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IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Why Saturn Day Period = 10.7 hours?
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –24th
May 2021
Abstract
Paper question
Why Saturn Day Period = 10.7 hours?
The question explanation
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance = 373644 km
= 98.67 % of Saturn Circumference (378675 km).
- The difference between the distance (373644 km) and Saturn Circumference =
5031 km.
- Saturn moves this 5031 km in 518 seconds. Means
- If Saturn day period = 39039 seconds Saturn could move during its day period a
distance = its circumference… why does Saturn day period is shorter with 1.3%?
Paper Argument
- The paper claims, Saturn day period be (10.7 h =38520s) and shorter than the
required period with 1.3% or 518 seconds because of geometrical necessities
- The paper vision supposes that, the solar group is a machine of gears each planet is
a gear in this same machine. Or the solar group is one geometrical design each
planet is a part of it.
- Based on this vision, each planet motion data can't be independent from the other
planets, on the contrary each planet data is created depends on the other planets
data.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
- By that, Saturn motion has to use the day (10.7 h) and cause Saturn to move a
distance less than its circumference because of the geometrical necessities required
for the other planets motions data configuration.
- That's why we analyze Saturn Day Period, because its analysis proves that, the
solar planets motions consist together one unified motion which needs each planet
data to be created in proportionality with the other planets data to create the
general motions harmony.
- (The planets unified motion is similar to the train carriages, they moves together
one general unified motion which necessitates a configuration for each planet
motion data to be in harmony with the others).
Please scan the figure
(ORCID)
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
1- Introduction
- Saturn day period =10.7 hours = π x 3.4 hours
- But
- 3.4 degrees = Venus Orbital Inclination
- Can the inclination (3.4 degrees) have any relationship with 3.4 hours?
- The basic difficulty in the solar system study by using planets data analysis is that,
the data provides us puzzled proportionality which we can't find explanations for
them, and then we have to neglect the data considering that they are found by pure
coincidences of numbers!
- On the other side, The planets data analysis is very useful method to study the
solar system creation and motion because it prevents us from the false imagination,
because the data force us to explain them, they save us always with the facts.
- The provided example is an interesting one, because, we have 2 values use
(different units) and we try to know how this data is created….
- Let's try to see the depth behind this data
o Venus diameter = 12104 km
o Usually this value (12104 km) is used as a period of time for different
planets motions as (12104 seconds), where
o 12104 seconds = 3.4 hours
o If Venus diameter is used as (12104 seconds) so the value 3.4 h may caused
Venus orbital inclination to be 3.4 degrees – Also
o 17.2 hours (Uranus day period) = 3.4 hours x 5.05
o I try to show that, the data is created based on geometrical and mathematical
system of data – which proves that- the solar system in one geometrical
design. The planets can no longer be considered as separated rigid bodies
from each other, but the whole system should be considered as one
geometrical building built based on one geometrical design.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
2- Saturn Day Period Analysis
I- Data
(1)
57.9 mkm = 17.2 mkm x 3.366
(2)
18048 mkm =360 mkm x 50.3
(3)
18048 mkm =17.2 mkm x 1049
(4)
Mercury (47.4 km/s) x 363600 seconds =17.2 mkm
(5)
(Uranus Mass/ Mercury Mass) = (2815.2 hours /10.7 hours)
(6)
(10747 x 24 x 6) =101 x 15323
(7)
(101 h/10.7 h) = (120536 km/12756 km) = (1433.5 mkm/ 151.8 mkm) = (23.4/2.5)
(8)
19 deg = 7 x 3.4 x 0.8
(9)
511 deg =101 x 5.05
(10)
3475 x 5031 = 17.48 mkm
4.7 x 38520 = 3600 x 50.3
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
II- Discussion
Equation no. (1)
57.9 mkm = 17.2 mkm x 3.366
- Where
- 57.9 mkm = Mercury Orbital Distance
- 3.4 degrees = Venus orbital inclination (different from 3.366 with 1%)
- 17.2 mkm = ??
Equation no. (2)
18048 mkm =360 mkm x 50.3
- Where
- 18048 mkm = Uranus Orbital Circumference
- 360 mkm = Mercury Orbital Circumference
- 50.3 mkm = Mercury Venus Distance
Equation no. (3)
18048 mkm =17.2 mkm x 1049
- Where
- 18048 mkm = Uranus Orbital Circumference
- 1047 = The Sun Mass / Jupiter Mass
Equation no. (4)
Mercury (47.4 km/s) x 363600 seconds =17.2 mkm
- Where
- 17.2 mkm = the distance Mercury moves in 101 hours (363600 s)
- The equations from (1 to 4) tell that, Venus data is created as a result of
intersection found between Mercury and Uranus motions. Mercury causes to create
Venus orbital inclination (3.4 deg) and we know that, 3.4 hours =12104 seconds
where 12104 km = Venus diameter.
- This process depends on the distance 17.2 mkm, where Mercury moves this
distance in 101 hours.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
- This explanation is some very simple one considering what's happening really, but
we don't need to make the discussion so complex in its early stage….we need to
keep the eyes on (17.2) this the basic key we need to discuss, let's remember its
data to be in front of us…
o 17.2 deg = Pluto orbital inclination
o 17.4 deg = the inner planets orbital inclinations total
o 23.4 deg = Earth Axial Tilt
o 23.6 deg = the outer planets orbital inclinations total
o 23.6 deg +17.2 deg = 17.4 deg +23.4 deg (A Geometrical System Of Data)
o Also
o 17.2 degrees = 17.4 degrees x 0.99
o 23.4 degrees = 23.6 degrees x 0.99
o But
o 17.2 hours = Uranus Day Period
- We should remember that, Uranus motion effected on Pluto motion and caused to
extend its day period to be =153.3 hours, Uranus did that because the solar system
design required that Pluto motion distance in its day period to be = Earth motion
distance during earth day period (error 1%). This equality of distances is a basic
cornerstone in the geometrical design and mechanism.
- That means, the 2 values (17.2 hours and 17.2 degrees) both created depending on
each other (or Pluto orbital inclination 17.2 deg is created depending on Uranus
day period) but Uranus used a geometrical system of data to create this result, and
based on Pluto orbital inclination (17.2 deg) Pluto extended its day period to be
153.3 hours.
- Equation no. (3) shows that Uranus orbital circumference (18048 mkm) depends
on the distance 17.2 mkm and the rate 1049 where (1047) is the rate between the
sun mass and Jupiter mass. that tells the masses gravity effects on this process
greatly.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
- The rate use (Jupiter mass) and not (Uranus mass) because the system of data uses
the inner planets data.
- The distance 17.2 mkm is passed by Mercury (47.4 km/s) in a period =101 hours.
- We know that,
- Mercury Orbital Period 88 days =1.5 x Mercury rotation period 58.66 days
- 1.5 x 101 hours = 151.5 hours (where Pluto day period =153.3 h) (error 1%).
- Shortly
- Based on the distance 17.2 mkm Pluto day period is extending to be 153.3 h
- (Notice, Pluto during 1016 hours moves a distance = 17.2 mkm).
Equation no. (5)
(Uranus Mass/ Mercury Mass) = (2815.2 hours /10.7 hours)
- Where
- 2815.2 hours = 2 x 1407.6 hours (Mercury Rotation Period)
- 10.7 hours = Saturn Day Period = Saturn Rotation Period
Equation no. (6)
(10747 x 24 x 6) =101 x 15323
- Where
- 10747 days = Saturn Orbital Period
- 15323 km = Mercury Circumference
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
Equation no. (7)
(101 h/10.7 h) = (120536 km/12756 km) = (1433.5 mkm/ 151.8 mkm) = (23.4/2.5)
- Where
- 10.7 h = Saturn Day Period
- 120536 km = Saturn Diameter
- 12756 km = Earth Diameter
- 1433.5 mkm = Saturn Orbital Distance
- 151.8 mkm = Earth Orbital Distance (149.6 mkm error 1.5%)
- 23.4 deg = Earth Axial Tilt
- 2.5 deg = Saturn Orbital Inclination
- The equations (5, 6 and 7) try to show that, Venus motion transports some (Data)
between Uranus and Saturn – this is clear from the equation
- (10.7 h/π) = (17.2 h /5.05) = 3.4
- This idea is a simple and direct one but how the motion be transported from a
planet to another? the planet isn't a gear and no collision is occurred to cause the
motion by touches… also we can't depend on the gravity force because of the great
distance between the planets. But the data shows that, some motion is transported
inevitably.
- This is one of the most useful results of the planets data analysis method because it
forces us to follow the facts and don't b lost in the imaginations…
- The data shows that, is a common data used for 3 planets motions which are
Uranus, Saturn and Venus. Where Venus works as a rate between the 2 planets.
- I want to say that, a motion is transported among the planets but w don't know the
geometrical rules based on which the motion is transported that's why we see the
motions data as puzzled data.
- The rate which we need to follow now is the rate (101) based on which the rate
between Mercury orbital period and rotation period caused Pluto day period to be
=153.3 hours.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
- The data tells, Uranus motion effect on Mercury motion and by that Uranus
defined Mercury motions periods (the orbital and rotation periods), this definition
is done by creation Venus orbital inclination 3.4 degrees (that tells Mercury cycles
periods depend on 3.4 degrees or hours)
- Mercury cycles periods caused Pluto day period to be 153.3 hours
- This process is done by interaction with Saturn because of that Saturn data is found
in all equations
- Why?
- Because Pluto day period and orbital inclination are defined based on a
geometrical mechanism found inside the moon orbit.
Equation no. (8)
19 deg = 7 x 3.4 x 0.8
- Where
- 7 deg = Mercury orbital inclination
- 3.4 deg = Venus orbital inclination
- 0.8 deg = Uranus orbital inclination
- 19 deg = the moon orbit regresses per year 19 degrees
Equation no. (9)
511 deg =101 x 5.05
- Where
- 511 deg = the planets axial tilts total
- The data shows that, the rate (101) expresses a general motion, because the value
(5.05) shows a motion transportation as we have discussed before and 511 deg (the
planets axial tilts total) that tells we deal with a general motion done by many
planets.
- That shows the facts because Pluto day period extension is one result of 4 results
(at least) are done by the interaction of motions inside the Earth moon orbit let's
remember these 4 results in following:
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
o Saturn day period be (10.7h=38520 s) less than the require period 39039 s to
move a distance = Saturn circumference (- 518 sec)
o Mercury day period be 4222.6 hours, less than 176 solar days with 5040
seconds.
o The moon orbital apogee circumference be 2550973 km less than the moon
displacements total during 29.53 days with 47720 km (2%)
o Pluto day period be 153.3 hours.
IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
References
Can Saturn Motion effect on Venus Motion?
https://www.academia.edu/49005865/Can_Saturn_Motion_effect_on_Venus_Motion
Did Lorentz Ask (How The matter is Created)?
https://www.academia.edu/48987206/Did_Lorentz_Ask_How_The_matter_is_Created_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Twitter https://twitter.com/GergesTawdrous1
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
box https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous
Please scan the figure
(ORCID)

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Why Saturn Day Period = 10.7 hours,

  • 1. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 1 Why Saturn Day Period = 10.7 hours? The Author Authorized To Be Used By Mr. Gerges Francis Tawdrous A Student–Physics Department- Physics & Mathematics Faculty – Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Dr. Budochkina, Svetlana Aleksandrovna Associate Professor (Mathematical Analysis and Theory of Functions Department) Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Phone +201022532292 E-Mail: mrwaheid@gmail.com Curriculum Vitae http://vixra.org/abs/1902.0044 Phone +7 (495) 952-35-83 E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru Website http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024 The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –24th May 2021 Abstract Paper question Why Saturn Day Period = 10.7 hours? The question explanation - Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance = 373644 km = 98.67 % of Saturn Circumference (378675 km). - The difference between the distance (373644 km) and Saturn Circumference = 5031 km. - Saturn moves this 5031 km in 518 seconds. Means - If Saturn day period = 39039 seconds Saturn could move during its day period a distance = its circumference… why does Saturn day period is shorter with 1.3%? Paper Argument - The paper claims, Saturn day period be (10.7 h =38520s) and shorter than the required period with 1.3% or 518 seconds because of geometrical necessities - The paper vision supposes that, the solar group is a machine of gears each planet is a gear in this same machine. Or the solar group is one geometrical design each planet is a part of it. - Based on this vision, each planet motion data can't be independent from the other planets, on the contrary each planet data is created depends on the other planets data.
  • 2. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 2 - By that, Saturn motion has to use the day (10.7 h) and cause Saturn to move a distance less than its circumference because of the geometrical necessities required for the other planets motions data configuration. - That's why we analyze Saturn Day Period, because its analysis proves that, the solar planets motions consist together one unified motion which needs each planet data to be created in proportionality with the other planets data to create the general motions harmony. - (The planets unified motion is similar to the train carriages, they moves together one general unified motion which necessitates a configuration for each planet motion data to be in harmony with the others). Please scan the figure (ORCID)
  • 3. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 3 1- Introduction - Saturn day period =10.7 hours = π x 3.4 hours - But - 3.4 degrees = Venus Orbital Inclination - Can the inclination (3.4 degrees) have any relationship with 3.4 hours? - The basic difficulty in the solar system study by using planets data analysis is that, the data provides us puzzled proportionality which we can't find explanations for them, and then we have to neglect the data considering that they are found by pure coincidences of numbers! - On the other side, The planets data analysis is very useful method to study the solar system creation and motion because it prevents us from the false imagination, because the data force us to explain them, they save us always with the facts. - The provided example is an interesting one, because, we have 2 values use (different units) and we try to know how this data is created…. - Let's try to see the depth behind this data o Venus diameter = 12104 km o Usually this value (12104 km) is used as a period of time for different planets motions as (12104 seconds), where o 12104 seconds = 3.4 hours o If Venus diameter is used as (12104 seconds) so the value 3.4 h may caused Venus orbital inclination to be 3.4 degrees – Also o 17.2 hours (Uranus day period) = 3.4 hours x 5.05 o I try to show that, the data is created based on geometrical and mathematical system of data – which proves that- the solar system in one geometrical design. The planets can no longer be considered as separated rigid bodies from each other, but the whole system should be considered as one geometrical building built based on one geometrical design.
  • 4. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 4 2- Saturn Day Period Analysis I- Data (1) 57.9 mkm = 17.2 mkm x 3.366 (2) 18048 mkm =360 mkm x 50.3 (3) 18048 mkm =17.2 mkm x 1049 (4) Mercury (47.4 km/s) x 363600 seconds =17.2 mkm (5) (Uranus Mass/ Mercury Mass) = (2815.2 hours /10.7 hours) (6) (10747 x 24 x 6) =101 x 15323 (7) (101 h/10.7 h) = (120536 km/12756 km) = (1433.5 mkm/ 151.8 mkm) = (23.4/2.5) (8) 19 deg = 7 x 3.4 x 0.8 (9) 511 deg =101 x 5.05 (10) 3475 x 5031 = 17.48 mkm 4.7 x 38520 = 3600 x 50.3
  • 5. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 5 II- Discussion Equation no. (1) 57.9 mkm = 17.2 mkm x 3.366 - Where - 57.9 mkm = Mercury Orbital Distance - 3.4 degrees = Venus orbital inclination (different from 3.366 with 1%) - 17.2 mkm = ?? Equation no. (2) 18048 mkm =360 mkm x 50.3 - Where - 18048 mkm = Uranus Orbital Circumference - 360 mkm = Mercury Orbital Circumference - 50.3 mkm = Mercury Venus Distance Equation no. (3) 18048 mkm =17.2 mkm x 1049 - Where - 18048 mkm = Uranus Orbital Circumference - 1047 = The Sun Mass / Jupiter Mass Equation no. (4) Mercury (47.4 km/s) x 363600 seconds =17.2 mkm - Where - 17.2 mkm = the distance Mercury moves in 101 hours (363600 s) - The equations from (1 to 4) tell that, Venus data is created as a result of intersection found between Mercury and Uranus motions. Mercury causes to create Venus orbital inclination (3.4 deg) and we know that, 3.4 hours =12104 seconds where 12104 km = Venus diameter. - This process depends on the distance 17.2 mkm, where Mercury moves this distance in 101 hours.
  • 6. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 6 - This explanation is some very simple one considering what's happening really, but we don't need to make the discussion so complex in its early stage….we need to keep the eyes on (17.2) this the basic key we need to discuss, let's remember its data to be in front of us… o 17.2 deg = Pluto orbital inclination o 17.4 deg = the inner planets orbital inclinations total o 23.4 deg = Earth Axial Tilt o 23.6 deg = the outer planets orbital inclinations total o 23.6 deg +17.2 deg = 17.4 deg +23.4 deg (A Geometrical System Of Data) o Also o 17.2 degrees = 17.4 degrees x 0.99 o 23.4 degrees = 23.6 degrees x 0.99 o But o 17.2 hours = Uranus Day Period - We should remember that, Uranus motion effected on Pluto motion and caused to extend its day period to be =153.3 hours, Uranus did that because the solar system design required that Pluto motion distance in its day period to be = Earth motion distance during earth day period (error 1%). This equality of distances is a basic cornerstone in the geometrical design and mechanism. - That means, the 2 values (17.2 hours and 17.2 degrees) both created depending on each other (or Pluto orbital inclination 17.2 deg is created depending on Uranus day period) but Uranus used a geometrical system of data to create this result, and based on Pluto orbital inclination (17.2 deg) Pluto extended its day period to be 153.3 hours. - Equation no. (3) shows that Uranus orbital circumference (18048 mkm) depends on the distance 17.2 mkm and the rate 1049 where (1047) is the rate between the sun mass and Jupiter mass. that tells the masses gravity effects on this process greatly.
  • 7. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 7 - The rate use (Jupiter mass) and not (Uranus mass) because the system of data uses the inner planets data. - The distance 17.2 mkm is passed by Mercury (47.4 km/s) in a period =101 hours. - We know that, - Mercury Orbital Period 88 days =1.5 x Mercury rotation period 58.66 days - 1.5 x 101 hours = 151.5 hours (where Pluto day period =153.3 h) (error 1%). - Shortly - Based on the distance 17.2 mkm Pluto day period is extending to be 153.3 h - (Notice, Pluto during 1016 hours moves a distance = 17.2 mkm). Equation no. (5) (Uranus Mass/ Mercury Mass) = (2815.2 hours /10.7 hours) - Where - 2815.2 hours = 2 x 1407.6 hours (Mercury Rotation Period) - 10.7 hours = Saturn Day Period = Saturn Rotation Period Equation no. (6) (10747 x 24 x 6) =101 x 15323 - Where - 10747 days = Saturn Orbital Period - 15323 km = Mercury Circumference
  • 8. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 8 Equation no. (7) (101 h/10.7 h) = (120536 km/12756 km) = (1433.5 mkm/ 151.8 mkm) = (23.4/2.5) - Where - 10.7 h = Saturn Day Period - 120536 km = Saturn Diameter - 12756 km = Earth Diameter - 1433.5 mkm = Saturn Orbital Distance - 151.8 mkm = Earth Orbital Distance (149.6 mkm error 1.5%) - 23.4 deg = Earth Axial Tilt - 2.5 deg = Saturn Orbital Inclination - The equations (5, 6 and 7) try to show that, Venus motion transports some (Data) between Uranus and Saturn – this is clear from the equation - (10.7 h/π) = (17.2 h /5.05) = 3.4 - This idea is a simple and direct one but how the motion be transported from a planet to another? the planet isn't a gear and no collision is occurred to cause the motion by touches… also we can't depend on the gravity force because of the great distance between the planets. But the data shows that, some motion is transported inevitably. - This is one of the most useful results of the planets data analysis method because it forces us to follow the facts and don't b lost in the imaginations… - The data shows that, is a common data used for 3 planets motions which are Uranus, Saturn and Venus. Where Venus works as a rate between the 2 planets. - I want to say that, a motion is transported among the planets but w don't know the geometrical rules based on which the motion is transported that's why we see the motions data as puzzled data. - The rate which we need to follow now is the rate (101) based on which the rate between Mercury orbital period and rotation period caused Pluto day period to be =153.3 hours.
  • 9. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 9 - The data tells, Uranus motion effect on Mercury motion and by that Uranus defined Mercury motions periods (the orbital and rotation periods), this definition is done by creation Venus orbital inclination 3.4 degrees (that tells Mercury cycles periods depend on 3.4 degrees or hours) - Mercury cycles periods caused Pluto day period to be 153.3 hours - This process is done by interaction with Saturn because of that Saturn data is found in all equations - Why? - Because Pluto day period and orbital inclination are defined based on a geometrical mechanism found inside the moon orbit. Equation no. (8) 19 deg = 7 x 3.4 x 0.8 - Where - 7 deg = Mercury orbital inclination - 3.4 deg = Venus orbital inclination - 0.8 deg = Uranus orbital inclination - 19 deg = the moon orbit regresses per year 19 degrees Equation no. (9) 511 deg =101 x 5.05 - Where - 511 deg = the planets axial tilts total - The data shows that, the rate (101) expresses a general motion, because the value (5.05) shows a motion transportation as we have discussed before and 511 deg (the planets axial tilts total) that tells we deal with a general motion done by many planets. - That shows the facts because Pluto day period extension is one result of 4 results (at least) are done by the interaction of motions inside the Earth moon orbit let's remember these 4 results in following:
  • 10. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 10 o Saturn day period be (10.7h=38520 s) less than the require period 39039 s to move a distance = Saturn circumference (- 518 sec) o Mercury day period be 4222.6 hours, less than 176 solar days with 5040 seconds. o The moon orbital apogee circumference be 2550973 km less than the moon displacements total during 29.53 days with 47720 km (2%) o Pluto day period be 153.3 hours.
  • 11. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 11 References Can Saturn Motion effect on Venus Motion? https://www.academia.edu/49005865/Can_Saturn_Motion_effect_on_Venus_Motion Did Lorentz Ask (How The matter is Created)? https://www.academia.edu/48987206/Did_Lorentz_Ask_How_The_matter_is_Created_ The Moon Orbital Motion Geometry (II) https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_ Light Motion Features Are Discovered in Planet Motion https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion Dr. Budochkina, Svetlana Aleksandrovna Associate professor - Candidate of physico-mathematical sciences (2005) http://www.mathnet.ru/eng/person22119 List of publications on Google Scholar List of publications on ZentralBlatt https://mathscinet.ams.org/mathscinet/MRAuthorID/757317 http://elibrary.ru/author_items.asp?spin=6087-3245 http://orcid.org/0000-0003-3447-0425 http://www.researcherid.com/rid/G-7453-2014 http://www.scopus.com/authid/detail.url?authorId=6507007003 https://www.researchgate.net/profile/Svetlana_Budochkina Full list of publications: http://web-local.rudn.ru/web- local/prep/rj/index.php?id=2944&p=15209 Mr. Gerges Francis Tawdrous +201022532292 Physics Department- Physics & Mathematics Faculty Curriculum Vitae http://vixra.org/abs/1902.0044 E-mail mrwaheid@gmail.com Twitter https://twitter.com/GergesTawdrous1 Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1 Facebook https://www.facebook.com Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/ ORCID https://orcid.org/0000-0002-1041-7147 Quora https://www.quora.com/profile/Gerges-F-Tawdrous Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en box https://app.box.com/s/47fwd0gshir636xt0i3wpso8lvvl8vnv Academia https://rudn.academia.edu/GergesTawadrous List of publications http://vixra.org/author/gerges_francis_tawdrous Please scan the figure (ORCID)