Saturn Day Period Analysis (II) (Revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
Saturn Day Period Analysis (II) (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –18th
May 2021
Abstract
Paper question
How Does The Gravity work?
The Question Explanation
- The motion at distance is one basic question still needs a sufficient answer.
- The mass gravity concept gives us no geometrical mechanism or any explanation
concerns the gravity works mechanism, so we don't know if the gravity needs time
or works immediately, or if the gravity causes the space to be formed in some
geometrical form to perform the gravity effect.
- We have only the word (gravity) which means, some mass will cause another mass
to be moving at distance but no details how this motion is done …
- Venus and Saturn motions data gives some reference that these 2 planets motions
depend on one another.
- How Venus and Saturn motions can be performed depending on each other?
Whatsoever the answer is, it means, (some effect at distance) is found between
these 2 planets.
- Can this effect be a reason for the motion at distance which we search for?
The paper analyzes the 2 planets motions data to see if such effect can be found
between the 2 planets and How this effect can be transported from one planet to
another?

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1- Introduction
- What do we try to do in this paper discussion?
- There's motion data is transported between Venus and Saturn, means
- Venus Motion Data is used as Saturn Motion Data.
- This correspondence of Data can't be found by pure coincidences of numbers, But
the data correspondence must be found by geometrical reasons (the paper
discussion proves these facts), So,
- We have to ask, how the (same data) b transported between Venus and Saturn?
- We don't know how the gravity works, and also there's no explanation tells us how
the motion at distance is done,
- But
- We have (data) is transported between 2 planets (between Venus and Saturn)
- Can this data be transported between the 2 planets?
- Or
- Can the motion be transported from one planet to another?
- This question significance can be discovered by the new vision revision:
o The solar system is one building each planet is a part of this same building.
o Specifically, the Solar system is a clock, each planet is a gear in it
o Means,
o 1 second of a planet motion = 1 minute of another planet motion = 1 hour of
third planet motion,
o By that, the solar system be one clock uses a motion of 1 second period and
produces a motion of 1 solar day period, and this process is done because
each planet rate of time is different from the other planets, and all these rates
of time are accumulated together to produce 1 solar day from 1 second.
o Shortly, if the solar system is a clock, a motion transportation must be used
in it.

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A Question
- Are the seconds periods of time of all solar planets be equal in their periods?
- This question is a simple and important one, let's try to answer it
o Does the second period of time made man period?
o No,
o Earth rotation period =23.9 hours but the solar day =24 hours, the difference
is 0.1 hour.
o That divides the solar day into, 24 hours and the hours is divided in 60
minutes (This division of the solar day is done by planet motion cycles)
o The division of the minute into 60 seconds will be a procedure very similar
to the hour division into 60 minutes
o By that, the second period of time is defined based on Earth motion cycles
o That means, this second must be called (Earth Second Period)
o Let's ask
o The Earth second period of time is defined based on Earth motion features
o But
o Mercury second period of time must be defined based on Mercury motion
features
o Where mercury motion is different from earth motion, that tells, the 2
planets seconds of time must be different…
o And that creates different rates of time through the solar planets motions,
but
o If different rates of time are found in the solar system, that means, a motion
transportation must be done in the solar system.
o And by this motion transportation the different rates of time are created from
one planet to another and based on these different rates of time the solar
system works as a great clock.

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2- Venus Motion data analysis
2-1 Preface
2-2 Data Transportation Among The Planets
2-3 Planet 8 days Cycle
2-1 Preface
- What treasure does this paper provide?
- Venus Motion Data is used by Saturn Motion Data and because of that the (same)
data is used by the 2 planets motions
- The paper tries to show that, this data can't be created by any pure coincidences of
numbers neither be found by any chance or random process. On the contrary, the
paper proves that some geometrical reason must be behind this data using.
- And
- We don't know by what geometrical mechanism the gravity works…. Also we
don't know how the motion at distance is done or by what geometrical rules, for
example, we can't attribute any mechanical features to the space as a medium to
transport the masses gravity force effect
- Also
- The planets don't touch each other to cause any motion transportation among them
- For that reason,
- The data which is used by Venus Motion and also be used by Saturn Motion, this
data should be considered as a treasure because it tells us some connection is found
between the 2 planets …where the current theory gives no reference to any motion
transportation among the planets
- What have we? It's only (DATA) is used by (2 Planets Motions) and we need to
explain why the (Same data) is used by the 2 planets motions…

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2-2 Planet 8 days Cycle
We need to review (the 8 days cycle) for the paper discussion
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- But
- 466884 km = 449197 km (Jupiter Circumference) + 17687 km
- Where
- (8 x 17687 km = 141496 km (Jupiter Diameter) (error 1%)
- Based on that, we have concluded that, Jupiter has a cycle of 8 days
- Jupiter (13.1 km/s) moves during 8 Jupiter days (79.2 h) a distance = 3735072 km
- (3735072 km= 8 Jupiter circumferences + 141496 km (Jupiter diameter) (1%)
(II)
- The distance 3735072 km is passed also by Saturn and Neptune with a rate 80%
depends on one another as following
- Saturn (9.7 km/s) moves during 10 Saturn days (107 h) a distance = 3736440 km
- (10 Saturn Circumferences = 3786750 km, the difference =50310 km = Uranus
Diameter error 1.5%)
- Neptune (5.4 km/s) moves during 12 Neptune days (193.2 h) a distance = 3755808
km
- (24 Neptune Circumferences = 3734323 km, the difference =21485 km = Mars
Circumference (error 0.6 %)
(III)
- Uranus (6.8 km/s) moves during Pluto day period (153.3 h) a distance = 3752784
km
- The distance 3752784 km = Jupiter motion distance during 8 days + 17687 km
- And because
- 17687 km x (8) = 141496 km = (Jupiter diameter error 1%)

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- That tells another Cycle is found between Uranus and Jupiter based on 8 Pluto
days
- That means, the distance passed by Uranus during 8 Pluto days equal the distance
passed by Jupiter during 64 Jupiter days and equal the distance passed by Saturn
during 80 Saturn days and equal the distance passed by Neptune during 100
Neptune days
In details
(a)
Jupiter (13.1 km/s) moves during (64 Jupiter days) a distance =29880756 km
(b)
Saturn (9.7 km/s) moves during (80 Saturn days) a distance =29891520 km
(c)
Neptune (5.4 km/s) moves during (100 Neptune days) a distance =31298400 km
(d)
Uranus (6.8 km/s) moves during (8 Pluto days) a distance =30022272 km
Comments
- The differences between these distances are less than 1 % (generally) and based on
that we can't consider they are different distances but we have to consider that they
are equal distances
- Although still there are small differences which are found for geometrical reasons
for example the difference between Jupiter and Saturn motions distances =
29880756 km – 29891520 km = 10921 = The Earth moon circumference

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The Discussion:
(I)
- Jupiter, Saturn and Neptune follow the cycle (8 Jupiter Days), where
- The distance Jupiter passes in 8 Jupiter days = the distance Saturn passes in 10
Saturn days = the distance Neptune passes in 12 Neptune days
(II)
- Uranus creates a greater (8 Days Cycle), where
- The distance Jupiter passes in 64 Jupiter days = the distance Saturn passes in 80
Saturn days = the distance Neptune passes in 100 Neptune days = the distance
Uranus passes in 8 Pluto days.
- The data shows that some geometrical mechanism must be found behind the
planets motions…
- In fact the previous data is so interesting but we can't use it because many basic
questions we can't answer for example….
o Why these planets motions distances are equal? They are equal distances
passed by different planets in different periods of time, can that be useful to
explain the geometrical reason based on which the motions are done?
o In old example, we have found that, Earth moves during its day period (24
h) a distance = the distance Pluto passes during its day period (153.3 h), can
these distances equality be effective on both planets days periods definition?
o The previous question tells that, because the 2 distances are equal earth day
period =24 hours and Pluto day period =153.3 hours, and in fact the data
supports this conclusion because (Earth velocity / Pluto velocity) = (Pluto
Day Period / Earth Day Period), some geometrical mechanism must be
found behind, But ….
o Any such supposed effect be found between the 2 planets tells that, some
(Transportation Of Motion Features) must be done among the planets…

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2-3 Data Transportation among the planets
I - Data
Group No. (A)
(1)
10 x 10747 days x 24 hours = 10.7 hours x 2 x 120536
(2)
9010 mkm x 10π = 378675 km x 373644 km
(3)
2802 hours = 107 hours x (5.11)2
(4)
10747 days x 24 hours = 10.7 hours x 2 x 12053.6
(5)
(12053 km x π)2
= 1433.5 mkm = Saturn Orbital Distance
Group No. (B)
(6)
120536 km = 5.05 x 23794 (but 9010 mkm = 378675 km x 23794)
(7)
5040 s x 35 km/s = 9.7 km/s x 3600 x 5.05
(8)
2 x 5.1 x 2.5 =(5.05)2
(9)
2 x 30589 days = 12104 days x 5.05
(10)
120536 km = 5.1 x 7510 x π
12104 km = 2390 km x 5.05
Group No. (C)
(11)
35 km/s x 355.2 seconds = 12430 km

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(12)
116.75 seconds x 29.8 km /s = 3475 km (the moon diameter)
Group No. (D)
(13)
(35 Venus velocity /6.8 Saturn velocity)= (24.1 Mars velocity/ Pluto velocity 4.7)= 5.1
(14)
(17.2 x 3600s) /12104 s = 5.1
II- Discussion
Equation no. (1)
10 x 10747 days x 24 hours = 10.7 hours x 2 x 120536
Where
10747 days = Saturn Orbital Period
10.7 hours = Saturn Day Period
120536 km = Saturn diameter
Equation no. (2)
9010 mkm x 10π = 378675 km x 373644 km
- Where
- 9010 mkm = Saturn Orbital Circumference
- 378675 km = Saturn Circumference
- 373644 km = Saturn motion distance during its day period
- Equations no.1 and 2 we have discussed in the previous paper, I use them here to
show that Saturn uses 10 (periods of time) as a basic geometrical feature in its
motion… as we have discussed in (8 days cycle), Jupiter moves during 8 Jupiter
days a distance = the distance Saturn passes in 10 Saturn days… because of that..
the period (10 Saturn days) shows a geometrical features of Saturn motion, becaue
it's a cycle

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- For that reason, Saturn uses 10 of its cycle periods and in Equations no. (1and 2)
use 10 Saturn orbital periods, this using of the (10) periods is found because of
Saturn motion during 10 Saturn days creates a cycle and this cycle moves from
small value into great value (as in earth cycle 365 +365 +365 +366 = 1461 days)
Notice
- If a planet moves during its day period a distance = its circumference, that will
divide this planet orbital period into pieces each piece = its day period and this
pieces total be = this planet circumference
- Saturn (9.7 km/s) moves during its day period (10.7 h) a distance = 373644 km
which =98.67 % of Saturn Circumference (378675 km) (means from rotation 360
degrees this distance rotates only 355.2 degrees)
- We expect Saturn circumference to be a rate between Saturn orbital period and
Saturn day period… although a dependency is found between these 3 values but
not accurately as we have expected, but that means, some geometrical reasons
must cause this change in Saturn motion data.
- Now let's discuss Equation no. 3

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Equation no. (3)
2802 hours = 107 hours x (5.11)2
- Where
- 2802hours = Venus Day Period
- 107 hours = Saturn day period x 10
- 5.1 degrees = the moon orbital inclination (Note 5.1 is used frequently here)
- Equation no. (3) tells that, Venus day period is rated with (10 Saturn days periods
total) with the rate 5.1 which is the data transported from Venus to Saturn
- So,
- The data is transported from Venus to Saturn is the value (5.1),
- This value is used frequently in Venus and Saturn Motions data and the Earth
moon orbital inclination =5.1degrees, that tells us
- The interaction of motions ( or transportation of motions) between Venus and
Saturn depends on this rate 5.1 and by this rate the earth moon creates its orbital
inclination to be 5.1 degrees
- We shouldn't interest for the moon orbital inclination for now but we should
follow Venus and Saturn motions to know how this rate 5.1 is transported between
them and why then we have to return to the moon orbital inclination to see how it's
created based on this rate.
Equation no. (4)
10747 days x 24 hours = 10.7 hours x 2 x 12053.6
Equation no. (5)
- (12053 km x π)2 = 1433.5 mkm = Saturn Orbital Distance
- Where
- 12104 km = Venus diameter (different from the value 12053 km with 0.4%)

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- The equations 4 and 5 we have discussed in the previous paper, I use them here
again to remember that, the value 12053 km which is very near to Venus diameter
12104 km is used in Saturn orbital period and in Saturn orbital distance. We don't
know why this same value (12053) is used in Saturn data, but the data tells some
geometrical mechanism is found behind and this mechanism caused the value
12053 to be used in the period and distance of Saturn motion.
Group No. (B)
Equation no. (6)
120536 km = 5.05 x 23794 (but 9010 mkm = 378675 km x 23794)
- Where
- 120536 km = Saturn Diameter
- 9010 mkm = Saturn Orbital Circumference
- 378675 km = Saturn Circumference
- Equation no. (6) shows the rate 5.05 is used between Saturn motion data
- I try to show that, some geometrical mechanism is found behind and because of
that the rate (5.05) is used so frequently
Equation no. (7)
5040 s x 35 km/s = 9.7 km/s x 3600 x 5.05
- Where
- 35 km/s = Venus Velocity
- 9.7 km/s = Saturn velocity
- 5040 seconds = Mercury day period 4222.6 h needs 5040 s to be 176 solar days
- Equation no. (7) tells us that,
- Venus moves during 5040 seconds a distance = 176400 km
- This same distance is passed by Saturn during 5.05 hours, again the data uses the
rate 5.05

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Notice
- Why we use the period 5040 seconds in Saturn motion data? Because
- Saturn (9.7) moves during its day period (10.7 h) a distance = 373644 km
- Saturn Circumference = 378675 km
- The difference
- 378675 km – 373644 km = 5031 km
- Because the value are very near (5040 and 5031) there's some feeling that,
Mercury period (5040 s) is related to Saturn period (5031 km)
- Indeed, Mercury (47.4 km/s) moves during 5040 seconds a distance =2 Saturn
diameters (error 1%)
- That tells because Saturn moves during its day period a distance less than its
Circumference with 5031 km because of that mercury day period is less than 176
solar days by 5040 seconds
- As a result, this value (5040 seconds) be effective in Venus and Saturn Motions
Data.
Equation no. (8)
2 x 5.1 x 2.5 =(5.05)2
- Where
- 5.1 degrees = the moon orbital inclination
- 2.5 degrees = Saturn orbital inclination
- Equation no. (8) tells that both planets orbital inclination depends on the rate
(5.05)

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Equation no. (9)
2 x 30589 days = 12104 days x 5.05
- Where
- 30589 days = Uranus orbital period
- 12104 km = Venus diameter (is used here in days units)
- Equation no. (9) shows that the rate (5.05) is used basically as Venus motion data,
because it's the rate between Uranus orbital period and Venus diameter (the next
equations show that clearly).
- So, this rate (5.05) is Venus Motion data
Equation no. (10)
120536 km = 5.1 x 7510 x π
12104 km = 2390 km x 5.05
- Where
- 120536 km = Saturn Diameter
- 7510 km = Pluto Circumference
- 12104 km = Venus Diameter
- 2390 km = Pluto Diameter
- Equation no. (10) shows more using for the rate (5.05)
Group No. (C)
Equation no. (11)
35 km/s x 355.2 seconds = 12430 km
- Where
- 35 km/s = Venus velocity
- Saturn moves during its day period a distance = 98.67 % of its Circumference,
means, from 360 degrees of its rotation, Saturn (by this distance 373644 km) can
rotate only 355.2 degrees
- Equation no. (11) uses this 355.2 degrees ad a period of time (355.2 seconds) and
during this period Venus moves a distance = 12430 km

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- The distance 12430 km is very specific one because it's the only middle point
between Venus diameter 12104 km and earth diameter 12756 km
- Also
- The value 12430 km is very specific because
- Saturn (9.7 km/s) moves during 12430 seconds a distance = 120536 km = Saturn
diameter
- And
- Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km = light
motion distance during 1 second
Equation no. (12)
116.75 seconds x 29.8 km /s = 3475 km (the moon diameter)
- Where
- 116.75 days = Venus day period
- 29.8 km/s = Earth Velocity
- Equation no. (12) tries to be similar to equation no. (11) and use the period 116.75
days as 116.7 seconds
- Notice
- 26.7 degrees = Saturn Axial Tilt
- On vertical will be 26.7 degrees +90 deg = 116.7 degrees
- If 1 degree = 1 day so 116.75 degrees will be equal 116.75 days (Venus day
period)

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Group No. (D)
Equation no. (13)
(35 Venus velocity /6.8 Saturn velocity)= (24.1 Mars velocity/ Pluto velocity 4.7)= 5.1
Equation no. (14)
(17.2 x 3600s) /12104 s = 5.1
- Where
- 17.2 hours = Uranus day period
- 12104 km = Venus diameter (here used in seconds units)
- Equations no (13) and (14) we have discussed before,
- They show clearly that, the rate 5.1 is used widely between Venus and Uranus
velocities, and also used between Pluto and Mars velocities
- The rate (5.1) or (5.05) is a basic value between Venus and Uranus motion
- Not only because it's the rate between their velocities
- But also
- Because it’s the rate between Uranus day period and Venus diameter
- This data shows there's geometrical reasons behind this using and this geometrical
reasons causes the rate (5.05) to be used frequently
- And then this same rate (5.05) is used by Saturn motion data as frequently as with
Venus itself
- That's why the paper claim (some motion must be transported between the 2
planets).

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
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Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
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List of publications http://vixra.org/author/gerges_francis_tawdrous

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