The Solar System Doesn't Move By The Sun Mass Gravity

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar System Doesn't Move By The Sun Mass Gravity
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –28th
August 2021
Abstract
Paper hypothesis
- The solar system is created out of one light beam its velocity (1.16 mkm/sec), and
moves depending on this light beam motion, And
- The light (1.16 mkm/sec) created the solar system distances in a network form.
The hypothesis explanation
- The existence proves of light supposed velocity (1.16 mkm/s) depend on the solar
system distances network proves.
- Because
- The solar system distances be created depending on each other by using the light
motion that caused the distances to be created in a network form, or based on one
geometrical design.
- Where (Distance = Energy). The distances creation process needed energy which
is provided by light motion. by that, light energy be registered in the created
distances, and by analysis of the distances values we can conclude that these
distances be created by energy provided by a light beam. And also we can discover
this light beam velocity be (1.16 mkm/s) because this light beam energy and
motion features are registered in the created distances.
Paper objective
- The paper proves the solar system distances network and based on this proof, the
paper proves the light supposed velocity (1.16 mkm/s) existence.

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Paper Conclusion
- Because the solar system be created out of light supposed velocity (=1.16mkm/s)
and the sun light velocity (= 0.3 mkm/s)
- Means, the light (0.3mkm/)be created as a side product from the original one (1.16
mkm/s)
- That proves
- The Sun Is Created After All Solar Planets Creation And Motion Which Disproves
Decisively Newton Theory Of The Sun Mass Gravity.
Please scan the figure (ORCID)

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Paper Contents
Subject Page No.
1- Introduction 4
2- Methodology 6
3-The Solar System Distances Be Created In A Network Form 8
3-1 Preface 8
3-2 The Solar System Distances Network Description 12
3-3 The Solar System Distances Network Analysis 28
4- Light Beam (1.16 mkm/s) Existence Proves Discussion 31
4-1 Preface 31
4-2 The Light Beam (1.16 mkm/s) Proves Discussion 32
4-3 Jupiter Orbital Circumference Analysis 66
5- Mercury Jupiter Distance Analysis 84
5-1 Preface 84
5-2 Mercury Jupiter Distance analysis 86
5-3 Planets Motions Interaction 102
5-4 Planets Unified General Motion 117
5-4-1 The Planets Unified General Motion Description 117
5-4-2 The Solar Planets Motions Are Complementary One Another 118
5-4-3 The Solar Planets Move An Unified Motion (A Team Motion) 123
6- The Sun Age Historical Proves 128
6-1 The Sun Circles The Earth 129
6-2 The Rate (1.0725) 130
6-3 The Sun Diameter Analysis 134
6-4 The Sun Rays Analysis 137
7- The Solar Planets Motions Depend On Different Rates of Time 142
7-1 Preface 143
7-2 Earth And Pluto Rate Of Time 144
7-3 Mercury Motion Rate Of Time 153
7-4 Saturn Motion Rate Of Time 156
7-5 Uranus And Jupiter Rate Of Time 158
8- The Solar Planets Motions Analysis 160
8-1 Preface 161
8- 2 The Equal Distances Method 162
8-3 The Inner And Outer Planets Motions Be Distinguished 168
Appendix No.1 The Solar System Equal Distances List 177
References and Biography 179

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1-Introdcution
- The paper hypothesis tells that
- The solar system is created out of one light beam its velocity (1.16 mkm/sec),
and moves depending on this light beam motion
- The hypothesis refers to a matter creation theory. Let's summarize it:
- The matter is created out of light
- The matter isn't separated from its light parent but the matter moves with the light
beam in one unified general motion.
- The matter and light motions use different rates of time.
- 1 second of light motion be equivalent to 1 solar day of planet motion.
- Or
- The energy of light motion for one second causes a planet to move for one solar
day.
- This is one more feature of the solar system motion which is strange from Newton
theory point of view.
- The rate (1 second = 1 solar day) is the general rate of light and matter motions.
- But
- The solar planets divide this rate among themselves into small rates. And by that,
the solar system works as a great clock. This clock input is an energy of light
motion for 1 second and its output is enough energy for a planet motion for a
period 1 solar day.
- The rates of time be distributed among the solar planets, for example
- 1 hour of Mercury motion = 1 second of light motion
- 1 hour of Mercury motion = 9.18 hours of Pluto motion
- 1 hour of Mercury motion = 24 hours of Jupiter motion
- 1 hour of Earth motion = 6.37 hours of Pluto motion
- 1 hour of Earth motion = 29.53 hours of the moon motion

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- We should discuss the planets motions rates of time in the paper discussion
- But
- This second feature of motion can be added to the first one (the distances network
form) and creates a vision concerning the solar system motion different from
Newton vision about it.
- The basic point is that, the planets motions analysis shows, the simple idea of
Newton Theory of The Sun Mass Gravity is an imaginary one, because the solar
system is so complex machine.
- I want to say,
- Not only the solar system distances are in network form or the planets motions
depend on different rates of time, but there are many other features in the solar
system disproves the simple idea of the sun mass gravity by Newton
- The basic proof against Newton theory should be the sun age, because, the planets
motions data analysis proves that the sun is created after all planets creation and
motion. this fact disproves Newton theory of The Sun Mass Gravity Decisively.

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2-Methodology
- I use the planets data analysis to discover the solar planets creation and motion.
- This method is so useful because it creates comparisons between planets motions
data and the theories which try to explain this planets motions data. Also the
method creates comparisons between planets motions data with each other.
- Let's use one example for explanation in following
- Example no. (1)
- Newton Theory of the planet motion depends on the sun mass gravity supposes
that the planet motion be independent from all other planets motions…
- We provide Planets data for a comparison. Then let's ask
- Can planets motions and distances be independent from one another? let's answer
in following
- Saturn Orbital Distance = 1433 km = Saturn Uranus Distance
= Mars Orbital Circumference
= Pluto Neptune Distance (error 1.5%)
= Pluto eccentricity Distance (error 1.5%)
= Neptune Orbital Distance/π
= Uranus Orbital Distance /2
= Mercury Jupiter Distance x 2
- If the planets motions be independent from one another how these distances be
equal?!
- Appendix no. (1) of this paper provides a complete list for the equal distances in
the solar system and proves that 50% of all distances in the solar system be equal
one another! why?
- Appendix no. 1 also provides another list shows that 40% of all distances in the
solar system be rated with one another by the same one rate (1.0725)!
- Can we ask why?
- It's a different vision
- Newton told us something has no proof in planets data…

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- Planet orbital and internal distances can't be independent from any other distances..
- The distances be created in a group and not individually. They are created based
on one geometrical design and not as independent distances from one another
- The distances creation in a network form is the first discussion in this paper, in
which we should prove by different data that the planets distances can't be created
independent from one another but dependent one each other and based on one
geometrical design.
- A direct proof for the network claim is the following data
- 50% of all distances in the solar system be equal one another and
- 40% of all distances in the solar system be rated with one another with the same
one rate (1.0725).
- This data we should discuss deeply because it proves directly that, the planets
distances be created based on one geometrical design and in network form. The
planets distances be created as a group based on a geometrical design where they
can't be created independently.

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3-The Solar System Distances Be Created In A Network Form
3-1 Preface
3-2 The Solar System Distances Network Description
3-3 The Solar System Distances Network Analysis
3-1 Preface
- The Solar Planets data analysis shows that, The Planets Distances Be Created In A
Network Form.
- That means,
- The solar system distances are considered as one geometrical design or one
geometrical system. there's no one distance defined as independent or created out
of this one geometrical design.
- Let's suppose that, this geometrical design be a square. So all dimensions in this
square be defined geometrically by this square data. means no one dimensions can
be created independent from this square data because all of them are parts in the
same one geometrical design.
- Imagine you have a triangle has 2 angles (60 degrees and 80 degrees) what's the
third one? (40 degrees). Can this angle be any thing else than (40 degrees)? NO it's
obligatory value defined by the geometrical basic rules
- When you use this same example for the solar planets distances we will have
surprises. Because this example tells (for example)
Venus Jupiter Distance be= 671 mkm because Earth Jupiter distance = 629 mkm
- That creates another vision
- While we consider Venus is a planet and earth is another planet an they move
independently from one another. we be astonished with the fact that, their
distances to Jupiter be defined based on one another! why? and How?
- The paper hypothesis tells that
- A light beam its velocity (1.16 mkm/sec) is found in the solar system

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- That means,
- Before the solar system creation, where no planet neither distance was found.
- In this case the light supposed velocity (1.16 mkm/sec) started the journey.
- The light supposed velocity (1.16 mkm/sec) motion created a planet and its
distance, and by more motion the light created another planet with its distance, and
then a third planet……etc
- Based on this idea
- The planet matter and distance be created out of the same light beam with
supposed velocity (1.16 mkm/sec). This idea is a simple one because the matter is
created of energy and the space is created of energy and the light beam has energy
- By this vision
- The solar system be similar to a rope. And the planets be a knot on this rope.
- This simple description for the idea as a rope with knots can't explain clearly the
facts. Because the light is the major moving player and the planets motions be
produced by light motion effect. By that many interactions and geometrical effects
be found between the light and planets motions data.
- In this point we analyze the distances in the solar system
- Now the picture is different
- Venus and Earth are Not independent planets move independently from one
another. but the 2 planets are puppets moving on the puppets theater and a light
beam motion is the main force behind both motions.
- The light supposed velocity (1.16 mkm/sec) motion creates the solar system
distances based on one geometrical design. And because of that Earth and Venus
distances are defined based on one another.
- Shortly
- The light moves from a point to another to create the distances, the distances be
created based on one geometrical design and by geometrical rules. The planets
have to accept their distances which are defined by light motion.

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- How Does Light Supposed Velocity (1.16 mkm/s) Create The Distances?
- The light supposed velocity (1.16 mkm/s) moves a distance and uses it as a period
of time to move another distance and uses the second one to move a third one. by
that, the distances be created in a network form and depends on one geometrical
design.
- This behavior be used by light supposed velocity (1.16 mkm/sec) and light known
velocity (0.3 mkm/sec) and even be used also by planets motions!
- The method causes to create the distances based on one geometrical design.
- By this vision, no a distance be created independently from the other distances.
The idea completely disproves the gravitation equation…
- We are far here from Newton Theory of the Sun mass gravity and the gravitation
equation. Completely the ideas are different. And the theory disproves specially
Planet Motion Independency Concept.
- Based on this idea
- The solar system distances be created as railways but the solar planets are similar
to trains. The railways creations cost energy provided by light motion (usually)
that means, the planets motion through the distances usually doesn't cost energy
because the distances required energy for creation be provided by light motion in
the first passage through these distances.
- As a result, The Solar System Distances Be Created In A Network Form
- What I try to do here is that, to persuade the respectful reader to look at the solar
system distances as total distances and not as individual distances.
- For example, 50% of all distances in the solar system are equal one another
(Appendix no.1 provides the list of these distances). Why these distances are
equal? Here we don't deal with individual distances. We deal with One Reason
caused 50% of all distances to be equal one another. that means we deal with one
machine where one reason can effect on many parts of it because these parts are
connected with each other and depend on one another.

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- The distances be used in the solar system by different forms, and there are many
complex points of using we should refer to, but
- We need before to prove the basic hypothesis that the distances be created by light
motion in a network form.
- In the next point we discuss the data to prove that the solar system distances be
created in network form.
- Notice
- Light motion uses the distance with the rate (1 mkm = 1second) but planet motion
uses the distance with the rate (1mkm = 1 solar day).
- This rate explains the rule (light motion for 1 second causes a planet motion for 1
solar day)

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3-2 The Solar System Distances Network Description
I-Data
(1)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 542 s = 629 mkm (Earth Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
(2)
1.16 mkm/s x 778.6 s x 2= 1806 mkm
1.16 mkm/s x 1806 s = 2094 mkm (Jupiter Uranus Distance)
1.16 mkm/s x 2094 s = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
(3)
1.16 mkm/s x 170 s = 197.2 mkm
1.16 mkm/s x 197.2 s = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
0.3 mkm/ x 193 s = 57.9 (Mercury Orbital Distance)
(4)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(5)
1.16 mkm/s x 1980 s = 2296.8 mkm
1.16 mkm/s x 2296.8 s = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 mkm/s x 2644.5 s = 3033.5 mkm (error 1%) (Uranus Pluto Distance)

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(6)
0.3 mkm/s x 1980 seconds = 594 mkm
(7)
1.16 mkm/s x 361 s = 419 mkm
1.16 mkm/s x 419 seconds = 486 mkm = 243 mkm x 2
1.16 mkm/s x 282 seconds = 327.6 mkm
1.16 mkm/s x 327.6 seconds = 380 mkm
1.16 mkm/s x 440.8 seconds = 511.4 mkm
(8)

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II-Discussion
- This discussion aims to prove that, the solar system distances are created based on
one geometrical design. And because of that, we need to look at the distances as
one group and not as individual distances
- Appendix no. (1) provides a list for the equal distances in the solar system, they be
formed around 50% of all distances. Let's provide this data here to help our
discussion
More Data
(A) (Why These Distances Are Equal?)
(1)
Saturn Orbital Distance = Saturn Uranus Distance
(2)
Mercury Neptune Distance = Saturn Pluto Distance
Jupiter Pluto Distance = Uranus Neptune Circumference
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Mercury Distance = 2 Mercury Orbital Circumference
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(Earth and Jupiter at 2 different sides from the sun)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
Pluto Orbital Distance = Earth Orbital Circumference x 2π
- It's illogical to imagine a different reason caused the equality between each 2
distances of this list. The logical idea is that, this distances equality depend on one
reason only which causes all these distances to be equal one another.
- Let's provide one more list in following

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(B) (Why These Distances Are NOT Equal?)
1. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
2. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
3. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
4. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
5. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
6. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
7. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
8. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
9. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(10)
- This list of distances be rated with one another with the same one rate (1.0725).
why these values are rated with the same rate (1.0725)
- Notice
- Light supposed velocity =1.16mkm/sec
- But
- 1.16 = (1.077)2
- That tells the rate (1.0725) must be created as an effect of light supposed velocity
(1.16 mkm/sec) motion of these dispatches
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II-Discussion (Continued)
- I try to show that, the solar system distances are created as one group and not as
individual distances.
- Many features of the solar system distances support this conclusion. Not only the
data equations which we will discuss here (8 equations). But also the equal
distances (50% of all distances) and the rated distances (40% of all distances), this
data refers to that we deal with one geometrical design. No a single proof suggests
any distance can be considered as individual distance or be created independently
- It's one machine which is proved clearly and strongly
- Because
- One geometrical design be found behind this data,
- Equation no. (4) provides very clear proof for the distances distribution based on
one design. This equation is the solar system main energy distribution equation.
- In following we discuss the data equations one by one to see how these distances
be created by light supposed velocity (1.16 mkm/sec) motion.
- But
- The paper hypothesis tells that,
- The solar system be created out of one light beam its velocity =1.16 mkm/sec,
- Where
- The sun rays velocity =300000 km,
- We conclude that, the light known velocity (0.3 mkm/sec) be crated as a side
product from the original one (1.16 mkm/sec) and the proves the claim (the sun be
created after all planets creation and motion)
- That means,
- We have 2 light beams velocities in the solar system, one is ancient and one is
modern. That means, the ancient and modern distance can be built by light
supposed velocity (1.16 mkm/sec) but light known velocity (0.3 mkm/sec) created
the modern distances only.

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Equation no. (1)
1.16 mkm/s x 500 s = 580 mkm
1.16 mkm/s x 580 s = 671 mkm (Venus Jupiter Distance)
1.16 mkm/s x 671 s = 778.6 mkm (Jupiter Orbital Distance)
1.16 mkm/s x 629 s = 720.7 mkm (error 1%) (Mercury Jupiter Distance)
1.16 mkm/s x 542 s = 629 mkm (Earth Jupiter Distance)
1.16 mkm/s x 5127 s = 5906 mkm (error 0.7%) (Pluto Orbital Distance)
- Equation no. (1) shows one series of the distances be created by light motion based
on each other.
- Jupiter distances specifically are so distinguish ns shows this fact clearly and
strongly… let's summarize the data in following
- Light supposed velocity (1.16 mkm/s) uses the period (500 seconds) to pass a
distance =580 mkm and uses this distance (580 mkm) as a period for time (580 s)
to pass a distance = 671 mkm (Venus Jupiter distance) and then uses this distance
as a period of time (671 s) to pass a distance = 778.6 mkm (Jupiter orbital
distance)
- Also, Light supposed velocity (1.16 mkm/sec) uses the distance between earth and
Jupiter (629 mkm) as a period of time (629 s) to pas a distance = 720.7 mkm (error
1%) (= Mercury Jupiter Distance)
- Also, Light supposed velocity (1.16 mkm/sec) uses the distance between Jupiter
and Pluto (5127 mkm) as a period of time (5127 s) to pass a distance = 5906 mkm
(= Pluto Orbital Distance)
- The distances are created in a network form depends on one another and based on
one geometrical design.
- If this explanation is wrong one, we have to explain why all distances be rated with
the rate (1.16) as seen clearly.
- Notice, light known velocity (0.3 mkm/s) needs 500 seconds to pass Earth orbital
distance (149.6 mkm)

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More Data
- 778.6 mkm (Jupiter Orbital Distance) = 1.0725 x 720.7 mkm (error 1%)
- 720.7 mkm (Jupiter Mercury Distance) = 1.0725 x 671 mkm
- 671 mkm (Jupiter Venus Distance) = 1.0725 x 629 mkm
- 629 mkm (Jupiter Earth Distance) = 1.0725 x 580 mkm (error 1%)
- This data also proves, these distances be created based on a geometrical design.
Because the same distances be rated on (1.0725 and 1.16).
- Please remember 1.16 =(1.077)2

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Equation no. (2)
1.16 mkm/s x 778.6 s x 2= 1806 mkm
1.16 mkm/s x 1806 s = 2094 mkm (Jupiter Uranus Distance)
1.16 mkm/s x 2094 s = 2 x 1205 mkm (error 0.8%) (Mars Saturn Distance)
- Equation no. (2) completes another part of this same series which we have
discussed in equation no. (1)
- Light supposed velocity (1.16 mkm/s) uses the distance 778.6 mkm (Jupiter orbital
distance) as a period of time (778.6 s x 2) to pass a distance = 1806 mkm
- And then
- Light supposed velocity (1.16 mkm/s) uses the produced distance 1806 mkm as a
period of time (1806s) to pass a distance =2094 mkm (= Jupiter Uranus Distance)
- Then
- Light supposed velocity (1.16 mkm/s) uses the distance 2094 mkm as a period of
time (2094s) to pass a distance = (2 x 1205 mkm) where (1205 mkm = Mars
Saturn Distance).
- Equation no.(2) started with the distance (778.6 mkm =Jupiter orbital distance) and
reach to (1205 mkm = mars Saturn distance).
- That makes the 2 equations consist one series

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Equation no. (3)
1.16 mkm/s x 170 s = 197.2 mkm
1.16 mkm/s x 197.2 s = 227.9 mkm (error 0.4%) (Mars Orbital Distance)
0.3 mkm/ x 193 s = 57.9 (Mercury Orbital Distance)
- Where
- 170 mkm = Mercury Mars Distance
- Equation no. (3) tells
- Light supposed velocity (1.16 mkm/s) travels during (170 seconds) a distance =
197.2 mkm) and then
- Light supposed velocity (1.16 mkm/s) uses the distance (197.2 mkm) as a period
of time (197.2 seconds) to pass a distance = 227.9 mkm(= Mars orbital distance)
- That means,
- Mars orbital distance depends on a period (=197.2 seconds) by light supposed
velocity (1.16 mkm/s) motion.
- But
- Mercury orbital distance (57.9mkm) depends on a period (193 seconds) by using
light known velocity (0.3 mkm/s) motion.
- The period (196.5 seconds) is used almost for Mercury, Mars and Jupiter Motions
as we discuss in point no. (4) of this paper. And because the 3 planets use equal
periods of time that cause their motions to be integrated in one unified general
motion.
- Equation no. (3) shows that, there's a reason behind the motions data consistency
between Mercury and Mars (and Jupiter also). We should prove this consistency of
motion in point no. (5-4) (Planets Unified General Motion)

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- Equation no. (4)
1.16 mkm per second x (2) x 86400 seconds =(2) x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + (2) x 86400 mkm
- This equation is the main equation of the solar system energy distribution. And this
is the main equation in my papers. Let's summarize it shortly in following
- (Part no. 1)
- 1.16 mkm per second x 2 x 86400 seconds
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400 s)a
distance = 100733 mkm= The Solar Planets Orbital Circumferences Total
- The equation shows a double value is used (2 x 100733 mkm), means
- The equation shows energy = 2 x The Solar Planets Orbital Circumferences Total
- Why does light supposed velocity (1.16 mkm/s) motion during a day (86400s)
pass a distance = The Solar Planets Orbital Circumferences Total?
- We can answer that,
- The light supposed velocity (1.16 mkm/s) depends on the solar day as its basic
period of time and
- The solar planets orbital circumferences be built based on a light beam motion its
velocity (1.16 mkm/s) during one solar day.
- Means,
- It's not by chance that, The Solar Planets Orbital Circumferences Total = (100733
mkm) but because the total be created by light motion for 1 solar day.
- (Part no. 3)
- (37100 mkm – 4900 mkm) x 2π
- 37100 mkm = Pluto Orbital Circumference
- 4900 mkm = Jupiter Orbital Circumference
- Part no. (3) shows why the equation no. (4) be a real one and not imaginary
equation. Because the difference in distance between Pluto orbital circumference
(37100 mkm) and Jupiter orbital circumference (4900 mkm) creates this equation.

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- We know that,
- The rate (2π) distinguish between light motion and planet motion. and the
difference (37100 mkm – 4900 mkm) refers to the planets motions by that the
value (100733 mkm x 2) is a real one
- (Part no. 4)
- 28255 mkm + 2 x 86400 mkm
- Where
- 28255 mkm =Neptune Orbital Circumference
- This part of equation is the reason of its importance…
- The equation other parts can work without the rate (2) which is used frequently.
The only part needs this rate is this part no. (4) for Neptune orbital circumference.
The equation tells the total energy (2 x 100733 mkm) reach to Neptune and
Neptune seized 14% of it and sent the rest energy into 2 trajectories of energy each
one has 86400 mkm
- And where these 2 trajectories be sent? The distance 86400 mkm tells us
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- The energy is sent to Venus and Earth in 2 equal trajectories because the error
between the 2 planets equations be 1% at max.
- Equation no. (4) shows that,
- The distances between Jupiter and Pluto on one side and the distances from
Neptune to Venus with Earth on the other side, All these distances be created and
distributed based on One Geometrical Design which is seen in the equation no.
(4) clearly.
- That shows the equation importance because
- The distances be created in comparison with one another and by that their
distribution proves their dependency on one another clearly. We deal with a
geometrical system and not with individual or independent distances from one
another. (This equation is discussed in more details in point no. 4-2)

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Equation no. (5)
1.16 mkm/s x 1980 s = 2296.8 mkm
1.16 mkm/s x 2296.8 s = 2644.6 mkm (error 0.7%) (Mars Uranus Distance)
1.16 mkm/s x 2644.5 s = 3033.5 mkm (error 1%) (Uranus Pluto Distance)
- Where
- 1980 mkm = the orbital circumferences total of (Mercury +Venus + Earth)
- Equation no. (5) shows another series
- Light supposed velocity (1.16 mkm/s) uses the distance (1980 mkm) as a period of
time (1980 seconds) to pass a distance = 2296.8 mkm and then
of time (2296.8 seconds) to pass a distance =2644.6 mkm (Mars Uranus Distance)
- And Then
of time (2644.6 seconds) to pass a distance =3033.5 mkm (Uranus Pluto Distance)
- The data shows more distances be created in a network form by using light
supposed velocity (1.16 mkm/s) motion.
- But
- This analysis for the distances is so limited because we should explain why the
produced distance depended on the input distance…
- That needs more analysis for this data…
- Here we deal with the solar system distances as a group or a network. We don't
deal with each distance in its details, instead we deal with the whole distances as
one group to prove the network theory.
- But
- The detailed analysis will explain why Uranus Pluto distance be produced by using
Mars Uranus distance. In many detailed discussions we should answer similar
questions.

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Equation no. (6)
- Where
- 1980 mkm = the orbital circumferences total of (Mercury + Venus + Earth)
- Equation no. (7) shows one more series of the distances
- Light known velocity (0.3 mkm/s) uses the distance (1980 mkm) as a period of
time (1980 seconds) to pass a distance = 594 mkm
- Then
- (687 days = Mars orbital period where (689/687) = (361/360)
- Then
- Light supposed velocity (1.16 mkm/s) uses the period (687 seconds) to pass a
distance = 800 mkm
- Then
- The distance 929 mkm = Earth Jupiter distance when the 2 planets be on the sun 2
different sides.

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Equation no. (7)
1.16 mkm/s x 361 s = 419 mkm
1.16 mkm/s x 419 seconds = 486 mkm = 243 mkm x 2
- Light known velocity (0.3mkm/s) needs 361 seconds to pass Venus orbital
distance (108.2 mkm), and
- Mercury orbital circumference =360 mkm
- We can use any of the 2 values to start the series of the equation no.(7).
- Light supposed velocity (1.16 mkm/s) travels during (361sec) a distance = 419
mkm and then
time (419 sec) to pass a distance = 2 x 243 mkm
- (Where 243 days = Venus Rotation Period, and the motion rate 1mkm =1 day
for a planet motion but 1 mkm = 1 second for light motion, so 243 days can be
used by light motion as 243 seconds)
time (243 sec) to pass a distance = 282 mkm.
time (282 sec) to pass a distance = 327.6 mkm (where 327.6 days = the moon
sidereal year. the value be used by light motion as 327.6 seconds)

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of time (327.6 sec) to pass a distance = 380 mkm. And by one more motion light
passes 440.8 mkm and
of time (440.8 sec) to pass a distance = 511.3 mkm. (where 511.1 degrees = the
solar planets axial tilts total)
of time (511.3 sec) to pass a distance = 593 mkm. (the distance 594 mkm be used
in equation no. 6) that connects equation no. (6) with equation no. (7) and creates
from them one continuous series.
- Notice (1)
- Light known velocity (0.3 mkm/s) needs (1397 seconds) to pass 419 mkm
- But
1397 mkm (1205 mkm = Mars Saturn Distance)
- I try to show that, the network is connected depends on the light 2 velocities
- But
- Light known velocity (0.3 mkm/s) needs (1205 seconds) to pass 361 mkm
- Notice (2)
- Mercury moves during its rotation period (1407.6 h) a distance =243 mkm (-1%)
- Mercury moves during Venus day period (2802 h) a distance =243 mkm
- Means, the distance 243 mkm be used geometrically by planets motions also not
only by light motions. where we see it as (243 days = Venus rotation period)

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Equation no. (8)
- Where
- 4224 seconds be used based mercury day period (4222.6 hours)
- 5678.1 mkm = Mars Pluto Distance
- Equation no.(8) tells
- Light supposed velocity (1.16 mkm/s) uses the period (4224 mkm) to pass a
distance =4900 mkm (=Jupiter Orbital Circumference)
- Then
time (4900 seconds) to pass a distance = 5678.1 mkm (= Mars Pluto Distance)
- Equation no.(8) shows more distances be created in the same network form, by
using light supposed velocity (1.16 mkm/s) motion

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3-3 The Solar System Distances Network Analysis
- The data discussion proves clearly the distances network claim, and based on the
data discussion we can conclude that, the solar system distances be created
depends on one geometrical design in a network form
- But
- The distances still have many puzzled secrets can't be discovered yet. Let's provide
2 of them in following
- (1st
Point)
- The solar system motions be consisted of light motion and planets motions.
- The solar system motions use different rates of time, as we have seen in the
comparison between light and planet motion where (1 second of light motion be =
1 solar day of planet motion)
- The solar planets motions depend on different rates of time which we will discuss
in this paper. For example (1 h of Mercury motion =9.18 h of Pluto motion)
- That creates different rates fro the distances using. Because light motion uses the
distance by the rate (1mkm =1sec) but planet motion uses the distance by the rate
(1mkm =1soalr day). Because of that, the solar system distances network should be
created based on one flexible geometrical design can be used in different rates.
This feature causes a difficulty to discover the solar system distances geometrical
design.
- (2nd
Point)
- The solar system motion depends on the equal distances.
- That means, the solar system motion causes to force the planets to move equal
distances in defined periods of time. Or the equal distances of planets motions
cause the solar system motion.
- In fact

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- I can't discover yet the geometrical effect of the equal distances, let's use one
example for better explanation
- Earth moves during a solar day (24 h) a distance = 2574720 km
- Pluto moves during its day period (153.3 h) a distance = 2593836 km
- The moon displacements total during (29.53 days) = 2598693 km
- These 3 distances are equal with max error only (1%)
- These distance can be considered equal distances, but can thi distances quality
effect on planets motions? yes
- Let's see the following data
- More Data
Group no. (1) (Pluto And Earth Rate Of Time)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ earth day period) = 6.37 (0.8%)
- Pluto orbital distance 5906 mkm = Earth orbital circumference 940 mkm x 2π
- Pluto orbital period 90560 days = Earth Cycle (1461 days) x 2π3
Group no. (2) (Pluto And The moon Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 406000 km = Pluto Motion Distance during a solar day
- 88000 km = The moon displacement daily
- 708.7 hours = The Moon Day Period
- 153.3 hours = Pluto Day Period
- And
- The angle 12.2 degrees = 13.177 deg – 0.98562 deg
- 13.177 degrees = The Moon Motion Degrees Per A Solar Day

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- 0.98562 degrees = The Earth Motion Degrees Per A Solar Day
- And
- 655.7 hours = The Moon Rotation Period.
- 153.3 hours = Also (153.3-) Pluto Rotation Period
- Shortly
- the 3 planets move equal distances in defined period of time and their motions data
be in proportionality with each other as seen clearly in data.
- Is the distances equality cause the data proportionality of vice verse? I can't
provide a decision.
- The fact is that, the distances are equal and the data is in proportionality.
- And
- This feature be repeated each time the planets move equal distance in define
periods of time
- And
- The planets uses the equal distances method frequently, and hundreds of times this
method using be observed
- How the machine works? I don't know? Of course Not by Newton theory
- But I can't discover the machine motor mechanism
- Because
- The equal distances works based on geometrical rule as a waterwheel or a lever.
The equal distances create basic geometrical effect on the planets motions. but
because I can't discover this effect the process be repeated before my eyes
hundreds of time but I understand nothing of its geometrical effect
- By that, the machine motor b out of our sight and because of that we can't
understand neither the distance role nor the machine motor mechanism
- The equal distances method is discussed in more details in point no.(8)

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4- Light Beam (1.16 mkm/s) Existence Proves Discussion
4-1 Preface
4-2 The Light Beam (1.16 mkm/s) Proves Discussion
4-3 Jupiter Orbital Circumference Analysis
4-1 Preface
- What Do We Try To Do In This Point?
- We analyze the distances between Mercury and Pluto as deep as possible to prove
that, these distances are created by energy of a light beam its velocity =1.16 mkm/s
- Let's summarize the idea in following:
- The Light supposed velocity (1.16 mkm/sec) started its motion from Mercury, and
moves in 2 basic trajectories.
- The First trajectory be from Mercury to Jupiter where the light supposed velocity
(1.16 mkm/sec) created Jupiter orbital circumference.
- And then
- This light beam travels from Jupiter to Pluto
- The second trajectory be from Mercury to Pluto Directly
- There's also one more trajectory, which is Mercury motion trajectory.
- We should discuss each one in details..
- Our main task here is that, to analyze different distances to prove that these
distances can't be created except by a light beam its velocity = 1.16 mkm/sec.
- We should keep an eye on Jupiter motion data and distances because Jupiter data
gives a strong proof for the light supposed velocity (1.16 mkm/sec) existence

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4-2 The Light Beam (1.16 mkm/s) Proves Discussion
I - Data
(1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
(2)
(3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm – 4900
mkm) x 2π = 28255 mkm + 2 x 86400 mkm
(4)
1.16 mkm/s x 5040 seconds = 5848 mkm (Mercury Pluto Distance)
And
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
(5)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And

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II- Discussion
Equation no. (1)
1.16 mkm/s x 86400 s = 100733 mkm
And
0.3 mkm/s x 86400 s = 25920 mkm
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 s) a distance =
25920 mkm.
- Because it's a light motion we see this value (25920 mkm) as a period of time
(25920 years = the Precession Cycle)
- Also
- The distance 25920 mkm be = The Planets Motions Distances Total During A
Period =1461 days (where 1461 days =365 +365 +365 +366)
- Because the period 1461 days is (Earth Cycle) we consider that the distance 25920
mkm be mentioned by planets motions total
- Notice, the distances total added the Earth moon motion distance to the 9 planets
motions distance to create the total per a solar day (17.75 mkm) where the moon
motion daily distance be considered = Earth motion daily distance because they
aren't separated from one another through their motions.
- The light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm = The 9 Planets Orbital Circumferences Total
- Equation no. (1) tries to prove that, Light Motion Uses The Solar Day Period As
Its Basic Period Of Motion.
- Light known velocity and light supposed velocity both use the solar day as the
basic period of time. Because of that, both light beams passes essential distances in
the solar system geometry.
- The next discussions will prove that these distances (25920 mkm and 100733
mkm) are essential distances in the solar system geometry.

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- Notice
- The rule tells
- (Light Motion For 1 Second = Planet Motion For 1 Solar Day)
- This rule which is a supposed one and we should prove it through the paper
discussions…
- This rule tells that,
- The light motion depends on the solar day as a period of time as similar to its
dependency on the second as a period of time.
- That means,
- These 2 periods of time (the second and the solar day) are the 2 basic columns for
light and planet motions accompaniment.
- And by that, light motion doesn't use the solar day as similar to any other planet
day period. On the contrary, the solar day is the basic period of time for light
motion (For both velocities, the known and supposed).

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The Motion 1st
Trajectory
- The Trajectory Summary
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Jupiter,
creating Jupiter orbital circumference
- And, then
- Light supposed velocity (1.16 mkm/s) travels from Jupiter to Pluto (Directly) and
doesn't touch any other planet in the way.
- The motion trajectory is built on 2 basic equations and many other additional data.
because
- Mercury Motion uses light supposed velocity (1.16 mkm/s) because of that,
different data of Mercury motion be created based on this light supposed velocity
(1.16 mkm/s) energy
- Shortly
- The motion 1st
trajectory is defined based on Equation no. (2) and (3) as basic
equations. And through discussion many other data be added
- Notice
- Equation no. (3) is the solar system geometry main equation and it's the paper
main one we discuss it along the paper,

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Equation no. (2)
- Where
- Equation no. (2) tells, the light supposed velocity (1.16 mkm/s) travels during
4224 seconds a distance = 4900 mkm = Jupiter Orbital Circumference.
- Now, let's suppose 1 second of light motion = 1 hour of Mercury Motion
- based on that, 4224 seconds be equivalent to 4224 hours (but 4222.6 hours =
Mercury Day Period).
- Equation no. 3 provides 3 braches of data! let's summarize them in following:
- (1st
Branch) Light supposed velocity (1.16 mkm/s) moves in (4224 s) a distance
=4900 mkm but Mercury moves during (4222.6 h) a distance = 720.7 mkm (=
Mercury Jupiter Distance) and we suppose that 1 second of light motion = 1
hour of Mercury Motion. Because of that we need to find some connection
between 4900 mkm and 720.7 mkm to create a comparison between light motion
and planet motion.
- The comparison is complex because, I suppose the rate (2π) distinguish between
light and planet motions. By that, if light moves 4900 mkm, a planet motion
should be 778.6 mkm but Mercury motion distance only be 720.7 mkm, where,
- 778.6 mkm (Jupiter orbital distance) =1.0725 x 720.7 mkm (Mercury Jupiter
Distance)
- The rate (1.0725) creates a negative effect on the rule of the value (2π). although
the rate (1.0725) be used between 40% of all distances in the solar system. But
because it be found here creates more complexity for the discussion and causes
some negative effect for the comparison between light and planet motions. because
always in other data we have found that the value (2π) distinguish clearly between

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light and planet motions but in our equation the rate (1.0725) causes some
difficulty for this comparison vision.
- Notice
- The distance 720.7 mkm (Mercury Jupiter Distance) be discussed in point no. (5)
of this paper.
- (2nd
Branch) Mercury Day Period Creation.
- We have supposed that, 1 second of light motion be equivalent to 1 hour of
Mercury Motion. that means the period (4224 s ) be equivalent to (4224 h) and
Mercury Day Period = (4222.6 hours).
- This supposition suggests that, Light supposed velocity (1.16 mkm/) motion causes
to create Mercury Day Period be (= 4222.6 hours).
- The data is accurate and clear
- NOW
- The data tells that…
- Mercury is the source of the light supposed velocity (1.16 mkm/s)
- The light supposed velocity (1.16 mkm/s) started from Mercury and sent to Jupiter,
creating the distance (4900 mkm = Jupiter Orbital Circumference).
- This motion depends on Mercury Day Period.
- As a result, Mercury Day Period be defined by light supposed velocity (1.16
mkm/s) motion effect on Mercury Motion.
- i.e.
- Mercury Day Period = 4222.6 hours
- And
- 4900 mkm= 1.16 mkm/s x 4224 seconds
- We suppose that, 1 hour of Mercury Motion = 1 second of light motion… means

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- The difference (4224 -4222.6 = 1.4) is created by the light supposed velocity (1.16
mkm/s) motion effect. that means,
- The light motion effected on Mercury Motion and caused Mercury day period to
be 4222.6 hours and less than 4224 hours with 1.4 hour = 5040 seconds
- Why? Because
- Light supposed velocity (1.16 mkm/s) travels during (5040 s) a distance =5848
mkm = Mercury Pluto Distance
- The light supposed velocity (1.16 mkm/s) created a connection between Mercury
and Pluto motions by creating the period 5040 seconds as a difference between
Mercury Day period (4222.6 h) and 176 solar days (=4224 hours).
- We can't discover the geometrical machine behind this data. But the data clearly
shows that, the light supposed velocity (1.16 mkm/s) travels during 5040 seconds a
distance = 5848 mkm.
- We have 3 information we got based on this analysis which are:
- (1st
) Mercury Is The Origin Point Of The Light Supposed Velocity (1.16 mkm/s)
- (2nd
) light supposed velocity (1.16 mkm/s) motion created Jupiter orbital
circumference 4900 mkm.
- (3rd
) Mercury Day Period be (4222.6 h) and less than (4224 h) with (5040 s)
because of light supposed velocity (1.16 mkm/s) effect on Mercury motion, to
create a connection between Mercury and Pluto motions.
- Notice
- The accompaniment of The Light supposed velocity and Mercury Motions caused
Mercury day Period to be (4222.6 hours) to create a connection between Mercury
and Pluto based on the distance (5848 mkm = Mercury Pluto Distance)
- Is There any Proof for this conclusion?
- Yes, There's a proof in Mercury Motion data,
- Let's analyze Mercury Motion Data in following:

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Mercury Motion Data
- 5040 seconds = 84 minutes
- Mercury (4.095 mkm/ daily) moves during 84 solar days a distance = 344 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 346.6 solar days a distance = 1419.5 mkm
- And
- Mercury (4.095 mkm/ daily) moves during 1419.5 solar days a distance = 5813 mkm
- But
- Mercury (4.095 mkm/ daily) moves during 1433.5 solar days a distance = 5870 mkm
Pluto Orbital Distance
- NASA Planetary Fact sheet had defined Pluto orbital distance as 5870 mkm
- And
- From 5 years NASA had modified this distance to be 5906 mkm
- In the theoretical calculations both distances are required!
- Let's explain that in following
o 5906 mkm – 57.9 mkm (Mercury orbital distance) = 5848 mkm
o This distance 5848 mkm accurately = 1.16 mkm/s x 5040 seconds
But
o Mercury motion during 1419.5 days passes a distance =5813 mkm = 5870
mkm – 57.9 mkm - And
o Mercury motion during 1433.5 days passes a distance =5870 mkm (Pluto
orbital distance)
Shortly
o Light motion depends on the distance (5906 mkm as Pluto orbital distance)
but Mercury motion depends on the distance (5870 mkm as Pluto orbital
distance).
o That tells both distances are found geometrically but also tells some
difference be found between light and planet motions.

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Mercury Motion Data Analysis
- The previous data shows that,
- Mercury uses light motion strategy. By that, Mercury moves a distance and then
uses this distance as a period of time to move another distance. By that the
distances be created in a network form.
- We don't know how a planet moves with low velocity can use distances values as
periods of time. The data needs more analysis to discover the rule on which this
using is done.
- Mercury motion aims to pass a distance = 5848 mkm= Mercury Pluto Distance,
this distance is the distinguish one in the 1st
trajectory of motion and also the 2nd
trajectory of motion. Many data be created in proportionality with this distance
which proves some geometrical machine be found behind these motions.
- Mercury moves the distance (5848 mkm) following light motion
- Mercury uses the rate (1 mkm= 1 solar day)
- Notice
- Jupiter Orbital Circumference (4900 mkm) is a very rich distance of discussions
and arguments. Because of that,
- Jupiter orbital circumference analysis be discussed in a separated point no. (4-3) .
- The idea is that, the light supposed velocity (1.16 mkm/s) creates a connection
between Mercury and Pluto by using Jupiter orbital circumference (4900). That
means, Jupiter orbital circumference be used as a central point in the light
trajectory of motion from Mercury to Pluto, because of that, the light supposed
velocity (1.16 mkm/s) created Jupiter orbital circumference (4900 mkm) by
different geometrical features which be required for this task. As a result we find
Jupiter orbital circumference is so complex distance and filled of questions.

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The Conclusions
- The data tells,
- Mercury is the origin point of the light supposed velocity (1.16mkm/s) motion. that
means, the light starts its motion from Mercury point. (A Conclusion No. 1)
- The light supposed velocity (1.16 mkm/s) passes the distance (4900 mkm = Jupiter
orbital circumference) in a period (4224 seconds). By that the light connects
between Mercury motion and Jupiter motion. (A Conclusion No. 2)
- Mercury Day Period be less than (4224 hours) by 5040 seconds because light
supposed velocity (1.16 mkm/s) travels during 5040s a distance = (5848 mkm) =
(Mercury Pluto Distance)
- Light supposed velocity (1.16 mkm/s) uses (5040s) to pass the distance (5848
mkm) and create a connection between Mercury motion and Pluto motion. (A
Conclusion No. 3)
- Notice
- 5848 mkm (Mercury Pluto Distance) –4900 mkm (Jupiter orbital circumference) =
946.5 mkm
- Where
- 940 mkm = Earth Orbital Circumference (error 0.7%)
- The value (946.5 mkm) is very important we will discuss in 2nd
Trajectory of
motion because it's related to Saturn motion data.

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Mercury Motion Data Analysis (Continued)
- The previous data analysis concluded that, Mercury is the source of light supposed
velocity (1.16 mkm/s).
- So, let's ask,
- Is Mercury Motion data in harmony with light supposed velocity (1.16 mkm/s)?
(I)
- Light suppose velocity (1.16 mkm/s) needs only 50 seconds to pass Mercury
orbital distance (57.9 mkm).
- Can this (50 s) be a data belong to Mercury Motion?
- Mercury (47.4 km/s) moves during 50.3 s a distance = 2390 km (Pluto diameter)
- Mercury (47.4 km/s) moves during 50.3 m x 60 s a distance = 142984 km (Jupiter
diameter)
- Mercury Venus Distance = 50.3 mkm ( 1mkm = 1 second)
- Mercury Neptune Distance (4437 mkm) = 50.3 mkm x 88
- (Mercury Orbital Period =88 days)
- Mercury Pluto Distance (5848 mkm) = 50.3 mkm x 116.2
- (57.9 mkm Mercury orbital distance x2 = 115.8 mkm)
- The data shows that, the period 50.3 seconds is a value be used frequently by
Mercury motion data. and mercury moves during (50.3 s) a distance = Pluto
diameter and moves during (50.3 m) a distance = Jupiter diameter, showing that
the 2 planets are the same planets mentioned by the 1st
trajectory motion.
- The basic difficulty is that, the light motion creates geometrical effects which we
can't discover because we don’t know neither their rule nor their effects. We have
only some data be transported from a point to another and that creates difficulties
for the analysis process.

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(II)
- Mercury Orbital Distance =57.9 mkm
- Mercury rotation period =58.65 solar days.
- The rate (1 mkm = 1 day) be used frequently in different motions data.
- The 2 values (57.9 mkm and 58.65 mkm) have an error (1%)
- Means, the 2 values (57.9 mkm and 58.66 days) can be created by the light
supposed velocity (1.16 mkm/s) motion during 50 seconds
- I try to show that, Mercury motion different data be in proportionality with light
supposed velocity (1.16 mkm/s) motion. which proves that Mercury is the origin
point of the light supposed velocity (1.16 mkm/s) motion.
- Because not only the period (5040 mkm) can be used or the period 4222.6 h
(which us equivalent to 4224 s) but also the period (50s)
- Notice
- 153.3 hours = Pluto day period
- 151.7 hours = 0.99 x 153.3 h (Pluto day period)
- But
- 176 mkm = 1.16 mkm/s x 151.7 seconds
- Where
- Mercury Day period =175.94 solar days (if 1 day = 1 mkm, the 2 values be
equivalent)

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- (3rd
Branch) Saturn Motion Effect.
- Saturn (0.838 mkm / daily) moves during = 5848 days, a distance = 4900 mkm
- This data shows Saturn motion effect on Mercury motion data
- And
- We have to discuss this data in separated point because Saturn creates another
reading for Mercury Motion Data.
- That means, the data be used by light motion for reasons but the same data be used
again by planet motion for different reasons.

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Equation no. (3)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm = 202318 mkm (error 1%)
- Where
- 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- 28255 mkm = Neptune orbital Circumference
- Equation no. (3) is the paper basic equation. Because it explains The Basic Energy
Trajectory Through The Solar System…
- First, We notice that,
- The equation uses the rate (2) because of Neptune orbital circumference. Where
the equation 3 parts can be used without the rate (2), But the last part (28255 mkm
+ 2 x 86400 mkm) needs the rate (2) because of Neptune orbital circumference
(28255 mkm). That explains why the equation uses the rate (2).
- Now let's divide the equation into 4 Parts.
(Part No. 1)
- 1.16 mkm per second x 2 x 86400 seconds = 2 x 100733 mkm
- Part no. (1) tells us a known information which is
- Light supposed velocity (1.16 mkm/s) travels during one solar day (86400s) a
distance = 100733 mkm = The 9 Solar Planets Orbital Circumferences Total
- The rate (2) is used for Neptune Orbital Circumference.
- This part of equation tells that, light motion depends on the solar day period. This
idea we have discussed in equation no. (1) of this discussion.
- Also we know that
- Light known velocity (0.3 mkm/s) travels during (86400 s) a distance = 25920
mkm

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- Where
- 25920 mkm = 17.75 mkm x 1461 days
- 17.75 mkm = the planets distances total during a solar day in addition to the Earth
moon motion distance during a solar day, and
- 1461 days = Earth Cycle (365 +365 +365 +366)
- The data tries to prove that, the light motion depends on the solar day period.
- Notice
- (25920 mkm x 2) =37100 mkm x 1.392
- Where
- The sun diameter =1.392 mkm
- The data uses the rate (2) because this rate be used in equation no. (4) which
expresses the solar system basic energy trajectory.
- That means the value (25920 mkm x 2) refers to the total energy according to light
known velocity (0.3 mkm/s) range of motion.
- The data tells the value (25920 mkm x 2) expresses really the total energy because
37100 km (Pluto orbital circumference) is the greatest orbit
- That means, when the total energy be expresses by the value (2 x 100733 mkm)
this energy be transported to the light known velocity based on the same rate
because it's one machine.
- The data proves the energy unification through the solar system spite of using 2
different velocities of light.

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(Part No. 3)
- 2 x 100733 mkm = (37100 mkm – 4900 mkm) x 2π =
- This part is very important because
- The data shows the energy motion (or light motion) started from 4900 mkm
- That means,
- To create Pluto orbital circumference 37100 mkm, the light starts from the point
4900 mkm and measures a distance = 100733 mkm by geometrical calculations.
- We have 3 points here
- The start point which is (4900 mkm =Jupiter orbital circumference)
- The direction of motion (toward Pluto)
- The measurement unit is 100733 mkm (defined by light supposed velocity motion
during a solar day)
- The data tells, Pluto orbital circumference is created depending on (4900 mkm )
Jupiter orbital circumference by using the light motion.
- We remember
- The distance 4900 mkm be passed by light supposed velocity (1.16 mkm/s)
depends on the period (4224 s) which is defined in comparison with Mercury day
Period (4222.6 hours)
- As A Result, we conclude that,
- Light supposed velocity (1.16 mkm/s) starts from Mercury to Jupiter and continues
from Jupiter to Pluto. that shows one clear trajectory of motion from Mercury to
Jupiter to Pluto.
- That means, the motion from Mercury to Jupiter considers Mercury is the head of
the inner planets and by that the connection between Mercury and Jupiter express
the connection between Jupiter and all inner planets.
- And
- The connection between Jupiter and Pluto doesn't contain any other planet. It’s one
directed motion from Jupiter to Pluto immediately

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- Shortly
- Jupiter and Pluto orbital circumferences be created by light supposed velocity
(1.16 mkm/s) motion depends on Mercury motion data by creating different steps
of motions to connect between Mercury and Pluto
- This data confirms that the distances be created based on network form and
according to one geometrical design.
Notice
- (2π) This rate distinguish between light motion and planet motion as we have
discussed before.
- The rate (2π) distinguishes here clearly between the planet and light motions.
where the difference (37100 mkm – 4900 mkm) refer to the planets motions where
the value 2 x 100733 mkm refers to the light motion and the rate (2π) distinguish
between the 2 motions.
- Venus equation which we will study with the part no. (4) of this equation uses also
the rate (2π) between the energy source and the planet received energy. we should
refer to this meaning in its discussion.

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(Part No. 4)
- 2 x 100733 mkm = 28255 mkm + 2 x 86400 mkm
- The total energy be reflected from Pluto to Neptune. The distances behave
perfectly as light beams.
- Neptune had seized 14% of the total energy and the rest of energy be reflected
toward the inner planets into 2 trajectories of energy each has (86400 mkm)
- We suppose that (Distance = Energy)
- The energy be sent from Neptune to Venus and Earth, let's see their equations in
following
- 2 x 86400 mkm = (28255 mkm – 680 mkm) x 2π (Venus Equation)
- Where
- 28255 mkm = Neptune Orbital Circumference
- 680 mkm = Venus Orbital Circumference
- Earth equation is perfectly similar to Venus equation where between both the error
is less than 1%
- Also we see the rate (2π) which distinguish between light and planet motion as we
have seen in our equation no. (2) (or it distinguish between the source of energy
and the planet received energy).
- Part (4) of the equation tells that, Neptune had seized 14% of the total energy and
the rest of energy is sent to Venus and Earth into equal trajectories of energy each
has (86400 mkm).
- That means, the inner planets energy be received from Neptune. And because of
that, the inner planets distance be controlled by Neptune orbital distance (4495.1
mkm) as the data shows that clearly.
- 4495.1 mkm (Neptune orbital distance) = 78.3 mkm x 57.9 mkm
- = 108.2 mkm x 41.4 mkm
- = (149.6 mkm x 120 mkm)/4

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- Where
- 57.9 mkm = Mercury Orbital Distance
- 108.2 mkm = Venus Orbital Distance
- 149.6 mkm = Earth Orbital Distance 41.4 mkm = Earth Venus Distance
- 78.3 mkm = Earth Mars Distance 120 mkm = Venus Mars Distance
- Now let's ask
- Why Neptune had seized 14% of the total energy but Pluto seized nothing?
- Because
- Mars Migration Theory tells us…
- Pluto was The Mercury Moon and had migrated with Mars Migration.
- Neptune, in that time, was occupied the point (5906 mkm = Pluto current orbital
distance). And
- Pluto be migrated and thrown to the end of the solar group, flying along way and
had collided with Neptune at the point (5906 mkm).
- Pluto had pushed Neptune and put it out of Pluto (influence area!), for that reason
Pluto eccentricity distance = 1410 mkm= Pluto Neptune Distance
- The collision between Pluto and Neptune produced Pluto moons and the Kuiper
belt.
- Neptune be forced to be more near to the sun with orbital distance =4495.1 mkm
and without orbit.
- Neptune be out of the distances network (the railways) generally and needed
energy to built its orbit
- That explains why Bode Law Couldn't predict Neptune orbital distance, because
it's created (additionally) on the original geometrical design to repair the planets
migration negative effects on the solar system motion. means, it's a distance not
designed geometrically with the original design. So the equations depend on the
original design couldn't predict Neptune orbital distance.
- Please review Mars Migration Theory (See The References).

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Notice
- 202318 mkm = (449197 km)2
- Where
- 449197 km =Jupiter Circumference
- Accurately
- (202318 mkm) / (449197 km)2
= (361/360)
- What's (361 degrees)?
- The cycle is 360 degrees but the Earth moon orbital regresses 19 degrees per year
and during 19 years moves Metonic Cycle (19 years) (=361 degrees).
- The moon orbit regression effects on many of the planets motions data and
because of that the usual rate (360) be changed into (361).

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The Motion 1st
Trajectory (A Summary)
- Mercury is the origin point of this motion trajectory
- The energy be transported from Mercury to Jupiter by the light supposed velocity
(1.16 mkm/s) motion and by this energy Jupiter orbital circumference be created
- The energy be transported from Jupiter to Pluto by the light supposed velocity
(1.16 mkm/s)
- The energy be reflected from Pluto to Neptune and
- The energy be reflected from Neptune to the inner planets
- The Motion 1st
Trajectory Shows the energy trajectory from Mercury to
Jupiter to Pluto, which creates the solar system basic energy trajectory.

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The Motion 2nd
Trajectory
- Light supposed velocity (1.16 mkm/s) travels starting from Mercury to Pluto
directly
- In this trajectory of motion the light doesn’t use a central point as did with Jupiter
orbital circumference. Instead the light travels from Mercury to Pluto directly.
- As a result, this Trajectory of motion be formed based on the following data,
(5848 mkm= Mercury Pluto Distance)
-
- This trajectory of motion we have studied deeply. Because the period (5040 s) is
distinguish Mercury day period as we have discussed.
- But this trajectory of motion still have more important data
- This trajectory of motion uses one equation only which is no. (4), let's discuss it in
following…

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Equation no. (4)
5848 mkm (Mercury Pluto Distance) – 4900 mkm = 948 mkm
- Where
- 5848 mkm = Mercury Pluto Distance
- 948 mkm = Earth orbital circumference (940 mkm) error (1%)
- Equation no. (4) shows Earth orbital circumference be taken into account with the
light supposed velocity motion for the 2 distances (5848 mkm and 4900 mkm)
- But
- Why the distance (948 mkm) be important here?
- The Earth moon daily displacement (=88000 km), and if the moon passes Earth
orbital circumference by using its displacement (88000 km), the moon needs a
period =10747 days to pass a distance = (945.5 mkm)
- Where 10747 days = Saturn Orbital Period
- The important information isn't (Saturn orbital period) but its (Saturn data),
because Saturn data be used frequently in the motions trajectories data between
Mercury and Pluto, for light and planet trajectories of motions.
- i.e.
- Through different data analysis we reach to Saturn data. this time we found (10747
days = Saturn orbital period), and in previous discussion we have found 3 data be
related Saturn motion defined by the light and mercury motions by using the
period (5040 seconds) which are:
o Saturn moves during (5848 days) a distance = 4900 mkm
o Mercury moves during (5040 seconds) a distance = 2 x Saturn diameters
o Mercury moves during 1433.5 days a distance = 5870 mkm = Pluto orbital
distance (old definition) or near to (5848 mkm = Mercury Pluto Distance)
Where (1433.5mkm = Saturn Orbital Distance)

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- Why (5848 mkm) – (4900 mkm) = 948 mkm (Earth Orbital Circumference)?
(error 1%)
- It's A Geometrical Distribution For Distances,
- But not only,
- Because this distribution contains data (10747 days) be used by Saturn and the
Earth moon motions…
- This data we should discuss with Saturn motion data because Saturn motion is
related to the light known velocity (0.3mkm/s) motion.
- The period 10747 days also be used by the moon to pass a distance = the distance
be passed by light known velocity motion during a solar day.

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The Motion 3rd
Trajectory
- Light supposed velocity (1.16 mkm/s) uses 2 different trajectories of motions (no.
1 and no. 2) to pass a distance =5848 mkm (Mercury Pluto Distance)
- And these motions be done by light velocity
- The first trajectory, the light travels from Mercury to Jupiter and then to Pluto
- The second trajectory, the light travels from Mercury to Pluto Directly
- The third trajectory expresses a motion from Mercury to Pluto (5848 mkm) but by
using mercury motion (Mercury velocity per a solar day =4.095 mkm)
- We have seen this data before, let's remember them:
o Mercury moves during 84 days a distance = 344 mkm
o Mercury moves during 346.6 days a distance = 1419 mkm
o Mercury moves during 1433.5 days a distance = 5848 mkm
o Where
o 5848 mkm = (Mercury Pluto distance)
o 1433.5 mkm = Saturn orbital distance
o 346.6 days = the nodal year.
- This trajectory of motion refers (frequently) to Saturn motion data among mercury
motion data. we don't know why that's happening…
- We can conclude that, the planet (Mercury) follows the light motion but with
different rate of time.
- Because this behavior is described by the matter creation theory. Where the theory
tells, the matter is born out of light but the born matter doesn't separate from its
light parent. On the contrary, they move together in one unified motion but by
using different rates of time.
- That's happening here. Mercury moves with light suppose velocity (1.16 mkm/s)
by using a different rate of time.

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- But the point we need to consider is, (Saturn Motion Data)
- Because in this trajectory of motion, Saturn motion data be used frequently and we
need to know why…
- Notice
- Equation no. (4) shows that Saturn data effects on Mercury motion data
- The fact is that, Saturn motion data be accompanying for Mercury motion data
along the way. We found Saturn motion data frequently in Mercury motion data
analysis.

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Equation no. (5)
1.16 mkm/s x 4900 seconds = 5678.1 mkm (Mars Pluto Distance)
And
- Where
- 4900 mkm =Jupiter Orbital Circumference
- Light supposed velocity (1.16 mkm/sec) travels during 4900 seconds a distance =
5678.1 mkm (Mars Pluto Distance).
- We remember that,
- The light supposed velocity (1.16 mkm/sec) depends on the period (4224 sec) to
pass the distance 4900 mkm.
- And depends on the period (5040 second to pass) the distance 5848 mkm (Mercury
Pluto distance)
- And we have asked why light supposed velocity (1.16 mkm/sec) created 2
trajectories between Mercury and Pluto positions? Or in more clear words why
light supposed velocity creates Jupiter orbital circumference (4900 mkm)by using
(4224 seconds)?
- Equation no. (5) gives an answer.
- Because light supposed velocity creates a connection between Mars and Pluto
positions with Mercury.
- Mars migration theory tells, Pluto was the Mercury moon and Mars was the next
planet to Mercury. And the 2 planets were migrated from their original positions.
- Light supposed velocity (1.16 mkm/sec) creates a connection between Mercury
and Pluto through the period 5040 second and another connection between Pluto
and Mars through the distance (4900 mkm)

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- Notice
- Light supposed velocity (1.16 mkm/sec) travels during 5687.1 seconds a distance
= 6585.4 mkm
- By the rate (1 mkm = 1 day) this distance 6858.4 mkm be = 6858.4 solar days
- Where (Saros Cycle =6858.4 solar days)
- Please remember
- Light known velocity (0.3 mkm/sec) moves during a solar day (86400 s) a distance
=25920 mkm,
- Where we see this distance (25920 mkm) as a period of time (25920 years = The
Procession Cycle)
- I try to show that, the period of Sarod Cycle (6585.39 days) is similar to the period
(25920 years), both be created by light motion behavior, which proves it's usual a
behavior in the solar system
- But that creates one more connection between Mars motion and the Earth moon
motion because Saros is a cycle produced by the moon motion effect.

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The Motion Trajectories Summary
- As we have discussed in the previous analysis,
- There are 3 motions started from Mercury moving toward Pluto, and these motions
are:
o Light supposed velocity (1.16 mkm/) motion during (5040 s) to pass (5848
mkm = Mercury Pluto Distance)
o Light motion from Mercury to Jupiter by using (4224s)
o 1.16 mkm/s x4224 seconds =4900 mkm (= Jupiter orbital circumference),
where Mercury uses Jupiter orbital circumference as its central point to
connect with Pluto.
o Mercury Motion depends on (5040) to pass in three steps toward Pluto by
the data
o 4.095 mkm x 84 days =344 mkm
o 4.095 mkm x 346.6 days =1419 mkm
o 4.095 mkm x 1433.5 days =5870 mkm (very near to 5848 mkm)
o Notice
o Light supposed velocity (1.16 mkm/s) motion depends on the rate (2π) but
Planet motion depends on (R). So if Mercury want to connects with Jupiter,
light motion doesn't use the distance (778.6 mkm Jupiter orbital distance)
but use (4900 mkm =Jupiter orbital circumference)
o 778.6 mkm =1.0725 x 720.7 mkm (Mercury Jupiter Distance)

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The General Discussion
- I have tried to arrange the data in best form to show that, the data be created based
on a geometrical design for a light beam motion by which the solar planets and
their distances be created.
- The paper hypothesis gives a chance for better explanation….
- The hypothesis tells a light beam its velocity (1.16 mkm/sec) caused the solar
system creation and motion, and by effect of the light motion the distances be
created in a network form.
- The hypothesis shows itself so complex because we need to prove (at first) that
there's a light beam its velocity =1.16 mkm/s
- By the planets motions data arrangement I have tried to show that the planets
motions data be created depends on a light beam its velocity =1.16 mkm/s and if
this light beam isn't found there's no chance to create the solar planets motions data
and their distances as their values. This discussion is done in so deep details where
Jupiter motion data and its distances with the inner planets and with Pluto, this all
data will be simply removed if there's no light beam its velocity =1.16 mkm/s.
- The data still have more support for the hypothesis but needs at first to discover
the geometrical design based on which the planets motions data be created.
- Although, this try is a strong one, but many basic questions are still left behind, we
have to face them as a part of our effort searching for the truth
- (A Question) what's the relationship between Planet motion distance and a
distance be found between 2 planets? If these 2 distances be equal why does this
give any geometrical meaning?
- For example
- Light supposed velocity (1.16 mkm/s) travels during 5040 seconds a distance =
5848 mkm = Mercury Pluto Distance
- What's the relationship between the distance be passed by light motion (5848
mkm) and Mercury Pluto Distance (5848 mkm)?

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- If these 2 distances are equal why this is important?
- My answer for this question is a simple one ( I Don't Know How The Machine
Works).
- For example
- Earth moves during a solar day (24 h) a distance = 2574720 km
- Pluto moves during its day period (153.3 h) a distance = 2593836 km
- These 3 distances are equal with max error only (1%)
- Can these equal distances effect on any planet motion data? yes
- As we discuss in (The Planets Motions Depend On Different Rates Of Time)
the three planets motion data be created in full proportionality with one another.
can this data be in proportionality because of the distances equality or the distances
equality be a result of the data proportionality, I can't give a decision.
- The fact is that, the planets data be in proportionality and the distances are equal.
- To prove this point of view let's bring the data here for better understanding…
- More Data
Group no. (1) (Pluto And Earth Rate Of Time)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours

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- Where
- 406000 km = Pluto Motion Distance during a solar day
- 88000 km = The moon displacement daily
- And
- And
- 153.3 hours = Also (153.3-) Pluto Rotation Period
- The data confirms the point of view, the equal distances effects on the planets
motion data be caused it to be in proportionality with one another. why or how?
We still search for the machine geometrical details.
- The discussion is limited and can't receives its power, as a creature crippled and
can't walk! Why? because we don't know the used geometrical rules based on
which the solar system be created and moving.
- For example
- The equal distances (as we have seen in Earth, its moon and Pluto data) is a
method used widely in the solar system. That means, all planets use this method.
All planets create equal distances with one another and based on these equal
distances the planets motions data be in proportionality with one another.
- Let's use one more example:
- Mercury moves during its rotation period (58.65 days) a distance = 243 mkm(1%)
- Mars moves during Venus day period ( 116.75 days) a distance = 243 mkm
- These are the equal distances, where is the proportionality of data?

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- (Mercury Day Period / Venus Day Period) = (Mercury orbital period/
Mercury rotation period)
- The data shows that, Venus Day period be created in proportionality with Mercury
cycles periods. Can that be a result for the equal distances?
- The equal distances is a method used thousands of times in the solar system, where
many planets motions distances be passed in defined periods of time be equal one
another. we don't know what effect be done from this distances equality and by
that a great part of the machine be out of our sight…
- Shortly,
- We have to depend on some conclusions (and even guess) to conclude how the
solar group be created and moving
- The other option is the imaginary ideas. As Newton idea of the sun mass gravity,
where he imagined that the sun is the planets motions reason while the fact is that
the sun is created after all planets creation and motion. and in fact the sun rays be
created by using the planets motions energies total. means, based on the planets
motions the sun be created, and that tells the planets can be found without the sun
but the sun can't be found without the planets. Newton idea is completely
mistaken.
- Our situation is not so better. The point is that, the geometrical rules book is inside
the light nature, and we can't catch how the geometrical effects be done but we can
discover them in every where.
- Let's summarize the machine basic difficulties
o Planet moves side by side with a light motion by that the planet motion
refers to light motion features but we can't catch the velocity which creates
these features
o The equal distances method is the method caused the planets motions. this
method works geometrically.

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o That means, this method works as a waterwheel or as a lever. A tool works
by a geometrical effect. But we don't understand what benefit be produced
by the equality of distances. This equality causes the planets motions but
how?
o We notice also that,
Jupiter motion depends on light supposed velocity (1.16 mkm/s) and
all distances around Jupiter be defined based on this velocity (1.16
mkm/) but
Saturn motion depends on the light (0.3 mkm/s) where different data
belong to Saturn depends on light known velocity.
The Earth moon motion be in proportionality with both light beam
velocities! The data confirms this meaning
10921 km x 27.3 days =300000 km (error 0.5%) the equation tells if
the moon rotates around its axis one time per solar day as Earth does,
the moon would pass by its circumference during 27.32 days (the
moon orbital period) a distance =300000 km = light known velocity
(0.3 mkm/s) motion distance during 1 second.
43000 km x 27.3 days =1160000 km (error 1.3%) the equation tells if
the moon is a point without circumference and moves from perigee
point to apogee in a solar day and in the next day moves from apogee
to perigee … during the moon orbital period (27.3 days)the moon
would move a distance =1.16 mkm
Notice (43000 km = the distance between perigee and apogee points)
10921 km x 86400s =940 mkm, the equation tells if Earth revolves
around the sun a complete revolution (940 mkm) in one solar day
only (86400 s), the moon circumference (10921 km) will equal a
distance of Earth motion during 1 second period of time. (notice, the
geometrical design can create the effect without planet real motion)

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4-3 Jupiter Orbital Circumference Analysis
I-Data
Group No. (1)
(A)
1.16 mkm/s x 4224 seconds = 4900 mkm (Light Motion Reading)
(B)
(449197 km / 27.78) = (4900 mkm /0.3 mkm)
(C)
1.16 mkm/s x 4224 seconds = 4900 mkm (Planet Motion Reading)
(D)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm
(E)
1.1318 mkm/s x 4222.6 days = 4780 mkm
(F)
4900 mkm = 449197 km x 10921 km
But
4846 mkm =1.392 mkm x 3475 km
(G)
9.7 km/s x 142984 seconds = 1386945 km (notice 1.392 mkm = the sun diameter)
(H)
4900 mkm = 0.384 mkm x 12756 km =0.406 mkm x 12104 km
(I) (please remember)
(37100 mkm – 4900 mkm) x 2π =28255mkm + 2 x 86400 mkm =2 x 1.16 mkm/s x 86400 s
Group No. (2)
(J)
(2 x The Sun Mass) = Jupiter Mass x 2094

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II-Discussion
- Jupiter orbital circumference is a very rich distance for discussion and analysis,
also it provides surprised using of data.
- There are 3 basic features of this distance makes it very specific distance, let's refer
to them in following:
- (1) The Distance 4900 mkm Is Defined By Many Planets Motions
- (2) The Distance 4900 mkm be in proportionality with The Sun Diameter.
- (3) The Distance 4900 Is Defined also by Light Motion Also.
- Let's analyze the distance 4900 mkm in following…
Equation No. (A)
1.16 mkm/s x 4224 seconds = 4900 mkm (Light Motion Reading)
- We have studied this equation deeply in the previous discussion.
- This equation is provided here to remember its meaning only because we need it in
the following discussion
- Equation no. (A) tells,
- Light supposed velocity (1.16 mkm/s) travels during the period 4224 seconds a
distance = 4900 mkm = Jupiter orbital circumference
- We consider that, 1 second of light motion be = 1 hour of Mercury motion and by
that the period (4224 s) be = (4224 hours)
- This analysis lead us to conclude that light supposed velocity (1.16 mkm/s) motion
effects on Mercury motion and causes Mercury day period to be 4222.6 hours and
decreased it from (4224 h) by (5040 seconds) because the light supposed velocity
(1.16 mkm/s) travels during 5040 seconds a distance = 5848 mkm (= Mercury
Pluto Distance). And by that the light supposed velocity creates a connection
between Mercury and Pluto motions.
- This is a summary for this equation which we have discussed deeply before in the
light supposed velocity proves discussion.

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Equation No. (B)
(449197 km / 27.78) = (4900 mkm /0.3 mkm) (error 1%)
- Where
- 449197 km = Jupiter Circumference
- 0.3 mkm/sec = light known velocity (300000 km /s)
- 27.78 km/s = The Moon Velocity.
- Equation no. (B) tells, the period the Earth moon needs to move a distance =
449197 km = Jupiter circumference = 16330 sec
- Light known velocity (0.3 mkm/) needs this same period of time (16330 sec) to
pass a distance =4900 mkm (= Jupiter orbital circumference)
- i.e.
- during the moon passes Jupiter circumference, the light known velocity (0.3
mkm/s) passes Jupiter orbital circumference! Why?
- Equation no. (f) causes more puzzles for this discussion, where (4900 mkm =
449197 km x 10921 km), it tells Jupiter orbital circumference be defined as a
multiplication between the moon circumference and Jupiter circumference!
- Geometrically we considered Jupiter orbital circumference (4900 mkm) be built
based on the 2 measurements (Jupiter circumference and the moon circumference!)
- This idea be supported by the fact
- Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km =Jupiter
diameter.
- This data gives a feeling, the geometrical structure of Jupiter orbital circumference
depended on Jupiter circumference and the moon circumference…. But
- What's the relation of this geometrical structure with light known velocity? How
light known velocity (0.3 mkm/s) be in proportionality with this same data?!
because light known velocity (0.3 mkm/s) should be an independent velocity and
has no proportionality with the planets motions velocities!

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- Can we understand this data?!
- Jupiter orbital circumference be created by a motion of light supposed velocity
(1.16 mkm/s) during the period (4224 seconds). But the distance (4900 mkm) be in
proportionality with light known velocity (0.3 mkm/s) in comparison with planets
motions velocities…
- Shortly why (449197 km / 27.78) = (4900 mkm /0.3 mkm)?
- Or
- (light velocity 0.3 mkm/ the moon velocity 27.78 km) = (4900 mkm /449197 km)?
- The rate (0.3 mkm /27.78) = 10800
- And
- The rate (4900 mkm/449197 km) =10921 (the moon circumference =10921 km)
- The difference between 10800 and 10921 is 1%
Notice
- Why the moon velocity be =27.78 km/s? because the moon moves daily a
distance = Earth motion distance daily because they aren't separated from one
another. means the moon daily motion distance =2.574 mkm but this distance be
effected by the rate 1.0725. (we have referred to that frequently before). We don't
know why the distance 2.574 mkm be effected by the rate (1.0725) but 40% of all
distances in the solar system be effected by this same rate 1.0725 and appendix
no.1provides a list for these distances. By that the moon distance 2.574 mkm be
=2.4 mkm daily which =27.78 km/sec.
Notice
- Earth (29.8 km/s) moves during (16330 sec) a distance = 4 x Saturn diameter (1%)
- Saturn (9.7 km/s) moves during (16330 sec) a distance = Uranus Circumference (1.3%)
- Neptune (5.4 km/s) moves during (16330 sec) a distance = 88000 km (the moon
daily displacement).

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Equation No. (C)
1.16 mkm/s x 4224 seconds = 4900 mkm (Planet Motion Reading)
- This equation we know perfectly
- Light supposed velocity (1.16 mkm/s) travels during 4224 seconds a distance =
4900 mkm = Jupiter Orbital Circumference
- But
- This equation has another reading, let's try with it in following
(1)
o Jupiter (13.1 km/s) moves during 24.6 h a distance = 1.16 mkm.
o Where (24.6 hours = Mars rotation period)
(2)
o Jupiter orbital circumference (4900 mkm) be divided on the distance 1.16
mkm and the rate 4224 (or 4222.6).
o Means, if each 1 hour of Mercury Day period be = 24.6 hours, based on that,
Jupiter during the period (4222.6) x (24.6 h) moves a distance =4900 mkm =
Jupiter orbital circumference
o (4331 days x 24 h = 4224 x 24.6h) where 4331 days = Jupiter orbital period
o Can that refer to some interaction of motions among the 3 planets (Mercury,
Mars and Jupiter)? Of course yes, this fact is proved in the planets unified
motion discussion in this paper (point no.6 of this paper) where huge
number of data shows clearly the motions interactions among the 3 planets.
(3)
o Notice
o Light supposed velocity (1.16 mkm/sec)moves during 4900 seconds a
distance = 5684 mkm (Mars Pluto Distance).
o By that,

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o Light supposed velocity (1.16 mkm/sec) creates ac connection between
Mercury, Jupiter and Mars motions, where Mars be connected with Mercury
through Pluto.
o The result is that,
o A strong connection be found between Mercury, Mars and Jupiter. And this
connection is seen clearly in the light motion data.
o But
o Can this connection be a real one? Is there really an interaction of motion
between Mercury, Mars and Jupiter?
o This question is answered in point no. (6) of this paper (The Solar Planets
move one unified general motion), where this point provides tenths of data
proves that, Mercury, Mars and Jupiter Motions can't be considered as 3
independent planets motions, On the contrary, The Data shows clearly that,
they move together one unified general motion which is proved strongly by
tenths of these planets motions data.
(4)
o I want to say that,
o We have 2 pictures for the same scene. As if we use 2 covers for the same
place. One cover is put on another. the 2 covers are equal in length. But they
are different in nature. Similar to that, we have equal distances (4900 mkm)
be passed by (light motion) and by (planet motion). the motions create
interactions in data. while we don't see the light motion but we see only the
planet motion. but we discover the interactions which are done as a result
for light motion effect on planet motion.
(5)
o The real data causes even more confusion, because light moves 1.16 mkm in
one second. but Jupiter moves 1.16 mkm in 24.6 hours, by that the simple
interactions which depend on (1 second) should be explained in some

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complex form based on the period (24.6 h) and then we have to ask (why
Jupiter uses Mars rotation period 24.6 h?). Because we know that some
relationship is found between Mercury Day Period and Jupiter orbital
circumference. And now we have a relationship between Jupiter orbital
circumference (4900 mkm) and Mars rotation period (24.6 h) through the
distance 1.16 mkm. That simply creates a relationship (or a proportionality)
between Mercury day period and Mars rotation period! (why?)
o Notice/
o (Mercury Day period 4222.6h) / (Mars rotation period 24.6 h) =170 (error 1%)
o Mercury Mars Distance = 170 mkm
o But
o (1407.6 h/ 24.6 h) = 2 x ( (4900 mkm) /(170 mkm)), where
o 1407.6 h = Mercury Rotation Period
o 24.6 h = Mars Rotation Period
o 4900 mkm = Jupiter Orbital Circumference
o I wish the argument logic is clear.
o Jupiter moves a distance 1.16 mkm during a period (24.6 h =Mars Rotation
Period) because (1st
, Jupiter motion and Jupiter orbital circumference 4900
mkm have a relationship with Mercury Day Period). And (2nd
, Mercury
motion has a relationship with Mars Motion as the previous data refers).
We deal with a machine of gears, the main motor is the light motion and the planets
are gears, because of that, their data be in proportionality with one another according
to the motions interactions.
Notice
Mars moves during 13.37 hours a distance = 1.16 mkm

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Equation No. (D)
4900 mkm = 360 mkm +680 mkm +940 mkm +1433 mkm +1433 mkm
(Error 1%)
- Where
- 360 mkm = Mercury Orbital Circumference
- 940 mkm = Earth Orbital Circumference
- 1433 mkm = Mars Orbital Circumference
- The data considers that, the Earth Moon Orbital Circumference around the sun
=1433 mkm = Mars Orbital Circumference.
- If we accept this idea, the data will give a clear meaning. Which tells that (Jupiter
orbital circumference = the inner planets orbital circumferences total)
- Then we have to ask.
Why does Jupiter Orbital Circumference=
= The Inner Planets Orbital Circumferences Total?
- More data can help our analysis,
(I)
- We accept that, Jupiter orbital circumference 4900 mkm be passed by a light
supposed velocity (1.16 mkm/s) in a period = 4224 seconds. And by this motion
the light caused to create Mercury day period (4222.6 h) where we accept that 1
second of light motion be = 1 hour of Mercury motion.
- Venus and Earth Data also be effected by (4224), Let's remember their data
o 4224 mkm = 2π x 671 mkm (Venus Jupiter Distance)
o And
o (5040 sec/4224 sec) = (928 mkm/778.6 mkm)
o Where

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o 778.6 mkm = Jupiter orbital distance
o 928 mkm = Earth Jupiter distance (notice 928 mkm= 778.6 mkm +149.6 mkm)
o 5040 sec = Mercury Day Period be less by 5040 seconds than 176 solar days
(II)
o 778.6 mkm = 1.0725 x 720.7 mkm (Mercury Jupiter Distance)
o 720.7 mkm = 1.0725 x 671 mkm (Venus Jupiter Distance)
o 671 mkm = 1.0725 x 629 mkm (Earth Jupiter Distance)
o 778.6 mkm = Jupiter Orbital Distance
(III)
o 1.16 mkm /sec x 500 sec = 580 mkm
o 1.16 mkm /sec x 580 sec = 671 mkm (Venus Jupiter Distance)
o 1.16 mkm /sec x 671 sec = 778.6 mkm (Jupiter Orbital Distance)
o 1.16 mkm /sec x 629 sec = 720.7 mkm (Mercury Jupiter Distance) (1%)
- The data shows, the distances between Jupiter and the inner planets are defined
based on Geometrical Calculations, because of that all distances are rated with
(1.0725) and (1.16).
- Means, these planets motions are not independent motions, on the contrary they
are (complementary motions) and be created based on One Geometrical Design.
- The previous data shows a complex geometrical machine behind. More analysis
provides even more complex interactions for example
- (778.6 mkm/ 629 mkm) = (720.7 mkm/580 mkm)
- These distances also we have used in the previous data. that means, the distances
between Jupiter and the inner planets be created by some geometrical system
makes these distances be in proportionality to one another mutually.
- Means,
- Not just, Jupiter orbital circumference be = the inner planets orbital circumferences
total, but also all used distances be created in proportionality with one another.

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Equation No. (E)
1.1318 mkm/s x 4222.6 days = 4780 mkm
- Where
- 1.1318 mkm /day = Jupiter motion distance during a solar day
- 4222.6 hours = Mercury Day Period
- Equation (E) supposes that 1 hour of Mercury Motion = 1 day of Jupiter motion.
by that, Jupiter uses Mercury Day Period as 4222.6 Solar Days
- During 4222.6 days Jupiter moves 4780 mkm. But during 4331 days Jupiter moves
4900 mkm.
- That means, the period 4222.6 days is incorrect period, because if we want to
measure the distance 4900 mkm we should use the period 4331 days
- But
- (4222.6 days /4331 days) = (654.9 mkm/ 671 mkm)
- Where
- 654.9 mkm = Jupiter Saturn Distance
- 671 mkm = Jupiter Venus Distance
- That tells the rate (4222.6 /4331) is defined geometrically and by that, the distance
4780 mkm which is less than 4900 mkm by 2.5% may refer to the distance 4846
mkm (with error 1.3%)
- Based on that
- Equation no. (E) tells, Jupiter moves during 4222.6 days a distance = (4780 mkm)
= 4846 mkm (the inner planets orbital circumferences total) (error 1.38%)
- Equation no. (E) can refer to that, 1 hour of Mercury Motion be = 24 hours of
Jupiter motion.
- This is the same rate of Uranus where 1 hour of Mercury Motion be =24 hours
of Uranus motion.
- Be we know that, 1 h of Mercury motion = 9.18 h of Pluto motion

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- Based on that
- 1 h of Pluto motion = 2.62 h of Uranus Motion = 2.62 h of Jupiter Motion
- We should discuss that in details in the planets motions depend on different rates
of time (Point no. 7) of this paper.
- The rate 2.62 is so specific for both planets
- Uranus Circumference x 2.62 = Uranus motion distance during its day period
(421056 km)
- And
- Jupiter Circumference x 2.62 = 1.16 mkm (error 1.4%)
- I try to show that, the distance (1.16 mkm) is found again under some new data. it's
not some random number found by chance in Jupiter data. it's a basic distance
based on which Jupiter motion and orbital circumference be designed, because of
that we face this distance (1.16 mkm) in any place we move.
- The negative point is that, we can't discover the geometrical design based on which
this distance 1.16 mkm be defined. For that reason, we meet this distance (1.16
mkm) frequently but couldn't catch the machine which produces it.
- Notice
- Light known velocity (0.3 mkm/s) x 4780s =1433.5mkm (Saturn Orbital Distance)
- Light known velocity (0.3 mkm/s) x 4879s =1461 mkm
- Where
- 4879 km = Mercury Diameter
- 1461 days = Earth Cycle (365 +365 +365 +366 days =1461 days)
- The distance 4780 mkm be used as (4780 seconds) where usually light uses the
rate (1 mkm = 1 second) but the planet uses the rate (1 mkm = 1 day).
- Please notice, again the distance (1461 mkm) be seen by us as a period of time
(1461 days) it's a usual behavior

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Equation No. (F)
4900 mkm = 449197 km x 10921 km
But
4846 mkm =1.392 mkm x 3475 km
- Where
- 449197 km =Jupiter Circumference
- 10921 km = The Moon Circumference
- And
- 1.392 mkm = The Sun Diameter
- 3475 km = The Moon Diameter
- 4846 mkm = The Inner Planets Orbital Circumferences Total
(4846 mkm = 360+680+940+1433+1433)
- Equation (F) tells, the multiplication of the sun diameter and the moon diameter =
accurately the value (4846 mkm)
- But
- The multiplication of the Jupiter Circumference and the moon Circumference =
accurately the value (4900 mkm)
- Can that refer to some relationship between the distance 4900 mkm and the sun
creation?
- Let's move step by step in following:
o Jupiter diameter x π2
= 1411196 km which is different from the sun diameter
1392000 km with the rate (1.38%)
o But
o Saturn (9.7 km/s) moves during 142984 seconds a distance = 1386945 km
(notice 1.392 mkm = the sun diameter and the difference 0.4%)
o Can this data tell (the sun is created in proportionality with Jupiter diameter)

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o We have 2 reasons for this conclusion. Because (1st
) the data refers to a
proportionality between the sun and Jupiter diameter and (2nd
) the data
refers to proportionality between the sun and Jupiter orbital circumference.
That shows 2 basic data be in proportionality with the sun diameter.
o The second player is the Earth moon
o The moon circumference (10921 km) be in proportionality with Jupiter
orbital circumference 4900 mkm based on Jupiter circumference (449197
km).
o And
o Jupiter (13.1 km/s) moves during 10921 sec a distance = 142984 km =
Jupiter diameter.
o I don't need to prove that, this data be created based on geometrical system.
Because the data proves that strongly and clearly. I need to discover this
geometrical system based on which this data be created.
o Shortly
o Jupiter is the basic player found on other side and effects on the sun creation
process. Where this event is happening, Jupiter adopted the Earth moon as
its own son and uses its data as part of Jupiter own data. as a result the earth
moon (small planet) has some chance to effect on the sun creation data!
o Again
o Why We See The Sun Disc =The Moon Disc? Because
o (The sun diameter / the moon diameter) = (Earth orbital distance/ Earth
moon Distance)
o Why The Diameters Rate = The Distances Rate?
o Because all players are created in proportionality with 4900 mkm (Jupiter
orbital circumference).
o The data can't be created by any pure coincidence. The fact can be seen if
we try to answer the question (how the matter is created?)

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Equation No. (H)
4900 mkm = 0.384 mkm x 12756 km =0.406 mkm x 12104 km
- Where
- 0.384 mkm = the moon orbital distance
- 0.406 mkm = the moon orbital Radius At Apogee
- 12756 km = Earth Diameter
- 12104 km = Venus Diameter
- Equation no. (H) shows, the distance 4900 mkm controls the data around the
moon motion.
- Earth and Venus Diameters must be ancient and aren't changed. That tells the
value (4900 mkm) use the 2 planets diameters as references to define the moon
motion range. By that the moon orbital distance be =0.384 mkm depends on Earth
diameter and the moon apogee radius be 0.406 mkm depends on Venus diameter.
- The data shows this meaning but no geometrical mechanism be discovered to
answer how this data be created in proportionality with one another.
- More data can support the same meaning for example
- This data tells that (the apogee orbital radius 406000 km be defined by Venus),
where (406000 km = 3475 km x 116.75), and 3475 km = The Moon Diameter and
116.75 days = Venus Day Period.
- The data gives the meaning but no geometrical mechanism be discovered.
- Shortly
- The distance 4900 mkm controls the sun creation process and the moon
orbital motion definition.
- The distance 4900 mkm uses Earth and Venus diameters as references to
define the moon orbital distance and its apogee radius.

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- Notice
- 1433 mkm =550.7 x 2.5986 mkm
- 2.598 mkm (the moon displacements total during 259.53 days),
- 550.7 mkm= Mars Jupiter Distance,
- 1433 mkm = Saturn Orbital Distance
- This data tells why the data considers the moon orbital circumference round the
sun be = 1433 mkm = Mars orbital circumference and Not be =940 mkm = Earth
orbital circumference.
- The data shows that, the Earth moon is the son of the inner planets. The moon isn't
belonged to the Earth alone where Venus effects greatly on the moon apogee
radius definition on one side where Mars still effect on the moon motion and
causes its orbital circumference around the sun be considered =1433 mkm = Mars
orbital circumference on the other side.
- The geometrical machine based on which this data be created has answers for the
question how this data be created.
Comments
- The distance 4900 mkm defines the moon diameter and its orbital motion range
- And
- The distance 4900 mkm controls the sun creation process and defines the sun
diameter.
- Because of that, the sun and moon data be created in proportionality as we have
discussed before.
- But
- Is the aforementioned data sufficient for this conclusion? Suppose (4900 mkm =
the sun diameter 1.392 mkm x 3475 km the moon diameter) can this data be a
sufficient for this heavy conclusion? Let's discuss the next data to answer this
question.

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Group No. (2)
Equation No. (J)
(2 x The Sun Mass) = Jupiter Mass x 2094
Where
2094 mkm = Jupiter Uranus Distance
- How to make the rate 2094 be = the distance 2094 mkm?
- Geometrically, this process depends on Jupiter motion. because Jupiter diameter
142984 km = (1 million km/7) where Mercury orbital inclination = 7 degrees
- That means, the interaction of motions between Jupiter and Mercury can produce
the distance 1 mkm based on Jupiter diameter.
- By that, the rate 2094 x 1 mkm = 2094 mkm (Jupiter Uranus Distance)
- Why do we need this data?
- I try to prove that, the sun is created by an effect of Jupiter motion. We have seen a
proportionality of data between the sun diameter and the distance 4900 mkm
(Jupiter orbital circumference) and also between the sun diameter and Jupiter
diameter. and this data shows a new proportionality between the sun mass and
Jupiter mass.
- Equation no. (J) shows that, Jupiter Uranus Distance has some role in the sun
creation (or perhaps Jupiter Uranus Motions Interaction does this role)
- Why does The Equation Use 2 Values Of The Sun Mass?
- We remember, Jupiter energy which is sent to Pluto used (2 solar days) where,
light supposed velocity (1.16 mkm/s) travels during one solar day a distance = the
solar planets orbital circumferences total, but Jupiter energy uses 2 solar days
which provides energy = 2 x the solar planets orbital circumferences total
- This is happened because of Neptune orbital circumference as we have discussed
before (equation no. 3). So if the used energy be double value, and the matter is
created of energy, that caused the sun mass be used in double value.

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- Based on different data, Jupiter motion shows its role in the sun creation.
- Jupiter Uranus Distance shows specific role in this process.
- The difficulty is that, We can't discover the geometrical mechanism by which this
process is done or this data be created. the data tells what's happened but doesn't
tell how that's happened. By that the argument provides clear meanings but not
clear mechanism of motions.
- One more important equation we need to remember is the following
- 90000 mkm = 2872.5 mkm (Uranus orbital distance) x (97/3.1)
- Where
- C2
= 90000 mkm (if the period of time be = 1 second)
- 97 deg = 97.8 deg (Uranus Axial Tilt) – 0.8 deg (Uranus orbital inclination)
- 3.1 deg = Jupiter Axial Tilt
- We need this data because the sun rays be created from the value (C2
)
- The data shows that, the interaction between Uranus and Jupiter effects on the sun
creation process.
- This data supports the meaning we get from the analysis of the distance 2094 mkm
(Jupiter Uranus Distance)
- Notice
- The machine depends on layers, So, the rate (97/3.1) uses the value 97
- But, other rates can use different data for example
- (97.8 deg /3.1 deg) x 2872.5 mkm = 90560 mkm
- (where 90560 days = Pluto Orbital Period)
- Also
- (98.6 deg /3.1 deg) x 778.6 mkm x 2 = 49528 mkm
- Where
- 98.6 deg =97.8 deg (Uranus axial tilt) + 0.8 deg (Uranus orbital inclination)
- 778.6 mkm = Jupiter orbital distance and 49528 km = Neptune diameter.

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The Conclusions
- Jupiter orbital circumference 4900 mkm effects greatly on the machine motion
- The distance 4900 mkm defines the moon diameter and its motion range and by
that Jupiter motion effect on the moon motion be defined clearly
- Also
- The distance 4900 mkm defines the sun diameter 1.392 mkm, and that be done
through interaction with Jupiter diameter.
- These effects are found by the energy provided for the sun rays creation process
- This energy is seen through the interaction between Jupiter and Uranus motions.

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5- Mercury Jupiter Distance Analysis
5-1 Preface
5-2 Mercury Jupiter Distance analysis
5-3 Planets Motions Interaction
5-4 Planets Unified General Motion
5-1 Preface
- Mercury Day Period =4222.6 hours
- Mercury moves during its day period a distance = 720.7 mkm = (Mercury Jupiter
Distance)
(I)
- The hypothesis tells that, Mercury motion depends on a motion of light beam its
velocity (1.16 mkm/sec). that means,
- Light supposed velocity (1.16 mkm/s) motion effect on Mercury Motion causes
Mercury to move a distance 720.7 mkm during (4222.6 hours)
(II)
- The hypothesis tells, the light supposed velocity (1.16 mkm/s) started its motion
from Mercury to Jupiter to Pluto and through Pluto the light motion creates a
connection with Mars motion.
- Means,
- The light supposed velocity (1.16 mkm/s) effects on Mercury, Mars, Jupiter and
Pluto. light motion forces these 4 planets to move equal distances (720.7 mkm) in
equal periods of time (4222.6 h = Mercury Day period) (Spite of the difference in
the planets motions velocities)
(III)
- Because light supposed velocity (1.16 mkm/s) causes the 4 planets to move equal
distances (720.7 mkm) in equal periods of time (4222.6 h), That causes the
motions of (Mercury, Mars and Jupiter) to depend on equal periods of time (196.5
seconds). The 3 planets motions depend on the period (196.5 seconds)

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(IV)
- Because the motions of the 3 planets (Mercury – Mars – Jupiter) depend on the
same period 196.5 seconds, that causes the 3 planets motions to be integrated into
one unified general motion.
- Means,
- Mercury, Mars and Jupiter moves together one unified general motion. and this
unified motion is shown and proved clearly in their motions data because they
depend on equal periods of time (196.5s) which enables the integration of the 3
planets motions into one unified general motion.
- This point no. (4) is divided into 3 basic points of discussion which are:
- Point no. (4-2 ) this point analyzes the distance 720.7 mkm which should be passed
by the 4 planets (Mercury – Mars – Jupiter – Pluto) in equal periods (4222.6 h)
(4-2 Mercury Jupiter Distance analysis)
- Point no. (4-3 ) this point shows how the motions of the 3 planets (Mercury – Mars
– Jupiter) depends on the period (196.5 seconds) which caused the integration of
the 3 planets motions into one unified motion.
(4-3 Planets Motions Interaction)
- Point no. (4-4) this point proves that, the 3 planets (Mercury- Mars – Jupiter) move
one unified general motion.
(4-4 Planets Unified General Motion)

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5-2 Mercury Jupiter Distance Analysis
I-Data
(a)
47.7 km/s (Mercury velocity) x 4222.6 h x 3600 s = 720.7 mkm
2.082 mkm/day (Mars velocity daily) x 346.6 days = 720.7 mkm
1.1318 mkm/ day (Jupiter velocity daily) x 636 days = 720.7 mkm
0.406 mkm/ day (Pluto velocity daily) x 1775.2 days = 720.7 mkm
Notice
720.7 mkm/ 196.5 mkm = 3.66
(b)
(929 mkm/629 mkm) = (940 mkm/636 mkm)
And
5848 mkm = 2π x 929 mkm
(c)
2.082 mkm/ day x 346.6 days =720.7 mkm
And
(5848 mkm x π) = 720.7 mkm x 25.2 (error 1%)
(d)
0.406 mkm/ day x 1775.2 days =720.7 mkm
But
(90560 days x 2) /1775 days = 102
(e)
(940 mkm/720.7 mkm) = (119.7 mkm/91.7 mkm) = (720.7/550.7) = (1557.2 mkm/
1205 mkm)=(2094 mkm/ 1622.7 mkm) = (5848 mkm/ 4495.1 mkm) = 1.3

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II-Discussion
- Why do we need to analyze the distance 720.7 mkm = Mercury Jupiter distance?
- Let's remember the theory ideas in following:
o The solar system is created out of one light beam its velocity (1.16mkm/s).
the light beam motion creates the planet matter and its orbital durance. By
that, the solar planets and their distances are created from one light beam
energy with supposed velocity (1.16mkm/s)
o The light motion creates one trajectory of energy for the solar system. and
the planets are points on this trajectory of energy
o Because of that, the theory tells, a planet motion covers a light motion. that
means, the planet is a puppet on the puppets theater, were the light motion
behind planet motion effects on the planets motion data.
o Light supposed velocity (1.16 mkm/s) travels during (4224 s) a distance =
4900 mkm (Jupiter Orbital Circumference). And the period (4224 s) caused
Mercury day period to be (4222.6 hours) because 1 second of light motion =
1 hour of Mercury Motion.
o Mercury moves during its day period (4222.6 h) a distance =720.7 mkm
o Now
o This story is a story and tells a part of the facts….
o Because
o Mercury is a name only. the light supposed velocity (1.16 mkm/sec) motion
is the basic player behind Mercury motion. that means, Mercury Motion
Distance during Mercury day period (720.7 mkm) is an effect of light
motion on Mercury motion. Mercury is a puppet and follower. Mercury
motion follows the light motion
o The theory creates another universe in parallel to the universe of matter. The
light motion creates this parallel universe. The light motion causes the
universe of matter to move.

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o I want to say
o The light motion is similar to a teacher and planet motion is similar to a
blackboard, by that, planet data be created by light motion effect on planet
motion.
o The light beam creates equal effects on the different planets. Because of
that, the light supposed velocity (1.16 mkm/sec) caused the 4 planets to
move equal distances (720.7 mkm) in the period (4222.6 hours) with
modifications required by the geometrical necessities
o This is a hypothesis and we try to prove it.
o That tells,
o The distance 720.7 mkm is a reference for light supposed velocity (1.16
mkm/sec) motion effect on the 4 planets motions.
o Now we have an information that
o The 4 planets (Mercury – Mars – Jupiter – Pluto) move equal distances
(720.7mkm) because of the light supposed velocity (1.16 mkm/sec) motion
effect on the 4 planets motions.
o How does the light supposed velocity do this task?
o By the distance 5848 mkm (Mercury Pluto Distance)
o That means,
o Through our discussion we should keep an eye on the distance 5848 mkm
because based on this distance the 4 planets move equal distances (720.7
mkm) in defined periods of time.
o That because the distance (5848 mkm) is a direct motion of light where light
supposed velocity (1.16 mkm/sec) travels during (5040 seconds) a distance
= 5848 mkm. By that the distance 5848 mkm shows a direct motion of light
supposed velocity and by this distance the light supposed velocity (1.16
mkm/sec) effects on the 4 planets motions to move 720.7 mkm in period
(=4222.6 hours) with the necessary modifications.

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Equation no. (b)
(929 mkm/629 mkm) = (940 mkm / 636 mkm)
- Where
- 629 mkm = Earth Jupiter Distance
- 929 mkm = Earth Jupiter Distance (The 2 Planets On The Sun 2 Sides)
- 940 mkm =Earth Orbital Circumference
- The basic equation is the next one….
- 5848 mkm = 2π x 929 mkm
- Let's remember what we know,
- Light supposed velocity (1.16 mkm/sec) travels from Mercury to Pluto (5848
mkm) based on the period (5040 seconds) where Mercury day period (=4222.6 h)
and needs (5040 seconds) to be (=4224 h) = (=176 solar days).
- We conclude that, the light supposed velocity (1.16 mkm/sec) caused Mercury day
Period to be less than (4224 h) with the period (5040 seconds) (may be to create a
connection between Mercury and Pluto positions)
- By that, light supposed velocity (1.16 mkm/sec) travels a direct distance (5848
mkm = Mercury Pluto Distance)
- Now
- We have a light beam motion (5848 mkm)
- And we know that
- The rate (2π) distinguish between light motion and planet motion. the light motion
distance is (5848 mkm) and based on that the planet motion distance must be (929
mkm).
- The distance 929 mkm = the distance between Earth and Jupiter when the 2 planets
be on 2 different sides from the sun.

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- That creates a geometrical connection between the 2distances (5848 mkm) and
(929 mkm).
- We conclude that, while light moves (5848mkm) the planet moves (929 mkm)
depends on the light motion….
Equation no. (b) (continued)
(929 mkm/629 mkm) = (940 mkm / 636 mkm)
- Equation no. (b) shows that we deal with a relationship between the Earth and
Jupiter. The distance (629 mkm = earth Jupiter Distance) and (940 mkm = earth
orbital circumference) shows earth data relating to Jupiter motion data.
- The distance 929 mkm which is born from light motion distance (5848 mkm) be
found here basically to create the last one (636 mkm)
- But
- Jupiter (1.1318 mkm/day) moves during (636 days) a distance =720.7 mkm
- Means,
- The light motion distance (5848 mkm) effects on Jupiter motion to move the
distance (720.7 mkm) in a period (636 days)
- but
- This period be created in proportionality with Earth distances data! why?
- Because
- Jupiter moves during (4222.6 hours) a distance =200 mkm = (629 mkm /π)
- i.e.
- Jupiter motion during the period (4222.6 h = Mercury day period) passes a
distance =200 mkm which is related to (629 mkm = Earth Jupiter distance),
- now
- the machine of gears uses this distance (200 mkm) to perform the required distance
(720.7 mkm) by using Earth distances data in proportionality with Jupiter distances
data.

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Equation no. (c)
2.082 mkm/ day x 346.6 days =720.7 mkm
- where
- 2.082 mkm / day = Mars Velocity Daily
- 346.6 days = The Nodal Year
- Equation no. (c) tells, Mars moves during 346.6 days (the nodal year) a distance
=720.7 mkm = Mercury motion distance during Mercury Day Period (4222.6h)
- Why?
- The 2 numbers are mentioned because 346.6 days= the nodal year and 720.7 mkm
= Mercury motion distance…. That means, this distance be mentioned to be passed
by Mars during this defined period of time (346.6 days) but why?
-
- My answer is (the machine is A Complex One)
- The following data may help a little
o Mercury day period needs 5040 seconds to be = (4224 hours)
o 5040 seconds = 84 minutes
o But
o Mercury moves during 84 solar days a distance = 344 mkm
o Mercury moves during 346.6 solar days a distance = 1419 mkm
o Mercury moves during 1433.5 solar days a distance = 5848 mkm (Mercury
Pluto Distance) (error 0.4%)
o This system of motion we have seen before in light motion, when the light
passes a distance and then uses this distance as a period of time to move
another distance and then uses the second one to move a third one
o We notice
o The period 346.6 days be used in Mercury motion which concerning the
distance 5848 mkm. By that we conclude the period 346.6 days has a
relationship with the distance (5848 mkm)

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o Where
o The distance 5848 mkm expresses the light motion effect on the 4 planets
motions to pass equal distances (720.7 mkm)
o By that
o Mars uses (346.6 days) to pass the require distance (720.7 mkm)
o That proves Mars motion for the distance 720.7 mkm be found by an effect
of light motion to pass the distance (5848 mkm) as similar to the other
planets.
o Of this explanation be insufficient
o The difficulty is in the period (346.6 days) which is used by Mercury and by
Mars. This using creates an interaction between the 2 planets motions
o (Notice, the point no.3-3 explains in details the planets motions interaction).
Notice (1)
(1407.6 h / 24.6 h) = (180 /π)
But
(4222.6 h /24.7 h)
- Where
- 1407.6 hours = Mercury Rotation Period
- 24.6 hours = Mars Rotation Period
- 24.7 hours = Mars Day Period
- 170 mkm = Mercury Mars Distance
Notice (2)
(5848 mkm x π) = 720.7 mkm x 25.2 (error 1%)
- Where
- 25.2 degrees = Mars Axial Tilt

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Equation no. (d)
0.406 mkm/ day x 1775.2 days =720.7 mkm
But
(90560 days x 2) /1775 days = 102 = (5848 mkm/57.9 mkm) (error 1%)
- Where
- 0.406 mkm / day = Pluto Motion Distance During A Solar Day
- 90560 days =Pluto Orbital Period
- 57.9 mkm =Mercury Orbital Distance
- 5848 mkm =Mercury Pluto Distance
- Equation no.(d) tells that,
- Pluto moves during 1775.2 days a distance =720.7 mkm
- This is the distance be required by light motion effect on the 4 planets motions
- Now
- The period 1775.2 days should be related to Mercury day period (4222.6 h)
- Equation tells that, the period 1775.2 days be rated with Pluto orbital period
(90560 days) by the same rate between (5848 mkm =Mercury Pluto distance) and
57.9 mkm (Mercury orbital distance)
- The equation tells, the period 1775.2 days is defined based on Pluto basic data in
proportionality with Mercury data.
- Shortly
- Pluto motion data be created takes into consideration the period 1775.2 day, that
tells the distance 720.7 mkm effects on Pluto motion also

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Equation no. (e)
(940 mkm/720.7 mkm) = (119.7 mkm/91.7 mkm) = (720.7 mkm /550.7 mkm) =
(1557.2 mkm/ 1205 mkm)=(2094 mkm/ 1622.7 mkm)=(5848 mkm/ 4495.1 mkm) =
1.3
- Where
- 720.7mkm = Mercury Jupiter Distance (our examined distance)
- 119.7 mkm = Venus Mars Distance
- 91.7 mkm = Mercury Earth Distance
- 550.7 mkm = Mars Jupiter Distance
- 1557.2 mkm = Jupiter Orbital Distance (1557.2 mkm =2 778.6 mkm)
- 1205 mkm = Mars Saturn Distance
- 2094 mkm = Jupiter Uranus Distance
- 1622.7 mkm = Uranus Neptune Distance
- 4495.1mkm = Neptune Orbital Distance
- 1.3 degrees = Jupiter Orbital Inclination
- Equation no. (e) shows that the planets distances be created in proportionality with
one another.
- Ion different many data I try to show that, no single distance be created
interpedently, we deal along time with one geometrical system, means the
distances be created based on one geometrical design.

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Earth Jupiter Distance Analysis
Equation no. (I)
100733 mkm = 929 mkm x 108.2 mkm = 671 mkm x 149.6 mkm
- Where
- 108.2 mkm = Venus orbital distance
- 149.6 mkm = Earth orbital distance
- 671 mkm = Venus Jupiter Distance
- 929 mkm = Earth Jupiter Distance (The 2 Planets Be On The Sun 2 Sides)
- Light supposed velocity (1.16 mkm/s) travels during a solar day (86400 s) a
distance = 100733 mkm
- Equation no. (I) tells, from one source of Energy the 4 distances be created
- Specifically
- From the distance 100733 mkm, the 4 distances are created
- These 4 distances be created from the same one distance (100733 mkm) in
comparison with one another. that means these 4 distances are created based on
one geometrical design which proves the network theory of distances.
Equation no. (II)
(940 mkm/680 mkm) = (929 mkm / 671 mkm)
- Where
- 671 mkm = Venus Jupiter Distance
- The distances are created for geometrical reasons and based on geometrical
mechanisms.

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Equation no. (III)
(778.6 mkm / 929 mkm) = (5848 mkm/4900 mkm) = 0.838
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 5848 mkm =Mercury Pluto Distance
-
- I try to show, the distance 929 mkm is built based on a geometrical mechanism
which creates a system for the distances creation, or a network of distances
- That means,
- The distance 929 mkm be taken into consideration by the light motion from
Mercury to Pluto (5848 mkm) because it expresses the planet motion (929 mkm)
in comparison with the light motion (5848 mkm=2πx 929 mkm)
- In following we analyze the distance 929 mkm to see if this distance can be found
geometrically…

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Earth Jupiter Distance Analysis (More Discussion)
- The previous analysis tries to show that, the distance between Earth and Jupiter
across the sun (929 mkm = 778.6 mkm +149.6 mkm) is defined as a basic point for
Mercury Pluto Distance (5848 mkm) where
- 5848 mkm = 929 mkm x 2π
- Let's analyze this distance in following
- The figure shows the sun and the 3 planets (Mercury – Venus – Earth)
- The 3 planets be drawn on 2 sides of the sun. and Jupiter is the planet (J)
- Now let's start our analysis
- The distance between Earth and Jupiter (on one side) = 778.6 -149.6 = 629 mkm
- The distance between Earth and Jupiter (on 2 sides) = 778.6 +149.6 = 929 mkm
- The distance between Earth and Mercury (on 2 sides) =57.9 +149.6 = 207.5 mkm
- The distance between Earth and Venus (on 2 sides) =108.2 +149.6 = 257.8 mkm
- The question is
- Are The Distances Across The Sun Be Considered Geometrically For The
Planets Motions And Orbital Distances?
- Let's test that with Venus Earth Distance in the following example

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Example no. (1)
Additional Equation (i)
Sin (23.6 deg) x 257.8 mkm = 103.4 mkm
- S= The Sun
- V = Venus
- E= The Earth
- ES = Earth Orbital Distance = 149.6 mkm
- SV = Venus Orbital Distance = 108.2 mkm
- EV = 103.4 mkm
- Notice
- The distance between Venus and Earth = 41.4 mkm and NOT 103.4 mkm. So how
this triangle be built?!
- let's move step by step:
o Earth orbital distance 149.6 mkm + Venus orbital distance 108.2 mkm =
257.8 mkm (This distance be found when Earth and Venus be on 2 different
sides from the sun with an angle 180 degrees between the 3 players)
o 257.8 mkm x sin (23.6 deg) = 103.4 mkm (=EV distance In The Triangle)
o 23.45 deg = Earth axial tilt (has a difference with 23.6 deg be 1%)
o In our triangle (SEV) the angles be defined geometrically as following
o The Angle (S) = 43.6 degrees
o The Angle (V) = 90 degrees
o The Angle (E) = 46.4 degrees (= 2 x 23.2 deg = Earth Axial Tilt error 1%)
o Now let's analyze this triangle in following

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- Is this triangle (SEV) be an imaginary one? because the distance between Venus
and earth be 103.4 mkm and the real distance = 41.4 mkm?
- We see that, the distance between the Earth and Venus can be even = 257.8 mkm
when the 2 planets be on 2 different sides from the sun. So if the distance can be =
257.8 mkm, that means, it can be also 103.4 mkm. That means this triangle can't
be an imaginary one.
- Why this triangle is useful?
- Because of the angle (E) = 2 x 23.2 degrees (Earth Axial Tilt) (error 1%)
- That tells, Earth axial tilt is produced by some interaction be found among Earth,
Venus and The Sun Data
- Why Venus angle =90 degrees?
- What Useful Results We Get From This Triangle? 2 Basic Results
- (1st
Result)
- The planets distances across the sun are used geometrically in the solar system
geometrical design.
- (2nd
Result)
- The Sun Be Perpendicular On Venus Planet in this triangle, while Earth axial tilt
be defined. Can that effect geometrically on the sun position relative to Venus and
Earth positions?
Notice
41.6 mkm = 0.384 mkm x 108.2 mkm (Venus Orbital Distance)
- 41.4 mkm = Venus Earth Distance (different from 41.6 mkm with 0.4%)
- 0.384 mkm = The Earth Moon Orbital Distance
- The data tells, The Earth moon orbital distance also be defined accordingly
- The paper provides an interesting approach to explain the solar planets motions.

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- While the solar planets motions description inherited from Newton Theory of the
sun mass gravity tells that each planet motion is independent from the other
planets motions. As a result each planet orbital distance be defined independently,
The suggested description tells that, each planet motion takes into consideration
the other planets motions.
- We here deal with a building stories found depending on one another. based on
this vision, because Venus orbital distance =108.2 mkm, that causes Earth orbital
distance to be 149.6 mkm
- And because of the 2 planets orbital distances be (108.2 mkm and 149.6 mkm) the
Earth moon orbital distance be (0.384 mkm).
- The vision is completely different from what Newton told us. while Newton
supposed the space is limitless and can contain hundreds of planets moving
without effect on each other. the fact is the 9 planets motions effect on one another
and forces each planet to define each motion in proportionality with the other
planets. The vision is different because Newton vision of (NO Effect) created
separated trajectories of motions. And based on this vision we see the planets as
cars move through track independently from one another (even the real cars can't
be independent because the track is the same one and all have to move in harmony
otherwise they will collide). The suggested description tells that, the motions be
built as a building and each motion depend on the other motions and by that they
need one geometrical design controls and manages all of them.

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Discussion
- This triangle I put here because it shows the distance between the earth and Venus
can be =257.8 mkm by put the 2 planets on 2 different sides from the sun.
- This behavior perfectly is similar to Earth Jupiter distance (929 mkm) while the 2
planets be on different 2 sides from the sun.
- I try to show that, it's part of the distances distribution system to use the planets
positions across the sun.
Notice
- The distance between Earth and Mercury across the sun be = 149.6 mkm + 57.9
mkm =207.5 mkm
- Pluto (0.406 mkm/day) moves during 511 days a distance = 207.5 mkm
- Where
- 511 degrees = The Solar Planets Axial Tilts Total
- A Summary
- The distances between Mercury and Pluto be distributed based on geometrical
design to create a proportionality between the 3 planets motions for periods (720.7
mkm). (the 3 planets are Mercury – Jupiter – Pluto)
- The distance distribution be performed by light motion effect on te planets
distances creation.

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5-3 Planets Motions Interaction
I- Data
(1)
8 x 9.9 x 3600 s = 285120 s = π x 90756.2 seconds
(90756.2 seconds – 90560 seconds) = 196.5 seconds
(2)
196.5 sec x 1.16 mkm/sc = 227.9 mkm (Mars Orbital Distance)
(3)
(90560 mkm x 2) = 227.9 mkm x 198.7
(4)
170 sec x 1.16 mkm/sec = 197.2 mkm
(5)
655.7 sec x 0.3 mkm/sec = 196.7 mkm
(6)
196.5 sec x 27.78 km/sec = 10921 km/2
(7)
194 sec x 35 km/sec = 6792 km
(8)
193 sec x 0.3 mkm/sec =57.9 mkm (Mercury Orbital Distance)
(9)
193.7 sec x 1.16 mkm/sec =224.7 mkm
224.7 sec x 1.16 mkm/sec =521.3 mkm
(10)
30589 days = 58.65 days =521.3
(11)
606.3 mkm = 193 mkm x π = 1.16 mkm/sec x 522 sec
(12)
643.3 sec x 0.3 mkm/sec = 193 mkm

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(13)
3735072 km = 196.5 x 19000
720.7 mkm =3.735 mkm x 193
And
(5687.1 mkm = 19000 sec x 0.3 mkm/sec)

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II –Discussion
- Let's summarize the analysis basic idea in following
- The theory tells, the light supposed velocity (1.16 mkm/s) started from Mercury
passing Jupiter, Pluto and Mars
- Light supposed velocity (1.16 mkm/s) motion effects on the 4 planets caused the 4
planets to move equal distances (720.7 mkm) in equal periods of time (4222.6h)
- Because of this motion
- 3 Planets motions depend on the period (196.5 seconds)
- The data discussion will explain the meaning of planet motion dependency on the
period of time 196.5 seconds.
- Because the 3 planets motions depend on equal periods of time (196.5 s) their
motions be integrated and unified into one general unified motion
- As A Result
- Mercury, Mars and Jupiter moves One Unified General Motion.
- This Unified Motion Be Proved in the 3 planets motions data.
- This point of discussion shows that, the 3 planets motions depend on the period
(196.5 seconds).
- The next point (4-5) proves the unified general motion of the 3 planets as a result
for their dependency on equal periods of time (196.5s)

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Equation no. (1)
8 x 9.9 x 3600 s = 285120 s = π x 90756.2 seconds
(90756.2 seconds – 90560 seconds) = 196.5 seconds
- Where
- 9.9 hours = Jupiter day period
- 90560 days =Pluto orbital period
- (8 days of Jupiter motion creates Jupiter 8 days cycle)
- The equation uses Pluto orbital period (90560 days) in seconds unit (90560
seconds) why?
- We know this answer, and keep it by heart
- (Light Motion For 1 Second Causes A Planet Motion For 1 Solar Day)
- By that, all periods in solar day units for planets motions be considered in second
units for light motion.
- What we need from this equation?
- The period 196.5 seconds
- This period is the connection reason among the 4 planets motions (Mercury – Mars
– Jupiter and Pluto)
- In fact our discussion cornerstone is the period 196.5 seconds
- Why is this period 196.5 s important for the planets motions?
- Because it's created by interaction between Jupiter and Pluto motions. and the
paper main equation which we have discussed deeply before tells
Equation no. (I) (The Paper Main Equation)
1.16 mkm per second x 2 x 86400 seconds =2 x 100733 mkm = (37100 mkm –
4900 mkm) x 2π = 28255 mkm + 2 x 86400 mkm
- We have discussed this equation before
- Equation no. (4) in point no. (3-2)

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- This equation shows, the solar system basic energy is sent from Jupiter to Pluto
and then reflected from Pluto to Neptune, means, the interaction between Jupiter
and Pluto deal with the solar system basic energy…
- This conclusion shows a great significance for the interaction between Jupiter and
Pluto motions. As a result, the value 196.5 seconds should be considered as a very
important period in the solar system motion.
- But
- 8 Jupiter days create (planet 8 days cycle for Jupiter). Can this period 196.5
seconds have any relationship with (Jupiter 8 days cycle?) we should in equation
no. (13) of this discussion.
- Notice
- The period 196.5 sec is defined by an interaction between Jupiter and Pluto
motions, and
- Light known velocity (0.3mkm/sec) needs 193 sec to pass Mercury orbital distance
(57.9 mkm).
- That means, Mercury orbital distance be defined by an effect of Jupiter and Pluto
motions interaction.
- That tells, Mercury Jupiter distance is defined at first and then the light beam built
Pluto orbital circumference and after that Mercury orbital distance be defined. (or
the sun position be defined)

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Equation no. (2)
Equation no. (8)
- The period 193 seconds is different from the period 196.5 seconds with (2%)
- We neglect this difference (2%) for now and consider the 2 periods are equal
- Now
- By equal periods of time (196.5 seconds), the 2 light beams defined the 2 planets
orbital distances…
- Light supposed velocity (1.16 mkm/sec) during (196.5 sec) travels a distance =
227.9 mkm = Mars orbital distance
- Light known velocity (0.3 mkm/sec) during (193 sec) travels a distance = 57.9
mkm = Mercury Orbital Distance
- By equal periods of time the 2 light different velocities defined the 2 planets
orbital distances.
- What Effect Can Be Produced By The Equal Periods Of Time?
- We deal with light motion…. let's use one example for help
- In light motion, if there's a phase between the light waves the experiment will
produce an interference but if there's no phase we will see light waves without
interference
- The phase creates the differences in motions
- But without phase
- The motions will be unified in one, means
- Mercury, Mars And Jupiter Move One Unified General Motion Because The
3 planets Use Equal Periods Of Time…

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- Let's summarize what we have…
- The 3 planets use equal periods of time (196.5 seconds) and by that their motions
will be unified in one unified general motion.
- The period 196.5 seconds is born by interaction between Jupiter and Pluto
motions. where this interaction express the solar system basic energy
- The unification of motions between Mercury, Mars and Jupiter can be produced by
Jupiter dependency on Mercury and Mars motions because they are the first and
last planets in the inner group and by that Jupiter creates a connection with the
inner planets through its connection with Mercury and Mars

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Equation no. (2) (Continued)
Equation no. (8)
- We know that mercury, Venus and Earth define their orbital circumferences to be
equal their distances to Jupiter.
- means, Mercury position is defined in the space relative to Jupiter position.
- Mars defined its orbital circumference to be equal Saturn orbital distance…
- That tells, Mercury and Mars positions are defined relative to Jupiter and Saturn
positions.
- And
- Their distances to the sun be defined by using equal periods of time (196.5 sec)
- Let's ask, if the 2 planets positions are defined, what result of their using of equal
periods of time?
- They almost define the sun position in the solar system
- The theory tells, the sun is created after all solar planets creation and motion. the
equal periods be used almost to define the sun position in the solar system relative
to Mercury and Mars positions relative to Jupiter position.
- The point is that,
- Mercury (4.095 mkm/day) moves during its rotation period (58.65 days) a distance
= 243mkm (error 1%)
- Mars (2.082 mkm/day) moves during Venus day period (116.75 days) a distance =
243 mkm
- Where, 243 mkm x 0.8 =196.5 mkm
- This motion is almost related to the sun creation process
Notice
- 243 mkm x 2 =40080 km (Earth Circumference) x 12104 km (Venus diameter)
- 29.8 km/sec x 12104 seconds = 3 x 120536 km

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Equation no. (3)
(90560 mkm x 2) = 227.9 mkm x 198.7
Equation no. (4)
170 sec x 1.16 mkm/sec = 197.2 mkm
- Where
- 90560 days = Pluto Orbital Period
- 227.9 mkm = Mars Orbital Distance
- 170 mkm = The Distance Between Mercury And Mars
- Equation no.(4) we have discussed in the distances series discussion (point no. 3)
of this current paper.
- Equation no. (3) tries to show that Pluto orbital period be in proportionality with
the period (196.5s)
- Notice
- The error (2%) between 193 seconds and 197 seconds we don't discuss because,
the machine is so complex
- We usually find the data in rates (100%, 99%, and 98%) these rates are repeated
frequently, and these rates may be created because of one geometrical necessity,
- For example Earth moves during its day period a distance =2.574 mkm (100%) but
the moon displacement total during 29.53 days =2.598 mkm (101%) and the moon
apogee orbital circumference =2.550 mkm (99%)
- The rates (98%, 99% and 100%) are used frequently, I can't write all data which
use these rates and can't explain the reason of it.

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Equation no. (5)
655.7 sec x 0.3 mkm/sec = 196.7 mkm
Equation no. (6)
196.5 sec x 27.78 km/sec = 10921 km/2
Equation no. (7)
194 sec x 35 km/sec = 6792 km
- Where
- 655.7 hours = The Moon Rotation Period
- 27.78 km/sec = The Moon Velocity
- 6792 km = Mars Diameter
- What do we need from these equations?
- Shortly
- We need equation no. (6) because it shows that, the moon circumference depends
on the period (196.5 seconds)
- We remember that,
- The 3 Planets (Mercury – Mars and Jupiter) depend on equal periods (196.5 sec) in
their motions. and these equal periods (196.5 sec) causes the 3 planets motions to
be unified in one general unified motion.
- Means, the period (196.5 seconds) is the cornerstone of these 3 planets motions.
- Now
- The moon circumference (10921 km) depends on the period (196.5 sec) also
- So, we have more players be under the same one unified general motion. because
the moon uses the same period, so no phase will be between the moon motion and
Jupiter motion, on the contrary, they move together one unified motion…
- That may explains the important following equations:
(NO. A)
- 4900 mkm (Jupiter orbital circumference) = 10921 km x 449197 km

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- Where
- 449197 km = Jupiter Circumference
(NO. B)
- Jupiter (13.1 km/sec) moves during 10921 sec a distance = 142984 km = Jupiter
diameter.
(NO. C)
- The moon (27.78 km/sec) moves during 5127 sec a distance = 142984 km =
Jupiter diameter.
- (where 5127 mkm = Jupiter Pluto distance)
- Notice
- Light supposed velocity (1.16mkm/sec) travels during 4900 sec a distance =
5678.1 mkm (Mars Pluto Distance)
- Notice
- The moon orbital apogee radius 406000km = 2jupiter diameters + 1 Saturn
Diameter.
Notice
- Why the moon velocity be =27.78 km/s? because the moon moves daily a
distance = Earth motion distance daily because they aren't separated from one
another. means the moon daily motion distance =2.574 mkm but this distance be
effected by the rate 1.0725. (we have referred to that frequently before). We don't
know why the distance 2.574 mkm be effected by the rate (1.0725) but 40% of all
distances in the solar system be effected by this same rate 1.0725 and appendix
no.1provides a list for these distances. By that the moon distance 2.574 mkm be
=2.4 mkm daily which =27.78 km/sec.

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Equation no. (8)
Equation no. (9)
193.7 sec x 1.16 mkm/sec =224.7 mkm
224.7 sec x 1.16 mkm/sec =521.3 mkm
Equation no. (10)
30589 days / 58.65 days =521.3
- Where
- 224.7 days = Venus Orbital Period
- 30589 days = Uranus Orbital Period
- 58.65 days = Mercury Rotation Period
- Equations (8), (9) and (10) show that, the rate between Uranus orbital period and
Mercury rotation period depends on the period (193 seconds) by light motion.
- The data shows that, the series creates a connection between the 2 planets
- But
- Mercury rotation period is related to Uranus motion by some complex geometrical
interaction because
- Mercury Uranus distance = 2814.6 mkm
- But
- 2815.2 hours = 2x 1407.6 h (Mercury rotation period)
- If 1 mkm = 1 hour that makes the distance 2815.2 mkm= 2 Mercury Rotation
Period, And
- Mercury moves during its rotation period a distance = 243mkm (error 1%)
- Where 243 days = Venus rotation period
- If 243 mkm be equivalent to 243 days that tells 1 mkm = 1 day
- By that Mercury creates with Uranus the rate of time (1 hour of mercury = 24
hours of Uranus) we discuss that in Planets motions use different rates o time point
no.(7) of this paper.

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Equation no. (11)
606.3 mkm = 193 mkm x π = 1.16 mkm/sec x 522 sec
- This equation gives 3 branches of data let's summarize each one in following
- (1st
Branch)
- 606.3 seconds x 1.16 mkm/sec = 703.3 mkm
- 703.3 seconds x 1.16 mkm/sec = 816 mkm
- 816 seconds x 1.16 mkm/sec = 946.6 mkm
- Where
- We remember that
- 5848 mkm (Mercury Pluto distance) – 4900 mkm (Jupiter orbital circumference) =
948 mkm (Earth Orbital Circumference) (error 1%)
- That means,
- The value (606.3 mkm) is connected with light supposed velocity (1.16 mkm/sec)
motion trajectory from Mercury to Jupiter and then to Pluto. This trajectory is the
1st
trajectory we have studied…
- (2nd
Branch)
- 193 seconds x 0.3 mkm/sec = 57.9 mkm (Mercury Orbital Distance)
- 193.7 seconds x 1.16 mkm/sec = 224.7 mkm (Venus orbital period 224.7 days)
- 224.7 seconds x 2 x 1.16 mkm/sec = 521 mkm
- (3rd
Branch)
- 30589 days (Uranus orbital period) = 58.65 days (Mercury rotation period) x 521
- Equation no. (11) connects many basic data together.

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Equation no. (12)
643.3 sec x 0.3 mkm/sec = 193 mkm
- Equation no. (12) is important because
- Jupiter moves during 636 days a distance = 720.7 mkm (where 636 days is
different from 643.3 days with 1%)
- The period (643.3 days) be used as (643.3 sec ) for light motion
- Equation no. (12) tells that, light known velocity (0.3 mkm/s) travels during (643.3
s) a distance = 193 mkm
- That causes the period 193 second be found related to the distance 720.7 mkm
- The basic difficulty is that the light creates geometrical interactions aren't clear for
our analysis and by that many geometrical effects be created but aren't known for
us because we don't realize perfectly how the machine works.

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Equation no. (13)
3735072 km = 196.5 x 19000
720.7 mkm =3.735 mkm x 193
And
(5687.1 mkm = 19000 sec x 0.3 mkm/sec)
- Where
- 3735072 km=the distance be passed by Jupiter during 8 Jupiter days (please
review Jupiter 8 days cycle)
- 19000 seconds the light known velocity (0.3 mkm/sec) needs to pass the distance
from Mars to Pluto (5678.1 mkm)
- We remember that
- 4900 sec x 1.16mkm/sec = 5687.1 mkm = (Mars Pluto Distance)
- The point is that,
- 720.7 mkm (Mercury Jupiter distance) = 3.735 mkm x 193
- That tells, the period (193 seconds) is defined by a geometrical mechanism takes
into consideration Mars Pluto Distance.
- Because, in fact
- Mars connection with Mercury and Jupiter be created through Pluto. where the
light supposed velocity (1.16 mkm/s) travels from Mercury to Jupiter directly and
doesn't touch Mars in the way.

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5-4 Planets Unified General Motion
5-4-1 The Planets Unified General Motion Description
- I suppose that (The Planets Motions Create One Unified General Motion)
- This hypothesis tells the planets motions be similar to Train Carriages Motion
- Also It tells the planets motions be similar to Chess Pieces Motions
- The hypothesis discovers One Law controls the solar system motion and data.
- The planets unified general motion forces each planet motion to be complementary
with other planets motions to perform The Unified General Motion. as a result,
The Planet motion be An Obligatory Motion.
- The Solar Planet creates its data to be in consistency with its motion.
- The planet can't change its motion, but can change its data to be in consistency
with its motion. And the planet data be created in consistency with its motion.
- Because the planet motion be complementary with other planets motions.
- The planet data be created complementary with other planets data
- Based On This Vision
- The solar planets data be created complementary to other planets data and based
on that the planets data be created depends on One Geometrical Design.
- And
- The Planets Creation And Motions Data Be Controlled By One Equation Only
Notice
- We have seen that the motions of the 3 planets (Mercury – Mars – Jupiter) depend
on the period 197 seconds. And I claim that the equal periods (197 s) causes these
3 planets motions to be integrated into one unified general motion.
- The next point provides the data discussion which proves that the 3 planets
motions be integrated into one unfio9ed general motion.
- By that the 3 planets can be used as example to prove the planets unfied general
motions.

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5-4-2 The Solar Planets Motions Are Complementary One Another
I-Data
(The Interaction between Mercury, Mars and Jupiter)
(No. 1) (Mercury and Mars Motions)
- Mercury moves during its day period (4222.6 h.) a distance = 720.7 mkm
- Mars moves during (2802 hours) a distance = 243 mkm
- Mercury moves during (1407.6 hours) a distance = 243 mkm (error 1%)
- Mars moves during 346.6 d. a distance =720.7 mkm (Mercury Jupiter Dis.)
- Mercury moves during 346.6 d. a distance =1419 mkm (with 1433 error 1%)
- Mars moves during 687 d. a distance = 1433 mkm (Mars orbit. Circum)
- Mercury moves during 687 d. a distance =2815mkm (Mercury Uranus Dis.)
- Mars moves during 4331d. a distance = 9010mkm (Saturn orbit. Circum)
- Mercury moves during 4331d. a distance = 2815 mkm x 2π
- Mars moves during 224.7 d. a distance = π x 149.6 mkm (Earth orb. Dis)
- Mercury moves during 224.7 d. a distance = 920 mkm (with 928 error 1%)
- Mars moves during 365.25 d. a distance = π x 243 mkm (0.5%)
- Mercury moves during 365.25 d. a distance = 2 x 748 mkm
- Mars moves during 5040s. a distance= 121464 km= Saturn Diameter (+1%)
- Mercury moves during 5040s. a distance= 238896 km= 2 Saturn Diameters (-1%)
Where
1407.6 h = Mercury Rotation Period 2802 h = Venus Day Period
346.6 days = the nodal year 224.7 days = Venus orbital period
687 days = Mars Orbital Period
4331 days = Jupiter orbital period = 2π x 687 days

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(No. 2) (Mars And Jupiter Motions)
- Mars moves during 636.7 days a distance =1325 mkm= (Venus Saturn Dis.)
- Jupiter moves during 636.7 days a distance =720.7 mkm
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Jupiter moves during 687 d. a distance= 778.6 mkm= Jupiter Orbital Distance
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Jupiter moves during 4331 d. a distance= 4900 mkm= Jupiter Orbital Circum.
- Mars moves during 778.6 d. a distance = 1622 mkm = Uranus Neptune Dis.
- Jupiter moves during 778.6 d a distance= 881 mkm =58 days x 15.19 mkm.
- ( 15.19 mkm = the 9 solar planets motions distances total per a solar day).
- Notice
- 2.082 mkm / day x 778.6 days = 1622 mkm = 1.1318 mkm /day x 1433 days

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(No. 3) (Mercury And Jupiter Motions)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 1433 d. a distance =5848 mkm= Mercury Pluto Dis.
- Jupiter moves during 1433 d a distance =1622 mkm=Uranus Neptune Dis.
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
- Mercury moves during 4222.6 h a distance = 720.7 mkm
- Jupiter moves during 4222.6 h a distance = 200 mkm = 629 mkm/π
- Mercury moves during 550.7 d a distance = π x 720.7 mkm (0.4%)
- Jupiter moves during 550.7 d a distance = 629 mkm (error 1%)
Please Remember,
Data Group No. (1)
- Mars moves during 687 d. a distance= 1433 mkm= Mars Orbital Circumference
- Mars moves during 4331d. a distance= 9010 mkm= Saturn orbital circumference
- Mars moves during 4331 x π d a distance= 28255 mkm= Neptune orbital circumference
Data Group No. (2)
- Mercury moves during 687 d. a distance= 2815 mkm= Mercury Uranus Distance
- Mercury moves during 4331d. a distance= 2815 mkm x 2π
Data Group No. (3)

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II-Discussion
- The planets move defined distances in defined periods of time.
- The Defined Distance means a distance is known in the solar system, as to be any
planet orbital distance or a distance between any 2 planets.
- The Defined Periods Of Time means a period of any planet cycle, as 365.25 days
(Earth orbital period) or any planet orbital period. Or any planet rotation period or
any planet day period. All these periods are defined periods of time
- The argument tells that
- If the solar planets move their motions independently from one another, based on
that, the planets motions during defined periods of time should pass (random)
distances. Because these Planets are independent in their motion from one
another. (For example) Mercury motion depends on its orbital period (88 days) and
doesn't interest neither for Mars orbital period (687 days) nor for Jupiter orbital
period (4331 days) and by that, Mercury during these periods (687 days and 4331
days) should move some random distances (not defined in the solar system
distances).
- The data disproves Planet Motion Independency Concept. because the (3)
planets move defined distances in defined periods of time. These planets motions
aren't independent from one another. These motions are done based on One
Geometrical Design. And these motions be are similar to Chess Board Pieces
Motions. Each Motion is calculated geometrically and be obligatory.

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- Notice
- The previous analysis of motions prove the interactions of motions among the
three planets (Mercury, Mars and Jupiter). These interactions we have referred to
them during our analysis for Jupiter orbital circumference (4900 mkm).
- The 2 parts of discussions can provide a clear vision for how the planet motion be
done. Because the planets motions data help us greatly and protect us from any
imaginary vision. Because of that, the motions interaction which we have
concluded based on the planets data analysis concerning Jupiter orbital
circumference be proved here clearly by the 3 planets motions analysis
- It's simply a fact
- If the geometrical machine based on which this data be created be discovered the
reasons will be known to answer how or why these motions have interactions.
- But even before this machine discovery the data shows the motions interactions in
both sides. In the planets data and in the planets motions.

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5-4-3 The Solar Planets Move An Unified Motion (A Team Motion)
- Let's Summarize The Proof Idea In Following:
- This proof depends on 2 planets motion cycles are discovered later. Which are
(planet 8 days cycles) and (planet 6 days cycles). We study one Cycle only in this
paper because both cycles provide the same argument.
- The Cycle Shows That Different Planets Motions Be Used In The Same One
Cycle To Create One Final Result.
- Means,
- Many planets move relative one another to create one result.
- For Example
- Jupiter moves a distance (A) and Uranus moves a distance (B).
- The different distance between (A) and (B) = Jupiter Diameter
- Now
- The machine uses this behavior frequently, and (the different distance = Jupiter
Diameter) be created frequently while the cycle uses its different periods (8 days,
16 days, 24 days….etc).
- Based on that,
- We can't consider these planets motions are independent from one another because
the different distance be defined by the 2 planets motions. we have to consider
these planets motions as a team motion. They move relative to one another which
proves The Unified General Motion Concept.
- Based on that,
- (Planet 8 and 6 Days Cycle) disproves Planet Independent Motion Concept.
- In following we study Planet 8 Days Cycle

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(Planet 8 Days Cycle)
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km be passed also by Saturn and Neptune with a rate 80%
depends on one another as following:
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %))
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km (Jupiter Diameter) (error 1%)
- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days

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- That means, the distance be passed by Uranus during 8 Pluto days equal the
distance be passed by Jupiter during 64 Jupiter days and equal the distance be
passed by Saturn during 80 Saturn days and equal the distance be passed by
Neptune during 100 Neptune days
Let's see that in following
(1)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(2)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(3)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(4)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- Uranus motion distance (30022272 km) – Jupiter motion distance (29880756 km)
= 141496 km (Jupiter Diameter)
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider they are
equal distances.
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = the moon circumference
- The data shows Planets Motions Dependency, because the different distances are
defined geometrically and that means these aren't 2 different distances of 2 plants
independent motions. On the contrary, the 2 distances are planned geometrically
and the 2 planets are 2 players to perform one different distance.

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The Discussion
- Let's discuss the previous data
(A)
- The outer planets are 5 planets, they consist 2 teams,
- The first team is consisted of Jupiter, Saturn and Neptune, these 3 planets move
based on a cycle (8 days cycle) depends on Jupiter motion with the rate 80%,
- That means
- The distance be passed by Jupiter in 8 Jupiter days be equal the distance be passed
by Saturn in 10 Saturn days and equal the distance be passed by Neptune during 12
Neptune Days
- The (small) difference between these 3 distances have geometrical necessities, as
we have seen in the difference between Jupiter and Saturn motions distances which
= 10921 km = The Earth Moon Circumference
- The moon circumference itself tells that it's a cycle because if it's not a cycle we
would find a part of the moon circumference
(B)
- The second team is Uranus and Pluto….
- Uranus uses Pluto day period (153.3 hours), and by that, Uranus (6.8 km/s) moves
during Pluto day period (153.3 hours) a distance = 3752784 km
- Because
- 3752784 km = Jupiter motion distance during 8 Jupiter days +17687 km
- Because of this data, we have concluded that, these motions depends on (8 days
Cycle), because
- Uranus needs to move during a period (= 8 Pluto days) to cause this value (17687
km) be = (141496 km (Jupiter Diameter) (1%)
- Because of Jupiter diameter we conclude that Uranus has a cycle of (8 Pluto days)
- Based on that

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- Uranus motion distance during 8 Pluto days = Jupiter motion distance during 64
Jupiter days = Saturn motion distance during 80 Saturn days = Neptune motion
distance during 100 Neptune days.
- How (Planet 8 Days Cycle) Can Prove The Unified Motion?
- Because
- Many planets motions be done to produce One Result
- This result be the different distance 141496 km (Jupiter Diameter) (1%)
- If we deal with planets independent motions this different distance can't be created
regularly and the Cycle can't be defined.
- Because (Planet 8 days Cycle) be defined, that means, the different distance
141496 km (Jupiter Diameter) be defined regularly which can be done only if
we deal with a team motion and NOT Planets independent Motions.
- Why does Uranus depend on Pluto Day Period?(additional question)
- Pluto day period is so long (153.3 h) in comparison with the outer planets days
periods. We suppose that, Uranus Motion effect on Pluto motion causes Pluto day
extension. We know Uranus did this effect because Pluto orbital inclination = 17.2
deg but Uranus day period =17.2 hours, even if we can't catch the mechanism of
this process yet, but the data shows that's Uranus effect on Pluto motion.
A Conclusion
Planet 8 Days Cycle disproves The Planet Independent Motion Concept,
On The Contrary, The Planets Move As A Team. (A Unified General
Motion)

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6- The Sun Age Historical Proves
6-1 The Sun Circles The Earth
6-2 The Rate (1.0725)
6-3 The Sun Diameter Analysis
6-4 The Sun Rays Analysis

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6-1 The Sun Circle The Earth
- The sun gives one face always to the Earth during the motion. although Earth
revolves around the sun a complete revolution, we always see the same face of the
sun, that tells the sun rotates with us giving The Earth The Same face always
- Can this motion refer to the Sun dependency on the period (365.25 days = Earth
orbital period)?
- Can that lead us to conclude, the sun be created after the Earth and because of that,
The Sun motion takes into consideration the period 365.25 days?
- Also
- The Sun Behavior is similar perfectly to the moon behavior, both give the same
face to the Earth during the motion.
- Why we accept that the moon be created after The Earth Creation but The Sun be
Created Before The Earth Creation? if the 2 behaviors are similar it may prove
both (the sun and the moon) be created after The Earth Creation.

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6-2 The Rate 1.0725
I- Data
(A)
Why These Distances Are Equal?
(1)
(2)
Earth Neptune Distance = Mercury Saturn Circumference (error 0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (error 1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (error 1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (error 0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (error 0.8%)

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(B)
More Data
Why These Distances Are NOT Equal?
10. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
11. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
12. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
13. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
14. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (Error 0.6%)
15. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (Error 0.8%)
16. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (Error 0.7%)
17. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (Error 0.7%)
18. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4846
= (Error 0.5 %)
(10)
Notice
4846 mkm =the inner planets orbital circumferences total. it will be discussed with Jupiter
orbital circumference analysis
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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II – Discussion
- The previous data shows that
- 50% of all distances in the solar system be equal one another, and
- 40% of all distances in the solar system be rated one another with the same rate
(1.0725)
- Why?
- The solar system motion analysis lead us to the conclusion that, the machine works
by equal distances feature (let's remember it in following)
- An Example
- Earth moves during its day period (24 h) a distance = Pluto motion distance during
its day period (153.3 h) (error 1%).
- We have observed this equality of distances.
- The periods of time are defined because they are defined by planets motions.
means, these periods of time aren't common periods but defined periods,
depending on planets motions.
- Means, these 2 distances be equal by some mentioned process. Because they
depend on 2 defined periods of time (depend on 2 planets motions).
- And,
- We have discovered that, this method is used by all solar planets motions. That
means, The equal distances method is used (thousands of times) in the solar
system motion.
- Because of this heavy using (50%) of all distances in the solar system to be equal
one another.
- That explains the data group No. (A) and makes it understandable.
- Means,
- 50% of all distances in the solar system are equal because of the equal distance
method Using.
- (The Equal Distances Method is discussed in details in point no.8)

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- Now
- The point needs explanation is the data group no. (B) where the distances are NOT
equal But Rated with 1.0725 (Why?)
- Why 40% of distances are rated with the same rate (1.0725)?
- Let's consider this question in following:
o The usual case is the equal distances as the data in Point no. (A), That
means, these rated distances were equal distances one another before and all
of them be effected by the rate 1.0725,
o Means,
o We have some historical order here, which is
o The distances were equal, but
o Some change caused these equal distances to be rated with (1.0725)
o And, 1.0725 = (100/100) + (7.25/100)
o We can conclude that,
o The distances were equal till The Sun Creation, and after the sun creation,
the sun obliquity on ecliptic (7.25 deg) caused the equal distances to be
rated with one another by the same one rate (1.0725).
o Means, the rate 1.0725 proves that, The Sun Is Created After All Solar
Planets Creation.
o One more feature supports this powerful argument, that
o The same rate (1.0725) is used for different distances. Because the sun
effects on all solar planets. That shows the rate (1.0725) must be related to
the sun because it's the same one rate. If this rate be belonged to any planet,
it will not effect on different distances equally because the sun only effects
on the planets equally. That shows the rate 1.0725 is belonged to the sun effect.

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6-3 The Sun Diameter Analysis
I-Data
1- Diameters
- (6792 km Mars Diameter) / (4879 km Mercury Diameter) =1.392
- (4879 km Mercury Diameter) / (3475 km the moon Diameter) =1.392 (1%)
- (71492 km Jupiter Radius) / (51118 km Uranus Diameter) =1.392
2- Distances
- (57.9 mkm Mercury orbital distance) /(41.4 mkm Venus Earth distance)=1.392
- (108.2 mkm Venus orbital distance) /(78.3 mkm Earth Mars distance)=1.392
- (149.6 mkm Earth orbital distance) /(108.2 mkm Venus orbital distance)=1.392
- (4267 mkm Mars Neptune distance) /(3061 mkm Saturn Neptune distance)=1.392
- (778.6 mkm Jupiter orbital distance) /(550.7 mkm Mars Jupiter distance)=1.392
- (550.7 mkm Mars Jupiter distance x 2) /(778.6 mkm Jupiter orbital distance) =1.392
- (5127 mkm Pluto Jupiter distance) /(3716 mkm Jupiter Neptune distance) =1.392
(error 1%)
- (5906 mkm Pluto orbital distance) /(4267 mkm Mars Neptune distance) =1.392
- (2872.5 mkm Uranus orbital distance) /(2094 mkm Jupiter Uranus distance) =1.392
3- Periods
- (243 days Venus Rotation Period) /(175.94 days Mercury day period) =1.392
- 2.5 deg (Saturn orbital inclination) /1.8 deg (Neptune orbital inclination) =1.392
- 1.8 deg (Neptune orbital inclination) / 1.3 deg (Jupiter orbital inclination) =1.392
- 5.1 deg (The moon orbital inclination) / 3.66 =1.392
4- The Sun Diameter
- 1.392 mkm (The Sun Diameter) = Venus Diameter 12104 km x 115.2
- 1.392 mkm (The Sun Diameter) = Mars Diameter 6792 km x 205.2
- 1.392 mkm (The Sun Diameter) = Neptune Diameter 49528 km x 28.3

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II- Discussion
- The data groups no. (1,2 and 3) show that,
- The rate 1.392 is used frequently among planets different data.
- Why? because
- The solar system is similar to one machine of gears and each planet is one gear in
it. because the machine moves one unified motion, the gears data should be in
proportionality with one another.
- Similar to that, the planets creation and motion data be created in proportionality
with one another. we will prove that in details in thus paper discussion.
- Based on this vision the solar planets data be created depends on one geometrical
design.
- This idea we have discussed before in the paper methodology, where the
(supposed) diameter 12430 km be defined geometrically and not created actually
- The Sun Diameter Can Have A Similar Discussion.
- The Sun Diameter Be defined geometrically before the sun creation.
- Because
- The machine depends on one geometrical design and each part should be created
in harmony with this geometrical design otherwise the machine can't work.
- We should notice that, the rate 1.392 is defined with the solar system creation
geometrically, Before the sun creation and also before the planets migration.
- This definition is done geometrically, so, the value (1.392) in the data is very
ancient. But the sun diameter (1.392 mkm) be created later.
- Let's discuss the data no. (4)

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Group Data No. (4)
- The sun diameter 1.392 mkm = Venus diameter 12104 km x 115.2 = Mars
diameter 6792 km x 205.2, But
- 25.2 + 90 = 115.2 and 115.2 +90 =205.2 where (25.2 degrees = Mars Axial Tilt)
And
- The sun diameter 1.392 mkm = Neptune diameter 49528 km x 28.3
- And 28.3 degrees = Neptune Axial Tilt
Discussion
- The data shows that, Venus, Mars and Neptune diameters are rated with the sun
diameter based on Mars axial tilt and Neptune axial tilt, Means,
- We have 3 planets diameters are rated with 2 planets axial tilts based on the sun
diameter.
- More logical that, the sun diameter is created after the 3 planets diameters,
depending on their values, causing planets axial tilts be created in proportionality.
- The opposite choice can't be working. Because if the sun be created at first and all
planets later, that creates a rule for the sun effect on the planets axial tilts, by that
we have to find (not) 3 planets only their axial tilts be rated based on the sun
diameter proportionality with their diameters, but found all planets behave by this
same rule because the sun has equal effect on all of them.
- The first option is more logical, that the sun is created after the planets creation and
the sun depended on 3 planets (specifically) for its diameter creation. by that the
data be more understandable
- Shortly
- The sun diameter analysis gives support for the claim (the sun is created after all
planets creation and motion).
Notice (1)
- In kepler third law in which (D3
= P2
x constant), the constant used for the solar
planets orbital distance and periods should be = 25

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6-4 The Sun Rays Analysis
- Let's Summarize The Sun Rays Creation Idea In Following:
(Point No. A)
o The Solar Planets Move One Unified General Motion. This Idea we discuss
and prove clearly in this paper.
o The planets unified general motion causes to unify the planets velocities in
one unifies velocity = the planets velocities total.
o The 9 planets velocities total =176 km/sec,
o But
o The Earth moon is a player and its velocity should be added, where the
moon velocity be considered = Earth velocity because they aren't separated
from one another through their motions.
o The 10 planets velocities total be 176 +29.8 =205.8 km/s
o Based on this velocity (205.8 km/s) the sun rays be created
(Point No. B)
o 10921 km (The Moon Circumference) x 86400 Seconds = 940 mkm
o This Equation tells. If Earth revolves around the sun a complete revolution
(=940 mkm = Earth Orbital Circumference) in one solar day only (86400
sec), in this case, the moon circumference (10921 km) will be equal the
Earth motion distance during 1 second.
o But, because
o Earth revolves around the sun in one year (=365.25 days), so this equation
may refer to a rate of time is used by The Sun herself.
o Let's use this idea as a hypothesis. where
o 1 Day Of The Sun Motion = 365.25 Days Of Earth Motion
o We suppose that's The Sun Rate Of Time

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(Point No. C)
o The velocity (205.8 km/s) passes during a solar day (86400 s) a distance
=17.75 mkm
o 1 day of Earth motion = 237 seconds of the sun motion.
(This value depends on our hypothesis)
o Now
o The distance =17.75 mkm and the time =237 seconds what's the velocity?
o 75000 km/s = (a quarter Light Velocity) = 0.25 C
o But
o Earth has a cycle of 4 years (1461 days = 365 +365 +365 +366)
o Based on one year, the velocity be (0.25 C)
o And
o Based on the cycle (4 years), the velocity (0.25C) became (C light velocity)
o Based on this explanation the sun rays be created.
(Point No. D)
o There's one more method to create the sun rays
o 0.25 C x 4 C = C2
o Where
o The velocity 0.25 C is produced already in the previous discussion
o We need only the value (4C) to perform this equation
o Jupiter motion enjoys by light motion supposed velocity (1.16 mkm/s) this
value is very near to our required value (4C)
o Light supposed velocity travels for 1 second and passed 1.16 mkm
o And
o Earth rotates around its axis one per solar day and move a distance = its
circumference =40080 km in a solar day
o If 1 solar day of Earth motion be = 1 second of light supposed velocity
motion.

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o Based on that, the distances can be added
o 1.16 mkm + 40080 km = 1.2 million km = 4C
o By that the equation works
o 0.25 C x 4 C = C2
o That explains why, Jupiter and The Moon data are the 2 basic players in the
sun data definition. Because the sun creation depends on Earth and Jupiter
motion. in addition to Uranus motion which is seen in the Earth moon
motion.
o The data explains how the sun rays be created
(Point No. E)
o The rate of time (1 solar day of planet motion = 1 second of light motion) is
the original rate of time in the solar system. We should refer to that in the
planets unified general motion discussion.
o The idea is that, the light motion for 1 second provides the required energy
for a planet to move one solar day, because the light motion depends on the
solar day as we have discussed. By that the planets divides this great rate of
time (1 sec = 86400 sec) on their motions to work as a great clock and
produce this rate by their Unified General Motion.
o The basic part (1 sec =365.25 sec) be between the Earth and the Sun motion.

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Extensive Discussion
- Why Does The Previous Investigation Prove The Claim?
- The claim tells that,
- The Sun Is The Solar System Last Created Piece. And that means, the sun is
created after All Planets Creation And Motion.
- If this fact can be proved, it will disprove Newton Theory of The Sun Mass
Gravity decisively.
- How to prove that the sun is created after all planets creation and motion?
- In addition to the historical proves there's one basic proof which is
- The sun rays velocity be = 300000 km
- While
- The solar planets matters and distances be created out of light beam its velocity
=1.16 mkm/sec.
- As a result, I have analyzed the planets data to prove that, this data be created
based on a light beam its velocity =1.16 mkm/sec
- After this analysis, we have to describe how the sun rays be created and the
previous data provides this description.
- Now
- Why Does This Analysis Provide A Sufficient Proof?
- The proof sufficiency depends on the arguments and discussions logic
- The discussions used hundreds of the planets data and put them in some form to
prove some idea. I can create the idea but can't create the data. that means if the
data be in harmony with the idea that supports the proof sufficiency.
- We have used hundreds of data in different discussion, if the discussion logic be
straight and the data be in harmony with it that proves the claim clearly
- The point is that, we searched for the rules based on which this data be created. so
as much as the used data be in harmony with these rules that prove these rules
sufficiency.

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- For example
- I claim (1 day of the sun motion = 1 year of Earth motion). this idea we have
accepted as a hypothesis and used it based on that
- But
- This idea is created because of the moon circumference equation (10921 km x
86400 seconds =940 mkm). Means, we have some data refer to this hypothesis.
- So we have used this idea as a hypothesis.
- We have found that, the data be in harmony and produce a velocity = (0.25 C)
- This velocity be created as a result for the hypothesis we suggested because of the
moon circumference
- But
- Earth Cycle (4 years) can change this velocity (0.25C) into ( 300000 km/s)
- I try to show that, w don't create the data
- We Rearrange The Data In New Positions Relative To One Another
- This is the basic method of the proof.
- Then we find that
- Jupiter (again) provides us a chance to create the value (C2
) (which can be a
source of the sun rays energy)
- So we used the velocity 1.16 mkm/s which we have learnt from Jupiter motion
data and added it to earth circumference to produce the required value (4C)
Notice
The planets unified general motion supports the proof with powerful arguments which
makes the proof more understandable and trustee.

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7- The Solar Planets Motions Depend On Different Rates of Time
7-1 Preface
7-2 Earth And Pluto Rate Of Time
7-3 Mercury Motion Rate Of Time
7-4 Saturn Motion Rate Of Time
7-5 Uranus And Jupiter Rate Of Time

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7-1 Preface
- The different rates of time is the logical result for light motion accompanying
planet motion.
- The matter is created out of light but be not separated from its light parent, on the
contrary, they move together one unified motion. but they use different rates of
time for their motions.
- The basic rate of time is (1 second of light motion = 1 solar day of planet motion)
- The solar planets divides this great rate (1s =86400 s) among their motions and
work as a great clock.
- The rate of time between Earth and the sun (1 s = 365.25 s) is produced through
this process.
- But
- How to prove that? for example If
- 1 hour of Mercury motion = 9.18 hours of Pluto motion, can we prove that?
- The rate of time is one data of the planets motion data, because of that we can
discover the rates of time by the planets motions data analysis.
Notice
- Mercury data analysis refers to the rate 1 hour of Mercury motion = 1 second of
light motion and
- 1 hour of Mercury motion = 24 hours of Jupiter motion
- The combination of these 2 rates produce the basic rate (1s =86400 s) but the
planets depend on one another to operate the great clock.

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7-2 Earth And Pluto Rate Of Time
I- Data
Group no. (1) (Earth and Pluto Rate Of Time)
(A)
- Earth (29.8 km/s) moves during a solar day (24 h) a distance = 2574720 km
- Pluto (4.7 km/s) moves during its day (153.3) a distance = 2593836 km
- Pluto and the moon motion distances be equal but they are different from Earth
motion distance with (1%).
(B)
(C)
- 1 hour of Earth motion= 29.53 hours of the moon motion (explained in discussion)
(1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
(2)
Tan (12.2) x 708.7 hours = 153.3 hours
(3)
Tan (13.17) x 655.7 hours = 153.3 hours
(4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
(5)
413600 km cos (10.96 deg) = 406000 km
(6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)

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II- Discussion
- The Rate Of Time Depends On Planets Velocities Rate (A hypothesis)
- But, this rule sometimes be violated and in this case we can use the simple rule
tells (Equal Distances Causes Different Rates Of Time)
- 1 hour of Earth motion = 6.37 hours of Pluto motion
- This rate is concluded simply from Earth and Pluto velocities
Because
- Earth velocity (29.8 km/s) = Pluto velocity (4.7 km/s) x 6.37
- Also
- Pluto Day Period (153.3 h) = Earth Day Period (24 h) x 6.37
- The rate (6.37) which creates the rate of time between Pluto and Earth Motions,
effects greatly on the 2 planets motions data. As we have seen.
- Let's summarize the data idea in following:
- There's a proportionality between Pluto Data on one side and Earth and its moon
data on the other side. No Pure Coincidence can be claimed, because the
connection among the three planets be defined based on their positions to one
another. the question be (How This Data Be Created?)

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Equation no. (C)
1 hour of Earth motion = 29.53 hours of the moon motion.
- Because
- The moon displacements total during the moon day period (29.53 days) = Earth
motion distance during a solar day Period. (error 1%)
- Because of that
- 1 Day Of Earth Motion =29.53 Days Of The Moon Motion.
- We can see that, the machine works with consistency, for example
o 1 hour of Earth motion =6.37 hours of Pluto motion
o 1 hour of Pluto motion = 4.61 hours of the moon motion
o And
o 1 hour of Earth motion = 6.37 x 4.61 = 29.53 hours of the moon motion
o The rates of time are created based on each planet motion data and be in full
harmony as we see. That tells we deal with a geometrical mechanism works
consistency…
- Let's see the rate of time of Pluto and the moon motions

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Discussion (continued)
Equation no. (1)
(406000 km /88000 km) = (708.7 h/ 153.3 h) = 4.61
- Where
- 406000 km = Pluto motion distance per a solar day
- 88000 km = The moon displacement per a solar day
- Based on the rule (Equal distances creates different rates of time).
- 1 hour of Pluto motion = 4.61 hours of the moon motion.
- This rate of time be concluded because Pluto moves during its day period (153.3 h)
a distance = the moon displacements total during its day period (29.53 days). By
that 708.7 hours of the moon motion = 153.3 hours of Pluto motion. And So, the
rate of time be concluded (1 h of Pluto motion =4.61 h of the moon motion)
- Again the rates of time causes (2 Planets All Data) to be in proportionality with
one another. in following equations we see that Pluto and the moon motions data
be in full proportionality which is very interesting data.
Equation no. (2)
Tan (12.2) x 708.7 hours = 153.3 hours
- Where
- Equation no. (2) shows that the moon and Pluto days periods are created based on
each other geometrically. The fact can't be denied. Pluto day period (153.3 h) is
created as a function in the moon day period (708.7 h).

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Equation no. (3)
Tan (13.17) x 655.7 hours = 153.3 hours
- Where
- 153.3 hours = Pluto Day Period and (153.3- ) = Pluto Rotation Period
- Equation no. (3) shows, Pluto rotation period is created depending on the moon
rotation period based on the angle (13.177 deg).
- The data of the 3 equations are strong and prove the idea clearly, because it's A
Directed Data. Means, this data be created based on geometrical mechanism be
found between Pluto and the moon motions. For that reason, the equations use (all)
data of the 2 planets. That shows the data is directed and can't be created by any
random process. It's data be created based on geometrical reasons and rules.
- The proportionality in data between Earth and its moon on one side and Pluto on
the other side shows that a geometrical mechanism must be found behind them.
Equation no. (4)
2 x 153.3 h = 4.61 x 66.8 But
(708.7 h /10.7 h) = (655.7 h /9.9 h) =66.23 (error 1%).
- 708.7 hours = The moon Day period
- 655.7 hours = The Moon Rotation Period
- 10.7 hours = Saturn Day Period
- 9.9 hours = Jupiter Day Period
- The rate (4.61) we have defined, where (1 hour of Pluto motion =4.6 hours of the
moon motion).
- Equation no.(4) tells that this rate (4.61) is known by Jupiter and Saturn motions.
- That tells, the rate (4.61) is transported among the solar planets and that explains
how this rate be created between the moon motion and Pluto motion.

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Equation no. (5)
413600 km cos (10.96 deg) = 406000 km
- Where
- 406000 km = Pluto Motion Distance During A Solar Day
- Equation no. (5) shows that, the motions interaction between the moon and Pluto is
a deep interaction. And effects on the planet motion basic data. Because
- The moon displacements total during 29.53 days =2598693 km = 2π x 413600 km
- The distance (413600 km) should be the moon apogee orbital radius if the moon
apogee orbital circumference = the moon displacements total during 29.53 days.
- This is the fact which should be performed
- But
- The moon apogee orbital circumference be (2550973 km) less than the moon
displacements total during (29.53 days) with 2%. This fact arises the question
Why? the moon apogee circumference should be 2598693 km (surely). But for
some geometrical miracle this distance became =2550973 km!
- The radius 413600 km be changed into 406000 km and this change be done based
on the equation no. (5). The angle (10.96) caused this change. We have discussed
this angle before deeply because it's the main angle in the moon orbit geometrical
structure (we will review a short notice about it later). The angle (10.96 deg)
causes the radius 413600 km to be 406000 km – why?
Equation no. (6)
(10.96 deg /1.7 deg) = (153.3 h /24 h) (error 1%)
- The angle 10.96 deg be created based on the rate between Pluto Day Period
(153.3h) and Earth Day Period (24 h). this rate be used between the angle (10.96)
which causes to decrease the radius from 413600 km to 406000 km, and the angle
1.7 deg which is the moon daily motion angle in the moon orbital equation (θ1= θ0
+ 1.7 deg). (The moon orbital equation be in my previous paper)

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Notice (1)
- The moon displacements total 2598693 km should be the moon apogee orbital
circumference, by that, the moon apogee orbital radius should be =413600 km
- But
- It's not true, the moon apogee orbital radius =406000 km
- Why? because of the angle (10.96 degrees)
- Let's remember this angle in following:
o The moon orbital perigee radius =363000 km
o The moon orbital apogee radius = 406000 km
o If we draw these 2 radiuses in 2 circles as in the figure
o The tangent DB = 181843 km, also
o The perigee orbital circumference = 2.28 mkm
o (181843 km /2.28 mkm) = 0.08
o 137 degrees x 0.08 = (10.96 degrees)
o As we remember that 137 degrees = 95.1 deg x 1.44 deg where
o 95.1 deg =90 deg + 5.1 deg (the moon orbital inclination)
o 1.44 deg = the moon orbit regression degrees per month.
o We have supposed that the angle 137 degrees is created based on the moon
orbital inclination (degrees) and the moon orbit regression angle monthly.
And this angle (137 deg) is the basic angle in the moon orbital geometrical
structure (hypothesis).
o The calculations of the tangent DB = 181843 km aimed to explain one basic
idea which is, the moon orbit is built geometrically to create the rate (0.08)
by which the moon orbital inclination and regression will create the angle
(10.96 deg).
o Let's explain that more clearly

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o The moon orbit inclination and regression controls the moon orbital motion.
this is a hypothesis. Now, the moon orbital motion creates the moon orbit
based on a geometrical design, the moon orbital motion uses the moon orbit
geometrical design to create the angle (10.96 deg) from the basic one (137
deg). by that the original angle is (137 deg) which is created by the moon
inclination and regression unification, and the born angle is (10.96 deg)
which is the motor of the machine.
o What we need to refer to is that, the moon orbit geometrical design is used
in this process. That's why the distance 413600 be decreased and became
406000 km. By that, the main player is the angle (10.96 deg).
- This explanation answers the question,
- Why Pluto Motion Distance During A Solar Day = The Moon Apogee Orbital
Radius=406000 km?

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Notice (2)
- The previous data still have another reading let's summarize it in following:
o Pluto day period is a very long day period in comparison with the outer
planets days periods, Why?
o We notice also that, Pluto Moves During Its Day Period A Distance =
Earth Motion Distance During Earth Day Period. That means, Pluto Day
Period be extending to perform this requirement.
o i.e.
o Pluto Day Period be extending to be 153.3 h to enable Pluto to move a
distance = Earth motion distance during Earth day period.
o Because of that,
o Pluto day period (and rotation period) be created as functions in the Earth
moon day and rotation periods as we have seen in the data discussion.
o i.e.
o The interaction between Pluto motion on one side with the Earth and its
moon motions on the other side caused the following results:
o (1st
Result) the moon apogee orbital radius be decreased from 413600 km to
be 406000 km
o (2nd
Result) Pluto Day Period be extending to be =153.3 days.
Notice (3)
- Uranus effect is the main force behind the changes for the 2 planets data.
- Uranus effect on Pluto is proved by Planet 8 days Cycle where Uranus uses Pluto
day period in its motion.
- Uranus effect on the moon is proved by the fact, Uranus orbital circumference =
19.2 Earth orbital circumference. The moon moves a cycle called Metonic cycle
and extends for 19 years. Metonic Cycle is caused almost by Uranus effect on the
moon motion.

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7-3 Mercury Motion Rate Of Time
I- Data
(1)
112.2 km/s = 4.7km/s x 23.9
(2)
1407.6 hours =153.3 hours x 9.18
(3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
(4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
II- Discussion
Equation (1)
112.2 km/s = 4.7 km/s x 23.9
- Where
- 112.2 km/s = The 3 Planets Velocities Total
- 4.7 km/s = Pluto Velocity
- Let's suppose, the 3 planets velocities (Mercury, Venus and Earth) be unified in
one velocity =112.2 km/s, So this velocity works as one gear and Pluto velocity
works as another gear, move relative to one another.
- By this supposed motion of 4 planets, the rate (1 hour = 23.9 hours) be created and
that causes 1 hours of a planet motion be = 23.9 hours of another planet motion.
- This process has a great effect on the solar planets rates of time because if the
planets motions rates of time depend only on the planets velocities that makes the
max rate is (10.08). Means, 1 hour of a planet motion be = 10.08 hours of another
planet motion. And this is a very narrow range of the rates of time. The 3 planets
velocities total creates an extension for this process and enables the system to
create the rate (1h = 23.9 h).

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Equation (2)
1407.6 hours =153.3 hours x 9.18
- Where
- 1407.6 hours = Mercury Rotation Period
- 153.3 days = Pluto Day Period.
- (9.18) = The rate of time between Mercury and Pluto motions.
- We conclude that mercury and Pluto motions rates of time is (9.18) based on this
equation. Means
- 1 hour of Mercury Motion = (9.18) hours of Pluto Motion.
- By this same method we conclude the rate of time between Pluto and the moon
motions. It was the rate between the moon day period and Pluto day period. But
here the rate (9.18) is between Mercury Rotation Period and Pluto Day Period
(where Pluto day period =153.3 h and Pluto rotation period = -153.3 h)
Equation (3)
90560 days = 4222.6 hours x 9.18 x 2.33 (error 2%)
- Where
- 90560 days = Pluto Orbital Period
- 4222.6 hours = Mercury day period
- 2.33 = ??
- Mercury velocity (47.4 km/s) = 10.08 x Pluto velocity (4.7km/s). if the planets
rates of time depend on their velocities. That means 1 hour of Mercury motion =
10.08 hours of Pluto motion. and in this case 24 hours of Pluto motion = 2.37
hours of Mercury Motion.
- That because the equation uses (Pluto orbital period 90560 solar days) in
comparison with 4222.6 hours (Mercury day period). The equation proves that the
rate (9.18) is the used one between the 2 planets.

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Equation (4)
(2 x 153.3 h x 3600 s) /5040 s =23.9 x 9.18
- Where
- 5040 seconds are required for Mercury day period to be 176 solar days
- 153.3 h = Pluto Day Period.
- 23.9 = the rate between the 3 planets velocities total (112.2 km/s) and Pluto
velocity (4.7 km/s).
- This equation also proves that the rate of time between Mercury and Pluto is (9.18)
- The data proves that, 1 hour or Mercury motion = (9.18) of Pluto motion.
Notice
- Different data of Mercury and Pluto Motions shows that the rate of time between
them is (9.18)
- Because this rate is used in different data in the 2 planets motions data, we
conclude that it's a fact and real one.
- I wish the proves show its power clearly. Because we deal with geometrical data.
We find for example a rate (9.18) between Mercury and Pluto motions data and
this rate be used between them frequently. That happens also with Earth (6.37) and
with the moon (4.61).
- The point is that, the rate of time has a massive effect on planets motion but we
still need to discover this effect clearly.
- It's noticeable to take into consideration the method by which the rate of time
effect on Planet Motion.
Notice
- If Mercury and Pluto motions rate of time be defined based on their velocities
only, The rate will be 10.08 (means 1 h of Mercury motion = 10.08 h of Pluto
motion). the rate (9.18) effect only on Pluto and Mercury motions but no other
planets. For example (Mercury 1 hour =46.1 h of The Earth moon motion), in this
case (46.1 = 10.08 x 4.61) , the data doesn’t use (9.18) but (10.08).

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7-4 Saturn Motion Rate Of Time
I- Data
(1)
Saturn moves daily 838080 km = the Earth moon displacement 88000 km x 9.5
(2)
Saturn diameter 120536 km = Earth diameter 12756 km x 9.5
(3)
Saturn orbital distance 1433.5 mkm = Earth orbital distance 149.6 mkm x 9.5
(4)
Earth axial tilt 23.4 deg = Saturn orbital inclination 2.5 deg x 9.5 (error 1.7%)
(5)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
II-Discussion
- Equation no.(1) shows that, the rate of time be produced as a rate between Saturn
motion distance per a solar day and the moon displacement per a solar day (9.5)
and this rate controls different data between Saturn on one side and Earth with it
moon on the other side.
- This feature is similar perfectly to Pluto data proportionality with Earth data.
- And also the data between Pluto and Mercury.
- The data tells that, the rate of time has a massive effect on the planets motions
data. This feature which we see frequently in different planets data.
- The data (1, 2 ,3 and 4) shows that the rate of time (9.5) creates a proportionality
between Saturn and Earth motions data.
- Let's discuss Equation No. (5) in following
Equation no. (5)
Saturn Orbital Period 10747 days = 365.25 days x 29.53 days
- We know that,
- 1 day of Earth Motion = 29.53 days of the moon motion
- And also we know

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- 1 day of the sun motion = 365.25 days of Earth Motion
- Based on that,
- 1 day of the sun motion = 365.25 x 29.53 days of The moon Motion, means
- 1 Day Of The Sun Motion = 10747 Days Of The Moon Motion
- Where
- Saturn Orbital Period =10747 days
- How this data be created?
- More interesting data be in our waiting
- The Earth orbital circumference =940 mkm but the moon daily displacement be
=88000 km, that means
- If the moon passes Earth orbital circumference (940 mkm) by using it daily
displacement (88000 km) the moon needs a period = 10747 days (error 0.6%)
- This data tells, the period 10747 days be defined regardless Saturn motion. or in
better words, the period 10747 days be defined before Saturn Creation.
- The data forces us to guess that, the Earth moon must be created before Saturn
creation. and as a result for the interaction with the moon motion Saturn uses the
period be defined by the moon motion. (also Saturn orbital distance =1433 mkm =
Mars orbital circumference. That tells may some interaction of motions between
Saturn and Mars caused Saturn to use mars orbital circumference as its orbital
distance. And if we put this data beside each other we may conclude that Saturn is
created after Mars migration and the moon creation).
- One more data can help our investigation
- The moon daily motion distance = Earth daily motion distance =2.574 mkm
(because they are not separated from one another)
- The moon distance be effected by the rate 1.0725 and because of that (2.574 mkm
=1.0725 x 2.4 mkm) the moon motion distance daily be =2.4 mkm
- During 10747 days the moon moves (2.4 mkm) a total distance =25920 mkm

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7-5 Uranus And Jupiter Rate Of Time
1 hour of Mercury motion = 24 hours of Jupiter motion = 24 hours of Uranus motion
(For Jupiter)
Old Equation No. (A)
4780 mkm = 1.1318 mkm per solar day x 4222.6 days
- Where
- 1.1318 mkm Per Solar Day = Jupiter Motion Distance Per A Solar Day
- The distance 4780 mkm is different from 4846 mkm with (1.38%)
- 4846 mkm = The Inner Planets Orbital Circumferences Total
- We have seen this equation before in our analysis for Jupiter orbital circumference
(4900 mkm).
- Equation no.(A) tells,
- 1 Hour Of Mercury Motion= 1 Solar Day Of Jupiter Motion.
- This rate equal Uranus rate also let's see it in following
-
(For Uranus)
Notice
- Mercury Uranus Distance = 2815.2 mkm
- Mercury rotation period = 1407.6 hours
- 2 x Mercury rotation periods = 2815.2 hours
- If 1 mkm = 1 hour, So the distance 2815.2 mkm be = 2 Mercury rotation periods
And
- Mercury (47.4 km/s) moves during its rotation period (1407.6 h) a distance = 243
mkm (error 1%)
- 243 solar days = Venus rotation period
- If each 1 mkm be =1 solar days, the distance 240 mkm be = 243 days (error 1%)

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Based on that
- Mercury as a player uses (1 mkm = 1 hour) and (1 mkm = 1 day =24 hours)
- That creates the rate (1 hour = 24 hours)
- But between whom? Almost
- Between Mercury and Uranus, means
- 1 hour of Mercury Motion =24 hours of Uranus Motion.
Notice
- 1 h of Pluto motion=2.62 h of Jupiter motion =2.62 h of Uranus motion.
- The rate 2.62 is so important for Jupiter and Uranus because
- Uranus Circumference 160592 km x 2.62 = 421056 km (Uranus Motion
Distance During Its Day Period)
- Jupiter Circumference 449197 km x 2.62 = 1160000 km (Jupiter Motion
Distance During Mars Rotation Period) (error 1.4%)
- This data we have discussed before.

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8- The Solar Planets Motions Analysis
8-1 Preface
8- 2 The Equal Distances Method
8-3 The Inner And Outer Planets Motions Be Distinguished

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8-1 Preface
- The paper claims that,
- The solar planets move a type of motion be different from the motion type Newton
had imagined based on The Sun Mass Gravity Concept.
- The previous discussion proves that:
1. The Planets Move One Unified General Motion, Disproving Newton Concept
Of Planet Independent Motion
2. The Planets Motions Depend On Different Rates Of Time.
- These Features Contradicts Newton Theory Of The Sun Mass Gravity.
- But
- There are more interesting features which prove that, the solar planets motions be
different in nature from the motion Newton had mentioned by The Sun Mass
Gravity.
- Among these features we study 2 basic features which are
o The Equal Distances Method
o The Distinguish between The inner and outer Planets Motions.
- Let's start our discussion in following…

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8- 2 The Equal Distances Method
- The Equal distances Method is A Feature be discovered in the solar system motion
- 2 Planets move equal distances in defined periods of time. And as a result this 2
planets data be in proportionality with one another.
- This feature be analyzed as deep as possible to know why it's used and what
geometrical effect it creates. Let's explain that by using examples in following:
Example No. (1) (Earth and Pluto Data)
(A)
- Earth moves during its day period a distance = Pluto motion distance during its day
period = the Earth moon displacements total during its day period (error 1%).
(B)
- (Earth velocity / Pluto velocity) = (Pluto Day period/ Earth day period) = 6.37 (0.8%)
(C)
- (Pluto motion distance daily406000 km/ the moon displacement daily88000 km)=4.61
- (The Moon Day Period 708.7 h / Pluto Day Period 153.3 h) = 4.61
- Tan (12.2) x 708.7 h (The Moon Day Period) = 153.3 hours (Pluto Day Period)
- Tan (13.17) x 655.7 h (The Moon rotation Period) = 153.3 hours (Pluto Day Period)
- (Where 13.17 deg = the moon daily motion degrees, and 12.2 deg =13.17 deg – 0.9856
deg Earth motion daily degrees)
- We have discussed this data before.
- The proportionality of data may be created by the equal distances of motions or by
the rate of time. Or may both be created based on each other.
- The fact is that,
- The 2 planets move equal distances in defined periods of time and their data be
created in proportionality with one another.

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- Let's analyze the previous example as possible:
o Equal Distances Be Passed By Earth And Pluto Motions,
o We should pay attention for the equal distances nature, because the distances
are equal. But these distances are not random distances. On the contrary,
these are mentioned distances because the planets pass these distances
during their days periods.
o It's necessary to put this data in front of our eyes (always). Because the
equal distances aren't any random equal distances but distances be passed
during defined periods of time and by that these distances be mentioned to
be equal.
o Defined period of time means a period be defined by a planet motion. as a
planet orbital period or day period or rotation period …etc
o Shortly a period depends on a planet motion
Example No. (2) (Mercury and Mars Data)
- Mercury moves during its rotation period a distance =243 mkm (error 1%)
- Mars moves during Venus day period a distance =243 mkm
- We have 2 equal distances! Where's the data proportionality?
- (Mercury Day Period)/ (Venus Day Period) = (Mercury Orbital Period / Mercury
Rotation Period)
- That tells, Venus day period is created as a function in Mercury cycles periods.
Can Mars motion for the distance 243 mkm be the reason of this proportionality?
Notice
243 solar days = Venus Rotation Period (if 1 mkm = 1 solar day), so this distance
(243 mkm) may refer to Venus Rotation Period
On the other side
Venus moves during (365.25 days) a distance = 1106 mkm =2π x 175.94 mkm
175.94 solar days = Mercury Day period (means, 1 mkm = 1 solar day is a rate
known by Venus and Mercury).

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The Equal Distances Using Range
- Why Do We Study The Equal Distances Method?
- Because
- This Method is almost the planets motions method. That means the solar planets
don't move by the sun mass gravity but move by the equal distances method (or at
least the outer planets move by the equal distances method).
- That means,
- The solar system motion depends on the equal distances method greatly.
- Why Do We Need to Know That? Even If Be A Fact
- Because
- This explains the heavy using of the equal distances methods in the solar system
motion. and by that we explain the following facts:
o 50% Of All Distances In The Solar System Be Equal One Another
o And
o 40% of all distances in the solar system be rated one another with the same
one rate (1.0725)
o This data be in appendix no. 1 of this paper
- Notice
- We have discussed this data before but the data of (50% of all distances are equal)
and (40% of all distances are rated) be put in the appendix no. 1 to be used as
reference

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Let's summarize the equal distances using range in following:
(1)
The data in appendix no. (1) shows that
50% of all distances in the solar system are equal one another
and
40% all distances in the solar system are rated with the same rate (1.0725)
(2)
Planet 8 days Cycle depends on the equal distances using
We have discussed Planet 8 days Cycle in The planets Unified General Motion
(3)
Different examples we have discussed as Earth and Pluto equal distances
And also Mercury and Mars equal distances
(4)
Planet diameter or circumference using as a period of time depends on equal distances
let's provide some examples in following:
o Jupiter (13.1 km/s) moves during 10921 second a distance =142984 km =
Jupiter diameter.
o Uranus (6.8 km/s) moves during 7510 second a distance =51118 km =
Uranus diameter.
o Pluto (4.7 km/s) moves during 10921 second a distance =51118 km =
Uranus diameter.
o Pluto (4.7 km/s) moves during 51118 seconds a distance =2 x 120536 km =
Saturn Diameter.
o Pluto (4.7 km/s) moves during 2 x 120536 seconds a distance =1.1318 mkm
= Jupiter motion distance during a soar day.
o Where
o 10921 km = The Earth Moon Circumference
o 7510 km = Pluto Circumference

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The Equal Distances Using Reason
- I provide here an explanation why the equal distances method be used
- I want to say,
- This explanation (whether be correct or incorrect) can't effect on the fact that (the
Equal distances is the reason of the solar planets motions) because this fact
depends on The Equal Distances Method Wide Range Of Using.
- So, let's ask
- Why Be The Equal Distances Used As The Method Of The Planets Motions?
- Because
- This is the method be used between light motion and planet motion. and between 2
planets motions.
- That means,
- If a light beam energy be used to cause a planet motion, this energy be used
through the equal distances method
- And
- If a planet motion energy be used to cause another planet motion, this energy be
used through the equal distances method
- It's the same one method by which the motion be transported from a light beam to
a planet or from a planet to a planet. One method be used for 2 jobs
- As a result, we find distances be passed by light motion and be passed (again) by
planets motions.
- That means, because The Matter Is Created Out Of Light
- The Solar Planets motions depend on the equal distances method

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Example
- Light known velocity (0.3 mkm/s) travels during a solar day (86400 seconds) a
distance= 25920 mkm
- But
- All planets motions distances per a solar day (=17.75 mkm) x 1461 days = 25920
mkm
- If the period of time is not the cycle (1461 days), this equation would have no any
value. But because the period of time is a cycle (1461 days =365 +365 +365 +366)
defined by Earth motion. that tells the distance 25920 mkm be passed by 2 players.
(A light beam and all planets motions total).
- To prove this is a light motion. we see the value 25920 mkm as a period of time
which is (the precession cycle 25920 years)
- Also
- The moon (2.4 mkm/ daily) moves during 10747 days a distance =25920 mkm
- The data tries to show that, the equal distances be use by light and planet motions
or by planet and planet motions.
- That makes this method so useful and suitable for the solar planets motions

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8-3 The Inner And Outer Planets Motions Be Distinguished
8-3-1 The Inner Planets Motion
I- Data
(1)
Earth Mass = The Masses total of (Mercury + Venus + Mars)
(2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
(3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
(4)
Earth Circumference = The moon freedom space of motion
II- Discussion
- The double production experiment tells us
- From Gamma ray one electron and one positron can be created, 2 particles equal in
mass and opposite in charge.
- Equation no. (1) tells, Earth Mass = The 3 Inner Planets Masses Total (error 1%)
- Can we imagine that, a great gamma ray be used to create the inner planets.
- Earth is (The Great Electron) (means, Earth atom has a positive nucleus and
negative charges revolve around)
- The 3 Inner Planets Consist Together (The Great Positron) (means, the inner
planets Mercury – Venus – Mars , Their atoms have negative nucleus and
positive charges move around)
- If these hypotheses be working, the inner planets can create One Electric Field to
cause their motions around the sun.
- The error (1%) refers to a part of mass be consumed to create the required energy
for these planets motions through their orbits.

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- By that the error (1%) is found for a physical necessity and not be found as an
error in measurements.
- The previous description provides a suitable base to create an eclectic field
- The electric field is better for the planets motions than the sun gravity force.
- Newton has no one proof for the sun mass gravity force but the electric field
theory depends on the masses equality fact.
- The next discussion can support the electric field theory.
Equation no. (2)
Earth Circumference = The 5 inner planets diameters total
(Means the diameters total of (Mercury + Venus + The Moon + Earth + Mars))
Equation no. (3)
2 x Earth Circumferences = 2 Mars Circumferences + Venus Circumference
- For what we search? For Electric Charges
- If we can prove that, some electric charge be found in the inner planets. That can
support this idea greatly
- Why these 2 equations refer to charges in the inner planets data?
- Because of Gauss Law!
- Gauss law tells, The Charges Be On The Outer Surface, that means, the outer
surface can be effected Geometrically by electric charges. Because more wide
outer surface receives more charges. That tells The Charge Electric Field Effect on
the matter dimensions must be A Geometrical Effect
- I want to say
- If some planet be charged its outer surface formation and dimensions should be
effected Geometrically because of the electric charge.
- Means, the geometrical effects should be used as a proof for charges existence.

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- The previous 2 equations no. (2 and 3) can support this idea because the inner
planets circumferences and diameters be created in proportionality which can refer
to geometrical effects be produced by electric charges on their creation.
Equation no. (4)
Earth Circumference = The moon freedom space of motion
- The moon orbital Perigee radius =363000 km
- The moon orbital apogee radius =406000 km
- The difference 43000 km
- But the space without the moon diameter =43000 km- 3475 km = 39500km= Earth
Circumference (error 1.3%)
- This data is used for the same argument, A geometrical effect be found on the
surface distances which can be used as a reference for an electric field effects on
the matter dimensions
- Notice
- We know the distance can't be charged unless under specific conditions, but I try
to show geometrical effects are found. It's not necessary for this effect to be a
direct one, but it can be found through interactions.
- Notice
- 43000 km (the distance from perigee to apogee) x 3475 km (the moon diameter)
=149.6 mkm (Earth Orbital Distance). I try to show that, geometrical features are
found behind the dimensions and distances definition in the inner planets. And
these geometrical features supports the electric field effect claim.
- Notice
- We have discovered that the planets motions can't be independent from the other
planets motions on the contrary the planets motions be similar to chess board
motions where each motion be calculated geometrically. This features (Chess

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Board Motion) we have discussed in the planets unified general motion. and I want
to say that, the electric field is the best method can provide this type of motion
(Chess Board Motion)
- That supports the claim, (The Inner Planets Motions Depend On Electric Field)
A Conclusion
- The electric field idea aims to create a source of motion for the inner planets. By
that the moving planets are the inner planets. That tells the inner planets motions
depend on the inner planets electric field. But the outer planets motions depend on
the motion transportation from the inner planets motions to the outer planets
motions.
- By that we have 2 different types of motions but both originated from the same
one source by 2 different methods and that enable the planets motions to be
integrated in one unified general motion
- If the 2 types of motions be proved that disprove Newton Theory of The sun mass
gravity.

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8-3-2 The Outer Planets Motion
The Outer Planets Motions Are Distinguish By 2 Features
- The outer planets motions be distinguished from the inner planets motions by 2
basic features which are
- (1st
Feature) Planet 8 days Cycle doesn't use any inner planet motion.
- (2nd
Feature) The outer planet moves during its day period a distance equal to, or
rated with its circumferences which is a feature doesn't be used by the inner planets
motions.
- Planet 8 days cycle we have studied before
- So,
- Let's discuss in following feature no. (2)

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(2nd
) Planet moves during its day period a distance = Its Circumference
The outer planet moves during its day period a distance equal to, or rated with its
circumferences
I-Data
(1)
Saturn moves During Its Day Period A Distance=Its Circumference (error 1.3%)
(2)
Jupiter moves During Its Day Period A Distance =Its Circumference (error 4%)
(3)
Uranus moves During Its Day Period A Distance =260% of Its Circumference
(4)
Neptune moves During Its Day Period A Distance =200% of Its Circumference
(5)
Pluto moves During Its Day Period A Distance =345.6 x Its Circumference

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II-Discussion
- We should notice that, Jupiter (4%) causes Planet 8 days Cycle
- And in Planet 8 days cycle we have seen that, a different distance = Jupiter
diameter be defined between Jupiter motion distance and its circumference which
creates planet 8 days cycle for Jupiter motion.
- I want to say that, the planet circumference is a player in this planet motion. and
because of that, the (4 great planets circumferences) have deviations from their
circumferences because of Planet 8 days cycle.
- Why does the outer planets be different from the inner planet?
- The outer planets move by observing their circumferences but the inner planets
moves observing their orbital circumferences. That may be happened because of
the electric field controls the inner planets motions and causes their motions be
controlled by their orbital circumferences. But the outer planets depend on the
motion transportation from the inner planets, and by that the outer planet almost
uses its circumference as a measurement for its motion.
Saturn Motion Analysis
- We analyze Saturn motion as an example for the 4 planets motions, in following
- Saturn (9.7 km/s) moves during its day period (10.7 hours) a distance = 373644 km
= 98.67 % of Saturn Circumference (378675 km).
- The difference between the distance (373644 km) and Saturn Circumference =
5031 km. (= 1.3%)
- Why is this interesting?
- Because if a planet moves during its day period a distance = its circumference that
will create a rate between this planet orbital period and day period
- Means
- (Planet Orbital Period/ Day Period) = (Planet Orbital Circumference / Planet
Circumference)
- For that reason, we interest in planet motion distance during its day period.

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- Saturn motion performs this rate
- But
- It shows that, the rate in Saturn data be changed because of geometrical necessities
which I claim they are produced as a result for (planet 8 days cycle). Let's
summarize the idea in following
o The inner planets move under their electric field because of that their
motions be defined by this field effect, but
o The outer planets receive the motion by transportation of motion. because of
that, the outer planets have no a guide in their motion, they use their
circumference as a guide and measurement.
o If this rule be working, the outer planet would move during its day period a
distance = its circumference - But
o Because planet 8 days cycles which causes the motion transportation among
the outer planets, that creates an interaction which changes the rule and
caused the outer planets to move during their days periods distances (NOT)
equal their Circumferences, but (rated with their circumferences)
o Jupiter (8 day cycle) shows clearly that, the planet circumference is a player
in the cycle and proves the interaction which is found among the outer
planets as a result for planet 8 days cycle.
o This explanation details disproves clearly Newton Description because the
motion (here) is transported from one planet to another clearly and with
strong proves which disproves the sun masses gravity concept
o The point is that, the interaction among the outer planets motions cause the
change in the rule and creates planet 8 days cycle. But. The rule still works
spite the deviation.
o I want to say that,

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o Saturn moves During Its Day Period A Distance=Its Circumference
(error 1.3%), But the machine feels that no error in Saturn motion.
because this error is found as a result for the configuration with Planet
8 days cycle
By this same explanation all outer planets motions be controlled. The errors in the
planets motions from the rule (Outer Planet moves during its day period a distance =
its circumference) still works sufficiently, the errors be found as a result for planet 8
days cycle. (hypothesis)

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Appendix No.1
The Solar System Equal Distances List
(A)
Why These Distances Are Equal?
(1)
(2)
Earth Neptune Distance = Mercury Saturn Circumference (0.5%)
(3)
Jupiter Venus Distance = Venus Orbital Circumference (1.5%)
Jupiter Earth Distance = Earth Orbital Circumference (1.2%)
(4)
Jupiter Mercury Distance = Mars Orbital Distance x π (0.6%)
Jupiter Uranus Distance = Venus Jupiter Circumference (0.8%)
II- Discussion (A)
The previous distances form around 50% of all distances found in the solar system
(All orbital and internal distances)… Why These Distances Are Equal One Other?
We may notice that – the distances equality can be produced more easily by light
motion than the rigid body motion - for example – when we push a ball toward a wall
the ball after collision with the wall will return a distance (NOT) equal the original
one - because the collision causes to decrease the ball motion momentum – but the
light can be reflected at equal distances easily – means – equal distances can be
produced by light motion more easy than the Rigid Body Motion.

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(B)
Why These Distances Are NOT Equal?
19. 0725
.
1
mkm
2.41
nce
Circumfere
Orbital
Moon
mkm
2.58
Motion
Daily
Earth
=
20. 1.0725
km)
(378500
radius
Eclipse
Solar
Total
km)
(406000
radius
orbital
Apogee
=
21. 0725
.
1
distance
Mercury
Jupiter
mkm
720.3
Distance
Orbital
Juppiter
mkm
6
.
778
= (Error 0.7%)
22. 1.0725
Distance
Venus
Jupiter
mkm
670
distance
Mercury
Jupiter
mkm
720.3
=
23. 1.0725
Distance
Earth
Jupiter
mkm
629
Distance
Venus
Jupiter
mkm
670
= (0.6%)
24. 1.0725
mkm)
(1325.3
Distance
Venus
Sarurn
mkm)
(1433.5
Distance
Orbital
Saturn
= (0.8%)
25. 1.0725
mkm)
(1205.6
Distance
Mars
Sarurn
mkm)
(1284
Distance
Earth
Saturn
= (0.7%)
26. 1.0725
mkm)
(2644
Distance
Mars
Uranus
mkm)
(2872.5
Distance
Orbital
Uranus
= (0.7%)
27. 1.0725
mkm)
(4495.1
Distance
Orbital
Neptune
mkm)
(4864
= (0.5 %)
(10)
Discussion (B)
The same rate (1.0725) is used for all equations (around 18 distances = 40% of all
solar system distances) – why?
Suppose the equal distances are produced by light reflection and that cause these
distances to be equal – as I have supposed in the previous point (A).
Now suppose– part of these equal distances – is passed through another frame relative
to us – so this part of distances will suffer from Lorentz Length Contraction Effect
which is seen in the rate 1.0725
(Another frame can be found in the solar system because we deal with light motion) –
This explanation can answer why some distances are equal and others are rated with
the same rate (1.0725) – it's simply a feature of light motion.
0725
.
1
T.
Axail
Earth
23.4
T.
Axail
Mars
25.2
T.
Axail
Mars
25.2
T.
Axail
Satrun
26.7
Tilt
Axail
Satrun
26.7
Tilt
Axail
Neptune
28.3
=
=
=

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References and Biography
(Preprint No. 1) Mars Migration Theory
https://www.academia.edu/49051037/_Preprint_No_1_Mars_Migration_Theory
(Preprint No. 2) The Moon Orbital Motion Equation
https://www.academia.edu/49051029/_Preprint_No_2_The_Moon_Orbital_Motion_Equation
The Solar Planets Motions Description (Revised)
https://www.academia.edu/49464125/The_Solar_Planets_Motions_Description_Revised_
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Twitter https://twitter.com/GergesTawdrous1
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Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
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The Solar System Doesn't Move By The Sun Mass Gravity

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