The Sun Creation Process.pdf

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawdrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Sun Creation Process
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –25th
August 2022
Abstract
Paper hypothesis
From One Light Beam Energy The Solar System Be Created
And
This Light Beam travels with 1.16 million km per second
The hypothesis explanation..
- (1)
- The solar system be created out of one light beam energy –
- The solar planets matters and their distances be created of one energy and this one
energy be provided by one light beam and this light beam travels with velocity
1160000 km/s –
- Shortly
- The physics book accepts that (matter and space be created of energies)
- The hypothesis adds one idea only tells
- (from the same one energy the solar planets matters and their distances be created)
this is the hypothesis main idea –
- Matter and Space creation be done from the same stuff (energy) but by using
different geometrical rules –the idea is similar to the creation of the oil and coal

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both be created from the same source but they have 2 different forms because the
creation process depend on 2 different geometrical rules.
- The matter and space creation process can be summarized by the following data
- (light 1.16 million/s = matter + space + light 300000 km/s)
- The data tells the input energy be a light beam its velocity 1160000 km/s, from this
energy the matter and space be created and the light known velocity 300000 km/s
be created as a side product from the process.
- Briefly
- If we find Matters in the universe – we can't find the light velocity 1160000 km/s
because its energy be consumed in the matter and space creation process and
produced the known light beam velocity 300000 km/s as a side product.
- Based on this vision
- The matter be a geometrical point found on a trajectory of energy or (on a light
beam) – by that – the matter moves by light motion –
- Imagine a rock in a tube form be found in some sea water and the water passes
through this rock tube and pushes the rock itself to move with the water-
- That answers the question (how does planet move?) no sun gravity be used here –
instead – the planet moves by light motion from its energy the planet be created.
- Here we disprove Newton theory of the sun gravity – because
- By one force the planet be created and moving otherwise this planet will be broken
by effect of 2 forces on it – here – the force caused the planet creation is the light
beam energy and the force causes the planet motion is this same light beam
motion- that explains the safe planet motion.
- (2)
- We notice that (1.16/0.3) x 2π =24.3
- The planet moves with the light beam based on different rate of time – by that –
one second of light motion be = one solar day of planet motion – this rule can be
used by all planets –

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- We choose Pluto motion and it depends on this same rate (one second of light
motion be = one solar day of Pluto motion) – here the used light velocity be equal
300000 km/s because the matter creation consumed the energy of the light beam
1160000 km/s already and the rest of energy is the light known 300000 km/sec.
- One more rate of time be happened in the solar system – it's the rate of time
between Mercury and Pluto where
- One Hour Of Mercury Motion Be = One Solar Day Of Pluto Motion –
- This rate of time is created among the planets –
- First we need to discover how the rate of time can effect on planet data,
- Let's suppose one hour of Mercury motion = one solar day of Pluto motion – this
rate of time controls the 2 planets data because – Mercury be similar to a great
river and Pluto be similar to its outlet – by that- the river (Mercury) sends 24 parts
of water but Pluto receives only one part and the rest of water (energy) be still in
the source because the outlet can't receive any more water
- Based on this vision – the amount of water in all passages be only (1/24) because
the outlet can't receive any more water than (1/24)
- That shows how the rate of time controls the amount of sent energy and controls
the data –
- Our situation is a reversed picture - the energy moves from Pluto to Mercury and
by that the energy be accumulated on Mercury – but the energy in all passages still
be 1/24 of Mercury energy because it's the sent energy from Pluto
- Shortly
- One Hour Of Mercury Motion = One Solar Day Of Pluto Motion
- And because of that
- One Hour Of Mercury Motion = One Solar Day Of Any Other Planet Motion

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- (3)
- We should notice that, the rate (1 to 24) is a geometrical rate be produced by
necessity because ((1.16/0.3) x 2π =24.3) by that, the rate (1 to 24) is found as a
geometrical necessity as a result of the interaction between the light beam its
velocity 1.16 million km per second and the known light beam velocity 300000
km/s
- For better explanation – let's ask
- Why are all motions trajectories in circular and elliptical forms?
- Because of the rate (2π) be found in the equation ((1.16/0.3) x 2π =24.3)
- The matter be created from light beam its velocity (1160000 km/s) and the matter
creation process consumed the energy and produced the light beam its velocity
300000 km/s as a result – by that the produced matter be connected with the 2 light
beams velocities – for that reason the rate (2π) effect on the matter motion and
causes matter motions trajectories forms to be in elliptical forms – this feature be
produced as a geometrical necessary result from the matter creation process out of
the light beam energy (its velocity 1160000 km/s)
- Similar to that
- The rate (1 to 24) be created as another geometrical necessary result – because –
one second of light (300000 km/s) be equal one solar day of a planet motion and
one second of light (1160000 km/s) be equal one solar day of another planet
motion – based on that the rate (1 to 24) among the planets be a necessary result
geometrically…
- (4)
- At Saturn point – the energy which be sent from Pluto to Mercury is suffered from
a reflection – means- a reflection be happened for the energy in Saturn- the
reflection be done inside t2he planet matter and by that the reflected light doesn't
travel in opposite direction of the original one but travels on angle 180 degrees

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with the original one – that's happened because the reflection be done inside Saturn
matter body.
- That explains why Saturn orbital distance = Saturn Uranus distance, because the
reflected energy produces equal values
- The reflection of energy causes the rate (24) to be squared (24)2
.
- Means
- 1 hour of Mercury motion be = 24 solar days of Saturn motion
- This rate of time causes a great accumulation of energy and caused to push great
amount of energy toward Mercury
- The energy accumulation be on Mercury and the accumulation be so great by the
rate 1/(24)2
- From this great energy the sun be created
- (5)
- The sun rays isn't created by any nuclear interaction be inside the sun – but the sun
rays be created by the planets motions energies total by using different rate of
time.
- The energies accumulation be produced by the rate (1 to 24) where the planets
motions energies during 24 hours can be used in one hour by Mercury which
shows accumulation of energy.
- But
- Saturn provides the great rate 1 /(24)2
and by that the energy be accumulated in
(24)2
days will be consumed in one solar day by Mercury and can be enough to
produce the sun rays.
- The sun science can be saved spite my theory – because – from the Energy every
thing be created and the science can be saved as a result but the source of energy
should be changed – no nuclear interactions be found here – instead it’s the planets
motions energies total by using different rate of time –a great difference in vision

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be produced by the source of energy change - because – instead the sun energy
found by chance and by no work – we found that the sun energy be found by great
work and effort be done by the planets motions – also – we catch the fact that the
sun be created after all planets creation and motion –this fact simply disproves
Newton theory of the sun gravity decisively because the planets motions be found
before the sun creation.
- But
- The basic result of this new vision about the sun rays energy source is that- the sun
creation depends on the planets motions – where the planets move in cycles that
means the sun existence depends on a cycle – means – There's A Cycle For The
Sun Creation And Death
The hypotheses proof
- The hypothesis be proved by Planet diameter equation (my 4th
equation)
- This equation proves that –
- Planet diameter be created as a function in its rotation period – and the planet
rotation period be created as a function in its velocity -
- The equation works from the Earth to Pluto – the equation forces each planet
diameter to be created as a function in its rotation period – where the planets data
follow the equation perfectly-
- The equation analysis explains why the equation works from the Earth to Pluto
only and answers all other questions. BUT
- What we search for is (The Equation Geometrical Effect) – means- we need to
answer the question – Why do the planets data follow this equation? What does
force each planet data to create its diameter as a function in its rotation period?
- The geometrical real effect is the rate of time between Mercury and Pluto (One
Hour Of Mercury Motion Be = One Solar Day Of Pluto Motion) –

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- The equation depends on this rate of time and causes all planets diameters to be
created as function in their rotation periods.
- The equation proves the hypothesis because
- The equation proves (A Continuum Be Found In The Solar System), means,
- The data be transported from one planet to another – that shows a continuum effect
be found on the solar system –
- Because
- Suppose Earth diameter be created as a function in its rotation period – why this
same feature be found on Mars, Jupiter, Saturn, Uranus, Neptune and Pluto? what
force does pass through these planets and force them to create their diameters as a
function in their rotation periods? To do such effect we need a continuum of data,
- The continuum of data can be similar to groundwater be found under 10 houses –
the houses are separated from one another but all of them suffer from the same one
problem (groundwater) – that explain the meaning of (The Continuum Of Data)
- But, we can't catch any continuum of data by the description tells (the solar planets
are rigid bodies separated from one another and revolve around the sun by the sun
gravity force) this description will never create any continuum of data
- Instead, the description tells
- The solar system is one light beam and the solar planets be geometrical points are
found on this same one light beam and the planets move with this light beam
motion by using different rates of time –
- This description can create a continuum of data – because the light beam works as
a connector between all planets –
- By that
- The rate of time (one hour of Mercury motion be = one solar day of Pluto motion),
this rate of time controls the passed energy from one point to another through the
solar system and the passed energy controls the data, as a result the planet diameter

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equation can effect on each planet to create its diameter as a function in its rotation
period.
- Let's summarize the planet diameter equation basic points in following..
Planet Diameter Equation
- The equation proves that each planet diameter be created as a function in its
rotation period -
- Planet diameter equation analysis can be summarized in 3 questions:
- (1) Can Planet Data Depend On Exaction Equations?
- (2) By What Equation Planet Diameter Can Be Defined?
- (3) How Can Planet Diameter Equation Change The Solar System Vision?
- Let's try to answer these questions in following…
(1st
Question)
Can Planet Data Depend On Exaction Equations?
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane or rocket manufacture – the manufacturer needs exact equations to
define this plane length, width, weight and all specifications, otherwise this plane
can't fly safely.
- The moving planet under the physical laws has to define its diameter, mass, orbital
distance, period, inclination, rotation period, axial tilt …and all data based on
Exact Equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically without
observation which prove this fact decisively.
- Then we have to ask (How Planet Data Be Created In Order?)

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- (2)
- Planet orbital distance be defined before this planet creation - because – the planets
motions leave an empty place for the new planet – by that- each planet orbital
distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves this fact – because – it proves each planet orbital distance
depends on its neighbor planet orbital distance –
- d2
=4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orbital distance
- Example (Venus orbital distance)2
= 4 (Mercury orbital distance) x50.3 million km
(Venus orbital distance=108.2 million km Mercury orbital distance =57.9 million km)
- This equation be tested and discussed in this paper – but its concept is a clear one –
it tells the planets leave an empty space for the new planet – for that reason each
planet orbital distance depends on its neighbor planet orbital distance.
- Logically the new planet can't disturb the current planets positions or motions
trajectories – by that –the orbital distance be defined by the neighbors positions –
- (3)
- The new planet has to revolve around the sun based on its orbital distance which
be defined obligatorily where no data of this planet be taken into consideration in
its orbital distance definition –neither mass nor diameter – instead – the distance
be defined based on the neighbor distance.
- But - Planet diameter should be a function in its orbital distance – otherwise – this
planet will be broken through its motion –
- The function between planet diameter and its orbital distance is the necessary
requirement to cause the planet safe motion – almost – planet mass can't cause this
planet to be broken but it may decrease its velocity or creates orbital inclination –
The planet geometrical motion form depends on Its Diameter – the wrong diameter
can cause this planet to be broken and destroyed.
- One more difficulty be found for the designer

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- If the function contains only 2 variables which are planet diameter and its orbital
distance – in case this planet changes its orbital distance for any reason- this planet
will be broken also –
- As a result
- The designer had to create a function between planet diameter and its orbital
distance but also to make this function contains more variables – by that- if this
planet changes its orbital distance for any reason – the other variables will be
changed but the diameter will be saved -
- As a result
- The designer has created the planet diameter as a function in its rotation period and
the rotation period be a function in its velocity and the velocity be a function in its
orbital distance –by that the function between planet diameter and its orbital
distance be created but contains also 3 variables (at least) which are this planet
rotation period, orbital period and velocity – in case of planet orbital distance
change these 3 variables will be changed as a result but the diameter will be saved.
- My fourth Equation proves this fact - let's see it in following…
(2nd
Question)
By What Equation Planet Diameter Can Be Defined?
- Planet diameter Equation (My 4th
Equation)
- (v1/ v2) = (s/r) =I
- v1 = planet velocity in second
- v2 = another planet velocity in second
- r = Planet Diameter of one planet of the 2
- s = The Planet Rotation Periods Number In Its Orbital Period
- (This value is belonged to the planet whose diameter is "r")
- I = Planet Orbital Inclination (of the planet whose diameter is "r")
(means, 1.8 degrees be produced as the rate 1.8)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet

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- we test, discuss and analyze this equation in this current paper.
- The equation tells each planet diameter be a function in the rate (s) which is (the
number of its rotation periods in its orbital period)
- (for example Earth orbital period =365.25 days but (s) =366.7 rotation periods)
- The planets data follow this equation perfectly and prove that this equation shows
a fact in the solar planets data.
- The Equation works from the Earth to Pluto only – by that – the 3 first planets
(Mercury- Venus and the moon) aren't players in this equation – why??
- Let's try to answer this question ….
- The moon orbital period = the moon rotation period =27.3 days, for that reason the
rate (s) = 1
- As a result the moon motion be used as the base for this equation and because of
that the equation starts its work from the Earth and continues to Pluto.
- The planets data follow the equation as we show in the paper discussion –
- But, we have to ask,
- Can a small planet as the moon be used as the base for this equation?
- Venus and Mercury Motions support the moon motion and the 3 planets motions
create one system based on which the moon orbital period be = the moon rotation
period –
- The paper discussion proves this fact strongly
- Clearly
- No tidal locking causes the moon orbital period be= the moon rotation period –
this idea is wrong totally –
- It's the effect of Venus and Mercury motion on the moon motion by which the
moon orbital period be = the moon rotation period
- The analysis of the 3 planets motions data prove this fact as we will do in this
paper.

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- Shortly
- (The moon orbital period be = the moon rotation period) this fact depends on the 3
planets motions integration (Mercury, Venus and the moon) which make this
equality of periods so strong point to be used as a base for the planet diameter
equation.
- That also explain why the 3 planets have the most long rotations and days periods
in the solar system. We deal with one group of planets do one integrated motion.
(3rd
Question)
How Can Planet Diameter Equation Change The Solar System Vision?
- Why all planets data follow this equation? The first equation concept is more clear
(d2
=4d0 (d-d0) where d=planet orbital distance and d0=its neighbor orbital distance)
- because it tells the current planets positions and motions define the new planet
orbital distance by that each planet orbital distance depends on its neighbor
distance – the 1st
equation shows that the solar system as one building and the
planets be similar to stories in the same one building -but –
- The 4th
equation ((v1/v2) = (s/r) =I) tells something a very new
- It Tells Some Continuum Of Data Be Found In The Solar System
- What does mean " A Continuum"?
- It's as groundwater be found under 10 houses – it's a continuum – all houses suffer
from the same effects and features – it's the same one force moves through all
houses and effect on them –
- This meaning can be seen by the (4th
equation) clearly-because each planet defines
its diameter as a function in its rotation period- here we don't see a point depends
on another point as stories of one house but we see a force passes through all data
and nothing can stop it –
- Means, There's a geometrical effect be created by the moon motion and passes
through all planets to Pluto and forces each planet to define its diameter as a

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function in its rotation period – this is a continuum- it's similar to the blood in a
creature body – it passes through all members does different jobs but nothing can
prevent it –this is the picture be understood by the planet diameter equation (my 4th
equation) – but how to understand it? how to create a continuum in the solar
system?
- While we see the planets (matters) as source of energy and consider the space as a
sea separate the planets from one another (as the sea separate the ships) –the
equation tells a new feature about the solar system – it tells
- From One Energy The Planets Matters And Distances Be Created
- This idea can be acceptable simply-because –the physics book accepts that matter
and space be created of energies – the equation tells one additional idea which is-
from The Same One Energy the planets diameters and their distances be created
that causes the continuum to be created in the solar system
- Shortly
- The solar planets matters and their distances be created of the same one trajectory
of energy – by that – the energy be not blockaded inside the planets matters but the
planets matters be geometrical points on this same one trajectory of energy (or
geometrical points on the same one light beam)
- For a simple description
- From one light beam energy the solar planets matters and their distances be created
– the light create the matter and space from the same stuff (energy) but, by using
different geometrical rules for creation, the matter and space be created in different
forms.
- That causes the continuum in the solar system – my fourth equation is one proof
and also mountains of data prove this fact (it tells, the solar system be created
based on a continuum of data-means- the data be transported through it).
- But
- What's the real geometrical effect based on which my 4th
equation depend?

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- It's A Rate Of Time
- One hour of Mercury motion = 24 hours Of Pluto Motion
- This rate of time be created between Mercury and Pluto - where Mercury, Venus
and the moon motions be integrated to create the moon cycles periods equality as
the equation base - and Pluto be the end terminal of the equation – by that – we
have 2 terminals (the moon and Pluto) But Mercury motion be used behind the
moon motion – and the rate of time be between Mercury and Pluto – and this rate
of time be created and passed through all planets and forces them to create their
diameters as function in their rotation periods –
- But
- Where's this rate of time in the equation?
- It's the rate (v1/v2) –the velocities rate creates the rate of time between the planets
– this idea can be acceptable simply in high velocity motions
- Also we have to ask
- Why can this rate of time force the planets data to follow the equation?
- The rate of time defines the rate of energy
- The river of water sends a great amount of water to the small canal but the canal
received only apart of this water and can't receive all amount -
- The rate of time between Mercury and Pluto is (1: 24)
- By that, Mercury energy will be divided by (24) and Pluto will receive energy =
(1/24) of Mercury energy –
- Now, we have a moving river and its outlet- the outlet can receive only 1/24 of the
total water- for that reason –the water in all passages be = (1/24) of the source
because the outlet controls the available water to be sent.
- That explains why Pluto data be found in all planets motions data analysis because
it's the range of available energy and no greater energy can be sent because the
outlet can't receive more that (1/24)

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Paper objective
- The paper proves its hypotheses
- (1) From One Light Beam Energy The Solar System Be Created and
- (2) This Light Beam travels with 1.16 million km per second
- (3) Planet Diameter Be A Function In Its Rotation Period (my 4th
equation)
- (4) Mercury, Venus And The Moon Motions Be Integrated Into One Motion
(Please scan the figure (ORCID)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Curriculum Vitae https://www.academia.edu/s/b88b0ecb7c
E-mail mrwaheid@gmail.com, mrwaheid1@yahoo.com
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Paper Contents
Subject Page No.
1-Introduction 21
2- Methodology 25
Part No. One
A- Planet Data Depends On Exact Equations 28
A-1 Preface 29
A-2 Planet Orbital Distance Equation (My 1st Equation) 32
A-3 The Solar System Distances And Velocities Maps 36
A-4 Planet Diameter Equation (My 4th Equation) 41
A-5 My Three Rest Equations Tests 50
B- Venus Effect On The Moon Motion 58
B-1 Preface 59
B-2 Moon Orbital Motion Description 61
B-3 Venus Orbital Motion Description 64
B-4 The Proportionality Of The Moon And Venus Orbits Areas 65
B-5 The Cycles Equality 66
B-6 The Moon Orbital Motion More Analysis 67
B-7 The Moon Orbit Area Analysis 70
B-8 Venus Orbit Area Analysis 77
B-9 Venus And The Moon Data Consistency 81
C- Mercury Motion Effect On The Moon Motion 87
C-1 Preface 88
C-2 Mercury Day Period Should Be 4224 Hours – Why? 90
C-3 Mercury And The Moon Motions Interaction 93
C-4 The Moon Motion For Metonic Cycle 99
C-5 The Moon, Venus and Mercury Cycles Periods Analysis 101
D- Jupiter Effect On Venus And The Moon Motions 102
D-1 Preface 103
D-2 Planets Positions Description 108
D-3 Mercury and the Moon Motions for 30 million km 111
D-4 Planet 8 Days Cycle 113
D-5 The Main Idea 118
D-6 Jupiter And The Moon Data Consistency 122
D-7 Venus Be The Solar System Central Point 124
D-8 The outer planets diameters total analysis 126
E- Planet Diameter Equation Analysis 128
E-1 Preface 129
E-2 The Equation Effect Description 134
E-3 The Moon Effect Analysis 135
E-4 The Relative Motion Between The Moon And Pluto 138
E-4-1 Planets Orbital Distances Distribution 139
E-4-2 Jupiter Motion Relative To Pluto Motion 142

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E-4-3 Jupiter And The 3 Planets Interaction 144
E-5 The 3 Inner Planets effect on Pluto motion 146
E-6 The Moon And Pluto Motions Data Consistency 148
E-7 The Outer Planets Diameters Total Effect 151
E-8 The Moon Orbit Geometrical Structure 153
E-9 Why Does The Moon Apogee Orbital Radius =406000 Km? 155
E-10 Saturn Effect Analysis 161
E-11 The Moon And Saturn Motions Data Consistency 163
E-12 Pluto Effect Analysis 168
E-13 Pluto And Neptune Data Consistency 171
E-14 Jupiter And The Moon Data Consistency (More Data) 173
E-15 The Equation Units Analysis 174
E-16 Planet Diameter Analysis 176
E-17 Jupiter and Saturn Equations Analysis 177
E-18 Questions And Answers 179
F- The Sun Creation Process 193
F-1 Preface 194
F-2 The Historical Story 196
F-3- The Energy Reflection In Saturn (The Proves Discussion) 200
F-4 The Rate Of Time (1 Hour = Equal 24 Solar Days) 204
F-5 The Sun Creation Process Details 207
Part No. Two 216
3- One Geometrical Design Be Found Behind The Solar System 217
3-1 Preface 218
3-2 The One Geometrical Design Proves 219
3-3 The One Geometrical Design Reason 226
3-4 The Planet Motion Trajectory Analysis 232
3-5 The One Geometrical Design Discussion 234
3-6 The One Geometrical Design Result 241
4- The Solar System Geometrical Design Analysis 245
4-1 Preface 247
4-2 Newton Theory Of The Sun Gravity Is Wrong 249
4-3 The Solar System Is Created Based On One Geometrical Design 251
4-4 The One Geometrical Design Depends On One Light Beam Energy 252
4-5 The Solar System Be Created Out Of One Light Beam Its Velocity 1.16 Million
Km Per Second.
254
4-6 The Solar System Motion Depends On One Geometrical Design 257
4-7 THE DATA PROVE THE THEORY 259
4-8 The Solar System Geometrical Description 304
4-9 How The Matter Be Produced Periodically? 309
4-10 The Planets Unified General Motion (More Data) 311
4-11 Questions And Answers (Extending Discussion) 321
5- The Moon Orbital Apogee Radius Analysis 336

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5-1 Preface 337
5-2 The Moon Orbital Motion Description (And Equation) 340
5-3 The Moon Orbital Apogee Radius Analysis 356
5-4 Can Uranus Motion Effect On The Moon Motion 362
5-5 The Moon Daily Displacement Analysis 366
5-6 The Moon And Mercury Motions Data Analysis 371
5-7 The Moon And Pluto Motions Data Consistency 374
5-8 Uranus Motion Effect On Pluto Motion 382
5-9 The Moon Orbital Apogee Radius Decreasing Details 385
5-10 The Moon Orbit Description
5-10-1 Preface
5-10-2 The Moon Orbital Triangle Description
5-10-3 The Moon Orbital Triangle Data Analysis
5-10-4 The Moon Orbital Triangle Major Points
389
390
391
401
402
6- Jupiter Motion Effect On Earth And Venus Motions 438
6-1 Preface 439
6-2 Jupiter Motion Effect On Earth And Venus Motions 444
6-3 Jupiter Orbital Circumference Analysis 451
6-4 The Sun Rays Creation 455
6-5 Saturn Velocity Analysis 461
6-6 The Solar System Creation and Motion Theory 481
7- The Solar Planets Motions Use Different Rates Of Time 488
7-1 Preface 489
7-2 The Planets Motions Rates Of Time 491
8- The Solar Planets Rates Of Time Analysis 495
8-1 Preface 496
8-2 Venus Motion Rate of time 497
8-3 Earth Motion Rate of time 499
8-4 Mars Motion Rate of time 501
8-5 Jupiter Motion Rate of time 503
8-6 Saturn Motion Rate of time 505
8-7 Uranus Motion Rate of time 507
8-8 Neptune Motion Rate of time 509
8-9 Pluto Motion Rate of time 511
8-10 The Planets Orbital Distances Test 513
8-11 One Law Controls The Planets Orbital Periods And Distances 518
8-12 The General Discussion 519
9- The Planets Motions Rates Of Time Effect Analysis 522
9-1 Preface 523
9-2 Planets Motions Rates Of Time And Distances Data 524
9-3 The Data Equal Distances 528
9-4 The Data and the planets velocities. 536
9-5 The Data Distances And Rates Of Time Interaction 540
9-6 The Data General Discussion 550

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9-7 Mars, Jupiter and Saturn Motions Analysis 552
9-8 Why Saturn And The Moon Use Equal Rates Of Time? 557
9-9 Why Mercury Use A Double Of Its Orbital Distance? 562
9-10 The Rate (4.61) be used between Pluto and the moon motion 563
10- Mars Migration Theory 567
10-1 Mars Migration Theory 568
10-2 Pluto Migration Theory 571
10-3 Planets Migration Theories Proves 573
10-4 Is There An Absent Planet In The Solar Group? 576
11-The Solar System Distances Be Created In A Network Form 579
11-1 Preface 580
11-2 The Continuum effect Through the Solar System Distances 582
11-3 The Solar System Distances Distribution 587
11-4 The Solar System Distances Dependency On One Another 591
12- The Continuum Effect Proof 593
12-1 The Continuum Effect Proof 594
12-2 Saturn Motion Analysis 600
12-3 Planet Diameter Analysis 626
12-4 Why do the planets revolve around the sun if there's no sun gravity? 628
13- Planet Mass Effect On its Motion 629
13-1 Preface 630
13-2 Planet Mass effect on its Motion 632
13-3 Saturn and Earth Motions Interaction 643
13-4 Planets Velocities Proportionality 652
14- Saturn Motion Analysis 660
14-1 Preface 661
14-2 Saturn Diameter Analysis 662
14-3 Neptune Circumference Analysis 673
14-4 Neptune Day Period Analysis 682
14-5 Mercury Motion effect on Jupiter and Neptune Motions 691
14-6 Earth Motion Distance Daily Analysis 698
14-7 Uranus Day Period Analysis 702
14-8 The Inner Planets Motions Analysis 708
15- The Sun Age Description 716
15-1 Preface 717
15-2 The Sun Circles The Earth 718
15-3The Rate (1.0725) 719
15-4 The Sun Diameter Analysis 722
15-5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days) 725
15-6 The Sun Rays Creation 733
16- Mercury Jupiter Distance Analysis 739
16-1 Mercury Jupiter Distance Analysis (720.7 mkm) 740

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16-2 (Jupiter And Mercury Motions Analysis) 753
16-3 Jupiter Distances Analysis 757
Appendix No.1 The Solar System Equal Distances List 758
References and Biography 760

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1- Introduction
- Why do Mercury, Venus and the moon have the longest rotation periods?
- Let's ask more simple question
- Can Venus Motion Affect On The Moon Motion?
- Yes,
- Venus motion affects on the moon motion and causes the moon orbital period to be
= the moon rotation period =27.3 days
- Means,
- No tidal locking causes the moon orbital period be = the moon rotation period –
this idea is wrong totally – instead it's Venus motion effect on the moon motion
- Let's prove this fact in following…
- (A)
- The moon daily displacement =88000 km and during 29.53 days (the moon day
period) the displacements total be = 2.598 million km = 2π x 413600 km
- The data tells us the moon orbital apogee radius should be 413600 km and also it
tells, because the moon daily displacement (88000 km) is so long, the moon should
revolve around the Earth through this apogee orbit its radius (413600km) only and
can't revolve around the Earth through any more near orbit…
- Not Facts
- The moon orbital apogee radius =406000 km only and the moon revolves around
the Earth through near orbits and can reach to perigee radius (363000 km).
- How Can The Moon Do That?
- (B)
- The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level by that the real displacement (L) through the orbit be less than
(88000 km) because it be (L = 88000 km cos θ), as a result the total displacements
be less than (2.598 million km) and that makes the moon orbital apogee radius to
be decreased from 413600 km to 406000 km.

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- We should pay attention to the angle (θ), because this angle controls the moon
motion features – where- with the angle (θ) increasing the real displacement (L) be
shorter and the moon can revolve around the Earth through more near orbits – but
–with the angle (θ) deceasing the real displacement (L) be longer and that pushes
the moon far from the Earth to more far orbits.
- The moon orbital motion equation depends on this angle (θ) it tells θ1 = θ0 +1.7
- where (θ1) = today angle and (θ0) =yesterday angle and 1.7 degrees be used for
the moon daily motion in the equation
- (C)
- As a result for the moon using of the angle (θ), the moon orbital radiuses be
defined based on Pythagorean rule – because – the moon uses the angle (θ) in its
motion – by that – Each point the moon passes shows this fact – and the radiuses
be defined based on one another by Pythagorean rule – let's prove that
- (363000 km)2
+ (86000 km)2
= (373000 km)2
- (373000 km)2
+ (86000 km)2
= (384000 km)2
- (384000 km)2
+ (86000 km)2
= (392000 km)2
- (392000 km)2
+ (86000 km)2
= (406000 km)2
(error 1%)
- Where
- 363000 km = The Moon Orbital Perigee Radius
- 373000 km = The Total Solar Eclipse Radius
- 384000 km = The Moon Orbital Distance
- The data shows, the moon orbital 4 basic radiuses be defined based on one another
by using Pythagorean rule.
- Now this type of motion is related to Venus motion – where – no other planet uses
this technique in its motion – the following data can prove this idea
- (i)
- (41.4 million km)2
+ (108.2 million km)2
= (115.8 million km)2

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- (ii)
- (iii)
= (680 million km)2
- Where
- 41.4 million km = Venus Earth Distance
- 108.2 million km = Venus Orbital Distance
- 50.3 million km = Venus Mercury Distance
- 119.7 million km = Venus Mars Distance
- 115.8 million km = 2 x 57.9 million km Mercury Orbital Distance
- 670.4 million km = Venus Jupiter Distance
- 680 million km = Venus Orbital Circumference
- I try to show that –Venus distances be defined based on Pythagorean rule as the
moon distances to the Earth – we should discuss why Venus needs to decrease its
distance by using this technique, but in all cases this is the moon motion behavior
and not the Earth – here we see a clear effect of Venus motion on the moon motion
–and we have a real reason to believe that Venus motion affect on the moon
motion to cause the moon orbital period = the moon rotation period = 27.3 days
- More data can help our investigation
- (243/224.7) = (29.53/27.3) =1.0725
- Venus rotation period = 243 days and Venus orbital period =224.7 days
- The moon rotation period = 27.3 days and The moon day period = 29.53 days
- The rate 1.0725 we discuss deeply in this paper where great effects depend on it
- Notice
- 5.1 deg (the moon orbital inclination) =3.4 deg (Venus orbital inclination) +1.7
deg - But
- The moon motion equation tells θ1 = θ0 +1.7 where (θ1) = today angle and (θ0) =
yesterday angle – by that we see an effect of Venus motion on the moon motion

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- Shortly
- Venus and Mercury support the moon motion and the 3 planets motions create one
system based on which the moon orbital period to be = the moon rotation period
=27.3 days.
- Now, based on this same system many other features be created as
- Mercury day period be = 2 Mercury orbital periods = 3 Mercury rotation periods
- Also
- Venus Day Period Be = 2 Mercury Rotation Period
- The Earth Orbital Period Be = 2π x Mercury Rotation Period
- It's one system depends on the 3 planets motions and create all cycles based on one
rule –
- We notice 365.25 days (Earth orbital period) be used here as the moon orbital
period around the sun – we deal with the 3 planets only.
- Let's see the paper contents in following…
- The Paper Contents
- The paper is divided into 2 parts
-
- Paper Part No. One
- This part discusses how the sun be created and analyzes the planet diameter
equation, proves that the moon orbital period be= the moon rotation period by
effect of Venus and Mercury on the moon motion
- Paper Part No. Two
- This part proves that, the solar system be built on one design because the planets
matters and their distances be created from the same one energy

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2- Methodology
- I use the planets data analysis to analyze the solar system data and discovers its
creation and motion facts –
- The method put the planets data in comparison with the theory and tries to know if
there's a consistency between both –
- Let's use an example to explain how this method works
- An Example (Mars Migration Theory)
- The 3 planets (Mercury – Venus – Earth) give the interesting data! why?
- Because, the 3 planets be in order for their diameters, masses and orbital distances.
Can this order be found based on a geometrical rule? let's try to discover
- But
- Mars causes a question, because Mars causes to break this order!
- What hypothesis do we need to explain this interesting data?
- The hypothesis tells (Mars Original Position Was Between Mercury And Venus)
- If this is the original position of Mars the planets order will be
- (Mercury – Mars – Venus – Earth)
- The 4 planets be in order for their diameters, masses and orbital distances
- Can we prove this hypothesis? Yes
- Mars had migrated from its original orbital distance to its current one – and Mars
in its migration motion had collided with Venus and then with Earth and Mars
itself caused to create the Earth Moon!
- Giant-Impact hypothesis tells that, a planet in Mars Size had collided with the
Earth and caused the moon creation.
- Can Mars Itself do that? the theory tells No Hope
- But, Planets data analysis suggested that Mars had migrated from its original
orbital distance to its current one –

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- Let's move with this hypothesis for a while
- Suppose Mars was the second planet after Mercury and had migrated to its current
point (227.9 million km) and Mars had collided with Venus and then with Earth –
can this idea help Giant-impact hypothesis? for example can this idea answers
(Why Does Venus Have No Moon?)
- (a)
- Imagine Mars was the second planet after Mercury (84 mkm) and had migrated to
its current position (227.9 mkm), in its displacement, Mars was pushing by force
and had collided with Venus and pushed all debris with it in its motion direction
- Venus had found no debris around – for that Venus couldn't create its own moon-
- (b)
- Another question asks about (the origin of the lunar magma ocean!) Venus, The
Lunar Magma Ocean is came from Venus, it's a part of Venus found by the
collision between Mars and Venus but Mars had pushed all debris with it in its
motion direction and left Venus without debris
- Earth gravity is greater than Venus' and the debris lost some of their momentum
and by that the Earth could create its own moon where the moon rocks are
consisted of Venus, Earth and Mars debris
- The fact Mars has 2 moons is one more proof for this idea, because Mars with
small mass could attract 2 moons and Venus couldn't.
- The rest debris be attracted by Jupiter and consisted the asteroid belt
- Shortly
- The planets data analysis puts planet data in comparison with the theory explains
its motion to test if the theory be sufficient and to discover the geometrical rules
based on which this data be created.
- Notice
- Mars Migration Theory be discussed and proved in point no. (10) of this paper

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Paper Part No. One
(Pages from 27 to 216)
This paper part analyzes and proves Planet Diameter Equation
and also proves the paper hypothesis tells
(The Moon Orbital Period Be = The Moon Rotation Period By Effect Of Venus
Motion On The Moon Motion)

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A- Planet Data Depends On Exact Equations
A-1 Preface
A-2 Planet Orbital Distance Equation (My 1st
Equation)
A-3 The Solar System Distances And Velocities Maps
A-4 Planet Diameter Equation (My 4th
Equation)
A-5 My Three Rest Equations Tests

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A-1 Preface
- What proves for the concept (Planet Data Be Created Based On Exact Equations)?
- Let's answer in following
- (1)
- I have discovered 5 Equations Prove the concept and enable to conclude the
planets data theoretically without observation –
- But the concept is proved even without my 5 equations
- (2)
can't fly safely.
distance, period, inclination, rotation period, axial tilt …and all data based on
Exact Equations otherwise this planet can't move safely and will be broken by its
motion.
- Simply, the safe motion is a proof that this planet data be created based on exact
equations –
- Let's refer to my 5 equations –all equations be tested in this point – where and the
paper discusses and analyzes the first and fourth equations basically
- My 1st
Equation (Planet Orbital Distance Equation)
- d2
= 4d0 (d-d0)
- d = A Planet Orbital Distance
- d0= Its Direct Previous Neighbor Planet Orbital Distance
- My 2nd
Equation (Planet Velocity Equation)
- (V0
2
/V2
) = 4 (1 – (V2
/ V0
2
)
- V = A Planet Velocity
- V0= Its Neighbor Planet Velocity

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- My 3rd
Equation (Depend On Kepler Law Equation)
- (d1/d2)=(v2/v1)2
- v = Planet Velocity
- My 4th
Equation (Planet Rotation Period Equation)
- (v1/ v2) = (s/r) =I
My 5th
Equation ( Planet Velocity Is A Complementary One)
vt =322 km
v = Planet Velocity
t = another planet velocity be used as a period of time
Example
Mercury (47.4 km/s) moves during 6.8 seconds a distance = 322 km but
Uranus (6.8 km/s) moves during 47.4 seconds a distance = 322 km
- This point discussion be divided into the following points
- A-2 Planet Orbital Distance Equation (My 1st
Equation)
- This equation defines each planet orbital distance depends on its neighbor distance
We test the equation with all planets data and discusses its concept.

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- A-3 The Solar System Distances And Velocities Maps
- This point shows that the solar system has one map for the distances and one map
for the velocities where the phase between the 2 maps be found to cause the
planets diameters to be created as function in their orbital distances.
- A-4 Planet Diameter Equation (My 4th
Equation)
- My fourth equation proves shows that, planet diameter be created as a function in
its rotation period – we test the equation with all planets data and discuss shortly it
concept
- But
- This equation (my fourth equation) be analyzed in details in the point No. (D) -
the equation analysis be put in independent point because of its wide and deep
discussions and arguments.
- A-5 My Three Rest Equations Tests
- In this point we test the rest 3 equations to be used as a reference.

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A-2 Planet Orbital Distance Equation
(My First Equation)
- The equation depends on the planets order, for that , just 2 neighbor planets can be
used in this equation, means if (d is Venus distance, d0 be Mercury distance)
- The equation exceptions are,
- Earth depends on Mercury Not Venus – and Mars depends on Venus Not Earth
And Pluto depends on Uranus Not Neptune
- Note, we don't use the forma (d=2d0) instead we use the forma (d2
= 4d0 (d-d0))
because it uses the distance between the 2 planets and that decreases the errors
- Let's test the equation
(1) Venus Motion
- (108.2)2
= 4 x 57.9 x (50.3)
- d= 108.2 million km = Venus Orbital Distance
- d0= 57.9 million km = Mercury Orbital Distance
- 50.3 million km = The Distance Between Venus And Mercury
- Venus Depends On Mercury
(2) Earth Motion
- (149.6)2
= 4 x 57.9 x (149.6-57.9) (error 2.8%)
- d= 149.6 million km = Earth Orbital Distance
- d0= 57.9 million km = Mercury Orbital Distance
- Earth depends on Mercury and doesn't on Venus
(3) Mars Motion
- (227.9)2
= 4 x 108.2 x (227.9-108.2)
- d= 227.9 million km = Mars Orbital Distance
- d0= 108.2 million km = Venus Orbital Distance
- Mars depends on Venus and doesn't on Earth
)
(
4 0
0
2
d
d
d
d −
=

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(4) Ceres Motion
- (415)2
= 4 x 227.9 x (415-227.9)
- d= 415 million km = Ceres Orbital Distance
- d0= 227.9 million km = Mars Orbital Distance
- Ceres depends on Mars
(5) Jupiter Motion
- (778.6)2
= 4 x 415 x (778.6- 415)
- d= 778.6 million km = Jupiter Orbital Distance
- d0= 415 million km = Ceres Orbital Distance
- Jupiter depends on Ceres
(6) Saturn Motion
- (1433.5)2 = 4 x 778.6 x (1433.5- 778.6)
- d = 1433.5 million km = Saturn Orbital Distance
- d0 = 778.6 million km = Jupiter Orbital Distance
- Saturn depends on Jupiter
(7) Uranus Motion
- (2872.5)2
= 4 x 1433.5 x (2872.5- 1433.5)
- d= 2872.5 million km = Uranus Orbital Distance
- d0 = 1433.5 million km = Saturn Orbital Distance Uranus depends on Saturn
(8) Neptune Motion (error 4%)
- (4495.1)2
= 4 x 2872.5 x (4495.1- 2872.5)
- d= 4495.1 million km = Neptune Orbital Distance
- d0 = 2872.5 million km = Uranus Orbital Distance Neptune depends on Uranus
(9) Pluto Motion
- (5906)2
= 4 x 2872.5 x (5906- 2872.5)
- d= 5906 mkm = Pluto Orbital Distance
- d0 = 4495.1mkm = Neptune Orbital Distance Pluto depends on Uranus
- Notice the error is less 1% for all planets except (Earth 2.8%) and Neptune (4%)

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Discussion
(a)
The Equation tells each planet orbital distance depends on its previous neighbor
planet orbital distance – but – there are 3 exceptions which are –
Earth depends on Mercury not Venus –
Mars depends on Venus not Earth–
Pluto depends on Uranus not Neptune–
(b)
The equation shows – the distance from the sun to Pluto be distributed based on one
geometrical design – means – the distances be created together as one group in one a
network form – the distances be similar to the chess board distances- they are
distributed geometrically and in one network based on one design -
Shortly
No Single Distance be Created independently or individually – We deal with one
network of distances -
Means
By Using Mercury Orbital Distance (57.9 million km) (one data) We Can Conclude
All Planets Orbital Distances (9 Data) By Using Mathematical Calculations Only
(c)
Kepler stated (Planet orbit defines its velocity) – this concept is used in my third
equation (d1/d2) = (v2/v1)2
where d= Planet Orbital Distance and v = Planet Velocity
The concept tells– If we know a planet orbital distance, we can conclude its velocity
by mathematical calculations only
Shortly
By Using my 1st
equation (d2
= 4d0 (d-d0)) and kepler law and the One Data (Mercury
orbital distance = 57.9 million km) we can conclude by mathematical calculations
only All Planets Orbital Distances, Velocities And Periods (27 Data)
That proves the concept (Planet data be created based on exact equations)

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A Comment
The equation gives a complete different vision from the physics book – because it
tells planets data be created based on exact equations.
And also it tells (Planet distance depends on its neighbor distance)
And
Newton wrong theory tells (Planet motion depends on its mass) and by that (Planet
orbital distance depends on the sun and planet masses gravity)
Planets data show that (Planet orbital distance depends on its neighbor distance) and
by that – planets data disproves Newton theory of the sun gravity and his concept of
planet motion depends on its mass – also disproves the gravitation equation.
No initial conditions effect on any planet data –because planet data be created based
on exact equations and mathematical calculations.
That makes my first equation is a very new equation in concept where the physicists
believe that (Planet orbital distance should be defined by the sun gravity mass unless
the initial condition effected on it) – this whole idea is wrong-
The fact is that (Planet orbital distance depends on its neighbor distance) – and this
dependency caused to create the solar system distances in one Network form and as
one group of distances (as chess board distances)
Also my first equation solves the problem of Titius Bode law because it argues that
planet orbital distance depends on its neighbor planet orbital distance and not on the
numbers order.
Notice
Ceres Orbital Distance =414 Million Km And Its Orbital Period 1680 Days (its
velocity 17.9 km/s)

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A-3 The Solar System Distances And Velocities Maps
The Idea Summary
Based on many sources of knowledge we have to consider the solar system as one
machine of gears – or one creature body- or one building – and the planets be similar
to members in this same creature body-
My first equation proves that – the distance between the sun and Pluto be designed as
one piece of distance – and my fourth equation proves that a continuum be found in
the solar system and that causes the data transportation and integration among the
planets.
I want to say-
Mountains of proves show that- the solar system is One Geometrical Design and
can't be considered as separated planets revolving around the sun.
As a result –
I provide 2 maps in this point – one map for the solar system distance which deals
with the distance from the sun to Pluto as one piece of distance and the planets be
distributed in it based on one geometrical design.
Another map for the velocities which consider the planets velocities total as the basic
value which be distributed for the planets based on one geometrical design.
The maps show and prove the data treatment based on the data total and not based on
individuals data – that shows – the integrating motion is a planned job for the solar
planets –
The map of distance depends on Jupiter and Pluto but the map of velocity depends on
Jupiter and Uranus – here Jupiter is used in both maps but while the distance map
reaches to Pluto the velocity map stops at Uranus why??
Because the phase between the 2 maps be used to define the planets diameters as
function in their orbital distances –let's discuss these 2 maps in following…

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FIRST - The Map Of Distance
The distances from the sun to Pluto has 2 features which are
(1st
Feature)
Each Planet Orbital Distance Depends On Its Neighbor Orbital Distance – this feature
depends on my first equation (d2
= 4d0 (d-d0)) we have discussed before
(d= Planet Orbital Distance and d0 = Its Neighbor Planet Orbital Distance)
We have discussed it
(2nd
Feature)
The distances map depends on Jupiter and Pluto as 2 basic points of this map
(Proof)
Data
37100 million km – 4900 million km = 32200 million km
32200 million km x π = 100733 million km
Where
100733 million km = The planets orbital circumferences total
37100 million km = Pluto Orbital Circumference
4900 million km = Jupiter Orbital Circumference
Discussion
The data proves the idea - because
The 3 values (4900 , 37100 and 100733) depend on one another, any 2 values enable
us to conclude the third one theoretically
Means,
If we know Jupiter orbital circumference =4900 million km and The planets orbital
circumferences total = 100733 million km, We can conclude theoretically Pluto
orbital circumference =37100 million km – We do that by using the data and even
without my first equation (d2
= 4d0 (d-d0))
The distances map tells –the map depends on 2 basic points (Jupiter and Pluto)

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More analysis of Data can prove that Mercury point be used as an origin point for
these 2 planets (Jupiter and Pluto) –
Shortly - Mercury be the origin point based on which the 2 points (Jupiter and Pluto)
be created based on them the solar planets orbital circumferences total be created.
Notice
For the distances Map we need to notice that – the distance 4900 million km (Jupiter
orbital circumference) is the central distance in the solar system because
(i)
The inner planets orbital circumferences total be (Mercury 360 mkm + Venus 680
mkm + Earth 940 mkm + Mars 1433 mkm + 1433 mkm) = 4900 million km (1%)
The total = 4900 million km but the distance (1433 mkm) be used 2 times!
(ii)
Jupiter Orbital Circumference (4900 million km)
(iii)
Uranus needs 4900 days to pass a distance = Uranus Orbital Distance
Neptune needs 2 x 4900 days to pass a distance = Neptune Orbital Distance (2%)
Pluto needs 3 x 4900 days to pass a distance = Pluto Orbital Distance (1%)
(iv)
(10747 /9800) = (9800 /9007)
10747 days = Saturn Orbital Period
9007 million km = Saturn Orbital Circumference
9800 = 2 x 4900
The data tells, the value 4900 be used by all planets (in different units)
The distance for Jupiter (and the inner planets) be used as a period of time for Uranus,
Neptune and Pluto–and Saturn uses this value as a distance and as a period of time
Based on that - we conclude the distance 4900 million km is the central one in the
solar system – We should discuss the reason in the paper discussion

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SECOND - The Map Of Velocity
The data shows that one map be found for the planets velocities – this map depends
on Jupiter and Uranus velocities – let's prove that in following –
Proof
Data
(i)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
Where
100733 million km = The Planets Orbital Circumferences Total
197393 days = The Planets Orbital Periods Total
1.16 million km/s = Light Supposed Velocity
0.6 million km/s = 2 x 0.3 million km/s (Light Velocity)
1.1318 million km/day = Jupiter Velocity Per A Solar Day
0.5875 million km/day = Uranus Velocity Per A Solar Day
(ii)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
0.6 million km/s = 2 x 0.3 million km/s (Light Supposed Velocity)
47.4 km/s = Mercury Velocity 24.1 km/s = Mars Velocity
35 km/s = Venus Velocity 17.9 km/s = Ceres Velocity
13.1 km/s = Jupiter Velocity
6.8 km/s = Uranus Velocity
Discussion
the discussion supposes a light beam its velocity 1.16 million km per second be found
Data No. (i) shows the planets orbital circumferences and periods total depend on the
2 planets (Jupiter and Uranus) velocities in comparison with the 2 velocities of light
Notice, The discussion supposes a light beam its velocity 1.16 million km/s be found
– we prove this fact Later

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Data No. (ii) shows that,
The rate of velocities between (Jupiter and Uranus) be used also by (Mars and
Mercury) and by (Venus and Ceres) – But
No any couple can be replaced in place of (Jupiter and Uranus) in Data no. (i) – that
shows, the planets orbital circumferences and periods be related to (Jupiter and
Uranus) velocities and not to any other couple of planets – they are the 2 basic players
in the design structure -
The data proves the idea tells
One Map of velocity be used for all planets velocities and in this map Jupiter and
Uranus are the 2 basic points (or 2 columns)
Notice
Light (300000 km/s) travels during 16330 sec a distance = 4900 million km
Light (1160000 km/s) travels during 4222.6 sec a distance = 4900 million km
Where
4900 million km = Jupiter Orbital Circumference (we have discussed before)
16330 hours = Mars Orbital Period
4222.6 hours = Mercury Day Period
Light motion uses 1 hour of planets cycles periods as one second of light motion
THIRD - Why Did The Designer Use 2 Maps For The Distance And Velocity?
Because the designer uses the phase between the distance map and velocity map to
define the planets diameters total– both Maps depend on Jupiter but the distance map
reaches to Pluto where the velocity map limits to Uranus – the phase between Pluto
and Uranus is found to define the planets diameters total 406000 km
This data will be useful in our analysis for my fourth equation (Planets Diameter
Definition Equation).

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A-4 Planet Diameter Equation (My 4th
Equation) (Test)
Planet Diameter Definition Equation (My Fourth Equation)
v = Planet Velocity
r= Planet Diameter
s= Planet Rotation Periods Number In Its Orbital Period
I= Planet Orbital Inclination (a rate to inclination unit)
v2, s, r and I be belonged to one planet and v1 be belonged to another planet
The planet (v1) be defined by test the minimum error
- Earth Equation uses Neptune velocity
- Mars Equation uses Pluto velocity
- Jupiter Equation uses the Earth moon velocity
- Saturn Equation uses Mars velocity
- Uranus Equation uses Neptune velocity (As Earth)
- Neptune Equation uses Saturn velocity
- Pluto Equation uses the Earth moon velocity (As Jupiter)
Notice / (The Equation Works From The Earth To Pluto Only)
The Equation Test
Earth equation (366.7/12756) = 5.4/ (29.8 x 2π) = 0.029
366.7 = Earth rotation periods number in Earth orbital period
12756 km = Earth diameter
29.8 km/s = Earth velocity
5.4 km/s = Neptune velocity
365.25 days = Earth orbital period (and Earth rotation period =23.9 hours)
I
r
s
v
v
=
=
2
1

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Mars equation (671/6792) = 4.7/ (24.1 x 2) =0.098 (error 1.2%)
671 = Mars rotation periods number in Mars orbital period
6792 km = Mars diameter
24.1 km/s = Mars velocity
4.7 km/s = Pluto velocity
687 days = Mars orbital period (and Mars rotation period =24.6 hours)
Jupiter equation (10500/142984) = 13.1/(27.78 x 2π) = 0.0734 (error 2.2%)
10500 = Jupiter rotation periods number in Jupiter orbital period
142984 km = Jupiter diameter
13.1 km/s = Jupiter velocity
27.78 km/s = The Earth Moon velocity
4331 days = Jupiter orbital period (and Jupiter rotation period =9.9 hours)
Saturn equation (24106 x2) /(120536) = 9.7/ 24.1 =0.4
24106 = Saturn rotation periods number in Saturn orbital period
120536 km = Saturn diameter
9.7 km/s = Saturn velocity
10747 days = Saturn orbital period (and Saturn rotation period =10.7 hours)
(1/0.4) = 2.5 where 2.5 degrees = Saturn Orbital Inclination
Uranus equation (42683 / 51118) = 5.4/6.8 =0.8 (error 5%)
42683 = Uranus rotation periods number in Uranus orbital period
51118 km = Uranus diameter
6.8 km/s = Uranus velocity
30589 days = Uranus orbital period (and Uranus rotation period =17.2 hours)
0.8 degrees = Uranus Orbital Inclination

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Neptune equation (89143 /49528) = 9.7/ 5.4 =1.8
89143 = Neptune rotation periods number in Neptune orbital period
49528 km = Neptune diameter
59800 days = Neptune orbital period (and Neptune rotation period =16.1 hours)
1.8 degrees = Neptune Orbital Inclination
Pluto equation (14178 /2390) = 27.78/ 4.7 =5.9
14178 = Pluto rotation periods number in Pluto orbital period
23908 km = Pluto diameter
27.78 km/s = The Moon velocity
4.7 km/s = Pluto velocity
90560 days = Pluto orbital period (and Pluto rotation period =153.3 hours)

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The Equation Discussion
(1) The Equation Modifications
Many planets cause modifications for the equation – let's refer to them in following
(a)
Mars and Saturn use the number (2) which isn't found in the original equation
(b)
The Earth and Jupiter use the rate (2π) which isn't found in the original equation
(c)
Uranus equation causes a great error = 5%
All errors are around (1%) except Jupiter (2.2%)
(d)
Pluto equation depends on the moon velocity – but – connected with Neptune
Because
(Pluto orbital period / Pluto rotation period) x 2π = (Neptune orbital period / Neptune
rotation period)
(e)
Jupiter and Saturn uses the rate (r/s) in place of the rate (s/r)
(f)
The orbital inclination rate (I) be produced in complex form – just with Saturn,
Uranus and Neptune the produced values refer to the planet orbital inclination clearly,
but with the others the produced values be complex – let's use an example
Example –Mars equation produces the value 0.098 – but
(1/0.098) = 10.2 = 2 x 5.1 (where the moon orbital inclination = 5.1 degrees)
Even if we accept this value – this isn't Mars orbital inclination– why??
7 deg (Mercury orbital inclination) = 5.1 degrees + 1.9 deg (Mars orbital inclination)
(5.1 degrees = The Moon Orbital Inclination)
Means - the definition isn't direct but with some complexity – that may be as result of
the moon motion effect on Mars motion.

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(2) The Equation Objective
The equation creates a function between planet diameter and (s) (its rotation periods
number in its orbital period) – then the rate (s) be a function in this planet velocity and
another equation shows that planet velocity be a function in its orbital distance - this
chain creates a function between planet diameter and orbital distance.
The equation shows that – planet diameter be created in harmony with its motion – as
in some canal water creates a vortex and for some reason the water lost its minerals
and salts around this vortex – with time some rock be created by the minerals and
salts and the rock be in a tube form through which the water moves – here the tube
dimensions be in harmony with this water motion because it be created by this water
motion effect.
(3) How Does The Equation Work?
The equation uses the moon and Pluto as 2 terminals of it – because
The Moon Orbital Period = The Moon Rotation Period =27.3 days, by that for the
moon the rate (s) be = 1
And
Pluto has 14177 rotation period in its orbital period and Pluto needs 14547 days to
pass a distance = 5906 million km = Pluto orbital distance.
By that the moon and Pluto each planet has 2 equal periods in its motion for that
reason the 2 planets motions be used as 2 terminals for the equation.
But
We still need to discover the consistency of these 2 planets motions – because – they
don't create comparable sense of motion – the data should be analyzed to know why
Pluto 14177 rotation periods and 14547 days be used as comparable with the moon
cycles periods (27.3 days) and how this is done? For example we may be forced to
suppose that (Pluto rotation period 153.3 hours be used equal to one solar day 24
hours?) (as a rate of time be used in the planet motion)

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Notice
The moon orbital period = The moon rotation period =27.3 days not for any tidal
locking – this idea is wrong and will be disproved through the discussion…
The moon periods equality be produced by Venus motion effect on the moon motion -
where Venus and Mercury supports the moon motion to cause its orbital period be =
its rotation period to make (s) to be =1
By that the moon motion be used as the equation base
(4) The Equation basic points
The Equation depends on 3 basic points
The moon where (The Moon Rotation Period = The Moon Orbital Period)
Saturn where (Saturn Rotation Velocity = Saturn Orbital Velocity)
Pluto where (Pluto Rotation Distance = Pluto Orbital Distance)
Pluto distances equality should be discussed in details in point No.(E-12)
And we should know why the Equation depends on these 3 planets and creates this
strange feature –
Shortly
We have to ask why this feature is necessary for the equation to be working
(5) Planet Rotation Period Analysis
According to kepler law (planet orbit defines its velocity), planet velocity be defined
by its orbital distance – by that –Planet should use its orbital velocity to define its
rotation period – and the rotation period by that will be a function in this planet
circumference -In this case Earth (29.8 km/s) would rotate around its axis in 22.4 min
only and not in 23.9 h
This is not the fact – Earth rotates around its axis in 23.9 hours –
Then we have to ask
Why doesn't planet use its orbital velocity to define its rotation period? because of
my fourth equation – the equation creates a function between planet diameter and its

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rotation period and this is the reason which prevents planet to use its orbital velocity
to define its rotation period –
Saturn is the only planet uses its orbital velocity to be equal its rotational velocity –
Saturn motion be distinguish among the planets – but it's part of the geometrical effect
of the equation on the planets motions – we should notice that
Saturn (9.7 km/s) moves during its rotation period (10.7 h) a distance = 373644 km
This distance equals approximately Saturn circumference (378675 km) (error 1.3%)
By that Saturn is the only planet uses its orbital velocity to define its rotation period
Jupiter (13.1km/s) also moves during its rotation period (9.9 h) a distance increased
4% than its circumference
Uranus (6.8 km/s) moves in its rotation period (17.2 h) a distance =2.6 its
Circumference
Neptune (5.4 km/s) moves in its rotation period (16.1 h) a distance = 2 its
Circumference
We can see that these distances be found by geometrical design – that tells we have an
effect passes through the planets and causes a geometrical effect through the planets
data
We analyze Saturn motion through the equation analysis in point No. (E-10)
(6) The Equation Geometrical Effect
Let's ask
Why does planets data follow this equation? What's this geometrical effect which be
started from the moon and reaches to Pluto and passes through all planets forces each
planet to create its diameter as a function in its rotation period (or in the rate (s))?

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We have answered this question before
It's a rate of time (One Hour Of Mercury Motion Be =24 Hours Of Pluto Motion)
On this rate of time the equation depends
How can the rate of time effect on planets data?
Because
The rate of time controls the amount of passed energy– here we see another vision for
the solar system
The planets matters and their distances be created from the same one energy and the
energy passes through all planets and causes their motions – by that - the energy isn't
blockade inside the planet body in mass form but the energy be in mass form and in
space form and be as a river water moves from a point to another
The planets matters be similar to geometrical points – as when the water creates a
rock tube of its salts and minerals and the water passes through this tube – the tube
walls be made of the water itself but the tube has a geometrical form distinguish from
the water – and still the tube can't continue in life without the water because it’s the
source of this tube salts and minerals –
As a result, The Solar System Be Similar To One Trajectory Of Energy –
Here, the rate of time be so powerful because it controls the passed amount of energy-
as the child hands can't hold all sweets be given by his mother hand- the rate of time
(1/24) makes Pluto to receive only (1/24) of the energy be sent from Mercury-
But
Because Pluto is the river outlet and no other place to put more energy in it – that
makes the energy which passes from Mercury to Pluto = (1/24) of Mercury energy
Here we get one more result – Pluto Data Controls The Solar System –
Because no other outlet be available for that all planets have to take into consideration
Pluto data because the energy which passes through each planet be defined by the rate
of time between Mercury and Pluto – here we see how the equation works and why all
planets data follow it.

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(7) The Equation Deep Analysis
My fourth Equation be analyzed in details in point No. (D)
I put the equation analysis in independent point because it's a wide analysis – where
many questions be left behind
Above all we need to know why Jupiter and Saturn use the rate (r/s) in place of (s/r)?
we discuss in point No. (E-17)
Also - the rate (s/r) itself be puzzled because
s= planet rotation periods number in its orbital period – for Earth it be 366.7
r= planet diameter –for Earth be 12756 km
how to define the units (s/r)??
because 366.7 be (366.7 Earth rotation periods) but (Earth rotation period =23.9 h)
how to create a consistency between these 2 values (s/r)?
We have to consider 23.9 hours to be equal =1 second
And
12756 km to be used as 12756 seconds
This is the way to create a harmony of the data –but how to use these units?!
How planet diameter be used as a period of time by the rate (1km = 1 second)?
And
How the planet rotation period (23.9 hours) be used as (one second)?!
We answer these questions in the Equation analysis Point NO. (D)
Here to prove the equation analysis will be interesting – I put some using of planets
diameters as periods of time – to show the analysis will provide discoveries …
Data
Jupiter (13.1 km/s) moves in 10921 seconds a distance= 142984 km= Jupiter diameter
Uranus (6.8 km/s) moves in 7510 seconds a distance= 51118 km= Uranus diameter
Pluto (4.7 km/s) moves in 10921 seconds a distance= 51118 km= Uranus diameter
Pluto (4.7 km/s) moves in 51118 seconds a distance= 2 x120536 km= Saturn diameter
Pluto (4.7 km/s) moves in 2 x120536 s a distance= (Jupiter motion distance daily)
(10921 km =the moon circumference and 7510 km =Pluto circumference)

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A-5 My Three Rest Equations Tests
In following I provide my rest 3 equations and their tests with planets data to be used
as reference for our discussion.
Planet Velocity Equation (My 2nd
Equation)
- V = A Planet Velocity
- V0= Its Neighbor Planet Velocity
- The equation depends on the planets order, means, just 2 neighbor planets can be
used in this equation, So if (d is Venus distance, d0 be Mercury distance)
- The equation exceptions are, Earth depends on Mercury Not Venus – and Mars
depends on Venus Not Earth And Pluto depends on Uranus Not Neptune.
- The equation system is very similar to my first equation system (Planet Orbital
Distance Equation)
(1) Venus Velocity
- (V0)2
/ (V)2
= 1.834
- (V)2
/ (V0)2
= 0.5452
- 4 (1- 0.5452) = 1.819
- (V0) = 47.4 km /s = Mercury Velocity
- (V) = 35 km /s = Venus Velocity
- Venus Depends On Mercury (The values 1.834 and 1.819 error 1%)
(2) Earth Velocity
- (V0)2
/ (V)2
= 2.53
- (V)2
/ (V0)2
= 0.39525
- 4 (1- 0.3952) = 2.4189
- (V0) = 47.4 km /s = Mercury Velocity
- (V) = 29.8 km /s = Venus Velocity
- Earth Depends On Mercury (The values 2.418 and 2.53 error 4 %)
)
1
(
4 2
0
2
2
2
0
V
V
V
V
−
=

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(3) Mars Velocity
- (V0)2
/ (V)2
= 2.1091
- (V)2
/ (V0)2
= 0.47413
- 4 (1- 0.47413) = 2.1034
- (V0) = 35 km /s = Venus Velocity
- (V) = 24.1 km /s = Mars Velocity
- Mars Depends On Venus (The values 2.109 and 2.103 No Error)
(4) Ceres Velocity
- (V0)2
/ (V)2
= 1.812
- (V)2
/ (V0)2
= 0.55166
- 4 (1- 0.55166) = 1.793
- (V0) = 24.1 km /s = Mars Velocity
- (V) = 17.9 km /s = Ceres Velocity
- Ceres Depends On Mars (The values 1.81 and 1.79 Error 1%)
(5) Jupiter Velocity
- (V0)2
/ (V)2
= 1.867
- (V)2
/ (V0)2
= 0.53559
- 4 (1- 0.53559) = 1.857
- (V0) = 17.9 km /s = Ceres Velocity
- (V) = 13.1 km /s = Jupiter Velocity
- Jupiter Depends On Ceres (The values 1.867 and 1.857 NO Error)
(6) Saturn Velocity
- (V0)2
/ (V)2
= 1.8238
- (V)2
/ (V0)2
= 0.548278
- 4 (1- 0.548278) = 1.80688
- (V0) = 13.1 km /s = Jupiter Velocity
- (V) = 9.7 km /s = Saturn Velocity
- Saturn Depends On Jupiter (The values 1.82 and 1.806 Error 1%)

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(7) Uranus Velocity
- (V0)2
/ (V)2
= 2.034818
- (V)2
/ (V0)2
= 0.49144
- 4 (1- 0.49144) = 2.0342
- (V0) = 9.7 km /s = Saturn Velocity
- (V) = 6.8 km /s = Uranus Velocity
- Uranus Depends On Saturn (The values 2.034 and 2.0342 NO Error)
(8) Neptune Velocity
- (V0)2
/ (V)2
= 1.5857
- (V)2
/ (V0)2
= 0.63062
- 4 (1- 0.63062) = 1.477
- (V0) = 6.8 km /s = Uranus Velocity
- (V) = 5.4 km /s = Neptune Velocity
- Neptune Depends On Uranus (The values 1.585 and 1.477 Error 7%)
(9) Pluto Velocity
- (V0)2
/ (V)2
= 2.093
- (V)2
/ (V0)2
= 0.4777
- 4 (1- 0.4777) = 2.089
- (V0) = 6.8 km /s = Uranus Velocity
- (V) = 4.7 km /s = Pluto Velocity
- Pluto Depends On Uranus (The values 2.093 and 2.089 NO Error)
- Notice
- The equation errors are (Neptune 7%), and (Earth 4%) but all other planets errors
are less than 1% -
- Ceres Orbital Distance =414 Million Km And Its Orbital Period 1680 Days (its
velocity 17.9 km/s)

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- The Equation Discussion
- My first and second equations depend on planets order –means- Just 2 neighbors
planets can be used in these 2 equations – the 2 equations behave typically and the
errors are similar also
- Shortly
- Each Planet orbital distance (and velocity) depends on its previous neighbor data –
- But
- Earth depends on Mercury Not Venus
- Mars depends on Venus Not Earth
- Pluto depends on Uranus Not Neptune
- All planets calculations errors are around 1% except
- Earth (4%) and Neptune (7%)
- (The great errors be because of the square value –the real error is only 3% and 4%)
- Simply we can conclude that, the planets orbital distances and velocities depend on
their neighbors orbital distances and velocities respectively.
- Notice
- Newton Concept (Planet motion depends on its mass) lost its 2 components,
Neither Planet orbital distance nor its velocity depend on its mass – by that no
proof for Newton concept at all – the idea is an imaginary one.

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My 3rd
Equation (Depends on Kepler Law)
- Kepler Law stated (Planet Orbit Defines Its Velocity), this equation depends on
this concept
- The equation doesn't depend on the planets order – Any 2 planets can be used
- Example No. (1)
- (108.2 mkm /57.9 mkm) = (47.4 /35)2
(error 1.8%)
- Where
- 57.9 million km = Mercury Orbital Distance
- 35 km/s = Venus Velocity
- 47.4 km/s = Mercury Velocity
- Example No. (2)
- (149.6 mkm /57.9 mkm) = (47.4/29.8)2
(error 2%)
- Where
- 149.6 million km = Earth Orbital Distance
- 57.9 million km = Mercury Orbital Distance
- 29.8 km/s = Earth Velocity
- Example No. (3)
- (149.6 mkm /108.2 mkm) = (35/29.8)2
(No error)
- Where
2
1
2
2
1
)
(
v
v
d
d
=

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- The Equation Discussion
- My first and second equations depend on the planets order –but this third equation
doesn't depend on the order
- Means,
- Any 2 Planets can be used in it
- For that I have provided just 3 examples – and all other planets be similar
- The errors be in range (2%)
- Notice
- My second equation is the logical one between the first and this third equation –
let's explain that in details
- My first equation tells that, Planet orbital distance depends on its neighbor planet
orbital distance – by that – the equation depends on the planets order-
- But
- Kepler stated (Planet Orbit Defines Its Velocity)- that means – if we know planet
orbital distance we can conclude its velocity theoretically –based on that my third
equation be created -
- But the third equation doesn't depend on the planets order – any 2 planets can be
used in this equation – how can that be done? If the distances be created based on
one another how this third equation be free from the planets order?
- Because the velocities be distributed based on the rule by which the distances be
distributed – that be clear in my second equation – one rule be used for both data
(distance and velocity) distribution – and as a result – the distribution be similar
and kepler could create its law and the third equation be free from the planets
order.
- Notice
- Planet velocity is so effective player on its data creation and the rate (v1/v2) be so
useful and effective in different using.

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Planet Velocity Is A Complementary One (My 5th
Equation)
v = Planet Velocity
t = another planet velocity be used as a period of time
Example
By that, Planet velocity be used as a period of time for the distance 322 km - Why??
Details Data
(1)
Mercury (47.4 km/s) moves during 6.8 hours a distance = 1160000 km
Uranus (6.8 km/s) moves during 47.4 hours a distance = 1160000 km
(2)
Mars (24.1 km/s) moves during 13.1 hours a distance = 1160000 km
Jupiter (13.1 km/s) moves during 24.1 hours a distance = 1160000 km
(error 2%)
(3)
Earth (29.8 km/s) moves during 2 x 5.4 hours a distance = 1160000 km
Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance = 1160000 km
(4)
Venus (35 km/s) moves during 2 x 4.7 hours a distance = 1160000 km
Pluto (4.7 km/s) moves during 2 x 35 hours a distance = 1160000 km
(error 2%)
Shortly
The distance 1160000 km be used as a reference to create planets velocity based on
one another. (why?)
Notice
Saturn (9.7 km/s) moves during 33.2 hours a distance = 1160000 km
(between 33.2 and Venus velocity 35 km/s the error 5%)
km
t
v 322
=

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The Equation Discussion
Data Analysis
The equation tells
Mercury velocity be complementary with Uranus Velocity
Venus velocity be complementary with Pluto Velocity
Earth velocity be complementary with Neptune Velocity
Mars velocity be complementary with Jupiter Velocity
But
Saturn velocity be complementary with Venus Velocity (with great error 5%)
Why? How Does Each Planet Choose Its Mate?
We notice that
The couple (Earth and Neptune) be used in my (5th
equation) and my (4th
equation)
The same couple be used in both equations –
A Question
Why does Mercury choose Uranus to be its mate? Jupiter choose Mars why?!
The answer
- Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
Why Mercury and Uranus? (as example)
This is a result of the geometrical distribution of the planet velocities –
The point is that the distance (1.16 million km) controls all planets motions –we
should discuss this distance later – because
The data analysis shows that a light beam its velocity be = 1.16 million km per second
be found and effect on the planets motions data – that causes the velocities depend on
this distance as a reference – We need to discuss that Part No. 2 of this paper.

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B- Venus Effect One The Moon Motion
B-1 Preface
B-2 Moon Orbital Motion Description
B-3 Venus Orbital Motion Description
B-4 The Proportionality Of The Moon And Venus Orbits Areas
B-5 The Cycles Equality
B-6 The Moon Orbital Motion More Analysis
B-7 The Moon Orbit Area Analysis
B-8 Venus Orbit Area Analysis
B-9 Venus And The Moon Data Consistency

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B-1 Preface
- In The Points No. (B) and (C) we analyze Venus and Mercury Motions to prove
that Venus and Mercury motion be integrated with the moon motion to create one
system of motion. By that we can consider the three planets as 3 gears in one
machine, and these 3 gears move together One Unified Motion –
- This proof is important because – the planet diameter equation (my 4th
equation)
uses the moon periods equality as the equation base (the moon orbital period = the
moon rotation period=27.3 days)- that makes the moon motion be used as the base
of the equation while the planet diameter equation effects on all planets from the
Earth to Pluto and caused each planet diameter to be created as a function in its
rotation period– here –the moon motion can't be a qualified base for such effective
equation and on the other side we have to ask why the equation works only from
the Earth to Pluto?
- These points force us to explain how the 2 planets (Mercury and Venus) motions
support the moon motion and make its motion a qualified to be used as the
equation base.
- Shortly
- If the 2 planets motions support the moon motion – this support should be seen and
proved in the moon motion data – because it's a fact –
- In these 2 points (No. B and C) I prove the 3 planets move in one integrated
motion – where the 2 planets effect on the moon motion is very clear effect and
proved not only because the three planets have the longest rotation and days
periods in the solar system – or because these periods be created depend on one
another – but because the main behavior of motion is common between the three
planets -
- For example, the moon creates an angle (θ) between its motion direction and its
orbit horizontal level- because the moon displacement daily (88000km) is so long

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one and the moon decreased its length through the orbit (because the real
displacement be= 88000 cos θ) the discussion proves this fact– But- This behavior
of Motion be used by Venus basically and Mercury but not any other planet use
this behavior of motion-
- Means, the moon uses this behavior of motion as a result of Venus Motion effect
on the moon motion
- Many other features of the moon motion be inherited by Venus and Mercury
motions effect on it – the discussions in the points (No. B and C) prove this fact
strongly.
- Later we have to discuss Jupiter Motion effect on Mercury and Venus motions
which causes more effect on the moon motion. by that – Mercury, Venus and
Jupiter on one side be considered another force affects on the moon motion in
comparison to the Earth motion effect on the moon motion.

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B-2 Moon Orbital Motion Description
- Why does the moon orbital apogee radius =406000 km?
- The moon daily displacement =88000 km and during 29.53 days (the moon day
period) the displacements total be = 2.598 million km = 2π x 413600 km
- The data tells us the moon orbital apogee radius should be 413600 km and also it
tells, because the moon daily displacement (88000 km) is so long, the moon should
revolve around the Earth through this apogee orbit its radius (413600 km) only and
can't revolve around the Earth through any more near orbit…
- Not Facts
- The moon orbital apogee radius =406000 km only and the moon revolves around
the Earth through near orbits and can reach to perigee radius (363000 km).
- How Can The Moon Do That?
horizontal level by that the real displacement (L) through the orbit be less than
(88000 km) because it be (L = 88000 km cos θ), as a result the total displacements
be less than (2.598 million km) and that makes the moon orbital apogee radius to
- We should pay attention to the angle (θ), because this angle controls the moon
motion features – where- with the angle (θ) increasing the real displacement (L) be
shorter and the moon can revolve around the Earth through more near orbits – but
–with the angle (θ) deceasing the real displacement (L) be longer and that pushes
the moon far from the Earth to more far orbits.
- The moon orbital motion depends on this angle (θ) it tells θ1 = θ0 +1.7
- where (θ1) = today angle and (θ0) =yesterday angle
- 1.7 degrees be used as the moon daily motion degrees for the equation

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- Now, one more question be raised, why the moon apogee radius be 406000 km?
why not shorter if the moon uses this technique which enable the moon to decrease
its orbital apogee radius as possible? Why specifically the radius 406000 km be
chosen?
- Because 406000 km = The Planets Diameters Total
- This result be produced by my fourth equation which proves a function be found
between planet diameter and its rotation period – where the equation uses the
moon motion as its base – we discuss that in point no. (D)
- Notice
- As a result for the moon using of the angle (θ), the moon orbital radiuses be
defined based on Pythagorean rule – because – the moon uses the angle (θ) in its
motion – by that – Each point the moon passes shows this fact – and the radiuses
be defined based on one another by Pythagorean rule – let's prove that
- (363000 km)2
+ (86000 km)2
= (373000 km)2
- (373000 km)2
+ (86000 km)2
= (384000 km)2
- (384000 km)2
+ (86000 km)2
= (392000 km)2
- (392000 km)2
+ (86000 km)2
= (406000 km)2
(error 1%)
- Where
- 373000 km = The Total Solar Eclipse Radius
- The data shows, the moon orbital 4 basic radiuses be defined based on one another
by using Pythagorean rule.
- This conclusion is so effective in the moon orbital motion explanation because it
shows accurate details in the moon motion – we conclude simply that – this angle
(θ) using is a feature be related to the moon motion – and not a general feature for

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all planets – also this angle (θ) using is a proved behavior by the moon motion data
because without this using the moon apogee radius should be =413600 km and the
moon would be prisoner in this orbit and revolves around the Earth only through
this orbit.
- The point is that, this using of the angle (θ) is the behavior of Venus motion and
the moon uses this same behavior as a result for Venus motion effect on the moon
motion –
- In following let's prove that –Venus motion depends on Pythagorean rule also.

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B-3 Venus Orbital Motion Description
I - Data
(1)
(41.4 million km)2
(2)
(50.3 million km)2
(3)
(670.4 million km)2
= (680 million km)2
Where
41.4 million km = Venus Earth Distance
108.2 million km = Venus Orbital Distance
50.3 million km = Venus Mercury Distance
119.7 million km = Venus Mars Distance
115.8 million km = 2 x 57.9 million km Mercury Orbital Distance
II - Discussion
The data proves that, Venus distances to Mercury, Earth, Mars and Jupiter be defined
based on one another by using Pythagorean rule – we here have identical behavior of
motion be done by 2 planets (Venus and the moon) and we have to consider that a
deep connection must be found between them –
The point is that - we know why the moon uses Pythagorean rule – because the moon
tries to decrease its daily displacement length and tries to revolve around the Earth
through more near orbits that this very far one its radius (413600 km) and also the
moon decreased its apogee from this far one to (406000 km) by using this intelligent
technique – here we have a geometrical reason behind the angle (θ) using by the moon
in its orbital motion – but why Venus uses a similar behavior?
Shortly, why does Venus use Pythagorean rule in its orbital motion and as a result the
rule controls the distances between Venus and the other planets? We should answer
this question in point no. (B-9)

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B-4 The Proportionality Of The Moon And Venus Orbits Areas
I- Data
(1)
The Moon Orbital Area From Perigee (363000 km) To Apogee (406000 km) Be
Equal = 103944 Million km2
This area is calculated for an area between 2 concentric circles small radius =363000
km and great radius =406000 km
(2)
Venus Orbital Area (the distance between the sun and Venus) be = 36780 x 1012
km
(3)
36780 x 1012
km = 103944 million km x 0.354 million km
II-Discussion
The moon perigee radius = 363000 km and is different from 354000 km with (2.5%)
The data tells the moon and Venus orbits areas are in proportionality and the moon
defines its perigee radius (363000km) by an effect of Venus motion - in fact Jupiter
also effects to define the moon perigee radius but we discuss that later.
Notice
Venus effect on the moon motion be seen basically in the moon orbital distance
384000 km –we have to prove that by different data – but the definition of the
distance 354000 km is found in comparison with 384000 km basically based on the
following data
(243/224.7) = (29.53/27.3) =(0.384/0.354) = 1.0725
243 days = Venus Rotation Period 224.7 days = Venus Orbital Period
29.53 days = The Moon Day Period 27.3 days = The Moon Orbital Period
We discuss this data in the next point (B-9)

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B-5 The Cycles Equality
- This feature supposes that-
- The moon orbital period be = the moon rotation period =27.3 days because
- Venus orbital period be = Venus rotation period –
- means
- Venus Cycles Periods Equality Causes The Moon Cycles Periods Equality!
- But
- Venus orbital period (224.7 days) and Venus rotation period (243 days)- these 2
periods aren't equal!
- Let's see the data in following..
- I- Data
- (1)
- (29.53 days /27.3 days) = (243 days /224.7 days) = (0.384 mkm/ 0.353 mkm) = 1.0725
- 29.53 days = The Moon Day Period
- 27.3 days = The Moon Orbital Period
- 243 days = Venus Rotation Period
- 224.7 days = Venus Orbital Period
- II- Discussion
- The periods 224.7 days be rated with 243 days by the rate (1.0725)
- Also
- The period 29.53 days be rated with 27.3 days by the rate 1.0725
- The secret be in the rate (1.0725)
- This is a very great rate in the solar system – it controls 40% of all distances, and
50% of all axial tilts and many other important data – also – this rate controls all
Jupiter distances to other planets –
- We should discuss the moon orbital motion description to discover this rate effect
– let's do that in the next point (B-6) –

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B-6 The Moon Orbital Motion More Analysis
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves
per a solar day 2.573 million km with an angle declines on the horizontal level
0.98562 degrees as typical to Earth motion
- If there's other effects on the moon motion, the moon motion trajectory would to
be a parallel line to Earth Motion Trajectory, But Some effect be on the moon
motion daily distance (2.573 million km) with the rate 1.0725 and causes this
distance to be contracted (2.4 million km)
- The moon difficulties are started here, because the difference between both
distances (0.17 million km) will cause the moon to be separated from Earth motion
inevitably
- We should notice that, these motions are done far from our observation, means, we
see nothing of this motion distance, because the moon moves on the Earth orbital
circumference revolving around the sun, but, even if we can't observe this motion
distance the motion is still fact and proved by its power, because the Earth moves
per a solar day 2.573 mkm and if the moon doesn't move this same distance every
solar day that necessities the moon to be separated from the Earth through their
motions course – based on that- the facts prove this motion regardless our
observation ability for it.
- Now the moon has an additional distance to be passed (0.17 million km) and the
moon has to pass this distance on the same solar day to avoid the separation from
the Earth during their motions.
- Because of that, the moon moves its daily displacement (88000 km) depends on
Earth gravity force (by which we see the moon in the Earth sky), but the different
distance (0.17 million km) to be covered still needs the moon to move one more
displacement (= 88000 km)

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- The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the
moon orbital motion around Earth but the other displacement should be done also
because this total distance (0.17 million km) is required to cover the different
distance and create the total (2.573 million km) which saves the moon and Earth
motions accompanying.
- Now we have 2 basic information about the moon orbital motion
o (1st
information) the moon uses Pythagorean triangle in its orbital motion
o (2nd
information) the moon has to move 2 displacements each =88000 km
and their total distance =0.17 million km which is a required distance
necessary to cover the difference between the moon and Earth motions
distances.
- This explanation helps us to understand why the moon uses Pythagorean triangle
in its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.4 mkm) and Earth motion distance (2.573 mkm), So
the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagorean triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…
- Notice,
- I suppose the effect which caused the rate 1.0725 to be Lorentz Length Contraction
Effect – based on velocity 99% of light velocity (1.0725 = (7.1/100) +1)

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- I want to say
- The rate (1.0725) causes some very complex effect on the moon motion – and by
that the effect of the rate (1.0725) on Venus and on the moon motions data should
be used as a proof for their mutual effect on their motions -
- But
- We can't catch the geometrical rule behind – because the geometrical effect is so
complex
- for example, the moon motion still needs one more displacement (88000 km), how
to solve this question?
- Mercury orbital period =88 days if 1 day = 1000 km this period will be =88000 km
but – Mercury day period = 176 days and this is the required distance 176000 km
- Can this data be found by pure coincidence? If not by what geometrical rule this
data can be arranged beside one another?!
- The moon orbital apogee radius 406000 km = 3475 km (the moon diameter) x
116.75 (where Venus day period =116.75 days)
- I just try to show that – the machine behind the 3 planets motions is so complex
one and needs deep geometrical analysis to see how each planet motion effect on
the other planets data…

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B-7 The Moon Orbit Area Analysis
- (1)
- The moon orbit be designed in proportionality with the planets diameters total -
Let's show that in following…
- (a)
- The moon orbital apogee radius =406000 km = The Solar Planets Diameters Total
- (b)
- The moon orbital perigee radius =363000 km = The Outer Diameters Total (1%)
- (c)
- The distance between the perigee and apogee = 43000 km – through this distance
the moon moves from perigee to apogee but if we remove the moon diameter from
this distance – the empty space will be 39525 km = the inner planets diameters
total = Earth Circumference (40080 km) (error 1%)
- (2)
- The moon orbit is designed in proportionality with the planets diameters because
the moon cycles and motion be used as the base of the Equation by which each
planet diameter be created as a function in its rotation period – (my fourth
equation) that explains why the moon orbital radiuses be in proportionality with
the planes diameters total.
- (4)
- The moon orbit design and its four radiuses definition depends on The Moon
Orbit Area (the four radiuses are, perigee radius, total solar eclipse radius, orbital
distance and apogee radius) (the area =103944 million km2
)
- (5)
- The Moon Orbit Area Depends On Jupiter Motion Data.
- Jupiter orbital period =103944 hours - just if each 1hour = 1 million km, the 2
values will be equal. the data discusses that

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The Moon Orbit Area Analysis
I- Data
(1)
The moon orbit area = 103944 million km2
(2)
103944 million km2
=2.598 million km x 40000 km
(3)
103944 million km2
(4)
103944 million km2
(5)
2 x 103944 million km2
=0.376 million km x 2π x 88000 km
(44000 = π x 14006 but 14177 is different 1.2%)
(6)
103944 million km2
= 0.406 million km x 23.9 x 10747
(notice 10747 =365.25 x 29.4)

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II- Data Analysis
- The figure tries to explain the moon orbit details –let's explain it in following
- The line F refers to the moon orbital perigee radius 363000 km - The most near
point to the Earth which the moon can reach
- The line C refers to an orbital radius =366500 km =363000 km + 3475 km (the
moon diameter) also 366500 km = the outer planets diameters total.
- The line B refers to the moon orbital apogee radius 406000 km - the most far
point from the Earth which the moon can reach
- The line A refers to the (supposed) moon orbital apogee radius 413600 km - the
radius which should be the moon apogee radius.
- The distance d3 =43000 km= the distance between perigee and apogee radius
- The distance d1 =40000 km= it be result when we remove the moon diameter
(3475 km) from the distance 43000 km
- The distance d2 =47000 km= it's the distance between the suppose radius (413600
km) to the radius 366500 km
- The distance d4 =50600 km= it's the distance between the suppose radius (413600
km) to the perigee radius 363000 km

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III- Discussion
Data No. (1)
The moon orbit area = 103944 million km2
This value is calculated as an area between 2 concentric circles – based on the 2
radiuses which are (the perigee radius 363000 km and the apogee radius 406000 km)
The area between the 2 radiuses be =103944 million km2
Data No. (2)
103944 million km2
Where
The moon displacements total in 29.53 days = 2.598 million km –
The data tells the distance 40000 km can't be longer – that tells the radius 413600 km
be decreased to 406000 based on geometrical design and mechanism.
The point is that, the distance between the perigee radius (363000 km) and the apogee
radius (406000 km) =43000 km and the moon diameter =3475 km
By that- the geometrical design aims to put the moon on the perigee line directly-
because the space 43000 km will be very near to 4000 km (error 1%)
Why does the design need to put the moon on the perigee line?
But this fact is proved by one more data – we have discussed it before –
366556 km = 3475 km x (655.7/2π)
Where 655.7 hours = the moon rotation period – this data connects the moon orbit
design with its rotation period – shortly –that tells –if the moon orbital period does
NOT = the moon rotation period – in this case – the moon orbit design will be
changed -
The geometrical rule which explains the data (366556 km = 3475 km x (655.7/2π)) or
(366556 km = 2390 km "Pluto diameter" x (153.3) "Pluto rotation Per. =153.3 h")
this geometrical rule is unknown but it connects the distance with planets diameters
with the moon and Pluto rotation periods – some very important machine be found
behind.

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Data No. (3)
103944 million km2
2.41 million km = the moon orbit circumference at its orbital distance (384000 km)
43000 km = the distance between the moon orbital apogee and perigee radiuses
The data shows the moon orbital distance be defined based on geometrical rules –
here no simple explanation be found for any data - we deal with a geometrical
machine and each piece of data be built on this machine one design.
Data No. (4)
103944 million km2
The distance 2.28 million = the moon orbital circumference at perigee radius (363000 km)
The distance 45590 km x π= 142984 km (Jupiter diameter)
Here we have 2 difficulties –
The data consistency between the moon and Jupiter can't be discussed here to avoid
the confusion of data – we do that in point no. (D-6) –
But
Even when we discuss this data we can catch nothing in our minds – because- the
used geometrical rules are unknown – by that the data can't be used –
For example
(1)
Jupiter orbital period = 103944 hours and the moon orbit area =103944 million km2
We need to suppose that 1 hour = 1 million km
But
The data doesn't stop here – it's more complex because
(2)
Jupiter orbital period = 374198400 seconds = π x (10921 seconds)2
(3)
Jupiter (13.1 km/s) moves in 10921 seconds a distance = 142984 km = Jupiter diameter
(10921 km = the moon circumference) – we discuss this data in point no. (D-6)

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Data No. (5)
2 x 103944 million km2
=0.376 million km x 2π x 88000 km
(44000 = π x 14006 but 14177 is different 1.2%)
Where
0.376 million km = the moon orbital radius at total solar eclipse
88000 km = the moon daily displacement
The data tells – the total solar eclipse radius be defined based on the moon daily
displacement because the moon orbit area be reference for all orbital radiuses –by that
– the total solar eclipse point depends on the moon daily displacement – this idea is a
logical one
Data No. (6)
103944 million km2
= 0.406 million km x 23.9 x 10747
(notice 10747 =365.25 x 29.4)
Where
406000 km =Pluto Motion Distance During A Solar Day
The data tells – Pluto moves in (10747 days) a distance = (1/23.9) of the moon orbit
area –
In this case we consider Pluto motion distance has a breadth = 1 million km because
the moon area is 103944 million km2
Of course this idea is not clear – but – I leave it to kepler to solve because Kepler told
the line between the planet and the sun sweeps equal areas in equal periods of time –
this is kepler second law – I couldn't understand it because planet motion can't
produce an area –planet moves a distance – and from where Kepler found the area?!
Kepler tells us that – the solar system is a machine greater than any planet motion
because it produces results can't be produced by any planet motion – we deal with a
general geometrical design and the planets motions be a part of this design and
because of that equal areas be swept in equal periods.

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Now
We leave the area question– and let's return to the data
Pluto moves in 10747 days a distance = 103944/23.9
Where
Also
The moon displacements total in 10747 days be = 940 million km = the Earth orbital
circumference (error 1%)
the moon orbit area = 103944 million km2
and what's 23.9??
the rate of time because
(one hour of Mercury motion = 23.9 hours of Pluto motion) or (1h = 1 solar day)
What does that mean??
The total energy =103944 million km2
Pluto receives only (1/24) of this energy because of the rate of time
And this energy be seen in Pluto motion during 10747 days which is the period
connects the moon, Saturn and Pluto motions
The data tells some great depth be there – we should return to this data one more time
in deep analysis in point no. (D) (My Fourth Equation Analysis)

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B-8 Venus Orbit Area Analysis
I - Data
- (a)
- 36780 x 1012
- (0.35338 mkm is different from 0.363 mkm with 2.5%)
- Where
- 36780 x 1012
km = Venus Orbit Area
- 103944 million km2
= The Moon Orbit Area
- 0.363 million km2
= The Moon Orbital Perigee Radius
- (b)
- (43000 km /40000 km) = (406000 km /378675 km) =1.0725
- Where
- 43000 km = the distance between the orbital apogee and perigee radiuses
- 40000 km = the space distance without the moon diameter (= 43000 km -3475 km)
= the inner planets diameters total = Earth Circumference
- (c)
- 41.4 million km = 108.2 million km x 0.384 million km
- (d)
- 108.2 million km = 149.6 million km x 0.363 million km x 2
- Where
- 41.4 million km = Venus Earth Distance
- 0.384 million km = The Moon Orbital Distance
- 0.363 million km = The Moon Orbital Perigee Radius

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- (e)
- 149.6 million km = 108.2 million km x 1.392 million km
- Where
- 1.392 million km = The Sun Diameter
- (f)
- (2.598 mkm / 2.28 mkm) = (3.024 mkm /2.598 mkm) (error 2%)
- Where
- 2.598 million km = The moon displacements total in (29.53 days)
- 2.598 million km = The moon orbital circumference at perigee radius (363000 km)
- 3.024 million km = Venus motion distance during a solar day
- This is the basic data of this point of discussion
- (g)
- 2.598 mkm x 243 days = 629 million km
- And
- (629/670.4) = (0.363 /0.384) (error 1%)
- Where
- 629 million km = Jupiter Earth Distance
- 670.4 million km = Jupiter Venus Distance
- 0.384 million km = The Moon Orbital Distance
- 0.363 million km = The Moon Orbital Perigee Radius
- (h)
- (670.4 mkm / 680 mkm) = (408/413.6) = (384000 km/ 378675 km)

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II–Discussion
- Let's see the data no. (f) in following
- (2.598 mkm / 2.28 mkm) = (3.024 mkm /2.598 mkm) (error 2%)
- Where
- 2.598 million km = The moon displacements total in (29.53 days)
- 3.024 million km = Venus motion distance during a solar day
- Let's summarize the idea ….
- Venus and the moon motions use the same behavior of motion – by that – both use
Pythagorean rule in their motion and distances definition –
- The moon uses Pythagorean to decrease its daily displacement to enable it to
revolve around the Earth trough more near orbits – but why does Venus use this
same behavior of motion?
- Venus uses Pythagorean rule to make its daily motion distance (3.024million km)
be equal the moon supposed orbital circumference (2.598 million km =2π x413600
km)
- By that,
- Venus decreased its distance (3.02 million km) to be (2.598 million km)
- We have many important data as a result
- (i)
- During 243 days (Venus oration period) the velocity (2.598 million km/day) passes
a distance =629 million km = Earth Jupiter Distance
- (ii)
- 3.024 million km cos (30.5) = 2.598 million km
- Where
- 171 degrees = 30.5 degrees x 5.6 degrees

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- (iii)
- (100733 million km/ 4900 million km) = (629 million km /30.5 million km)
- (iv)
- 3.024 million km = 2.598 million km x (1.0725)2
(error 1%)
- (v)
- 3.024 million km x tan (27.1) = 1.546 million km
-
- We can't discuss this data here – we have to do that with Jupiter effect analysis on
Venus and the moon motions –
-
- But we can summarize the idea in following…
- Venus uses Pythagorean rule to decrease its motion distance per a solar day from
3.024 million km to be 2.598 million km by that Venus moves in a solar day a
distance = 2.598 million km = the moon displacements total in 29.53 days (the
moon day period and = Pluto motion distance in Pluto rotation period (153.3 h) –
also this distance (2.598 million km) is different from the Earth motion distance
per a solar day with error (1%) only
- We can't examine what's happening perfectly because we don't know the effect of
the equal distances – where – we have 4 planets move equal distances (Pluto – the
moon – Venus –Earth) approximately in their days periods (except Venus) we
don't know what's the result of this distance equality- for that we can't catch the
real geometrical effect on these planets motions
- All what I can say is that
- The geometrical design aimed to cause these 4 planets to move equal distances and
a basic geometrical effect be produced by these planets motions – we should
analyze that later with Jupiter motion effect – but we know now that the design
aimed to make these 4 planets motions distances be equal one another.

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B-9 Venus And The Moon Data Consistency
- I- Data
- (1)
- (243/224.7) = (29.53/27.3) =(0.384/0.354) = 1.0725
- 243 days = Venus Rotation Period 224.7 days = Venus Orbital Period
- 29.53 days = The Moon Day Period 27.3days= The Moon Orbital Period
- (2)
- 5.1 deg (the moon orbital inclination) =3.4 deg (Venus orbital inclination) +1.7 deg
- (3)
- 177.4 deg =5.1 deg x 17.4
- 243 = 5.1 x 2 x 23.6
- (4)
- (4.87/0.073) = (655.7/9.9) = (708.7/10.7)
- (5)
- 680 million km = 38025 km x 17883 km
- And
- 612 million km = 10921 km x 17883 km x π
- (6)
- 100733 million x sin (3.4) = 5906 million km
- (7)
- 680 x 8 = 5440
- 5440 x 0.3 =1632
- 1620 x 3.024 =4900
- (8)
- (30.5/3.024) = (3.024/0.3) = (47.4/4.7) = (6939.7/687) =(720.7/71.5) = (4900/486)
= (670.4/66.5)

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- II- Discussion
- The data tries to show that, Venus and the moon motions data be created based on
one source and as one group of data – data No. (1) shows this fact –
- Data, No. (2)
- 5.1 deg (the moon orbital inclination) =3.4 deg (Venus orbital inclination) +1.7 deg
- We have discussed the moon orbital motion equation – it tells θ1 = θ0 +1.7 deg.
- where (θ1) = today angle and (θ0) =yesterday angle and 1.7 degrees be used for
the moon daily motion. also (3.4 deg = 2 x 1.7 deg.)
- Data no. (3)
- 177.4 deg = 5.1 deg x 17.4
- 243 = 5.1 x 2 x 23.6
- Where
- 177.4 degrees = Venus Axial Tilt
- 5.1 degrees = The Moon Orbital Inclination
- 17.4 degrees = The Inner Planets Orbital Inclinations Total
(Pluto Orbital Inclination =17.2 degrees 1%)
- 23.6 degrees = The Outer Planets Orbital Inclinations Total
(Earth axial tilt =23.4 degrees 1%)
- We have a reason to consider Venus as the basic point in the solar system – this
idea can be more clear in Jupiter motion effect discussion point no. (D-7)
- I put the data here to make be vision for the data but this data should be discussed
with Jupiter motion effect.
- Data no. (4)
- (4.87/0.073) = (655.7/9.9) = (708.7/10.7) =66.2
- where

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- 4.87 x 1024
kg = Venus Mass
- 0.073 x 1024
kg = The Moon Mass
- 655.7 hours = The Moon Rotation Period
- 708.7 hours = The Moon Day Period
- 9.9 hours = Jupiter rotation period
- 10.7 hours = Saturn rotation period
- Data no. (5)
- 680 million km = 38025 km x 17883 km
- And
- 612 million km = 10921 km x 17883 km x π
- Where
- 38025 km = Venus Circumference
- 10921 km = The Moon Circumference
- 612 million km = the distance be equal the moon displacements total in 6939.75
days (Metonic Cycle)
- Notice
- Venus moves during 6939.75 days a distance = (41970 million km /2)
- (41970 million km = 1.13184 million km x 37100 days)
- We need to see the value 17883 km = (142984 km/8), this distance is the central
distance in planet 8 days cycle – we should discuss that with Jupiter effect on the
moon and Venus motions (Point No. D-7)
- Data no. (6)
- 100733 million x sin (3.4) = 5906 million km
- Where
- 100733 million km = The Planets Orbital Circumferences Total

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- 5906 million km = Pluto Orbital Distance
- 3.4 degrees = Venus Orbital Inclining
- This data no. (6) is the central one in the group of data. because it shows Venus
effect on the solar system design.
- The distances 100733 million km and 5906 million km are found based on
geometrical rule because the planets orbital circumferences be created based on
one another and reach to Pluto position –means- the inclination 3.4 degrees is the
central one in the solar system –
- I wish I can show the data depth – because- many rules are unknown by that we
can't catch the fact clearly
- But Venus motion distance (3.024 million km) be contracted (as I claim) to be =
(2.598 million km) = The moon displacements total in 29.53 days = Pluto motion
distance in its day period (153.3 hours)
- There's a geometrical machine behind but we can't see because we can't catch the
geometrical result of the equal distances-
- There are hundreds of data connects Venus with Pluto based on this equality of
distances – let's refer to one of them –
- Venus (35 km/s) moves during 12104 seconds a distance = 421056 km = Pluto
(4.7 km/s) motion distance in 90560 seconds (90560 days = Pluto orbital period)
where 421056 km = Uranus motion distance during its day period
- Also by my fifth equation (Venus 35 x Pluto 4.7 x 2 =322.2) (error 2%)
- The unknown geometrical rules makes the data as puzzles
- Notice
- 3.4 hours =12104 seconds

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- Data no. (7)
- 680 million km x 8 = 5440 million km
- 5440 x 0.3 =1632
- 1620 x 3.024 =4900
- Where
- 5440 million km = 2 x 2723 million km (Earth Uranus Distance)
- 1620 million km =Neptune Uranus Distance
- 3.024 million km = Venus Motion Distance Per A Solar Day
- Data no. (8)
- (30.5/3.024) = (3.024/0.3) = (47.4/4.7) = (6939.7/687) =(720.7/71.5) = (4900/486)
= (670.4/66.5)
- Where
- 3.024 million km = Venus Motion Distance Per Solar Day
- 0.3 million km = Light Motion Distance Per Second
- 4.7 km/s = Pluto Velocity
- 6939.75 days = Metonic Cycle
- 687 days = Mars Orbital Period
- 720 million km = Mercury Jupiter Distance
- 71.5 million km = The moon motion distance in 29.53 days (2.4 x 29.53)
- 4900 million km = Jupiter Orbital Circumference
- 486 = 2x 243 = (243 days = Venus Rotation Period)
- 670.4million km = Jupiter Venus Distance
- 66.5 = (4.87/0.073) =(655.7/9.9) = (708.7/10.7)

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A COMMENT
The consistency between Venus and the moon motions data is greater than the
previous data and more deep than the explanation be provided –
Venus is the real mother of the moon and it's the basic source of its motion and
behavior –
The discussion can't explain the meaning clearly because we need to put Jupiter in the
picture to make it more clear
But the using of Pythagorean rule in motion is a behavior used by the moon and
Venus only and it's a clear proof for the interaction of their motions –
I want to say
Venus and the moon motions be comparable motion because the moon moves with
the Earth – means – if the moon doesn't move with the Earth the moon would to move
with Venus but because the moon moves with the Earth the moon observes Venus
motion and makes its motion comparable to Venus motion
The analysis of Jupiter motion data will show that a great effect of Venus be found on
the moon motion – we do this analysis in the next point (D-7)

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C- Mercury Motion Effect On The Moon Motion
C-1 Preface
C-2 Mercury Day Period Should Be 4224 Hours – Why?
C-3 Mercury And The Moon Motions Interaction
C-4 The Moon Motion For Metonic Cycle
C-5 The Moon, Venus and Mercury Cycles Periods Analysis

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C-1 Preface
In this point we analyze Mercury motion effect on the moon motion –
Let's summarize this point idea in following:
(1)
Mars position was between Mercury and Venus with orbital distance =84 million km,
and Mars had migrated from its original orbital distance to the current one (227.9
million km) – in its motion from (84 million km to 227.9 million km) Mars had
collided with Venus and then with The Earth – from these collisions the moon be
created - and Mars is the planet caused the moon creation- this fact I have proved in
(Mars Migration Theory) (Point no. 10)
This theory answers the question (Why Does Venus Have No Moon?) because Mars
had collided with Venus and it was pushed by force –as a result – Mars had pushed all
debris with it in its motion direction –Venus had found no debris around and couldn't
create its own moon – but the Earth gravity is greater than Venus and the debris lost
some of their momentum – for that the Earth could create its own moon
The full story be told in details in point no. (10)
From this story – I need one data only – let's write it in following…
(2)
Mercury axial tilt was one degree before Mars Migration and after the events of
Migration Mercury axial tilt be (Zero degree)
That's the reason of the interaction between Mercury and the moon motions -
Because Mercury needs to create one degree in place of its axial tilt which be
destroyed –
Mercury depends on the moon motion to use this one degree from the moon data – in
fact – Mercury uses one degree from the moon orbital inclination (5.1 degrees) - the
story be discussed in details in this current point no. (C)

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I want to say Mercury and the moon are 2 gears in one motion – neither Mercury nor
the moon can move without the other planet –because Mercury axial tilt be destroyed
in the planets migration events and by that Mercury lost the (one degree) of its axial
tilt – this event can change Mercury motion finally and Mercury can't return to its
original motion unless it can find another (one degree) to be used in place of its axial
tilt.
This is the fact simply -
The moon also can't move without Mercury because the moon depends on Mercury
in its motion directly as much as the moon depends on the Earth in its motion
The data proves that –
Now, one more interesting data tells that,
Mercury moves during (6939.75 days) a distance = 28244 million km = Neptune
orbital circumference – Mercury is connected with this period (6939.75 days) because
of the migration events – we discussed that in point no. (C) – but we see the moon
moves Metonic Cycle (939.75 days)
Means, Metonic Cycle is a period related to Mercury motion basically but because
Mercury depedns on the moon motion the moon moves with Mercury this cycle
(6939.75 days) (Metonic Cycle)
This data answers old question asked
(Why Does The Moon Move Metonic Cycle If Earth Doesn't Move This Cycle?)
another planet must be the reason – and we catch this planet here it's Mercury.
The data discussion proves this fact clearly – let's start the discussion directly.

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C-2 Mercury Day Period Should Be 4224 Hours – Why?
- (1)
- We know that a rate of time be found between Mercury and Pluto where (One
Hour Of Mercury Motion Be = 24 Hours Of Pluto Motion)
- We discuss how this rate be created in point no. (E)
- The rate of time is important one because it controls the sent energy rate – by that
– we imagine Mercury as a great river sends (24 parts of water) to Pluto –but Pluto
(the river outlet) can't receive more than (1/24) of the water amount – as a result –
the passages between the river and its outlet contains only (1/24) of the total
amount of water.
- Shortly
- Because
- (One Hour Of Mercury Motion Be = 24 Hours Of Pluto Motion)
- (One Hour Of Mercury Motion Be = 24 Hours Of Any Other Planet Motion)
- (notice, later we will prove that Saturn doesn't follow this rule)
- (2)
- Now, the real machine uses a reversed picture – the energy be sent from Pluto to
Mercury –1 hour of Mercury = 24 hour of Pluto – by that -Pluto motion energy for
24 hours will produce one hour of Mercury motion – by that the rate of time aims
to accumulate the energy on Mercury point -
- The planets motions energies be accumulated by using the rate of time on Mercury
position-
- Shortly – the planets motions energies total be transported and accumulated on
Mercury point.
- This is the result produced by the rate of time between Mercury and the planets
motions.
- But – Practically – how to collect the planets motions energies on one point? What
should we do to concentrate the planets motions energies on one point?

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- The Planets Velocities Total Express The Total Energy
- Briefly
- The planets motions energies total depends on these planets velocities total
- For that reason – the 9 planets velocities total 176 km/sec should be seen as one
data of Mercury data
- For that reason Mercury day period should be =176 solar days =4224 hours.
- That answer why Mercury day period should be 176 days
- But in fact Mercury day period =175.94 days =4222.6 hours! Why??
- Notice
- (a)
- The light supposed velocity (1.16 million km per second) travels during 4224
seconds a distance = 4900 million = Jupiter Orbital Circumference
- That shows a good reason to connect Mercury with Jupiter Orbital Circumference
- (b)
- The orbital periods total of (Mercury + Venus + Earth) = Mars orbital period =687
days = 16488 hours (error 1.3%)
- The light known velocity (0.3 million km per second) travels during 16488
seconds a distance = 4900 million = Jupiter Orbital Circumference (error 1%)
- That connects Mars also with Jupiter orbital circumference – we need to discus
this data later in point no. (3)
- (3)
- Mercury Motion Be Under Neptune Effect
- As we have seen, Mercury day period should be 176 days =4224 hours but it's not
the fact – Mercury day period be 4222.6 hours only – the different 5040 seconds
be created by a direct effect of Neptune Motion on Mercury Motion.
- We know that because
- Mercury moves during 6939.75 days (Metonic Cycle) a distance = 28244 million
km = Neptune Orbital Circumference

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- Later we should discuss this data
- But we need here to see how Neptune binds Mercury and prevented its day to be
=176 solar days but be only 175.94 solar days
- The difference has a great effect – because the value 176 refers to (the planets
motions energies total), where Mercury be limited to the value 175.94 which
shows less value than 176 days (less energy than the total)
- The energy works by quantum and by that the small difference prevents the
process.
- The value (5040 seconds) should be used as a proof for Neptune motion effect on
Mercury motion – now this effect be done through the planets migration events
and Mars Migration.
- I try to show that – Mercury be under Neptune effect by different features and the
number 5040 seconds is one proof only
- The number 5040 s shows a complex data – let's refer to it without explanation
o Light supposed velocity (1.16 million km/s) travels during 5040 s a distance
= 5848 million km = Mercury Pluto Distance
o 5040 seconds = 84 minutes
o Mercury in 84 days moves a distance = 344 million km
o Mercury in 344 days moves a distance = 1410 million km
o Mercury in 1410 days moves a distance = 5848 million km (error 1.3%)
- The data is so complex but it connected with Neptune because
- The orbital distance 5906 million km is Pluto Current Orbital Distance but it was
Neptune orbital distance before the collision between Pluto and Neptune by that
we can't catch the mentioned planet by Mercury and light motions
- Also - Neptune orbital period =344 x Mercury orbital period
- This number (344) is produced in the data
- Also, 346.6 days = the nodal year, which makes Mercury and the moon connected
with Neptune.

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C-3 Mercury And The Moon Motions Interaction
- The Moon and Mercury Motions be integrated into one motion be done by the 2
planets – each planet move a part of this one motion and use a part of its result.
- Let's explain why each planet needs the other planet help
- The moon displacement daily is (88000 km) and the moon motion needs a distance
= 2 x 88000 km – by that – the moon needs Mercury to cause its displacement
88000 km to be = 2 x 88000 km.
- Mercury axial tilt was one degree before Mars migration and after it became Zero
degree – Mercury needs the moon – because – Mercury uses one degree of the
moon orbital inclination (5.1 degrees)
- Let's prove that in following…
- (1st
Point, The Moon Motion Depends On Mercury Motion)
- The moon moves per a solar day a typical motion to the Earth motion to avoid the
- If there's NO other effects on the moon motion, the moon motion trajectory would
to be a parallel line to Earth Motion Trajectory, But Some effect be on the moon
motion daily distance (2.573 million km) with the rate 1.0725 and decreased this
distance to be only (2.4 million km)
distances (0.17 million km) will cause the moon to be separated from Earth motion
inevitably

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- Now the moon has an additional distance to be passed (0.17 million km) and the
moon has to pass this distance on the same solar day to avoid the separation from
the Earth during their motions.
distance (0.17 million km) to be covered still needs the moon to move one more
because this total distance (0.17 million km) is required to cover the different
distance and create the total (2.573 million km) which saves the moon and Earth
motions accompanying.
o (1st
o (2nd
and their total distance =0.17 million km which is a required distance
necessary to cover the difference between the moon and Earth motions
distances.
- (2nd
Point, Mercury Motion Depends On The Moon Motion)
- Data
- 5.1 degrees – 4.1 degrees = 1 degrees
- 5.1 degrees = the moon orbital inclination

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- 4.1 degrees =Mercury motion per solar day (=360 degrees /88 days)
- The difference one degree (this is the angle Mercury needs to replace in place of
its axial tilt which was one degree and be destroyed in the Mars Migration events)
- (3rd
Point, How that be happened)
- (i)
- Mercury moves per a solar day 4.1 million km = 0.8 x 5.15 million km
- Means
- Uranus orbital inclination 0.8 degree affect on Mercury motion distance per solar
day and cause this distance to be = 5.15 million km –
- This is the distance the moon needs in 29.53 days – because – the moon
displacements total in 29.53 days =2.598 million = 0.5 x of 5.15 million km – by
that Mercury motion produces the required distance for the moon motion.
- Shortly 0.17 million km x 29.53 days = 5.1 million km
- (i)
- The distance 5.1 million km we see as 5.1 degrees (the moon orbital inclination)
where Mercury moves per solar day 4.1 million km and 4.1 degrees because
Mercury orbital circumference =360 million km – by that Mercury uses the angle
5.1 degrees and its motion angle 4.1 degrees to create the (required one degree)
which be used in place of Mercury axial tilt which be destroyed in the planets
migration events.
- By that – the distance 5.1 million or the moon orbital inclination 5.1 degrees is the
solution for the moon motion and for Mercury motion.
- Notice
- 7 deg (Mercury orbital inclination) = 1.9 deg (Mars orbital inclination) + 5.1 deg
- This data shows that - some system contains these 3 planets orbital inclinations –
we should notice that Mercury is the first inner planet and Mars is the last inner
planet and by that some geometrical machine be found to cause this data

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- (iii)
- Why is Uranus Orbital Inclination Used In This Data?
- It's Uranus effect on Venus data – let's prove it
- 177.4 degrees (Venus axial tilt) +3.4 deg (Venus orbital inclination) =180.8 deg
- Uranus orbital inclination =0.8 degrees and Uranus causes Venus data enjoys a
similar value based on (180 degrees) and that gives Venus a great power in the
solar system.
- Uranus practices more effect on the inner planets through Venus – for example
- 97.8 degrees (Uranus axial tilt) = 90 degrees + 7 degrees + 0.8 degrees
- This data shows that some perpendicularity be found between Uranus and the inner
planets –this perpendicularity be more clear with the moon axial tilt where (97.8
deg = 90 deg +6.7 deg (the moon axial tilt) +1.1 deg)
- (4th
Point, How 1 solar day of Mercury = 29.53 days of the moon)
- We know that, one rate of time be found between Mercury and Pluto which is one
hour of Mercury = 24 hours of Pluto and because Pluto is the river outlet no
greater outlet be found and by that the rate (1 to 24) controls all planets motions –
- Shortly – because
- One Hour Of Mercury Motion = One Solar Day Of Pluto Motion
- One Hour Of Mercury Motion = One Solar Day Of Any Other Planet Motion
- Based on that
- One day of Mercury motion be = 24 days of the moon motion.
- But
- 29.53 days (the moon day period) x 0.8 = 24 days (error 1.5%)
- That means,
- The moon day period (29.53 days) be considered = one day of Mercury motion –
the difference between 29.53 days and 24 days be removed by the rate 0.8 – that
happened also by the effect of (Uranus orbital inclination 0.8 degrees)
- We realize that all data be controlled by one machine be found behind.

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- (5th
Point, Metonic Cycle Motion)
- The point we need to notice is that – Mercury motion be under Neptune control –
as we have explained before
- Now the problem is that –
- Mercury moves during (6939.75 days ) a distance = 28244 million km = Neptune
orbital circumference
- Where
- 6939.75 days = Metonic Cycle Period
- Here we see (for first time) the period 6939.75 days!
- Why for first time?
- Because Mercury is older than the moon and Metonic Cycle is the moon cycle –
that tells the cycle be found (related to Mercury) and was found before the moon
creation
- The moon moves Metonic Cycle (6939.75 days) but Mercury be connected with
Metonic Cycle before the moon creation and because Mercury depends on the
moon orbital inclination to provide the one degree (in place of Mercury axial tilt)
and the moon depends on Mercury to move the other displacement 88000 km by
that the moon find it's an obligation to move Metonic Cycle with Mercury
- Notice
- (406000 km/35) x 0.8 = 28244 million km /3.024 million km.
- Where
- 406000 km = The Moon Orbital Apogee Radius
- 35 km/s = Venus velocity
- 28244 million km = Neptune Orbital Circumference
- 3.024 million km = Venus Motion Distance Per Solar Day

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- Notice
- Mercury motion effect on the moon motion can be seen in more data– because
Mercury moves the other required displacement 88000 km – but
- If 1000 km = 1 solar day, Mercury orbital period 88 days will be =88000 km and
Mercury day period 175.94 days will be = 176000 km = the required distance for
the moon motion.
- means
- Mercury day period = 2 Mercury orbital periods because the moon moves 88000
km daily but the moon needs 176000 km daily
- We see there's a great machine behind – and based on this machine the moon
orbital period be = the moon rotation period =27.3 days (that disproves the tidal
locking idea decisively).
- Also notice
- Mercury and Venus be connected strongly in the moon motion – for example
- The moon orbital apogee radius 406000 km = 3475 km (the moon diameter) x
116.75 (where Venus day period =116.75 days)
- Venus motion effect on the moon motion be studied in details in point no. (B)

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C-4 The Moon Motion For Metonic Cycle
The figure describes the positions of 5 planets around the sun – on one side – Jupiter,
Venus and Mercury – and on the other side – the Earth with its Moon
Venus = the red ball, Mercury = the brown ball, Earth =the green ball
(I)
We need this distribution for the planets for our discussion – because – the idea tells
that - Jupiter motion effects on the moon motion through Venus and Mercury and not
through the Earth by that – the moon be connected with Jupiter by strong connections
far from the Earth – or we can say Jupiter connects the Earth through its moon.
(II)
Here we have 2 forces effect on the moon (before the sun creation) and the 3 planets
(Mercury, Venus and Jupiter) on one side and the Earth of the other side
We can consider these 2 forces effects create the moon orbit regression – and by that
Metonic Cycle Motion Be Created
But we should notice Uranus effect on Metonic Cycle Creation – because
(III)
Uranus orbital distance = 19 Earth orbital distance,
Means, if the 2 planets velocities are equal, while Uranus revolves around the sun one
complete revolution, the Earth would revolve 19 revolutions (19 years) – by that we
discovered Metonic Cycle be created by effect of Uranus motion on the moon motion-
and we discovered that –the 3 planets effect (Mercury – Venus And Jupiter) causes to
make Uranus velocity to be = Earth Velocity. But how??
29.8 km/s (Earth velocity) = 6.8 km/s (Uranus velocity) x 4.4
Where
4.4 degrees = 1.3 deg (Jupiter orbital inclination) + 3.1 deg (Jupiter Axial Tilt)

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It's a direct effect of Jupiter on the motion and we accept that because we accept
Jupiter shows the inner planets effects total on point – we discuss in point no. (D)
Shortly
By the 3 planets effect on the moon – Uranus velocity be = Earth velocity and by that
the moon moves Metonic Cycle under effect of Uranus motion-
That tells we have 2 reasons for the moon to move Metonic Cycle – Mercury motion
integration with the moon and Uranus motion effect on the moon.
Notice (1)
4.4 x 2π = 27.64
Where
4.4 degrees = 1.3 deg (Jupiter Orbital Inclination) +3.1 deg (Jupiter Axial Tilt)
27.3 days = The Moon Orbital Period
Notice (2)
778.6 million km x 0.404 million km x 2 = 629 million km
And 612 million km is different from 629 million km by 3%
Where
0.406 million km = the moon orbital apogee radius (with 0.404 error 0.5%)
778.6 million km = Jupiter Orbital Distance
629 million km = Jupiter Earth Distance
612 million km = The moon displacements total in Metonic Cycle (6939.75 days)
The data tries to show that, a clear connection be found between the moon motion in
Metonic Cycle and Jupiter Earth distance
This is a complex data – let's write it without explanation
Light (300000 km/s) travels during (6939.75 seconds) a distance =2094 million km
Light (300000 km/s) travels during (2094 seconds) a distance =629 million km
2094 million km = Jupiter Uranus Distance

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C-5 The Moon, Venus and Mercury Cycles Periods Analysis
Planet Rotation period Orbital period Day period
Mercury 1 1.5 (2Π/ Π+1) 3
Venus Π+1 2
Earth - 2Π -
The moon 0.465 0.465 0.5
(224.7/58.65) = (687/175.94)
88+ 224.7 +365.25 =677.95
88+ 224.7 +365.25 +29.53 = 707.48
Where
58.65 days = Mercury Rotation Period
175.94 days = Mercury Day Period
29.53 days = The Moon Day Period
224.7 days = Venus Orbtial Period
365.25 days = Earth Orbtial Period
687 days = Mars Orbtial Period (different with 678 days with 1.3%)
The data shows that –based on one system these periods be created and this data
proves the idea tells
The moon orbtial period be = the moon rotation period =27.3 days by effect of Venus
and Mercury motions on the moon motion and not by any tidal locking
It's one system behind all periods.

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D- Jupiter Effect On Venus And The Moon Motions
D-1 Preface
D-2 Planets Positions Description
D-3 Mercury and the Moon Motions for 30 million km
D-4 Planet 8 Days Cycle
D-5 The Main Idea
D-6 Jupiter And The Moon Data Consistency
D-7 Venus Be The Solar System Central Point
D-8 The outer planets diameters total analysis

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D-1 Preface
- Can Jupiter Motion Effect On The Moon Motion?
- This discussion proves an idea tells (Jupiter Motion Effects On The Moon Motion)
- In fact
- Jupiter should be considered another force effects on the moon motion and by that
the moon be under 2 forces effects which are (The Earth And Jupiter)
- Jupiter effect on the moon motion doesn't depend on the mass gravity - there are 3
reasons support this idea let's refer to them in following…
- (1st
Reason)
- My fourth equation claims that a geometrical effect be started from the moon and
reaches to Pluto –and this geometrical effect causes each planet diameter to be a
function in its rotation period – let's remember the equation …
- By What Equation Planet Diameter Can Be Defined?
- My 4th
Equation (Planet Rotation Period Equation)
- (v1/ v2) = (s/r) =I
- The equation tells each planet diameter be a function in its rotation period (or the
rate "s") depends on the moon motion because ("s") for the moon =1 and by that
the moon be used as the equation base
- Then we ask what's this geometrical effect on which the equation depends?

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It's a rate of time
(One Hour Of Mercury Motion = 24 Hours Of Pluto Motion)
Accurately (1 h of Mercury = 23.9 h of Pluto) but I use (24 for simplicity)
How can the rate of time cause this effect?
Because it controls the rate of the sent energy
The great river (Mercury) sends its water (energy) to its outlet Pluto, but Pluto can
receive only (1/24) of the sent water (energy) – and – because Pluto is the river outlet
there's no other place to store the energy in – as a result the used energy be only (1/24)
of Mercury energy (total energy) and by that all planets receive only (1/24) of the
total energy because Pluto (the outlet) controls all passages.
Shortly
The solar system be built based on the rate (1/24) because the energy be divided by
this rate between Mercury and Pluto - and because Pluto is the outlet – Pluto rate of
energy controls all planets.
The rate of time controls the energy and by that effects on all planets and forces them
to create their diameters as function in their rotation periods (or in the rate "s")
We discuss this idea in details in point no. (E-1)
But
How can this rate of time be produced?
Because
(Mercury, Venus and the moon velocities total = 23.9 Pluto velocity)
47.4 +35 +29.8 = 112.2 km/s = 23.9 x 4.7 km/s (Pluto velocity)
(the moon velocity be 29.8 km /s = the Earth velocity because they aren't separated in
their revolutions around the sun)
As a result
The 3 planets velocities total cause to create the rate (1:24) with Pluto velocity

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But
Where can we find this total (112.2 km/s)? On Jupiter
Why? because
The 3 planets define their orbital circumferences to be = their distances to Jupiter
In details
(a)
Mercury moves during its day period a distance = 720.7 million km = Jupiter Mercury
Distance
(b)
Venus moves during its orbital period a distance = 680 million km = Jupiter Venus
Distance (670.4 million km error 1.4%)
(c)
Earth moves during its orbital period a distance = 940 million km = Jupiter Earth
Distance (929 million km error 1 %)
But
929 million km = 149.6 million km +778.6 million km – means – the Earth and
Jupiter should be on 2 different sides from the sun to create this distance 929 million
km –
I found this data as a proof for the 3 planets integrated velocities on Jupiter point
Notice, the rate of time still be between Mercury and Pluto,
It's a complex machine but Jupiter can refer to the 3 planets velocities total.
(2nd
Reason)
The rate of time controls the sent energy, the rate between Mercury and Pluto (1:24)
and it controls the sent energy – but the first point receives the energy is the moon
because it be used as the equation base
As a result – Mercury moves in its day period a distance =720 million – but the
moon receives 30 million km – where – the moon displacements total in 346.6 days =
30.5 million km (346.6 days = the Nodal year)

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The distance 30 million km be passed by Jupiter and all outer planets in cycles also (a
new cycle I have discovered and called planet 8 days cycle)
The data show this fact clearly – now –the distance (energy) be transported from
Mercury to the moon and from the moon to Jupiter and from Jupiter to the rest outer
planets –by that – geometrical interactions be found between Jupiter and the moon
depends on the transportation of energy
(This idea will be so clear in planet 8 days cycle discussion point no.(D-4)
(3rd
Reason)
These geometrical interactions cause Jupiter and the moon motions data be in full
harmony with one another –the analysis of Jupiter orbital circumference (4900 million
km) proves this fact clearly
(1)
Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter
(2)
4900 million km = 449197 km x 10921 km = 1.392 million km x 3475 km
10921 km = The Moon Circumference
449197 km = Jupiter Circumference
1.392 million km = The Sun Diameter
3475 km = The Moon Diameter
(3)
(Earth Orbital Distance / The Sun Diameter) = 109
(The Sun Diameter / The Earth Diameter) = 109
(Earth Moon Distance / The Moon Diameter) = 109
(4)
Jupiter orbital distance =5.2 x Earth orbital distance
(the moon orbital inclination = 5.1 degrees error 2%)

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Shortly
The geometrical effect of my fourth equation create a deep interaction between Jupiter
and the moon motions because both planets are players in the equation for 2 basic
jobs – Jupiter because it creates the velocities total point and the moon because its
motion be used as the equation base.
That tells a great geometrical machine be found behind Jupiter and the moon motions
We should notice that
Venus and Mercury supports the connection between the moon and Jupiter–
The data discussion shows clearly these facts and proves the machine be found
behind.

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D-2 Planets Positions Description
The figure describes the positions of 5 planets around the sun – on one side – Jupiter,
Venus and Mercury – and on the other side – the Earth with its Moon
Venus = the red ball, Mercury = the brown ball, Earth =the green ball
(I)
We need this distribution for the planets for our discussion – because – the idea tells
that - Jupiter motion effects on the moon motion through Venus and Mercury and not
through the Earth by that – the moon be connected with Jupiter by strong connections
far from the Earth – or we can say Jupiter connects the Earth through its moon.
(II)
This distribution of the planets explain important data which is
(a)
Mercury moves during its day period a distance = 720.7 million km = Jupiter Mercury
Distance
(b)
Venus moves during its orbital period a distance = 680 million km = Jupiter Venus
Distance (670.4 million km error 1.4%)
(c)
Earth moves during its orbital period a distance = 940 million km = Jupiter Earth
Distance (929 million km error 1 %)
But
929 million km = 149.6 million km +778.6 million km – means – the Earth and
Jupiter should be on 2 different sides from the sun to create this distance 929 million
km – by that – the planets distribution found a sense in planets data.

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(d)
(257.8 million km /720.7 million km) = (0.406 million km/ 1.1318 million km)
Where
720.7 million km = the distance between Mercury and Jupiter = the distance Mercury
moves in its day period (4222.6 hours)
1.13184 million km = Jupiter Motion Distance Per Solar Day
257.8 million km = The distance between the Earth and Venus while both planets be
on 2 different sides from the sun
0.406 million km = the moon orbital apogee radius = Pluto motion distance per solar
day.
This data is interesting one – because – 720.7 million km is the distance between
Mercury and Jupiter where Mercury passes it in its day period (4222.6 hours) but in
what time Jupiter passes this same distance? (637 days)
The data connects this motion with the distance between Earth and Venus while both
planets be on different sides from the sun.
That shows the figure expresses many of the planets data
(III)
Why Is This Planets Distribution Be A Useful One?
The distribution shows that some strong connection must be found among Mercury,
Venus and the moon – a clear strong connection can be concluded here – that explains
why the 3 planets have the most long rotations and days periods in the solar planets –
there's a connection between these 3 planets which causes their rotations periods to be
so long.
Also,
This distribution can explain the 3 planets connection with Jupiter – the data can help
us to see the depth of this connection
(i)
58.56 days +243 days + 27.3 days = 328.95 days

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The moon sidereal year = 327.6 days (different with less than 1%)
(ii)
4331 days (Jupiter Orbital Period) = 327.6 days x 13.22
13.17 degrees = the moon motion degrees per solar day
It's hard to explain this data –but it shows some connection between it.

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D-3 Mercury and the Moon Motions for 30 million km
I- Data
(1)
Mercury moves during its day period a distance =720.7 million km
But
720.7 million km = 30 million km x 24
(2)
The moon daily displacement = 88000 km and during 346.6 days the displacements
total be = 30.5 million km
Where
346.6 days = The Nodal Year.
II- Discussion
The data tells, the energy (distance 720 million km) be divided by 24 and to 30
million km where the moon moves this 30 million km in its cycle period (346.6 days)
I try to say
This distance (30 million km) be transported from Mercury to the moon based on the
rate (1/24) and then be transported from the moon to Jupiter and from Jupiter to the
other outer planets (the outer planets transport the motion by the rate 80%)
This idea I have concluded because – the distance 30 million km be passed by these
planets in cycles periods – the moon uses 346.6 days to pass this 30 million km and
the outer planets uses a new cycle I have discovered (I call it planet 8 days cycle) –
we study this cycle in the next point (no.D-4)
In this cycle the distance 30 million km be transported from Jupiter to Saturn to
Neptune and transported from Jupiter to Uranus. We will discuss this cycle in details
Now
Mercury moves 720 million km in its day period (4222.6 hours) -
I want to say – there's a reason to cause all planets move (30 million km) in cycles
periods only – there's a geometrical necessity behind.

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I can't put all data together in one page to avoid the concussion- but we keep in mind
that – the distance 30 million km is our discussion target.
Notice
The main idea which explains the data will be provided in the discussion end (point
no. (D-5)
But I can here refer to the concept behind the data in following…
The data shows that (a transportation of data be found in the solar system) and based
on that (a transportation of energy be found in the solar system)
The energy is transported among the planets –
This idea is proved clearly by my fourth equation
Also
Planet 8 days cycle is a clear proof for this fact

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D-4 Planet 8 Days Cycle
Planet 8 days cycle is a cycle I have discovered found between the 4 planets (Jupiter,
Saturn, Uranus and Neptune) where Uranus motion uses Pluto day period (= Pluto
rotation period)
The cycle depends almost on 4% found as a difference between Jupiter motion
distance during its rotation period and Jupiter circumference – the cycle describe the
data behavior without explanation for this behavior reason –
The cycle proves that – the 4planets moves as one machine of gears where their
motions be integrated with one another.
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) (96%) + 17687 km (4%)
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following:
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km

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- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)

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- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider they are
equal distances.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform one different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (=Jupiter Diameter) be defined regularly which can be done only
if we deal with a team motion and NOT Planets independent Motions.
- Why does Uranus depend on Pluto Day Period?(additional question)
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours
- Pluto during its day period (153.3 hours) moves a distance = the Earth moon
displacements total during 29.53 days (the moon day period) = Earth motion
distance during earth day (24 hours) (error 1%) which shows Uranus caused Pluto
day period to be =153.3 hours for a geometrical necessity and reason.
A Conclusion
Planet 8 Days Cycle disproves The Planet Independent Motion Concept,
On The Contrary, The Planets Move As A Team. (A Unified General Motion)

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D-5 The Main Idea
The data proves that,
The energy be transported among the planets – the idea is written in point no. (E-1)
and I write it again here because of its clear vision
(1)
We have to suppose the following concept
(The Planets Matters And Distances Be Created From The Same One Energy)
The concept can be acceptable simply – but it causes great change in the vision –
The physics book accepts that, matter and space be created of energy
The concept gives one addition only which is (From The Same One Energy)
The idea is acceptable because you can create an electric current by solar cell from
sun rays – so the light which you see by eyes be changed into electric current in your
solar cell –the energy still the same one and be used in 2 different forms –
The matter and space can be created from the same energy by using different rules of
creation as the oil and coal be created of the same source but the different creation
methods give different forms for each –
From the same one energy the planets matters and distances be created
This is the concept I try (persistently) to prove
But what change this concept can cause?
From one energy the planets matters and their distances be created – that means – the
energy be transported from one point to answer –
Similar to that
From the same blood the child liver and heart be created – 2 different members of the
same happy child – if the source is one the blood must be transported – that's the point
– the energy must be transported through the solar system
This is the direct result of the concept (from one energy the planets matters and
distances be created)
The transportation - is the word – I have tried to prove since years- because

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The Data Be Transported Among The Planets
Mountains of proves are found and provided for this fact – the data isn't prisoner
inside the rigid body (planet matter) but it transported and moves from a point to
another –my fourth equation (planet diameter equation) is one proof for this fact –but
the planets data ha s thousands of similar proves that the data be transported
The vision tells the rigid body a source of energy and limits every effect on its mass
neglect any type of planets data put us in darkness and prevent any light to come in
Where the fact is that –
The energy is similar to water under the houses causes connection between all houses
and causes to transport the data
(2)
The Solar System Be Built On A Continuum Of Data
This is the conclusion of the concept (from one energy the solar system be created)
The data continuum is a feature found in each piece of the solar system – the eclipse
can be example – where We see the sun disc = the moon disc because
(the sun diameter/ the moon diameter) = (Earth orbital distance/ Earth moon distance)
Why the distances rate = the diameters rate?!
The continuum means, the solar system be similar to chess board all distances be
created based on one geometrical design and all motions be done in comparison with
one another by using mathematical calculations.
The continuum can explain how the planets data follow the equation
But
What's the real geometrical effect on which the equation depends? Again
Why do the planets data follow this equation?
(3)
The geometrical effect is a rate of time where

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Why this rate of time be produced? Because
We have a group of 3 planets on one side and one planet on the other side – Mercury
be the representative of the group and by that the rate be between (Mercury and Pluto)
The rate of time depends on the rate of velocity – and
The rate (v1/v2) in the equation causes to transport the rate of time among the planets
Notice/ the moon velocity here equal Earth velocity because they doesn’t separate one
another in their revolution around the sun
Here we have a direct answer
The real geometrical effect is a rate of time (1h =24h) be created between (Mercury
and Pluto) based on their velocities rate and this rate of time be transported among the
planets (based on the rate v1/v2) and effect on each planet data to cause its diameter
to be a function in its rotation period (or in the rate "s")
(4)
there's no other place to store the energy in – as a result the used energy be only
(1/24) of Mercury energy (total energy) and by that all planets receive only (1/24) of
the total energy because Pluto (the outlet) controls all passages.
Shortly
energy controls all planets – by that the rate be between Mercury and all planets (1 to
24)

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(5)
as a result
Mercury moves in its day period a distance =720 million km but the moon receives
only (1/24) which is 30.5 million km – where the moon displacements total in 346.6
days be =30.5 million km (346.6 days = the nodal year)
The distance Mercury moves is its day period (a cycle) be passed by all planets in
(cycles) also based on the rate (1/24) and for that the outer planets create a cycle to
pass this distance (30 million km) (this cycle I have discovered and called "planet 8
days cycle") we study it in this paper.
Based on that,
We can see the energy be transported in cycles and that explains why the universe
depends on cycles – because the energy be transported in cycles
Also we should notice that – the vision creates one more universe in parallel to the
universe of matter – where the universe of Matter be part of the general universe.

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D-6 Jupiter And The Moon Data Consistency
I- Data
(1)
The Moon Orbital Area =103944 million km2
Jupiter orbital period =103944 hours
(2)
Jupiter orbital period = (374198400 seconds) = π x (10921 seconds)2
(3)
Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter diameter
(4)
4900 million km = 44917 km (Jupiter Circumference) x 10921 km
Where
10921 km = The Moon Circumference
449197 km = Jupiter Circumference
More Data
(a)
(The Sun Diameter / The Moon Diameter) = (Earth Orbital Distance / Earth Moon
Distance)
(b)
(Earth Orbital Distance / The Sun Diameter) = 109
(The Sun Diameter / The Earth Diameter) = 109
(Earth Moon Distance / The Moon Diameter) = 109
(c)
Jupiter orbital circumference = the sun diameter x the moon diameter = Jupiter
circumference x the moon circumference
(d)
Jupiter orbital distance =5.2 x Earth orbital distance

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(the moon orbital inclination = 5.1 degrees error 2%)
(e)
Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter (where 10921 km = The Moon Circumference)
(f)
The sun diameter = Jupiter diameter x π2
(error 1.4%)
II- Discussion
We see "The Sun Disc = The Moon Disc" By A Complex Geometrical Machine
Which creates a proportionality between the diameters and distances –
My fourth equation should player here – but – there are more geometrical interaction
found with it to create this a great machine.
We notice that, Jupiter and the moon data be in full harmony – more analysis be
required for better vision but the data is so strong and clear –
By that we have many reasons to suppose Jupiter (and Venus) should be considered as
a second force effect on the Earth moon motion.

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D-7 Venus Be The Solar System Central Point
I- Data
(1)
2.598 million km x 243 days = 629 million km = 30.5 million km x 20.6
(2)
(100733/4900) = (629/30.5) = 20.6
II- Discussion
Data no. (2)
(100733/4900) = (629/30.5) = 20.6
30.5 million km = the moon displacements total in 346.6 days
We have discussed the distance (30.5 million km) frequently before
Data no. (1)
We have discussed the distance (2.598 million km) which equal the moon
displacements total in (29.53 days)
And
We have discussed that, Venus motion distance daily (3.024 million km) be decreased
by Venus using the type of the moon motion in which the moon creates an angle
between its motion direction and its orbit to decrease its daily displacement - Venus
uses a similar behavior and causes its distance (3.024 million km) to be decreased to
(2.598 million km) to accompany the moon in its motion
During (243 days) (Venus rotation period), the distance 2.598 million km daily
produced 629 million km = Jupiter Earth Distance (directly)

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This data should be used as a proof for Venus role to connect the moon with Jupiter
motion-
What we need to notice is that the rate (20.6)
Because
The moon distance (30.5 million km) is the distance the moon received from Mercury
based on the rate 1/24, where Mercury moves 720 million km in its day period
(4222.6 h) but the moon receives only 30.5 million km based on the rate (1/24) which
be defined between Mercury and Pluto and controls all other planets
The rate (20.6) shows that, the rate (629 million km/ 30.5 million km) be comparable
to (100733 million km /4900 million km)
Where these 2 distances (100733 million km and 4900 million km) are the 2 basic
distances in the solar system as we have discussed before – that shows Venus is the
central point in the solar system
The data be proved also by another one
(100733 million km x sin (3.4 degrees) = 5906 million km = Pluto orbital distance)
(3.4 degrees = Venus orbital inclination)

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D-8 The outer planets diameters total analysis
I –Data
(1)
366556 km = 363000 km +3475 km
(2)
366556 km = 3475 km x (655.7 /2π) = 2390 km x 153.3
(3)
(30.5 million km /0.366556 million km) = (300000 /3600)
(4)
366556 km = 24 x 15330 km
II –Discussion
Data no. (1)
366556 km = 363000 km +3475 km
Where
366556 km = The Outer Planets Diameters Total
363000 km = The Perigee Radius
The data tells, there's a geometrical importance to put the moon on the perigee line,
not clear why! but the data forces us to feel that the correct place for the moon is on
the perigee radius directly –by that the distance between the Earth and the moon be =
the outer planets diameters total!
Data no. (2)
366556 km = 3475 km x (655.7 /2π) = 2390 km x 153.3
where
2390 km = Pluto diameter
655.7 h = The Moon Rotation Period
153.3 h = Pluto Rotation Period

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Data No. (1) told us, the moon correct position should be on the perigee radius – and
Data No. (2) tells that, this is a correct conclusion
Because the moon rotation period will be defined there – also – Pluto rotation period
will be defined based on its diameter rate to the outer planets diameter total!
We can't catch the idea behind
We are similar to a person walks in some street doesn't know where he goes but every
one tells him that (he goes in the right way!)
Data no. (3)
(30.5 million km /0.366556 million km) = (300000 /3600)
The distance 30.5 million km is the distance the moon received from Mercury based
on the rate (1/24) and this distance the moon transported to Jupiter and Jupiter
transported to the other outer planets
This distance may be the secret one because the outer planets diameters total (366556
km) be created in comparison with this distance based on (300000 / 3600)
300000 km = light motion distance in one second
3600 seconds = one hour
A complex geometrical machine be found behind this data –
The light motion is the reason why the value (366556 km) be used to define the
planets rotation periods as rates to their diameters
This data needs more deep analysis
Data no.(4)
366556 km = 24 x 15330 km
15330 km = Mercury Circumference
The data tells, the outer planets diameters total (366556 km) be rated with (15330 km)
(Mercury circumference) based on (1/24) because this is the rate of time between
Mercury and Pluto (and be used between Mercury and all planets)

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E- Planet Diameter Equation Analysis
(My Fourth Equation Analysis)
E-1 Preface
E-2 The Equation Effect Description
E-3 The Moon Effect Analysis
E-4 The Relative Motion Between The Moon And Pluto
E-4-1 Planets Orbital Distances Distribution
E-4-2 Jupiter Motion Relative To Pluto Motion
E-4-3 Jupiter And The 3 Planets Interaction
E-5 The 3 Inner Planets effect on Pluto motion
E-6 The Moon And Pluto Motions Data Consistency
E-7 The Outer Planets Diameters Total Effect
E-8 The Moon Orbit Geometrical Structure
E-9 Why Does The Moon Apogee Orbital Radius =406000 Km?
E-10 Saturn Effect Analysis
E-11 The Moon And Saturn Motions Data Consistency
E-12 Pluto Effect Analysis
E-13 Pluto And Neptune Data Consistency
E-14 Jupiter And The Moon Data Consistency
E-15 The Equation Units Analysis
E-16 Planet Diameter Analysis
E-17 Jupiter and Saturn Equations Analysis

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E-1 Preface
In This Point – We Discuss The Real Geometrical Effect Behind My 4th
Equation
Shortly – here we answer the question
(Why Do Planets Data Follow This Equation?)
Let's remember the equation
v = Planet Velocity
r= Planet Diameter
- (The Equation Works From The Earth To Pluto Only)
The question asks…
(Why Do Planets Data Follow This Equation?)… Let's try to answer in following…
(1)
We have to suppose the following concept
(The Planets Matters And Distances Be Created From The Same One Energy)
The concept can be acceptable simply – but it causes great change in the vision –
I
r
s
v
v
=
=
2
1

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The physics book accepts that, matter and space be created of energy
The concept gives one addition only which is (From The Same One Energy)
The idea is acceptable because you can create an electric current by solar cell from
sun rays – so the light which you see by eyes be changed into electric current in your
solar cell –the energy still the same one and be used in 2 different forms –
The matter and space can be created from the same energy by using different rules of
creation as the oil and coal be created of the same source but the different creation
methods give different forms for each –
From the same one energy the planets matters and distances be created
This is the concept I try (persistently) to prove
But what change this concept can cause?
From one energy the planets matters and their distances be created – that means – the
energy be transported from one point to answer –
Similar to that
From the same blood the child liver and heart be created – 2 different members of the
same happy child – if the source is one the blood must be transported – that's the point
– the energy must be transported through the solar system
This is the direct result of the concept (from one energy the planets matters and
distances be created)
The transportation - is the word – I have tried to prove since years- because
The Data Be Transported Among The Planets
Mountains of proves are found and provided for this fact – the data isn't prisoner
inside the rigid body (planet matter) but it transported and moves from a point to
another –my fourth equation (planet diameter equation) is one proof for this fact –but
the planets data ha s thousands of similar proves that the data be transported
The vision tells the rigid body a source of energy and limits every effect on its mass
neglect any type of planets data put us in darkness and prevent any light to come in
Where the fact is that –

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The energy is similar to water under the houses causes connection between all houses
and causes to transport the data
(2)
The Solar System Be Built On A Continuum Of Data
This is the conclusion of the concept (from one energy the solar system be created)
The data continuum is a feature found in each piece of the solar system – the eclipse
can be example – where We see the sun disc = the moon disc because
(the sun diameter/ the moon diameter) = (Earth orbital distance/ Earth moon distance)
Why the distances rate = the diameters rate?!
The continuum means, the solar system be similar to chess board all distances be
created based on one geometrical design and all motions be done in comparison with
one another by using mathematical calculations.
The continuum can explain how the planets data follow the equation
But
What's the real geometrical effect on which the equation depends? Again
Why do the planets data follow this equation?
(3)
The geometrical effect is a rate of time where
Why this rate of time be produced? Because
We have a group of 3 planets on one side and one planet on the other side – Mercury
be the representative of the group and by that the rate be between (Mercury and Pluto)
The rate of time depends on the rate of velocity – and
The rate (v1/v2) in the equation causes to transport the rate of time among the planets
Notice/ the moon velocity here equal Earth velocity because they doesn’t separate one
another in their revolution around the sun

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Here we have a direct answer
The real geometrical effect is a rate of time (1h =24h) be created between (Mercury
and Pluto) based on their velocities rate and this rate of time be transported among the
planets (based on the rate v1/v2) and effect on each planet data to cause its diameter
to be a function in its rotation period (or in the rate "s")
(4)
there's no other place to store the energy in – as a result the used energy be only
(1/24) of Mercury energy (total energy) and by that all planets receive only (1/24) of
the total energy because Pluto (the outlet) controls all passages.
Shortly
energy controls all planets – by that the rate be between Mercury and all planets (1 to
24)
(5)
as a result
Mercury moves in its day period a distance =720 million km but the moon receives
only (1/24) which is 30.5 million km – where the moon displacements total in 346.6
days be =30.5 million km (346.6 days = the nodal year)
The distance Mercury moves is its day period (a cycle) be passed by all planets in
(cycles) also based on the rate (1/24) and for that the outer planets create a cycle to

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pass this distance (30 million km) (this cycle I have discovered and called "planet 8
days cycle") we study it in this paper.
Based on that,
We can see the energy be transported in cycles and that explains why the universe
depends on cycles – because the energy be transported in cycles
Also we should notice that – the vision creates one more universe in parallel to the
universe of matter – where the universe of Matter be part of the general universe.
In this point we analyze the Equation to see its real geometrical effect as clear as
possible on the planets data.

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E-2 The Equation Effect Description
Let's summarize the idea in following….
The Equation works depending on three basic points which are (the moon – Saturn
and Pluto)
The moon and Pluto are the equation 2 terminals and Saturn be the central point of the
equation
Let's look at each point deeply in following
For The Moon – The Periods Are Equation Because
(The Moon Orbital Period = The Moon Rotation Period)
For Saturn – The Velocities Are Equal – Because
(Saturn Orbital Velocity = Saturn Rotational Velocity)
For Pluto – The Distances Are Equal – Because
(Pluto moves in its rotation period a distance = the moon
displacements total in its day period)
We examine these 3 points in details in this discussion to discover how the equation
work and why these planets show these features.
The Moon Effect Analysis Contains The Points (from No. E-3, to No. E-9)
Saturn Effect Analysis Contains The Points No. (E-10 and E-11)
Pluto Effect Analysis Contains The Points No. (E-12 and E-13)

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E-3 The Moon Effect Analysis
Why does the moon orbital period = the moon rotation period =27.3 days?
"Because Of The Tidal Locking" – A wrong answer!
Because
The moon cycles equality be found to be used as the base for the equation which
defines the planets diameters as we have discussed -
Here we have 2 answers for the same one question – I say my answer is the fact
For that –I have to provide facts prove my claim and disprove the other answer –
Shortly
The moon cycles periods equality depend on Venus and Mercury motions – by that –
the 3 planets motions cycles create one system and depend on one another –
Means - Venus and Mercury cycles be created to support the moon cycles periods
equality -Let's try to prove that in following
I- Data
(1)
1407.6 hours (Mercury Rotation Period) = 153.3 hours x 9.18
2802 hours (Venus Day Period) = 153.3 hours x 9.18 x 2
708.7 hours (The Moon Day Period) = 153.3 hours x (9.18/2)
(153.3 hours = Pluto Rotation Period)
Shortly
Venus day period = 2 Mercury rotation period = 4 the moon day period (error 1%)
Mercury day period = 2 Mercury orbital period = 3 Mercury rotation period
(2)
(90000 /4900) = 2 x 9.18
(3)
(29.53/27.3) = (243 /224.7) =1.0725
(4)
Mercury moves during its rotation period a distance = 243 million km (error 1%)

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II- Discussion
The idea tells – Venus and Mercury motions and cycles support the moon cycles and
cause the moon orbital period = the moon rotation period=27.3 days
Data No. (1)
Data No. (1) tries to prove this idea – the equality of the moon 2 cycles periods should
be compared with Mercury and Venus cycles periods – because – many other equal
and rated periods be used for the 2 planets – it should be many pure coincidence if the
3 planets cycles aren't connected…
The data tells
Venus day period= 2 Mercury rotation period= 4 the moon day period (error 1%)
And
Data no. (3) proves the cycles are connected – let's see it in following
Data no. (3)
(29.53/27.3) = (243 /224.7) =1.0725
Where
29.53 days = The Moon Day Period 27.3 days = The Moon Rotation Period
224.7 days =Venus Portal Period 243 days = Venus Rotation Period
The rate 1.0725 we have discussed before because of its using in the solar system
The data tells the cycles are connected
means, the equality and rates in the 3 planets cycles be mentioned for geometrical
necessity – that tells there's a geometrical reason caused Mercury day period to be = 2
Mercury orbital periods = 3 Mercury rotation periods.
Notice
Data no. (4) connects Mercury motion with Venus rotation period –
Mercury moves in its rotation period a distance =243 million km (error 1%) and if
each 1 million km = 1 day the period 243 days = Venus rotation period

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Data no. (2)
(90000 /4900) = 2 x 9.18
Where
90000 million km = C2
for a period 1 second (c = light velocity)
This data tries to show that the rate 9.18 is found in the basic data of the solar system
motion- because Jupiter orbital circumference is the central distance in the solar
system and the value (C2
) refers to main energy –
I want to say – the rate 9.18 in the data no. (1) is found through the solar system main
data –means – the connection between Mercury, Venus and the moon cycles is a
deep connection in the solar system motion data and can form the solar system design
backbone.
Notice
The rate (9.18) is our main point of discussion, we will return to it for deep analysis
but here the discussion aimed only to prove that there's a connection between the 3
planets cycles periods and this connection can't be explained by the tidal locking idea
which explains the moon cycles periods equality – the correct explanation depends on
my equation – because the moon cycles periods equality causes the rate (s) to be equal
(= 1) and by that the moon motion be used as the base for the equation depends on
which all planets diameters be defined as functions in their rotation periods – here the
idea of support Mercury and Venus for the moon motion is a suitable idea because the
moon is a small planet and can't be a qualified base for the whole solar group but if
Venus and Mercury support the moon motion that creates a point of connection
between the 3 planets which can be used as the base of the equation controls all solar
planets.
that also explains why the Equation works only from the Earth to Pluto.

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E-4 The Relative Motion Between The Moon And Pluto
Let's summarize the idea in following…
- (I)
- I add The velocities of (Mercury 47.4 + Venus 35+ the moon 29.8) = 112.2 km/s
(The moon velocity be considered 29.8 km/s = Earth velocity- because they aren't
separated in their revolutions around the sun)
- The 3 planets velocities total =112.2 km/s
- And
- Pluto velocity 4.7 km/s
- And
- We imagine that, the total velocity (112.2 km/s) moves relative to Pluto velocity
(4.7 km/s) where 112.2 km/s = 23.9 x 4.7 km/s
- This data means, 1 hour of the velocity (112.2 km/s) be = 23.9 hours of Pluto and
- As a result –
- We suppose that 1 hour of (Mercury) = 23.9 hours of Pluto
- Here Mercury be the point of the total velocity (112.2 km/s) in compare with Pluto
- This rate of time be created based on the total velocities (112.2 km/s)
- Notice
- The rate of time depends on the velocities – and that supports the idea tells – the
rate of time be seen in the equation in the rate (v1/v2)
- This idea can be acceptable simply in high velocity motions
- Shortly
- Because the total velocity (112.2 km/s) =23.9 x 4.7 km/s that creates a rate of time
between Mercury and Pluto (1 to 23.9)
- Pluto can receive only (1/23.9) of the energy and for that all planets energy be
controlled by this rate (1/23.9)
- Mercury be (23.9 or 24 for simplicity) and any other planet will be (1)
- By that the rate (1 to 24) controls the planets data – let's see in following.

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- E-4-1 Planets Orbital Distances Distribution
- I- Data
- (1)
- Π x 37100 million km = 4900 million km x 23.9
- 100733 million km = 4900 million km (23.9 – Π)
- 100733 million km = Π ( 37100 million km - 4900 million km)
- (2)
- 100733 million km x 23.9 = 37100 million km x 20.5 Π
- 100733 million km = 4900 million km x 20.5
II- Discussion
- Data no. (1)
- Π x 37100 million km = 4900 million km x 23.9
- 100733 million km = 4900 million km (23.9 – Π)
- 100733 million km = Π ( 37100 million km - 4900 million km)
- Where
- 37100 million km = Pluto Orbital Circumference
- The 3 values (4900, 37100 and 100733) we have discussed before with the map of
distances where we have discovered that these 3 values depend on one another and
any 2 values can conclude the third one –
- Our current new data shows that – the 2 values depends on 4900 million km –
- Means, Jupiter orbital circumference (4900 million km) be created at first and
based on this distance the other 2 distances be created as functions in it – by that
37100 and 100733 be created depending on 4900 million km

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- The used factor is (23.9) this is the secret rate behind – if we know this rate and
Jupiter orbital circumference (4900 million km) we can conclude the 2 values
(37100 million km and 100733 million km)
- That tells the planets orbital distances distribution took into consideration the rate
(23.9) as a basic geometrical requirement in this distribution – why??
- Let's see the next data
- Data No. (2)
- 100733 million km x 23.9 = 37100 million km x 20.5 Π
- 100733 million km = 4900 million km x 20.5
- We have a new rate which is 20.5 what's this one?
- 2x 20.5 = 41 where (the planets orbital inclinations total = 41 degrees)
- That tells, the solar system distances be created based on (4900 million km Jupiter
orbital circumference) and the rate (23.9) which causes the planets orbital
inclination total to be = 41 degrees.
- The data leads to the following conclusions
- (1)
- Planet orbital distance depends on its neighbor planet orbital distance (be proved
by my first equation)
- (2)
- The planets orbital distances distribution depends on Jupiter orbital circumference
4900 million km
- (3)
- Pluto orbital distance and position depended on the rate (23.9) between Pluto and
Jupiter distances – by that – Pluto position be defined depending on Jupiter
position and the rate (23.9), That made this rate (23.9) as a basic one in the planets
distances distribution definition - and this rate be essential data.

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- (4)
- The rate (23.9) be effective on planets distances because this rate is found to
support the planets diameters definition -
- As we remember
- Planet diameter should be a function in its orbital distance to move safely and can't
be a direct function has only 2 variables (planet diameter and orbital distance) but
has to have many other variables to save this planet diameter in case of the planet
migration – by that - planet diameter be a function in rotation period and the
rotation be a function in the velocity then the velocity be a function in orbital
distance – this is the basic idea we deal with –
- Here the rate (23.9) is the rate (supposed) to be produced by planets relative
motions between the 3 planets and Pluto – and this rate of time (1 h =23.9 h) be
transported through the planets to cause each planet to define its diameter as a
function in its rotation period – this is the idea we have discussed –
- That explains why the planets distance distribution take into consideration this rate
(23.9) because the diameters should be created function in these distances and the
distances create configuration with the data to cause the function works softly
- Means
- The rate (23.9) is the feedback be sent from the planets diameters functions to the
distances to cause a general configuration and harmony of data.

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- E-4-2 Jupiter Motion Relative To Pluto Motion
- I- Data
- (a)
- 103944 days x 0.406 million km = 37100 days x 1.1318 million km = 90560 days
x 0.466884 million km = 3.024 million km x 2 x 6939.75 days = 142984 seconds
x 0.3 million km/s (error 2%)
- (b)
- (90560 /4331) = (103944 /4900)
- (c)
- (59800 /16.1) = (90560 /153.3) x 2π
II- Discussion
- Data no. (a)
- 103944 days x 0.406 million km = 37100 days x 1.1318 million km = 90560 days
x 0.466884 million km = 3.024 million km x 2 x 6939.75 days = 142984 seconds
x 0.3 million km/s (error 2%)
- Where
- 103994 hours = 4331 days = Jupiter Orbital Period
- 90560 days = Pluto Orbital Period
- 37100 million km = Pluto Orbital Circumference
- 0.406 million km = Pluto Velocity Per Solar Day
- 0.466884 million km = Neptune Velocity Per Solar Day
- 1.13184 million km = Jupiter Velocity Per Solar Day
- 3.024 million km = Venus Velocity Per Solar Day
- 6939.75 days =Metonic Cycle
- Data no. (b)
- (90560 /4331) = (103944 /4900)

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- 4331 days = Jupiter Orbital Period
- The previous data shows that – Jupiter motion uses 103944 in comparison with
90560 for Pluto motion – which refers to the rate (1 = 23.9)
- Data no. (c)
- (59800 /16.1) = (90560 /153.3) x 2π
- Where
- 59800 days =Neptune Orbital Period
- 153.3 hours = Pluto Rotation Period
- 16.1 hours = Neptune Rotation Period
- This data tries to explain how Neptune motion be seen in data no. (a) where
Neptune moves during 90560 days a distance = Pluto motion distance during
103944 days – (where 90560 d =Pluto Orbital Period)
- This is happened because there's a deep interaction between Pluto and Neptune –
and in fact this interaction contains Uranus also – we have to examine this
interaction through the paper discussion.
- Notice
- Light (300000 km/s) travels during 103944 seconds a distance = 32200 million km
(error 3%) where 32200 million km = Pluto orbital circumference 37100 – Jupiter
orbital circumference 4900
- I try to prove that a geometrical mechanism be found behind.
- But, let's ask
- why Jupiter is the point of the 3 planets motions effect? what connects Jupiter with
the 3 planets (Mercury- Venus and the moon) – we answer in following..

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- E-4-3 Jupiter And The 3 Planets Interaction
- I- Data
- (1)
- Mercury moves during its day period a distance = 720.7 million km = Jupiter
Mercury Distance
- (2)
- Venus moves during its orbital period a distance = 680 million km
- (Jupiter Venus Distance =670.4 million km "error 1.4%")
- (3)
- Earth moves during its orbital period a distance = 940 million km
- (Jupiter Earth Distance = 929 million km "error 1.2%")
- Notice
- Jupiter Earth Distance be = 929 million when the 2 planets be on 2 different sides
from the sun.
- We have discussed this data before in point no. (D-2) –we see it here for remember
- (4)
- The inner planets orbital circumferences total be (Mercury 360 mkm + Venus 680
mkm + Earth 940 mkm + Mars 1433 mkm + 1433 mkm) = 4900 million km (1%)
- The total = 4900 million km but the distance (1433 mkm) be used 2 times!
- This data we have seen before – it's another data connects the 3 planets with
Jupiter – I try to show we have a reason to suppose that the total velocity (112.2
km/s) works on Jupiter point because Pluto uses 23.9 with Jupiter and the 3 planets
create deep connections with Jupiter.

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- (5)
- 778.6 million km (Jupiter orbital distance) =1.16 million km /s x 670 seconds
- 778.6 million km (Jupiter Mercury distance) =1.16 million km /s x 629 seconds
- 5906 million km (Pluto orbital distance) =1.16 million km/s x 5127seconds
- Where
- 670 million km = Jupiter Venus Distance
- 5127 million km = Jupiter Pluto Distance
- We know that Jupiter distances depend on 1.16 where we have studied that before
in details – but the 3 inner planets and Pluto distances to Jupiter be the most clear
distances in Jupiter data depend on the (1.16)
- I use different data to show that a connection point must be found between Jupiter
and the 3 inner planets from one side and Pluto from the other side.
- (6)
- 1.1318 million km = 112.2 km/s x 5040 seconds x 2
- Where
- 1.1318 million km = Jupiter Motion Distance Per A Solar Day
- 112.2 km /s = The 3 planets velocities total (47.4 +35+ 29.8)
- 5040 seconds = The Period Mercury needs to make its day =4224 hours
- This more data shows a connection between the 3 planets and Jupiter
II- Discussion
- I put different types of planets data to show that the connection between the 3
inner planets and Jupiter can't be a simple one but it's a deep connection and based
on it huge amount of data be created – which shows its effect on the planets
creation and motion data.
- The difficulty is that - many used geometrical rules be unknown for that we can
catch clearly the geometrical machine behind the data.

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E-5 The 3 Inner Planets effect on Pluto motion
- I- Data
- (1)
- 90560 days = 4222.6 hours x 9.18 x 2.33
- (2)
- ((2x 153.3 x 3600)/ (5040)) =23.9 x 9.18
- (3)
- 90560 =23.9 x 346.6 x 10.9
- (4)
- (406000 km / 88000 km) = (708.7 h/ 153.3 h) = 4.61 =(9.18/2)
II- Discussion
- Data no. (1)
- 90560 days = 4222.6 hours x 9.18 x 2.33
- Where
- 90560 days =Pluto Orbital Period
- 4222.6 hours = Mercury Day Period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = Pluto velocity (4.7 km/s) x 10.08 –because of that
- The rate 2.33 be found between (one day of Pluto and one hour of Mercury)
because 2.33 x 10.08 = 24
- The rate 2.33 be used because we use Pluto orbital period (90560 days) in
comparison with Mercury Day Period (4222.6 hours)
- The data tries to show that the rate (9.18) is the basic one between the 3 inner
planets and Pluto
- Notice / we have studied this rate (9.18) in the beginning of this discussion and we
still use it because it's the basic one between the 3 planets and Pluto
- Data no. (2)

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- ((2x 153.3 x 3600)/ (5040)) =23.9 x 9.18
- Where
- 153.3 hours = Pluto rotation period = Pluto day period
- 5040 seconds = a period be required by Mercury day period to be =4224 hours
- The data shows that, the same rate (9.18) be used between different data of the
same planets – that tells a geometrical mechanism be found behind this rate and
effect on these planets data.
- Data no. (3)
- 90560 =23.9 x 346.6 x 10.9
- Where
- 346.6 days = The Nodal Year
- 10.9 =??
- The moon orbital apogee radius should be 413600 km but it decreased and be only
406000 km where 406000 km = 413600 km x cos (10.9 degrees)
- It's a complex data – later we will see more shared data be used by the moon and
Pluto supports this one – and also we should discuss how the moon orbital apogee
radius be 406000 km – our current data here only aims to show that the rate (23.9)
be found between Pluto orbital period and the nodal year.
- Data no. (4)
- (406000 km / 88000 km) = (708.7 h/ 153.3 h) = 4.61 =(9.18/2)
- 406000 km = Pluto motion distance during solar day
- 88000 km = The Moon Displacement during solar day
- 708.7 hours = the moon day period
- 153.3 hours = Pluto day period =Pluto rotation period
- This data be discussed in the next point no.(E-6)

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E-6 The Moon And Pluto Motions Data Consistency
I- Data
- (A)
- 5906 mkm (Pluto orbital distance) = 940 mkm (Earth orbital circumference) x 6.3
- 153.3 hours (Pluto day period) =24hours (Earth Day Period) x6.3 (error 1.4%)
- 90560 days (Pluto orbital period) = 1461 days (Earth Cycle) x 6.3 x π2
- (B)
- Pluto (4.7 km/s) moves during a solar day = 406000 km = apogee radius
- Pluto (4.7 km/s) moves during Pluto day 153.3 h = 2.5986 km = the moon
displacements Total during 29.53 days
- Earth moves during a solar day =2.574 mkm is different with 2.598 mkm by 1%
- (C)
- 406000 km (Pluto motion daily) / (88000 km the moon displacement) = 4.61
- (708.7h the moon day period /153.3h Pluto day period) = 4.61
- (D)
- Pluto day be created as a function in the moon cycles – the data proves that -
- Tan (12.19) x 708.7 hours = 153.3 hours (708.7 h = the moon day period)
- Tan (13.17) x 655.7 hours = 153.3 hours (655.7 h = the moon rotation period)
- (10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- 13.177 degrees = The Moon Daily Motion Degrees
- 12.19 degrees = 13.177 degrees – 0.9856 degrees (Earth motion daily degrees)
- (E)
- Pluto (4.7 km/s) moves during 88000 seconds a distance 413600 km
- Pluto (4.7 km/s) moves during 10.7 h (Saturn day period) a distance 181800 km
- (F)
- (708.7 h /10.7 h)= (655.7 h/ 9.9 h)= (224.7/3.4)= (2 x 153.32
h)/708.7 h = 66.2
- 10.7 h = Saturn Day Period
- 9.9 h = Jupiter Day Period
- 153.3 h = Pluto Day Period

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- 3.4 degrees = Venus Orbital Inclination
- (66.2 = Venus Mass / The Moon Mass)
- Notice No. 1
- 17.2 degrees = Pluto Orbital Inclination (error 1%)
- 23.4 degrees = Earth Axial Tilts (error 1%)
- 17.4 degrees = 5.1 deg (the Moo Orbital Inclination) x 3.4 deg (Venus Orbital
Inclination)
- Notice No. 2
- Pluto (4.7 km/s) moves during a solar day a distance =406000 km
- Pluto (4.7 km/s) moves during a Pluto day period a distance = 2.598 mkm
- Pluto (4.7 km/s) moves during 88000 seconds = 413600 km
- Pluto (4.7 km/s) moves during 10.7 h (Saturn day period) = 181800 km
- All distances be used in the moon orbital motion data
II- Discussion
- The data gives a sense for the idea – and tells – some concrete base be found under
it – because – it's not one data be in consistency between the 2 planets (the moon
and Earth on one side and Pluto on the other side) but almost all planets data be in
consistency…
- In fact - we can conclude all Pluto data based on the moon and Earth data – if
there's no a geometrical reason behind we would lose any logical thinking here –
- The data shows the fact clearly and tells that based on a geometrical reason the
data of (the Earth and moon) on one side be connected with Pluto data on the other
side.

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A Comment Of The Previous Discussion (No.1)
- The previous 6 points of the discussion tried to show that- A Geometrical Effect be
created on the moon and passes through the planets data – where this effect causes
each planet diameter to be created as a function in its rotation period as the
equation proves clearly.
- This geometrical effect be the rate of time (1 hour = 23.9 hours) which be found
between 2 points in the solar system (Mercury and Pluto) as the data shows.
- But, the fact is that,
- Although we know the geometrical effect is the rate of time (1 to 23.9 or 24), and
we realized that the rate of time controls the transported amount of energy and by
that its controls the planets data – but the detailed effect of this rate of time is still
needs more analysis to be discovered –
- We should try to deepen our discussion in the next points.

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E-7 The Outer Planets Diameters Total Effect
I-Data
(1)
366556 km = 2390 km x 153.3 = 3475 km x (655.7/2π)
(2)
406000 x 0.105 = 43000
But
105 x 3475 km = 366556 km
(3)
Saturn (9.7 km/s) moves during its rotation period a distance =373644 km
(4)
366556 km = 15327 x 23.9
II- Discussion
Data No. (1)
366556 km = 2390 km x 153.3 = 3475 km x (655.7/2π)
[
2390 km = Pluto Diameter
153.3 hours = Pluto rotation period
655.7 hours = the moon rotation period
Simply the planet diameter relative to The Outer Planets Diameters Total produces a
rate can be used as this planet rotation period – of course a geometrical mechanism be
found behind this data – we just don't know how the geometrical rules work -
The 2 planets are the equation terminals (The Moon And Pluto),
The data clearly depends on a geometrical mechanism.
Data no. (2)
406000 x 0.105 = 43000 But 105 x 3475 km = 366556 km
406000 km = the apogee radius, 43000 km the distance between perigee and apogee

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This data shows one more feature for this geometrical mechanism by which the
planets diameters rates define their oration periods.
Data No. (3)
Saturn (9.7 km/s) moves during its rotation period a distance =373644 km
The data shows Saturn also has a connection with this distance 366556 km because
the distance 373644 km is different from 366556 km with (2%) while the distance
373644 km is different from (378675 km Saturn Circumference) with (1.3%)
There's a geometrical machine behind this data because Saturn is the third player in
the equation with the moon and Pluto – by that - Saturn also has a connection with
the outer planets diameters total 366556 km –
Data No. (4)
366556 km = 15327 x 23.9
15327 km = Mercury Circumference
The data shows the rate (23.9) proves the rate of time idea
I wish we can extend our thinking because the rates of the diameters be used as
periods of time (rotation periods) and this using refers to unknown geometrical effect
I want to say- the geometrical machine works and produces its results and we can't
catch these results because we don't know the used geometrical rules - for that – we
see puzzled data which be created based on a geometrical machine
For example - the simple question –
Why planet rotation period can be defined as a rate between its diameter and the outer
planets diameters total? what's the great geometrical effect of this outer planets
diameters total?
Notice
We have to keep in mind this number 366556 km because it's a main distance in the
moon orbit geometrical structure.

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E-8 The Moon Orbit Geometrical Structure
I- Data
(1)
366556 km = The Outer Planets Diameters Total = 3475 km +363080 km
40080 km = The Inner Planets diameters total = the Earth Circumference
406000 km = The Planets Diameters Total
(Notice/ Pluto Moves During A Solar Day A Distance = 406000 km)
(2)
17.4 degrees = The Inner Planets Orbital Inclinations Total
17.2 degrees = Pluto Orbital Inclination (error 1%)
23.6 degrees = The Outer Planets Orbital Inclinations Total
23.4 degrees = Earth Axial Tilts (error 1%)
17.4 degrees = 5.1 deg (the Moo Orbital Inclination) x 3.4 deg (Venus Orbital
Inclination)
17.2 degrees = 2 x 5.1 deg (the Moo Orbital Inclination) +7 deg.
7 degrees = 5.1 deg (the Moo Orbital Inclination) + 1.9 deg (Mars. Orb. Inclin)
II- Discussion
Data No. (1)
This data tells – if the moon be on its perigee radius (363000 km), the distance from
the Earth to the moon includes the moon diameter be = 366556 km= the outer
diameters total – in this case the rest distance after the moon diameter to its apogee
radius be (406000 km – 366556 km = 39500 km)
The distance (39500 km) be different with 1% from the inner planets diameters total =
40080 km = the Earth Circumference
That tells the moon orbit is divided into 3 parts according to the planets diameters
total – the apogee radius refer to all planets diameters total and perigee radius refers to
the outer planets diameters total and the distance between them refers to the inner
planets diameters total – of course there's a geometrical reason behind

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The point is that,
The data (366556 / the moon diameter 3475 km) = (655.7 /2π)
(655.7 hours = the moon rotation period)
This data refers to some geometrical machine which effects on the moon orbital
radiuses (perigee and apogee)
It's so important result because the moon could change its orbital radiuses if its
rotation period be changed or its diameter be changed – we here very near to the
meaning be suggested from the equation –
Data No. (2)
The data tells that
Pluto orbital inclination (17.2 degrees), the moon orbital inclination (5.1 degrees) and
the inner planets orbital inclination total (17.4 degrees) – these values be created by
one machine of data –
We can't see separated values or data from one another – we see one stream of data be
created by one force for one process and for that the data be in harmony with one
another
These are summarized data –I have tried to show that the moon orbit geometrical
structure be created based on this geometrical effect which be found behind the
suggested rate of time we have discussed as a reason for the equation –
Shortly
We deal with a great machine and it effects greatly on the planets motions and data -
In the next point (No. E-9) we examine the moon motion in more details to show that
more data of the moon motion be in harmony with this geometrical effect which is
covered by the suggested rate of time.

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E-9 Why Does The Moon Apogee Orbital Radius =406000 Km?
(1)
The Planets Diameters Total = 406000 km
Pluto moves in a solar day a distance = 406000 km
The moon orbital apogee radius = 406000km
(2)
Earth moves during its day period (24 hours) a distance = 2.574 million km
Pluto moves during its day period (153.3 hours) a distance = 2.59 million km
The Earth moon displacements total during 29.53 days = 2.59 million km
The 3 distances are equal (error 1%)
Why the 3 planets move equal distances in their days periods?!
(3)
We have discussed this idea before but we review it here for the additional data
The Moon Orbital Motion
The moon daily displacement =88000 km and during 29.53 days the displacements
total be = 2.598 million km = 2π x 413600 km
The data tells the moon orbital apogee radius should be 413600 km and
The moon daily displacement (88000 km) is long, because of that, the moon should be
prisoner in the orbit with radius (= 413600 km) and the moon can't revolve around the
Earth through any more near orbit!
Not facts – The moon orbital apogee radius =406000 km and the moon revolves
around the Earth through near orbits and can reach to perigee radius (363000 km).
How Can The Moon Do That?
The intelligent moon creates an angle (θ) between its motion direction and its orbit
horizontal level by that the real displacement (L) through the orbit be less than (88000
km) because it be (L = 88000 km cos θ), as a result the total displacements be less
than (2.598 million km) and that makes the moon orbital apogee radius to be
decreased from 413600 km to 406000 km.

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We should pay attention to the angle (θ), because this angle controls the moon motion
features – where- with the angle (θ) increasing the real displacement (L) be shorter
and the moon can revolve around the Earth through more near orbits – but –with the
angle (θ) deceasing the real displacement (L) be longer and that pushes the moon far
from the Earth to more far orbits.
The moon orbital motion depends on this angle (θ) it tells θ1 = θ0 +1.7
where (θ1) = today angle and (θ0) =yesterday angle
Now, one more question be raised, why the moon apogee radius be 406000 km? why
not shorter if the moon uses this technique which enable the moon to decrease its
orbital apogee radius as possible? Why specifically the radius 406000 km be chosen?
Because 406000 km = The Planets Diameters Total
We still be connected with my fourth equation – and the geometrical effect based on
which the planets diameters be created as functions in their rotation periods
Shortly
The orbital apogee radius 406000 km be defined by effect of this equation on the
moon motion
(4)
Why Does The Moon Move Daily A Displacement = 88000 km?
- The moon moves with The Earth and by its Earth velocity daily, this fact we know
because the Earth and the moon move together and don't separate each other
through the motions course revolving around the sun.
- Means,
- The moon moves per solar day a distance = Earth motion distance per solar
day = 2.574 million km.
- But
- The moon distance (2.574 mkm) be contracted by the rate 1.0725 and for that this
distance 2.574 mkm be 2.4 mkm

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- Now the moon difficulties be started, because, the difference 176000 km will
cause the moon to be separated from the Earth in their motions course
- For that reason the moon moves a displacement =88000 km (50%) depending on
the Earth gravity –
- We notice that, we don't see the moon motion for the distance 2.4 mkm neither the
original one 2.574 mkm, we see only the moon displacement 88000 km in the
Earth sky –
- The question we need to solve is that, why the moon doesn't separate from the
Earth if the different distance be 176000 km and the moon moves only 88000 km?
how the rest (88000 km) be adjusted?
- This story is a complex one and we need to move step by step to catch the idea
behind
- Firstly, how the rest distance (88000 km) be adjusted? This question answer be
provided by the generous Mercury, because Mercury is the basic helper behind the
moon motion - any way – Mercury uses very strange language for us – where the
moon displacement be 88000 km Mercury sees it as (88 days = Mercury orbital
period) and while the required distance is 176000 km, (Mercury day period =176
days approximately) – means – Mercury is our hope now –
- And
- This rate (1.0725) we have discussed frequently before –it's the basic rate in the
solar system and 40% of all distances in the solar system be rated by it and around
50% of all planets axial tilts be rated by it and also this is the rate between the
moon and Venus cycles (29.53 /27.3) = (243/224.7) =1.0725
- This rate (1.0725) is the reason to decrease the moon distance from 2.574 million
km to 2.4 million km.
- The data tells a deep geometrical machine be found between the 3 planets
(mercury, Venus and the moon) and by that not only the 2 planets cycles support
the moon cycles but even the 3 planets almost integrate their motions into one
unified motion.

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(5)
- Metonic Cycle
- Why does the moon rotate Metonic Cycle (19 years)?
- Because of Uranus motion effect on the moon motion – we know that because
- Uranus Orbital Distance =19.2 Earth Orbital Distance - means
- If Uranus and Earth velocities be equal, while Uranus revolves around the sun one
revolution Earth would revolve 19 revolutions (19 years)
- That's why I have suggested Uranus effect is the reason of the moon Metonic
Cycle
- In fact Uranus has 3 effects which are
- (a)
- Uranus motion effect on the Earth moon to rotate Metonic Cycle –and by this
effect - Uranus cause the moon orbital inclination to be 5.1 degrees and this
inclination causes to decrease the moon orbital apogee radius from 413600 km to
406000 km
- (b)
- Uranus effects on Pluto motion and causes Pluto rotation period to be (153.3 h)
- We know that because Uranus rotation period =17.2 hours and Pluto orbital
inclination be =17.2 degrees – the geometrical rule is unknown but Uranus is the
reason.
- Also Uranus uses Pluto rotation period in (Planet 8 days cycle) –we discuss it with
Saturn effect analysis (Point No. E-10)
- (c)
- Uranus axial tilt effects on all planets axial tilts and prevent the overturning motion
of any planet around the sun.
- This effect shows why Earth and Uranus use Neptune velocity in their Equations
(in my fourth Equation) – because Uranus guides all planets motions directions
and Uranus is one column of the velocity map 2 columns – where Earth is the
central point of the solar system motion

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- Uranus may use Venus motion to do this effect – by that – Uranus effect on Venus
axial tilt and Venus axial tilt effect on the moon orbital inclination – we should
notice that a very strong connection be found between Venus and Uranus on one
side and Venus and Jupiter on the other side.
- Notice (1)
- (153.3/ 53.9) = (1.16/0.406)
- Where
- 153.3 hours = Pluto Rotation Periods
- 53.9 hours = The 4 Outer Planets Rotations Periods Total
- 406000 km = Pluto motion distance per solar day
- 1160000 km = light supposed velocity
- Notice (2)
- I wish the (new) type of motion which be done by Planets be seen by us – because
- Uranus effect on Pluto motion to increase its rotation period (and day period) to be
(153.3 hours) but Pluto moves during this period (153.3h) a distance =2.598million
km = The moon displacements total during its day period (29.53 days) = Earth
motion distance during its day period (24 h) (error 1%)
- Here Uranus caused Pluto rotation period to be (153.3 h) for a geometrical reason
by which the planets move equal distances – but we understand nothing! Because
we don't realize any produced effect by the motions equal distances - Because we
don't know the produced geometrical effect we don't understand the whole process.
- It's a type of motion - the planet does- (which be unknown for us)
- We see only planet revolution around the sun but planet does many different other
motions which we don't observe nor understand because their geometrical effects
are unknown for us –

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A Comment Of The Previous Discussion (No.
A Comment Of The Previous Discussion (No.2
2
2
2)
)
)
)
- The discussion of the previous points (E-7, E-8 and E-9) give us 2 clear
information which are
- (1)
- The used geometrical rules to create the moon orbit are unknown
- (2)
- The rate of time (1 =23.9) coves a great geometrical effect – and the moon orbit be
created in comparison with the data be provided by this rate of time
- The moon orbit should be a proof for this rate existence and geometrical effect on
the solar system creation.
- But
- As long as we don't know the effect of the diameters rate on the rotation periods
and how to distinguish between the distance and planets diameters we can't reach
to a clear meaning in this discussion

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E-10 Saturn Effect Analysis
- Let's remember the equation basic points
- The equation depends on 3 points (The Moon –Saturn –Pluto)
- For The Moon
- The periods are equal because
- The moon orbital period = the moon rotation period =27.3 days
- For Saturn
- The velocities are equal because
- Saturn Orbital Velocity = Saturn Rotational Velocity
- Saturn is the an unique planet in the solar system which uses its orbital velocity to
be = its rotational velocity – and because of that –
- Saturn (9.7 km/s) moves during its rotation period (10.7 hours) a distance =
373644 km = Saturn circumference 378675 km (error 1.3%)
- For Pluto
- We supposed the distances be equal –we should discuss that in Pluto discussion.
- But, even if, this vision is a correct one and the periods be equal on the moon and
the velocities be equal on Saturn and the distances be equal on Pluto – how does
the Equation work? why do these equalities effect on the equation work?
- I try to show we still need to deepen our discussion for better understanding
- Now, let's ask, what's Saturn effect on the equation? Let's see this data
- Saturn moves in its rotation period a distance = its circumference (error 1.3%)
- Jupiter moves in its rotation period a distance = its circumference (error 4%)
- Uranus moves in its rotation period a distance = 2.6 x its circumference
- Neptune moves in its rotation period a distance = 2 x its circumference

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- These 4 planets data refer to some geometrical effect behind – this data can’t be
created by any random process – a geometrical effect be found behind and caused
this data.
- This data discussion should be more clear with (Planet 8 Days Cycle) we have
discussed in point no. (D-4)

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E-11 The Moon And Saturn Motions Data Consistency
Because The Moon Motion Be The Equation Base And Saturn Motion Be The Central
Point In This Equation. The 2 Planets Motions Data be in deep harmony and even
they use identical data- let's refer to them in following
(1)
The moon orbital radius in the total solar eclipse be = 373644 km = Saturn motion
distance during its rotation period (10.7 h) where (Saturn Circumference =378675 km
-error 1.3%)
That makes Saturn a goal for all proportionality of dimensions based on which the
total solar eclipse be created – as example
(a)
(The sun diameter /the moon diameter) =(Earth orbital distance /Earth moon distance)
Based on this equality we see the sun = the moon disc and that enable the total solar
eclipse to be occurred – Earth moon distance here refers to Saturn Circumference
(b)
Earth orbital distance 149.6 million km = The sun diameter 1.392 million km x 109
The sun diameter 1.392 million km = the Earth diameter x 12756 km x 109
The Earth moon distance (373644 km) = the moon diameter 3475 km x 109
The sun diameter / the Earth moon distance = Earth diameter / the moon diameter
(2)
Saturn orbital period =10747 days - and
The moon displacements total during 10747 days = 940 million km = Earth orbital
circumference
By that the 2 planets use the period 10747 days.

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- More Data
- (3)
- 10747 days x 2.4 mkm/ day = 25920 million km
- (4)
- 17.2 x 3600 x 0.838 mkm/ day = 2 x 25920 million km
- 17.2 x 3600 x 88000 km/day = 2 x 2723 million km
- (5)
- The values 10.7 and 10.9
- (6)
Discussion
- The data proves that– A deep harmony of the motion data be found between Saturn
and the moon – let's examine the data in following…
- Data No. 3
- It's interesting data - because – light 300000 km/s moves during a solar day
(86400 s) a distance =25920 million km
- The moon moves equal distance during Saturn orbital period – here we have more
than one interesting data – because
- The moon displacement per solar day be =88000 km and during Saturn orbital
period 10747 days the displacements total be 940 million km (Earth Orbital
Circumference).
- But – we know that – the moon moves daily a distance = Earth motion distance
daily because they aren't separated from one another and by that we know the
moon moves per solar day 2.574 million km where the rate (1.0725) effects on this
distance and contracted it to be (2.4 million km) by this last distance per solar day

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the moon moves during Saturn orbital period (10747 days) a distance = Light
motion distance in solar day.
- It's of course interesting data -
- Data No. 4
- 17.2 x 3600 x 0.838 mkm/ day = 2 x 25920 million km
- 17.2 x 3600 x 88000 km/day = 2 x 2723 million km
- This data uses Uranus day period (17.2 x 3600 = 61920 seconds),
- If the 2 planets (Saturn and the moon) use this value in days units (61920 days) in
this case
- Saturn will pass a distance = 2 x 25920 million km and
- The Moon will pass a distance = 2 x 2723 million km and
- Where
- 25920 million km = light (300000 km/s) motion distance during a solar day
- 2723 million km = Uranus Earth Distance
- Notice
- This data is a complex one because it tells during Uranus day period (61920
seconds) Saturn moves a distance = 600000 km
- But Uranus moves equal distance (600000 km) in a period =24.6 hours = Mars
rotation period -But
- Jupiter moves in 24.6 hours (Mars rotation period) a distance = 1.16 million km =
light supposed motion distance in one second.
- I can't catch the geometrical machine behind but this data be created based on one
another.
- Data No. 5
- The values 10.7 and 10.9
- The period 10.7 hours = Saturn oration period = Saturn day period

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- But, What's 10.9??
- The moon orbital apogee radius should be 413600 km (because the moon
displacements total during 29.53 days be 88000 km x 29.53 = 2.59 mkm= 2π x
413600 km)- as we have discussed before.
- Where 413600 km cos (10.9) = 406000 km.
- By that this 2 values (10.7 and 10.9) are different with 2% which tells they be rated
to each other – it may be the reason to decrease the moon orbital apogee radius
with 2%.
- Data No. 6
- This data tells, Saturn moves the distance 100733 million km in a period = 120536
days where
- 120536 km = Saturn Diameter

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A Comme
A Comme
A Comme
nt Of The Previous Discussion (No.
nt Of The Previous Discussion (No.
nt Of The Previous Discussion (No.3
3
3
3)
)
)
)
- The discussion of the previous points (E-10 and E-11) shows that
- The equality of Saturn orbital velocity and rotational velocity is a result depends
on a geometrical machine – where a continuous geometrical effect be seen on the
outer planets data-
- Means
- A geometrical effect be passed through the planets data and be seen by the equality
of Saturn orbital velocity and rotational velocity – this continuous geometrical
effect can be seen in (Planet 8 days cycle) (point no. D-4)
- This vision supports the equation concept tells (The equation depends on a
geometrical effect be passed through Planets data and forces each planet to create
its diameter as a function in its rotation period)
- In our discussion we have examined Saturn motion and have discovered this
geometrical effect based on which Saturn orbital velocity be = Saturn rotational
velocity.
- That may explain why the outer planets diameters total be a player in Pluto and the
moon rotation periods definition as rates to their diameters – here we deal with a
great geometrical machine contains the outer planets –one feature of this machine
we have discovered which is (Planet 8 days cycles)
- This discussion should be added to Neptune and Pluto data consistency (point
No.E-13) which shows more features for this same machine behind the outer
planets data.

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E-12 Pluto Effect Analysis
As we have discussed –My fourth equation depends on 3 points (the moon –Saturn
and Pluto)
For The Moon – The Periods Are Equation Because
(The Moon Orbital Period = The Moon Rotation Period =27.3 days)
For Saturn – The Velocities Are Equal – Because
(Saturn Orbital Velocity = Saturn Rotational Velocity)
For Pluto – The Distances Are Equal – Because
what are the equal distances? Let's see the data
I-Data
(1)
The 3 distances are equal (error 1%)
Why the 3 planets move equal distances in their days periods?!
(2)
2.59 million km = 346.6 x 7510 km
(3)
Pluto orbital circumference = 7510 km x 4.94 million km
(4)
Pluto (4.7 km/s) moves during 88000 seconds a distance =413600 km

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II-Discussion
What's the distances equality of Pluto? in the moon and Saturn the data related to the
orbital and rotation – at the distances that will be – Pluto circumference and its orbital
circumference – where the rate between both = 4.94 million
But
Pluto moves during its rotation period a distance = 2.59 million km =346.6 x 7510 km
(Pluto Circumference)
346.6 days = The Nodal Years
That may tell Pluto motion effects on the moon orbit and causes its regression yearly
and the nodal year creation
The basic secret is found in the first data
Data No. (1)
Also
Venus decreased its distance from 3.024 million km to be 2.59 million km to support
the moon motion- (point no. B-9)
The question is (What's The Result Of These Distances Equality?)
What's the geometrical effect we produce if 2 planets move equal distances in their
rotation periods
Here's the secret which can add a new book of geometry to the physics library.
The point is that
The 3 planets velocities total be 112.2 km/s = 4.7 km/s (Pluto velocity) x 23.9
By that one hour of a planet = 23.9 hours of Pluto
But
153.3 hours /23.9 hours = 2π (error 2%)

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But
5906 million km (Pluto Orbital Distance) = 940 million km (Earth Orbital
circumference) x 2π
That shows the data be created based on this rate of time – and by that – this rate of
time covers a geometrical effect passes through the planets data to effect on it and
create it by this effect.
Here the motions distances equality shows a great significance

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E-13 Pluto And Neptune Data Consistency
I- Data
(1)
(90560 /153.3) x 2π = (59800/ 16.1)
(2)
Uranus Orbital Distance = 2 x Saturn Orbital Distance
Neptune Orbital Distance = π x Saturn Orbital Distance
Pluto Orbital Distance = (π+1) x Saturn Orbital Distance
(3)
Neptune needs 2 x 4900 days to pass a distance = Neptune Orbital Distance
Pluto needs 3 x 4900 days to pass a distance = Pluto Orbital Distance
Max error 2%
(4)
406000 km = Pluto velocity (4.7 km/s) x 86400 seconds
406000 km = Uranus velocity (6.8 km/s) x 59800 seconds
(5)
Neptune (5.4 km/s) moves during 155597 seconds a distance = 2 x 421056 km
II- Discussion
The data tries to prove that a deep interaction be found between Uranus, Neptune and
Pluto motions data. let's refer to each data in details
Data No. (1)
(90560 /153.3) x 2π = (59800/ 16.1)
Where
90560 days = Pluto Orbital Period
59800 days = Neptune Orbital Period
153.3 hours = Pluto rotation period
16.1 hours = Neptune rotation period

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Data no. (4)
406000 km = Pluto velocity (4.7 km/s) x 86400 seconds
406000 km = Uranus velocity (6.8 km/s) x 59800 seconds
406000km= the moon orbital apogee radius = the planets diameters total = Pluto
motion distance in a solar day period.
Also
Uranus (6.8 km/s) moves during 59800 sec a distance =406000 km
Where
59800 days = Neptune orbital period
Data no. (5)
Neptune (5.4 km/s) moves during 155597 seconds a distance = 2 x 421056 km
Where
421056 km = Uranus Motion Distance During Uranus Day Period
155597 km = Neptune Circumference

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E-14 Jupiter And The Moon Data Consistency(More Data)
I- Data
(1)
Jupiter (13.1km/s) moves during 10921 s a distance = 142984 km = Jupiter diameter
Where the moon circumference =10921 km (where 1 km= 1 sec)
(2)
4900 million km = Jupiter Circumference (449197 km) x 10921 km
4900 million km = The Sun Diameter x The Moon Diameter
(4900 million km = Jupiter Orbital Circumference)
And
(Jupiter diameter x π2
= the sun diameter – error 1.4%)
(3)
Jupiter orbital distance 778.6 million km = Earth orbital distance 149.6 million km x 5.2
(5.1 degrees = The Moon Orbital Inclination)
(4)
The moon orbital apogee circumference should be 2.59 million but the fact it be
2550973 km the difference = 47720 km = Jupiter motion during one hour.
The data tries to prove that a deep interaction and consistency be found between the
moon and Jupiter motion data.

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E-15 The Equation Units Analysis
Let's review the Equation in following
v = Planet Velocity
r= Planet Diameter
A Question
Are The Equation Units Be In Harmony?!
Not because
(s/r) a rate can't be understandable where
s= planet rotation period number in its orbital period
r= uses km units
for example for Jupiter s =10500 and its units be 10500 Jupiter rotation periods
(Jupiter rotation period =9.9 hours) but
412984 km = Jupiter diameter - how to create a harmony for these units?
Planet rotation period should be considered = one second
I
r
s
v
v
=
=
2
1

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Jupiter rotation period 9.9 hours and we have to consider this 9.9 hours = 1 second
And
Planet diameter value be used in second units
Based on that
(s) for Jupiter =10500 Jupiter rotation period will be used as 10500 seconds
And
142984 km will be used as 142984 seconds
By that the rate (s/r) can find a harmony for its units.
Example – Jupiter diameter be 142984 km be used as 142984 seconds
How this data can be used by these units?!
Here we have 2 questions
How planet diameter can be used as a period of time?
This question is answered in point no. (E-16)
And
How planet rotation period can be used as (1 second)?
This question be answered in Part No. (2) of this paper

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E-16 Planet Diameter Analysis
I- Data
(1)
- Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter- (10921 km = the Earth moon circumference)
(2)
- Pluto (4.7 km/s) moves during (10921 s) a distance = 51118 km = Uranus diameter
- Pluto (4.7 km/s) moves during (51118 s) a distance = 2 x 120536 km = Saturn
diameter.
- Pluto (4.7 km/s) moves during (2 x 120536 s) a distance = 1.13184 million km =
Jupiter motion distance per a solar day
(3)
- Uranus (6.8 km/s) moves during 7510 seconds a distance =51118 km = Uranus
diameter- (7510 km = Pluto Circumference)
(4)
- Venus (35 km/s) moves during 12104 seconds a distance =421056 km = Uranus
motion distance during Uranus rotation period -
- (12104 km = Venus diameter)
- Also
- Venus (3.024 million km per solar day) moves during 12104 days a distance = 2 x
18048 million km = Uranus Orbital Circumference) (error 1.4%)
II- Discussion
- The data tells –planet diameter and circumference can be used as period of time –
- It's not clear how or why – but the data shows the facts
- This feature may be found because planet diameter be created as a function in its
rotation period and the designer needed to create a measurement to diameter
definition – in all cases the type of motion is unknown.

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E-17 Jupiter and Saturn Equations Analysis
- My 4th
Equation (Planet diameter Equation)
- (v1/ v2) = (s/r) =I
Jupiter equation (10500/142984) = 13.1/(27.78 x 2π) = 0.0734 (error 2.2%)
10500 = Jupiter rotation periods number in Jupiter orbital period
142984 km = Jupiter diameter
27.78 km/s = The Earth Moon velocity
4331 days = Jupiter orbital period (and Jupiter rotation period =9.9 hours)
Saturn equation (24106 x2) /(120536) = 9.7/ 24.1 =0.4
24106 = Saturn rotation periods number in Saturn orbital period
120536 km = Saturn diameter
10747 days = Saturn orbital period (and Saturn rotation period =10.7 hours)
(1/0.4) = 2.5 where 2.5 degrees = Saturn Orbital Inclination
Let's remember the question

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Why do Jupiter and Saturn use the rate (r/s) in place of (s/r)?
Because
The solar system be created of one energy – or one trajectory of energy-
The data shows that some reflection be occurred in Saturn data –that may effect on
Jupiter also
The reflection of energy be discussed in details the paper part No. Two
Point no. (14)

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E-18 Questions And Answers
1st
Question
Can Venues Motion Effect On The Moon Motion And Causes The Moon Rotation
Period To Be = The Moon Orbital Period?
1st
Answer
(243/224.7) = (29.53/27.3) =1.0725
Venus rotation period = 243 days and Venus orbital period =224.7 days
The moon rotation period = 27.3 days and The moon day period = 29.53 days
The secret is in the rate 1.0725 because –this rate controls 40% of all distances and
50% of all planets axial titles – the moon motion details can show a great effect of this
rate on the moon motion – let's explain that in following…
The moon moves per a solar day a motion typical to the Earth motion to avoid the
separation from Earth through their motions, based on this rule, the moon moves per a
solar day 2.573 million km with an angle declines on the horizontal level 0.98562
degrees as typical to Earth motion
If there's other effects on the moon motion, the moon motion trajectory would to be a
parallel line to Earth Motion Trajectory, But Some effect be on the moon motion daily
distance (2.573 million km) with the rate 1.0725 and causes this distance to be
contracted (2.4 million km)
The moon difficulties are started here, because the difference between both distances
(0.17 million km) will cause the moon to be separated from Earth motion inevitably
We should notice that, these motions are done far from our observation, means, we
distance the motion is still fact and proved by its power, because the Earth moves per

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a solar day 2.573 mkm and if the moon doesn't move this same distance every solar
day that necessities the moon to be separated from the Earth through their motions
course – based on that- the facts prove this motion regardless our observation ability
for it.
Now the moon has an additional distance to be passed (0.17 million km) and the
moon has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
Because of that, the moon moves its daily displacement (88000 km) depends on Earth
gravity force (by which we see the moon in the Earth sky), but the different distance
(0.17 million km) to be covered still needs the moon to move one more displacement
(= 88000 km)
The previous explanation tells that, the moon has to move 2 displacements each =
88000 km, while we see one displacement only because it's done through the moon
orbital motion around Earth but the other displacement should be done also because
this total distance (0.17 million km) is required to cover the different distance and
create the total (2.573 million km) which saves the moon and Earth motions
accompanying.
Now we have 2 basic information about the moon orbital motion
(1st
(2nd
information) the moon has to move 2 displacements each =88000 km and their
total distance =0.17 million km which is a required distance necessary to cover the
difference between the moon and Earth motions distances.
This explanation helps us to understand the effect of the rate (1.0725) on the moon
motion and by that we can see the deep connection between the moon and Venus
motions based on this rate
Notice,

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I suppose the effect which caused the rate 1.0725 to be Lorentz Length Contraction
Effect – based on velocity 99% of light velocity (1.0725 = (7.1/100) +1)
I want to say
The rate (1.0725) causes some very complex effect on the moon motion – and by that
the effect of the rate (1.0725) on Venus and on the moon motions data should be used
as a proof for their mutual effect on their motions -

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2nd
Question
Planet Diameter Equation uses the moon motion as its base – and the equation refers
to an effect passes through all planets and causes each planet diameter to be a function
in its rotation period – why the moon velocity can control all planets velocities?
(the equation effect is a rate of time which be transported by velocities rate)
2nd
Answers
- My 4th
- (v1/ v2) = (s/r) =I
The equation tells, a geometrical effect be created and passed through all planets to
create each diameter as a function in its rotation period (or the rate "s")
This effect is a rate of time passes through the planets based on the rate (v1/v2) in the
equation –and by this rate of time – the passed energy be defined and that causes the
effect on all planets data
The question asks-
Why can the moon velocity do this great effect? where the moon is a small planet –
Because
The moon uses the Earth velocity

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The moon and Earth don't separate one another in their revolutions around the sun and
for that we have to consider their velocities are equal
The Earth velocity is the master velocity in the solar system
Why??
Because the sun creation depends on the Earth motion and for that all planets move
based on the guidelines defined by the Earth to cause the sun creation
The next question should be (how is the sun created?)

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3rd
Question
How Is The Sun Created?
3rd
Answers
(1)
The sun rays is created by the planets motions energies total – means-
The planets motions energies be accumulated during 1461 days and be used by the
sun in one day to produce the sun rays – for that – 1461 days of Earth motion = 1 day
of the sun motion
That's the reason of the Earth cycle (365 +365 +365 +366 =1461 days)
(2)
The Earth and the moon motions causes the rate (1461 =1) to be created – and the
Earth with Venus, Jupiter and Uranus define the sun position in the sky after its
creation – the total solar eclipse is the method by which the Earth defines the sun
position in the sky by using the moon effect to define as accurate as possible the sun
position
(3)
This fact is shocked because it simply disproves Newton theory of the sun gravity –
where no planet moves by the sun gravity but the sun itself be created by the planets
motions energies accumulation using- means –the sun be created after all planets
creation and motion
(4)
This theory doesn't effect on the current sun science greatly because from the energy
the sun matter be produced and all observed features can be found but the source of
energy isn't any nuclear interactions inside the sun but it's the accumulated energy of
the planets motions energies.
(5)
This fact – I have reach by analysis for the planets data – I can prove by so many data
For example

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(a)
Light (300000 km/s) travels in one solar day (86400s) a distance = the solar planets
motions distances total in 1461 days why? my theory answers this question
(b)
The moon circumference (10921km) x 86400 = 940 million km (Earth orbital
circumference) -how to explain this data??
It tells if the Earth revolves around the sun a complete revolution in one solar day
only (86400 sec) the moon circumference will be equal a distance of the Earth motion
for 1second.
(c)
The moon circumference (10921km) x 27.3 = 300000 km
This data also gives an interesting meaning…
It tells if the moon rotates around its axis one time each solar day (as Earth does) the
moon would to move in 27.3 days (the moon orbital period) a distance =300000 km =
light motion distance in one second.
I try to show that – the planets motions depend on light motion and for that reason the
sun creation from the planets motions energies will not be so strange because the
whole universe be created of energy (provided by light beam)
(6)
The previous idea is my theory – but – about the accurate creation of the sun diameter
I can provide so many interesting data – because I want to make the idea as logical as
possible and to prevent any hope in the claim (pure coincidence of numbers)
THE DATA
(i)
4900 million km = the sun diameter x the moon diameter = the moon circumference x
Jupiter circumference = Jupiter Orbital Circumference

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Please note, the distance 4900 million km is the central one in the solar system and
the whole design depends on it
(ii)
(Earth diameter / the moon diameter) = (the sun diameter/ 378675 km)
Where
378675 km = The Earth Moon Distance In The Total Solar Eclipse = Saturn
Circumference
(iii)
(The sun diameter / the moon diameter) = (Earth orbital distance/ Earth moon distance)

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4th
Question
Is There A Relationship Between The Planet Eccentricity And Its Orbit Area?
4th
Answer
The answer must be positive one because
Data
- (1)
- 36780 x 1012
- (0.35338 mkm is different from 0.363 mkm with 2.5%)
- Where
- 36780 x 1012
km = Venus Orbit Area
= The Moon Orbit Area
- 0.363 million km2
= The Moon Orbital Perigee Radius
- (2)
- (29.53 days /27.3 days) = (243 days /224.7 days) = (0.384 mkm/ 0.353 mkm) = 1.0725
- 29.53 days = The Moon Day Period
Data No. (1) shows the moon orbit area is rated with Venus orbit area by (0.353)
where this same distance be used in Data No.(2)
In fact – Venus effects on the moon basically on the point 384000 km (the moon
orbital distance) this fact we have proved frequently in Venus motion effect on the
moon motion-
I want to say the distance (0.353) is a basic player and mentioned value between The
moon and Venus motion data
Venus eccentricity =0.7 = 2 x 0.353 –the data tells some geometrical machine be
found behind.

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That may have root in Kepler Law (the line swept equal areas in equal periods), where
the planet moves distances and not areas
That tells some geometrical machine be found behind use the distances to pass equal
areas in equal periods.

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5th
Question
Why Does Mercury Day Period = 2 Mercury Orbital Periods = 3 Mercury Rotation
Periods
5th
Answer
Because
Data
(1)
Venus day period= 2 Mercury rotation period= 4 the moon day period (error 1%)
And
(2)
The Moon Orbital Period = The Moon Rotation Period =27.3 Days
(3)
(243/224.7) = (29.53/27.3) =1.0725
Venus rotation period = 243 days and Venus orbital period =224.7 days
The moon rotation period = 27.3 days and The moon day period = 29.53 days
Discussion
It's one system of motion contains Mercury, Venus and the moon motions, they
integrate their motions to cause the moon orbital period to be = the moon rotation
period –and by this equality – the moon motion be used as the base of planet diameter
equation because (s be =1) let's refer to this equation in following
- My 4th
- (v1/ v2) = (s/r) =I

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6th
Question
- How to explain an idea tells (Planet Data Depend On Exaction Equations)?
- (1)
- Planet Data Be Created Based On Exact Equations –
can't fly safely.
distance, period, inclination, rotation period, axial tilt …and all data based on exact
equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically without
observation which prove this fact decisively.
- Then we have to ask (How Planet Data Be Created In Order?)
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets
motions leave an empty place for the new planet – by that- each planet orbital
distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves this fact – because – it proves each planet orbital distance
depends on its previous neighbor planet orbital distance –
- d2
=4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orbital distance
- This equation be tested and discussed in this paper – but its concept is a clear one –
it tells the planets leave an empty space for the new planet – for that reason each
planet orbital distance depends on its neighbor planet orbital distance.
- Logically the new planet can't disturb the current planets positions or motions
trajectories – by that – the orbital distance be defined by the neighbors positions.
- (3)
- The new planet has to revolve around the sun based on its orbital distance which
be defined obligatorily where no data of this planet be taken into consideration in

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its orbital distance definition –neither mass nor diameter – instead – the distance
be defined based on the neighbor distance.
- But
- Planet diameter should be a function in its orbital distance – otherwise – this planet
will be broken through its motion –
- The function between planet diameter and its orbital distance is the necessary
requirement to cause the planet safe motion – almost – planet mass can't cause this
planet to be broken but it may decrease its velocity or creates orbital inclination –
the planet geometrical motion form depends on its diameter – the wrong diameter
can cause this planet to be broken and destroyed.
- One more difficulty be found for the designer
- If the function contains only 2 variables which are planet diameter and its orbital
distance – in case this planet changes its orbital distance for any reason- this planet
will be broken also –
- As a result
- The designer had to create a function between planet diameter and its orbital
distance but also to make this function contains more variables – by that- if this
planet changes its orbital distance for any reason – the other variables will be
changed but the diameter will be saved - my fourth Equation proves this fact
(Planet Diameter Equation Analysis)

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F- The Sun Creation Process
F-1 Preface
F-2 The Historical Story
F-3- The Energy Reflection In Saturn (The Proves Discussion)
F-4 The Rate Of Time (1 Hour = Equal 24 Solar Days)
F-5 The Sun Creation Process Details

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F-1 Preface
- Planets Motions Data Understanding Difficulty
- There are 2 difficulties in the understanding of the planets motions data which are
- (1st
Difficulty)
- 2 planets move equal distances in defined periods of time – for example Pluto
moves in its day period (153.3 h) a distance = 2.598 million km = the moon
displacements total in the moon day period (29.53 days) = the Earth motion
distance in its day period (24 h) (error 1%)
- Why these 3 planets move equal distances in their days periods?
- This is not specific case – it's a usual behavior motion – for example
- Neptune moves in a solar day a distance = Jupiter motion distance in Jupiter day
period –
- Because we don't know why these planets move equal distances in defined periods
of time and we don't know the effect of this distances equality, as a result we miss
many basic points in the solar system motion understanding
- Imagine some engineer builds a lever by one board and some rock with some
measurements and calculations – but we don't understand the used geometrical rule
– by that we understand nothing of his work and we can't understand how he can
raise a heavy weight by using a small one –because the geometrical rule is absent
from us -
- Similar to that – we don't know why the planets move equal distances in defined
periods of time and by that basic points be missed in the understanding
- Notice
- Here we don't argue around the motion by the sun gravity according to Newton
theory – I have disproved Newton theory of the sun gravity since long time and I
have proved that no planet moves by the sun gravity - we here analyze the real
reason and mechanism of planet motion.

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- (2nd
Difficulty)
- The planet uses its diameter as a period of time – for example
- Jupiter (13.1 km/s) moves in 10921 sec a distance =142984 km = Jupiter diameter
- And
- Uranus (6.8 km/s) moves in 7510 sec a distance =51118 km= Uranus diameter
- Where
- 10921 km = The Earth Moon Circumference
- 7510 km = Pluto Circumference
- The using of the planets diameters and circumferences as periods of time is a
usual using in the solar system – we don't know why this using is important and
what effect it does on the planet motion –by that more basic points of the
understanding be missed from us.

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F-2 The Historical Story
- We need the historical story to understand the interaction of motions between
Mercury and the moon –this story is proved in Mars Migration Theory (No. 10) –
- (1)
- In ancient times – the inner planets had another order – they were as following
- Pluto- Mercury – One Planet – Mars – Venus – Earth…etc
- Mercury orbital distance was 58 million km and now be 57.9 million km
- Pluto was the Mercury moon revolves around it
- The (one planet) had an orbital distance = 71 million km
- Mars original orbital distance was = 84 million km
- Venus and Earth orbital distances didn’t change more than 2%
- Also - Mercury Axial Tilt was (one degree) – and now be (Zero degree)
- The historical events tell that
- Mars (by effect of Neptune) had been pushed strongly and collided with the one
planet (71 million km) and Mars had caused to break this planet and destroy it
- This collision reaction had pushed Mars to move in the opposite direction and by
that Mars had migrated from its original orbital distance and moved to its current
one (227.9 million km)
- While Mars had moved from (84 million km) to (227.9 million km), Mars had
collided with Venus and then with the Earth and by these collisions the Earth
moon be created – by that – Mars is the planet caused the moon creation.
- That answers why (Venus Does Have No Moon?), because Mars was pushed by
force in its motion and by that Mars had pushed all debris with it in its motion
direction – Venus had found no debris around and because of that Venus couldn't
create its own moon-
- The Earth gravity is greater than Venus and the debris lost some of their
momentum- for that – Earth could catch some debris from which the moon be
created

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- The rest debris had moved with Mars from which the 2 moons of Mars be created
and the rest debris be attracted by Jupiter gravity and created the asteroid belt.
- The collision between Mars and the (one planet which was on 71 million km)
caused an earthquake in the solar system-
- This earthquake caused 4 basic changes which are:
- (First change) Pluto which was the Mercury moon, be pushed strongly to the end
point of the solar system with orbital distance 5906 million km – (more details
later)
- (Second change) Mercury Axial Tilt be changed from (one degree) to be (Zero
degree) - This Caused A Final Change In The Mercury Motion – and Mercury can
move its original motion only if it can create (one degree) to be used in place of its
axial tilt.
- (Third change) Mercury orbital distance be changed from (58 million km) to be
(57.9 million km)
- (Fourth change) Mercury day period be changed from 4224 hours to be 4222.6 h
- (2)
- The Planets Migration Effect On Mercury Motion
- The basic difficulty of Mercury motion is the change in its axial tilt from (one
degree) to be (Zero) - because that caused a change in Mercury motion and this
change will be a final one and Mercury can't return again to its original motion
unless Mercury can find one degree to be used in place of its axial tilt
- (3)
- More Details
- Pluto was the Mercury moon and was pushed by the great force of the planets
collisions – by that – Pluto be thrown to the end point in the solar system – the
orbital distance 5906 million km –

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- In that time – Neptune was occupied this point (5906 million km) and because
Pluto was pushed by a great force – Pluto had collided with Neptune and pushed it
out of the orbit (5906 million km)
- That explains why Pluto eccentricity distance = Pluto Neptune distance =1410
million km –
- A great problem be created here because Neptune was pushed out of the orbit and
be in some area isn't designed in the original solar system design.
- Shortly
- Neptune needed energy to create its orbital distance (4495.1 million km)
- Later – Neptune had seized 14% of all energy of the solar system to build its
orbital circumference (28244 million km) – more details later.
- (4)
- The Sun Creation
- The previous events are done before the sun creation –
- We have 3 clear historical events be defined before the sun creation
- First – The Earth Moon Be Created – As A Result For Mars Migration
- Second – Saturn Be Created After The Earth Moon Creation
- Third – The Sun be Created Depends On Saturn Motion.
- (5)
- The sun rays energies be found by the planets motions energies total –
- No nuclear interactions be found inside the sun and causes the sun rays – this idea
is wrong –
- The fact is that – the planets motions energies be accumulated together on one
point and from this energy the sun rays be created –
- The sun science can be saved just we need to change the source of the sun rays
energy
- The basic method to create the sun rays is the energies accumulation – this is the
method – if no energies accumulation be found no sun rays can be produced

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- The rate of time (1 hour of Mercury = 24 hours of Pluto) causes to accumulate the
energy on Mercury point – that explains why the sun be created beside Mercury
directly
- The main force behind this story comes from Saturn because the energy be
reflected in Saturn and the reflection causes the rate (1 to 24) to be squared and
became (1 to 242
) and that means one hour of Mercury motion be = 24 solar days
of Saturn motion – by that the energy accumulation rate be doubled and the energy
be so great and enough to produce the sun rays.
- Please note,
- The sun rays creation from the planets motions energies isn't the most great thing
be happened in the solar system – because – the matter be created from the light
velocity 1160000 km/s, and the process produces the light velocity 300000 km/s as
a side product.
- Now in our universe no light its velocity be 1160000 km/s because this velocity be
consumed by the matter creation and produced only the velocity 300000 km/s as a
side product.
- If the situation be as this – no any new tree will be found and no any child can be
born!
- The new matter tells that, the velocity 1160000 km/s be produced also- and that
means – the planets energies accumulation isn't able to create the sun rays its
velocity 300000 km/s but also can create the original light beam its velocity
1160000 km/s from which the matter be created.

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F-3- The Energy Reflection In Saturn (The Proves Discussion)
- Data
- (1)
- Saturn and Jupiter uses the rate (r/s) in place of (s/r) in the planet diameter
equation (v1/v2)=(s/r) =I
- (2)
- Saturn Orbital Distance = Saturn Uranus Distance =1433 Million Km
- (3)
- 4900 days = The period Uranus needs to move a distance = its orbital distance
- And
- (10747 /9800) = (9800 /9007)
- (4)
- 2.41 million km= 1/(0.406 million km)
- And

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Discussion
- The data suggests the idea tells (the energy be reflected in Saturn), because the
data be used in reflected forms frequently around Saturn data
- First using we have seen in the planet diameter equation – we remember the
equation (v1/v2) = (s/r) =I
- V= planet velocity, r =planet diameter and s = planet rotation periods number in its
orbital period and I = planet orbital inclination
- The equation uses 2 planets velocities – all data be belonged to (v2) but the strange
planet uses the velocity (v1)
- While all planets from the Earth to Pluto use the equation perfectly only Saturn
and Jupiter uses the reflected rate (r/s) in place of the rate (s/r)
- There's no more explanation can be available except that – some reflection must be
done there –
- Data No. (2)
- Saturn Orbital Distance = Saturn Uranus Distance =1433 Million Km
- Why these distances be equal?
- There's a feeling that these distances be as similar to light beams and the light
beam be reflected inside Saturn –
- The data tells that, one light beam in a distance form (1433 million km) comes
from Uranus reaches Saturn and inside Saturn this light beam is reflected – now
the reflected light beam creates an angle =180 degrees with the original light beam
and because the reflection causes the energies to be equal the first light beam
(distance length) be = equal the reflected light beam (distance length) and by that
the 2 distances be equal one another
- Even if this idea be a strange one – the previous data supports it and that makes
many data to support the same conclusion.
-

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- Data no. (3)
- 4900 days = The period Uranus needs to move a distance = its orbital distance
- And
- (10747 /9800) = (9800 /9007)
- This data also supports the same conclusion because the values be reflected on
Saturn – what's used as distance for Jupiter (4900 million km = Jupiter orbital
circumference) be used as period for Uranus (4900 days)
- Where Uranus needs 4900 days to move a distance = Uranus orbital distance
- And Neptune needs 2x 4900 days to move a distance = Neptune orbital distance
- Also Pluto needs 3x 4900 days to move a distance = Pluto orbital distance
- Neptune and Pluto confirms the same using of the period of time
- Why the distance for Jupiter = a period for Uranus?
- Also
- Saturn itself use this same value as a period and as distance
- (10747 /9800) = (9800 /9007)
- Where
- 10747 days = Saturn Orbital Period
- 9007 million km = Saturn Orbital Circumference
- 9800 = 2 x 4900
- The data shows there's a real reason to conclude the idea (a reflection of energy
must be happened in Saturn)
- Data (4)
- And
- Where

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- 2.41 million km = The Moon Velocity Daily
- 2.082 million km = Mars Velocity Daily
- 0.4668 million km = Neptune Velocity Daily
- 0.406 million km = Pluto Velocity Daily
- The data tells there's some reason to create the reflected values based on the solar
day period
- Notice
- Venus velocity daily x Mars velocity daily = 2π million2
km per day
- Earth velocity daily x The moon velocity daily = 2π million2
km per day
- Mercury velocity daily x Ceres velocity daily = 2π million2
km per day
- I try to show that based on geometrical mechanism these velocities be created and
this mechanism takes into consideration the reflection of energy in Saturn.
-

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F-4 The Rate Of Time (1 Hour = Equal 24 Solar Days)
- Let's summarize the idea in following…
- The rate of time is a feature we have proved between Mercury and Pluto where
one hour of Mercury motion = 24 hours of Pluto motion and this rate be used
generally where (one hour of Mercury motion be =24 hours of any planet motion)
- As a result
- one hour of Mercury motion be should be = 24 hours of Saturn motion
- But
- The energy is reflected in Saturn and by that the reflected energy caused to square
the rate (1 to 24) and by that 1 hour of Mercury motion be = 242
hours of Saturn
motion.
- Means
- 1 hour of Mercury motion be = 24 solar days of Saturn motion
- Here Saturn provides a greater rate of time any by that more energy can be
accumulated – means – the accumulated energy doesn't depend only on (1 to 24)
but depend on (1 to 276), that shows a great rate of time and a great accumulation
of energy.
- Shortly
- This is the idea – if it's a fact we have to find this rate in the data
- Let's see the data

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- Data
- (1)
- In 6939.75 days Mercury passes 28244 million km but Saturn passes this distance
28244 million km in a period = 33705 days
- 33705 = (24) x 1407.6
- And
- 6939.75 days = 58.65 days x 118.3
- (2)
- 10 x 33705 x 0.3 million km/s = 100733 million km
- (3)
- 576 = 365.25 x 1.6 = 61 x 9.44
Discussion
- Data no.(1) tells
- Saturn moves 28244 million km in a period = 33705 days but when 1 hour of
Mercury = 24 days of Saturn, this period will be 1407.6 hours for Mercury =
Mercury rotation period (58.65 solar days)
- Means Mercury rotation period be 1407.6 hours passes on Mercury as this period
but passes on Saturn as 33705 solar days during this period Saturn moves a
distance = 28244 million km = Neptune orbital circumference
- Mercury passes this same distance (28244 million km) in a period =6939.75 days
(Metonic Cycle)
- 6939.75 days = 56.8 days x 118.3
- Where
- Neptune axial tilt 28.3 degrees + 90 degrees = 118.3
- The data tells there's a reason to consider this rate (1 to 242
) or (1 to 576 ) is a real
one
- Data no. (2)
- 10 x 33705 x 0.3 million km/s = 100733 million km

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- Where
- 300000 km/s = Light Known Velocity
- We should keep our eyes on the rate (10) we need it in the next point discussion
(point no.F-5)
- This data depends on the value (33705 = 24 x 24 x 58.65)
- Light known velocity (300000 km/s) travels during a the period 337050 a distance
= The Planets Orbital Circumferences Total
- The data tells this period isn't common one – there's a geometrical reason behind
its using.
- Data No. (3)
- 576 = 365.25 x 1.6 = 61 x 9.44
- The rate (242
= 576) be used for Saturn data clearly
- Where
- 365.25 days = Earth Orbital Period
- 1.6 = Mercury and the Earth velocities rate
- 61 = Saturn orbital period / Mercury orbital period
- 9.44 = Saturn orbital distance /Earth orbital distance

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F-5 The Sun Creation Process Details
- Historically, the events should be ordered as following
- Mars Migration Event (and Pluto Migration also)
- The Moon Creation As A Result For Mars Migration
- Saturn Creation After The Moon Creation
- The Sun Creation After Saturn Creation.
- The concept behind the sun creation be the planets motions energies accumulation,
by this method the energy be enough to create the sun rays-
- The energy accumulation depends on the rate of time between Mercury on one
side and Pluto on the other side where 1 h of Mercury =24 h of Pluto
- Pluto rate of time controls all other planets and as a result
- One hour of Mercury motion be = 24 hours of any other planet motion –
- The rate (1 to 24) be produced by the interaction between light supposed velocity
1160000 km/s and the light known velocity 300000 km based on the following
data ((1.16/0.3) x 2π =24.3), this data tells the motions trajectories should be in
circular and elliptical forms and also tells the rate (1 hour =24 hour) should be
created among the planets.
- The happy news come from the beautiful Saturn, because the energy which be sent
from Pluto to Mercury based on the rate of time (1 =24) this energy be reflected
inside Saturn matter body and the reflected light beam creates an angle 180
degrees with the original one – for that reason Saturn orbital distance = Saturn
Uranus distance.
- The sun creation process discussion be divided into the following points
- F-3-i Preface
- F-3-ii Saturn Role In The Sun Creation Process
- F-3-iii The Sun Creation Details
- F-3-iv The Sun Life Cycle

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F-3-i Preface
- Let's Summarize The Idea Of The Sun Creation Depends On The Planets Motions
In Following…
- The fact which be proved is the rate of time between the planets- where – one hour
of Mercury motion be = 24 hours of Pluto motion
- that causes (One hour of Mercury motion be = 24 hours of any planet motion,
- this fact be proved by planet diameter equation (my 4th
equation) and based on it
many conclusions be concluded…
- Also, we have discussed the real effect of the rate of time on the planets data,
because the planets be created from one energy (or one light beam energy) and by
that the energy be moved from Mercury to Pluto (or vice versa), means, the energy
be in a continuum form transports from a planet to another and the classical vision
of the planets as rigid bodies separated from one another be removed now – where
we accept that the planets are geometrical points found on the same trajectory of
energy (or on the same light beam).
- The rate of time controls the amount of energy be transported from a planet to
another – that makes the rate of time as a strong force effect on the data – imagine
you control the amount of money be paid for the workers – by that you effect
greatly on them
- That shows the rate of time effect on the planets data and this effect passes through
all planets and depends on this effect planet diameter equation (my 4th
equation)
depends
- The real machine shows that
- The energy be moves from Pluto to Mercury based on this rate of time (one hour
of Mercury motion = 24 hours of Pluto motion)
- Pluto motion energy be sent to Mercury based on this rate – and all planets
motions energies be sent to Mercury based on this rate – by that Mercury be the
point on which the energy be accumulated.

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- For that reason Mercury day period should be 176 days because the 9 planets
velocities total be = 176 km/sec – by that Mercury day period should express the
planets velocities total – the geometrical rule is still unknown but the data shows
the fact.
- We need to create the sun from this accumulated energy
- But
- Neptune binds Mercury by some force and by that the value (176) be decreased to
be (175.94) where the energy be used based on the quantum – the small difference
caused to prevent the process.
- Shortly
- The energy is not enough to create the sun rays and for that no sun rays be created
- 2 helper players be added later – the Earth moon and Saturn
- The Earth moon velocity should be = the Earth velocity because they aren't
separated from one another through their revolutions around the sun - and because
the moon motion be used as the base of the planet diameter equation (my 4th
equation) that causes the Earth moon velocity to be added to the 9 planets as one
of them – the total velocity be 205.8 km/s
- Saturn caused the energy to be reflected – means – the energy be sent from Pluto
to Mercury be reflected in Saturn that causes the rate (24) to be squared (24)2
,
means, 1 hour of Mercury Motion be = 24 solar days of Saturn motion
- The new rate causes to accumulate a great amount of energy –by this energy the
sun rays be created -
- In following we discuss the process in details.

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F-3-ii Saturn Role In The Sun Creation Process
- Data
- (1)
- 1.16 million km /s x 10.7 h x 2 x 3600 s = 90000 million km
- (2)
- 5.4 km/s x 10.7 h x 2 x 3600 s = 416000 km
- 4.7 km/s x 10.7 h x 2 x 3600 s = 362100 km
- 29.8 km/s x 10.7 h x 2 x 3600 s = 2295792 km
- (3)
- 35 km/s x 10.7 h x 2 x 3600 s = 2700000 km
- But (103944/2.7) = (38500)
Discussion
- Data No (1)
- 1.16 million km /s x 10.7 h x 2 x 3600 s = 90000 million km
- The data tries to show the using of Saturn day period (10.7 hours) in the sun
creation process.
- The sun creation depends on the energy of the distance 90000 million km – this is
the energy from which the sun be created – we discuss that in the next point no. (F-
5)
- The data shows light supposed velocity (1160000km/s) travels this distance
90000millionkm during 2 x 10.7 hours (where 10.7 hours = Saturn day period)
- That shows clear using for Saturn data in the sun creation process
- Data No (2)
- 5.4 km/s x 10.7 h x 2 x 3600 s = 416000 km
- 4.7 km/s x 10.7 h x 2 x 3600 s = 362100 km
- 29.8 km/s x 10.7 h x 2 x 3600 s = 2295792 km

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- This data tells,
- Neptune (5.4 km/s) moves during the same period (2 x 10.7 h) a distance = 416000
km – this is the supposed apogee radius in the moon motion – because the moon
daily displacement be 88000 km and during 29.53 days the total displacements be
= 2.598 million km = 2π x 413600 km
- The data tells, the moon orbital apogee radius should be 413600 km – we have
discussed that before
- Neptune moves 416000 km (error less 1%) –
- And
- Pluto (4.7 km/s) moves during the same period (2 x 10.7h) a distance = 362100 km
where 363000 km = the moon orbital perigee radius (no error)
- And
- Earth (29.8 km/s) moves during the same period (2 x 10.7h) a distance =
2295792km = the moon orbital perigee circumference
- Here we deal with a system of data depends on the period (2 x 10.7 hours)
- Data No. (3)
- 35 km/s x 10.7 h x 2 x 3600 s = 2700000 km
- But (103944/2.7) = (38500)
- Where
= the moon orbit area
- 38500 seconds = 10.7 hours (Saturn day period)
- It's very hard to explain how this data be created – but– we see many basic motions
depend on 2 x Saturn day period – that shows Saturn is a basic player in these
motions.
- We have to notice that the moon is a basic player with Saturn also- that shows the
reason behind the consistency of Saturn and the moon data

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F-3-iii The Sun Creation Details
- Data
- (1)
- 90000 million km = C2
for one second
- (2)
- 90000 million km = 0.838 million km x 10747 days x 10
- (3)
- 2579280 hours = 10747 days x 24 hours x 10
- (4)
- 118.3/1.8 = (708.7/10.7) = (655.7/9.9) = 66.2 (error 1%)
- (5)
- 90000 million km = 2872 million km x 31
Data Analysis
- Data No. (1)
- 90000 million km = C2
for one second
- This data tells the value C2
be = 90000 million km if we use one second of time,
that means, we see a distance =90000 million km but it's in fact an energy = C2
from this energy the sun be created.
- The one second is used for the solar system geometrical design because the rate of
time depends on one second of light motion
- By that, the distance 90000 million km be the source of the sun rays energy
Data No. (2)
- 90000 million km = 0.838 million km x 10747 days x 10
- Shortly
- Saturn orbital circumference be = 9000 million km – so we need only (10) to reach
to the required distance 90000 million km – the point is that – the rate (10) be used
with Saturn data frequently –

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- We have seen this rate (10) in the previous point discussion.
- Data (3)
- 2579280 hours = 10747 days x 24 hours x 10
- This is a complex data
- Because
- If 1 hour = 1 km we will reach to the distance 2579280 km
- This distance is so specific because
- The moon displacements total in 29.53 days be = 2598693 km
- Pluto motion distance in its day period (153.3 hours) be = 2598693 km
- Earth motion distance in its day period (24 hours) be = 2579280 km
- Also
- Uranus moves in 378675 seconds a distance = 2579280 km
- (378675 km = Saturn Circumference)
- This data is a player in the sun creation
- But it's hard to be explained
- Data no. (4)
- 118.3/1.8 = (708.7/10.7) = (655.7/9.9) = 66.2 (error 1%)
- Where
- 118.3 degrees = 90 degrees + 28.3 degrees (Neptune Axial Tilt)
- 1.8 degrees = Neptune Orbital Inclination
- 708.7 h = The Moon Day Period
- 9.9 h = Jupiter rotation period
- 655.7 h = The Moon Rotation Period

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- Data no. (5)
- 90000 million km = 2872 million km x 31
- 2872 million km = Uranus Orbital Distance
- And
- 31 = Uranus axial tilt 97.8 deg/ Jupiter axial tilt 3.1 deg
Notice
Saturn moves during 5.2 days a distance = 4.37 million km = the sun circumference
Discussion
- There's a deep interaction between the moon and Saturn motion – by that Saturn
rate (24)2
be used practically through the moon and earth – by that-
- The basic rate of time is (1 day of the sun = 365.25 days of the Earth), based on
this rate – the planets velocities total be = 75000 km/sec = (a quarter of the light
velocity 300000 km/s)
- For that reason the Earth needs its 4 years cycle (365 +365 +365 +366 =1461 days)
by this cycle the quarter (1/4) became one (1) and by that the planets motions
distances total during 4 years (including the moon) = the light motion distance
during one solar day (light known velocity 300000 km/s)
- That shows how this rate be used practically
- Please notice,
- When we talk about the Earth we should remember the moon, because the moon is
connected with Venus and Mercury and also with Saturn and by that the moon can
add to the Earth more features of motion – for example the moon moves Metonic
Cycle which the Earth doesn't move – also the moon uses Pythagorean rule which
be inherited from Venus but the Earth doesn't use this behavior of motion.
- That also explain why the moon and Saturn use the period 10747 days (Saturn
orbital period) where the moon displacements total in 10747 days be = 940
million km = the Earth orbital circumference around the sun

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F-3-iv The Sun Life Cycle
- The previous analysis and discussion has tried to explain the basic idea that (the
sun rays energy be created by the planets motions energies accumulation)
- By that the sun existence depends on a cycle because the planets move in cycles
and by that the sun energy isn't stored inside the sun body and we should account
the consumption amount – instead – it's a cycle of motion –
- Means,
- The sun be a phenomenon as any other phenomenon– for example – the eclipse is
a phenomenon be done based on a cycle with defined periods of time – the sun be
similar to that and it be a phenomenon be occurred based on a cycle and a defined
period of time
- I can say that – the sun life depends on a cycle –means - the sun creation and
death depends on a cycle and a defined period oftime2 and after the sun death a
new sun be created because it's a cycle
- I also can refer to the cycle 2737 years as the cycle which be related directly to the
sun creation and death.
- The cycle 2737 years I have discussed in my previous papers- this cycle depends
on Metonic Cycle.

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Paper Part No. Two
(Pages from 216 to 760)
This Part Proves That,
The Solar System Be Built On One Design, Because
The Planets Matters And Their Distances Be Created From The Same One
Energy

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3- One Geometrical Design Be Found Behind The Solar System
3-1 Preface
3-2 The One Geometrical Design Proves
3-3 The One Geometrical Design Reason
3-4 The Planet Motion Trajectory Analysis
3-5 The One Geometrical Design Discussion
3-6 The One Geometrical Design Result

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3-1 Preface
Let's remember the paper basic points
(1)
Planet data be created based on exact equations as Plane specifications be defined by
exact equations –
(2)
The planet data exact equations depend on one geometrical design found behind the
solar system – (The one geometrical design be discussed in this current point no. 3)
(3)
One Geometrical Design be found behind the solar system because the planets matters
and their distances be created of the same one energy – be discussed also in this
current point no. (3)
(4)
The Solar System One Energy Be Provided By One Light Beam (Point no.4)
(5)
This light beam travels with a velocity 1.16 million km per second (Point no. 4)
In this current point we discuss the one geometrical design which be found behind the
solar system and was found before the solar system creation.

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3-2 The One Geometrical Design Proves
There are 4 proves for the one geometrical design theory which are
(1)
My 5 equations proves (Planet Data Be Created Based On Exact Equations)
(2)
The planet motion analysis proves that one geometrical design be found behind the
solar system
(3)
The distances are one Network proves one geometrical design be found behind the
solar system
(4)
The eclipse analysis proves one geometrical design be found behind the solar system
Let's study these proves in following

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(Proof No. 1) (My 5 Equations)
The idea tells
Planet data be similar to a plane specifications which be defined by exact equations –
In plane or rocket creation the maker needs exact equations for this plane length,
width, …etc all specifications need exact equations
The Planet data be similar to that and depends on exact equations –means
Planet mass, diameter, orbital distance, period, inclination, rotation period and axial
tilt –all data be created based on exact equations – for that reason – we can conclude
this data by mathematical calculations only –
My 5 equations enable us to conclude the planet data by mathematical calculations
only and that prove the idea (planet data be created based on exact equations)
My 5 equations are
- (1) Planet Orbital Distance Equation
- d2
= 4 d0 (d-d0)
- (2) Planet Velocity Equation
- (V0
2
/ V2
) = 4 (1- (V2
/ V0
2
))
- V = Planet Velocity
- (3) Planet orbital distance and velocity equation (Kepler law)
- (d1/ d2) = (v2/v1)2
- d = Planet Orbital Distance
- (4) Planet Diameter Definition Equation
- (v1/v2) = (s/r)= I

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- (5) Planet Velocity Is A Complementary One
- vt = 322 km
- t = another planet velocity be used as a period of time
Example

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(Proof No. 2) (Planet Motion Analysis)
We accepted that, One Force Should Cause The Planet Creation And Motion, this
idea disproves Newton theory of the sun gravity in its logic –
That tells Newton was so wrong in thinking –
Because if 2 forces effect on the planet creation and motion – this planet will be
broken – that necessitates to have one force only caused the planet creation and
motion-
The sun caused no planet to be created and for that the sun causes no planet motion
This analysis gives us a good vision about the planet motion
The planet creation and motion data be in harmony because they be created by one
force only
The next question should be about how many forces be found in the solar system - of
course we have NOT one force for each planet – we have one force for all planets
creation and motion –
Now we have one force caused all planets creation and motion – and that tells all
planets data be created based on one law –
Can that be possible without geometrical design? How can one force create 9 planets
and cause their motions with their moons? This one force needs one geometrical
design to perform this great job
That tells the planets motions prove that one geometrical design must be found behind
their creation and motion.

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(Proof No. 3) (The Distances Are One Network)
The solar system distances be created as one group and in one network form –means –
The solar system distances be similar to the chess board distances - No one distance
be created individually or independently – The planets data proves this fact.
Data
(1)
1.16 x 580 mkm = 671 mkm (Venus Jupiter Distance)
1.16 x 671 mkm = 778.6 mkm (Jupiter Orbital Distance)
1.16 x 629 mkm = 720.7 mkm (Mercury Jupiter Distance)
1.16 x 542 mkm = 629 mkm (Earth Jupiter Distance)
1.16 x 5127 mkm = 5906 mkm (Pluto Orbital Distance)
(2)
1.16 x 778.6 mkm x 2 = 1806 mkm
1.16 x 1806 mkm = 2094 mkm (Jupiter Uranus Distance)
1.16 x 2094 mkm = 2 x 1205 mkm (Mars Saturn Distance)
(3)
(1.16)2
x 170 mkm = 227.9 mkm (Mars Orbital Distance)
Where 170 mkm = Mercury mars Distance
(5)
1.16 x 1980 mkm = 2296.8 mkm
1.16 x 2296.8 mkm = 2644.6 mkm (Mars Uranus Distance)
1.16 x 2644.5 mkm = 3033.5 mkm (Uranus Pluto Distance)
(6)
778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm
720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm
Notice/ 1.16 =(1.0725)2
(Data Max Error 1%)

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- The rate 1.16 be a rate between many of the solar system distances – it shows the
distances be created as one group based on one geometrical design
- Also the rate 0.3 be used among many other distances –
- This data can be understood if we suppose that
- (1) (The light 300000 km/s uses distances as periods of time to create more
distances in the same network) and
- (2) (A light beam its velocity 1.16 million km per second be found)
- The data will be explained as following…
- Light (1160000 km/s) travels during 671 seconds a distance = 778.6 million km
- Light (1160000 km/s) travels during 629 seconds a distance = 720.7 million km
- Light (1160000 km/s) travels during 940 seconds a distance = 2 x550 million km
- All other distances be similar to that….
- Also
- Light (300000 km/s) travels during 2094 seconds a distance =629 million km
- (2094 million km = Jupiter Uranus Distance) and (629 million km = Jupiter Earth
Distance)
- And
- Light (300000 km/s) travels during 2723 s x 2 a distance =1622 million km
- (2723 million km = Uranus Earth Distance) and (1622 million km = Uranus
Neptune Distance)
- I try to show, It's a behavior of light motion to create the distances depend on one
another in a network form – the hypothesis be about the velocity (1160000km/s) to
be proved in our discussion because it be found in the data in massive using.
- Shortly
- Whatsoever the explanation of the data the rate (1.16) and (0.3) proves that the
distances be created in one group and in one a network form.

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(Proof No. 4) The Solar Eclipse Occurrence
(The sun diameter/ the moon diameter) = (Earth orbital distance / Earth moon distance)
And
Jupiter orbital distance = 5.2 x Earth orbital distance = 10921 km x Jupiter Radius
And
Jupiter (13.1km/s) moves during 10921 s a distance = 142984 km = Jupiter diameter
Can we can understand this data?
Jupiter (13.1 km/s) uses a period (10921 s) to pass a distance = 142984 km= Jupiter
diameter – for some wonder the moon circumference =10921 km (where 1 km= 1 sec)
But
Jupiter Circumference (449197 km) x 10921 km = 4900 million km = Jupiter Orbital
Circumference = The Sun Diameter x The Moon Diameter
(Jupiter diameter x π2
= the sun diameter – error 1.4%)
Nothing be created by pure coincidence
Based on a geometrical rule the total solar eclipse be occurred but we don't know this
geometrical rule– the data tells –Each planet motion takes into consideration the other
planets motions.
I want to say,
The phenomenon (eclipse in our example) is mentioned in the planet motion – the
previous data shows that the moon diameter be 3475 km because of the total solar
eclipse which is a conspiracy be planned by the sun, Earth, the moon and even Jupiter.
Later we should deepen our understanding for this point.

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3-3 The One Geometrical Design Reason
The One Geometrical Design depends on One Energy be used to create The
Solar System -
Let's summarize the idea in following
(1)
The planet data be created based on exact equations similar to any plane or rocket
creation– As a planet maker needs exact equations to define its length, width and all
its specifications – similar to that –Planet data be created based on exact equations –
by that – Planet data can be concluded by mathematical calculations –
My 5 Equations Prove This Fact
How Can Planet Data Be Created Based On Exact Equations?
Because
One Geometrical Design Be Found Behind The Solar System
This fact be proved by our previous discussion and data –
But
How Can One Geometrical Design Be Found Behind The Solar System?
If the solar planets matters and their distances be created from One Energy – and this
energy was under A Geometrical Design - That can create (One Geometrical Design
Behind The Solar System)
Do we know any energy in a geometrical design?
We can think about a river – the water is energy moves in geometrical design –
A light beam is similar also – Almost all known energies be in geometrical designs
Let's examine this idea deeply – it's a simple idea
The physics book accepts that (Matter And Space Be Created Of Energies)
My addition is one idea tells …
From The Same One Energy all planets matters and distances be created
We need to prove this interesting idea

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Let's examine it before
Suppose from the same energy all planets matters and distances be created can that
cause one geometrical design to be found behind the solar system
Of course yes
The double production answers clearly
From gamma ray one electron and one positron be created – the particles move by one
law – why?? because they be created from the same one energy
Gamma ray charge is Zero, for that the 2 particles charges total is Zero
One law controls the 2 particles creation and motion data
If all planets be created from the same one energy – one law should control all planets
creations and motions data
It's a clear and trustee conclusion
Let's prove the idea in following…
The Proves
(I) The Type of Creation Proves One Energy Be Found Behind The Solar System
(II) The Solar System Distances Be Created In A Network Form
(III) There's A Continuum In The Solar System
(IV) The One Geometrical Design Depends On One Energy
(V) Light motion features be discovered in planet motion, proving, light motion be
found behind the planet motion and shows that the one energy is a light beam energy
Let's examine these proves in details in following…

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(Proof No. I) The Type Of Creation
From Gamma Ray One Electron And One Positron Be Created – We Know That The
2 Particles Be Created Of Gamma (Zero Charge) Because Their Charges Total Be
Equal (Zero)
The Male And Female Creature Refer To A Similar Type Of Creation Tells That
Almost One Energy Be Found Behind Both Because One Law Control The 2
Creatures
Because the type of creation is almost similar – we can guess that – the solar system
be created of one energy
Means
The planets matters and their distances be created of the same one energy
(Proof No. II) The Solar System Distances Be In A Network Form
We Have Studied This Proof Among The One Geometrical Design Proves

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(Proof No. III) There's A Continuum In The Solar System
The continuum is a force effected on wide range of data – as in the next example
Example / (the rate 1.0725)
This rate effect on a wide range of data in the solar system –among which -
(A)
40% of all distances be rated by (1.0725) –
Jupiter Distances Can Be Used As Example – We Have Discussed Them Among The
One Geometrical Design Proves. Let's remember some of them here –
778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm
720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm
(B)
The rate (1.0725) effects on 50% of All Planets Axial Tilts
(28.3/26.7) = (26.7/25.2) = (25.2/23.4) = (122.5/113.4) = ( 97.8 /91.3) = 1.0725
28.3 degrees = Neptune Axial Tilt 26.7 degrees = Saturn Axial Tilt
25.2 degrees = Mars Axial Tilt 23.4 degrees = Earth Axial Tilt
122.5 degrees = Pluto Axial Tilt 97.8 degrees = Uranus Axial Tilt
91.3 degrees = 90 degrees + 1.3 degrees (Jupiter Orbital Inclination)
113.4 degrees = 90 degrees + 23.4 degrees (Earth Axial Tilt)
(C)
The rate (1.0725) effects on different cycles periods
(29.53 days /27.3 days) = (224.7 days /243 days) =1.0725
29.53 days = the moon day period, 27.3 days = the moon orbital period,
224.7 days = Venus orbital Period 243 days = Venus rotation period.
We can explain the continuum effect only based on one energy idea – means-
Because the solar system be created from one energy and this energy had a continuum
a wide range of data be effected by this continuum which be seen in data wide range.

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(Proof No. IV) The One Geometrical Design Depends On One Energy
We have at least 2 basic proves for the one geometrical design – which are –
(1)
Planet data be created based on exact equations – as we have discussed – and my 5
equations prove this fact (the 5 equation be tested in Point no. A)
(2)
Planet motion analysis proves one geometrical design be found behind.
Because
We accepted that (Newton Theory Of The Sun Gravity Is Wrong In Logic) basically
because – The planet should be created and moving by the same one force – means-
the force which created the planet it causes its motion – otherwise this planet will be
broken because 2 forces effect on it-
That tells, No planet moves by the sun gravity, because no planet be created by the
sun gravity effect.
But - There are no 9 forces to cause the 9 planets creations and motions - instead –
it's just one force causes all planets creation and motion – this vision tells– this one
force uses a geometrical design to cause the planets creation and motion.
Briefly
One force causes all planets creation and motion by using One Geometrical Design
to do these 2 jobs (the creation and motion)
The one geometrical design – which is necessary for planets motions be a proof for
the one energy be found behind it.

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(Proof No. V) Light Motion Features Be Discovered In Planet Motion
These features prove, Light motion be found behind the planet motion and shows that
the One Energy is A Light Beam Energy.
The idea simply tells
From one light beam energy All Solar Planets Matters And Distances be created
This is the fact behind all our discussions – but I have tried to provide it in detailed
points to make it as acceptable as possible
The question always be (Can Matter And Space Be Created Of Light Energy?)
From Gamma ray an electron and a positron be created – that may prove the idea
The point is that –
Light motion features be discovered frequently in planets motions – and by that- the
solar system motion can't be explained by the classical mechanics science
I want to say,
The one geometrical design is a fact and not just a conclusion – we will study it in
details – But this geometrical design be created based on light motion – we have to
accept that the planets matters and distances be created of one light beam energy.
Also
We have to accept one more hypothesis tells:
From One light beam energy all planets matters and distances be created –And This
light beam travels with a velocity 1.16 million km per second
The velocity be registered in the planets data and we can examine the solar system
geometrical design only by using this supposed velocity.

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3-4 The Planet Motion Trajectory Analysis
We have 2 different ways of thinking – Kepler way of thinking which is correct – and
my way of thinking which needs to be tested
Kepler have seen the planets motions be done in defined clear trajectories be in
elliptical forms – here the trajectory be seen as 2 points (start and end) while the
trajectory form be in elliptical form -
In this way of thinking – kepler doesn't consider any phenomenon as effective of the
type of motion – for example – If the moon does a total solar eclipse – this eclipse
phenomenon can't effect on the moon motion trajectory but the trajectory will be the
same one with the eclipse and without eclipse – the eclipse here is an additional
phenomenon can't effect on the moon motion trajectory
I have a different idea –
I suppose the planet moves in steps – the moon needs to cause the eclipse to complete
its revolution around the Earth – if the eclipse wasn't found the moon can't complete
its revolution motion – it's my idea – by that I see the motion trajectory as integration
for small parts of motions – not necessary to be similar to each other – instead – small
parts of distances different from one another be integrated together to create the moon
motion trajectory – let's try to draw that in following
In the figure – the black trajectory is planet
motion according to Kepler
The blue trajectory is the planet motion by
my idea – the planet moves from one point
to another (step by step) because the
motion depends on phenomena as eclipses,
alignments and perpendicularity.

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The difficulty here is the question how to deal with this situation
If we accept Kepler trajectory – we will consider all phenomena as additional effects
have no role in the planets motions – and that will cause to suppose thousands of data
be created by pure coincidences of numbers. Also we will not use all phenomenon at
all – means shortly – if all eclipses, alignments and perpendicularities be removed
nothing will change in the moon motion trajectory – this idea I can't accept-
It's wrong idea – and these phenomena have effects on the planet motion –
But
If we insist on the phenomenon effect on the planet motion we will reach to a question
about Kepler trajectory – which is correct and trustee –
There's some solution for this dilemma – we should search for
And
We should keep in mind the difference between the 2 types of motion –
Kepler tells (Planet Moves In Revolution As One Piece Of Motion)
And my idea tells (Planet moves from point to another point and the revolution is the
summation of these points)
Kepler told, the car has enough fuel to complete the track as one piece
But my idea tells
The car has to stop in each point to refuel again before to complete its track-
Each phenomenon has effect on the planet motion –
This is the question we keep in minds and search for its answer
Notice
Because of the light motion effect on planet motion our discussion can find acceptable
solution for the 2 types of motions trajectories –
That means- Kepler is correct and may be my idea correct also but the answer be
provided by light motion effect on planet motion which we discuss in the next point
No. (2-5 The One Geometrical Design Discussion)

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3-5 The One Geometrical Design Discussion
Data
(A)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
Where
0.6 million km/s = 2 x 0.3 million km/s (Light Velocity)
(B)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
6.8 km/s = Uranus Velocity
(C)
Jupiter Orbital Circumference = 4900 million km
(D)
Light (300000 km/s) travels during 16330 sec a distance = 4900 million km
Light (1160000 km/s) travels during 4222.6 sec a distance = 4900 million km
16330 hours = Mars orbital period and 4222.6 hours = Mercury Day period

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Discussion
The paper discusses in details the solar system one geometrical design – and our
discussion here is just a small reference about it –
The selected data tried to show that, the solar system is one geometrical design
depends on the distance 4900 million km (= Jupiter orbital circumference)
We remember this distance in the eclipse phenomenon discussion - where
4900 million km = the sun diameter x the moon diameter = Jupiter circumference x
the moon circumference – we don't discuss the eclipse here –
Shortly
The solar system is one building an its structure depends on this distance 4900 million
km – each planet be similar to a story in the same building – but
The 2 main players in the solar system one design are (Jupiter and Uranus)
The previous data tried to prove this fact –
Data No. (A) shows the planets orbital circumferences and periods total depend on the
2 planets (Jupiter and Uranus) velocities in comparison with the 2 velocities of light
(the known velocity 300000km/s and the supposed velocity 1160000 km/s)
Data No. (B) shows that, the rate of velocities between (Jupiter and Uranus) be used
also by (Mars and Mercury) and by (Venus and Ceres) – But
No any couple can be replaced in place of (Jupiter and Uranus) in Data no. (A) – that
shows, the planets orbital circumferences and periods be related to (Jupiter and
Uranus) velocities and not to any other couple of planets – they are the 2 basic players
in the design structure -
(In fact there are so many other reasons to support this conclusion by I limit my
discussion for the provided)
Now let's return again the most important distance (4900 million km)
Data No. (D) shows that, Mars and Mercury Cycles Periods be used by light motion
based on the rate (1 hour of planet motion be = 1 second of light motion) –the 2
planets cycles periods be used by the same rate –

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Data no. (C) tells one more interesting data
The distance of Jupiter (4900 million km = Jupiter Orbital Circumference) be used as
a period of time for Uranus (4900 days!)
And to create a confidence in the conclusion – Neptune and Pluto use this rule also
Neptune needs (2 x 4900 solar days) to pass its orbital distance (error 1.8%) and
Neptune needs (3 x 4900 solar days) to pass its orbital distance (error 1 %)
It's hard to suppose (Pure Coincidence) behind this data!
The explanation is so hard
The light beam can use the distance as a period of time – means- only the light motion
can solve this question – Jupiter distance be used as periods for (Uranus, Neptune and
Pluto)!
Can A Reflection Of Energy Be Caused This Result?
Saturn gives us a piece of gold in its data – let's look at it
(10747 /9800) = (9800/9007) where
9007 million km = Saturn Orbital Circumference
9800 = 2 x 4900
Saturn simply uses (4900) as a period and as a distance
The simple idea tells that
The solar system is one light beam and some reflection be happened at Saturn for that
reason the data before Saturn be reflected on the data after Saturn.
Notice
The discussion isn't clear because the data be created based on geometrical rules but
we don't know these geometrical rules – for that reason the data be created based on
each other but we can't catch its geometrical rule
The data tells we deal with one trajectory of motion – one energy – one light beam –
One Stream Of Data – Mercury day period isn't strange from Mars orbital period –
there's some connection – we don't know what's it but we can prove it's found.

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Imagine you read a family tree –
While you read – you catch similar names – you aren't sure if they are different
persons or not – you can't catch perfectly how they are relatives to one another but
you know they are one family.
It's one stream of energy – it's one light beam from which the solar planets and their
distances be created.
In the paper I provide in Point no. (4) tenths of groups of data depend on light both
velocities (300000 km/s and 1160000 km/s) and I argue that this data be in harmony
with the 2 velocities because the 2 velocities are real and the data be created
depending on them.
(As we have seen in Jupiter distances which be created based on the rate 1.16)
Notice
This distance is still more important than what I have written – it has tenths of effects
on the solar system data- especially because
37100 million km – 4900 million km = 32200 million km
32200 million km x π = 100733 million km (The planets orbital circumferences total)
(37100 million km = Pluto Orbital Circumference)
Means
The distance 4900 million km be created based on a geometrical necessity because it's
the rate between the planets orbital circumferences total and Pluto orbital
circumference – and these 2 values must depend on one another because the distances
can't be beyond Pluto Position.
Let's refer to the matter creation process in following

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Matter Creation Process
- The matter is created out of light beam, by that, the matter and space be created
together of this light beam energy and the matter doesn't separate from its parent
light but move together one unified motion by using different rates of time, by that
the matter be movable by nature because it be created out of light beam
- For the solar system –
- The solar planets matters and their distances be created out of one light beam
energy – by that – this light beam provided the required energy to create the
planets matters and their distances – that also can explain how the energy be
distributed based on a geometrical design and not in chaos form – also – the most
important is that – the light velocity be registered in the produced matters and
distances because the energy be provided by it.
- By this idea the solar planets be similar to ships sail over a sea, where the sea is the
light motion –
- Let's Ask
- Why Be All Motions In The Universe In Circular Forms?
- The solar system (planets matters and distances) be created of energy of one light
beam its velocity 1.16 million km per second – but
- The matter creation consumed the energy of this light beam – means –
- The matter creation process INPUT was the light beam with velocity 1.16 million
km per second - and the creation process OUTPUT was (matter + space+ light
beam with velocity 300000 km/sec)
- Here the light known velocity (300000 km/sec) be created as a side product in the
matter creation
- The next calculation can tell what's happened…
- (1.16/0.3) x 2π = 24.3
- Where
- 24.3 refers to (24 hours = the solar day) (error 1%)

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- 1.16 and 0.3 are the 2 light beam velocities –
- But
- What's this rate (2π)??
- This rate (2π) is the reason of all circular motions in the universe – while – the
light moves in a straight lines – and the born matter should move with its parent
light beam in straight lines – the production of the light known velocity (300000
km/s) caused the straight line trajectory of motion to be in circular trajectory and
that causes the planets motions trajectories to be in elliptical forms –
- We should notice that – the matter creation is a process done for one time – and
the light known velocity (300000 km/s) be produced as a side product also for one
time only – after the creation – the light (300000 km/s) travels and the matter be
created forever – because
- The matter can't return again into its original light beam form because a part of the
energy be traveled already which is the light known velocity – means –
- The input was a light beam its velocity 1.16 million km per second (Energy =E)
and the output was (matter + space + light known velocity) (Energy = E)
- But
- The light known velocity (300000 km/s) be traveled and disappeared by that the
total energy be less than (E) and by that the energy in the matter be a prisoner in
this matter forever
- The light known velocity (300000 km/s) traveled and caused to decrease the total
energy (E) and also caused the motion trajectories to be in circular or elliptical
forms in place of the straight line forms.
- Let's try to see this picture – after the matter creation –
- A light beam will be seen traveling to the end of the universe and the produced
matter will move in circular trajectories forever – but – in darkness – no more light
be found – because – the source (1.16 million km per second) be used to produce
(matter+ space + light known velocity) and the light known velocity is traveling

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now and moving to the end of the universe where the matter be created by the rest
energy in movable case and the trajectory be a circular one which will not change
again by that the matter will revolve in the circular trajectory forever in darkness.
- The motion is available but no light be available!!
- Notice
- The explanation tells a light beam its velocity 1160000 km/s be required to
produce the matter –
- We think about any new tree or a newborn creature – the light 1160000 km/s is
necessary to cause the birth for this matter!

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3-6 The One Geometrical Design Result
If the solar system creation and motion depends on one geometrical design – can this
design effect on the solar system motion? what's the result of this one design if found?
This question can be more clear by another one
Let's ask it
If the sun doesn't cause any planet motion –Why the sun be found in the solar system?
Another question can help also
If the matter be created of energy (as electron and positron from gamma ray) can this
creation persistent in life if the cycle be not complete one – means- if the matter can't
produce equal energy for its own creation can the matter persistent in existence?
Shortly
The solar planets motions be integrated into one unified general motion – or – the
planets velocities be added together and produce one total velocity
The unified motion and velocity aims to accumulate the planets motions energies in
one point – and – then –the sun uses this energy to produce the sun rays
The sun uses a different rate of time which is
1 day of the sun motion = 1461 days of the Earth motion
By that, the energy be accumulated during (1461 days) be used by the sun in 1 day
and by this energy the sun rays be produced – No Nuclear Interactions -
That explains the data
Light (300000 km/s) travels during a solar day a distance =25920 million km
The planets motions distances total during 1461 days be =25920 million km
(include the moon motion distance)
Briefly
The sun rays be produced by the planets motions – this idea tells some interesting
result tells – The sun itself is created of a cycle and its existence depend on a cycle.

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Notice
This idea tells how Newton is so wrong
The Sun Be Created After All Planets Creation And Motion.
The sun creation we discuss in the paper – here we can only refer to the one unified
motion to prove the idea
The Planets Unified General Motion
Preface
- I claim that (The Planets Motions Create One Unified General Motion)
- This claim tells the planets motions be similar to one machine of gears (or One
Mechanical Clock)
- Also It tells the planets motions be similar to Chess Pieces Motions
- That because One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.

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The Solar Planets Motions Are Complementary One Another
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motions from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.
- Notice
- This data is a part of the unified motion discussion we analyze in details in the
paper discussion – but this part be brought here to explain the idea.

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4- The Solar System Geometrical Design Analysis
4-1 Preface
4-2 Newton Theory Of The Sun Gravity Is Wrong
4-3 The Solar System Is Created Based On One Geometrical Design
4-4 The One Geometrical Design Depends On One Light Beam Energy
4-5 The Solar System Be Created Out Of One Light Beam Its Velocity 1.16 Million
Km Per Second.
4-6 The Solar System Motion Depends On One Geometrical Design
4-7 THE DATA PROVE THE THEORY
4-7-1 Data No. (1)
The data proves (Planet Orbital Distance Be Defined Based On Light Motion)
4-7-2 Data No. (2) (My 5th
Equation Analysis)
The data proves (Planet Velocity is a Function in Light Velocity)
4-7-3 Data No. (3) (Jupiter and Uranus Velocities analysis)
The data proves
Jupiter and Uranus are the solar system 2 basic planets
The Solar System Depends On One Geometrical Design
Light velocity 1.16 million km per second be found
4-7-4 Data No. (4) (Uranus Velocity Analysis)
The data proves
One Geometrical Design Be Found Behind The Solar System
Uranus is the Solar System Main Planet.
4-7-5 Data No. (5) (Metonic Cycle)
The data proves
The Solar Planets Move One Unified Motion And This Motion Depend On The Moon
Metonic Cycle (19 years)

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The Planets Unified Motion Proves And Depends On The Solar System One
Geometrical Design
The Moon Metonic Cycle Be Done Depending on the solar System One Geometrical
Design.
4-7-6 Data No. (6) (The Distances Be Created In A Network form)
The data proves
The Solar System Distances Be Created Together As A Group Of Data (Network)
And No Single Distance Can Be Created Individually
4-8 The Solar System Geometrical Description
4-9 How The Matter Be Produced Periodically?
4-10 The Planets Unified General Motion (More Data)
The data proves (The Planets Move One Unified Motion As A Machine Of Gears)
4-11 Questions And Answers (Extending Discussion)

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4-1 Preface
- The paper main hypothesis tells…
- The solar planets and their distances be created out of one light beam – and this
light beam travels with 1.16 million km per second.
- The point no. (4-7) provides the data to prove the hypothesis and to prove the
Concept (Planet Motion Depends On Light Motion)
- So,
- Let's ask, Based On What Basics This Hypothesis Depend?
- I have 5 reasons to suggest this hypothesis which are:
- (1)
- The solar planets matters and distances be created of One Energy as we have
discussed in Newton Theory Refutation
- (2)
- This One Energy Was Found In A Geometrical Form And Not In A Chaos Form.
- Means, the one energy from which all planets matters and distances be created was
found in a geometrical form and not in a chaos form. Planets data analysis proves
this fact as we have seen in the (5) equations discussions (Point no.3)
- (3)
- Because the energy was in a geometrical form – one geometrical design be found
behind the solar system and was found before the solar system creation.
- Because one geometrical design be found behind the solar system creation and
motion – that causes the planets creation and motion data to be complementary one
another – by that– One Law Controls All Planets Data – as a result –Planets data
be created based on exact equations – I have discovered these equations and
provided them in the paper (5 Equations) – based on that –Planets data can be
concluded theoretically – as we have seen in the 5 equations discussions – means –
the 5 equations prove that One Geometrical Design be found behind the solar
system and was found before the solar system creation.

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- The one geometrical design causes the planets to move one unified motion.
- (4)
- The velocity 1.16 million km per second be registered in Planets matters and
distances data, because the planets matters and distances energy be provided by
this light beam energy, so the light velocity be registered in all planets and their
distances data, by that the velocity 1.16 million km/sec be found in the solar
planets data thousands of times and by using this velocity thousands of puzzles in
the planets data can be solved. The paper proves that strongly.
- (5)
- The (5) equations prove (Planet Motion Depends On Light Motion) – specially –
the Equation No. 1 and the Equation No.5 which can be explained only by light
motion effect on planet motion – we discuss these 2 equations with planets data in
this current point (No.4)
- Notice
- The current point no. (4) provides the data proves the paper theory – for that – the
description which be written in the paper introduction will be written again in this
point (No. 4) as a reference for the data – because – the provided data tries to
prove this description– But the description will be inserted in parts because each
part be belonged to its data – Where the whole vision be written in the paper
introduction.

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4-2 Newton Theory Of The Sun Gravity Is Wrong
- There are 3 basic reasons can refute Newton Theory of the sun gravity which are:
- (1) (The Gravitation Equation Is Wrong)
- The gravitation equation is wrong because it can't define any planet orbital
distance – where the initial conditions idea is wrong because planets data be
created based on exact equations and mathematical calculations and no any data
be created by initial conditions, historical unknown factors or any random process.
- Shortly
- The Solar System Be Created Of Energy Was Found In A Geometrical Design
- (2) (The Theory Concept is Wrong)
- Planet orbital distance be defined based on its neighbor planet orbital distance – as
proved by my 1st
equation – and we should explain why in the discussion in this
point no. (4)
- Also
- Kepler stated (Planet Orbit Defines Its Velocity), means, planet velocity depends
on its orbital distance and not its mass – my 2nd
and 3rd
equations prove that –
- As a result
- The concept (Planet motion depends on its mass) losses its 2 components where
Neither Planet Orbital Distance Nor Its Velocity Depend On Its Mass –
- Newton Theory Concept Is Wrong In Principle.
- (3) (The Theory Logic Is Wrong)
- The Planet should be created and moving by one force – because – if 2 forces
caused the planet creation and motion –this planet will be a conflict point between
these 2 forces and will be broken and destroyed.
- As a result

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- If the sun causes planet motion, the sun should create this planet, otherwise, the
sun will force this planet to move against its internal structure and will cause this
planet to be broken and destroyed.
- Shortly, (One Force Only Caused The Planet Creation And Motion)
- (The Correct Conclusion)
- As A result
- Mercury Motion And Creation Data Be In Harmony, Because Both Be Created By
One Force… and
- Venus Motion And Creation Data Be In Harmony, Because Both Be Created By
One Force… but
- Can have we 9 forces in the solar system, one force for each planet? Of course
NOT
- One Force Caused To Create And Move All Planets - Means,
- One Geometrical Design Be found Behind the Solar system Creation And Motion-
- That's the correct conclusion – no planet be created or moving independently –
instead – all planets be created and moving by one force based on one design.
- This Geometrical Design Be Found Before The Solar System Creation – By That-
The Solar System Data Be Created Based On A Planned Design And This Planned
Design Causes The Planets Motions
- Where's The Rich Point Under This Argument?? Where's the Gold??
- The solar system be created of One Energy Found In A Geometrical Form
- This is the paper discovery and the basic treasure of it –
- The solar planets and distances be created of energy (these are facts) but this
energy be one energy found in a geometrical form controlled by a geometrical
design and rules – that's why the solar system is one building has a planned design
be found before its creation.
- The next discussions will explain these meanings more clear and proved by
powerful data and arguments.

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4-3 The Solar System Is Created Based On One Geometrical Design
- Let's remember,
- The matter and space be created of energy – these are acceptable facts
- I conclude that, the energy from which the solar system be created was formed in a
geometrical design – means- this energy wasn't found in explosion or chaos form
but found in a geometrical design- imagine a river moves through a desert – this
river is energy but moves in a geometrical design not in a chaos or explosion form
- The idea tells that this energy was found in a geometrical design and not in a chaos
form.
- We accepted that Newton Theory Logic Is wrong because one force should create
and cause the planet motion – based on that – we conclude the concept-
- from One Energy Was Found In A Geometrical Design – the solar system be
created – that caused the planets data be created based on one design and as a
result the planets data be created based on exact equations which we have
discovered
- The Solar Planets And Their Distances Be Created Of One Energy Was
Found In A Geometrical Design. (A Basic Conclusion)
- But, We have asked
- Is There A Parallel Universe?
- The matter and space be created of energy – but – why just part of energy be in
matter form and how?
- Suppose we have amount of energy and some matter be created of this energy,
how the rest energy will deal with the born matter? Are these 2 players consist 2
Parallel Universes?
- We review here this part of the introduction concerning the one geometrical design
because the data of this current point (No. 4) tries to prove this one design
existence and to discover its geometrical features – means –the data analysis
process aims basically to prove this fact, so we have to remember it.

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4-4 The One Geometrical Design Depends On One Light Beam Energy
- The Solar System Creation And Motion Theory (Revision)
- The matter is created out of light beam, by that, the matter and space be created
together of this light beam energy and the matter doesn't separate from its parent
light but move together one unified motion by using different rates of time, by that
the matter be movable by nature because it be created out of light beam
- For the solar system – my theory tells –
- The solar planets matters and their distances be created out of one light beam
energy – by that – this light beam provided the required energy to create the
planets matters and their distances – that also can explain how the energy be
distributed based on one geometrical design and not in chaos form – also – the
most important is that – the light velocity be registered in the produced matters and
distances because the energy be provided by it.
- By this idea the solar planets be similar to ships sail over a sea, where the sea is the
light motion –
- Also, the solar planets can be similar to 9 waterwheels be built on one canal and
this canal water motion causes these 9 waterwheels rotations – by that – the light
motion (the canal water motion) causes the planets motions (the 9 waterwheels)
- We need more details for this description because the waterwheels are made of the
canal water – because – the planets matters are made of the light beam energy –
and the light causes these planets motions – by that – this light beam is the one
force which caused the planet creation and motion.
- (Here we can see the wrong concept in Planets motions explanation- where the
explanation searched for a force causes planet motion because it believed that
planet matter can't move by nature and needs gravity to cause its motion – for that
– the explanation searched for a force – and supposed the gravity is the required

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force which depends on planet mass – by that – the motion reason be found in
planet mass - But in fact – planet motion depended on the cycles and directions
definition where planet can't be stopped because it's created out of light but can
move in a wrong direction – by that – planet motion definition doesn't depend on
any force but depend on the definition of motion cycles and directions)
- I try to show, how the explanation process looks wrongly for long period because
it had avoided the question (How The Matter Be Created?)

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4-5 The Solar System Be Created Out Of One Light Beam Its Velocity 1.16
Million Km Per Second.
- The solar planets matters and distances be created of One Energy
- This energy be provided by One Light beam
- This light beam travels with a velocity 1.16 million km per second
- This velocity (1.16 million km per second) be registered in Planets Matters and
distances Data - means – This velocity be used in Planets data thousands of times –
and thousands of planets data puzzles can be solved only by using this velocity
1.16 million km per second –
- This current point (no. 4) provides a great part of data to prove this velocity
existence and effect.
- But,
- Let's try to refer to one clear effect of this light velocity on planet motion in
following….
- Planet Motion Elliptical Trajectory Analysis
- The solar system (planets matters and distances) be created of energy of one light
beam its velocity 1.16 million km per second – but
- The matter creation consumed the energy of this light beam – means –
- The matter creation process INPUT was the light beam with velocity 1.16 million
km per second - and the creation process OUTPUT was (matter + space+ light
beam with velocity 300000 km/sec)
- Here the light known velocity (300000 km/sec) be created as a side product in the
matter creation
- The next calculation can tell what's happened…
- (1.16/0.3) x 2π = 24.3

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- Where
- 24.3 refers to (24 hours = the solar day) (error 1%)
- 1.16 and 0.3 are the 2 light beam velocities
- But
- What's this rate (2π)??
- This rate (2π) is the reason of all circular motions in the universe – while – the
light moves in a straight lines – and the born matter should move with its parent
light beam in straight lines – the production of the light known velocity (300000
km/s) caused the straight line trajectory of motion to be in circular trajectory and
that causes the planets motions trajectories to be in elliptical forms –
- We should notice that – the matter creation is a process done for one time – and
the light known velocity (300000 km/s) be produced as a side product also for one
time only – after the creation – the light (300000 km/s) travels and the matter be
created forever – because
- The matter can't return again into its original light beam form because a part of the
energy be traveled already which is the light known velocity beam – means –
- The input was a light beam its velocity 1.16 million km per second (Energy =E)
and the output was (matter + space + light known velocity) (Energy = E)
- But
- The light known velocity (300000 km/s) be traveled and disappeared by that the
total energy be less than (E) and by that the energy in the matter be a prisoner in
this matter forever
- The light known velocity (300000 km/s) traveled and caused to decrease the total
energy (E) and also caused the motion trajectories to be in circular or elliptical
forms in place of the straight line forms.
- Let's try to see this picture – after the matter creation –
- A light beam will be seen traveling to the end of the universe and the produced
matter will move in circular trajectories forever – but – in darkness – no more light
be found – because – the source (1.16 million km per second) be used to produce

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(matter+ space + light known velocity) and the light known velocity beam is
traveling now and moving to the end of the universe where the matter be created
by the rest energy in movable case and the trajectory be a circular one which will
not change again by that the matter will revolve in the circular trajectory forever in
darkness.
- The motion is available but no light beam be available!!
- The next question should
- What's the sun?
- If the planet moves by light motion and the energy be consumed in matter and
motion – from where the sun be created and why the sun be in the solar system?
- Let's try to answer in the next point

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4-6 The Solar System Motion Depends On One Geometrical Design
- The solar planets move in elliptical forms – by that – the planets kinetic energy be
accumulated on one point resulting of the elliptical (or circular) trajectories.
- Means
- The Planets Motions Energies Be Accumulated On The Sun Point –
- Shortly
- The sun rays energy isn't created by any nuclear interactions be found inside the
sun – instead – This Energy Be Provided By Planets Motions Kinetic Energy
- That's the useful result of the circular and elliptical trajectory of planet motion, the
energy be accumulated on the sun one point and caused to create the sun rays.
- But the energy isn't enough to create the sun rays
- For that reason, the sun uses a different rate of time
- 1461 solar days of the planets motions be equivalent to 1 solar day of the sun
motion – by that – the planets motions energies be accumulated during 1461 days
be used by the sun in 1 day only – by that – the energy be enough to create the sun
rays and light beams
- From The Sun Rays (Energy) The Sun Disc Itself Be Created –
- For more simple vision, we can consider that
- The planets velocities be accumulated together on one point to create one unified
velocity – The 9 planets velocities total be (176 km/s) but this value isn't enough
and it's necessary to add the Earth moon velocity (29.8 km/s) and the total will be
(205.8 km/s) by this total of velocities the sun rays be created – because – the sun
uses different rate of time (1461 days of planets = 1 day of the sun) by that the
velocity 205.8 km x (1461 seconds) = 300000 km (per second)
- The Earth moon is a necessary component here because the rate of time (1461 days
= 1 day) is the Earth Cycle (1461 days) by that the Earth and its moon are basic
players in the sun creation process.
- At end we have an answer for the old question

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- Why Do We See The Sun Disc = The Moon Disc??
- Because
- (The Sun Diameter / The Moon Diameter) = (Earth Orbital Distance/ Earth Moon
Distance)
- Why Does The Diameters Rate =The Distances Rate?
- No Longer Pure Coincidence be the answer – but because
- The Moon Is A Basic Player In The Sun Creation
- Notice (1)
- The point is that – We live on the Earth which be made of light beam its velocity
1.16 million km per second and we look at the sun rays its velocity be 300000
km/sec by these 2 velocities the vision of the universe be created and by that the
circular trajectories of motions be created.
- And that explain why all motions in the universe be in circular forms
- Notice (2)
- The Sun be created based on the planets motions energies accumulation –
- This fact disproves Newton Theory of the sun gravity decisively
- But
- The important point here is that –
- Because the sun be created depends on the planets motions energies total, and the
planets move in cycles – that tells – The Sun Existence Depends On A Cycle

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4-7 The Data Prove The Theory
4-7-1 Data No. (1) (Part I)
Proves Planet Orbital Distance Be Defined Based On Light Motion
The following Data Proves,
Planet Motion Data Be Defined By Light Motion
- (A) Light supposed velocity (1.16 mkm/s) travels a distance = The Planet Orbital
Circumference in a period (T seconds)
- (B) Light known velocity (0.3 mkm/s) travels during this period (T) a distance = D
- (C) Planet moves a distance d in a period (=Ph) where D = 2π d
- And
- Ph = The Planet Orbital Period (in hours units and not solar days)
- Let's Test That In Following:
- (1) Mercury Motion
- During 310.4s light supposed velocity (1.16 mkm/) travels 360 = 2π x 57.9 mkm
- During 310.4 s light known velocity (0.3 mkm/) travels 93.1 = 2π x 14.8 mkm
- Where
- 360 mkm = Mercury Orbital Circumference
- 57.9 mkm = Mercury Orbital Distance
- 88 days = Mercury Orbital Period
- Mercury moves during 88 hours a distance = 14.8 mkm (error1.4 %)
- (2) Venus Motion
- During 586s light supposed velocity (1.16 mkm/) travels 680 = 2π x 108.2 mkm
- During 586s light known velocity (0.3 mkm/) travels 175.8 = 2π x 28 mkm
- 680 mkm = Venus Orbital Circumference
- Venus moves during 224.7 hours a distance =28 mkm (error1%)

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- (3) Earth Motion
- During 810s light known velocity (0.3 mkm/) travels 243 = 2π x 38.7 mkm
- Where
- 940 mkm = Earth Orbital Circumference
- 149.6 mkm = Earth Orbital Distance
- Earth moves during 365.25 hours a distance = 38.7 mkm (error 1.2%)
- (4) Mars Motion
- During 1235s light known velocity (0.3 mkm/) travels 371 = 2π x 59 mkm
- Where
- 1433 mkm = Mars Orbital Circumference
- 227.9 mkm= Mars Orbital Distance
- Mars moves during 687 hours a distance = 59 mkm (error 1%)
- (5) Jupiter Motion
- During 4222.6s light supposed velocity (1.16 mkm/) travels 4900=2π x 778.6 mkm
- During 4222.6s light known velocity (0.3 mkm/) travels 1267 = 2π x 201.7 mkm
- Where
- 4900 mkm =Jupiter Orbital Circumference
- 778.6 mkm = Jupiter Orbital Distance
- 4222.6 h = Mercury Day Period
- Jupiter moves during 4331 hours a distance = 201.7 mkm (error 1.3%)

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- (6) Saturn Motion
- During 7765s light supposed velocity (1.16 mkm/) travels 9007 = 2π x 1433 mkm
- During 7765s light known velocity (0.3 mkm/) travels 2330 = 2π x371 mkm
- Where
- 9007 mkm = Saturn Orbital Circumference
- 1433 mkm = Saturn Orbital Distance
- Saturn moves during 10747 hours a distance = 371 mkm (error 1%)
- (7) Uranus Motion
- During 15559s light supposed velocity (1.16 mkm/) travels 18048=2π x 2872 mkm
- Where
- 18048 mkm = Uranus Orbital Circumference
- 2872 mkm = Uranus Orbital Distance
- 30589 days = Uranus Orbital Period
- Uranus moves during 30589 hours a distance = 742 mkm= 2 x 371 (error 1%)
- (8) Neptune Motion
- During 24348s light supposed velocity (1.16 mkm/) travels 28244 =2π x4495 mkm
- Where
- 28244 mkm = Neptune Orbital Circumference
- 4495.5 mkm = Neptune Orbital Distance
- 59800 days = Neptune Orbital Period
- Neptune moves during 59800 hours a distance = 1163 mkm = π x 371

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- (9) Pluto Motion
- During 31983s light supposed velocity (1.16 mkm/) travels 37100= 2π x 5906mkm
- Where
- 37100 mkm = Pluto Orbital Circumference
- 5906 mkm = Pluto Orbital Distance
- Pluto moves during 90560 hours a distance = 1527 mkm = (π +1) 371
- (1527 = 2π x 243)
- (10) The Earth Moon Motion
- During 639s light supposed velocity (1.16 mkm/) travels 742 mkm = 2 x 371
- During 639s light known velocity (0.3 mkm/) travels 191.6 = 2π x 30.5 mkm
- But
- 30.5 mkm = 88000 km x 346.6 days
- The moon displacements total during 346.6 (solar days) = 30.5 mkm
- Where
- 346.6 solar days= The nodal year
- 88000 km = The moon displacement for a solar day
- 742 mkm = The distance be passed by Uranus in 30589 hours (error 1%)
- This data tells, the moon orbit regression be done by effect of Uranus motion.
- Notice
- The moon motion be done in a period 346.6 solar days and not 346.6 hours (that
creates a special case for the moon motion) – because we need to know why the
moon uses the period (346.6) in days units and not in hours as the others.
- The moon motion data depends on the distance (742 mkm) which be defined by
Uranus motion data

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- Notice
- The inner planets distances in blue color ( 93.1, 175.8, 243, 370.6) can be used as
cycles periods because
- 175.8 solar days =Mercury day period
- 243 solar days = Venus rotation period
- 370.6 solar days are near to 365.25 days (error 1.5%),
- (93.1 days x 2π= 584 days =the period of periodical meeting of Earth and Venus)
- This equality depends on the rate 1mkm = 1 day
- That tells each planet creates its PREVIOUS NEIGHBOR CYCLE PERIOD
- And the outer planets distances in blue color (1267, 2330 , 4664, 7305, 9595)
- 2330 = 2 x 1165 = 2π x 371
- 4664 = 4 x 1165 = 4π x 371
- 7305 = 2π x 1165 =2π2
x 371
- 9595 = 8 x 1165 = 8 π x 371 (error 3%)
- This data cornerstone is the number (371), to understand it we need to look at the
data part no. (II) in following..
- We have to provide a comment for this current part of data (Part No. I) before to
discuss data Part No. (II).

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Comments On Data No. (1) (part no. I)
The data shows all planets use the same system sufficiently –
Planet T/ P The values rate
Mercury 88/310.4 = 0.283 28.3% (----)
Venus 224.7/ 586 = 0.383 38.3 % (---)
Earth 365.25 /810 = 0.45 45% (--)
Mars 687/1235 = 0.55 55.6% (-)
Jupiter 4331 /4222.6 = 0.97 97.5%
Saturn 10747/7765 =1.384 72.2% (+)
Uranus 30589/15559 = 1.966 50.8% (++)
Neptune 59800 /24348 = 2.456 40.7% (+++)
Pluto 90560/31983 =2.8315 35.3% (++++)
- T = The period of time be required by light motion
- P = Planet Orbital Period
- The values rate measures the rate between the 2 periods of time (T and P), and
because of that (for example), the period T = 15559 while and P (Uranus orbital
period) =30589, and for that the period 15559 be 50.8% of Uranus orbital period.
- The data shows Jupiter is the nearest point for the equality of the 2 periods (T and
P) (The difference is only 2.5% - because Jupiter velocity (1.1318 million km per a
solar day) be less than light supposed velocity 1.16 with (2.5%)
- The inner planets data shows the period (T) is less than planet orbital period (P)
- But
- This fact is reversed in the outer planets data where the planet orbital period (P) be
greater than the period (T). That shows Jupiter is the balancing point between all
planets data because of its velocity per a solar day.

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The Planets Data (No. 1) (Part II)
A hypothesis (Mercury Is The Solar System Origin Point)
I- Data
(1)
50.3 days x 24 hours = 1207.2 hours
Light (known velocity 0.3 mkm/s) travels during 1207.2 seconds a distance = 362
million km (where 360 million km= Mercury Orbital Circumference)
But
50.3 million km = The Distance Between Mercury And Venus
(2)
91.7 days x 24 hours = 2201 hours
Light (known velocity 0.3 mkm/s) travels during 2201 seconds a distance = 660
million km (where 680 million km= Venus Orbital Circumference)
91.7 million km = The Distance Between Mercury And Earth
(3)
170 days x 24 hours = 4080 hours
million km!
170 million km = The Distance Between Mercury And Mars
(Notice 4900 million km = 4 x 1224 million km)
(4)
million km!
720.7 million km = The Distance Between Mercury And Jupiter

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(5)
Light (known velocity 0.3 mkm/s) travels during 33015 seconds a distance = 2 x 4952
million km!
1375.6 million km = The Distance Between Mercury And Jupiter
(6)
Light (known velocity 0.3 mkm/s) travels during 67550 seconds a distance =4 x 5066
million km!
2814.6 million km = The Distance Between Mercury And Uranus
(7)
4437.2 days x 2 x 24 hours = 2 x 106493 hours = 212985.6 h
Light (known velocity 0.3 mkm/s) travels during 212985.6 seconds a distance =4π x
5080 million km!
4437.2 million km = The Distance Between Mercury And Neptune
(8)
Light (known velocity 0.3 mkm/s) travels during 140355 seconds a distance = 2 (π+1)
x 5080 million km

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II- Discussion
- Let's summarize the idea of the previous data in following…
- (1)
- Mercury is the solar system origin point – as a result –Planet orbital circumference
be defined based on the distance between this planet and Mercury.
- Example no. (a)
- Mercury Venus Distance 50.3 million km, based on this distance, light motion
defines the distance (362 million km) which is Mercury Orbital Circumference
- By that,
- Mercury orbital Circumference (360 million km) be defined based on Mercury
Venus Distance (50.3 million km) where light motion uses this distance as a period
of time (where 50.3 million km be considered equivalent to 50.3 days =50.3 x 24 h
= 1207.2 hours, the light uses this period as 1207.2 seconds)
- Example no. (b)
- Mercury Earth Distance 91.7 million km, based on this distance, light motion
defines the distance (660 million km) where Venus Orbital Circumference = 680
million km (error 3%)
- By that,
- Venus orbital Circumference (680 million km) be defined based on Mercury Earth
Distance (91.7 million km)
- Light uses this distance also as a period of time –
- Notice
- Light known velocity (300000 km/s) travels during a solar day (86400 s) a
distance = 25920 million km but we see this distance as 25920 years (The
Precession Cycle)
- I try to prove that, the distance using as a period of time is a usual using by light
motion in the solar system where different data be created based on it.

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- Now we have a clear rule, tells that
- Each planet defines an orbital circumference based on its distance to Mercury
because Mercury is the solar system origin point.
- We notice that, each planet defines its previous planet orbital circumference - by
that the distance between Mercury and Venus defines Mercury orbital
Circumference and the distance between Mercury and Earth defines Venus orbital
Circumference –
- This rule gives us a reason for my (1st
Equation) which tells (d2
= 4d0(d- d0) this
equation tells each planet orbital distance depends on its previous neighbor planet
orbital distance – this rule be inherited from light motion effect on planet motion
as seen clearly in Mercury, Venus and Earth data –
- But
- Why Doesn't Mars Follow This Rule Also??
- Because
- Mars original position was between Mercury and Venus – Mars original orbital
distance was 84 million km and Mars had migrated from its original position to its
current one (227.9 million km) – and during its displacement from (84 mkm) to
(227.9 mkm) Mars had collided with Venus and then with Earth – Mars itself is the
planet which caused the Earth moon creation – This fact I proved in this current
paper in point no. (10) (Mars Migration Theory)
- Mars migration caused to break the rule – because it caused to change – the
original geometrical distribution of the solar system distances – by that – no
longer planet orbital circumference be defined based on its distance to Mercury –
- We should see clearly why the rule be broken?
- Because of Mars Migration – Mars is the reason – and any repair process for the
solar system design should takes Mars new orbital distance into consideration –
because Mars is the reason of the rule breaking.
- What Does The Rest Data Tell Us? let's look at them

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- (2)
- The distance between Mercury and Jupiter provides the value 5189 million km
- The distance between Mercury and Saturn provides the value 2x 4952 million km
- The distance between Mercury and Uranus provides the value 4x 5066 million km
- The distance between Mercury and Neptune provides 4π x 5080 million km
- The distance between Mercury and Pluto provides 2 (π+1) x 5080 million km
- Notice
- 2872 mkm (Uranus Orbital Distance) = 2 x 1433 mkm Saturn Orbital Distance
- 4495 mkm (Neptune Orbital Distance) = π x 1433 mkm Saturn Orbital Distance
- 5906 mkm (Pluto Orbital Distance) = (π+1) x 1433 mkm Saturn Orbital Distance
- This data explains how the rates (4, 4π and 2(π+1)) be created.
- Shortly
- The 3 planets (Uranus, Neptune and Pluto) orbital distances depend on Saturn
orbital distance - and
- Saturn orbital distance = Mars orbital circumference =1433 mkm
- That explains why the rate (371) be used in these planets in (Data No. 1) (Point no.
4-7)
- Let's summarize the idea in following…
- (3)
- The original rule was (Each planet defines its orbital circumference based on its
distance to Mercury because Mercury is the origin point) this rule be used by
Venus and Earth – then be broken by Mars Migration –
- The solar system depends on one geometrical design – if no repair be occurred –
Mars Migration will cause to destroy the whole solar system -
- The solution be (We Need A Point Of Agreement Between Mercury And Mars)
because no other planet violated the design except Mars – if Mercury finds a point
of agreement with Mars that will repair the solar system.
- The point is 4900 million km - WHY? Because

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- Light supposed velocity (1.16 mkm/s) needs 4222.6s to pass 4900 million km
- And
- Light known velocity (300000 km/s) needs 16330s to pass 4900 million km
- Where
- 16330 hours = Mars Orbital Period (687 days)
- By that the distance 4900 million km is the agreement point between Mercury and
Mars – where (4900 million km = Jupiter Orbital Circumference)
- For that reason
- All planets tries to perform this distance by their calculations as seen in the data –
all data ranged between (5189 and 4900) which very near to the value (4900)
- Not only that, the outer planets use the value (4900) by different forms – let's show
that in following
- (4)
- And
- 4900 solar days Uranus needs to move a distance = Uranus Orbital Distance
- 2 x 4900 solar days Neptune needs to move a distance = Neptune Orbital Distance
- 3 x 4900 solar days Pluto needs to move a distance = Pluto Orbital Distance
- For Saturn
- (9007 /9800) = (9800 /10747) where
- 9007 million km = Saturn Orbital Distance
- 10747 solar days = Saturn orbital Period
- 9800 million km = 2 x 4900 million km
- I try to prove that, the value 4900 is the basic value in the solar system
- We have a clear reference for one geometrical design be found behind.
- Notice, Pluto was the Mercury Moon and had migrated with Mars Migration

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II- The Solar System Is A Light Beam
I - Data
(1)
360 million km = 1.16 million km /sec x 310 seconds
93 million km = 300000 km /sec x 310 seconds
93 days x 24 h =2232 hours
Light (300000 km/s) travels during 2232 seconds a distance = 680 mkm (error 1.5%)
93 x 2π = 586
Where
360 million km = Mercury Orbital Circumference
680 million km = Venus Orbital Circumference
The data tells that, light motion defines Venus Orbital Circumference depends on
Mercury Orbital Circumference
(2)
175.9 million km = 300000 km /sec x 586 seconds
175.9 days x 24 h =4222.6 hours
Light (300000 km/s) travels during 4222.6 seconds a distance = 1267 mkm
1267 x 2 = π x 810
(3)
Where
940 million km = Earth Orbital Circumference
(4)
Where 1433 million km = Mars Orbital Circumference

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II- Discussion
- The previous data is so interesting… please note
- (A)
- 370 days = Earth Orbital Period (365.25 days error 1.3%)
- 243 days = Venus rotation period
- 175.9 days = Mercury Day Period
- 93 x 2π = 586 (but 584 days is a cycle between Earth and Venus)
- By that, each planet motion data defines its previous neighbor cycle period
- Mars defines Earth Cycle, Earth defines Venus, and Venus defines Mercury –
- (B)
- The data shows, Venus Orbital Circumference Be Created Depending On Mercury
Orbital Circumference, and
- Earth Orbital Circumference Be Created Depending On Venus Orbital
Circumference, But,
- Mars Orbital Circumference Be Created Depending On Venus and Not Earth
Orbital Circumference,
- This data is so interesting and explains my (1st
) equation- let's refer to it again
- d2
= 4d0 (d-d0)
- where d= planet orbital distance and d0 = its previous neighbor planet distance
- the equation is proved here (again) simply by light motion – each planet period of
time for light motion be defined by its previous neighbor data –
- this equation has 3 exceptions because Earth depends on Mercury and not Venus
but Mars depends on Venus and not Earth – also – Pluto depends on Uranus and
not Neptune – here we see why Mars depends on Venus and not Earth- because
light motion for the period (1235 sec) can more simple to use the value (1267) in
place of the value (810) by that the data shows Venus is the player for Mars and
not the Earth.

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- (C)
- Again the simple rules be broken after Mars – because of Mars Migration- let's see
Jupiter data in following –
- 4900 million km = 1.16 million km /sec x 4222.6 seconds
- 1267 million km = 300000 km /sec x 4222.6 seconds
- Where
- The value 1267 doesn't express any Cycle – the rule be broken in Jupiter why?
- Because each planet defines its Previous neighbor cycle period - the previous is
Mars – and Mars was migrated and caused a great change in the solar system one
geometrical design and by that – Mars can define Earth Cycle period but Jupiter
Can’t define Mars Cycle Because Mars is in the wrong position.
- Notice,
- Jupiter orbital period 4331 days =2π x 687 days Mars orbital period)
- Notice
- Let's summarize the idea in following….
- The solar system is one light beam, from this light beam energy the planets matters
and their distances be created –
- The one light beam creates one geometrical design - because it's one player behind
– by that – all planets creation and motion data be created based on this one
geometrical design.
- The idea is clear, one light beam creates one geometrical design, based on this
design all planets creation and motion data should be created – as a result – the
planets data be created based on exact equations and mathematical calculations –
this idea be proved clearly in the paper by its discussion for my 5 equations by
which we can conclude theoretically all planets creation and motion data

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4-7-2 Data No. (2) (My 5th
Equation Analysis)
(Proves Planet Velocity is a Function in Light Velocity)
We discuss here My 5th
equation – where
V= Planet velocity
The next data be a powerful proof for (Planet velocity depends on light velocity)
(A)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
Where
(B)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
9.7 km/s = Saturn Velocity
- The data tells
- (1) Planet Velocity Be A Function In Light Velocity
- (2) Planets orbital distances and periods be created depending on light motion
- (3) The planets velocities be classified into 2 groups one belonged to (300000
km/s) and the other belonged to (1.16 million km/sec)
322
2
1 =
v
v

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- Shortly
- (1.16/0.3) x 6.8 (Uranus Velocity) = 2 x 13.1 (Jupiter Velocity)
- The rate (2) be used in the solar system data for a geometrical necessity.
- This data be discussed deeply later in point No. (4-7)
In following
- We review the data be discussed in planet velocity analysis (Point No. 3-7-2)
- As we have discussed (Planet Velocity Definition Is A Complex Process), we have
proved that in Point no. (3-7) but why??
- Planet velocity be created as a function in light velocity – that's the reason why
planet velocity definition is a complex process.
(Revision of Point 3-7-2) Planet Velocity In Comparison With Light Velocity
I - Data
The data supposes – a light beam its velocity 1.16 million km per second be found.
Means, we compare planet velocity with 2 velocities of light (1.16 and 0.3)
300000 km = 3600 km x 83.33
1160000 km = 3600 km x 322.2
Planet 322.22 (Column No. 1) 83.333 (Column No. 2)
Mercury 47.4 6.8 1.76 = (π)0.5
Venus 35 9.2 2.38
Earth 29.8 10.8 2.8
The moon 27.78 11.6 3
Mars 24.1 13.37 3.4578
Ceres 17.92 17.92 4.65
Jupiter 13.1 24.6 6.361 = 2π
Saturn 9.7 33.21 8.6
Uranus 6.8 47.4 12.25 = 4π
Neptune 5.4 59.67 15.432
Pluto 4.7 68.56 17.73

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II- Discussion
- (1)
- (The Table Column No. 1)
- The data in column No. (1) compares between planet velocity and Light supposed
velocity (1.16 million km/sec)
- The planets velocities are complementary clearly – as a result
- Mercury (47.4 km/s) moves during 6.8 hours a distance = 1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance = 1.16 million km
- Venus (35 km/s) moves during 2 x 4.7 hours a distance = 1.16 million km
- Pluto (4.7 km/s) moves during 2 x 35 hours a distance = 1.16 million km
- (error 2%)
- Earth (29.8 km/s) moves during 2 x 5.4 hours a distance = 1.16 million km
- Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance = 1.16 million km
- Mars (24.1 km/s) moves during 13.1 hours a distance = 1.16 million km
- Jupiter (13.1 km/s) moves during 24.1 hours a distance = 1.16 million km
- (Error 2%)
- (In fact Jupiter moves during 24.6 hours a distance 1.16 mkm)
- Venus (35 km/s) moves during 9.7 hours a distance = 1.16 million km
- Saturn (9.7 km/s) moves during 35 hours a distance = 1.16 million km
(error 5%)
- Why be planets velocities complementary one another based on this distance 1.16
million km?

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- Because the planets velocities be created as a function in the light supposed
velocity (1.16 million km per second)
- We have to accept this answer as a hypothesis till perform our analysis
- In all cases we should find the real geometrical reason for which the planets
velocities be created complementary one another based on this velocity or distance
per a second (1.16 million km)
- (2)
- We have 2 light velocities (0.3 million km/s) and (1.16 million km/sec) how these
2 velocities be in harmony with each other?
- (1.16/0.3) x 2π = 24.3
- This calculation tells some great secrets
- The value (24.3) is different by (-1%) with 24 hours (the solar day) and by (+1%)
with 24.6 hours (Mars Rotation Period)
- Here the hours be created
- As we have discovered in point no. (3-2) light motion uses 1 hour of planet motion
as 1 second of light motion – We have seen that frequently- in that point.
- This using of that rate of time be done as a result of the interaction between the 2
light velocities.
- The rate which we need to see is (2π)
- Why this rate (2π) be created here? let's try to discover the answer by analysis of
planet elliptical trajectories
- Can we explain why all motions trajectories be in circular or elliptical forms?

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- (Question No. A)
- Why Do All Motions Trajectories Be In Circular Or Elliptical Forms?
- (1.16/0.3) x 2π = 24.3
- This calculation is the reason – let's remember how the matter be created –
- The matter is created out of light beam - Means
- The solar planets and their moons and their distances all be created out of one light
beam – this light beam velocity be = 1.16 million km per second
- Let's see the process in details
- The creation process INPUT is (a light beam its velocity be 1.16 million km/s)
- And the creation process OUTPUT are (Matter + Space + light 300000 km/s)
- Means
- The light energy be consumed by Matter and space Creation, and the rest energy
be emitted in light form but this produced light velocity be 300000 km/s
- The input is a great energy light beam with velocity 1.16 mkm/s -But
- The output (movable matter + space + light 300000 km/s) 3
- And what's happened after the creation directly?
- The light beam (300000 km/s) is traveled and disappeared into the universe
- As a result,
- The energy in Matter and Space can never again be a light (1.16 mkm/s) because
this energy is decreased by the value of light (300000 km/s) which is traveled
directly after the creation – and left the energy as prisoner in the matter forever
- And what does happen next? the calculation (1.16/0.3) x 2π = 24.3 can tell
- 2 light beam velocities be found together in one event – they had an interaction
and caused this calculation to be produced - and what has this calculation?
- 24.3 hours = the time be created here because the time is the matter cycle
- 2π = the produced matter is movable by nature but the motion be done only in
circular or elliptical forms – that explains why all motions be in circular and
elliptical forms.

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- (3)
- (The Table Column No. 2)
- The column no.2 deals with light known velocity (300000 km/s)
- We see clearly that,
- 1 second of light Motion be = 2π hours of Jupiter Motion,
- 1 second of light Motion be = 4π hours of Uranus Motion,
- But
- Jupiter (13.1 km/s) moves in (24.6 hours) a distance 1.16 million km
(Light supposed velocity for 1 second)
- And
- Uranus (6.8 km/s) moves in (24.6 hours) a distance 0.6 million km
(Light known velocity for 2 seconds)
- This fact is important because Jupiter and Uranus are the main 2 columns of the
solar system geometrical design – We should analyze their velocities in more deep
in the next point (4-7-3)
- Notice
- Saturn (9.7 km/s) moves in 17.2 hours a distance = 600000 km
- (17.2 hours = Uranus Day Period)
- Uranus moves 600000 km in a period 24.6 hours (Mars rotation period)

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- Notice
- (1 hour of planet motion = 1 second of light motion)
- This rate we have used frequently in the first data (4-7-1)
- If this rate be effective in all planets motions – that means- planet velocity per a
solar day should be compared with light motion for 24 seconds.
- We use here light known velocity (300000 km/s) = c
- Mercury velocity per solar day 4.095 million km = v1
- Venus velocity per solar day 3.024 million km = v2
- Earth velocity per solar day 2.574 million km = v3
- Mars velocity per solar day 2.082 million km = v4
- Jupiter velocity per solar day 1.1318 million km = v5
- Saturn velocity per solar day 0.838 million km = v6
- Uranus velocity per solar day 0.5875 million km = v7
- Neptune velocity per solar day 0.4668 million km = v8
- Pluto velocity per solar day 0.406 million km = v9
- We find that
- (24)2
c2
= π (v1)2
- (24) c2
x 26.6 = 2π (v2)2
- (24) c2
x 19.2 = 2π (v3)2
- (24) c2
= 0.5 (v4)2
- (24) c2
= π0.5
(v5)2
(error 2.5%)
- (24) c2
= π (v6)2
- (24) c2
=2π (v7)2
- (24) c2
= π2
(v8)2
- (24) c2
= 4π (v9)2
(error 4%)
- This data compares between planet and light velocities, we analyze this data later
in Point (4-7-4)

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4-7-3 Data No. (3) (Jupiter and Uranus Velocities Analysis)
The data Proves
1- Jupiter and Uranus are the solar system 2 basic planets
2- The Solar System Depends On One Geometrical Design
3- Light velocity 1.16 million km per second be found
(1)
- Jupiter moves in Mars rotation period (24.6 hours) a distance =1.16 million
- Light supposed velocity travels 1.16 million km per second –
- If 1 second of light motion be = 1 day of planet motion, in this case the light and
Jupiter velocities will be equivalent
- And
- Uranus moves in Mars rotation period (24.6 hours) a distance =0.6 million
- Light known velocity travels 0.3 million km per second –
- If 2 seconds of light motion be = 1 day of planet motion, in this case the light and
Uranus velocities will be equivalent
- NOTICE
- Jupiter behaves in place of (1.16 million km per second) and Uranus behaves in
place of (300000 km/sec), where
- My theory tells that, the solar system be created out of one light beam its velocity
1.16 million km per second – the creation process be as following
- INPUT be 1.16 million km/sec and
- OUTPUT be Matter + Space + a light beam its velocity 300000 km/sec
- Means
- The 2 velocities (1.16 million km /s and 300000 km/s) be used by the light beam
from which the solar system be created
- That explains why Jupiter and Uranus are the 2 basic planets in the solar system
because the behave in place of the 2 light velocities by using the same rate of time
(1 second = 1 day)

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(2)
(A)
(2 x 100733 million km /197393 days) = (1.16/1.1318) = (0.6/0.5875)
Where
(B)
(1.16/0.6) = (47.4/24.1) = (35/17.9) = (13.1/6.8) Where
9.7 km/s = Saturn Velocity
- The data tells
- (1) Planet Velocity Be A Function In Light Velocity
- (2) planets orbital distances and periods be created depending on light motion
- (3) The planets velocities be classified into 2 groups one belonged to (300000
km/s) and the other belonged to (1.16 million km/sec)
- Shortly
- (1.16/0.3) x 6.8 (Uranus Velocity) = 2 x 13.1 (Jupiter Velocity)
- The rate (2) be used in the solar system data for a geometrical necessity.

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(3)
- 1 second of light velocity (300000 km/s) = 2π hours of Jupiter velocity (13.1 km/s)
- And
- 1 second of light velocity (300000 km/s) = 4π hours of Uranus velocity (6.8 km/s)
- (Jupiter velocity error 1.2% and Uranus error 2.5%)
- The errors are so low and can't contradict the idea-
- The data tells,
- Jupiter and Uranus velocities be defined by geometrical necessity because these 2
velocities are required to be used as cornerstones in the solar system one design.
(4)
- The value 4900
- 4900 days = The Period Uranus Needs To Move Its Orbital Distance
- 2 x 4900 days = The Period Neptune Needs To Move Its Orbital Distance
- 3x 4900 days = The Period Pluto Needs To Move Its Orbital Distance
- Notice
- The distance 4900 million km is a agreement point between Mercury and Mars
because
- Light (1.16 million km/s) travels in 4222.6 s a distance 4900 million km
- Light (300000 km/s) travels in 16330 s a distance 4900 million km
- Where
- 16330 hours = Mars Orbital Period = 687 days (error 1%)
- That shows the significance of the value 4900 as a distance to be used by 3 planets
(Jupiter, Mercury and Mars) and to be used as a period by 3 planets (Uranus,
Neptune and Pluto)
- We have to keep our eyes on this value (4900).

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(5)
- 197393 days = 4π x 15710 days
- 100733 mkm = 2π x 16033 mkm
- (Notice 100733 x 2 = 201466 = approximately 197393 (error 2%))
- That shows the value (16030) is a central value - where
- Light (300000 km/s) travels during 16030 s a distance = 4810 million km
- Light (1.16 million km/s) travels during 2 x 16030 s a distance = 37100 million km
- 4810 mkm = 4900 mkm Jupiter Orbital Circumference (error 2%)
- That shows the value (16030) is the central one – where – it's belonged to the
period 16330 s by which light (300000 km/s) moves 4900 million km
- I try to show that – ONE GEOMETRICAL DESIGN be found behind because we
move in a circular data – one data lead us to the other and then we return to the
first – this behavior of data can be done only if we deal with ONE DESIGN.
- Notice
- 37100 mkm (Pluto Orbital Circumference) – 4900 mkm (Jupiter Orbital
Circumference) = 32200 million km = 2 x 16100 million km
- (The number 16330 we see again in a new form 16100!!! "error 1.4%")
- The point is that
- The planets data be created based on light motion – by that – the data analysis
shows the distances be used as periods of time and vice versa which is a feature of
light motion – when we refuse light motion effect on planet motion – we will have
to suppose thousands of these calculations be found by pure coincidences –
because all planets data be created by light motion and this using is a usual one in
the solar system creation and motion data
- Notice
- Jupiter moves during 37100 solar days a distance = 4 x 10747 million km
- (10747 days = Saturn Orbital Period) (error 2.5%)

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(6)
- 2094 million km = Jupiter Uranus Distance
- This data tells, a light beam travels from the Earth to Uranus and passes by Jupiter
causes to create the 2 distances – the direction of motion needs more analysis but I
prefer the sun rays motion direction – this data will be discussed deeply later
(7)
- Light (300000 km/s) needs 1200 sec to pass 3600 mkm = Mercury Orbital
Circumference
- Mercury moves during 1200 solar days a distance =4900 million km - And
- Light (300000 km/s) needs 16330 sec to pass 4900 mkm = Jupiter Orbital
Circumference
- Jupiter moves during 16330 solar days a distance = 18482 million km
- And
- Light (300000 km/s) needs 60160 sec to pass 18048 mkm = Uranus Orbital
Circumference (error 2.5% with 18482 mkm)
- Uranus moves during 60160 solar days a distance = 35344 million km
- The data shows a series of 3 points moves from Mercury to Jupiter to Uranus – the
data tries to show that one geometrical design be found behind the solar system
- This data be analyzed deeply in the next point (4-7-4)
- Notice
- The period 4900 days is the central value in the solar system – because –
- 4900 solar days = 117600 hours
- The distance 35344 million km provides a strong proof that – One Geometrical
Design be found behind the solar system – we discuss this distance 35344 million
km in the next point (4-7-4)

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4-7-4 Data No. (4) (Uranus Velocity Analysis
The data proves
1- One Geometrical Design Be Found Behind The Solar System
2- Uranus is the Solar System Main Planet.
(1)
- 100733 million km = 2π x 16030 million km
- 197393 solar days = 4π x 16030 solar days (error 2%)
- Where
- 100733 million km = The Solar Planets Orbital Circumferences Total
- 197393 solar days = The Solar Planets Orbital Periods Total
- We should keep an eye on the number (16030)
(2)
- Light known velocity (0.3 mkm/s) travels during 16030 seconds a distance = 4810
million km (4900 million km = Jupiter Orbital Circumference) (error 2%)
- And
- Light supposed velocity (1.16 mkm/s) travels during 2 x 16030 seconds a distance
= 37100 million km (= Pluto Orbital Circumference)
- By that the 2 planets orbital distances depend on the value 16030 sec.
- Notice
- 100733 mkm x 2 = 32200 mkm x 2π
- Where
- 100733 million km = The Solar Planets Orbital Circumferences Total
- 32200 million km =The Different Distance between Pluto orbital circumference
(37100 mkm) and Jupiter Orbital Circumference (4900 mkm)
- (32200 = 2 x 16100 where the error between 16030 and 16100 is 0.5%)

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(3)
Table (No. 1) (Planet Motion In Comparison With Light Motion)
Planet Light motion Planet motion Total
Mercury 101.8 mkm 4914 mkm 360 mkm
Venus 258 mkm 6866 mkm 1040 mkm
Earth 419 mkm 8065 mkm 1980 mkm
Mars 788 mkm 2 x 4972 mkm 3413 mkm
Jupiter 4950 mkm 18487 mkm 8313 mkm
Saturn 12240 mkm 2 x 12580 mkm 17320 mkm
Uranus 35344 mkm 35344 mkm 35344 mkm
Neptune 69321 mkm 43955 mkm 63524 mkm
Pluto 104737 mkm 50209 mkm 100733 mkm
- Let’s explain each columns in following…
- Light motion – Mercury as example –
- Mercury needs 14.14 solar days to pass a distance = 57.9 mkm = Mercury orbital
distance, this period 14.14 solar days = 339 hours
- Light known velocity (0.3 mkm/s) uses it in seconds (339 seconds) and passes a
distance = 101.8 million km as seen in the table –
- Planet motion – Mercury as example
- Mercury orbital circumference =360 million km
- Light known velocity (0.3 mkm/s) passes this distance 360 mkm in a period =1200
seconds –
- Mercury moves in 1200 solar days a distance = 4914 million km
- Total (The Last Column) refers to the planets orbital circumferences total at this
planet – for example – at Venus the total be 360 mkm +680 mkm = 1040 mkm

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The Analysis of The Table No. (1)
- The table has one basic question which is
- Why Be Uranus 3 Values Equal?
- Why the 3 values (= 35344 million km)? Let's analyze this data in following…
The Distance 35344 Million Km
(1)
- 35344 million km = 4900 days x 24 hours x (300000 km/s)
(light 300000 km/s uses each one hour as one second)
- 35344 million km = The planets orbital circumferences total till Uranus (including
Uranus Orbital Circumference)
- 35344 million km = Uranus motion distance in 60160 solar days
- 35344 million km = Jupiter motion distance in 31200 solar days
- 35344 million km = light (1160000 km/s) travels this distance in 30589 seconds
(light 1160000 km/s uses 1 day as one second Uranus orbital period 30589 days)
(2)
- 35344 million km = Jupiter motion distance in 31200 solar days
- Light (300000 km/s) travels during 103944 sec a distance = 31200 million km
- 103944 hours = 4331 days = Jupiter Orbital Period
(3)
- (1.1318 /1.16) = (30589 x 2)/ (17.2 x 3600)
- Where
- 1.16 million km /sec = light supposed velocity
- 1.1318 million km /sec = Jupiter velocity per a solar day
- 17.2 hours = Uranus Day Period
- The data tries to prove that (1) Uranus is the main planet in the solar system one
geometrical design and we need to discover why? we discuss that in the next point
no. (4-8)

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- Revision For The Distance 4900 Million Km
- Light (300000 km/s) travels a distance 4900 million km in a period 16330 seconds
- Light (1160000 km/s) travels a distance 4900million km in a period 4222.6 seconds
- Where
- 16330 hours = Mars orbital period (687 days)
- And
- Also
- Uranus needs (4900 solar days) to pass 2872 million km = Uranus orbital distance
- Neptune needs (2 x 4900 solar days) to pass 4495 million km = Neptune orbital
distance (error 2%)
- Pluto needs (3 x 4900 solar days) to pass 5906 million km = Pluto orbital distance
(error 1%)
- For Saturn
- (10747 /9800) = (9800/9007)
- Where
- 10747 solar days = Saturn Orbital Period
- 9007 million km = Saturn Orbital Circumference
- 9800 million km = 2 x 4900 million km

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4-7-5 Data No. (5) (Metonic Cycle)
The data proves
1- The Solar Planets Move One Unified Motion And This Motion Depend On
The Moon Metonic Cycle (19 years)
2- The Planets Unified Motion Proves And Depends On The Solar System One
Geometrical Design
3- The Moon Metonic Cycle Be Done Depending on the solar System One
Geometrical Design.
- (1)
- Metonic Cycle Period =19 Years = 6939.75 days
- Mercury moves during 6939.75 days a distance = 28244 million km (=Neptune
Orbital Circumference)
- Venus moves during 6939.75 days a distance = 20986 million km
- Earth moves during 6939.75 days a distance = 18048 million km (=Uranus Orbital
Circumference) (error 1%)
- Mars moves during 6939.75 days a distance = 14450 million km (= 50% of
Neptune Orbital Circumference) (error 2.5 %)
- Jupiter moves during 6939.75 days a distance = 7855 million km
- Saturn moves during 6939.75 days a distance = 5848 million km (= Mercury Pluto
Distance)
- Uranus moves during 6939.75 days a distance = 4077 million km
- Neptune moves during 6939.75 days a distance = 3240 million km
- Pluto moves during 6939.75 days a distance = 2814 million km (Mercury
Uranus Distance)
- The planets (Mercury, Earth, Mars, Saturn and Pluto) move defined distances
which supports the idea tells (One Geometrical Design be found behind)
- The rest planets move undefined distances – let's analyze Uranus distance

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- Uranus Distance Analysis
- Uranus moves during 6939.75 days a distance = 4077 million km
- What's this 4077 million km??
- 2 x 4077 seconds x (300000 km/s) x (1160000 km/s) = 2872 million km (error 1%)
- Where
- 2872 million km = Uranus Orbital Distance
- The distance 4077 million km is a value used to define Uranus orbital distance and
this definition be done by using the 2 light beam velocities as the data shows
- Means
- Uranus orbital distance – basically- be defined based on the period 6939.75 days
(Metonic Cycle)
- Not for vain, Uranus forces the Earth moon to move Metonic Cycle (19 years)
because Uranus orbital distance itself be defined based on it
- No fighting here for Uranus mass effect on the moon motion – we deal with light
beam connected between Uranus and the moon – and the motion be transported by
the light beam – this is the meaning of – One Geometrical Design-
- It's one machine because it's one light beam travels and creates the planets, their
distances, their data and their motions.
- And
- Uranus moves in a solar day 587500 km (= 0.6 million km) (= light 300000 km/s
motion for 2 seconds) and
- Uranus moves in 2 solar days 1.16 million km (where 1.16 million km/s = light
supposed velocity)
- By that Uranus caused to be the solar system main planet as we should explain in
the next point no. (4-8)

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- The Rest 3 Planets Distances Analysis
- (a)
- Venus (20986 million km)
- Light (1160000 km/s) travels during 18048 seconds a distance = 20986 million
km– where (18048 million km = Uranus Orbital Circumference)
- (b)
- Jupiter (7855 million km)
(error 1%) – where (9007 million km = Saturn Orbital Circumference)
- (c)
- Neptune (3240 million km)
- Light (1160000 km/s) travels during 2815 seconds a distance = 3240 million km –
where (2815 million km = Mercury Uranus Distance)
- A Comment
- Because the planets move defined distances in Metonic Cycle Period we conclude
that one geometrical design be found behind the solar system- why??
- Because
- If the planets are separated points each planet will interest in its own orbital period
– So the period of Metonic Cycle (6939.75 days) should be strange for them and
by that they should move random distances during this period
- Otherwise
- The solar system be created in one geometrical design – the motion of one planet
causes another planet motion – by that – all planet move one cycle and their
motions be planned geometrically –as the chess board – no single distance be
planned individually – on the contrary – all distances be planned as one group
based on one geometrical design
- By that the planets move defined distances

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- (2)
- (6939.7 days)2
= 2 x (4900 days)2
- Where
- 6939.75 days
- 4900 days (or million km) – (This Is The Main Value In The Solar System)
- The data tells us why the value (4900) be the main value in the solar system? and
why it be used so frequently?
- Let's summarize the idea in following
- The solar system is one light beam – this light beam moves and all planets move
with it by using different rates of time –by that the planets move one unified
motion
- This unified motion depends on the cycle (6939.75 days) (Metonic Cycle)
- The period 4900 be created depending on this cycle 6939.75 days
- The light uses the period as distance and vice versa – that shows the reason for the
importance of this value (4900) and it's frequently using…
- (3)
- Light (300000 km/s) travels during 6939.75 seconds a distance =2094 million km
where 2094 million km = Jupiter Uranus Distance
- That tells, Metonic Cycle is created by light motion through an interaction be
found between Jupiter and Uranus – the distance 2094 million km be analyzed
deeply in point no. (4-8) to discover what relationship be found between Jupiter
and Uranus motions..
- (A Question)
- Why Do The Planet Move Together The One Unified Motion Of Metonic Cycle?
What’s The Positive Result Of Their Motions During Their Cycle?
- This question answer will be in point No. (6)

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- Notice
- (The Moon Motion Effect)
- (A)
- 4900 million km = 0.3 mkm/ s x 16330 seconds = 449197 km x 10921 km
- 449197 km = 27.78 km/s x 16330 seconds
- 680 million km = 1.16 mkm/ s x 586 seconds
- 16330 km = 27.78 km/s x 586 seconds
- (B)
- 10921 km = 27.78 km/s x 394 seconds
- 155597 km = (394 km)2
- But
- (86400 s/ 16030 s) = 5.4
- Where
- 449194 km = Jupiter Circumference
- 27.78 km/s = The moon velocity (proved in point no. 6-2)

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4-7-6 Data No. (6) (The Distances Be Created In A Network Form)
The data proves
The Solar System Distances Be Created Together As A Group Of Data (Network)
And No Single Distance Can Be Created Individually
This Meaning Can Be Concluded From My (1st
Equation) (d2
=4d0(d-d0)) Because
The Equation Tells That, The Distance From The Sun To Pluto Be Distributed Based
On One Geometrical Design Regardless Any Planet Data.
(A)
- 0.3 mkm /s (light known velocity) passes in 2094 seconds a distance =629 mkm
- 629 mkm = Earth Jupiter Distance
- 2094 mkm= Jupiter Uranus Distance
- The data shows that, a light beam started from the Earth to Jupiter and passed from
Jupiter to Uranus
- The data shows that the 2 distances (629 mkm and 2094mkm) are created together
based on a geometrical mechanism
(B)
- 0.3 mkm /s (light known velocity) passes in 2 x 2723 sec a distance = 1634 mkm
- 2723 mkm = Earth Uranus Distance
- 1622.7 mkm = Uranus Neptune Distance (with 1634 mkm error0.7%)
- The data shows that, a light beam started from the Earth to Uranus and passed
from Uranus to Neptune -
- The data uses the rate (2) because the distance 2723 mkm x 2 = Earth Uranus
Orbital Diameter through the revolution around the sun – the data shows (two)
distances be used in equivalence to (one) distance- which is a known feature of the
solar system motion- as –Uranus orbital distance = 2 Saturn orbital distances
- The data shows that the 2 distances (2723 mkm and 1622.7 mkm) are created
together in a network form
- These 2 data we have seen before and will be discussed deeply in point No. (4-7)

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(Data Part I)
(C)
- The distance 1622.7 mkm be used as a period of time =1622.7 seconds and
- 1622.7 seconds = 2 x 810 seconds
- Where the period 810 seconds is very famous in the solar system motion –because
light supposed velocity (1.16 mkm/sec) passes in 810 sec a distance 940 mkm –
and light known velocity (0.3 mkm/s) passes in 810 seconds a distance= 243 mkm-
- That shows the distances be distributed based on one geometrical design
(D)
- 0.3 mkm /s (light known velocity) passes in 18048 sec a distance = 5415 mkm =2
x 2707 mkm (Earth Uranus Distance 2723 mkm error 0.5%)
- The data shows that, the distances 18048 mkm and 2723 mkm be distributed based
on one geometrical design.
(E)
- 0.3 mkm /s (light known velocity) passes in 4345.5 sec a distance = 1303 mkm
- 1411 mkm =1.0725 x 1303 mkm (error 1%)
- Where
- 4345.5 mkm = Earth Neptune Distance
- 1411 mkm = Neptune Pluto Distance
- Notice (1)
- The rate (1.0725) is used with around 40% of all distances in the solar system –
- This rate (1.0725) be discussed in point no. (5-5) on this current paper
(F)
- 0.3 mkm /s (light known velocity) passes in 5756.4 sec a distance = 1727 mkm
- Where
- 5756.4 mkm = Earth Pluto Distance

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- 1727 mkm = π x 550.7 mkm Mars Jupiter Distance
- Notice (2)
- The data deals with Earth distances to the outer planets in order and it shows all
distances must be distributed based on one geometrical design –which proves
clearly that the solar system distances be created in a network form based on one
geometrical design –and Earth distances shows one feature of this design features
- Notice (3)
- 37100 x (0.3)3
=1000 mkm
- 1000 x (1.16)3
= 2 x 780 mkm
- 1000 x 0.3 =300 mkm
- Where
- 300 mkm = Earth orbital diameter (=149.6 mkm x 2 = 299.2 mkm)
- Notice (2)
- 100733 x (0.3)2
= 9066 mkm
- Where
- 100733 mkm = The solar planets orbital circumferences total
- 9007 mkm = Saturn Orbital Circumference (with 9066 error 0.6%)
- This data may refer to specific importance of Saturn motion in the solar system
motion.

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(Data Part II)
(1)
310.3 =(360 mkm/1.16) = (351.3 /1.13184)
- 1.1318 mkm = Jupiter Velocity Per A Solar Day
- 1.16 mkm = light supposed velocity
- 351.3 = ??
(2)
586.6 = (680 mkm/ 1.16) = (663.5 mkm/ 1.1318)
- 663.5 mkm = 670.4 mkm (Venus Jupiter Distance error 1%)
- (light supposed velocity 1.16mkm/s moves 680 mkm in 586.6 seconds)
(3)
810.4 = (940 mkm /1.16) = (917.2 /1.1318)
- 917.2 = 929 mkm (Earth Jupiter Distance error 1.3%)
- (929 mkm be produced when Earth and Jupiter be on 2 different sides from the sun)
(4)
2 x 243 = (654.9 mkm /1.162
) = (550.7/1.1318)
- 654.9 mkm = Jupiter Saturn Distance
- 550.7 mkm = Mars Jupiter Distance

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(5)
1850 = (2146 mkm/1.16) = (2094/1.1318)
- 2146 mkm = (4292 mkm/2) (where 4267 mkm Mars Neptune Distance)
- 1.16 mkm = light supposed velocity and 2094 mkm = Jupiter Uranus Distance
(6)
4530 = (5259 mkm /1.16) = (5127.4/1.1318)
- 5259 mkm = (2630 mkm x 2) (Where 2644 mkm Mars Uranus Distance)
- 5127.4 mkm = Jupiter Pluto Distance
(7)
550.7 = (644.6 mkm/1.16) = (629/1.1318)
- 644.6 mkm = ???
- 629 mkm = Jupiter Earth Distance
(8)
578.6 = (670.4 mkm /1.16) = ( 654.9 /1.1318)
- 670.4 mkm = Jupiter Venus Distance
- 1.16 mkm = light supposed velocity and 654.9 mkm= Jupiter Saturn Distance
(9)
3283.6 = (3809 mkm/1.16) = (3717 mkm /1.1318)
- 3809 mkm = (3809 mkm = π x 1205 mkm Mars Saturn Distance)
- 3717 mkm = Jupiter Saturn Distance

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II- More Data
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (Mercury Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (Pluto Orbital Distance)
1.16 mkm/s x 2094 s x 2 = 4900 mkm (Jupiter Orbital Circumference)
Max error (1%)
5127 million km = Jupiter Pluto Distance
2094 million km = Jupiter Uranus Distance
- This data shows that, there are more distances of Jupiter be distributed based on
the rate (1.16) or by using light supposed velocity (1.16mkm/s) which proves that
the solar planets distances be distributed based on One Geometrical Design and the
distances be created in a network form.
- In fact,
- Jupiter distances are a simple and direct example to prove the theory tells (the solar
system distances be created in a network form)
- The distances be created based on one another, where light (1160000 km/s) uses
the distance as a period of time to create another distance –
- I wish I prove my point of view clearly as possible – because – I don't aim to
create the idea tells (Light motion effect on planet motion), this idea I have to
create to understand how the planets data be created – Jupiter distances be a part of
a great treasure of Gold – the physicist who refuses light motion effect on planet
motion will stay in his office repeating along day 2 words (Pure Coincidence),
because thousands of such calculations be found in the solar system – the only5
logical solution is top suppose that the light creates a distance and uses it as a
period of time to create another distance – if we accept that – this data will be a
proof for the existence of the light velocity (1160000 km/s)

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- But this behavior is used one in the solar system – and used also by the known
light velocity (300000 km/s) – the rich Jupiter provides us this piece of gold also
- 2094 seconds x 300000 km/s = 629 million
- This calculation be discussed deeply in this paper in point no. (4-8)
- The difficulty here is how to see the motion – for example – this calculation tells
one light beam (300000 km/s) travels from Earth to Uranus passes by Jupiter (or
vice versa) – the question is – how the real motion be done? From the Earth to
Uranus or from Uranus to the Earth? We know the light passes by Jupiter in all
cases but what's the motion direction?
- Because
- We sit down in the cave (with Plato) and looks from the other side of the mirror –
and who can looks from the point above the cave?
- Light (300000 km/s) travels in one solar day (86400 seconds) a distance = 25920
million km – but we see this distance as – 25920 years (the procession cycle)

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Comments
- Let's summarize the data idea in following:
- The data compares between light supposed velocity (1.16 mkm/s) and Jupiter
motion distance during a solar day (1.13184 mkm/day)
- The data uses 2 columns, one of them depends on light supposed velocity (1.16
mkm/s) and the other depends on Jupiter velocity per a solar day 1.1318 mkm
- The column of light motion uses the distances between Jupiter and the other
planets –
- The column of Jupiter motion produces 3 types of motions (first type 4 distances
between Jupiter and other planets, and 3 distances between Mars and other
planets and 2 values which are 351.3 and 644.6 which be related to the distance
720.7 mkm = Mercury Jupiter Distance)
- The Argument tells the following:
- I can provide a hypothesis tells that (A light beam its velocity be 1.16 mkm/s be
found and effective on the solar system motion), it's my hypothesis, and
- Because Jupiter velocity be 1.13184 mkm per a solar day, the 2 velocities 1.16
mkm and 1.1318 mkm be so near and that may effect on the planets motions data–
I also can conclude this idea
- But
- I can't define the planets positions based on my hypothesis unless the hypothesis
be a fact. If there's no light velocity = 1.16 mkm that should cause a chaos for the
distribution of data – but wee see a consistency of data – because
- 4 results are Jupiter distances to other planets and 3 results be Mars distances to
other planets. That tells 7 results are related to Jupiter motion – that because
Jupiter moves depending on Mars Period of time – that means- there's a deep
interaction between Mars and Jupiter Motions cause the 2 motions be considered
as one motion – by that Jupiter motion depends on Mars period of time – for

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example Jupiter motion a distance = 778.6 mkm = Jupiter orbital distance in a
period = 687 days = Mars orbital period
- The basic point here is that, Jupiter moves during (Mars rotation period 24.6 h) a
distance =1.16 mkm where Jupiter orbital circumference be designed based on the
distance 1.16 mkm –that creates the deep interaction between Jupiter and Mars
motions –
- The point is that, because the data defines clearly the planets positions based on
the 2 velocities 1.16 mkm/s and 1.13184 mkm /day that proves the hypothesis is a
fact otherwise why the planets positions be defined based on these velocities?
- We have only the rest 2 distances (351.3 mkm and 644.6 mkm)
- 351.3 mkm = 2 x 175.95 mkm ( Mercury Day Period = 175.95 days)
- 644.6 mkm = (during a period 636.3 days Jupiter motion 720.7 mkm)
- Mercury moves 720.7 mkm in its day period (175.95 solar days)
- This data shows a connection with the distance 720.7 mkm.
A Conclusion
- All used and produced distances are defined distances which means we deal with
One Geometrical Design And A Network Form. There's no random process can
be found here we deal completely with a geometrical system which proves the
light supposed velocity (1.16 mkm/sec) is a real one and a fact.

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4-8 The Solar System Geometrical Description
- Many basic changes be provided by the new analysis of the solar planets data, the
question we need to answer – Can the solar system description be changed than
what Kepler described as a result for the planets data analysis?
- Let's try to answer this question in a short discussion be built on question and
answer system – let's try in following…
- (Question No. 1)
- Can Jupiter and Uranus motions interaction modify the solar system description?
- Let's try to see this question depth in following
- Data No. (A)
- Where
- The data tells some interesting meaning – that- the light sees the distance 2094
million km as a period of time (2094 seconds) and based on it the light passes the
distance from Jupiter to Earth
- By that, one light beam travels between Uranus and the Earth passes by Jupiter and
creates the 2 distances geometrically by this calculation
- This interesting meaning we catch in another data also –
- Data No. (B)
- Light (300000 km/s) travels during 5446 seconds a distance = 1622.6 million
km
- Where
- 1622.6 million km = Uranus Neptune Distance
- 5446 million km = 2 x 2723 million km (Uranus Earth Distance)
- Here also, the light travels from Earth to Neptune and passes by Uranus – 2
distances one of them be used as a period of time for the other! why and how?

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- (Question No. 2)
- Why Is The Time A Scalar Value And Not A Vector?
- The question asks (Based on what roots the time definition depends?)
- Let's discuss the data no. (A)
- Means
- 0.3 million km /s x 2094 seconds = 629 million km
- The light velocity and the distance be 2 vectors but the period (2094s) be defined
as a scalar value…
- Let's suppose, the time is a vector
- In this case what would happen?
- The distance 2094 million km will be in (x-y plain) but the distance 629 million
km will be in (z-plain) – means –
- The distance between Jupiter and Uranus will be perpendicular on the distance
between the Earth and Jupiter.
- The description tells – the distance from the sun to Jupiter be as a straight line
(horizontal level) but Uranus position should be perpendicular on this distance!
- Can that be real??
- From long time I have suggested some perpendicularity must be found between
Uranus and the Earth moon because Uranus axial tilt =97.8 deg and the moon axial
tilt =6.7 degrees and by some perpendicularity be so near in data but why? we may
discover here what's happening…
- The data tells some perpendicularity must be found (if the time is a vector), by this
discussion we gain 2 positive points, one to modify the solar system description
and the other to examine why the time isn't a vector…
- How to receive these 2 positive points? If we can prove there's some
perpendicularity here – that can help greatly our analysis – let's try in following..

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- Can Uranus Position Be Perpendicular On Jupiter Position?
- NO
- But, Where This Perpendicular Can Be Found?
- Uranus position can be perpendicular on Saturn Position
- But
- Light motion defines the Perpendicularity between Uranus and Jupiter – this
definition is the basic and central one – but – for geometrical necessity – the
perpendicularity be moved from Jupiter to Saturn
- So
- We need to discover the geometrical necessities prevented the perpendicularity on
Jupiter position and we need a proof for this perpendicularity on Saturn position..
- (I)
- Why Uranus can't be perpendicular on Jupiter?
- Because
- 629 mkm /654.9 mkm = 24/24.7 (error 1%)
- Where
- 654.9 million km = Jupiter Saturn distance
- 24 hours = Earth Day Period
- 24.7 hours = Mars Day Period
- Between 629 mkm and 654.9 mkm there's a difference = (4%)
- Almost Mars motion is the reason – specifically – Mars Migration is the reason –
- Shortly
- Because Mars is the planet before Jupiter that prevent Uranus perpendicularity.

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- (II)
- Are there proves for Uranus perpendicularity on Saturn position?
- (a)
- Saturn orbital distance = Saturn Uranus distance
- And
- Jupiter Earth distance is almost = Jupiter Saturn distance (error 4%)
- Can Be A Reason Behind These Distances Equality?
- Because we deal with light beam – can we imagine some reflection be done in
Saturn – and this reflection caused the distances be equal because the distance is
energy and the reflection causes equal energies –
- I don't say this is a proof – we just analyze the data to see if it has some reference
for this suggested reflection –
- (b)
- The Three Planets Distances Be Rated To Saturn
- Uranus Orbital Distance 2872 mkm = 2 x Saturn Orbital Distance 1433 mkm
- Neptune Orbital Distance 4495 mkm = π x Saturn Orbital Distance 1433 mkm
- Pluto Orbital Distance 5906 mkm = (π+1) x Saturn Orbital Distance 1433 mkm
- The rates (2, π and π+1) be used frequently in these 3 planets data analysis – can
that tell Saturn is a central point for this 3 planets? Can that support the refection
idea?!
- (c)
- The perpendicularity definition be done between Uranus and Jupiter but be seen
between Uranus and the Earth moon because Uranus axial tilt 97.8 deg and the
moon axial tilt 6.7 deg, that gives a reference for a perpendicularity. But the
perpendicularity be occurred actually between Uranus and Saturn – let's see that
geometrically – in following –
- The figure tries to describe the planets
Order – Uranus perpendicular on Saturn

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- Please note
- Saturn orbital distance = Saturn Uranus distance =1433 million km
- If we use the angle (90 degrees) and the 2 dimensions (1433 mkm) in one triangle,
the hypotenuse will be = 2026 million km
- The distance doesn't equal Uranus orbital distance 2872 mkm
- But
- 2026 mkm is almost equal Jupiter Uranus distance (2094 mkm) (error 3%)
- And
- (2872 mkm /2094 mkm) = ((π+1) /3)
- NOTICE
- If the data analysis be a correct and Uranus be perpendicular on Saturn and planets
to the sun as the figure shows – that will make Uranus the central planet in the
solar system because it be the perpendicular planet on the solar system – by that –
Uranus motion can effect (vertically) –
- That's what we have discovered before and referred to frequently –
- There are 3 basic results of Uranus position which are
- Uranus motion effect on the moon motion and caused the moon to move Metonic
Cycle (19 years)
- Uranus motion effect on Pluto and caused Pluto day period to be so long (153.3 h)
- And
- Uranus axial tilts effect on all planets axial tilts and prevented the overturning
motion around the sun.
- Also
- The data no. (4-7-4) shows that Uranus is the solar system central planet because
its 3 distances are equal (35344 million km)

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4-9 How The Matter Be Produced Periodically?
- Let's remember how the matter be created….
- (1)
- The matter be created out of light beam its velocity 1.16 million km /sec
- The process be as following
- The Process INPUT is (1.16 mkm/s) - And
- The Process OUTPUT is (matter movable + space + light 0.3 mkm/s)
- The produced light (300000 km/s) be traveling and disappeared by that the energy
in the matter and space can't be return as light again because a part of energy be
decreased already
- The process has 2 light velocities
- (1.16 /0.3) x 2π = 24.3
- By this calculation we understood that, the time be created with the matter creation
and we can define the time as a matter cycle period
- The calculation tells that the period (24.3 hours) be created based on the rate (2π)
that may tells the time needs the matter to move in circular trajectories – or it may
tell, the matter should move in a cycle – because the time is the matter cycle period
- (2)
- The matter is produced from light 1.16 million km /sec for one time – means-
when the matter be created the parent light (1.16 million km/s) be consumed and
no more matter can be produced because the energy be consumed already –
- Now let's ask
- How new trees be planted? New animals be born and even more children?
- The machine has to produce a light beam its velocity 1.16 million km/s to cause
new matters to be found!
- Means,
- We see the sun, and never expected that, planets motions energies be accumulated
to produce the sun rays while this is the fact which be seen every day

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- But
- The fact which isn't seen even is that, the solar system motion has to produce a
light beam it's velocity =1.16 million km /s otherwise no new matter can be created
- Again we can learn something
- Uranus velocity per solar day be equivalent to (0.6 million km) (error 2%) because
the machine has to produce the light beam its velocity (300000 km/s)
- And
- Jupiter velocity per solar day be equivalent to (1.16 million km) (error 2.5%)
because the machine has to produce the light beam its velocity (1.16 million km/s)
– because the last light beam is the method of a new matter creation
- The proportionality between the 2 planets velocities to the 2 light beam velocities
isn't pure coincidence or found for some common reason – but – be found as – the
cornerstone of the machine motion task.
- We can't move inside this explanation to the end because tenths of questions be left
in the way and we can make no progress without answer these questions
- For the reason the point no. (4-11) contains questions and answers – we try to
compare the solar system vision which depends on Newton theory, the Big bang
theory and general relativity theory – with – our new vision about the solar system
which depends on one geometrical design be created by energy of one light beam.
- We have to put the questions and answers in point no. (4-11)
- Because
- Point no. (4-10) provides proves for the idea (the planets move one unified motion)
we need these proves because it adds one more proof for the deep relationship
between Jupiter and Uranus motions.

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4-10 The Planets Unified General Motion
4-10-1 The Planets Unified General Motion Description
4-10-2 The Solar Planets Motions Are Complementary One Another
4-10-3 The Solar Planets Move An Unified Motion (A Team Motion)
4-10-1 The Planets Unified General Motion Description
- I claim that (The Planets Motions Create One Unified General Motion)
- This claim tells the planets motions be similar to one machine of gears (or One
Mechanical Clock)
- Also It tells the planets motions be similar to Chess Pieces Motions
- That because One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
- Please remember
- The Solar Group is similar to a machine of gears each planet is a gear in it, or
- The Solar Group is similar to one building and each planet is a part of this same
building, or
- The Solar Group is similar a canal water moves through the canal and causes the
rotation of 9 waterwheels.

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4-10-2 The Solar Planets Motions Are Complementary One Another
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.

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4-10-3 The Solar Planets Move An Unified Motion (A Team Motion)
- Let's Summarize The Proof Idea In Following:
- This proof depends on 2 planets motion cycles are discovered later. Which are
(planet 8 days cycles) and (planet 6 days cycles). We study one Cycle only in this
paper because both cycles provide the same argument.
- The Cycle Shows That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Result.
- Means,
- Many planets move relative one another to create one result.
- For Example
- Jupiter moves a distance (A) and Uranus moves a distance (B).
- The different distance between (A) and (B) = Jupiter Diameter
- Now
- The machine uses this behavior frequently, and (the different distance = Jupiter
Diameter) be created frequently while the cycle uses its different periods (8 days,
16 days, 24 days….etc).
- Based on that,
- We can't consider these planets motions are independent from one another because
the different distance be defined by the 2 planets motions. we have to consider
these planets motions as a team motion. They move relative to one another which
proves The Unified General Motion Concept.
- Based on that,
- (Planet 8 and 6 Days Cycle) disproves Planet Independent Motion Concept.
- In following we study Planet 8 Days Cycle

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(Planet 8 Days Cycle)
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following:
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days

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- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider they are
equal distances.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform one different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with a team motion and NOT Planets independent Motions.
- Why does Uranus depend on Pluto Day Period?(additional question)
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of
this process yet, but the data shows that's Uranus effect on Pluto motion.
A Conclusion
Planet 8 Days Cycle disproves The Planet Independent Motion Concept,
On The Contrary, The Planets Move As A Team. (A Unified General Motion)

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4-11 Questions And Answers (Extending Discussion)
This point provides many questions and their answers for more extending discussion –
let's start in following…
(Question no. 1)
- Why Is The Big Bang Theory A Wrong One?
- Because, the energy from which the planets matters and distances be created
wasn't found in a chaos form but was found in a geometrical design controlled by
geometrical rules.
- The wrong idea is very near to the correct one
- The matter is created of energy and the space is created of energy – these are facts
be acceptable almost – so the big bang accepted them also –
- But
- The Big Bang had Supposed That The Energy Was In Chaos Form
- Why?
- Based on what roots the theory supposed the energy be found in a chaos form- it's
The Result Of The Explosion Description
- Because the big bang supposed the first explosion and the energy be found in a
chaos form – that's the mistake
- The basics are correct
- But the imagination supposed the energy be in a chaos form –
- Could the theory avoid this mistake?
- Yes, If the theory analyzes the planets creation and motion data – the data doesn’t
show any random process or chaos structure of data (as we have proved)
- The planets data show that no planet can be independent neither in creation nor in
motion – The solar system is one trajectory of energy and the planets are points on
this trajectory.

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(Question no. 2)
- Why Is Newton Theory Of The Sun Gravity A Wrong One?
- Because
- Newton didn't ask (How The Matter Be Created?)
- The theory is wrong in its Logic
- This point is that–
- One Force Should Create The Planet And Causes Its Motion
- This is the basic point against Newton theory
- If the planet be created by some force and then the sun causes the planet motion-
that means- the sun forces this planet to move against its internal structure – by
that this planet will be a conflict point between its internal structure and the sun
gravity – as a result – this planet will be destroyed.
- The concept is that
- One Force Should Create The Planet And Causes Its Motion
- And this is the fact
- The planet be created of light beam energy and be moving by this light beam
motion – one force causes both jobs.
- The logic leads to the conclusion (One Design Be Behind The Solar System)
because –
- One force causes planet creation and motion – so – have we 9 forces in the solar
system one force for each planet? Of course not – it's one force for the 9 planets
and their moons – that proves one geometrical design be found behind the solar
system.

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(Question no. 3)
- Why Isn't The Time A Vector?
- The time is a scalar value and can't be a vector - Why? Based on what this
definition depends?
- We notice that,
- Light motion can use the distance as a period of time and the distance be a vector –
- By that, light motion effect on planet motion can cause the time to be a vector and
not be a scalar
- Notice
- Light (300000 km/s) moves in one solar day (86400 s) a distance =25920 million
km –
- We see this distance as (25920 years = The Precession Cycle)
- By planets data analysis we can define the time as (The Matter Cycle Period)

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(Question no. 4)
- How The Matter Be Created
- The matter is created out of light beam its velocity 1.16 million km per second.
- in details
- The creation process INPUT is (a light beam its velocity be 1.16 million km/s)
- And the creation process OUTPUT are (Matter + Space + light 300000 km/s)
- Means
- The light energy be consumed by Matter and space Creation, and the rest energy
be emitted in light form but this produced light velocity be 300000 km/s
- The input is a great energy light beam with velocity 1.16 mkm/s -But
- The output (movable matter + space + light 300000 km/s) 3
- And what's happened after the creation directly?
- The light beam (300000 km/s) is traveled and disappeared into the universe
- As a result, the energy in Matter and Space can never again be a light (1.16
mkm/s) because this energy is decreased by the value of light (300000 km/s)
which is traveled directly after the creation – and left the energy as prisoner in the
matter forever – The next calculation tells the fact
- (1.16 /0.3) x 2π =24.3 where
- 24.3 is (24 hours = the solar day) (the time be created as matter cycle period)
- 2π be the matter circular or elliptical motion trajectory
- The calculation tells the story
- The light (1160000 km/s) energy be consumed in matter and space creation and
one light beam (300000 km/s) be emitted and traveled –
- The matter be created movable and its motion depends on its parent light beam
but the matter motion trajectory isn't a straight line as expected (light travels in
straight lines), because of the interaction between 1160000km/s and 300000 km/s
the matter motion trajectory be in elliptical form.
- That explains why all motions in the universe be in circular or elliptical forms.

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(Question no. 5)
- Can Lorentz Transformations Help To Discover The Matter Origin?
- Lorentz length contraction tell
- Particle length be contracted by its high velocity motion
- But
- A fierce fighting be found between 2 ideas
- One tells (No Real Contraction Be Occurred For Particle Own Length But Illusion
Of Measurements)
- The other tells (Particle Own Length Be Contracted Really)
- Our question was (How The Matter Is Created?)
- The matter is created out of light beam
- That's why the high velocity motion changes the particle length and data because
this particle data be created based on light beam velocity –
- I want to say
- We can reach to this conclusion by 2 roads – by Lorentz transformations (one
road) or by planets data analysis (another road)
- That tells, Lorentz Transformations be in the same phase with the results be
produced by the planets data analysis – that shows a real fact be found behind.

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(Question no. 6)
- Can The Solar Planets Move A Unified Motion As A Machine Of Gears?
What's The Result Of This Motion?
- The solar planets move a unified motion as machine of gears – or in better
similarly – as a Great Mechanical Clock
- The solar planets move as gears in one machine, because of that, the planets
motions be complementary one another and no one motion be done independently
- The planets unified motion cause to add the planets velocities together – means-
the planets motions energies be accumulated on one point (the sun) and because
the sun uses a different rate of time (1 day of the sun =1461 days of the planets)
the energy be accumulated in 1461 days be used by the sun on one day and by that
the energy be sufficient to produce the sun rays
- That Tells The Sun Is The Planets Motions Result And Not The Reason – Newton
Was Wrong.
- The sun rays creation details and calculations be discussed in point no. (6) of this
paper.
- Notice
- Light (300000 km/s) travels in one solar day (86400 s) a distance = 25920 million
km
- The solar planets motions distances total in (1461 solar days) be = 25920 million
km (including the Earth moon motion distance)
- We see this distance 25920 million km as (25920 years = The Procession Cycle)
because it's a light motion.

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(Question no. 7)
Why Doesn't The Planet Break After Its Creation?
- This question deepens our understanding about how the solar planets be created –
because- it asks
- Why be Planet Diameter in harmony with this planet motion Features?
- If a planet circumference contradicts this planet motion features that will lead to
destroy this planet – it will be as a wall be built in water – the water will destroy it-
it doesn't happen – The planets live millions of years and still in life – how to
explain that?
- The planet dimensions and data be created depending on this planet motion
features –Means- the creation process be a part of this planet motion – means
Planet motion be defined before this planet creation-
- No Hope Planet Motion Depends On Its Mass
- That tells why Newton theory of the sun gravity is mistaken – because – Newton
imagined – Planets be created (by unknown process) and their data be created (by
some historical events and unknown factors) –
- Then
- Newton theory of the sun mass gravity works on the created planet – it tells- The
planet be forced by the sun mass to move a specific motion – this motion is
defined by factors (aren't related to the creation process) –
- Here we catch the Newton Mistake
- Because Newton told there are 2 players effect on the planet motion- means- 2
sources of force – the force which caused the planet creation and the sun gravity
force which caused the planet motion –
- That tells simply the planet motion be a conflict point between these 2 forces – the
result should be the planet destruction
- Newton Theory Is Mistaken In Its Original Logic

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(Question no. 8)
Why Do We See The Sun Disc = The Moon Disc?
- Because
- (The Sun Diameter/ The Moon Diameter) = (Earth Orbital Distance/ Earth Moon
Distance) - then – Why The Diameters Rate = The Distances Rate?
- The question is a simple one but it refers to a serious point of conflict in the solar
system motion description –
- It asks, If Planets creation data be created based on geometrical calculations – or
by some random and unknown factors –
- A next question can be added (Can we conclude planets diameters theoretically?)
- The big bang theory be refuted at end – but – its ideas still live in many of the
scientific minds – as a result– There's an idea tells – Planet data be created based
on historical events and random unknown factors – which still be taught till now!
Shortly
- The planets creation data be created based on exact equations and geometrical
calculations – this is the only method can provide the general harmony of motions
- My (2nd
Equation) Proves That
- (v1/v2) = (s/r) = I
- v = Planet velocity and r= a diameter of one of the 2 planets
- s= the planet rotation periods number in its orbital period
- (the value "s" is belonged to the planet whose diameter is "r")
- I= Planet orbital inclination (of the planet whose diameter is "r")
- Example (Neptune Equation)
- (89143 /49528) = (9.7 /5.4) =1.8
- Neptune Orbital Period (59800 days) has 89143 Neptune rotation periods (16.1 h)
- 49528 km = Neptune Diameter
- 5.4 km/s = Neptune Velocity (The data error is less than 1%)
- 1.8 degrees = Neptune Orbital Inclination 9.7 km/s = Saturn Velocity

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(Question no. 9)/ Why Can Kepler Laws Predict Planet Motion Trajectory?
- Kepler laws predict, Planet motion trajectory is an ellipse and also its tells this
interesting law (p2
/d3
) = Constant - Let's modify the question –
- If planets creation data be created based on historical events and unknown random
factors how the planets motions can be defined based on exact laws and equations
as kepler laws?
- The planet motion according to Newton theory tells that
- Planet moves by the sun mass gravity – the idea – supposed the planet be created
(by any process) and by (any data) – The force depends on The Sun gravity
- Based on this idea we have 2 options
- (1st
Option) The Planet Motion Be In Harmony With This Planet Creation Data
(By Pure Coincidence) or
- (2nd
Option) The Planet Motion Be Not In Harmony With This Planet Creation
Data (The logical case) –
- In this last case The planet will be destroyed because the planet moves against its
creation data –
- This is similar to a wall be built in some water – the water will destroy this wall-
- Briefly, The Planet Can't Move Against Its Creation Data,
- That's Why Newton Theory of the sun gravity is mistaken –because it supposes
that – the planets motions be started after these planets creation – this meaning is
mistaken in its principle logic
- By that –No way to attribute the planet motion to its mass gravity to the sun –
because the motion was found before the planets creations – the motion forced to
create the planet creation data in a harmony with this motion- here we don't have 2
players (the planet creation process and its motion by the sun gravity) instead we
have one process contains the planets creations and their motions and create the
data based on exact equations and geometrical calculations to perform the final
harmony of the motions.

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(Question no. 10)
Can Planets Data Be Created Based On Exact Equations?
- Let's analyze this question in following:
- The question asks if planet data (Creation And Motion Data) be created based on
exact equations and mathematical calculations…
- For example, the moon diameter =3475 km,
- The moon be created by a collision be done by the Earth and another planet – how
the diameter 3475 km can be concluded based geometrical calculations? But
- 4900 million km = 3475 km x 1.392 million km (The Sun Diameter) also
- 4900 million km = 10921 km x 449197 km (Jupiter Circumference)
- 4900 million km = Jupiter orbital circumference
- If The Moon Diameter Isn't Created Based On Geometrical Calculations,
This Data Should Be Attributed To (Pure Coincidence). OR
- We have to suppose that the whole solar system data be created based on exact
equations and geometrical calculations.
- There are 2 reasons force us to accept that this hypothesis which are
- (1st
Reason)
- Kepler laws prove, Planets move based on exact laws and that necessitate the
planets data to be created based on exact equations and geometrical calculations
- (2nd
Reason)
- My 3 equations prove that we can conclude the planets data theoretically – means-
if we know that (Mercury orbital distance =57.9 million km) based on this one data
and by using of (my 3 equations) we can conclude theoretically All Planets orbital
distances, periods, velocities, inclinations, rotation periods, diameters, masses and
axial tilts – means – all planets data can be concluded theoretically without
observation by my 3 equations – that can be done only if – the planets data be
created based on exact equations and mathematical calculations.

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(Question no. 11)
Can The Planets Motions Be In Harmony If They Move By The Sun Gravity
Force As Newton Theory tells?
- NO
- Why? Because
- The theory tells,
- The Planet Be Created And Then Be Attracted By The Sun Gravity Which Caused
Their Motions
- Here,
- There are 2 forces effect on the planet
- The Sun gravity force which effects on the planet and causes its motion
- And
- This Planet Creation Data -
- If the planet motion contradicts its creation data that will cause to destroy it
- And
- We can't guarantee that the planet motion features don't contradict this planet
creation data – because
- The planet creation process is independent from this planet motion reason – that's
Why Newton Theory is (A Mistaken Idea In Its Original Logical Principle)
- If the solar system moves by the sun gravity force as Newton told that would cause
the solar system destruction (Newton Is Mistaken)

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(Question no. 12)
Why do Mercury, Venus and the Moon have long rotation periods? Because
- (A)
- The 3 planets rotation periods be defied based on the next formulation
- Planet rotation period = (Planet Circumference)2
/ Planet Orbital Velocity
- Mercury rotation period 1407.6 hours = (15327 km)2
/47.4 (error 2%)
- Venus rotation period 5832.5 hours x 2 = (38025 km)2
/35 (error 1.6%)
- The moon rotation period 655.7 hours x 2 = (10921 km)2
/27.78 (error 10%)
- 47.4 km/s = Mercury velocity 35 km/s = Venus velocity
- 27.78 km/s = The moon velocity (be proved in the paper discussion)
- 15327 km = Mercury Circumference 38025 km =Venus
Circumference
- Only the moon equation has an error (10%) but the 2 other planets data be defined
simply without great errors – We need to notice the following:
- (B)
- (29.53 days/27.3 days) =(243 days /224.7 days)
- 29.53 days = The Moon Day Period 27.32 days = The Moon Orbital Period
- 224.7 days = Venus Orbital Period 243 days = Venus rotation Period - And
- Venus Rotation Period 243 days = 1.0725 x 224.7 days (Venus Orbital Period)
- (The rate 1.0725 we discuss its origin in the paper discussion)
- It tells, Venus orbital period was = Venus rotation period (as in the moon case)
but the rate (1.0725) decreased Venus orbital period to be (224.7 days)
- Notice
- Mercury (47.4 km/s) moves in its rotation period (1407.6 h) a distance = 243
million km (error 1%) (if 1 million km = 1 day this distance will be = 243 days)
- That tells Venus rotation period (243 days) controls these 3 planets motions for
their rotation periods.

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(Question no. 13)
Why Don't Kepler Laws Depend On The Planets Order?
- Let's try to explain this question in following:
- My equation tells d2
= 4 d0 (d- d0)
- Example,
- (108.2)2
= 4 x 57.9 x (108.2-57.9) (Venus depends on Mercury)
- d= 108.2mkm (Venus Orbital Distance) d0= 57.9 mkm (Mercury Orbital Distance)
- My equation defines each planet orbital distance based on its direct neighbor.
- (Notice, Earth depends on Mercury, Mars on Venus and Pluto on Uranus)
- The question asks, while Kepler Laws tell (Planet orbit defines its velocity) why
doesn't use the planets order? Why does describe each planet case only?
- My equation works sufficiently and can be considered an important equation
because the gravitation equation contradict the planets order- and when we have
asked why? The answer was (because of the Initial Conditions) – where are them?
My equation defines each planet orbital distance clearly without problem.
- Why Doesn't Kepler Use The Planets Order? Kepler laws are more complex than
my equation! why he couldn't catch it? let's analyze this equation
-
- (1st
Point) Planets Data Can Be Concluded Theoretically
- Kepler tells (Planet Orbit Defines Its Velocity), means, if we know (Mercury
orbital distance = 57.9 million km) we can conclude theoretically Mercury orbital
period and velocity – and – my equation tells – If we know (Mercury orbital
distance =57.9 million km) we can conclude theoretically All Planets Orbital
Distances
- Means by one data we can conclude theoretically 27 data
- Why Planets data can be concluded theoretically?

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(Question no. 14)
Kepler (3rd
) Law tells (P2
/d3
) = Constant, Why?
- Kepler law tells that (Planet Orbital Distance Defines Its Velocity v), because,
- By planet orbital distance we can define its orbital period, then its velocity But
- (1)
- My first equation tells (d2
= 4 d0 (d- d0)) (the equation uses the planets order)
- My (1st
Equation) tells, each planet orbital distance depends on its neighbor And
- (2)
- My third equation tells (v1v2= 322) – for example
- Mercury Velocity (47.4 km/s) x Uranus Velocity (6.8 km/s) = 322 also
- Venus Velocity (35 km/s) x Pluto Velocity (4.7 km/s) x 2 = 322 (error 2%)
- Earth Velocity (29.8 km/s) x Neptune Velocity (5.4 km/s) x 2 = 322
- (3)
- We conclude that (v1/v2)2
= (d/d0) but (the equation doesn't use the planets order)
- Based on my third equation tells (v1v2= 322)
- Mercury (47.4 km/s) moves during 6.8 hours a distance =1.16 million km
- Uranus (6.8 km/s) moves during 47.4 hours a distance =1.16 million km
- Earth (29.8 km/s) moves during 2 x 5.4 hours a distance =1.16 million km
- Neptune (5.4 km/s) moves during 2 x 29.8 hours a distance =1.16 million km
- I want to say. Kepler (3rd
) law ((p2
/d3
) = constant) depends on the distance 1.16
million km – means- because the planets velocities are complementary one another
based on the distance 1.16 million km – because of that - ((p2
/d3
) = Constant)
- Means, Kepler (3rd
) law depends on this distance 1.16 million km!
- Why?

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(Question no. 15)
How Does Planet Create Its Data?
- (1)
- According to my analysis
- Planet orbital distance be defined at first (according to my first equation) and then
based on Kepler laws –Planet Orbital Distance Defines Its Orbital Period And
Velocity –
- Then
- The planets velocities rates (v1/v2) be used as planets orbital inclinations –
- Then
- By my second equation, planet rotation period and diameter can be defined as
functions in the rate (v1/v2)
- Also
- Planet orbital inclination be used as a rate between 2 planets masses
- My third Equation tells planets velocities be created complementary one another.
- (2)
- By My first equation d2
= 4 d0 (d- d0)
- (Notice, Earth depends on Mercury, Mars on Venus and Pluto on Uranus)
- (3)
- My (3rd
Equation)
- (v1/v2) = (s/r) = I
- v = Planet velocity and r= a diameter of one of the 2 planets
- s= the planet rotation periods number in its orbital period
- (the value "s" is belonged to the planet whose diameter is "r")
- I= Planet orbital inclination (of the planet whose diameter is "r")

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5- The Moon Orbital Apogee Radius Analysis
5-1 Preface
5-2 The Moon Orbital Motion Description (And Equation)
5-3 The Moon Orbital Apogee Radius Analysis
5-4 Can Uranus Motion Effect On The Moon Motion
5-5 The Moon Daily Displacement Analysis
5-6 The Moon And Mercury Motions Data Analysis
5-7 The Moon And Pluto Motions Data Consistency
5-8 Uranus Motion Effect On Pluto Motion
5-9 The Moon Orbital Apogee Radius Decreasing Details

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5-1 Preface
- As we have discussed, the moon apogee radius be decreased from 413600 km to
406000 km. let’s review why
- The moon displacement 88000 km and during 29.53 days (the moon day period)
the total be 2598693 km = 2π x 413600 km
- That means the moon apogee radius should be 413600 km but it be 406000 km
- Because
- The moon creates an angle (θ) between its motion direction and its orbit horizontal
level and by that the real displacement be (L = 88000 cos θ)
- That decreases the moon displacement and its total which causes to decrease the
moon apogee radius to (406000 km) – where
- 4136000 km x cos (θ) = 406000 km means (θ = 10.96 degrees)
- But
- Because the genus moon has this intelligent technique, the moon can decrease the
apogee radius even shorter than (406000 km).
- The question was why the moon choose this angle (10.96 degrees)??
- As we remember – another question can explain this one –
- Why does the moon move Metonic Cycle? Because The Earth doesn't? the answer
tells another planet motion must effect on the moon motion – and – the data shows
that the planet we search for is Uranus –
- The conclusion tells that, Uranus effects on the moon motion and causes it to move
Metonic Cycle – and by this effect the moon inherited the angle (10.96 deg) by
which the supposed apogee radius (413600 km) be decreased to be (406000 km)
- This process – as we have referred is complex one because it necessitates Uranus
motion to effect on Pluto motion and extend Pluto day period to be 153.3 hours,
this process also led to create Pluto orbital inclination to be 17.2 deg based on
which the moon orbital inclination be created 95.1 deg) and Venus orbital
inclination be created (3.4 deg)

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- The complex details provide a range of effect can't be explained by any known
force – the gravitation equation simply prevents Uranus effect on the moon – and
in much force Pluto effect on the moon -
- The simple question is,
- How Uranus motion effects on the moon and causes o decrease its apogee radius ?
by what force Uranus can do that? or how Pluto can have any effect in such
process?
- The answer tells
- The solar system is one machine be built based on one geometrical design, we can
imagine that, the solar system is similar to a chess board, each piece motion effects
on the other pieces motions – also the solar system be similar to a machine of gears
each gear motion effects on the others motions-
- Also the solar system is similar to a zither, it's a musical tool works by strings, the
motion of any string effects on the other strings motions- because this tool be built
on One Geometrical Design.
- Shortly
- The moon moves Metonic Cycle (19 years) and its apogee radius be decreased
from 413600 km to 406000 km by an effect of Uranus motion but this effect be
transported to the moon by the One Geometrical Design Controls The Solar
System – by that – Uranus causes the moon to be in the basic trajectory of the
solar system motion and the moon motion be effective as similar to any planet in
the solar system. For that reason we should consider the solar system be consisted
of 10 planets and not 9.
- The angle (10.96 degrees) be inherited from this effect. and because of that the
angle refers to the solar system one geometrical design – let's remember this data.
- From where the moon gets the angle (10.96 degrees)?
- From Uranus –
- Because

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- (153.3 h /17.2 h) = (97.8 deg /10.96 deg)
- Where
- 153.3 hours = Pluto Day Period
- 97.8 degrees = Uranus Axial Tilt
- 10.96 degrees = Our Angle
- This data shows that, Uranus causes the extension for Pluto day period basically
because of the angle (10.96 degrees)
- And
- 86400 seconds (the solar day) x sin (10.96 degrees) = 16330 seconds
- This period 16330s is The Cornerstone Of The Solar System Geometrical
Design
- Briefly
- What will we do in this point?
- We will analyze the moon apogee radius to discover (as possible) the geometrical
details of the machine by which Uranus effects on the moon motion and forces it
to move Metonic Cycle –and – forces the moon orbital apogee radius to be
decreased –
- Here – we discover a real part of the moon motion – But the rich moon doesn't
leave us to go empty, instead, The generous moon will provide us A Part Of The
Solar System Geometrical One Design Understanding.
-

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5-2 The Moon Orbital Motion Description (And Equation)
- Let's explain why we discuss the moon orbital equation in this point…
- The moon needs 1700 solar days to pass a distance = 149.6 mkm=Earth orbital
distance by using its daily displacement 88000 km
- If 1000 km = 1 degree, so 1700 days will be 1.7 degrees
- In fact the moon orbital equation uses the angle 1.7 deg as the moon motion angle
per a solar day
- Because of that, the angle 1.7 degrees found its source 1700 solar days.
- But
- Can 1000 km= 1 day or 1 degree?
- If that's happened so, the moon daily displacement 88000km will be equal 88 days
= Mercury orbital period
- And
- In many other situations we found that it's useful to use the rate 1000 km = 1 day
=1 degree and because of that we study the moon orbital equation to show how the
angle 1.7 degrees be used by the moon motion.
- Let's summarize the moon orbital motion equation in following

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I- Why Does The Moon Use Pythagorean Triangle In Its Motion?
- Let's summarize this question answer in following:
o The moon uses Pythagorean triangle basically to decrease its displacement
daily through its orbit
o The moon daily displacement = 88000 km and the moon has to move this
distance every day without any decreasing (later we will know why!)
o But
o If the moon moves by this displacement as its orbital displacement the moon
would revolve around Earth through its apogee orbit only (r=0.406 mkm)
o For that reason
o The moon creates an angle between its motion direction and its orbit
horizontal level to create a displacement through its orbit less than (88000
km)
o As a result of this technique, the moon can revolve around Earth through
more near orbits than apogee orbit (r=0.406 mkm)
o Simply, because the moon uses this technique the moon can revolve around
Earth through perigee orbit (r=0.363 mkm)
o Let's explain this intelligent technique with some details to show the useful
result of using Pythagorean triangle by the moon orbital motion….

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II- How Does The Moon Use Pythagorean Triangle In Its Motion?
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbit horizontal
level, by that the real displacement through the moon orbit will be (L= 88000 km
cos (θ)), and by that, spite the moon moves 88000 km, but the real orbital
horizontal displacement be less than (88000 km) and this is the objective for which
the moon uses Pythagorean triangle –
As an example,
- If (θ) =28.63 degrees, the real displacement (L== 88000 km cos (θ)) = 77237 km,
So, if the moon real displacement daily be (77237 km), during 29.53 days the
moon will pass a distance = 2.28 million km and this will be the moon orbital
circumference, where 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagorean triangle,
- Now let's suppose the moon doesn't use Pythagorean triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm where 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving around Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagorean triangle is so useful for the moon orbital motion.

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The Angle θ
- The angle (θ) should get our attention for its specific effect…let's summarize the
idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and by that the moon can be near or at
Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon can be near or at apogee orbit
(r=0.406 mkm)
o That means, the angle (θ) changes the real displacement (L) and also
changes the distance between the moon to perigee or to apogee, shortly, the
angle (θ) defines the moon position (as a ship) between 2 river banks….
- The angle (θ) defines the moon orbital motion basic features and we have to
discuss is deeply with the moon orbital motion equation (θ1= θ0 + 1.7 degrees),
but before we need to analyze the moon orbital motion
Notice
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee, we will need
this notice later in our discussion

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III- The Moon Orbital Motion
- The moon moves per a solar day a motion typical to the Earth motion to avoid the
- If there's no Lorentz Length Contraction Phenomenon effect on the moon motion,
the moon motion trajectory would to be a parallel line to Earth Motion Trajectory,
But Lorentz Length Contraction effects on the moon motion daily distance (2.573
mkm) with a rate 1.0725 and causes this distance to be contracted (2.399 mkm)
distances (0.17 mkm) will cause the moon to be separated from Earth motion
inevitably
- Now the moon has an additional distance to be passed (0.17 mkm) and the moon
has to pass this distance on the same solar day to avoid the separation from the
Earth during their motions.
distance (0.17 mkm) to be covered still needs the moon to move one more

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because this total distance (0.17 mkm) is required to cover the different distance
and create the total (2.573 mkm) which saves the moon and Earth motions
accompanying.
o (1st
o (2nd
and their total distance =0.17 mkm which is a required distance necessary to
cover the difference between the moon and Earth motions distances.
- This explanation helps us to understand why the moon uses Pythagorean triangle
in its motion, because the moon can't decrease its daily displacement (88000 km)
because the moon needs this distance to cover the different distance between its
contracted motion distance (2.399 mkm) and Earth motion distance (2.573 mkm),
So the moon needs to move this displacement perfectly, but if it's used as a
displacement through the moon orbit, the moon would be always a prisoner in the
apogee orbit (r=0.406 mkm) as we have discussed before, because of that, the
moon creates Pythagorean triangle technique by which the moon moves actually
88000 km daily but the real displacement through the moon orbit became less (L =
88000 Cos θ) and by that the moon can achieve 2 objectives, First to pass the
required distance (88000 km) and Second to move in near orbits to Earth, that
shows the intelligent moon motion technique…
- (Notice, Lorentz Length Contraction Effect Discussion is in Appendix No. 1)

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The Moon Orbital Motion Needs One More Orbit
- The previous explanation tells that, the moon moves 2 displacements each =88000
km, we see one of these 2 displacements but where's the other displacement?!
- We know that, the moon original motion (2.573 mkm) which is contracted to be
(2.399 mkm) isn't seen by us because the moon moves this distance revolving with
Earth around the sun along the Earth Orbital Circumference
- We may accept that, the 2nd
displacement the moon does on this same trajectory
and isn't seen by us.
- So,
- There must be one more orbit for the moon to move through this 2nd
displacement.
means,
- There's 2nd
Orbit For The Moon Motion
- But
- How can we discover this second orbit if we can't observe the 2nd
displacement
motion?
- We can discover this 2nd
orbit by the moon orbit data analysis. So we should
depend on the moon orbital triangle data analysis to define this 2nd
orbit position.
- For that we have to discuss the moon 2nd
orbit in our deep analysis of The Moon
Orbital Triangle Geometrical Structure.

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IV- The Moon Orbital Motion Equation
A- The Equation Concept
B- The Equation Test and Accuracy
A- The Equation Concept
The Moon Orbital Motion Equation
(θ1= θ0 + 1.7 degrees)
- The moon orbital motion equation is created depending on the concept we have
discussed, which is (the moon uses Pythagorean triangle in its orbital motion)
- The moon uses Pythagorean triangle and by this intelligent technique the moon be
under control of the angle (θ) change
- The angle (θ) defines almost all the moon motion features.…
- The moon uses this technique, aiming to create a real displacement shorter than its
actual displacement (88000 km) based on the equation (L =88000 cos (θ)) and by
that while the moon moves a displacement =88000 km but the real displacement
(L) through its orbit be shorter than 88000 km and by that the moon can revolve
around Earth through more near orbits than its apogee orbit (r=0.406 mkm).
- The moon orbital motion equation depends on this concept and, the equation
uses (the constant) 1.7 degrees as the moon daily motion degrees, and the equation
uses the previous day angle (θ0) to produce the today angle (θ1)
- We have 3 questions in this equation study which are:
o How does this equation work?
o Is this equation trustee and correct?
o Why does the equation use the angle 1.7 degrees for the moon daily motion?
Let's try to answer….

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How to use this equation?
- Perigee Radius =0.363 mkm, so Its Orbital Circumference =2.28 mkm
- Suppose the moon will revolve around Earth through perigee orbit only during
29.53 days, so
- (2.28 mkm /29.53 days) = 77237 km
- This is (the real displacement = L = 88000 km Cos θ = 77237 km),
- What's the angle θ value? the angle θ = 28.63 degrees
- Suppose the moon stand on this point yesterday with the angle (θ) =28.63 degrees,
where the moon will move today?
- From Perigee (the most near point to Earth) the moon will move in Ascending
motion because it moves from perigee (0.363 mkm) to apogee (0.406 mkm)
- In Ascending motion we use (-1.7 degrees) because the angle (θ) is decreased
where the real displacement (L) is increased, So let's do that in following
o (θ1= θ0 - 1.7 degrees)
o (θ1= 28.63 degrees - 1.7 degrees) = 26.93 degrees
o L = 88000 Cos (26.93 degrees) = 78454 km
o During 29.53 days so (78454 km x 29.53 days = 2.316 mkm)
o 2.316 mkm = 2π x 368722 km
That means
o The moon was (before motion) on Perigee radius (r=0.363 mkm) and starts
its motion displacement 88000 km. For day motion the equation uses 1.7
degrees, that means, the moon on perigee uses Pythagorean triangle with
angle (28.63 degrees) and during one solar day the moon uses - 1.7 degrees
and by that the angle will be (26.93 degrees)…... The angle 1.7 degrees
expresses The Moon Daily Motion
o By using Pythagorean triangle its angle (θ) = 26.93 deg, the displacement
(88000 km) will create a real displacement through the moon orbit = 78454
km and the moon will finish its motion today at a distance 368722 km

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means the moon is far from perigee radius with (368722 km-363000 km
=5722 km )
o So, the moon after 1 day motion will be at the point 368722 km and will
have the Pythagorean triangle its angle 26.93 degrees.
The Descending Motion
o When the moon moves from apogee (0.406 mkm) to perigee (0.363 mkm),
so the angle (1.7 degrees) will be positive (+1.7 degrees) because the angle
(θ) is increased and the real displacement (L = 88000 Cos (θ)) be shorter.
So
o If the moon in apogee radius (r=0.406 mkm), what's the angle (θ)?
o The apogee orbital circumference = 0.406 mkm x2π =2.55 mkm = 29.53
days x 86400 km, the angle (θ) = 10.96 degrees (=11 deg approx.)
o The moon moves from apogee to perigee (descending motion)
o (θ1= θ0 + 1.7 degrees) means (θ1= 11 degrees + 1.7 degrees) = 12.7 deg.
o L = 88000 Cos (12.7 degrees) = 85847 km
o During 29.53 days so (85847 km x 29.53 days = 2.535 mkm)
o 2.535 mkm = 2π x 403467 km
So
o After one day the moon will be on 403467 km far from apogee (406000 km)
with 2540 km
Now let's see this equation test and efficiency in following

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B- The Equation Test and Accuracy
- I have tested the Equation with real data for 2 months June 2020 and October 2020
- The results are very good and I provide the results here for better vision
concerning the equation efficiency
1st
Test June 2020
Day Registered Data The Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[

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The 1st
Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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2nd
Test October 2020
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[

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The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily

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The Value 1.7 degrees
- The 3rd
question was, why the equation uses 1.7 degrees?
Because
1.7 degrees = 0.98562 degrees + 0.712 degrees
Where
- 0.98562 degrees = Earth motion daily degrees, and it equals the moon daily
motion degrees because the moon has to move an equal distance to Earth motion
daily distance to save their motions accompanying
- This question and the angle 0.712 degrees is discussed in my previous paper.

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The Moon Motion Difficulties
- There are 2 basic difficulties are observed in the moon orbital motions, let's refer
to them in following:
o (1st
Difficulty) The moon moves per day different distances from perigee to
apogee…..
o We know the moon moves from perigee to apogee (go and back) during
Anomalistic month (27.55 solar days)
o (43000 km x 2) / 27.55 days = 3122 km
o The moon doesn't use this rate (3122 km) in its motion, instead the moon
can move (6000 km) on one day only and on another day may move only
2500 km (or even less)!
o The moon orbital equation tries to solve this difficulty by using the rate 1.7
degrees in the equation (θ1 = θ0 + 1.7 degrees), the value 1.7 degrees is a
great number and enables the moon to move around (5000 km) per solar day
and by that if the moon moves per solar day 4000 km the different distance
will be 1000 km and if the moon moves 6000 km the different will be
– 1000 km, it’s the same difference, and by that, the error be minimized as
possible enabling the equation to be more efficient..
o (2nd
Difficulty) The moon stays in perigee and apogee points long time….
- That means, while the moon be on perigee or apogee, the moon doesn't use the
equation and doesn't change its distance to perigee or apogee for long days…we
may notice that in the equation tests, when the moon reach to perigee or apogee the
equation stops its work and stays 2 or 3 days to return to its work… because the
moon consumes long time to leave the points (perigee and apogee)…

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5-3 The Moon Orbital Apogee Radius Analysis
Let's remember our questions
- Why Does The Moon Orbital Apogee Radius Be = 406000 km?
- Why Does The Moon Move Metonic Cycle (19 years)?
- Why the moon displacement daily be 88000 km only where the moon motion data
analysis showed that, the moon needs daily a distance = 176000 km?
1st
Question
Why The Moon Orbital Apogee Radius =406000 km?
- The moon daily displacement is 88000 km and during 29.53 days (the moon day
period), the total be =2598693 km = 2π x 413600 km – means
- The moon orbital apogee radius should be 413600 km, How it be 406000 km??
- (1)
horizontal level, by that, the real displacement (L) through the orbit be shorter than
88000 km because it be (L = 88000 km cos θ) – by this technique the total be
2.5509 mkm (r=0.406 mkm) in place of 2.5986 mkm (r= 0.4136 mkm)
- Also we note
- If the moon motion depends on the daily displacement 88000 km without using the
angle (θ) in its motion, the moon apogee radius would be 413600 km and also the
moon would be prisoner in this orbit (r=413600 km) and has to revolve around the
Earth through this orbit only, and can't revolve through any more near orbit.
- Also we note
- Because the moon creates an angle (θ) between its motion direction and its orbit
horizontal level, the moon motion basic points be defined based on one another by
using Pythagorean rule – let's test that –
- The moon points are (Perigee radius 363000km, total solar eclipse radius 373000
km, the moon orbital distance 384000 km and the apogee radius 406000 km), these
4 radiuses be defined based on one another in order (by Pythagorean rule)

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- Example,
- (363000 km)2
+ (86000 km)2
= (373000 km)2
- The rest radiuses be defined by similar calculations – just the apogee radius needs
to use the rule (2 times) to reach to it from the radius (384000 km)
- The dimension 86000 km be used for all radiuses –
- (86000 km = 2 x 43000 km the distance between the perigee and apogee)
- The 4 points be defined by Pythagorean rule because the moon uses the angle (θ)
in its motion- that enables the angle (θ) to control the moon motion features – As a
result the moon motion orbital equation be (θ1= θ0+ 1.7 deg)
- (2)
- The radius 413600 km be decreased to 406000 km based an angle (θ = 10.9 deg)
- 413600 km cos (10.9 degrees) = 406000 km also
- 406000 km sin (10.9 degrees) = 77235 km
- 413600 km sin (10.7 degrees) = 77235 km
- Where
- 77235 km x 29.53 days = 2.28 mkm = 2π x 363000 km (Perigee Radius)
- Means, the apogee and perigee radiuses be defined based on the angle (10.9 deg)
- Also we note
- The angle (θ) controls the motion features –let's define it in the basic radiuses
- (Perigee Radius 363000) uses an angle (θ = 28.63 degrees) – because
- 88000 km cos (28.63 deg) = 77235 km during 29.53 days (total be 2.28 mkm)
- (Apogee Radius 406000) uses an angle (θ = 10.9 degrees) – because
- 88000 km cos (10.9 deg) = 86400 km during 29.53 days (total be 2.5509 mkm)
- And (θ = 28.63 degrees) - (θ = 10.9 degrees) = 17.73 degrees
- Means, the angle 17.73 degrees controls the moon motion between the perigee and
apogee – that shows a great importance for this angle (17.73 degrees).

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- (3)
- In This Right Triangle
- (1)
- If the dimensions (BC) = Perigee Radius = 363000 km and AB = 86000 km
- The angle (C) = 13.32 degrees
- (2)
- If the hypotenuse (AC) = Apogee Radius = 406000 km and AB = 86000 km
- The angle (C) = 12.22 degrees
- The difference = (13.32 deg – 12.22 deg) = 1.1 degrees
- Shortly
- The angle (1.1 degrees) controls the moon motion through the distance between
perigee and apogee –that means – The angle (1.1 deg) controls the moon motion
(totally) – we have 2 notices here
- Notice No. (1)
- The moon motion from perigee to apogee depends on 2 angles which are (17.73
degrees and 1.1 degrees), these 2 angles be analyzed deeply later – but
- What we need here only is to add them
- 17.73 degrees + 1.1 degrees = 18.83 degrees
- The moon orbit regresses yearly 19 degrees (error 1%) and the moon regression is
the reason behind Metonic Cycle –
- Means, the moon motion between perigee to apogee be effected and controlled by
the moon orbit regression.
- That shows a continuous effect in the moon motion data
- Notice No. (2)
- 97.8 degrees (Uranus Axial Tilt) = 1.1 deg + 96.7 deg (= 90 deg +6.7 deg)
- 96.7 degrees =1.1 deg+ 95.6 deg (=90 deg+5.1 deg +0.5deg)
- 95.6 degrees = 1.1 deg + 94.5 deg
- 94.5 degrees = 1.1 deg + 93.4 deg (= 90 deg +3.4 deg)

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- Where
- 6.7 degrees = The Moon Axial Tilt
- 0.5 degrees = The Moon Diameter Angle
- The system of data depends on the angle 1.1 degrees. Why?
- The moon motion depends on the angle (1.1 degrees) and that tells these values be
defined based on the moon motion (the values are 6.7, 5.1 and 3.4)
- (Notice, 5.6 degrees be = the moon orbital inclination when be measured above the
moon diameter)
- Notice No. (3)
- Uranus motion effect on the moon motion be seen in this angle 19 degrees and
because of that, Uranus motion effects the moon motion generally because this
angle 19 degrees = 1.1 deg +17.73 deg, the 2 angles control the moon motion
between the perigee and apogee –
- In point no. (6-4) We discuss Uranus motion effect on the moon motion by this
angle (19 degrees).
- Here we have a clear point, where, the moon moves Metonic Cycle (19 years)
because the moon orbit regresses (19 degrees yearly) and the moon orbital
inclination be 5.1 degrees because of this angle (19 degrees) (as we should discuss
later) and because of the moon orbital inclination (5.1 deg) the moon apogee radius
- Notice
- 19 degrees = 17.2 deg (Pluto orbital inclination) +1.8 deg ( Neptune Orbital
Inclination)- and
- 17.73 degrees = 17.2 degrees +0.5 degrees (The Moon Diameter Angle)

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- (4)
- (I)
- In the figure,
- The inner circle refers to perigee orbit (r=363000 km)
- The outer circle refers to the apogee orbit (r=406000 km)
- (406000)2
= (181843)2
+ (363000)2
- The dimension DB = 181843 km
- The perigee radius (363000 km), its circumference (2.28 mkm)
- (181843 km/2.28 mkm) = 0.08 - we remember that
- (II)
- We have the angle (10.9 degrees) and rate (0.08) by them we found that
- 137 degrees x 0.08= 10.9 degrees And
- 137 degrees = 95.1 degrees x 1.44 degrees
- (1.44 degrees = the moon orbit regression degrees monthly)
- (95.1 degrees = 90 degrees +5.1 degrees The Moon Orbital Inclination)
- means, the moon motion depends on its orbital inclination (5.1 deg) and its orbit
regression angle monthly (1.44 deg) where based on these values the angle (137
deg) be created by which the 2 values (10.9 degrees and 0.08) are produced
- The figure shows the effect of this data on the moon orbital motion and how this
effect creates A Specific Geometrical Design for the moon orbit, depending on
Pythagorean triangle (1,2 and51/2
)
- Notice
- The moon velocity =27.78 km/s, we have proved before
- But
- (27.78 =1/(sin 10.93)2

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- (That tells the angle (10.9 deg) has a great effect on the moon motion)
-
- Notice
- Because the angle (θ = 10.9 deg) is different from (10.7 deg) with (2%) and
- The radius 413600 km is different from 406000 km with (2%), that shows a
proportionality between the moon and Saturn motion, we should discuss it later
- Specially because
- The moon displacements total be =940 mkm = Earth orbital circumference during
a period =10747 days = Saturn orbital period

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5-4 Can Uranus Motion Effect On The Moon Motion
2nd
Question
Why Does The Moon Move Metonic Cycle (19 years)?
- We accepted that, another planet motion must effect on the moon motion to force
the moon to move Metonic Cycle (19 years) because Earth Cycle is 4 years (= 365
+365 +365 +366 = 1461 days),
- The planet its motion effect on the moon motion must provide the number (19)
where Metonic Cycle extends (19 years) because the moon orbit regresses (19
degrees) yearly.
- The planet we search is Uranus because
- (1)
- Uranus orbital distance 2872.5 mkm =19.2 Earth orbital distance 149.6 mkm,
means, If the 2 Planets velocities are equal, while Uranus revolves around the sun
one revolution, Earth would revolve 19 revolutions (19 years).
- Uranus data provides the period (19 years) we need, Can Uranus motion effect on
the moon motion and force it to move Metonic Cycle (19 years)? the following
data can help
- More Data
- (a) Uranus axial tilt 97.8 deg = 19.2 x 5.1 deg (the moon orbital inclination)
- (b) 23.75deg x 0.8 deg = 19 deg (where 0.8 deg = Uranus orbital inclination) and
(23.4 deg is different from 23.7 deg with error 1.5%),
The Moon Orbit Regresses Yearly 19 Deg
- (c) (Uranus mass / Earth mass) =(Uranus diameter / the moon diameter) (error 1%)
- (Notice 23.45 deg x 0.8 = 18.83 deg = 17.73 deg +1.1 deg)

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- (2)
- In the figure, the blue ball is Uranus, and the green ball is the Earth – the blue
circle is the moon orbit around the Earth – (the brown arrow refers to the circle
tangent and Earth effect on the moon motion- and the blue arrow refers to Uranus
effect on the moon motion)
- The figure shows that there's a perpendicularity between the 2 planets effects on
the moon motion.
- (A)
- The moon motion be shown as a wave form which be created by effect of 2
forces – Earth force effects horizontally and Uranus force effects vertically
- (B)
- The moon axial tilt (6.7 deg) declines on the Earth ecliptic with (1.6 degrees)
because the moon orbital inclination = 5.1 degrees And
- 97.8 deg (Uranus axial tilt) – 6.7 deg (the moon axial tilt) = 91.1 degrees, means
- 97.8 deg (Uranus axial tilt) – 96.7 deg (the moon axial tilt vertically) = 1.1
- but
- 1.6 degrees = 1.1 degrees + 0.5 degrees (The Moon Diameter Angle)
- By that the 2 forces effect on the moon be perpendicular on each other (takes into
account the moon diameter angle) and that means – Uranus caused the moon
orbital circumference to be 5.1 degrees and also caused the moon diameter angle to
0.5 degrees by that the total be 5.6 degrees
- (The moon orbital inclination when be measured above the moon diameter = 5.6 deg)
- NOTICE
- The data shows a proof for the idea – because – the degrees (1.6 deg) is accounted
based on the moon orbital inclination on the Earth elliptic line – means – Uranus

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data should not be a player in the definition of this value (1.6 degrees) – but on the
other side – Uranus axial tilt causes to create the angle (1.1 degrees) with the
moon axial tilt on vertical axis (6.7 deg + 90 deg = 96.7 deg) – But the difference
between (1.6 degrees) - (1.1 degrees) = 0.5 degrees where the moon diameter
angle be = 0.5 degrees
- I try to show we have 2 players (the Earth and Uranus) effect on one point (the
moon) and their effects create harmony and consistency for their data – it's hard to
do that if there's no an interaction between the 2 players themselves– that proves
Uranus effect on the moon motion must be a real one and Uranus causes the moon
to move Mertonic Cycle – and this effect on Uranus motion on the moon motion
be seen in the moon motion data. - Please remember-
- 97.8 deg = 1.1 deg +96.7 deg (= 90 deg + the moon axial tilt 6.7 degrees)
- 96.7 deg = 1.1 deg +95.6 deg (= 90 deg +5.6 degrees)
- 95.6 deg= (2 x 1.1 deg) + 93.4 deg (= 90 deg + 3.4 deg)
- (this system of data we have discussed in point no. 6-3)
- Notice
- The angle (1.1 degrees) = 0.5 degrees + 0.6 degrees Where
- (0.5 degrees) = The Moon Diameter Angle and (0.6 degrees) = ???
- This angle shows a significant data because
- 1.3 deg (Jupiter orbital inclination) + 0.6 deg = 1.9 deg (Mars orbital inclination)
- And
- 1.9 deg (Mars orbital inclination) + 0.6 deg = 2.5 deg (Saturn orbital inclination)
- That shows an interaction is done between Jupiter and Saturn motion based on this
angle (1.1 deg) - And
- (708.7 h /10.7 h)= (655.7 h/ 9.9 h)= (224.7/3.4)= (2 x 153.32
h)/708.7 h = 66.2
- This equation we should discuss with Pluto and the moon motions data analysis
(Point no. 5-7)
- Notice 587500 km Uranus motion distance daily/88000 km the moon displacement=
6.7 ( 6.7 degrees = The Moon Axial Tilt And)

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(3) (Light Motion Effect)
(A)
- Uranus Motion
- During 15559s light supposed velocity (1.16 mkm/) travels 18048=2π x 2872 mkm
- Where
- 2872 mkm = Uranus Orbital Distance
- Uranus moves during 30589 hours a distance = 742 mkm (error 1%)
(B)
- The Earth Moon Motion
- During 639s light supposed velocity (1.16 mkm/) travels 741 mkm
- During 6393s light known velocity (0.3 mkm/) travels 191.6 = 2π x 30.5 mkm
- But
- 30.5 mkm = 88000 km x 346.6 days
- The moon displacements total during 346.6 (solar days) = 30.5 mkm
- Where
- 346.6 solar days= The nodal year
- 88000 km = The moon displacement for a solar day
- 742 mkm = The distance be passed by Uranus in 30589 hours (error 1%)
- The data tells, the moon orbit regression be done by effect of Uranus motion.
- We have studied this data before with the other planets and found that the distance
742 mkm causes to create the moon nodal year (346.6 days)
- Notice/
- The moon motion uses 346.6 days and not 346.6 hours.
- This data also can prove Uranus motion effect on the moon motion and causes to
create the nodal year (which be found as a result for Metonic Cycle)

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5-5 The Moon Daily Displacement Analysis
3rd
Question
Why Does The Moon Move Daily A Displacement = 88000 km?
- The moon moves with The Earth and by its Earth velocity daily, this fact we know
because the Earth and the moon move together and don't separate each other
through the motions course revolving around the sun.
- Means,
The moon moves a distance/ solar day =Earth motion distance /solar day = 2.574
million km.
- But
- The moon distance (2.574 mkm) be contracted by the rate 1.0725 and for that this
distance 2.574 mkm be 2.4 mkm
- Now the moon difficulties be started, because, the difference 176000 km will
cause the moon to be separated from the Earth in their motions course
- For that reason the moon moves a displacement =88000 km (50%) depending on
the Earth gravity –
- We notice that, we don't see the moon motion for the distance 2.4 mkm neither the
original one 2.574 mkm, we see only the moon displacement 88000 km in the
Earth sky –
- The question we need to solve is that, why the moon doesn't separate from the
Earth if the different distance be 176000 km and the moon moves only 88000 km?
how the rest (88000 km) be adjusted?
- This story is a complex one and we need to move step by step to catch the idea
behind
- Firstly, how the rest distance (88000 km) be adjusted? This question answer be
provided by the generous Mercury, because Mercury is the basic helper behind the
moon motion - any way – Mercury uses very strange language for us – where the

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moon displacement be 88000 km Mercury sees it as (88 days = Mercury orbital
period) and while the required distance is 176000 km, (Mercury day period =176
days approximately) – means – Mercury is our hope now –
- but
- Before we should ask what's this rate (1.0725) which caused to decrease the moon
motion distance from 2.574 mkm to 2.4 mkm.
(1) (The Rate 1.0725)
I-Data
(a)
778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (Jupiter Mercury Distance)
(b)
720.7 mkm (Jupiter Mercury Distance)= 1.0725 x 670.4 mkm (Jupiter Venus Distance)
(c)
670.4 mkm (Jupiter Venus Distance)= 1.0725 x 629 mkm (Jupiter Earth Distance)
(d)
629 mkm (Jupiter Earth Distance)= 1.0725 x 586.5
And
586.5 mkm = 1.0725 x 550.7 mkm (Jupiter Mars Distance)
(e)
4495.1 mkm (Neptune Orbital Distance) =1.0725 x 2 x 2094 mkm (Jupiter Uranus Distance)
(f)
5906 mkm (Pluto Orbital Distance) = (1.0725)2
x 5127 mkm (Jupiter Pluto Distance)
(g)
5127 mkm (Jupiter Pluto Distance) = (1.0725)2
x 4437 mkm (Mercury Neptune Distance)
(h) (Please Remember)
2.574 mkm (Earth motion distance daily) = 1.0725 x 2.4 mkm
Notice
(1.0725)2
= (1.16) (error 0.8%)

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II-Discussion
- Let's remember
- Why do we need to study the rate (1.0725) in this point?
- Because,
- The moon moves per a solar day a distance = 2.574 mkm = The Earth motion
distance per a solar day, but this rate (1.0725) effected on the moon motion
distance and doesn't effect on the Earth motion distance by that the moon motion
distance be 2.4 mkm and that creates a different distance between the Earth and the
moon motions distances = 2.574 mkm – 2.4 mkm = 176000 km
- The moon has to move 88000 km daily (its displacement) depending on the Earth
gravity.
- What's this rate (1.0725)??
- This rate effects on (40%) of all distances in the solar system, in appendix no. (1)
there's a list of these distances.
- And
- The rate (1.0725) effects specially on all distance between Jupiter and the other
planets! This feature we have discovered before where – Jupiter distances be
distributed based on the rate (1.0725) –
- Why this rate (1.0725) be found?
- The answer tells,
- The Rate (1.0725) is (A Rate Be Produced By Lorentz Length Contraction
Phenomenon)
- Shortly
- A velocity = 99% of light known velocity 0.3 mkm/s causes a length contraction
rate 7.1 but
- (7.1/100) + 1 =1.071
- This is the most near rate to ours (1.0725)
- The idea tells, the distances be contracted by length contraction phenomenon- and
that's happened for the moon motion distance – And

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- This is happened also for Jupiter all distances –
- We can conclude simply that, the very close relationship between the moon and
Jupiter motions (will be discussed later) is the reason why the moon motion be
effected by the rate (1.0725) –
- Regardless the idea (Lorentz Length Contraction Phenomenon), the fact is that,
the rate (1.0725) effects on all Jupiter distances and a very close relationship be
found between the moon and Jupiter for that reason the moon be effected by its
master motion features
- For revision we may refer to some of Jupiter distance in following
- 778.6 mkm (Jupiter orbital distance) = 1.0725 x720.7mkm (Mercury Jupiter Dis)
- 720.7 mkm (Mercury Jupiter distance) = 1.0725 x 670 mkm (Venus Jupiter Dis)
- 670 mkm (Venus Jupiter distance) = 1.0725 x 629 mkm (Earth Jupiter Dis)
- 629 mkm (Earth Jupiter distance) = (1.0725)2
x 550.7 mkm (Mars Jupiter Dis)
- The data shows that, the distances be created based on one another by this rate
(1.0725) and that tells Jupiter motion be under (Lorentz Length Contraction
Phenomenon) that explains why its all distances be rated with (1.0725)
- Notice
- The (Lorentz Length Contraction Phenomenon) isn't limited for this rate
(1.0725) in the solar system. many other rates be used but all of them be created by
the same one velocity (99% of light velocity 300000 km/s), for that reason, the rate
(7.1) also be used – as in following
- 2.574 mkm (Earth daily motion distance) =7.1 x 0.363 mkm (the moon perigee
radius)
- 778.6 mkm (Jupiter orbital distance) =7.1 x 108.2 mkm (Venus orbital distance)
- But, The idea is that,
- The (Lorentz Length Contraction Phenomenon) is done based on the rate 7.1
- because its velocity equals (99% of light velocity 300000 km/s) but the solar
system geometrical design creates different forms (as 1.0725) to use this rate (7.1)

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- (2) (The distance 742 mkm)
- Because light motion analysis shows that, the distance (742 mkm) is the
connection between the moon and Uranus motions, we analyze it in following:
- (a)
- Uranus moves in 30589 hours a distance = 742 mkm
- (b)
- The moon displacements total in 346.6 days be = 30.5 mkm = (742 mkm /2π)
- The distance 742 mkm is a cornerstone for Uranus motion and the moon motion!
- The light motion data analysis for Uranus and the moon motions concerning the
distance 742 mkm supports the claim that (Uranus motion effects on the moon
motion and caused it to move Metonic Cycle 19 years)
- Notice (1)
- The value 742 is found in Uranus data by specific details because
- Uranus day period = 61920 seconds and Uranus orbital period =30589 days
- We know that
- The period (1 solar day) of a planet motion be= the period (1 second) of light
motion – for that reason – All planets orbital periods can be used in seconds units
in place of the days units (30589 seconds)
- Now
- 61920 seconds = 2 x 30589 seconds + 742 seconds
- We know 1 mkm can be = 1 day or 1 second
- I try to show that, the value 742 is found deeply in Uranus motion data for basic
geometrical reasons and necessities.
- Notice (2)
- light (0.3 mkm/s) travels during 742 seconds a distance =222.6 mkm (if 1 mkm = 1
day this number 222.6 days be = Venus orbital period 224.7 d, error 1%)
- Notice (3) - The moon displacements total during (2 x 4222.6 days) = 742 mkm
(4222.6 h = Mercury day period)

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5-6 The Moon And Mercury Motions Data Analysis
I- Data
(1)
The solar planets days periods total = 3766.6 hours = 0.89% of Mercury day period
(2)
4222.6 h (Mercury day period) = 3766.6 hours (89.1%) +456 hours (10.9%)
(3)
3766.6 h = 344.6 h x 10.9
(4)
4222.6 h (Mercury day period) x 2 = 344.6 x 24.5
(5)
456 h= 47.4 x 9.7 (error 0.8%)
Where
47.4 km/s = Mercury velocity
9.7 km/s = Mercury velocity

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II- Discussion
- Why do we study Mercury data here?
- Because
- The difference (10.9%) be found between Mercury day period (4222.6 h) and the
rest planets days periods total (3766.6 h)
- I suppose this difference (10.9%) is related to the moon motion angle (10.9 deg)
by which the apogee radius (413600 km) be decreased to (406000 km)
- Again Mercury uses the strange language
- Our 88000 km (the moon displacement) be as (88 days Mercury orbital period)
- The required distance 176000 km be as (175.9 days Mercury day period)
- And the angle (10.9 degrees) be as (10.9%)
- It's hard all numbers be typical by chance – a geometrical mechanism behind must
be found .
Notice
(1)
365.25 s x 0.3 mkm/s x π = 1.16 mkm/sec x 299.2 s
(2)
10747 s x 0.3 mkm/s x π = 1.16 mkm/sec x 9007s (error 3%)
No. (1)
365.25 s x 0.3 mkm/s x π = 1.16 mkm/sec x 299.2 s
- 365.25 days = Earth orbital period
- 0.3 mkm/s = light known velocity
- 1.16 mkm/s = light supposed velocity
- 299.2 mkm = the Earth orbital diameter (= 2 x 149.6 mkm)
- Earth orbital period (365.25 days) be used in seconds units (365.25s) and its orbital
diameter (299.2 mkm) be used in second periods ( 1 mkm= 1 second)
- Spite that
- Earth data be created in proportionality for the 2 light beams velocities rate –

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No. (2)
10747 s x 0.3 mkm/s x π = 1.16 mkm/sec x 9007s
- 10747 days = Saturn orbital period
- 9007 mkm = Saturn orbital Circumference (error 3%)
- The point is that, Saturn orbital period = 10747 days = 365.25 x 29.4 and the moon
day period = 29.53 – that makes Saturn orbital period is related almost with the
Earth orbital period –
- Light behavior with Earth and Saturn motions be distinguish from all other planets
motions – and we know that the sun circles Earth during 365.25 days and gives it
the same one face always
- I want to say, This distinguish behavior of the sun toward the Earth depends on a
distinguish behavior of light motion concerning Earth motion data – if this is
correct – we should ask (If the sun gives one face to Saturn also as The Earth)

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5-7 The Moon And Pluto Motions Data Consistency
- 17.2 degrees = Pluto Orbital Inclination
- And
- (θ = 10.9 deg) = the moon motion angle by which the apogee radius be decreased
from 413600 km to 406000 km
- Notice
- 17.2 deg – (θ = 10.9 deg) = 6.3 deg
- (1) (The Rate 6.3)
- Pluto motion data on one side and The Earth with its moon Motions Data on the
other side be rated by this rate (6.3), the following data proves this idea
- (A)
- 5906 mkm (Pluto orbital distance) = 940 mkm (Earth orbital circumference) x 6.3
- 153.3 hours (Pluto day period) =24hours (Earth Day Period) x6.3 (error 1.4%)
- 90560 days (Pluto orbital period) = 1461 days (Earth Cycle) x 6.3 x π2
- (B)
- Pluto (4.7 km/s) moves during a solar day = 406000 km = apogee radius
- Pluto (4.7 km/s) moves during Pluto day 153.3 h = 2.5986 km = the moon
displacements Total during 29.53 days
- Earth moves during a solar day =2.574 mkm is different with 2.598 mkm by 1%
- (C)
- 406000 km (Pluto motion daily) / (88000 km the moon displacement) = 4.61
- (708.7h the moon day period /153.3h Pluto day period) = 4.61
- (Notice sin 4.61 deg = 0.08)
- (D)
- Pluto day be created as a function in the moon cycles – the data proves that -
- Tan (12.19) x 708.7 hours = 153.3 hours (708.7 h = the moon day period)
- Tan (13.17) x 655.7 hours = 153.3 hours (655.7 h = the moon rotation period)
- (10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- 13.177 degrees = The Moon Daily Motion Degrees

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- (E)
- Pluto (4.7 km/s) moves during 88000 seconds a distance 413600 km
- Pluto (4.7 km/s) moves during 10.7 h (Saturn day period) a distance 181800 km
(the distance 181800 km we have discussed in the 2 concentric circles figure)
- Notice
- 413600 km x cos (10.7 degrees) = 77235 km
- (77235 km) x 29.53 days = 2.28 mkm (the perigee circumference)
- 363000 km x sin (θ) = 77235 km based on that (θ) = 12.19 degrees
- (12.19 deg = 13.17 deg – 0.986 deg)
- Notice
- (708.7 h /10.7 h)= (655.7 h/ 9.9 h)= (224.7/3.4)= (2 x 153.32
h)/708.7 h = 66.2
- 153.3 h = Pluto Day Period
- (Notice 3.4 hours = 12104 seconds (1%) where 12104 km = Venus Diameter)
- Please remember
- The angle (1.1 degrees) = 0.5 degrees + 0.6 degrees Where
- (0.5 degrees) = The Moon Diameter Angle and (0.6 degrees) = ???
- 1.3 deg (Jupiter orbital inclination) + 0.6 deg = 1.9 deg (Mars orbital inclination)
- And
- 1.9 deg (Mars orbital inclination) + 0.6 deg = 2.5 deg (Saturn orbital inclination)
- That shows an interaction is done between Jupiter and Saturn motion based on this
angle (1.1 deg) specifically (based on the angle 0.6 degrees)

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- The data shows Pluto day period be created as function in the moon (day and
rotation periods) – this dependency be done by support of Jupiter and Saturn
motions interaction
- Please remember
- 17.2 degrees = Pluto Orbital Inclination (error 1%)
- 23.4 degrees = Earth Axial Tilts (error 1%)
- 17.4 degrees = 5.1 deg (the Moo Orbital Inclination) x 3.4 deg (Venus Orbital
Inclination)
The data shows there's a complex machine behind the interaction between the moon
and Pluto motions data.
- Notice
- Pluto (4.7 km/s) moves during a solar day a distance =406000 km
- Pluto (4.7 km/s) moves during a Pluto day period a distance = 2.598 mkm
- Pluto (4.7 km/s) moves during 88000 seconds = 413600 km
- Pluto (4.7 km/s) moves during 10.7 h (Saturn day period) = 181800 km
- All distances be used in the moon orbital motion data

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- Notice No. (1)
17.2 sec x 0.3 mkm/sec = 5.16 mkm (= 58.65 days x 88000 km)
17.2 deg = 5.1 deg x 3.4 deg (error 1%)
- Where
- 58.65 days = Mercury Rotation Period
- 88000 km = The moon daily displacement
- The equation tells that, light known velocity travels in 17.2 seconds a distance =
5.16 mkm – this distance be = the moon displacements total during (58.65 days)=
Mercury rotation period
- Also 1mkm be = 1 degree – So
- 5.16 mkm be = 5.16 deg (= the moon orbital inclination 5.1 deg error 1%)
- In fact
- 17.4 degrees = The Inner Planets Orbital Inclinations Total = 5.1 x 3.4
- 5.1 degrees = The moon orbital inclination
- 3.4 degrees = Venus orbital inclination
- 17.2 degrees = 0.99 x 17.4 degrees - And
- 23.45 degrees = Earth Axial Tilt = 0.99 x 23.6

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- Notice No. (2)
Data
(27.78 x π2
/ 47.4 x2) = 2.86 (error 1%)
(35 x2 /24.1) = 2.86 (error 1.5%)
(4 x29.8 / 13.1π) = 2.86 (error 1.3%)
(27.78 /9.7) = 2.86 (Zero error)
(24.1 x 2 / 5.4 π) = 2.86 (error less 1%)
(2π x 13.1)/(5.4)2
= 2.86 (error 1.3%)
(9.7 x 2/6.8) = 2.86 (error less 1%)
(6.8 x 2/ 4.7) = 2.86 (error 1%)
(1.16/0.406) = 2.86 (Zero error)
- Where
- 47.4 km/s = Mercury velocity
- 29.8 km/s = Earth velocity
- 27.78 km/s = The Earth Moon velocity
- 24.1 km/s = Mars velocity
- 13.1 km/s = Jupiter velocity
- 9.7 km/s = Saturn velocity
- 6.8 km/s = Uranus velocity
- 5.4 km/s = Neptune velocity
- 4.7 km/s = Pluto velocity
- 1.16 mkm = Jupiter motion distance during mars rotation period
- 0.406 mkm = Pluto motion distance during a solar day

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- Notice No. (3)
- (1.16/0.3) =(3030/778.6) = (5127/1325) = (654.9/170) = (1411/360)= (2815/720.7)
= (680/2644.5) = (929/243) = (2094/550.7) = (32200/8323) =
- Where
- 1.16 mkm /s = light Supposed Velocity
- 0.3 mkm /s = light Known Velocity
- 3030 mkm = Uranus Pluto Distance
- 5127 mkm = Jupiter Pluto Distance
- 1325 mkm = Saturn Venus Distance
- 654.9 mkm = Jupiter Saturn Distance
- 170 mkm = Mercury Mars Distance
- 1411 mkm = Neptune Pluto Distance
- 360 mkm =Mercury Orbital Circumference
- 2815 mkm =Mercury Uranus Distance
- 778.6 mkm = Jupiter Mercury Distance
- 2644.5 mkm = Mars Uranus Distance
- 550.7 mkm = Jupiter Mars Distance
- 2094 mkm = Jupiter Uranus Distance
- 929 mkm = Jupiter Earth Distance (be on 2 different sides from the sun)
- 243 mkm = Venus Rotation Period (=243 days)
- 32200 mkm = the distance between Pluto and Jupiter orbital circumferences
- 8323 mkm = 4 x 2080 mkm (where 2094 mkm Jupiter Uranus Distance)
- Max Error 2%
- This data tries to show that many distances in the solar system be rated based on
the rate between the 2 light beams velocities (light supposed velocity 1.16 mkm/s
and light known velocity 0.3mkm/s).

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- Notice No. (4)
The rate (4.61) be between Pluto and the moon data – we have discussed in branch
no.(A) - This rate effects on around 50% of all distances in the solar system
778.6 mkm (Jupiter Orbital Distance) = 4.61 x 170 mkm
550.7mkm (Jupiter Mars Distance) = 4.61 x 119.7 mkm
2094 mkm (Jupiter Uranus Distance) = 4.61 x 2 x 227.9 mkm
2872.5 mkm (Uranus Orbital Distance) = 4.61 x 629 mkm
3033.5 mkm (Uranus Pluto Distance) =4.61 x 654.9 mkm
5127 mkm (Jupiter Pluto Distance) = 4.61 x 2 x 550.7 mkm
5906 mkm (Pluto Orbital Distance) =4.61 x 1284 mkm
1375.6 mkm (Mercury Saturn Distance) =4.61 x 2 x 149.6 mkm
3062 mkm (Saturn Neptune Distance) =4.61 x 671 mkm
4345.5 mkm (Earth Neptune Distance) =4.61 x 940 mkm
4267.2 mkm (Mars Neptune Distance) =4.61 x 929 mkm
170 mkm = Mercury Mars Distance
119.7 mkm = Venus Mars Distance
227.9 mkm = Mars Orbital Distance
629 mkm = Jupiter Earth Distance 654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance 1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance 671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
929 mkm = Earth Jupiter Distance when the 2 planets be on the sun 2 sides
(Max error 1%)
- The previous distances are (22 distances) where all distances in the solar system
are (45 distances) –means these distances be around 50% of all distances in the
solar system and be controlled by this rate (4.61)
- This great effect be found because of the proportionality between Pluto motion and
the light supposed velocity motion

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- Notice No. (5)
- 366560km (the outer planets diameters total)= 3475km (the moon diameter)x (655.7/2π)
(error 1%)
- And
- 366560 km (the outer planets diameters total) =7510 km (Pluto diameter) x 153.3
- Where
- 655.7 h = The Moon Rotation Period
- 153.3 h = Pluto Moon Rotation Period

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5-8 Uranus Motion Effect On Pluto Motion
- Uranus motion effects on Pluto motion and causes Pluto day period to be 153.3
hours which is so long in comparison with all other outer planets days periods
- We know Uranus motion does this effect because
- (1)
- Pluto orbital inclination = 17.2 degrees and Uranus day period =17.2 hours
- (2)
- 551880 seconds (Pluto Day Period) = 31983 seconds x 17.2
Where
17.2 h = Uranus Day Period) and
31983 s = the period light supposed velocity (1.16 mkm/s) needs to pass a distance
= 37100 mkm = Pluto orbital circumference
- (3)
- Uranus depends on Pluto day period in its motion through Planet 8 Days Cycle
(this cycle be discussed in point No.4-10)
- (4)
- 53.9 h (The 4 outer planets days total) = π x 17.2 h (Uranus Day Period)
- And
- (153.3 h /53.9 h) = (1.16 mkm / 0.406 mkm) = 2.86
- 153.3 h = Pluto day period
- 1.16 mkm = light supposed velocity motion distance in one second
- (Notice, the rate 2.86 controls all planets velocities, it discusses it before)

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(I) (The Motions Interaction Of Uranus, Neptune and Pluto)
Data
- (1)
- 1.44 deg = 0.8 deg x 1.8 deg (Neptune orbital inclination)
- Where (0.8 deg = Uranus orbital inclination) and
- (1.44 deg = the moon orbit regression monthly)
- (2)
- 17.2 hours – 1.1 hours = 16.1 hours
- 16.1 hours = Neptune Day Period
- (3)
- 4.7 x 86400 = 406000 km
- 6.8 x 59800 = 406000 km
- Where
- 86400 s = the solar day
- (4)
- 2 d Venus =2 x 269.7d (Neptune) moves (251 mkm) (but 1 h Earth =250 h Pluto)
- 1 d Venus =406.7 d (Pluto) moves (165.1 mkm) (but 1 h Earth = 165.1 h Neptune)
- (5)
- 4900 days x 0.5875 = 2872.5 mkm
- 2 x 4900 days x 0.46688 = 4576 mkm (error 1.8%)
- 3 x 4900 days x 0.406 = 5968 mkm (error 1 %)

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- (6)
- 1433.5 mkm Saturn Orbital Distance
- 2 x 1433.5 mkm Uranus Orbital Distance
- (π) x 1433.5 mkm Neptune Orbital Distance
- (1+ π) x 1433.5 mkm Pluto Orbital Distance
-
- (7)
- 90560 days x 2 x 24 h = 153.3 h x 28355
- 59800 days x 24 h = 16.1 h x 28375 x π = 89143 Neptune days periods
- Where
-
- (8)
- 30589 days x 2 x 24 h = 24.6 h x 59800
- Where
- 24.6 hours = Mars rotation period
- (9)
- Tan (8.9) x 153.3 hours = 24 hours
- Where
- (153.3 h /17.2 h) = 8.9
- (Notice during 4495 s Uranus moves 30589 km)

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5-9 The Moon Orbital Apogee Radius Decreasing Details
- (1)
- Let's ask again,
- From where the moon gets the angle (10.96 degrees)?
- From Uranus
- Because
- (153.3 h /17.2 h) = (97.8 deg /10.96 deg)
- 97.8 degrees = Uranus Axial Tilt
- 10.96 degrees = Our Angle
- This data shows that, Uranus causes the extension for Pluto day period basically
because of the angle (10.96 degrees)
- (A)
- 86400 seconds (the solar day) x sin (10.96 degrees) = 16330 seconds
- This period 16330 seconds is the cornerstone based on which the solar system
geometrical design be created. In the paper discussions we keep our eyes always
on this period 16330 second which we will use frequently.
- We should remember that
- the value 16030 seconds or mkm be the central value in The Solar System
Geometrical Design. (between 16030 and 16330 an error 2%)
- Notice (2)
- 42683 seconds x 2 = 16330 seconds x (10.96 degrees)
- Where
- Uranus orbital period (30589 days) has 42683 of (Uranus day period 14.2 h)
- I try to show, by different forms the same value be used by the 2 planets motions
(Uranus and the moon)
- The next notice makes the picture more clear.

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- (B)
- Light (300000 km/s) travels during 16330 seconds a distance = 4900 mkm
- Where
- 4900 mkm = Jupiter Orbital Circumference
- But
- Uranus needs 4900 days to pass a distance = 2872.5 mkm = Uranus orbital
distance
- And
- The moon circumference 10921 km x 449197 km = 4900 mkm
- 449197 km = Jupiter Circumference
- That shows the 2 planets (Uranus and the moon) are connected with the value
(4900) which shows their connection with the solar system geometrical design.
- (C)
- The angle (10.96 degrees) is inherited from Uranus motion by different forms
- Let's provide one more form for it
- 10.96 deg + 90 deg = 10.96 deg = π deg + 97.8 deg (Uranus Axial Tilt)
- Also
- 2π x 2815 mkm (Mercury Uranus Distance) = 10.9 x1622.7 mkm (Uranus Neptune
Distance)
- (D)
- 63.7 deg (the sun pole declination) x 2 x 0.8 = 100.96 deg = 90 deg + 10.96 deg
- 0.8 degrees = Uranus Orbital Inclination
- And
- 10.9 x 17.2 deg (Pluto orbital inclination) = 187 deg = 180 deg +7 deg (Mercury
orbital inclination)
- Notice
- 187 mkm x 0.8 = 149.6 mkm (Earth Orbital Distance)
- And
- 187 degrees /(95.1 degrees) = 0.642/0.33

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- 0.642 x 1024
kg = Mars Mass 0.33 x 1024
kg = Mercury Mass
- (2)
- The moon displacements total = 2598693 km, and
- The moon orbital apogee circumference be = 2550973 km
- The difference 47720 km
- Jupiter (13.1 km/s) passes this distance in a period one hour (3600 s) (error 1%)
- And
- Jupiter moves during Pluto orbital period (90560 days) a distance = 102500 km
- The distance 103944 mkm is different from 102500 mkm with (1.4%)
- But
- The moon orbital distance from perigee to apogee radiuses creates an area =
103944 mkm2
- And
- Jupiter orbital period 4331 days = 103944 hours
- We should notice that,
- The motion be done by Jupiter during Pluto orbital period – here we use the 2
planets their data shows the solar system geometrical design that because
- Light (0.3 mkm/s) travels during 16330 s a distance = 4900 mkm = Jupiter orbital
circumference
- And
- Light supposed velocity (1.16 mkm/s) travels during 2 x 16330 s a distance =
37100 mkm = Pluto orbital circumference
-
- Notice
- Pluto orbital period = 90560 days = 2178206 hours
- And
- 2178206 km x sin (10.96 deg) = 413600 km (supposed apogee radius)
- 2178206 km x sin (10.76 deg) = 406000 km (apogee radius)

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- 2178206 km x sin (9.5 deg) = 363000 km (perigee radius)
- 9.5 x 2 = 19 degrees (the moon orbit regresses 19 degrees yearly)
- Notice
- The moon displacements total = 2598693 km (-) 2178206 = 421056km
- (Uranus motion distance during its day period =421056 km)
-
- Notice
- 103944 days x sin (10.96 degrees) = 10747 days (Saturn orbital period)
-
- The data tries to show that, the moon motion of Metonic Cycle and its orbital
apogee radius definition depends on the angle (10.96 degrees) which be defined
by Uranus motion and be transported by the solar system one geometrical design
- That proves the hypothesis
- (One geometrical design be found behind the solar planets motions and data)

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5-10-1 Preface

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5-10-1 Preface
This point suggests that
THE MOON ORBIT BE IN A TRIANGULAR FORM
The point creates the moon orbital triangle and tries to prove it
- Here we discuss how to create this moon orbital triangle and to define its distances
and angles, also we discusses the major points of this triangle geometrical design,
where these major points are required in the paper hypothesis proves discussion.
- This triangle is created by creation a vertical line BC perpendicular on the triangle
base. This vertical line should be used 2 times in the triangle, one time when the
moon be in perigee and the second time when the moon be in apogee. For that
reason the triangle creates one form for each case and then created also one
combined form for the 2 cases.
- The moon using of Pythagorean triangle is discovered by analyze the moon motion
basic points which are
o Perigee point (r=363000 km), the nearest point the moon can reach to Earth
o Pongee point (r=406000 km), the far point the moon can reach from Earth
o T.S. Eclipse (r=373000 km), the moon creates total solar eclipse at it
o The distance (r=384000 km) which is registered as the moon orbital distance
The following data proves their using of Pythagorean rule.
These 4 points are defined based on each other by Pythagorean rule:
o (363000 km)2
+ (86000 km)2
= (373000 km)2
o (373000 km)2
+ (86000 km)2
= (384000 km)2
o (384000 km)2
+ (86000 km)2
= (393000 km)2
o (393000 km)2
+ (86000 km)2
= (406000 km)2
(Error 1%)
- By this data it's discovered the moon using of Pythagorean triangle in its motion
Notice
- The perpendicular Line (BC) which we use to create the moon orbital triangle its
length =86000 km.

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- When we use the vertical line BC to be perpendicular on the moon in the perigee
point, the triangle form be as following..
- When we use the vertical line BC to be perpendicular on the moon in the apogee
point, the triangle form be as following..
- The combined form be as following..

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The Triangle Data Summary
- The moon moves on its orbital plane (the Red Line) from Perigee to apogee
- This distance is defined by M1 and M2 distance (=43000 km) and the distance BD
=42800 km be a very similar to it
- The line BC is perpendicular on a point parallel to the perigee point
- So the triangle CBD expresses the moon motion from perigee to apogee
- This triangle data is
o The angle BCD = 26.46 degrees
o The line BC = 86000 km
o The hypotenuse CB = 96062 km
Notice
- This figure I have brought from internet to use in the Explanation -
- We have supposed, the inner circle is the Perigee orbit and the outer circle is the
apogee orbit, And we have calculated the tangent DB = 181843 km
- Perigee radius r =0.363 mkm Apogee radius r =0.406 mkm
- Based on that, The triangle (ODB) angles are 26.564 deg. and 63.435 deg.
- But the triangle (BCD) in our triangle is a similar to this triangle (ODB), their
dimensions are rated and their angles are equal, both are created as a specific
Pythagorean triangle (1, 2 and 51/2
).
Why is this specific Pythagorean triangle (1,2 and 51/2
) is a necessary tool for the
moon orbital motion? The paper answers this question.

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The Moon Orbital Triangle Building
(1st
Point) The Earth Position (Point E)
- The Point (T) refers to The Earth Center
- The Point (M1) refers to The Moon Center (The moon in Perigee Point).
- The Points (T, Q and Y) are on The Earth Ecliptic Line
- The Red Line (TM) is the moon orbit plane with an inclination 5.1 degrees on the
Earth ecliptic line.
- The Green Line (BE) is the moon triangle base, the distance BE = 363000 km, I
choose it and accordingly I have to define the point (E) position.
- The line BC is a perpendicular on the triangle base (BE), its length =86000 km
- The line BC is perpendicular on the triangle base (BE) on the point (B), parallel to
the moon perigee point. (The 1st
Case).
- The angle CBE =90 degrees but the angle CYT = 89.557 degrees.
- The points (Q and P) are the intersection points of CE with the ecliptic and the
moon orbit plane respectively.
- The line TX is a perpendicular from the Earth Center on the base BE
- K is the intersection point between the triangle base (BE) & the moon orbit plane.
- The angle is Zero between the points ( A, B , K , X and E).
- The line EC connects between the points C & E where BC =86000 km and BE =
363000 km (As The Triangle Creation Requirements).

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(2nd
Point) The Moon Motion (From Perigee To Apogee)
- The moon moves on its orbit planet (MT) with an inclination 5.1 degrees on the
ecliptic, from Perigee (M1) (r=363000 km) to Apogee (M2) (r=406000 km).
- The distance M1 M2 = 43000 km (=The Perigee Apogee Distance)
- The line M1B is perpendicular on the triangle Base (EA) on The perigee point.
Notice
- M1B and M2D are perpendicular on the moon orbital triangle base (EA) (the
Green Line) …… BUT
- M1B and M2D are perpendicular on the triangle Base EA on (x-y plain) but the
line BC is perpendicular on the base (EA) on the (z-axis)
- Based on that
- The distance BD is parallel to M1R, and the moon motion from perigee to apogee
(M1M21) can be expressed on the triangle base by the distance (BD) where the
distance (M1M2) =43000 km and the distance BD =42800 km (error 0.4%)
- The blue line is the moon equator line, where the triangle Base (EA) has 1.1
degrees above the moon equator and has 0.443 degrees under the ecliptic.

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- Let's define the Earth Point in following:
(1) In the Triangle ATK
o The angle ATK = 5.1 degrees (the moon orbital inclination)
o The angle TAK =0.443deg (an angle between the base and ecliptic)
o The angle AKT = 174.457 degrees
o The angle BKM1 = 5.543 degrees
(2) In the Triangle M1BK
o The angle M1KB = 5.543 degrees
o The angle KM1B = 84.457 degrees
o The angle RM1M2 = 5.543 degrees
o The distance M1B = 31604 km
o The distance M1K = 327188 km
o The distance BK = 325658 km
o The distance KT = 35812 km
o The distance BX = 361300 km
(3) In the Triangle RM1M2
o The angle M2M1R = 5.543 degrees
o The angle RM2M1 = 84.457 degrees
o The angle M1M2N = 6.643 degrees
o The distance M2R = 4153 km
o The distance M1R = 42800 km
(4) In the Triangle KTX
o The angle XKT = 5.543 degrees
o The distance TX = 3460 km
o The distance KX = 35644 km

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(5) In the Triangle TM1Y
o The angle TM1Y = 84.457 degrees
o The angle TYM1 = 90.443 degrees
o The angle M1TY =5.1 degrees
o The distance TM1 = 363000 km
o The distance YT = 361313 km
o The distance M1Y = 32269.5 km
o The distance YB = 665 km
o The distance M1B = 31604 km
(6) In the Triangle KTE
o The angle E = 63.87 degrees
o The angle ETK = 110.6 degrees
o The angle ETQ = 115.7 degrees
o The distance TX = 3460 km
o The distance TE = 3854 km
o The distance XE = 1700 km (to make the distance BE =363000 km)
o The distance KE = 37344 km (= 35644+1700)
(7) In the Triangle EPK
o The angle EPK = 161.1 degrees
o The angle EKP = 5.543 degrees
o The angle PEK = 13.328 degrees
o The distance PK = 26604 km
o The distance PE = 11147 km
(8) In the Triangle EPT
o The angle TEP = 50.54 degrees
o The angle ETP = 110.57 degrees (84.457+26.12)

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o The angle EPT = 18.89 degrees
o The distance TP = 9190 km
(9) In the Triangle QTP
o The angle TPQ = 161.1 degrees
o The angle T = 115.72 degrees
o The angle PTQ = 5.1 degrees
o The angle TQP = 13.78 degrees
o The distance TQ = 12491 km
o The distance QP = 2529 km
o The distance EQ = 13673 km = 11144 + 2529
Data Analysis
(1)
o The Triangle TXE
o The distance TX = 3460 km The distance XE =1700 km
o The moon diameter =3475 km and the moon radius =1737.5 km, both are
equal the triangle 2 dimensions (error around 2%). That shows geometrical
interaction in this distances definition.
(2)
o The Point (E) is found inside the Earth but far from its center with 3854 km
with an angle 63.8 degrees where its level is far from the Earth center with a
perpendicular distance =1700 km.
(3)
o The line M1B has an angle 90 degrees (M1BK) but the angle M1YT
=90.443 degrees.

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(3rd
Point) The Point (A)
- The Point (A) is a point on the Ecliptic Line I have choose and caused to create it
with an angle =0.443 degrees under the ecliptic line. By that the triangle base (AB)
be found under the Ecliptic with 0.443 degrees and above the moon equator line
(the blue line) with 1.1 degrees.
- That means, the triangle base (AB) depends on the Earth ecliptic line.
- The triangle ABC is a closed triangle where the point (A) is the intersection point
between the ecliptic line, the triangle base AB and the triangle dimension AC
- I choose the distance AB =86000 km.
- The line BC is a perpendicular on the point B, (which is parallel to the perigee
point M1 with a radius r=363000 km). (1st
Case)
- The line BC length =86000 km (I choose it).
Notice
- The moon equator line (the blue line) doesn't intersect neither with the ecliptic nor
the moon orbital triangle AB on the point (A),
- The moon equator line (the blue line) will intersect the ecliptic line beyond the
point (A) with a long distance

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- Let's define this intersection point position in following:
o The moon orbit plane declines on the Ecliptic line with 5.1 degrees, means,
far distance be found between the Earth and moon will cause longer
perpendicular distance between the moon center and the ecliptic line
o For that, we use the moon distance on a apogee because it's the most far
point the moon can reach from Earth
o ON APOGEE …
o Earth moon distance on apogee point = 406000 km
o The perpendicular distance from the moon center to the ecliptic line = 36091
km, because of the moon orbital inclination (5.1 degrees)
o But
o The angle between the ecliptic line and the moon equator line =1.543 deg
o So these 2 lines will be intersected each other at a distance =1340318 km
o i.e.
o The ecliptic line will intersect with the moon equator line after the apogee
point with a distance =1340318 km
o but the distance from perigee to apogee =43000 km
o i.e. The ecliptic line will intersect with the moon equator line after the
perigee point with a distance =1383318 km
o Notice, the lunar eclipse umbra length =1392000 km (error 0.6%)
The Useful Result :
The triangle base (AE) has an angle = 1.1 degrees with the moon equator line.

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(4th
Point) The Line BC
- The line BC is perpendicular on the triangle base on the point (B), so, the angle
ABC =90 degrees. The blue line is the moon equator line and the red line is the
moon orbit plane – the green line is the triangle Base (BA).
- Based on that,
o The angle BYA =89.557 degrees
o The angle CYA =90.443 degrees
o The angle M1NV =91.1 degrees
o The angle M2NM1 =88.9 degrees
o The angle M1NM2 =6.643 degrees
o The angle between the blue line (the moon equator) and the green line
(the triangle Base BA) = 1.1 degrees
o The distance BC = 86000 km (I have choose it)
o The distance AB = 86000 km (I have choose it)
o The distance AY = 86009 km
o The distance YB = 665 km
o The distance MB = 31604 km

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(1st
Question)
- The moon orbital triangle geometrical structure depends on 3 points (E, C and A),
- The Point (E) (found inside Earth)
- The point (C) (found on z-axis)
- But
- What's the point (A)? how this point can be created and effect on the moon orbital
motion and triangle?! Because this point is far from apogee radius with 43000 km
and the moon can't move beyond the apogee radius, means, this point (A) is found
in space and should have no effect on the moon orbital motion! so to find this point
(A) in the moon orbital triangle geometrical structure that creates a question needs
to be solved!
- Geometrically the point (A) is one pillar of the moon orbital triangle pillars,
means, the geometrical structure forces us to accept the massive importance of the
point (A).
- The paper claims that (Another force effects on the moon orbital motion in
addition to Earth gravity force and this point (A) refers to this 2nd
force)
- Our investigation in this study tries to discover if this claim can be proved based
on the moon orbital triangle geometrical design analysis.
(2nd
Question)
- The moon daily displacement 88000 km during 29.53 days creates a total distance
= 2598693 km
- But The moon orbital circumference at apogee orbit =2550973 km
- Where The apogee point is the most far point the moon can reach from Earth, that
means, the moon orbital circumference is shorter than the moon displacements
total during the moon day period (29.53 solar days) with a distance = 47720 km
- Why the moon orbital circumference at apogee doesn't =2598693 km?

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The following major points are selected from the moon orbital geometrical design
discussion because we need them to prove the paper hypotheses – let's refer to these
points in following:
5-10- 4-1 The Necessity of Pythagorean Triangle (1, 2, 51/2
)
5-10- 4-2 The Triangle Data (The Combination Form)
5-10- 4-3 The Value 1290 degrees
5-10- 4-4 The Trapezoid CDM2M1
5-10- 4-5 The Triangle CDM2
5-10- 4-6 The angle 17.4 degrees
5-10- 4-7 The moon orbital triangle modification

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5-10- 4-1 The Necessity of Pythagorean Triangle (1, 2, 51/2
)
(1st
Point) The Moon Motion Limits Definition
- In this moon orbital triangle I have added the line CA2 to create a total angle =137
degrees – based on that
(A)
- The angle ECA2 =137 degrees
- The distance BA2 = 150628 km
- The distance A2A = 64628 km
- The hypotenuse C A2 = 173450 km
- The perimeter of the triangle BCA2 = 173450 +150628 +86000 = 410080 km
- The triangle perimeter (BCA2) =410080 km= the apogee radius (406000 km)
(error 1%)
(B)
- The perimeter of the triangle (A CA2) =121622 + 173450 +64628 = 359700 km
- Perigee radius = 363000 km (error 1%)
A Conclusion
- The triangle BCA2 defines the moon motion limits from perigee to apogee by a
geometrical mechanism depends on The angle 137 degrees……. Why & How?

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(2nd
Point) The Rate 0.08
Why Pythagorean Triangle (1,2, 51/2
) Is Required?
This figure is discussed before.
- The inner circle refers to the perigee orbit
- The outer circle refers to the apogee orbit
- OB = 406000 km = Apogee Radius
- OR = 363000 km = Perigee Radius
- DB = 181843 km
- Perigee Orbital Circumference = 2.28 mkm
- Apogee Orbital Circumference = 2.55 mkm
I - Data
(1)
(DB / Perigee Orbital Circumference) = (181843 km/2.28 mkm) = 0.08
(2)
10.96 = 137 (The basic Angle) x 0.08
(3)
Sin (10.96 degrees) x 406000 km = 77237 km
(4)
Cos (10.96 degrees) 88000 km = 86400 km
II – Discussion
- Why is the Pythagorean triangle (1,2,51/2
) required for the moon orbital motion?
- Because, the rate (0.08) is required to create interaction with the angle (137 deg),
and based on this interaction, the valuable angle (10.96 degrees) will be created,
and based on this angle (10.96 degrees) most of the moon orbital motion data will
be created.
- That answers the question why the rates (1,2,51/2
) were required necessary for the
moon orbital motion? because based on these rates the rate (0.08) will be produced
which will be used to produce the angle (10.96 degrees)…… So

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- Based on the angle (CA2E =137 degrees), the moon orbital motion receives 3
basic data which are
o The apogee point radius (r=0.406 mkm) which is defined by the triangle BC
A2) Perimeter
o The Perigee point radius (r=0.363 mkm) which is defined by the triangle AC
A2) Perimeter
o And the rate (0.08) which is defined between the tangent DB (181843 km)
and the perigee orbital circumference (2.28 mkm)…….. then
o 10.96 = 137 x 0.08
o The valuable angle (10.96 degrees) is created.
Equation No. (3)
Sin (10.96 degrees) x 406000 km = 77237 km
- This equation tells the story in more clear way….
- The value 77237 km is very important…. If the moon moves daily a displacement
= 77237 km, during 29.53 days, the total distance will be = 2.28 mkm = the moon
orbital circumference at perigee orbit (r= 363000 km)
- Means, the perigee orbital circumference = 29.53 displacements each =77237 km,
that tells the value (77237 km) is defined by perigee radius (r=0.363 mkm) and the
moon day period (29.53 solar days), whatsoever the moon apogee radius be ….
Now the angle (10.96 deg) is defined before (10.96 = 137 x 0.08), and by that the
apogee radius is defined….
- I try to show that, we deal here with few players are created depending on each
other , all of them has one origin which is the angle 137 degrees, and has one
result which is the angle (10.96 deg)… what I try to do here is to show how the
data is arranged in a clear direction, by that, I may prove this is Directed Data.
Equation No. (4)
Cos (10.96 degrees) 88000 km = 86400 km
- The analysis is still complex and we need to consider it deeply in following…..

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- Where
o The moon orbital circumference at apogee radius (r=0.406 mkm) equals
only 2.55 mkm and this distance is short!
o Because
o The moon daily displacement =88000 km and during 29.53 solar days the
total displacements will be = 2.598 mkm …..if this distance be the moon
orbital circumference the radius will be = 0.4135 mkm
o Means, The apogee radius will not be 0.406 mkm but 0.4135 mkm !
o Which proves the conclusion, that, the moon uses Pythagorean triangle in its
motion,
o But Why the moon orbital circumference at apogee is not = 2.598 mkm?
o The angle (10.96 degrees) shows that the 2 values are created by
geometrical interaction because
Cos (10.96 degrees) 2.598 mkm =2.55 mkm
- This is the 2 discussed values (2.598 mkm = the moon displacements total during
29.53 days) and (2.55 mkm = the moon apogee orbital circumference), and the
equation tells that the angle (10.96 degrees) defines them based on each other (for
some geometrical reason). We have to find out what's this geometrical reason for
which the moon apogee orbital circumference is created shorter than its
displacements total.
Notice
137 =95.1 x 1.44
- We still don't know why this angle 137 degrees has so massive effect on the moon
orbital motion…? The previous data is
o 95.1 degrees = 90 degrees + 5.1 degrees (the moon orbital inclination)
o 1.44 degrees = the moon orbit regression degrees per month

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- The angle 137 degrees, is created by the moon orbit motion effect,
- 2 features of the moon orbit motion are unified together to produce this angle (137
degrees) which is the origin of the moon motion distance from perigee to apogee..
which are
o The moon orbital inclination 5.1 degrees
o The moon orbit regression 1.44 degrees per Month.
These 2 features of the moon orbital motion creates together the angle 137 degrees as
their platform to create the moon orbital motion in harmony with these 2 features…

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5-10- 4-2 The Triangle Data (The Combination Form)
- The triangle data is referred before we add the new data only
- The distance CL = 12250.2 km
- The distance CN = 121758.2 km
- The distance CM1 = 117605 km
- The distance CB = 86000 km
- The hypotenuse CM2 = 129064 km
- The hypotenuse Cr = 124660 km (rM2 = 4404 km)
- The hypotenuse CS = 91158.3 km (SM2 = 37905.7 km)
- The distance rM1 = 41339 km (Rr=1461 km)
- The distance SB =30229.7 km (SD= 12570.3 km)
- The hypotenuse BM2 =53204.5 km
- The angle BRM1 =36.44 degrees The angle LM2N =1.1 degrees
- The angle RM1M2 =5.543 degrees The angle M2CN=19.367 degrees

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5-10-4-3 The Value 1290 degrees
- How to create the value 1290 degrees (or days)?
- Imagine the moon moves in a vertical motion from perigee to apogee and return
back consuming a distance 43000 km x 2 =86000 km in this vertical motion,
where no any distance is done on the orbit horizontal level, means the moon is still
in its original position in its revolution around Earth and the distance 86000 km the
moon consumes in a vertical motion from, perigee to apogee (43000 km) and
return back
- But the moon daily displacement =88000 km
- Means, the moon still have only 2000 km can be passed
- Now
- Imagine that the moon will use this 2000 km only in its horizontal motion
revolving around Earth
- The moon apogee orbital circumference =2550973 km, and if the moon moves
only 2000 km through this orbit, the moon would complete its revolution around
Earth through its apogee orbit in a period =1290 days (error 1%)
- Because of this interesting idea, I searched behind the value 1290 trying to find out
if it's an effective value in the moon orbital motion and found the following:
I-Data
(a)
254 x 5.08 degrees = 1290 degrees
(5.1 deg= the moon orbital inclination) (254 =6939.75 days /27.32 days)
(b)
175.94 x 1.44 =253.3 = 1290 /5.1
(c)
719.76 x 1.79 = 1290 degrees
(d)
7 x 29.2 x 2π =1290 degrees

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(e)
13.177 x 97.8 = 1289 degrees
(f)
17.4 x 11.8 x π = 1290 degrees (11.8 deg =5.1 deg +6.7 deg)
II-Discussion
Equation No. (a)
254 x 5.08 degrees = 1290 degrees
(5.1 deg= the moon orbital inclination) (254 =6939.75 days /27.32 days)
- Equation no. (a) tells us a very interesting new data let's summarize it
- Metonic Cycle (6939.75 solar days) = 254 lunar sidereal month (27.32 days)
- The moon orbit revolve around Earth one time per month and that means the moon
creates its inclination angle (5.1 degrees) by its motion during this month
- That means,
- The value 1290 degrees = the total degrees the moon creates by its motion during
Metonic Cycle –
- This is a simple idea and we know one similar to it
- The moon orbit regresses 1.44 degrees per month and by that the moon orbit total
regression per a year =19 degrees and during 19 years (6939.75 days) the total
degrees will be 361 degrees (full revolution).
- The equation no. (a) tells us that, not only the moon orbit regression is registered
per month (1.44 deg) but also the moon orbital inclination (5.1 deg), and as the
moon regression creates 361 degrees during Metonic Cycle the moon orbital
inclination creates 1290 degrees during Metonic Cycle.

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Equation No. (b)
175.94 x 1.44 =253.3 = 1290 /5.1
- Equation no. (b) tries to know if there's a relationship between the value 1290
degrees and the value 1.44 degrees (the moon orbit regression per month)
- We have found that the value 254 (The Months Number In Metonic Cycle) = the
moon regression value per month (1.44 deg) multiply with 175.94
- And what's this value 175.94
- Mercury Day Period =4222.6 hours =175.94 solar days
- Equation no. (b) tells that, 1.44 deg (the moon orbit regression per month) x 5.1
deg (the moon orbital inclination per month) x 175.94 (Mercury day period) =1290
- Why Mercury day period?
- The other values are acceptable, the data tells that, the moon regression per month
is interacted with the moon orbital inclination per month and both are controlled
by the value 1290 degrees (which express Metonic Cycle and because of that it
controls both values)…
- But why Mercury day period (175.94 solar days) is used as their platform?!

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Equation No. (c)
719.76 x 1.79 = 1290 degrees
- What's 719.76 degrees? It's Mercury Day Period
- Mercury revolve around the sun 2 times to create one day – means the total
degrees should be 360 degrees x 2 =720 degrees
- But
- Mercury day period doesn't = 2 mercury orbital periods perfectly, instead it less
with a value 5040 seconds, for that reason the total degrees doesn't =720 degrees
but equal = 719.76 degrees
- 1.79 degrees = Neptune orbital inclination (1.8 degrees)
- The value 1290 degrees is inherited from Mercury…
- The moon motion is controlled by the value 1290 degrees to create Metonic Cycle
where this value the moon has inherited from Mercury motion – Mercury creates
this value 1290 degrees by its motion interaction with Neptune and then the moon
has to move under its control.
- For that reason, Equation no. (b) shows Mercury day period (175.94 solar days)
because the value 175.94 days is used as a period of time for Mercury but for the
moon it's used as the period in prison, under which the moon has to live.

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Equation No. (d)
7 x 29.2 x 2π =1290 degrees
- As a result the moon live under this value control
- Earth moves during (29.53 solar days) a value = (29.2 degrees)
- The moon moves during (29.53 solar days) a value = (360 deg+ 29.2 degrees)
- 7 degrees = Mercury Orbital Inclination
- Earth and the moon motions are done based on Mercury orbital inclination
interaction with the value 1290 degrees.
Equation No. (e)
13.177 x 97.8 = 1289 degrees
- 13.177 deg = The moon daily motion degrees
- 97.8 deg = Uranus Axial Tilt
Equation No. (f)
17.4 x 11.8 x π = 1290 degrees
- 11.8 deg =5.1 deg (the moon orbital inclination) +6.7 deg (the moon axial tilt)
- 17.4 deg = the inner planets orbital inclinations total (7+3.4+5.1+1.9)
- Notice
- 17.4 deg x 0.99 =17.2 deg (Pluto orbital inclination) =17.2 deg +0.2 deg

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5-10- 4-4 The Trapezoid CDM2M1
I-Data
- The hypotenuse CD = 96061.6 km
- The distance DM2 = 35759 km
- The distance M2M1 = 43000 km
- The distance CM1 = 117605 km
- The angle DM2M1 = 84.457 degrees
- The angle M2M1C = 95.543 degrees
- The angle M1CD = 26.57 degrees
- The angle CDM2 = 153.4 degrees
- The perimeter of the trapezoid CDM2M1= 292426 km
(g)
Tan (17.2 deg) x 943819 km = 292426 km
(h)
Sin (17.1 deg) x 292426 km = 86000 km

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Discussion
Equation no. (g)
Tan (17.2 deg) x 943819 km = 292426 km
- 17.2 degrees (Pluto orbital inclination)
- 943819 km = The Perimeter Of The Triangle AEC (discussed in 1st
Case)
(The triangle AEC dimensions are AE =449197 km, AC =121622
km and CE =373000 km)
- Pluto Orbital Inclination (17.2 degrees) effects on the moon orbital triangle
dimensions and data – we should know why and how?
Equation no. (h)
Sin (17.1 deg) x 292426 km = 86000 km
- The line BC =86000 km
- The angle 17.1 degrees = approximately 17.2 deg (Pluto orbital inclination)
- Why and how Pluto orbital inclination can effect on the moon orbital triangle
dimensions and creation.
Equation no. (i)
Tan (23.4) x 292426 km = 127757 km
- The perimeter of the triangle RM1B =127757 km, that tells us, the value 292426
km is effective value and used by Pluto orbital inclination (17.2 deg) and by Earth
axial tilt (23.4 deg) – that refers to some relationship between Earth and Pluto
which we need to discover it
Notice
- The Perimeter of the triangle CM2N = 293662 km = approximately the perimeter
of the trapezoid CDM2M1= 292426 km

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5-10-4-5 The Triangle CDM2
I-Data
- The Triangle CDM2 – its dimensions are
- The hypotenuse CM2 = 129064 km
- The distance DM2 = 35759 km
- The hypotenuse CD = 96061.6 km
- The angle DM2C = the angle M2CB =19.367 degrees
- The angle DC M2 = 7.25 degrees
- The angle M2DC = 153.4 degrees
- The angle CDB = 63.4 degrees
(j)
97.8 deg (Uranus axial tilt) =5.1 deg (the moon orbital inclination) x 19.17 deg
(Where 19.637 deg the angle DM2C= M2CM1 x 0.99 = 19.17 deg)
(k)
(153.3 degrees x 8) + 63.6 degrees =1290 degrees

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Equation no. (j)
97.8 deg (Uranus axial tilt) =5.1 deg (the moon orbital inclination) x 19.17 deg
(Where 19.637 deg the angle DM2C= M2CM1 x 0.99 = 19.17 deg)
- Equation no. (j) tells that, the line CM2 express Uranus Motion effect on the
moon orbital motion, and the angle 19.367 degrees shows that clearly
- We should consider that this triangle M2CM1 is the one shows Uranus effect
on the moon orbital motion!
- Let's review some data to prove this point
o 29.2 degrees x 0.8 = 23.4 degrees
o We know that Earth moves during 29.53 days a value 29.2 degrees (because
29.53 days x 0.98562 deg per day=29.2 deg) and the moon moves during
this same period a value = (360 deg +29.2 deg) (because 29.53 days x 13.17
degrees per day = 360 deg +29.2 degrees) ………..And
o 0.8 degrees = Uranus orbital inclination
o 23.4 degrees = Earth Axial Tilt
o By Uranus effect Earth axial tilt is created from the value 29.2 degrees
(please note, almost of the Earth and its moon motions data is defined based
on a defined period of time which is one month 29.53 days- based on this
period the data is created)
o 36.44 degrees x 0.8 = 29.2 degrees
o The angle M1RB =36.44 degrees
o That shows the interactions found through the triangle.
Notice
- The Triangle CDM2 Perimeter = 260885 km
- Tan (26.3 deg) x 260885 km = 129064 km (the hypotenuse CM2)
- The angle DCB =26.57 degrees (difference 1%) with 26.3 deg

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Equation no. (k)
(153.3 degrees x 8) + 63.6 degrees =1290 degrees
- The angle M2DC =153.4 degrees
- The angle CDB = 63.4 degrees
- What does this equation tells us?
- We know the value 1290 degrees which we have discussed before, and we know
now that this value express Metonic Cycle period 6939.75 days because each 5.1
degrees express a lunar sidereal month (27.32 days). So this value express Metonic
Cycle (19 years =6939.75 days)
- (153.4 degrees x 8) + 63.4 =1290
- What's this value 8 ? why we need it here?
- It's a cycle
- Earth has a cycle of 8 years (2922 days = 2 x 1461 days)
- Where 1461 days = (365 +365+ 365 +366 days)
But
- 2922 days = 107.4 x 27.2 days
- 27.2 days is the nodal month during which the moon orbit regresses 1.44 degrees
- 107.4 =90 +17.4 degrees (the inner planets orbital inclinations total)
- Also
- 17.4 deg =0.2 deg + 17.2 deg (Pluto orbital inclination)
Let's add some more data for better explanation
- Pluto moves during its day period (153.3 hours) a distance = Earth motion
distance during its day period (24 hours) = the moon displacements total
during 29.53 solar days (error 1%) why?

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- Let's ask a simple question in following
- Why Pluto day period =153.3 hours?
- But
- Uranus day period =17.2 hours
- Neptune day period =16.1 hours
- Saturn day period =10.7 hours
- Jupiter day period =9.9 hours
- Pluto is absolute exceptional between the outer planets, why its day period so long
in comparison with the other planets?
- Our triangle can help us
- The cycle which is consisted of 8 years (for Earth) is used for Pluto as a cycle of
(8 days of Pluto days) but this same cycle is used for Jupiter as 64 days of Jupiter
days, and for Saturn as 80 days of Saturn days and for Neptune as 100 days of
Neptune days
- This cycle is discussed deeply in Uranus Motion Analysis (Point No. 12 of this
paper)
But
- Pluto orbital inclination effect on the moon orbital motion is so massive effect, the
data shows a great effect by Pluto motion on the moon motion

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5-10-4-6 The angle 17.4 degrees
I-Data
- I have used the angle BCU =17.4 degrees
- The angle C = the angle CAB = 45 degrees because AB = BC =86000 km
- The angle UCA =27.6 degrees, where The Anomalistic month = 27.55 days
- Means if 1 day = 1 degree
- So, this angle 17.6 degrees may express the Anomalistic month
- let's examine the triangle UCA
- The distance BU = 26951 km and so the distance UA = 59050 km
- The hypotenuse CU = 90125 km The hypotenuse AC = 121622 km
- The perimeter of the triangle UCA = 270797 km
But
- 86200 km x π = 270797 km
- The line BC =86000 km = 2 x 43000 km (Perigee apogee distance)
The data shows that, the angle 17.4 deg creates data similar to the moon orbital
motion data (notice 17.4 deg x 0.99 =17.2 deg Pluto orbital inclination)
This data also supports the paper hypotheses that Pluto motion effects on the moon
orbital motion – let's try to prove this fact in the next point.

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5-10-4-7 The moon orbital triangle modification
5-10-4-7-1 The Triangle Modification

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5-10-4-7-2 The Triangle Creation Concept
I-Data
(Point No. 1)
- In this triangle I use 4 parts which are (BD =DA=AK=KK1=42800 km)
- The distance BK1 = 171200 km
- The angle FK1B =33.8 degrees……………. Why I use 4 parts??
- Based on the angle 33.8 degrees, the triangle K1KC4 dimensions are created
relative to Jupiter and Uranus data………. Specifically
- K1K +KC4 = Jupiter Radius (42800 km +28652 km = 71452 km)
- and
- The hypotenuse K1C4 = Uranus diameter (51505 km) (error 0.7%)
But
- The solar planets diameters total = 2 Jupiter diameters + 1 Saturn diameter
- Based on this data, I have concluded that, this moon orbital triangle may be built
on 2 Jupiter diameters, where each part of distance (42800 km) provides Jupiter
radius, so I have concluded that this triangle may be consisted of 4 parts in its
basic geometrical design……BUT
- Because of the triangle CBD (the specific Pythagorean triangle 1, 2 and 51/2
) I
thought that, the altitude of a triangle (BC) should be still used to save the triangle
CBD and also the triangle EBC
- For that, I have created 2 altitudes for this triangle BC =86000 km (the triangle
original altitude) and also the altitude BF, let's write the triangle K1FB Data
o The distance K1B = 171200 km (= 4 x 42800 km)
o The altitude BF = 114609 km (= 86000 km +28609 km)
o The hypotenuse FK1 = 206022 km (= 4 x 51505 km)
o The Perimeter =491831 km
Notice
K1B 171200 + BF 114609 = 285809 = 2 x 142905 km (Jupiter diameter 142984 km).

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(Point No. 2)
- I have connected the points (R & K), then we need to define the data of the basic
Triangle RCV
o The angle K1CB = 63.328 degrees
o The angle RCB = 20.228 degrees
o The angle RCV = 43.33 degrees (V & K1 on the same line)
o The angle CRV = 89.77 degrees
o The angle CVR = 46.9 degrees
o The angle CK1B = 26.672 deg
o The distance CR = 125005 km
o The distance RV = 117478 km
o The hypotenuse CV = 171200 km
o The distance VK1 = 20267 km (20387 km)
o The distance VK =26312 km
o The distance VV1 = 9150 km
- The perimeter of the triangle RCV = 125005 + 117478 + 171200 = 413683 km
o The triangle perimeter is so important because
o The moon displacements total during 29.53 days =2598693 km =2π x
413600 km.
Notice (1)
- Sin (20.228 deg) x 91166 km = 31521 km (= The Distance DR=31605 km)
- Cos (20.228 deg) x 91166 km = 85543 km (= The Distance DK=85600 km)

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(Point No. 3) (1) The Triangle FBK1
- BK1 = 171200 km FK1 = 206022 km
- BF = 114609 km The perimeter = 491831 km
- EB = 363000 km ED =406000 km
- EA = 449197 km EK =492197 km
- EK1 = 535197 km
- BK1F = 33.8 degrees BK1C =26.67 deg
(2) The Triangle CBK1
- BK1 = 171200 km CK1 = 191587 km
- The perimeter = 448787 km (Note 120536xπ/2) =191587 km
(3) The Triangle K1CF
- CK1 = 191587 km FK1 = 206022 km
- FC =28609 km The Perimeter = 426218 km
(4) Perigee And Apogee Proportionality
- Cos (26.6) x 406000 km = 363000 km
- Tan (41.8) x 406000 km = 363000 km
- In this triangle bc = 406000 km and ab =363000 km
- The angle bca = 41.8 degrees
- The hypotenuse ac = 544614 km
- Note EK1 = 535197 km (error 1.8%)
o This analysis tries to prove that, the distance EK1 is a real distance based on
which the moon orbital motion is done, because of that, the 2 points of the
moon motion (perigee and apogee) defines this distance (544614 km)
without any additional data – means- this value is a real value found
geometrically based on the perigee and apogee data
o This conclusion gives a support for the moon orbital triangle development,
telling that, the base (171200 km) is a real value and isn't an invented one.
(544614 km x sin (10.96) = 2 x 51772 km)

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More Triangle Data
The Triangle CKR
KR =91166 km KC = 154554 km CR= 125005 km
The perimeter of the triangle CKR = 91166+154554+125005 = 370725 km
The angle CRK = 89.77 deg The angle CKR = 54.041 deg
The angle RCK = 36.189 deg
The perimeter of the triangle CVK = 26312+ 154554+ 171200 = 352066 km
The Triangle CDK
- The angle CDK = 116.46 The angle DKC = 33.81
- The angle DCK = 29.73 Perimeter = 336217 km
The Triangle CDK1
- The angle CK1D = 26.67 The angle K1DC = 116.46
- The angle DCK1 = 36.87 Perimeter = 416050 km

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(Point No. 4) The Trapezoid CVV1B
- This is the trapezoid CVV1B, I cut it from the moon orbital triangle to be used in
our discussion, I have added also the line Vb to create the rectangle VV1Bb and
the triangle VCb, and also I added the diagonals CV1 and VB.
- The Trapezoid Data
- The distance VV1 = 9185 km K1V1 = 18200 km
- The distance V1B = 153000 km V1K = 24600 km
- The angle CVV1 =116.67 The angle K1CB = 63.328
The Trapezoid diagonals
- V1 C = 175592 km V1V2 = 16814.6 km
- VB = 153360.2 km VV2 = 14690.2 km
The Trapezoid Perimeter And Area
- The perimeter of the trapezoid CVV1B = 419390 km
- The area of the trapezoid CVV1B = 7282 mkm2
- The area of the rectangle VV1Bb = 1407.6 mkm2
- The area of the rectangle VbC = 5876.3 mkm2

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The Triangle CBV2
- CB =86000 km CV2 = 158777.4 km BV2 = 138670 km
- The perimeter of the triangle CBV2 = 383448 km
The Triangle CBV1
- The perimeter of the triangle VV1V2 = 40605 km
- The angle V B V1 = 3.4 degrees
The Triangle CVb (Data)
- Vb = 153000 km
- VC = 171200 km
- Cb =76814 km
- Bb = 9185 km The angle CVb = 26.67 degrees.
- The perimeter of the trapezoid CVV1B = 419390 km
- The perimeter of the triangle CbV = 401014 km
- The perimeter of the rectangle V1VbB = 324400 km
Notice (1)
- 1407.6 mkm = 18200 km x 77237 km ……..Where
o 18200 km = 171200 km -153000 km
o The distance cb = 76814 km (very near to 77237 km error 0.6%)
Notice (2)
- Cos (17) x 419390 km = 401014 km
- Cos (17) x 401014 km = 383448 km
- Cos (29.2) x 88000 km =76814 km
Notice (3)
- 6.7 deg x 17.4 deg = 116.58 deg
- 5.194 deg x 12.1907 deg = 63.328 deg

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II- Data Analysis
- There are 3 aforementioned values should get our attention which are
o (1) The perimeter of the triangle RCV = 413683 km
o (2) The distance EK1= 535197 km
o (3) The trapezoid area (7282 mkm2
) and its parts area (the rectangle VV1Bb
= 1407.6 mkm2
) and (the triangle VbC = 5876.3 mkm2
)
- The distance EK1 (No. 2) we have discussed its significance before, where this
distance is created with the perigee and apogee orbital distances geometrically,
means, if perigee and apogee are 2 points defined based on each other
geometrically that necessitates to create the distance 535197 km (or more accurate
544614 km), so this point is discussed before
- The point no. (1) refers to the distance 413683 km, and this distance is very
specific in the moon orbital geometrical structure because – the moon
displacements total during 29.53 days = 2598693 km = 2π x 413683 km
- But
- The moon orbital circumference at apogee radius (r=406000 km) = 2550973 km
- Means
- The moon apogee orbital circumference is shorter that the moon displacements
total during 29.53 days with a distance = 47720 km
- Because the perimeter of triangle CRV = 413683 km, the question is raised, can
this triangle data analysis help us to know how or why the moon apogee orbital
circumference be shorter than the moon displacements total, or to answer, why the
moon doesn't reach to this point (r=413683 km) but its apogee radius =406000 km
only?
- We know that, the moon orbital inclination (5.1 deg) causes to decrease the moon
orbital circumference with this difference 47720 km! but
- Can this triangle gives us more light how that happens?! Let's try to know

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(1)
7282 mkm2
= 1407.6 mkm2
x 5.173
(2)
26.67 deg = (5.164 deg)2
(3)
7301 mkm2
= 47720 km x 153000 km
(4)
7282 mkm2
= 2598693 km x 2802 km
(5)
1407.6 mkm = 18200 km x 77237 km (or 76814 km)
III- Discussion
Equation (1)
7282 mkm2
= 1407.6 mkm2
x 5.173
- The rate between the areas of the trapezoid (VV1BC) and the rectangle (VV1Bb) =
5.17
- The moon orbital inclination = 5.1 degrees
- The data tells that, the values are very near to each other
Also
- The angle CVV1 = 116.67 degrees = 90 degrees +26.67 degrees
- Where
- 26.67 degrees = (5.164 deg)2
- Once again the data refers to the moon orbital inclination 5.1 degrees
Equation (3)
7301 mkm2
= 47720 km x 153000 km
- The value 7301 mkm2
is almost equal the trapezoid area = 7282 mkm2
- 47720 km = the distance between the moon apogee orbital circumference and the
moon displacements total during 29.53 days.

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- 153000 km = the distance V1B = The Trapezoid Base
- Equation no. (3) tells us that, by some geometrical interaction this trapezoid effects
on the process by which the moon orbital circumference is decreased from
2598693 km to be 2550973 km…
- In more clear words
- This trapezoid is created for this process…. Because its base is interacted with the
distance 47720 km to create its area (taking into consideration the significance of
this specific trapezoid base because this same base is used by the triangle VbC).
But How This Process Is Done?
Equation (4)
7282 mkm2
= 2598693 km x 2802 km (1km = 1 hour!)
- 7282 mkm2
is the trapezoid area (VV1BC)
- 2598693 km = the moon displacements total during 29.53 days
- But
- What's this value 2802 km??
- We have no this value but we have a similar one 2802 hours = Venus Day Period
- How to understand that??
- Let's prove at first, that, this data is created by geometrical reason and not by pure
coincidence of numbers … in following
o 406000 km (apogee radius) = 3475 km (the moon diameter) x 116.75 days
(Venus Day Period)
o 2550973 km (the moon apogee orbital circumference) = 21.86 x 116662 km
o 21.86 = Jupiter Mass / Uranus Mass
o If 1000 km = 1 day so 116662 km will be = 116.75 days (Venus Day Period)
o If 1000 km = 1 day so 88 days (Mercury orbital period) = 88000 km
For more confidence in this discussion let's see the following equation

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Equation (5)
1407.6 mkm = 18200 km x 77237 km (or 76814 km)
- This equation we will discuss later, but now we need only the number 1407.6
mkm2
where Mercury rotation period =1407.6 hours
- The geometrical design uses the distances as periods of time!
- The data which we search (in distances values) are hidden in periods of time! And
vice versa
- Let's remember this number 1407.6 in more details in following…
o Mercury day period =4222.6 hours
o Mercury moves during its day period a distance =720.7 mkm
o During 8 Days of Mercury Days Period (33780.8 hours), Mercury moves
720.7 mkm x 8 = 5745 mkm ( 2 x Uranus Orbital Distance 2872.5 mkm)
o Why Uranus orbital diameter (5745 mkm) is very important for Mercury?!
But
o 8 Days of Mercury Days Period (33780.8 hours) =1407.6 solar days
o How these numbers are created depending on each other? I don't know yet?
But these 1407.6 numbers are created depending on each other (surely)
- Let's provide one more data which may help our discussion
o Mercury moves during its rotation period (1407.6 hours) a distance =243
mkm
o Venus Rotation Period =243 Solar Days
o This language is known by Mars also … because of that….
o Mars moves during 116.75 days (Venus day period) a distance =243 mkm

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Equation (5) (continued)
1407.6 mkm = 18200 km x 77237 km (or 76814 km)
- The difference between 7237 km and 76814 km = 0.5%, although our data gives
the number (76814 km), but I can't escape to refer to the value 77237 km because
of its massive significance with hope that some unknown error (0.5%) causes this
difference
- 77237 km x 29.53 days = 2.28 mkm = the moon orbital circumference at perigee
- That means, the value 77237 km is the first moon displacement defined by the
moon orbital geometrical design, we know that, the moon use Pythagorean triangle
in its motion, and the number 77237 km is 1st
value defined for the perigee radius.
- The distance 18200 km = the difference between 171200 km (the base BK1)
and 153000 km the trapezoid base (BV1)
- The area of the rectangle VV1Bb = 18200 x 77237 Why?
- Equation no. (5) tells that, the difference between 171200 km and 153000 km
defines the distance 77237 km
- Why?
- Let's review ….
- The moon displacements total during 29.53 days = 2598693 km but the moon
apogee orbital circumference =2550973 km
- Why? because of the effect of the moon orbital inclination (5.1 degrees)
- The trapezoid VV1BC is a player in the process in which the moon orbital
circumference is decreased by 47720 km as a result of the creation of inclination
5.1 degrees
- That means, in this process the perigee radius is defined (and automatically the
distance 77237 km) is defined also – we find it here –
- By What Geometrical Mechanism This Process Is Done? let's ask a question
- How The Perigee Radius Is Created? let's try to answer this question in
following…

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5-10-4-7-3 The Perigee Radius Discussion
I- Data
Group No. 1
(a)
Cos (28.63) x 88000 km = 77237 km
(b)
Cos (28.63) x 413600 km = 363000 km
(c)
Sin (10.96 ) x 406000 km = 77237 km (Cos (10.96 ) x 88000 km = 86400 km)
(d)
Cos (26.608) x 406000 km = 363000 km
(e)
Tan (97.8/3.1) x 142984 km (Jupiter diameter) =88000 km (error 1%)
(f)
The distance 77237 km x 2 = 154554 km (the hypotenuse CK)
But
155597 km x (cos 6.7) = 154554 (6.7 deg = The Moon Axial Tilt)
(g)
(155597 km x π) - (77237 km x2π) =3528 km (the moon diameter 3475 km (1.5%)
(h)
Tan (33.8) x 77237 km =51118 km (Uranus diameter) (error 1%)
(i)
(28.63) – (10.96) = 17.67 degrees
But
17.36 deg = 5.6 deg x 3.1 deg

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Group No. 2
- We know that (363000)2
+ (86000)2
= (373000)2
- In Pythagoras triangle with dimensions (363000 km, 373000km, 86000 km),
what's the angle (θ)? The angle (θ) = 13.33 degrees
- Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
- I have used (363000 km and 406000 km) because they are the perigee and apogee
radiuses between which the moon moves.
- The difference between angles = 1.1 degrees
i.e.,
- The angle (1.1 deg.) controls the moon motion from perigee to apogee
Group No. 3
- 2.5735 mkm = Earth motion distance during A Solar Day
- 2.5735 mkm = 7.1 x 363000 km (Perigee Radius)
- 363000 km (Perigee Radius) = 7.1 x 51118 km (Uranus Diameter).
Group No. 4
- 29.8 km /sec x 12104 seconds = 360670 km
Pluto Motion
- 4.7 km /sec x 77237 seconds = 363014 km (Perigee Radius)
- 4.7 km /sec x 86400 seconds (Solar Day) = 406000 km (Apogee Radius)
- 4.7 km /sec x 153.3 hours (Pluto Day) = 2593836 km
o 2593836 km= The moon displacements total during 29.53 days (0.2%)
Notice
- 77237 seconds is used by Pluto motion, BUT the perigee orbital circumference
=29.53 displacements each =77237 km

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II- Discussion
How The Perigee Radius (r=363000 km) is defined?
Equation No. (a)
Cos (28.63) x 88000 km = 77237 km
Equation No. (b)
Cos (28.63) x 413600 km = 363000 km
- Equation no. (b) is our target because the radius 413600 km is produced by the
moon displacements total during 29.53 days (2598693 km = 2π x 413600 km)
- Means, these 2 equations are one equation, just we multiply 29.53 days with 88000
km to produce (2π x 413600 km) and with 77237 km to produce (2π x363000 km)
- Nothing we can get from these 2 equations more, the angle 28.63 degrees defines
the range from perigee to (NOT Apogee 406000) but to (413600 km)
o Notice (1)
o 28.63 deg = (180 degrees /2π) (accurately = 28.6478 deg)
o Notice (2)
o 28.63 deg = 1.1 deg x 26 deg But 26 degrees = (5.1 deg)2
Equation No. (i)
(28.63) – (10.96) = 17.67 degrees But 17.36 deg = 5.6 deg x 3.1 deg
- The difference between our angle (28.63) and the valuable angle (10.96 deg) =
17.67 degrees but the moon angular diameter =0.5 degrees means this value can be
=17.17 degrees +0.5 degree, where 17.2 deg = Pluto Orbital Inclination
17.36 deg = 5.6 deg x 3.1 deg
- 17.36 degrees = (the inner planets orbital inclination total =17.4 degrees)
- 3.1 degrees = Jupiter Axial Tilt
- 5.6 degrees = 5.1 deg (the moon orbital inclination) + 0.5 deg (the moon
angular diameter).
- 5.6 deg = the moon orbital inclination above the moon diameter

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- Equation no. (i) tells that, the 2 basic angles (28.63 deg and 10.96 deg) depend on
Pluto Orbital Inclination
- This idea we have suggested before, and this equation supports it
Equation No. (c)
Sin (10.96 ) x 406000 km = 77237 km (Cos (10.96 ) x 88000 km = 86400 km)
- The angle 10.96 degrees is crated rated to the angle 28.63 degrees which we have
discussed in the previous 3 equations
- But the angle 10.96 degrees is an independent piece because it's created by the
equation (137 degrees x 0.08) which we have discussed deeply before and also
where (The angle 137 degrees = 1.44 degrees x 95.1 degrees), where 1.44 deg =
the moon orbit regression per month and 95.1 degrees = 90 deg +5.1 deg (the
moon orbital inclination)
- Now
- What angle is the original and what's the result?
- The angle 10.96 deg is original and Pluto orbital inclination 17.2 deg is original
data, that means, the angle 28.63 degrees is created based on these 2 angles (17.2
deg and 10.96 deg)
- This idea may be logical because (the hypothesis tells that) the moon apogee
orbital circumference became shorter than the moon displacements total during
29.53 days by the value 47720 km because of the moon orbital inclination creation
which is done by Pluto orbital inclination effect on the moon orbital motion.
- Shortly
- 10.96 & 17.2 degrees are Original Data
- 28.63 degrees is A Result Data

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Notice (1)
- The perimeter of the triangle (Cvb) = 401014km, this value is used as a passage to
transport the value (419390 km) to be (383448 km) based on the angle 17 deg
- Where
Notice (2)
- The rectangle area 1407.6 mkm shows that some geometrical interactions is done
to produce the value 76814 km (very near to 77237 km) based on the distance
18200 km which equal (171200 km -153000 km).

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6-Jupiter Motion Effect On Earth And Venus Motions
6-1 Preface
6-2 Jupiter Motion Effect On Earth And Venus Motions
6-3 Jupiter Orbital Circumference Analysis
6-4 The Sun Rays Creation
6-5 Saturn Velocity Analysis
6-6 The Solar System Creation and Motion Theory

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6-1 Preface
- This Point No. (6) Provides Proves For 2 Ideas
- (1st
Idea) The sun rays be created from the planets motions energies total
- (2nd
Idea) The sun position be defined by Jupiter motion effect on the Earth and
Venus motions- let's summarize the 2 ideas in following…
- (1st
Idea)
- The planets motions energies be accumulated on the sun point – and – the sun uses
different rate of time – which is – 1461 days of Planets motions = 1 day of the sun
motion – by that – the planets motions energies accumulation during 1461 days
can be used by the sun in 1 solar day only- and by that – the energy be enough to
produce the sun rays
- Means
- The sun rays energy isn't created by any nuclear interactions found inside the sun –
the energy be provided by the planets motions energy accumulation on the sun
point with using a different rate of time between the sun and planets motions -
- Shortly
- The planets velocities be added one another with using a different rate of time to
produce light known velocity 300000 km/s from this energy on the sun point – and
by this energy the sun rays be created – and by the creation of the light known
velocity 300000km/s the process be completed and nothing change in the whole
machine – that guarantee the planets motions be still in elliptical (or circular)
forms to support the light creation process
- By that
- The sun be created by the planets energies accumulation-
- Now we have defined the sun energy and we need to define the sun position –
means- why the sun be in this position?

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- (2nd
Idea)
- This figure tries to help our discussion point– let's provide the data in following...
- Venus Jupiter Distance = 670.4 mkm but Venus orbital circumference =680 mkm
(The difference is a round 1.4%)
- And
- Earth Jupiter Distance = 929 mkm but Earth orbital circumference =940 mkm
(The difference is a round 1.2%) – But
- The distance 929 mkm can be produced when Jupiter and Earth be on 2 different
sides from the sun, as the figure shows – and based on that the distance be 928.2
mkm = 149.6 mkm (Earth orbital distance) + 778.6 mkm(Jupiter orbital distance)
- This point discussion tries to analysis the period of time of Earth orbital
circumference – because – Light supposed velocity (1.16 mkm/sec) passes 940
- This figure tries to help our discussion point– let's provide the data in following...
- Venus Jupiter Distance = 670.4 mkm but Venus orbital circumference =680 mkm
(The difference is a round 1.4%) - And
- Earth Jupiter Distance = 929 mkm but Earth orbital circumference =940 mkm
(The difference is a round 1.2%) - But
- The distance 929 mkm can be produced when Jupiter and Earth be on 2 different
sides from the sun, as the figure shows – and based on that the distance be 928.2
mkm = 149.6 mkm (Earth orbital distance) + 778.6 mkm(Jupiter orbital distance)
- This point discussion tries to analysis the period of time of Earth orbital
circumference – because – Light supposed velocity (1.16 mkm/sec) passes 940

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mkm in a period = 810 seconds – this point of discussion tries to analyze this
period (810 seconds)
- The figure tries to explain the basic idea of this point – let's summarize it in
following –
o The point supposes that, the sun is created after all planets creation and motion –
o From the figure we can see that, Venus is connected with Jupiter from one
Side of the sun and Earth is connected with Jupiter from the other side of the
sun – if the sun is not created yet – this distribution of planets may aim to
define the sun position to be created – we here discuss about the distances
distribution to give the suitable position for the sun to be created in it
regardless the source of energy – for now – we here deal with the distances
distribution –and I suppose the equal distances of Venus and Earth to Jupiter
with their orbital circumferences be found to define the sun position to be
created in it – and by that – the sun be created in its position based on this
definition..
o The period 810 seconds is the main player behind the distances distribution
–that's why we discuss this subject with analysis of Earth period of time –
the period 810 seconds be used to create the suitable distribution of
distances to define the sun creation –this is the basic idea of discussion-let's
accept it as a hypothesis and try to analyze the period 810 as deep as
possible to know if this hypothesis can be proved…
- Notice
- The period 810 be used as 810 seconds for light motion and be used as 810 days
for planets motions – we here deal with the same period –it's seen as 810 seconds
for light motion but seen as 810 solar days for planet motion because the solar
system creation theory supposes that (1 second of light motion be = 1 solar day of
a planet motion)

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- Notice
- The data discussion is somehow complex, for that I need to make the ideas as clear
as possible before our discussion – the next ideas explain the historical situation
before the sun creation – we can accept these ideas as hypothesis till be proved by
the planets motions data – but the historical records are necessary to understand
the geometrical meaning behind the data which we will discuss –
- Mars Migration theory which be discussed in point no. (10) of this paper proves
many of these historical records
- Let's summarize these historical records in following…
- The Sun Is Created After All Planets Creation And Motion –
- Mars orbital distance was 84 mkm, also Pluto was the Mercury moon and had
migrated with Mars migration- Neptune orbital distance was 5906 mkm in that
time – and
- Mars was migrated from its original orbital distance (84 mkm) to its current one
(227.9 mkm) and in its displacement from (84 mkm) to (227.9 mkm) Mars had
collided with Venus and Earth – Mars itself Caused the Moon Creation
- Pluto was the Mercury moon and had migrated with Mars Migration – Pluto was
as cannonball and collided with Neptune pushed it out and occupied its position
with an orbital distance 5906 mkm – Pluto pushed Neptune out of its orbital
distance – for that reason – Pluto Eccentricity Distance = 1411 mkm= Pluto
Neptune Distance –
- Saturn be created after the Earth moon creation and the sun be created after Saturn
Creation-
- This story tries to tell – we have only 5 planets on board –which are (Mercury-
Venus –Earth –Jupiter – Uranus) - These are our planets on board based on their
positions the sun position be defined – why??

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- Because the other planets had changed their positions and orbital distances –by
that the distances distribution based on which the sun position will be chosen
depend on the planets which didn't change their positions which are our 5 basic
planets – that's what I try to explain –
- Shortly
- The sun position is defined based on the distances distribution and the distances
distribution be performed depending on the 5 planets whose positions weren't
changed and they didn't migrate – for that reason
- The sun position be defined based on the distances distribution which depends on
the 5 planets (Mercury – Venus – Earth - Jupiter – Uranus)
- The period of time 810 seconds (or solar days) be used for the 5 planets to create
the distances distribution map – and based on this map the sun position be chosen
- This is the idea simply as possible –the real process is so complex –we have to
move with the data as close as possible to see how that be done – one notice we
should keep in mind – that – Mercury role in the process isn't so clear – we search
after it in our discussion and try to know why Mercury role isn't clear as the rest 4
planets whose roles are defined clearly
- Let's start the data discussion

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6-2 Jupiter Motion Effect On Earth And Venus Motions
I- Data
(1)
3.024 mkm / day x 243 days = 734.8 mkm= 626.6 mkm +108.2 mkm
2.574 mkm / day x 243 days = 625.5 mkm
(2)
100733 mkm = 108.2 mkm x 931 = 149.6 mkm x 673.4
(3)
810 sec x 0.3 mkm/sec = 243 mkm
810 sec x 1.16 mkm/sec = 939.6 mkm
(4)
150.6 mkm = 1.392 mkm x 108.2 mkm
(5)
2094 sec x 0.3 mkm /sec = 629 mkm
4900 sec x 0.3 mkm/sec = 2 x 735 mkm
(6)
721.3 sec x 0.3 mkm/sec = 216.4 mkm
997.3 sec x 0.3 mkm/sec = 299.2 mkm
(7)
810 days x 2.574 mkm/day = 2085 mkm
810 days x 3.024 mkm/day x 2 = 4900 mkm
810 days x 1.13184 mkm/day = 917 mkm
(8)
810 days x 88000 km = 71.2 mkm = 2.4 mkm x 29.7 days

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(9)
810 mkm = 0.3 mkm /sec x 2700 sec = 1.16 mkm /sec x 699 sec (but 699 = π x222)
(10)
810 seconds = 13.5 minutes (27min/2)
(11)
810 mkm = 4.37 mkm x 185.35 mkm = 1.392 mkm x 582 mkm
(12) 100733 mkm = 41.4 mkm x 2433.2 (but 2433.2 x 0.3 = 730 mkm)
(13) 3475 x 0.3 = 1042 mkm = 2085 mkm/2
(14) (810 sec -310 sec = 500 sec)

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II- Discussion
Equation no. (1)
3.024 mkm / day x 243 days = 734.8 mkm= 626.6 mkm +108.2 mkm
2.574 mkm / day x 243 days = 625.5 mkm
- Where
- 3.024 mkm / day = Venus Motion Distance During A Solar Day
- 2.574 mkm / day = Earth Motion Distance During A Solar Day
- 108.2 mkm = Venus Orbital Distance
Equation no. (2)
100733 mkm = 108.2 mkm x 931 = 149.6 mkm x 673.4
- Where
- 670.4 mkm = Venus Jupiter Distance
- 929 mkm = Earth Jupiter Distance (the 2 planets on 2 different sides)
- 100733 mkm = The Solar Planets Orbital Circumferences total
Equation no. (3)
810 sec x 0.3 mkm/sec = 243 mkm
810 sec x 1.16 mkm/sec = 939.6 mkm
- Where
- These three equations are important – because –they tells that the solar planets
orbital circumferences total (100733 mkm) which equals the distance be passed by
light supposed velocity (1.16 mkm/s) in a solar day

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- This distance (100733 mkm) be defined depending on Earth and Venus relative to
Jupiter – shortly – this energy be found between Jupiter on one side and Earth with
Venus on the other side – we need this information because – the process basically
depended on Uranus and Uranus depended on the 3 planets together (Mercury,
Venus and Earth), for that reason – Mercury moves in its day period a distance
=720.7 mkm = Mercury Jupiter Distance – means Mercury is joined to Venus and
Earth in this process – BUT –for some reason we can't realize its role – by that –
the energy in fact depended on Earth and Venus motions
Equation no. (4)
150.6 mkm = 1.392 mkm x 108.2 mkm
- Where
- 1.392 mkm = The Sun Diameter
Equation no. (5)
2094 sec x 0.3 mkm /sec = 629 mkm
4900 sec x 0.3 mkm/sec = 2 x 735 mkm
- Where
- 2094 mkm = Jupiter Uranus Distance
Equation no. (6)
721.3 sec x 0.3 mkm/sec = 216.4 mkm
997.3 sec x 0.3 mkm/sec = 299.2 mkm
- Where
- 216.1 mkm = Venus Orbital Diameter
- 299.2 mkm = Earth Orbital Diameter

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- 720.7 mkm = Mercury Jupiter Distance
- (997.3/1000) = (360/361)
Equation no. (7)
810 days x 3.024 mkm/day x 2 = 4900 mkm
810 days x 1.13184 mkm/day = 917 mkm
- Where
- 3.024 mkm / day = Venus Motion Distance During A Solar Day
- 2.574 mkm / day = Earth Motion Distance During A Solar Day
- 1.1318 mkm/day = Jupiter Motion Distance During A Solar Day
- 0.838 mkm / day = Saturn Motion Distance During A Solar Day
- Notice
- 810 seconds x 2 = 1620 seconds = 27 minutes
- (27.3 is different from 27 with 1%)
- We remember that, light supposed velocity (1.16mkm/s) travels in 810 seconds a
distance = 940 mkm,
- Venus moves in 810 days a distance = 4900 mkm- we remember that this distance
covers the solar system geometrical design– we have analyzed this distance deeply
- The equations tells that, Venus must be a player in the basic Design of the solar system –
the data tells we deal with a geometrical mechanism depends on Earth and Venus
Equation no. (8)
810 days x 88000 km = 71.2 mkm = 2.4 mkm x 29.7 days
- 88000 km = The moon Daily Displacement
- 2.4 mkm = The moon Daily Motion Distance
- 29.7 days = 29.53 days (error 0.6%)
Equation no. (9)
810 mkm = 0.3 mkm /sec x 2700 s = 1.16 mkm /sec x 699 s (but 699 = π x222)

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- 0.3 mkm/s = Light known velocity
- 1.16 mkm/s = Light Supposed velocity
- 699 seconds = 222.5 seconds x π
- 2723 mkm = Earth Uranus Distance (with 2700 error 0.8%)
Equation no. (10)
810 seconds = 13.5 minutes (27min/2)
Equation no. (11)
810 mkm = 4.37 mkm x 185.35 mkm = 1.392 mkm x 582 mkm
- 4.37 mkm = The Sun Circumference
- 1.392 mkm = The Sun Diameter
Equation no. (12)
100733 mkm = 41.4 mkm x 2433.2 (but 2433.2 x 0.3 = 730 mkm)
- 100733 mkm = The Solar Planets Orbital Circumferences Total
- 41.4 mkm = Venus Earth Distance
- 730 mkm = Mercury Jupiter Distance (720.7 mkm) (error 1.3%)
Equation no. (13)
3475 x 0.3 = 1042 mkm = 2085 mkm/2
- 3475 km = The Moon Diameter
- 0.3 mkm/sec = Light Known Velocity
- 2094 mkm = Jupiter Uranus Distance (with 2085 mkm error 0.4%)
Equation no. (14)
810 sec – 310 sec = 500
- 810s the time required for light supposed velocity (1.16mkm/s) to pass 940 mkm
(= Earth Orbital Circumference)
- 310s the time required for light supposed velocity (1.16mkm/s) to pass 360 mkm
(= Mercury Orbital Circumference)
- 500s the time required for light known velocity (0.3mkm/s) to pass 150 mkm (=
Earth Orbital Distance)

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- The equation tells a geometrical mechanism behind it
- (that explains why Earth depends on mercury and not Venus in the equation d2
=4d0 (d-d0))
- The rest two planets (Mars and Pluto) also be exceptions in the equation for similar
geometrical necessity
Equation no. (15)
810 x 4.095 = 3317 mkm
3317 mkm = π x 1055 mkm
2112 mkm = 2 x 1055 mkm = 24 x 88
Equation no. (16)
- 142560 seconds = 810 seconds x 176 (Zero Error)
- 4.37 mkm = 810 km x 5395 (but 5395 = 24 x 224.79)
- 176 km/s = the planets velocities total

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6-3 Jupiter Orbital Circumference Analysis
- Jupiter Orbital Circumference = 4900 mkm,
- We analyze the value (4900) which I claim be considered The Solar System
Geometry Cornerstone – let's summarize this value using in following
- (A) The Inner Planets
- The Inner Planets Orbital Circumferences total = 4846 mkm
- (with 4900 mkm there's an error 1%) –the total 4846 mkm is needed to be
explained in our discussion
- (B) Jupiter Orbital Circumference = 4900 mkm
- Jupiter orbital distance 778.6 mkm and its circumference =4900 mkm
- (C) Saturn Is The Central Point Should Be Discussed Alone
- (D) Uranus Motion Needs 4900 Solar Days
- Uranus moves in a period 4890 solar days a distance =2872.5 mkm = Uranus
Orbital Distance
- (E) Neptune Motion Needs 4900 Solar Days
- Neptune moves in a period 2 x 4900 solar days a distance =4572 mkm = Neptune
Orbital Distance (4495.1 mkm) (error 1.7%)
- (F) Pluto Motion Needs 4900 Solar Days
- Pluto moves in a period 3 x 4900 solar days a distance =5970 mkm = Pluto Orbital
Distance (5906 mkm) (error 1 %)
- Saturn Data
- (1)
- Saturn Orbital Distance =9007 mkm = 2 x 4503 mkm
- And 4830 mkm =1.0725 x 4503 mkm (the distance 4830 mkm has an error 1.4%)
- (2)
- Saturn needs 1710 days to pass a distance =1433 mkm = Saturn orbital distance
- 1710 x 3 = 5130 days and it's different from 4900 days with 4.7%

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Discussion
- Let’s summarize the using of 4900 in following:
- (I) After Saturn
- Uranus, Neptune and Pluto uses the value 4900 solar days in gradual categories
(1,2 and 3). Based on
- Uranus needs (4900 solar days) to move a distance = Its Orbital Distance
- Neptune needs (2 x 4900 solar days) to move a distance = Its Orbital Distance
(error 1.7%)
- Pluto needs (3 x 4900 solar days) to move a distance = Its Orbital Distance (error
1%)
- The rates (2 and 3) are so important in our discussion – we keep them in mind
- (II) Before Saturn
- All planets use the value 4900 as a distance 4900 mkm – Specifically
- Jupiter Orbital Circumference = 4900 mkm
- And
- The inner planets orbital circumferences are = 4846 mkm (error 1%)
- But how this total be produced
- (360 Mercury +680 Venus +940 Earth +1433 Mars + 1433) = 4846 mkm
- The data considers the Earth moon is an independent planet and its Orbital
Circumference around the sun = Mars Orbital Circumference!
- Regardless any explanation the data be in consistency by this suggested idea
- Based on that the total (4846 mkm) be produced and be different from Jupiter
orbital circumference (4900 mkm) with 1%
- I try to show that we deal with a geometrical design depends on the value 4900,
and we have to accept that this geometrical design be created by light motion
because the light only can use the same value as a distance and as a period of time.

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- (III) Saturn Data Analysis
- As we have seen before Saturn the value 4900 be used as a distance 4900 mkm and
after be used as a period 4900 days
- For Saturn the value 4900 be used 2 times as a distance and as a period
- 4900 mkm x 2 =9800 mkm =1.0725 x 9140 mkm (where 9007 mkm =Saturn
orbital circumference ) (error 1.5%)
- The rate (1.0725) is used as a result of Lorentz Length Contraction Phenomenon-
this rate be used for 40% of all distances in the solar system – we have discussed
this rate in point no. of (5-5)
- In appendix no.(1) there's a list of these distances which use the rate (1.0725)
- Means, Saturn orbital circumference depends on the distance 4900 mkm by the
rate (2)
- Also
- Saturn needs 1710 solar days to move a distance = Its Orbital Distance
- 1710 solar days x 3 = 5130 solar days
- The value 5130 solar days be different from 4900 solar days with (4.7%)
- The 2 rates (2 and 3) be used with Saturn motion data
- Please Remember
- Uranus Orbital Distance =2872 mkm = 2 Saturn Orbital Distance 1433.5 mkm
- Neptune Orbital Distance =4495 mkm = π x Saturn Orbital Distance 1433.5 mkm
- Neptune Orbital Distance =4495 mkm = Saturn Pluto Distance
- The data shows that the rate (2 and 3) be used because of a geometrical reason

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- (IV) Saturn Data More Analysis
- We know that,
- Mercury day period 4222.6 hours= 2x Mercury orbital period 2112 hours =3 x
Mercury rotation period 1407.6 hours
- I claim the rates which we have seen, be used again with Mercury cycle periods.
- Let's deepen this discussion as possible in following
- Light supposed velocity (1.16mkm/s) travels during 4222.6 seconds a distance =
4900 mkm = Jupiter orbital circumference
- And
- Light supposed velocity (1.16mkm/s) travels during 1407.6 seconds a distance =
1633.3 mkm
- But
- Light known velocity (0.3 mkm/s) travels during 16333 seconds a distance = 4900
mkm = Jupiter Orbital Circumference
- Between (4222.6 and 1407.6) the rate is (3) and between (1633.3 and 16333) the
rate is (10)
- I want to say the rate (10) be created here –Saturn uses it –as in following:
- 10747 days x 24 h x 10 =10.7 hours x 120536
- Where
- 10.7 hours = Saturn Day Period
- The data shows, the rate (10) is necessary to produce Saturn diameter
Notice
Saturn velocity be discussed in the next point No. (6-5)

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- Let's Summarize The Sun Rays Creation Idea In Following:
(Point No. A)
o The Solar Planets Move One Unified General Motion. This Idea we discuss
and prove clearly in this paper.
o The planets unified general motion causes to unify the planets velocities in
one unifies velocity = the planets velocities total.
o The 9 planets velocities total =176 km/sec,
o But
o The Earth moon is a player and its velocity should be added, where the
moon velocity be considered = Earth velocity because they aren't separated
from one another through their motions.
o The 10 planets velocities total be 176 +29.8 =205.8 km/s
o Based on this velocity (205.8 km/s) the sun rays be created
(Point No. B)
o The rate of time (1 day of the sun motion =365.25 of Earth motion)
o This rate of time we have discussed, and it depends on the 5 planets motions
interaction
o Notice the moon is a basic player as we see in the data, let's remember the
following equation
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.

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o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o Let's use this idea as a hypothesis. where
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o We suppose that's The Sun Rate Of Time
(Point No. C)
o The velocity (205.8 km/s) passes during a solar day (86400 s) a distance
=17.75 mkm
o 1 day of Earth motion = 237 seconds of the sun motion.
(This value depends on our hypothesis)
o Now
o The distance =17.75 mkm and the time =237 seconds what's the velocity?
o 75000 km/s = (a quarter Light Velocity) = 0.25 C
o But
o Earth has a cycle of 4 years (1461 days = 365 +365 +365 +366)
o Based on one year, the velocity be (0.25 C)
o And
o Based on the cycle (4 years), the velocity (0.25C) became (C light velocity)
o Based on this explanation the sun rays be created.
(Point No. D)
o There's one more method to create the sun rays
o 0.25 C x 4 C = C2
o Where
o The velocity 0.25 C is produced already in the previous discussion
o We need only the value (4C) to perform this equation

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o Jupiter motion enjoys by light motion supposed velocity (1.16 mkm/s) this
value is very near to our required value (4C)
o Light supposed velocity travels for 1 second and passed 1.16 mkm
o And
o Earth rotates around its axis one per solar day and move a distance = its
circumference =40080 km in a solar day
o If 1 solar day of Earth motion be = 1 second of light supposed velocity
motion.
o Based on that, the distances can be added
o 1.16 mkm + 40080 km = 1.2 million km = 4C
o By that the equation works
o 0.25 C x 4 C = C2
o That explains why Jupiter and The Moon data are the 2 basic players in the
sun data definition. Because the sun creation depends on Earth and Jupiter
motion. in addition to Uranus motion which is seen in the Earth moon
motion.
o The data explains how the sun rays be created
(Point No. E)
o The rate of time (1 solar day of planet motion = 1 second of light motion) is
the original rate of time in the solar system. We should refer to that in the
planets unified general motion discussion.
o The idea is that, the light motion for 1 second provides the required energy
for a planet to move one solar day, because the light motion depends on the
solar day as we have discussed. By that the planets divides this great rate of
time (1 sec = 86400 sec) on their motions to work as a great clock and
produce this rate by their Unified General Motion.
o The basic part (1 sec =365.25 sec) be between the Earth and the Sun motion.

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Extensive Discussion
- Why Does The Previous Investigation Prove The Claim?
- The claim tells that,
- The Sun Is The Solar System Last Created Piece. And that means, the sun is
created after All Planets Creation And Motion.
- If this fact can be proved, it will disprove Newton Theory of The Sun Mass
Gravity decisively.
- How to prove that the sun is created after all planets creation and motion?
- In addition to the historical proves there's one basic proof which is
- The sun rays velocity be = 300000 km
- While
- The solar planets matters and distances be created out of light beam its velocity
=1.16 mkm/sec.
- As a result, I have analyzed the planets data to prove that, this data be created
based on a light beam its velocity =1.16 mkm/sec
- After this analysis, we have to describe how the sun rays be created and the
previous data provides this description.
- Now
- Why Does This Analysis Provide A Sufficient Proof?
- The proof sufficiency depends on the arguments and discussions logic
- The discussions used hundreds of the planets data and put them in some form to
prove some idea. I can create the idea but can't create the data. that means if the
data be in harmony with the idea that supports the proof sufficiency.
- We have used hundreds of data in different discussion, if the discussion logic be
straight and the data be in harmony with it that proves the claim clearly
- The point is that, we searched for the rules based on which this data be created. so
as much as the used data be in harmony with these rules that prove these rules
sufficiency.

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- For example
- I claim (1 day of the sun motion = 1 year of Earth motion). this idea we have
accepted as a hypothesis and used it based on that
- But
- This idea is created because of the moon circumference equation (10921 km x
86400 seconds =940 mkm). Means, we have some data refer to this hypothesis.
- So we have used this idea as a hypothesis.
- We have found that, the data be in harmony and produce a velocity = (0.25 C)
- This velocity be created as a result for the hypothesis we suggested because of the
moon circumference
- But
- Earth Cycle (4 years) can change this velocity (0.25C) into ( 300000 km/s)
- I try to show that, w don't create the data
- We Rearrange The Data In New Positions Relative To One Another
- This is the basic method of the proof.
- Then we find that
- Jupiter (again) provides us a chance to create the value (C2
) (which can be a
source of the sun rays energy)
- So we used the velocity 1.16 mkm/s which we have learnt from Jupiter motion
data and added it to earth circumference to produce the required value (4C)

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- Notice
(A)
- The inner planets required periods total = 235.8 days
- The outer planets required periods total = 31469 days
- The solar planets required periods total = 31705 days
- 31469 days = 133 x 235.8 days (error 0.4%)
(B)
- The inner planets orbital periods total = 1480 days
- The outer planets orbital periods total = 196027 days
- The solar planets orbital periods total = 197027 days
- The total 197027 days = 1480 days x 133
(C)
- The solar planets orbital distances total = 16030 mkm
- 16030 mkm = 53.99 x 2 x 149.6 mkm (Earth orbital distance) (error 1%)
- Where
- 53.99 mkm = the distance be passed by Pluto in 133 days
- The data shows that the planets data system depends on the rate133 which is the
rate of time between Mars and Pluto, the 2 migrants planets.
- The geometrical system depends on these 2 planets rate of time because they had
migrated and it's necessary to depend on their motions to repair the negative results
of their migration –
- But in this process the system uses 149.6 mkm Earth orbital distance to prove that
Earth is a distinguish planet in the solar system and to prove that the sun circles
Earth based on a geometrical necessity defined by the geometrical design.
- Notice
- More Data be discussed in the point (The Sun Age Description) No. (15)

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6-5 Saturn Velocity Analysis
- The point provides a hypothesis tells (Light Known Velocity 0.3 mkm/s Be
Created As A Different Velocity Between Jupiter And Saturn Velocities)
- Because, this idea is a complex one, we need to deal with it in details and by a
simple explanation – so let's move with this idea step by step in following:
- (1st
Point)
- How does Special Theory of relativity define the light velocity? Let's review ….
- If we have 2 light beams, each travels with 300000 km per second relative to us,
how these 2 light beams will see each other? based on the theory, the 2 light beams
should see each other as particles because no difference in velocities be found
between the 2 motions.
- On the other side we see the 2 light beams as light beams because we have a
difference in velocities (= 0.3 mkm/s) and by that they are light beams for us while
they are particles relative to one another.
- This explanation tries to claim that the light known velocity (0.3 mkm/sec) is
created as a difference in motions velocities. This meaning is the basic meaning of
light velocity definition based on Special Theory Of Relativity.
- This definition shows that light velocity be produced as a different velocity
between 2 points of Motions.
- Our 2 points of motion be Saturn and Jupiter motions – the hypothesis tells that –
the different velocity between Jupiter and Saturn motions causes to produce light
known velocity (0.3 mkm/sec).
- The data is simple but the idea is so complex. Because Jupiter moves during a
solar day a distance = 1131840 km, and
- Saturn moves during a solar day a distance = 838080 km
- The different distance between both = 1131840 km – 838080 km = 293760 km
- Indeed the different distance be = 293760 km (with 300000 km error 2%), which
equal light known velocity (0.3 mkm/s) motion distance for 1 second.

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- means we have the required distance but this distance be passed in a solar day
- Now
- We need to take this 1 solar day and make it = 1 second and that will cause to
create the light known velocity (0.3 mkm/s)
- Shortly
- The light known velocity (0.3 mkm/s) be created in 2 basic steps, the first step
produced the required distance (293760 km) in a solar day and the second step
caused this 1 solar day to be = 1 second
- As a result for this 2 steps the light known velocity (0.3 mkm/s) be created
- Let's study each step in a separated point
- (2nd
Point) (The Distance 293760 km)
- The planets masses rate define their orbital inclination (And Planet Axial Tilt), we
explain this idea in point no.(13) of this current paper
- Saturn Mass (568) = 0.3 x Jupiter Mass (1898)
- The rate (0.3) is supposed to be the reason behind the distance (293760 km) based
on which the light known velocity (0.3 mkm/s) be created
- The idea tells that, masses rate causes to create the planets orbital inclination
which be used as a rate between the planets velocities – we have the rate (0.3) and
this rate can be also (3.34) (because Jupiter mass = 3.34 Saturn mass)
Equation no. (a)
3.34 = 3.1 x 1.0725 where
- 3.1 degrees = Jupiter Axial Tilt
- 1.0725 = The rate be used between 40% of all distances in the solar system
- the using of the rate (1.0725) is explained before in point no.(5-5)
- The Equation tells, the masses rate causes to create Jupiter axial tilt in value (3.1
degrees), and
- The rule tells that the masses rate creates planets orbital inclinations and caused
them to be used as rates between these planets velocities – let's see that

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Equation no. (b)
13.1 km /s = 9.7 km/s x 1.35
- Where
- 9.7 km / s = Saturn velocity
- 13.1 km / s = Jupiter velocity
- 1.3 degrees = Jupiter orbital inclination (with 1.35 error 4%)
- We accept that planet orbital inclination is complementary to its axial tilt, and that
tells Jupiter and Saturn velocities be defined in proportionality with their masses –
and the rate (0.3) between their masses caused to create the different distance
(293760 km) between their motions distances during a solar day.
- Shortly
- The different distance (293760 km) is supported by the 2 planets masses rate and
the planets data designed to create a different distance = (293760 km) between the
2 planets motions distances per a solar day
- (3rd
Point) (1 Solar Day = 1 Second)
- Let's summarize the idea in following
- 1 second of Uranus Motion be = 1 solar day of the Earth moon motion
- This idea is concluded by the data analysis which we will discuss
- But how that is happened? We have 2 methods to answer
- (1st
Method)
- How generally 1 second = 86400 seconds? By the following
- 86400 =520.2 x 165.8= 344.6 x250
- 1 second of Mercury motion= 520.2s of Pluto motion= 344.6 s of Neptune motion
- 1 second of Earth motion= 250s of Pluto motion= 165.8 s of Neptune motion
- These rates we prove clearly in this paper.
- 1 second can be 86400 seconds if Mercury and Earth motions on one side get
interaction with Pluto and Neptune motions on the other side
- If the rate be produced for Earth motion, the moon can reach it

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- (2nd
Method)
- How 1 second of Uranus motion = 86400 seconds of the moon motion?
- 86400 = 24 x 60 x 60
- 1 second of Mercury motion= 61s of Saturn motion= 61 s of the moon motion
- And
- 1 second of Mercury motion= 174 s of Uranus motion
- 174 = 24 x 7.25 where 7.25 deg = the sun obliquity on the ecliptic
- The idea tells that, because of the sun creation some reflection of energy be done
so the rate 174 between Mercury and Uranus be reflected to be (1 s of Uranus) =
(24s of Mercury) and be = (24 x 61 =1464s of Saturn), here we suppose the
refection effects on Saturn and in place (1 s of Saturn = 1 s of the moon) ,
- Saturn uses Mercury rate toward the moon (1464 x 61=86400s)
- The question point is (can reflection of energy be done?) we discuss it in point no.(5)
(4th
Point) (The Data Discussion)
I- Data
Group No. (A)
(1)
742 mkm = 1.16 km/s x 639.6 sec = 6.8 x 30589 x 3600
And
191.9 mkm = 0.3 km/s x 639.6 sec = 2π x 30.5 mkm
But
30.5 mkm = 88000 km x 346.6 days
(2)
(61920 sec /6939.75 sec) = (153.3 /17.2)
(3)
2722.9 mkm = 88000 km x 30960 days = 41.4 mkm x 65.77
(4)
30589 =24 x 1274.5 but (1275.6 = 7.25 x 175.94)

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(5)
224.7 /3.4 = 66.1 = (708.7/10.7) = (655.7/9.9)
(6)
200 mkm = 66.2 x 3.024 mkm/ day
(7)
1898 = 86.8 x 2 x 10.93
2 x 568 = 86.8 x 13.1
(8)
27.32 x 0.8 = 21.86
Group No. (B)
(9)
810 x 1.16 mkm/s = 940
800 x 1.16 mkm/s =929
810 x 0.3 mkm/s = 243
(10)
810 x 0.838 mkm/s = 680
800 x 0.838 mkm/s =670.4 mkm
(11)
300000 km = 9.7 km/s x 30928 sec
(12)
749 sec x 0.3 mkm/s = 224.7
749 sec x 1.16 mkm/s = 8 x 108.6 mkm
(13)
810 days x 0.838 mkm / day = 680 mkm (Venus Orbital Circumference), but light
supposed velocity (1.16 mkm/s) passes 680 mkm in 586.2 seconds.
And, 586.2 days x 0.838 mkm / day = 2 x 245.2 mkm (with 243 mkm error 1%)

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II- Discussion
Equation No. (1)
742 mkm = 1.16 km/s x 639.6 sec = 6.8 x 30589 hours x 3600 s
And
191.9 mkm = 0.3 km/s x 639.6 sec = 2π x 30.5 mkm
But
30.5 mkm = 88000 km x 346.6 days
- Where
- 30589 days = Uranus orbital period (be used here in hours units)
- 346.6 days = the nodal year
- 88000 km = the moon daily displacement
- This data we have discussed before in points no. (3 and 4) – Let’s summarize its
meaning in following
- Uranus moves during 30589 hours a distance = 742 mkm – as the data shows in
Uranus motion which we have discussed before
- The distance 742 mkm is used by the same light motion which be used for any
planet orbital circumference – light supposed velocity (1.16 mkm/s) travels during
639.6 seconds a distance = 742 mkm and the light known velocity (0.3 mkm/s)
travels during 639.6 seconds a distance = 191.9 mkm = 2π x 30.5 mkm
- Where the moon daily displacement (88000km) in 346.6 days be = 30.5 mkm
- Means the moon displacements total during a nodal year (346.6 days) be = 30.5
mkm.
- Based on this explanation, The moon motion and its nodal year be connected
clearly with Uranus motion.
- Based on this data and many others, we have guessed that Uranus motion may
effect on the moon motion and cause it to move Metonic Cycle (extends for 19
years)

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Equation No. (2)
(61920 sec /6939.75 sec) = (153.3 /17.2)
- Where
- 61920 seconds = Uranus Day Period
- 6939.75 days = Metonic Cycle Period (19 years)
- This equation is one basic point in our discussion – because one solar day of the
moon Metonic Cycle Period be in comparison with one second of Uranus day
Period – that means – One Solar Day of the moon motion be in comparison with
One Second of Uranus Motion.
- The next question supports this same meaning
Equation No. (3)
2722.9 mkm = 88000 km x 30960 days = 41.4 x 65.77
- Where
- 2722.9 mkm = Earth Uranus Distance
- 88000 km = The moon daily displacement
- 30960 seconds = A Half Of Uranus Day Period (= 61920 sec /2)
- 41.4 mkm = Earth Venus Distance
- 65.77 =??
- This equation tells that, the moon moves a distance = 2722.9 mkm (Earth Uranus
Distance) in a period = 30960 solar days where 30960 seconds be = 50% of
Uranus day Period – that means- the second of Uranus day period be used as a
solar day by the moon motion.
- Let's summarize the basic meaning of the previous data in following:
- The 3 previous equations try to connect the moon motion with Uranus motion, and
this connection depends on the rate (1second= 1 solar day) for that reason different

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data of Uranus and the moon motions be created based on this rate – for that
reason the moon moves during 61920 solar days a distance = 2 x 2722.9 mkm
(Earth Uranus Distance) where 61920 seconds = Uranus Day Period
- Please Note
- Nothing can be done without Mercury motion – Mercury is the cornerstone on
which Uranus and the moon depend in their interactive motions.
Equation No. (4)
30589 =24 x 1274.5 but (1275.6 = 7.25 x 175.94)
- Where
- 7.25 degrees = The Sun Obliquity On The Earth Ecliptic
- The equation shows that, the rate 7.25 be used as a rate between Uranus and
Mercury motions data for the 2nd
time –shows this rate is found for a geometrical
reason.
- The equation tells one hour of Mercury (1 h) be = one solar day of Uranus (24 h)
and this isn't the meaning we suggested, on the contrary, one hour of Uranus (1 h)
be = one solar day of Mercury (24 h), the misunderstanding of data be caused
because of the reflection energy effect – because it's the same rate between the
same 2 planets but the direction is reversed – in all cases we need this rate which is
(1 hour of Uranus motion = 24 hours of Mercury motion) because based on this
rate the moon motion will create the general rate (1 second of Uranus motion = 1
solar day of the moon motion).
- This rate we should discuss deeply in the energy reflection point – but here we
need to see clearly how the distance (293760 km) be transported from Jupiter and
Saturn to the moon motion – let's complete the data discussion
Equation No. (5)
224.7 /3.4 = 66.1 = (708.7/10.7) = (655.7/9.9)

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- Where
- 708.7 hours = The moon day period
- 655.7 hours = The moon rotation period
- 10.7 hours = Saturn day period
- 9.9 hours = Jupiter day period
Please remember the number 65.77
(Equation No. (3) 2722.9 mkm = 88000 km x 30960 days = 41.4 mkm x 65.77)
Equation No. (6)
200 mkm = 66.1 x 3.024 mkm/ day
- Where
- 3.024 mkm = Venus Motion Distance During A Solar Day
- 66.1 days = This period is found based on the rate (66.1) found in the
previous equation no. (5)
- 200 mkm = light (0.3 mkm/s) motion distance in 670 seconds
- 200 mkm = The distance Jupiter moves in a period 4222.6 hours
- The discussion tries to find the origin of the rate 66.1 and Venus motion lead us to
the distance 720.7 mkm (Mercury Jupiter Distance) that because Mercury moves
during its day period (4222.6 h) a distance = 720.7 mkm but Jupiter during this
same period moves only 200 mkm – Jupiter in fact needs a period = 200 x 2π days
to pass a distance =720.7 mkm- and that shows a geometrical mechanism be found
behind – shortly – the rate 66.1 depends on the distance 720.7mkm by some a
complex geometrical design.
Equation No. (7)
1898 = 86.8 x 21.86 = 86.8 x 2 x 10.93
2 x 568 = 86.8 x 13.1

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- Where
- 1898 x 1024
kg = Jupiter mass
- 86.8 x 1024
kg = Uranus mass
- 568 x 1024
kg = Saturn mass
- The equation shows the masses rate between the planets – and shows specially the
rate (10.93) which is used for Mercury Day Period as we discussed in point no.(4-
6) and this same rate (10.9) be used as the basic angle in the moon orbit
geometrical design – the data tells the rate (10.93) is found as a rate between the
planets masses originally…
Equation No. (8)
27.32 x 0.8 = 21.86
- Where
- The equation tells that the moon motion data depends on Uranus motion data,
please note many other data can be added to support this same meaning for
example …
- Uranus orbital distance 2872.5 mkm = Earth orbital distance149.6 mkm x 19.2
- Uranus Axial Tilt 97.8 degrees = 5.1 degrees (the moon orbital inclination) x 19.2
- 24 hours x 0.8 (Uranus Orbital Inclination) =19.2h
- More data
- (Uranus mass/ Earth mass) =(Uranus diameter/ the moon diameter) = (97.8 deg
Uranus Axial Tilt /6.7 deg the moon Axial Tilt)

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Data Group No. (B)
- The data group no. (B) is provided to prove that, Saturn velocity per a solar day is
an effective velocity and can create an effect equivalent to light velocity effect –
because of that the planets motions data be in harmony with Saturn velocity as
similar as their harmony with the light velocities- basically this harmony is the
reason to claim that light known velocity (0.3 mkm/s) be created as a difference in
velocities between Jupiter and Saturn – the data proves this idea clearly –let's see
that in following -
Equation No. (9)
810 x 1.16 mkm/s = 940 mkm
800 x 1.1318 mkm/s =929 mkm
810 x 0.3 mkm/s = 243 mkm
Equation No. (10)
810 x 0.838 mkm/s = 680 mkm
800 x 0.838 mkm/s = 670.4 mkm
- 929 mkm = Earth Jupiter Distance when the 2 planets be on 2 different sides
from the sun
- 670.4 mkm = Venus Jupiter Distance
- 1.1318 mkm =Jupiter velocity per a solar day
- 0.838 mkm = Saturn Motion Distance Per A Solar Day
- The data proves that Saturn velocity per a solar day (0.838 mkm/day) be used in so
harmony motion as similar to the light velocities.

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Equation no. (11)
300000 km = 9.7 km/s x 30928 sec
- Where
- 30928 seconds = 50% of Uranus Day Period
- 300000 km = light motion distance during 1 second
- The equation shows specific interaction between Saturn an Uranus motions data
because Saturn moves during Uranus day period a distance = 600000 km while
Uranus passes this distance in a period =24.6 h (Mars rotation period)
Equation no. (12)
749 sec x 0.3 mkm/s = 224.7 mkm
749 sec x 1.16 mkm/s = 8 x 108.6 mkm
- Where
- 0.3 mkm/s =Light known velocity
- 1.16 mkm/s =Light supposed velocity
- 108.2 mkm = Venus orbital distance
- 224.7 days = Venus orbital Period (be used as distance 224.7 mkm)
- The data tries to prove that the value 749 sec is related to Venus motion data in
different forms – that explains the effect of Uranus motion on Venus motion data.
Equation no. (13)
810 days x 0.838 mkm / day = 680 mkm (Venus Orbital Circumference), but light
supposed velocity (1.16 mkm/s) passes 680 mkm in 586.2 seconds.
And, 586.2 days x 0.838 mkm / day = 2 x 245.2 mkm (with 243 mkm error 1%)
- This data proves the idea clearly
- Light supposed velocity (1.16 mkm/s) needs 810 seconds to pass the distance 940
mkm = Earth Orbital Circumference.
- The rule tells 1 second of light motion = 1 solar day of planet motion, based on
that, Saturn moves during (810 solar days) a distance = 680 mkm (Venus Orbital

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Circumference) where light supposed velocity (1.16 mkm/s) passes 680 mkm in a
period = 586.2 seconds, but on the other side Saturn moves during 586.2 days a
distance = 2 x 245.6 mkm (different with 243 mkm by an error 1%) but also light
known velocity (0.3 mkm/s) travels during (810 seconds) a distance = (243 mkm)
(where 243 days = Venus rotation period)
- I try to prove the deep harmony of the motion data with light velocity per second
and Saturn velocity per a solar day.
- This is one example only and many other data can be added and show that Saturn
velocity be in harmony with motion data as similar as light velocity – where we
have discovered that Jupiter moves in a solar day a distance = (1.13184 mkm)
which is different from (1.16 mkm/sec) motion for 1 second with 2.5% which
makes the 2 planets motions in deep harmony with light motion data- this
explanation tries to support the hypothesis that light known velocity be created
based on the 2 planets velocities difference
- Notice
- The point discussion tried to prove that light known velocity (0.3 mkm/s) be
created as a difference between Jupiter and Saturn velocity per a solar day. The
basic point is that, the solar day be changed into one second and by that the
distance 293760 km which is a different distance for a soar day be a different
distance for 1 second which cause light known velocity (0.3 mkm/s) to be created.
- The cornerstone of this process is the change of 1 solar day into 1 second – this
rate of time –is the base on which the rate of time between the Earth and the sun be
created – where 1 second of the sun motion be = 365.25 seconds of Earth motion –
this rate depends on the rate (1 second = 1 solar day) by which the different
distance (293760 km) causes to create light known velocity
- Now we should ask about the 2% of this value because the required distance is
300000 km – now this 2% is absorbed into the geometrical design, specifically the
moon apogee radius should be =413600 km and be only = 406000 km with

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decreasing 2% for this reason as a geometrical solution for this question. That also
explains why Earth moves in its day period a distance = Pluto motion distance in
its day period (error 1%) and = the moon displacements total during 29.53 days
(error 1%) –
- I want to say
- All these motions be done to create the suitable geometrical environment to
receive the light known velocity.

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(5th
Point) (The Energy Reflection)
I- Data
(a)
4 x 90560 sec x 0.3 mkm/sec = 3 x 37100 mkm (error 2.5 %)
(b)
π x 59800 sec x 0.3 mkm/sec = 2 x 28244 mkm
(c)
2 x 30589 sec x 0.3 mkm/sec =18048 mkm (error 1.7 %)
(d)
30589 sec x 0.3 mkm/sec =9007 mkm (error 1.9 %)
(e)
π x 4900 sec x 0.3 mkm/sec = 4331 mkm x 1.0725
(f)
(g)
2π x 940 sec x 0.3 mkm/sec = 5 x 354.39 mkm
II- Data Analysis
Equation no. (a)
4 x 90560 sec x 0.3 mkm/sec = 3 x 37100 mkm (error 2.5 %)
- Where
- 0.3 mkm/s = Light known Velocity
Equation no. (b)
- Where

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Equation no. (c)
2 x 30589 sec x 0.3 mkm/sec =18048 mkm (error 1.7 %)
- Where
Equation no. (d)
30589 sec x 0.3 mkm/sec =9007 mkm (error 1.9 %)
- Where
- 9007 mkm = Saturn Orbital Circumference
Equation no. (e)
- Where
Equation no. (f)
- Where
- 1433 mkm = Mars Orbital Circumference
Equation no. (g)
2π x 940 sec x 0.3 mkm/sec = 5 x 354.39 mkm
- Where

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- 354.39 days = The Lunar Synodic Year
Equation no. (h)
224.7 sec x 0.3 mkm/sec = 680 mkm /π2
(error 2%)
- Where
Equation no. (i)
7 x 175.94 sec x 0.3 mkm/sec = 360 (error 2.5%)
- Where
- 7 degrees = Mercury Orbital Inclination

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II- Discussion
- Let's summarize the idea behind the previous data:
- Light known velocity (0.3 mkm/sec) connects between the planet orbital period
and its orbital circumference – in all equations the used data is just planet orbital
period and circumference – the equation uses some constants as (π, 2 , 3 ,4 or 5)
but the basic idea is the same in all equations
- What we need to notice is the equations no. (e, f and g), these equations use some
reflected data – all equations use the planets orbital period as periods and the
planet orbital circumference as distances – but these 3 equations use the 3 planets
orbital circumferences as periods of time and their orbital periods be produced in
distances form – I use this data to prove that some reflection be found in the solar
system – the idea is that – the reflection is done and caused the energy to be
reflected into the moon orbit – this reflection process can explain how the rate of
time between Mercury and Uranus be reversed as we have discussed in the
previous point…
- I want to explain that the energy reflection process has many proves in the planets
data – let's provide more data to prove it
- Pluto velocity per a solar day = (1/the moon velocity per a solar day), in numbers
- 0.406 mkm (Pluto velocity) = (1/2.4 mkm) (the moon velocity) (error 2.6%)
- This is occurred again with Neptune
- Neptune velocity per a solar day= (1/Mars velocity per a solar day), in numbers
- 0.46688 mkm (Neptune velocity) = (1/2.082 mkm) (Mars velocity) (error 2.8%)
- This idea can explain why Pluto moves in a solar day a distance = 0.406 mkm =
the moon orbital apogee radius – this idea also can simply explains the wide data
proportionality we have discovered between Pluto motion on one side and the
Earth and its moon on the other side

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- The reflection process can be occurred simply in the solar because the whole solar
system is created out of light by that the light reflection can simply creates this
effect which be seen in the data clearly
Notice
Equation no. (e)
- This is Jupiter equation and it uses the rate 1.0725 – the notice which we need to
refer is that, Jupiter all distances almost be under effect of this rate (1.0725), that
means this using isn't a unique one but almost all Jupiter distances uses this rate
(1.0725) – we have discussed this rate using in point no.(5-5)
- Let's remember some of this data
- 778.6 mkm (Jupiter orbital distance) = 1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- 720.7 mkm (Mercury Jupiter Distance) = 1.0725 x 671 mkm (Venus Jupiter
Distance)
- 671 mkm (Venus Jupiter Distance) = 1.0725 x 629 mkm (Earth Jupiter Distance)
- That shows the rate is used frequently in Jupiter distances! Why?
- We accept that, light known velocity (0.3 mkm/s) be created as a difference in
velocities of Jupiter and Saturn by help of the rate of time between Uranus and the
moon motions (1 second = 1 solar day) – that means- the light known velocity (0.3
mkm/s) be created by this motion and based on the light creation another frame be
created in the planets motions – this new frame caused to create relativistic effects
– the rate 1.0725 is found as a result of Lorentz length Contraction phenomenon,
which is created based on the velocity 0.29376 mkm/sec which be = 0.98c

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- We noticed also that
- The moon moves per a solar day a distance = 2.574 mkm = Earth motion distance
during a solar day to save its accompanying with Earth in motion, but the length
contraction phenomenon effects on the moon motion distance (2.574 mkm) by the
rate = 1.0725 and caused to decrease it to be 2.4 mkm per a solar day which
pushed the moon to move its daily displacement (88000 km) to compensate the
different distance (where the moon needs 176000 km it moves only a displacement
=88000 km and left Mercury to help him by the other required displacement- that
explains why Mercury orbital period =88 day and its day period =175.94 days)

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6-6 The Solar System Creation and Motion Theory
(I)
- Matter is Created out of light beam, and the produced matter isn't separated from
its light parent but moves with it one unified motion by using different rates of
time between the matter and light.
- The matter is created of energy and the space is created of energy and by that, the
matter is created in motion. that means, the space is created obligatory with the
matter creation.
(II)
- The solar planets and their distances are created out of one light beam its velocity
=1.16 mkm/sec (The Theory Hypothesis)
- The energy of light supposed velocity (1.16 mkm/sec) be used for the solar system
creation and by that this light beam motion features be registered in the planets
matters and their distances.
- The planets move in comparison with their parent light beam (1.16 mkm/s) in one
unified general motion by using different rates of time
- The basic rate of time is
(1 Second Of Light Motion = 1 Solar Day Of Planet Motion)
- Means
- (Energy of light motion for 1 second be used to move a planet for 1 solar day)
- This great rate be divided among the planets motions rates of time
- As A Result,
- The Using Of Different Rates Of Time Should Be A Feature Of The Solar
Planets Motions
(III)
- The Solar System Be Similar To A Great Clock.

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- The Clock input is an energy of light motion for 1 second and the clock output is
an energy enough for a planet motion for 1 solar day –
- The rates of time be used by the planets to create One Unified General Rate Of
Time which be used by the planets unified motion. (The General Rate Of Time
Is That 1 Second Of One Motion Be = 1461 Seconds Of Another Motion)
(IV)
- The solar planets be similar to points on the same one trajectory of energy – or
they are knots on the same rope –
- Also
- The solar planets be similar to gears in one machine of gears – or the planets be
similar to puppets on a puppets theater –
- The rope can show the best similarity for the solar planets – the matter and apace
be created out of light beam energy – and by that – the light creates planet matter
and its distance by light energy – by that – light created planet matter and its
distance to be in proportionality with other planets data because all of them be
created out of the same one source of energy.
(V)
- Because all planets be created of one light beam, the planets move with this light
beam and by that we conclude a light beam motion be in accompanying with
planets motions –
- Light motion be accompanying with planets motions– because of that
- The solar planets motions be integrated into One Unified General Motion.
- The solar planets move one unified general motion – This motion be similar to
Train Carriages Motion – they all move together one unified general motion– spite
the planets velocities are different from one another – but as a machine of Gears –
the gears move by different velocities but create one unified general motion.
(VI)
- A canal water motion can be very good example for our explanation ….

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- Imagine 9 waterwheels be built on one canal, so the 9 waterwheels rotate because
of the water motion (the water motion here is similar to light motion and the
waterwheels are similar to the solar planets)
- This example is a great help for our explanation – the water motion direction is
perpendicular on the waterwheels rotation direction but no waterwheel can rotate
without water motion–also– the waterwheel motions effect on one another because
they effect on the water amount from one to another – that perfectly shows how
the solar system works
(VII)
- Now we have one more great help,
- The solar planets move One Unified General Motion because the light beam deal
with the unified motion of the planets
- The planets unified motion forces each planet to move a complementary motion
which can be integrated with one another to create the planets unified general
motion.
- Now each planet motion became (some how) obligatory motion because it should
be integrated with other planets motions to create the unified general motion.
- By that the planets motions be obligatory motions
- Planet data should be in harmony with this planet motion –the motion is obligatory
to be integrated with other planets motions – based on that – the planets motions
data should be complementary data with one another.
- There's one law controls all planets motions data –that because – the data should
be created in harmony with their motions and the motions must be complementary
to create one unified general motion of the solar planets motions.
- By that, the light beam motion controls the solar planets motions and their data –
shortly we have One Law controls all data.

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(VIII) (The Distances Network Form)
- The solar system distances be created in a network form.
- The solar system is similar to a board of chess and the distances be created
together based on one geometrical design. Here we don't deal with an individual
distance be defined by masses gravity. Instead we deal with a group of distances
be distributed based on one geometrical design for that reason the solar system
distances be created in a network form. This idea is so important one because
when we try to define a planet orbital distance we don't use the gravitation
equation but we use the neighbor planets orbital and internal distances to discover
the required one.
- The network theory of the solar system distances provides a very good solution to
explain how the distances be created. And provides perfect explanations for
different features be discovered in the distances analysis. For example around 50%
of all distances in the solar system be equal one another (Notice, the solar system
all orbital and internal distances be 55 distances and around 30 of them be equal
one another), how can we explain this feature? Also one rate as (2.48) be used
between around 50% of all distances, and other rates as (4.61 and 31) be used as
rates between around 45% of all distances – how to explain this feature? The data
shows the distances be created together as one group of distances be distributed
geometrically and all of them can be effected by one reason. Also one more rate
(1.0725) be used between 40% of all distances (Appendix no.1 of this current
paper provides many lists of these distances with comments on them)
(IX) (The Continuum Effect)
- A continuum effect can be proved clearly in the solar planets data –let's explain the
continuum effect meaning in following..
- In ancient time there was an illness called (Leprosy), it's very interesting illness
because it infects the human, and the cloths and also the buildings!!
- How can that be possible? It's the continuum effect meaning

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- One reason moves through the planets data to use matters dimensions, distances,
periods and other components in one unified operation and make all of them be
rated by this one reason.
- The rate 1.0725, be inserted in this current paper appendix no. 1, explains this
meaning, the rate (1.0725) be used between 40% of all distances in the solar
system but be used also between 8 planets axial tilts and be used also between
many planets periods of time! The same one rate (1.0725)
- It's A Continuum Effect Can Be Created Only By Light Motion
- The Continuum Effect Is A Light Motion Feature
- The light can use distance as a period of time and can create the matter of light
energy by that the continuum effect should be a proof for the planets creation of a
light beam – We discuss the continuum effect and prove it in this current paper
discussion.
(X) (The Planets Order)
- The solar planets original order almost has been similar to the interference of
young experiment of light coherence (the double slits experiment)
- The planets were perfectly arranged as the fringes,
- Jupiter was the greatest fringe and found in the middle, and then
- The planets on its left be ordered as following (Earth – Venus – Mars – Mercury),
- The planets on its right be ordered as following (Neptune – Uranus), (Where
Saturn be created after Mars migration and before the sun creation)
- (Where Mars Migration theory proves this order and be discussed in point no. 9)
- Based on that,
- We see the bright fringes as matters and the dark fringes we see as space – and the
interference be the most suitable form for the solar planets order.
- But
- Why do we see the bright fringes as matters?

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(XI) (The Mind Effect On Matter Creation)
- Let's suppose the human mind uses light known velocity (0.3 mkm/s) in realization
process, means, we realize the outer world because our mind works by a velocity
300000 km/s
- It's just a hypothesis, let's test it
- If 2 light beams travel beside each other how each one will see the other? as a
particle! Why? because no difference in their velocities –
- Simply, if our mind works by light velocity – the result will be that, we will see all
light beams (0.3 mkm/s) around as matters and the low motion objects we will see
as light beams because of the difference in velocities…
- If this idea be correct – it will explain the confusion of Lorentz Transformations,
where Lorentz told that (Particle own length will be contracted if this particle
travels by high velocity motion) and we have to ask Why?? what's the relationship
between particle dimensions and its motion velocity? The relationship is found
from our realization for this particle dimensions – because we realize the particle
dimensions and data by using light velocity (0.3 mkm/s) in our mind and by that
when the particle travels with high velocity motion it effects on the basic
realization process components- means- the matter is created out of light by effect
of the human mind realization process on the universe.
- This idea tells shortly
- The matter is created out of light beam by effect of a human mind.
- Means, The Universe Is Created Of Light Beams, But
- Our minds effect to create The Matter
- Notice
- Some claims tell Particle own length isn't contracted by high velocity motion but
it's illusion of measurement – we refuse this meaning because (1) the physics is the
science of measurement and (2) we don't want to make ourselves the universe
reference point.

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- Notice
- In young experiment (the double slits experiment), the produced interference of
bright and dark fringes be created based on some geometrical design, by that, one
equation defines the fringes and distances breadths -
- The geometrical features are light motion features and by that if the matter shows
any geometrical feature that means the matter inherited these features of light
motion- also that tells – as long as the matter follows the light motion direction the
matter follows the geometrical rules otherwise the matter moves into chaos. The
Chaos may be created because the mass gravity may enable the matter to move
contradicting the light motion direction, by that 2 directions of motions be created
and caused the chaos creation.

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7- The Solar Planets Motions Use Different Rates Of Time
7-1 Preface
7-2 The Planets Motions Rates Of Time

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7-1 Preface
(I)
- The solar planets motions rates of time depend on the planets required periods to
move distances = their orbital distances.
- For example Venus needs 35.8 solar days to pass a distance = 108.2 mkm = Venus
orbital distance.
- The planets motions rates of time be defined based on these periods by which the
planets need to move distances = their orbital distances
- Let's write a list of these periods in following:
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
- The periods are understandable simply, for example
- Earth moves during (58.1 Solar Days) a distance = 149.6 mkm = Earth orbital
distance.
- We notice, The Earth moon needs 1700 days because the moon daily displacement
=88000 km and the distance from the Earth to the sun =149.6 mkm and because of
that the moon needs 1700 days. And we notice that Saturn needs 1710 solar days
which makes the moon and Saturn rates of time are equal approximately
- We notice also that, the moon apogee radius =406000 km and this distance needs
only 4.61 days to be passed by the moon daily displacement 88000km. by that the
moon has 2 periods of time for its orbital distance, 4.61 days for the distance from
the moon to the Earth and 1700 days for the distance from the moon to the sun.
- The planets motions rates of time be defined based on these periods.
(II)

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- The planets motions rates of time be the rate between any 2 periods, let's use
Mercury rates of time as example in following
- Notice for Mercury we 27.9 days and not 14.13 days, we should explain why in a
separated point of discussion in point no. (7-9) of this paper.
- Mercury Motions Rates Of Time
- (35.8 /27.9) = 1.279, means
- 1 hour of Mercury Motion = 1.279 hours of Venus Motion
- (58.1 /27.9) = 2.078, means
- 1 hour of Mercury Motion = 2.078 hours of Earth Motion
- (1700 /27.9) = 60.8, means
- 1 hour of Mercury Motion = 60.8 hours of The Moon Motion
- (109.4 /27.9) = 3.91, means
- 1 hour of Mercury Motion = 3.91 hours of Mars Motion
- 687 /27.9) = 24.6, means
- 1 hour of Mercury Motion = 24.6 hours of Jupiter Motion
- (1710 /27.9) = 61.1, means
- 1 hour of Mercury Motion = 3.91 hours of Saturn Motion
- (4890 /27.9) = 174.8, means
- 1 hour of Mercury Motion = 174.8 hours of Uranus Motion
- (9635 /27.9) = 344.8, means
- 1 hour of Mercury Motion = 344.8 hours of Neptune Motion
- (14547 /27.9) = 520.2, means
- 1 hour of Mercury Motion = 520.2 hours of Pluto Motion
- Let's test these rates in the next point…
- Notice
- The rate of time be defined based on the planets velocities but here we define it
based on the planets orbital periods because the planets distances be created based
on geometrical design enable the planets orbital periods to do this job.

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7-2 The Planets Motions Rates Of Time.
MERCURY MOTION RATES OF TIME LIST
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
- Notice
- The planets motions rates of time cause the planets revolutions around the sun to
be done in equal periods of time.
- That because
- If 1 day of Mercury motion = 61.1 days of Saturn motion, during Saturn orbital
period (10747 days) Mercury uses a period =175.94 = Mercury day period, that
makes all planets orbital periods are equal in proportionality with their motions
rates of time.
- Let's try to prove that in following…

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Mercury Rates Of Time Test
224.7 days (Venus orbital period) = 1.279 x 175.94 days (Mercury Day Period)
365.25 days (Earth orbital period) = 2.078 x 175.94 days (Mercury Day Period)
687 days (Mars orbital period) = 3.91 x 175.94 days (Mercury Day Period)
4331 days (Jupiter orbital period) = 24.6 x 175.94 days (Mercury Day Period)
10747 days (Saturn orbital period) = 61.1 x 175.94 days (Mercury Day Period)
30589 days (Uranus orbital period) = 174.8 x 175.94 days (Mercury Day Period)
59800 days (Neptune orbital period) = 344.6 x 175.94 days (Mercury Day Period)
90560 days (Pluto orbital period) = 520.2 x175.94 days (Mercury Day Period)
- The errors are 1.4% and 1% with Neptune and Pluto orbital periods respectively,
no other error more than 1%
- The data tells, Mercury rate of time defines all planets orbital periods based on
Mercury Day Period (175.94solar days).
- Now we notice that, Mercury use 27.9 days in place of 14.13 days and use its day
period (175.94 days) in place of its orbital period (88 days). Shortly Mercury uses
a double value of its data we should discover why in point no. (7-9) of this paper.
- The data shows that the periods of time are equal – for example – 1 Mercury day -
=2.078 days of Earth motion. by that 175.94 days of Mercury motion be = 365.25
days of Earth motion. that means 175.94 days be = 365.25 days. As a result all
planets revolve around the sun in equal periods of time depending on their motions
rates of time.
- The point is, All solar planets orbital periods are defined based on these rates of
time, similar to Mercury Data Using.
- We have to test all planets motions data to prove all planets follow this same using
of data and by that we obtain a rule control the data clearly. We test all planets in
the next point no. (6)
- Then we have to discuss the planet motions rates of time meaning and effect on the
planets motions.

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NOTICE
- While we analyze the planets motions rates of time using, I wish the vision be seen
clearly from out of the analysis process.
- The analysis process tries to prove that the planets motions data be created as
layers above one another. we here deal with some fruit as (one onion) it consists of
layers above one another.
- The planet motion creates these players one above another. while the outer vision
shows (one onion) may be so strong as a rigid body but in fact it consists of layers
one above another. so the analysis process moves from one layer to the next and
we should follow this process with attention to discover how the planet data be
created and how this planet motion be in harmony with its data.
NOTICE
- In the next point no. (6) We use Mercury as an example for all planets motions
data. The point no. (6) is a simple one because we test just the rates of time in it.
but
- There are 2 important data we should keep in mind.
- The first data is the planets orbital distances which are defined also based on the
planets motions rates of time and we prove that in point no. (5, 6 and 7)
- The second data is the planets required periods to move their orbital distances,
these periods have a great significance …
- I want to say,
- The planets motions rates of time are rates defined based on the required periods,
but these rates of time control all planets motions data. I have to arrange the data in
best form for that the simple test I put in points no. (5, 6 and 7) as an approach, but
many other analysis we have to discuss in the paper rest points to explain the
major significance of the planets motions rates of time.
- The basic difficulty is the theoretical explanations, for example, when someone
asks how the planet low velocity motion can use different rate of time?

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- This question I can't answer simply… also
- Another question asks,
- Why Do The Planets Motions Use Different Rates Of Time?
- Also this question is hard to answer!
- It doesn't mean, it has no answer. It has an answer.. let's write it
- The planets motions use different rates of time to work as a great clock to create
one great rate of time (1 day of the sun motion = 365 days of Earth motion)
- This rate of time is required to be built because the sun rays energy be provided by
the planets motions energies accumulation. Means, the sun rays aren't produced by
any nuclear interactions inside the sun, on the contrary, the planets motions
energies be accumulated during one year (365 days) and the sun use it on one day
and by that the energy be enough for the sun rays creation.
- The answer is surprised and my be refused…
- That's why I don't answer the theoretical questions
- I want to put the data in front of the respectful readers. The planets motions data
isn't my opinion or theory, it's the planets motions data and we have to explain
how this data be created even if all my explanations be mistaken.
- I want to say
- The planets motions data contradicts Newton theory of the sun mass gravity and
the whole description of the solar system motion. this is the point we need to
prove.
- Newton theory which is lived for 400 years created its environment inside the
physics book, that's why the contradiction has a massive negative effect.
- It's not a small point in the physics book we should repair. It's a wide vision and
understanding concerning the solar system motion. the contradiction means we
should change a great part in the physics book.

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8- The Solar Planets Rates Of Time Analysis
8-1 Preface
8-2 Venus Motion Rate of time
8-3 Earth Motion Rate of time
8-4 Mars Motion Rate of time
8-5 Jupiter Motion Rate of time
8-6 Saturn Motion Rate of time
8-7 Uranus Motion Rate of time
8-8 Neptune Motion Rate of time
8-9 Pluto Motion Rate of time
8-10 The Planets Orbital Distances Test
8-11 One Law Controls The Planets Orbital Periods And Distances
8-12 The General Discussion

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8-1 Preface
- In this point we follow the example of Mercury motion. by that we define each
planet motion rates of time relative to the other planets and prove these rates of
time define all other planets orbital periods. (and also All Orbital Distances)
- There are 2 basic tasks we have to notice in our discussion which are:
- (1st
Task) The Comparison Of The Data With Newton Vision.
- We need to consider this comparison, because it's not enough to write a sentence
as this one (Newton Description Contradicts The Planets Motions Data), this
sentence is a fact but not enough. We have to see the planets data and to follow the
planets motions different forms to see how Newton description be so far from the
truth. We here don't deal with some wrong idea we need to disprove, but we deal
with a wrong vision and we need to rearrange the data in their correct positions to
see the real picture.
- If we do that, we will discover (for example) that, the sun is the last created piece
in the solar system, the sun be created after all planets creations and motions, that
shows clearly how Newton theory is mistaken because Newton saw what's result
as a reason and what's a reason he considered as a result, means, according to
Newton we have to see a reversed vision for the truth.
- (2nd
Task) The Observation Of The Data Values
- The values are our treasures we should analyze them to their depth. For example
the moon needs 1700 solar days to pass the distance 149.6 mkm = Earth orbital
distance by using its daily displacement 88000 km and Saturn needs 1710 solar
days to move a distance = 1433.5 mkm= Saturn orbital distance, we should know
why these 2 periods are equal and what effect be done as a result
- The data which we analyze here to prove the planets motions rates of time are
priceless data we should keep and follow them – because by the analysis we can
see the different layers of motions which create the planet and its motions data.
- Notice (The Data Be Discussed In Point 6-12)

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8-2 Venus Motion Rate Of Time
I – Data
VENUS MOTION LIST
1 hour of Venus motion = (0.78) h of Mercury Motion
1 hour of Venus motion = 1.62 h of Earth Motion
1 hour of Venus motion = 3.057 h of Mars Motion
1 hour of Venus motion = 19.233 h of Jupiter Motion
1 hour of Venus motion = 47.8 h of Saturn Motion
1 hour of Venus motion = 136.7 h of Uranus Motion
1 hour of Venus motion = 269.4 h of Neptune Motion
1 hour of Venus motion = 406.7 h of Pluto Motion
1 hour of Venus motion = 47.54 h of The Moon Motion
- In Following We Provide The Data Analysis

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II–Data Analysis
175.94 days (Mercury day period) = 0.78 x 224.7 days (Venus orbital period)
365.25 days (Earth orbital period) = 1.62 x 224.7 days (Venus orbital period)
687 days (Mars orbital period) = 3.057 x 224.7 days (Venus orbital period)
4331 days (Jupiter orbital period) = 19.2 x 224.7 days (Venus orbital period)
10747 days (Saturn orbital period) = 47.8 x 224.7 days (Venus orbital period)
30589 days (Uranus orbital period) = 136.7 x 224.7 days (Venus orbital period)
59800 days (Neptune orbital period) = 266.2 x 224.7 days (Venus orbital period)
90560 days (Pluto orbital period) = 403 x 224.7 days (Venus orbital period)
- There Are Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Venus orbital period (224.7 days)
by using the rates of time between Venus and these planets –
- No error in all data more than 1% -
- The Data Proves That – The Rate of Time Controls The Solar System motion

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8-3 Earth Motion Rate Of Time
I – Data
EARTH MOTION LIST
1 hour of Earth motion = (0.48) h of Mercury Motion
1 hour of Earth motion = (0.617) h of Venus Motion
1 hour of Earth motion = 1.88 h of Mars Motion
1 hour of Earth motion = 11.8 h of Jupiter Motion
1 hour of Earth motion = 29.4 h of Saturn Motion
1 hour of Earth motion = 84.1 h of Uranus Motion
1 hour of Earth motion = 165.8 h of Neptune Motion
1 hour of Earth motion = 250.4 h of Pluto Motion
1 hour of Earth motion = 29.3 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.48 x 365.25 days (Earth orbital period)
224.7 days (Venus orbital period) = 0.617 x 365.25 days (Earth orbital period)
687 days (Mars orbital period ) = 1.88 x 365.25 days (Earth orbital period)
4331 days (Jupiter orbital period) = 11.8 x 365.25 days (Earth orbital period)
10747 days (Saturn orbital period) = 29.4 x 365.25 days (Earth orbital period)
30589 days (Uranus orbital period) = 84.1 x 365.25 days (Earth orbital period)
59800 days (Neptune orbital period) = 163.8 x 365.25 days (Earth orbital period)
90560 days (Pluto orbital period) = 248 x 365.25 days (Earth orbital period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Earth orbital period (365.25 days)
by using the rates of time between Earth and these planets –
- No other error in all data more than 1% -

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8-4 Mars Motion Rate Of Time
I – Data
MARS MOTION LIST
1 hour of Mars motion = (0.255) h of Mercury Motion
1 hour of Mars motion = (0.327) h of Venus Motion
1 hour of Mars motion = (0.531) h of Earth Motion
1 hour of Mars motion = 6.3 h of Jupiter Motion
1 hour of Mars motion = 15.6 h of Saturn Motion
1 hour of Mars motion = 44.71 h of Uranus Motion
1 hour of Mars motion = 88.1 h of Neptune Motion
1 hour of Mars motion = 133 h of Pluto Motion
1 hour of Mars motion = 15.55 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.255 x 687 days (Mars Orbital Period)
224.7 days (Venus orbital period) = 0.327 x 687 days (Mars Orbital Period)
365.25 days (Earth orbital period = 0.531 x 687 days (Mars Orbital Period)
4331 days (Jupiter orbital period) = 6.3 x 687 days (Mars Orbital Period)
10747 days (Saturn orbital period) = 15.6 x 687 days (Mars Orbital Period)
30589 days (Uranus orbital period) = 44.7 x 687 days (Mars Orbital Period)
59800 days (Neptune orbital period) = 88.1 x 687 days (Mars Orbital Period)
90560 days (Pluto orbital period) = 133 x 687 days (Mars Orbital Period)
- Errors (1.2% and 1%) With Neptune And Pluto Orbital Periods Respectively
- Shortly
- All planets orbital periods be created based on Mars orbital period (687 days) by
using the rates of time between Mars and these planets

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8-5 Jupiter Motion Rate Of Time
I – Data
JUPITER MOTION LIST
1 hour of Jupiter motion = (0.040) h of Mercury Motion
1 hour of Jupiter motion = (0.0419) h of Venus Motion
1 hour of Jupiter motion = (0.084) h of Earth Motion
1 hour of Jupiter motion = (0.1589) h of Mars Motion
1 hour of Jupiter motion = 2.48 h of Saturn Motion
1 hour of Jupiter motion = 7.1 h of Uranus Motion
1 hour of Jupiter motion = 14 h of Neptune Motion
1 hour of Jupiter motion = 21.1 h of Pluto Motion
1 hour of Jupiter motion = 2.47 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 4331 days (Jupiter Orbital Period)
224.7 days (Venus orbital period) = 0.0419 x 4331 days (Jupiter Orbital Period)
365.25 days (Earth orbital period = 0.084 x 4331 days (Jupiter Orbital Period)
687 days (Mars orbital period) = 0.1589 x 4331 days (Jupiter Orbital Period)
10747 days (Saturn orbital period) = 2.48 x 4331 days (Jupiter Orbital Period)
30589 days (Uranus orbital period) = 7.1 x 4331 days (Jupiter Orbital Period)
59800 days (Neptune orbital period) = 14 x 4331 days (Jupiter Orbital Period)
90560 days (Pluto orbital period) = 21.1 x 4331 days (Jupiter Orbital Period)
- Errors (1.4% and 1%) With Neptune And Pluto Periods respectively
- All planets orbital periods be created based on Jupiter orbital period (4331days)
by using the rates of time between Jupiter and these planets

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8-6 Saturn Motion Rate Of Time
I – Data
SATURN MOTION LIST
1 hour of Saturn motion = (0.016) h of Mercury Motion
1 hour of Saturn motion = (0.0209) h of Venus Motion
1 hour of Saturn motion = (0.0339) h of Earth Motion
1 hour of Saturn motion = (0.0639) h of Mars Motion
1 hour of Saturn motion = (0.403) h of Jupiter Motion
1 hour of Saturn motion = 2.857 h of Uranus Motion
1 hour of Saturn motion = 5.63 h of Neptune Motion
1 hour of Saturn motion = 8.5 h of Pluto Motion
1 hour of Saturn motion = 1 h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.040 x 10747 days (Saturn Orbital Period)
224.7 days (Venus orbital period) = 0.0209 x 10747 days (Saturn Orbital Period)
365.25 days (Earth orbital period = 0.0339 x 10747 days (Saturn Orbital Period)
687 days (Mars orbital period) = 0.0639 x 10747 days (Saturn Orbital Period)
4331 days (Jupiter orbital period) = 0.403 x 10747 days (Saturn Orbital Period)
30589 days (Uranus orbital period) = 2.857 x 10747 days (Saturn Orbital Period)
59800 days (Neptune orbital period) = 5.63 x 10747 days (Saturn Orbital Period)
90560 days (Pluto orbital period) = 8.5 x 10747 days (Saturn Orbital Period)
- Errors (1%) Only With Neptune And Pluto Orbital Periods
- Shortly
- All planets orbital periods be created based on Saturn orbital period (10747 days)
by using the rates of time between Saturn and these planets

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8-7 Uranus Motion Rate Of Time
I – Data
URANUS MOTION LIST
1 hour of Uranus motion = (0.0057) h of Mercury Motion
1 hour of Uranus motion = (0.0073) h of Venus Motion
1 hour of Uranus motion = (0.011) h of Earth Motion
1 hour of Uranus motion = (0.022) h of Mars Motion
1 hour of Uranus motion = (0.14) h of Jupiter Motion
1 hour of Uranus motion = (0.3499) h of Saturn Motion
1 hour of Uranus motion = 1.97 h of Neptune Motion
1 hour of Uranus motion = 2.97 h of Pluto Motion
1 hour of Uranus motion = (0.349) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0057 x 30589 days ( Uranus Orbital Period)
224.7 days (Venus orbital period) = 0.0073 x 30589 days ( Uranus Orbital Period)
365.25 days (Earth orbital period = 0.011 x 30589 days ( Uranus Orbital Period)
687 days (Mars orbital period) = 0.022 x 30589 days ( Uranus Orbital Period)
4331 days (Jupiter orbital period) = 0.14 x 30589 days ( Uranus Orbital Period)
10747 days (Saturn orbital period) = 0.3499 x 30589 days (Uranus Orbital Period)
59800 days (Neptune orbital period) = 1.97 x 30589 days ( Uranus Orbital Period)
90560 days (Pluto orbital period) = 2.97 x 30589 days ( Uranus Orbital Period)
- No Error In All Data More Than 1% -
- All planets orbital periods be created based on Uranus orbital period (30589 days)
by using the rates of time between Uranus and these planets

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8-8 Neptune Motion Rate Of Time
I – Data
NEPTUNE MOTION LIST
1 hour of Neptune motion = (0.0029) h of Mercury Motion
1 hour of Neptune motion = (0.0037) h of Venus Motion
1 hour of Neptune motion = (0.006) h of Earth Motion
1 hour of Neptune motion = (0.011) h of Mars Motion
1 hour of Neptune motion = (0.0713) h of Jupiter Motion
1 hour of Neptune motion = (0.177) h of Saturn Motion
1 hour of Neptune motion = (0.507) h of Uranus Motion
1 hour of Neptune motion = 1.509 h of Pluto Motion
1 hour of Neptune motion = (0.1773) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.0029 x 59800 days (Neptune Orbital Period)
224.7 days (Venus orbital period) = 0.0037 x 59800 days (Neptune Orbital Period)
365.25 days (Earth orbital period = 0.006 x 59800 days (Neptune Orbital Period)
687 days (Mars orbital period) = 0.011 x 59800 days (Neptune Orbital Period)
4331 days (Jupiter orbital period) = 0.0713 x 59800 days (Neptune Orbital Period)
10747 days (Saturn orbital period) = 0.177 x 59800 days (Neptune Orbital Period)
30589 days (Uranus orbital period) = 0.507 x 59800 days (Neptune Orbital Period)
90560 days (Pluto orbital period) = 1.509 x 59800 days (Neptune Orbital Period)
- Neptune orbital period creates an error 1.3% with all data except Pluto and
Uranus
- All planets orbital periods be created based on Neptune orbital period (59800 days)
by using the rates of time between Neptune and these planets

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8-9 Pluto Motion Rate of time
I – Data
PLUTO MOTION LIST
1 hour of Pluto motion = (0.00192) h of Mercury Motion
1 hour of Pluto motion = (0.00245) h of Venus Motion
1 hour of Pluto motion = (0.00399) h of Earth Motion
1 hour of Pluto motion = (0.0075) h of Mars Motion
1 hour of Pluto motion = (0.0472) h of Jupiter Motion
1 hour of Pluto motion = (0.1174) h of Saturn Motion
1 hour of Pluto motion = (0.336) h of Uranus Motion
1 hour of Pluto motion = (0.662) h of Neptune Motion
1 hour of Pluto motion = (0.11743) h of The Moon Motion

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II–Data Analysis
175.94 days (Mercury day period) = 0.00192 x 90560 days (Pluto Orbital Period)
224.7 days (Venus orbital period) = 0.00245 x 90560 days (Pluto Orbital Period)
365.25 days (Earth orbital period = 0.00399 x 90560 days (Pluto Orbital Period)
687 days (Mars orbital period) = 0.0075 x 90560 days (Pluto Orbital Period)
4331 days (Jupiter orbital period) = 0.0472 x 90560 days (Pluto Orbital Period)
10747 days (Saturn orbital period) = 0.1174 x 90560 days (Pluto Orbital Period)
30589 days (Uranus orbital period) = 0.336 x 90560 days (Pluto Orbital Period)
59800 days (Neptune orbital period) = 0.662 x 90560 days (Pluto Orbital Period)
- Pluto orbital period creates error 1% with all data.
- No error In All Data More Than 1% -
- All planets orbital periods be created based on Pluto orbital period (90560 days)
by using the rates of time between Pluto and these planets –
The Data Proves That – The Rate of Time Controls The Solar System motion

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8-10 The Planets Orbital Distances Test
- Let's refer to what we will do here
- We remember here Mercury rates of time with the other planets
- Then
- We suppose that, Mercury moves during one solar day
- And
- We will find the other planets periods of time in comparison with this 1 solar day
of Mercury motion based on these planets rates of time with Mercury
- Then
- We will discover the distances the planets pass during these periods
- Then
- We will compare these distances with Mercury motion distance for 1 solar day
=4.095 mkm
- Based on this comparison, we should test if the planets orbital distances be defined
based on these planets rates of time,
- Let's Do That In Following…

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I- Data
Mercury Rates Of Time
1 hour of Mercury motion = 1.279 h of Venus Motion
1 hour of Mercury motion = 2.078 h of Earth Motion
1 hour of Mercury motion = 3.91 h of Mars Motion
1 hour of Mercury motion = 24.6 h of Jupiter Motion
1 hour of Mercury motion = 61.1 h of Saturn Motion
1 hour of Mercury motion = 174.8 h of Uranus Motion
1 hour of Mercury motion = 344.6 h of Neptune Motion
1 hour of Mercury motion = 520.2 h of Pluto Motion
1 hour of Mercury motion = 60.8 h of The Earth Moon Motion
The Motions Distances Based On Mercury Rates Of Time
(1)
Mercury (4.095 mkm / solar day) moves during 1 day a distance =4.095 mkm
(2)
Venus (3.024 mkm / solar day) moves during 1.279 days a distance =3.867 mkm
(3)
Earth (2.574 mkm / solar day) moves during 2.078 days a distance = 5.35 mkm
(4)
Mars (2.082 mkm / solar day) moves during 3.91 days a distance = 8.14 mkm
(5)
Jupiter (1.13184 mkm / solar day) moves during 24.6 days a distance = 27.8 mkm
(6)
Saturn (0.838 mkm / solar day) moves during 61.1 days a distance = 51.2 mkm
(7)
Uranus (0.5875 mkm / solar day) moves during 174.8 days a distance = 102.7 mkm
(8)
Neptune (0.4665 mkm / solar day) moves during 344.8 days a distance = 160.8 mkm
(9)
Pluto (0.406 mkm / solar day) moves during 520.2 days a distance = 211.2 mkm

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II- Data Analysis
No. (2)
(Venus motion distance=3.867 mkm) /(Mercury Motion Distance 4.095 mkm) =0.944
Where
(Venus orbital circumference =680 mkm) /(Mercury Distance 720.7 mkm) =0.944
No. (3)
(Earth motion distance=5.35 mkm) /(Mercury Motion Distance 4.095 mkm) =1.3
Where
(Earth orbital circumference =940 mkm) /(Mercury Distance 720.7 mkm) = 1.3
No. (4)
(Mars motion distance=8.14 mkm) /(Mercury Motion Distance 4.095 mkm) = 1.98
Where
(Mars orbital circumference =1433 mkm) /(Mercury Distance 720.7 mkm) = 1.98
No. (5)
(Jupiter motion distance=27.8 mkm) /(Mercury Motion Distance 4.095 mkm) = 6.8
Where
(Jupiter orbital circumference =4900 mkm) /(Mercury Distance 720.7 mkm) = 6.8
No. (6)
(Saturn motion distance=51.2 mkm) /(Mercury Motion Distance 4.095 mkm) = 12.5
Where
(Saturn orbital circumference =9010 mkm) /(Mercury Distance 720.7 mkm) = 12.5
No. (7)
(Uranus motion distance =102.7 mkm) /(Mercury Motion Distance 4.095 mkm) =25.1
Where (Uranus orbital circumference =18048 mkm) /(Mercury Distance 720.7 mkm) = 25.1
No. (8)
(Neptune motion distance =161 mkm) /(Mercury Motion Distance 4.095 mkm) =39.3
Where
(Neptune orbital circumference =28255 mkm) /(Mercury Distance 720.7 mkm) = 39.3
No. (9)
(Pluto motion distance =211.2 mkm) /(Mercury Motion Distance 4.095 mkm) =51.6
Where (Pluto orbital circumference =37100 mkm) /(Mercury Distance 720.7 mkm) = 51.6

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III- Discussion
(A)
- Let's summarize the idea in following:
- As we have seen the planets orbital periods and distances be defined clearly based
on the rates of time which we have calculated.
- And
- The rates of time be calculated based on the required periods for the planets to
move distances = their orbital distances, means
- The required periods should be considered as the cornerstone of the rates of time
definition and using.
- Shortly
- We conclude that, the planets orbital periods and distances be created as function
in these planets required periods to move their orbital distances, let's remember
these required periods in following
- Mercury needs 14.13 Solar Days (27.9 Solar Days)
- Venus needs 35.8 Solar Days
- Earth needs 58.1 Solar Days
- The moon needs 1700 Solar Days
- Mars needs 109.4 Solar Days
- Jupiter needs 687 Solar Days
- Saturn needs 1710 Solar Days
- Uranus needs 4890 Solar Days
- Neptune needs 9635 Solar Days
- Pluto needs 14547 Solar Days
(B)
- We notice that,
- The planet motion rates of time be defined also as the rates between this planet
orbital period and the other planets orbital periods.
- As we have noticed before

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- The planets orbital period defines planet orbital Circumference but
- The planets required period defines planet orbital Distance but
- Please review the discussion (The planets motions rates of time A Summary)
(C)
- The next step is to create one equation express these required periods of time,
- Means, if we have one equation controls the planets required periods of time, that
will create one law controls all planets orbital periods and distances.
- Let's discover this one law in the next point (6-11)

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8-11 One Law Controls The Planets Orbital Periods And Distances
- Let's Summarize The One Law Idea In Following:
(A)
- The inner planets required periods total = 235.8 days
- The outer planets required periods total = 31469 days
- The solar planets required periods total = 31705 days
- Notice
- 31469 days = 133 x 235.8 days (error 0.4%)
(B)
- The inner planets orbital periods total = 1480 days
- The outer planets orbital periods total = 196027 days
- The solar planets orbital periods total = 197027 days
- The total 197027 days = 1480 days x 133
(C)
- The solar planets orbital distances total = 16030 mkm
- 16030 mkm = 53.99 x 2 x 149.6 mkm (Earth orbital distance) (error 1%)
- Where
- 53.99 mkm = the distance be passed by Pluto in 133 days

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8-12 The General Discussion
- What conclusions we can reach through the previous data?
- The data tries to create an approach for the planets motions data analysis… we try
to know why or how this data be created by these values?
- One notice is, Saturn motion rate of time equal approximately the moon motion
rate of time. No any source in physics book tells this information or tells that the
Earth moon and Saturn have some interaction of motions. but the data shows that's
truth.
- The rate of time of Saturn and the moon motions be equal because their motions
creates this equality. For example the moon daily displacement 88000 km needs a
period 10747 days to pass a distance = 940 mkm (Earth orbital circumference),
where (10747 days = Saturn orbital period)
- I want to say
- The previous data analysis open the planets data and arrange it in some form to
facilitate the analysis process. We try to test Newton vision for the planet motion.
here we can't show the contradictions in each point spite they are found, but we
interest to see the planet motion depth as possible. It's not enough to say that
Newton was the bad person in our physics book, it's not our objective, we need to
know why Newton is mistaken?, why the planet motion in its depth be different
from the outer observation? Why the direct vision only without data analysis
deceives us?
- For the last question I have a very interesting answer let's write it in an example for
explanation in following:
- Example For Explanation
- The moon displacement per a solar day = 88000 km
- The moon day period =29.53 solar day
- By that, the distances total which be passed by the moon in its day period should
be =(88000 km x 29.53 days = 2598640 km = 2π x 413600 km)

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- Based on this data, The Moon Apogee Radius Should Be = 413600 km
- But it's not a fact
- The moon apogee radius = 406000 km
- Means,
- The moon can't be far from the Earth at a distance more than 406000 km, and the
moon never visit the point 413600 km
- This data shows clearly we can't understand the moon motion trajectory by the
observation only but we need to analyze the motion data to know what's going on.
- Again
- How the moon apogee radius be (406000 km)? while it should be (413600 km?)
- Notice
- There's one more feature should be referred as a result because the distance
(2598640 km) is so long the moon would have to revolve around Earth through its
(new) apogee orbit
- Shortly
- Based on this data, the moon would revolve around Earth along month through the
apogee orbit whose radius (r=413600 km) and would be prevented to revolve
around Earth through any more near orbits!
- The Fact Is That,
- The moon creates an angle (θ) between the moon displacement direction and the
moon orbit horizontal level, by that, while the moon moves daily 88000 km but
this distance doesn't be accounted for the moon orbit. The orbit considers another
displacement depend on the angle, let's call it (the real displacement L)
- (The Real Displacement) L = 88000 km cos (θ)
- As a result
- The real displacement be shorter than (88000 km) and the total displacements
during (29.53 days) be less than (2598640 km) and be = (2550973 km) (-2%)

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- By this intelligent technique, the genius moon can revolve around Earth through
more near orbits and avoid to visit the point 413600 km forever and makes its
apogee radius =406000 km
- I wish the example proves the idea clearly, that we can't understand the planets
motions by observation only, but it necessitates to use the planets motions data
analysis.
- I want to say
- The previous analysis is an approach, the rest paper points use this approach to
analyze different points of the planets motions data. because of that the paper will
discuss the equality of the rates of time between Saturn and the moon.
- Let's summarize what we try to do here
- I arrange the planets motions data to enable the analysis process to be done. In our
minds we compare between Newton vision of the solar system motion and the
planets motions data analysis. By that the contradictions will be seen along the
analysis process. After we finish we should suggest our description for the solar
system motion which be in harmony with the planets motions data analysis.

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9- The Planets Motions Rates Of Time Effect Analysis
9-1 Preface
9-2 Planets Motions Rates Of Time And Distances Data
9-3 The Data Equal Distances
9-4 The Data and the planets velocities.
9-5 The Data Distances And Rates Of Time Interaction
9-6 The Data General Discussion
9-7 Mars, Jupiter and Saturn Motions Analysis
9-8 Why Saturn And The Moon Use Equal Rates Of Time?
9-9 Why Mercury Use A Double Of Its Orbital Distance?
9-10 The Rate (4.61) be used between Pluto and the moon motion
9-11 The Moon Orbital Motion Equation

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9-1 Preface
In this point we provide analyze the motions rates of time and their distances –
In next point we provide a table for the data we analyze in this point.
Let's use some of this data as example to explain how the table data works
Planet Rate of time Relative to Motion Distance
Mercury 1 day 1.279 days Venus 3.867 mkm
2.078 days Earth 5.37 mkm
3.91 days Mars 8.14 mkm
Let's explain this part of the table
1 day of Mercury motion = 1.279 days of Venus motion and Venus moves during
1.279 days a distance = 3.867 mkm
1 day of Mercury motion = 2.078 days of Earth motion and Earth moves during
1 day of Mercury motion = 3.91 days of Mars motion and Mars moves during 3.91
days a distance = 8.14 mkm
By this way the table works

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9-2 Planets Motions Rates Of Time And Distances
I- Data
(This table we have discussed before, we use it here as a reference for the point
discussion)
Planet Rate of time Relative to Motion Distance
Mercury 1 day 1.279 days Venus 3.867 mkm
days The moon
24.6 days Jupiter 27.84 mkm
61.1 days Saturn 51.2 mkm
174.8 days Uranus 102.7 mkm
344.6 days Neptune 160.8 mkm
520.2 days Pluto 211.2 mkm
Venus 1 day 0.78 days Mercury 3.194 mkm
1 day Venus 3.024 mkm
The moon
47.8 days Saturn 40 mkm
Earth 1 day 0.481 days Mercury 1.97 mkm
0.617 days Venus 1.866 mkm

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1 day Earth 2.574 mkm
The moon
250 days Pluto 101.5 mkm
Mars 1 day 0.255 days Mercury 1.044 mkm
1 day Mars 2.082 mkm
The moon
133 days Pluto 53.99 mkm
Jupiter 1 day 0.0406 days Mercury 0.1664 mkm
0.0520 Venus 0.1572 mkm
0.08474 Earth 0.2181
0.1587 Mars 0.3304 mkm
The moon
1 day Jupiter 1.1318 mkm

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14 days Neptune 6.5318 mkm
Saturn 1 day 0.01639 days Mercury 0.0671 mkm
The moon
0.4032 days Jupiter 0.4563mkm
1 day Saturn 0.838 mkm
Uranus 1 day 0.00572 days Mercury 0.0234 mkm
0.0223 days Mars 0.04657 mkm
The moon
1 Uranus 0.5875 mkm
Neptune 1 day 0.0029 days Mercury 0.0118 mkm
0.0060 days Earth 0.01552

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0.1135 days Mars 0.02363 mkm
The moon
1 Neptune 0.46656 mkm
Pluto 1 day 0.00192 days Mercury 0.00 787mkm
0.00245 days Venus 0.007435 mkm
0.007518 days Mars 0.01565 mkm
The moon
0.04739 days Jupiter 0.05364mkm
1 Pluto 0.406 mkm

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9-3 The Data Equal Distances
I-Data
(1)
102.7 mkm =0.5875 mkm /day x174.8 days
102.4 mkm = 0.838 mkm /day x 61.1 days x 2
101.5 mkm = 0.406 mkm /day x 250 days
(2)
88000 km x 29.53 = 2.5986 mkm
And
Earth motion distance per a solar day =2.574mkm (error1%)
(3)
4.163 mkm = 2.57 mkm /day x 1.62 days
4.177 mkm = 0.5875 mkm /day x 7.11 days
(4)
88.1 x 0.4665 mkm x 2 =136.7 x 0.5875 mkm (2.3%)

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II- Discussion
Equation no. (1)
102.7 mkm =0.5875 mkm /day x174.8 days
102.4 mkm = 0.838 mkm /day x 61.1 days x 2
101.5 mkm = 0.406 mkm /day x 250 days
- Where
- 0.838 mkm = Saturn Velocity per a solar day
- 0.5875 mkm = Uranus Velocity per a solar day
- 0.406 mkm = Pluto Velocity per a solar day
- And
- 1 Day Of Mercury = 61.1 Days Of Saturn =174.8 Days Of Uranus
- 1 Day Of Earth =250 Days Of Pluto
- Equation no.(1) is clear, 1 day of Mercury = 61.1days of Saturn =174.8 days of
Uranus, and
- Saturn moves during 61.1 days (51.2 mkm) and Uranus moves during 174.8 days
(102.4 mkm) the 2 distances be equal when we use the double value of Saturn
motion.
- Let's summarize the basic points in following:
(1) Uranus Orbital Distance = 2 Saturn Orbital Distance because of that all
produced distances of the table shows this fact. Uranus Motion Distance be
(always) = 2 Saturn motion distance
(2) Mercury velocity = 2 Mars velocity (error 1.7 %), because of that all produced
distances of the table shows this fact. Mercury Motion Distance be (always) = 2
Mars motion distance (error 1.7%)
(3) The table shows interesting feature and shows the rate (2) be used frequently
among many different of table data. we have to notice that the data considers
planet velocity effect= planet orbital distance effect which we need to analyze
in the general discussion.

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- Now the equality between Uranus motion distance (102.7 mkm) and double Saturn
motion distance (2 x 51.2 mkm) is a basic feature of the table but why these 2
distances = Pluto motion distance during 250 days (101.5 mkm) (error 1%)?
- Why these 3 distances are equal?
- Why any 2 distances be equal in the solar system? what's the result of this equality
of distances?
Equation no. (2)
88000 km x 29.53 = 2.5986 mkm
And
Earth motion distance per a solar day =2.574mkm (error1%)
- We understand this data clearly,
- The Earth velocity per a solar day = 2.574 mkm
- The moon displacement total during 29.53 days = 2.598 mkm
- The difference (1%) we consider the 2 distances are equal and the difference be
(1%) be found for a geometrical necessity… but
- Why these 2 distances are equal?
- What effect be done on Earth motion or the moon motion as a result for this
quality of distances?
- Notice
- The equal distances is a very important feature in the solar planets motions, we
have to know why these distances be equal because huge number of data be
created as a result for the planets distances equality – the point is that – the
equality of distances which effects greatly on the planets motions and data uses
some unknown method for us. by the equality of distances effects on the planets
motions and data but we can't catch this effect because we didn't discover the
method by which this equality effects on the planets motion. let's us one example
for better explanation.

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- Example no. (1)
- Earth moves during the solar day (24 hours) a distance = 2.574 mkm
- The moon displacements total during 29.53 days =2.598 mkm
- Pluto moves during its day period (153.3 hours) a distance = 2.593 mkm
- This equation of distances between the 3 planets produced a deep proportionality
between these planets motions data… let's refer to some of them in following
(I)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
(II)
(a)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(b)
Tan (12.2) x 708.7 hours = 153.3 hours
(c)
Tan (13.17) x 655.7 hours = 153.3 hours
(d)
2 x 153.3 h = 4.61 x 66.5 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 0.4%).
(e)
413600 km cos (10.96 deg) = 406000 km
(f)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
Notice
4.7 km/sec x 88000 seconds = 413600 km

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Equation no. (3)
4.163 mkm = 2.57 mkm /day x 1.62 days
4.177 mkm = 0.5875 mkm /day x 7.11 days
- 1 day of Venus motion = 1.62 days of Earth motion, Earth moves during this
period (1.62 days) a distance = 4.163 mkm
- 1 day of Jupiter motion = 7.11 days of Uranus motion, Uranus moves during this
- The 2 distances are equal approximately (error around 0.3%)
- Why the 2 distances are equal?
Equation no. (4)
88.1 x 0.4665 mkm x 2 =136.7 x 0.5875 mkm (2.3%)
- 1 day of Venus motion = 136.7 days of Uranus motion, Uranus moves during this
- 1 day of Mars motion = 88.1 days of Neptune motion, Neptune moves during this
period (88.1 days) a distance = 41.1 mkm for that reason the rate (2) is used and
then the value (41.1 be 82.2 which is different from 80.3 with 2%)
- Again
- Why the distances are equal?
- I wish our try to analyze the planets motions data be seen as clear as possible… the
classical vision which tells the planets move independent motions be refuted
frequently by different data of planets motions. we here depend on the suggested
vision which tells the planets motions be done by planets motions dependency on
one another. that tells the equality of distances can't be created by any random
process. The equality of distance be done by geometrical necessity which is used
by planets motions. that means, if these distances aren't equal the planets motion
necessitate to change as a result….
- The difficulty is, we can't catch the distances equality effect on planets motions.
As a result we can't understand what would happen if these distances aren't equal

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- Here, in more clear light
- We can see the mistake of Newton theory of the sun mass gravity. The basic
difficulty is, Newton supposed that the planets motions be independent from one
another. by that all previous data should be created by some random process and
pure coincidences of numbers. The sun mass gravity isn't a theory we need to
remove from the physic book. It's the parent of the big bang theory – the sun mass
gravity is a result of the wrong in vision and wrong in the thinking direction and
description. The basic illness behind is the hypothesis that the solar system be
create out of any mentioned geometrical design.
- The basic description told that, the planets be created by some random process and
without any geometrical design found before this creation.
- That's why we fight against Newton so strongly
- It's not the wrong idea of the sun as a reason for the planets motion while in fact
the sun be created after all planets creation and motions –This is not the point we
fight Newton for – the point is that – Newton supposed the whole machine be
created by some random process without a geometrical design found before – that's
the main point-
- On The Contrary
- There Is A Geometrical Design Found Before Any Planet Creation.
- The planet data be created based on some map be defined before this planet
creation. here is the point-
- The next question is
- Who created this design which is found behind the planets creation?
- The light beam
- For that reason we fight against Newton, Because
- While the universe is create basically out of light and the matter be created as a
form of light (coherence) or (interference) by that there are 2 different universes
around us, the light motion network universe and the matter motion universe

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- The planets be as ships sail over sea,
- The ships are the planets and the sea is the light motion network – by that – light
motion (continuously) effect on the planets motions. That's why our equations be
created depending on geometrical necessities even if we don't know these
necessities because the light motion creates these geometrical necessities and
create the planets motions data.
- Newton simply remove the other universe and told us that the universe is these
planets matters and distances where they define their motions by their-selves but
when we analyze the data always found that a strange players are found an effect
on the planets motions data – as a result the idea told by Newton contradicts
(frequently) the planets data.
- Now Newton idea is similar to some claim tells the animal is a body only, and in
this case I can't distinguish between a living animal and a dead one
- The point is that, the random creation and motion independency removes the other
universe which is found behind and so we still imprisoned behind the sun mass
gravity concept trying to understand how this concept causes the planets motions
while the data (frequently and always) be in contradictions.
- Let's remember these contradictions in following
- First,
- Newton told the planet orbital distance be defined by the gravitation equation, but
The planets order disproves the gravitation equation frequently, for explanation
(the planets initial conditions claim) be invented and so the contradiction be
covered – But- no support from the planets order for the gravitation equation – and
why it's acceptable
- Second
- Newton told the planet velocity be defined based on the masses gravity force, but
(Venus velocity/ Uranus velocity) = (Mars velocity/ Pluto velocity) = (the
velocity/ Neptune velocity)

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- This proportionality of velocities isn't supported by masses rates and by that the
definition of velocity violate the law and concept which Newton defined!
- Again planets data against Newton
- One more problem in Newton theory of the sun mass gravity that, the theory
doesn't tray to explain how the planets data be created? and of course Newton
supposed that the planets use the same rate of time –
- I want to say
- Newton theory be so far from the truth of the planets creations and motions – the
basic point is that – Newton depended on the outer observation as a basic reference
and didn't use any analysis of the planets motion – this point essentially is the big
bang mistake which is found in Newton theory – because any planets data analysis
can simply disprove the big bang theory, because the big bang concept tells the
solar group be created by some random process and without any geometrical
design be found before the planets creation – this is perfectly the point by which
Newton theory of the sun mass gravity be refuted – because the solar group is built
based on a geometrical design be found before any planet creation – the
geometrical design be created by light motion which is found before any planet
creation and motion– the light is found before the matter -

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9-4 The Data and the planets velocities.
- In the table there are 3 important values which are (2.078 – 3.057 – 2.48)
- Where
- 1 day of Mercury =2.078 days of Earth
- But
- 2.082 mkm per solar day = Mars velocity
- And
- 1 day of Venus =3.057 days of Mars
- But
- 3.024 mkm per solar day = Venus velocity (difference with 1%)
- And
- 1 day of Jupiter = 2.48 days of Saturn
- But
- (2.574 mkm (Earth velocity daily) + 2.4 mkm (the moon velocity daily)) /2 = 2.48
mkm per a solar day
- Means 2.48 mkm daily is the average velocity for Earth and the moon motions
- By that we have 3 velocities which be used as rates of time these velocities are:
- (1) Venus velocity per a solar day 3.024 mkm
- (2) The velocity 2.48 mkm per a solar day (the average of Earth and the moon)
- (3) Mars velocity per a solar day 2.082 mkm
- And Mercury velocity = 2 Mars velocity (error 1.7%) and the rate (2) be used
frequently in the table data.
- That means,
- The inner planets velocities be produced among the rates of time
- First
- Let's test what would happen if the rate of time be equal a planet velocity – let's
test that with Mars in following…
-

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(1) Mars Velocity = Mercury Earth Rate Of Time
Mars velocity 2.082 Earth Rate Mercury Rate
2.082 x 1/2.082 (Mercury) = 1
2.082 x 1/1.62 (Venus) =1.279
2.082 x 1.88 (Mars) =3.91
2.082 x 11.8 (Jupiter) 24.6
2.082 x 29.4 (Saturn) 61.1
2.082 x 84.1 (Uranus) 174.8
2.082 x 165.8 (Neptune) 344.6
2.082 x 250 (Pluto) 520.2
- The data shows the idea clearly
- Earth column shows the rates of time between the Earth and the other planets
- Mercury column shows the rates of time between Mercury and the other planets
- 2.078 is the rate between earth and Mercury (means 1 h Mercury =2.078 h Earth)
- 2.082 mkm = Mars Velocity Per A Solar Day
- By that simply
- Earth column be used as periods of time and Mercury columns be used as
distances passed by Mars during these periods of time
- The same result will be told with the 2 other velocities (3.024 mkm Venus velocity
per a solar day and 2.48 mkm the average velocity of Earth and the moon per a
solar day)
- Let's see their tables in following

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(2) Venus velocity 3.024 =Venus Mars Rate Of Time (3.057) (error 1%)
Venus velocity 3.024 Mars Rate Venus Rate
3.024 x 0.255 (Mercury) = 0.77
3.024 x 0.327 (Venus) = 1
3.024 x 0.531 (Earth) = 1.62
3.024 x 6.3 (Jupiter) = 19.2
3.024 x 15.6 (Saturn) = 47.8
3.024 x 44.7 (Uranus) = 136.7
3.024 x 88.1 (Neptune) = 269.7
3.024 x 133 (Pluto) = 406.7
Max error 1%
(3) The Average Velocity 2.48 = Jupiter Saturn Rate Of Time
The average Venus 2.48 mkm Saturn Rate Jupiter Rate
2.48 x 0.0163 (Mercury) = 1/24.6
2.48 x 1/47.8 (Venus) = 1/19.2
2.48 x 1/ 29.4 (Earth) = 1/11.8
2.48 x 1/15.6 (Mars) = 1/6.3
2.48 x 1/2.48 (Jupiter) = 1
2.48 x 2.857 (Uranus) = 7.1
2.48 x 5.63 (Neptune) = 14
2.48 x 8.51 (Pluto) = 21.1
Max error 1%
- The data shows simply
- One column works as periods of time and the other column work as distances
- The idea is clear – but we don't know why the inner planets velocities only be
found among the planets motions rates of time? Why not the outer planets?!

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- Comments And Questions
- The inner planets velocities are found among the motions rates of time, and that
may cause the planets velocities proportionality – as we have seen before – let's
remember this data in following:
- (1)
- (Venus Velocity / Uranus Velocity) = (Mars Velocity / Pluto Velocity) = (the
moon velocity/ Neptune)
- (2)
- (Mercury velocity / Venus Velocity) = (Jupiter Velocity/ Saturn Velocity)
- (3)
- (Earth velocity /Mars velocity) = (Uranus Velocity / Neptune Velocity) (error 2%)
- This proportionality of planets velocities must be created by using the planets
motions rates of time because the inner planets velocities be used as rates of time
of the planets motions.
- That means, the planets velocities be in proportionality based on interaction of
motions done by the planets motions rates of time – that tells how the machine
transports the data through the planets
- The data be transported (as the velocities proportionality rates) be done by using
the planets motions rates of time -
- But
- We still need to answer the question – how the planets motions rates of time
effect on the planets motions. where the motions rates of time be transported
among the planets and transport the motions data with it. but how this
transportation process is done? This question should be answered when clearly we
know how the planets motion –while no sun gravity is used and the hypothesis
tells that the matter is created out of light and by that the matter is created basically
in motion - the transportation process should be done by the light beam from
which the planets be created.

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9-5 The Data Distances And Rates Of Time Interaction
- This point deals with the table distances produced with planets motions, where
these distances equal rates of time – for example
- 1 day of Venus motion =3.057 days of Mars motion and Mars moves during these
- 1day of mars motion =6.3 days of Jupiter motion
- If
- 1 mkm = 1 day
- The distance 6.3 mkm =6.3 days
- We analyze this data by this method to show that some continuum be found
through this data – we should discuss that after the data provision – but let's
summarize the idea in following….
- Some continuous effect be found through the planets motions data -
- This effect uses periods of time and distances through different planets – by that
the planet itself be As A Point On A Straight Line – the planet here isn't the
player but be the board on which the player writes – again – the planet in this case
be as a hole but the player be as a digger – now this player may be the planet
motion or other planets motions or light motion found behind the board.
- That's what I try to tell
- The data be created by some powerful hand moves through the planets, the planet
here be as a gear be assembled in some greater machine. The planet has to move
because the machine pushes it. and by the planet motion the machine data be seen
in this planet motion.
- Let's see the data in following

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I- Data
(A)
- 1 day of Venus = 3.057 days of Mars and mars moves during (3.057 days) a
distance =6.3 mkm (1 day of mars =6.3 days of Jupiter)
(B)
- 2 days of Venus = 2 x 269.7 days of Neptune and Neptune moves during (2 x
269.7 days) a distance = 250 mkm (1 day of Earth =250 days of Pluto)
(C)
- 1 day of Venus = 406.7 days of Pluto and Pluto moves during (406.7 days) a
distance = 165.1 mkm (1 day of Earth =165.1 days of Neptune)
(D)
- 1 day of Earth = 0.481 day of Mercury and Mercury moves during (0.481 days) a
distance = 1.97 mkm (1 day of Uranus =1.97 days of Neptune)
(E)
- 1 day of Earth = 0.671 day of Venus and Venus moves during (0.671 days) a
distance = 1.88 mkm (1 day of Earth =1.88 days of Mars) (error 0.8%)
(F)
- 1 day of Earth = 1.88 days of Mars and Mars moves during (1.88 days) a distance
= 3.91 mkm (1 day of Mercury =3.91 days of Mars)
(G)
- 1 day of Earth = 29.4 days of Saturn and Saturn moves during (29.4 days) a
distance = 24.6 mkm (1 day of Mercury =24.6 days of Jupiter)
(H)
- 1 day of Mars = 6.3 days of Jupiter and Jupiter moves during (6.3 days) a
distance = 7.11 mkm (1 day of Jupiter =7.11 days of Uranus)

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(I)
- 1 day of Jupiter = 2.48 days of Saturn and Saturn moves during (2.48 days) a
distance = 2.078 mkm (1 day of Mercury =2.078 days of Earth) –also (2.082mkm
per solar day = Mars velocity)
(J)
- 1 day of Jupiter = 21.1 days of Pluto and Pluto moves during (21.1 days) a
distance = 8.56 mkm (1 day of Saturn =8.51 days of Pluto) (error 0.7%)
(K)
- 1 day of Saturn = 2.857 days of Uranus and Uranus moves during (2.857 days) a
distance = 1.52 mkm (1 day of Neptune =1.509 days of Pluto) (error 0.7%)
II- Discussion
- We notice that, the most distances which can be used as rates of time be found in
Earth and Venus data, then there are some few rates in Mars, Jupiter and Saturn,
then no more planets distances can be used as rates of time
- How Does This Machine Work?
- Why the planets motions produce distances can be used as rates of time? Is this
feature found only in this table which I have created? of course not, it's feature of
the planets motions – for example
- Mercury moves during its rotation period (1407.6 h) a distance =243 mkm (1%)
- And
- Mars moves during Venus day period (2802 h) a distance =243 mkm
- Where 243 solar days = Venus rotation period
- One more example
- Venus moves during 365.25days a distance = 2π x 175.94 mkm where (Mercury
day period =175.94 solar days)
- The pure coincidence of numbers claim is useless and gave nothing, let's analyze
some of this data in following:

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(1st
Point)
I-Data
(1)
1 day of Earth motion = 29.4 days of Saturn motion, and Saturn moves during 29.4
days a distance = 24.6 mkm
(2)
Jupiter moves during 29.4 days distance = 33.3 mkm
(3)
0.838 mkm x 33.3 days =1.1318 mkm x 24.6 days = 27.9 mkm =47.4 x 0.5875
And
(24.6 mkm/0.838 mkm/day) = (33.3 mkm /1.1318 mkm/day)
(4)
Mercury moves during 27.9 days a distance = 2 x 57.2 mkm (mercury orbital distance
57.9 mkm error 1%)
(5)
1 day of Mercury motion = 24.6 days of Jupiter motion
(Notice No.1 47.4 km/s x 6.8 h x 3600 s = 1.16 mkm)
(Notice No.2 175.94 days =6 days x 29.33 mercury moves during 6 day 24.6 mkm)
(Notice No.3 33.48 hours = 120536 seconds, but 120536 km =Saturn diameter)
(6)
(29.4/27.9) =(12756 km/ 12104 km)

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II-Discussion
- Let's summarize the previous data in some understandable form
- 1 Day of Earth motion be = 29.4 days of Saturn motion, and Saturn moves during
this period 29.4 days a distance = (24.6 mkm)
- 24.6 mkm of Saturn be used as 24.6 solar days by Jupiter, a planet motion distance
be used as a period of time by another planet.
- Jupiter moves during (24.6 days) a distance = 27.9 mkm
- 27.9 mkm of Jupiter motion be used by Mercury as a period of time and be used as
(27.9 days)
- Mercury moves during (27.9 days) a distance = 2 x 57.2 mkm (mercury orbital
distance = 57.9 mkm error 1%).
- Where
- 1 day of Mercury motion = (24.6 days) of Jupiter motion
- And
- 1 day of Jupiter motion = (2.48 days) of Saturn motion.
- Shortly
- We have some transportation of data from Saturn to Jupiter to Mercury…
- We can explain the previous data only by transportation of data because no
random process can produce this data…
- The data is more complex. And I can't extend the discussion greatly because I'm
afraid from the confusion… but
- We should see that, Uranus moves this distance (24.6 mkm) in 47.4 days where
47.4 km/sec = Mercury velocity… the notice is that, (Mercury moves during 6.8
hours a distance =1.16 mkm where 6.8 km/sec = Uranus velocity).
- Let's write the analysis of the distance (24.6 mkm) in following

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- (24.6 mkm) = 4.095 mkm x 6 days
= 3.027 mkm x 8.13 days
= 2.574 mkm x 9.55 days
= 2.4 mkm x 10.25 days
= 1.1318 mkm x 21.7 days
= 0.838 mkm x 29.35 days
= 0.5875 mkm x 41.8 days
= 0.46656 mkm x 52.7 days
= 0.406 mkm x 60.6 days
- Now let's see the second point in following…

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(2nd
Point)
I-Data
(1)
1 day of Jupiter motion =21.1 days of Pluto motion, but Pluto moves during 21.1 days
a distance = 8.51 mkm
(2)
1 day of Saturn motion = 1 day of the moon motion = 8.51 days of Pluto motion.
II-Discussion
- If 1 mkm be = 1 day, so
- 1 day of Saturn motion = 8.51 days of Pluto motion and 1 day of Jupiter motion
causes to be equal 8.51 days of Pluto motion.
- 1 day of Jupiter motion = 2.48 days of Saturn motion
- But here we see that 1 day of Jupiter =8.51 days of Pluto and 1 day of Saturn
=8.51 days of Pluto.
- That means,
- 1 day of Saturn motion should be = 1 day of Jupiter motion relative to Pluto
- As a result
- The rate 2.48 between Jupiter and Saturn be transported to Pluto motion data and
because of that 90560 days (Pluto orbital period) = 2.48 x 37100 days (where
37100 mkm = Pluto orbital circumference)
- I try to prove, different data shows the transportation of data among the planets.
- Notice
- The rate 2.48 be transported from Pluto data to Earth data because of that (365.25
days /149.6 mkm) = 2.48 (error 1.5%), we should know how this rate be
transported to the Earth later.

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(3rd
Point)
I-Data
(1)
Saturn moves during 8.51 days a distance = 7.13 mkm
(1 day of Jupiter motion =7.11 days of Uranus motion) and
(2)
Pluto moves during 7.11 days a distance = 2.895 mkm
(1 day of Uranus motion =2.96 days of Pluto motion) (with 2.895 the error =2%)
II-Discussion
- The data tries to show that, the planets motions rates of time creates some series in
data. and by that planets data be created based on other planets data in some series.
- Here we have no pulses of data but we have some direction and the data be
transported or produced based on this direction.
- I wish the data proves the idea clearly
- We are very far from Newton theory of the sun mass gravity, the planets aren't
some rigid bodies separated from one another and found by some random process.
The planets are building be created based on one another and by participation of all
members according to their motion and energy.
- The mistake isn't just one point but the mistake is a general direction. Newton had
lost into the imagination and created and idea completely different from how the
machine works. By this imagination the splendid geometrical design of the solar
system be covered

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(4th
Point)
I-Data
(1)
24.6 mkm = 2.57 mkm (Earth motion daily) x 9.55 days
(1.1318 mkm x 8.51 days = 9.6 mkm)
(2)
24.6 mkm = 1.1318 mkm (Jupiter motion daily) x 21.7 days
(21.9 mkm = 8.51 days 2.57 mkm)
(3)
2.57 mkm x 9.55 = 1.1318 mkm x 21.7 days = 29.4 days x 0.838 mkm
(0.838 mkm Saturn Motion Distance During A Solar Day)
Notice 8.51 mkm = 88000 km x 96.7 (the moon axial tilt 6.7 deg +90 deg =96.7 deg)
II-Discussion
- The previous data be provided for 2 reasons let's summarize them in following:
- (1st
Reason)
- The data shows a system of data. we deal with the same numbers which are used
tenths of time. This behavior is the geometrical rule behavior and no pure
coincidences or any random process can produce this data.
- Shortly, we deal with a geometrical machine which produces the data.
- (2nd
Reason)
- I have provided the data may someone can discover the geometrical rule based on
which this data is created. Let's try with it as we can in following
- (1)
- We have 2 basic players which are Jupiter and Saturn, the data uses their motions
with Earth and Mercury (Point no. 1) and with Pluto (Point no.2)
- The same 2 players Jupiter and Saturn … this is the first observation
- The second observation be that, the used rule almost the same, because Saturn
moves a distance =24.6 mkm and Jupiter uses a period =24.6 days (in point no. 1)
and

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- In Point no. (2)
- Pluto moves the distance (8.51 mkm) based on it rate of time with Jupiter and 1
day of Saturn motion be = 8.51 days of Pluto. here the motion be done by Pluto in
compassion with Jupiter and Saturn data
- From that we understand
- Jupiter and Saturn motions do some specific job for Earth and Mercury on one side
and for Pluto on the other side.
- Now
- We should notice that, the connection between Earth and Mercury depend on the
value (24.6 mkm or day or hours)
- That may tell us, Jupiter and Saturn tried to connect Mercury and Earth with Mars
because the basic used value is (24.6 hours =Mars rotation period)
- Now we can reach to some conclusion
- The 2 planets (Mars and Pluto) had migrated from their original orbital distances
to the current one. The solar system distances be created as a network, we can
imagine these distances be created as a chess board. The migration of the 2 planets
caused confusion for the distances distribution and by that the planets motions
tried to repair the negative effects of the 2 planets migration. After Saturn creation,
the repair process be started, where Saturn and Jupiter tried to connect the solar
system together as a unified unit. By that Jupiter and Saturn motions connect
between Mercury and Earth on one side with Mars and with Pluto on the other
side. That may explain the previous data.
- But
- There's something important in this vision,
The value 24.6 mkm or days or hours is a cornerstone in the solar group repair
process. This value in inherited from Mercury because this value Mercury defined
before the planets migration. Mercury insist to use this value (24.6) because by that
the repair process will be built based on the solar system original geometrical design.

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9-6 The Data General Discussion
- About What This Table Data Analysis Argue?
- We have 2 clear visions
- Newton Theory Of The Sun Mass Gravity And Its Description For The Planets
Motions – which considers the planet motion be independent from all other planets
and the planets move by the sun mass gravity – and this motion be done even if
one planet only be found in the solar group.
- The paper suggested vision tells that, the solar group is one machine, and each
planet is part of this machine by that each planet motion and data be created
depending on the other planets motions and data
- We analyze the planets data in some form to create confidence in the suggested
vision against Newton theory
- Our suggested vision has an advantage over Newton theory because we try to
explain how the planets motions data be created –
- For example
- Newton would tell that, the table data be created by pure coincidence of numbers,
but we see clearly that the table data be created based on a system of data. We
didn't find any feature of random process as a reason behind this data. for example
we have the rate (2) be found frequently in data but we don't find any other rates
repeated frequently as this rate, and the fact tells that Uranus orbital distance =2
Saturn orbital distance and mercury velocity = 2 Mars velocity (error 1.7%) by that
there's some logical conclusion to find the rate (2) in the table data and not any
other rate – that shows we don't deal with some random process but we deal with
directed data.
- By that, the table data provides a description for one feature of the solar planet
motion features –here we have some advantage against Newton.
- Now, we have to ask

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- Did we understand this table data?
- For example
- Pluto moves during 15.6 days a distance =6.3 mkm where
- 1 day of Mars = 15.6 days of Saturn and
- 1day of Mars = 6.3 days of Jupiter and
- How can we explain this data?
- Why Pluto velocity be created as a rate between Jupiter, Saturn and mars data?
- Let's ask one more question
- Why the inner planets velocities only be found in the planets motions rates of
time?
- I suppose that the inner planets be created with charges by that the Earth is the
great electron and the rest inner planets together be the great positron – I suggest
this hypothesis because Earth mass alone = the rest inner planets masses total,
(error 1%)
- and
- The electron and positron are 2 particle equal in mass
- This idea tries to attribute some different charges for the inner planets, and because
the charges are different the inner planets create an electric field for their motions.
- The accurate motion of planets can depend on electric filed in place of the sun
mass gravity and also the electric field idea be more suitable for the planets
motions more than the sun gravity force –
- Also I suppose the outer planets motions depend on the inner planets motions,
means the motion be transported from the inner planets to the outer planets.

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9-7 Mars, Jupiter And Saturn Motions Analysis
I - Data
(1)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
(2)
- 4331 days (Jupiter Orbital Period) =2π x 687 days (Mars Orbital Period)
- 1433 mkm (Saturn Orbital Distance) =2π x227.9 mkm (Mars Orbital Distance)
- 10747 days (Jupiter Orbital Period) =2.5 x 4331 mkm (Jupiter Orbital Period)
- 24.1 km/s (Mars Velocity) =2.5 x 9.7 km/s (Saturn Velocity)
- 24.6 h (Mars rotation period) =2.5 x 9.9 h (Jupiter Day Period)
- ((10747 days x 24 h) /24.6 h) = ((4331 days x 24 h) /9.9h) = 10485
- 3.1 deg (Jupiter Axial Tilt) x 2 = (2.5 deg = Saturn orbital inclination)2

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II –Discussion
Equation no. (1)
- 1 hour of Mars Motion = 6.3 hours of Jupiter Motion = 15.56 hours of Saturn
Motion = 44.6 hours of Uranus Motion = 88 hours of Neptune motion = 132.7
hours of Pluto motion
- i.e.
- 1 Solar Day of Mars Motion = 6.3 Solar Days of Jupiter Motion = 15.56 Solar
Days of Saturn Motion = 44.6 Solar Days of Uranus Motion = 88 Solar Days
of Neptune motion = 132.7 Solar Days of Pluto motion.
- Let's define the distances which these planets pass during these periods of time
- Mars (2.08 mkm per solar day) moves during 1 solar day a distance = 2.082 mkm
- Jupiter (1.1318 mkm per day) moves during 6.3 solar days a distance = 7.13 mkm
- Saturn (0.838 mkm per day) moves during 15.56 solar days a distance =13.1 mkm
- Uranus (0.5875 mkm per day) moves during 44.6 days a distance=26.22 mkm
- Neptune (0.466560 mkm per day) moves during 88 days a distance = 41.05 mkm
- Pluto (0.406 mkm per day) moves during 132.7 solar days a distance =53.88 mkm
- Based on that
- Mars during (1 solar day) moves 2.082 mkm
- Jupiter during (6.3 solar day) moves 7.13 mkm
- Saturn during (15.5 solar day) moves 13.1 mkm
- Uranus during (44.6 solar day) moves 26.22 mkm
- Neptune during (88 solar day) moves 41.05 mkm
- Pluto during (132.7 solar day) moves 53.88 mkm

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Data Analysis
(1)
- Saturn motion distance = 13.1 mkm = Mars Motion Distance 2.08 mkm x 2π
- This data explains why
- Saturn orbital circumference 9007 mkm = Mars orbital circumference 1433
mkm x 2π
(2)
- Uranus motion distance = 26.22 mkm = Saturn Motion Distance 13.1 mkm x 2
- Uranus orbital circumference 18048 mkm = Saturn orbital circumference
9007 mkm x 2
(3)
- Neptune motion distance =41.05 mkm =Saturn Motion Distance 13.1 mkm x π
- Neptune orbital circumference 28255 mkm = Saturn orbital circumference
9007 mkm x π
(4)
- Pluto motion distance =53.9 mkm =Saturn Motion Distance 13.1 mkm x 4.11
- Pluto orbital circumference 37100 mkm = Saturn orbital circumference 9007
mkm x 4.11
(5)
- Pluto motion distance =53.9 mkm =Uranus Motion Distance 26.22 mkm x 2.06
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06

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Discussion (Continued)
- Now we know that,
- Saturn moves a distance =13.1 mkm = 2π x Mars Distance 2.082 mkm
- Simply that rate (2π) is created here because of the motions rates of time among
the planets.
- We have explained one data
- Based on that, the rate (2π) isn't be created by any pure coincidence of numbers
but because,
- 1 day of Mars motion = 6.3 days of Jupiter motion = 15.56 days of Saturn motion
- These rates of time effect on the planets motions distances
- The period 15.56 days enables Saturn to move 13.1 mkm = (2π) x Mars Motion
Distance per a solar day (2.082 mkm).
- By that we explain clearly how these planets data be created.
- The result is important because, it tells we can explain all planets motions data
origin.
- Now
- We explained why Saturn orbital distance = (2π) Mars orbital distance
- Let’s try with another data
- Why Mars Velocity =(2.5) Saturn Velocity?
- Let's analyze the data no (4 and 5) to explain this one
(5)
- Pluto orbital circumference 37100 mkm= Uranus orbital circumference 18048
mkm x 2.06 = Saturn orbital circumference 9007 mkm x 4.1
- Pluto is a common point between the 2 planets (Saturn and Uranus), and the rates
are (4.1 and 2.06), but we know that, Mercury motion distance per a solar day
=4.095 mkm and Mars motion distance per a solar day =2.08 mkm (error 1%)
- The rates can be used as these planets velocities…

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- That tells Mercury Velocity = 2 x Mars velocity (approximately), because Uranus
orbital distance = 2 x Saturn orbital distance – that connects the solar system and
makes it as one machine.
- But
- Even if we accept that, the velocities are Mars and Mercury, where we search for
Mars and Saturn velocities rate,
- BUT
- Mercury velocity 47.4 km/s x 2 = (Saturn velocity 9.7 km/s)2
- That makes Saturn velocity as a function in Mercury velocity, the point is we have
seen this type of equation before let's remember it
- 3.1 deg (Jupiter Axial Tilt) x 2 = (2.5 deg = Saturn orbital inclination)2
- I want to say,
- It's a geometrical method used by Saturn with Jupiter and with Mercury
- Please Notice
- By discovery of the planets motions rates of time we enable to explain the rate
(2π) between Saturn and Mars orbital distances. And now we have a trustee
method to explain this rate (2π).
- But, there are many other geometrical methods needed to be discovered to explain
the other data because of that the form (Data)2
is a form we need to discover its
geometrical mechanism. But the data isn't created by pure coincidence of numbers
on the contrary base on a geometrical mechanism need to be discovered.
- Notice
- The planet motion has its own effect on its data for example (26.7 =2.5 x10.7)
(where 10.7 h = Saturn day period, 2.5 deg = Saturn orbital inclination, 26.7 deg =
Saturn Axial Tilt) There's a geometrical machine behind this data but we still need
to analyze Saturn motion data in more deep analysis.
- Also 687 days (Mars Orbital Period) + 2 x 3.1 = 2 x 346.6 days (the nodal year)
(where 3.1 deg = Jupiter Axial Tilt)

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9-8 Why Saturn And The Moon Use Equal Rates Of Time?
I-Data
(1)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
(Earth orbital distance) by using its daily displacement 88000 km
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 1710.457 days = 251 hours)
(2)
90560 seconds = 25.1 hours
(3)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
(4)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm)
(5)
317050 days = 37100 days x 8.5
(6)
31705 solar days = 109.4 solar days x 133 x 2.18

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II-Discussion
Equation No. (1)
- The moon needs accurately 1700 solar days to pass a distance = 149.6 mkm =
Earth orbital distance
And
- Saturn needs accurately 1710.457 solar days to pass a distance = 1433.5 mkm =
Saturn orbital distance
- The difference between the 2 periods (1700 days and 171.457 days = 251 hours)
- The planets rates of time depends on the required periods to move their orbital
distances, and Saturn required period is 1710.457 solar days but the moon required
period is 1700 solar days – That causes their rates of time to be almost equal, for
example 1 hour of Earth motion be = 29.4 hours of the moon motion = 29.3 hours
of Saturn motion. almost they are equal
- We have to ask why?
- Let's summarize the idea in following:
(I)
- Uranus Orbital Distance =19.2 Earth Orbital Distance,
- This data means, if Uranus and Earth velocities are equal, During Uranus revolves
around the sun one revolution, Earth revolves around the sun 19 revolutions (19
years)
- And
- The Earth moon moves a cycle called Metonic Cycle continues for 19 years. we
know that Earth Cycle is 4 years (365 +365 +365 +366 days =1461 days) for that
we have asked frequently, why the moon moves Metonic Cycle?
- A suggested answer tell
- The Moon Moves Metonic Cycle By An Effect Of Uranus Motion
- And

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- We know that the moon and Saturn be created after Mars and Pluto migration,
(II)
- The idea is that, Uranus Motion effects on Saturn and the moon and by this effect,
Uranus caused the 2 planets periods to be (1700 days and 1710.5 days) (the
difference between them be 251 hours).
- Why? because
- Mars moves during 25.1 hours a desistance = 2.18 mkm
- This we have seen in the equation no. (6)
Equation No. (6)
- Where
- Mars needs 109.4 days to pass a distance =227.9 mkm = Mars orbital distance
- 1 Mars motion solar day =133 solar days Pluto motion
- This equation we have discussed before,
- but for revision
- This equation needs the distance 2.18 mkm to define the periods 31705 days which
is the total required periods of the solar planets. Mars moves 2.18 mkm in a period
25.1 hours and the difference between the 2 planets (251 hours) be found to
support Mars motion.
- The number 251 hours is so effective because
- (1)
- If 1 hour = 1 month based on that 251 hours will be =251 months but Metonic
Cycle is (254 months) (error 1%)
- (2)
- 25.1 hours = 90560 seconds where Pluto orbital period =90560 days
- (3)
- 251 hours = 25.1 hours x 10 but

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- 10747 days (Saturn Orbital Period) x 24 h x 10 = 10.7 h x 2 x 120536
- (where 10.7 h = Saturn day period and 120536 km = Saturn diameter)
- I try to show that, the data is integrated in harmony with one another, we don't
know the geometrical mechanism but the data shows interesting integration ability
- Shortly
- Uranus caused the 2 planets periods to be rated with the difference 251 hours
(error 0.5%) and by that Uranus effect on the planets motions caused their required
periods to be equal approximately
Equation No. (3)
4.095 mkm (Mercury velocity per solar day) x 1433.5 days = 5848 mkm
0.838 mkm (Saturn velocity per solar day) x 6939.75 days = 5848 mkm
1.16 mkm/sec x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
- The idea tells, Uranus effect on the 2 planets be done through Metonic Cycle,
Equation no. (3) gives one proof for this claim, because
- Saturn (0.838 mkm per a solar day) moves a distance =5848 mkm during (6939.75
solar days = Metonic Cycle)
- The distance 5848 mkm = (Mercury Pluto Distance) is the basic Distance in the
solar system design and based on it many important data be created.
- The point is that, Mercury moves the distance 5848 mkm by using a period
=1433.5 days where 1433.5 mkm = Saturn Orbital Distance
- And Saturn moves equal distance (848 mkm) during Metonic Cycle, and Saturn
moves during (5848 days) a distance =4900 mkm= Jupiter orbital circumference,
that shows Saturn motion harmony in data.
- The data shows a deep connection between Mercury and Saturn motions.

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Equation No. (5)
317050 days = 37100 days x 8.5 (where 3710 mkm =Pluto orbital circumference)
But
Equation no. (6)
31705 solar days = The planets required periods total
Equation no. (6) be discussed before
Equation No. (4)
(4900 days /1710 days) = (153.3 hours / 53.9 hours) = (1.16 mkm /0.406 mkm) =
(30589 days/10747 days) - Where
- 4900 Days Uranus Needs To Move Its Orbital Distance
- 1710.5 Days Saturn Needs To Move Its Orbital Distance
- 53.9 hours = the outer planets days periods total
- 0.406 mkm = Pluto velocity Per A Solar Day.
- This equation tries to prove that Pluto day period (153.3 h) effects on the 4 outer
planets days total (53.9 hours).
- Notice
- The sun is the last created piece in the solar system and is created after all planets
creations and motions

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9-9 Why Mercury Use A Double Of Its Orbital Distance?
- In our discussion we have seen that, Mercury used its double values usually
- Because of that,
- Mercury required period is 27.9 solar days and Mercury moves during this period a
distance = 2 x 57.2 mkm (Mercury Orbital Distance)
- Mercury uses its day period (175.94 solar days) and not its orbital period (88 solar
days)
- Also Mercury uses the distance 720.7 mkm in place of its orbital circumference
360 mkm
- Shortly
- Mercury uses double of its data values
- Why?
- If we use Mercury values as all other planets, means if we use (88 days, 360 mkm
and 14.4 solar days as required period), no change will be done for the rates of
time system, the system will work normally
- But
- Mercury motion depends on the distance 720.7 mkm
- Mercury moves during its day period 720.7 mkm and
- 720.7 mkm =Mercury Jupiter Distance
- These facts make this distance 720.7 mkm is the basic distance in Mercury motion.
Mercury all other data be created based on thi0s distance 720.7 mkm
- Why?
- A deep interaction is found between Mercury and Jupiter based on this distance
720.7 mkm –
- In more clear words –
- The distances network (and system) between Jupiter and the inner planets depends
on this distance 720.7 mkm.

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9-10 The Rate (4.61) be used between Pluto and the moon motion
- The rate (4.61) is the main rate between the moon and Pluto motion
- To show this fact as clear as possible 3 groups of Data we have to see
- Let's provide the first group in following
- I- Data
Group No (I)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- Pluto and the moon motion distances be equal but they are different from Earth
motion distance with (1%).
Group No (II)
(1)
406000 km (Pluto motion distance during a solar day) = 4.61 x 88000 km
(88000 km = the moon daily displacement)
(2)
708.7 h (The moon day period) = 4.61 x 153.3 h (Pluto Day Period)
(3)
Tan (12.2) x 708.7 hours = 153.3 hours
(4)
Tan (13.17) x 655.7 hours = 153.3 hours
(5)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- Notice
- 13.177 degrees = the moon daily motion degrees
For revision
(708.7 h /10.7 h) = (655.7 h /9.9h) = 66.23 = (132.47/2)

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II- Discussion
Equation no. (2)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- 708.7 hours = The Moon Day Period
Equation no. (3)
Tan (12.2) x 708.7 hours = 153.3 hours – where
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- The Equation shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).
Equation no. (4)
Tan (13.17) x 655.7 hours = 153.3 hours where
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- The Equation shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.

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- More Data
Group No (III)
Where
629 mkm = Jupiter Earth Distance 654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance 1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance 671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference
(Max error 1%)
Notice
The previous distances are (22 distances) where all distances in the solar system are
(45 distances) –means these distances be around 50% of all distances in the solar
system and be controlled by this rate (4.61)

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II- Discussion (Continued)
- Let's summarize this discussion
(I)
- How the rate 4.61be found?
- Pluto orbital distance 5906 mkm = Earth orbital distance 5906 mkm x 39.4
- But
- 1 solar day of the moon motion be =8.51 days of Pluto motion
- 39.4 = 8.51 x 4.61
- That means, the rate (4.61) is the complementary one with the rate of time
(II)
- Why this rate (4.61) controls more than 50% of the solar system distances?
- Because of the equation importance we brought it for revision here
For revision
(708.7 h /10.7 h) = (655.7 h /9.9h) = 66.23 = (132.47/2)
- Where
- 708.7h = the moon day period
- 655.7h = the moon rotation period
- The equation is so accurate,
- The rate 66.2 = 132.4/2
- 1 solar day of Mars motion =133 solar days of Pluto motion
- But
- The outer planets required periods total =133 The inner planets required periods
total, as we have seen before
- That makes the rate (133) is a basic one and by that the rate (4.61) is a basic one
also.

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10- Mars Migration Theory
10-1 Mars Migration Theory
10-2 Pluto Migration Theory
10-3 Planets Migration Theories Proves
10-4 Is There An Absent Planet In The Solar Group?

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10-1 Mars Migration Theory
- Mars was the next planet after Mercury with original orbital distance =84 mkm
and Mars had migrated into Mars current orbital distance (227.9 mkm)
- Through Mars Displacement from (84 mkm) to (227.9 mkm), Mars had collided
with Venus (at first) and then with Earth (at second) and then reach to its current
orbital distance point (227.9 mkm).
- Mars had moved from (84 mkm) to (227.9 mkm) in a direct displacement – and
had pushed with it all collisions debris in its direction
- From these collisions debris the Earth could create its own moon and also Mars
moons are created from them and the rest debris be attracted by Jupiter Gravity
and Created The Asteroid Belt.
- Means,
- Mars Migration Theory is in full harmony with (Giant- Impact Hypothesis), but
- Mars itself had collided with Earth and caused the moon creation and not the
ancient planet (theia) as supposed by the Giant-impact hypothesis.
- The point is that, the planets order (Mercury – Venus –Earth) shows that Mars was
the second planet after Mercury – and Mars had migrated from (84 mkm) to (227.9
mkm) –through this displacement – Mars has collided with Venus and Earth–
- Mars collisions with Earth and Venus left many proves behind which prove that
Mars did these collisions and not the planet (theia).
- Mars Migration theory answers many of the Giant-impact hypothesis questions.
- Let's do that in following
(1st
Question)
- Why has Venus no a moon? spite it suffered from a similar collision as Earth?
- Mars had moved its displacement from (84 mkm) to (227.9 mkm), and through
this displacement Mars pushed all debris with it in its motion direction and
because of that, Venus had found no debris around, And couldn't create its own
moon because of that.

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- But the debris lost some of their motion momentum at Earth position and Earth
gravity is more strong than Venus, by that Earth could attract some debris by
which Earth created its moon.
(2nd
Question)
- What's The Lunar Magma Ocean (LMO) Origin?– It's Venus
- Because
- The Earth moon rocks are created from the 3 planets debris (Mars- Venus – Earth)
and for that the moon has a Magma Ocean (LMO).
(3rd
Question)
- Why The Iron Oxide (Feo) of the Moon= (13%)?
- Because The rate (13%) is a middle rate between Mars rate (18%) and the
terrestrial mantle (8%).
Notice no.(1)
- Mars Moons Creation is a good proof for Mars Migration Theory.
- The collisions debris lost the great part of their momentum when reach to Mars
orbital distance point (227.9 mkm), because of that, Mars with its small mass could
attracted 2 moons, because the debris is too much around it and can attract them
easily.
- But Venus great gravity couldn't create even one moon because no debris be found
around it
Notice no.(2)
- The asteroid belt is one more proof for Mars Migration
- The collisions debris which were pushed with Mars motion to its current orbital
distance point (227.9 mkm) couldn't all be attracted by Mars gravity because of its
small mass, Mars had attracted only its 2 small moons
- But
- Jupiter great gravity attracted the rest debris and they created the asteroid belt.
- The whole trajectory is filled with references of the event and shows that it's a fact.

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Notice no.(3)
- Mars diameter before Migration was 7070 km and be 6792 mkm after migration as
a result for the collisions Venus and Earth
- We know that because
- The equation (7070 km x 1092
= 84 mkm), where 84 mkm=Mars original orbital
distance.
- The equation (d = r x 1092
) is the equation controls planet orbital distance based on
its diameter. The equation be used by Mercury, Earth and Saturn but the planets
migration effects negatively on the other planets using of it.
- From this analysis we conclude, Mars Diameter be decreased with 4.1%
- Additional Data
- Mercury Orbital Distance 57.9 mkm = Mercury Diameter 4879 km x 1092
- Earth orbital distance 149.6 mkm = Earth diameter 12756 km x 1092
- Saturn orbital distance 1433.5 mkm =Saturn diameter 120536 km x 1092
Notice no.(4)
- If Mars Mass be decreased as a result for the collisions with 8%, in this case
- Mercury mass (0.33) and its orbital distance (57.9 mkm) be in proportionality with
Mars mass (0.688) and Mars original orbital distance (84 mkm) based on Newton
gravitation Equation – this same proportionality be working also with the current
data of Jupiter and Saturn.

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10-2 Pluto Migration Theory
- Pluto Was The Mercury Moon
- One great force stroke Mercury, Pluto and Mars, with order
- Means,
- Mercury had received the most strong stroke directly, Mercury couldn't escape
from its fate. But Mercury axial tilt was (One Degree) and after the stroke be (0.01
Degree or even Zero)!
- The third stroke be received by Mars by which Mars had Migrated
- The second stroke be received by Pluto, which caused Pluto to be flying along the
solar system and reach to the end point of the solar system.
- The solar system end point with distance (5906 mkm) is a defined geometrically.
- Before Pluto migration –
- Neptune orbital distance was 5906 mkm
- Means,
- Neptune was in the position in which Pluto now be found. The distance 5906 mkm
was Neptune original orbital distance
- Pluto had flying along the solar system distance and reach to Neptune position, and
had collided with Neptune, pushed it out of its orbit and then put it out of (Pluto
Influence area) – That's why Pluto Neptune Distance = Pluto eccentricity Distance
Result No. 1
Mercury Pluto Distance = 5848 mkm = 101 x Mercury orbital distance 57.9 mkm
- This data is so important because the solar system distances be designed in
proportionality with it. based on that the rate (101) is one geometrical pillar in the
solar system design.
Result No. 2
Neptune Be Out Of The Network
- We will study that, the solar system distances be created in a network form in point
no. (10), with many proves we discuss this point…
- But

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- How the distances be created in a network form? We should answer this question
in details in that point no.(10) – but let's summarize the idea in following:
- Matter is created out of light and the planets be created of one light beam- light
motion creates the distances through which the planets move – by that –
- The Solar System Distances Be Similar To Railways
- And, the planets be similar to trains
- That shows why the planets motions be obligatory motions that because light
provides the required energy for distances creation and forces the planets to move
through these distances by this energy.
- Now, we have very (unclear) event – because –
- Pluto had pushed Neptune and put it Out Of The Railways
- That means, Neptune has no orbit and no definition of motion – and because of
that Neptune needed energy to build its orbit!
- Frankly
- I don't understand correctly the meaning of the network or how Neptune be out of
the network- because no space (I know) out of the network and I can't define any
point out of the network
- But
- This idea I have built on 2 data which are
- (1) Neptune Pluto Distance = Pluto Eccentricity Distance =1411 mkm
- (2) Neptune has seized 14% of Jupiter energy to create its orbital circumference
28255 mkm and this lost energy is registered clearly in the solar planets distances.
- These 2 data pushed us to conclude that, Neptune had no orbit and had to create
one for which Neptune seized the energy, Now this result must be done by the
collision between Neptune and Pluto.
Result No. 3
- Pluto and Neptune collisions caused to create Pluto moons and the Kuiper belt.

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10-3 Planets Migration Theories Proves
(Point No. 1) (Mars Migration Proves)
Mars Migration proves depends on the interaction of motion between Mercury and
Mars supposing that Mars was Mercury neighbor.
I- Data
(a)
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
(b)
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
(c)
7 degrees = 5.1 degrees + 1.9 degrees
II- Discussion
Equation No. (a)
(Mars Mass / Mercury Mass) = (6792 km/4879 km)2
= 0.524
- Where
- 6792 km = Mars diameter
- 4879 km = Mercury diameter
- Equation no. (a) tells that, Mercury And Mars Masses And Diameters Are Rated
With Each Other.
Notice
- Mars motion daily =0.524 degrees
Equation No. (b)
(687 days /175.94 days) = (227.9 mkm /57.9 mkm)
- Where
- 227.9 mkm = Mars Current orbital distance
- 57.9 mkm = Mercury Current orbital distance

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- More data is rated between Mars and Mercury
- We should notice that, the data proportionality is done mostly between the
neighbor planets… for example
- Mars orbital period (687 days) = the moon orbital period (27.3 days) x 25.2
- Where 25.2 deg = Mars Axial Tilt. Also
- 25.2 deg = 1.9 deg x 13.17 deg
- Where, 13.17 deg = The Moon Daily Degrees
- And 1.9 deg = Mars orbital inclination
Equation No. (c)
7 degrees = 5.1 degrees + 1.9 degrees
- Where
- 7 deg = Mercury orbital inclination
- 5.1 deg = The moon orbital inclination
- 1.9 deg = Mars orbital inclination
- Mercury motion data shows a strong proportionality with Mars motion data which
gives reference that Mars once was a neighbor to Mercury.

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(Point No. 2) (Pluto Migration Proves)
Pluto Migration proves depends on the fact that Pluto was the Mercury moon and by
that Pluto be longed to the inner planets.
I- Data
(d)
Pluto is a planet belonged to the inner planet (small mass and long day period)
(e)
The rate (101) controls the solar system basic data
(Mercury Pluto Distance/ Mercury orbital distance) = 101
II- Discussion
- In Part no.(II) there are many other proves supports Pluto Migration Theory and
proves that Pluto be belonged to Mercury in its original case
- Notice
- 17.4 deg = 7 deg (Mercury orbital inclination) x 2.5 deg (Saturn orbital inclination)
- 17.4 deg = 5.1 deg (the moon orbital inclination) x 3.4 deg (Venus orbital
inclination)
- 17.2 deg = Pluto orbital inclination (error 1%)
- Notice
- Pluto Migration explains why bode law couldn’t predict Neptune Orbital Distance
– Because Neptune orbital distance be created as additional trajectory in the solar
system distances network – means- the equations be built on the original design
couldn't predict Neptune orbital distance because this distance be defined after The
Planets Migration.

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10-4 Is There An Absent Planet In The Solar Group?
- The planets motions data analysis tells that, one more planet should be absent from
the solar group
- This planet orbital distance was almost 71 mkm and its diameter was 6020 km =
Venus radius (0.5%)
- And its orbital period almost be 121 days and velocity 3.7 mkm per solar day –
these period and velocity values be calculated as a average based on the planets
required periods of time to pass distance = theory orbital distances
- There are 3 proves for this planet existence in the history which are
- (1) Mars and Pluto migration because the collision between Mars and this planet
caused reactions of these planets and by that the force pushed the 2 planets (mars
and Pluto)to migrate from their original orbital distances.
- (2) Mercury axial tilt was 1 degree and after this planet destruction be 0.01 deg,
that tells some change is found in Mercury motion forever.
- (3) many data of this planet be similar to Venus data which may show that Venus
may be created after this planet creation.
MORE DETAILS
- This planet was between Mercury and Mars ancient point (84 mkm) (in this
distance Mars require period to pass its orbital distance may be =24.6 days)
- Mars almost had collided with this planet and caused to destroy this planet.
- This is the catastrophe be occurred for the solar group before Mars migration,
- The reaction force of this collision had pushed Mars to migrate from its original
orbital distance (84 mkm) to its current one (227.9 mkm)
- The collision be done almost because of Mars eccentricity, but
- Mars couldn't destroy that planet if the collision depended on the eccentricity only,
Mars had depended on one more force which caused the collision to be so strong
and the other planet be destroyed in it.
- This force be found by an effect of Neptune.

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- Neptune was the planet behind Jupiter directly and occupied (2872.5 mkm) and
Uranus occupied in that time the point 5906 mkm which is the last point in the
solar system
- Neptune was very near to Jupiter- But Neptune effect in this collision still need to
be analyzed.
- The point is that, Mercury moves during 6 days a distance =24.6 mkm
- Mercury orbital inclination be 7 degree but Mercury axial tilt was 1 degree and by
that (7 degree – 1 degree) = 6 degrees = 6 days
- After Mars migration Mercury axial tilt be = 0.01 deg or even Zero.
- That means, the distance 24.6 mkm from which the period 24.6 days or 24.6 hours
(Mars rotation period) be created.
- I want to say,
- This period (24.6 hours) is produced based on the situation before migration. That
tells why this period is so important in the solar system motion data as we have
seen – because the new changes be built on the ancient geometrical design and
Mercury created this period 24.6 days or hours to be the connection point between
the repair process for the solar group and the ancient geometrical design.
- Notice
- The previous description tells that, the solar planets order was done similar to the
interference of young experiment of light coherence (double slits experiment)
- The planets were perfectly arranged as the fringes,
- Jupiter was the greatest fringe and found in the middle, and then
- The planets on its left be ordered as following (Earth – Venus – Mars – Mercury),
and we know that Pluto was the mercury moon, by that the planets order moves
gradually from the greater to the smaller perfectly as the interference fringes
- And the planets on Jupiter right side be in Order Neptune and Uranus
- Where Saturn wasn't created yet and Neptune was more near to Jupiter that Uranus
which occupied the point 5906 mkm

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- That tries to tell, the matter is a form of light coherence
- The Absent Planet Data
- Planet Orbital Distance = 71.5 mkm
- Planet diameter = 6020 km
- Planet Orbital Circumference = 449.4 mkm =2 x 224.7 mkm
- (7510 km /6020 km) = (6020 km /4879 km)
- Velocity =3.7 mkm per a solar day
- Orbital period = 121 solar days

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11-The Solar System Distances Be Created In A Network Form
11-1 Preface
11-2 The Continuum effect Through the Solar System Distances
11-3 The Solar System Distances Distribution
11-4 The Solar System Distances Dependency On One Another

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11-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- Means,
- The solar system distances are considered as one geometrical design or one
geometrical system. There's no one distance defined as independent distance or
created out of this one geometrical design.
- Let's suppose, this geometrical design be a square. So all dimensions in this
square be defined geometrically based on this square angles and data. means no
one dimension can be created independently from this square data because all of
them are parts in the same one geometrical design.
- Suppose we have a triangle its 2 angles are (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- Similar to that,
- The Solar System Distances Be Created Based On One Geometrical Design.
- But
- By using this vision we will have surprises. Because this vision tells (for example)
Venus Jupiter Distance be= 671 mkm Because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and Earth is another planet and they move
independently from one another. We are astonished now with this fact that, their
distances to Jupiter be defined based on one another! How? And Why?
- How (Because The Solar System Distances Be Created In A Network Form)
- Why (this answer was discussed in Mercury Motion Analysis)
- The fact is proved strongly that
- The Solar System Distances Be Created in A Network

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- There Are Many Basic Proves For This Fact which are:
- (1) The Continuum effect Through the Solar System Distances
- (2) The Solar System Distances Distribution
- (3) The Solar System Distances Dependency On One Another
- Let's discuss these proves in their details in following
- Notice
- The idea tells that,
- By energy the distances be created in a network form
- means
- The Distances Be Similar To The Railways And The Planets Be Similar To The
Trains Move On The Railways.
- The important point is that, the distance be created by energy and because of that
it's a defined trajectory of motion. that makes the planet moves in some obligatory
motion because the energy created the distances.
- Means, the distances aren’t common space but defined distances be built for
specific reason. Based on that (Distance = Energy)
- And
- The created distance defined a trajectory of motion
- As a result
- The solar system distances be as a map created by energy

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11-2 The Continuum effect Through the Solar System Distances
Point No. (I)
The Continuum Effect Description
I- Data
(1)
50% of all distances in the solar system be equal one another
(2)
40% of all distances in the solar system be rated one another
Let's provide this data in details in following:
Data Group No. (A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
(These Equal Distances Be Around 50% Of All Distances In The Solar System)

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Data Group No. (B)
Why These Distances Are NOT Equal?
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(These Rated Distances Be Around 40% Of All Distances In The Solar System)
Additional Data
(10)
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II- Discussion
- Let's suppose that,
- The solar planet moves independently from all other planets motions depending on
the sun mass gravity, in this case how these equal distances (50%) and the rated
distances (40%) be created?
- No logic can imagine a different reason for each 2 equal distances? We conclude
logically that (One Reason Caused These Distances To Be Equal)
- Based on that, we don't deal with independent distances instead we deal with one
machine be created by all distances integration. and As A Result, ONE REASON
effects on (the machine) caused (all distances to be effected by this one reason)
- I want to say,
- These 2 groups of data disproves Planet Motion Independency Concept.
- There's no way to create the equal and rated distances in huge percentage if the
planets motions be independent from one another.
- But
- Why These Distances Are Equal?
- The answer is somehow complex….. let's provide a short answer in following:
- The solar planets don't move by the sun mass gravity. But they move by equal
distances method (or at least the outer planets move by this method)
- The equal distances method is a method be used by many planets. Let's explain
how this method be used…. 2 Planets move equal distances in defined periods of
time (as example, Earth moves during its day period a distance =2.574mkm and
Pluto moves during its day period a distance = 2.598 mkm, these 2 distances are
different with 1% only and by that they can be considered equal distances. As a
result for these 2 motions equal distances Earth and Pluto motions data be in
proportionality with one another)

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- This feature be used hundreds of time by the solar planets, I guessed that, because
this method is used hundreds or even thousands of times in the solar system, this
method causes the planets motions (but I don't know how yet). The idea is that,
this method (the equal distances) works by a geometrical rule, as a waterwheel or a
lever, these methods work by geometrical rules. Similar to that the equal distances
method caused the planets motions
- As a result for using the equal distances method, 50% of all distances in the solar
system be created equal one another and also 40% of all distances be rated with
one another by the same one rate (1.0725)
- But , Please note
- The 50% equal distances be created because the solar system uses the equal
distances method as I have explained it before.
- But
- Why Does The Rate (1.0725) effect On 40% Of All Distances?
- The rate (1.0725) effect on (40% distances) is a proof for a continuous effect
through the distances. There's Some Effect Like A Continuum effects on the
solar system distances!
- How that can be done if the planets move independently from one another? and
- If the distances be created independently from one another how one effect can be
continuous through (40%) of all distances?
- I try to prove, the distances are created in a network or by one geometrical design.
- means,
- the distances be created together in one geometrical system as one machine
because of that one effect can continue through (40%) of all distances
- the explanation of using this rate (1.0725) isn't our question…. Our basic notice is
that this effect has a continuous task through the solar system distances which
can't be done except if these distances be created based on one geometrical system
or in one Network

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- I wish the argument is powerful and proved strongly
- The data gives us a chance to show that, the planet motion can't be independent
from other planets motions. we here don't deal with independent data but with one
system of data.
- Notice
- The Continuum Effect Through The Solar System Is A Powerful Proof For The
Planets Creation And Motion Depend On A Light Beam
- Because
- The Continuous Motion And Effect Is A Feature Of Light Motion – and by
that – the solar planets can't be described as separated rigid bodies.
- Based on that,
- The solar system distances as a network should be used as a proof for the solar
planets creation out of light.

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11-3 The Solar System Distances Distribution
(1st
Point) The Idea Explanation
- There are 2 basic features we should discuss about the solar planet motion, thee 2
features are:
- (1) The Planets Motions Use Different Rates Of Time
- (2) The Planets Motions Use The Distances As Periods Of Time
- These 2 features we have discussed before in this paper discussion
- I need here just to explain how these features be used to test their effects on the
distances distribution
- There are different rates of time be used by the solar planets example:
- 1 hour of Mercury motion = 24.6 hours of Jupiter Motion
- And
- We have seen the rate (4.61) be the working rate between Pluto and the Earth
moon motions.
- Because the distances be used as periods of time and vice versa, the causes the rate
of time to be used as rates among the distances – as we have seen that the rate
(4.61) controls 50% of all distances in the solar system.
- Let's remember this rate in following
- 1 hour of Pluto motion =8.5 hours of the moon motion
- 8.5 =2 x 4.25 but (4.61 = 1.0725 x 4.25) (error 1%)
- By that the rate (4.61) be produced based on the rate of time (8.5) between Pluto
and the moon motion. and for geometrical reason this rate is the working one – for
that,
- Pluto move during a solar day 406000 km = 4.61 x (88000 km)
- (The moon displacement per a solar day =88000 km),
- and
- 708.7 hours (The Moon Day Period) = 4.61 x 153.3 hours (Pluto Day Period)

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- Now this rate (4.61) we see in Pluto and the moon motion data, but because it
works as a rate of time, it effects great on the distances distribution, let's remember
its data in following…
(2nd
Point) The Rate (4.61) Effect On The Distances Distribution
I- Data
Where
629 mkm = Jupiter Earth Distance
654.9 mkm = Jupiter Saturn Distance
550.7 mkm = Jupiter Mars Distance
1284 mkm = Earth Saturn Distance
149.6 mkm = Earth Orbital Distance
671 mkm = Jupiter Venus Distance
940 mkm = Earth Orbital Circumference (Max error 1%)

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II- Discussion
- The solar system orbital and internal distances total be (45 distances)
- The previous data shows that (22 distances) are rated with the rate (4.61)
- Means
- 50% of all distances in the solar system be rated with one another based on this
same rate (4.61).
- The data proves the distances distribution depends on the planets motions rates
time.
- The data proves, The Solar System Distances Be Created As A Network.

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(3rd
Point) The Distances Distribution Proof.
I - Data
Equation no. (A)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- Where
- 100733 mkm = The 9 Planets Orbital Circumferences Total
- This equation is the paper main equation and we have discussed it deeply before
(Equation no. 11-2-d)
- The equation shows that, the solar system distances be distributed based on
geometrical design.

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11-4 The Solar System Distances Dependency On One Another
I-Data
(1)
1.16 x 580 mkm = 671 mkm (Venus Jupiter Distance)
1.16 x 671 mkm = 778.6 mkm (Jupiter Orbital Distance)
1.16 x 629 mkm = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 x 542 mkm = 629 mkm (Earth Jupiter Distance)
1.16 x 5127 mkm = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 x 778.6 mkm x 2 = 1806 mkm
1.16 x 1806 mkm = 2094 mkm (Jupiter Uranus Distance)
1.16 x 2094 mkm = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
(1.16)2
x 170 mkm = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
Where 170 mkm = Mercury mars Distance
(5)
1.16 x 1980 mkm = 2296.8 mkm
1.16 x 2296.8 mkm = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 x 2644.5 mkm = 3033.5 mkm (error 1%) (Uranus Pluto Distance)
We have discussed this data before, let's summarize its idea

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II-Discussion
We have discussed this data before, let's summarize its idea
- The previous distances are example for similar huge number of distances which
depend on the rate (1.16)
- We should analyze this rate (1.16) later
- But
- We need here to see how the distances be distributed base don this rate (1.16)
- The next data can help our analysis greatly
More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2
The analysis shows that the solar system distances can't be created interpedently from
one another but created in a network form. And because of that the distances be
distributed based on a geometrical design and as a result the distances be rated with
the rates (1.16) and (1.0725)

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12- The Continuum Effect Proof
12-1 The Continuum Effect Proof
12-2 Saturn Motion Analysis
12-3 Planet Diameter Analysis
12-4 Why do the planets revolve around the sun if there's no sun gravity?

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12-1 The Continuum Effect Proof
I - Data
(1) (Distances)
2 x 149.6 mkm (Earth orbital distance) = 119.7 mkm (Venus Mars distance) x 2.48
227.9 mkm (Mars orbital distance) =91.7 mkm (Mercury Earth Distance) x 2.48
2 x 680 mkm (Venus orbital Circumference) =550.7 mkm (Jupiter Mars distance) x 2.48
778.6 mkm (Jupiter orbital distance) = 2π x 550.7 mkm (Venus Mercury distance) x 2.48
720.7mkm (Mercury Jupiter distance)= π x 91.7 mkm (Mercury Earth Distance) x 2.48 (1%)
1375 mkm (Mercury Saturn distance) = 550.7 mkm (Venus Mercury distance) x 2.48
1325 mkm (Venus Saturn distance) = π x 170 mkm (Mercury Mars Distance) x 2.48
2815 mkm (Mercury Uranus distance) = π x 360 mkm (Mercury orb. Circumference) x 2.48
2764 mkm (Venus Uranus distance) = 2 x 550.7 (Jupiter Mars distance) x 2.48(1%)
4267 mkm (Mars Neptune distance) = π x 550.7 (Jupiter Mars distance) x 2.48
3030 mkm (Uranus Pluto distance) = 1205 (Mars Saturn distance) x 2.48 (1.4%)
5127 mkm (Jupiter Pluto distance) = π x 655 (Jupiter Saturn distance) x 2.48
5678 mkm (Mars Pluto distance) = π x 720.7 (Mercury Jupiter distance) x 2.48 (1%)
654.9 mkm (Jupiter Saturn distance) = 84 mkm (Mars Original Point) x 2.48 (1%)
Notice
The used distances more than 60% of all distances in the solar system.
(2) Diameters
12104 km (Venus diameter) = 4879 km (Mercury Diameter) x 2.48
2 x 49528 km (Neptune diameter) = 40080 km (Earth Circumference) x 2.48
120536 km (Saturn diameter) = 49528 km (Neptune diameter) x2.48 (2%)
142984 km (Jupiter diameter) = 57655 km x 2.48
(3) Periods
10747 days (Saturn orbital period) =4331 days (Jupiter orbital period) x 2.48
59800 days (Neptune orbital period) = 2 x 12057 x 2.48
(4) Degrees

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17.4 degrees = 7 degrees (Mercury orbital inclination) x 2.48
97.8 degrees (Uranus Axial Tilt) = 39.4 degrees x 2.48
174 degrees (Venus Data) = 28.3 deg Neptune axial tilt x (2.48)2
25.2 degrees (Mars Axial Tilt) = 2 x 5.1 deg (The moon orbital inclination) x 2.48
3.1degrees (Jupiter Axial Tilt) =1.25 degrees (1/Uranus orbital inclination) x 2.48
118.3 deg (=90 +28.3) = 2 x 23.8 deg x 2.48
23.4 deg = 9.42 x 2.48 But 9.42 = 2 x 1.9 deg x 2.48
26.7 (Saturn Axial Tilt) =10.76 x 2.48
Where
17.4 deg = The Inner Planets Orbital Inclinations Total
23.8 deg = The outer Planets Orbital Inclinations Total (23.6 deg) (error 1%)
39.4 = 4π2
1.9 deg = Mars Orbital Inclination.

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II – Discussion
- The Distances Data
- The solar system has 55 distances contains the solar planets orbital distances and
their internal distances. The data provided are 28 distances of this total which
equal more than (50%) of the solar system all distances.
- The data contradicts Newton theory in 2 basic points.
- (1st
Point) The data shows that no planet motion be independent because the
planets orbital and internal distances be created in some network form- we don't
deal here with separated distances, on the contrary- we deal with one network of
distances. The distances be created together based on one geometrical design
regardless the gravitation equation. Clearly Newton is mistaken
- (2nd
Point) The distances be rated with (2.48) where Saturn orbital inclination =2.5
degrees. The data shows that they are created to be in harmony with Saturn
motion. We here don't deal with equal planets in their motions. but we deal with a
geometrical design depends on main points. And this geometrical design depends
on Saturn motion and the data be created in harmony with Saturn motion data.
- I want to say
- We have another vision contradicts Newton theory of the sun mass gravity,
Newton is wrong, but, to prove this fact we have a hard task.
- The first observation is that, The solar system geometrical design is different from
what Newton tells because of 2 reasons, (1st
reason) is, The planet motion
Independency concept refutation and the (2nd
reason) is, the solar system design be
created for Saturn motion.
- Means,
- No planet motion be done independently and the planets motions be done to be in
proportionality with Saturn motion. that means, not only the planets motions be
done depending one another but also this dependency has a direction. It's directed
toward Saturn! why? The other data is found to support this same meaning –

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- The Continuum Effect
- The continuum effect is a clear meaning we can realize that from the data. the rate
(2.48) is used between 50% of all distances in the solar system, that shows the
meaning clearly
- The dependency meaning is understandable but why the rate (2.48) be used along
very many distances? Why not different rates be used? That because the reason
which creates this rate (2.48) continuous through the solar planets motions. the
meaning is something very interesting – it's the continuum – let's use an example
to explain this meaning…..
- In ancient time there was an illness called (Leprosy), it's very interesting illness
because it infects the human, and the cloths and also the buildings!!
- How can that be possible? I don't know,
- But it's one illness and infects different forms of matters…(I think the cancer is
similar because some glass also may suffer of cancer!)
- It's the continuum effect meaning
- The reason which creates the rate (2.48) effects on (50% of all distances in the
solar system) and no force prevents its effect, still this reason has more power to
effect on some planets orbital periods, diameters, axial tilts and orbital inclinations.
- Why do I suppose the matter be created out of light?
- The light creates the matter and space
- Simply this is the fact,
- The light can creates this continuum effect through matter different data. the light
can use the distances as periods of time and vice versa
- I suppose the matter and space are created out of light simply because the matter
motion features can be created only by light motion.
- The Continuum Effect is one real force against Newton theory of the sun mass
gravity – and we can simply say that Newton is mistaken because of The Solar
System Continuum Effect Of Data.

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- I hope to show how this argument is powerful and able to disprove Newton theory
and to do that let's refer to some other data….
- In our study we have seen more rates as (1.0725) and (4.61) and (31)
- The rate (1.0725) be used as a rate between 40% of all distances in the solar
system, a list for these distances be provided in appendix no. (1) of this current
paper
- And also the rate (4.61) be used as a rate between around 50% of all distances of
the solar system, and this rate we discuss deeply in point no. (7-10) with the rate of
time between Pluto and the moon motions.
- I try to show that, the using of rates between huge number of distances (or other
data) is a usual using of data in the solar system – this feature can be created only
if the data be created by a continuum effect- let's to explain the meaning in more
clear words in following
- If the planets motions be independent, no any rate can b used among huge number
of distances as we see – this using of the rates means we deal with planets move
depending on one another – and
- If this dependency is local – means- each planet depends on another planet but
without a series of dependency – the rate (2.48) will not be continuous so long –
but will be so limited in using -
- The rates continuous using tells that we deal with some textile. It's a network
designed basically for a purpose and moves from a point to another point trying to
create one trajectory of energy which we see as a rate be used between huge
number of distances (or other data).
- The Continuum Is A Light Motion Feature. By that, sometimes the continuous
effect has to be cut. In Fact the continuum isn't cut but it's hidden behind some data
not understandable by us. let's use one example
- 142984 km (Jupiter diameter) = 2.48 x 57655 km
- Now what's this value (57655 km)?? it's very near to 57960 seconds (error 0.5%)

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- Where
- 57960 seconds be = 16.1 hours = Neptune Day Period
- If 1 km = 1 second we may find the meaning behind this data!
- But
- What's the fact really? the fact is that
- 4 Jupiter days periods = 39.6 hours = 142560 seconds
- That means,
- Jupiter diameter be =142984 km because it expresses for 4 Jupiter days periods,
- Where (142984 /142560) =(361/360)
- And
- The previous data shows there's a proportionality with Neptune day period – that's
found because Jupiter moves during its day period a distance = 466884 km =
Neptune motion distance during a solar day.
- The difficulty was that to prove the relationship between Jupiter diameter 142984
km and Jupiter 4 days periods (142560 seconds) which is a very far meaning to us
and by that the continuum effect be hidden behind the un-understood data but not
be cut.
- The simple question should be why Jupiter diameter be in proportionality with 4
Jupiter days (specifically)? Why 4 days??
- My basic fight point is to prove The Continuum Effect
- The Discussion Conclusions
- There are 2 basic reasons disproving Newton theory of the sun gravity
- (1st
Reason) The solar planets motions data be transported among the planets
- (2nd
Reason) The solar planets motions data be created in a continuum feature.

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12-2 Saturn Motion Analysis
I- Data
(1)
(27.78/9.7) = (2x 9.7/6.8) = (2x6.8/4.7)= (2 x35/24.6)= (2 x24.6/17.2) = 1.16mkm
/0.406 mkm = (0.3 mkm /104895 km)
(2)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
(3)
1.16 mkm/ 13.1 km = 602208 km /6.8 =416232 km /4.7
(4)
24.1+25.2 = 24.6 + 24.7
(5)
300000 = 27.78 x 10800 = 13.1 x 22901 = 47.4 x 6330 = 9.7 x 30928
(6)
(1163352 /29.8) = (378675 /9.7) = (300000π / 24.1) = (210816/5.4) = (2x
470416/24.1)
(7)
(373644 /9.7) = (2 x 90560/4.7) = (2 x 464166 /24.1)
(8)
2 x 466884 = π x 297228 (1%)

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(9)
119590 x (9.7)2
=24.1 x 466884
(10)
(1.16 mkm /9.7 km) =119590 = 2x 2.48 ((10747 x 24)/10.7)
(11)
(1.16 mkm /35 km) = 33182= (10747 x 9.7)/ π
(12)
(24.6/17.2) = (9.72/6.8) but (9.72/9.7) =(361/360)
(13)
(142984/90560) =(4495.1/2872.5) = π/2
(14)
10747 x 24 h = 24.6 h x 10500
But
10500 x 9.9 h = 4331 days x 24
(15)
9.7 km/s x 2 x 155597 seconds = 8 x 378675 km

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II- Discussion
Equation no. (1)
(27.78/9.7) = (2x 9.7/6.8) = (2x6.8/4.7)= (2 x35/24.6)= (2 x24.6/17.2) = 1.16 mkm
/0.406 mkm = (0.3 mkm /104895 km)
- Where
- 27.78 km /s = The Moon Velocity
- 9.7 km /s = Saturn Velocity
- 6.8 km /s = Uranus Velocity
- 4.7 km /s = Pluto Velocity
- 35 km /s = Venus Velocity
- 24.6 hours = Mars Rotation Period
- 0.3 mkm = light known velocity (0.3 mkm/s)
- 1.16 mkm = Jupiter motion distance during 24.6 hours
(There's a light beam its velocity supposed to be 1.16 mkm/s)
- I have tried to write equation no. (1) to be in the best form but it still doesn't tell
the fact clearly – let's move with its step by step
- (1st
Point)
- We see 4 planets velocities are rated one another which are (the Earth moon,
Saturn, Uranus and Pluto), these 4 planets velocities are rated with one another –
we need to know why?
- But
- The equation doesn't tell the facts clearly – the fact is that:
- During Uranus day period (17.2 h) Saturn moves 600000 km

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- And
- During Mars rotation period (24.6 h) Uranus moves 600000 km
- And
- During 2 x 12430 seconds Mars moves 600000 km
- And
- During 35.5 hours Pluto moves 600000 km
- This fact has many points to notice
- First, the distances are equal
- Second, the distance 600000 km = light motion distance for 2 seconds
- Third, the periods are defined by the 4 planets and no information are needed!
- Based on that, Saturn motion uses Uranus day period and Uranus motion uses
Mars rotation period and Mars motion uses the period 12430 sec (this period is
defined by Saturn motion because during 12430 seconds Saturn moves a distance
= 120536 = Saturn diameter), and Pluto uses (35.5 hours) (And this period = 2
Uranus Days periods with error 3%)
- (Notice Venus needs 35.8 days to pass a distance = Venus orbital distance) (error
1%) ( if 1 hour be = 1 day that makes the 2 periods are equal)
- I want to say
- The 4 planets move equal distances in periods defined by themselves and no data
is needed and the equal distance = light motion distance for 2 second….
- No pure coincidence here be found – we have some very complex geometrical
machine – but how this data be created?
- Because all distances = light motion we can consider the light motion be a basic
player behind – but how?
- The first question we have left as (Why The Velocities Are Rated?)

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- (2nd
Point)
- The second point is the number (2) in the equation
- We see clearly that, this number is used for the moon velocity where the other
planets velocities can be rated simply without this (2) but the moon forces all
planets to use this (2) to create a general harmony for the equation
- The moon has this power because of the rate (1.16 mkm/0.406 mkm), where this
part of equation doesn't use the number (2), because of that, all planets have to use
the number (2) even if the moon velocity be not found
- We need to notice that the rate (1.16 mkm/0.406 mkm) = 2.86 controls many basic
data in the solar system – that makes this rate be so powerful – let's refer to some
of this data in following
- Additional Data
- The solar planets masses total x 2 = Jupiter mass x 2.86 (error 1.8%)
- The solar planets diameters total 406000 km = Jupiter diameter x 2.86 (0.7%)
- Jupiter diameter 142984 km = Neptune diameter 49528 km x 2.86 (1%)
- Mars diameter 6792 km = Pluto diameter 2390 km x 2.86
- 511.1 deg (all planets axial tilts total) = 180 x 2.86
- 278.4 deg (the outer planets axial tilts total) = 97.8 de (Uranus Axial Tilt) x 2.86
- 5.1 deg (the moon orbital inclination) = 1.8 deg (Neptune orbital inclination) x 2.86
-
- Many other basic data can be added to show the significance of this rate (2.86)
- What I'm trying to do is that, to prove the data be created based on a geometrical
system and trying to discover it – in fact – some great machine of geometry be
found behind but because many concepts be unknown we can't catch this machine
clearly as possible

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- (3rd
Point)
- (2 x 24.6 h/17.2 h) = (2.86)
- 24.6 hours =Mars Rotation Period
- 17.2 hours =Uranus Day Period
-
- This part of equation creates a proportionality between Mars rotation period (24.6
h) and Uranus day period (17.2 h),
- Why this proportionality is found? What's the relationship between Uranus and
Mars motions?. The data tells Uranus uses Saturn motion as a mediator to Mars
motion. Why Uranus motion should have a connection with Mars motion? what a
big deal behind?
- During Mars rotation period Jupiter moves 1.16 mkm and
- During Mars rotation period Uranus moves 2 x 300000 km
- Both Motions Are Light Motions Distances?
- Why Mars Rotation Period is important for many planets motions?
- My problem is that,
- I'm afraid to write more data to avoid the confusion but on the other side no
meaning can be concluded from the (short) data – let's look inside Uranus day
period
- 17.2 hours = 61920 seconds
- This powerful period how to understand? 61920 sec = 2 x 30589 s +742 sec
- 742 seconds = 1% of 61920 seconds
- Means
- Uranus orbital period 30589 days should be used in seconds units, then
- 2 x 30589 seconds = Uranus day period 61920 second with error (1%)
- Why?? But
- Light known velocity (0.3 mkm/sec) needs 4950 seconds to pass a distance = 1484
mkm = 2 x 742 mkm

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- If 1 second = 1 mkm that makes the distance 742 mkm be found in relationship
with 742 seconds – light motion be found behind Uranus motion to create Uranus
day period and orbital period in proportionality with one another based on light
motion.,
- Why this concussion is not an imaginary idea?! because
- Uranus needs 4900 solar days to move a distance =2872.5 mkm = Uranus orbital
distance – and we know that – 1 second of light motion = 1 day of planet motion.
- Now, this deep analysis doesn't tell why Uranus day period =17.2 hours, nor tells
why Uranus day period be in proportionality with Mars rotation period 24.6 hours?
- The data be created by unknown geometrical rules and we are watchers in some
Cinema –the nature creates its great tools and we don't understand what's happing
because of our less knowledge.
- Notice
- Uranus moves during 30589 hours a distance = 748.8 mkm wit error 1% with the
distance 742 mkm
- (4th
Point)
- The data forces for some modification let's see in following
- The distance 1200000 km
- Be passed by Mercury in a period =2 x 12658 seconds, and
- Be passed by Venus in a period = 9.52 hours, and
- Be passed by Earth in a period = 40269 seconds, and
- Be passed by The moon in a period = 43200 seconds, and
- Be passed by Mars in a period = 49793 seconds, and
- Be passed by Jupiter in a period = 91603 seconds, and
- Be passed by Saturn in a period = 2 x 61920 seconds, and
- Be passed by Uranus in a period = 2 x 24.6 hours, and
- Be passed by Neptune in a period =2 x 61.7 hours, and
- Be passed by Pluto in a period =71 hours

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- The period 40269 seconds be equal Earth circumference 40080 km (error 0.5%) if
1 km = 1 second– by that the distance be passed by Earth and the Earth
circumference be used as the period of time –
- The period 49793 seconds be equal Neptune diameter (49528 km) (error 0.5%) if 1
km = 1 sec. that shows why we need 1.2 mkm and not 600000 km because if we
use 600000 km mars will use a period =(24896 second) which can be equal
Neptune radius – but for diameter we need 1.2 mkm –
- That's happened with Earth circumference also – we need 1.2 mkm because we
can't divide Earth circumference into parts.
- The period 91603 seconds has an error (1%) with the period 90560 seconds (where
90560 days = Pluto orbital period)
- Here also we need the distance 1.2 mkm because Jupiter can't use part of Pluto
orbital period
- (Notice, we usually uses the periods in days, minutes or seconds. For example
Pluto moves during 90560 seconds a distance = 425632 km = Uranus motion
distance during its day period with error 1%)
- The motions of Saturn and Uranus use the periods in 2 cycles (2 Uranus days 17.2
hours) and (2 Mars rotation periods = 24.6 h), and it's possible to use the cycles in
any number but that the distance 1.2 mkm can create a general harmony of motion
for many planets.
- Notice
- The period Mercury needs to pass 1.2 mkm = 7 hours but
- 24 hours /7 hours =3.4 (can that have a relationship with Venus orbital inclination
3.4 degrees?)
- And
- The period Venus needs to pass 1.2 mkm = 9.52 hours but
- 24 hours /9.52 hours =2.55
- (The moon orbital inclination 5.1 degrees =2 x 2.55)

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Equation no. (2)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
- Where
- 6.8 km/s = Uranus Velocity
- 24.1 km/s = Mars Velocity
- 27.78 km/s = The moon Velocity
- 5.4 km/s = Neptune Velocity
- Simply Equation no. (2) is produced from equation no. (1)
- Equation no. (2) shows that one force effects on the 6 planets and cause their
velocities to be rated with (5.14)
- But, again
- The equation can't tell the facts clearly, Let's try to do that in following
o Uranus moves during its day period (17.2 h) a distance = 421056 km
o Venus moves during 12104 seconds a distance = 423640 km
o Pluto moves during 90560 seconds a distance = 425632 km
o Neptune moves during 155597 seconds a distance =2x 420111 km
o The moon moves during 15328 seconds a distance = 425807 km
o Mars moves during 17660 seconds a distance = 425632 km
o The max error among these distances be 1%
o Where
o 12104 km = Venus Diameter
o 155597km = Neptune Circumference
o 90560 days = Pluto Orbital Period
o 15328 km = Mercury Circumference
o 17660 km x8= 141555 km (Jupiter diameter error 1%)
- Shortly

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- All planets move equal distances to Uranus motion distance during its day period
by using their own data except the moon uses Mercury circumference as a period
of time and Mars uses (1/8) of Jupiter diameter as a period of time
- The point is that the distance 17660 km is the basic distance in Planet 8 Days
Cycle
- The data may tell, that Mars should have a relationship with Planet 8 days cycle
- I want to say
- The simple form of the equation tells nothing about its deep fact – let's try to
deepen this discussion as possible in following
Equation no. (2) (continued)
(35/6.8) = (24.1/4.7) = (27.78/5.4) = 5.14
- This simple form of Equation no. (2) tells noting about the facts because not only
the planets velocities are rated but also the periods of time are rated and the planets
diameters and circumferences be used as periods of time in proportionality to pass
the required distance –
- Again
- We are invited to this happy party, but we get nothing of it! we don't listen any
beautiful song and not watch any interesting film, we don't listen any told joke for
laughing – we are invited visitors but we stand behind the glass wall looking but
understand nothing! Why
- Because we don't know by what geometrical rules this data be created and why.
- Why the planets have to move equal distances? What the big benefit if the planets
do? Why the planets use different sources of data? some planets use their
diameters or circumferences as periods of time others use their orbital periods by
change the units from one day into one second – the whole machine works before
our eyes and the data move from point to another point along the discussion but we
understand and learn nothing because we don't know neither the geometrical rules

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based on which the machine works nor the geometrical design by which the
machine be designed– then simply one question can expose our weak situation –
Let's ask, Why does the planet move if there's no sun gravity? Or what positive
result be produced by the planet motion?
- Notice
- 8 days of Uranus days periods =137.6 hours
- 137.6 hours = 24.6 hours (Mar rotation period) x 5.6
- What's 5.6??
- 0.5 degrees = The moon angular diameter
- 5.6 degrees = the moon orbital inclination be measure above the moon body
- Also
- 137.6 hours = 8.51 x 16.1 hours (Neptune Day Period)
- 1 hour of Saturn motion = 8.51 hours of Pluto motion
- 16.1 hours of Saturn motion = 137.6 hours of Pluto motion
- That means
- 1 Neptune day period (16.1 h) can produce 8 Uranus days period (137.6 h) by
using the rate of time between Saturn an Pluto (8.51) but how? by what
geometrical rule that can be done?

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Equation no. (3)
1.16 mkm/ 13.1 km = 602208 km /6.8 km=416232 km /4.7 km
- Equation no. (3) tells
- Jupiter (13.1 km/s) moves during Mars rotation period (24.6 hours) a distance =
1.16 mkm
- And
- Uranus (6.8 km/s) moves during Mars rotation period (24.6 hours) a distance = 2 x
300000 km
- And
- Pluto (4.7 km/s) moves during Mars rotation period (24.6 hours) a distance =
416232 km
- But
- Sin (12.19 deg) x 416232 km = 88000 km (The moon daily displacement)
- The angle 12.19 degrees = 13.177 deg – 0.98562 deg
- 13.177 deg = The moon motion degrees per a solar day
- 0.9856 deg = The Earth motion degrees per a solar day
- Means, the distance 416232 km is related to the moon daily displacement – We
know that Pluto motion has some effect on The moon daily displacement but why
Mars rotation period is so effective??
- Notice
- 49528 km (Neptune diameter) x π2
=488822 km = 5.4 km/s x 90522 sec.
- But
- (488822 km = 466884 km + 2 x 10921 km the moon circumference)
- Notice
- 27.78 km/s (the moon velocity) x 4331 sec = 120316 km (but 120536km = Saturn
diameter) where 4331 days = Jupiter orbital period

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Equation no. (4)
24.1+25.2 = 24.6 + 24.7 = 49.3
- Where
- 25.2 degrees = Mars Axial Tilt
- 24.7 hours = Mars Day Period
-
- I don't know how this equation can work!
- Just it's accurate equation, the numbers work accurately but the units cause a great
confusion
- It's Mars own data
- The simple conclusion is that, the planet data be created of periods of time –
means- the building unit is a period of time –
- No mass and no distance – the universe building unit is a period of time – that
makes all data be created from the same kitchen – and any data can be replaced in
place of any other data – the exchange be found simply because all components are
periods of time – whatsoever we see – all things are periods of time –
- For better explanation
- Imagine we see some distance, or we have some matter with mass, or we have 3
angles of triangle…etc all these components are (periods of time)
- It's the universe secret
- And
- What's our task now?
- We have to find the player-For Whom All Components Can Be Periods Of
Time? What's the player which can see (every thing) as periods of time?
- A Conclusion (The Universe Building Unit Is A Period Of Time)

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Equation no. (5)
300000 = 27.78 x 10800 = 13.1 x 22901 = 47.4 x 6330
- Where
- 300000 km/s = Light Velocity
- 27.78 km /s = The Moon Velocity
- 13.1 km /s = Saturn Velocity
- 47.4 km = Mercury Velocity
- 10800 sec = (1/8) x 86400 seconds
- 10921 km = The moon circumference (error 1%)
- 142984 km = Jupiter diameter = 22901 km x 2π (error 0.6%)
- 6330 sec = where Earth radius =6378 km (error 0.7%)
- The Equation shows an important observation that,
- The moon and Jupiter diameters be created equal to their rates between light
velocity (0.3 mkm/s) and their velocities (27.78 km/s and 13.1 km/s)
- Mercury motion uses (6330 sec) which be related to (Earth radius) and we have
seen that the moon uses Mercury circumference to pass the distance 425807 km
(=Uranus motion distance during its day period)
- Some deep relationship must be found between the moon and Mercury motions.
- But
- The question still has no answer
- The moon and Jupiter diameters be created as rates between light velocity and
their velocities – can that be a general rule? because no other planet use this same
rule just Mercury and defines another planet radius (Earth) and not its own
- So,
- Can a proportionality be found between planet diameter and its velocity?

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- More Data
- 300000 km = 47.4 km /s (Mercury velocity) x 6330 seconds
- 300000 km = 35 km /s (Venus velocity) x 8571 seconds
- 300000 km = 29.8 km /s (Earth velocity) x 10067 seconds
- 300000 km = 27.78 km /s (The Moon velocity) x 10800 seconds
- 300000 km = 24.1 km /s (Mars velocity) x 12430 seconds
- 300000 km = 13.1 km /s (Jupiter velocity) x 22901 seconds
- 300000 km = 9.7 km /s (Saturn velocity) x 30928 seconds
- 300000 km = 6.8 km /s (Uranus velocity) x 44117 seconds
- 300000 km = 5.4 km /s (Neptune velocity) x 55556 seconds
- 300000 km = 4.7 km /s (Pluto velocity) x 63830 seconds
- Notice
- ( 300000 km /5.4 km) =55556 = π2
(155597 km/27.78) (error 0.5%)
- Where (155597 km = Neptune Circumference)
- This notice tries to show that, Neptune circumference be used also as a rate
between light and Neptune velocities –The difficulty is
- While the moon and Jupiter diameters show direct dependency on the planets
velocities rates with light velocity, we expect this rule to be used for all planets-
this is usual thinking that any acceptable equation or rule should be used for all
planets data – also kepler laws prove this fact- my point of view contradicts this
idea – the point is that – the solar planets aren't similar planets to one another in all
data- because they are integrated with one another – that makes some data be
similar and others be different – for that reason not all equations be used by some
planets should be used by the others – we learn that from the nature – even in the
creatures creation – male and female have similar parts and different parts – the
point is that – the solar system is an integrated machine its parts are integrated with
one another – by that we need different parts to create this integration. Means the
rule is correct but not always be used by direct relationships

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Equation no. (6)
(1163352 /29.8) = (378675 /9.7) = (300000π / 24.1) = (210816/5.4) = (2x 470416/24.1) =
39040 AND (1160000/1163352) = (360/361)
- Where
- 9.7 km/s = Saturn Velocity
- 300000 km/s = light velocity
- Mars moves during 12430 sec (=39040 /π) a distance = 300000 km = light motion
distance during 1 second. based on that, Mars moves during 39040 seconds a
distance = 300000 km x π
- Earth moves during 39040 seconds a distance = 1163352 km
- Saturn moves during 39040 seconds a distance = 378675 km = Saturn
Circumference
- 155597 sec x 9.7 km/s = 4 x 378675 km (error 0.35%)
- Notice
- 155597 km (Neptune Circumference) = 4 x 38899 km
- We use the period (39040 seconds) frequently, so if 1 km = 1 sec, So
- 38899 km be =39040 sec (error 0.4%)
- That means,
- The period (39040 seconds) which we have used frequently is found based on
Neptune Circumference -
- As a result
- 2 x 155597 km (Neptune circumference) = 311193.6 km
- 24.1 km/s (Mars velocity) x 311193.6 seconds = 25 seconds x 0.3 mkm/sec
- (Mars axial tilt =25.2 degrees)

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- Notice
- Neptune moves during Neptune day period (16.1 h) a distance = 2 Neptune
Circumference
- Notice
- (1160000/1163352) = (360/361)
- Light velocity 1.16 mkm/s is rated to earth motion distance 1.163352 mkm by the
rate (361/360)
- Because
- The moon orbit regresses 19 degrees per year and during 19 years the total be 361
degrees, by that all data be configured based on this rate (361/360) showing the
moon orbit effect on the solar system motion data.

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Equation no. (7)
(373644 /9.7) = (2 x 90560/4.7) = (2 x 464166 /24.1)
- Where
- 9.7 km/sec = Saturn velocity
- 4.7 km/sec = Pluto velocity
- 24.1 km/sec = Mars velocity
- 373644km = The distance be passed by Saturn during its day period (10.7 h)
(Saturn day period 10.7 h = 38520 seconds)
- 90560 days =Pluto orbital period – in data it's used as a distance = 90560 km –
- The equation tells that Pluto moves a distance = (2x 90560 km) during the period
38520 seconds = 10.7 hours = (Saturn day period)
- 464166 km = this distance is very near to the distance (466884 km) (error 0.6%)
- The equation tells that, Mars moves during (10.7 hours) (Saturn day period) a
distance = 2 x 466884 km (error 0.6%)
- We know that, Jupiter moves during its day period a distance = 466884 km =
Neptune motion distance during a solar day
- I wish the data analysis does its task and causes to get the respectful readers
attention-because
- It's some very interesting feature that the data be so limited and we discover that
each planet uses the same data which be used by the other planets – even if the
geometrical explanation be still far to be discussed but the data disproves the
independent motions or random creation
- In fact the words can't tell the facts
- It's incredible to find the numbers are so limited and simply the same numbers be
used for all planets motions – where what's used as distances for one planet be
used again as periods for another one – and by that we discover at end Saturn
depends on the period 39040 sec to move a distance = its circumference where this

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period 39040 sec be = (25% of Neptune Circumference and each 1 km be = 1
second!)
- Notice
- During 10.7 hours (38520 seconds) (Saturn Day Period)
o Mercury (47.4 km/s) moves distance = 1825848 km
o Venus (35 km/s) moves distance = 1348200 km
o Earth (29.8 km/s) moves distance = 1147896 km
o The Moon (27.78 km/s) moves distance= 1070086 km
o Mars (24.1 km/s) moves distance = 928332 km = 2 x 464166 km
o Jupiter (13.1 km/s) moves distance = 504612 km
o Saturn (9.7 km/s) moves distance = 373644 km
o Uranus (6.8 km/s) moves distance = 261936 km
o Neptune (5.4 km/s) moves distance = 208008 km
o Pluto (4.7 km/s) moves distance =181044 km =2 x 90522 km
- We notice that,
- Earth moves during (38520 seconds) a distance = 1147896 km but Jupiter moves
during a solar day a distance =1131840 km (error 1.4%)
- Can These 2 Distances Be Equal? if we neglect the error (1.4%) and consider the
2 distances be equal, why they are equal??
- We notice also that
- Uranus moves during (38520 sec) a distance = 261936 km =the distance Mars
moves in 10921 seconds (error 0.5%) (where 10921km = the moon circumference)
- I try to show that
- We don't deal with independent points may some connections connect them by
chance – but we deal with one body- each part is connected with the other parts by
several connections – that means- any planet data analysis will show another
planet data behind it! but why Uranus and Mars here?

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Equation no. (8)
2 x 466884 = π x 297228 (1%)
- Where
- 297228 km = 300000 km (error 1%)
- 466884 km = the distance be passed by Jupiter in its day period (9.9 h) = the
distance be passed by Neptune in solar day
- We have discussed this distance in the previous equation,
- Equation no. (8) tells some very interesting information
- Light motion distance for 1 second 300000 km is a diameter for a circle its
circumference be = 942478 km = 2 x 466884 km
- Now, One more surprise!
- The distance which we have analyzed deeply before, which Jupiter passes it in its
day period (9.9 h) and Neptune passes it in a solar day (24 h), and Mars passes
double this distance in (10.7 h) = (Saturn day period)
- This distance be defined by light motion (Why??)
- The planets motions simply followed light motion
- Again we don't know the used geometrical rule!
- But the planets motions be done depending on light motion – the light motion is
the train engine and the planets are the train carriages
- Why this distance 466884 km be defined based on light motion?
- Can we remember this number 942478 km ??
- We have studied it in the moon orbital triangle where the triangle be consisted of
3 dimensions their measurements were (449197 km +373000 km +120536 km),
the triangle perimeter be = 942478 km!
- Notice
- The data tells that we Will Perform A Great Progress When We Discover The
Definition Of (π) And Its Effect On The Planets Motions.
- The value (π) has a great effect on the planet motion

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- For the moon orbital triangle and its discussion
- Please read my paper.
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
- Notice
- (The Distance 466884 Km)
- 466884 km = 47.4 km /s (Mercury velocity) x 9850 s
- 466884 km = 35 km /s (Venus velocity) x 13339 s = 222.3 m
- 466884 km = 29.8 km /s (Earth velocity) x 15667 s = 261 m
- 466884 km = 27.78 km /s (The Moon velocity) x 16807 s = 4.66 h
- 466884 km = 24.1 km /s (Mars velocity) x 38520/2s
- 466884 km = 13.1 km /s (Jupiter velocity) x 9.9 hours
- 466884 km = 9.7 km /s (Saturn velocity) x 48133 s
- 466884 km = 6.8 km /s (Uranus velocity) x 68660 s
- 466884 km = 5.4 km /s (Neptune velocity) x 86400 s
- 466884 km = 4.7 km /s (Pluto velocity) x 99337 s
- Notice
- 68660 km = 2π x 10921 km (The Moon Circumference)
- 30589 days = 2 x 15295 (where 15328 km = Mercury Circumference)

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Equation no. (9)
119590 x (9.7)2
=24.1 x 466884
- Where
- 120536 km = Saturn diameter
- 466884 km = our distance which is passed by Jupiter in Jupiter day period (9.9
h) and equal the distance be passed by Neptune in a solar day period and equal half
the distance passed by Mars during 10.7 h (Saturn day period)
- How This Equation Be Found?
- We have 2 values 119590 km (which = 120536 km Saturn diameter error 0.8%)
And
- 466884 km = 3 x 155597 km (Neptune Circumference)
- Also
- We have 9.7 km/s = Saturn velocity, where
- Saturn moves during 12430 seconds a distance = 120536 km = Saturn diameter
- 12430 km x π =39040 km
- And
- 39040 km x 4 = 155597 km = Neptune Circumference
- Shortly
- The distance 120536 km (Saturn diameter) be defined by Neptune circumference
- And
- The distance 466884 km = 3 x 155597 km (Neptune Circumference)
- Where
- (Mars velocity / Saturn velocity ) = 2.48
- And
- 1.16 mkm /466884 km = 2.48

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Equation no. (10)
(1.16 mkm /9.7 km) =119590 = 2x 2.48 ((10747 x 24)/10.7)
- Where
- 119560 km = Saturn diameter (120536 km error 0.8%)
- What's the surprise of this equation?
- (10747 days x 24 hours) /10.7 hours = 24105.4
- And
- 2 x 24105.4 = 48211
- But
- 48211 seconds x 9.7 km/s = 467647 km ( = 466884 km error 0.2%)
- We know that
- 1.16 mkm /466884 km =2.48
- These notices show how the Equation no. (10) be built, but more important, the
equation shows that Saturn orbital period (10747 days) and Saturn day period
(10.7 h) be created based on a geometrical rule takes into consideration the
distances 1.16 mkm and 466884 km.
- Time after time we see much better how the planets data be created- there's a
geometrical machine behind this data and they are created toward one direction.
The light motion almost uses the distance (466884 km) by different forms and
that's the reason for which we find this distance frequently in our data and to be
used as a reference behind – there's a geometrical rule for this using and when we
discover it all questions will be answered…

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Equation no. (11)
(1.16 mkm /35 km) = 33182= (10747 x 9.7)/ π
- Where
- The equation tells
- Venus (35 km/s) moves during 33182 seconds a distance = 1.16 mkm
- And
- Saturn (9.7 km/s) moves during 10747 seconds a distance =104246 km
- Where
- 104246 km = π x 33182 km
- Let's summarize this equation in best form
- Venus (35km/s) moves a distance = 1.16 mkm x π in a period = 104121 seconds
- Saturn (9.7 km/s) moves during 10747 seconds a distance = 104121 km
- Notice (104121 seconds = 1375 minutes = 29 hours
- The moon radius =1735 km
- And
- Saturn orbital period (10747 days) = 365.25 days x 29.4 (with 29 error 1.5%)
- By that
- Venus motion data be transported to Saturn motion data based on the Earth moon
data – that may explain – why Saturn and the moon uses equal rates of time –
Venus should be considered the mother of both.
- The equation still has more secrets
- (First) the distance 466884 km Venus passes in a period = (224.7 minutes) (1%)
(where 224.7 days = Venus orbital period)
- And
- (Second) the value 1735 minutes which cause the moon radius to be 1735 km

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Equation no. (12)
(24.6/17.2) = (9.72/6.8) but (9.72/9.7) =(361/360)
- Where
- 24.6 h = Mars Rotation Period
- 17.2 h = Uranus Day Period
- The data rated to the basic gear (361/360) which we have discussed before
- The gear (361/360) is found as a result for the moon orbit regression.
- Why the data be modified based on the rate (361) as a result for the moon orbit
regression? it's very hard question to answer – the simple question we also can't
solve! Let's ask it
- Why Does The Moon Orbit Regresses?
Equation no. (13)
(142984/90560) =(4495.1/2872.5) = π/2
- Where
- 142984 km = Jupiter diameter
- 4495.1 mkm = Neptune Orbital Distance
- 2872.5 mkm = Uranus Orbital Distance
- This equation tries to tell that, the value (π) is an independent player in the solar
system geometry. Here the value (π) isn't related to any planet motion but it's used
for the solar system general geometrical design –it's part of the motion reason of
the solar planets –

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Equation no. (14)
10747 x 24 h = 24.6 h x 10500
But
10500 x 9.9 h = 4331 days x 24 h
- Where
- 4331 days = Jupiter orbital period
- 9.9 hours = Jupiter Day Period
- 24 hours = the solar day
- We have 3 values of 10500 which are:
- Jupiter has 10500 Jupiter days (9.9 h) in its orbital period
- Saturn has 10500 Mars rotation periods (24.6 h) in its orbital period
- Neptune in 10500 solar days moves a distance =4900mkm = Jupiter orbital
circumference – these 3 values should be equal because Jupiter moves during its
day period a distance = 466884 km = Neptune motion distance during a solar day
Equation no. (15)
9.7 km/s x 2 x 155597 seconds = 8 x 378675 km
-
- This equation tells that –
- 155597 km= Neptune circumference, if this distance be used as a period of time,
Saturn (9.7 km/s) moves during it (155597 seconds) a distance = 8 Saturn
circumferences where 8 Saturn circumferences =3.024 mkm = Venus motion
distance per a solar day

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12-3 Planet Diameter Analysis
I- Data
Planet Diameter Divided by (π) Divided by (π2
)
4879 km 1553 km 494.4 km
12104 km 3852.8 km 1226.4 km
12756 km 4060.4 km 1292.5 km
3475 km 1106.2 km 352.1 km
6792 km 2162 km 688.2 km
142984 km 45513.2 km 14487.3 km
120536 km 38367.8 km 12213 km
51118 km 16271.4 km 5179.3 km
49528 km 15765.3 km 5018.3 km
2390 km 761 km 242.3 km
- Why do we analyze the planets diameters based on the rates (π) and (π2
)? Because
I try to show that the proportionality of data isn't some random process – it's not
true- the data mentioned the proportionality- this table tries to help our analysis but
before let's summarize the idea as clear as possible in following
- The Almighty Creator uses the numbers – here – there are no periods neither
distances – the basic using depends on the numbers – He creates a series of
numbers – when the series be completed He uses this series to create the periods
and the distances (and the planets diameters), here our difficulty be seen because
we distinguish between the period and the distance –the number doesn't –
- I want to say – in the kitchen – the number 86400 is a just number – for us it be
86400 seconds (a solar day) but the kitchen still can produce 86400 mkm or 86400
minutes or 86400 hours -
- The table shows that clearly

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- For example
- 3852.8 km can be used as 38520 seconds = Saturn day period
- 1106 km can be used as 1106 mkm the distance passed by Venus in 365.25 days
- 38367.8 km can be used Venus Circumference (error 1%)
- 761 km can be used as 760 seconds the period needs by light (0.3 mkm/s) to pass
227.9 mkm = Mars orbital distance
- 45513.2 can be used as 90560/2 where 90560 days = Pluto Orbital Period
- 1226.4 km can be used as 1226.4 hours =8 Pluto days periods total
- 688.2 km can be used as 687 days = Mars Orbital Period
- 242.3 km can be used as 243 days = Venus rotation period
- It's NOT random numbers found by chance – it's a series of numbers be used in
distances, periods, planets diameters ….etc
- By that it's some very strange situation that we don't understand how the solar
planets move till now because the machine is created by some defined system- and
the mathematical analysis can help greatly to discover the basic concept behind the
machine geometrical design.
- The fighting has no meaning – it's found just because of the wrong vision – as in
the big bang theory which was a wrong theory in concept – the mistake was just
clear that the theory supposed the universe be created by some random process and
no geometrical design be found before creation –the principle itself is mistaken
because the planets data show a system of data – disproving the random creation.

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12-4 Why do the planets revolve around the sun if there's no sun gravity?
- Let's provide one idea can solve this question in following:
- The solar system geometrical design forces the planets to revolve around the sun –
this process is done basically depends on Saturn motion – that shows the rate
(2.48) is found for a geometrical necessity
- Uranus almost has a vertical effect by which Uranus causes Saturn to do its job to
direct the planets revolving around the sun
- In this process Uranus depends on Venus, Earth and Pluto motions
- But basically
- The vertical and horizontal motions harmony depends on the harmony of Earth and
Venus Motions –
- In more clear words
- Venus Mass be = 80% of Earth Mass because of the effect of Uranus orbital
inclination (0.8 degrees) or Uranus inclination be created as a result for this rate of
masses.
- This idea can be more clear when we answer the following question
- Why Saturn orbital distance = Saturn Uranus distance? And more important we
should ask if the sun, Saturn and Uranus be on a straight line (180 degrees) or on
perpendicularity (90 degrees)?
- Please Notice
- 778.6 mkm (Jupiter orbital distance) = 3.024 mkm x 257.4 = 2.57 mkm x 302.5
- 100733 mkm = 149.6 mkm x 671 mkm = 108.2 mkm x 929 mkm Where
- 3.024 mkm = Venus motion distance during a solar day
- 2.574 mkm = Earth motion distance during a solar day
- 100733 mkm = the solar planets orbital circumferences total
- 149.6 mkm = Earth orbital distance 108.2 mkm = Venus orbital distance
- 671 mkm = Venus Jupiter distance
- 929 mkm = Earth Jupiter distance (Be on 2 different sides from the sun)

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13- Planet Mass Effect On its Motion
13-1 Preface
13-2 Planet Mass effect on its Motion
13-3 Saturn and Earth Motions Interaction
13-4 Planets Velocities Proportionality

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13-1 Preface
- How Does Planet Mass Effect On Its Motion?
- I suggest the following rule
- (Planet Mass / Planet Mass) = Planet Orbital Inclination = (Planet Velocity /
Planet Velocity)
- The suggested rule tells that
- Planets masses rates define Planets orbital inclinations for their motions and based
on Planets orbital inclinations the planets velocities be defined in comparison one
another – this idea we can conclude from Saturn Motion Analysis because
- (Saturn velocity 9.7 km/s) / (Neptune velocity 5.4) = 1.8
- Neptune orbital inclination = 1.8 degrees
- Also
- (Mars velocity 24.1 km/s) /(Saturn velocity 9.7 km/s) = 2.5
- Saturn orbital inclination = 2.5 degrees
- That shows directed data and gives hope that the rule is a correct one – means- the
planets masses causes to create their orbital inclinations and the orbital inclinations
define each planet velocity in comparison with other planets
- Now we should ask
- The planets velocities be decreased from the sun to Pluto in order and that shows
the velocities must be created in one system – can we find one system expresses all
planets orbital inclinations? The following data may answer this question
- Notice
- The inner planets orbital inclinations total = 17.4 degrees
- Pluto orbital inclination = 17.2 degrees (error 1%)
- The outer planets orbital inclinations total = 23.6 degrees
- Earth axial tilt = 23.4 degrees (error 1%)

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- The data shows the planets orbital inclinations be created by one system which
support the velocities regular distribution
- But
- The planets motions create interactions among one another – for example
- 7 deg (Mercury orbital inclination) = 1.9 deg (Mars orbital inclination) + 5.1
deg (Mercury orbital inclination)
- This data tells the planets orbital inclinations can be suffered from interactions
which force the rule to be used through additional geometrical and mathematical
methods –
- The points no. (12-2) and (12-3) try to prove the suggested rule
- The point no. (12-4) analyze the planets velocities rates
- Let's discuss the planets data in following to test how to use the rule –

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13-2 Planet Mass Effect On Its Motion
I –Data
Equation no. (1)
(0.642/0.33) = 1.94 = (47.4 /24.1) (error 1%)
Equation no. (2)
(0.073 /0.0146) = 5.1- = (24.1/4.7) = (27.78/5.4)
Equation no. (3)
(4.87/5.97) = (23.4/29.2) = 0.81
Equation no. (4)
(4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9)
Equation no. (5)
(1898 / 568) = 3.34
Equation no. (6)
(568/4.87) = 116.6
Equation no. (7)
(0.33 /0.0131) = 49
Equation no. (8)
(568/102) = (0.073 /0.0131) = 5.56 = (29.8/5.4)
Equation no. (9)
(102 /5.97) = 17.1
Equation no. (10)
(1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
Equation no. (11)
(The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772
Equation no. (12)
(The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44

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II –Discussion
Equation no. (1)
(0.642/0.33) = 1.94 = (47.4 /24.1) (error 1%)
- 0.33 x 1024
kg = Mercury Mass
- 0.642 x 1024
kg = Mars Mass
- Now
- What's 1.94?
- Mars orbital inclination = 1.9 degrees and it different from 1.94 with error 2.4%
- We may accept that this value (1.94) refers to Mars orbital inclination (1.9 deg)
- We may explain the error existence in following –
- Where 7 degrees (Mercury orbital inclination) = 1.9 deg +5.1 deg (the moon
orbital inclination) – the data tells that the motions get configuration for data
among one another – and by that the error can be produced
- Mercury and Mars data gives a good example for the suggested rule – we still need
to examine the planets motions data – because
- Mars moves during one solar day a distance = 0.52 degrees = (1/1.9) that shows
the masses rate effect on the motion and causes the velocities rate.
Equation no. (2)
(0.073 /0.0146) = 5.1 = (24.1/4.7) = (27.78/5.4)
- 0.073 x 1024
kg = The Moon Mass
- 0.0146 x 1024
kg = Pluto Mass
- 0.0131 x 1024
kg = Pluto Mass (old registered value)
- 27.78 km/s = The moon velocity

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- Pluto mass was registered as 0.0131, and based on it the rate between the moon
and Pluto masses be = 5.6 but with the new registered Pluto mass the rate be 5.1
- We see the rate 5.1 isn't between the moon and Pluto velocities directly but it uses
2 more planets (Mars and Neptune velocities) – the explanation is that –because
the planets motions depend on one another that causes the 2 planets velocities be
use – Please remember
- (Venus velocity 35 / Uranus velocity 6.8) = 5.1
- (Mars velocity 24.1/ Pluto velocity 4.7) = 5.1
- (the moon velocity 27.78/ Neptune velocity 5.4) = 5.1
- That shows a continuous interaction among many planets to create the moon
orbital inclination 5.1 degrees
- Notice
- Pluto mass old registered value (0.0131) can be used in this equation also because
in this cases (the moon mass / Pluto mass) =5.6 and this rate can create the moon
orbital inclination 5.1 degrees because the moon diameter needs angle 0.5 degrees
and that means the moon orbital inclination be measured talking into consideration
the moon diameter.
- Notice
- (Mercury Mass 0.33 / Pluto Mass 0.0131) =25.2 = (5.02)2
- Mars Axial Tilt = 25.2 degrees
- The moon orbital inclination = 5.1 degrees (with 5.02 has an error 1.6%)
- And
- 7 degrees = 5.1 degrees + 1.9 degrees
- And
- 17.2 degrees = 5.1 degrees x 3.4 degrees (Venus orbital inclination)
- We have seen the proportionality of the 6 planets velocities for 5.1

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Equation no. (3)
(4.87/5.97) = (23.4/29.2) = 0.81
- 4.87 x 1024
kg = Venus Mass
- 5.97 x 1024
kg = Earth Mass
- 23.4 degrees = Earth Axial Tilt
- 29.2 degrees = Earth motion degrees during 29.53 solar days
- Earth has no orbital inclination – for that reason the data uses its axial tilt (23.4
deg)
- The equation doesn't use Earth velocity directly – that because Earth doesn't move
alone but with its moon and the moon motion be part of Earth motion and for that
its data be seen in Earth motion data
- We notice that the moon moves during 29.53 days 13.177 x 29.53 = 389.2 deg =
360 degrees + 29.2 degrees
- Notice
- 0.8 degrees = Uranus orbital inclination, and the equation may show Uranus
motion effect on Earth and Venus Motions. other data can supports this meaning –
for example
- 116.75 days (Venus day period) x 0.8 = 93.4 (Zero error)
- 93.4 degrees = 90 deg + 3.4 deg (Venus orbital inclination)
- Also
- 102 (Neptune Mass) x 0.8 = 81.6 = (Uranus mass 86.8 – Venus mass 4.87)
- The data refers to the same meaning but by using different geometrical and
mathematical forms –
- Also
- 2.551392 mkm (the moon orbital circumference) = 116750 km x 21.8
- (where 21.8 = Jupiter mass / Uranus mass) and
- 116.75 days (Venus day period) x 1000 km = 116750 km
- (if the rate 1 day = 1000 km be used)

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Equation no. (4)
(4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9)
- 4.87 x 1024
kg = Venus Mass
- 0.073 x 1024
kg = The moon Mass
- 708.7 hours = The moon day period
- 655.7 hours = The moon rotation period
- 66.7 = π2
x 6.7 degrees (The Moon Axial Tilt)
- Notice
- (Uranus Mass 86.8) / (Venus Mass 4.87) = 17.8
- 17.8 =5.1 x 3.49 (3.4 degrees = Venus orbital inclination error 2.5%)
- That shows Venus orbital inclination and the moon orbital inclination be created in
comparison with one another –this fact is supported by different data let's refer to
then in following
- 17.2 degrees = Pluto orbital inclination
- 17.4 degrees = The inner planets orbital inclinations total
- The data be created similar to one another because of the wide interaction behind
the moon orbital inclination creation – as the planets velocities show
- For more explanation
- Jupiter orbital distance 778.6 mkm = Earth orbital distance 149.6 mkm x 5.2
- That shows the moon orbital inclination be created as 5.1 degrees for different
used data
- Notice
- (Neptune Mass 102) / (Earth Mass 5.97) = 17.1
- The rate 17.1 is more near to 17.2 deg (Pluto orbital inclination), we will discuss
later

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- Equation no. (4) shows that there's a strong connection behind this data – the 4
periods (708.7 h – 655.7 h – 10.7 h -9.9 h) are created based on one another by a
great accuracy and for that the rate between them has Zero error – here this
connection depends on a great part on Venus motion – where Venus motion data
shows a great effect from Uranus on Venus by different forms of data – this effect
makes Venus as a land of project – it works as a place of work and through Venus
Jupiter and Saturn motions effect on the moon cycles periods - Please remember
- (243 days /224.7 days) = (29.53 days /27.3 days)
- 243 days = Venus rotation period
- 224.7 days = Venus orbital period
- 29.5 days = The moon day period 27.3 days = The moon orbital period
Equation no. (5)
(1898 / 568) = 3.34
- 1898 x 1024
kg = Jupiter Mass 568 x 1024
kg = Saturn Mass
- 3.4 degrees = Venus orbital inclination (error 1.7% with 3.34)
- Equation no. (5) shows that Venus orbital inclination is created as a rate between
different data and that because of Venus position as a point of work for many
planets motions effect which effect on the moon motion –
- We see that Venus orbital inclination be created as a rate between 2 great masses
planets – that tells – the solar system be designed by one geometrical design and
the planets motions effect on one another through one general system – that
explains why the 2 great masses planets effect to create Venus orbital inclination
to be 3.4 degrees – the effect is done as a rate of masses but in a general deign for
the whole area as one playground – Jupiter and Saturn doesn't create the rate 3.4
for themselves – but because they are the 2 basic masses and columns in the solar
system they define the required data for the whole playground- for that reason –
the choose Venus orbital inclination to be 3.4 deg – noting that – the rate 3.4 still
can effect on the 2 great planets motions.

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Equation no. (6)
(568/4.87) = 116.6
- 4.87 x 1024
kg = Venus Mass
- 568 x 1024
kg = Saturn Mass
- 116.75 days = Venus day period
- The rate 116.6 between Saturn and Venus masses can cause Venus day period to
be 116.75 days – but also this same rate effects on Saturn motion data because
116.7 degrees = 90 degrees +26.7 degrees (Saturn Axial Tilt), the data forces us to
accept very specific relationship between Saturn and Venus –This relationship be
seen also in different data of Saturn and Venus motions – for example 1433.5 mkm
= Saturn orbital distance = (37862 km)2
where 38025 km = Venus Circumference
(error 0.4%) – Also – (12104 km Venus diameter)2
= 120536 km Saturn diameter
Equation no. (7)
(0.33 /0.0131) = 49 ( Mercury orbital inclination = 7 degrees)
- 0.33 x 1024
kg = Mercury Mass
- 0.0131 x 1024
kg = Pluto Mass (old value)
- The equation shows that Mercury orbital inclination 7 deg be created as a rate
between the masses of Mercury and Pluto – we realize clearly that – Pluto motion
data effect on Mercury motion data by many and different forms- and we conclude
clearly that Pluto effects on Mercury motion data more than any other planet in the
solar system – the fact is that – Pluto was the mercury moon before te planet
migration – Mars migration theory proves this fact – it's found in point no. (9) of
this current paper.
- Please remember

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- Mercury effects on the inner planets orbital inclinations, this fact we conclude
from the calculation 7 deg = 5.1 deg +1.9 deg, by that the value 17.4 may be
created by Mercury motion effect on the inner planets by interaction with Pluto
motion.
Equation no. (8)
(568/102) = (0.073 /0.0131) = 5.56 = (29.8/5.4)
- 568 x 1024
kg = Saturn Mass
- 102 x 1024
kg = Neptune Mass
- 0.073 x 1024
kg = The Moon Mass
- 0.0131 x 1024
kg = Pluto Mass
- 29.8 km /sec = Earth velocity
- 5.4 km /sec = Neptune velocity
- (1)
- The Equation uses Pluto old registered mass which creates the rate 5.56 with the
moon mass – this same rate equal Neptune mass to Saturn mass – it's so interesting
equation because it tells the geometrical design of the solar system takes into
consideration all planets data and the rule or rate which is used for massive masses
planets be used again for the mall masses planets to create one design for the
whole system – the data provides very good vision about how the solar system be
created – the data shows clearly Newton theory of the sun mass gravity is mistaken
because no category be created based on planet mass value but the system uses
planets masses rates.
- (2)
- The Earth and Neptune velocities rate be created based on this data – we notice
that Earth mass is not a player in the equation – So how to explain the production
of the velocities rate? Any way the moon mass can refer to the motion and because
the Earth motion be connected with the moon motion that creates effect of this
equation data of Earth velocity – better answer we find in the next equation no. (9)

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Equation no. (9)
(102 /5.97) = 17.1
- 102 x 1024
kg = Neptune Mass
- 5.97 km /sec = Earth Mass
- This equation gives better answer for the question of the previous one – the
interaction between Pluto and the moon motions be connected also with Earth
motion with equal connection – Pluto connects with Earth and its moon strongly –
and by this interaction of motions Pluto orbital inclination be created –
- 10747 days (Saturn orbital period) = 17.1 x 629 days
- 629 mkm = Earth Jupiter distance be used as a period of time
- We should discuss this data in that point but I want to refer to one interesting fact
that the data ((102 /5.97) = 17.1 = (10747/629)) this data is so accurate – there
error is Zero between all these values which creates a real astonishment
Equation no. (10)
(1898 /102) = (5.97/0.33) = 18.6 (error 2.8%)
- 1898 x 1024
kg = Jupiter Mass
- 102 x 1024
kg = Neptune Mass
- 5.97 x 1024
kg = Earth Mass
- 0.33 x 1024
kg = Mercury Mass
- The idea we have concluded in the previous equation no. (8) be supported here
again by this equation – the rates be used by the massive masses planets be used
again by small masses planets to create one geometrical design for the system.
Equation no. (11)
(The Planets Masses Total 2666.7) / (Uranus mass 86.8) = 30.772
- 2666.7 x 1024
kg = The solar Planets Masses Total
- 86.8 x 1024
kg = Uranus Mass

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- Uranus Axial Tilt 97.8 deg = 31.13 deg x π
- The error between 30.722 and 31.13 = (1.3%)
- There's one more rate can be useful in our discussion
- (The Sun Mass / The Planets Masses Total 2666.7) = 749
- We remember that the number 749 is related to Uranus motion – we discuss it
deeply in Point no.(13-7) (Uranus Day Period Analysis) let's refer to it in brief
- Uranus day period = 17.2 h = 61920 seconds, and Uranus orbital period =30589
days, we need to us this period in seconds units to be 30589 seconds
- 61290 seconds = 2 x 30589 seconds + 742 seconds
- This is our number (742) and it different with (749) by an error 1%
- The equation tells an interesting meaning – for some reason Uranus occupied the
basic planet in the solar system and because of that the data uses the planets
masses total – I guess Uranus position is the reason – that Uranus position enables
it to control the other planet motions or by some effect Uranus can effect on them
– the point is that – the planets masses rates caused to create the planets orbital
inclinations – and the orbital inclinations cause to create the planets velocities rates
- This meaning tells that – the masses distribution is a basic player in the planets
motions – here is the basic point we search for – because the masses distribution
gives Uranus special position and enables it to practice a great effect on other
planets –
- I have discussed before an idea tells– Uranus motion effects on all planets Axial
Tilts to prevent the planets from the overturning motions around the sun.
- I want to say Uranus position has specific effect in the planets masses distribution.
- That explains the data – and also shows the importance of 742 seconds.

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Equation no. (12)
(The inner planets masses total 11.8) /(Venus mass 4.87) = 2.44
- 11.8 x 1024
kg = The Inner Planets Masses Total
- 4.87 x 1024
kg = Venus Mass
- 2.5 degrees = Saturn orbital inclination (error 2.5%)
- The rate (2.48) we have discussed in point no. (5,6 and 7) (The Solar Planets
Motions Use Different Rates Of Time) – this is the rate of time between Jupiter
and Saturn – and this rate be transported to Pluto by interaction with Jupiter
motion for that this rate be seen in Pluto motion data for example
- (90560 /37100) = 2.44 (error 2%)
- Where
- And because of the interaction between Earth and Pluto motions this rate be
transported to Earth motion data – for example
- And in discussion there was a confusion because we don't discover how the rate
(2.48) be transported from Pluto to Earth -
- The Equation answers this question because it shows that the rate be transported
by help of the inner planets masses total
- That may explain the old data we have seen – let's remember it here

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13-3 Saturn and Earth Motions Interaction
- Can Saturn motion effect on Earth motion?
- Many basic data shows that Saturn motion effects on Earth and its moon motions
strongly. Let's summarize this data in following
- (1)
- Saturn orbital period =10747 days = 29.5 x 365.25 days (Earth orbital period),
- Saturn orbital period shows interesting effect because the Earth moon daily
displacement = 88000 km and Earth orbital circumference = 940 mkm by that the
moon needs 10747 days to pass 940 mkm by its daily displacement (error 0.6%).
This data means, the moon needs the period 10747 days regardless Saturn motion.
The question should be why Saturn orbital period be 10747 days? Can this period
of time proves an interaction of motions be found between Saturn and Earth?
- (2)
- The planets use different rates of time which we discuss in point no. (5,6 and7) of
this current paper. Saturn and The moon use equal rates of time for their motions –
by that 1 hour of Earth motion= 29.4 hours of Saturn motion= 29.4 hours of the
moon motion.
- (3)
- Earth (29.8 km/s) moves during 12104 seconds a distance = 360700 km = 3 Saturn
diameters (error 0.3%) where
- 12104 km = Venus diameter (be used as a period of time by a rate 1 km= 1sec)
- The moon orbital perigee radius = 363000 km (different with 360700km by 0.6%)
- (4)
- (28.3 deg /26.7 deg) = (26.7 deg/25.2 deg) =(25.2 deg/23.8 deg) =(122.5 deg/115.2
deg)
- 28.3 degrees = Neptune Axial Tilt
- 26.7 degrees = Saturn Axial Tilt

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- 23.6 degrees = The outer planets orbital inclination total (different from 23.8
degrees with 0.7%)
- 122.5 degrees = Pluto Axial Tilt
- 115.2 degrees = 90 degrees +25.2 degrees (Mars Axial Tilt)
- (5)
- Light (0.3 mkm/sec) travels during 120536 seconds a distance = 36161 mkm
where 36161= 2π x 5757 mkm (= Earth Pluto Distance)
- And 120536 km = Saturn Diameter
- (6)
- The cycle 2737 which is repeated on 3/12/2012
- This cycle is repeated one time each 2737 years and in this cycle the 3 planets
Mercury, Venus and Saturn were perpendicular on the 3 heads of the great
pyramids in Egypt. Some records told the phenomenon be recorded by picture.
- The point is that, Saturn is one planet of the 3, and that shows the interaction
between Saturn and Earth motions because Venus motion can simply have an
interaction with Earth motion but Saturn is so far and by that the cycle adds one
more proof for the interaction of motions between Earth and Saturn and that may
explain the 2 planets motions data.
- Let's discuss the data to test if Saturn and Earth motions can have an interaction
- Notice
- The error of data be found for geometrical reasons – for example –the error 1% is
repeated frequently in data that because it's used for geometrical necessities – also
the rate (0.3%) this rate means (0.3% = 361/360) – and this rate be found as a
result for Metonic Cycle – because the moon orbit regresses 19 degrees per year
and during 19 years the total be 361 degrees which creates another scale (=361)
and not (360) by that the planets motions data make configuration with the new
scale– based on that – when the error 1% be decreased with 0.3% the rest be
=0.7% which is repeated error also

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I- Data
(1)
86400
E
J
T
2
2
=
e
v
v
x
S
(2)
1898 x 0.33 = 102 x 5.97 = 629 (error 2.8%)
(3)
6939.75 seconds x 0.3 mkm/s = 2094 mkm
2094 seconds x 0.3 mkm/s = 629 mkm
(4)
(568/1898) = 0.3

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II- Discussion
Equation no. (1)
86400
E
J
T
2
2
=
e
v
v
x
S
- Where
- 86400 seconds =The Solar Day
- S = The Sun Mass = 1988500 x 1024
kg
- T = Saturn Mass = 568 x 1024
kg
- J = Jupiter Mass = 1898 x 1024
kg
- E = Earth Mass = 5.97 x 1024
kg
- v = Light known velocity =300000 km/sec
- ve = Earth velocity
- Equation error = 0.7%
- The equation shows the effect of 4 players on Earth velocity creation – light
velocity be one player – that because the matter is created out of light – the 3
massive masses effect on Earth motion in comparison with Earth mass –
- That shows the masses gravity concept is a correct one – but not as Newton told.
- The equation aims to prove the a interaction or effect be found by Saturn on the
Earth motion which can explains the 2 planets motions data
- Please note that, the other planet in the equation is Jupiter and that tells Jupiter and
Saturn has equal effect on Earth motion – that explains many of the planets
motions data for example
- Please remember equation no. (4) of point (12-2)
- (4.87 /0.073) = 66.7 = (708.7 /10.7) = (655.7/9.9) – where
- 708.7 h = the moon day period 655.7 h = the moon rotation period
- 10.7 h = Saturn day period 9.9 h = Jupiter day period

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Equation no. (2)
1898 x 0.33 = 102 x 5.97 = 629 (error 2.8%)
- Where
- 0.33 x 1024
kg = Mercury Mass
- 1898 x 1024
kg = Jupiter Mass
- 102 x 1024
kg = Neptune Mass
- 5.97 x 1024
kg = Earth Mass
- The equation suggests very strange meaning – where the distance can be produced
by Masses multiplication – the explanation can be based on the energy because the
mass is made of energy and I suppose the space is made of energy – the equation
still complex in meaning – but its tells the 4 planets masses are rated and because
of that they can be written in another form (1898/102) = (5.97/0.33) = 18.6
- The error is still (2.8%)
- I can't explain how the masses can create the distance directly – but as we have
seen in the previous point of discussion – the masses rates creates the planets
orbital inclinations and that defines the planets velocities rates – that can enable
the masses rate to be transported to the distances rate by planets motions-
- The point of this equation is the distance 629 mkm =Earth Jupiter distance, we
have 2 questions related to this distance – the second question is in Equation no.(3)
so let's ask the other one here
- 227.9 mkm (Mars orbital distance) x 2 x 1.392 = 629 mkm (error 1%)
- The sun diameter = 1.392 mkm. Means the sun diameter be defined as a rate
between Mars orbital distance and Earth Jupiter distance – we remember that – the
lunar eclipse umbra length = 1.392 mkm = the sun diameter and this umbra be
created in the distance between Mars and Earth -
- Notice 224.7 days (Venus orbital period) can be used in place of 227.9 and the
error will be (0.5%) if the period 224.7 days can be used as a rate only.

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Equation no. (3)
6939.75 seconds x 0.3 mkm/s = 2094 mkm (error 0.6%)
Where
6939.75 days = Metonic Cycle Period
2094 mkm = Jupiter Uranus Distance
629 mkm = Jupiter Earth Distance
- Light (0.3 mkm/s) uses the period 6939.75 days as 6939.75 seconds, and during it
the light passes a distance = 2094 mkm = Jupiter Uranus Distance,
- The light (0.3 mkm/s) uses the passed distance as a period of time based on the
rate 1 mkm = 1 second, and during 2094 seconds the light passes a distance = 629
mkm = Earth Jupiter Distance
- By that Jupiter be as a point on a trajectory of light motion extends from Earth to
Uranus and vice versa – and this motion of light causes to create both distances
from Earth to Jupiter and from Jupiter to Uranus by one motion of light
- That supposes a massive effect of Metonic Cycle motion – and while we see the
Earth moon moves Metonic Cycle the moon refers by its motion to a great motion
be done by the light behind.
- The distance 629 mkm is our point of discussion – If we suppose the period 224.7
days be used to define the sun diameter by the data (629 mkm = 2 x 224.7 x 1.392
mkm), if we accept this data, that may explain important other data – because
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2
- Where 25.2 degrees = Mars Axial Tilt and 115.2 deg = 25.2 deg + 90 deg
- That tells the values (227.9 and 224.7) are crated depending on one another and
both be used for the sun diameter definition.

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- Notice
- 10747 days (Saturn orbital period) = 17.1 x 629 days
- 629 mkm = Earth Jupiter distance be used as a period of time
- Please remember equation no. (9) in point no (12-2)
(102 /5.97) = 17.1
- Where
- 102 x 1024
kg = Neptune Mass
- 5.97 km /sec = Earth Mass
- The astonishment be found in the data accuracy where
- (102/5.97) = 17.08 = (10747/629)
- These 5 data are created together where the error generally is (Zero)
- That tells clearly, the period 10747 must be created for the moon motion and an
interaction must be found between Saturn and the moon motion and by this
interaction the period 10747 days be used as (Saturn orbital period)
- That means the data gives one more proof for an interaction must be found
between Earth and Saturn motions.

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Equation no. (4)
(568/1898) = 0.3
- Where
- 568 x 1024
kg = Saturn Mass
- 1898 km /sec = Jupiter Mass
- 0.3 = ??
- We know that (1898/568) = 3.34, which causes Venus orbital inclination to be
created as (3.4 degrees) (error 1.7%)
- We accept also that 1 degree can be = 1 mkm
- Can this value (0.3) be = 0.3 mkm
- I want to say that,
- This value is 0.3 mkm/sec and it's the light velocity – or in more clear words – it's
the creation of light with velocity = 0.3 mkm/s
- The idea is that, the mass distribution and proportionality creates the planets
orbital inclinations and the orbital inclinations cause the velocities to be created in
proportionality and comparison -
- By this machine – a motion velocity be equal 0.3mkm/s and by this velocity the
light be produced – this velocity be seen as a rate between Saturn and Jupiter
masses as seen in the equation –
- Based on this conclusion
- The sun rays creation be done by using Saturn and Jupiter motions data, that
explains why Saturn motion distances be related frequently with motions distance
of light (0.3 mkm/s).
- The point is that, Venus orbital inclination (3.4 deg) be created also by this process
that means, Venus is a basic player in the sun rays creation – that explains why the
sun diameter 1.392 mkm = 115.2 Venus diameter 12104 km

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- Notice
- The sun diameter 1.392 mkm= 115.2 x Venus diameter = 28.3 x Neptune diameter
= 205 x Mars diameter 6792 km
- where
- 28.3 degrees = Neptune Axial Tilt
- 115.2 degrees = 90 degrees + 25.2 degrees
- 205 degrees = 180 degrees + 25 degrees
- That tells the sun diameter be created based on these 3 planets data – we should
discuss that in the sun creation point no. (14)
- Notice
- The solar system be created of one light beam its supposed 1.16 mkm/s and the
light known velocity (0.3 mkm/s) be created later with the sun creation – the light
supposed velocity existence proves be discussed in point no. (3-4)
- I want to say
- Newton is mistaken because the sun is created after all planets creation and motion
The light beam (0.3 mkm/s) proves that the planets be created before the sun
because the light supposed velocity (1.16 mkm/) was found before this light (0.3
mkm/s) creation.

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13-4 Planets Velocities Proportionality
I- Data
Data Part No. (1)
The Following Rule Controls Planet Motion Data
(r/R)= (v1/ v2)
Where
- r = The Planet Rotation Periods Number In Its Orbital Period
- R = The Planet Diameter
- V1 = The Planet Velocity
- V2 = Another Planet Velocity
- Also
- The rate (v1/ v2) defines the planet orbital inclination –
- Let's test this rule for the solar planets data in following
(a)
(89143 /49528) = (9.7 /5.4)
(b)
(24106 x2 /120536) = (9.7 /24.1)
(c)
(42683 /51118) = (5.4/6.8) (error 5%)
(d)
(14178 /2390) = (27.78/4.7)
(e)
(10500 / 142984) = (13.1/29.8 x8)
(f)
671/6792 = (4.7 /24.1 x2) (error 1.3%)

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Data Part No. (2)
(1)
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where
- 13.1 km/s = Jupiter Velocity
(2)
(35/24.1) = π2
/ 6.8
(9.7 /6.8) = (35/24.1) (1.8%)
(35/ π2
) = 47.4/13.37 = 24.1 /6.8 = (2 x 9.7) /5.4 (1.3%)
(3)
(27.78 x π2
/ 47.4 x2) = 2.86 (error 1%)
(35 x2 /24.1) = 2.86 (error 1.5%)
(4 x29.8 / 13.1π) = 2.86 (error 1.3%)
(27.78 /9.7) = 2.86 (Zero error)
(24.1 x 2 / 5.4 π) = 2.86 (error less 1%)
(2π x 13.1)/(5.4)2
= 2.86 (error 1.3%)
(9.7 x 2/6.8) = 2.86 (error less 1%)
(6.8 x 2/ 4.7) = 2.86 (error 1%)
(1.16/0.406) = 2.86 (Zero error)

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Where
- 27.78 km/s = The Earth Moon velocity

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II- Discussion
- We analyze the planets velocities proportionality as an independent subject before
our main discussion - because I try to show the transportation of motion is a
meaning has roots in the planets motions – We can't explain how the planets
velocities be defined in such proportionality unless a transportation of motion must
be found among the solar planets – simply no planet can move independently from
the others and their velocities be rated in such proportionality - I try to prove that
we don't deal with separated rigid bodies move independently from one another –
one the contrary we deal with one machine or one creature where the planets
motions show this creature members motions – because of that – the motions and
velocities be rated with one another – the data discussion will prove this meaning
clearly – let's start with Data Part No. (1) - Let's remember the rule -
(r/R) (v1/ v2)
Where
- r = The Planet Rotation Periods Number In Its Orbital Period
- R = The Planet Diameter
- V1 = The Planet Velocity
- V2 = Another Planet Velocity
Equation no. (a)
(89143 /49528) = (9.7 /5.4)
- Neptune Orbital Period (59800 solar days) has 89143 Neptune rotation periods
(16.1 h)
- The data follows the rule perfectly – error less than 1%
- Also
- 9.7 /5.4 = 1.8 where 1.8 degrees = Neptune Orbital Inclination

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Equation no. (b)
(24106 x2 /120536) = (9.7 /24.1)
- Saturn Orbital Period (10747 solar days) has 24106 Saturn rotation periods (10.7h)
- Also
- 24.1/9.7 = 2.5 where 2.5 degrees = Saturn Orbital Inclination
Equation no. (c)
(42683 /51118) = (5.4/6.8) (error 5%)
- Uranus Orbital Period (30589 solar days) has 42683 Uranus rotation periods
(17.2h)
- 51118 km = Uranus Diameter
- The data has an error 5%
- Also
- 5.4/6.8 = 0.8 where 0.8 degrees = Uranus Orbital Inclination
Equation no. (d)
(14178 /2390) = (27.78/4.7)
- Pluto Orbital Period (90560 solar days) has 14178 Pluto rotation periods (153.3 h)
- 2390 km = Pluto Diameter
- 27.78 km/s = The moon Velocity
- The moon orbital inclination (5.1 degrees) is defined as a rate between its velocity
and Neptune velocity (27.78/5.4) = 5.1

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Equation no. (e)
(10500 / 142984) = (13.1/29.8 x 6)
- Jupiter Orbital Period (4331 solar days) has 10500 Jupiter rotation periods (9.9 h)
- 142984 km = Jupiter Diameter
- Also
- (29.8/13.1) x 2 = 4.5 where (Jupiter orbital inclination 1.3 deg + Jupiter axial tilt
3.1 deg) = 4.4 deg
Equation no. (f)
671/6792 = (4.7 /24.1 x2)
- Mars Orbital Period (687 solar days) has 671 Mars rotation periods (24.6 h)
- 6792 km = Mars Diameter
- The data has error 1.3%
- Also
- Mars orbital inclination 1.9 deg be defined as a rate between Mercury and Mars
velocities
- The rule doesn't work with the Earth almost because the moon orbital period = the
moon rotation period – and there are difficulties to us the rule with Mercury and
Venus because the rotation period is so great in comparison with the orbital period

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Data Part No. (2)
Equation no. (1)
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where
- I use these 4 planets velocities as example for analysis – the rates shows clearly
that – there are found based on a geometrical mechanism and rules – we don't deal
with separated motions be done independently from one another but we deal with
some machine – imagine we analyze a car motion – the four wheels move relative
to one another – the motions be in comparison to one another – by that – I try to
show the planets motions can't be independent which supports the claim of the
transportation of motions among the solar planets.

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Equation no. (2)
(35/24.1) = π2
/ 6.8
(9.7 /6.8) = (35/24.1) (1.8%)
(35/ π2
) = 47.4/13.37 = 24.1 /6.8 = (2 x 9.7) /5.4 (1.3%)
Where
- 13.1 km/s = Jupiter velocity (error 2% with 13.37)
- Equation no.(2) supports the same discussion meaning and proves it
- Notice
- Equation no.(3) shows one equation controls all planets velocities – that creates
one connection for all planets motions which disprove the planet independent
motion concept.

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14- Saturn Motion Analysis
14-1 Preface
14-2 Saturn Diameter Analysis
14-3 Neptune Circumference Analysis
14-4 Neptune Day Period Analysis
14-5 Mercury Motion effect on Jupiter and Neptune Motions
14-6 Earth Motion Distance Daily Analysis
14-7 Uranus Day Period Analysis
14-8 The Inner Planets Motions Analysis

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14-1 Preface
- Can The Motion Be Transported Among The Solar Planets?
- The motion data be transported among the planets, how can motions data be
transported if the motions aren't? Can the data transportation among the planets be
considered as a proof for the motion transportation?
- I use Saturn motion data as example to prove that the data be transported among
the planets motions – let's make this point more clear by using an example for
explanation
- Example No. (1)
- 10 x 10747 days x 24 hours = 10.7 hours x 2 x 120536
- Where
- Later we may explain how the data use Saturn diameter as a rate in it
- The point which I try to explain is that –
- The 3 values (10747 days, 10.7 hours and 120536 km) are Saturn Data and without
the number (10) the values can't be created as seen in this equation –
- I want to say
- This number (10) is transported from a planet to another – and this number is
necessary for Saturn motion data as the previous equation shows –In the discussion
Point (No. 13) we will follow the number (10) from a planet to another proving
that all planets motions data aimed to transport this number (10) to Saturn motion
data –
- Shortly- I try to prove that the data be transported from a planet to another and I
use this number (10) as one example – during the discussion we will see tenths of
data be transported from a planet to another but we keep our eyes on this number

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(10) specifically to prove that it's (really) transported among the planets motions
data.
- This task of the discussion point is a promised task and important one – basically
because it proves there's a transportation of data (or of motions) among the planets
be performed –
- The Idea Summary
- The discussion tries to prove a transportation of motion be found in the solar
system among the planets– we use Saturn data and especially the number (10) as
our guide through the planets motions to discover if the motions or the motions
data really be transported.

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14-2 Saturn Diameter Analysis
I- Data
(1)
2 x 16.1 h x 3600s x 13.1 = 1518552 km = 4 x 379638 km =9.7 x 156552
(5.4 x 155597 = 7 x 120536 = 840224 km)
(2)
13.1 x 49528 = 648817 =5.4 x 120151 = 4 x 162204 (error 1%)
(3)
(378675 /13.1) =(155597/5.4) =28800 = 8 x 3600
(4)
13.1 x 51118 = 5.4 x 2 x 17.2 h x 3600 s
(5)
0.6 hour = 2160 s where 13.1 x 2160 = 28296 km
(6)
49528 x 1.13184 mkm = 2 x 28029 mkm
28244 days x 1.13184 mkm = 32200 mkm (0.7%)
(7)
9.7 x 2 x 16.1 h x 3600 = 13.1 x 85834 (error 0.6%)
(8)
13.1 x 120536=1579029 =47.4 x 33313=35x 45115 = 29.8 x 53000 = 27.78 x 56840=
24.1 x 65519 =9.7 x 162785 = 6.8 x 232210 =5.4 x 292411=4.7 x 335962

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II- Discussion
Equation no (1)
2 x 16.1 h x 3600s x 13.1 = 1518552 km = 4 x 379638 km =9.7 x 156552
And
Equation no (7)
9.7 x 2 x 16.1 h x 3600 = 13.1 x 86400 (error 0.6%)
- Equation no. (1) tells that
- Jupiter (13.1 km/s) moves during 2 Neptune days periods (2x16.1 h =2x 57960s) a
distance = 1518552 km = 4 Saturn Circumferences = Saturn motion distance
during 155597 seconds (where 155597 km =Neptune Circumference)
- And
- Equation no. (7) tells that
- Saturn (9.7 km/s) moves during Neptune day period (2 x 16.1 h =2 x 57960s)
a distance = 1124424 km = Jupiter motion distance during a solar day
- The main player in these motions is Neptune day period – Jupiter moves a distance
related to Saturn motion and Saturn moves a distance related to Jupiter motion
Why??
- The fact is that
- (13.1)2
/(4 x 9.7) = 4.4 = (378675/86400)
- Where
- 13.1 km /sec = Jupiter velocity
- 9.7 km /sec = Saturn velocity
- 378675 km = Saturn Circumference
- 86400 sec = The Solar Day
- We generally accept the supposed rate (1 km = 1 second)
- Based on the previous equation, Jupiter and Saturn both move during 2 Neptune
Days periods distances are rated to Saturn Circumferences and Jupiter motion
during the solar day period – the point is that –Saturn moves during its day period

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a distance = Saturn circumference (error 1.3%), that makes Saturn motion
distances rated to Saturn Circumferences
- This simple explanation left many questions behind – for example – can any planet
motion distances be rated with its circumference?– Saturn moves during its day
period a distance = Saturn Circumference (error 1.3%), Jupiter does the same but
the error is greater (4%) Uranus moves a distance = 2.6 its Circumference and
Neptune moves 2 Circumferences in its day period –the rule isn't clear yet –
- But
- The question was, Why both planets move distances related to each other during
Neptune day period?
- The part one is answered because of ((13.1)2
/(4 x 9.7) = 4.4 = (378675/86400) )
this part provides the answer but – part 2 isn't answered yet-Why during Neptune
day period specially? Let's answer that with Neptune Day period analysis point no.
(13-4)
- Here let's try to see why Jupiter and Saturn velocities be rated by this rule in
following (additional rule for Planets Velocities Analysis)
- A Rule For Planet Velocity Definition
- 4 x 5.4 (Neptune velocity) = (4.7)2
(error 2%)
- 4 x 6.8 (Uranus velocity) = ((5.4)2
) / 1.0725
- 4 x 9.7 (Saturn velocity) = 6.8 x 5.4 (error 5%)
- 4 x 13.1 (Jupiter velocity) = 9.7 x 5.4
- 8 x 24.1 (Mars velocity) = 6.8 x 27.78 (error 1.8%)
- 4 x 27.78 (the moon velocity) = 24.1 x 4.7 (error 1.8 %)
- 8 x 29.8 (Earth velocity) = 6.8 x 35
- 4 x 35 (Venus velocity) = 29.8 x 4.7
- 4 x 47.4 (Mercury velocity) = 27.78 x 6.8
- (4.7 km/s = Pluto velocity)

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- The previous rule shows that the form of (4 v1 = v2 x v3) or (4 v1 = v2
) is a usual
form of using and by that the rule we have found which is
- (13.1)2
/(4 x 9.7) = 4.4 = (378675/86400)
- This rule is found based on the same rule we have explained – and by that we
discover one more rule be found behind the planets velocities definition –
- Let's complete our data discussion
Equation no (2)
13.1 x 49528 = 648817 =5.4 x 120536 = 4 x 160592 (error 1%)
- Where
- 13.1 km /s = Jupiter velocity
- 5.4 km /s =Neptune velocity
- 160592 km = Uranus Circumference
- The data shows interesting feature – because –
- Each time Neptune diameter be used as a period of time for (any) planet motion,
the passed distance be related to Saturn Diameter –let's prove that in following
(1)
- Jupiter (13.1km/s) moves during 49528 sec a distance = 648817 km = the distance
be passed by Neptune in a period 120536 sec (where 120536 km =Saturn diameter
and 49528 km = Neptune diameter)
(2)
- Saturn (9.7 km/s) moves during 155597 sec a distance = 1509291 km = 4 x
378675 km (Saturn Circumference) (Where 155597 km =Neptune Circumference)
(3)
- Neptune (5.4 km/s) moves during 155597 sec a distance = 840224 km = 7 x
120536 km (Saturn Diameter) = Saturn motion distance during a solar day

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(4)
- 8 Neptune days periods = 466884 seconds (error 0.7%) where
- 466884 km = Neptune motion distance during a solar day = 3 x 155597 km
(Neptune Circumferences)
Equation no (3)
(378675 /13.1) =(155597/5.4) =28800 = 8 x 3600
- Where
- 155597 km = Neptune Circumference
- Equation no. (3) tells that,
- Jupiter (13.1 km/s) moves during (8 hours) a distance = 378675 km = Saturn
Circumference
- And
- Neptune (5.4 km/s) moves during (8 hours) a distance = 155597 km = Neptune
Circumference
- The secret is that 8 hours is around (50%) of Neptune day period (16.1 h)
- Means
- During 2 Neptune days periods
o Jupiter moves a distance = 4 Saturn Circumferences
o Neptune moves a distance = 4 Neptune Circumferences
o Saturn moves a distance = Jupiter motion distance during a solar day
- Why?
- What's the big secret in Neptune day period? It = 67% of a solar day!
- That's all why it's very specific period of time?!
- We should discuss that in point no. (13-4)

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Equation no (4)
13.1 x 51118 = 5.4 x 2 x 17.2 h x 3600 s
- Where
- 51118 km = Uranus diameter
- 17.2 hours = Uranus diameter
- Equation no. (4) shows that,
- Uranus data be used also in this same network –
- We clearly have some network between Jupiter, Saturn and Neptune, in this
network the 3 planets diameters, days periods and velocities are rated to perform
specific motions which be seen in the passed distances proportionality
- Equation no.(4) and Equation no. (2) tell that Uranus data be used also in this same
network – by that –
- Jupiter (13.1 km/s) moves during (51118 seconds) a distance = 669646 km = the
distance be passed by Neptune during 2 Uranus days periods – The proportionality
of data be seen clearly..
- To make this discussion more understandable let's see the 4 planets velocities
proportionality again in following
- The 4 Planets Velocities
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- And
- (9.7/5.4) + (13.1/9.7) = π
- Where

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- The point is that these velocities be created based on one another by specific
geometrical rule – the motions distances are mentioned and defined clearly for
geometrical necessities –
- We clearly deal with one machine and these 5 planets are players in one team
move defined distances for specific geometrical reasons
- Notice
- Pluto is the fifth player where
- Pluto (4.7 km/s) moves during 51118 seconds a distance = 2 x 120536 km (Saturn
diameter) (where 51118km= Uranus diameter)
- And
- Pluto (4.7 km/s) moves during 2 x 120536 seconds a distance = 1.13184 mkm
(=Jupiter motion distance during a solar day)
- Pluto talk a similar language to the 4 other planets – it moves distances equal
Saturn diameters or circumferences and when this distance be used as a period of
time Pluto moves during it a distance = Jupiter motion distance during a solar day
– Why? What's the geometrical mechanism which causes this network of planets to
move as pieces of chess each piece moves a distance be calculated and defined in
comparison and proportionality with the other distances?
- I wish the data shows and proves that we are very far from the point on which
Newton theory of the sun gravity stand – where we discuss and analyze different
motions features completely from his description of the planets motions

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Equation no (5)
0.6 hour = 2160 s where 13.1 x 2160 = 28296 km
- Where
- 0.6 hours = 24.6 h (Mars rotation period) – 24h (the solar day)
- The Equation tells that
- Jupiter moves during (0.6 hours) distance = 28296 km
Equation no (6)
49528 x 1.13184 mkm = 2 x 28029 mkm
28244 days x 1.13184 mkm = 32200 mkm (0.7%)
- Where
- 1.13184 mkm = Jupiter Motion Distance During a solar day
- 28244 mkm = Neptune Orbital Circumference (be used as a period of time)
- 32200 mkm = The different distance between Pluto orbital circumference
(37100mkm) and Jupiter orbital Circumference (4900 mkm)
- The Equation tells Jupiter moves during (28244 days) a distance = 32200 mkm

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Equation no (8)
13.1 x2x 120536=2 x 1579029 =47.4 x 66626=35x 90560 = 29.8 x 106000 = 27.78 x
113680= 24.1 x 131038 =9.7 x 2x 162785 = 6.8 x 2x 232210 =5.4 x2x 292411=4.7 x
2x 335962
- Where
- 27.78 km/s = The moon velocity
- 4.7 km/s =Pluto velocity
-
- Equation no. (8) tells that,
- Jupiter (13.1 km/s) moves during ( 2 x 120536 seconds) a distance = 2 x 1579029
km – this distance be passed by the other planets in different periods of time – the
point is that – Each planet uses a very specific period of time – let's refer to Venus
Motion in following
- Venus Motion
- Venus (35km/s) moves during 90560 seconds the distance = 2 x 1579029km
- Where
- 90560 solar days = Pluto Orbital Period
- Venus uses 90560 seconds
- The data is a complex one because –

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- Pluto (4.7 km /s) moves during 90560 seconds a distance = 425632 km = Venus
motion distance during 12104 seconds (where 12104 km = Venus diameter)
- But
- The distance 425632 km = Uranus motion distance during its day period 421056
km (error 1%)
- Means
- Venus moves the distance 2 x 1579029km in 90560 seconds because there's
another connection between Venus and Pluto related to Uranus motion distance
during its day period – but still we need to discover the geometrical mechanism
based on which these motions be done
- We deal with a network or a board of chess – each piece moves in comparison
with the other pieces based on geometrical calculations.
- Let's look at Saturn motion
- Saturn Motion
- Saturn (9.7 km/s) moves during (2 x 162785 seconds = 160592 error 1%) where
(160592 km = Uranus diameter) the distance 2 x 1579029
- Saturn using of Uranus diameter as a period of time be created based on the
network of the 5 planets we have discussed before
- The other planets data be interesting and we will use them in different points of
discussion – but there's a difficulty to explain them in details here because it needs
extending discussion – the next points of discussion will make them more clear

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14-3 Neptune Circumference Analysis
Group no. (I)
(1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
(2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
(3)
(9.7 / 5.4) = 4π/7
(4)
155597 sec x 5.4 km/s = 840224 km = 2 x 420112 km = 7 x 120536 km = 373644 km
+ 466884 km
(5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm =
(6)
49528 km = 9.7 x 5106 sec
Group no. (II)
(7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
(8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
(9)
(120536 km /5.4 km) = (25920 mkm /1.16 mkm)
Notice
In Neptune Circumference analysis there are many data be used from Saturn diameter
analysis but we need to extend the discussion for better vision – for that we have to
repeat the data using.

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II-Discussion
Equation no. (1)
155597 sec = 4 x 10.7 hours x 3600 s (error 1%)
Equation no. (2)
120536 sec = π x 10.7 hours x 3600 s (error 0.4 %)
Equation no. (3)
(9.7 / 5.4) = 4π/7
- Where
- The previous data shows that
- Neptune Circumference and Saturn diameter both can be considered as functions
in Saturn day period if 1 km be = 1 second - the data has error (1%) and (0.4%),
the functions depend on (4) for Neptune and (π) for Saturn and by that the rate
between both = (4/π)
- The 2 planets velocities rate be (4π/7), we see that the 2 rates are near
- We should ask why the 2 rates are near?
- The point I need to discuss now immediately is the result of this proportionality,
because it has a massive effect on both planets motions –
- Let's see the next equations

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Equation no. (4)
+466884 km
Equation no. (5)
2 x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
Equation no. (6)
49528 km = 9.7 x 5106 sec
- Shortly
- Neptune motion during (155597 s) passes a distance = 7 Saturn diameters
- Saturn motion during (155597 s) passes a distance = 4 Saturn Circumferences
- We notice that
- Neptune Circumference =4 Saturn days periods if 1 km = 1sec and
- Saturn Diameter =π x Saturn day period if 1 km = 1sec and
- I try to prove that a geometrical rule must be found behind this proportionality of
data, before any progress in the discussion we need to know why Saturn velocity
=9.7 km/s and Neptune velocity =5.4 km/s – because the rate between the 2
velocities is very near to the rate between Neptune circumference and Saturn
diameter – No hope to use (the pure coincidence of numbers) as a method of
Escape – because we have many different data be created depends on one another.
- Let's see equation no. (4) in following

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Equation no. (4)
+466884 km
- Where
- 838000 km = Saturn motion distance during a solar day
- 421056 km = Uranus motion distance during Uranus day period
- 120536 km= Saturn diameter
- 373644 km = Saturn motion distance during Saturn day period
- 466884 km = Neptune motion distance during a solar day
- 155597 km= Neptune Circumference
- Neptune (5.4 km/s) moves during 155597 sec a distance = 840224 km
- But, the distance 840224 km is so interesting one because
- (1)
- 840224 km = it equals Saturn motion distance during a solar day (838000 km)
- (840224 /838000) =(361/360)
- (2)
- 840224 km = 2 x Uranus motion distance during Uranus day period (17.2 h)
- 840224 km = 2 x 420112 km (Uranus motion distance =421056 km)
- (3)
- 840224 km =373644 km + 466884 km
- So
- Neptune motion during (155597 sec) moves distance = 7 Saturn diameters =
Saturn motion distance during a solar day = 2 Uranus motion distance during its
day period = the total of Neptune motion distance during a solar day plus Saturn
motion distance during Saturn day period
- It must be the greatest happy chance in the universe which produces so many
(correct) distances by one motion!

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Equation no. (5)
155597 sec x 9.7 km/s = 4 x 378675 km
- Saturn moves during 155597 sec a distance = 4 Saturn Circumferences
- Here
- Neptune motion and Saturn motion (during the same period of time 155597 sec)
pass distances = Saturn diameters and circumferences respectively! Why?
- But
- 2 values of 155597 sec makes a difference because
2x 155597 sec x 9.7 km/s = 8 x 378675 km = 3.024 mkm
- Saturn moves during (2 x 155597 sec) a distance = 8 Saturn circumferences
- And
- For one more happy chance the 8 Saturn circumferences total be = 3.024 mkm =
Venus motion distance during a solar day
- Why?
- By the way
- 35 km/sec (Venus velocity) = 2x (9.7)2
x 5.4
- Means, Venus velocity is produced as a function in Saturn velocity (9.7 km/s) and
Neptune velocity (5.4 km/s)
- And
- (35/6.8) = (24.1 /4.7) = (27.78 /5.4)
- Where
- 27.78 km/s = The Moon Velocity

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- That makes Uranus velocity be rated with Venus velocity through this interesting
machine of velocities
- Notice
- Neptune moves during its day period a distance = 2 Neptune Circumferences = 2 x
155597 km
- This information is an important one because Neptune motion uses (usually) the
value (2 x 155597 km) as we have seen.
- Also
- 2 x 155597= 311194 km =Jupiter diameter +Saturn diameter + Uranus diameter (1%)
- This data shows again Neptune motion uses the value (2 x 155597 km) better than
(155597 km) and that means the geometrical design uses this distance of motion be
passed by Neptune during its day period and not uses Neptune circumference.

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Equation no. (6)
49528 km = 9.7 x 5106 sec
- The Equation tells that, Saturn (9.7 km/s) moves during 5106 seconds a distance =
49528 km (Neptune diameter) –
- but we know that –
- Mercury day period needs 5040 seconds to be 4224 hours
- 5106 seconds is different from 5040 seconds with (1.3%) - Means
- Saturn moves during (5040 seconds) a distance = Neptune diameter (error 1.3%)
- Mercury moves during (5040 seconds) a distance = 2 Saturn diameters (error -1%)
- Mars moves during (5040 seconds) a distance = Saturn diameter (error +1%)
Equation no. (7)
142984 sec = 4 x 9.9 hours x 3600 s (error 361/360)
- Where
- 142984 km =Jupiter diameter
- Equation no.(7) tells simply that, Jupiter diameter can be equal 4 days of Jupiter
days if 1km= 1 second
- 4 Jupiter days = 142560 seconds
- And
- (142984 /142560) = (361/360)
- Now
- Jupiter is the 3rd
planet whose diameter can be used as a period of time because it
equals 4 Jupiter days periods (the 2 planets are Saturn and Neptune)
- Again
- We have to ask (Can Planet diameter depend on it day? Or on any period of time?)
Why the planet diameter be used as a period of time?!

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Equation no. (8)
2x 160592 sec = 9 x 9.9 hours x 3600 s (error 361/360)
- Where
- 160592 = Uranus Circumference
- 9.9 hours = Jupiter Day Period
- Equation no.(8) tells 2 Uranus circumferences can be = 9 Jupiter days if
- 1 km =1 second
- Shortly
- Saturn and Neptune diameters depend on Saturn Day Period
- And
- Jupiter And Uranus Diameters Depends One Jupiter Day Period
- We remember that
- 2 Jupiter circumferences – 2 Saturn circumferences = 1 Jupiter diameter (1.3%)
- This data tells that
- Saturn diameter be created as a function in Jupiter diameter and that connects the 4
planets data together
- Can Saturn day period (10.7 h) depend on Jupiter day period (9.9 h)?
- Notice
- Neptune Circumference depends on 4 Saturn days periods
- Jupiter diameter depends on 4 Jupiter days periods
- Earth cycle is 4 years (365 +365 +365 +366 =1461 days)
- Can this (4 Periods) Cycle be a general cycle in the solar system?

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- The Discussion Summary
- Let's summarize the discussion idea in following:
- There are 2 reasons of proportionality between Saturn and Neptune motions data –
- (First) (Saturn velocity /Neptune velocity) = (4π /7)
- (second ) (Saturn diameter be produced by a motion during 155597 seconds
whether . .this motion be done by Saturn or by Neptune
- Here we have 2 reasons of proportionality, and no logic to suppose both of them
be created by chance -
- If the 2 planets diameters be created as function in Saturn day period (although we
don't know how that can be possible) – the question is still on table asks that why
the velocities are rated? It's incredible the 2 planets diameters are rated and also
their velocities – that makes the 2 planets motions data some how identical – for
example –
- Neptune orbital distance 4495.1 mkm = Saturn orbital distance 1433 mkm x π
- And
- Neptune orbital period 59800 d = Saturn orbital period 10747 d x (π)3/2
- The 2 planets motions data be some how identical because of this proportionality

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14-4 Neptune Day Period Analysis
I-Data
(1)
8 x 16.1h x 3600s =3 x 155597s =466884 s
(2)
8 x 466884 km = 31 x 120536 km
(3)
16.1 -10.7 = 5.4 but 5.4 x 2 = 10.8 hours
(10.8 + 10.7 x 2 = 2 x 16.1)
(4)
24.1 x 5.4h x 3600 = 466884 km
13.1 x 5.4h x 3600 = (51118 km x5)
9.7 x 5.4h x 3600 = (378675 km /2)
6.8 x 5.4h x 3600 = (21346.6 km x 2π) (error 1.5%)
5.4 x 5.4 h x 3600 = 9.7 x 10747 (error +0.7%)
4.7 x 5.4 h x 3600 = 90560 (error 1%)
(5)
16.1 -9.9 = 6.2 hours x 3600 = 22320 seconds
(6)
(17.2 h -16.1h) = 1.1h = 3960 seconds
(7)
(24/16.1)= (16.1/10.7) (error -1%)
Where
24 h = The Solar Day
16.1 h = Neptune Day Period
10.7 h = Saturn Day Period
Notice
Saturn day period should be 10.8 hours to remove the equation error

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(8)
(24.1/4.7) x 7510 = 3600 x 10.7
Where
24.1 km/s = Mars Velocity
4.7 km/s = Pluto Velocity
10.7 h = Saturn Day Period

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II – Discussion
Equation no. (1)
8 x 16.1h x 3600s = 3 x 155597s = 466884 s
- Where
- 466884 km = Neptune Motion Distance During a solar day = Jupiter motion
distance during Jupiter day period
- Equation no. (1) explains how Neptune circumference be created depending on
Neptune day period – this creation depends on the rate (8/3) (= 2.6666)
- The fact is that
- 4 Saturn days periods total = 10.7 h x 4 = 154080 sec (=155597 km error 1%)
- And
- 8 Neptune days periods total = 466884 sec= 3 x 155597 sec
- That because
- 12 Saturn days periods total = 128.4 hours
- 8 Neptune days periods total = 128.8 hours
- The difference 0.4 hour = 1440 seconds
- That explain the connection between the 2 periods –
- But
- Why Neptune moves during its day period a distance = 466884 km = 3 Neptune
Circumferences = and can be = 8 Neptune days periods total if 1 km = 1 sec?
- Where
- Jupiter motion distance during Jupiter day period be = 466884 km
- How to understand this data??

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Equation no. (2)
8 x 466884 km = 31 x 120536 km
- Where
- 120536 km = Saturn diameter
- We notice that,
- (1)
- Neptune moves during 22320 seconds a distance = 120536 km
- The period 22320 seconds = 6.2 hours = the difference between Neptune day
period 16.1 hours and Saturn day period 10.7 hours
- (2)
- Neptune moves during 10800 seconds a distance = 58320 km =3600 x 16.2
- (3)
- (466884 sec /86400 sec) = 5.4 (error 0.6%)
- Also
- We need to ask (How Planet Velocity Be Defined?)
- Let's try to answer this question with the next equation
Equation no. (3)
16.1 -10.7 = 5.4 but 5.4 x 2 = 10.8 hours
(10.8 + 10.7 x 2 = 2 x 16.1)
- Where
- Equation no.(3) is important for many reasons – let's refer to them in following:

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- (1st
Reason)
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance= 373644 km
= Saturn circumference (378675 km) (error 1.3%). Accurately 378675 km is
different from 373644 km by a distance 5031 km
- Saturn needs its day period to be 10.84 hours to move a distance = 378675 km, by
that the difference 5.4 hours x 2 = 10.8 hours can be used as a period of time for
Saturn to move a distance = its circumference, more better than Saturn day 10.7
hours –that makes equation no. (3) important equation – but why Saturn day period
isn't equal = 10.84 hours and enable Saturn to move in its day period a distance =
its Circumference?
- We should discuss this question deeply – but for a short notice – that be a result of
Neptune motion effect on Saturn- let's add one more data in following
- Additional data no. (a)
- Neptune (5.4 km/s) moves during Saturn day period (10.7 h) a distance =208008
km and
- Uranus (6.8 km/s) moves during (30589 seconds) a distance =208008 km
- The point is that,
- Uranus orbital period = 30589 days and Uranus uses in its motion (30589 sec),
where this period of time be very accurate value has (Zero error), That shows the
period of Neptune motion was accurate also and that shows the period (10.7 h) is
almost created as a result of interaction between the 2 planets motions – and that
tells Saturn day period be defined based on this balancing of the 2 planets motions
periods.
- (2nd
Reason)
- We have 2 data pushed us to ask the question how the planet velocity be created?
which are:
- (466884 sec /86400 sec) = 5.4 (error 0.6%)
- And

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- 16.1 -10.7 = 5.4 but 5.4 x 2 = 10.8 hours
- Neptune velocity (5.4 km/sec) needs very happy pure coincidence to be equal the
rate (5.4) in the previous 2 data – otherwise – Neptune velocity be created based
on this proportionality between the periods of time
- (3rd
Reason)
- The 4 Planets Velocities
- (9.7 /5.4) = 4π / 7
- (6.8 /5.4) = 4/ π (1%)
- (9.7 /6.8) = π2
/ 7 (1%)
- (9.7/5.4) + (13.1/9.7) = π
- Where
- Again we need to ask (how planet velocity be defined?) the data provides a
complete different vision from Newton theory and hypotheses –no planet moves
independent motion and no velocity be defined independently – Newton is wrong
– but – how a planet velocity be defined?

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Equation no. (4)
24.1 x 5.4h x 3600 = 466884 km
13.1 x 5.4h x 3600 = (51118 km x5)
9.7 x 5.4h x 3600 = (378675 km /2)
6.8 x 5.4h x 3600 = (21346.6 km x 2π) (error 1.5%)
5.4 x 5.4 h x 3600 = 9.7 x 10747 (error +0.7%)
4.7 x 5.4 h x 3600 = 90560 (error 1%)
- Where
- And
- 51118 km = Uranus Diameter
- 21346.6 km = Mars Circumference
- 90560 days = Pluto orbital period
- Equation no. (4) shows that, the period 5.4 hours (= around 50% of Saturn day
period), this period is a specific one because 6 planets move defined distances
during it.
- Let's analyze Neptune Motion in following:

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Neptune Motion Analysis
- 0.466884 mkm x 344.6 days = 160.9 mkm
- (if 10 mkm = 1 hour, So, 160.9 mkm = 16.1 hours = Neptune Day Period)
- But
- Jupiter moves during its day period (9.9 hours) a distance = 0.466884 mkm
- Means, during (344.6 Jupiter days period) Jupiter moves 160.9 mkm
- 344.6 Jupiter days periods = 3411.5 hours
- But
- The 4 inner planets orbital circumferences total (Mercury + Venus +Earth + Mars)
be = (360 mkm + 680 mkm + 940 mkm + 1433 mkm) = 3411.5 mkm
- If 1 mkm = 1 hour, the 2 values will be equal
- That means, There's a number (10) between Jupiter and Neptune Motions!
- Let's try to discover what does that mean
- 160.9 mkm / 9.9 = 16.26
- Neptune Day period = 16.1 and different from 16.26 with 1%
- That means, there's interaction of motions between Neptune and Jupiter motions,
and based on this interaction, Jupiter and Neptune Days Periods be created.
- That means, the 2 days periods (9.9 h and 16.1 h) be created depending on one
another – as a result for the 2 planets motions interaction
- Shortly
- Because Jupiter motion during its day period =466884 km = Neptune motion
during a solar day – This equality of distances be found as a result for an
interaction between Jupiter an Neptune motions and based on this interaction the 2
planets days periods of time be created depending on one another.
- Notice
- The rate (10) which we search for be seen here and we understand that the
proportionality of data be found for a geometrical necessity which is to transport
this rate (10) from Neptune and Jupiter motions to Saturn motion

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- Notice
- Because Mercury Motion effects on Jupiter and Neptune motions, Can that be the
reason behind the 2 planets motions interaction –
- Mercury Motion effect on Jupiter motion – because
- Mercury moves during its day period a distance =720.7 mkm = Mercury Jupiter
Motion
- And
- Mercury Motion effect on Neptune motion – because
- Mercury moves during 84 days a distance =344 mkm
- where 1 solar day of Mercury motion be = 344.6 solar days of Neptune motion
- These 2 data refer to Mercury motion effect on the 2 planets motions and this
effect may cause the 2 planets motions to create interaction depending on Mercury
Motion as a point of connection between the 2 planets
- Based on the previous data and discussion we have to extend our analysis for the
three planets motions –
- Let's do that in the next point of discussion under title (3-5 Mercury Motion effect
on Jupiter and Neptune Motions)

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14-5 Mercury Motion effect on Jupiter and Neptune Motions
I – Data
(1)
3446000 km =29.8 km/s x2 x 16.1 x 3600
And
3446000 = 327.6 x 10519
(2)
59800 days = 133 x 2 x 224.7 days
(3)
32200 mkm = 133 x 243 mkm
(4)
90560 mkm = 133 x 680 mkm
(5)
28244 mkm = 133 x 108.2 x 2 (error 1.8%)
(6)
31055 days = 133 x 2 x 116.75 days
(7)
1.609 mkm = 133 x 12104 km
(8)
16.1 x 10.7 x 2 = 344.6
(9)
243 x 14181 = 344.6 x 104
(10)
3446460 hours = 2820 h x (4920/4)
(11)
2π x 32200 mkm = 28244 mkm + 2π x 27705 mkm

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(12)
3.024 mkm x 10648 days =32200 mkm
And
88000 km x 10648 days = 937 mkm - And
0.466884 km x 10648 days = 4971 mkm
(but 4971 solar days =119304 hours which is different with 120536 by 1%)

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II – Discussion
Equation no. (1)
3446000 km =29.8 km/s x 2 x 16.1 x 3600
And
3446000 = 327.6 x 10519
- Where
- 327.6 days = The moon sidereal year
- 10500 = The number of Jupiter days in Jupiter orbital period
- Earth (29.8 km/s) moves during 2 Neptune days a distance = 3446000 km
- We know that
- 1 Solar Day of Mercury Motion = 344.6 Solar Day of Neptune Motion
- The distance 3446000 km can be = 344.6 days if 10000 km = 1 day
- The data analysis gave us another rate which is 1000 km = 1 day , this rate we
have concluded from the moon daily displacement (88000 km) because Mercury
orbital period = 88 days and from long time we have asked if 1000 km be = 1day,
that will make the moon daily displacement (88000 km) be related perfectly with
the moon daily displacement – specially – Mercury Day Period= 175.94 solar days
and the moon orbital motion needs a displacement =2 x 88000 km as we prove that
in the moon orbital motion equation discussion in point no. (7-11)
- By that the rates are different
- Although it's a correct motion that the distance 3446000 km be done by Earth
motion but –our idea can't work because of the suggested rate– 1 day = 10000 km
isn't supported clearly by motions - But

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- Let's remember the following data
- 344.6 of Jupiter days = (344.6 x 9.9h = 3412 hours) and the 4 inner planets orbital
circumferences total be = (360 + 680 +940 +1433 = 3412 mkm) by that we can
suppose 1mkm = 1 hour
- And
- Neptune moves during 344.6 solar days a distance = 160.9 mkm
- If 10 mkm be = 1 hour by that this distance 160.9 mkm will be = 16.1 hours =
Neptune Day Period
- In comparison we see the rate (10) is found between the 2 calculations,
- And this same rate (10) be found between the (10000 km) and (1000km) , from
this data we can conclude that a great geometrical machine be found behind this
data – and this machine connects Mercury, the moon, Jupiter, Neptune and Earth
motions together – it's a very great one
- But our job be some how clear, we need to know how the rate (10) be produced as
a rate between Neptune and Jupiter motion and be used between Mercury and the
moon motion and why that's done?
- Let's do that in a separated Point no.(13-6) under the Tile (Earth Motion Distance
Daily Analysis)
-
- Notice
- During 2 Neptune days periods (2 x 16.1 h)
- Jupiter (13.1 km/s) moves 1518552 km = 50% of Venus motion distance during a
solar day
- Saturn (9.7 km/s) moves 1124424 km = Jupiter motion distance during a solar day
- Neptune (5.4 km/s) moves 625968 km = 4 x 155597 km (Neptune Circumference)
- Earth (29.8 km/s) moves 3446000 km

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Equation no. (2)
59800 days = 133 x 2 x 224.7 days
- Where
Equation no. (3)
32200 mkm = 133 x 243 mkm
- Where
- 32200 mkm = The different distance between Pluto orbital circumference
(37100mkm) and Jupiter orbital circumference (4900 mkm)
Equation no. (4)
90560 mkm = 133 x 680 mkm
- Where
- 90560 days = Pluto orbital period
- 680 mkm = Venus orbital circumference
Equation no. (5)
28244 mkm = 133 x 108.2 x 2 (error 1.8%)
- Where
- 28244 mkm = Neptune orbital circumference
- 108.2 mkm = Venus orbital distance
Equation no. (6)
31055 days = 133 x 2 x 116.75 days
- Where
- 116.75 days = Venus Day Period

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- 31055 s =??
- What's 31055 seconds? It's 50% of Uranus day period where
- (61920 sec /62110 sec) = (360/361)
- That creates some relationship between Uranus day period and Venus day period –
where we know that – Venus moves during 12104 sec a distance = Uranus motion
distance during its day period
Equation no. (7)
1.609 mkm = 133 x 12104 km
- Where
- 12104 km = Venus diameter
- 16.1 hours = 1.61 hours x 10
- Equation no. (7) tells that, Venus diameter be used as a period of time (12104 sc)
because it originated from Neptune day period (16.1 hours)!
Equation no. (8)
16.1 x 107.2 x 2 = 344.6
- Where
- 16.1 hours = Neptune day period
Equation no. (9)
243 x 14181 = 344.6 x 104
- Where
- 243 solar days = Venus rotation period
- 14181 = Pluto days number in Pluto orbital period
Equation no. (11)
2π x 32200 mkm = 28244 mkm + 2π x 27705 mkm
- 32200 mkm = the different distance between Pluto orbital circumference (37100
mkm) and Jupiter orbital circumference (4900 mkm)

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- 2 x27705 mkm = the distance be passed by Neptune in (344.6 days)2
where 1
Mercury solar day = 344.6 Neptune solar day because of that (344.6 day) of
Mercury = (344.6 days)2
of Neptune
Equation no. (12)
3.024 mkm x 10648 days =32200 mkm
And
88000 km x 10648 days = 937 mkm - And
0.466884 km x 10648 days = 4971 mkm
(but 4971 solar days =119304 hours which is different with 120536 by 1%)
Where
3.024 mkm = Venus motion distance during a solar day
10648 days = very near to 10747 days Saturn orbital period (error 1%)
32200 mkm = the different distance between Pluto orbital circumference (37100
mkm) and Jupiter orbital circumference (4900 mkm)

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14-6 Earth Motion Distance Daily Analysis
I – Data
(1)
Earth (29.8 km/s) moves during a solar day a distance = 2574720 km
(2)
Pluto (4.7 km/s) moves during its day period (153.3 h) a distance = 2593836 km
(3)
The moon displacements total during 29.53 days = 2598693 km
(4)
Uranus (6.8 km/s) moves during 378675 seconds a distance = 2574990 km
(5)
Saturn 10 orbital periods = 2579280 km
(6)
10 x 10747 days x 24 h= 10.7 x 2 x 120536 =2579280 hours
(7)
629 mkm = 40080 hours x 15694 km

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II – Discussion
The Moon Orbit Analysis
- The moon daily displacement =88000 km
- During 29.53 days the moon displacements total during 29.53 days =2598640 km
- We know this circumference be = 2π x 413600 km
- Means, the moon orbital apogee radius should be 413600 km
- And
- Jupiter (13.1 km/s) moves during 263053 sec a distance = 3446000 km
- But
- Saturn (9.7 km/s) moves during 263053 sec a distance = 2551614 km (the moon
apogee circumference ) where (the apogee radius =406000 km)
- Let's remember the question
- Where can we find the rate (10) which was between (10000) and (1000)?
- It's found in Saturn motion which causes the moon orbital circumference to be
2551614 km -
- Notice
- Please remember Earth moves during 2Neptune days periods total a distance = =
3446000 km
- Equation no. (6)
- 10 x 10747 days x 24 h= 10.7 x 2 x 120536 =2579280 hours
- Where
- 2574720 km = Earth motion distance during a solar day which is different from the
moon apogee orbital circumference (2551614 km) with (+1% ) and different from
the moon displacements total 2598640 km with (-1%)
- Earth motion distance (2574720 km) can be equal Saturn Value (2579280 h) if
1km = 1 h
- But how that can be possible? Where can we find this rate 1 km = 1 h??
- Let's see Equation no. (7)

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- Equation no. (7)
- 629 mkm = 40080 hours x 15694 km
- Where
- 40080 km = Earth Circumference and used here as a period of time (40080 h)
- 15694 km = Planet motion Distance During 1 hour (Pluto)
- Let's move step by step
- We need to find the rate 1 km = 1 hour because based on this rate we will compare
Saturn Period 2579280 hours with Earth motion distance during a solar day =
2574720 km
- I suppose Earth Circumference (40080 km) be used as a period of time based on
this same rate (1km= 1 h) and by that (40080 km) will be =(40080 hours)
- Pluto moves during 40080 hours a distance = 629 mkm = Earth Jupiter Distance
- I use this data as a proof for the motion existence – means- if the motion is an
imaginary one the passed distance should not be defined distance and also be
related to Earth distances – by that I use the distance 629 mkm as a proof for the
motion existence
- But
- Pluto moves during 1 hour a distance = 16920 km and not 15694 km
- And
- 16920 km = 1.0725 x 15694 km
- We know the rate (1.0725) which is used as a rate between more than 40% of all
distances in the solar system – the suggested idea to explain the rate (1.0725) using
is that – this rate be found by Lorentz Length Contraction Phenomenon – means-
(for example) the distances was 16920 km but became 15694 km by length
contraction effect on it – means –Pluto moves 16920 km but we see it as 15694 km
because of the contraction effect –
- Please remember

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- This same rate (1.0725) effects on the moon daily motion – where the moon moves
per a solar day a distance = Earth motion distance per a solar day = 2.574 mkm,
But the rate (1.0725) contracted this distance and caused it to be 2.4 mkm daily
that creates the necessity for the moon to move its daily displacement to cover the
different distances (2 x 88000 km) – (that causes the moon used velocity be 27.78
km/sec)
- This idea is explained and proved clearly in The Moon Orbital Motion Equation
point no. (7-11)
- Please notice
- The moon (27.78 km/s) moves during 1 hour a distance = 100000 km
- And
- 100000 km=6.37 x 15694 km
- Where the rate 6.37 is the working rate between Earth and Pluto motions –because
many data shows this fact – for example
- 5906 mkm (Pluto orbital distance) = 6.3 x 940 mkm (Earth orbital circumference)
- 153.3 h (Pluto day period) = 6.3 x 24 h (Earth day period) (error 1.6%)
- Also
- 406000 mkm (Pluto motion distance daily) = 4.61 x 88000 km (the moon daily
displacement)
- 708.7 h (the moon day period) =4.61 x 153.3 h (Pluto day period)
- Notice
- We find the rate (10) be using by Saturn motion for the moon motion –that means
– the rate be found between Neptune and Jupiter motions based on an interaction
and by this interaction the rate (10) be transported through the motions till reach to
Saturn motion which is used for the moon motion and by this rate Mercury and the
moon motions shows their dependency

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14-7 Uranus Day Period Analysis
- (1)
- Uranus day period =17.2 hours = 61920 seconds
- Uranus orbital period = 30589 solar days
- We will use this period as 30589 seconds
- Uranus day period = 61920 seconds = 2 x 30589 seconds + 742 seconds
- The value 742 seconds be 1% of Uranus day period
- (2)
- During 30589 hours Uranus moves 748.8 mkm
- If 1 mkm = 1 second the 2 values (748.8 mkm and 742 seconds) will be equal with
an error = (1%)
- (3)
- Why do we need to analyze Uranus Day Period here? Because
- The moon daily displacement is 88000 km and the moon needs to move daily
double this distance – means the moon moves 88000 km but needs 2 x 88000 km
- I imagine that the moon and Mercury motions be done together as one motion – in
this motion the rate (1000 km = 1 hour) be used –and based on that – the moon
daily displacement 88000 km be seen in Mercury motion as 88 solar days and as a
result Mercury Day Period 175.94 solar days will be used as the distance required
for the moon motion (88000 km x 2=176000 km)
- The point here is, Uranus moves during (30589 hours) a distance = 748.8 mkm but
- Uranus day period (61920 seconds) = 2 x 30589 seconds + 742 seconds
- Regardless all difficulties and geometrical requirements – the idea is that –
- Uranus uses one (30589) in motion but the data uses two values of (30589), that's
what we search for because the moon moves only 88000 km but the moon motion
data needs 176000 km – and this behavior is similar to Uranus data behavior
because of that we search after it to know if there's a connection between the moon
and Uranus motions data be done through Mercury Motion.

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I-Data
(1)
748.8 mkm =0.5875 mkm / day x 1274.6 days
(2)
748.8 mkm = 84 x 8.9142
(3)
929 mkm x 0.8 = 743.2 mkm
(4)
86400 seconds = 743.2 x 116.25
II – Discussion
Equation no. (1)
748.8 mkm =0.5875 mkm / day x 1274.6 days
- This equation tells that Uranus moves during 30589 hours (or 1274.6 solar days)
a distance = 748.8 mkm
- We know that – the point we need from this equation is that – the period 30589
hours = 1274.6 solar days
- Where
- Metonic Cycle =19 years = 254 sidereal months = 6939.75 days
- 1290 degrees = 254 x 5.1 degrees (error 0.5%)
- Where
- 5.1 degrees = the moon orbital inclination
- The value 1274.6 degrees is different from 1290 degrees with around 1.5%
- If 1 degree = 1 day
- The period 1274.6 days should be related to the moon motion –

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- Notice
- Uranus (6.8 km/s) moves during the period 742 seconds a distance = 5045 km
- Uranus (6.8 km/s) moves during the period 5040 seconds a distance = 34272 km
- (34272 km = π x 10921 km the moon circumference)
- Mercury Day Period needs 5040 seconds to be = 4224 hours
- If 1 km = 1 second
- The distance 5045 km may be the reason of Mercury period 5040 sec Creation,
that means, Uranus motion effect on Mercury motion and caused to make its day
period less than 4224 hours with 5040 seconds by using the period ( 742 second)
of Uranus data
- Spite the machine is a complex one but the data moves in the right way and guides
us clearly to define the selected point of effect.
- Shortly
- Uranus motion interaction for the period (742 sec) between Uranus day and orbital
periods hide a complex machine which effected on Mercury motion and caused
Mercury Day Period to be less than 4224 hours with 5040 seconds – this effect
almost caused Mercury Day Period to be = (2 x Mercury orbital period) which is
the necessary question for the moon motion, which moves daily a displacement
=88000 km but needs 176000 km otherwise it will be separated from Earth in their
course of motions.
- I want to say that
- Mercury Day Period be = 2 Mercury orbital periods for geometrical necessity
related to the moon daily motion which does a necessary job for the moon without
which the moon can't move its orbital motion neither around The Earth nor around
the Sun

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Equation no. (2)
748.8 mkm = 84 x 8.9142
- This equation shows Neptune Effect on Mercury Motion through the same
distance 748.8 mkm
- We know that
- Neptune orbital period (59800 days) has a number 89142 of Neptune days (16.1 h)
- And
- Mercury Day Period needs 5040 sec = 84 minutes to be 4224 hours
- And
- Mercury moves during 84 solar days a distance = 344 mkm
- Where
- 1 day of Mercury Motion = 344.6 days of Neptune Motion
Equation no. (3)
929 mkm x 0.8 = 743.2 mkm
- Where
- 743.2 mkm is near to our discussion distance (748.8 mkm) (error 0.8%)
- 929 mkm =Earth Jupiter distance when they be on 2 different sides from the sun
- 940 mkm = Earth orbital circumference (error 1% only with 929 mkm)
- The equation shows that, Uranus effects on Earth motion by 2 data of its motion
which are (0.8 degrees = Uranus orbital inclination) and the distance 743.2 mkm
- Earth Jupiter distance be = 929 mkm when the 2 planets be on 2 different sides
from the sun by that the total (929 mkm = 778.6 mkm +149.6 mkm) –
- The equation tells this distance (929 mkm) is defined by Uranus motion effect on
the Earth motion – based on this distance (929 mkm) Earth created its orbital
circumference 940 mkm which is different with 1.2 % only – this behavior is a

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usual behavior in the 3 inner planets motions –which we have discussed deeply
before – let's remember this data in following
- Venus Jupiter distance = 670.4 mkm but Venus orbital circumference =680 mkm
the difference is 1.2% - also
- Mercury moves during its day period a distance = 720.7 mkm =Mercury Jupiter
Distance
- Mars is exceptional is almost because of Mars Migration which we discuss and
prove in point no. (9) of this paper
- The 3 inner planets (Mercury – Venus – Earth) create their orbital circumferences
equal or at least a function in their distances to Jupiter
- I want to say that
- Uranus motion effects on the Earth motion to define its distance to Jupiter and
based on this distance Earth orbital circumference be defined which means Uranus
effects on Earth motion to define its orbital circumference
Equation no. (4)
86400 seconds = 743.2 x 116.25
- 743.2 = the distance be used in the previous equation no. (3) but be used here as a
rate
- 86400 seconds = the solar day
- 116.25 = 365.25 /π
- The equation tells that 365.25 days can be 1 solar day
- It's the rate of the sun
- One day of the sun motion = 365.25 days of Earth motion
- The equation defines Earth orbital period (365.25 days) based on the sun one day
and by an effect of Uranus motion
- Notice
- The value 743.2 is so accurate value in previous both equations for that I can't
change it neither with (742) nor with (748.8) –

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- Clearly it's a mentioned number and not be equal either
- The error is so small with and because of that no search behind it to know why this
number (743.2) isn't = (742) accurately – in fact the number 116.25 can't change at
all because of 365.25 and π
- The data tells that Uranus effect to define Earth orbital circumference and period
and by that effects on Earth motion.
- That support the hypothesis tells (the Earth moon move Metonic Cycle which
extends for 19 years under Uranus motion effect on the moon motion)

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14-8 The Inner Planets Motions Analysis
- We analyze the inner planets distances to Jupiter as passed distances by their
motion – let's start in order
(1) Mercury Motion
- 720.7 mkm (Mercury Jupiter Distance) = 0.17064 mkm x 4222.6 hours
- Where
- 0.17064 mkm = Mercury Motion Distance during one hour
- 4222.6 hours = Mercury day period
- Let's move step by step
- (a)
- 720.7 mkm (Mercury Jupiter Distance) = 0.17064 mkm x 4222.6 hours
- (4222.6 hours = Mercury Day Period) and ( 0.17064 mkm = Mercury motion
distance during one hour)
- (b)
- Suppose 1 h = 1 mkm
- 4222.6 mkm = 0.17064 mkm x 24746 hours (Neptune radius =24746 km)
- (c)
- Suppose 1 h = 1 km
- 24746 km = 47.4 km/s x 522 seconds
- Light (0.3 mkm/s) moves during 522 seconds a distance = 2x 78.3 mkm (Earth
Mars Distance)
(2) Venus Motion
- (a)
- 670.4 mkm (Venus Jupiter Distance) = 0.126 mkm x 5320.6 h
- (0.126 mkm = Venus motion Distance during one hour)
- (5320 hours =221.7 days = Venus orbital period 224.7 days error 1%)
- (b)

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- 5320.6 mkm = 0.1264 mkm x 4222.6 hours x 10
- (c)
- 4222.6 mkm x 10 = 0.126 mkm x 335127 hours
- (d)
- 335127 km = 35 km/s (Venus velocity) x 9575 seconds
- Light (0.3 mkm/s) moves during 9575 seconds a distance = 2872.5 mkm (Uranus
Orbital Distance)
(3) Earth Motion
- (a)
- 928 mkm = Earth Jupiter Distance when the 2planets be on 2 different sides from
The Sun
- 928 mkm (Earth Jupiter Distance) = 0.10728 mkm x 8652.6 h
- (0.10728 mkm = Earth motion Distance during one hour)
- (8652.6 hours = 360.5 solar days)
- (b)
- 8652.6 mkm = 0.10728 mkm x 80652 hours
- (c)
- 80652 km = 29.8 km/s (Earth velocity) x 2706.5 seconds
- Light supposed velocity (0.3 mkm/s) moves during 2706.5 seconds a distance = 4
x 778.6 mkm (Jupiter Orbital distance) (error 0.8%)

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(4) Mars Motion
- (a)
- 550.7 mkm = Earth Jupiter Distance
- 550.7 mkm (Mars Jupiter Distance) = 0.08675 mkm x 6348 h
- (0.08675 mkm = Mars motion Distance during one hour)
- (6348 h =264.5 days = (16.23)2
- (b)
- 6348 mkm = 0.08675 mkm x 73175.8 hours
- (c)
- 73175.8 mkm = 0.08675 mkm x 843525 hours
- (d)
- 843525 km= 24.1 km/s (Mars velocity) x 35001 seconds
- Light (0.3 mkm/s) moves during 35001 seconds a distance =10500 mkm
- Notice
- 35001 km = Saturn Motion Distance During One Hour

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Discussion
- Let's refer to some significant noticeable observations in the previous data in
following:
- (1)
- Saturn orbital period (10747 days) has 10500 Mars rotation periods – the number
10500 is related basically to Jupiter because Jupiter orbital period has 10500
Jupiter days – we didn't understand why Saturn orbital period has 10500 Mars
rotation period – Mars Motion Data shows that the number 10500 connects light
motion with Mars motion where Mars motion connects also with Saturn motion
- (2)
- We keep our eye on the rate (10) for which we search through the planets motions
and in this discussion we find it in Venus motion.
- (3)
- Planets diameters and circumferences be produced through these motions as
distances and be used as periods of time – for example – Mercury moves during a
period = 24746 hours a distance = 4222.6 mkm, where
- (Neptune radius =24746 km)
- Also
- The distance 33512.7 km = 35 x 9575 seconds = 27.78 x 12104 seconds
- Where
- 27.78 km/s = the moon velocity
- 12104 km = Venus diameter
- That creates the harmony between the planets diameters and their motions – and
that enable the planets to use their diameters and circumferences as periods of
time.
- Let's analyze Venus motion – We bring the data to be the discussion reference

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Venus Motion Analysis
- (a)
- 670.4 mkm (Venus Jupiter Distance) = 0.126 mkm x 5320.6 h
- (0.126 mkm = Venus motion Distance during one hour)
- (5320 hours =221.7 days = Venus orbital period 224.7 days error 1%)
- (b)
- 5320.6 mkm = 0.1264 mkm x 4222.6 hours x 10
- (c)
- 4222.6 mkm x 10 = 0.126 mkm x 335127 hours
- (d)
- 335127 km = 35 km/s (Venus velocity) x 9575 seconds
- Light (0.3 mkm/s) moves during 9575 seconds a distance = 2872.5 mkm (Uranus
Orbital Distance)
- What does this data tell us?
- We have 4 parts of motions – all of them be done by Venus Motion - means we
have one player behind this data
- The data moves in a network connects one another and by that no data be
separated or independent
- The motion connects between the distance 670.4 mkm (Venus Jupiter Distance)
and the distance (2872.5 mkm) (Uranus orbital Distance) by interaction with light
motion.
- The motion system uses the passed distances as a period of time by different rates
of time
- This system of motion creates the distances in a network form – and the data
shows the used machine to produce this network of the solar system distances

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Venus Jupiter Distance Analysis
Venus Jupiter Distance = 670.4 mkm
Planet needs time (t) to pass a distance = 670.4 mkm
Mercury (0.17064 mkm per hours) needs 3929 hours (163.7 days)
Venus (0.126 mkm per hours) needs 5320.6 hours (221.7 days)
Earth (0.10728 mkm per hours) needs 6251 hours (260.5 days)
Mars (0.08676 mkm per hours) needs 7728 hours (322 days)
Jupiter (0.04716 mkm per hours) needs 14215.2 hours 592.3 days)
Saturn (0.03492 mkm per hours) needs 19200 hours (800 days)
Uranus (0.0234 mkm per hours) needs 27386.5 hours (1141 days)
Neptune (0.01944 mkm per hours) needs 34460 hours (1436.3 days)
Pluto (0.01692 mkm per hours) needs 39629.6 hours (1651.23 days)
Data Analysis
- Let's use Neptune motion as example
- Neptune needs 34460 hours to move a distance =670.4 mkm (Venus Jupiter
Distance)
- But
- 1 hour of Mercury motion = 344.6 hours of Neptune motion
- By that 34460 h of Neptune motion = 100 h of Mercury motion
- During 34460 hours Neptune moves 670.4 mkm (Venus Jupiter Distance)
- And
- During 100 hours Mercury moves 17.1 mkm – what's this 17.1mkm?
- 17.1 mkm x 2π = 108.2 mkm = Venus Orbital Distance
- The 2 planets motions pass distances related to Venus motion data- why? because
we use the distance 670.4 mkm (Venus Jupiter Distance) –
- I want to say

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- because the basic distance related to Venus all planets motions based on their rates
of time will pass distances related to Venus with different forms
- For example
- Venus needs 5320.6 hours to pass a distance 670.4 mkm (Venus Jupiter Distance),
and 1 hour of Venus = 3.057 hours of Mars by that the period 5320.6 h for Venus
motion will be = 5320.6 x 3.057 = 16265 hours for Mars motion
- Mars moves during 16265 hours a distance = 1411.2 mkm (Pluto Neptune
Distance) but 1411.2 mkm = 2π x 224.7 mkm (where Venus orbital period be
224.7 solar days and the distance be used as a period of time by the rate 1 mkm = 1
day)
- I try to explain how the planets motions data be created in proportionality with one
another – the data uses different passages to create each other but these passages
be found based on the planets motions – the point is that – the motions are not
clear – the planets do thousands of specific motions which be integrated in the
planets motions revolving around the sun and by that the specific motions are not
observed – where the data be created based on another by these specific motions –
- Please Note
- The analysis needs extension but the data can cause confusion – let's see one more
data only –
- Mercury moves in 100 hours (or 101 hours) a distance = 17.2 mkm where Pluto
orbital inclination = 17.2 degrees and Uranus day period =17.2 hours – the data
shows proportionality but no clear explanation for that – but the deep analysis
shows more proportionality – because the period 101 h = 366560 s (1% error)
where the outer planets diameters total = 366560 km we need only to suppose that
1km = 1 second – this data is still complex because 53.9 h (the 4 outer planets days
periods total) = π x 17.2 h (Uranus day period)
- I try to show that – the planet motion be done for specific distances – each distance
be used by another planet motion in different forms (weather as a distance or as a

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time) and the planet revolution around the sun is the summation of all these
specific distances – the summation covers the parts
- For example
- Jupiter diameter =142984 km = 8 planets diameters total (+ the Earth moon)
(no error)
- When we use Jupiter diameter (142984 km) we use in fact 9 planets diameters total
– it's a system be used on the solar system motion – as a result for this system
using the planets motions data be created based on one another – for example
- (Neptune orbital circumference 28244 mkm / Mercury Jupiter distance 720.7 mkm) =
- (Pluto orbital distance 5906 mkm / Earth orbital distance 149.6 mkm) =
- (Saturn orbital circumference 9007 mkm / Mars orbital distance 227.9 mkm) =
- (Venus orbital circumference 680 mkm / the distance 17.2 mkm) =
- (Uranus Neptune distance 1622.7 mkm / Venus Earth distance 41.4 mkm) =
- (Neptune orbital period 59800 days x 2 / Uranus Pluto distance 3030 mkm) =
- Max error (1%) - Many similar data can be added here –
- Notice
- I don't choose the numbers, I test them, means,
- In Venus motion we have 3 parts each part produces one period which are (a)
(4222.6 x 10 hours) (b) (335127 hours) (c) (9575 seconds)
- I don't choose the last one (9575 sec) to be used for light motion – it's the period
during which the light passes a defined distance (2872.5 mkm= Uranus Orbital
distance)
- For example, the period 4222.6 seconds can be used by light supposed velocity
(1.16 mkm/s) to pass a distance = 4900 mkm = Jupiter orbital circumference but
the rate (10) prevents us
I mean, I test the values and choose the most near and min error – for that reason
some planets motions use 3 parts of motion (a, b and c) and some planets needs 4
parts of motion

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15- The Sun Age Description
15-1 Preface
15-2 The Sun Circles The Earth
15-3The Rate (1.0725)
15-4 The Sun Diameter Analysis
15-5 The Sun And Earth Motions Rate Of Time (1 day =365.25 days)

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15-1 Preface
- The sun gives 2 reasons disproving Newton Theory of the sun mass gravity, which
are
- (1st
Reason) The sun is created after all planets creation and motion. that disproves
Decisively Newton Theory Of The Sun Mass Gravity
- (2nd
Reason) the sun light velocity =300000 km
- But
- The solar planets and their distances be created out of one light bam its velocity
=1.16 million km per second
- That tells the light known velocity (.3 mkm/s) is created as a product from the
original light beam whose velocity 1.16 mkm/s
- That proves the sun is created after all solar planets creation and motions.
- The fact is that, the sun rays is created from the planets motion energies total as we
should prove in this point. This fact disproves Newton theory decisively
- The sun rays creation depend on the Sun And Earth motions rate of time which is
(1 day of the sun motion= 365.25 days of the Earth motion)
- The historical order can help our analysis.
o After Mars and Pluto migration, Saturn be created
o For that reason the period 10747 days is used by the moon and Saturn
motions (will be discussed in our analysis). (Notice Saturn is the last crated
planet)
o The sun is created after Saturn creation and depends on the period 365.25
days which be inherited in Saturn orbital period (10747 days).

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15-2 The Sun Circles The Earth
- The sun gives one face always to the Earth during the motion. although Earth
revolves around the sun a complete revolution, we always see the same face of the
sun, that tells the sun rotates with us giving The Earth The Same face always
- Can this motion refer to the Sun dependency on the period (365.25 days = Earth
orbital period)?
- Can that lead us to conclude, the sun be created after the Earth and because of that,
The Sun motion takes into consideration the period 365.25 days?
- Also
- The Sun Behavior is similar perfectly to the moon behavior, both give the same
face to the Earth during the motion.
- Why we accept that the moon be created after The Earth Creation but The Sun be
Created Before The Earth Creation? if the 2 behaviors are similar it may prove
both (the sun and the moon) be created after The Earth Creation.

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15-3 The Rate (1.0725)
I- Data
(A)
Why These Distances Are Equal?
(1)
Saturn Orbital Distance = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (error 0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (error 1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (error 1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (error 0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (error 0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π

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(B)
More Data
Why These Distances Are NOT Equal?
10. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
11. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
12. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
13. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
14. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (Error 0.6%)
15. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (Error 0.8%)
16. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (Error 0.7%)
17. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (Error 0.7%)
18

The Sun Creation Process.pdf

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The Sun Creation Process.pdf