun Disc = The Moon Disc? Because
(The Sun diameter/ the moon diameter) =(Earth orbital distance/ Earth moon distance)
The geometrical force which created the solar system used planets diameters and distances to create A Geometrical Situation- the answer (Coincidence) is incorrect – but the wrong answer is originated from a wrong concept –
Gerges Francis Tawdrous +201022532292
Does Planet Day Period Depend On Its Circumference (VI)Gerges francis
Paper hypothesis
-The Moon Orbital Distance Is Proportional To Its Parent Circumference
-This hypothesis is suggested by the previous observation, which are
o Saturn moves during its day period a distance = its circumference
o Jupiter moves during its day period a distance = its circumference (+4%)
o Neptune moves during its day period a distance = 2 x circumferences
o Uranus moves during its day period a distance = 2.6 x circumferences
- This observations lead us to conclude that, Planet motion may depend on its circumference or the motion distance be function of the planet circumference..
- Then, the moon orbital radiuses analysis lead us to conclude this hypothesis, this paper tries to prove it
- By the hypothesis prove, many other old claims can be supported in addition, let's write them down here:
Gerges Francis Tawdrous +201022532292
Jupiter and mercury motions analysis (revised) (2)Gerges francis
Abstract
Paper Argument
- Jupiter Motion analysis disproves Newton Theory of The Sun Mass Gravity and Planet Motion Independency Concept.
- Because
- Jupiter Motion depends on Mercury and Mars Cycles Periods
- This dependency proves that,
- The solar planets motions be integrated into One Unified Motion
- Means,
- The solar planets be similar to gears move in one machine they do their motions in comparison with each other, or
- The solar planets be similar to train carriages they move together One Unified General Motion
- The solar system distances be similar to railways be built by energy and the planets be similar to trains move on these railways
- Jupiter Motion analysis disproves Newton theory in 2 basic points which are
- (1) The Planet Motion Can't be Independent from the other planets motions
- (2) The Planet Motion Be done by the same force by which Planet Matter is created, Because the motion features be effective in Planet Matter Dimensions.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Similar to The Moon Orbital Motion Description (2nd Revised) (20)
2012 Phenomenon Has Told Facts Because (The Sun Is A Phenomenon).pdfGerges francis
Best greetings –
2012 Phenomenon has told Facts Because (The Sun Is A Phenomenon)
Abstract
Paper hypothesis
The sun is a phenomenon created by the planets motions – means - the sun is not doing nuclear fusion to create its rays but the sun rays be created by Planets Motions Energies total- As a result – the sun is created after all planets creation and motion which disproves Newton theory of the sun gravity where no planet moves by the sun gravity –
The hypothesis explanation
The sun creation as a phenomenon depends on the planets motions energies shows a great gab between the solar system motion description and the real facts of this motion –for that reason – I provide 2 more points to confirm this gab existence while the 2 points be less strange in meaning can prove clearly this gab is found deeply in the description– not only for the sun rays source of energy but also for the basic ideas of the solar system motion.
(Point No. I)
The Mass Gravity Force Can't Cause The Solar System Motion
The planet moves by the force which caused its creation otherwise this planet will be broken by its motion because 2 forces affect on it- Newton Is Wrong In Logic – But –
I wish to move beyond this point –because – I refuse generally the mass gravity force using as a reason for the solar system motion – the idea is wrong in concept –
Basically because
The mass gravity force is so limited force in range and can't provide the solar system motion features – we need one more powerful and intelligent force – the eclipse phenomenon may help this explanation –the force which created the planets diameters in proportionality with specific distances – and the sun diameter be used also in this process- the force considers each planet motion and velocity – thinking about the whole process to produce the total solar eclipse by many players their creation data be created for this purpose.
Usually the total solar eclipse be considered as pure coincidence result and the beauty of geometry be removed- the paper analyzes the eclipse geometrical data to show a small part of the beauty –
Can the mass gravity poor concept do that? the description Newton told can explain how the matter be created? or how is planet data created? why is the moon diameter =3475 km? because if it be 5000 km the whole geometry will be changed….
The moon creation can help to see another part of this force beauty – the moon be created by planets collision but the moon diameter be created based one exact equations – means- the force works geometrically even through the collisions
In fact
This idea also shows the gab between the solar system facts and the current theory because – while – the current description supposes the planets data be created by random process, initial conditions and unknown historical factors that fact is that the planets data be created based on exact equations
Gerges Francis Tawdrous +201022532292
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Rays Production Theory
Abstract
Paper hypothesis
The Sun Rays Energy Source Is The Planets Motions Energy – means- The Sun Is Not doing nuclear fusion to create its rays – instead – the planets motions energies total be used to create the sun rays.
The hypothesis explanation
I- The Sun Rays Creation Depend On The Relative Motion Concept
This point provides the method by which the sun rays be created – the rays creation depend on the relative motion – that means- we need to find 2 motions in the solar system move relative one another and the different velocity between the 2 motions be = Light Velocity = 300000 km/sec
Regardless – this is possible or not – our job be defined clearly –
We need 2 motions move relative one another and the different velocity between these 2 motions be = Light Velocity = 300000 km/sec
II- Can We Attribute Mechanical Features For The Space?
Here we try to produce the 2 relative motions –
(Let's suppose the sun isn't found but the planets still revolve around its space point)
We have to attribute mechanical features for the space – let's do that in following
We suppose the space be similar to a sea water and the planet be similar to a stick moves perpendicularly through the sea water – this is similar to – a spoon turns water in a vessel - the spoon motion through the water causes a wave in the water –
The theory supposes the planet motion causes a wave in the space –
let's use this hypothesis in our analysis…
Mercury revolves around the sun (point) with velocity 47.4 km/sec – how to see that in our description?
Mercury (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Mercury velocity is 47.4 km/sec and that causes the wave velocity to be (47.4 km/sec)
And -
Venus (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Venus velocity (35 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec = 82.4 km/sec)
And – The Earth moon (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion –the moon velocity (29.8 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec +29.8 = 112.2 km/sec) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Is a Phenomenon, Created By The Planets Motions Energies (revised).pdfGerges francis
Paper hypothesis
The solar planets distribution between the sun and Pluto depends on one design – this design uses the distance 90000 million km as a distance unit.
The hypothesis explanation
The hypothesis tells – the planets distribution uses one design and this one design gives a chance for the planets to make their distances total equal 90000 million km for a unit period of time – there's a necessity to use this distance we explain here.
The data shows 2 facts
(1st Fact) One Map (One Design) Controls The Planets Distribution Between The Sun And Pluto –
(2nd Fact) This One Design Uses The Distance 90000 Million Km As A Unit
Paper first question
Why does the solar system design use the distance 90000 million km as a unit?
Let's answer in following…
If (c =300000 km/sec = light velocity) how can we measure the value (c2)?
Let's suppose we use the value (c2) for one second – how can we measure it?
In this case the value (c2) will be = 90000 million km
Now
The hypothesis tells, the planets motions aim to pass this distance (90000 million km) and to use this distance based on A Motion For A Period Of Time = One Second
(We Discover In The Paper Discussion How This Motion Can Be Created)
As a result –
The distance 90000 million km will be a equivalent to the value (c2)
And
The value (c2) is the source of energy from which the sun rays be created.
Based on that
The Sun Rays Be Created By The Planets Motions Energies Total
Means,
The Sun Is Not Doing Nuclear Fusion - Instead – the planets motions energies total be accumulated and be used as energy source to produce the sun rays- then the sun disc and body be created from the sun rays energy.
And
Because the planets motions aim to create the sun rays they aim to pass the required distance 90000 million km and the solar system design causes this distance to be used by a motion depends on one second
Paper second question
Can Light Beam Be Produced By Matters Relative Motion?
The planets motions distances total per solar day (=17.75 million km)
(This distance contains the Earth moon velocity which is equal Earth velocity)
During 1461 days the planets motions distances total be =25920 million km
Light (300000 km/s) travels in one day (86400 s) a distance =25920 million km
But the Earth Cycle is (365 +365+365+366 =1461 days)
The idea tells us – if 1461 seconds of the Earth motion = 1 second of the sun motion – the velocities difference between the 2 motions will be= Light Velocity (300000km/s)
The paper discusses how that can be possible- but – here – we discuss the conceptual question- can light beam be created by matters relative motion?
The planets data tells about a new method which is (Motions Use Different Rate Of Time) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
The Sun Is Not Doing Nuclear Fusion
Saturn motion causes to produce the sun rays
means, Saturn moves by light velocity relative to the sun point –
The hypothesis Proof
The paper hypothesis tells Saturn motion causes to produce the sun rays
Let's prove that in following
(1)
The Planets Motions Use Different Rates Of Time Where
One hour of Mercury motion be = 24 hours of any planet motion (except Saturn)
One hour of Any Planet motion be = 24 hours of Saturn
These rates of time be proved in the paper discussion.
(2)
Saturn moves a distance =90000 million km in a period = 107470 days
The period 107470 days (of Saturn) = 576 x 186.6 days (Of Mercury)
Means this period (107470 days) be seen on Mercury as (186.6 days)
(3)
The 9 planets velocities total be =176 km/sec –
This total be created relative to the point of space on which the sun will be created –
Means
We suppose the sun isn't found and the planets still revolve around the point of space on which the sun will be created-
Mercury (47.4 km/s) revolves around this point of space and creates a different in velocity with it = (47.4km/s)
Venus (35 km/s) revolves around this point and creates a different in velocity = 47.4km/s + 35km/s =82.4 km/s
The 9 planets velocities total 176 km/s causes to create a different velocity =176 km/s with this point of space
Now
The rate of time be created based on the rate of velocities –means
1day of this point of Space be =176 days of Mercury
(Mercury controls this velocities total 176 km/s)
But
107470 days (of Saturn) be =186.6 days (of Mercury) = 1.0725 days of the point of space
We know the rate (1.0725) effect on the solar system – for example – this rate effect on 40% of all distances and 60% 0f all planets axial tilts and effect on many other data-
By this rate (1.0725) the period (1.0725 days) will be = one day
Means
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space
But
The solar system creation theory tells– the planets matters and their distances be created from one energy and this energy be provided by one light beam and the planets move with this light beam based on the rate of time (One Second of Light motion be = One Solar day of Planet Motion)
This must be the same rate be used with the space because the matter and space be created together.
As a result
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space =one second of light motion
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
(1)
The Sun Rays Be Produced By Planets Velocities Total - The Sun Is Not Doing Nuclear Fusion
Light (300000 km/sec) travels in one solar day a distance = the solar planets motions distances total in 1461 solar days–
The solar planets velocities total uses this rate of time (1=1461) and produces light velocity (300000 km/sec) from the planets velocities total
(2)
If the solar planets motions can't produce light velocity the solar system would be destroyed.
Paper conclusion
Because the sun rays energy be provided by the planets motions energies total and the planets move in cycles – that necessitates – the sun creation and death depend on a cycle –means- after this sun be dead another sun will be created because the sun is a phenomenon created based on a cycle (as the eclipse)
The hypothesis explanation
(1)
The Planets Matters And Their Distances Be Created Out Of One Energy -
This idea can be acceptable simply by the physics book because it's known that the matter and space be created of energies – here – I add one idea only tells that-from the same one energy the planets matters and their distances be created –
The matter and space have different forms spite they be created from the same energy because the creation rules be different for them- as the oil and coal - they be created from the same source but the creation rules be different and the forms be different as a result
The idea causes basic change in the solar system motion description–because –instead of the separated planets as separated points – we deal with one energy which causes to create a continuum of data – by that –the data can be transported among the planets (in fact it does).
The idea doesn't create any new thing– but – it discovers the unjustifiable description for the planets motions – where it be believed that the planets are separated from one another as islands in a sea and no connection can be available – this description is mistaken in concept because the matter is created of energy and the space is created of energy and it's illogical to prevent the contact between them -here – the transportation of data among the planets should be a proved fact depend on the planets motions.
Shortly
The continuum of data of the solar system is a logical fact should be proved, and the separated points description should be considered unjustifiable vision.
A Conclusion
From one energy the planets matters and their distances be created
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Is A Phenomenon
Abstract
Paper hypothesis
The solar planets velocities total be equivalent to light velocity 300000 km/s
The hypothesis explanation
- The Sun Is A Phenomenon Created By The Planets Motions –
- Means-
- The Sun Rays Energy Source Isn't Any Nuclear Interaction Found Inside The Sun – But – The Sun Rays Energy Be Found By The Planets Motions Energies Total
- Shortly
- The Planets Velocities Total Be Used As One Motion Velocity – And This Motion Uses A Rate Of Time To Reach To Light Velocity.
- Let's explain that in details in following…
- (1)
- We need to suppose that (One Hour Of Mercury Motion =24 Hours Of Any Planet Motion) and
- (One Hour Of Mercury Motion = 24 Solar Days Of Saturn Motion)
- These rates of time be proved in the discussion clearly –
- (2)
- The 9 planets velocities total be =176 km/sec – this value be seen in Mercury Data as (176 solar days = Mercury Day Period)
- We conclude that, Mercury controls this velocities total 176 km/s
- And
- After The Earth Moon Creation, the moon velocity 29.8 km/sec be added to the 9 planets velocities total (176 +29.8 =205.8 km/s)
- The total 205.8 km/s be seen in the moon motion data as (205.8 x π =655.7) (error 1.4%) where (655.7 hours = the moon rotation period)
- That tells the velocities total be seen also in the moon rotation period (a cycle period as Mercury)
- But
- Why for Mercury used (DAYS) but for the moon used (HOURS)??
- Because
- (One Hour Of Mercury Motion = 24 Hours Of The Moon Motion)
- (3)
- The total (205.8 km/s) can create the velocity 300000 km/s only if the rate of time (1=1461) be created – let's see the light velocity creation -
- 300000 km = 205.8s x 9.7 km/s x 24 x 2π
- Let's explain how the light velocity (300000 km/s) be created.
- The planets velocities total (205.8km/s) moves for 1second and passes 205.8 km, this distance be sent from the moon to Saturn in a period form (205.8 seconds)
- But (one hour of any planet motion = 24 hours of Saturn motion) for that reason the period (205.8 s of the moon motion) be equal = (205.8 s x 24) of Saturn motion.
- The rate (2π) be found by the geometrical design
- The data tells, each second Saturn moves, passes a distance =9.7 km but the solar system passes a distance =300000 km
- If the solar system moves (one motion) and uses (one velocity) for this distance (300000 km) for each second - The Solar System Velocity Should Be Equivalent To Light Velocity (300000 km/s) – means – The Planets Velocities Total Should Be Equivalent To Light Velocity (300000 km/s) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
National Bank Of Egypt Practice The Fraud (2020-2022).pdfGerges francis
Please help (1-9-2022)
National Bank Of Egypt Practice The Fraud (2020-2022)
National bank of Egypt practice Fraud and Breach of Trust
Because
It refused the judgment issued by The French ministry of Justice and denies the money by judged and disregarded the Foreign Court Judgment.
Sent to the honorable united Nations Secretary – General
António Guterres
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
best Greetings
The Sun Creation Process
Abstract
Paper hypothesis
From One Light Beam Energy The Solar System Be Created
And
This Light Beam travels with 1.16 million km per second
The hypothesis explanation..
- (1)
- The solar system be created out of one light beam energy –
- The solar planets matters and their distances be created of one energy and this one energy be provided by one light beam and this light beam travels with velocity 1160000 km/s –
- Shortly
- The physics book accepts that (matter and space be created of energies)
- The hypothesis adds one idea only tells
- (from the same one energy the solar planets matters and their distances be created) this is the hypothesis main idea –
- Matter and Space creation be done from the same stuff (energy) but by using different geometrical rules –the idea is similar to the creation of the oil and coal both be created from the same source but they have 2 different forms because the creation process depend on 2 different geometrical rules.
- The matter and space creation process can be summarized by the following data
- (light 1.16 million/s = matter + space + light 300000 km/s)
- The data tells the input energy be a light beam its velocity 1160000 km/s, from this energy the matter and space be created and the light known velocity 300000 km/s be created as a side product from the process.
- Briefly
- If we find Matters in the universe – we can't find the light velocity 1160000 km/s because its energy be consumed in the matter and space creation process and produced the known light beam velocity 300000 km/s as a side product.
- Based on this vision
- The matter be a geometrical point found on a trajectory of energy or (on a light beam) – by that – the matter moves by light motion –
- Imagine a rock in a tube form be found in some sea water and the water passes through this rock tube and pushes the rock itself to move with the water-
- That answers the question (how does planet move?) no sun gravity be used here – instead – the planet moves by light motion from its energy the planet be created.
- Here we disprove Newton theory of the sun gravity – because
- By one force the planet be created and moving otherwise this planet will be broken by effect of 2 forces on it – here – the force caused the planet creation is the light beam energy and the force causes the planet motion is this same light beam motion- that explains the safe planet motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Vodafone-Egypt Practices a fraud and breach of trust during 2013-2022.pdfGerges francis
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
2013-2022: Egypt authority prevented any job from me and prevented me to travel abroad- They Torture My Mother By Electric Shock And Try To Kill Her By Insulin Injection- they threaten our lives –Please Help
2010-2013: I have studied in Faculty of physics & Math– Physics Department – Peoples Friendship University of Russia – Moscow – Russian Federation.
2013-2022 (Details) - Because I couldn't return to Moscow - I have performed an interesting research in astrophysics- many international physicists interested for it – while Egypt authority realized my research importance they:
(I) torture my mother by electric shocks to force me stop publishing my papers
(II) They practice hacking on my accounts & Telephone Calls (+201022532292).
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Petition (with signature) (Egypt Persecution Against The Coptic).pdfGerges francis
Please help
Egypt Authority Persecutes The Coptic -Please Help
EGYPT AUTHORITY TRIES TO KILL MY MOTHER – PLEASE HELP
(Also they force my family to send me to the madhouse)
Because
Egypt Authority tries to STEAL my astrophysics research results, I worked in it since 2013 till now –Egypt authority torture us to steal my research – they hanged many of my accounts and even prevent me to write my research papers by using torture.
(They try to burn my laptop- which is my only source for all my research materials)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
Address /11 Mohamed Rageb st- Madenet El Saada – EL Materiya District – Cairo – Egypt
Planet Diameter Be A Function In Its Rotation PeriodGerges francis
Abstract
Paper hypothesis
- Planet Diameter Be Created As A Function In Its Rotation Period
The hypothesis Explanation
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane manufacture – the maker needs exact equations to define this plane length, width, weight …etc otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its data based on exact equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically prove this fact decisively.
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves each planet orbital distance depends on its previous neighbor planet orbital distance –
- d2 = 4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orb. distance
- We test and discuss this equation in the current paper–
- As a result –
- The planet found itself in an obligatory position be defined by other planets data and the planet data itself has no role in its orbital distance definition.
- (3)
- Planet motion can be a dangerous one if this planet diameter isn't in harmony with its orbital distance – means- the wrong diameter can cause the planet to be broken (The mass can decrease planet velocity – but the wrong diameter can break it) – for that reason – the planet has to create its diameter as a function in its orbital distance to move safely.
- But
- If the function has only 2 variables (planet diameter and its orbital distance), If this planet changes its orbital distance for any reason its diameter will be broken as a result –
- The designer had to create the function between planet diameter and its orbital distance as indirect function contains many other variables and by that if the planet changes its orbital distance the other variables will be changed but the diameter will be saved.
- As a result
- Planet diameter be created as a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance – by that – the function between planet diameter and its orbital distance be created but contains also other variables to protect the diameter.
- My fourth equation proves this fact let's see it
- (4)
- Planet Diameter Definition Equation (My Fourth Equation)
- (v1/v2) = (s/r) =I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination (a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- we test, discuss and analyze this equation in this current paper.
Gerges Francis Tawdrous +201022532292
-Physics and Mathematics Faculty - Peoples' Friendship university of Russia –
Gerges Francis Tawdrous (Curriculum Vitae).pdfGerges francis
Gerges Francis Tawdrous (Curriculum Vitae)
My Research Argument
(Why Should We Refuse Newton Theory Of The Sun Gravity?)
1-Planet Data Be Created Based On Exact Equations
Planet diameter, mass, orbital distance, period, inclination, rotation period and axial tilt – All planet data be created based on exact equations and geometrical rules - No single data be created based on random process, initial condition nor unknown historical factors.
As in a plane or a rocket manufacture, the maker needs exact equations to define this plane length, width, weight and all its specifications and dimensions –
If this plane data be created by inaccurate dimensions, this plane can't fly
Similar to that
Planet moves through the space under physical laws and if its data be not created based on exact equations this planet will be broken through its motion – because – the safe motion necessitates a full harmony between planet data one another and with the physical laws controls the motions through space
In this investigation we try to define how Planet creates its data – or in more accurate words – By What Order Planet Data Be Created? what data be created at first and what be later? – by that – we can discover the harmony original point.
I have discovered 5 equations by which we can conclude planet data theoretically without observation that proves the idea decisively
2- Planet Orbital Distance Be Defined Before Its Creation
This simple fact be proved by 2 basic proves – "First Proof" The Logical Analysis
The current planets positions define the new planet position
The balancing effect of the planets motions forces the new planet to take the left place for it – because the planets revolve around the sun in their trajectories of motions – for that – the new planet has to find a place far from these trajectories.
Imagine you are in some crowded bus – the people pushed you to the last place in this bus because it's the only free place there – you came later and this is the only available place for you – by that – you are forced to accept this place
Planet orbital distance be defined before the planet creation – the logic proves this fact clearly
"Second Proof"
My First Equation tells (d2 = 4d0 (d-d0))
d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
My equation tells– Planet Orbital Distance Depends On Its Neighbor Distance
It's a simple and a trustee equation – let's use Venus as example
(108.2 million km)2 = 4 (57.9 million km) (50.3 million km)
where
108.2 million km = Venus orbital distance and
57.9 million km = Mercury orbital distance and (50.3 = 108.2 -57.9)
(There are 3 exceptions – Earth depends on Mercury – Mars depends on Venus and Pluto depends on Uranus –
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity.pdfGerges francis
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
Abstract
Paper Argument
- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
- (1)
- By one force planet be created and moving – means - the force which created the Planet– it causes its motion – as a result
- (No Planet Moves By The Sun Gravity) because (The Sun Had Created No Planet)
- One more force caused the planets creation and their motions
- For that reason
- Planet creation and motion data be in harmony one another –
- For example (Mercury creation and motion data be in harmony one another) and Mercury moves safely and isn't broken
- But -we don't have 9 forces in the solar system – One force for each planet – instead – We have one force only caused All Planets Creation And Motion
- Now- let's ask
- How Can One Force Create 9 Planets And Causes Their Motions?
- This force needs to use One Geometrical Design to do this job – as 9 gears be moving by one motor we need a machine to do this job
- Based on this analysis – No planet moves by the sun gravity – Newton is wrong
- (2)
- The gravitation equation is wrong because no planet orbital distance be defined based on it- and that explains the contradiction between the planets masses order and their orbital distances
- This fact is a powerful against Newton – but the logic still more power
- Because
- The planet orbital distance be defined before this planet creation – because – the distance be defined by other planets distances – means - the new planet orbital distance be defined based on the balancing of the current planets motions trajectories and by that the new planet will find itself in a position defined obligatory by other planets –
- This fact be proved also by my first equation which proves that each planet orbital distance depends on its neighbor planet orbital distance (Not On Its Mass)
- My First Equation tells (d2 = 4d0 (d-d0))
- d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
- (My 5 Equations Be Tested And Discussed In The Paper)
- I want to say
- The principle idea is wrong because the distance be defined obligatory by other planets motions trajectories and planet mass can do nothing to change it
- (3)
- The logic still moves against Newton because
- The planet is found itself in an obligatory position and has to revolve around the sun from this position – now what about this planet diameter – because
- If the planet diameter isn't in harmony with its orbital distance this planet will be broken – here – Newton idea is wrong completely because he looked at the mass but planet mass can decrease its velocity where the wrong diameter can cause the planet to be broken – by that – the planet has to create a function between its orbital distance and its diameter to move safely otherwise it will be broken – the point is Newton defined the mass as the basic player! (continued)
Gerges Francis Tawdrous +201022532292
Physics Department
,Why Does Planet Orbit Define Its Velocity, (Kepler Law Analysis).pdfGerges francis
Why Does Planet Orbit Define Its Velocity? (Kepler Law Analysis)
Abstract
Paper question
Kepler stated (Planet Orbit Defines Its Velocity) - Why?
What would happen if (Planet Orbit Doesn't Define Its Velocity)?
The answer of this question be summarized in 5 points which are:
(1)
Planet Data Be Created Based On Exact Equations
(2)
Planet Diameter Should Be An Indirect Function In Its Orbital Distance
(3)
Planet Mass Effects On Its Diameter Definition Equation
(4)
The Necessity Of The Function Between Planet Orbit And Its Velocity
(5)
The Refutation Of Newton Theory Of The Sun Gravity And The Big Bang Theory.
Let's consider each point in some details in following
(Point No. 1)
Planet Data Be Created Based On Exact Equations
- Planet data (Planet diameter, mass, orbital distance, period, inclination, velocity, rotation period and axial tilt), this data be created based on exact equations and no single data be created by random process, initial condition nor unknown historical factors.
- As in a plane or rocket manufacture, the maker needs exact equations to define this plane length, width, weight….etc – all data and specifications be defined based on exact equations – similar to that Planet data be created based on exact equations.
- If planet data doesn't depend on exact equations, this planet can't move because the planet is moving through its trajectory and if this motion suffer from no harmony with All planet data – this planet will be broken through its motion – because it moves against its internal structure – we will discuss this idea deeply later.
(continued)
The Solar Eclipse (Questions And Answers).pdfGerges francis
The Solar Eclipse (Questions And Answers)
Abstract
Paper objective
The paper answers the following questions
1. Can each planet orbital distance depend on its neighbor planet orbital distance? In this case how the distance between the sun and Pluto be created? (Can One Map Be Drawn For All Planets Orbital Distances?)
2. Is There a necessity to create a proportionality between planet diameter and orbital distance?
3. Can Planet rotation period be defined based on its velocity?
4. Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its Orbital Distance And By That This Planet Will Not Be Broken Through Its Motion?)
5. Why Does Venus Have The Longest Rotation Period In The Solar System?
6. Can Planet orbital Distance be Defined before this planet creation? where planet orbital distance be defined based on its neighbor orbital distance?
7. Why Doesn't The Planet Break After Its Creation?
8. Planet data be (Mass – Diameter- Orbital Distance- Period –Inclination….etc) what data be created at first and what be created later?
9. Explain The Relationship Between Planet Diameter And Orbital Distance?
10. Why does the moon orbital period = the moon rotation period (No For Tidal Locking – this idea is wrong)?
11. Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total?
12- Can Solar System Depend On One Geometrical Design?
13- Why Does The Moon Orbital Apogee Radius = 406000 km?
14- Can Mars Orbital Distance Be Changed From 84 million km to 228 million km?
15- Did Newton realize The Solar system Motion Logic?
16- How Be The Sun Disc Created?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Solar Eclipse Phenomenon Analysis (Revised).pdfGerges francis
The Solar Eclipse Phenomenon Analysis (Revised)
Abstract
Paper Argument
The planets motions can be explained only based on the concept (One Geometrical Design Be found Behind the Solar System)
The Argument explanation
The solar planets are created complementary one another and their motions be integrated into one unified motion – by that- the planets be similar to members of one creature - Their creation data depends on one design and their motions be integrated together into one unified motion (as a machine of gears – many gears motions but the machine produces One Unified Motion)
Because of that
Any planet motion can be explained only through the concept (One Geometrical Design Be found Behind the Solar System), because based on this one design the planets be created and by this one design the planets motions be integrated and produced one unified motion.
Paper objective
- We have proved the one geometrical design before
- In this current paper we examine the one geometrical design details – by that the paper provides rich points of discussion because we discuss the geometrical details of this one design and their effects on the planets creation and motion data.
- The paper discussions points be summarized in following:
- (1)
- The paper proves the one design uses one map for the distance - means
- The solar system design uses the distance from the sun to Pluto as one piece of distance be distributed based on one map –
- (2)
- The paper proves the solar system design uses one more map for the velocities. by that, the design considers the planets motions be integrated into one unified motion as a machine of gears and this (unified velocity) be distributed for the planets velocities based on one more map.
- (3)
- The paper answers the question (why does the design use 2 different maps?) and explains the massive importance for this using
- The paper analyzes also my fourth equation to prove that – planet diameter be created as a function in its rotation period and the rotation period be created a function in its velocity and the velocity be a function in its orbital distance.
- (4)
- The paper disproves the tidal locking claim as a reason for the moon cycles periods equality – the idea is wrong – where – the moon orbital period = the moon rotation period because of the solar system one design effect on the moon motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Dancing Planets
Abstract
Paper hypothesis
From One Energy The Solar Planets Matters And Their Distances Be Created
The hypothesis explanation
- (1)
- Newton Theory of the sun gravity is wrong in its logic because by one force the planet should be created and moving –otherwise this planet will be broken -means- The force which created the planet it causes its motion – by that no planet moves by the sun gravity
- (2)
- The Big Bang Theory Is Wrong Because – It Supposed – The First Energy Was In A Chaos Form Resulting From The First Explosion – in Fact – The First Energy (Of The Solar System) was in A Geometrical Design Form.
- (3)
- The physics book accepts (Matter and Space be Created Of Energies) – The paper hypothesis adds one idea tells (From One Energy They Were Created) – means - The planets matters and their distances be created from The Same One Energy
- Let's see the paper basic ideas in following
- (A)
- Planet Data Be Created Based On Exact Equations- As any plane or rocket creation – the maker needs exact equations to define this plane length, width and All Other Specifications-
- Similar to that,
- Planet mass, diameter, orbital distance, period, velocity, inclination, rotation period and axial tilt – all data be created based on exact equations and no data be created by any random process, initial conditions or historical unknown factors.
- By that, the planets data can be concluded by mathematical calculations only
- My 5 equations prove this fact (The 5 equations be tested in point no. 3)
- (B)
- The Planet data Exact equations depend on One Geometrical Design –means-
- Because the solar system creation and motion depends on One Geometrical Design, the planets data be created based on exact equations
- The One Geometrical Design is the basic argument of the paper –
- It's similar to the electron and positron be created from Gamma ray (The double production experiment), The 2 particles charges total be (Zero) because gamma ray charge is (Zero)
- By that, one law controls the 2 particles motions – and similar to that – one law or One Geometrical Design controls the solar planets creations and motions
- Also, from Planet motion analysis- we can reach to this same conclusion
- We accept that, one force only be used for planet creation and motion, and the force which created the planet causes its motion –otherwise this planet will be broken because 2 forces effect on it- but
- We don't have 9 forces create the 9 solar planets and cause their motions – instead- we have only one force causes all planets creation and motion –
- This one force can do this job only by using One Geometrical Design -
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Planet Diameter Definition Equation
Abstract
Planet Diameter Definition Equation (My Fourth Equation)
(v1/v2) = (s/r) = I
v = Planet Velocity
r= Planet Diameter
s= Planet Rotation Periods Number In Its Orbital Period
I= Planet Orbital Inclination
v2, s, r and I be belonged to one planet and v1 be belonged to another planet
The Equation Role
- The equation proves that, Planet diameter be created based on geometrical rule and as a function in this planet motion data –
- That tells, the motion was found and defined before this planet creation and for that the planet diameter be created depending on this planet motion data
The Equation Significance
- The Equation proves the argument
- By One Force The Solar Planets Be Created And Moving
- The sun didn't cause any planet creation, So (No planet moves by the sun gravity)
- By One Force and From One Energy All Planets Matters And Their Distances Be Created And This Energy Causes The Planets Motions.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Geometry Of Light Motion
Abstract
Paper hypothesis
- The planets matters and their distances be created from The Same One Energy.
- This one energy is provided by one light beam
- This light beam travels with a velocity =1.16 million km per second
Paper objective
- The paper is consisted of 2 parts
- Part no. (I) provides My Research Presentation Summary
- Part no. (II) discusses The Geometry Of Light Motion
- Let's refer to them in following..
Part No. (I) Research Presentation Summary
My research presentation is consisted of 6 points which are
(1)
Planet Orbital Distance Equation (My 1st Equation)
(2)
The Refutation Of Newton Theory Of The Sun Gravity
(No Planet moves by The Sun Gravity)
(3)
The Research Method explanation And Using to prove 2 basic new discoveries which are:
(Mars Migration Theory) and
(The moon using of an angle θ between its motion direction and its orbit level)
(4)
The Research hypothesis (The planets matters and their distances be created from One Energy)
That's why (The Solar System Be Created Based On One Geometrical Design)
Means (One Geometrical Design was found before the solar system creation)
That refutes (The Big Bang Theory)
(5)
The One Energy Is Provided By One Light Beam
(6)
The light beam travels with a velocity 1.16 million km per second.
That refutes (The hypothesis of the Special Theory of Relativity)
Part No. (II) Geometry Of Light Motion
What's the direct question behind this paper?
The matter and space are created from one light beam – means – the matter and space are forms of light forms –
Now, if this is a fact,
Why do we need to fight so hard to prove this very simple and clear fact?
Because
The light uses unknown geometrical rules –
By that this paper should be similar to a book of Geometry – because – it shows types of geometrical rules are unknown for us and not found in our Geometry books
It's a direct answer but not clear
Why don't we know these rules? Why can't we catch them in lab experiments? If so many unknown geometrical rules of light motion are found, and we couldn't catch them during the empirical physics history why can we do that now? Can any one stole at end the Geometry book from the heaven library?!
I have brought with me the planets data and later I have discovered that all unknown geometrical rules be hidden in them.
Shortly
The light creates the matter and space by using unknown geometrical rules – and – we can discover these geometrical rules by using planets data analysis – means – we can know these geometrical rules only if we can read correctly the planets data – for example – if we can answer the question (why the moon diameter =3475 km?) that will help us to discover the rules based on which the moon diameter be created.
So I will present my research summary then we should discuss these unknown geometrical rules.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
A Research Presentation Summary
Abstract
My research presentation is consisted of 6 points which are
(1)
Planet Orbital Distance Equation (My 1st Equation)
(2)
The Refutation Of Newton Theory Of The Sun Gravity (No Planet moves by the sun gravity)
(3)
The Research Method explanation and using to prove (Mars Migration Theory) and (The moon using of an angle θ between its motion direction and its orbit level)
(4)
The Research hypothesis (The planets matters and their distances be created from One Energy)
That's why (The Solar System Be Created Based On One Geometrical Design)
Means (One Geometrical Design was found before the solar system creation)
That refutes (The Big Bang Theory)
(5)
The One Energy Is Provided By One Light Beam
(6)
The light beam travels with a velocity 1.16 million km per second.
That refutes (The hypothesis of the Special Theory of Relativity)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
(May 29th, 2024) Advancements in Intravital Microscopy- Insights for Preclini...Scintica Instrumentation
Intravital microscopy (IVM) is a powerful tool utilized to study cellular behavior over time and space in vivo. Much of our understanding of cell biology has been accomplished using various in vitro and ex vivo methods; however, these studies do not necessarily reflect the natural dynamics of biological processes. Unlike traditional cell culture or fixed tissue imaging, IVM allows for the ultra-fast high-resolution imaging of cellular processes over time and space and were studied in its natural environment. Real-time visualization of biological processes in the context of an intact organism helps maintain physiological relevance and provide insights into the progression of disease, response to treatments or developmental processes.
In this webinar we give an overview of advanced applications of the IVM system in preclinical research. IVIM technology is a provider of all-in-one intravital microscopy systems and solutions optimized for in vivo imaging of live animal models at sub-micron resolution. The system’s unique features and user-friendly software enables researchers to probe fast dynamic biological processes such as immune cell tracking, cell-cell interaction as well as vascularization and tumor metastasis with exceptional detail. This webinar will also give an overview of IVM being utilized in drug development, offering a view into the intricate interaction between drugs/nanoparticles and tissues in vivo and allows for the evaluation of therapeutic intervention in a variety of tissues and organs. This interdisciplinary collaboration continues to drive the advancements of novel therapeutic strategies.
Nutraceutical market, scope and growth: Herbal drug technologyLokesh Patil
As consumer awareness of health and wellness rises, the nutraceutical market—which includes goods like functional meals, drinks, and dietary supplements that provide health advantages beyond basic nutrition—is growing significantly. As healthcare expenses rise, the population ages, and people want natural and preventative health solutions more and more, this industry is increasing quickly. Further driving market expansion are product formulation innovations and the use of cutting-edge technology for customized nutrition. With its worldwide reach, the nutraceutical industry is expected to keep growing and provide significant chances for research and investment in a number of categories, including vitamins, minerals, probiotics, and herbal supplements.
The increased availability of biomedical data, particularly in the public domain, offers the opportunity to better understand human health and to develop effective therapeutics for a wide range of unmet medical needs. However, data scientists remain stymied by the fact that data remain hard to find and to productively reuse because data and their metadata i) are wholly inaccessible, ii) are in non-standard or incompatible representations, iii) do not conform to community standards, and iv) have unclear or highly restricted terms and conditions that preclude legitimate reuse. These limitations require a rethink on data can be made machine and AI-ready - the key motivation behind the FAIR Guiding Principles. Concurrently, while recent efforts have explored the use of deep learning to fuse disparate data into predictive models for a wide range of biomedical applications, these models often fail even when the correct answer is already known, and fail to explain individual predictions in terms that data scientists can appreciate. These limitations suggest that new methods to produce practical artificial intelligence are still needed.
In this talk, I will discuss our work in (1) building an integrative knowledge infrastructure to prepare FAIR and "AI-ready" data and services along with (2) neurosymbolic AI methods to improve the quality of predictions and to generate plausible explanations. Attention is given to standards, platforms, and methods to wrangle knowledge into simple, but effective semantic and latent representations, and to make these available into standards-compliant and discoverable interfaces that can be used in model building, validation, and explanation. Our work, and those of others in the field, creates a baseline for building trustworthy and easy to deploy AI models in biomedicine.
Bio
Dr. Michel Dumontier is the Distinguished Professor of Data Science at Maastricht University, founder and executive director of the Institute of Data Science, and co-founder of the FAIR (Findable, Accessible, Interoperable and Reusable) data principles. His research explores socio-technological approaches for responsible discovery science, which includes collaborative multi-modal knowledge graphs, privacy-preserving distributed data mining, and AI methods for drug discovery and personalized medicine. His work is supported through the Dutch National Research Agenda, the Netherlands Organisation for Scientific Research, Horizon Europe, the European Open Science Cloud, the US National Institutes of Health, and a Marie-Curie Innovative Training Network. He is the editor-in-chief for the journal Data Science and is internationally recognized for his contributions in bioinformatics, biomedical informatics, and semantic technologies including ontologies and linked data.
Earliest Galaxies in the JADES Origins Field: Luminosity Function and Cosmic ...Sérgio Sacani
We characterize the earliest galaxy population in the JADES Origins Field (JOF), the deepest
imaging field observed with JWST. We make use of the ancillary Hubble optical images (5 filters
spanning 0.4−0.9µm) and novel JWST images with 14 filters spanning 0.8−5µm, including 7 mediumband filters, and reaching total exposure times of up to 46 hours per filter. We combine all our data
at > 2.3µm to construct an ultradeep image, reaching as deep as ≈ 31.4 AB mag in the stack and
30.3-31.0 AB mag (5σ, r = 0.1” circular aperture) in individual filters. We measure photometric
redshifts and use robust selection criteria to identify a sample of eight galaxy candidates at redshifts
z = 11.5 − 15. These objects show compact half-light radii of R1/2 ∼ 50 − 200pc, stellar masses of
M⋆ ∼ 107−108M⊙, and star-formation rates of SFR ∼ 0.1−1 M⊙ yr−1
. Our search finds no candidates
at 15 < z < 20, placing upper limits at these redshifts. We develop a forward modeling approach to
infer the properties of the evolving luminosity function without binning in redshift or luminosity that
marginalizes over the photometric redshift uncertainty of our candidate galaxies and incorporates the
impact of non-detections. We find a z = 12 luminosity function in good agreement with prior results,
and that the luminosity function normalization and UV luminosity density decline by a factor of ∼ 2.5
from z = 12 to z = 14. We discuss the possible implications of our results in the context of theoretical
models for evolution of the dark matter halo mass function.
Cancer cell metabolism: special Reference to Lactate PathwayAADYARAJPANDEY1
Normal Cell Metabolism:
Cellular respiration describes the series of steps that cells use to break down sugar and other chemicals to get the energy we need to function.
Energy is stored in the bonds of glucose and when glucose is broken down, much of that energy is released.
Cell utilize energy in the form of ATP.
The first step of respiration is called glycolysis. In a series of steps, glycolysis breaks glucose into two smaller molecules - a chemical called pyruvate. A small amount of ATP is formed during this process.
Most healthy cells continue the breakdown in a second process, called the Kreb's cycle. The Kreb's cycle allows cells to “burn” the pyruvates made in glycolysis to get more ATP.
The last step in the breakdown of glucose is called oxidative phosphorylation (Ox-Phos).
It takes place in specialized cell structures called mitochondria. This process produces a large amount of ATP. Importantly, cells need oxygen to complete oxidative phosphorylation.
If a cell completes only glycolysis, only 2 molecules of ATP are made per glucose. However, if the cell completes the entire respiration process (glycolysis - Kreb's - oxidative phosphorylation), about 36 molecules of ATP are created, giving it much more energy to use.
IN CANCER CELL:
Unlike healthy cells that "burn" the entire molecule of sugar to capture a large amount of energy as ATP, cancer cells are wasteful.
Cancer cells only partially break down sugar molecules. They overuse the first step of respiration, glycolysis. They frequently do not complete the second step, oxidative phosphorylation.
This results in only 2 molecules of ATP per each glucose molecule instead of the 36 or so ATPs healthy cells gain. As a result, cancer cells need to use a lot more sugar molecules to get enough energy to survive.
Unlike healthy cells that "burn" the entire molecule of sugar to capture a large amount of energy as ATP, cancer cells are wasteful.
Cancer cells only partially break down sugar molecules. They overuse the first step of respiration, glycolysis. They frequently do not complete the second step, oxidative phosphorylation.
This results in only 2 molecules of ATP per each glucose molecule instead of the 36 or so ATPs healthy cells gain. As a result, cancer cells need to use a lot more sugar molecules to get enough energy to survive.
introduction to WARBERG PHENOMENA:
WARBURG EFFECT Usually, cancer cells are highly glycolytic (glucose addiction) and take up more glucose than do normal cells from outside.
Otto Heinrich Warburg (; 8 October 1883 – 1 August 1970) In 1931 was awarded the Nobel Prize in Physiology for his "discovery of the nature and mode of action of the respiratory enzyme.
WARNBURG EFFECT : cancer cells under aerobic (well-oxygenated) conditions to metabolize glucose to lactate (aerobic glycolysis) is known as the Warburg effect. Warburg made the observation that tumor slices consume glucose and secrete lactate at a higher rate than normal tissues.
This pdf is about the Schizophrenia.
For more details visit on YouTube; @SELF-EXPLANATORY;
https://www.youtube.com/channel/UCAiarMZDNhe1A3Rnpr_WkzA/videos
Thanks...!
Multi-source connectivity as the driver of solar wind variability in the heli...Sérgio Sacani
The ambient solar wind that flls the heliosphere originates from multiple
sources in the solar corona and is highly structured. It is often described
as high-speed, relatively homogeneous, plasma streams from coronal
holes and slow-speed, highly variable, streams whose source regions are
under debate. A key goal of ESA/NASA’s Solar Orbiter mission is to identify
solar wind sources and understand what drives the complexity seen in the
heliosphere. By combining magnetic feld modelling and spectroscopic
techniques with high-resolution observations and measurements, we show
that the solar wind variability detected in situ by Solar Orbiter in March
2022 is driven by spatio-temporal changes in the magnetic connectivity to
multiple sources in the solar atmosphere. The magnetic feld footpoints
connected to the spacecraft moved from the boundaries of a coronal hole
to one active region (12961) and then across to another region (12957). This
is refected in the in situ measurements, which show the transition from fast
to highly Alfvénic then to slow solar wind that is disrupted by the arrival of
a coronal mass ejection. Our results describe solar wind variability at 0.5 au
but are applicable to near-Earth observatories.
1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Orbital Motion Description (2nd
Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –29th
January 2021
Abstract
Paper hypothesis No. (1)
There's 2nd
force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm
this distance should be = the moon orbital circumference, and this distance = the
moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement
through its orbit, the moon would revolve around Earth only through its apogee
orbit (r=0.406 mkm), and be always on the most far point from Earth and can't
revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000
km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ))
by this displacement (L) the moon passes through its orbit although the moon
actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more
near orbits as perigee orbit (r=0.363 mkm)
2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
- The moon using of Pythagoras triangle technique causes the moon orbit to be
created in a triangle form, which we analyze in this paper
- The moon orbital triangle data analysis lead to the following hypothesis (A 2nd
Force must effect on the Moon Orbital Motion in addition to Earth Gravity
Force)
- Also the 2nd
hypothesis is created based on this first one, (Uranus effects on the
moon orbital motion, causing to create Metonic Cycle).
Paper Main Idea
- The paper claims, the moon orbital triangle is created based on logical geometrical
structure, can't be created by the Sun and Earth gravities effects only.
- Planets (As Jupiter and Uranus) can effect by their gravities on the moon orbital
motion and these effects are seen in the moon orbital motion data and features.
- The Proving process depends on that, The triangle geometrical structure is created
by many players effects. This fact is proved by the triangle geometrical analysis,
and this fact shows different planets gravities effects on the moon orbital motion.
- These planets different effects are defined under one title (2nd
force effects on the
moon orbital motion)
- This conclusion supports the hypothesis (Uranus Motion causes to create Metonic
Cycle in the Moon Orbital Motion)
3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
Contents
Subject Page N
1- Introduction 4
2- The Moon Orbital Triangle Description
2-1 The Moon Orbital Triangle Description
2-2 The Moon Orbital Triangle Data Analysis
5
3- The Moon Orbital Motion Analysis
3-1 Why Does The Moon Use Pythagoras Triangle In Its Motion?
3-2 How Does The Moon Use Pythagoras Triangle In Its Motion?
3-3 The Moon Orbital Motion Analysis
3-4 The Moon Orbital Motion Equation
19
4-The Moon Orbit Geometrical Design
4-1 Preface
4-2 The Necessity Of Pythagoras Triangle (1, 2, 51/2
)
4-3 Why The Moon Displacement Daily =88000 km?
4-4 The Moon Motion Angle (12.195 degrees) Analysis
4-5 Why The Moon Day Period =29.53 solar days?
35
5- The Moon Orbital Triangle Benefits
5-1 Preface
5-2 The Moon orbital triangle shows that (2nd
force effect on the moon motion)
5-3 The Moon orbital triangle shows that (There's 2nd
Orbit for the moon motion)
5-4 The Moon orbital triangle shows that Uranus effects on the moon motion
56
6- Metonic Cycle Is A Proof of Uranus Effect On The Moon Motion
6-1 Preface
6-2 Uranus Effect On The Moon Orbital Motion
6-3 Uranus, The Moon And Pluto Motions Interaction
6-4 The Moon Orbital Triangle Angles Discussions
6-5 Moon Day Period Analysis (29.53 Solar Days)
61
7- Uranus Motion Analysis
7-1 Uranus Motion During 1440 Of Its Days Period
7-2 Uranus Motion During 8 Pluto Days period
7-3 Uranus 144 Days Cycle
82
8- Appendix No.1 103
4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
1- Introduction
- The moon uses Pythagoras triangle as one of the moon orbital motion techniques
- The moon motion 4 basic points were the method by which I have discovered that,
the moon motion 4 basic points are:
o Perigee radius (r=0.363 mkm), the most near point the moon can reach to
Earth.
o Apogee radius (r=0.406 mkm), the most far point the moon can reach from
Earth
o Total Solar Eclipse radius (r= 0.373 mkm), the moon creates A total solar
eclipse when the moon be at this distance from Earth or Shorter.
o The Moon Orbital distance (r=0.384 mkm), this value is the registered one
in the moon data sheet as the moon orbital distance.
- These 4 points are defined based on each other by Pythagoras rule:
o (363000 km)2
+ (86000 km)2
= (373000 km)2
o (373000 km)2
+ (86000 km)2
= (384000 km)2
o (384000 km)2
+ (86000 km)2
= (393000 km)2
o (393000 km)2
+ (86000 km)2
= (406000 km)2
(Error 1%)
- Based on this data, the concept is discovered that, The Moon Uses Pythagoras
Triangle As One Of The Moon Motion Techniques
- But 2 questions are raised with this concept (1st
question) why does the moon use
Pythagoras triangle (2nd
question) what's this dimension (86000 km) which is used
frequently in the previous data?
- By answering these question, the following results are produced
o The moon motion data analysis refers to The Moon Orbital Triangle
o The moon motion data analysis refers to The Moon Motion Equation
- Let's discuss these tools in following in addition to discover how the moon uses
Pythagoras triangle and what benefits the moon receives for this using…
5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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2- The Moon Orbital Triangle Description
2-1 The Moon Orbital Triangle Description
2-2 The Moon Orbital Triangle Data Analysis
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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2-1- The Moon Orbital Triangle Description
- This is the suggested moon orbital triangle
- In following we discuss how this triangle is created
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The Moon Orbital Triangle Building
(1st
Point) The Earth Position (Point E)
- The Point (T) refers to The Earth Center
- The Point (M) refers to The Moon Center
- The Points (T, Q and Y) are on the Ecliptic Line
- The Red Line (TM) is the moon orbit plane with an inclination 5.1 degrees on the
ecliptic.
- The Green Line (BE) is the moon triangle base, I choose the distance BE to be =
363000 km and accordingly I have to define the point (E) position.
- The line BC is a perpendicular on the triangle base (BE), its length =86000 km
- The line EC is the triangle dimension to connect the points (E and C).
- The points (Q and P) are the intersection points of CE with the ecliptic and the
moon orbit plane respectively.
- The line TX is a perpendicular from the Earth Center on the base BE
- The point K is the intersection point between the moon orbital triangle base (BE)
(the Green Line) and the moon orbit plane (the Red Line)
- The angle is Zero between the points ( A, B , K , X and E).
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Notice
- The Line MB is Perpendicular on the Moon Orbital Triangle Base (BE)
- And
- MB has an angle =90.443 degrees with the Ecliptic Line……….because
- The moon orbital triangle base is under the ecliptic with an angle =0.443 degrees
- Let's define the Earth Point in following:
o The Triangle TMY
o The distance TM = 363000 km (The perigee radius)
o The distance TY = 361313 km
o The distance MY = 32269 km
o The angle MTY = 5.1 degrees (the moon orbital inclination)
o The Triangle TXK
o The distance KX = 35640 km
o The distance KT =35807 km
o The distance TX = 3460 km
o The angle XKT = 5.543 degrees
o The Triangle BMK
o The distance KM = 327193 km
o The distance KB =325663 km
o The distance MB = 31604 km The distance YB = 665 km
o The angle KMB = 84.9 degrees
o The distance XB = KX + KB = 35640 +325663 = 361303 km …But
o The triangle base (BE) I choose to be =363000 km, based on that the
distance XE = 1697 km
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o The Triangle TXE
o The distance TX = 3460 km
o The distance XE =1697 km
o The distance TE =3854 km
o The angle XET = 26.12 degrees But
o The triangle angle CEB = 13.328 degrees, because of that the triangle
dimension CE connects the point (E) under the hypotenuse ET.
o The Triangle PET
o The distance PE = 6244 km
o The distance PT =2640 km The angle ETP = 148.4 degrees
o The Triangle KPE
o The distance KE =37337 km
o The distance KP = 26554 km
o The distance PE =11152 km
o The angle EPK = 161.12 degrees
Data Analysis
(1)
o The Triangle TXE
o The distance TX = 3460 km The distance XE =1697 km
o The moon diameter =3475 km and the moon radius =1737.5 km, both are
equal the triangle 2 dimensions (error around 2%). That shows geometrical
interaction in this distances definition.
(2)
o The line MY is perpendicular on the moon orbital triangle base (BE) and has
an angle 90.443 degrees with the Ecliptic Line. And
o There's an angle = 0.443 degrees between the ecliptic line and the moon
orbital triangle base (EB).
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(2nd
Point) The Moon Motion (From Perigee To Apogee)
- The moon moves on its orbit planet (MT) with an inclination 5.1 degrees on the
ecliptic Line.
- The moon moves from perigee point (r=363000 km) to the apogee point
(r=406000 km)
- The Point M1 refers to the perigee Point, and M2 refers to the apogee point.
- The distance M1 M2 = 43000 km (=The Perigee Apogee Distance)
- The distance between perigee and apogee =43000 km.
- M1B and M2D are perpendicular on the moon orbital triangle base (EA) (the
Green Line) …… Based on that
- The distance BD is parallel to M1R, where this distance (M1R) is the adjacent in
the triangle M1M2N in which the distance M1M2 expresses the perigee apogee
distance, by that, the distance BD expresses the moon motion from perigee to
apogee and vice versa.
- The basic reference in this triangle is that, the 2 distances M1B and M2D are
perpendicular on the moon orbital triangle base (AB) and Not on the Ecliptic Line,
where the moon orbital triangle base (AB) has an angle 0.443 degrees with
ecliptic, i.e., the triangle base (AB) passes under the ecliptic with 0.443 degrees.
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- The blue line is the moon equator line, where an angle =1.543 degrees is found
between this line and the ecliptic line.
- Let's consider this triangle data in following:
- I- Data
o The angle M1 T Y = 5.1 degrees (the moon orbital inclination)
o The angle M2 M1 R = 5.543 degrees
o The angle M1 M2 R = 84.457 degrees
o The angle B M1 R = 90 degrees
o The angle T M1 B = 84.457 degrees
o The angle T Y B = 90.443 degrees
o The angle B N M2 = 88.9 degrees
o The angle M1 N V = 91.1 degrees
o The distance M1 Y = 32269 km But
o The distance B Y = 665 km
o The distance M1 B = 31604 km
o The distance M2 D = 36092 km But
o The distance D d = 333 km
o The distance M2 D = 35760 km
o In the Triangle RM1M2
o The distance RM2 = 35760-31604 = 4156 km
o The distance M1M2 = 43000 km
o The distance M1 R = 42800 km = The distance BD
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(3rd
Point) The Point (A)
- The blue line is the moon equator line and it has an angle =1.543 degrees with the
Ecliptic Line
- The Point (A) is a point on the Ecliptic Line I have choose and caused an angle
=0.443 degrees under the ecliptic line and created the Base AB =86000 km.
- That means, the triangle base (AB) depends on the ecliptic line only
- But
- Because of the angle 1.543 degrees between the ecliptic & the moon equator lines,
the triangle base (AB) gets an angle =1.1 degrees with the moon equator line (blue
line)
- i.e. above the triangle base (AB) there's an angle with the Ecliptic = 0.443 deg and
under the triangle base (AB) there's an angle with the moon equator =1.1 deg.
- The triangle ABC is a closed triangle where the point (A) is the intersection point
between the ecliptic line, the triangle base AB and the triangle dimension AC
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- But
- The moon equator line (the blue line) doesn't interest neither with the ecliptic nor
the moon orbital triangle AB on the point (A),
- The moon equator line (the blue line) will interest the ecliptic line beyond the
point (A) with a long distance
- Let's define this intersection point position in following:
o The moon orbit plane declines on the Ecliptic line with 5.1 degrees, means,
far distance be found between the Earth and moon will cause longer
perpendicular distance between the moon center and the ecliptic line
o For that, we use the moon distance on a apogee because it's the most far
point the moon can reach from Earth
o ON APOGEE …
o Earth moon distance on apogee point = 406000 km
o The perpendicular distance from the moon center to the ecliptic line = 36091
km, because of the moon orbital inclination (5.1 degrees)
o But
o The angle between the ecliptic line and the moon equator line =1.543 deg
o So these 2 lines will be intersected each other at a distance =1340318 km
o i.e.
o The ecliptic line will intersect with the moon equator line after the apogee
point with a distance =1340318 km
o but the distance from perigee to apogee =43000 km
o i.e. The ecliptic line will intersect with the moon equator line after the
perigee point with a distance =1383318 km
o Notice, the lunar eclipse umbra length =1392000 km (error 0.6%)
The Useful Result :
The triangle base (AE) has an angle = 1.1 degrees with the moon equator line.
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(4th
Point) The Line BC
- The line BC is perpendicular on the triangle base on the point (B), so, the angle
ABC =90 degrees. The blue line is the moon equator line and the red line is the
moon orbit plane – the green line is the triangle Base (BA).
- Based on that,
o The angle BYA =89.557 degrees
o The angle M1NV =91.1 degrees
o The angle M2NM1 =88.9 degrees
o The angle CYA =90.443 degrees
o The angle between the blue line (the moon equator) and the green line
(the triangle Base BA) = 1.1 degrees
o The distance BC = 86000 km (I have choose it)
o The distance AB = 86000 km (I have choose it)
o The distance AY = 86009 km
o The distance YB = 665 km
o The distance MB = 31604 km
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2-2 The Moon Orbital Triangle Data Analysis
- This figure of 2 circles I have brought from internet to use in the Explanation -
- We have supposed, the inner circle is the Perigee orbit and the outer circle is the
apogee orbit, And we have calculated the tangent DB = 181843 km
- AB = 363686 km (= Perigee Radius Approximately)
- Perigee radius r =0.363 mkm
- Apogee radius r =0.406 mkm
- Based on that,
- The triangle (ODB) angles are 26.564 deg. and 63.435 deg.
But
- The triangle (BCD) in the moon orbital triangle is a similar to this triangle (ODB)
where their dimensions are rated and their angles are equal, both are created as a
specific Pythagorean triangle (1, 2 and 51/2
)
- The first question should be (what's the geometrical necessity for which the
specific Pythagorean triangle (1, 2 and 51/2
) is used for the moon orbital motion?)
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The Triangle BCD
- Please remember, the green line (the triangle base EA) has a n angle 1.1
degrees with the moon equator line, and an angle 0.443 degrees with the
Earth Ecliptic
- The triangle (BCD) should be the basic triangle in the moon orbit, because
o The distance BD refers to the moon motion distance from perigee to apogee
o The triangle (BCD) is similar to the triangle (ODB) and both are specific
type of Pythagorean triangle (1,2, 51/2
)
o The angle (BCD) = 26.56 degrees
o The angle (CDB) = 63.44 degrees
o The perimeter of triangle (BCD) = 225151 km
o Sin (5.1) x 225151 km x 2 = 40080 km (Earth Circumference)
o (5.1 degrees = The Moon Orbital Inclination).
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The Triangle BCZ
- The triangle BCZ is a specific triangle in the moon orbit because
o BZ = 18586 km
o The Angle BCZ =12.195 degrees
o The hypotenuse CZ = 88000 km = the moon displacement daily
- The data is interesting because it tells that, there's some relationship between the
moon daily displacement (88000 km) and the angle (BCZ =12.195 degrees)
- The angle 12.195 degrees = 13.177 degrees – 0.9856262 degrees
- Where
o 13.177 degrees = The Moon Motion Degrees Daily
o 0.98562 degrees= Earth Moon Motion Degrees Daily
o Because of that
o 12.195 degrees x 29.53 days (the moon day period ) = 360 degrees
o Can we conclude that, the moon daily displacement is defined relative to
this angle (12.195 degrees)? We should discuss this question later.
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The Point (A)
- The moon orbital triangle geometrical structure depends on 3 points (E, C and A),
- The Point (E) (found inside Earth)
- The point (C) (found on z-axis)
- But
- What's the point (A)? how this point can be created and effect on the moon orbital
motion and triangle?! Because this point is far from apogee radius with 43000 km
and the moon can't move beyond the apogee radius, means, this point (A) is found
in space and should have no effect on the moon orbital motion! so to find this point
(A) in the moon orbital triangle geometrical structure that creates a question needs
to be solved!
- But geometrically the point (A) is one pillar of the moon orbital triangle pillars,
means, the geometrical structure forces us to accept the massive importance of the
point (A) where no clear reason we have to explain why this point has such
massive importance?!
- The paper answers this question by the hypothesis: (Another force effects on the
moon orbital motion in addition to Earth gravity force and this point (A) refers to
this 2nd
force) –
- The paper tries to prove its hypotheses.
Notice
- In following we need to answer Why & How the moon uses Pythagorean
triangle in its motion, explaining The Moon Orbital Motion Equation… This
discussion is necessary to be done before our try to deepen the moon orbital
triangle data analysis.
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Gerges Francis Tawadrous/
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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3- The Moon Orbital Motion Analysis
3-1 Why Does The Moon Use Pythagoras Triangle In Its Motion?
3-2 How Does The Moon Use Pythagoras Triangle In Its Motion?
3-3 The Moon Orbital Motion Analysis
3-4 The Moon Orbital Motion Equation
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3-1 Why Does The Moon Use Pythagoras Triangle In Its Motion?
- Let's summarize this question answer in following:
o The moon uses Pythagoras triangle basically to decrease its displacement
daily through its orbit
o The moon daily displacement = 88000 km and the moon has to move this
distance every day without any decreasing (later we will know why!)
o But
o If the moon moves by this displacement as its orbital displacement the moon
would revolve around Earth through its apogee orbit only (r=0.406 mkm)
o For that reason
o The moon creates an angle between its motion direction and its orbit
horizontal level to create a displacement through its orbit less than (88000
km)
o As a result of this technique, the moon can revolve around Earth through
more near orbits than apogee orbit (r=0.406 mkm)
o Simply, because the moon uses this technique the moon can revolve around
Earth through perigee orbit (r=0.363 mkm)
o Let's explain this intelligent technique with some details to show the useful
result of using Pythagoras triangle by the moon orbital motion….
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3-2 How Does The Moon Use Pythagoras Triangle In Its Motion?
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbit horizontal
level, by that the real displacement through the moon orbit will be (L= 88000 km
cos (θ)), and by that, spite the moon moves 88000 km, but the real orbital
horizontal displacement be less than (88000 km) and this is the objective for which
the moon uses Pythagoras triangle –
As an example,
- If (θ) =28.63 degrees, the real displacement (L== 88000 km cos (θ)) = 77237 km,
So, if the moon real displacement daily be (77237 km), during 29.53 days the
moon will pass a distance = 2.28 million km and this will be the moon orbital
circumference, where 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagoras triangle,
- Now let's suppose the moon doesn't use Pythagoras triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm where 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving around Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagoras triangle is so useful for the moon orbital motion.
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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
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3-3 The Moon Orbital Motion
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves
per a solar day 2.573 million km with an angle declines on the horizontal level
0.98562 degrees as typical to Earth motion
- If there's no Lorentz Length Contraction Phenomenon effect on the moon motion,
the moon motion trajectory would to be a parallel line to Earth Motion Trajectory,
But Lorentz Length Contraction effects on the moon motion daily distance (2.573
mkm) with a rate 1.0725 and causes this distance to be contracted (2.399 mkm)
- The moon difficulties are started here, because the difference between both
distances (0.17 mkm) will cause the moon to be separated from Earth motion
inevitably
- We should notice that, these motions are done far from our observation, means, we
see nothing of this motion distance, because the moon moves on the Earth orbital
circumference revolving around the sun, but, even if we can't observe this motion
distance the motion is still fact and proved by its power, because the Earth moves
per a solar day 2.573 mkm and if the moon doesn't move this same distance every
solar day that necessities the moon to be separated from the Earth through their
motions course – based on that- the facts prove this motion regardless our
observation ability for it.
- Now the moon has an additional distance to be passed (0.17 mkm) and the moon
has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
- Because of that, the moon moves its daily displacement (88000 km) depends on
Earth gravity force (by which we see the moon in the Earth sky), but the different
distance (0.17 mkm) to be covered still needs the moon to move one more
displacement (= 88000 km)
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- The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the
moon orbital motion around Earth but the other displacement should be done also
because this total distance (0.17 mkm) is required to cover the different distance
and create the total (2.573 mkm) which saves the moon and Earth motions
accompanying.
- Now we have 2 basic information about the moon orbital motion
o (1st
information) the moon uses Pythagoras triangle in its orbital motion
o (2nd
information) the moon has to move 2 displacements each =88000 km
and their total distance =0.17 mkm which is a required distance necessary to
cover the difference between the moon and Earth motions distances.
- This explanation helps us to understand why the moon uses Pythagoras triangle in
its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.399 mkm) and Earth motion distance (2.573 mkm),
So the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagoras triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…
- (Notice, Lorentz Length Contraction Effect Discussion is in Appendix No. 1)
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The Moon Orbital Motion Needs One More Orbit
- The previous explanation tells that, the moon moves 2 displacements each =88000
km, we see one of these 2 displacements but where's the other displacement?!
- We know that, the moon original motion (2.573 mkm) which is contracted to be
(2.399 mkm) isn't seen by us because the moon moves this distance revolving with
Earth around the sun along the Earth Orbital Circumference
- We may accept that, the 2nd
displacement the moon does on this same trajectory
and isn't seen by us.
- So,
- There must be one more orbit for the moon to move through this 2nd
displacement.
means,
- There's 2nd
Orbits For The Moon Motion
- But
- How can we discover this second orbit if we can't observe the 2nd
displacement
motion?
- We can discover this 2nd
orbit by the moon orbit data analysis. So we should
depend on the moon orbital triangle data analysis to define this 2nd
orbit position.
- For that we have to discuss the moon 2nd
orbit in our deep analysis of The Moon
Orbital Triangle Geometrical Structure.
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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3-4 The Moon Orbital Motion Equation
3-4-1 The Equation Concept
3-4-2 The Equation Test and Accuracy
3-4-1 The Equation Concept
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed before which is (the moon uses Pythagoras triangle in its orbital motion)
- The moon uses Pythagoras triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
(θ1= θ0 + 1.7 degrees)
- We have 3 questions in this equation which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees? Let's try to answer….
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and starts
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagoras triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagoras triangle its angle (θ) = 26.93 degrees, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km
28. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion (tomorrow) will be at the point 368722 km
and will have the Pythagoras triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following
29. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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3-4-2 The Equation Test and Accuracy
(θ1= θ0 + 1.7 degrees)
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[
30. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
Category of results defines the moon position in error range from (2000
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily
31. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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(θ1= θ0 + 1.7 degrees)
2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[
32. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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32
The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
Category of results defines the moon position in error range from (2000
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily
33. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
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3-4-3 The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
(θ1= θ0 + 1.7 degrees)
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed deeply (Metonic Cycle
Discussion Point No. 6)
34. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be more less
enables the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
o That means, while the moon be on perigee or apogee, the moon doesn't use
the equation and doesn't change its distance to perigee or apogee for long
days…we may notice that in the equation tests, when the moon reach to
perigee or apogee the equation stops its work and stays 2 or 3 days to return
to its work… because the moon consumes long time to leave the points
(perigee and apogee)…
35. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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4-The Moon Orbit Geometrical Design
4-1 Preface
4-2 The Necessity Of Pythagorean Triangle (1, 2, 51/2
)
4-3 The moon motion angle (12.195 deg) Analysis
4-4 Why The Moon Displacement Daily =88000 km?
4-5 The angle 71.9 degrees
4-6 Why The Moon Day Period =29.53 days?
4-7 The Perpendicular Line BC (=86000 km)
4-8 The Point (F) Position Analysis
36. IN THE ALMIGHTY GOD NAME
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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4-1 Preface
On What Facts This Study Depend?
On The Logical Geometrical Structure
- Please remember, the green line (the triangle base EA) has an angle 1.1 degrees with the
moon equator line, and an angle 0.443 degrees with the Earth Ecliptic
- Example.
- The moon orbital triangle base (The Green Line) (EA) = 449197 km
- In this distance, the point (A) I have concluded and was not found in the moon
motion data sheet, so Can be this point (A) a real point, or it's invented one?
o The distance EA causes the distance BD (43000 km) be = DA (43000 km)
o The distance EA 449197 km = Jupiter Circumference
o The distance BA = 86000 km = BC
o The triangle BCD is a Pythagorean specific triangle (1, 2, 51/2
)
o The perimeter of the triangle (ECA) = the distance from the point (A) to the
end on the lunar eclipse umbra length (1.392 mkm).
If I have invented the point (A), how can I created these relationships with it, where I
depend on the moon orbital motion real data? The main power behind this analytical
study is The Logical Geometrical Structure Of The Moon Orbital Motion Data.
37. IN THE ALMIGHTY GOD NAME
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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4-2 The Necessity of Pythagorean Triangle (1, 2, 51/2
)
(1st
Point) The Moon Motion Limits Definition
- In this moon orbital triangle I have added the line CS to create a total angle =137
degrees – based on that
(A)
- The angle ECS =137 degrees
- The distance BS = 150628 km
- The distance SA = 64628 km
- The hypotenuse CS = 173450 km
- The perimeter of the triangle BCS = 173450 +150628 +86000 = 410080 km
- The triangle perimeter (BCS) =410080 km= the apogee radius (406000 km)
(error 1%)
(B)
- The perimeter of the triangle (ACS) = 121622 + 173450 +64628 = 359700 km
- Perigee radius = 363000 km (error 1%)
A Conclusion
- The triangle BCS defines the moon motion limits from perigee to apogee by a
geometrical mechanism depends on The angle 137 degrees……. Why & How?
38. IN THE ALMIGHTY GOD NAME
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2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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(2nd
Point) The Rate 0.08
Why Pythagorean Triangle (1,2, 51/2
) Is Required?
This figure is discussed before.
- The inner circle refers to the perigee orbit
- The outer circle refers to the apogee orbit
- OB = 406000 km = Apogee Radius
- OR = 363000 km = Perigee Radius
- DB = 181843 km
- Perigee Orbital Circumference = 2.28 mkm
- Apogee Orbital Circumference = 2.55 mkm
I - Data
(1)
(DB / Perigee Orbital Circumference) = (181843 km/2.28 mkm) = 0.08
(2)
10.96 = 137 (The basic Angle) x 0.08
(3)
Sin (10.96 degrees) x 406000 km = 77237 km
(4)
Cos (10.96 degrees) 88000 km = 86400 km
(5)
Sin (10.96 degrees) 449197 km = 85403 km
II – Discussion
- Why is the Pythagorean triangle (1,2,51/2
) required for the moon orbital motion?
- Because, the rate (0.08) is required to create interaction with the angle (137 deg),
and based on this interaction, the valuable angle (10.96 degrees) will be created,
and based on this angle (10.96 degrees) most of the moon orbital motion data will
be created.
39. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- That answers the question why the rates (1,2,51/2
) were required necessary for the
moon orbital motion? because based on these rates the rate (0.08) will be produced
which will be used to produce the angle (10.96 degrees)…… So
- Based on the angle (CSB =137 degrees), the moon orbital motion receives 3 basic
data which are
o The apogee point radius (r=0.406 mkm) which is defined by the triangle
BCS) Perimeter
o The Perigee point radius (r=0.363 mkm) which is defined by the triangle
ACS) Perimeter
o And the rate (0.08) which is defined between the tangent DB (181843 km)
and the perigee orbital circumference (2.28 mkm)…….. then
o 10.96 = 137 x 0.08
o The valuable angle (10.96 degrees) is created.
Equation No. (3)
Sin (10.96 degrees) x 406000 km = 77237 km
- This equation tells the story in more clear way….
- The value 77237 km is very important…. If the moon moves daily a displacement
= 77237 km, during 29.53 days, the total distance will be = 2.28 mkm = the moon
orbital circumference at perigee orbit (r= 363000 km)
- Means,
- The perigee orbital circumference = 29.53 displacements each =77237 km, that
tells the value (77237 km) is defined by perigee radius (r=0.363 mkm) and the
moon day period (29.53 solar days), whatsoever the moon apogee radius be ….
Now the angle (10.96 deg) is defined before (10.96 = 137 x 0.08), and by that the
apogee radius is defined….
- This explanation is not so correct because the apogee radius is defined before by
the triangle (BCS) Perimeter and (the rate 0.08) is defined based on it because we
use it in the circles figure.
40. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- I try to show that, we deal here with few players are created depending on each
other , all of them has on origin which is the angle 137 degrees, and has one result
which is the angle (10.96 deg)… what I try to do here is to show how the data is
arranged in a clear direction, and by that, I may prove this is A Directed Data.
Equation No. (4)
Cos (10.96 degrees) 88000 km = 86400 km
- The analysis is still complex and we need to consider it deeply in following…..
- Where
o The moon orbital circumference at apogee radius (r=0.406 mkm) equals
only 2.55 mkm and this distance is short!
o Because
o The moon daily displacement =88000 km and during 29.53 solar days the
total displacements will be = 2.598 mkm …..if this distance be the moon
orbital circumference the radius will be = 0.413 mkm
o Means, the apogee radius will not be 0.406 mkm but 0.413 mkm !
o Which proves the paper claim, that, the moon uses Pythagorean triangle in
its motion,
o But
o Why the moon orbital circumference at apogee is not = 2.598 mkm? Why
the moon orbital circumference at apogee =2.55 mkm and les with (1%)
than the total displacements during 29.53 days?
- Equation No. (4) tells us this story clearly, where the apogee orbit permits for a
moon daily displacement =86400 km and NOT 88000 km
Notice
- This is a theoretical analysis and not a practical one, the moon could use 88000 km
as its displacement without using Pythagorean triangle technique for any days
during the month BUT with a condition that, the total distance isn't grater than
2.55 million km (= the moon apogee orbital circumference).
41. IN THE ALMIGHTY GOD NAME
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I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- Why the apogee orbital circumference doesn't equal 2.598 mkm?
- Let's analyze the moon different motions in following to see this data as clear as
possible
More Data
(A)
The moon orbital circumference at apogee point = 2.55 mkm (100 %)
The Earth moves per solar day a distance = 2.5734 mkm (101%)
The moon total displacements during 29.53 days = 2.598 mkm (102%)
Pluto motion distance during its day (153.3 h) = 2.5938 mkm (102%)
(B)
137 =95.1 x 1.44
More Discussion
Data No. A
- The first and third distances are the moon motion distances, where, it’s the moon
orbital circumference (2.55 mkm) and its total displacements (2.598 mkm)…
- The second distance is the moon motion distance also, because the moon moves
per solar day a distance equal earth motion distance per solar day perfectly
otherwise the moon and Earth will be separated in the motions course.
- We have 3 motions are arranged in (100%, 101%, 102%) all of the are done by the
moon motions – There must be a geometrical mechanism behind this order-
- We deal with some gears, and these gears are required to be rated to each other to
enable to do their jobs –
- i.e.
- The moon orbital circumference at apogee (2.55 mkm) is NOT short distance, it's
created for some geometrical necessity to enable the machine of gears to work
- This discussion should be completed with answering of the question (Why the
moon daily displacement =88000 km? (its discussion is in "point No. 4-4")
42. IN THE ALMIGHTY GOD NAME
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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Equation No. (B)
137 =95.1 x 1.44
- We still don't know why this angle 137 degrees has so massive effect on the moon
orbital motion…?
- Equation no. (B) may help us let's discuss it
o 95.1 degrees = 90 degrees + 5.1 degrees (the moon orbital inclination)
o 1.44 degrees = the moon orbit regression degrees per month
- So, the angle 137 degrees, is created by the moon orbit motion effect,
- 2 features of the moon orbit motion unifies together to produce this angle (137
degrees) which is the origin of the moon motion distance from perigee to apogee..
which are
o The moon orbital inclination 5.1 degrees
o The moon orbit regression 19 degrees per year
- These 2 features of the moon orbital motion creates together the angle 137 degrees
as their platform to create the moon orbital motion in harmony with these 2
features…
Notice
- 180 degrees -137 degrees = 43 degrees
- If 1 degree =1000 km, so
- The value 43 degrees expresses the distance 43000 km which is the distance
between Perigee and apogee….
- Also, the triangle (ACS) Perimeter =359700 km = 360000 km
- If 1 degree =1000 km, so this value 360000 km will be equivalent to 360 degrees.
- The data tells that, a geometrical mechanism is found behind it creates this data
based on each other geometrically
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Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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(3rd
Point) The Angle 10.96 degrees
By this triangle we follow the moon motion data based on the angle 10.96 degrees.
We start from apogee radius (r=406000 km) on the AC as following
(1)
- AC =406000 km the angle C= 10.96 deg what's BC?
- BC = 398595 km
(2)
- AC =398595 km the angle C= 10.96 deg what's BC?
- BC = 391324 km
(3)
- AC =391324 km the angle C= 10.96 deg what's BC?
- BC = 384186 km
(4)
- AC =384186 km the angle C= 10.96 deg what's BC?
- BC = 377179 km
(5)
- AC =377179 km the angle C= 10.96 deg what's BC?
- BC = 370300 km
(6)
- AC =370300 km the angle C= 10.96 deg what's BC?
- BC = 363546 km
The 4 distances (in blue color) are the moon motion basic 4 points.
The moon motion depends on the angle 10.96 degrees.
44. IN THE ALMIGHTY GOD NAME
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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Equation No. (5)
Sin (10.96 degrees) 449197 km = 85403 km
- Equation no. (5) tries to help the explanation,
o The distance 85403 km is very near to the line BC =86000 km (error 0.7%)
o Also the distance 86000 km = 2 x 43000 km ( Perigee apogee distance)
o But
o The distance 449197 km is created based on the point (A) which is created
and not found in the moon data sheet….
o By what geometrical mechanism the angle 10.96 degrees uses the distance
449197 km to produce the line BC 86000 km?! The data tells that the
distance (449197 km) is a real one and isn't invented …. Also the line BC
(86000 km) is real data.
o That means, the moon orbital triangle is discovered and not invented.
o And the data which is concluded by its as real as the moon registered data
by observation.
45. IN THE ALMIGHTY GOD NAME
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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4-3 The Moon Motion Angle (12.195 degrees) Analysis
I-Data
(I)
Sin (12.195 degrees) x 407300 km = 88000 km
And
13.177 degrees – 0.98562 degrees = 12.195 degrees
(II)
(10.96 degrees) + 1.25 degrees =12.195 degrees
Where
13.177 degrees = the moon daily motion degrees
0.98562 degrees = Earth daily motion degrees
0.8 degrees = Uranus Orbital Inclination
II- Discussion
- The Apogee Orbit (r=0.406 mkm) permits a displacement =86400 km only based
on the valuable angle (10.96 degrees), as maximum displacement during 29.53
days because (86400 km x 29.53 days = 2.55 mkm = 2π x 0.406 mkm)
- But
- What about the actual displacement 88000 km, which angle expresses it?
- The data shows that, the angle 12.195 degrees can define this displacement (88000
km) relative to the radius (407300 km) which is very near to apogee radius =
(406000 km) (error 0.3%).
- Equation No (II) tells that, Uranus orbital inclination 0.8 degrees is used as (1/0.8),
i.e.
- The angle (10.96 degrees) + (1/0.8 degrees) = 12.195 degrees
- The data shows Uranus effect on the moon orbital motion
NOTICE (1)
Uranus effect on the moon orbital motion will be discussed in the next point (no. 4-4,
why the moon daily displacement =88000 km?)
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NOTICE (2)
The following explanation shows a new geometrical technique is using in the moon
geometrical structure, it's just example using the angle 12.195 deg in this technique
I-Data
- In the triangle ABC
- AB = 12.195 km
- AC = 2 x 29.53 km
- The Angle A = 78.081
- The Angle C = 11.919 degrees
- But
- Cos (12.195 degrees) x 12.195 degrees = 11.919 degrees
1- How This Triangle Is Created?
- The geometrical structure uses the angle 12.195 degrees as a distance= 12.195 km,
and creates the angle (C) depends on the angle 12.195 degrees as the data shows
- So this triangle is created depending on the angle 12.195 degrees
2- This Triangle Purpose
- The triangle aims to create the hypotenuse AC = 59.06 km = 2 x 29.53 km
3- Why This Triangle Is Created?
- To create the value (29.53 km) depends on the value 12.195 degrees geometrically,
both data is the moon motion data, but the triangle tries to connect both data
geometrically, why? because Nothing is independent (the geometrical concept),
because of that, the new data should be created based on the old data, and by that
there's always one line connecting all data
This simple example is for this technique explanation.. and the rate (1km=1degree) is
used here only and not a general rate, although the value (2x 29.53) is used more
widely than (29.53) in all data. (For example, Earth during 59 days moves a distance
= its orbital distance "Error 1%" ).
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4-4 Why The Moon Displacement Daily =88000 Km?
Earth motion distance during its day period = the moon displacements total
during its day period = Pluto motion distance during its day period (error 1%)
I - Data (Old Data)
The moon orbital circumference at apogee point = 2.55 mkm (100 %)
The Earth moves per solar day a distance = 2.5734 mkm (101%)
The moon total displacements during 29.53 days = 2.598 mkm (102%)
Pluto motion distance during its day (153.3 h) = 2.5938 mkm (102%)
II - Data (New Data)
(1)
Earth moves during (6939.75 solar days) a distance = 17859.325 mkm
(2)
Pluto moves during (6939.75) x (153.3 hours) a distance = 18000.57 mkm
(3)
The moon displacements total during (6939.75) x (29.53 days) = 18034.278 mkm
(4)
Uranus Orbital Circumference = 18048.449 mkm
Where 153.3 hours = Pluto day period 29.53 days = the moon day period
The moon daily displacement =88000 km
III - Data Analysis
(4) – (1) = 189.124 mkm
(4) – (2) = 47.879 mkm
(4) – (3) = 14.171 mkm
(3) – (1) = 174.953 mkm
(3) – (2) = 33.708 mkm
(2) – (1) = 141.245 mkm
- Sin (17.2) x 47.879 mkm = 14.171 mkm
- Tan (10.96) x 174.953 mkm = 33.708 mkm
- Tan (13.3) x 141.245 mkm = 33.708 mkm (error 1%)
- 0.8 x 174.953 mkm = 141.245 mkm (error 1%)
- Sin (4.63) x 174.953 mkm = 14.171 mkm
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o 0.8 degrees = Uranus Orbital Inclination. Sin (4.63) =0.08
o 17.2 degrees = Pluto Orbital Inclination
o 13.3 degrees = The angle of (E) in the moon orbital inclination
o 10.96 degrees (Cos 10.96 degrees x 88000 km = 86400 km)
VI –Discussion
- The previous 4 angles are the basics data for their planets, let's try to show that
o 0.8 degrees = Uranus Orbital Inclination
o 122.5 deg (Pluto Axial Tilt) x 0.8 = 97.8 deg (Uranus Axial Tilt)
o Pluto orbital inclination 17.2 degrees = 0.99 x 17.4 deg (The inner planets
orbital inclinations total) … also
o Pluto orbital inclination 17.2 deg x 7.1 = 122.5 deg (Pluto Axial Tilt)
o 13.3 degrees is the angle of point (E) (Earth) in the moon orbital triangle
(Earth Orb. Period 365.25 d = The moon Orb. Period 27.3 d x 13.3)
o The angle 10.96 degrees is the valuable angle we have discussed deeply
where (Cos 10.96 degrees x 88000 km = 86400 km).
o Sin (4.63) = 0.08 This rate effects on the moon orbit geometrical design
There's an interaction occurred here between these 4 planets (Uranus, Pluto, Earth and
its moon), and in this interaction, these 4 basic values are created and based on these 4
values many other data of these planets is created … means, this interaction forms the
geometrical structure of these planets motions …. And if we limited our discussion
for the moon orbit structure, that lead us to conclude that, the moon orbit geometrical
structure is effected by these 4 planets motions interaction as seen in the data.
i.e.
These 4 planets motions interaction effects on the moon orbital motion and causes to
create Metonic Cycle. (this discussion should be completed with Metonic Cycle
Discussion Point No. 6)
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4-5 The angle 71.9 degrees
- Please remember, the green line (the triangle base EA) has an angle 1.1 degrees
with the moon equator line, and an angle 0.443 degrees with the Earth Ecliptic
The angle 71.9 degrees is an angle created by the interaction between the 4 planets
Motions (Earth, its moon, Pluto and Uranus).
(Why we need to discuss this angle 71.9 degrees?)
Because this angle can answer why the moon orbital motion equation uses the
constant 1.7 degrees for the moon daily motion (θ1= θ0 +1.7 degrees).
The Figure Description
- In this moon triangle, I added CM, where the angle ECM= 49.77 degrees
- And the angle MCA = 71.9 degrees
- The angle M1 N M2 =88.9 degrees
- AM = 129630 km
- CM = 96434 km
- EM = 319370 km
- The Perimeter of the triangle (MCA) = 347684 km
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I- Data
(1)
The angle M1 N M2 =88.9 degrees
88.9 degrees – 71.9 degrees = 17 degrees
(2)
(17 degrees /0.8) = 21.25 degrees
(3)
21.25 degrees x 0.08 = 1.7 degrees (the moon motion equation constant)
(4)
17 degrees x 1.7 degrees = 29 degrees
(5)
23.4 deg = 1.8 deg x 13.177 deg x 0.98562 deg
II- Discussion
- Equations (from 1 to 3) give us a simple geometrical method to change the value
17 degrees into 1.7 degrees, but why this method is useful?
- Because the value 21.25 degrees is one of the moon motion angles which is
- 21.25 degrees = 11.8 degrees x 1.8 degrees
- Where
- 11.8 degrees = 5.1 deg (the moon orbital inclination) +6.7 deg (the moon axial tilt)
- But what's 1.8 degrees?! Let's discover in following…
o The moon moves from perigee to apogee and return back during its orbital
period.
o The distance from perigee to apogee on the moon orbital triangle (BD)
controlled by the angle (BCD =26.56 degrees)
o The moon go and return during the cycle (26.56 degrees x 2 = 53.12 deg)
o (53.12 degrees /29.2 solar days) =1.8 degrees
o Why I divide this angle 53.12 degrees on 29.2 days?
o Because
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o The Earth moves during 29.53 solar days 29.2 degrees
o But
o The moon moves during 29.53 solar days (360 degrees + 29.2 degrees)
- The previous explanation shows that, the angle 21.25 degrees is used in the moon
orbital motion because it depends on 2 angles (11.8 deg) and (1.8 deg) are used in
the moon day motion. based on that, the interaction between the angle 17 degrees
and 21.25 degrees can be created because both angles are used in the same motion
- Then
- The last step is to change the angle 21.25 degrees into 1.7 degrees as following
- 21.25 degrees x 0.08 = 1.7 degrees
- We remember this rate (0.08) based on which the valuable angle (10.96 deg) is
created.
Notice
- The most 3 basic values in the moon motion are (137 deg, 10.96 deg and 0.08)
- As the valuable angle (10.96 deg) is created based on this rate (0.08), the moon
orbital motion equation angle (1.7 deg) is created based on it….BUT
- Why the data shows that, Uranus orbital inclination (0.8 degrees) is used in this
process? The data uses (17 degrees /0.8 degrees) = 21.25 degrees, showing clearly
the using of Uranus orbital inclination (0.8 degrees) Why? because the data tries to
show Uranus effect on the moon orbital motion…. the next points supports it.
Equation No. (4)
17 degrees x 1.7 degrees = 29 degrees
- We know both angles 17 and 1.7 degrees but what's this 29 degrees?!
- The major lunar standstill can be +28.5 = (23.4 deg + 5.1 deg)
- The moon angular diameter = 0.5 degrees, that means, when the moon orbital
inclination is measured above the moon diameter it will be =5.6 degrees
- So the angle 28.55 degrees +0.5 degrees = 29.05 degrees
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- That shows Uranus effect on the moon motion during Metonic Cycle, which effect
on the moon daily orbital motion and effect on the moon motion equation by the
constant (1.7 degrees)
Equation No. (5)
23.4 deg = 1.8 deg x 13.177 deg x 0.98562 deg
Where
23.45 deg = Earth Axial Tilt 0.98562 deg = Earth motion daily degrees
13.177 deg = the moon daily motion degrees
1.8 degrees = is the angle we have discussed in the previous equation (no.3), the
angle of the moon motion from perigee to apogee during its day period (52.6/29.2)
Equation no. (6) shows that Earth axial tilt is created depending on the moon motion.
Planets Effect on Data
(1)
- Uranus (6.8 km/sec) moves during 51118 seconds a distance = 347603 km
- This distance = the triangle (MCA) perimeter accurately, showing Uranus effect
on the moon orbital geometrical structure by using the angle 71.9 degrees.
(2)
- Tan (71.9 deg) x 43000 km = 129630 km (error 1.5%)
- Where 43000 km = Perigee Apogee Distance and AM =129630 km
(3)
- 17 degrees = 0.99 x 17.2 degrees (Pluto orbital inclination)
- But , 17.2 degrees = 0.99 x 17.4 degrees (the inner planets orbital inclinations total)
- Also, 23.4 degrees = 0.99 x 23.6 degrees (the outer planets orbital inclinations total)
Notice
The angle 71.9 degrees is a very rich angle and the previous discussion is a small part
of it, for that, this discussion should be completed with Meronic Cycle Discussion
Point .6 and Uranus Motion analysis Point no. 7.
under the title ("The Interaction Angle 71.9 degrees" Continued)
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4-6 The Perpendicular Line BC (=86000 km)
- Let's summarize how this triangle idea is created in following:
o Uranus Axial Tilt =97.8 deg and the Earth Moon Axial Tilt =6.7 deg. So
between them (97.8 – 6.7 = 91.1 degrees)
o The number 91.1 degrees gives a reference for some perpendicularity
between the moon axial tilt and Uranus axial tilt, but there's 1.1 deg!
o So, the solution was to decline the triangle base (EA) with 1.1 degrees on
the horizontal level and by that Uranus axial tilt will be perpendicular on the
triangle base (AE) if this triangle based depends on the moon axial tilt…
o This is the original idea of this triangle
o For that reason the line BC is perpendicular on the moon orbital triangle
- Based on this description
- The line BC shows Uranus motion effect on the moon orbital motion.
- In Metonic Cycle Discussion we should discuss more effects done by this line BC
on the moon orbital motion trying to prove that Uranus Motion effect on the orbtial
motion is a real effect.
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4-7 Why the moon day period =29.53 solar days?
I-Data
Equation No. (A)
Tan (12.195 deg) x 708.7 hours (the moon day period) = 153.3 h (Pluto day period)
Tan (13.177 deg) x 655.7 h. (the moon rotation period) = 153.3 h (Pluto day period)
- The angle 12.195 deg. is the moon angle (12.195 deg. = 13.177 deg. - 0.9856 deg),
Based on this angle the moon & Pluto days periods are defined relative to each
other… Why?
- The angle 13.177 degrees is the moon motion daily angle (360 =13.17 deg x 27.3)
and based on this angle the moon & Pluto rotations periods are defined relative to
each other… Why?
- Why the moon day period =29.53 solar days? Because the moon day period is
created in proportionality with Pluto day period and both are created relative to
each other…..But the better question is ….
Why Earth day period =24 hours?
Equation No. (B)
Tan (8.9 deg) x 153.3h (Pluto day period) = 24 hours
- The angle 8.9 degrees =98.9 degrees – 90 degrees (discussed in page no. 35)
- By this angle Earth and Pluto days periods are created relative to each other!
- Pluto, Earth and the moon motions are interacted because of their motion distances
relative to Uranus orbital circumference (discussed in page no. 37) means this data
is a point of a sea of data which we have to discuss in Metonic Cycle discussion
Shortly
- The moon day period (= 29.53 solar days) because it's created by 2 motions effect
on the moon orbital motion (Earth & Uranus motions) through the 4 planets
motions interaction. (Metonic Cycle is discussed in Point No. 6)
- (In that discussion we should discuss, Why "Earth velocity/ Pluto velocity" = Pluto
day period / Earth day period?).
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4-8 The Point (F) Position Analysis
- In the triangle PM2F
o The angle PM2F = 6.643 degrees
o The angle M2PF = 161.129 degrees
o The angle F = 12.228 degrees
o The distance PM2 = 403360 km
o The distance M2F = 615895 km
o The distance PF = 220305 km
o The distance EF = 214061 km
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5- The Moon Orbital Triangle Geometrical Benefits
5-1 Preface
5-2 The Moon orbital triangle shows that (2nd
force effect on the moon motion)
5-3 The Moon orbital triangle shows that (There's 2nd
Orbit for the moon motion)
5-4 The Moon orbital triangle shows that Uranus effects on the moon motion
5-1 Preface
- The moon orbital triangle geometrical analysis provides a new and effective idea
let's try to summarize it in following
o The moon orbital triangle shows that many forces effect on the moon orbital
motion because of that many geometrical rules are used in this motion to
define each force balancing points
o I refer to Earth gravity force effect on the moon motion as 1st
force
o I refer to all other planets effects on the moon motion as 2nd
force
o The sun gravity force is considered to be including into both forces
- The triangle shows that, many forces (or motions) interaction effects on the moon
motion and by that the moon orbit geometrical design became a specific one,
showing these forces effects.
- The triangle analysis depends on the Logical Geometrical Analysis, for that, the
absent data can be concluded and (more important) the forces created this data can
be discovered
- Based on that, Jupiter and Uranus (in addition to other planets) have effects on the
moon orbital motion. this conclusion can be formed by the moon orbital triangle
data analysis.
- This analysis can support the paper hypotheses which are: (1st
) (There's 2nd
force
effects on The Earth Moon Orbital Motion (2nd
) (Uranus Motion effects on the
Earth moon orbital motion and creates Metonic Cycle)
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5-2 The Moon orbital triangle shows (2nd
force effect on the moon motion)
(The Triangle Data Analysis In Discussed In Point No. 1 Of This Current Paper)
- What Proves Can Be Provided For The 2nd
Force Hypothesis?
o (1st
Proof) The Point (A) In The Moon Orbital Triangle
o (2nd
Proof) The 2nd
Displacement 88000 km
o (3rd
Proof) Metonic Cycle Creation…. Let's discuss them in following:
(1st
Proof)
- The moon orbital triangle causes to raise the question, because the Point (A) is one
of its 3 basic points and no force we know can create this Point (A) which is found
far from apogee radius (r=0.406 mkm) with a distance =43000 km, because of that
the distance EA =449197 km
- So how this point is found and effect on the moon orbital triangle? We have no
answer except that 2nd
force is found effects on the moon orbital motion, this 2nd
force effects on the Point (A). So Earth gravity force effects on the moon motion
on one side and this 2nd
force effects on the moon motion on other side to create
general balancing of the moon motion.
- Although no clear definition for the force creates the point (A), this force is still
fact because of the geometrical massive significance of the point (A).
- means, the point (A) should be considered as a proof for this force existence
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(2nd
Proof) The 2nd
Displacement 88000 km
- The moon orbital motion story tells us, the moon contracted distance (2.399 mkm)
needs (0.17 mkm) to be = Earth motion distance (2.573 mkm) per solar day, and
the moon has to move this additional distance (0.17 mkm) on the same solar day,
But the moon daily displacement =88000 km, means, the moon has to move one
more displacement (88000 km) which we don't see…
- If this story is real, and the distance 0.17 mkm should be passed, and if 1 force
only effects on the moon, so this force should cause the moon to move 0.17 mkm
completely…but the moon displacement is only (a half) of the required distance…
that tells us there are 2 forces causes 2 equal displacements (regardless our
observation for them).
- The argument here depends on the moon basic motion (2.573 mkm) which creates
the moon daily displacement (88000 km), if the connection between these 2
distances is a real one, so the 2nd
displacement must be a fact and that necessitates
to find 2nd
force effects on the moon orbital motion.
(3rd
Proof) Metonic Cycle Creation.
- Uranus Orbital Circumference =19 Earth Orbital Circumference …… means
- While Uranus revolves around the sun one revolution, Earth (and its moon)
revolve around the sun 19 revolutions (19 years =6939.75 solar days)
- If Uranus motion effect on the Earth moon motion, the period 19 years should be
seen in this effect data because it’s the basic rate between the 2 orbits
- The moon Metonic Cycle (6939.75 solar days=19 years) tells that, there's a
possibility of Uranus motion effect on the moon motion..
- The point is, if Uranus really effects on the moon orbital motion to create Metonic
Cycle, so this will be a solution for the question (What's this 2nd
force effects on
the moon orbital motion), or at least will give us a light to see other players effect
on the moon orbital motion in place of the one planet gravity effect vision.
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5-3 The Moon orbital triangle shows (There's 2nd
Orbit for the moon motion)
I- Data
(1)
The moon orbital triangle (ECA) Perimeter = 943817 km
The Lunar Eclipse Umbra Length = 1.392 mkm
The distance (EA) = 449197 km + (The Perimeter) 943817 km = 1.392 mkm
II- Discussion
- The Point (A) divides (the lunar eclipse umbra length) into 2 equal parts, after the
Point (A) this part is seen in the triangle perimeter (ECA) and
- Before the Point (A) this part is seen in the distance from the Point (A) to the end
of The Lunar Eclipse Umbra Length
- Can This Be A Proof?
- The geometrical division is a proof, because the moon orbit data is created based
on geometrical interactions for that reason the moon orbital triangle shows these
geometrical interactions and rules, and these geometrical rules tell, many players
are interacted here –for that reason, the triangle (ECA) perimeter has a relationship
with The Lunar Eclipse Umbra Length (Where the geometrical necessity of this
relationship still need to be caught, but the mere existence of this relationship is a
proof for different player effect on the moon orbit geometrical creation).
- I want to say, the moon orbit is NOT a trajectory of a rigid body revolves around
Earth, instead, it's a network of forces lines and the moon moves through this
networks taking into consideration these forces lines effects AND shows that in its
motion data.
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5-4 The Moon orbital triangle shows that Uranus effects on the moon motion
- Let's review the triangle concept in following:
o The moon orbital triangle is a vertical triangle effects on the moon orbit,
where the line (BC) is perpendicular on the moon orbital triangle base (EA)
and because of that the point (C) is found on (z-axis), where the moon
orbital motion is done on (x-y plain)
o How That Can Be Possible?
o I supposed Uranus Axial Tilt (97.8 degrees) is the line (BC), the moon axial
tilt =6.7 degrees and the difference =91.1 degrees, for that reason the moon
orbital triangle declines on the moon equator line with 1.1 degrees and the
line (BC) is perpendicular (90 deg) on the moon orbital triangle base (EA).
o I have designed this triangle basically based on this data and the triangle is
used sufficiently for the moon real motion and data.
o Uranus indeed effects on the moon orbital motion in different features, not
only in Metonic Cycle, but also by Uranus axial tilt effect on the moon axial
tilt, not that only…
o Earth moves during its day period a distance = The moon displacements
total during its day period = Pluto motion during its day period, (error 1%),
This feature also is found by Uranus effect on the moon orbital motion
o The moon day period (29.53 solar days) is a piece of gold because this
period of time shows that it's created by 2 motions effect on the moon
orbital motion – shortly – Earth and Uranus motions effect on the moon
orbital motion, forcing the moon day period to be 29.53 solar days.
o This discussion should be completed with Metonic Cycle Discussion (Point
No. 6 of this paper).
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6- Metonic Cycle Is A Proof of Uranus Effect On The Moon Motion
6-1 Preface
6-2 Uranus Effect On The Moon Orbital Motion
6-3 The 4 Planets Motions Interaction
6-4 The Moon Orbital Triangle Angles Discussions
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6-1 Preface
Paper 2nd
hypothesis
- The Earth Moon Metonic Cycle (6939.75 Solar Days) is created by Uranus
Motion Effect On The Moon Orbital Motion.
The Hypothesis Proves
o (1st
Proof) Uranus Orbital Circumference =19 Earth Orbital Circumference,
So while Uranus revolves around the sun 1 complete revolution the Earth
(with its moon) revolve around the sun 19 revolutions..
o If Uranus Motion effects on the moon orbital motion, the number 19 should
be seen in this effect data because it’s the rate between both orbits.
(Sub-Point 6-2)
o (2nd
Proof) Earth Motion Distance During Its Day Period = The Moon Total
Displacements During 29.53 solar days (The Moon Day Period) = Pluto
Motion Distance During 153.3 hours (Pluto Day Period) – this feature of
motion is created by Uranus motion effect on the 3 planets.
(Sub-Point 6-3)
o (3rd
Proof) Uranus Moves During (1440 Of Its Days Period) A Distance =
The Earth Moon Total Displacements During Metonic Cycle (6939.75 Solar
Days)
(Point No.7 "Uranus Motion Analysis")
o (4th
Proof) The Moon Orbital Triangle Data Shows Uranus Effect On The
Moon Motion.
63. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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63
6-2 Uranus Effect On The Moon Orbital Motion (1st
Proof)
In this figure
- The Red Ball Shows Earth
- The Yellow Ball shows The Earth Moon
- The Blue Ball shows Uranus
- (S) is the Sun
- The figure suggests that, a triangle contains these 3 planets together in their
revolutions around the sun
- Let's suppose the three planets, Earth, its moon and Uranus move in parallel to
each other in their revolutions around the sun, and to guarantee this parallelism
between them the figure provides a triangle contains these 3 planets -
- Uranus orbital circumference = Earth orbital circumference x 19
In accurate calculations
- Uranus (18048 mkm) = Earth (940 mkm) x 19 (error 1%)
- This data means, while Earth revolves around the sun 19 times, Uranus revolves
around the sun 1 time only
64. IN THE ALMIGHTY GOD NAME
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I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- If the 3 planets move in parallel to each other, that means, Uranus will divide its
revolution trajectory around the sun into 19 parts, and each part will be a qualified
for one Earth orbital circumference (difference 1%)
- Uranus motion trajectory effect is observed on the Earth moon motion trajectory,
let's show how that happens:
- The moon moves through its orbital circumference revolving around the Earth
(while the masses gravity forces imprison the moon inside the range from perigee
(0.363 mkm) to apogee (0.406 mkm) and prevents the moon to move out of this
motion range).
- But
- Uranus motion effects on the Earth moon motion (inside its prison) and forces the
moon to change its motion trajectory through 19 years. Because of that the moon
doesn't move through the same point 2 times during 19 years (6939.75 solar days),
that creates Metonic Cycle, that happens because the moon motion reflects Uranus
Motion Effect revolving around the sun, where Uranus moves on a trajectory
doesn't pass through the same point 2 times during (19 years) (according to the
moon time) similar to that the moon moves through its orbital circumference
doesn't pass through the same point 2 times during 19 sidereal years.
- Shortly
- Metonic Cycle Is Created By Uranus Motion Effect On The Moon Orbital Motion.
65. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
65
6-3 The 4 Planets Motions Interaction (2nd
Proof)
(We use here a discussion from the Point no. 4-5 page 49 of this paper)
Earth motion distance during its day period = the moon displacements total
during its day period = Pluto motion distance during its day period (Error 1%)
6-3-1 The 4 Planets Motions Interaction Analysis
I - Data
(1)
Earth moves during (6939.75 solar days) a distance = 17859.325 mkm
(2)
Pluto moves during (6939.75) x (153.3 hours) a distance = 18000.57 mkm
(3)
The moon displacements total during (6939.75) x (29.53 days) = 18034.278 mkm
(4)
Uranus Orbital Circumference = 18048.449 mkm
Where 153.3 hours = Pluto day period 29.53 days = the moon day period
The moon daily displacement =88000 km
II - Data Analysis
(4) – (1) = 189.124 mkm
(4) – (2) = 47.879 mkm
(4) – (3) = 14.171 mkm
(3) – (1) = 174.953 mkm
(3) – (2) = 33.708 mkm
(2) – (1) = 141.245 mkm
- Sin (17.2) x 47.879 mkm = 14.171 mkm
- Tan (10.96) x 174.953 mkm = 33.708 mkm
- Tan (13.3) x 141.245 mkm = 33.708 mkm (error 1%)
- 0.8 x 174.953 mkm = 141.245 mkm (error 1%)
o 0.8 degrees = Uranus Orbital Inclination.
o 17.2 degrees = Pluto Orbital Inclination
o 13.3 degrees = The angle of (E) in the moon orbital inclination
o 10.96 degrees (Cos 10.96 degrees x 88000 km = 86400 km)
66. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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III –Discussion
- The previous 4 angles are the basics data for their planets, let's try to show that
o 0.8 degrees = Uranus Orbital Inclination
o 122.5 deg (Pluto Axial Tilt) x 0.8 = 97.8 deg (Uranus Axial Tilt)
o Pluto orbital inclination 17.2 degrees = 0.99 x 17.4 deg (The inner planets
orbital inclinations total) … also
o Pluto orbital inclination 17.2 deg x 7.1 = 122.5 deg (Pluto Axial Tilt)
o 13.3 degrees is the angle of point (E) (Earth) in the moon orbital triangle
(Earth Orb. Period 365.25 d = The moon Orb. Period 27.3 d x 13.3)
o The angle 10.96 degrees is used to define the moon orbital apogee radius
(r= 0.406 mkm) because (86400 km x 29.53 days = 2π x0.406 mkm). The
apogee orbit doesn't permits for a daily displacement greater than 86400 km,
where (Cos 10.96 degrees x 88000 km = 86400 km).
There's an interaction occurred here between these 4 planets (Uranus, Pluto, Earth and
its moon), and in this interaction, these 4 basic values are created and based on these 4
values many other data of these planets is created … means, this interaction forms the
geometrical structure of these planets motions …. And if we limited our discussion
for the moon orbit structure, that lead us to conclude that, the moon orbit geometrical
structure is effected by these 4 planets motions interaction as seen in the data.
i.e.
These 4 planets motions interaction effects on the moon orbital motion and causes to
create Metonic Cycle.
That supports the hypothesis (Metonic Cycle is a proof of Uranus motion effect on the
moon motion.)
67. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
67
6-3-2 The Interaction Angle 71.9 Degrees
I- Data
1- The Moon Orbital Circumference at apogee radius = 2550973 km (100%)
2- Earth Daily Motion Distance = 2573483 km (101%)
3- Pluto moves during 153.3 hours =2593836 (102%)
4- The displacements 88000 km total during (29.53 days) = 2598693 km (102%)
5- Uranus motion distance (during 378675 seconds) = 2574990 km (101%)
5-1 = +24017 km
5-2 = +1507 km
5-3 = - 18846 km
5-4 = - 23703 km
4-1 = 42863 km
4-2 = 25210 km
4-3 = 5867 km
3-2 = 20353 km
3-1 = 41853 km
2-1 = 22510 km
II- Data Analysis
(I)
Cos (71.9) x 18846 km = 5867 km
Sin (71.9) x 23703 km = 22510 km And (Cos (71.9) = tan (17.25))
- The angle (71.9 degrees) I call (The Interaction Angle)
- This angle connects 5 basic values which are:
o 17.2 deg (Pluto orbital inclination)
o - 18846 km = the difference (Uranus motion & Pluto motion)
o – 23703 km = the difference (the moon displacements & Uranus motion)
o 22510 km = the difference (the moon orbit & Earth motion)
o 5867 km = the difference (the moon displacements & Pluto motion).
68. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
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- It's a clear interaction between the 4 planets motions, because it's directed data….
This data is not random but directed, because of that the same angle (71.9 degrees)
is used frequently Because It's Found In The Interaction Point.
(II)
2 x 71.9 degrees = 12.195 degrees x 11.8 degrees
Where
12.195 degrees = The moon motion angle (13.177 deg – 0.98562 deg)
11.8 degrees =6.7 degrees (moon axial tilt) + 5.1 deg (moon orbital inclination)
Why does the data use double values (2 x 71.9 deg)??
(III)
122.5 = 71.9 degrees x 1.7
Where
122.5 degrees = Pluto Axial Tilt
1.7 degrees = The moon motion equation constant ((θ1= θ0 + 1.7 degrees)
- Why does the equation use 1.7 degrees for moon motion daily? (this question is
asked in the moon motion equation discussion), the data tells that the angle 71.9
degrees (the interaction angle) has an effect to do that
- So, the constant (1.7 deg) depends on the interaction angle (71.9 deg) and Pluto
Axial Tilt (122.5 deg)…
BUT
- (122.5 deg -71.9 deg) x 2 = 101.2 degrees
- In the distances data Earth motion distance daily (2573483 km) is considered as
(101%), If there's a relationship between this 101% and the value 101 deg, we may
conclude, this value also refers to the using of (2 x 71.9 degrees)! Why?
ALSO
- 71.9 degrees / 101.2 = 0.712 we remember θ1= θ0 + 1.7 degrees where 1.7 deg =
0.98562 deg +0.712 deg, it's another proof that, the constant (1.7 deg) is produced
by the planets interaction (specifically between Pluto and the moon motion).
69. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
69
(IV)
- 14 degrees x 5.1 degrees (the moon orbital inclination) =71.4 degrees
- 71.9 degrees = 71.4 degrees + 0.5 degree (the moon angular diameter)
- And
- 14 degrees = (5.1 degrees (the moon orbital inclination) + 8.9 degrees)
Let's remember 8.9 degrees
o 95.6 deg + 1.1 deg = 96.7 deg
o 96.7 deg + 1.1 deg = 97.8 deg
o 97.8 deg + 1.1 deg = 98.9 deg
o (Please review page no. 36)
Where
o 95.6 deg = 90 deg + 0.5 degrees + 5.1 deg (The Moon orbital inclination)
o 96.7 deg = 90 deg + 6.7 deg (The Moon Axial Tilt)
o 97.8 deg = Uranus Axial Tilt
o 96.7 deg = 90 degrees + 8.9 degrees
o 1.1 deg = the angle of the moon triangle base (EA) & moon equator line.
(V)
- 63.7 degrees = (71.9 deg – 8.9 deg) + (71.9 deg – 8 x 8.9 deg)
- Where
- 63.7 deg = The Sun Declination
- Equation no. (V) tells a very important information, which are:
o (1) The interaction angle (71.9 deg) is used in double Value (2 x 71.9),
because of a geometrical necessity.
o (2) The (8 days) Cycle, we have discovered in Jupiter & Uranus motions, is
used here to define the interaction angle based on which the most of the
moon data is created – i.e. the cycle (8 days) effects on the moon motion
- The cycle (8 days) is discussed with many details in Point No. (7) (Uranus Motion
Analysis).
70. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
70
II- Data Analysis (Continued)
(VI)
Tan (29.53) x 18846 km = 23703 km
o - 18846 km = the difference (Uranus motion & Pluto motion)
o – 23703 km = the difference (the moon displacements & Uranus motion)
- We have found the moon day period (29.53 days), it's created as an angle (29.53
degrees) in this same interaction ….
- The moon orbit regresses 19 degrees per year and causes to change the eclipse
calendar by 19 days by this regression , showing that, 1 degree = 1 day
- By this data we can explain some other important data, let's remember them
Old Data
Tan (12.195 deg) x 708.7 hours (the moon day period) = 153.3 h (Pluto day period)
Tan (13.177 deg) x 655.7 h. (the moon rotation period) = 153.3 h (Pluto day period)
- We have discussed this data with our discussion for the question (Why the moon
day period = 29.53 solar days?) (Point 4-5) (Page no. 42).
- This old data told us, the moon day =29.53 solar days because the moon an Pluto
days are created relative to each other (depends on the angle 12.195), and here we
catch the interaction point on which these 2 days periods are created relative to
each other…
- Where
- 29.53 degrees x 12.195 = 360 degrees.